#help-10
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oh!
Okay so now
We need to make sure that 1+sqrt(2) and 1-sqrt(2) fit the domain we defined above for the arcsin function
What was the domain we defined for the arcsin function leila?
[-1, 1]
Yep!
So we just have to find out if 1+sqrt(2) and 1-sqrt(2) are inside that domain
So take sqrt(2) as 1.4 for simplicity sake
What do you have approximately for both of them
2.4 and -0.4?
nope!
Exactly !!
So that solution is an extraneous solution
So we just have to worry about the -0.4 one
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Ik how to factor the denominator but Idk how to factor the numerator
I tried the cube factoring but it won't work
Is that a 9x or a 4x
9x
First factor the obvious first factor, x
The x^3 term has a common factor of x with the term -9x
So factor it
Ahh gcf?
,rcw
Disregard x(x-9x)
Breh
But there's nothinf to cancel
Yeahhh?
The factoring is wrong
Why?
,w expand (x+7)(x-3)
Isn't really 9x
Yeah no worries then yeah you are right
Anyways you can actually continue
With factoring
Hint: difference of squares
Ohhhhhhhhhh
Do u see how? Haha
Ding ding
Good handwriting
Should I substitute the x to 3 now?
Haha thank you
Sure
Yeah
Woooo
Is it correct?
Yeah sorry if I sounded a bit rude, have a nice day :3
.close
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how can i remove the log from both sides?
Exponentiate as you would do normally
log_c(a) = log_c(b) so c^log_c(a) = c^log_c(b) or simply a = b
so to remove the log i have to apply always the exp?
Yeah
ok, so basically when i have log(a) = log(b) i can directly write a = b
Yes
perfect, thank you!
Also make sure that a and b are both positive
yes
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Where on earth did the 2y go, and where did the lnk come from?
ln1 is written as lnk
why is it ln 1?
-ln(1-y^2) = ln(1/1-y^2) = ln1 - ln(1-y^2)
okay, where did the 2y go?
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need some explanation again:')
i was guided
got the answer but not sure how things work
i still don't get why it's 34/3
no.
Plz dont use chatgpt here ffs
<@&268886789983436800> chatgpt abuse
is that a bot?
then you are unwelcome here.
I think mods aren't around I pinged them for this in another channel
what's that
an AI
this
where
so an arithmetic progression is written like this :
$T_n = T_1 + (n-1)d$
Herels
the first term is $T_1 = 8$ and the last term $T_n = 34$
Herels
not really n but thats an n we want to find
found the n ald
.
ah okay i missed that somehow
do we know d ?
cant see*
AP? 👀
so i first did 34=8+(6-1)d and it was wrong, so they told me to replace 34 with 34/3
with that
What you did shouldnt be wrong
I'm getting 26 = [n-1] x 2/3
,w 6(x+8) = 116
with that you can have d and its over
There are 2 main formula's
a,n = a + [n-1] x d
Where a,n is the desired term, a is the first number of the AP, n is the numbers and d is the common difference
All the other sums you will have will revolve around the same, but will have twists
these 2 are the same right?
n/2(a+l)
n/2[2a+(n-1)d]
Yes
But the second one is used the most. As if you dont have the last term you can directly do the second one
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do you know the expression/formula for the sum of the first n terms in an arithmetic series?
sn formula?
yes
n/2[2a+(n-1)d]
yeh
so you have
S_n = n/2[2a+(n-1)d]
and you know everything except for the n you're being asked to find
plug in those values and solve for that n
you do not "move" anything anywhere.
so how do i continue?
expand carefully
i still don't get it💀
sorry, do u mind if i ping u later if this channel closes?bc im being called
sorry im back
@royal basin
is the expanding something like this
where's the rest of it
solve it like you would solve any algebraic equation
stuck
whether its valid depends on what else you plan on writing
these are just expressions
what we're tying to get you to do is no different to expanding something like
a(b+c)
but there's another bracket in the bracket
don't let fractions / large expressions intimidate you
well take it one step at a time if needed
so (n-1)5/2 is c?
yes
you can view it like that if you are struggling to combine multiple steps
(and is recommended until you get comfortable enough)
like this?
no
the whole right side, yes
looks ok so far
ik i shouldn't be confused by fractions but i am💀
if you can simplify
$$2 \times \frac{3}{7}$$
you shouldn't really have an issue here
ℝamonov
,w 5/2*n^2 + 23n/2 - 5580 when n=45
,w sum from 1 to 45 of 7 + (n-1)*5/2
looks good
i also got a negative num while factorising
ik that's impossible but is there a way to check it
check what
ik it's not
there's no need to check then
the negative value for n does not make sense in the context of the problem
alr ty😅
though you'd show the factorisation within the work and state reasons for the exclusion
instead of jumping straight from the quadratic equation to the final solution by what seems to be magic
sorry, so how do i state reasons
something like since n>1, should be sufficient
i see, ty
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hi
i have no clue where to start here
they didnt give us any training yet and just asked us to attempt
ive tried 2 cases where numerator <0 and denom >0
and vice versa
you want $\frac{x(k-x)-400}{x^2 - x + k - 38} < 0$ to be true for all $x$...
Ann
pretty sure this means both the numerator and denominator will have to have negative discriminants so they don't have any roots
ohhh
so i take discriminant of numerator <0 for one case and discriminant of denominator <0 for another case?
and find largest k?
those won't be cases
you will have two inequalities, each with its own solution set, and you will want the largest integer in the INTERSECTION of those
ohh okay tysm
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H
you missed a term I think, that's why
?
use the product rule twice
im not sure why
"not sure why" what?
why product rule twice
First apply the product rule to $(t) \cdot (e^t \cot(t))$
cwatson
Then you'll have to apply the product rule for $e^t \cot(t)$
cwatson
what about -csc(t)
try following what I suggested, write it all out, and see what you get
what was your original answer, that you said was marked wrong?
ok, it should be $e^t \cot(t) + te^t \cot(t) - te^t \csc^2(t)$
cwatson
You missed the squared part of $\csc^2(t)$ in the last term
cwatson
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f(n+1) = [f(n)]^2 + 1
how do I proove there is no f from integer to integer
there is no integer function f
f(n+1) = [f(n)]^2 + 1
f(n) = [f(n-1)]^2 +1
f(n-1) even -> f(n) odd -> f(n+1) even
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how to solve 1,4 ,5 and 6?
@timid silo Has your question been resolved?
Could you solve it please
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
So no, we can’t just do your homework for you
I'll tell you how to solve it
you solve it by yourself
The fastest way to learn something is by doing it on your own
So I'll tell you the concept
And if you're able to do the sums on your own then you're set for the test
So these questions are implicit functions
Implicit functions are functions of functions
Basically multiple functions combined to form one whole single function
First question of example
There is an exponential, a trigonometric function and an algebraic function
You have to differentiate this whole thing
There's two ways you can do this
One is by using the chain rule
The other directly by the outer inner method
I prefer the direct meth
Method**
What's the direct method?
You start differentiating the function from outside to inside
SO in the case of the 1st question
I think using chain rule is better
I'm gonna try using chain rule
Well chain rule you start from the inside
It’s just rewording
And while doing the direct method you start from outside
@timid silo do you have the answer key??
The 5th question is it prove dy/dx+ sin4x or sin^4(x)???
Yes combine both cosec to get cosec squared
Write answer in simplest possible terms
Okay
Yep
alright
im stuck on question 4 though
i used the quotient rule
but i got a complete diff answer
Don't covert in terms of cos
I got sec^2 (root x) tan (root x)/(root x)
Nope
First the exponent gives 2 sec root x then differentiate sec you get sec root x tan root x and then differentiate root x
You get 1/2 root x
Cancel 2 from numerator and denominator
we do use quotient rule though, right?
what question is this
Question 4
wait let me try to solve without looking at ur paper LOL
What grade are you in?
11th
Dy/dx(root x)= 1/2 rootx
Huh
Differentiate using the first principle and check for yourself
Wait wdym
Well that's one way to write it as well
i thought we didnt have to differentiate
You do
so first we rewrite sec root x as
It's from my 11th grade textbook
i have
trigonometric derivatives and implecit differentiation
and youtube isnt helping somehow
cant find any good math teachers
Khan academy
Are you good at functions?
What country are you from?
is the syllabus difficult?
Learn all 6 trig derivatives
And do you know first principle of differenciation?
i'm pretty good won't say im bad
iraq
Okay then that's okay
nope but my teacher brings hard questions
so im just solving as much as i can
Aah I don't know much about the syllabus from there
Ah that's okay
Okay
Are you good with manipulating trig functions?
Just keep doing implicit functions
what's that?
@simple iron can i solve number 2 with chain rule?
im trying to get better this year so im alright
okay
does it become 2sinxcosx -cscxcotx?
It's an exponential function and algebriac function
where did cosx come from?
so the question is (sinx +cscx)^2 right
then we do 2sinx right
and sinx is cosx
so 2sinxcosx?
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@simple iron thanks
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help please I just need to be helped with the steps
<@&286206848099549185>
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what do you want to find?
the area
The area of a kite is half the product of the diagonals
then find the area of triangle AOD = triangle COD
So basically 1/2 • AC • BD
so then 30 ?
30 is the area for triangle COD = AOD
sry
it's ok
@lapis vortex did you do what I told you to do
I tried
What is AC
12
What is BD
12
So what is 1/2 • 12 • 12
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Proof that for every triangle that is true 1<cos(α)+cos(β)+cos(γ)<=3/2
I tried doing it and cant figure out how to
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something is not right here, when I plug in x to the original equation I get different answers for both sides
,w (-2ln(2)-7ln(3))/(2ln(2)-ln(3))
should be $\frac{-2\ln2-7\ln3}{2\ln2-\ln3}$ instead of $-\frac{2\ln2-7\ln3}{2\ln2-\ln3}$
Denascite
i don't see the difference?
the location of the minus
$-(a-b)=-a+b \ne -a-b$
SWR
ya
OK I need to remember that
I can't just pull first minus sign from numerator like that and put it in front of a rational
well, sometimes I can lol
like -7/3 is -(7/3)
but only because it's monomial on top and bottom?
with polynomial it's different?
or even -7/(x+3) I don't know if I could also write it -(7/x+3)?
is it implied distribution to numerator or denominator?
you can write that
MathIsAlwaysRight
is also equal to that
so what's the rule when i'm allowed to move the - sign at beginning of numerator or denominator to be in front of the fraction?
because sometimes it works, sometimes it doesn't
in my case above it doesn't
as long as it's in front of WHOLE the numerator in parenthesis or WHOLE the denominator in parenthesis, you can
oh I see, I see
thank you
that makes better sense
so 7/(-x+3) would not work
that's like saying 7/(3-x)
so brackets are super important for fractions
can make a big difference, with or without
i always thought brackets were implied with fractions
like they are always there
invisible
what you could do is 7/(3-x)=7/-(x-3)=-7/(x-3)
like a jail for the entire numerator and denominator
oh..
so brackets are optional for fractions, adding them around the entire numerator, or entire denominator doesn't make any difference
because it's already implied?
it's like giving double brackets (())
if it's in text you should definitely add them
$\frac{x+1}{x+2}$
MathIsAlwaysRight
wdym by in text?
If you write x+1/x+2 I am not sure if it's x+(1/x)+2 or x+(1/(x+2)) or whatever it is
but when you use texit, you dont need to use parenthesis
ya
but when writing it like this, no need for brackets
yeah, if you write it on paper you dont need to use parenthesis
you can just assume brackets are there with fractions. always and forever. the entire numerator is being divided by the entire denominator. we just don't show the brackets
when there is a divisor line
by default
but still important to use brackets where necessary
ty that helps me to understand what's really going on
do you think math could be easier to teach if we always used brackets for numerator and denominator? even in fraction form when writing it. or it would be worse?
I dont think it would be easier
i think for a lot of new students maybe they don't understand this part
the complete implications of that, maybe
or do you mean more work to write it?
always with paranthesis
MathIsAlwaysRight
The parenthesis are just unnecessary I guess
that part yes, but signs could still be a tad bit confusing, as per the above example
if it was possible with signs, it would imply that what I've written would be also true
I wouldnt complicate the notation too much
OK heheh, just curious if it could be any better for those starting out..
I think the big one everyone agrees on is sin^(-1). Bad bad bad.
Bad notation.
This was confusing me too, but after few examples you get familiar with the notation
well it may be confusing, but it's not too bad
lol it doesn't mean 1/sin
lol, only 1 extra character
actually it's much easier to write arcsin than sin^(-1) in latex
sin^(-1) is now 2 characters longer than arcsin
raising function to negative one is general notation for inverse, but I've never seen arc outside trig
the ^-1 later becomes a general notation for inverse
Understandable confusion. It's widely accepted that sin^(-1) is awful notation
arcsin and csc is best and clear
well i guess im in the 1% of people who dont mind it
For function inverse and multiplicative inverse, respectively
well you can thank this guy for it
https://en.wikipedia.org/wiki/John_Herschel
Sir John Frederick William Herschel, 1st Baronet (; 7 March 1792 – 11 May 1871) was an English polymath active as a mathematician, astronomer, chemist, inventor, experimental photographer who invented the blueprint and did botanical work.Herschel originated the use of the Julian day system in astronomy. He named seven moons of Saturn and four m...
according to Google..
I will keep using sin^(-1) together with asin
asin is acceptable, it's at least not so long
Oh asin is also good
I'm afraid it'll be confused with a * sin for a constant a, but context usually rules that out
ya I would assume it as a * sin too, dunno if I've seen it written that way before
my instructors usually just write it as arcsin, so it's crystal clear
lol are mathematicians really this lazy to avoid writing "rc"?
arcsin is less confusing, no need to double check if "a" is a constant, if (^1) is an inverse, it just means arcsin
I dunno why John Herschel even invented this notation to begin with
like if there is anything you can do with sin^(-1) that you can't do with arcsin?
and now it's like a cancer in all of math, can't get rid of it
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I have a quick question:
lets say that F(t, P(t)) = f(t,P(t))-g(P(t))
what would the partial derivative of F regarding t be?
When I do it, I think that I have to derive both f() and g() since they both depend on t. But in the solutions the result is simply f't(t, P(t) with no g() at all. Why is that?
Also the task states that P is defined "implicitly" through t, and sometimes it is written just P, sometimes P(t).
<@&286206848099549185>
im gonna try help
nice
deriving I guess
ok that's the question
right?
ok leme try then
the entire block yes. the last sentence is just additional info.
g() is just a constant so when differentiating with respect to t it’s zero
but its g(P(t))? how is it a constant then?
Though it’s been ages since I took diff eq so could be wrong
how is it a constant though?
<@&286206848099549185>
Sorry let me think a sec
np
@balmy steeple Has your question been resolved?
@balmy steeple Has your question been resolved?
@balmy steeple Has your question been resolved?
if you do partial derivatives, then you assume that all the other variables are constant, and that’s why you only derive f’(t, P(t))
however you can also try to have a total derivative with respect to t, and it’s marked as $\frac{d}{dt}$ instead of $\frac{\partial}{\partial t}$
rkky
and then you’ll get f’t(t, P(t)) + f’P(t, P(t)) * P’(t) -g’(P(t)) * P’(t)
alright thanks, let me ask a super quick follow up question though:
in the case of f(x,y) = 3x^2+5y where y is a function of x
the partial derivative regarding x would still be simply 6x then?
exactly
Okay thanks
I am testing something out rn to check whether I fully understood it, so I may write something in a few minutes again
I think I got it, thanks for clearing it up
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For #1 I always remember this (easy)
but for #2 I keep forgetting..
Anybody else the same way? Can you convert #2 to #1 if you forget?
from 2 -> 1 take log_a for both sides
oh interesting..
wait, how would you take it for both sides?
log_a(a^(log_a(x)) = log_a(x)
log_a(x) = log_a(x)
ok maybe its not exactly 2->1 but it atleast should convince you that 2 is true
which is the best way to remember something imo
it's confusing lol. I feel like I'm doing logarithm in reverse
reverse engineering it
for #2
Looking at 1 vs 2, you have log(a^x) vs log(x), and for log(x) you can't have negative numbers
not log, log_a(a^x)
Or were you not referring to the domain?
log by default is log_10
I know
but you said log(a^x)
I was not feeling to type out _a
in math, log is always natural log
who put X for this?
but its just that they are inverses
???
Not really
log is always base 2
yes really
log is normally base 10
That's math software though, log on calculators defaults as log_10
ln is natural log
log is base 10
not software
log is binary by default
in general
log is used for natural
no.
nope
Then explain log vs ln on physical calcs
and log is used for base 10
its the same
Casio calculators log = base 10
No it's not
yes
that's because its catered for non math people
have yall not used a calculator?
they are literally different buttons on calculators
in pure math almost always log = natural log
no its not
If you watch 3b1b's video on the triangle of power, he states that base 10, e, and 2 are used for logs in different contexts
,w log(e)
the computer scientists want base 2
Not a physical calculator but fair enough
oh now it's "almost always", we have backed down from original statement lol
And I'm referring to physical calculators, like ti calculators where it has log and ln, where log is log_10
exactly
same with casio
real question is why u on light mode
just to get asked
Bros pulling up receipts 💀💀
i agree with snow, i have never seen anyone use log for log_10
inside math context
but a lot of people on here do so i just go with it
cause it doesnt matter
what you call something lol
as long as you are clear its what oyu mean
what?
who cares about always vs almost always it's like there's gonna be a few use cases but it's rare
That is such a lie
Ive seen it for a precalc class and never again
Calculators
for the engineers
i have never used a physical calculator
literally all calculators approved for math exams are log base 10
ANYWAY
if you wanna change the base there is another button, log[]
Why do you ask?
where you can use your own base
If you've used ti calcs then you know that calculators use log as log_10
but ive never used one
mathematicians don't design calculators
also physical cals are not for pure mathematicians
Casio fx 83-gtx standard GCSE and a level calculator : https://gyazo.com/46abb6ceaf3245465cc8e9de5598d5e1
And that's the reason why
lol i feel like i'm in the Twilight Zone
potential bingo square unlocked!
"Argument about whether log is base e,2, or 10"!
you even been to class bro>

yes.
i know what it looks like. i just never see anyone use it in a maths class
and ive never used it myself either
so what do u use in exams?
its just notation, generally i find that log without any base has about the same chance of referring to natural log as base 10
You're not millennial then
:
also physical calcs are incredibly common for exams
Yea
which i believe my calc also has log for base 10 and ln for natural base
That is an absolute lie. There is no way you are 23 and have not used a physical calc
He would've for exams
if you dont do math related exams you probably never need a calculator
hes cappin
a physical one at least
Maths is mandatory in my country and probably most others
until 16
in which the test u take u need a calculator
If you don't do any stem classes, then you'll never need a physical ti calc that stem uses, like casio or ti 84
ask a question on Discord they said...
business also needs it
like accounting
i love how this channel just turned into a big pissing match 
what even was the question 
I don't even remember anymore
how to remember that log_a and a^ are inverses
Business has their own economics related calc
quite sure they also use scientific calculators
i used maple in highschool and in elementary, we used geogebra for graphs and no calculators
They have a ti ba 2 plus
What about exams?
highschool exams was maple and no calcs for elementary exams
i dont think its that specific. literally just google "calculator for economic exam" and plenty of scientific calculators show up
Your school trusted you that much to not roam on the inter webs for answers?
maple is an application. wifi is turned off that dya
I refuse to beleive in 23 years of living you've never used a physical calculator
in my uni the only requirement is that its just a regular scientific calculator with no special functions. there are thousands of different calculators i can use. id reckon its the same for business
BRO THAT IS THE OPPOSITE TO MINE, only 2 are allowed
trig questions are a lot easier with calculator. i know the unit circle, but an approved exam calculator tells me and it's much faster
never needed a calculator for an exam in any of the STEM classes I took
what
except for one bullshit class in economics
sounds like a murica moment
my whole guideline was
if you needed a calculator with functions restricted that a laptop could provide
the class probably was a joke
its stupid because in a level (exams end of highschool) we were allowed to have BETTER calculators
as in they have more functions
Anyways this has gone off the rails, peace out
says the train conductor himself
yea
i will not correct my proffessor for example
it means base 10
when he uses log for natural log
and say pysical calc disagrees with youi
its moronic
mathj is more than this
if i see log alone i will generally ask what base it is since its extraordinarily common for teachers to use log for base e
stop getting hung up on thsi stuff
which i honestly find kinda dumb, ln is slightly less effort and removes any potential confusion
why not write it ln if it's base e? it's one less character and professors usually love less work
yeah thats what im saying, i would not write log ever for base e
that is the question
but a lot of people do
but tbf
If I see log alone, I normally assume log_10 because apparently I'm one of the few people who uses a physical calc where it uses log as log_10 and ln as log_e so I'm used to that notation based on physical calcs
i do 💀
Most programs (non calcs) do take log as base e
i like log better
i did until i joined this discord
and now ive seen so many log being base e
that i need to ask
i agree and so does 99% of the british population
if people just stopped using log for base e then id always assume base 10. but thats just not the case
i rarely see people use log with different than base e
maybe thats just why
i like log as base e
yeah it looks too much like in
yes log looks prettier
I feel like you see log_10 a lot in things like engineering
but with things involving calculus, then it's log_e
ye im pure math so maybe thats the disconnect
guess it makes sense why im middle ground then. physics moment 
log_2 is very popular in computer science
so if you were asked to like integrate 1/x you'd say log(x)
If there was a duh emoji, I would have used it because base 2 is binary related
you can easily see why i would just ask what base it is instead of just assume its base 10. personally i dont see a reason to use log for natural since there is literally no downside and a slight upside (avoiding confusion) to using ln over it
but its just a notational definition lol
notational definitions vary even from paper to paper
like how you type out vectors
some notation is truly awful
Also a good chunk of the internet searches, I'm looking at, uses log as log_10
you are 100% right
but i will still use log as base e liol
i just like it more
also when you are speaking
i just say log
so i also typ elog
yknow?
NAW THE CLOCKS WENT foward and now its 2 am
i always say "el en" when referring to natural log. so i guess thats a slight reason to use "log" instead since its 1 syllable instead of 2
really micro managing the efficiency of a potential lecture there
I'm sticking to what I know and is used to and that's log is log_10 and ln is log_e, you guys do you
'lin' is what i say
people only care on the internet anyways it seems
and people who skip classes and get confused by notation
did you actually get an answer to your question
no but I will close this now
it was too cancel out all the x's
I gotta go the gym lol
i gotta go to sleep#
.close
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Hi. Doing disk and washer methods and not sure how to do the formula.
The original equations are y=1/(1+x), y=0, x=0, x=3
y = 0 is a flat line, so it's just [f(x)]^2
you forgot the $\pi$
hannibal
Oops. Got it now
But the circles are in terms of y, so to find the radius you need to use x
Input x, output y
Am I wrong?
@untold mica Has your question been resolved?
<@&286206848099549185>
Maybe?
Didn’t realize
We can tinder stand this stuff
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1st one converges becuz cn is just constant
2nd series converges because its just a constant * a constant?
3rd doesnt because it alternates
same for 4th?
your justifications don't make sense
what do you mean it's a constant? or constant times a constant?
and when x = -4, the series is alternating and the series converges.
Cn is a constant
each term is constant, but the terms are not all the same...
oh so how do we do this
its centered around
1.5
you know when $x=-4$ the series is convergent. So, necessarily, $\lim_{n\to\infty}c_n(-4)^n =0$. So $0\leq|c_n| <4^{-n}$
Zybikron
but they also said 7
so would it be
-4<x<7
is it not that?
ah, true, so you can say something like $7^{-n}\leq |c_n| < 4^{-n}$
Zybikron
where did the -n come from
@civic zealot
@spark field Has your question been resolved?
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how does he get -55?
-350/-4 just gives me 87.5
cant wrap my head around it
oh my god
Im too tired
its okay bro sorry to waste your time
Just realized my error
no worries
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thanks again
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<@&268886789983436800> why did my question chhanel turn to hidden?
it must have timed out
were you asking about the centroid question or something else?
no something else