help-13

[gritty viper]

you could probably find the nearest square number and go from there

[dapper sonnet]

I'm sure that there's a math way of doing it

[gritty viper]

like look at floor(sqrt(n))

[tame wraith]

hmm, the permiter of each square goes from 1 to 4 + 4 to 12 + 4 to 20 + 4. so 1 8 16 24

[gritty viper]

you see the square numbers occupy special spots here

so you can find the nearest square number and then go based off of there

[dapper sonnet]

The point is that each one

If odd

Goes in -1

One time more than the last odd

For even it's -1x that

That's for x

For y it's -1 times x

And that's easy if i loop til the number but not the way i wanna do it

Lemme hop on my PC 2 min

[tame wraith]

each square contains the digits from 1 + 8 + ... (n - 1) - 1 to 1 + 8 + .... (n - 1) + n - 1

[long swan]

Wait I have an idea, use the odd squares as anchor points.
For a given input n, find the nearest odd square greater than n. Call this odd square s.
Then, take the difference s-n.
Then, take the floor of the quotient: [sqrt(s)/2] + 1. Call this q, this determines the layer you are on.
Finally, you take the coordinates of s and move a certain amount depending on the layer

[dapper sonnet]

hmm wait

[dapper sonnet]

wouldnt s-n be 1 tho

cause say we get the square 16, the nearest higher odd square would be 17

17-16=1

or in cases where its already odd, 2

[tame wraith]

formula for permiter is n=1 , p_n = 1. but then from n=2 onwards, p_n = (2(n-1) - 1)*4 + 4

[long swan]

Odd square means the square of an odd number

[dapper sonnet]

yeah figured a second ago

yeah no this is wayyy too complicated

cant believe that there's not a simple solution for this yet lmao

[mossy mango]

@inland fossil

Are you the gf of @gritty viper ?

[inland fossil]

yeah

[gritty viper]

[mossy mango]

[cedar kiln]

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[royal fox]

.open

Three urns contain marbles. Each urn is big enough to hold all the bubbles. The only authorized operation is to double the number of balls contained in an urn by taking a ball from another.

Demonstrate that it is possible, whatever the initial configuration, to obtain a configuration where one of the urns is empty.

[cedar kiln]

Please don't occupy multiple help channels.

[sonic thistle]

,rccw

[wispy marten]

La première chose à se convaincre, c'est que le processus s'arrêtera quand 2 urnes auront le même nombe de boules

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@royal fox Has your question been resolved?

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[crimson sedge]

i don't understand the last pit where he did 180+45=225. as i understand i'm supposed to get the reference angle for 45 in quadrant 3 so shouldn't that be 180-45=135 degrees?

[modern compass]

quadrant 3 is in the bottom left, between 180 and 270

[crimson sedge]

yes

[modern compass]

135 is not in that range. so subtracting 45 does not put you in quadrant 3, where adding 45 does.

[crimson sedge]

i see,so what would be the correct steps for it? i don't think i understand it

[modern compass]

determine what quadrant your reference angle should be in, add that angle to the lower bound of the quadrant.

[crimson sedge]

i see i see, so if it was said to be in Q4 would that mean i should add 270?

[modern compass]

yes

[crimson sedge]

im sorry if im asking too much, but then why in this example here he did 360-60=300 ? shouldn't be 270+60=330.

i know it wouldn't make a difference in this question since its out of the period

[cedar kiln]

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@crimson sedge Has your question been resolved?

[crimson sedge]

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[marsh pond]

I don’t quite fully understand how the denominator is difference of two squares

Maybe the b term is throwing me off or something

[crystal raptor]

It looks like (a-b)(a+b)

[marsh pond]

Yeah.. it’s difficult for me to see it from the original equation

I am basically just multiplying by the conjugate of the denominator? 1/1

[crystal raptor]

a=tanθ, b =secθ-1

You are timesing by 1/1 yes

[marsh pond]

Are you allowed to change more than one operator sign for the conjugate?

Or conjugate only works for binomials?

[crystal raptor]

Uh conjugate is a very broad term, there are kinds of conjugates for things for more than 2 terms, quarternions for example

[marsh pond]

Here I manipulated the b term to be in brackets first, and match the b term for the numerator, then took conjugate of binomial thanks to the brackets

[crystal raptor]

But for two terms you're just flipping the sign of the relevant term to make things cancel usually by difference of two squares

[marsh pond]

OK

[marsh pond]

So I guess what I’m asking is.. it it possible to multiply the first line by the denominator’s conjugate directly? Or the way I did it by adding brackets and matching the b term first is the only way to do it?

[crystal raptor]

I don't know what you mean by directly

[marsh pond]

To have a,b and c terms to solve instead of making it a,b only

Here I am flipping signs of denominator only and multiplying by 1

[crystal raptor]

Well you're only flipping those certain signs because you know a prori what it should look like

[marsh pond]

Lol .. I guess I am trying to understand.. how do you know to do difference of squares as the first step to solving? Just by practice?

Or we wanna try to cancel factors and difference of squares is the easiest way to do that in this case

I don’t see it immediately but maybe I just need more practice

For me I would prob make tan into sin/cos and distribute everything out it would be a nightmare haha

[crystal raptor]

Conjugation will always lead to different of two squares, it's always something to try

You have tan and sec in the denominator and you have theorems relating the squares of those quantities

So it's a sensible thing to try

[marsh pond]

Is thus 1/1 considered conjugation of the denominator? Or not a conjugate at all, since it’s 3 terms?

[crystal raptor]

What?

[marsh pond]

The way I flipped two operators

Normally when I see a conjugate it’s only the middle operator that gets changed between a and b

Not familiar with quarternions

[crystal raptor]

But you can make it two terms

Tanθ and (-secθ+1)

[marsh pond]

Yeap, I know, but just curious if this still counts as conjugate?

Or nothing conjugate about this lol

[crystal raptor]

A conjugate is loosely just flipping the sign of a term in an expression

You can view tanθ-secθ+1 as an expression with two terms, and you flip one to get the conjugate

It's really just a matter of perspective

[marsh pond]

Hmmm OK so the conjugate I’m familiar with so far would be flipping of one operator only (the middle)

Yeah I’m in deep waters with this

https://tenor.com/view/huh-gif-21170943

[crystal raptor]

Yes it's the same as flipping the operator inbetween the TWO terms tanθ and (secθ+1)

Or w/e the signs are

[marsh pond]

We talking domain with this stuff? [a,b]

I’ll leave quaternions for later

[crystal raptor]

No

Unrelated

[marsh pond]

OK

[crystal raptor]

Also very strange notation for quarternions no one uses

[marsh pond]

Found it here

https://www.haroldserrano.com/blog/quaternions-in-computer-graphics

[crystal raptor]

Yeah don't go to computer scientists for maths advice lol

[marsh pond]

They will tell me subtraction and division are things of my imagination. “Just use addition maaan”

Which is kinda true, at least that’s my understanding of how computers handle the math

123 - 3
123 + (-3)

I learned today that BEDMAS order of operations could really just be BEMA

And that these math acronyms (including FOIL) can be kind if silly

[marsh pond]

Basically addition is all that is needed

`“Adders” are built into them. They’re a collection of “logic gates” that work together to either power on or off a capacitor. Then, based on a strong of these, you have a bunch of “active” or “non-active” states. Ie, 1s or 0s which is what Binary is, the computer simply reads the resulting states in binary.

The adders are built by humans to turn the capacitors on or off based on the incoming input of 1s and 0s.

Subtraction is the same as “Adding a negative number.” Ie: 5 - 3 = 5 + (-3). So adders are the only thing needed, as negative numbers are also expressible in binary.

You can make multipliers the same way.`

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[gleaming fox]

Hi, I have this two functions and want to calculate the point where they both touch. For that I made them equal but I'm unable to form them the right way

[dusk finch]

,rotate

[cedar kiln]

@gleaming fox Has your question been resolved?

[gleaming fox]

<@&286206848099549185>

[dire geode]

Can you show the original two functions from the question and the instructions

Screenshot or picture is best

[gleaming fox]

Yeah, thats too bad, the instructions are german

I just dont know the algebra

Or the arithmetic

[dire geode]

Just show it anyway

The original equations are what's important and you can translate verbatim

[gleaming fox]

There are no equasions, but I can transllate wou the task

[dire geode]

Then where did these two come from

[gleaming fox]

From the text

[dire geode]

So you probably interpreted the problem incorrectly

[gleaming fox]

Maybe

[dire geode]

Or got the wrong equations from the text

[dire geode]

Yea that's why this is important to do

[gleaming fox]

Good

But still, even if wrong, how would I solve an equasion like in my original question. My problem is the x as exponent

And If this is not possible or just under special circumstances, it would be good to know too

Anyway, thank you, and have a quite nice day!

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[runic garnet]

U want to simplify

?

[wraith otter]

no

i got the simplified

i need the for

[runic garnet]

So domain?

[wraith otter]

yeah

whatever makes it undefined

i think

can u help pls

[runic garnet]

So whatever makes it undefined should not be included

[wraith dagger]

Stephen

Stephen

[wraith otter]

yeah

u would put in the box

x does not equal______

or y does not equal __

oh i got it

thank you

[runic garnet]

Are there options or do u have to type something

[cedar kiln]

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[quaint agate]

hello pls help ive been strugling with this exercise like 3 hours and cant find a solution with steps nowhere

[quaint agate]

the upper image is the correct answer

i think i calculated the zeros correctly, and it has to do something with the inequation sign

the problem is i dont know why the x=>-1 should be x<=-1

<@&286206848099549185>

[cedar kiln]

@quaint agate Has your question been resolved?

[quaint agate]

nvm

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[tame wraith]

How to find the numbers of x and y where x + y is divisible by xy - 1. Where x and y are non zero integers. Is it really just only 1 and 2.

[modern compass]

no

non zero integers, or non zero positive integers?

[cedar kiln]

@tame wraith Has your question been resolved?

[tame wraith]

Aslong as it isn't say -A A, cuz that's trivial.

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[scarlet ginkgo]

How is $(x-1)^2(x+1)^2$ computed?

[wraith dagger]

Willow

[flint plinth]

x^2 - 1 = (x+1)(x-1)

square both sides

[scarlet ginkgo]

$(x^2-1)^2 = (x+1)^2(x-1)^2$

[wraith dagger]

Willow

[scarlet ginkgo]

this?

[flint plinth]

yep

[scarlet ginkgo]

this is so difficult to see

could I have stopped at the point where I marked an arrow in the picture?

[flint plinth]

sure, unless there's some requirement to get it into a specific form

btw, in addition to $x \neq 1$ there should also be $x \neq -1$

[wraith dagger]

Bungo

[flint plinth]

it's usually nice to reduce it further if you can see how to do it, but if i were grading it i'd be ok with the line marked with the arrow

[scarlet ginkgo]

ok, ty

because on an exam, i don't think I would have seen the reduction here

[flint plinth]

in general when you have polynomials you can try to factor them, but if you don't immediately see it (especially in an exam where there's time pressure) i would just move on

but i'm not your instructor, i don't know how they grade

it wouldn't be cool if they took off points for a correct answer tho

[scarlet ginkgo]

ty

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[drowsy glen]

hi

[drowsy glen]

anyone here know about selling price,cost price,discount,ratios and percentages?

if yes plz ping me here

[dire geode]

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[opal egret]

Circular measure,
Find the perimeter of shaded region. So far i only able to find radius of the circle from the question

[south tundra]

Note that tan(36) = 7/AC and sin(36) = 7/BC, meaning AC = 7/tan(36) and BC = 7/sin(36)

Can you figure out what AT and BS are equal to then?

[opal egret]

No, sorry im slow learner🥲

[opal egret]

Ok noted

Do we have to change it to radian?

[south tundra]

AC = AT + TC, right?

[opal egret]

Yeah

[south tundra]

You know AC and TC

You can solve for AT

[opal egret]

TC is 6

[south tundra]

7/tan(36) = AT + 6

[opal egret]

How is tht 🥲

Why not use sin

[south tundra]

sin is opp/hyp

And AC isn't any of those

It's adjacent

So we need tan

[opal egret]

Okay noted

I kinda can understand that

[south tundra]

So AT = 7/tan(36) - 6

[opal egret]

Oooohhh yeahh

[south tundra]

And similarly BS = 7/sin(36) - 6

So now we know AB, BS and AT

We only need the length of the arc ST

[opal egret]

Uhuh

[south tundra]

Generally length of an arc is product of the circle's radius and the sector's angle

In radians though

Meaning, in this case, ST is 6 * pi/5

[opal egret]

Yeah

So i have to find tht to get ST and im done

[south tundra]

Yeah

[opal egret]

Okay i got it now

Thanks a lot

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[austere patrol]

can someone explain to me these steps

[tropic oxide]

we have not been told what u_n and S_n are

however $6 - \frac{2^{n+1}}{3^{n-1}} - \paren{6 - \frac{2^n}{3^{n-2}}} = \frac{2^n}{3^{n-1}}$ might be explainable

[wraith dagger]

Ann

[tropic oxide]

is that the step whose explanation you are looking for?

@austere patrol

[austere patrol]

this is the qn

[austere patrol]

well im wondering how did they get this

[buoyant latch]

So this part?

[austere patrol]

yeah

[buoyant latch]

Try simplify the left side

And take a picture of your attempt

[austere patrol]

i could only take out the 6

[tropic oxide]

,rccw

[tropic oxide]

good. now convert these fractions to the common denominator 3^(n-1)

[cedar kiln]

@austere patrol Has your question been resolved?

[buoyant flame]

how do you do that?

[tropic oxide]

multiply the num and denom of the second fraction by 3...

[austere patrol]

so like this?

[tropic oxide]

,rcw

[tropic oxide]

yes, now simplify the numerator

[cedar kiln]

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[cedar kiln]

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[mental depot]

Im having trouble finding 2) b)

[mental depot]

I just cant find IK= 1/6 AB + 1/3 AC

I hate vectors sm omg

I have -1/6 and its either BA or AB
I also dont know what to do with JB???

[cedar kiln]

@mental depot Has your question been resolved?

[brittle stag]

you are having trouble with IK=1/6 AB +1/3 AC?

[mental depot]

Yess

Maybe im just dumb but idkfhfjds

[brittle stag]

separate IK at B

you get IB + BK right?

[mental depot]

Yurr

[brittle stag]

we know BK is 1/3 BC

we can separate BC at A and get BA and AC

we just have to deal with IB now

[mental depot]

O

[brittle stag]

know how to continue?

[mental depot]

How do we get BA to be 1/6

[brittle stag]

once you turn IB to a term with AB or AC, theyll sum up to 1/6

[mental depot]

waitjrhehwist i dont gwt the IB part 😭😭😭

[brittle stag]

what do you know about IB

[mental depot]

Its the half of AB

OHHHH

[brittle stag]

right

[mental depot]

IM STUPID MBB

[brittle stag]

[mental depot]

We need more ppl like you

TYSM

[brittle stag]

are you lebanese btw, this book looks like something i studied with

[mental depot]

WAIT YEAH I AM

[brittle stag]

🫂

[mental depot]

My name is Ali so yk

OMG UR MY BEST FRIEND NIW

[brittle stag]

Lebanese brothers

[mental depot]

First lebanese online friend

[mental depot]

Yeah we aree

I mever thought id make a friend in a math server 💀💀

[brittle stag]

hahaha

from a math book, quickly recognized the possibility that you are Lebanese 🤣

[mental depot]

They all look the same tbh

Im hesitant to post my book on here

I AINT DOXXING MYSELF

HOW DO I CLOSE A CHANNEL BTW..

[brittle stag]

.close

[mental depot]

.close

[cedar kiln]

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[mental depot]

TYY

[cedar kiln]

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[cedar kiln]

@dull elbow Has your question been resolved?

[dull elbow]

The first 4 terms of a geometric progression are 0.5, 1, 2 and 4. Find the smallest nuber of terms that will give a sum greater than 1000000

i found r to be 2

[livid hound]

4 terms of a geoetric progression r 0.5, 1, 2 n 4
can you write that more clearly

[cedar kiln]

Channel closed

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[livid hound]

is that n supposed to mean and

also make a new channel now since you deleted the op, this will lock any second now

[cedar kiln]

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[vocal nest]

someone help me with this i'm really confused

[cedar kiln]

@vocal nest Has your question been resolved?

[cedar kiln]

@vocal nest Has your question been resolved?

[rotund fox]

All 5?

[vocal nest]

thank you! but i think i figured it out :))

.close

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[full timber]

If A + B = - 3 5/12 how much is:

A) a - 7 5/6 + b + 7 5/6
B) a + 1 5/6 + b - 2 2/5
C) -a-(-5 1/6) + b - 2 2/5
D) 2 5/8 + a - 4 5/6 - b
E) 4 5/18 - a - b + 3 13/27

[full timber]

thx

who helps

[halcyon orbit]

remove parentheses first

[full timber]

why its how it is in the question

there

[halcyon orbit]

then add the numbers

for example for the first you'll have

$a+b+\frac{75}{6}-\frac{75}{6}=a+b$

[wraith dagger]

Arian

[full timber]

OH K

arian

[halcyon orbit]

Yes

[full timber]

can i send u a screenshot from the book

[halcyon orbit]

Of course

[full timber]

sorry my phone is slow

[halcyon orbit]

No problem

[full timber]

480

if a + b is ( ) how much is:

[halcyon orbit]

Oh, you live in Moscow, right?

[full timber]

no

serbia

[halcyon orbit]

Oh

So the country which Tesla borned there

[full timber]

yea

[halcyon orbit]

which one do have problem with it?

[full timber]

all 5

i forgot maths

i was on a break

😭

my teacher said who does not finish it all (100 solves whatever) is getting a LOCKED F

until next grade

[halcyon orbit]

You should just get rid of the parentheses first as I said and then calculate the numbers
If you want I can describe more about it

forexample part b

[full timber]

is there some website that can do this for me

[halcyon orbit]

$\left(a+1\frac{5}{6}\right) + \left(b-2\frac{2}{5}\right) = a+b+1\frac{5}{6}-2\frac{2}{5}$

[wraith dagger]

Arian

[full timber]

yes

thats it

[halcyon orbit]

https://study.com/learn/lesson/parentheses-math-rules-examples.html

[halcyon orbit]

and then...

[full timber]

is that a website that can caluclate

i need a website that can calculate this

[halcyon orbit]

wolframalpha

fxSolver

Symbolab

And ...

[cedar kiln]

@full timber Has your question been resolved?

[cedar kiln]

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[south cobalt]

Hello! please help, show step by step 💖

[livid hound]

have you tried anything by yourself?

[grand forge]

im guessing all 3 are side by side

?

[south cobalt]

idk...

[crystal raptor]

have you tried anything by yourself?

[drifting marlin]

!show

[cedar kiln]

Show your work, and if possible, explain where you are stuck.

[south cobalt]

.close

[cedar kiln]

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[unborn sonnet]

yes

you can solve f'' =0

by using quadratic formula

yes

bro

yes

you can do

quadratic formula

to find x1 and x2

nice

[cedar kiln]

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[unborn sonnet]

btw i have a maths channel

on youtube

@sand cradle

lemme give you link

[cedar kiln]

✅

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[graceful pike]

Hello guys

[graceful pike]

Can anyone help me with this please

For the first one I tried the ratio test but i don’t think it works

[cedar kiln]

@graceful pike Has your question been resolved?

[graceful pike]

<@&286206848099549185> please 🥺

[cedar kiln]

@graceful pike Has your question been resolved?

[graceful pike]

Done with 1,2 just need help with 3,4 please

[inland fossil]

3a is begging to use the ratio test

[graceful pike]

Right so a_n+1 and a_n both tends to 0 but wouldnt that be 0/0

[graceful pike]

Right, but how does that help

[inland fossil]

just divide both sides by |a_n|

[graceful pike]

Right

[graceful pike]

So would r be less to equal to x by the ratio test

[inland fossil]

yeah

then for the power series to converge you need

[graceful pike]

Doesn't that mean R < 1?

[cedar kiln]

@graceful pike Has your question been resolved?

[slow thicket]

Or equal to 1

Because an-> 0

[graceful pike]

But its asking me to show R>=1

[slow thicket]

Yes

The radius of convergence

Not the values for x

X has to be <= 1

But it can also be up to -1

[graceful pike]

Oh

[slow thicket]

So the radius is <=1

[graceful pike]

Yeah so |x| <= 1, but how is R => 1?

[graceful pike]

What how did you know lol

This is Warwick year 1 😂

[crystal raptor]

if this is warwick that means this counts towards your grade 🧐

[graceful pike]

Yes it does, but they do say I’m allowed to work with other people but have to write in our own words, so just no copying

[crystal raptor]

interesting, fair enough!

[graceful pike]

Exactly 😂

[cedar kiln]

@graceful pike Has your question been resolved?

[cedar kiln]

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[random echo]

help

[worn wave]

[random echo]

x=11,v=492 =

and thats the values given

to solve the 2 equation above

[random echo]

?

[crimson sedge]

confused what the question is asking

was that exactly what the question said?

[random echo]

k let me

rephrase this

The Linear Equation, 663x^2+v

you gotta plug in the values

that is given

up their

[crimson sedge]

663x^2+v is neither linear or an equation

[random echo]

oops srry

[crimson sedge]

but

if you know

[random echo]

?

[crimson sedge]

the value of x an v

you can just plug in the values

[random echo]

yeah

oh nvm thats simple

and also

one more question

nvm

.close

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[limpid brook]

can someone explain how to find x in the simplest way possible

like EXPLAIN to me how to get it

I've tried multiple times I dont wanna guess or learn how to do it

I just want someone to explain how to find x

[obsidian coral]

Find the lcm of the denominators, multiply all the terms by that lcm, you cancel stuff out to get rid of fractions, then simplify and solve for x

[limpid brook]

whats the common denominator

my friend said multiply one side by x+1 and x-2

and im so confused

[obsidian coral]

https://www.youtube.com/watch?v=LMS1NR4gZN8&ab_channel=MathandScience

That is a good resource

[limpid brook]

omg ok tysm

.close

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[dapper field]

can someone help me with this with the method provided?

[dapper field]

can someone pls help me?

@everyone

😭

[cedar kiln]

@dapper field Has your question been resolved?

[dapper field]

no

dude

I'm the only one who isn't helped

[obsidian coral]

.close

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[frosty ocean]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[limpid brook]

1

[frosty ocean]

Expand both the sides

[limpid brook]

uh

ok

and when u mean expanf

like

make it x^2?

like

uknow

FOIL?

[frosty ocean]

Yes

[limpid brook]

ok

i did it

now what

[frosty ocean]

Show your work

[limpid brook]

x^2 + x - 10 = 3x -13

[frosty ocean]

Bring all the terms to the left side.

[limpid brook]

to make one side = 0?

[frosty ocean]

Yes

[limpid brook]

kk!

kk

I got

x^2 - 2x + 3 = 0

yay

[frosty ocean]

Can you factorise now?

[limpid brook]

oh ok i think

um

u cant factor that tho

[hollow nebula]

You cant

[crimson sedge]

oh shit

[limpid brook]

Ummm

[crimson sedge]

my bad

lmfao sorry

[limpid brook]

girll what do i do then

[hollow nebula]

Quadratic formula

[limpid brook]

kk

[frosty ocean]

,w solve for (x-2)(x+3)-4=3(x-4)-1

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Hazysleet#7757

[limpid brook]

ummm

[frosty ocean]

Do you know how to get these roots?

[limpid brook]

what is an i

[hollow nebula]

Uh oh

[limpid brook]

we never learned i and stuff

like i know how to use quadratic formula

but like

[crimson sedge]

then you can probably write "doesn't have a real solution"

[frosty ocean]

It's alright, leave your answer as it is.

[hollow nebula]

Are you sure this is the right problem

[limpid brook]

yep..

[frosty ocean]

Are you asked to simplify or solve for x?

[crimson sedge]

if you didn't learn about complex numbers, the teachers prob don't expect you to write the imaginary roots of an equation

[limpid brook]

solve any method

that was b)

wanna see a) LOL

its also like crazy hard

[hollow nebula]

What

“Crazy hard”

[limpid brook]

their from the same question

to solve

[limpid brook]

WE NEVER LEARNT THIS.

[hollow nebula]

You can google it

Lol

[limpid brook]

ya but likeee

[hollow nebula]

It’s not crazy hard

[runic garnet]

bruh milochkaa i remember going over this with u and u didnt know how to subtract fractions. did u learn the fundamentals?

[limpid brook]

bro

[hollow nebula]

bruh

[limpid brook]

nah bro u didnt help me at all u got me super confused

i will ask the teacher

tmr

[hollow nebula]

This is not crazy hard, you just haven’t learned it yet and that’s ok

[limpid brook]

ok thank u anyways

:-)

.close

[cedar kiln]

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[runic garnet]

lol i literally laid it out step by step, try reading it again if you have gained some new perspective, ill link the convo here #help-2 message

[cedar kiln]

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[deft meadow]

Quick question does this mean state the non permissible values?

[runic garnet]

values that would make the denominator = 0

[hollow nebula]

Where does it say that

[deft meadow]

Thank you

.close

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[cedar kiln]

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[marsh pond]

I thought polynomials have domain (-Inf, Inf) and can’t have fractions, radicals, or absolutes for terms?

Polynomials are the most well behaved functions.. so why is this first one classified as a polynomial?

[dusk finch]

Why not?

[marsh pond]

Rational terms.. is the issue not with constant for denominator, but variable in denominator?

[dull oxide]

any real number is acceptable as a coefficient for polynomials

[marsh pond]

I thought rationals were not allowed for polynomials

[dull oxide]

Yeah not that I'm aware

You could have $\pi x^2+ex+\sqrt{2}$

[wraith dagger]

SWR

[mossy mango]

Even p Adic coefficients

Complex numbers too

[marsh pond]

😬 but domain is not (-Inf, Inf) anymore

[dusk finch]

Why not?

it is

[dull oxide]

which value cannot be in the domain?

[mossy mango]

It is

[marsh pond]

Root

[mossy mango]

Give a counter example.

Or just plug ur counter example into a root finder calculator

[dusk finch]

There is no root (if you mean square root)

There is a big differnce between these 2 things

[marsh pond]

So it couldn’t include 1/x or sqrt(2)

Those terms would limit the domain

[dull oxide]

you're losing me

[marsh pond]

To be polynomial

[dull oxide]

Can you write an actual polynomial example without a (-inf, inf) domain?

[marsh pond]

No

[marsh pond]

According to the textbook

[dull oxide]

which condition here is not being satisfied?

[marsh pond]

This

[dull oxide]

y=1/x is not a polynomial

y=sqrt(2) is a polynomial of degree n=0

[marsh pond]

As terms

[dull oxide]

so what? Like y=sqrt(2)x?

[marsh pond]

Poly means many

Oh and 1

[dull oxide]

poly does mean many, yes, but 0 is a non-negative integer

[marsh pond]

Sure, or anything with terms that limit the domain

[dull oxide]

which x value is not allowed in that example then?

[marsh pond]

As soon as you put a non polynomial term the entire polynomial is a non polynomial

[dull oxide]

what was the non-polynomial term?

[marsh pond]

Sqrt(x)

1/x

[dull oxide]

I never did sqrt(x)

I did sqrt(2)

[marsh pond]

I know

I’m asking

[dull oxide]

y=1/x and y=sqrt(x) are not polynomials

[marsh pond]

OK

[dull oxide]

(they are conics though, but that's unrelated)

So I'm still lost then, because you opened the thread saying this was not a polynomial

[marsh pond]

Wait technically this is correct

Monomial is one term

Binomial is also considered polynomial

[marsh pond]

Now i think I understand .. denominator can only be a non zero constant

Rationals are still OK as long as no variables are in the denominator

[dull oxide]

reals too

[sacred grail]

why are you talking about denominators

[dull oxide]

$\frac{x^2}{\pi}$ is a polynomial

[near birch]

In other words, the exponent of all variables must be a natural number or 0

[wraith dagger]

SWR

[sacred grail]

nowhere in the definition of a polynomial is a denominator mentioned

it is irrelevant

[dull oxide]

$(\frac{x}{\pi})^2$ is a polynomial

[wraith dagger]

SWR

[marsh pond]

Because if x is 0 it limits the domain and polynomials must have (-Inf, Inf) for their domain

[sacred grail]

[sacred grail]

a polynomial is defined to be a sum of nonnegative powers of a variable

[near birch]

As I said, the exponent of every variable is a natural number or 0

[sacred grail]

with real coefficients

[near birch]

That is all a polynomial is

[sacred grail]

there is no denominator relevant to this definition

[marsh pond]

This is the definition from

[dull oxide]

,rcw

[dull oxide]

Okay, so @marsh pond, do you have any questions remaining?

[marsh pond]

Im confused now

[sacred grail]

x^3/3 - x^2/2 - 2x + 1/3 is a polynomial because it is a sum of nonnegative powers of x with real coefficients

[marsh pond]

Is domain not relevant to polynomial?

[sacred grail]

sqrt(x) is not a polynomial because it is not a sum of nonnegative powers of x with real coefficients

[dull oxide]

Domain is not part of the definition of polynomial, it's a consequence of it

[sacred grail]

the domain of a polynomial is a consequence of the definition

it is not relevant to the definition

i should probably clarify that it is nonnegative integer powers

[dull oxide]

avidrunner's definition already mentions that too, fyi

[sacred grail]

yes

[sacred grail]

the coefficients are 1/3 for x^3, -1/2 for x^2, -2 for x and 1/3 for x^0

all of which are real

that is all that is relevant

[marsh pond]

Is there an example of a polynomial term that does not have all real numbers for its domain?

OK

[dull oxide]

Nah

[sacred grail]

the domain can be many things

[dull oxide]

It's easy to prove once you go through calculus

polynomials are differentiable everywhere, so they are continuous everywhere, so they are defined everywhere

[sacred grail]

lol it's the other way round

[dull oxide]

Yeah true, you can define a smaller interval

[sacred grail]

no i mean like

[dull oxide]

realized as I hit enter

[marsh pond]

So this is fine?

[sacred grail]

a polynomial can be over general rings

as long as the coefficients make sense for the ring you can define an evaluation map

[marsh pond]

We are getting into the weeds with abstract and it’s miles above where I am.. this textbook is Calculus 1

[sacred grail]

yes you should just take the fact that they have domain R to be a consequence of the definition

it is not part of the definition

[marsh pond]

OK…

[mossy mango]

snow

[sacred grail]

[mossy mango]

MG

[sacred grail]

[cedar kiln]

@marsh pond Has your question been resolved?

[cedar kiln]

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[sturdy dew]

Im confused, for some reason i keep getting 48.99 could someone tell me what im doing wrong here

[tropic oxide]

show your work that leads to 48.99

@sturdy dew

[sturdy dew]

so i just did it again and got 71.66 but that cant be right

[tropic oxide]

it's sin(23°) = y/28, not sin(23°) = 28/y

28 is the hypotenuse

[sturdy dew]

thanks, but I still don't understand how I'm getting 71.66

[cedar kiln]

@sturdy dew Has your question been resolved?

[tropic oxide]

you are getting 71.66 through erroneous manipulations

71.66 is the wrong answer

it does not deserve any more of your attention

i have already told you where your mistake is

[cedar kiln]

@sturdy dew Has your question been resolved?

[honest rune]

Your answer should be 10.94 or approximately 11

It's really simple, just equate sin 23= y/28

[honest rune]

You did the reciprocal of what the correct expression is on the rhs

[cedar kiln]

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[bright shadow]

How can i convert this theta to radian by hand? Without using calculator

[cedar kiln]

@bright shadow Has your question been resolved?

[bright shadow]

Anyone?

[crimson delta]

you dont

[cedar kiln]

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[indigo owl]

just need quicl help on how to use the math bot

[fickle trellis]

the Math bot?

[indigo owl]

i know how to do stuff like $\frac{x}{y}$

[wraith dagger]

Twin Turbo

[indigo owl]

yea

texit

[crimson delta]

google latex

see #latex-help

[indigo owl]

latex?

isnt that the suit thing

oh

right

[crimson delta]

well that aswell

but not here

[fickle trellis]

You mean @wraith dagger

[indigo owl]

thanks ill go to latex help

yup

.close

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[fair bough]

Can someone confirm that if I'm doing this right at all? 2x²-2x+1 is gonna be a negative square root using the quadratic formula so idk if that'd be right or not

[grand raft]

Looks good to me

[fallen moat]

you'll have to write something about rejecting the negative square root side (at least I'll have to do that)

,calc 2*(1.225)^2-1.225-1

[wraith dagger]

Result:

0.77625

[fallen moat]

,calc 2*(-1.225)^2-(-1.225)-1

[wraith dagger]

Result:

3.22625

[fallen moat]

yea, otherwise it looks good

[fair bough]

ok cool thank you

.close

[cedar kiln]

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[worn glacier]

I got 5 but I couldn't get -3 can someone walk me through it pls

[fallen moat]

did you consider whether x is < 3 or >3?

[cedar kiln]

@worn glacier Has your question been resolved?

[sonic thistle]

bring that whole thing into a quadratic< or >0

then plot it

[lusty grotto]

or multiply both the top and bottom of LHS with x-3

so the denominator then becomes a positive qty when x != 3

and u can multiply thru by the denominator and simplify

[cedar kiln]

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[fallow vale]

Dear Helpers,
my math teacher failed to explain integrals.. we’re supposed to do exercise a-f (compare picture below) by hand, and I still don’t understand how.. And I have had troubles understanding the Antiderivative.
Translation: Calculate the integral using an antiderivative.

[fallen moat]

for a-f, you can search for
"power rule for integration" and
"definite integral"

[fallow vale]

Pardon…?

[fallen moat]

here's a website for definite integral
https://www.mathsisfun.com/calculus/integration-definite.html

[fallow vale]

I’m sorry, I truly am

[fallow vale]

Ah, thank you!

[fallen moat]

and site for power rule
https://www.cuemath.com/calculus/power-rule-of-integration/

[fallow vale]

I’ll read through that

Many thanks, @fallen moat

[cedar kiln]

@fallow vale Has your question been resolved?

[cedar kiln]

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[cedar kiln]

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[crimson sedge]

HUH

[crimson sedge]

can someone explain perhaps

it goes towards 0 below the root ? Hmm

[patent cape]

try working out a recursive formula

[crimson sedge]

I have no idea what that even is

Just started learning math

[patent cape]

define something in terms of itself

[crimson sedge]

$\sqrt{n+\sqrt{n+\sqrt{n+\hdots}}} = k$

[wraith dagger]

$∮ \text{your mom} \dd{z} = 0$

[patent cape]

i think $t = \sqrt{t² + t}$ would be the recursive formula

[wraith dagger]

Kel.plush

[frosty thicket]

seems a bit off

[tame wraith]

I think it's because the closer it gets to 0, the more the infinite subsequent square roots blow it back up to 1

[patent cape]

oh yes its wrong i just noticed

[frosty thicket]

I think giving an example of another "self-mentioning infinite sequence" would help them understand better

[tame wraith]

||Oh right yh, and so √(n+k) = k. When n goes to 0, √k = k, so k = 1. Damn kinda genius||

[frosty thicket]

like $x = \frac{1}{1+\frac{1}{1+\frac{1}{1+ \text{...}}}}$

[wraith dagger]

biggboy

[frosty thicket]

@crimson sedge can you see how this sequence mentions itself or references itself

[vagrant elbow]

$\phi$

[wraith dagger]

NEONPerseus

[frosty thicket]

(true!)

[vagrant elbow]

ew how do I get the sexy phi

[frosty thicket]

curvy one?

[vagrant elbow]

$\varphi$

I think

[wraith dagger]

NEONPerseus

[vagrant elbow]

yeah

[frosty thicket]

yeh

[vagrant elbow]

this is what I write irl xD

[frosty thicket]

very cool

[vagrant elbow]

$\pi \varpi$

[wraith dagger]

NEONPerseus

[vagrant elbow]

-.-

I should stop fooling around

[frosty thicket]

yeah

[frosty thicket]

interesting though

[vagrant elbow]

It's used in astronomy as far as I know

[frosty thicket]

that's what they said

[tame wraith]

What i said?

As in i did say that

[frosty thicket]

yeah

[crimson sedge]

The example above your message ? Its unrelated to the picture i sent though right ?

[frosty thicket]

somewhat related

they both contain self referencing sequences which is crucial to solving your problem

but one is nested fractions other one is nested roots

still the idea carries over

[crimson sedge]

Hmm

Do you have to rewrite the roots here ?

As exponents

[frosty thicket]

if you get this explanation though no need to ponder with mine I guess :D

not really

radical symbol is fine

[crimson sedge]

I dont really get it to be honest

But i have a feeling that this perhsps wont be part of my exam if its a fucked up wuestion? xd

[frosty thicket]

not a fucked up question

pretty valid one

[crimson sedge]

Thanks!

.close

[cedar kiln]

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[cold briar]

2x + 3y ? 8
im trying to show working for finding an equation from a graph and i haven't shown the working for deciding if it is < or >, what mathematical symbol should i replace the " ? " with in my working

[unborn sonnet]

cann you show

the

work

[cold briar]

No

Anyways..

.close

[cedar kiln]

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[cold briar]

Nvm

Srry

Gtg

[unborn sonnet]

https://www.youtube.com/channel/UCfXqObiiBoOHzj2vZMZbwWA

subscribe plss

[cold briar]

No

Jk, maybe later

[unborn sonnet]

ok:).

np

bye bye

[cedar kiln]

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[red pumice]

okay for the second part of the question

[red pumice]

i wrote $\min(f,g) \bigcap f \setminus {s \in S: f(s) = g(s)}$

[wraith dagger]

heavy

[red pumice]

which is then in fancy A

the answer has a different (easier) way

but im mostly wondering about the notation

is this notation correct?

.close

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[wispy marten]

No

[cedar kiln]

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[crimson sedge]

ive been needing help with this

[livid hound]

how are you getting 300

[crimson sedge]

apparently that is the right answer

because it is in terms of pi

[livid hound]

who's saying its 300pi

[crimson sedge]

the school i go to

well i geuss im not ment to multipky by pi

[livid hound]

have you attempted this yourself?

[crimson sedge]

because its already there

yes

[livid hound]

can you show your work

[crimson sedge]

umm

it was in my head?

i know the area is pi rsqrt

r squared

sqaure root of 144 is 12

so um

12 i thought was the radius

lthen i did normal triangle are formula

got 60/2

[livid hound]

pi rsqrt
pi r squared
better denoted as pi * r^2 in plain text

[crimson sedge]

ok sorry

[livid hound]

12 i thought was the radius
the radius of the base will be 12(m), yes

lthen i did normal triangle are formula
got 60/2
wdym

[crimson sedge]

welll for normal triangle multiplaction

its 12*5

[livid hound]

why are you calculating the area of a triangle with height 5 and base 12

[crimson sedge]

which equals 60

because i dont know the area of a cone?

[livid hound]

you mean 60?, but why are you doing such a calculation

[crimson sedge]

this is kind of new to me

[livid hound]

were you just trying random things?

there's a formula for calculating the (surface) area

[crimson sedge]

no but a cone resembles a triangle

so i thought

its was a failed theory

[livid hound]

yeh, that's not going to work here.

there are formula for things like these

[crimson sedge]

aight tell me please

[livid hound]

perhaps you should first look up on surface area of a cone,
or actually lateral/curved area of a cone would be more helpful

and state any parts (if any) that you don't understand

[crimson sedge]

curved?

what curved part