help-10

[woeful talon]

I've tried so many things

[royal basin]

@woeful talon can you show some examples of the things you have tried

maybe you were on the right track

[woeful talon]

okay so

I was doing

this

so the consecutive numbers are

x, x+1, x+2, x+3 etc

and then I tried something completely unrelated

and that didn't work

it might be cause I'm not interpreting this correct

[royal basin]

here's a hint: consider the remainders of your integers mod 4

[woeful talon]

Ok

[obtuse pebble]

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[neat rivet]

its an riemann sum question, i dont know what f(x) is in this summation: $\lim_{n \to 0} \sum_{k=1}^{n} \frac{1}{n+k}$

[warm shale]

임도현

[neat rivet]

n to inf btw

.close

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[random arch]

hello, can somebody check if my answer is correct?

[random arch]

I am pretty sure its the 3th or 4th because to negate the whole statement there must be at least one number for which the second part does not apply

[obtuse pebble]

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[nocturne minnow]

That has test in the title, so if it actually is a test, you can't get help on tests

[random arch]

it is homework

[obtuse pebble]

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@random arch Has your question been resolved?

[rotund anchor]

In a negation, "there exists" becomes "for all" and vice versa

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[random arch]

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[clear girder]

Hello Guys, i am unfortunately stuck on this problem:
you all know the fibonacci sequenze, but there is generalized fibonacci sequenze too. It looks like that f_0 = z, f_1 = y, f_n+1 = a* f_n + b*f_n . Wikipedia says that f_n+1/f_n (f is here the normal sequence again) converges for n against infinity to: (1+sqrt(5))/2. So it is possible to calculate sqrt(5) with fibsequence. Now the question is: how can i caculate the square root of any number? To solve that problem i need to know what limit f_n+1/f_n for n against infinity is, for the generalized fibonacci number.

[obtuse pebble]

@clear girder Has your question been resolved?

[clear girder]

<@&286206848099549185>

[obtuse pebble]

@clear girder Has your question been resolved?

[clear girder]

<@&286206848099549185>

or should i ask this question on an another channel?

[obtuse pebble]

@clear girder Has your question been resolved?

[brave bramble]

The big deal ends up being the roots of:
x² = ax + b
Note these roots are φ and 1 - φ for the regular fib sequence

Then, when taken to a large value of n, the φⁿ blows up, while the (1 - φ)ⁿ shrinks to 0

Yes, you can get any end behavior you want. If u and v are the two roots then:

• Have u relate to the number you are looking for, and u > 1
• Have -1 < v < 1

.
As an example, have:
f(n+1) = f(n) + (1/4)f(n-1)

The roots are [1 ± √2] / 2
The end behavior should be [1 + √2]/2

Note starting numbers don't matter

Sadly you get fractions with this one, but with some you won't

Can confirm a few terms in and I'm pretty close to 1 + √2 / 2

[clear girder]

ahh i see, and i get (1+sqrt(3))/2 if f(n+1) = f(n) +(1/9)f(n-1)?

thanks a lot i appreciate it!

[brave bramble]

Neat question, feel free to ask if you have anything else

[clear girder]

but how did you got the answer?

[brave bramble]

So there is a general formula for the fib sequence, which the roots give you

In your case, you don't care about the general formula, you only care about the end ratio. So, I found how the general formula affected the ratio

[clear girder]

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[inland parrot]

Can someone help me ?
I ve been ignored for a day here

[obtuse pebble]

@inland parrot Has your question been resolved?

[ocean topaz]

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[full aspen]

how many numbers are there that the digits are in increasing order, like 12345 and are divisible by 5

[full aspen]

how would I get the number of combinations

[chrome orbit]

use the fact that the last digit can only be five

[full aspen]

yup

I get that, so there has to be 4 other digits before, or at least we can use 4 other digits

[chrome orbit]

and so, the rest of the digitts beyond five can only be 1,2,3 or 4

if it's strictly increasing, then the answer is only 1

12345

[full aspen]

just increasing

[chrome orbit]

else if it is non-decreasing, you can have these combinations

115,125,135,145,225.. 555

this way

[full aspen]

kk

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[uncut citrus]

let's say a relation R = {(1,1),(4,1)}

[uncut citrus]

obviously the first element of R which is (1,1) is both reflexive and symmetric but that is not the case with the second element (4,1) so does that mean you can't consider that Realtion R to be relfive and symmetric since the second element doesn't really follow that property?

[plain owl]

For R to be reflexive, an extra element (4,4) should be included

R would be symmetric if (1,4) was also included

R is neither symmetric nor reflexive if it only includes (1,1) and (4,1)

[obtuse pebble]

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[timid silo]

5-b

[chrome orbit]

did you not ask this exact question few days back?

[karmic whale]

Just enter it

[timid silo]

No

[royal basin]

what is troubling you here?

[timid silo]

I didn't understand it

[chrome orbit]

@timid silo I'm pretty sure you did

[timid silo]

Noo

[royal basin]

are you unable to calculate the values 8 - 2*7 + 3*5 (for a) and 8 - 2*(-2) + 3*4 (for b)?

[karmic whale]

So it will be like just enter the h and k to value $8-2\times(-2)+3\times4$

[timid silo]

it is new lession

[timid silo]

B

[chrome orbit]

just enter the values my man

enter and calculate

[timid silo]

Are u helping or no

[chrome orbit]

i am?

am i not?

[timid silo]

No you are not

[royal basin]

do you need to be taken step by step through the calculation of 8 - 2*(-2) + 3*4?

[timid silo]

Yes Please!

[royal basin]

okay

do you know the order of operations?

[timid silo]

Not alot

[royal basin]

???

you either do or you don't.

[timid silo]

No

[royal basin]

please do not reply-ping me so often.

have you not heard of PEMDAS?

[timid silo]

I did

[royal basin]

please do not reply-ping me.

[chrome orbit]

isnt it bodmas?

[royal basin]

PEMDAS and BODMAS are regional variations of one another and both suck

[chrome orbit]

brackets div mult add subtract

[zinc flax]

oh k

[royal basin]

anyway

whatever the acronym, multiplication comes first.

@timid silo can you calculate 2 * (-2)?

[timid silo]

ye

-4

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[royal basin]

oh, you don't need any help anymore?

ok

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[timid silo]

Help with 2ci and ii pls

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

<@&286206848099549185>

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

<@&286206848099549185> ?

[obtuse pebble]

@timid silo Has your question been resolved?

[rugged kite]

For both questions you just need to give a rough estimate

So for instance, longer than 8.2cm also means longer than 8.0cm

You only have info about specific ranges that don't quite fit the values given

So then, can you tell me how many earthworms are longer than 8cm? If so, then you know that at most that many earthworms are longer than 8.2cm (you have an upper bound on that amount of earthworms)

Likewise, how many earthworms are longer than 8.5cm? That's at least how many earthworms longer than 8.2cm there are (you have a lower bound)

[timid silo]

@rugged kite

I tried using interpolation

8.0 - 8.2 - 8.5
56 - x - 66

Then x would the the number of earth worms

Once I get x I find the difference then add it to 4

But it was wrong

And now idk what to do

[timid silo]

U have 14 earthworms longer than 8cm

[timid silo]

4 earthworms r longer than 8.5cm

[rugged kite]

I don't know if you can do much better than "between 4 and 14"

But you could try interpolation I guess

[timid silo]

I tried that but it didn't work

[timid silo]

Wait wdym?

[rugged kite]

Like, for all you know there could be 10 of them 8cm long, or 10 that are 8.4cm long

In either of those cases, you have 14 and 4 that are 8.4cm long respectively

So like, can you really say anything more precise?

[timid silo]

Icl idk what to do to make to more precise

Its confusing

[lament delta]

@timid silo have you tried edexcel's solution bank for the question?

[timid silo]

Yh but it's just says 70-62 = 8

Didnt really help

[lament delta]

so im assuming they calculated that there are 62 worms smaller than 8.2cm

Oh ok, I think i understand ci

So the way that they calculated it, they have the length: 8.2cm and the bound 8.0cm-8.5cm and there are 10 worms inside of the bound

[warm shale]

OnlyTheBest

[lament delta]

I think that edexcel calculated it to be 4, using 0.3 instead of 0.2, so their answer is 4+4 = 8

but it should be 10

@timid silo try the same logic for ii and see if you get the answer in the book

[timid silo]

I did but I got 10

8.0 8.2 8.5

56 x 66

I did it like that

Then I solved for x

I was 60

Then I found the difference

Which was 6

So in the range 8.2 to 8.5 there are 6 earthworth with that length

Add that to 4 gives 10 earthworms

Idk how they got 8

They couldn't even give a proper working

[south fossil]

Thats what he explained that perhaps the answer for part(i) in book is wrong by mistake

[timid silo]

Can I ask a question here?

I’m struggling to do dy/dx of ln(e^(4+ln2) + 1)

I made t = (e^(4+ln2) + 1)

Then I did y =ln(t) and dy/dt of that is 1/t and I substituted my t back in

[short spruce]

#❓how-to-get-help

[timid silo]

My bad

[timid silo]

Ahh alr thanks

[obtuse pebble]

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[timid silo]

how do i explain whats happening in the graph as the n slider becomes positive or negative

[plain owl]

Scaling along x-axis about x=-π/2

[timid silo]

what about the period increases as the slider increase

but the period also increases when the slider is a decreasing

[unique solstice]

Arent they asking specifically about positive to negative

Or vice versa

[unique solstice]

I mean you could describe it in many ways

[plain owl]

Yeah like n=0 gives a straight horizontal line and graph is mirrored when n goes from positive to negative...

[timid silo]

i wrote for n = 0 "when n = 0, the function dilates (stretches) horizontally, hence making it stationary along the x-axis."

same thing right

[plain owl]

Yeah same thing

Sort of infinite stretching

[timid silo]

so can i say " as the n slider increases the period of the graph increases from both sides at the point (-pi/2,0)

[plain owl]

Doesn't period decrease when "n" increases from 0?

[timid silo]

period is the cycle, think of it like the unit circle

the first intersection is at pi

and the second is 2 pi

1 full rotation around the sine unit circle, is one period

does that make sense?

like dis

[plain owl]

Yes

[timid silo]

so the period is increasing right?

as the slider increases

[plain owl]

Period is decreasing because we are able to complete the cycle faster

[timid silo]

ohh i get what u mean

can i just say then, the cycle increases

what about "when n > 0, the graph’s cycles increases from both sides at point (-pi/2, 0)"

and then when the slider is decreasing the graph produces the same affect but the graph is flipped along the x - axis

[plain owl]

Yes. Flipped about x=-π/2

[timid silo]

alr got it ty!!

.close

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[dusk cedar]

I heard somewhere that if G = (V, E) is k-colourable then G has a vertex cover of size ≤ n − n/k, but I can't seem to figure out why that is true. Would someone be able to briefly explain why that is. I know that the independent set = n - size of vertex cover, so i guess a better question is why is n/k the size of the independent set?

[obtuse pebble]

@dusk cedar Has your question been resolved?

[dusk cedar]

<@&286206848099549185>

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[cyan fractal]

n-α(G) ≤n-n/k then n/k≤α(G) that mean n/α(G) ≤k

[obtuse pebble]

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[low snow]

What do the arrow and the dot mean? Its an equation for gravity.

[low snow]

My school hasn't taught me anything like this

[obtuse pebble]

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[hazy grove]

Is there anything similar to markov chains, but with short term memory? For example immediate previous step and average previous step are taken into the prediction of next step

[royal basin]

you could make a markov chain with n^2 states where each state encodes the pair (current state, prev state) from your short-term-memory chain

[obtuse pebble]

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[hazy grove]

Does it mean that if I have chains of ABCBCA I have double states AB, BC, CB, BC, CA?

@royal basin

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[royal basin]

.reopen

[obtuse pebble]

✅

[royal basin]

@hazy grove yes, that's how the trajectories would be mapped to one another

[hazy grove]

Okay, thank you very much

[royal basin]

.close

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[timid silo]

how do you apply the linear transformation T to C and plot D = T(C)?

[timid silo]

i believe i need the matrix of T firsrt?

tbh i never done geometric linear transformations so not sure how to look at it

[dapper bloom]

I would find T first as well.

I think there's a fast way to do this by looking at what T does to a basis maybe.

But I don't remember that.

[timid silo]

yeah

[dapper bloom]

A good place to start might be to let T be a matrix with four unknown entries.

You can compute Tx=y for the four different pts you are given in the top of the figure

[timid silo]

the square?

[dapper bloom]

I'd bet that will give you a system of equations to solve for the entries of ur matrix.

Yes for the square.

It's just a guess as to how you can try to solve the problem.

In the context of a real class you might have learnes an even easier way to do this.

[timid silo]

sounds good thanks

lol nah we didn't learn anything in class

[dapper bloom]

Ah also pretty sure this kind pf xform has a real specific form.

Lemme chk real quick it might save u effort

[timid silo]

thatd be great👍

[dapper bloom]

It is a shearing transform

If you google that you should be able to find some 2x2 ex's

[timid silo]

ohhh ic

just googled it

[dapper bloom]

It will make the method I suggested much simpler

In the context of ur class u should still figure out ur professors intended soln tho

Just so u don't miss anything or get marked down unfairly

[timid silo]

yup ill for sure ask

and just to clarify

when it asks for matrix T, is it seperate matrices for every shape.. or A to B is one matrix?

[dapper bloom]

So what I think the question is asking is like: "T does this to shape A, what does T do to shape C?"

So that would only be one matrix for T

But we could both be misinterpreting the question I suppose.

[timid silo]

ok ill look into it more
thanks so much for the help

[dapper bloom]

No problem

[timid silo]

.close

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[proper raptor]

whats the difference?

[royal basin]

there is none

[quaint glen]

Both equations have the same solution set. There isn't one.

[royal basin]

|3x-4| and |4-3x| are one and the same

[proper raptor]

ok!

ty for the help

.close

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[vital vale]

Hey there! This is my hamiltonian cycle, have some problem to add a constraint that assure my problem to not take some forbidden sequences! Any help?

[obtuse pebble]

@vital vale Has your question been resolved?

[vital vale]

<@&286206848099549185>

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[indigo inlet]

can anyone explain this to me

what exactly is a borel set

what do these terms mean

<@&286206848099549185>

[obtuse pebble]

@indigo inlet Has your question been resolved?

[indigo inlet]

<@&286206848099549185>

i need help :(((

[obtuse pebble]

@indigo inlet Has your question been resolved?

[indigo inlet]

<@&286206848099549185>

heloooooooooooooooooooooooooo

anyone home

https://mathworld.wolfram.com/RandomNumber.html

apparently this is a similar way of saying the same thing

can you explain this to me instead????

[indigo inlet]

!close

[obtuse pebble]

@indigo inlet Has your question been resolved?

[digital ivy]

It’s .close

Oh you need answer to your question

[obtuse pebble]

@indigo inlet Has your question been resolved?

[indigo inlet]

doesnt like anyones coming to answer this

might as well close it

.close

[obtuse pebble]

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[neat widget]

i need

[neat widget]

help

i am having trouble with reading and solving algebra grade 8

i need to add to my memory aid but i dont know alot about it

[serene salmon]

Do you have a specfic question or just in general

[neat widget]

genral

general

[serene salmon]

What exactly are you having trouble with

[neat widget]

reading and solving algebra

[unique solstice]

Like x+2=3x?

[neat widget]

nah

its includes fractions

[unique solstice]

Can you give an example

[neat widget]

hol up ill get one

like the stuff on the right

[lilac valve]

What r u asked to do?

Simplify?

[neat widget]

solve

[unique solstice]

You can't solve it

[lilac valve]

You can only solve equations

[neat widget]

ik

[unique solstice]

Do you mean simplify?

[neat widget]

yes

i fund a diffrrent photo that fits what we are doin gin class

[lilac valve]

I can show how to do 5)

[neat widget]

vc

???

[lilac valve]

Sure

[obtuse pebble]

@neat widget Has your question been resolved?

[obtuse pebble]

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[timid hare]

Hello! I have a complex analysis question! I think I have completed it, but my classmates are telling me they got different answers. So can somebody help me confirm my answer is correct or incorrect?

[timid hare]

This is the question

This is my solution

In particular, can somebody confirm

1. My gamma is correct for the given description
2. My integration is good?

I keep getting told the answer is 8i*pi

[obtuse pebble]

@timid hare Has your question been resolved?

[obtuse pebble]

@timid hare Has your question been resolved?

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[lavish fable]

hello I need help

[lavish fable]

The text is in French. I translated it from French to English: We Consider the parallelepiped rectangle shown here. Is the AFC triangle a rectangle
I dont know how where to start or exactly what to do

[obtuse pebble]

@lavish fable Has your question been resolved?

[lavish fable]

.close

[obtuse pebble]

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[obtuse pebble]

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[short moss]

I feel like this is easy but I'll ask anyway
You have 2 variables, a and b.
Both a and b can be either 0, 1 or 2
Is there any SINGLE possible equation where the equation will only be true if both a and b are 1? (not equal to signs are allowed)

[obtuse pebble]

@short moss Has your question been resolved?

[short moss]

Oh I'm so dumb

It was just a^2 + b^2 = 2

[obtuse pebble]

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[spiral maple]

signed area

the area is positive if it's above the x axis and negative if it's below the x axis

assuming integration wrt x

Yes, but corrected your lack of a word

[obtuse pebble]

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[obtuse pebble]

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[shut lily]

@nocturne minnow

What do i do

[nocturne minnow]

,rotate

[nocturne minnow]

The coefficient of the x and y terms have to be 1, for equation of a circle

[shut lily]

Yeah so what to do

[nocturne minnow]

Don't forget that you can write $(3x^2)$ like $3(x^2)$

[warm shale]

dldh06

[shut lily]

Oh i can ic

[nocturne minnow]

That should help out

[shut lily]

Can i just divide them all by 20?

[nocturne minnow]

No

[shut lily]

Then what

[nocturne minnow]

Because the equation of a circle is $$(x - h)^2 + (y - k)^2 = r^2$$

[warm shale]

dldh06

[nocturne minnow]

Notice how the x and y terms have a coefficient of 1

[shut lily]

Oh yeah bruh

[nocturne minnow]

So when you rewrite, it should look like $3(x^2) + 3(y - 2)^2 = 20$

[warm shale]

dldh06

[nocturne minnow]

Can you see what you have to do now?

[shut lily]

Nope

[nocturne minnow]

How would you get a coefficient of 1?

For the x and y terms?

[shut lily]

Dont they already have a coefficient of 1?

[nocturne minnow]

No

[shut lily]

Then no clue

[nocturne minnow]

Does $3(y-2)^2$ look like something like ?$(y -h)^2$

[warm shale]

dldh06

[shut lily]

Nope coz 3 is still there

Can i divide both 3s with 3?

[nocturne minnow]

Yes, divide by 3

To all the terms

[shut lily]

Ok nvm to all terms nowonder

Aight thanks

.close

[obtuse pebble]

Channel closed

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[shut lily]

.reopen

[obtuse pebble]

✅

[nocturne minnow]

Also, next time don't ping me. You can just post your question/work and someone would be by to help

[shut lily]

Yeah my bad

I thought it was easier coz you already know what im asking. Sorry wont happen again

.close

[obtuse pebble]

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[autumn meadow]

Hi I am new so to navigate in this server is quite confusing i really need help in math right now (quantitative reasoning) its questions about percentages and assumptions

[autumn meadow]

A store is currently offering a 60% discount on all items
purchased. Your cashier is trying to convince you to open
a store credit card and says to you, "In addition to the
60% discount you are receiving for purchasing these
items on sale today, you will get an additional 20% off for
opening a credit card account. That means you are
getting 105% off!"
a. What is the mistaken assumption here?
b. Why is that assumption incorrect?
c. If you did truly have 80% discount, explain what
should happen when you go to the counter to buy
$500 worth of items? show calculation
If you got your 60% discount and opened up the
card for an additional 20%, what is the actual %
discount you would receive? show calculation
e. Is it better to apply the 60% discount first or the
20% discount first? show calculation

[inland ingot]

hint to the first one

their total revenues might not be equal

so the percentages don't tell the true story

[short spruce]

i mean that's just the answer to the first one

[inland ingot]

it doesnt answer c :)

also B for the first one is kinda weird, because if the assumption is their revenues isn't the same then that info isn't even given in the question. The assumption could be totally correct

it assumes real world knowledge about Apple's actual revenue compared to Microsoft, which they don't provide

[autumn meadow]

I appreciate the help I just needed help on 1, 3 and 4! And I am working on C . For number 4 that is typed out I am more stuck on than 3. Percentages and this type of math is pretty much difficult for me! So I may seem a little lost but im learning at the same time thank you for the explanations

<@&286206848099549185>

[obtuse pebble]

@autumn meadow Has your question been resolved?

[obtuse pebble]

@autumn meadow Has your question been resolved?

[obtuse pebble]

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[short spruce]

the equation y=1 has a slope of zero

[nocturne minnow]

Derivative of constant is 0, is that what you mean?

[restive acorn]

The derivative represents how something changes.

Constant values like 1 do not change

So their derivative is 0

Meaning they always have 0 change

Nah as long as you understand eventually

That's all that matters

[obtuse pebble]

@azure herald Has your question been resolved?

[obtuse pebble]

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[main lichen]

pls its due today and i am kinda confused

how would one go about doing this?

[restive acorn]

So all lines can be written in this form:

y = m*x + b

[main lichen]

yes i remember that

[restive acorn]

x and y are variables

[main lichen]

slope intercept form

[restive acorn]

m is slope

Correct

[main lichen]

and b is y intercept

[restive acorn]

They gave you part of the equation

You are missing y intercept

[main lichen]

ok

[restive acorn]

But for now i can safely say the equation looks like this:

y = -(5/11)x + b

[main lichen]

so i find it by using the slope from that point until i reach the Y intercept

[restive acorn]

Use the equation I'd recommend

[main lichen]

ok

[restive acorn]

The point they gave you is on the line

So the point (7, -5) = (x,y)

Tells you when x = 7, y = -5

[main lichen]

ok

[restive acorn]

Plug those in to your line equation

-5 = (-5/11)(7) + b

And solve for b

[main lichen]

ok i get it now

[restive acorn]

You can always do this for slope and one point

[main lichen]

ok

thanks

[restive acorn]

Yw

[main lichen]

for this its making me do point slope form

so would it be y − (−5) = − 5/11( x − 7 )

[restive acorn]

Yea that's even easier xD

[main lichen]

ah ok

so what would i do to solve that

[restive acorn]

So

The point is (x , y)

(7 , -5)

Take the slope and the 7 and put them with x

(-5/11)*(x-7)

X -7 in parentheses

Notice it's minus with a positive 7

That's one side

The other side is

y - (-5)

From the point

The form is

y - y1 = m*(x-x1)

Where (x1, y1) is on the line

And m is slope

[main lichen]

ok

[obtuse pebble]

Channel closed

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[obtuse pebble]

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[timid silo]

i need help

[timid silo]

can someone help me?

PLEASE

[chrome orbit]

send your question and we'll try

[timid silo]

thanks

i got like 4 questions

this is the first

[chrome orbit]

https://www.onlinemath4all.com/families-of-quadratic-functions.html

[timid silo]

is it easy?

like for u?

[chrome orbit]

just read the link, if you need further help, ask

[timid silo]

btw

i failed that test

the one u told me was correct

like u told me the answer

and it was wrong

[chrome orbit]

should have studied

[timid silo]

but why'd u do that

my mom got mad at me

[chrome orbit]

i did not give you a wrong ans on purpose

it was probably a result of miscommunication

that's why you should study

[timid silo]

ok but can u help me with this one?

[chrome orbit]

yes, and i did

[timid silo]

my teacher wants me to retake the test ive failed

[chrome orbit]

ouch

so did you study this time?

[timid silo]

fine

ill study

https://drive.google.com/file/d/1LgwayW9ULMG2JJpH9H0WB11LQpY_2aRx/view?usp=sharing

please

im having trouble

i dont understand what shes saying

[chrome orbit]

what?

ok, what do you need help in?

but i'm warning you, i can't give you an asnwer

[timid silo]

okay

[chrome orbit]

.

[timid silo]

uhh

how do u solve it?

what's the step by step explanation

[chrome orbit]

did you go through the article i sent?

[timid silo]

just tell me

i dont understand that article

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

hello

[obtuse pebble]

@timid silo Has your question been resolved?

[supple quest]

@dusky radish

you here?

[royal basin]

they have left the server outright.

.close

[obtuse pebble]

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[obtuse pebble]

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[warm shale]

Sherlock Holmes

[obtuse pebble]

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[ebon holly]

Oh?

Noted that.

.close

[obtuse pebble]

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[timid silo]

im hoping someone can speak german but i will try to translate the excercise regardless

[timid silo]

in the next pictures you see graph of a function f and the lower bound(? under sum?) U (=the summ of the Area of the dark rectangles) and the upper bound o (the summ of the dark adn light rectangles) in the interval [-a;a]
for 2 functions, of which the graph is shown, the given integral is valid in the interval [-a;a] if the width of the rectangles is constant

so my question is how do i know what to cross

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

<@&286206848099549185>

[obtuse pebble]

@timid silo Has your question been resolved?

[plain stag]

@timid silo is it asking for which functions have an area under the graph equal to the average of O and U?

[timid silo]

it asks you to cross those with the given connection

the connection being the integral

[timid silo]

well if no one can help me with taht question i have another question

the amount studied in minutes can be approximated with this integral

calculate the approximation and calculate the actual amount of minutes

how do i calculate the actual amount of minutes?

this is f(t)

<@&286206848099549185>

.close

[obtuse pebble]

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[proven axle]

can vectors multiplied by points or scaler?

[brazen viper]

A vector can be multiplied by a scalar

[proven axle]

but not points?

[brazen viper]

For the purposes of this discussion, no

[proven axle]

ok

[brazen viper]

A displacement vector I assume

Likely there's a multiple choice question they're trying to answer

Or a select all of the following that apply

[proven axle]

no I am not dude

it's not a mc

[brazen viper]

Anyway if you're done don't forget to close the channel@proven axle

[proven axle]

.close

[obtuse pebble]

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[signal cobalt]

***********************PROBLEM 2 ******************

[brazen viper]

What have you tried so far?

[signal cobalt]

no idea

I need an idea

[brazen viper]

Try setting the two equations equal to each other

And see where you get two values for a

[signal cobalt]

OHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

so

$x^3-x^2+3x=ax^2-x$

[brazen viper]

Not quite

[warm shale]

LittleMouse

[brazen viper]

Ok better

Solve for a

[signal cobalt]

so

[warm shale]

LittleMouse

[brazen viper]

So we have a and then an equation in x.

The latex one

[signal cobalt]

yes

[brazen viper]

For which values of a do we get two different values for x?

You can think of this as drawing a line across the graph

[signal cobalt]

other than the origin point

?

[brazen viper]

Graph it and see what I mean

[brazen viper]

Right. Now if you draw horizontal lines across this graph at different values of a where do you get two solutions?

[signal cobalt]

horizontal lines?

you mean this?

[brazen viper]

Yeah

So you see here when a=4 the graph intersects 2 times

[signal cobalt]

oh

[brazen viper]

The original lines intersect 3 times at this value of a

Because one of the solutions is at x = 0 and will always be there

So you need to find the two places where your horizontal line just hits this graph

[signal cobalt]

vertex

[dim root]

Wouldnt the best approach to this problem be to make a function for a like

and where x values are, thats the crossing?

[brazen viper]

That's exactly what is going on?

This is what it looks like when you find one of vertexes.

[dim root]

Oh, ok i misunderstood what you were saying

[brazen viper]

In the original graph

[dim root]

looks good

[signal cobalt]

so how do we find a

?

.cloase

.closae

.clasose

.claose

.closes

.close

[obtuse pebble]

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[restive acorn]

<@&268886789983436800> this guy spamming in help channels

Edit: taken care of thank you

[obtuse pebble]

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[obtuse pebble]

@sudden condor Has your question been resolved?

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[meager sorrel]

mark scheme:

I have got up to producing 2x+4y=0 but I don't know what to do next

[obtuse pebble]

@meager sorrel Has your question been resolved?

[meager sorrel]

<@&286206848099549185>

[timid silo]

have you done implicit differentiation

[meager sorrel]

ye so I did everything for the differentiation part

thats how I got 2x+4y=0

[timid silo]

I'm trying to understand how they got the x² = 36 and y² = 9

Ohhb

I got it @meager sorrel

[meager sorrel]

how

[timid silo]

2x + 4y = 0
2x = -4y
x = -2y

Sub that into equation

main equation

you'll get y² = 9

[meager sorrel]

thanks

[timid silo]

no problem took me a minute

[meager sorrel]

i’m super annoyed because I did exactly that like 4 times previously and kept getting a different answee

I need to brush up on basic algebra lol

[timid silo]

haha I feel that

[meager sorrel]

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[jagged solstice]

This ones really stupid lol

[jagged solstice]

0.00200414 is my answer

It says give the answer with three non zero digits

Is that just 0.002? Or 0.0020041

[mild ocean]

probably the second one

that question is weird though

[tacit bronze]

Thats an awfully worded question, you should ask the prof to be sure

Not ur fault lol

[obtuse pebble]

@jagged solstice Has your question been resolved?

[jagged solstice]

That’s what I thought hahahah @tacit bronze @mild ocean , I’m just gonna round it to 3 sig figs as all the other answers are like 0.12443 etc, it’s just this one with a gap of 0’s in between

[obtuse pebble]

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[frozen willow]

Apologies the last channel timed out

[frozen willow]

Why is the answer infinity?

when lim [h->0] f(-8+h)/h is 0/0

[obtuse pebble]

@frozen willow Has your question been resolved?

[spiral maple]

f(-8)=0

so you're doing $\lim_{h\to 0}\frac{f(-8+h)-f(-8)}{h}$

[warm shale]

Mosh

[frozen willow]

i see

thank you

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[short spruce]

ok

[obtuse pebble]

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[timid silo]

hi

[timid silo]

not understanding f or g in relation to the formula provided

[hybrid gull]

f. a = 5x, n =2
g. a = x + 1, n = 2

@timid silo

[timid silo]

so for F it wants to me simply 25?

ok thats fine then i thought it just wanted "a" in the lines so I put |25x|

G im not getting

[final python]

how u come to x+2x+1

as u can see x^2+2x+1 is the expanded form of (x+1)^2

[timid silo]

x^2 and the index cancels so i just go to x+2x+1 dont know how else to go there

[final python]

no

sqrt(a+b) is not the same as sqrt(a) +sqrt(b)

when u have

sqrt(x^2) u get |x|

here is x = (x+1)

|| because n is even

[timid silo]

ok but i just dont see how they got from their first part to the second part

second part to answer makes sense

[final python]

bump

[timid silo]

I know I can foil (x+1)^2 and get the first part but my issue is simplying that first part

what concept is that called to turn that long form into foil

[final python]

dunno if u see something like ax^2+bx+c

then try to play with (ax+c)^2

till u get the long form

[timid silo]

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[final python]

tg=sin/cos

?

30 is sqrt(2) right?

[spiral maple]

Very confused on what you're asking.

Wow, that suddenly makes everything so much clearer

thanks

Oh, forgot the \s

[mild ocean]

everyone knows that mosh would never say thanks

[spiral maple]

But anyway... still no clue why you can't just draw the special triangle and compute the tangents

[quaint glen]

If i had to guess, the pythagoras part would be finding the sqrt(3) side in the 30-60-90 triangle

[spiral maple]

draw the triangle.

the 30-60-90 is a triangle w/ known side lengths

Yes.

Google it

[short spruce]

you make negative sense

[final python]

hahaha

[short spruce]

you seem like a nice guy

now i want to help you

[spiral maple]

<@&268886789983436800>

[hybrid gull]

Lmao

[final python]

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[distant cave]

5105 The area bounded by the curve y = 3x² - x³ and the positive x-axis rotates around the y-axis. Determine the volume of the rotating body formed.

[viral crown]

what have you tried?

[distant cave]

Can you give me tips

[obtuse pebble]

@distant cave Has your question been resolved?

[distant cave]

$$V=2\pi \int _0^3x\cdot 3x^2-x^3dx:$$

[warm shale]

Theophania

[distant cave]

Is this right?

[warm shale]

Theophania

[obtuse pebble]

@distant cave Has your question been resolved?

[distant cave]

How did they get 3x^3 - x^4 in there?

[nocturne minnow]

$$x \cdot (3x^2 - x^3) = (x \cdot 3x^2 - x \cdot x^3)$$

[warm shale]

dldh06

[distant cave]

ah of course, thanks

So we have

[warm shale]

Theophania

Theophania

Theophania

[distant cave]

And I think that's the final answer 🤔

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[timid silo]

hi! so im unsure whether my c is correct or not, may i get that checked please? and if not, may i ask for the reasoning? thank u sm!

[brave bramble]

Show work, we can check it for you

[timid silo]

here you go!

so for c, i assumed it was a horizontal shift to the right by 1 bc i associated it with january being the first month, but im unsure if thats the correct reasoning

[brave bramble]

You raise a fair point, and I'm sure a teacher would be convinced

One could also make a case for jan = 0

I'm not certain which the box expects, sry.

[timid silo]

no worries! thank u sm for your time!

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[fading herald]

What can I do after this?

[hoary shell]

don't bring 4 in the power at first

first of all take 4 common from the last two terms

like 4[log (ac) - 1] base as a

and then you can write 1 as log a (with base a)

so on you can solve and get option C as answer

[fading herald]

okay let me try it and I'll send it in to see if its right

[fading herald]

by common do you mean constant?

[hoary shell]

common is like

as you have 4log (ac) - 4

I'm just taking out 4 from both the terms and writing it in this way 4[ log(ac) -1]

[fading herald]

@hoary shell

would you also be able to explain the question on the bottom

[hoary shell]

suree

lemme see

@fading herald is the answer 3?

[fading herald]

@hoary shell yeah

[hoary shell]

that's even simple at first simply the expression which says y=a^x....

just subtract the two indices you see (as we know the property like when a^x/a^y we write that as a^(x-y))

so that you will be left with y = a^(-x+6)

and as mentioned in the question log y = x (with base as a)

we can write that as a^x = y

and at the end we get y = a^x ----- equation 1 and y = a^(-x+6) ------ equation 2

equate both of them

and then you get your answer

[fading herald]

okay thank you, I'll close this room now

.close

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[urban jacinth]

Uh hello?

<@&286206848099549185>

darn it

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[urban jacinth]

.reopen

[obtuse pebble]

✅

[urban jacinth]

.helpers

<@&286206848099549185>

[obtuse pebble]

@urban jacinth Has your question been resolved?

[obtuse pebble]

@urban jacinth Has your question been resolved?

[urban jacinth]

Ty

[neat patrol]

working on Q2 now

[urban jacinth]

alrite

[neat patrol]

@urban jacinth Hope I could help. The writing isn't in Indonesian though

[urban jacinth]

Can you translate?

[stuck briar]

hello

i need help

pls

II

[obtuse pebble]

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[wide orchid]

John has a fake coin. There is a 90% chance of getting a heads and a 10% chance of
get the tails.

What is the probability that he gets heads twice in a row?

[obtuse pebble]

@wide orchid Has your question been resolved?

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[split adder]

How can I get the values for x, y, u and z?

[split adder]

Oh wait, I've just realised something

[obtuse pebble]

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[lean tendon]

[ \sum_{n=1}^{\infty} \frac{x^{n+2}}{2n!}]

[warm shale]

Ziggy

[lean tendon]

$$R = \infty; I = (- \infty, \infty)$$

[warm shale]

Ziggy

[lean tendon]

why is this the answer?

this is the correct answer FYI

[obtuse pebble]

@lean tendon Has your question been resolved?

[obtuse pebble]

@lean tendon Has your question been resolved?

[lethal crest]

R is the radius of convergence

why don't you use the radius of convergence using the formula

[hybrid gull]

The series will converge for all real numbers x

[obtuse pebble]

@lean tendon Has your question been resolved?

[obtuse pebble]

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[inland pine]

Can some one tell me how LHS became RHS

[drifting wraith]

X^(n-1) is X^n/X

[inland pine]

Yea ok

[drifting wraith]

so we have (-1)^n - n(-1)^n

[inland pine]

Ohh okk... Then

[drifting wraith]

then you separate the (-1)^n

and done

[inland pine]

Wow omg that was easy
I got rly confused for some reason
Thanks for the explanation 😊

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[timid silo]

In the survey, each participant is asked: “Do you normally use drugs at least once a week?”. To achieve randomized responses, the participant is then instructed to respond as follows:
1. Flip a fair coin (i.e., 50% chance of heads and 50% chance of tails).
2. If tails, then respond truthfully.
3. If heads, then flip the coin again. Respond “Yes” if heads, and “No” if tails.

suppose b is the value of the true answer to the question, where b = 1 is “Yes” and b = 0 is “No”.
where b' = 1 means the participant responded “Yes” and b' = 0 means the participant responded “No” 

To formalize this idea, let q [0,1] denote the true fraction of the population that frequently uses drugs. Compute the probability P(b = 0 | b' = 0) that the true answer is “No”, given that the survey response is “No”. Your answer should be in terms of q and constants.

Compute the probability P(b = 0 | b' = 0) that the true answer is “No”, given that the survey response is “No”. our answer should be in terms of q and constants.

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

I need help using Baye's rule using what I found in an earlier question as shown above. Last time I had to find P(b' = 0 | b = 0) but this time I need to find P( b= 0 | b' = 0).

Compute the probability P(b = 0 | b' = 0) that the true answer is “No”, given that the survey response is “No”. Your answer should be in terms of q and constants.

Done with the question set up. Sorry it took so long

my work so far:

P( b= 0 | b’ = 0) =  P( b’ | b) * P(b) / P(b’)
( ,75 * .5 ) / (.5) = 0.75

can someone verify this? I'm stuck because I'm not sure where q comes into play. How can I write my answer in terms of q

<@&286206848099549185>

[obtuse pebble]

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[timid silo]

oh damn

[obtuse pebble]

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[pine shadow]

Does anyone know how I can solve this reciprocal equation

.close

[obtuse pebble]

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[plain owl]

Divide by x² and form polynomial of x+1/x

[obtuse pebble]

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[narrow pewter]

I need help with this question , i came up with the slope of the perpendicular line which became -3/2 , i got the midpoint but i dont know how to get the other part , i dont know whether it is 17/4 or 23/4 , the mid point is (1/2 , 5 ) ...... On the answer sheet they put it C , but i got it D and i made sure of everything

[warm shale]

KurtDee

KurtDee

[narrow pewter]

Yes that is true

They got "b" equal 17/4

[warm shale]

KurtDee

[narrow pewter]

That's fair

I substituted and got it 23/4 lol

Uuuuh

[warm shale]

KurtDee

[slim nebula]

help

quickly

[narrow pewter]

I am not sure if i was wromg

Sure

Shit internet sry for late

It's fine

Well as i got it right by your saying maybe there was a typo in the answer sheet

Yes

[warm shale]

KurtDee

[narrow pewter]

Hmm

Well thank you

I will tell my teacher about it then

Yep ig

Ty again lol

.clear

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[safe egret]

A tennis player hits a ball towards a wall 5.0 m away. If the ball is hit with a speed of 10.7 m/s at an angle of 40.4 degrees, how high on the wall does the ball hit?