#help-10

1 messages · Page 479 of 1

cosmic kiln
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so if i dont do it i wanna know how far my grades gonna do down

royal basin
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ok

junior inlet
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what's the weight of (the graded part)?

cosmic kiln
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and the other two assignments arent in the grade book but their 100s

royal basin
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,calc (100 * 25 + 100 * 10)/(25+10+25)

warm shaleBOT
#

Result:

58.333333333333
cosmic kiln
#

aint no way boyah

royal basin
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,calc (100 * 25 + 100 * 10 + 60 * 35 * 2)/(25+10+25+35+35)

warm shaleBOT
#

Result:

59.230769230769
cosmic kiln
#

is my current grade in that result?

royal basin
#

this is with the 2 sixties you mentioned.

cosmic kiln
#

would i divide that by 64

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and My final grade would be a 65?

royal basin
#

??

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where are you getting 64 from?

cosmic kiln
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my current grade

royal basin
#

?????

cosmic kiln
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ight look

royal basin
#

are there some assignments you're not mentioning?

cosmic kiln
#

The unit 4 exam i got a 64 on but its not in the grade book yet

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and the war of 1812 assignment i got a 100 but its not in yet

royal basin
#

....

cosmic kiln
#

same thing with this assignment

royal basin
#

boy this sure is a fucking lot

cosmic kiln
#

Ill give you a hug

royal basin
#

no

short spruce
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have you tried just doing the assignment so you don't get a 65

cosmic kiln
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I dont have the equipment

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and its 4am

short spruce
#

sounds like a you problem

cosmic kiln
#

What does that have to do with the math tho

royal basin
#

let's see here, hold on

short spruce
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well let's do some simple math right

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do assignment? better grade!

cosmic kiln
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I dont have the equipment

royal basin
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ok no nvm

strong vale
#

what's going on here

royal basin
#

turns out i do not have the energy to trudge through this much bureaucracy after all

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or decipher what's meant by what

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bring shit up bring shit down who gives a fuck

short spruce
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what does "i don't have the equipment" mean

strong vale
#

no pen probably

cosmic kiln
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I do not have the nesaccary items to complete my task

short spruce
#

seems like "i don't want to do it :("

cosmic kiln
#

Seems like your not helpful

glossy yacht
#

Stop playing fortnite and do the bloody work

short spruce
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lmfaoo

cosmic kiln
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No glue

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or tape

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or scissors

short spruce
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and when is it due

cosmic kiln
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in 3 hours

glossy yacht
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then go out and buy some

cosmic kiln
#

everythings closed

glossy yacht
#

definitely a you problem, sounds like you had ages to do it

short spruce
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seems you should've thought about this assignment before 4 am lmao

cosmic kiln
#

Damn yall are useless

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stick to math

glossy yacht
#

And we should put more effort in than you are because?

junior inlet
# cosmic kiln in 3 hours

you know, most channels here take more than 3 hours to resolve

just do the assignment and don't waste your time with this channel

#

do .close

glossy yacht
#

Or on fortnite

short spruce
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"i neglected an assignment until it was too late and now i want to know if i'm passing if i don't turn it in, do it for me while i play fortnite or you're useless"

strong vale
short spruce
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i think he left lmao

glossy yacht
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.close

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sad that not everyone can close

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but makes sense

strong vale
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lol

strong vale
obtuse pebbleBOT
#

@cosmic kiln Has your question been resolved?

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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remote arrow
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hi how would i start this question? i’m very confused

remote arrow
high lily
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apply properties of parallel lines

remote arrow
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shouldn’t i combine like terms first or no?

high lily
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you'd first need to apply the appropriate property to set up an equation

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before you can proceed

remote arrow
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since it’s parallel wouldn’t it be the same as the left side?

high lily
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wouldn't what be the same as the left side

remote arrow
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the left side is the same to right side? so 7x would be on the top right and 2x+16 on the bottom right too bc they’re parallel or am i wrong

high lily
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you are wrong

remote arrow
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let me look at my notes

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i couldn’t find any notes of properties of parallel lines could 9x + 36 = 180 be it bc that’s all i could find in my notes

high lily
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9x + 36 = 180
yes

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that's what you get that from applying properties of parallel lines

remote arrow
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oh ox let me see what i get

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I got 16 from that is that right?

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x = 16

high lily
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yes

remote arrow
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ok thanks 😊

#

.close

obtuse pebbleBOT
#
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dusty fjord
obtuse pebbleBOT
dusty fjord
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i need help with e

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Ummm i actually have

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i dont remember it too well tho😓

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is that why im having trouble with e,

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i see thanks

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ill do that

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oh and can you lmk if i got d correct as well too?

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this is what i got

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i found the second derivative (i hope i did it correct) and got acceleration

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oh i see

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so i should be good then

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thank u!

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i just hope i did the derivatives right lmaoo but i think i did

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thank u again for ur help @severe marsh

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gotcha!

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hmm thats odd

rough stratus
dusty fjord
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i got -.684 but it doesnt match? Im not sure if i calculated wrong tho..

rough stratus
dusty fjord
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oh so i just did an extra step

rough stratus
#

The product rule in case you didn't know

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P.S I can't understand your handwriting

dusty fjord
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i did product rule but with (t+3)(sin(t))

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ah sorry🥲

rough stratus
dusty fjord
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i think i did all the derivatives right tbh but i couldnt get this to match

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i prob could’ve done an easier way tho

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i have a -2+cos(t)/(t+3)^2 in there

warm shaleBOT
dusty fjord
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yep

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i distributed the - but yep

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wait

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t+3^2

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i have a (t+3)^2 there too

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oh ok

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and then i found the derivative of that again

warm shaleBOT
dusty fjord
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yeah i see it

dusty fjord
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sorry i never checked this before, this is pretty new

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ahh ok gotcha

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I tried checking it but it doesnt match. So im not sure what im doing wrong

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i mean i tried checking if s’(t)= those things

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i get this

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no i dont get it

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it doesnt match

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i replace t=.1 and i do s’(.1)=sin(.1) - (2-cos(.1))/(.1+3)

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and i get -.2243

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.2243

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Okay!

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the middle one is my answer

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oh wait whaa😲

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YESSS

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it worked

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Im a huge one😭

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should i check the other one or am i good

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season 2 you mean? Yeah’n

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!!*

unique solstice
dusty fjord
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HAHAHA

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@severe marsh

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ahh ur prob busy but tysm!!!

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oh how so

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so type this in calculator,

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oh so im nit suppose to use the calculator? i was gonna just match it again

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not

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im kinda confused how to check for acceleration then @severe marsh should i not use thus

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its at the bottom

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@severe marsh so how would i do it then?

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no no

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all the way at the bottom

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i mean this

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yeah my bad that was the substitution

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yeahh

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i think i’ll just leave it like that then, i think its correct (i hope)

dusty fjord
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LMAO

dusty fjord
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thats t

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I see

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alright thank you!!

#

.close

obtuse pebbleBOT
#
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royal basin
#

@timid silo go ask a calculator

upbeat plinth
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@timid silo pls dont troll

#

.close

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hasty harbor
#

By what sort of theorem or statement could I justify $\sum_{n=1}^{\infty}a_n=\sum_{n=1}^{\infty}a_{2n}+\sum_{n=1}^{\infty}a_{2n-1}$. Given that $\sum_{n=1}^{\infty}a_n$ converges.

warm shaleBOT
#

glomswamp

hasty harbor
#

Would it just be the algebra of infinite series?

obtuse pebbleBOT
#

@hasty harbor Has your question been resolved?

royal basin
#

@hasty harbor you couldnt because this isnt always true

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take the series 1 - 1 + 1/2 - 1/2 + 1/3 - 1/3 + 1/4 - 1/4 + ...

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taking just the even or just the odd terms yields the harmonic series

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i think it might work if you require that the original series (\sum a_n) be absolutely convergent, in which case the two series you're trying to split it into will be absolutely convergent as well

obtuse pebbleBOT
#

@hasty harbor Has your question been resolved?

obtuse pebbleBOT
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woven shoal
#

could I get help with how they got force 3 and 4

woven shoal
#

<@&286206848099549185>

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nvm i think i got it

obtuse pebbleBOT
#

@woven shoal Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

Need urgent help

obtuse pebbleBOT
timid silo
#

My mind is blanking on how to do this

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How would I go about solving

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<@&286206848099549185>

timid silo
#

then use just do simplifications and so on and you should get a very nice answer

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you should be able to cancel out the denominator after factoring and applying the limit

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Oh okay thank you so much this makes sense

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I'm gonna try it rn

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Im a little stuck rn

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So now that I have this where would I go from here

mild ocean
#

divide it all by h

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afterwards let h = 0, since there’s no division left

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remember that this is a limit

timid silo
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After I do all that I get 2x-2

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Am I supposed to set that equal to zero and solve for x?

mild ocean
#

no

timid silo
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OHH

mild ocean
#

that’s the answer

timid silo
#

2x-2 is the answer

mild ocean
#

yes

timid silo
#

Damn I've been dancing around that for the past 10 minutes

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Thank you so much

mild ocean
#

lol it’s fine, derivatives aren’t super easy at first

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whenever you’re done, don’t forget to do .close

timid silo
#

Thanks quantum glad tidings

#

.close

obtuse pebbleBOT
#
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bleak dragon
#

My problem was about a thousand characters too long for discord x) So here it is as a text file I guess?
Also: Applied Mathematics warning :)

bleak dragon
#

Considering my approach to this, I want to essentially find the function of a "Spherical Bezier-Curve", which connects two points on a geodesic of a sphere respectivel, where both of the geodesics intersect orthogonally, such that the "ends" of the spherical bezier curves are also orthogonal to the geodesic they lie on. This is defined a little vaguely, but I hope you get the picture.

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I then want to find a function based on this curve, that calculates the "spherical distance" (not linear distance) i.e. arc-length between a given arbitrary point on the surface of the sphere and a point on the bezier-curve based on t (the interpolation value of the bezier curve) which is contrained between 0 and 1. I then also need to find the derivative of this function...

unique solstice
#

Wots the application of this problem

bleak dragon
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Limiting the rotation of a bone transform in an IK Solver.

unique solstice
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Is there not an industry standard way to do that?

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IK is common enough that I would think so

bleak dragon
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Apperantly not lol. I have searched far and wide

unique solstice
#

I mean it reminds me of just like

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arccos(a dot b) < angle

bleak dragon
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Most IK solvers either just make it a "normal" cone, which is trivial. Or they get around the problem by letting you define a polygonal-shape. However I want to approach this in an analytical way.

bleak dragon
unique solstice
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a would be the vector down the center of the cone

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And b would be your bone direction vector

bleak dragon
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Well yeah that works for a "regular" cone. What makes it hard is that I want my cone to have different angles for all of the cardinal directions

unique solstice
#

So like an oval cone?

bleak dragon
#

Sort of. Its hard for me to visualize, but imagine having some forward axis, then you rotate the forward axis in all of the cardinal directions (up, down, left, right) by varying angles. This will give you four points on the surface of the sphere, now you have to connect these 4 points, such that the transition between the curves is smooth, and the curve always lies on the surface of the sphere.

unique solstice
#

Hmm

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Sounds weird

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Wait and so what's the purpose of this different type

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Over a normal cone

bleak dragon
#

Think of your wrists. They can rotate up, down, left, and right. But they can rotate more up and down, than left an right. And it can rotate more down than up.
You can rotate your wrist approximately 20° to the right 35° to the left, 85° down and 75° up.

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So I'd like to incorporate that into my IK Solver...However, that requires solving this problem...

unique solstice
#

I kinda see what you mean by bezier

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You could make a custom form of the dot product trick that has the radius of the cone as a function of the angle from some upper bone vector

bleak dragon
#

You can use the Casteljau-Algorithm to construct a Bezier-Curve using Linear Interpolations. However that only works for affine spaces.
You can however use the same idea in SO-3 using Slerp

unique solstice
#

I'm not sure it sounds very complex

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But it could just be my lack of understanding

bleak dragon
#

I guess Im gonna ping the Helpers?

unique solstice
#

You might wanna go to a specialized channel for help with linear algebra stuff

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But I feel like there's a simpler solution

obtuse pebbleBOT
#

@bleak dragon Has your question been resolved?

bleak dragon
#

<@&286206848099549185> This is a much more complex problem than I originally anticipated. Would appreciate if I could get some help or at least an idea of how to better approach this :)

obtuse pebbleBOT
#

@bleak dragon Has your question been resolved?

unique solstice
#

I mean it wouldnt be that hard to define a cone with a changing radius

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Based on a polar function like that or something

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Thered be two angles

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α, the thing you wanna limit, and the dot product angle of the bone

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β, the angle of rotation of the bone around the joint head on based on the upwards direction

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For every β there would be a maximum allowable α based on some polar function

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Which could change to fit to any shape you want

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If that doesnt make sense with the weird isosceles view

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Heres a side and head on view of α and β

bleak dragon
#

Hmm I think I understand...However how do you find the spherically closest point on the boundary then?

unique solstice
#

I would probably just like

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mag(bone-origin)

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Then uhhh

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Well you could construct a vector using α and β I suppose

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And use that magnitude

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Prob a better way though

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Yeah def

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So by the definition of being spherically closest itd be perpendicular to the closest edge of the thing

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Which has already been calculated using the big alpha angle

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Calculated by your polar function

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So you could say

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$\sin(A - \alpha)=\frac{opp}{||bone node - origin||}$

warm shaleBOT
#

PapaBread

unique solstice
#

Then you could do bone-origin cross product with front vector then itself or something

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Then multiply that by opp and add it onto bone

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And you should get the endpoint closest point

obtuse pebbleBOT
#

@bleak dragon Has your question been resolved?

bleak dragon
#

I will think about this again tomorrow...

obtuse pebbleBOT
#
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tired shell
#

A circle with radius r has area 505. Compute the area of a circle with diameter 2r.

tired shell
#

Is it just times two?

forest sinew
#

plumorant

high lily
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wdym by it

forest sinew
#

why are you asking this

nocturne minnow
soft sail
#

"with diameter 2r" catGiggle

warm shaleBOT
#

dldh06

high lily
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formula for area isn't even needed

nocturne minnow
#

So it's not just double, it's more like the area is squared

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Or something like that

tired shell
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505*4=2020

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oh that makes sense since this is a 2020 question, thanks!

high lily
#

"with diameter 2r"

tired shell
#

.close

obtuse pebbleBOT
#
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mild ocean
high lily
#

no

soft sail
#

that's wrong

forest sinew
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lol

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you dont need any formulas

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well maybe the formula for diameter

thorny dome
#

The question is strange

high lily
#

year specific questions usually have the year in the question rather than the answer

thorny dome
#

Seems like it's the same circle to me

obtuse pebbleBOT
#
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obtuse pebbleBOT
fickle swan
#

Since diameter is always double right?

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So

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The circle will always be the same

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As long as the diameter is double the radius

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Oh wait

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Sorry helpers

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Sorry for wasting ur time

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Ill close this now

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.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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novel flint
obtuse pebbleBOT
novel flint
#

it is showing up as wrong

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waitnvm

#

.close

obtuse pebbleBOT
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static patio
obtuse pebbleBOT
static patio
#

Is this proof of partial order correct ?

warm shaleBOT
obtuse pebbleBOT
#

@static patio Has your question been resolved?

static patio
#

i picked number 1

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is a k from Z

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ups, k is from N

warm shaleBOT
static patio
#

,rotate

warm shaleBOT
static patio
#

Why ?

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What is missing ?

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That's how we do it in school

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Computer science

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yes, its not course for pure mathematicians

warm shaleBOT
static patio
#

that similiar to what i did

warm shaleBOT
static patio
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i have found it there

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everywhere its different so i am confused

warm shaleBOT
static patio
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but its reflexivity and we want only one element

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like aRa

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(a,b)R(a,b)

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i know

warm shaleBOT
static patio
#

((a,b),(a,b)) would be N^2 x N^2

warm shaleBOT
static patio
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if i had worked with only with relation on NxN

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I would write for all (a,a)

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?

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i dont know

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let it be

warm shaleBOT
static patio
#

we dont do it in this way in school

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also some lecture books do not have this kind of notation

warm shaleBOT
static patio
#

be we want only one same element

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we dont do it like this in school

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let it be

plain owl
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Aren't the individual elements just (a,b)

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And all elements of the form (ka,kb) where k is a positive integer are in the same equivalence class

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Writing for all ((a,b),(a,b)) or for all (a,b) shouldn't matter

static patio
#

i dont really now

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everywhere is different notation, Im confused

warm shaleBOT
static patio
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i will do it somehow

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...

plain owl
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$\forall (a,b)\in \mathbb{N}^2$

warm shaleBOT
#

Euclid31415

static patio
#

ok

#

.close

obtuse pebbleBOT
#
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timid silo
#

could someone please explain to me where the -3 comes from in this?

elder oasis
#

(a+b)²= a²+2ab+b².
In your case -½x is your a
And 3 is your b

timid silo
#

sorry i do not understand

#

within the distribution of the ^2 how do we get -3?

#

i understand the rest just not the -3?

high lily
#

can you expand (a+b)^2?

timid silo
#

a^2+b^2?

high lily
#

no

#

that is not the correct expansion

#

$(1+1)^2 \neq 1+1$

warm shaleBOT
#

ℝamonov

timid silo
high lily
#

no

#

do you know what it means to square something

timid silo
#

yeah

#
  • by itself
high lily
#

yes

#

apply that to (a+b)^2

timid silo
#

a^2b^2

high lily
#

no

#

what do you immediately get when applying the definition of squaring to (a+b)^2

timid silo
#

a^2+2ab+b^2

high lily
#

not quite what I was asking
you jumped ahead and that is the correct expansion

#

and apply that to what you had in your original question

timid silo
#

hold on writing it now

elder oasis
timid silo
#

yeah this is long as fuck i am trying to think of a better way to do this than the foil method

high lily
#

remember (a+b)^2 = a^2 +2ab + b^2 and/or binomial theorem

timid silo
high lily
#

whut

#

are you doing

timid silo
#

multiplying everything

high lily
#

you have (-1/2 x +3)^2 in the question
NOT (-1/2 + x + 3)^2

timid silo
high lily
#

you have (-1/2 x +3)^2 in the question
NOT (-1/2 + x + 3)^2
you didn't set up your multiplication table properly

high lily
#

why did you split the -1/2 x like that

timid silo
#

because it is ^2

high lily
#

no

#

that does not explain why you split the -1/2 x

#

in
-1/2 x + 3
-1/2 x is your first term
and 3 is your second term

timid silo
#

ohhh

#

hold on i will change

#

i forgot the x in -3x

#

but that should be correct

timid silo
obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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obtuse pebbleBOT
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wintry iris
#

if (2^a)(3^b)=(2^c)(3^d) does this mean that a=c and b=d?

wintry iris
#

both of em should be natural numbers

brave bramble
#

Yes! Because prime factorization is unique.

#

As long as a,b,c,d are natural

wintry iris
#

Thank you!

#

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clear sinew
#

Let $$Q \in \mathbb{R}^{n \times n} $$ be an orthogonal matrix. Then $$ \det{Q} = \pm 1 $$. Now, when Q is a householder matrix $$Q_v$$, then $$ \det{Q_v} = -1 $$. I can't wrap my head around why the determinant of the householder matrix equals -1?

warm shaleBOT
#

mrbrown

obtuse pebbleBOT
#

@clear sinew Has your question been resolved?

dawn parrot
#

and there is very nice properties of thr householder matrix in that regards

clear sinew
#

that makes me question: What are the eigenvalues of an orthogonal matrix?

dawn parrot
#

if its orthogonal then +-1

#

i assume you know that

#

cause of the definition you sent

clear sinew
#

I know that for householder we have following properties:
(i) Q is symmetric
(ii) Q^2 = I
(iii) Qy = v <=> (y^T)v = 0
(iv) Qv = -v

clear sinew
#

$$ \lambda_1 = \pm 1, \lambda_2 = \pm 1, ..., \lambda_n =\pm 1 $$

warm shaleBOT
#

mrbrown

dawn parrot
#

right so now you have an issue of who is + and who is -

#

good thing for you

clear sinew
#

yeah! 😄

#

I'd need to figure out if I have an odd or even amount of -1

dawn parrot
#

another hint
Qu=u if u is orthogonal to v

clear sinew
#

v is the normal vector to the "mirror-plane" right?

#

and u is the "Point" i want to mirror

#

If u is orthogonal to v then the scalar product of v and u is 0.

dawn parrot
#

yes v is the normal vector
and u is a vector orthogonal to v

#

to which is there is n-1 independent vects of them

clear sinew
#

Oh wait

#

Now I understand 💡

#

A property of Eigenvalues is $$Ax = \lambda x$$ (correct if I say something wrong please.

#

Now if $$Qu = u \implies \lambda = 1$$

warm shaleBOT
#

mrbrown

#

mrbrown

clear sinew
#

Ok, I just don't know how multiple Eigenvalues apply to the statement $$Ax = \lambda x$$

warm shaleBOT
#

mrbrown

clear sinew
#

But if I understood it correctly I have two cases with householder matrices.

#

If $$Qu = u \implies \lambda = 1$$ and if $$ Qu = -u \implies \lambda = -1 $$

warm shaleBOT
#

mrbrown

clear sinew
#

Ok, now I need to figure out the amounts of +1 and -1. You said "to which is there is n-1 independent vects of them"

#

I can't figure it out 🙈. How do we arrive at the conclusion $$ Qu = u \implies (n-1) independent vecs$$

warm shaleBOT
#

mrbrown

dawn parrot
#

yet another recall
dimW+dimW^T=n
so alll you have to prove is...

clear sinew
#

🤯 😅

obtuse pebbleBOT
#

@clear sinew Has your question been resolved?

clear sinew
#

I won't be able to solve this with my rusty knowledge about eigenvalues and span.

dawn parrot
#

well the goal is to improve that rusty knowledge
you'll get the hang of it
more hints and it'll just be giving the answer lol

clear sinew
#

😄

clear sinew
#

I stumbled across another problem

#

The householder transformation is given by $$Q = I - 2 \frac{vv^T}{v^Tv} $$

warm shaleBOT
#

mrbrown

clear sinew
#

I tried to calculate the determinant for a 2x2 matrix xD

#

first of all $$ I - 2 \frac{vv^T}{v^Tv} = \begin{pmatrix} 1 & 0 \ 0 & 1 \end{pmatrix} - \frac{2}{v_{1}^{2} + v_{2}^{2}} \begin{pmatrix} v_{1}^{2} & v_1 v_2 \ v_2 v_1 & v_{2}^{2} \end{pmatrix} $$

#

😵

warm shaleBOT
#

mrbrown

clear sinew
#

nice

#

$$ = \begin{pmatrix} 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} & -\frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \ -\frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 & 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2}\end{pmatrix} $$

warm shaleBOT
#

mrbrown

clear sinew
#

$$ \det{Q} = \begin{vmatrix} 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} & -\frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \ -\frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 & 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2}\end{vmatrix} $$

warm shaleBOT
#

mrbrown

clear sinew
#

$$ = \left( 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} \right) \left( 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2} \right) - \left( \frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \right)^{2} $$

warm shaleBOT
#

mrbrown

clear sinew
#

$$ = 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2} - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} + \left( \frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \right)^{2} - \left( \frac{2}{v_{1}^{2} + v_{2}^{2}} v_1 v_2 \right)^{2} $$

warm shaleBOT
#

mrbrown

clear sinew
#

$$ = 1 - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{2}^{2} - \frac{2}{v_{1}^{2} + v_{2}^{2}}v_{1}^{2} \neq -1 ? $$

warm shaleBOT
#

mrbrown

clear sinew
#

oh

#

I didn't see something

#

$$ =1 - 2 \left( \frac{v_2^2 + v_1^2}{v_1^2 + v_2^2 } \right) = -1 $$

warm shaleBOT
#

mrbrown

clear sinew
#

ok

clear sinew
#

$$ Q = Q^T $$ this means the eigenvectors of Q are orthogonal to each other

warm shaleBOT
#

mrbrown

clear sinew
#

I give up lol

#

maybe another time, for now I will just memorize it.

#

wow 5 hours spent on this

#

thanks for the help, i learnt a little bit but my rusty knowledge wasn't enough 😅

#

.close

obtuse pebbleBOT
#
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ebon cave
#

.reopen

obtuse pebbleBOT
ebon cave
#

so the problem is to walk across from AC or ABC

#

all the lengths are there and u are given to rate of change for the first and second path

#

the first AC is 2km/h and the second is 4km/h

#

u wanna see which one is the fastest

#

and i feel like im missing something

#

i have layed out each trajectory and stuff and im trying to figure out relationships to make me unstuck the angle

#

but i can seem to get anywhere

#

so any clue would be appreciated thanks

#

the first trajectory is easy but its the ABC one im stuck on

#

its a calc question (differential only ) and theres no area involved so im quite confused

obtuse pebbleBOT
#

@ebon cave Has your question been resolved?

obtuse pebbleBOT
#

@ebon cave Has your question been resolved?

obtuse pebbleBOT
#

@ebon cave Has your question been resolved?

wary vigil
#

if i'm getting it correct then you need to check which is faster

#

going from A to C with 2km/h

#

or from A to B to C with 4km/h

#

?

#

is that right?

#

there's the theorems you can use @ebon cave

#

1st is thales

#

and 2nd is angle to point on circle is 1/2 angle to center of circle

#

angle at the centre theorem

obtuse pebbleBOT
#
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thick torrent
#

Could someone help me check my answer for the area bounded by these 3 lines in the first quadrant, marked by orange? I was wrong 2 previous times. My answer is: 46/21

mild ocean
#

i will try

#

but i can’t guarantee my attempts will be successful

obtuse pebbleBOT
#

@thick torrent Has your question been resolved?

thick torrent
#

Thanks! It was correct. catthumbsup

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glossy yacht
#

for two sets $A$ and $B$, is it sufficient to say that they cannot be put have a one to one correspondence if $|A| \neq |B|$?

warm shaleBOT
#

Xetrov

obtuse pebbleBOT
#

@glossy yacht Has your question been resolved?

obtuse pebbleBOT
#

@glossy yacht Has your question been resolved?

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obtuse pebbleBOT
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wanton leaf
#

Hello! i need help, I have 2 functions, and questions asking (f+g)(x). what does this answer mean in relation to the two functions? (f-g)(x). why does it matter which order we subtract the functions?(fg)(x)Does it matter which order we multiply in?

quaint glen
#

(f+g)(x)=f(x)+g(x), (f-g)(x)=f(x)-g(x) and (fg)(x)=f(x)g(x)

timid silo
#

^^^^^

quaint glen
#

why does it matter which order we subtract the functions
because subtraction isn't commutative in general.

wanton leaf
#

what about multiplication?

quaint glen
#

multiplication is commutative, so fg=gf

wanton leaf
#

so it does not matter

quaint glen
#

Nope.

wanton leaf
#

sweet thank u sm u have no idea how much this helps!

#

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cloud patio
#

Can someone tell me how to solve question 1 and 2? (I just need hints)

obtuse pebbleBOT
#

@cloud patio Has your question been resolved?

obtuse pebbleBOT
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@cloud patio Has your question been resolved?

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cloud patio
#

No

obtuse pebbleBOT
cloud patio
#

.close

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timid silo
#

The height of a projectile can be described by the Vertical Motion Model: h = -16t2 + vt + s, where t is
the time (in seconds) the object has been in the air, v is the initial vertical velocity (in feet per second)
and s is the initial height (in feet). To catch a Frisbee, a dog leaps into the air with an initial velocity of 23
feet per second.

timid silo
#

Write a model for the height of the dog above the ground.

#

what is a model?

#

do they mean -16^t2+23t

#

I'm assuming s is 0?

#

.close

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lost bay
#

How would I approach solving this

obtuse pebbleBOT
#

@lost bay Has your question been resolved?

obtuse pebbleBOT
#

@lost bay Has your question been resolved?

obtuse pebbleBOT
#

@lost bay Has your question been resolved?

lost bay
#

No motherfucker it has not been solved

#

Why ask if you can clearly see there’s no response - stupid bot

novel knoll
#

Language my friend

#

And a) is just computing derivative

lost bay
turbid wolf
obtuse pebbleBOT
#

@lost bay Has your question been resolved?

novel knoll
lost bay
#

Quite new to calculus

novel knoll
#

$\partial…$ means the partial derivative

lost bay
#

Is it just partial derivatives you're seeing here? Is there anything else you think I should know - I'm almost looking at a blank slate

#

My lawd - My brain doesn't work at all

#

But still - haven't worked with them before - I've clearly got some work to do

warm shaleBOT
#

ScapeProf

spiral maple
#

quite new to calculus

Doin multivar calc sully

mild ocean
#

also i just realized this person has two channels open

hot hazel
#

.close

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untold pike
obtuse pebbleBOT
untold pike
#

I tried to solve it and I got 36.869 or something like that

#

Is this right?

daring parcel
#

What is your question exactly?

untold pike
#

What's the value of x?

daring parcel
#

x is the angle here? You have a right triangle, the length of the hypothenus and the length of the opposite side to your angle, can you think of any ways to use this data to your advantage?

untold pike
#

3/4
Shift>tan>3/4=36.869

daring parcel
#

Close

#

It's not tan though

untold pike
#

What?

#

Oppo/adj

#

How it's now tan?

#

Not*

daring parcel
#

That's not adjacent though

#

It's opposite/hypothenus

untold pike
#

Ohhhhhhhhhhhhhhhh

#

Sin

daring parcel
#

Yes!

#

So we have sin(x) = 3/4

#

We now must solve for x

untold pike
#

I don't believe I fall to this mistake 😭😭

untold pike
daring parcel
#

It happens 🙂

untold pike
untold pike
daring parcel
#

Yes 🙂

untold pike
#

Noice

#

Thanks for help Yakitori_give_me_hug Yakitori_heartlove

daring parcel
#

Nw!

untold pike
#
  • btw, this question is not about math, but did I make any mistake in grammar/spelling?
#

I'm trying to improve my English skills, If I made any mistake pls let me know about it oCMz75

daring parcel
#

No everything seemed good

untold pike
#

Noice, thanks again for help Yakitori_give_me_hug Yakitori_heartlove

daring parcel
#

❤️

untold pike
#

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vale bobcat
#

I'm stuck on what to do

obtuse pebbleBOT
vale bobcat
#

.close

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whole delta
#

lemme get the formula real quick

obtuse pebbleBOT
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carmine pewter
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cloud patio
#

how is
$d ((dy / dx) × (dy /dx))/dx$
equal to
$(d(dy / dx) / dθ) x (dθ / dx)$

cloud patio
#

basically how did we arrive step 2 from step 1

#

i get that they differentiated but it doesn't check out

slow wedge
#

Well df/dx= d theta/dx * df/dtheta by the chain rule

#

Apply this to f= dy/dx

cloud patio
#

where is f

#

Im confused

slow wedge
#

Your problem applies this to f=dy/dx

cloud patio
#

thats not the problem i had i think you're explaining the wrong statement

#

i am talking about the second statement

slow wedge
#

You are trying to see how you go from step 1 to step 2 right

cloud patio
#

marked with '2'

#

yeah

slow wedge
#

Well i am telling you how,

#

So d^2y/dx^2 is the same as d/dx(dy/dx) right

#

And then use the chain rule, which says you differentiate theta with x first and then this with theta

cloud patio
#

dy / dx = dy / dθ × dθ / dx right?

slow wedge
#

Yeah

cloud patio
#

then you differentiate that

slow wedge
#

So we arent using product rule or whatever

#

In what you wrote

cloud patio
#

and you somehow get this

slow wedge
#

Replace y with dy/dx

cloud patio
#

replace y with what

#

i dont get it how can you replace a variable with its derivative

slow wedge
#

Is not only true for y

#

But for any function right

cloud patio
#

yeah

#

because dθ cancel out

slow wedge
#

So instead of y if it were the function dy/dx it would still be true yeah

cloud patio
#

rught

slow wedge
#

Right so what does that tell you

#

When you have dy/dx in this guy

cloud patio
#

oooo

#

i kinda get it now

#

so those dθ's in the second step are just remains from thr first step

#

okay I get it

slow wedge
#

Nice

cloud patio
#

thank you

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @cloud patio

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
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worthy dune
#

does 0.9 recurring really equal 1 tho

obtuse pebbleBOT
worthy dune
#

i mean sure 0.3 recurring is equal to 1/3

#

and 1/3 x 3 is 3/3

#

which is 0.3 recurring x3

#

which is 0.9 recurring

#

but is 0.9 recurring actually 1

willow onyx
#

its infinetly close to one but its just not enough to be one

mighty geyser
#

for any two real numbers, if they are distinct, you can find a real number between them

worthy dune
#

hmph

#

screw math

#

math confuse

mighty geyser
#

think about how you would define 0.9 recurring

worthy dune
#

0.9999999999999999

#

e

mighty geyser
#

it's the limit of a sequence

#

0.9, 0.99, 0.999, 0.9999...
yeah?

worthy dune
#

right but like 0.9 recurring could never actually equal 1 tho right

mighty geyser
#

the question is how you would define 0.9 recurring

worthy dune
#

also have 1 more question

#

1+1=

willow onyx
#

oh frik

willow onyx
worthy dune
#

such hard

worthy dune
mighty geyser
#

please don't troll lol

worthy dune
#

ok anyway

worthy dune
willow onyx
#

if its not 1 its not 1

worthy dune
#

doesnt still never equal 1 tho

#

yeah

willow onyx
#

if its 0. something

#

its not one

mighty geyser
#

alright, what does 3.1415926... mean?

willow onyx
#

its lower than one

worthy dune
#

pi

#

but

willow onyx
worthy dune
#

its like infinite

#

so

mighty geyser
#

but it's not pi yet

worthy dune
#

yeah

#

but

mighty geyser
#

at every step when we keep adding digits, it's not pi yet

worthy dune
#

0.9 recurring will still never be 1 even if continue long time

#

yes

#

like 0.9 will never be 1

mighty geyser
#

but how can you be so sure 3.1415926... is pi

willow onyx
#

ask vsauce

mighty geyser
#

you continue a long time and you still have finitely many digits
it's still not pi

willow onyx
#

true

mighty geyser
#

so, pi is simply the limit of the sequence
3, 3.1, 3.14, 3.141, 3.1415, 3.14159, ...

#

none of the individual terms are pi

#

likewise for
0.9, 0.99, 0.999, 0.9999, .... none of the individual terms are 1

#

but the limit is

willow onyx
#

ohhhhh

#

@worthy dune come back

worthy dune
#

im back

#

hm

#

but

#

this is confuse

mighty geyser
#

the question is "what is an infinite decimal"

worthy dune
#

if it doenst doesnt start with 1 its not 1?

#

ok

#

never ending stuf

#

yes

mighty geyser
#

and if you look at pi, it has an neverending decimal representation

worthy dune
#

also how many other people has asked this question here

mighty geyser
#

none of the truncations equal to pi

#

many many others, I can be sure

worthy dune
#

lmao

mighty geyser
#

it is confusing when people first encounter the concept of numbers with more than one decimal representation

worthy dune
#

lol

#

still kinda confuse

mighty geyser
#

alright, you got the 3.14159... is pi bit, right?

worthy dune
#

yes

mighty geyser
#

and you understand no matter how many digits we present, it's not pi

worthy dune
#

yes

mighty geyser
#

likewise for 0.99999...

worthy dune
#

yes'

mighty geyser
#

no matter how many digits we present, it's still not 1

worthy dune
#

yes

mighty geyser
#

but when you go to infinitely many digits, we define it as the limit of the sequence

worthy dune
#

ok

mighty geyser
#

so how we define 0.99999... is just the limit of
0.9, 0.99, 0.999, ...
do you know how limits are defined, epsilon-N?

worthy dune
#

i am only grade 8 chill bruh

#

lmao

mighty geyser
#

there's a pretty formal definition of limits that would help deal with this problem

#

essentially it's like a game

worthy dune
#

ok

#

ill do this when im like actually ok at math

mighty geyser
#

Alice will say a particular epsilon, say "0.00001"

worthy dune
#

ok

mighty geyser
#

then Bob will try to find some N such that after the Nth term, all the values do not differ from 1 by more than epsilon

#

if Bob can win no matter what positive epsilon says, then the limit is 1

worthy dune
#

i dont understand rip

#

this is very confusing

mighty geyser
#

alright so imagine we plot the terms of this sequence on this graph

worthy dune
#

yes

mighty geyser
#

Alice will select a small horizontal band around the limit, 1

#

and Bob will have to say how far right you have to go such that the points plotted will never leave the band from that point onwards

worthy dune
#

im very confused still

mighty geyser
#

IF
no matter what small horizontal band Alice chooses
Bob can go far enough to stay within that band
THEN
the sequence has a limit

worthy dune
#

when do you learn this epsilon thing

#

what grade

#

or university

mighty geyser
#

hmm Khanacademy probably has a video on it

#

lemme find

worthy dune
#

wait

#

but what grade

#

or when did you learn it

#

or smthn

mighty geyser
#

I think 9?

worthy dune
#

grade 9

#

middle schol?

mighty geyser
#

but for different countries it might not map on that cleanly

worthy dune
#

ok

#

i should sleep now

#

bye and thanks

clear sinew
#

I learnt it in university lol

worthy dune
#

what year

mighty geyser
#

probably first year

worthy dune
#

wait

clear sinew
#

first year

#

yea

worthy dune
#

so element you learnt in grade 9 middle school

clear sinew
#

it was so confusing

worthy dune
#

or

worthy dune
mighty geyser
#

yeah I only could find limit of a function on KA

worthy dune
#

bruh

#

have no idea still

clear sinew
#

not anymore thankfully. I accepted that mathematics is, let's say somewhat flexible. I used to believe that maths is... stiff.

mighty geyser
#

found it

#

Math is just the rigourous language we use to explain ideas

clear sinew
#

I think Element118 explained it very nicely. That's the explanation that clicked with me.

worthy dune
mighty geyser
#

KA has about the same visualisation

#

might want to watch that linked video

worthy dune
#

ok

#

thank you

#

i am going to close now

#

i might learn this a bit later

clear sinew
#

wait borio

worthy dune
#

when im actually smart

#

yeah

clear sinew
#

let's look at the function f(x) = e^(-x) for example

#

looks like this when plotted with geogebra

#

now what would your guess be if we go further to the right?

worthy dune
#

im just confused now

#

what

clear sinew
#

sorry

worthy dune
#

i obviously havent learnt any of this

mighty geyser
#

what does the graph seem to approach as it goes to the right

worthy dune
#

our school has a really bad math system

mighty geyser
#

towards 0, yeah?

worthy dune
#

yes

clear sinew
#

👍 🙂

worthy dune
#

but never reaching 0 right

#

or

#

lol

clear sinew
#

I think yes lol

worthy dune
#

oke

clear sinew
#

but the point is now, let's say you have me as someone who wants to oppose you

worthy dune
#

yes

clear sinew
#

so, I am claiming "no, Borio, the graph will jump and rise again if we go far another to the right"

#

enough*

worthy dune
#

ok

clear sinew
#

we arrive at Element118 explanation:

#

wait

#

i'll rephrase my words

#

"the graph will never go below 0.1"

worthy dune
#

ok

clear sinew
#

but you want to show me that the graph does go below 0.1

#

what do you do?

worthy dune
#

idk

clear sinew
#

$$ f(x) = e^{-x} $$

warm shaleBOT
#

mrbrown

clear sinew
#

let's make it easier

worthy dune
#

i still dont know what f(x)

#

what is f(x)

#

i havent learnt this

clear sinew
#

ohhhhhh ok

#

it's called a function

worthy dune
#

i know that much

clear sinew
#

you can plug in values x and it gives you a value f(x)

worthy dune
#

yes

clear sinew
#

is e^(-x) the confusing part?

worthy dune
#

not really

#

ok

#

um

clear sinew
#

hmm

worthy dune
#

lol

clear sinew
#

😅

worthy dune
#

mind blank

#

its almost 12 here

#

i really should sleep

clear sinew
#

okokokok

worthy dune
#

anyway thank you

clear sinew
#

😄

worthy dune
#

very much

clear sinew
#

thank you too

worthy dune
#

i have learnt like a bit

#

it has broadened my view of math i guess

clear sinew
#

i think it will work out 🙂

worthy dune
#

and that im behind in math rip

#

or am i

clear sinew
#

haha

worthy dune
#

do you at all remember what you learnt in grade 8 middle school

clear sinew
#

it is a good thing to realize something like that, I used to believe i was the pinnacle lol and unviersity killed me 😂

worthy dune
#

bruh

#

is university that hard

#

damn

clear sinew
#

i don't remember exactly. I knew about functions and somoe geometry

worthy dune
#

oke

#

my school has a really bad math system

#

sadge

mighty geyser
#

hmm maybe you can look at khanacademy

worthy dune
#

i could

clear sinew
#

no, it is actually doable imo, but need to discplined and definitely visit the counselling hours and ask quesitons, no matter how the lecturers react. Just ask ask ask. That was the best advice a friend of mine gave me. I improved siginificantly by asking about stuff i didn't understand.

worthy dune
#

but i should sleep lmao

mighty geyser
#

they are a pretty good starter sits and you can learn stuff from it

worthy dune
#

yeah