#help-10

1 messages · Page 150 of 1

chilly lark
#

so like x = arcsin(1+ sqrt 2) and x = arcsin(1- sqrt 2)?

timid silo
#

Yes!!

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exactly!

chilly lark
#

oh!

timid silo
#

Okay so now

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We need to make sure that 1+sqrt(2) and 1-sqrt(2) fit the domain we defined above for the arcsin function

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What was the domain we defined for the arcsin function leila?

chilly lark
#

[-1, 1]

timid silo
#

Yep!

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So we just have to find out if 1+sqrt(2) and 1-sqrt(2) are inside that domain

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So take sqrt(2) as 1.4 for simplicity sake

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What do you have approximately for both of them

chilly lark
#

2.4 and -0.4?

timid silo
#

Yep!!

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So is 2.4 in our domain?

chilly lark
#

nope!

timid silo
#

Exactly !!

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So that solution is an extraneous solution

#

So we just have to worry about the -0.4 one

obtuse pebbleBOT
#

@chilly lark Has your question been resolved?

obtuse pebbleBOT
#
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obtuse pebbleBOT
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chrome star
obtuse pebbleBOT
chrome star
#

Ik how to factor the denominator but Idk how to factor the numerator

#

I tried the cube factoring but it won't work

timid silo
#

Is that a 9x or a 4x

chrome star
#

9x

timid silo
#

The x^3 term has a common factor of x with the term -9x

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So factor it

chrome star
#

Ahh gcf?

timid silo
#

Uh sure yes

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So what would it be

chrome star
#

Okay so it went like this

timid silo
#

,rcw

chrome star
#

Disregard x(x-9x)

warm shaleBOT
timid silo
#

Breh

timid silo
#

Well err

chrome star
#

But there's nothinf to cancel

timid silo
#

Denominator

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Is wrong

#

Like

chrome star
#

Yeahhh?

timid silo
#

The factoring is wrong

chrome star
#

Why?

timid silo
#

,w expand (x+7)(x-3)

warm shaleBOT
timid silo
#

Isn't really 9x

chrome star
#

It's 4x on the denominator

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It's 9x on the numerator

timid silo
#

Oh

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Okay my bad

chrome star
#

I thought you were pertaining to the numerator

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My bad as well

timid silo
#

Yeah no worries then yeah you are right

timid silo
#

With factoring

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Hint: difference of squares

chrome star
#

Ohhhhhhhhhh

timid silo
#

Do u see how? Haha

chrome star
#

It went like this

#

Wait its not sending

timid silo
#

Pff it's fine give it time

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Or just type it

chrome star
#

There we go

timid silo
#

Ding ding

jolly ginkgo
#

Good handwriting

chrome star
#

Should I substitute the x to 3 now?

chrome star
jolly ginkgo
#

Sure

timid silo
chrome star
#

Okayy hold up

timid silo
#

Woooo

chrome star
#

Is it correct?

timid silo
#

Good job!!

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Yeah it is

chrome star
#

Thanks!!

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It's been a great help

#

Have a nice day

timid silo
#

Yeah sorry if I sounded a bit rude, have a nice day :3

chrome star
#

.close

obtuse pebbleBOT
#
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timid silo
#

how can i remove the log from both sides?

obtuse pebbleBOT
sage geode
#

Exponentiate as you would do normally

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log_c(a) = log_c(b) so c^log_c(a) = c^log_c(b) or simply a = b

timid silo
sage geode
#

Yeah

timid silo
# sage geode Yeah

ok, so basically when i have log(a) = log(b) i can directly write a = b

sage geode
#

Yes

timid silo
#

perfect, thank you!

sage geode
#

Also make sure that a and b are both positive

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

.close

obtuse pebbleBOT
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small scaffold
obtuse pebbleBOT
small scaffold
#

Where on earth did the 2y go, and where did the lnk come from?

timid silo
#

ln1 is written as lnk

small scaffold
#

why is it ln 1?

timid silo
small scaffold
#

okay, where did the 2y go?

obtuse pebbleBOT
#

@small scaffold Has your question been resolved?

obtuse pebbleBOT
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frosty valve
#

need some explanation again:')

obtuse pebbleBOT
frosty valve
#

i was guided

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got the answer but not sure how things work

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i still don't get why it's 34/3

royal basin
#

no.

alpine raven
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Plz dont use chatgpt here ffs

royal basin
#

<@&268886789983436800> chatgpt abuse

frosty valve
royal basin
#

then you are unwelcome here.

warm canopy
#

I think mods aren't around I pinged them for this in another channel

alpine raven
#

yea cya

frosty valve
#

what's that

alpine raven
#

an AI

frosty valve
#

oh

#

so yea can anyone explain:)

frosty valve
alpine raven
warm shaleBOT
#

Herels

warm canopy
alpine raven
#

the first term is $T_1 = 8$ and the last term $T_n = 34$

warm shaleBOT
#

Herels

alpine raven
#

not really n but thats an n we want to find

frosty valve
#

found the n ald

alpine raven
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the sum of the first six terms is 58

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ah ok

frosty valve
#

i was guided

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but idk why there's 34/3

frosty valve
plucky swan
alpine raven
frosty valve
alpine raven
#

cant see*

timid silo
#

AP? 👀

alpine raven
#

S6 = 6*(8+T6)/2 = 58

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we solve for T6

frosty valve
alpine raven
#

yea basically what you wrote is T6 = T1 + (6-1)d

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but you need to find T6 first

alpine raven
timid silo
#

I'm getting 26 = [n-1] x 2/3

alpine raven
#

,w 6(x+8) = 116

warm shaleBOT
frosty valve
#

thx

alpine raven
#

with that you can have d and its over

frosty valve
#

still kinda confused on which formula to use tho

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even for other questions

timid silo
#

There are 2 main formula's

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a,n = a + [n-1] x d

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Where a,n is the desired term, a is the first number of the AP, n is the numbers and d is the common difference

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All the other sums you will have will revolve around the same, but will have twists

frosty valve
#

these 2 are the same right?

n/2(a+l)

n/2[2a+(n-1)d]

timid silo
#

Yes

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But the second one is used the most. As if you dont have the last term you can directly do the second one

frosty valve
#

alr thx

#

.close

obtuse pebbleBOT
#
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frosty valve
obtuse pebbleBOT
frosty valve
#

back again💀💀💀

high lily
#

do you know the expression/formula for the sum of the first n terms in an arithmetic series?

high lily
#

yes

frosty valve
#

n/2[2a+(n-1)d]

high lily
#

yeh

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so you have
S_n = n/2[2a+(n-1)d]
and you know everything except for the n you're being asked to find

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plug in those values and solve for that n

frosty valve
#

the moving part is confusing me

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2790=n/2[14+(n-1)5/2]

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how do i move n/2

royal basin
#

you do not "move" anything anywhere.

frosty valve
royal basin
#

expand carefully

frosty valve
#

i still don't get it💀

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sorry, do u mind if i ping u later if this channel closes?bc im being called

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sorry im back

#

@royal basin

#

is the expanding something like this

high lily
#

where's the rest of it

tame narwhal
#

solve it like you would solve any algebraic equation

frosty valve
high lily
#

whether its valid depends on what else you plan on writing

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these are just expressions

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what we're tying to get you to do is no different to expanding something like
a(b+c)

frosty valve
#

but there's another bracket in the bracket

high lily
#

don't let fractions / large expressions intimidate you

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well take it one step at a time if needed

frosty valve
#

so (n-1)5/2 is c?

high lily
#

yes

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you can view it like that if you are struggling to combine multiple steps

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(and is recommended until you get comfortable enough)

frosty valve
#

like this?

high lily
#

no

frosty valve
#

oh wait

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sorry

#

divide 2?

high lily
#

the whole right side, yes

frosty valve
#

@high lily is this right?

high lily
#

looks ok so far

frosty valve
#

ik i shouldn't be confused by fractions but i am💀

high lily
#

if you can simplify
$$2 \times \frac{3}{7}$$
you shouldn't really have an issue here

warm shaleBOT
#

ℝamonov

frosty valve
#

@high lily is this right?

#

@high lily

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ig not?

high lily
#

,w 5/2*n^2 + 23n/2 - 5580 when n=45

high lily
#

,w sum from 1 to 45 of 7 + (n-1)*5/2

high lily
#

looks good

frosty valve
#

i also got a negative num while factorising

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ik that's impossible but is there a way to check it

high lily
#

check what

frosty valve
#

if the negative num is the correct answer

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ik it's not, im just curious

high lily
#

ik it's not
there's no need to check then

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the negative value for n does not make sense in the context of the problem

frosty valve
#

alr ty😅

high lily
#

though you'd show the factorisation within the work and state reasons for the exclusion

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instead of jumping straight from the quadratic equation to the final solution by what seems to be magic

frosty valve
#

sorry, so how do i state reasons

high lily
#

something like since n>1, should be sufficient

frosty valve
#

i see, ty

obtuse pebbleBOT
#

@frosty valve Has your question been resolved?

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haughty onyx
#

hi

obtuse pebbleBOT
haughty onyx
#

i have no clue where to start here

#

they didnt give us any training yet and just asked us to attempt

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ive tried 2 cases where numerator <0 and denom >0

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and vice versa

royal basin
#

you want $\frac{x(k-x)-400}{x^2 - x + k - 38} < 0$ to be true for all $x$...

warm shaleBOT
royal basin
#

pretty sure this means both the numerator and denominator will have to have negative discriminants so they don't have any roots

haughty onyx
#

ohhh

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so i take discriminant of numerator <0 for one case and discriminant of denominator <0 for another case?

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and find largest k?

royal basin
#

those won't be cases

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you will have two inequalities, each with its own solution set, and you will want the largest integer in the INTERSECTION of those

haughty onyx
#

ohh okay tysm

obtuse pebbleBOT
#

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lean spear
#

H

obtuse pebbleBOT
lean spear
tame narwhal
#

you missed a term I think, that's why

lean spear
#

?

tame narwhal
#

use the product rule twice

lean spear
#

im not sure why

tame narwhal
#

"not sure why" what?

lean spear
#

why product rule twice

tame narwhal
#

First apply the product rule to $(t) \cdot (e^t \cot(t))$

warm shaleBOT
#

cwatson

tame narwhal
#

Then you'll have to apply the product rule for $e^t \cot(t)$

warm shaleBOT
#

cwatson

lean spear
#

what about -csc(t)

tame narwhal
#

try following what I suggested, write it all out, and see what you get

lean spear
#

ok

#

what happens next you think?

tame narwhal
#

what was your original answer, that you said was marked wrong?

lean spear
tame narwhal
#

ok, it should be $e^t \cot(t) + te^t \cot(t) - te^t \csc^2(t)$

warm shaleBOT
#

cwatson

tame narwhal
#

You missed the squared part of $\csc^2(t)$ in the last term

warm shaleBOT
#

cwatson

lean spear
#

oh

#

.close

obtuse pebbleBOT
#
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tropic leaf
#

f(n+1) = [f(n)]^2 + 1

obtuse pebbleBOT
tropic leaf
#

how do I proove there is no f from integer to integer

#

there is no integer function f

#

f(n+1) = [f(n)]^2 + 1
f(n) = [f(n-1)]^2 +1
f(n-1) even -> f(n) odd -> f(n+1) even

obtuse pebbleBOT
#

@tropic leaf Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

how to solve 1,4 ,5 and 6?

obtuse pebbleBOT
timid silo
#

do i use power rule for first?

#

this is derivatives

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

simple iron
#

It's an implicit function

timid silo
#

Could you solve it please

grizzled shore
#

!nosols

obtuse pebbleBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

grizzled shore
#

So no, we can’t just do your homework for you

timid silo
#

its not homework

#

I just found it online

#
  • I have math test tomorrow so
simple iron
#

I'll tell you how to solve it

#

you solve it by yourself

#

The fastest way to learn something is by doing it on your own

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So I'll tell you the concept

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And if you're able to do the sums on your own then you're set for the test

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So these questions are implicit functions

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Implicit functions are functions of functions

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Basically multiple functions combined to form one whole single function

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First question of example

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There is an exponential, a trigonometric function and an algebraic function

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You have to differentiate this whole thing

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There's two ways you can do this

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One is by using the chain rule

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The other directly by the outer inner method

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I prefer the direct meth

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Method**

timid silo
#

What's the direct method?

simple iron
#

You start differentiating the function from outside to inside

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SO in the case of the 1st question

timid silo
#

I think using chain rule is better

grizzled shore
#

That’s just the chain rule

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But renamed

timid silo
#

I'm gonna try using chain rule

simple iron
#

alright

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Use the chain rule then

simple iron
grizzled shore
#

It’s just rewording

simple iron
#

And while doing the direct method you start from outside

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@timid silo do you have the answer key??

timid silo
#

nope

#

im nearly done

#

ok

#

i got

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-12xcsccot(2+3x^2) . csc(2+3x^2)

simple iron
timid silo
#

sin^4x

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i solved that

#

i got -sin4x cos2x

simple iron
#

Write answer in simplest possible terms

timid silo
#

ah yes

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thank you

simple iron
timid silo
#

so it becomes

#

-12xcsc^2cot(2+3x^2) . (2+3x^2)

simple iron
#

Yep

timid silo
#

alright

#

im stuck on question 4 though

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i used the quotient rule

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but i got a complete diff answer

simple iron
#

Don't covert in terms of cos

timid silo
#

i didnt even get cos

#

i got

simple iron
#

I got sec^2 (root x) tan (root x)/(root x)

timid silo
#

csc^2x - tanxcsc^2x + sec^2x - sec^2xcotx/ 1-tanx squared

#

how

simple iron
#

Nope

#

First the exponent gives 2 sec root x then differentiate sec you get sec root x tan root x and then differentiate root x

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You get 1/2 root x

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Cancel 2 from numerator and denominator

timid silo
#

wait im confused now

#

ok question though

simple iron
#

Look

timid silo
#

we do use quotient rule though, right?

simple iron
#

Nope

#

There's no fraction how will you use quotient rule?

timid silo
#

what question is this

simple iron
#

Question 4

timid silo
#

Oh bruh

#

theres 2 number 4 questions

#

I was talking about the other one 😂

simple iron
#

OH

#

Wait then lemme solve it

timid silo
#

wait let me try to solve without looking at ur paper LOL

simple iron
#

What grade are you in?

timid silo
#

11th

timid silo
#

could u explain how u got it?

simple iron
timid silo
#

Huh

simple iron
#

Differentiate using the first principle and check for yourself

timid silo
#

Wait wdym

simple iron
#

Different root x

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Differentiate

timid silo
#

square root x is 1/2x^-1/2 right

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ohh

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oh i get u i get u

simple iron
timid silo
#

i thought we didnt have to differentiate

simple iron
timid silo
#

so first we rewrite sec root x as

simple iron
timid silo
#

sec root x tan root x

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then diff the root x

timid silo
#

i never knew this lmao

simple iron
#

It's from my 11th grade textbook

timid silo
#

could you share some important details

#

because mine has nothing

simple iron
#

what all is there in your syllabus?

#

What do you have for your test tmrw?

timid silo
#

i have

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trigonometric derivatives and implecit differentiation

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and youtube isnt helping somehow

#

cant find any good math teachers

simple iron
#

Khan academy

#

Are you good at functions?

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What country are you from?

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is the syllabus difficult?

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Learn all 6 trig derivatives

#

And do you know first principle of differenciation?

timid silo
timid silo
simple iron
#

Okay then that's okay

timid silo
#

so im just solving as much as i can

simple iron
timid silo
#

its pretty much the same

#

i could send u our math book

simple iron
#

Ah that's okay

simple iron
#

Are you good with manipulating trig functions?

#

Just keep doing implicit functions

timid silo
timid silo
#

@simple iron can i solve number 2 with chain rule?

simple iron
#

Yes you can

timid silo
#

im trying to get better this year so im alright

#

okay

#

does it become 2sinxcosx -cscxcotx?

simple iron
#

It's an exponential function and algebriac function

timid silo
#

and 2sinxcosx is sin2x

#

-2sinx?

#

huh

simple iron
#

2 (sin x +cos x) (cos x -cosec x sec x)

#

Sorry this is the correct answer

timid silo
#

where did cosx come from?

#

so the question is (sinx +cscx)^2 right

#

then we do 2sinx right

#

and sinx is cosx

#

so 2sinxcosx?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

#
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timid silo
#

@simple iron thanks

obtuse pebbleBOT
#
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• Be polite and have a nice day!

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lapis vortex
#

help please I just need to be helped with the steps

lapis vortex
#

<@&286206848099549185>

fierce lagoon
#

!15m

obtuse pebbleBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

sick jewel
#

what do you want to find?

lapis vortex
#

the area

sick jewel
#

Ah

#

find the area of triangle ABO = triangle BOC

fierce lagoon
#

The area of a kite is half the product of the diagonals

sick jewel
#

then find the area of triangle AOD = triangle COD

fierce lagoon
#

So basically 1/2 • AC • BD

sick jewel
#

do what he told

lapis vortex
#

so then 30 ?

fierce lagoon
#

No

#

Bruh don't just tell him the answe

sick jewel
#

30 is the area for triangle COD = AOD

sick jewel
lapis vortex
#

it's ok

fierce lagoon
lapis vortex
#

I tried

fierce lagoon
#

What is AC

lapis vortex
#

12

fierce lagoon
#

What is BD

lapis vortex
#

12

fierce lagoon
#

So what is 1/2 • 12 • 12

lapis vortex
#

72

#

thank you

fierce lagoon
#

Go get your own channel

#

I need to close this one

#

Go to a vacant one

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @fierce lagoon

Use .reopen if this was a mistake.

#
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manic mango
#

Proof that for every triangle that is true 1<cos(α)+cos(β)+cos(γ)<=3/2

manic mango
#

I tried doing it and cant figure out how to

obtuse pebbleBOT
#

@manic mango Has your question been resolved?

obtuse pebbleBOT
#
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shadow lava
obtuse pebbleBOT
shadow lava
#

something is not right here, when I plug in x to the original equation I get different answers for both sides

dark stirrup
#

,w (-2ln(2)-7ln(3))/(2ln(2)-ln(3))

kind hawk
#

should be $\frac{-2\ln2-7\ln3}{2\ln2-\ln3}$ instead of $-\frac{2\ln2-7\ln3}{2\ln2-\ln3}$

warm shaleBOT
#

Denascite

shadow lava
kind hawk
#

the location of the minus

shadow lava
#

oh it's distributed

#

hmmm

dark stirrup
#

$-(a-b)=-a+b \ne -a-b$

warm shaleBOT
shadow lava
#

ya

#

OK I need to remember that

#

I can't just pull first minus sign from numerator like that and put it in front of a rational

#

well, sometimes I can lol

#

like -7/3 is -(7/3)

#

but only because it's monomial on top and bottom?

#

with polynomial it's different?

#

or even -7/(x+3) I don't know if I could also write it -(7/x+3)?

#

is it implied distribution to numerator or denominator?

trim portal
shadow lava
#

weird

#

same thing in this case

warm shaleBOT
#

MathIsAlwaysRight

trim portal
#

is also equal to that

shadow lava
#

so what's the rule when i'm allowed to move the - sign at beginning of numerator or denominator to be in front of the fraction?

#

because sometimes it works, sometimes it doesn't

#

in my case above it doesn't

trim portal
#

as long as it's in front of WHOLE the numerator in parenthesis or WHOLE the denominator in parenthesis, you can

shadow lava
#

oh I see, I see

#

thank you

#

that makes better sense

#

so 7/(-x+3) would not work

#

that's like saying 7/(3-x)

#

so brackets are super important for fractions

#

can make a big difference, with or without

#

i always thought brackets were implied with fractions

#

like they are always there

#

invisible

trim portal
#

what you could do is 7/(3-x)=7/-(x-3)=-7/(x-3)

shadow lava
#

like a jail for the entire numerator and denominator

shadow lava
#

so brackets are optional for fractions, adding them around the entire numerator, or entire denominator doesn't make any difference

#

because it's already implied?

#

it's like giving double brackets (())

trim portal
#

$\frac{x+1}{x+2}$

warm shaleBOT
#

MathIsAlwaysRight

shadow lava
trim portal
shadow lava
#

oh

#

yeah of course, you mean Latex?

trim portal
shadow lava
#

ya

shadow lava
trim portal
#

yeah, if you write it on paper you dont need to use parenthesis

shadow lava
#

you can just assume brackets are there with fractions. always and forever. the entire numerator is being divided by the entire denominator. we just don't show the brackets

#

when there is a divisor line

#

by default

#

but still important to use brackets where necessary

#

ty that helps me to understand what's really going on

#

do you think math could be easier to teach if we always used brackets for numerator and denominator? even in fraction form when writing it. or it would be worse?

trim portal
shadow lava
#

the complete implications of that, maybe

shadow lava
#

always with paranthesis

warm shaleBOT
#

MathIsAlwaysRight

trim portal
#

The parenthesis are just unnecessary I guess

shadow lava
#

that part yes, but signs could still be a tad bit confusing, as per the above example

trim portal
#

I wouldnt complicate the notation too much

shadow lava
#

OK heheh, just curious if it could be any better for those starting out..

#

I think the big one everyone agrees on is sin^(-1). Bad bad bad.

#

Bad notation.

trim portal
#

This was confusing me too, but after few examples you get familiar with the notation

trim portal
shadow lava
#

lol it doesn't mean 1/sin

trim portal
#

yeah

#

it's arcsin

#

but arcsin is way too long

shadow lava
#

lol, only 1 extra character

#

actually it's much easier to write arcsin than sin^(-1) in latex

#

sin^(-1) is now 2 characters longer than arcsin

trim portal
#

raising function to negative one is general notation for inverse, but I've never seen arc outside trig

#

the ^-1 later becomes a general notation for inverse

tardy epoch
tardy epoch
#

arcsin and csc is best and clear

trim portal
#

well i guess im in the 1% of people who dont mind it

tardy epoch
#

For function inverse and multiplicative inverse, respectively

shadow lava
# trim portal well i guess im in the 1% of people who dont mind it

well you can thank this guy for it
https://en.wikipedia.org/wiki/John_Herschel

Sir John Frederick William Herschel, 1st Baronet (; 7 March 1792 – 11 May 1871) was an English polymath active as a mathematician, astronomer, chemist, inventor, experimental photographer who invented the blueprint and did botanical work.Herschel originated the use of the Julian day system in astronomy. He named seven moons of Saturn and four m...

#

according to Google..

trim portal
#

I will keep using sin^(-1) together with asin

#

asin is acceptable, it's at least not so long

tardy epoch
#

Oh asin is also good

#

I'm afraid it'll be confused with a * sin for a constant a, but context usually rules that out

shadow lava
#

ya I would assume it as a * sin too, dunno if I've seen it written that way before

#

my instructors usually just write it as arcsin, so it's crystal clear

#

lol are mathematicians really this lazy to avoid writing "rc"?

#

arcsin is less confusing, no need to double check if "a" is a constant, if (^1) is an inverse, it just means arcsin

#

I dunno why John Herschel even invented this notation to begin with

#

like if there is anything you can do with sin^(-1) that you can't do with arcsin?

#

and now it's like a cancer in all of math, can't get rid of it

obtuse pebbleBOT
#

@shadow lava Has your question been resolved?

#
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#
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balmy steeple
#

I have a quick question:

obtuse pebbleBOT
balmy steeple
#

lets say that F(t, P(t)) = f(t,P(t))-g(P(t))

#

what would the partial derivative of F regarding t be?

#

When I do it, I think that I have to derive both f() and g() since they both depend on t. But in the solutions the result is simply f't(t, P(t) with no g() at all. Why is that?

#

Also the task states that P is defined "implicitly" through t, and sometimes it is written just P, sometimes P(t).

#

<@&286206848099549185>

hard anvil
balmy steeple
#

nice

hard anvil
#

so what's the problem? what kind

#

calculus? topology? algebra?

balmy steeple
#

deriving I guess

hard anvil
#

right?

#

ok leme try then

balmy steeple
#

the entire block yes. the last sentence is just additional info.

idle sandal
#

g() is just a constant so when differentiating with respect to t it’s zero

balmy steeple
idle sandal
#

Though it’s been ages since I took diff eq so could be wrong

balmy steeple
#

<@&286206848099549185>

idle sandal
#

Sorry let me think a sec

balmy steeple
#

np

obtuse pebbleBOT
#

@balmy steeple Has your question been resolved?

obtuse pebbleBOT
#

@balmy steeple Has your question been resolved?

obtuse pebbleBOT
#

@balmy steeple Has your question been resolved?

vast linden
#

however you can also try to have a total derivative with respect to t, and it’s marked as $\frac{d}{dt}$ instead of $\frac{\partial}{\partial t}$

warm shaleBOT
vast linden
#

and then you’ll get f’t(t, P(t)) + f’P(t, P(t)) * P’(t) -g’(P(t)) * P’(t)

balmy steeple
#

alright thanks, let me ask a super quick follow up question though:

#

in the case of f(x,y) = 3x^2+5y where y is a function of x

the partial derivative regarding x would still be simply 6x then?

vast linden
#

exactly

balmy steeple
#

Okay thanks

#

I am testing something out rn to check whether I fully understood it, so I may write something in a few minutes again

#

I think I got it, thanks for clearing it up

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @balmy steeple

Use .reopen if this was a mistake.

#
Available help channel!

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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shadow lava
obtuse pebbleBOT
shadow lava
#

For #1 I always remember this (easy)

#

but for #2 I keep forgetting..

#

Anybody else the same way? Can you convert #2 to #1 if you forget?

sonic anchor
#

from 2 -> 1 take log_a for both sides

shadow lava
#

oh interesting..

#

wait, how would you take it for both sides?

#

log_a(a^(log_a(x)) = log_a(x)

#

log_a(x) = log_a(x)

sonic anchor
#

ok maybe its not exactly 2->1 but it atleast should convince you that 2 is true

#

which is the best way to remember something imo

shadow lava
#

it's confusing lol. I feel like I'm doing logarithm in reverse

#

reverse engineering it

#

for #2

sonic anchor
#

yes its the inverse

#

that kind of what reverse engineering is i guerss

nocturne minnow
#

Looking at 1 vs 2, you have log(a^x) vs log(x), and for log(x) you can't have negative numbers

shadow lava
#

not log, log_a(a^x)

nocturne minnow
#

Or were you not referring to the domain?

shadow lava
#

log by default is log_10

nocturne minnow
shadow lava
#

but you said log(a^x)

nocturne minnow
#

I was not feeling to type out _a

shadow lava
sonic anchor
#

i think hes talking about the equality

#

itself

wild swallow
#

in math, log is always natural log

shadow lava
#

who put X for this?

sonic anchor
#

but its just that they are inverses

shadow lava
sonic anchor
#

log is mostly used for ln

#

ive nevers een it used for log_10

static beacon
atomic agate
wild swallow
#

yes really

static beacon
#

log is normally base 10

nocturne minnow
static beacon
#

ln is natural log

shadow lava
#

log is base 10

wild swallow
#

not software

atomic agate
wild swallow
#

in general

sonic anchor
#

ok, who cares

#

what log is

#

lol

wild swallow
#

log is used for natural

shadow lava
#

no.

static beacon
#

nope

shadow lava
#

ln is used for natural log

#

lg is used for base 2

nocturne minnow
shadow lava
#

and log is used for base 10

atomic agate
static beacon
#

Casio calculators log = base 10

nocturne minnow
shadow lava
#

yes

sonic anchor
#

who

#

cares

#

its not important

wild swallow
#

that's because its catered for non math people

static beacon
#

have yall not used a calculator?

shadow lava
wild swallow
#

in pure math almost always log = natural log

static beacon
wooden cipher
#

If you watch 3b1b's video on the triangle of power, he states that base 10, e, and 2 are used for logs in different contexts

sonic anchor
wild swallow
#

the computer scientists want base 2

static beacon
wild swallow
#

other people want base 10

#

but the mathematicians almost always use base e

shadow lava
nocturne minnow
#

And I'm referring to physical calculators, like ti calculators where it has log and ln, where log is log_10

shadow lava
static beacon
#

same with casio

shadow lava
static beacon
#

real question is why u on light mode

shadow lava
wooden cipher
#

Bros pulling up receipts 💀💀

static beacon
#

well

#

fair enough

sonic anchor
#

i agree with snow, i have never seen anyone use log for log_10

#

inside math context

#

but a lot of people on here do so i just go with it

#

cause it doesnt matter

#

what you call something lol

#

as long as you are clear its what oyu mean

wild swallow
#

who cares about always vs almost always it's like there's gonna be a few use cases but it's rare

static beacon
#

That is such a lie

wooden cipher
#

Ive seen it for a precalc class and never again

nocturne minnow
wild swallow
#

for the engineers

sonic anchor
#

i have never used a physical calculator

shadow lava
#

literally all calculators approved for math exams are log base 10

wooden cipher
#

ANYWAY

shadow lava
#

if you wanna change the base there is another button, log[]

wooden cipher
#

Why do you ask?

shadow lava
#

where you can use your own base

nocturne minnow
#

If you've used ti calcs then you know that calculators use log as log_10

wild swallow
#

mathematicians don't design calculators

sonic anchor
#

also physical cals are not for pure mathematicians

static beacon
sonic anchor
#

i never see anyone use a physical calc lol

#

in a maths calss

nocturne minnow
shadow lava
timid silo
#

potential bingo square unlocked!

"Argument about whether log is base e,2, or 10"!

static beacon
sonic anchor
static beacon
#

u sure?

#

from what im seeing u dont know what a physical calculator looks like

sonic anchor
#

i know what it looks like. i just never see anyone use it in a maths class

#

and ive never used it myself either

static beacon
#

so what do u use in exams?

fading quest
#

its just notation, generally i find that log without any base has about the same chance of referring to natural log as base 10

nocturne minnow
sonic anchor
#

im 23

#

idkw hat that is millenial or no

static beacon
#

:

fading quest
#

also physical calcs are incredibly common for exams

static beacon
#

Yea

fading quest
#

which i believe my calc also has log for base 10 and ln for natural base

nocturne minnow
#

That is an absolute lie. There is no way you are 23 and have not used a physical calc

fading quest
#

if you dont do math related exams you probably never need a calculator

static beacon
#

hes cappin

fading quest
#

a physical one at least

static beacon
#

Maths is mandatory in my country and probably most others

#

until 16

#

in which the test u take u need a calculator

nocturne minnow
#

If you don't do any stem classes, then you'll never need a physical ti calc that stem uses, like casio or ti 84

shadow lava
fading quest
#

like accounting

timid silo
#

i love how this channel just turned into a big pissing match xd

#

what even was the question xd

shadow lava
sonic anchor
nocturne minnow
#

Business has their own economics related calc

fading quest
sonic anchor
#

i used maple in highschool and in elementary, we used geogebra for graphs and no calculators

nocturne minnow
shadow lava
#

found the part where this channel #help-10 went off the rails

sonic anchor
fading quest
nocturne minnow
sonic anchor
#

maple is an application. wifi is turned off that dya

static beacon
fading quest
#

in my uni the only requirement is that its just a regular scientific calculator with no special functions. there are thousands of different calculators i can use. id reckon its the same for business

static beacon
shadow lava
#

trig questions are a lot easier with calculator. i know the unit circle, but an approved exam calculator tells me and it's much faster

frosty spoke
#

never needed a calculator for an exam in any of the STEM classes I took

frosty spoke
#

except for one bullshit class in economics

fading quest
static beacon
#

Uk

fading quest
#

ah, well uk is basically the same

#

in most regards

#

capitalist hell

frosty spoke
#

my whole guideline was

#

if you needed a calculator with functions restricted that a laptop could provide

#

the class probably was a joke

shadow lava
static beacon
#

as in they have more functions

nocturne minnow
#

Anyways this has gone off the rails, peace out

shadow lava
sonic anchor
#

usually you know what log means from context anyways

#

so it doesnt matter

static beacon
#

yea

sonic anchor
#

i will not correct my proffessor for example

static beacon
#

it means base 10

sonic anchor
#

when he uses log for natural log

#

and say pysical calc disagrees with youi

#

its moronic

#

mathj is more than this

fading quest
#

if i see log alone i will generally ask what base it is since its extraordinarily common for teachers to use log for base e

sonic anchor
#

stop getting hung up on thsi stuff

fading quest
#

which i honestly find kinda dumb, ln is slightly less effort and removes any potential confusion

shadow lava
fading quest
#

yeah thats what im saying, i would not write log ever for base e

fading quest
#

but a lot of people do

static beacon
#

but tbf

nocturne minnow
sonic anchor
#

i do 💀

static beacon
#

Most programs (non calcs) do take log as base e

sonic anchor
#

i like log better

fading quest
#

and now ive seen so many log being base e

#

that i need to ask

static beacon
fading quest
#

if people just stopped using log for base e then id always assume base 10. but thats just not the case

sonic anchor
#

i rarely see people use log with different than base e

#

maybe thats just why

#

i like log as base e

fading quest
#

do you just dislike ln?

#

i dont see the point in using log instead of ln

frosty spoke
#

yeah it looks too much like in

sonic anchor
#

yes log looks prettier

static beacon
#

???

#

ln is pretty

frosty spoke
#

I feel like you see log_10 a lot in things like engineering

#

but with things involving calculus, then it's log_e

sonic anchor
fading quest
#

guess it makes sense why im middle ground then. physics moment HahaBall

frosty spoke
#

log_2 is very popular in computer science

static beacon
frosty spoke
#

yes

#

,w integrate 1/x

warm shaleBOT
nocturne minnow
nocturne minnow
#

That's from geeks for geeks

fading quest
#

you can easily see why i would just ask what base it is instead of just assume its base 10. personally i dont see a reason to use log for natural since there is literally no downside and a slight upside (avoiding confusion) to using ln over it

sonic anchor
#

notational definitions vary even from paper to paper

#

like how you type out vectors

frosty spoke
#

some notation is truly awful

nocturne minnow
#

Also a good chunk of the internet searches, I'm looking at, uses log as log_10

sonic anchor
#

but i will still use log as base e liol

shadow lava
sonic anchor
#

i just like it more

#

also when you are speaking

#

i just say log

#

so i also typ elog

#

yknow?

static beacon
#

NAW THE CLOCKS WENT foward and now its 2 am

fading quest
#

i always say "el en" when referring to natural log. so i guess thats a slight reason to use "log" instead since its 1 syllable instead of 2

#

really micro managing the efficiency of a potential lecture there

nocturne minnow
#

I'm sticking to what I know and is used to and that's log is log_10 and ln is log_e, you guys do you

sonic anchor
#

people only care on the internet anyways it seems

fading quest
shadow lava
#

thanks for the super checkmark @static beacon

sonic anchor
#

did you actually get an answer to your question

shadow lava
#

no but I will close this now

static beacon
shadow lava
#

I gotta go the gym lol

static beacon
#

i gotta go to sleep#

shadow lava
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @shadow lava

Use .reopen if this was a mistake.

obtuse pebbleBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

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untold mica
#

Hi. Doing disk and washer methods and not sure how to do the formula.

untold mica
#

The original equations are y=1/(1+x), y=0, x=0, x=3

timid silo
untold mica
#

But it’s revolves around y=4

#

Sorry. Forgot to put that in

warm shaleBOT
#

hannibal

untold mica
#

Oops. Got it now

timid silo
#

if it's about the y-axis, you should integrate wrt y

#

so dy

untold mica
#

But the circles are in terms of y, so to find the radius you need to use x

#

Input x, output y

#

Am I wrong?

obtuse pebbleBOT
#

@untold mica Has your question been resolved?

untold mica
#

<@&286206848099549185>

spring marsh
#

Huh

#

I’m a helper?

untold mica
#

Maybe?

spring marsh
#

Didn’t realize

river hare
#

Me and Neelus are in 7th grade

#

Lol

#

We don’t understand that

spring marsh
#

We can tinder stand this stuff

untold mica
#

Ok. I’ll ask later

#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @untold mica

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#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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spark field
obtuse pebbleBOT
spark field
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can sm1 help me with this

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what am i doing wrong with the ratio test

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.close

obtuse pebbleBOT
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#
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spark field
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wanted to ask

obtuse pebbleBOT
spark field
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1st one converges becuz cn is just constant

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2nd series converges because its just a constant * a constant?

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3rd doesnt because it alternates

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same for 4th?

civic zealot
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your justifications don't make sense

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what do you mean it's a constant? or constant times a constant?

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and when x = -4, the series is alternating and the series converges.

civic zealot
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each term is constant, but the terms are not all the same...

spark field
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its centered around

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1.5

civic zealot
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you know when $x=-4$ the series is convergent. So, necessarily, $\lim_{n\to\infty}c_n(-4)^n =0$. So $0\leq|c_n| <4^{-n}$

warm shaleBOT
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Zybikron

spark field
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so would it be

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-4<x<7

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is it not that?

civic zealot
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ah, true, so you can say something like $7^{-n}\leq |c_n| < 4^{-n}$

warm shaleBOT
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Zybikron

spark field
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@civic zealot

obtuse pebbleBOT
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@spark field Has your question been resolved?

obtuse pebbleBOT
#
Channel closed

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obtuse pebbleBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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tame relic
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.open

obtuse pebbleBOT
tame relic
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how does he get -55?

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-350/-4 just gives me 87.5

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cant wrap my head around it

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oh my god

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Im too tired

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its okay bro sorry to waste your time

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Just realized my error

latent walrus
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no worries

tame relic
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Fucking forgot what unit Im even doing

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.close

obtuse pebbleBOT
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Channel closed

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tame relic
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thanks again

obtuse pebbleBOT
#
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warm siren
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<@&268886789983436800> why did my question chhanel turn to hidden?

idle thunder
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were you asking about the centroid question or something else?

warm siren
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no something else