#help-10

1 messages · Page 78 of 1

rich roost
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Replace logx logy and logz by the equations given

plain plaza
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id like to know how to do the stuff i need but i’m just

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so sleepy

rich roost
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That’s fair

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Here it’s asking you when V gets doubled

plain plaza
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yeah

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my friend showed me how to do it with graph

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but i dunno if it should be 6 or 7

rich roost
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7, it’s asking for more than double

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6 is a bit under doubling

plain plaza
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ooh ok

rich roost
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So you round up

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So you have to have to use this formula for c)

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You isolate t and that’s the answer

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You have to use logarithms so I can just do it if you forgot how for this stuff

plain plaza
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i think i figured out how to do it but i think i put the wrong number for t for the second bit???

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or maybe it’s all wrong idk

rich roost
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For the second part of 8) it’s fine

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But third part is wrong

plain plaza
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oh really?

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ooh

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what about it

rich roost
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It’s gonna be less than 2 years

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*a bit more

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Your answer is 4 times the actual answer

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I think you forgot the 4 in the exponent

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But otherwise it’s the right answer

rich roost
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Idk how you got something different tho

plain plaza
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ooh

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what should i have done

rich roost
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For the second one or third one

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Cause second one is just calculator usage

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Third one, see this x?

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It should be 4x

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Thats the thing you forgot

obtuse pebbleBOT
#

@plain plaza Has your question been resolved?

plain plaza
#

ooh ok

obtuse pebbleBOT
#

@plain plaza Has your question been resolved?

plain plaza
#

is it gonna ask me this forever

rich roost
#

You have to answer yes for it to end lol

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I mean is there something left

obtuse pebbleBOT
#

@plain plaza Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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stone flint
obtuse pebbleBOT
stone flint
timid silo
#

What's the objective + what have you tried

stone flint
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To solve

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Tried : nothing

patent jetty
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What do u want to solve for

stone flint
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How do I even start

timid silo
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Are u trying to solve for y or x

stone flint
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Shouldn't I be trying to solve both

timid silo
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I mean you got to have something to solve for, the first one is just an ellipse

stone flint
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How can u tell

timid silo
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Discriminant I guess

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But that's outside of the point

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We need to know what you are solving for

obtuse pebbleBOT
#

@stone flint Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

Grade 8 linear equations

obtuse pebbleBOT
earnest elk
warm shaleBOT
earnest elk
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have you tried anything?

timid silo
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Yes

earnest elk
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show your working

timid silo
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I have multiplied 2 by 2x and -3

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Can u explain me from beginning plz

slow hornet
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the question is asking to find x, correct?

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@timid silo

timid silo
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Yes the question is asking to find x

slow hornet
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Alright, you see the "x-5" as the denominator, correct?

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you can multiply both sides by "x-5"

timid silo
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Ok

slow hornet
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does that help a little? @timid silo

timid silo
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Next step

slow hornet
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after that, look at the left hand side

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do you see that the "x-5" has been cancelled out?

timid silo
slow hornet
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this is because when you multiply a number by the same number in a denominator

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the numbers will "cancel out"

timid silo
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Can u plz show me on paper

slow hornet
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alright

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$$(x-5) \times \frac {(x+2)(2x-3)-2x^2+6}{x-5}$$

warm shaleBOT
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hahahxrvy

slow hornet
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this is your left hand side after you multiply the x-5, correct?

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you can see that after multiplying x-5 to the fraction, there will be an "x-5" on top and on the bottom

timid silo
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Yes

slow hornet
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because of this, you can cancel them both out, as diving a number by itself will equal to 1

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does that make sense?

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because you can think of this as

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replacing the fraction with a division symbol @timid silo

timid silo
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Ok

slow hornet
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so because that is gone, what are you left with?

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on the left hand side

timid silo
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Next step

slow hornet
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what you do on the left hand side, you also do to the right hand side

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so multiply the right hand side, (which is 2) by "x-5"

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got it?

timid silo
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Ok

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So is it 10

slow hornet
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yep

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that is what i got

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x = 10

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do you want me to show you the full working out

timid silo
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Ya

slow hornet
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here you go

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hope this helped

timid silo
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Ok

slow hornet
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if you got something like this, you should be right

timid silo
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Thank you

slow hornet
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You're welcome

timid silo
#

.close

obtuse pebbleBOT
#
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muted girder
#

anybody know how to solve this?

obtuse pebbleBOT
#

@muted girder Has your question been resolved?

obtuse pebbleBOT
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@muted girder Has your question been resolved?

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uneven night
#

. In a given bacterial population, the number of bacteria changes at a rate proportional to the number of bacteria. The proportionality constant is 0.1 h^-1. The number of bacteria at time zero is 1000. a) Set up a differential equation for the number of bacteria at time t and solve it. Also calculate the number of bacteria at time t = 6 h. b) Calculate the time it takes for the bacterial population to double

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I need only help with b

obtuse pebbleBOT
uneven night
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Can someone help me please

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Only with b)

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How do I calculate the time it takes for the bacterial population to double?

obtuse pebbleBOT
#

@uneven night Has your question been resolved?

obtuse pebbleBOT
#

@uneven night Has your question been resolved?

obtuse pebbleBOT
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shrewd vault
obtuse pebbleBOT
shrewd vault
#

Could someone help me with this? Atleast telling me how to do it would be enough

timid silo
#

1 - Use the formulas for the surface area of a cylinder, paying attention to the sides that are not exposed.
2 - Make the total area a function and minimise it.

obtuse pebbleBOT
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@shrewd vault Has your question been resolved?

shrewd vault
#

As in

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How do I make the total area of a function and minimise it

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Do I differentiate

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And find the 2nd derivative

obtuse pebbleBOT
#

@shrewd vault Has your question been resolved?

obtuse pebbleBOT
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@shrewd vault Has your question been resolved?

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obtuse pebbleBOT
#

@real lynx Has your question been resolved?

obtuse pebbleBOT
#

@real lynx Has your question been resolved?

obtuse pebbleBOT
#

@real lynx Has your question been resolved?

glossy wharf
#

so youre given f2/sinbeta=f3/singamma and f3sin(beta-90)+f2sin(gamma-90)=f1, and you want to show that f1/sinalpha is equal to either of them?

obtuse pebbleBOT
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bleak flax
#

Need help finding the coordinates for a parabola. I'm given this equation: PARABOLIC CURVE
EQUATION: x=[0.263]6.677xY^2

obtuse pebbleBOT
#

@bleak flax Has your question been resolved?

obtuse pebbleBOT
#

@bleak flax Has your question been resolved?

obtuse pebbleBOT
#

@bleak flax Has your question been resolved?

obtuse pebbleBOT
#

@bleak flax Has your question been resolved?

bleak flax
gaunt rover
bleak flax
#

ty that actually worked lmao

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.close

obtuse pebbleBOT
#
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timid silo
obtuse pebbleBOT
timid silo
#

what was done wrong in this solution?

nocturne minnow
#

Answer isn't exact

timid silo
#

that much is obvious bruh

nocturne minnow
#

That's why it's wrong

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The process is correct

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You just didn't have exact answers

timid silo
#

24*

civic zealot
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that and the -24 should be +24

nocturne minnow
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And that too, I mean your teacher did mark what was wrong

timid silo
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yeah

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so wait

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how does it go

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      • = -
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isn't + * - = - as well?

nocturne minnow
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Because a negative times positive equals a negative

timid silo
nocturne minnow
timid silo
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oh, okay

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btw, how is root(12) = 3.4?

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acc it is, nvm

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that's all for now

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thanks guys

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btw, how do i close this

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!close

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.close

obtuse pebbleBOT
#
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timid silo
obtuse pebbleBOT
timid silo
#

how do i know when i have to excrete?

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bcz a 3rd step in photomath was my friend's 1st step

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i'm interested in why couldn't i stayed with 3x-x^2 and 6-2x

dark mango
timid silo
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wdym wdym

timid silo
dark mango
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I dont know what that word means in this context

timid silo
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like

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to cut down

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the number

dark mango
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factor?

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ohhh

timid silo
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yeah

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LMAO

dark mango
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I wouldnt say excrete in the future

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fyi

timid silo
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i won't bbg dw

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help me out there

dark mango
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You dont have to factor

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it just helps make it easier

timid silo
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how do i know when i can and can't use it

dark mango
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intuition I guess

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there is no defining characteristic to immediately tell you to factor here but if you do it makes the math nicer

timid silo
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🧍

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rly?

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bruh

dark mango
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you didnt have to factor

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you could have just multiplied by both denoms as is

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and got to your solution

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its just uglier

dark mango
timid silo
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what is a common factor

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and how do i check that

dark mango
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like they both have

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(3-x)

timid silo
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ohh thst yes

dark mango
timid silo
#

btw sry if im asking like dumb questions

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its like 3:30am

dark mango
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its okay

timid silo
#

💀

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thanks

dark mango
#

its just intiution and practice

timid silo
#

ill just do it every time

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and if there is no common factor

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ill just erase it

dark mango
#

yeah that works

timid silo
#

thank you once again

#

.close

obtuse pebbleBOT
#
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short siren
obtuse pebbleBOT
#

@short siren Has your question been resolved?

short siren
#

<@&286206848099549185>

obtuse pebbleBOT
#

@short siren Has your question been resolved?

obtuse pebbleBOT
#

@short siren Has your question been resolved?

obtuse pebbleBOT
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signal ember
#

can anyone guide me through these problems

obtuse pebbleBOT
signal ember
#

not a test btw, its a checkpoint so like hw

tranquil quiver
#

which one are you stuck on

signal ember
#

all 4

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im just a bit confused

tranquil quiver
#

do you know log laws

signal ember
#

yea

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so 1 a

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i think i do

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log 2500 - 2 log 5

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so i do log 2500 - log 5^2

tranquil quiver
#

Yeah

signal ember
#

then log 2500 - log 10

tranquil quiver
#

no

signal ember
#

then log (2500/10)

tranquil quiver
#

it's 5 to the power of 2

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Not 5 times 2

signal ember
#

oh

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wait so 25

tranquil quiver
#

5^2 = 5*5 = 25

signal ember
#

yea

tranquil quiver
signal ember
#

so then log (2500/25)

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log(100)?

tranquil quiver
#

also log by itself is implciity base 10 right

signal ember
#

yea

tranquil quiver
signal ember
#

ohhh

tranquil quiver
#

And then 10 to the power of what gives 100

signal ember
#

2

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10^2

tranquil quiver
#

yes

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so log(100) = 2

signal ember
#

ohhhhh

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can we try the one with fractiom

tranquil quiver
#

1b)?

signal ember
#

yep

tranquil quiver
#

sure

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Do you also know your exponent laws

signal ember
#

yea i think so

tranquil quiver
#

okay

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Where do you get stuck

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It's a similar process to 1a

signal ember
#

log 8 (3/64) + log 8 (1/9) ^ 1/2

tranquil quiver
#

yeah good

signal ember
#

then log(3/64) * 2/9?

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because i cross multiply 1/9 and 1/2

tranquil quiver
#

wut

signal ember
#

uh

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wait nvm

tranquil quiver
#

you multiplied again

signal ember
#

yea...

tranquil quiver
#

It's to the power of 1/2

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which is the same as what

signal ember
#

that gives me 0.333333

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= 3/9

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then log(3/64) * 3/9?

tranquil quiver
#

did you use calculator for that

signal ember
#

yea..

tranquil quiver
#

you shouldn't

signal ember
#

tech can be 1/3

tranquil quiver
#

Use your exponent laws

signal ember
#

add the exponents

tranquil quiver
#

do you know $x^\frac{1}{2} = \sqrt{x}$

warm shaleBOT
signal ember
#

ohhh right

tranquil quiver
#

also $(\frac{a}{b})^n = \frac{a^n}{b^n}$

warm shaleBOT
signal ember
#

yea i know this one

tranquil quiver
#

$(\frac{1}{9})^\frac{1}{2} = \sqrt{\frac{1}{9}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}$

warm shaleBOT
tranquil quiver
#

makes sense?

signal ember
#

yea

tranquil quiver
#

so then you have

signal ember
#

then log8(3/64) * 1/3?

tranquil quiver
#

not quite be careful with parenthesis

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you get the product inside one log

signal ember
#

log8(3/64 * 1/3)?

tranquil quiver
#

yeah

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then the 3's cancel out

signal ember
#

1/64

tranquil quiver
#

$\log_8 {\frac{1}{64}}$

signal ember
#

log8(1/64)

tranquil quiver
#

exactly

#

oops

signal ember
#

i seeeee

warm shaleBOT
signal ember
#

can we go through 2a and 2 b as weel

#

well

tranquil quiver
#

wait

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this isnt done

signal ember
#

oh right

tranquil quiver
#

you can evaluate it down to a number

signal ember
#

8^x = 1/64

cold abyss
#

are yall done i have really easy problem that i get any good help

#

im sorry to interupt

tranquil quiver
cold abyss
#

i have a channel

tranquil quiver
#

first can you write 64 as eight to the power of smth

tranquil quiver
signal ember
#

8^2 = 64

tranquil quiver
#

yeah

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hence

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$\frac{1}{64} = \frac{1}{8^2}$

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right

warm shaleBOT
tranquil quiver
#

also do you know this fact

#

$x^{-1} = \frac{1}{x}$

signal ember
#

yea

#

yes

warm shaleBOT
tranquil quiver
#

so $\frac{1}{8^2} = 8^{-2}$

#

makes sense?

warm shaleBOT
signal ember
#

uhhh

#

ohhh

tranquil quiver
#

yeah?

signal ember
#

yea

tranquil quiver
#

then

#

$\log_8 (8^{-2}) = -2$

warm shaleBOT
tranquil quiver
#

makes sense?

signal ember
#

wait so we started with log8(1/64)

tranquil quiver
#

yes

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but we found 1/64 = 8^-2

signal ember
#

right

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so log8(8^-2)

tranquil quiver
#

so what do you need to raise 8 to in order to get 8^-2

#

of course you need to raise it by the power of -2

signal ember
#

-2

tranquil quiver
#

you can also just use ur log laws

#

$\log_8 (8^{-2}) = -2 \cdot \log_8 (8) = -2 \cdot 1 = -2$

warm shaleBOT
signal ember
#

oh yeah

#

i can move it down

tranquil quiver
#

yeah

signal ember
#

i see

tranquil quiver
#

okay

#

what part are you stuck on for the q2

signal ember
#

1/3 log a + log (c-4)

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log a ^1/3 + log (c-4)

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log(a^1/3 * c-4)

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is that it?

tranquil quiver
#

make sure to use parenthesis

signal ember
#

because its in a single log

tranquil quiver
#

log(a^1/3 * (c-4))

#

yeah

signal ember
#

oh

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wow okay

tranquil quiver
#

since you need to multiply the whole expression

signal ember
#

and 2b is just log x- 2 log y + log (-z)

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so then

tranquil quiver
#

make sure you dont forget the restrictions part

signal ember
#

log (x-2 * -z /y)

tranquil quiver
#

hold on

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wut

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the x -2 isnt in the log

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its

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$\log(x) -2\log(y) + \log(-z)$

warm shaleBOT
signal ember
#

oh

#

wait

#

log (x) - log y^2 + log -z

#

so first

tranquil quiver
#

you can combine them in any order doesnt really matter

signal ember
#

im changing -z to square root z

tranquil quiver
#

wut

#

hows that work

signal ember
#

nvm

#

its ^1/2 is root

#

my b

#

then its just

#

log(x*-z/y^2)

tranquil quiver
#

yeah

signal ember
#

how do i do restrictions

tranquil quiver
#

for

#

$\log(x)$

warm shaleBOT
tranquil quiver
#

what is the restriction on x

signal ember
#

cant be 0

tranquil quiver
#

hmm so can it be -1

signal ember
#

nooo

tranquil quiver
#

so whats the full restriction

signal ember
#

so x > 0

tranquil quiver
#

yes

#

so any input needs to be greater than zero

signal ember
#

x > 0, xer

tranquil quiver
#

x > 0
y > 0
-z > 0
z < 0

#

then you can do the same for a

#

1a

#

make sure u simplify the inequality so you have the variable on one side

signal ember
#

ah okay

#

thanks so much for taking the time to walk me through these problems and also being a good teacher by making me do the work aswell :D

tranquil quiver
#

no problem

#

make sure you understand each step

#

then you can solve any problem which is like this

signal ember
#

👍

#

-close

cold abyss
#

when you are done helping him mind helping me

tranquil quiver
tranquil quiver
signal ember
#

.close

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eager falcon
#

This is a rather silly question: what is s longest paths?

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austere crater
#

Anyone got a clue how to do 1.(c)?

obtuse pebbleBOT
trail musk
#

1/(1×3) + 1/(3×5) + 1/(5×7) + ...

#

= Σ 1/((2k-1)(2k+1)) from k=1 to k=n

#

,w partial fractions 1/((2k-1)(2k+1))

trail musk
#

= 1/2 (Σ 1/(2k-1) - Σ 1/(2k+1))

#

Now just find a formula for Σ 1/(ak+b)

#

Nvm that gets ugly lol

#

Maybe we should actually expand

#

= Σ 1/(4k^2 - 1)

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timid silo
#

I need to rearrange the formula so that 'a' is in terms of 'b' and 'c'

timid silo
#

I tried to simplify the formula to be able to rearrange it easier, but this is as simple as I could get it

#

If it helps, this is the original

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timid silo
warm shaleBOT
#

Sculptuura

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

$\frac{c}{\sqrt{(4(\sin(90-\frac{180}{b}))^2(\sin(\frac{180}{b}))^2)+(4\sin(90-\frac{180}{b})(\sin(\frac{180}{b}))^2))+1}}$

warm shaleBOT
#

Sculptuura

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queen crater
#

Hello! Could someone explain me, please, how can I integrate this term by term?

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#

Please don't occupy multiple help channels.

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queen crater
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<@&286206848099549185> please

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solar trellis
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silver plover
#

..

obtuse pebbleBOT
silver plover
#

part c

#

am i doing this correctly so far?

timid silo
#

Bernoulli equation I would imagine?

silver plover
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last crow
#

How can I find the bounds of the parameterization of the intersection of z = 16 - 2x - y and x^2 + y^2 = 4

last crow
#

I've written the parameterization as r(z, t) = 2cos(t) i + 2sin(t) j + (16 -2cost - sint) k

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ruby skiff
#

how come for b u switch the x and y values?

#

why would u not just do tan^-1(1/-1.7)

#

wait nvm

winter ether
#

im not sure what youre asking there, it doesnt swap. tan(t) = O/A = y/x

ruby skiff
#

yea sry I was short circuiting for a second

winter ether
#

all good it happens

ruby skiff
winter ether
obtuse pebbleBOT
#

@ruby skiff Has your question been resolved?

ruby skiff
#

like if u look at b

#

instead of finding the one in 4 we find teh one in 2?

winter ether
#

its been a while so I forget which one tan is, I tihnk it works in the first and second, though

ruby skiff
#

na tan is only positive in the first and third

winter ether
#

its not about where its positive I think

ruby skiff
#

oh its the negative

winter ether
#

no I think you want a mix

ruby skiff
#

btw could u help me with this too?

winter ether
#

ahh thats why I was imagining it shifted over one

ruby skiff
#

its like for b i got 1

#

but it is actually -1

#

is it bc on the unit circle the x is negative?

winter ether
#

yeah

#

x is negative, y is positive, so their quotient is negative

ruby skiff
#

yea but i thought the hypotnus could not be -

winter ether
#

the hypotenuse cant, but that's not what you're solving for

ruby skiff
#

oh the angle right

winter ether
#

also no\

#

youre solving for the ratio between the y and the x

#

tan(3pi/4) inputs an angle -> outputs y/x at that angle (on the unit circle, so radius 1)

ruby skiff
winter ether
#

uh, not sure what that means

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dusky ledge
#

The base of S is the region enclosed by the parabola y = 1-x^2 and the x-axis. Cross-sections perpendicular to the y-axis are squares.

dusky ledge
#

That is my work. But Answer sheet says 8/3. May someone point out the mistake in this

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#

@dusky ledge Has your question been resolved?

timid silo
#

does anyone know what discrete, continous and categorical data is. i might be 10 years backed up but its ight

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pastel lichen
#

im doing a limit

obtuse pebbleBOT
pastel lichen
#

of lim x-->-2 of 1/x+2

#

but its been a hot min and i dont remeber what to do here

#

normally you can factor or use lh rule but i dont think so here so is it just DNE ?

sharp pecan
pastel lichen
#

nothing cause you cant have 1/0?

sharp pecan
#

its a limit

#

it approaches 1/0

#

but its not actually 1/0

pastel lichen
#

hmm

sharp pecan
#

let me ask different

#

what is 1/n, where n is some extremely, extremely small number?

#

almost 0, but just not 0 enoigh

pastel lichen
#

near zero but probably not touching zero

sharp pecan
#

ah no

#

1/2 is 0.5, 1/1 is 1, 1/(0.5) is 2

#

1/(0.25) is 4

pastel lichen
#

infinity ?

sharp pecan
#

yes

pastel lichen
#

hmm

#

but i thought

sharp pecan
#

thats the answer

pastel lichen
#

you only do that

#

if its like

#

lim x-->2^- or +

sharp pecan
#

whats that?

pastel lichen
#

like

#

as x approaches 2 from the left or the right

sharp pecan
#

in your case its both right

pastel lichen
#

cause all i know here is that x is apporaching 2 but not from which direction

sharp pecan
#

posetive infinity

#

well you can try that out no

#

1/(0.0000000000000000000001) and 1/(-0.0000000000000000000000001)

pastel lichen
#

yea and thatll say if its pos or neg infinity but it dont have a direction ?

sharp pecan
#

its posetive and negative infinity

pastel lichen
#

so it dosnt exist then ?

#

because if the limit is from both positive infinity and negative infinity it dosnt exist

sharp pecan
#

true

#

in our class we had to write both down, so if no direction was given but the limit is different, we had to say it becomes a from the left and b from the right

#

but it seems you can also write it has no solution

#

since limit from the right and left are different for you

pastel lichen
#

what about

#

lim x-->-2 of 1/(x+2)^2

#

.close

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native shuttle
#

hey

obtuse pebbleBOT
broken nest
native shuttle
#

is this mine or yours now?

final thunder
native shuttle
#

oh

#

great

#

so quick question

#

if I‘m trying to find the interest rate at which 2 projects would have the same npv, do I make an equation, with one project on each side, with the interest rate being x?

unique kettle
#

That sounds right

#

NPV of A = NPV of B

native shuttle
#

it gave me a weird number though

#

but tbh, the npv I got was wrong anyways

unique kettle
#

What did it give you.

native shuttle
unique kettle
#

Sometimes cash flows with a lot of direction changes between positive and negative can give weird IRRs

native shuttle
#

aah fuck

#

I figured it out lmao

unique kettle
#

Correct me if I’m wrong because this has slightly different notation but PV of A should be 1400?

native shuttle
#

yes

unique kettle
#

And then you probably made the same mistake with B

native shuttle
#

yes

#

the mistake was me trying to get it for one year earlier than I was supposed to

unique kettle
#

You discounted the first payment, on accident, should probably resolve your second part to that question lol

native shuttle
#

yup

#

got it right now

#

hahah

#

thanks

unique kettle
#

Nice

native shuttle
#

fml

#

dude I‘ve come so far

#

how do I close this

#

.close

obtuse pebbleBOT
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timid silo
obtuse pebbleBOT
timid silo
#

for part (a)

#

would you not just do:

H_0: p = 0.9
H_1: p > 0.9

X ~ B(10, 0.9)

size = probability of being in critical region

#

i don't understand this

#

where did the 0.7 come from...

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#

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hollow tartan
#

can somebody help me with the second question. I need help forming the equations and graphing much appreciated

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wide robin
obtuse pebbleBOT
knotty crow
#

3 * 4 = 12
3 * b = 3b
a * 4 = 4a
a * b = ab

#

u know how matrix multiplication works?

wide robin
#

im kinda new to it but I have an idea

wide robin
knotty crow
#

no, rather

wide robin
#

ah okay

#

thank u

#

I know how to do it with numbers but I'm unfamiliar with the variables

#

would it be 2q - p?

knotty crow
#

ye

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finite loom
obtuse pebbleBOT
finite loom
#

Hey is this a permutation or a combination?

#

permutation = order matters

#

sooo this is a combination?

civic zealot
#

permutation

finite loom
#

Wait does the question mean

#

pick 3 positions for the office

#

and those 3 positions are president, vp secretary

civic zealot
#

yes

#

if you're picking people for certain offices, if the same 3 people wind up in different offices, then it's a different outcome. So order matters

finite loom
#

oh okay

#

ty

#

.close

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nocturne schooner
obtuse pebbleBOT
knotty crow
#

,rccw

warm shaleBOT
nocturne schooner
#

u got anythign?

#

<@&286206848099549185>

timber fox
#

for part a)

#

consider a f(x) with degree 2 and vertex at the point (-1,2)

#

and understand that the inverse of a function is that function flipped on the y=x line

nocturne schooner
#

ok

timber fox
#

wait

#

im trolling a little bit

#

need to think of another example KEK

#

ok

#

pretty sure a) may be true

#

as the function to be invertible has to be be one to one so it will go from neg inf to pos inf, so when you flip it, they will cross at some point

nocturne schooner
#

what

narrow vault
#

clarkie are you reading the question right

timber fox
#

potentially

#

not

narrow vault
#

i think you're overthinking a bit

nocturne schooner
#

its easy

#

but nto for me

narrow vault
#

although it's actually not all that simple to explain without just saying the right answer maybe

and idk what your teacher has/hasn't taught

for starters, for a function y=f(x), if you're trying to find its inverse, what's the first step you take

nocturne schooner
#

u swap y for x

#

?

#

im trying to self learn this stuff its hard

narrow vault
#

ok, so you have the inverse $f^{-1}(x)$ satisfying $x=f(y)$

warm shaleBOT
narrow vault
#

so if $(x,y)$ is a point on $y=f(x)$, can you find a point using $x$ and $y$ that's on $x=f(y)$?

warm shaleBOT
nocturne schooner
#

u sub x and y into x = f(y)?

narrow vault
#

that requires knowing the function f

can you find a point that is on x=f(y) without having to know what f is, given that (x,y) is on y=f(x)

nocturne schooner
#

idk how

narrow vault
#

notice how x=f(y) and y=f(x) look really really similar 👀

nocturne schooner
#

is it the reflection of the point on y=x

#

or something idk

narrow vault
#

it is, but you should be able to represent the point using 2 values

nocturne schooner
#

i am lost

#

what 2 values?

narrow vault
#

i guess an example should help (and give away everything)

let y=f(x)=2x, it's known that when x=1, y=2 so (x,y) = (1,2) is on y=f(x)

then finding the inverse of f you start with x = f(y) = 2y, what's the point corresponding to x=2?

nocturne schooner
#

1,??

#

Im lacking on fuctions i need to go bac to basixs

narrow vault
#

these points are represented in the form (x,y)

nocturne schooner
#

(2,-1)

#

?

#

(2,1)

#

I probably will give up on this question and go relearn basics of functions cus i dont think i understand

#

Ty for the help though

#

.close

obtuse pebbleBOT
#
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limber gazelle
#

Can someone help fully explain the steps taken to get the answers that they did on this problem please.

limber gazelle
#

I especially do not understand the t = 4 months and how that fits in to the total calculation, is it multiplied, divided or what?

narrow fiber
#

They have an equation interest = P • r • t

#

And that equation requires t in terms of years

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So you convert 4 months to __ years

limber gazelle
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I understand but I can see the ansers but need to know how they worked through it to get those answers.

narrow fiber
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Ok so first up is the equation
I = Prt
I: Interest
P: principal
r: rate
t: time

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The question wants to find out what is the interest if you miss payment no.4

limber gazelle
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yes

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I pretty much just do not understand what they did with the time, is it multiplied, divided or how does it work into the problem?

narrow fiber
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The time is 4 months right?

limber gazelle
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yes

narrow fiber
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We want that in years

limber gazelle
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yes

narrow fiber
#

We know that
12 months = 1 year

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So
4 months = ?? years

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What is ??

limber gazelle
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12

narrow fiber
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The 12 became 1, the 4 becomes 12?

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If the 12 becomes 1, the 4 should become 1/3

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The general equation should be
Time in years = time in months divided by 12

limber gazelle
#

ok but what then do you do after knowing this/

narrow fiber
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You plug in the 4 into "time in months

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Time in years = 4 divided by 12

limber gazelle
#

ok so what would I do if it were 5 months?

narrow fiber
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You would plug in 5

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And get 5/12

limber gazelle
#

so what then would I do with the decimal?

narrow fiber
#

You would keep it as a fraction until the very end

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And then you'd round it however many places you need (usually into just the cents place)

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So in our question, how much is the time in years?

limber gazelle
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I was trying to see how in the beginning with the example if it is kind of like this problem at all fully I understand how to do this one to a certain point up until t this is why I asked about 5/12

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because this asks me about fifth month I wasnt sure if its worked out different then the example

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because when I do 5/12 then it turns into a decimal

narrow fiber
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Decimals don't change how math works

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The math will work the same exact way

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Just the numbers are different

limber gazelle
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how would I do 5

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I just do not understand how this is worked can you show me please.

narrow fiber
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You would do
Time in years = time in months divided by 12
And since you know time in months = 5, you get
Time in years = 5 divided by 12
t = 5/12

And then plug that into i = prt

limber gazelle
#

how do you plug it in, that is my problem that I do not understand and is what I have been trying to ask.

narrow fiber
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i = pr(5/12)

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$I = pr\frac{5}{12}$

warm shaleBOT
#

jafar/جعفر

narrow fiber
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$I = \frac{5pr}{12}$

warm shaleBOT
#

jafar/جعفر

narrow fiber
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That is how you plug it in

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(Btw sorry if me constantly saying "plug it in" instead of "substitute that in" bothers you)

limber gazelle
#

I am trying to help my daughter with this problem, her teacher just showed the answers but did not fully explain how to do the work, step by step.

narrow fiber
limber gazelle
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so basically i still do not get it due to the fact it is not explained on how they got to the final answer

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they gave that example with no explaniations at all.

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I need to know do you multiply, divide or the exacts steps.

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so I can fully understand how to help her to understand it.

narrow fiber
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Should I type in general language from now on "time in years = time in months divided by 12" or in math language "t_y = t_m/12"?

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Which do you prefer

limber gazelle
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please yes general language.

narrow fiber
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Ok, so we have "Interest = principal multiplied by rate multiplied by time"

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The question said that "you bought a computer for $945.00 plus 7% sales tax"

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That translates to "principal = $945.00 plus 7% sales tax"

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Correct?

limber gazelle
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yes

narrow fiber
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Now what does "$945.00 plus 7% sales tax" mean?

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It means "1.07 multiplied by $945.00"

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(the 1.07 is because the tax is 7%, if it was 8% then the number would instead be 1.08 and so on)

limber gazelle
#

yes that I understand

narrow fiber
#

So we have so far "principal = 1.07 multiplied by $945.00"

limber gazelle
#

ok

narrow fiber
#

Which becomes "principal = $1011.15"

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Now we have found the principal

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Next up,

limber gazelle
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20.99

narrow fiber
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don't forget the %

limber gazelle
#

yes

narrow fiber
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"Rate = 20.99% or 0.2099"

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Next up,

narrow fiber
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The time must be in years for the equation to work

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We have "time = 4 months"

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We need to use another rule

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"time in years = time in months divided by 12"

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So because we know "time = 4 months",

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We can plug that in and get "time in years = 4 divided by 12"

limber gazelle
#

3?

narrow fiber
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4/12 is the same as 1/3

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So we have "time in years = 1 divided by 3"

limber gazelle
#

ok

narrow fiber
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What is the value of 1/3 (in decimals)?

limber gazelle
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0.33333

narrow fiber
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Yup

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Should we use the fractional version or the decimal version?

limber gazelle
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not sure

narrow fiber
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Let's go with the fractional version

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So now we have found all of the variables

narrow fiber
narrow fiber
narrow fiber
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Now we can plug them into the original equation

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"Interest = principal multiplied by rate multiplied by time"

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"Interest = $1011.15 multiplied by 0.2099 multiplied by 1 divided by 3"

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Does that make sense?

limber gazelle
#

yes

narrow fiber
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I got 70.746795

limber gazelle
#

ok so what about the problem she needs to solve with the 5/12 for time, it can't be reduced? so this I do not understand either.

narrow fiber
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It will stay 5 divided by 12

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And the final equation will look something like "Interest = $1011.15 multiplied by 0.2099 multiplied by 5 divided by 12"

limber gazelle
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so then in decimal it is 0.41666666667, so we do not use the decimal, just take and multiply by 5 then divide by 12 instead?

narrow fiber
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Yup exactly

limber gazelle
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ok thank you I will have her try and see if it works, then I will let you know, and ty

narrow fiber
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Np, glad to help

limber gazelle
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I think it helped her, her answer is 56.98 if her calculations and your guidance is correct, anyways thank you again

narrow fiber
limber gazelle
#

I am so happy you could help me to help her, thank you, it was very much appreciated.

narrow fiber
#

Gladly, 😊

#

(don't forget to .close)

limber gazelle
#

I will

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.close

obtuse pebbleBOT
#
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steady phoenix
#

a teacher has 36 students. 10 gave roses and chocolates, 14 gave only chocolates and 12 gave only roses how many students did not give the teacher gifts

steady phoenix
#

can you please answer this question?

#

set operations

#

venn diagram

timid silo
steady phoenix
#

math

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like union intersection...

obtuse pebbleBOT
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@steady phoenix Has your question been resolved?

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obtuse pebbleBOT
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still rivet
#

Can someone explain how to find a vector that is both parallel to a plane and perpendicular to a line? I can find the vector with one condition, but I don't know how to find the vector with more than one condition

brisk matrix
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find a vector that is orthogonal to the line and the plane’s normal

still rivet
#

so i should fine the normal vector of both the line and the plane and find the cross product of that?

brisk matrix
#

find the cross product of the line’s direction vector and the plane’s normal

#

notice that if the line’s direction and plane’s normal are parallel, you’ll get the zero vector, but you should be able to consider that case separately (just take any vector on the plane)

still rivet
#

ohh okay got it thanks!

#

.close

obtuse pebbleBOT
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next wagon
obtuse pebbleBOT
next wagon
#

Still stuck on this

#

<@&286206848099549185>

obtuse pebbleBOT
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@next wagon Has your question been resolved?

next wagon
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.close

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ember sigil
obtuse pebbleBOT
ember sigil
#

is this enough?

#

what can i improve

#

except for the messiness hehe

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ruby path
#

$\int \frac{\sqrt{\cos 2x}}{\sin x} dx$

obtuse pebbleBOT
warm shaleBOT
#

NEONPerseus

ruby path
#

Man where have we come from there's exactly one number in this math question

warped agate
#

i think ull get it

ruby path
#

Hmm

warped agate
#

it will be long tho

ruby path
#

Yeah that's expected

ruby path
#

If I put sin into the square root

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I get root of cot squared - 1

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Then I take cot = sin

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And figure some shit out from there

#

nvm I should use sec not sin

warped agate
#

ya

obtuse pebbleBOT
#

@ruby path Has your question been resolved?

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timid silo
#

I’m stuck

obtuse pebbleBOT
timid silo
#

Anyone?

#

🥲

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@timid silo Has your question been resolved?

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rare lodge
#

Help me pls (francais)

obtuse pebbleBOT
timid silo
#

quel est le problème thinkies

rare lodge
#

Jai des problèmes sur les fonctions

timid silo
#

pose ta question alorrs

rare lodge
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Soit f la fonction qui a x assicie -4x-3
Soit C sa représentation graphique
Quelle est labcisse du point ordonné-5 de C

timid silo
#

Ah désolé :( je pense que cest au dessus de mes connaissanes

#

vous pouvez demandr en anglais peut-être que d'autres le sauraient

rare lodge
#

Ok

#

Et enlever des parenthèse a des expressions t'y arrive

obtuse pebbleBOT
#

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rare lodge
#

Svp

obtuse pebbleBOT
rare lodge
#

I have a question

void swift
#

yes

#

send it

rare lodge
#

Let f be the function which associates -5x-4 with a.

Let C be its graphical representation.

What is the abscissa of the ordinate point -3 of C?

Give the answer as a fraction or whole number.

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So

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????

woeful folio
#

I am Jose Mourinho

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atomic tendon
#

my mother, who is a math major is telling me that in 12 less than 15
12 is first.
12-15 is (-3)
but i think it is 15
15-12 is 3
so which one of us is right?

atomic tendon
#

oh and i know its a simple question
i just need to solve a word problem with less than