help-10

[primal dust]

no its just an optional practice test for my test in a few days

is e the base of ln?

[fierce lagoon]

I mean yeah

ln = log_e

[primal dust]

i see

so would the answer just be 6x^4?

cuz the e would cancel out

right

?

[random depot]

Yeah

[primal dust]

ok cool

thanks

[obtuse pebble]

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[dry oak]

Hello

[dry oak]

.close

[obtuse pebble]

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[dry oak]

Sorry

[violet sentinel]

hi what's your question

oh haha

nvm

[dry oak]

It's been solved alr HAHAHA

[obtuse pebble]

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[sick granite]

where does the e^-x come from? i thought it would only be -2x^2/e^x

[sick granite]

if it was an indeterminate from 0 * infinity and you had x would that be rewritten into a negative as well?

sorry some of it is crossed out but my professor showed something like this

oh wow i see

ok cool thank you 🫡

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[untold mica]

Hey. I’m confused on this question and don’t really know how to start. Thanks.

[civic zealot]

integrate f''(x) to get f'(x) and solve for the C you obtain using f'(8) = 50
Then do it again to get f(x) and solve for the C you add with f(1)

[untold mica]

Just got it. Thanks

.close

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[robust hearth]

what's the way to solve these types of problems?

Trevor takes an exam with 30 true-false questions each worth 2 points and 10 multiple choice questions
each worth 4 points. Trevor gets a true-false question right with probability 0.8 and a multiple choice
question correct with probability 0.7. What is the expected value of Trevor’s score on the exam?

[red tinsel]

It is basically about finding the expected value for a discrete probability distribution

[robust hearth]

sorry one sec

[red tinsel]

You can start by finding the expected number of questions that Trevor will get right, separately for True false questions and multiple choice questions.

[robust hearth]

so it'd just be 30*0.8 for the expected number of true-false questions that trevor gets right and 10*0.7 for the expected number of multiple choice questions correct?

or is expected number something different

[red tinsel]

Yes, that's true. The distributions have binomial distribution so it is simply the product of total number of trials and the product of probability of success on single trial

[timid silo]

Really random, but you have the same name as my friend haha @red tinsel

[red tinsel]

well its a very common name lol

[timid silo]

Yeah I'd suppose so, but it's very interesting since I have not seen anyone else with the same name yet

[robust hearth]

oh alright the score would just be 76% then

[red tinsel]

You have seen it now!

[red tinsel]

Yes 48+28=76

[robust hearth]

oh ok its that easy?

thats all?

[red tinsel]

Yes!

[robust hearth]

alright thanks for the help

[red tinsel]

👍

[robust hearth]

.close

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[true grail]

what did i do wrong here

[violet sentinel]

Howdy can you show how you got your answers?

[true grail]

cot= cos/sin

cot = 4/3

cos = 4

sin = 4

tan = sin/cos

[red tinsel]

how's cos 4?

[true grail]

cause cot = cos/sin

and cot = 4/3

[red tinsel]

yes but you only know cot

you neither know cos nor sin

[true grail]

then how do i find the other 5

given cot

[violet sentinel]

I think here a triangle would really help

[red tinsel]

or the square identities can be used.

[violet sentinel]

yeah true

[true grail]

ty

got it

.close

[obtuse pebble]

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[vague orbit]

<@&286206848099549185> I got a few 20 questions I don’t quite know the answers to

[loud dirge]

You can find both

Wait a second let me just rethink that.

[vague orbit]

Ok bro

It’s B

Right?

[loud dirge]

Yeah actually I believe so, I was just thinking if there was a tricky way to find the radius

But there's not so yeah.

My bad

[vague orbit]

What about this

Volume of cube is 1/3Pie x r^2h

[loud dirge]

Yeah usually written as pi(r^2)×h/3

[vague orbit]

Ye

[loud dirge]

So substitute r/4 instead of r and let it equal 3

[vague orbit]

Ye but there 2 variables how do we do

[loud dirge]

Ok let me write this because it's hard to explain without doing it

[vague orbit]

👌

I got 18 more questions to do

If u want u can just say the answer

[loud dirge]

Yeah okay I'll just do that then let me just work it out quick

[vague orbit]

Is it D?

[loud dirge]

Yeah nice job

1/4 squared leaves a factor of 16 needing to be multiplied in

[vague orbit]

🙂

This I’m not sure what to do

[loud dirge]

I wish I had a pen and paper with me.

[vague orbit]

RIP

[loud dirge]

Do you mind waiting a second for me to get it?

Paper and pen?

[vague orbit]

Bet

I got 46 Mins to answer 17Q’s

[vague orbit]

I’m thinking D

[loud dirge]

I don't have any paper and pens on me so ping helpers

I'll keep trying this in my head if none manage to come sorry.

[vague orbit]

Ok thanks anyways 🙏

[vague orbit]

<@&286206848099549185>

[loud dirge]

For that one you deleted

[vague orbit]

This one

I’m now doing this

[loud dirge]

Oh ok

[vague orbit]

It’s A?

[loud dirge]

I don't know if I can do that in my head hopefully a helper comes...

[vague orbit]

These are kinda mental questions

[loud dirge]

Well the formula is in terms of r^3 not squared so you would have to do some rearranging I think...

[vague orbit]

What grade maths u studying?

[loud dirge]

12

[vague orbit]

This should be easy for u then

This 9th grade math

[loud dirge]

Theoretically haha, but it's been a long time since I worked on geometry like this.

[vague orbit]

True true

[loud dirge]

Oh yeah it's A it says surface area not volume lol

[loud dirge]

Wait that's an extremely hard question isn't it? By removing it you expose the internals which may have an even larger surface area. I am just going to directly ping someone to help you speedrun this.

[vague orbit]

TSA = 3 pi(r^2)

Of hemisphere

TSA of Sphere = 4 pi(r^2)

[loud dirge]

How do you only have 40 minutes for this, that's pretty impressive honestly.

[vague orbit]

I don’t have time to do this lol

It’s either A/B

[loud dirge]

<@&286206848099549185>

[vague orbit]

They ded

[loud dirge]

Just did that one it's A

Took a long time tho jeez

Let me do the previous one with the cut out of 1/8th

[vague orbit]

This one harder

[loud dirge]

The one with the surface area it's actually b

Earlier

With the 1/8th of the sphere

[vague orbit]

For the current one or previous

?

[loud dirge]

For the one with 1/8th of a circle

Sphere cut out

[vague orbit]

Ohk

[vague orbit]

I don’t understand

[loud dirge]

For this current one with the cuboid it's D

[loud dirge]

Keep going I'll keep trying to answer as quickly k as possible

[vague orbit]

What about this

?

[loud dirge]

Volume becomes 2 times

So B

[vague orbit]

23mins left

It’s B right?

[tardy epoch]

Yes

[loud dirge]

Nice we have a helper let's go

[loud dirge]

D

[vague orbit]

Ye

[loud dirge]

Same question?

[vague orbit]

This

[loud dirge]

Should be D but let's see if the helper can confirm that...

Put D for now and move on

If you have more questions put them here pretty fast because my phones low battery

[obtuse pebble]

@vague orbit Has your question been resolved?

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[vague orbit]

@loud dirge I done

Thanks You Very Much

[obtuse pebble]

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Channel closed

Closed due to the original message being deleted

[karmic socket]

Arithmetic sequence, how to find or what's the value of an if the difference is -1/3k and the first term is k ?

[tardy epoch]

Your channel will close

[red tinsel]

Do you know the general formula for an?

[tardy epoch]

Should just open a new one

[karmic socket]

Yesh

[red tinsel]

Plug in the values then

[obtuse pebble]

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[karmic socket]

This is what keep on getting

[karmic socket]

Fg wrong one

[red tinsel]

,rotate

[red tinsel]

That is correct.

What's the issue?

[karmic socket]

That's already the value of an?

Shouldn't u only have n= something or not ? @_@

[royal basin]

the first term and common difference are given in terms of the letter k for you

[red tinsel]

Not necessary. Since a1 was in form of k, an will also be in form of k

[karmic socket]

I see, thank u!

.close

[obtuse pebble]

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[timid silo]

hee hee clap

[obtuse pebble]

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[slow tundra]

Hello can any1 help me with -3/16×y², if y is 8

[red tinsel]

Substitute the value

[slow tundra]

is it -3/16×81 so its -3/16×64/1 u multiply so its -192/16?

[royal basin]

8^2 is not 81

[slow tundra]

64 mb

[obtuse pebble]

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[daring rock]

Double angle identity

$2\sin(\theta)\cos(\theta) = \sin(2\theta)$

[warm shale]

tatpoj

[daring rock]

No, the double angle identities for cos are different

But yeah, for now you kinda have to memorize them. If you keep studying math, you'll learn where they come from soon

yeah

Oh, are you asking if you can switch the sin(x) and cos(x)?

Yes, of course. ab is the same as ba

right

so

2sin(x)cos(x) is the same as

2cos(x)sin(x)

They're equivalent

Yeah sorry I thought you were asking for formulas for cos(2x)

meh they're basically all the same if you know sin^2(x) + cos^2(x) = 1

a horizontal line has a slope of 0

So yeah

take g'(x)

And find x such that g'(x) = 0

Looks good

a clue: e^(3x) never equals 0 for any real number x

[obtuse pebble]

@uncut fulcrum Has your question been resolved?

[obtuse pebble]

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[obtuse pebble]

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[formal kite]

.close

[obtuse pebble]

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[obtuse pebble]

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[oak bear]

Hi, just asking how to find the range and domain for two inequality function

x+y<10
x-y>12

[oak bear]

,rotate

[obtuse pebble]

@oak bear Has your question been resolved?

[obtuse pebble]

@oak bear Has your question been resolved?

[oak bear]

.close

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[slow phoenix]

hello yall im kinda stuck at this part i forgot how limits work soo

[sage geode]

What's n approaching?

[slow phoenix]

n tends to the infinity btw!

[sage geode]

Ah

[slow phoenix]

yup forgot to write that down apologies!

[timid silo]

L'hopitaaaaaaaaal

where u aaaaaaaaaat

[slow phoenix]

would it be n(n+1)/(n+3)

[sage geode]

Then you can rewrite the thing as ln((n+3)/(n+1))/(1/n) and apply L'hopital's rule

[slow phoenix]

eh wait did i write that wrong o.0

[royal basin]

that's gonna be painful

[slow phoenix]

im kinda a bit lost

[timid silo]

it always is like that with those types of questions

surprisingly doesnt take thaat long

[slow phoenix]

i learnt that l'hopital thing but i think i cant rmbr -

[slow phoenix]

wait i have a qs how did the 1/n come about?

[timid silo]

anyways @slow phoenix multiply the numerator and denominator by 1/n

[slow phoenix]

ohhhh its that thing

[sage geode]

n = 1/(1/n)

[timid silo]

so you have a infinity/infinity indeterminate form

and take l'hopital by taking the derivative of the numerator and the denominator

[slow phoenix]

wait ah so uk from my pic uk i took out the n is that part correct?

[timid silo]

you just have to do it once to get rid of the ln

and then simplify the complex fraction and just do normal limit procedures

[slow phoenix]

ah got it

[timid silo]

Anyways show me ur steps just to make sure u didn't mess up somewhere

[slow phoenix]

yup sure

oh god its rotated

how do i rotate it ik theres a way to do it

is that part correct?

[timid silo]

,rotate

[timid silo]

okay okay wait

[slow phoenix]

mhm?

[timid silo]

what happened inside the ln

[warm canopy]

I imagine the intent here is to use the limit definition of e^(ax)

[slow phoenix]

idk TVT i think i killed it

[slow phoenix]

that sounds complex but i think thats what i am supposed to do

[warm canopy]

(n+3)/(n+1) = 1 + 2/(n+1)

[timid silo]

i mean thats basically going to end up doing what l'hopital here is doing

but thats also fair

[warm canopy]

Also it's ambiguous where your power of n is being applied

[slow phoenix]

the power n is applied to the [(n+3)/(n+1)]

sorry my handwriting is kinda bad

i mean im supposed to do the limit of [(n+3)/(n+1)]^n

[warm canopy]

It's not your handwriting it's just the fact that writing lnx^a is ambiguous

[slow phoenix]

but i added the ln cus thats how i usually solve these but i am not sure if thats wrong

oop -

[timid silo]

what was your starting limit?

was it the one you posted

[slow phoenix]

mhm

[timid silo]

wait, so in your original problem, before you added the ln

[slow phoenix]

i am actually doing sequences and i need to see if the particular sequence converges

[timid silo]

was it just (n+3/n+1)^n?

[slow phoenix]

mhm

[warm canopy]

I mean you're just doing to have to undo the ln eventually if it wasn't there to start with

[slow phoenix]

yep

[timid silo]

yeah u still have lny

anyways @slow phoenix

[slow phoenix]

hmm makes sense

[timid silo]

just continue what u were doing with l'hopital

[slow phoenix]

yep im here

oh wait the last pic of mine was it correct?

[timid silo]

you don't have to do whatever u did inside the ln

[slow phoenix]

okay so thats wrong

[timid silo]

just multiply the numerator and denominator by 1/n to get an indeterminate form

[slow phoenix]

wait do u think u can write out this part so i can visualise it im kinda struggling to understand it TvT im sorry for the trouble!!

[timid silo]

mmm okay lemme get a paper because i hate latex

[slow phoenix]

haha ye i struggle to type it in here cus im not used to it ty btw!

[timid silo]

yeah neither i am lmaoo

[slow phoenix]

i was like shook when i saw how people did it

[timid silo]

@slow phoenix

[wild swallow]

what wrong with applying limit definition of e?

[timid silo]

Nothing

[wild swallow]

no lhopital

no pain

[timid silo]

they were doing l'hopital when they said they wanted to apply it, so i thought it was better to stick to one instead of confusing them by going towards two different things

[wild swallow]

well sometimes using lhopitals to solve a limit is just a bad idea

[timid silo]

thats fair

[obtuse pebble]

@slow phoenix Has your question been resolved?

[obtuse pebble]

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[timid silo]

Why does the 0,5 turn into -0,5?

[red tinsel]

Do you know about power rule for derivatives?

[timid silo]

I know that you do 3 x 0,5

Which explains the 1,5 i guess

But not sure what happened with the 0,5 afterwards

Do you have to do 0,5 -1 ?

[red tinsel]

Yes.

[timid silo]

And if it would be -0,5 and you would keep on going it would be -0,5-1 = -1,5 for the next one ?

[red tinsel]

,w d/dx (ax^b)

[timid silo]

I thought removing 0,5 makes it 0 and then the next step would be to remove the F

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by tayyab#3386

[red tinsel]

Check the general formula of derivative of a expression with constant exponent

[timid silo]

This is the general order isnt it?

How it usually goes

[red tinsel]

Yes you subtract 1 from the exponent

And multiply the exponent

[timid silo]

I dont know how to get to the point where you remove X because in the first example its 0,5 and not 1 as the power

So it will never be removed will it

[red tinsel]

No it won't. It can only be removed if there's only x^1

[timid silo]

Like this right?

And next would be -2,5

[timid silo]

Thanks for clarifying

Any idea why its 5 ?

Should it be 0,5 x (-10) = -5?

[red tinsel]

Yes it should be -5

[timid silo]

I think i have to look at the entire piece then, i guess that was my bad

Somehow they changed something that made it 5 instead of -5

[red tinsel]

Oh yeah they shifted it to the other side so sign changed

[slow phoenix]

haha ty btw! i went out and i realised the channel closed

[timid silo]

ohh ofc dw about it!

btw u can follow what snow said there, they show another method of going about doing the limit you shown and it is more time efficient and nicer

[slow phoenix]

haha yep i saw that

[obtuse pebble]

@timid silo Has your question been resolved?

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[obtuse pebble]

Please don't occupy multiple help channels.

[timid silo]

.close

[obtuse pebble]

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[timid silo]

Any explanation how they multiplied it ?

[loud tangle]

they did the math i guess

[obtuse pebble]

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[lunar ravine]

The distance between Exeter and London is 175 miles. At 10:00 on Tuesday Sam left Exeter for London and Morgan left London for Exeter They travelled on the same road. Up to the time when they met, Sam's average speed was 25 miles per hour, and Morgan's average speed was 35 miles an hour.how far away from exeter when sam and Morgan met?

[obtuse pebble]

Please don't occupy multiple help channels.

[lunar ravine]

ok sry

but pls

urgent

[obtuse pebble]

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[lunar ravine]

<@&286206848099549185>

help pls

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[jovial stag]

Hello I computed nash equilibrium and all cancelled to 0

[jovial stag]

what does that mean

[obtuse pebble]

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[grizzled glen]

Hey. I need to determine the growth rate from the
half-life constant of an exponential function. I cannot seem to find a formula for that

[obtuse pebble]

@grizzled glen Has your question been resolved?

[grizzled glen]

<@&286206848099549185> can anyone help with this?

[obtuse pebble]

@grizzled glen Has your question been resolved?

[pulsar veldt]

do u know calculus?

[grizzled glen]

not too sure what that is. English isnt my first language.

i forgot to say that the half life constant is 8,9

[pulsar veldt]

ohh sorry. English isnt my first language too. cant help mate.

[grizzled glen]

so maybe like that?

[grizzled glen]

what about my solution. Does that look probable

[pulsar veldt]

nope sorry. u r beyond my reach of help.

i dont know

[grizzled glen]

alright then have a nice day

[pulsar veldt]

u too..

[jovial stag]

@grizzled glen do you know what derivative is or what is taylor series?

[grizzled glen]

No idea

[jovial stag]

then do you use some tables with values of logarithms?

[grizzled glen]

we wont learn about logoriths until a week or two

[obtuse pebble]

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[deft egret]

hello
why sin(-6*pi ) is equal to zero?

[loud dirge]

Do you know about the unit circle?

[deft egret]

Yeah

[loud dirge]

Well one thing that can be noticed is that

Sin(pi) = 0 and sin(2pi)=0 -6 pi is going to have the same sin as any multiple of 2 pi

So for that reason I know that

Sin(-100000 pi) = 0

[deft egret]

Nice ok, thank you

I don't know why I was stuck on this

[loud dirge]

It's okay, just remember that 2pi is a full lap around the circle so any sin(x) = sin(x + 2kpi)

Anyways glad I could help.

[deft egret]

.close

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[unreal whale]

hey

[obtuse pebble]

Please don't occupy multiple help channels.

[unreal whale]

hey

my thing disappeared

but anyways

9j^2-5j-4

factor

two numbers that multiply to get -4 that add to get -5?

[smoky slate]

,w factorize 9j^2-5j-4

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ralvrz#3477

[high lily]

not quite

[unreal whale]

ramanov help

plz

[high lily]

your quadratic isn't monic, (the leading coefficient isn't 1)
instead you'd consider the pair of numbers that multiply to ac = 9 * -4 = -36
that sum to -5

[unreal whale]

uhh

so

(3j-4)(3j+1)

?

[unreal whale]

simplar terms?

@high lily

[high lily]

doesn't get much simpler than that

[unreal whale]

is my answer correct

[high lily]

no

[unreal whale]

oh alr

thx anyways

.close

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[jagged cargo]

so i know the taylor of series 1/(1-x) is the n from 0 to inf of x^n. for 1/(1+x) its the same but (-1)^n (x)^n. why is it not just -x^n?

[jagged cargo]

and what makes those not mean basically the same thing?

[civic zealot]

if you put the -x in parethensis then it is the same thing

[narrow vault]

the simple answer is that if you multiply 1/(1-x) by -1 you get -1/(1-x) or 1/(x-1)

[dark mango]

its the same thing

its just (ab)^n is the same as a^n * b^n

[civic zealot]

generally speaking -x^n = -(x^n)
So it would always be negative, but that is quickly not true just by plugging in numbers.

[jagged cargo]

oh so a parentheses makes a difference. I see. I didnt put that. may be why my homework didnt accept it

[narrow vault]

yeah, that's -1 mark for sure :p

[jagged cargo]

yeah i put just -x^n

rather than (-1)^n x^n

[civic zealot]

yeah (-x)^n = (-1)^n(x)^n

-x^n = (-1)(x)^n

[jagged cargo]

hm i see

thank you all for the help!

.close

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@lost ocean Has your question been resolved?

[obtuse pebble]

@lost ocean Has your question been resolved?

[gilded needle]

"the set of all points (x,y) in the 2d euclidean plane satisfying the indicated inequality"

[obtuse pebble]

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[little steeple]

Could someone check this (b)(i) for me? I’m just unsure as to whether I’ve written the union of the two sets correctly

[obtuse pebble]

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<@&286206848099549185>

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[timid silo]

would (x^2/3)(x^5/3) in radical form be the cube root of x^7

[timid silo]

or is there a way to simplify it further

[narrow vault]

nah, that's as tidy as it gets

[timid silo]

k

thx

wait can you also help me get this into exponential form?

[narrow vault]

simplify the fraction to a single expression first

[timid silo]

like this?

sorry if that too blurry

@narrow vault

[narrow vault]

ye, now can you simplify the expression inside

[timid silo]

so far i got it into (a^3 x b^10 over a^2)^1/5

ik i didn't write that correct but i think it makes sense

@narrow vault

nvm i got it

.close

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[gusty stone]

Can anyone help me. On why this is wrong?

[gusty stone]

I thought all was good but teacher cut some points

[glad plover]

i mean youre writing things that arent correct first of all

"So $a_n = a_{n+1}$"

[warm shale]

moonside

[obtuse pebble]

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[hollow carbon]

what is the model for Logistic Regression (with 3 predictors x1, x2, x3) and list the assumptions?

[obtuse pebble]

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<@&286206848099549185>

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[thick harness]

3^2x - 3^x+2 + 8 = 0, solve for x

[thick harness]

I'm trying to find out how to do this

[stone bone]

Use log

[earnest elk]

Let 3^x = y

It should become a quadratic then

[thick harness]

so

does it become

a^2 - a +2 +8 = 0

because I don't understand you do that part with 3^x+2

[earnest elk]

3^(x+2) = (3^x)(3^2)

Which is

9(3^x)

[earnest elk]

No

Do you understand?

[thick harness]

does this become 27^x?

(3^x)^3

so it's like

let 3^x = a

• a^3 + a^2 + 8 = 0

is that right?

[earnest elk]

No

[thick harness]

so what's the right answer

oh nv

nvm

I get it now

(3^x)^2 -3^x * 3^2 +8 = 0

let 3^x = a

a^2 - 9a + 8 = 0

right?

alr

I got it

thanks

then you solve for a

a=8 or a=1

then you equate those values to 3^x

and you get x = 0 or x = logbase 3(8)

btw in a text is it best to leave it as that log

or

3logbase3(2)

?

or does it not matter

[obtuse pebble]

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[lone vault]

how do i solve this?

i tried doing it in like the cross mutiply n quad way

how do they get - infty?

[obtuse pebble]

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[meager halo]

Write an equation of a linear and exponential function that both have an average rate of change of −2 on the interval 0 ≤ 𝑥 ≤ 2.

[obtuse pebble]

Please don't occupy multiple help channels.

[meager halo]

.close

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[violet mulch]

hello! I have some trouble setting up a differential equation

[violet mulch]

the information I am given is:

at time t=0

there are 144 units

the rate of change of the units is inversely proportional to the square root of units

and another measurement when t=152. there are 64 units left

now I have tried to set up this ODE to be:

which in turn gives me

at this point I am not sure how to proceed or what I am doing wrong

[river tree]

First change i'd make to this, is that if the rate of change is "inversely proportional to the square root of units", that would mean dy/dt is equal to k divided by the square root of y

[violet mulch]

Aha

[obtuse pebble]

@violet mulch Has your question been resolved?

[violet mulch]

yeah Im still stuck though

[obtuse pebble]

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[bright scaffold]

Hi, I'm just curious how i can simplify this expression into something that gives us Euler's formula.

[ruby path]

I mean you can apply it right now

[bright scaffold]

[ruby path]

whats the original question

[bright scaffold]

Sorry for not seeing it, can u show me?

[ruby path]

and very pretty brackets

i like

[ruby path]

e^inpi

[bright scaffold]

Oh dw, its correct

[bright scaffold]

hahah ty

[ruby path]

nah I don't doubt you

I just need context

[bright scaffold]

Oh sure

I can send the whole problem if u want?

its not that complex

https://cdn.discordapp.com/attachments/342850939306246145/1042775121246556180/IMG_0946.jpg

[ruby path]

holy shit

[bright scaffold]

hahaha

But how do u mean that i can apply it right now?

Isnt the -2 in our way?

[ruby path]

You can just expand it

$-2(\cos n\pi + i\sin n\pi)$

[warm shale]

NEONPerseus

[bright scaffold]

Oh yeahhh

[ruby path]

$-2\cos n\pi -2i\sin n\pi + \cos n\pi -i\sin n\pi$

[warm shale]

NEONPerseus

[ruby path]

$-(\cos n\pi + 3i\sin n\pi)$

[warm shale]

NEONPerseus

[bright scaffold]

oooh

well yeah that can work indeed

[ruby path]

also sin npi is always 0

if n is an integer

[bright scaffold]

Yeah!

so our -2e thingy

its just cosnpi

[ruby path]

so it just becomes -cos npi xD

[bright scaffold]

brilliant

[ruby path]

yup

[bright scaffold]

LOL

Tysm

[ruby path]

np

[bright scaffold]

!close

[ruby path]

.close

[bright scaffold]

ooh

@ruby path Did u expand that last term into cosnpi - i sinnpi btw?

[ruby path]

Yeah I did that to e^(-inpi)

[bright scaffold]

oh nice, i didn't know u could do that, why haven't they included that xd

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[obtuse pebble]

@timid silo Has your question been resolved?

[fallow void]

Write down mathematically what does the area of square E is 44% bigger than the area of square F

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[alpine veldt]

if A ⊂ [0, 1] and A is open is it true that λ(A) = λ(A-) where A- is closure of A?

[nocturne sun]

what's λ(A)?

[alpine raven]

measure ?

[alpine veldt]

its measure yes

i tried thinking of a 'small' open set with a 'big' closure but nothing comes to mind

[obtuse pebble]

@alpine veldt Has your question been resolved?

[alpine veldt]

<@&286206848099549185>

[obtuse pebble]

@alpine veldt Has your question been resolved?

[obtuse pebble]

@alpine veldt Has your question been resolved?

[wild swallow]

A is union of open sets so its open

Q is dense so A- is [0, 1]

measure will be at most 1/9

[alpine veldt]

what is B?

[wild swallow]

🅱️all

[alpine veldt]

ohh ok i see

thanks a lot

.close

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[noble ermine]

i need help for this please

Let f be a continuous function. To make a change of variable of an integral defined as follows, what values ​​of a and b must be taken?

this is the answer

@tardy epoch

[tardy epoch]

Don't ping me out of nowhere

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[weary ember]

hi

[weary ember]

For part a , I got the x intercepts as 4 and -4.

M is (-3,7)

N is (3,7)

Answer to part b incase you need it is 49

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[obtuse pebble]

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[weary ember]

<@&286206848099549185>

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[acoustic granite]

could someone please check over my answer

[acoustic granite]

im not sure what im doing wrong

[obtuse pebble]

@acoustic granite Has your question been resolved?

[obtuse pebble]

@acoustic granite Has your question been resolved?

[obtuse pebble]

@acoustic granite Has your question been resolved?

[obtuse pebble]

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[timid silo]

if I am given this function

and I am given an interval of 2 x values

how do I start with estimating the integral ?

with reimans theory

how would I go about drawing the function to start drawing the squares

[brave bramble]

Riemann sums asks you to construct rectangles under the function, then dying the area of those rectangles

[timid silo]

is what I am trying to figure out

[timid silo]

yes

am I supposed to know how to draw the parabola by just looking at it though?

all I know here is that it slopes down

[brave bramble]

We don't normally need a drawing to use this method, but it is just a parabola

[timid silo]

due to the a being negative

[brave bramble]

Slopes down, has a y-int of 7

[timid silo]

how did you figure this out?

the 7 at the end

ok

[brave bramble]

(bonus: has a slope of 6 at the y-int)

(Which is quick to check with the derivative at x = 0)

[timid silo]

how could you draw the squares without the parabole being drawn precicely ?

[brave bramble]

It can be handy to draw the squares to visualize what you are doing. But with some practice you won't need a drawing

Unless the question is specifically asking you to draw it lol

[timid silo]

its asking me to trace the rectangles

and calculate the left 2

left 4

etc..

same with right side interval

basically calculate the sums of these squares

I am assuming that all I need to do is to find the summit of the parabola

and the zeros

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

for some weird reason the top of the parabola is in the wrong x

.close

[obtuse pebble]

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[floral rock]

I need help with geometry idk how to solve for X

[floral rock]

No come back where did you go

[warped crest]

just make a bunch of rectangles for all the surfaces

[floral rock]

Ok

[warped crest]

once you have all the surface areas of the rectangles

and you have all the rectangles you cannot yet find the surface area of

youre gonna plug it all into a big equation thatll equal 264

[floral rock]

Ok

[obtuse pebble]

@floral rock Has your question been resolved?

[floral rock]

Okay I did what you asked my answer is 7.6

The correct answer is 9.55

Idk how to do it

[warm shale]

Couldn't find an attached image in the last 10 messages.

Nov 18, 2022, 1:09 AM

[floral rock]

.close

[obtuse pebble]

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[fathom kindle]

lol

How do I do this

[hazy vine]

try to find the factors of 3, 12 and 9 first

[fathom kindle]

ya

3

its 3

[rich echo]

ok so 3(x^2+4x+3)

how can i make a help page?

[hazy vine]

#❓how-to-get-help

[fathom kindle]

uh

??

OH

[rich echo]

what i wrote the answer above

[fathom kindle]

well yeah thats what I thought is the answer

but the text book wrote this

?!!??!?!

[rich echo]

yeah make sense

[fathom kindle]

ummm

[rich echo]

the made 2 terms with x^2+4x+3

[fathom kindle]

ig

ooh

[rich echo]

do SPF Sum Product

[fathom kindle]

ok i get it thanks

.close

[rich echo]

np

[obtuse pebble]

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Closed by @fathom kindle

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[fathom kindle]

.reopen

wait

[obtuse pebble]

✅

[fathom kindle]

@rich echo so what would be the final answer

[fathom kindle]

do I have to make this into this

[fathom kindle]

into this

[rich echo]

what the textbook shows, both are right but the 2 terms simplifies it more

[fathom kindle]

oh ok

kk thx

[rich echo]

np

[fathom kindle]

.close

[obtuse pebble]

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[void ridge]

Need to confirm my answer

[void ridge]

this is what I did

[solemn osprey]

,calc 36 * pi

[warm shale]

Result:

113.09733552923

[solemn osprey]

,calc 12^2 * pi * 2

[warm shale]

Result:

904.77868423386

[solemn osprey]

First of all, the radius is 6 while the diameter is 12

[void ridge]

ohh

I thought that was the radius

thought the radius was 12...

[solemn osprey]

Second of all, You doubled the circle area twice, u essentially multiplied by 4

[void ridge]

oh

[solemn osprey]

,calc 9 * 12pi * 2

[warm shale]

Result:

678.5840131754

[void ridge]

hey, after fixing those 2 mistakes what will be the answer?

[solemn osprey]

Lemme calc

[void ridge]

thanks : )

[solemn osprey]

,calc 9*12pi + 12^2pi/2

[warm shale]

Result:

565.48667764616

[void ridge]

thank goodnesssss u came in time. I was about to submit this

[solemn osprey]

Np : )

[void ridge]

my teacher said to round

so

it will be 565?

[solemn osprey]

Yeah do that

Yup!

[void ridge]

THANK YOU SO MUCH!!!

[solemn osprey]

Np

[void ridge]

.close

[obtuse pebble]

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[fathom kindle]

I need to factor that....

but the bx thing is ocnfusing me lol

[earnest elk]

Okay so

[fathom kindle]

hii

[earnest elk]

Start out by looking for something common for all of those terms

That would be b

[fathom kindle]

yes

[earnest elk]

Factor it out first

What do you get?

[fathom kindle]

wdym by factor b

isnt it just b

idk

[earnest elk]

Factor b out

It’s common

[fathom kindle]

ok

[earnest elk]

All the terms have b

[fathom kindle]

ya ik

[fathom kindle]

uhh

[earnest elk]

So Ye what you get?

[earnest elk]

#❓how-to-get-help

[fathom kindle]

b(x^2 + 10x - 24) ??

idk

[earnest elk]

Yes

[fathom kindle]

o

ok

[earnest elk]

Can you factor out the (x^2+10x-24) further?

[fathom kindle]

yes

b(x+12)(x-2)

[earnest elk]

Then it should be good to go:)

[fathom kindle]

Ok thx

[earnest elk]

Yes:)

Np

Have a good day

[fathom kindle]

I have another question lol its about the same thing

If u have time

[earnest elk]

Okay

[earnest elk]

Sho ahead

[fathom kindle]

what if u have it cubed

x^3

[earnest elk]

What’s common?

[fathom kindle]

well x

[earnest elk]

factor it out

[fathom kindle]

but theres different x's

x^3 and x^2 and x

[earnest elk]

x^3 is just x * x * x

[fathom kindle]

oh

oops lol

obviously

ok

one sec

x(x^2+18x+72)

[earnest elk]

18x

But yes

[fathom kindle]

oh

oh yes

[earnest elk]

You should be able to take it away from here

Gtg

[fathom kindle]

ok i get it

thx

.close

[obtuse pebble]

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[restive sapphire]

So do I what in the how

[obtuse pebble]

@restive sapphire Has your question been resolved?

[drowsy nest]

@restive sapphire 1/e = e^-1

[restive sapphire]

howd you come to this

i need to know how to get it myself if that makes sense

[drowsy nest]

1 divided by a variable is just the variable itself to the power -1

for example 1/a = a^-1

1/s = s^-1

[restive sapphire]

hmm did i type it in wrong?

[drowsy nest]

1/alpha = alpha^-1

nooo i didnt list that as the answer

[restive sapphire]

ohhh my fault

[drowsy nest]

if you did 1/e = e^-1 you would have e^ln(e^-1)

[restive sapphire]

okay

[drowsy nest]

ln(e^-1) = -1

its a property just like e^(ln(x)) = x

or ln(e^(x)) = x

[old dagger]

$x^{log_x{a}} = a$

[warm shale]

Noone

[drowsy nest]

ln is inverse of e

[restive sapphire]

okay that makes sense

okay

so we have e^-1?

[drowsy nest]

ya

[restive sapphire]

thanks kings

.close

[obtuse pebble]

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[drowsy nest]

you wrote 1/e = e^-1 on your program. its actually e^-1 all by itself

[restive sapphire]

ye

[drowsy nest]

yay

[restive sapphire]

you got time for one more

[obtuse pebble]

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Remember:
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drowsy nest]

sure

[drowsy nest]

you can plug sqrt(b) into the equation

and solve the log expression