#help-10
1 messages · Page 479 of 1
ok
what's the weight of (the graded part)?
and the other two assignments arent in the grade book but their 100s
,calc (100 * 25 + 100 * 10)/(25+10+25)
Result:
58.333333333333
aint no way boyah
,calc (100 * 25 + 100 * 10 + 60 * 35 * 2)/(25+10+25+35+35)
Result:
59.230769230769
is my current grade in that result?
this is with the 2 sixties you mentioned.
my current grade
?????
ight look
are there some assignments you're not mentioning?
The unit 4 exam i got a 64 on but its not in the grade book yet
and the war of 1812 assignment i got a 100 but its not in yet
....
boy this sure is a fucking lot
Ill give you a hug
no
have you tried just doing the assignment so you don't get a 65
sounds like a you problem
What does that have to do with the math tho
let's see here, hold on
I dont have the equipment
ok no nvm
what's going on here
turns out i do not have the energy to trudge through this much bureaucracy after all
or decipher what's meant by what
bring shit up bring shit down who gives a fuck
what does "i don't have the equipment" mean
no pen probably
I do not have the nesaccary items to complete my task
seems like "i don't want to do it :("
Seems like your not helpful
lmfaoo
and when is it due
in 3 hours
then go out and buy some
everythings closed
definitely a you problem, sounds like you had ages to do it
seems you should've thought about this assignment before 4 am lmao
And we should put more effort in than you are because?
you know, most channels here take more than 3 hours to resolve
just do the assignment and don't waste your time with this channel
do .close
Or on fortnite
"i neglected an assignment until it was too late and now i want to know if i'm passing if i don't turn it in, do it for me while i play fortnite or you're useless"
what grade are you in?
i think he left lmao
lol
this is not real life, you can't beat me up and make me do your homework haha!
@cosmic kiln Has your question been resolved?
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hi how would i start this question? i’m very confused
apply properties of parallel lines
shouldn’t i combine like terms first or no?
you'd first need to apply the appropriate property to set up an equation
before you can proceed
since it’s parallel wouldn’t it be the same as the left side?
wouldn't what be the same as the left side
the left side is the same to right side? so 7x would be on the top right and 2x+16 on the bottom right too bc they’re parallel or am i wrong
you are wrong
let me look at my notes
i couldn’t find any notes of properties of parallel lines could 9x + 36 = 180 be it bc that’s all i could find in my notes
yes
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i need help with e
Ummm i actually have
i dont remember it too well tho😓
is that why im having trouble with e,
i see thanks
ill do that
oh and can you lmk if i got d correct as well too?
this is what i got
i found the second derivative (i hope i did it correct) and got acceleration
oh i see
so i should be good then
thank u!
i just hope i did the derivatives right lmaoo but i think i did
thank u again for ur help @severe marsh
gotcha!
hmm thats odd
You can use some shortcuts to obtain derivatives
i got -.684 but it doesnt match? Im not sure if i calculated wrong tho..
i see do u know if i did it right? i think the orofessor would prefer if i do it the long way sadly
oh so i just did an extra step
NP bro if your professor can understand it, there is no problem
i think i did all the derivatives right tbh but i couldnt get this to match
i prob could’ve done an easier way tho
i have a -2+cos(t)/(t+3)^2 in there
yep
i distributed the - but yep
wait
t+3^2
i have a (t+3)^2 there too
oh ok
and then i found the derivative of that again
yeah i see it
so that means it worked then?
sorry i never checked this before, this is pretty new
ahh ok gotcha
I tried checking it but it doesnt match. So im not sure what im doing wrong
i mean i tried checking if s’(t)= those things
i get this
no i dont get it
it doesnt match
i replace t=.1 and i do s’(.1)=sin(.1) - (2-cos(.1))/(.1+3)
and i get -.2243
.2243
Okay!
the middle one is my answer
oh wait whaa😲
YESSS
it worked
Im a huge one😭
should i check the other one or am i good
season 2 you mean? Yeah’n
!!*

HAHAHA
@severe marsh
ahh ur prob busy but tysm!!!
oh how so
so type this in calculator,
oh so im nit suppose to use the calculator? i was gonna just match it again
not
im kinda confused how to check for acceleration then @severe marsh should i not use thus
its at the bottom
@severe marsh so how would i do it then?
no no
all the way at the bottom
i mean this
yeah my bad that was the substitution
yeahh
i think i’ll just leave it like that then, i think its correct (i hope)
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@timid silo go ask a calculator
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By what sort of theorem or statement could I justify $\sum_{n=1}^{\infty}a_n=\sum_{n=1}^{\infty}a_{2n}+\sum_{n=1}^{\infty}a_{2n-1}$. Given that $\sum_{n=1}^{\infty}a_n$ converges.
glomswamp
Would it just be the algebra of infinite series?
@hasty harbor Has your question been resolved?
@hasty harbor you couldnt because this isnt always true
take the series 1 - 1 + 1/2 - 1/2 + 1/3 - 1/3 + 1/4 - 1/4 + ...
taking just the even or just the odd terms yields the harmonic series
i think it might work if you require that the original series (\sum a_n) be absolutely convergent, in which case the two series you're trying to split it into will be absolutely convergent as well
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could I get help with how they got force 3 and 4
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Need urgent help
My mind is blanking on how to do this
How would I go about solving
<@&286206848099549185>
f(x+h) = (x+h)^2-2(x+h)+9
then use just do simplifications and so on and you should get a very nice answer
you should be able to cancel out the denominator after factoring and applying the limit
Oh okay thank you so much this makes sense
I'm gonna try it rn
Im a little stuck rn
So now that I have this where would I go from here
divide it all by h
afterwards let h = 0, since there’s no division left
remember that this is a limit
After I do all that I get 2x-2
Am I supposed to set that equal to zero and solve for x?
no
OHH
that’s the answer
2x-2 is the answer
yes
lol it’s fine, derivatives aren’t super easy at first
whenever you’re done, don’t forget to do .close
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My problem was about a thousand characters too long for discord x) So here it is as a text file I guess?
Also: Applied Mathematics warning :)
Considering my approach to this, I want to essentially find the function of a "Spherical Bezier-Curve", which connects two points on a geodesic of a sphere respectivel, where both of the geodesics intersect orthogonally, such that the "ends" of the spherical bezier curves are also orthogonal to the geodesic they lie on. This is defined a little vaguely, but I hope you get the picture.
I then want to find a function based on this curve, that calculates the "spherical distance" (not linear distance) i.e. arc-length between a given arbitrary point on the surface of the sphere and a point on the bezier-curve based on t (the interpolation value of the bezier curve) which is contrained between 0 and 1. I then also need to find the derivative of this function...
Wots the application of this problem
Limiting the rotation of a bone transform in an IK Solver.
Is there not an industry standard way to do that?
IK is common enough that I would think so
Apperantly not lol. I have searched far and wide
Most IK solvers either just make it a "normal" cone, which is trivial. Or they get around the problem by letting you define a polygonal-shape. However I want to approach this in an analytical way.
What are a and b there?
a would be the vector down the center of the cone
And b would be your bone direction vector
Well yeah that works for a "regular" cone. What makes it hard is that I want my cone to have different angles for all of the cardinal directions
So like an oval cone?
Sort of. Its hard for me to visualize, but imagine having some forward axis, then you rotate the forward axis in all of the cardinal directions (up, down, left, right) by varying angles. This will give you four points on the surface of the sphere, now you have to connect these 4 points, such that the transition between the curves is smooth, and the curve always lies on the surface of the sphere.
Hmm
Sounds weird
Wait and so what's the purpose of this different type
Over a normal cone
Think of your wrists. They can rotate up, down, left, and right. But they can rotate more up and down, than left an right. And it can rotate more down than up.
You can rotate your wrist approximately 20° to the right 35° to the left, 85° down and 75° up.
So I'd like to incorporate that into my IK Solver...However, that requires solving this problem...
I kinda see what you mean by bezier
You could make a custom form of the dot product trick that has the radius of the cone as a function of the angle from some upper bone vector
You can use the Casteljau-Algorithm to construct a Bezier-Curve using Linear Interpolations. However that only works for affine spaces.
You can however use the same idea in SO-3 using Slerp
I'm not sure it sounds very complex
But it could just be my lack of understanding
I guess Im gonna ping the Helpers?
You might wanna go to a specialized channel for help with linear algebra stuff
But I feel like there's a simpler solution
@bleak dragon Has your question been resolved?
<@&286206848099549185> This is a much more complex problem than I originally anticipated. Would appreciate if I could get some help or at least an idea of how to better approach this :)
@bleak dragon Has your question been resolved?
I mean it wouldnt be that hard to define a cone with a changing radius
Based on a polar function like that or something
Thered be two angles
α, the thing you wanna limit, and the dot product angle of the bone
β, the angle of rotation of the bone around the joint head on based on the upwards direction
For every β there would be a maximum allowable α based on some polar function
Which could change to fit to any shape you want
If that doesnt make sense with the weird isosceles view
Heres a side and head on view of α and β
Hmm I think I understand...However how do you find the spherically closest point on the boundary then?
I would probably just like
mag(bone-origin)
Then uhhh
Well you could construct a vector using α and β I suppose
And use that magnitude
Prob a better way though
Yeah def
So by the definition of being spherically closest itd be perpendicular to the closest edge of the thing
Which has already been calculated using the big alpha angle
Calculated by your polar function
So you could say
$\sin(A - \alpha)=\frac{opp}{||bone node - origin||}$
PapaBread
Then you could do bone-origin cross product with front vector then itself or something
Then multiply that by opp and add it onto bone
And you should get the endpoint closest point
@bleak dragon Has your question been resolved?
I will think about this again tomorrow...
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A circle with radius r has area 505. Compute the area of a circle with diameter 2r.
Is it just times two?
wdym by it
why are you asking this
Area of a circle formula is $A = \pi \cdot r^2$, right?
"with diameter 2r" 
dldh06
formula for area isn't even needed
So it's not just double, it's more like the area is squared
Or something like that
"with diameter 2r"
.close
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no
that's wrong
The question is strange
year specific questions usually have the year in the question rather than the answer
Radius length r = diameter length 2r
Seems like it's the same circle to me
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Its so ez
Since diameter is always double right?
So
The circle will always be the same
As long as the diameter is double the radius
Oh wait
Sorry helpers
Sorry for wasting ur time
Ill close this now
.close
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Closed by @novel flint
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Is this proof of partial order correct ?
@static patio Has your question been resolved?
Why ?
What is missing ?
That's how we do it in school
Computer science
yes, its not course for pure mathematicians
that similiar to what i did
i have found it there
everywhere its different so i am confused
((a,b),(a,b)) would be N^2 x N^2
if i had worked with only with relation on NxN
I would write for all (a,a)
?
i dont know
let it be
we dont do it in this way in school
also some lecture books do not have this kind of notation
Aren't the individual elements just (a,b)
And all elements of the form (ka,kb) where k is a positive integer are in the same equivalence class
Writing for all ((a,b),(a,b)) or for all (a,b) shouldn't matter
$\forall (a,b)\in \mathbb{N}^2$
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could someone please explain to me where the -3 comes from in this?
(a+b)²= a²+2ab+b².
In your case -½x is your a
And 3 is your b
sorry i do not understand
within the distribution of the ^2 how do we get -3?
i understand the rest just not the -3?
can you expand (a+b)^2?
a^2+b^2?
ℝamonov
would this be ab^2
a^2b^2
a^2+2ab+b^2
not quite what I was asking
you jumped ahead and that is the correct expansion
and apply that to what you had in your original question
hold on writing it now
yeah this is long as fuck i am trying to think of a better way to do this than the foil method
remember (a+b)^2 = a^2 +2ab + b^2 and/or binomial theorem
multiplying everything
you have (-1/2 x +3)^2 in the question
NOT (-1/2 + x + 3)^2
so what have i done wrong
you have (-1/2 x +3)^2 in the question
NOT (-1/2 + x + 3)^2
you didn't set up your multiplication table properly
why did you split the -1/2 x like that
because it is ^2
no
that does not explain why you split the -1/2 x
in
-1/2 x + 3
-1/2 x is your first term
and 3 is your second term
thank you for your help this has just blew my mind
@timid silo Has your question been resolved?
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if (2^a)(3^b)=(2^c)(3^d) does this mean that a=c and b=d?
both of em should be natural numbers
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Let $$Q \in \mathbb{R}^{n \times n} $$ be an orthogonal matrix. Then $$ \det{Q} = \pm 1 $$. Now, when Q is a householder matrix $$Q_v$$, then $$ \det{Q_v} = -1 $$. I can't wrap my head around why the determinant of the householder matrix equals -1?
mrbrown
@clear sinew Has your question been resolved?
recall: determinant=product of eigenvalues
and there is very nice properties of thr householder matrix in that regards
that makes me question: What are the eigenvalues of an orthogonal matrix?
if its orthogonal then +-1
i assume you know that
cause of the definition you sent
I know that for householder we have following properties:
(i) Q is symmetric
(ii) Q^2 = I
(iii) Qy = v <=> (y^T)v = 0
(iv) Qv = -v
makes sense. That would mean that all the n Eigenvalues are either 1 or -1
$$ \lambda_1 = \pm 1, \lambda_2 = \pm 1, ..., \lambda_n =\pm 1 $$
mrbrown
another hint
Qu=u if u is orthogonal to v
v is the normal vector to the "mirror-plane" right?
and u is the "Point" i want to mirror
If u is orthogonal to v then the scalar product of v and u is 0.
yes v is the normal vector
and u is a vector orthogonal to v
to which is there is n-1 independent vects of them
Oh wait
Now I understand 💡
A property of Eigenvalues is $$Ax = \lambda x$$ (correct if I say something wrong please.
Now if $$Qu = u \implies \lambda = 1$$
Ok, I just don't know how multiple Eigenvalues apply to the statement $$Ax = \lambda x$$
mrbrown
But if I understood it correctly I have two cases with householder matrices.
If $$Qu = u \implies \lambda = 1$$ and if $$ Qu = -u \implies \lambda = -1 $$
mrbrown
Ok, now I need to figure out the amounts of +1 and -1. You said "to which is there is n-1 independent vects of them"
I can't figure it out 🙈. How do we arrive at the conclusion $$ Qu = u \implies (n-1) independent vecs$$
mrbrown
yet another recall
dimW+dimW^T=n
so alll you have to prove is...
🤯 😅
@clear sinew Has your question been resolved?
After my research, it seems like the span{v} plays a role in this.
I won't be able to solve this with my rusty knowledge about eigenvalues and span.
well the goal is to improve that rusty knowledge
you'll get the hang of it
more hints and it'll just be giving the answer lol
😄
I stumbled across another problem
The householder transformation is given by $$Q = I - 2 \frac{vv^T}{v^Tv} $$
mrbrown
I tried to calculate the determinant for a 2x2 matrix xD
first of all $$ I - 2 \frac{vv^T}{v^Tv} = \begin{pmatrix} 1 & 0 \ 0 & 1 \end{pmatrix} - \frac{2}{v_{1}^{2} + v_{2}^{2}} \begin{pmatrix} v_{1}^{2} & v_1 v_2 \ v_2 v_1 & v_{2}^{2} \end{pmatrix} $$
😵
mrbrown
nice
$$ = \begin{pmatrix} 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} & -\frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \ -\frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 & 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2}\end{pmatrix} $$
mrbrown
$$ \det{Q} = \begin{vmatrix} 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} & -\frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \ -\frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 & 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2}\end{vmatrix} $$
mrbrown
$$ = \left( 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} \right) \left( 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2} \right) - \left( \frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \right)^{2} $$
mrbrown
$$ = 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2} - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} + \left( \frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \right)^{2} - \left( \frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \right)^{2} $$
mrbrown
$$ = 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2} - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} \neq -1 ? $$
mrbrown
oh
I didn't see something
$$ =1 - 2 \left( \frac{v_2^2 + v_1^2}{v_1^2 + v_2^2 } \right) = -1 $$
mrbrown
ok
$$ Q = Q^T $$ this means the eigenvectors of Q are orthogonal to each other
mrbrown
I give up lol
maybe another time, for now I will just memorize it.
wow 5 hours spent on this
thanks for the help, i learnt a little bit but my rusty knowledge wasn't enough 😅
.close
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so the problem is to walk across from AC or ABC
all the lengths are there and u are given to rate of change for the first and second path
the first AC is 2km/h and the second is 4km/h
u wanna see which one is the fastest
and i feel like im missing something
i have layed out each trajectory and stuff and im trying to figure out relationships to make me unstuck the angle
but i can seem to get anywhere
so any clue would be appreciated thanks
the first trajectory is easy but its the ABC one im stuck on
its a calc question (differential only ) and theres no area involved so im quite confused
@ebon cave Has your question been resolved?
@ebon cave Has your question been resolved?
@ebon cave Has your question been resolved?
if i'm getting it correct then you need to check which is faster
going from A to C with 2km/h
or from A to B to C with 4km/h
?
is that right?
there's the theorems you can use @ebon cave
1st is thales
and 2nd is angle to point on circle is 1/2 angle to center of circle
angle at the centre theorem
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Could someone help me check my answer for the area bounded by these 3 lines in the first quadrant, marked by orange? I was wrong 2 previous times. My answer is: 46/21
Yep I also got 46/21
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Thanks! It was correct. 
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for two sets $A$ and $B$, is it sufficient to say that they cannot be put have a one to one correspondence if $|A| \neq |B|$?
Xetrov
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Hello! i need help, I have 2 functions, and questions asking (f+g)(x). what does this answer mean in relation to the two functions? (f-g)(x). why does it matter which order we subtract the functions?(fg)(x)Does it matter which order we multiply in?
(f+g)(x)=f(x)+g(x), (f-g)(x)=f(x)-g(x) and (fg)(x)=f(x)g(x)
^^^^^
why does it matter which order we subtract the functions
because subtraction isn't commutative in general.
what about multiplication?
multiplication is commutative, so fg=gf
so it does not matter
Nope.
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Can someone tell me how to solve question 1 and 2? (I just need hints)
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No
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The height of a projectile can be described by the Vertical Motion Model: h = -16t2 + vt + s, where t is
the time (in seconds) the object has been in the air, v is the initial vertical velocity (in feet per second)
and s is the initial height (in feet). To catch a Frisbee, a dog leaps into the air with an initial velocity of 23
feet per second.
Write a model for the height of the dog above the ground.
what is a model?
do they mean -16^t2+23t
I'm assuming s is 0?
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How would I approach solving this
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@lost bay Has your question been resolved?
No motherfucker it has not been solved
Why ask if you can clearly see there’s no response - stupid bot
How do you know - what indicates it’s a derivative
I had the same question but I figured it may be assuming that you solved it on your own, or found help somewhere else, even on in this server in another channel
ahhh I see
@lost bay Has your question been resolved?
a) is verify the formula given for the partial derivatives - wdym how did I know its a derivative?
Haven't learnt partial derivatives - I meant how did you recognise they were derivatives
Quite new to calculus
$\partial…$ means the partial derivative
Is it just partial derivatives you're seeing here? Is there anything else you think I should know - I'm almost looking at a blank slate
My lawd - My brain doesn't work at all
But still - haven't worked with them before - I've clearly got some work to do
ScapeProf
quite new to calculus
Doin multivar calc 
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What is your question exactly?
x is the angle here? You have a right triangle, the length of the hypothenus and the length of the opposite side to your angle, can you think of any ways to use this data to your advantage?
3/4
Shift>tan>3/4=36.869

Noice
I don't believe I fall to this mistake 😭😭
=48.59
It happens 🙂
Yeah 🫂💔
Right?

Yes 🙂
Nw!
- btw, this question is not about math, but did I make any mistake in grammar/spelling?
I'm trying to improve my English skills, If I made any mistake pls let me know about it 
No everything seemed good
Noice, thanks again for help

❤️
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I'm stuck on what to do
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not sure if you solved this problem bc you closed the channel but you can do 10 choose 3 on a calculator
lemme get the formula real quick
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how is
$d ((dy / dx) × (dy /dx))/dx$
equal to
$(d(dy / dx) / dθ) x (dθ / dx)$
basically how did we arrive step 2 from step 1
i get that they differentiated but it doesn't check out
This is just what the chain rule generally is for any function f
Your problem applies this to f=dy/dx
thats not the problem i had i think you're explaining the wrong statement
i am talking about the second statement
You are trying to see how you go from step 1 to step 2 right
Well i am telling you how,
So d^2y/dx^2 is the same as d/dx(dy/dx) right
And then use the chain rule, which says you differentiate theta with x first and then this with theta
dy / dx = dy / dθ × dθ / dx right?
Yeah
then you differentiate that
and you somehow get this
Replace y with dy/dx
replace y with what
i dont get it how can you replace a variable with its derivative
So this
Is not only true for y
But for any function right
So instead of y if it were the function dy/dx it would still be true yeah
rught
oooo
i kinda get it now
so those dθ's in the second step are just remains from thr first step
okay I get it
Nice
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does 0.9 recurring really equal 1 tho
i mean sure 0.3 recurring is equal to 1/3
and 1/3 x 3 is 3/3
which is 0.3 recurring x3
which is 0.9 recurring
but is 0.9 recurring actually 1
its infinetly close to one but its just not enough to be one
yes
for any two real numbers, if they are distinct, you can find a real number between them
think about how you would define 0.9 recurring
right but like 0.9 recurring could never actually equal 1 tho right
the question is how you would define 0.9 recurring
oh frik
3 duh
such hard
ggs lets goo
please don't troll lol
ok anyway
wdym define tho
if its not 1 its not 1
alright, what does 3.1415926... mean?
its lower than one
pi
but it's not pi yet
at every step when we keep adding digits, it's not pi yet
0.9 recurring will still never be 1 even if continue long time
yes
like 0.9 will never be 1
but how can you be so sure 3.1415926... is pi
ask vsauce
you continue a long time and you still have finitely many digits
it's still not pi
true
so, pi is simply the limit of the sequence
3, 3.1, 3.14, 3.141, 3.1415, 3.14159, ...
none of the individual terms are pi
likewise for
0.9, 0.99, 0.999, 0.9999, .... none of the individual terms are 1
but the limit is
the question is "what is an infinite decimal"
and if you look at pi, it has an neverending decimal representation
also how many other people has asked this question here
lmao
it is confusing when people first encounter the concept of numbers with more than one decimal representation
alright, you got the 3.14159... is pi bit, right?
yes
and you understand no matter how many digits we present, it's not pi
yes
likewise for 0.99999...
yes'
no matter how many digits we present, it's still not 1
yes
but when you go to infinitely many digits, we define it as the limit of the sequence
ok
so how we define 0.99999... is just the limit of
0.9, 0.99, 0.999, ...
do you know how limits are defined, epsilon-N?
there's a pretty formal definition of limits that would help deal with this problem
essentially it's like a game
Alice will say a particular epsilon, say "0.00001"
ok
then Bob will try to find some N such that after the Nth term, all the values do not differ from 1 by more than epsilon
if Bob can win no matter what positive epsilon says, then the limit is 1
yes
Alice will select a small horizontal band around the limit, 1
and Bob will have to say how far right you have to go such that the points plotted will never leave the band from that point onwards
im very confused still
IF
no matter what small horizontal band Alice chooses
Bob can go far enough to stay within that band
THEN
the sequence has a limit
I think 9?
but for different countries it might not map on that cleanly
I learnt it in university lol
what year
probably first year
wait
so element you learnt in grade 9 middle school
it was so confusing
or
is it still confusing
yeah I only could find limit of a function on KA
not anymore thankfully. I accepted that mathematics is, let's say somewhat flexible. I used to believe that maths is... stiff.
found it
Math is just the rigourous language we use to explain ideas
I think Element118 explained it very nicely. That's the explanation that clicked with me.
somewhat flexible
hm
indeed 😄
im still have no idea what he was talking about
wait borio
let's look at the function f(x) = e^(-x) for example
looks like this when plotted with geogebra
now what would your guess be if we go further to the right?
sorry
i obviously havent learnt any of this
what does the graph seem to approach as it goes to the right
our school has a really bad math system
smaller
towards 0, yeah?
yes
👍 🙂
I think yes lol
oke
but the point is now, let's say you have me as someone who wants to oppose you
yes
so, I am claiming "no, Borio, the graph will jump and rise again if we go far another to the right"
enough*
ok
we arrive at Element118 explanation:
wait
i'll rephrase my words
"the graph will never go below 0.1"
ok
idk
$$ f(x) = e^{-x} $$
mrbrown
let's make it easier
i know that much
you can plug in values x and it gives you a value f(x)
yes
is e^(-x) the confusing part?
hmm
lol
😅
okokokok
anyway thank you
😄
very much
thank you too
i think it will work out 🙂
haha
do you at all remember what you learnt in grade 8 middle school
it is a good thing to realize something like that, I used to believe i was the pinnacle lol and unviersity killed me 😂
i don't remember exactly. I knew about functions and somoe geometry
hmm maybe you can look at khanacademy
i could
no, it is actually doable imo, but need to discplined and definitely visit the counselling hours and ask quesitons, no matter how the lecturers react. Just ask ask ask. That was the best advice a friend of mine gave me. I improved siginificantly by asking about stuff i didn't understand.
but i should sleep lmao
they are a pretty good starter sits and you can learn stuff from it
yeah


