#help-10

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obtuse pebbleBOT
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tiny edge
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shoould this be 0 or 1/7??

obtuse pebbleBOT
tiny edge
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i did it by doing the lkimit on the tan first, it is 0, than anything times 0 is just 0, but photomath used L'sHopital rule and ended up with 1/7

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i used photomath to be sure, but now idk what is right

fierce lagoon
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You can't do the multiplication thing if one of the limits is not defined as a real number

burnt vale
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cot7/x dne

fierce lagoon
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cot(7/x) goes to infinity as x-> infinity

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So you can't do 0 * infinity

tiny edge
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oh thats true, forgot that

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but there are no DNE option in the quiz, wtf

burnt vale
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so u can try L'sHopital rule like np tan(k)/1/coty

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to do 0/0

tiny edge
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i don't know the L'hopital rule, not yet lol, if someone can teatch me

burnt vale
# tiny edge i don't know the L'hopital rule, not yet lol, if someone can teatch me
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tiny edge
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thank you

obtuse pebbleBOT
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@tiny edge Has your question been resolved?

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spark stump
obtuse pebbleBOT
spark stump
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i dont understand why when x=2 dy/dx =0

high lily
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stationary point at (2,7)

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definition/property of stationary point

spark stump
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so when y=7, dy/dx=?

high lily
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insufficient info

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there are two coordinates where y=7

spark stump
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uhh

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@high lily do u have any advice

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to generally

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preparing for a math exam?

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sorry for random question XD

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but my exam is in 5 days

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and im kinda

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nervous

high lily
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practice, do past papers under exam conditions

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identify knowledge gaps

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review content/questions on those

spark stump
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o

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what about physics and chem? same thign?

high lily
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yes

spark stump
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alr

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.close

obtuse pebbleBOT
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agile nest
obtuse pebbleBOT
agile nest
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where can I learn discrete mathematics?

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I don't understand the concepts at all

obtuse pebbleBOT
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@agile nest Has your question been resolved?

agile nest
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.close

obtuse pebbleBOT
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obtuse pebbleBOT
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timid silo
timid silo
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@tight oasis

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sorry for the late reply

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but heres the link

tight oasis
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@timid silo Why taking k=1,3,5,7 ?

timid silo
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k= 0,1,2,3

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or well it kinda is

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if u solve it you will get e^ipi(1+2k)/8

tight oasis
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oh yeah my bad

timid silo
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1/2 i pi (e^-i(pi/8) + e^-i3pi/8 + e^-i5pi/8 + e^-i7pi/8) was my result of the integral idk if its right or not

obtuse pebbleBOT
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@timid silo Has your question been resolved?

timid silo
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<@&286206848099549185>

obtuse pebbleBOT
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@timid silo Has your question been resolved?

tight oasis
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Why the 1/2? You don't need it

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@timid silo

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Also your exponent should be positive

obtuse pebbleBOT
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obtuse pebbleBOT
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molten dune
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Im relearning math for the GED and i guess I got confused and maybe over complicated it. Apologies if this seems incredibly simple and stupid of me.
So it wants me to find the equation that runs through the line (1,6) (-1,2) I already know the answer but i guess i got lost in the steps.
I know this ties in with y=mx+b
So I solved for M using m=rise over run which is 2
So youre left with y=2x+b and then you plug in either of the coords and the steps after have me confused I guess

high lily
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which part of the last step is confusing

molten dune
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The test gave me the steps for the answer and I understood it up to this point.
Im not understanding how in the steps we went from
2=-2+b to 2+2=b like the equation got flipped or i missed something

high lily
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add 2 to both sides of the equation

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basic equation manipulation

crimson axle
mighty hearth
crimson axle
tardy epoch
mighty hearth
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FUCK U RIEMANN

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YOU BEANER

tardy epoch
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Yummmm beans

mighty hearth
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fuckin hate beaners like u

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sorry im jus a lil buzzed

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from the bar

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should i sleep

crimson axle
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On the right side, if you solve for b, you'll find that it's the same value as the left side.
The point of the question is so you can express y in terms of x without any other unknown variables in the equation
@flint glade

molten dune
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I believe i’ve understood it.

polar fossil
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<@&268886789983436800>

grizzled shore
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<@&268886789983436800>

obtuse pebbleBOT
#

@molten dune Has your question been resolved?

obtuse pebbleBOT
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burnt otter
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I just had a question

obtuse pebbleBOT
burnt otter
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whats dx/dy e^2x just 2e^2x

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or does the x also go down

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i forgot how the rule went

warm shaleBOT
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guinearW

kind hawk
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well what is y

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there is no y in the expression so it would just be 0

burnt otter
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i mean when you differentiate

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yep thanks

kind hawk
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you are differentiating with respect to y

frosty river
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NO

burnt otter
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what

frosty river
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You're unhelpful, @abstract snow

high lily
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you didn't notate your expressions properly

frosty river
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dx/dy e^(2x) =0

high lily
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you typed out
$$\dv{x}{y}e^{2x}$$
when you probably mean
$$\dv{x}e^{2x}$$

warm shaleBOT
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ℝam()n()v

burnt otter
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ohhhhhh

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yea that's what i meant

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sorry

kind hawk
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or dy/dx where y=e^(2x)

burnt otter
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yep that's that

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this is my 2nd past paper and i'm getting tired sorry ToT

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but thank you for the help

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.close

obtuse pebbleBOT
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frosty river
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You were right but coincidentally haha

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bc op didn't know how to write properly

burnt otter
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.open

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.reopen

obtuse pebbleBOT
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burnt otter
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shouldn't it be 2x in the denominator

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wait hold on

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i don't understand how they got that once they simplified

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nvm i stuffed up

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.close

obtuse pebbleBOT
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obtuse pebbleBOT
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timid silo
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Is this right

obtuse pebbleBOT
royal basin
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let's see...

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b) incorrect: missing -4
c) incorrect: missing -1
i) incorrect: missing -4, -1

everything else is correct

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im assuming this strange symbol is supposed to be a 1

timid silo
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Yes

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Thank you

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.close

obtuse pebbleBOT
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obtuse pebbleBOT
warm shaleBOT
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SilverSoldier

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SilverSoldier

#

SilverSoldier

obtuse pebbleBOT
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lost tree
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whhops

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how do i reclaim the channel

chrome crypt
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Epsilon Delta Proofs?

lost tree
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when can i say a is non positive

chrome crypt
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I just presume epsilon is a widely used variable.

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is it the epsilon delta definition of a limit?

lost tree
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im not trying to prove a limit here

chrome crypt
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Interesting so ur questioning why the proof works in a certain manner for a certain theorem?

lost tree
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ig im just confused about the order in which quantifiers are used and how to like use themtogether

chrome crypt
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Questioning why the proof works the way it does?

lost tree
chrome crypt
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im not speaking abt epsilon delta

lone echo
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he's questioning if those two statements are equivalent

chrome crypt
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im asking for whatever theorem ur doing rn.

lost tree
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😅

chrome crypt
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I love that.

lost tree
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and if i see something like $\forall\epsilon>0, a<\epsilon\implies a\leq0$, how shud i interpret it

warm shaleBOT
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SilverSoldier

lost tree
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without any brackets

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maybe the comma means everything after it shud be bracketed?

obtuse pebbleBOT
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hot ermine
#

hey

obtuse pebbleBOT
gaunt walrus
#

hi

pulsar quarry
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hey

hot ermine
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Guys if i am solving absolute values inequalities, Should i always make an associated equation?

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Or i can just evalute the inequality for x?

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For these.

royal basin
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idk what you mean by "evaluate the inequality for x"

pulsar quarry
royal basin
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is that not synonymous with "solving the inequality"?

hot ermine
hot ermine
royal basin
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i have... no idea what you're saying

hot ermine
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like this

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should i do this or i can just solve inequality?

royal basin
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well i can see an alternative route here yes

hot ermine
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ohh

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So it doesnt matter which method i do?

royal basin
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i guess it doesn't

hot ermine
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got it. I'll just won't do this.

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Thanks

obtuse pebbleBOT
#

@hot ermine Has your question been resolved?

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timid silo
obtuse pebbleBOT
timid silo
#

“Check answers for Q2 and 3 “

royal basin
#

question 2:
a) correct
b) correct
c) correct
d) incorrect: asked for first FIVE square numbers, saw only four
e) correct
f) incorrect: 4/5 and 9/10 are greater than 3/4.

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Q3 is all correct

timid silo
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Now?

royal basin
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i can't read these

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61/100, 31/100, 63/100, 32/50?

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@timid silo

timid silo
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And

timid silo
royal basin
timid silo
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Ohyea

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Then 62/100 shud work

royal basin
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@timid silo here

lone echo
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i'd like to add in 1c, 1d and 1i that you should probably be more careful with where you put the decimal point. It looks like a dot product

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poor handwriting makes for easy-to-miss mistakes later on

timid silo
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😄

lone echo
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any of them. The purple is yours, right?

timid silo
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Ye

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Ty

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I just realized mah mistske rn

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Lclose

#

.close

obtuse pebbleBOT
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winter cloak
obtuse pebbleBOT
#

@winter cloak Has your question been resolved?

obtuse pebbleBOT
#

@winter cloak Has your question been resolved?

obtuse pebbleBOT
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shut hatch
#

please someone help me with this:

obtuse pebbleBOT
shut hatch
#

I broke down the components of force N and F

teal kiln
#

its physics

shut hatch
#

🤯

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the magnitude of vertical component for N + magnitude of vertical component for F = 10 right?

teal kiln
#

10g

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can u show the FBD u drawn?

shut hatch
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i didnt draw any

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just use the one in the question

shut hatch
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yes i am aware

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but i dont rly care abt units rn

frank monolith
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what is your doubt?

shut hatch
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there are two variables

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i dont know how to find them

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like

thin star
#

You just need to break it down, no?

frank monolith
#

did you try to balance forces in horizontal direction?

shut hatch
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|N|sin(55)+|F|sin(35)=10 right

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for vertical

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how am i meant to find |N| and |F| from that

frank monolith
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Ncos btw

thin star
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define your axis to be on the direction of F

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makes life easier

shut hatch
#

wait no

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like

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for horixontal its

teal kiln
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Here , X = mgcos35 and Z = mgsin35

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equate them u will get the ans

shut hatch
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i dont understand

teal kiln
#

See

shut hatch
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ok disregard what ive been saying

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ive been doing random shit

teal kiln
#

From fig N=x right?

shut hatch
#

ye

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s

teal kiln
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and F=Z

shut hatch
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i only need to find N

teal kiln
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then X=mgcos35

shut hatch
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whats mg

teal kiln
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and N=X

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10g

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M is mass of block

shut hatch
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why is it assumed as a right angle triangle

teal kiln
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and G is gravitational force

shut hatch
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why does 10 become hypotenuse

teal kiln
teal kiln
shut hatch
#

why can u use trig then?

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sorry im js so lost rn

teal kiln
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i just resolved the forces

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i resolved the mg force in direction of N and F

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didnt get it?

shut hatch
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oh wait

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z + x = 10g?

teal kiln
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yeaa vector addition

shut hatch
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ohh the 10g is the resultant vector right?

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and since F and N are perpendicular

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its trig right?

teal kiln
#

Ys

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if u didnt got it i can explain it one by one no worries

shut hatch
#

OHHHHHHHHHHH

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THANMK YOU

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omg ive been struggling for like 30 minutes on this stupid question

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thank you

teal kiln
#

no worries

shut hatch
#

.close

obtuse pebbleBOT
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polar pine
#

Kinda wondering where I'm going wrong here

obtuse pebbleBOT
violet sentinel
#

j/k

polar pine
teal kiln
#

i didnt understod what u did in this steps

polar pine
teal kiln
#

no not that

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is it power to root 15?

polar pine
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the little 5/5 and 3/3 are meaningless I was just using them to help me remember what I was doing. (In this case multiplying the top and bottom of both fractions by 3 then 5 for the second one)

teal kiln
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ahhh fine it confused me

frank monolith
#

,calc 81*15

warm shaleBOT
#

Result:

1215
frank monolith
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not 135

polar pine
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Sorry which line are you referring to?

frank monolith
#

5th

polar pine
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81 * 15?

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it's 9 * 15 I'm doing surely?

teal kiln
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its under root

polar pine
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Is this not correct?

frank monolith
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it is

polar pine
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So where is the 81 coming from?

frank monolith
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but 9sqrt(15) is not sqrt(135)

polar pine
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the 9 isn't getting squared anywhere unless I've missed something

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ah sorry it's not the 9th root of root15 its 9 * root15

frank monolith
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yh ik that

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still not equal

polar pine
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Oh i see where I've made a mistake

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I took a 9 out of the root 135 and didn't put it under a root symbol lol

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so it should be root9root15 over 1

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or 3 * root15 over 1

frank monolith
#

correct

polar pine
#

Ah cheers for the help everyone, It's greatly appreciated as always

obtuse pebbleBOT
#

@polar pine Has your question been resolved?

obtuse pebbleBOT
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tired hawk
#

the opposite hypotenuse and adjacent are all in correct spots right?

tired hawk
#

simple question but i think im losing my mind

hidden sand
#

They are

tired hawk
#

cool thanks

#

.close

obtuse pebbleBOT
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fading sigil
#

Hi

obtuse pebbleBOT
fading sigil
#

Can someone help with this

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I need to make a graph with off these

vocal temple
#

I think it’s probably easiest to just draw each of these separately and then if you’re pedantic join them up

fading sigil
#

thats the problem

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idk how to combine them

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i graphed it...

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is this how

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os this

lone echo
fading sigil
lone echo
#

that sounds like they want one graph per condition

fading sigil
#

all the given conditions

fading sigil
#

but yeah they want all the graphs

lone echo
#

if you want one graph that satisfies everything at the same time, you can just draw the parts close to the points given, and then join them (or not) however you like. They never say that the function needs to be continuous where you're not given a condition

fading sigil
#

did i do it right

lone echo
#

i'd bitch about how badly you drew the branches that go to inf and -inf at 0 and 2, but it looks like the conditions are satisfied

fading sigil
#

ikr lol, its not the best

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but i fixed it in the actual paper

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anyways thanks

obtuse pebbleBOT
#

@fading sigil Has your question been resolved?

obtuse pebbleBOT
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real oriole
#

Letter B number 9 and 10

obtuse pebbleBOT
real oriole
#

I have no idea ://

#

Helpp asap

obtuse pebbleBOT
#

@real oriole Has your question been resolved?

obtuse pebbleBOT
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wild vigil
#

okey so

obtuse pebbleBOT
wild vigil
#

lets say i i have to make a function

#

or better to say i got given info

#

i know that P1(x y) P2(x y) and i know the vertex which is also where the y interecept is

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is there anyway that i can calculate this with the calculator

sharp ivy
#

If you know 3 points on a parabola, you can find its equation. Is that what you're asking?

nocturne minnow
wild vigil
#

so if u could please tell me how lol (my b for the trauma dump)

nocturne minnow
#

As I mentioned, a calculator is a tool, not something you should use to rely on

#

But post an image of the problem you are doing

wild vigil
#

Tennis players often train with a ball machine. The one described here is in one half of a 24m long tennis court and shoots tennis balls from a height of 1m into the other half of the field in such a way that the balls cross the net at a height of 1.3m.
Where should the ball machine be located so that the tennis balls hit the ground 0.5m in front of the baseline in the other half of the field when the ball is at the apex of the parabolic trajectory when crossing the net?
At what height does a tennis player have to hit the ball when he is 2m in front of the net?

Solution

#

i dont rlly need the solution just the way how to put it into the calc

nocturne minnow
#

You can do that all without a calculator. But if you want to keep being persistent and wanting to use a calculator to do every single math problem, so be it. Good luck with your future classes, because some classes don't allow a calculator

wild vigil
#

well thats why im trying to use it cuz i can i know how to solve but that just takes time our teacher allows us to do the vertex zeros everything with the calc so i just wanted to know if something like this were to come up how would i need to solve it

sharp ivy
#

You still haven't posted the question, but seriously a calculator doesn't help you here. It's just not the right tool.

nocturne minnow
#

If you know how to solve it without a calculator, then do it without the calculator, and send your work

wild vigil
#

a= -26/2654

sharp ivy
# nocturne minnow <@201551020382355456>

Omg, sorry, I saw the start of this and I thought you were OP was ranting about tennis players using machines to train as a metaphor for using a calculator to train. Sorry!

sharp ivy
#

Yeah, so a calculator doesn't really help, does it? You just start with the form of the equation, then plug in the point where the ball lands. I guess you can use a calculator here to solve for one of the coefficients.

#

a=-1.3/11.5^2
It seems like you understand that though.

wild vigil
# wild vigil like

so theres no way to just write this formula into the calc in get the a 😦

wild vigil
#

.close

obtuse pebbleBOT
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wary trout
#

Sorry for skill issue just wanna know how to do this

royal basin
#

exponent laws

wary trout
#

What I did is I multiplied 7/4 by 3/2

royal basin
#

and extra care when doing shit w/ fractions

wary trout
#

Then I got n to the power of 21/8

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What do I do after i multiply thr bottom

timid silo
#

multiplica em cima e em baixo por n^(2/3)?

wary trout
timid silo
#

no denominador?

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tá certo oq tu fez

wary trout
#

n entendi ent

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a minha resposta final foi 89/24

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AH

#

entendi oq eu fiz de errado

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n pera

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n entendi n

#

kkkkk

timid silo
#

multiplica o numerador e denominador por n^(2/3)

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dps do q tu fez

#

é a msm coisa que multiplicar por 1

wary trout
#

mas teoricamente n era pra eu fazer a parte de cima menos a parte de baixo?

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@timid silo

wary trout
timid silo
#

vai dar n^(-79/24)

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que é a msm coisa

wary trout
#

eu botei 89/24 errei a conta de mais e esqueci de mandar pra baixo pra ficar positivo

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mas vlw pela ajuda men

timid silo
#

tmj

wary trout
#

.close

obtuse pebbleBOT
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jagged edge
obtuse pebbleBOT
jagged edge
#

I know for a fact that’s not the right answer

#

Where did I mess up

#

I have last try on the hw :/

obtuse pebbleBOT
#

@jagged edge Has your question been resolved?

hot ermine
#

hi

#

is 0 a part of solution set of this inequality?

#

hey

obtuse pebbleBOT
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@jagged edge Has your question been resolved?

obtuse pebbleBOT
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tardy idol
obtuse pebbleBOT
tardy idol
#

ive currently tried to do ∫2 over 0 pi(sqrt(x))^2

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but its saying the answer is 64pi/15 so i have no idea how to get there but i understand the basics

hollow dove
#

you're rotating about the y-axis, so you should be integrating whatever x is equal to (so an integral of y^2 or 2y)

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it's also the region bounded between the two curves

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so you should be subtracting something here (figure out which is "further" from the y-axis)

#

your bounds 0 to 2 look fine

tardy idol
#

oh for real? i thought if i rotate over the y-axis i would do it with respect to y so id try to find what is = to y

tight oasis
#

"about the line x=0"

tardy idol
hollow dove
#

this is what the graph looks like

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if you just integrate one, you get area between that line and the y-axis rotated

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so here you want the area between

tardy idol
#

ohhh okay okay

hollow dove
#

so do the volume of rotation for the 2y line, then y^2 line, and find the difference

tardy idol
#

can i ask why would i subtract the 2y line from the y^2 line

hollow dove
#

other way around

tardy idol
#

ohh okay

hollow dove
#

the integral with 2y gives a cone thing

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with base radius 4 and height 2

#

so you can remove the smaller funnel you get from the y^2 rotation to get the desired volume

tardy idol
#

okok

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so i got 32pi/3 - 32pi/5

hollow dove
#

looks good

tardy idol
#

ohh

#

yeah

#

thats the answer LOL

#

mb i thought i did something wrong

#

would u mind if i ask some logistical questions abt these types of problems

hollow dove
#

okay

tardy idol
#

so for these types of questions

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i got this one right so i dont really need help on it

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do i not have to subtract anything from it to find the solid because it gets cut off from the bounds

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like for example

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the area i shaded in; if i wanted to find the solid from the x-axis i wouldnt have to subtract anything from it id just do bounds of 5 to 1 pi(x-1)

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bc like the rest of the equation gets cut out

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after the bounds

hollow dove
#

you subtract whenever you have a concavity basically

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for both of those, it's just a solid thing up to the axis

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it's not like a coffee cup or something which has a void between the volume and the axis of rotation

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whereas the original question is a cone with a funnel in the middle removed, which is concave

tardy idol
#

ohhhh okay okay

#

well now i have another one idk how to do lol

#

if anyone can help me with this one

#

im pretty sure the bounds are 4 and 0

hollow dove
#

yes

#

now you're integrating what y is equal to

tardy idol
#

so i tried doing ∫4 over 0 pi(x/2)^2 - ∫4 over 0 pi(sqrt(x))^2

tardy idol
hollow dove
#

consider the order of your integrals

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you subtract the thing that's closer to the axis of rotation

tardy idol
#

wdym by closer?

hollow dove
#

the parabola describes a larger volume

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because it's higher up than the line

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it's further from the x-axis over [0,4]

tardy idol
#

like further as in it contains more area?

hollow dove
#

sure

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or just

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draw vertical lines from the x-axis to the lines; you meet the line before the parabola

tardy idol
#

oh yeah its further from the axis from 0 to 4

tardy idol
#

so i set up the equations right i just subtracted in the wrong order?

hollow dove
#

yes

tardy idol
#

ooo okok

#

tysmmm i got it right

#

ur so smart

#

no more hw now :,)

#

.close

obtuse pebbleBOT
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earnest frost
#

yooo

obtuse pebbleBOT
earnest frost
#

i need help with this question

spring elk
#

whats the question?

earnest frost
#

im not that good at math btw

spring elk
#

have you done any working so far?

earnest frost
#

yeah but this is online and it keeps saying im wrong

spring elk
#

okay what working have you done?

earnest frost
#

like pi times d

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get the circumference then multiply 5

spring elk
#

okay thats the SA of the outer edge

earnest frost
#

huh

spring elk
#

the surface area of the outer edge

earnest frost
#

o yeah

spring elk
#

height*

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do you know how to get the surface area of the top and bottom

earnest frost
#

yeah but idk if its write or not

spring elk
#

thats fine

#

what was the working?

earnest frost
#

6a squared

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Right*

spring elk
#

whats the a? sorry if im missing something

earnest frost
#

the side

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i searched it up on google

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it said that

spring elk
#

im not sure what you mean sorry

earnest frost
#

well it said that for a triangular prism

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wait ill send a photo

spring elk
#

but i would use the area of a circle to work out the area of the top and bottom

spring elk
earnest frost
#

thats what i found on google

spring elk
#

thats for a cube not a cylinder

earnest frost
#

o

#

ok

spring elk
#

its alright

earnest frost
#

what is it for the cylinder then?

spring elk
#

the formula for this if SA=2pirh+2pir^2

earnest frost
#

whats pirh

#

or pir

spring elk
#

pi as in 3.14.... , r is radius and h is height

earnest frost
#

yeah

#

oooo

#

ok

#

ima write this down

#

what does the arrow pointing to the top mean

#

like squared

spring elk
#

yes

earnest frost
#

o

#

also how do you this question

spring elk
#

okay so this is alot of smaller equations

earnest frost
#

o wait no ik how to do this

#

dont you add all the faces up to get hte SA

spring elk
#

yes

obtuse pebbleBOT
#

@earnest frost Has your question been resolved?

earnest frost
#

yes

obtuse pebbleBOT
#
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obtuse pebbleBOT
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modern palm
obtuse pebbleBOT
modern palm
#

So i have the system of equations

obtuse pebbleBOT
#

@modern palm Has your question been resolved?

modern palm
#

<@&286206848099549185>

obtuse pebbleBOT
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@modern palm Has your question been resolved?

modern palm
#

<@&286206848099549185>

modern palm
#

<@&286206848099549185>

modern palm
#

<@&286206848099549185>

naive sigil
#

beta is the angle with the -x axis, not the +x axis.

obtuse pebbleBOT
#

@modern palm Has your question been resolved?

timid silo
#

helpers were dead

obtuse pebbleBOT
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timid silo
#

Am I stuck here

#

I am kinda confused here

#

I have to solve for theta

alpine raven
#

huh

#

$e^{i\theta} = \cos(\theta) + i \sin(\theta)$

warm shaleBOT
#

Herels

native inlet
#

this is an identity

#

it's always true, you cannot "solve for theta"

timid silo
#

i thought i could

thin star
#

also you can't factor out x like that

native inlet
#

nope :) it's name: Euler's Identity

#

you can derive it using Taylor Series

timid silo
#

thx

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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broken hare
obtuse pebbleBOT
broken hare
#

curious if i did this right as i dont have a way to check

obtuse pebbleBOT
#

@broken hare Has your question been resolved?

obtuse pebbleBOT
#

@broken hare Has your question been resolved?

obtuse pebbleBOT
#

@broken hare Has your question been resolved?

obtuse pebbleBOT
#

@broken hare Has your question been resolved?

drowsy burrow
#

It looks like you cropped out a good chunk of your question

obtuse pebbleBOT
#

@broken hare Has your question been resolved?

viscid gull
#

Actually wait

#

OK yeah nvm it's got things wrong

#

want me to try to draw out the answer or do you wanna give it another shot or go step by step on the mistakes or what :p

obtuse pebbleBOT
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broken hare
broken hare
#

Or if u just want to explain which parts are wrong

broken hare
obtuse pebbleBOT
#

@broken hare Has your question been resolved?

broken hare
#

<@&286206848099549185>

timid silo
#

question?

broken hare
broken hare
broken hare
#

<@&286206848099549185>

obtuse pebbleBOT
#

@broken hare Has your question been resolved?

obtuse pebbleBOT
#

@broken hare Has your question been resolved?

broken hare
#

No one knows how to solve this?

tight oasis
#

Where is the problem

tight oasis
broken hare
tight oasis
broken hare
#

Can you elaborate

tight oasis
#

For instance at x=1.5 your function f(x) should be positive

broken hare
#

I didn’t do x=1.5

#

So my line is not precise

#

But the points I did do, are those wrong?

#

That’s what I need to know to know if I’m understanding conceptually

tight oasis
#

It doesn't matter, between 1 and 2 it should be positive not null

broken hare
#

Null?

#

Do you mean 0

tight oasis
#

And between x=1 and x=2 the function should be positive

broken hare
#

x=4 should be -4?

tight oasis
#

Do you know what the integral computes?

broken hare
#

No actually it should be -3.5

#

Explain how that’s wrong

#

I just did the math again

#

Do you?

tight oasis
broken hare
#

I dont understand, are u here to help or?

#

Why is -3.5 wrong

tight oasis
#

WAIT I read your graph wrongly sorry

broken hare
#

(2.5 * -3) / 2

#
  • .025
tight oasis
#

You should graduate your axis bro 😭

broken hare
#

🙄

#

Okay so it’s right then

tight oasis
#

You just want the answer

#

I'm not giving free answer and I'm not spending my time to solve your exercise right?

broken hare
#

Bro I know what an integral is wtf

#

Just stop lol

tight oasis
#

The answer I wanted was:
The integral computes the area between 1 and x
You have to add the area that is above the x axis and substract the area that is under the x axis.

broken hare
#

Which is what I did lol

tight oasis
#

So as long as you know how to compute an area you should be ok

broken hare
#

Yes, I literally just wanted a second pair of eyes

#

I think it’s correct

tight oasis
broken hare
#

The area under the curve🤓

#

.close

obtuse pebbleBOT
#
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latent kernel
#

can someone help with this

obtuse pebbleBOT
wild scarab
#

Do you know the formula for this

tranquil sonnet
#

use power of a point

obtuse pebbleBOT
#

@latent kernel Has your question been resolved?

obtuse pebbleBOT
#

@latent kernel Has your question been resolved?

latent kernel
#

<@&286206848099549185>

eternal vortex
#

yo

latent kernel
#

how do i do this

eternal vortex
#

what?

latent kernel
#

im getting any other answer

latent kernel
normal fractal
#

so uh ED =x then (2+x)/3 * (4+(2+x)/3) =2*(2+x) or something

latent kernel
#

.close

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zinc tree
obtuse pebbleBOT
zinc tree
#

is this correct

#

i dont really get the whole compress dicompress stuff yet

#

nevermind i graphed it and its fine without that

#

.close

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opal reef
#

How i can prove is it total ?

obtuse pebbleBOT
opal reef
#

n belong to total

shut lagoon
#

What do you mean by total? Like natural numbers?

opal reef
#

Like integer

#

i try designate n for integer numbers

shut lagoon
#

But it's not an integer though

#

Not for all n

opal reef
#

ye i now, i wana designate for whats n it is integral

shut lagoon
#

oh okoko

opal reef
#

but i dont have idea

#

maybe you have any idea

#

?

shut lagoon
#

Well the first n multiple doesn't change much about whether or not the result is an integer

#

So you should be looking at n's such that $$\frac{\sqrt{(n+1)}}{\sqrt{2}}$$ is an integer

warm shaleBOT
#

Azyrashacorki

opal reef
#

i try something that

#

or that

shut lagoon
#

Now you can rewrite this as $$\sqrt{\frac{n+1}{2}}$$

warm shaleBOT
#

Azyrashacorki

shut lagoon
#

Yes I guess

#

Then you just need n such that (n+1)/2 is a perfect square

opal reef
#

ye i know but can it be prove

shut lagoon
#

What do you want to prove? It's pretty clear that your expression is an integer if and only if (n+1)/2 is a perfect square.

#

Just from that it's pretty clear that n must be odd.

opal reef
#

ok, all is clear

#

thanks

#

.close

obtuse pebbleBOT
#
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topaz tartan
obtuse pebbleBOT
topaz tartan
#

the paper says two step equations

#

can someone help step by step

scarlet gale
#

OK, you want to isolate a.

topaz tartan
#

wait so whats the difference between one step and two step

scarlet gale
#

So, if you knew a and you were calculating the right side, what would you do first and second?

#

Like let's say a = 10.

topaz tartan
#

brb sorry

#

back

topaz tartan
scarlet gale
#

Well, let's learn how to do it in general.

#

If a = 10, how do you figure out 5a + 2? What do you do first?

topaz tartan
#

uh

#

how do we find out tho

#

that a = 10

scarlet gale
#

This isn't about finding a.

topaz tartan
#

oh

scarlet gale
#

This is about how you do arithmetic.

topaz tartan
scarlet gale
#

Arithmetic is like having numbers and doing addition, subtraction, multiplication, division, exponents, roots.

topaz tartan
#

alright

scarlet gale
#

So, if I tell you a = 10, what number is 5a + 2?

topaz tartan
#

so what answer are we trying to find from 2 step equations

scarlet gale
#

No, don't worry about your problem right now.

topaz tartan
#

sorry

scarlet gale
#

Forget about two-step equations for right now.

#

If a = 10, how do you figure out what 5a + 2 is?

topaz tartan
#

5 * 10

#

since that comes first

scarlet gale
#

Then what?

topaz tartan
#

50

#

the 50 + 2

#

52

#

then*

scarlet gale
#

OK, so you multiply a by 5, then you add 2, right?

topaz tartan
#

yep

scarlet gale
#

OK, now we're going to do the opposite backwards.

topaz tartan
#

what?

scarlet gale
#

What's the opposite of adding 2?

topaz tartan
#

oh

#

sub

scarlet gale
#

Right, subtracting 2.

#

What's the opposite of multiplying by 5?

topaz tartan
#

dividing

scarlet gale
#

Right, dividing by 5.

#

So, I did the opposite for each step, and the steps are done in reverse.

topaz tartan
#

so do we divide first or subtract

#

so sub first

scarlet gale
#

Right, subtract 2 from both sides of 5a + 2 = 7.

topaz tartan
#

2-2

#

0

#

7-2

#

5

scarlet gale
#

OK, so 5a = 5, right?

topaz tartan
#

uh

#

i guess

#

i dont rly understand how tho

scarlet gale
#

OK, so our backwards opposite thing was subtracting 2, then dividing by 5, right?

topaz tartan
#

yeah

#

brb

scarlet gale
#

OK, so here's the first step:

5a + 2 = 7
5a + 2 - 2 = 7 - 2

#

Do you see how I subtracted 2 from both sides?

topaz tartan
#

ye

scarlet gale
#

OK, now we simplify it a bit.

#

What is 5a + 2 - 2?

#

If you simplify it.

topaz tartan
#

wheres the 5

scarlet gale
#

The 5?

topaz tartan
#

from the 7 we deducted out of

scarlet gale
#

Well, I went back a step because you didn't understand how I got 5a = 5.

#

So, I'm showing more clearly what I'm doing.

topaz tartan
#

ah

#

alr

#

wait now i think ik where the 5 came from

#

since 2-2 is 0

#

that cancels that out

scarlet gale
#

So, we have:

5a + 2 = 7
5a + 2 - 2 = 7 - 2

topaz tartan
#

ye

#

so we were left with 5 after subbing from both sides

#

5a = 5

scarlet gale
#

Right.

#

What was the next step in our backwards opposite thing?

topaz tartan
#

dividing by 5

#

10 / 5

scarlet gale
#

Where are you getting the 10 from?

topaz tartan
#

you said a = 10

scarlet gale
#

Oh, that was an example.

topaz tartan
#

oh

scarlet gale
#

It might be 10, it might not, but to get the backwards opposite thing, we need to get the forwards regular way thing.

topaz tartan
#

so 5 / 5

scarlet gale
#

So, I was getting you to do it the normal way, then doing it backwards and opposite.

topaz tartan
#

thats the only numbers we know in here

scarlet gale
#

Right, so what's 5a/5?

topaz tartan
#

1

scarlet gale
#

Almost.

topaz tartan
#

a = 1?

scarlet gale
#

Well, maybe.

#

5a/5 has a in it.

topaz tartan
#

oh

#

so just a alone

scarlet gale
#

Right!

#

What's 5/5?

topaz tartan
#

1

scarlet gale
#

So, we have:

5a = 5
5a**/5** = 5**/5**
a = 1

#

Do you see how to get the forwards regular way, how to do that backwards and opposite, and then you isolate the variable that way?

topaz tartan
#

uh

#

kinda hard to understand

#

but i think

scarlet gale
#

To calculate 5a + 2, you multiply a by 5 and then add 2, right?

topaz tartan
scarlet gale
#

No, that's almost the two steps.

#

We get that next.

topaz tartan
#

so the opposite is onestep

scarlet gale
#

So, do you see why you multiply a by 5 and then add 2 to calculate 5a + 2?

topaz tartan
#

5 * 5

#

wait

#

nvm

scarlet gale
#
5a + 2

Regular way:

1. Multiply by 5
2. Add 2

Backwards and opposite:

1. Subtract 2 from both sides
2. Divide both sides by 5
#

The backwards and opposite steps are the two steps.

topaz tartan
#

alright

#

wait so onestep

#

do we add both sides

scarlet gale
#

What's an example of a one-step problem?

#

From your homework or whatever.

topaz tartan
#

nvm im only focusing on 2 step

scarlet gale
#

Oh, OK.

topaz tartan
#

since thats what my paper says

#

so wait ima try to do the steps again

scarlet gale
#

OK.

topaz tartan
#

5a+2=7

#

2-2

#

0

#

7-2

#

5

#

5-5

remote pine
#

Can anyone dm

topaz tartan
#

= a

remote pine
#

Me

topaz tartan
#

a = 1

scarlet gale
#

It's unclear what steps you're doing.

#

Generally, you want to write it like this:

#
5a + 2 = 7
5a + 2 - 2 = 7 - 2
5a = 5
5a/5 = 5/5
a = 1
remote pine
scarlet gale
#

That way, you can see exactly what's going on.

topaz tartan
remote pine
#

Please

#

Please

scarlet gale
topaz tartan
#

wasnt gonna

remote pine
scarlet gale
remote pine
#

I just wanted to somome to dm cause I forgot what they were covering and I needed somome to send me practice problems cause o need to study out of school

scarlet gale
remote pine
#

Bro please

#

Can we just dm

#

I feel embarrassed to say what it is

topaz tartan
#

isnt there help channels?

scarlet gale
#

Sorry, we don't really help over DMs, you just ask in the MATH HELP (AVAILABLE) channels. People have problems with all kinds of math, so we're not going to shame you or whatever.

remote pine
#

Positive and negative integers but it’s not just adding and subtracting them it’s like simpfying fractions to see if there integers

#

Is there a channel for those

#

And absoulte vaule

scarlet gale
#

That's fine. Just ask a question in one of the MATH HELP (AVAILABLE) channels.

#

If you have a textbook, you can show a problem from the book you're stuck on.

remote pine
#

I don’t

#

We don’t use textbooks in my grade

scarlet gale
scarlet gale
remote pine
#

Wait

#

Is that 5th grade math

#

(

scarlet gale
#

It has 5th grade math, yes.

remote pine
#

Oh I see

#

I was like “ oh didn’t I do that a while back

scarlet gale
topaz tartan
#

hold on

#

yep

scarlet gale
#

OK.

topaz tartan
#

can i write it like this

#

ima send it

scarlet gale
#

OK.

remote pine
#

@scarlet gale is this like a + 2 = 7? Stuff

scarlet gale
#

Yes.

topaz tartan
#

bruh its sideways

scarlet gale
#

,rccw

warm shaleBOT
topaz tartan
#

also pardon my handwriting

scarlet gale
#

OK, that's good, except do both sides.

topaz tartan
#

i did

remote pine
scarlet gale
#

I mean you have 5 on the third line there, but you don't have 5a on the third line.

topaz tartan
#

ah

#

hold on

#

ill fix that

remote pine
#

And do you guys have positive and negative Intgers in channels?

topaz tartan
#

wait so question

scarlet gale
topaz tartan
#

does 5a come first when dividing]

remote pine
topaz tartan
#

well im in highschool

#

but were reviewing this stuff

scarlet gale
remote pine
#

Please send it

remote pine
#

Cool

scarlet gale
#
5a + 2 = 7
    -2  -2
==========
5a       5
#

Something like that.

topaz tartan
#

so does 5a come first when dividing

#

like 5a / 5

scarlet gale
#

Oh, you can do either side first.

remote pine
#

I don’t see anything with intgers on this sever

topaz tartan
#

well what if theyre different numbers

scarlet gale
#
5a + 2 = 7
    -2  -2
==========
5a       5
/5      /5
==========
 a       1
topaz tartan
#

wait

scarlet gale