#groups-rings-fields
406252 messages · Page 489 of 407
right
right, look at f on stalks
@olive mirage I dont' know what a canonical form for finitely generated abelian groups is
I’m almost a little worried the map doesn’t extend to the field of fractions
Wouldn’t the map have to be injective?
it induces O_Y,η -> O_X,ξ
In order to do that
Field of fractions is functorial, right?
Also, second quick question, what does a set of representatives look like? Say for example for the conjugacy classes of S_4?
No alex you don't
need to take field of fractions
The local ring is the function field
Right?
Isnt that the previous problem?
Dude omg I’m dumb
Lmaooo
No I don’t see how it could be
yeah
You’d need objectivity to do it in the obvious way
Right
Maybe in like Ring_mono to Ring
Or Field I guess
Wait no!
Mono isn’t even injective
Yeah I agree now
Lmao
So you get a map from the residue field of the kernel
like φ : B -> A induces a map κ(ker φ) -> Frac(A)
Right?
if you do the obvious thing
Ihhh
And for φ mono you get a map on the fraction fields

Wut
?
Yeah
We can extend maps into a field to the field of fractions
Yes
So we get Frac(B/ker φ) -> Frac(A)
κ(p) = Frac(B/p), right?
Lmaooo
okay so we know how the field extension works
I feel like the number of sheets should be the cardinality of the fiber of η
err, the degree of the extension
Sheets?
Not number of sheets
Oh lmfao
I was thinking of covering spaces lol
lmaooooo
Lmaooo
Absolutely not
Okay, I gotta do something for a bit
Tfw shamrock who said he isn’t doing AG is better at it than you
Oh wait, f is finite type
Yeah this is mondo important
Yeah that’s the goal
does finite type imply finite type on stalks?
Then do Zariski’s lemma
well take a cover by affine with the finite type assumption
Since I thought I had to take FOF
Take the cover element containing your point
Because I was peanut brain
take the same generators
Now you're looking at localization
And it's easy
I think
Idk, I think generic finiteness might matter here
I feel like you need a finite cover or something
It probably will later, but I think this proves the extension is finite
You have a finite cover
By?
But also I don't see why that's relevant
Self oof time
I think it's just true that a locally finite type map of schemes is finite type on stalks
Maybe
By going to affines and thinking about localization
Yup
Now you want an open that’s dense
So like
Any open nbd of the generic point will be dense
I mean like
I guess we're saying the same thing lol
Image is dense
Ahh yeah
Sorry that was very not clear
Oh wait
That’s doesn’t matter I think
The problem want an open dense subset of Y
But that just means nonempty like you said lmao
Right lol
lol
Mood
Still seems unlikely
ugh I gotta work through Hartshorne now so I can keep flexing on magician
btw, I really like Liu's algebraic geometry text
that's the one my profs were really advocates for
I've heard good things about it modulo his treatment of cohomology
Tbh when I do Vakil's class I'm thinking of TeXing notes of my own lol
dangerous game there
yeah, I'm usually looking for "Who gives me the right three sentence intuition for this"
which is not what Liu does, btw. But Liu does the technical stuff in sufficient generality to apply it\
Honestly one thing that I'm realizing might have hurt me with Hartshorne is that it doesn't have a ton of examples
Maybe they were in the exercises I didn't do
But I don't feel like I can write down very many interesting schemes ig
I can write down one for every ring
(yeah I wasn't counting affine ones as "interesting" lol)
yeah, I think a rich stable of examples you care about is essential in algebraic geometry
and most algebraic geometry texts are allergic to examples
When I think about like, schemes that aren't affine I'm pretty much just looking at projective space and the line with a doubled origin
there's all this complicated machinery for gluing
Baked into the definition of a scheme
And I don't really see the point
I mean, it is helpful to note that for curves, they're all affine plus some stuff
so you really are getitng nearly the whole picture by thinking about affines
if X is a curve, take the field of rational functions on X, and then the places of that form the points of a smooth projective variety.
(this may not be the kind of thing that makes you happy, but I find it reassuring)
(it also shows you that the notion of a "point at infinity" is nonsense)
Sorry, I don't know what the places of a field are
and I happen to like my point at infinity thank you very much
you can define nonarchimedean norms on a field
these induce discrete valuation rings, and then places
the places are the valuations, like Q, for example, has ap lace for each prime, and the archimedean absolute value
(which, not at all coincidentally, corresponds to the points of Spec(Z))
though the analogy is a little messy, and I think people oversell the "Spec(Z) is a curve" stuff
ahhh
note I"m using "variety" here in the sense of "special type of scheme"
yup
because if you do the whole thing I suggested, you definitely get fuzzy points, like the valuation corresponding to (x^2+1) if that happens to be irreducible over your field
So how is the original curve related to this new thing built out of places?
(Spec(RealNumbers[x]) is a great example to understand geometrically what is happening so you have better intuition for e.g. Spec(F_p[x])
so, are you familiar with divisors?
no, sorry
I dropped out of my ag course before we got to curves and divisors and stuff
didn't understand schemes well enough
So, this is something that shows up in a lot of places, but if you have a function, then the divisor of the function is a formal sum of the zeroes of the function minus the poles of the function
I feel like this showed up in my complex analysis course
not under that name
or stated explicitly
it definitely did. Divisors, like most of algebraic geometry, is just a very good fake of complex analysis.
lol
but the elements of your function field are the meromorphic functions on your curve
and the valuations let you calculate the divisors of them
which lets you calculate the sheaf of functions and all that jazz
ugh this is the thing about AG. Every time someone talks to me about it it sounds really interesting and cool, but then when I actually try to learn it I just get stuck on nitty gritty details about schemes
I guess that's the price of the theory
But a nice example of this is if you consider that ugly nodal cubic, Spec(k[t^2,t^3]) and you do this process, the fraction field is definitely k(t)
so then you get P^1
and so this even kills all the singularities for you
so by only looking at fields you lose some information
(and yeah @latent anvil with you 100%, I definitely spend a lot of my life feeling that way when drudging through algebraic geometry stuff)
Well, lose or gain, depending on your view. If you want to study singularities of curves, yes, you lost something
but this means every curve is automatically and canonically associated with a smooth projective curve which it is birational to.
and for most applications, if you are looking at a singular curve, what you actually want is the smooth projective thing it is a singular model of.
ahh it kind of makes sense that this new projective curve will be birational to the original one
Since we built it up out of the function field
Yeah Shamrock the promise land exists
Once you finally get to riemann roch
And some coho
The world opens up
(note this all falls apart terribly once you get to surfaces)
You just have to go through an entire quarter of bullshit to get there
I mean, it is incredibly frustrating how long it takes to get to things like dimension in algebraic geometry that are intuitive and basic
I meaaaan
Dimension is intuitive
In the great cases
But can go really fuckly in the not great cases
Well, I assume no one does algebraic geometry for any reason other than counting solutions to polynomials over finite fields
so dimension there isn't messy
A completely harmless assumption
Haha
Finite fields scare me
Besides F_p for a prime p
and even those
(but one consequence of that function field stuff is that every curve is birational to the zero set of a two variable polynomial)
which element of F_2 scares you?
Fields without 2 🤢
F_2 has a 2
that 2 just happens to be 0
Here is a fun problem: Prove that no ring has exactly 5 units
Proof 5 is prime QED
I want to say ζ will generate a field
:^)
No
I know several rings with a prime number of units
It’s a joke
I disagree with myself
why finite?
anything is a unit or a zero divisor
Something like that was on our algebra midterm I feel
Are all the zero divisors contained in the Jacobson radical or something?
But I forget if it was unit or whatnot
Sounds fake
Hold up let me get problem
The image will also have 5 units

Wait doesn't that mean the image is Z[x]/(x^5 - 1)?
Which has too many units
Idk if that was correct
Alex check what I did or else
🔫
ζ satisfies it right?
Why specifically 5?
It'll be the elephant
Or is it
It kind of is
ζ^5 = 1
I'm not sure why you assumed that you could get rid of the zeta-1?
Wym zeta?
This wouldn’t happen with 3. Because 3 is great. No I mean why does this argument work for 5 but not any random ass prime
The image will contain ζ-1
I only get to Z[x]/<x^5-1>
I think you assumed something about no zero divisors to get further
haha I don't get any points for seeing things in a problem I gave you haha
hmm this is less good
So wlog we're looking at quotients of Z[x]/(x^5 - 1)
and x generates the group of units
Shamrock is just good at algebra
I wanted to list off the ideals containing x^5 - 1
Lol
you are missing only one key idea, although you alluded to it earlier
Characteristic?
hmm I don't really see how to determine that easily
Or what it tells us
What can you say about the unit group of a ring of, say, characteristic 0
No
Whoops
(supposing it is finite)
it's even
I was thinking about <1> under addition
The ideal contains 2?
We're looking at a quotient of F2[x]/(x^5 - 1)
that's pretty small
The kernel
So we start with some abstract ring
then we get a map from Z[x]
Right?
I showed that that ring has to have char 2
Which means the kernel of the unique map from Z is (2)
So the map from Z[x] contains 2 in its kernel
by looking at the image we can reduce to looking at quotients of F2[x]/(x^5 - 1)
And F2[x] is a very nice ring
The ideals containing (x^5 - 1) are just that, (1), (x-1), and (x^4 + x^3 + x^2 + x + 1)
right?
I have no clue tbh. I hate finite fields
okay so from the beginning, assume A is a ring with 5 units
I don’t see why you can’t factor the elephant tho
oh I think I've just done that before?
In like Galois theory
Might be wrong though
Hmm ig this is over F2
Idk I hate F2
It has no roots
So that’s why I’m concerned
It has to factor as a product of quadratics
x^2 + x + 1 is the only irreducible quadratic right?
it is
Yes
(it does not)
(x^2+x+1)^2=x^4+x^2+1 because of squaring in char 2 etc
Oh yeah
F2[x]/(x-1) = F2 has too few units
F2[x]/(elephant) is F16 I think?
It's a finite field anyways
F2[x] has how many units?
and note that F_16 has a unit group of order 15, which is divisibe by 5, which is a nice little sanity check there
It has 2 though I think
(I think just 1 unit in F_2[x])
Tfw
(no no, you're good)
The final
Yeah we can
Why not?
They're both irreducible
so they generate coprime ideals
since we're in a PID
So the last ring is F2 × F16
which doesn't work
which has 31 units?
It has 15 units still
(1, 0)^(-1) time
Yeah
That was a fun problem zeta!
haha I looooove algebra problems, I have many
I may put it on my algebra problem sets next year...
it is not so hard to go from there to showing exactly which odd numbersa re the number of units in a ring
Yeah so odd implies char 2
Wait uhhh
Oh but it might not be cyclic
Are you going to run 398 again?
(though you need to throw around the word semi simple, which is not a word I'm very happy when shows up)
I'm bummed about not getting 33X
Okay. If u are let me know I can help again if u like
But ig I'll have more time
are you an undegrad, grad student, prof shamrock?
undergrad
we're mostly taking the same courses
We go to the same uni and everything 🤗
magician and I
Although next year not really 😦
anyway, if you want a massive pile of algebra problems let me know
Yeah manifolds is pretty great
😦
Zeta pm me with them or post a link or something
Ty
I was going to start doing research stuff
After my break
This is more fun
lol
I’m gonna get so good at manifolds you’ll be so jealous. You’ll be like woaaah you solved the tubular neighborhood problem so quickly woaaah
if you decide you want more, I have all manner of old exams and homework sets I've given grad/undergard courses, so if you want to use them pedagogically I'm happy to share those
Except I won’t since you’re mad nasty at manifolds apparently lol
(though I won't post that in public channel, but you can PM)
Wow that’s a lot of problems
so for context about what I was saying with problem sets
I started an algebra study group in my first year
and ran it for students this year
I was in it first year!
The undergrad algebra courses here are pretty slow
(This packet was originally constructed to help students study for quals when I was a grad student. Though since then I've often used it to write quals)
students in honors analysis usually don't like them because of the pace
But it's hard to skip directly to grad algebra
Yeah it looked like quals type stuff Zeta
oh that's cool
But yeah, I think there are a lot of problems in there that are naturally sort of intriguing
I am always happy to steal more problems
so this is your syllabus for your study group?
I was going to say "this doen'st seem so slow" haha
There were some difficulties this year
Yeah the issue is that I organized the study group in my first year primarily for myself
So I could learn algebra
And I had a little bit of background with group theory already
so the original schedule and problem sets were written to accommodate that (also the person running it was insane and had no concept of difficulty)
bffs tho
Now he’s at Berkeley studying ANT
So
Yeah he’s so sweet
He baked us cookies when we studied for math tests in analysis
Since he was our analysis TA
Yeah, my problem set is definitely designed with the idea that you can tease hints at people to guid them through it if they get stuck
galaxy brain algebra course:
Give them that problem set packet
meet twice a week
that's it
no structure to the meetings
just work on the problems and learn as needed
Lol
oh yeah I forgot to brag about the other cool thing with my study group
hahaha, nah, if I'm doing grad algebra I'm not giving up having a captive audience to listen to me talk about algebra for hours 😛
Mine were great
I was guessing that from the guest lecture thing
Yours were looooong
I still maintain in winter I got the longest one
Okay yes
But by spring one was good
I wrote the write up
And Thomas said “this is a good write up”
And I was like yesssss
I kind of want to start another study group
For
If you do ANT
Blood pact
get Thomas to TA over zoom
These are good problem sets, and I've seen some nice ones here I had not seen befroe
Zoph is typing
The quality gets dodgy at the second half of spring
It’s so crazy
Corona made things awkward
haha yeah Well if you want a lot of Galois Theory problems, there is no shortage
although problem one is "Prove everything about Finite fields"
Aiyayay
These were originally written by an algebraic number theory person who has a finite group theory hobby
Yeah all the ring theory was just number theory lol
Which I think is a great combination for intro group theory and Galois theory
But the ring theory section had to be reworked...
We also had fun and tried to use the word involution as much as possible for the week 1 hw
Our TA randomly used it and we thought it was funny
I really dig finite group theory, it's an excuse to do combinatorics. And ring theory is mostly pretty ugly
ring theory thinks you're ugly too
it is commutative algebra I don't like. I like all the polynomial rings over fields stuff.
oh zeta you might find this interesting: https://math.berkeley.edu/~tb65536/Commuting_Probability.pdf
Ohhhh that’s so cool
there was a problem on those problem sets about commuting probability
which we were very excited to put on there
Shamrock
because it's cool
Show him the secret problem
I have it memorized, the number
1004913?
Yeah
Also, the fact he emailed them and they got back!
what?
He posted it in slack I think
aight I gotta go think about operads
this problem looks familiar
It’s cool
I think this is in Dummit and Foote?
or something similar
the probability two elements commute paper is awesome
It is
It’s a problem, but this dude put it on our like hw for week 5 lmao
Absolutely insane haha
You can also solve it via rep theory using induced characters
something something tensor product disappears in a puff of smoke
well, a character is equivalaent to a module over the group ring FG
and the induced character is what you get by doing the change of base tensor product of an FH module to an FG module
Ah okay, yeah I never learned induced character
We stopped right before that in our class
And I don’t really care for rep theory
which is on the one hand easy to say and on the other hand horrible haha
I just don’t get rep theory haha
haha and yet to a lot of people the whole point of algebraic geometry is to produce representations of Qbar
Anytime I have to do anything related to semisimodules or rep theory I have to crack open my textbook
Yeah I think someone at my uni does that for her research
Julia Petsova I believe
Yeah, I really do not know why, but modules do not... how do you youths say... vibe with me 😛
Like she has some papers doing some rep theory stuff over schemes, I don’t get it at all
I like modules
They’re cool
I love group actions and vector spaces
Also how do you do AG
and a module is just like those two had a baby
I don't really think of those as modules, intuitively
they're functions
and I get functions
Oh wow
I am like
Damn why would this be true...
Ohhh it’s true for modules
Haha
like sure, C([0,1]) is a C(R) module, but I'm not inclined to think of it that way
That’s fair
Wait
Oh yeah, I would more naturally think of it as an R-module
But maybe R embeds into C(R) like, faithfully as constant functions
So C(R) might just be a strict expansion, but I’m too tired to think about it lol
I think it does haha
Idk, thinkin of stuff as functions isn’t really@how I go about it
Like for schemes people talk about like the functions being ideals or something and the primes the points
And evaluating is quotienting??
I don’t get that at all and don’t bother thinking about it that way haha
like, thinking of the germ of a function makes way more sense to me than thinking about localizing at a maximal ideal
Oh I am complete opposite
Then again I haven’t ever seen a definition of germ, but to me that is just the image of the function in the stalk lmao
In the case where your sheaf is like C^infinity functions or something
the germ is tantamount to the Taylor series if your function is holomorphic
Is it?
Huh
I guess that makes sense given that germ to my knowledge is supposed to be like it’s local behavior
yeah, so the germ is really some kind of (inverse?) limit over open sets taht contain your point
That’s just how you construct the stalks haha
ahhh, but complex geometry is so rigid that knowing the local behavior at one point dictates the entire global behavior
Yeah, so that's why a germ is equivalent to a Taylor series
It’s like the super gluing axiom haha
(note that real functions are horrible creatures, so this is not at all true if you look at, say, real manifolds)
but Algebraic Geometry is just Complex Analysis
(nothing like real analysis, basically)
:^)
My uh frehsman honors analysis prof is cited in Hartshorne
For a paper he did with his advisor Kodaira
But back then AG was just several complex variables haha
there is a big theorem of Serre that goes by the somewhat comical name GAGA, that says that after you develop all this machinery, algebraic geometry over C is exactly isomorphic to analytic geometry over C
He just retired at the end of this year
Yeah GAGA is big
I’ve heard of it
A friend read it
And his only comments were
“The results should not follow from the machinery”
He basically said that like
but the way I always frame it is that C is the answer in the back of the book for algebraic geometry that told us we got the answer right
For how relatively basic the machinery was
and gives us hope that the results will be meaningful elsewhre
well, manifolds over C include C^n and such
Ah okay, I wasn’t sure if analytic geometry over C included that
Yeah, it does.
I see
(so it isn't just for curves)
I want to learn some several complex variables eventually
It seems fun
But I need to redo my riemann surfaces stuff
My class fell apart due to COVID
So I learned like nothing
several complex variables is an area I know almost nothing about that I wish I knew more of
I am going to really make myself learn Griffiths and Harris some day 😛
I’d like to understand riemann surfaces eventually too lol
But from the small amount of stuff I did
All of it is about understanding LFTs and uhhh, fucking groups of automorphisms
it does Riemann Surfaces and algebraic geometry together, and is amazing
Fuchsian groups and stuff
We used “a concise course” and I highly disagree with that choice of text
We did not use it the other two quarters
And we black boxed stuff so I didn’t feel like I actually understood it
I wish my first semester of algebraic geometry had been Miranda, but instead I only found the book after spending years learning the stuff
oh you would hate me as a lecturer, I blackbox everything haha
The exercises were very hard
And nothing like anything we did before, and none of it used tiemann surfaces
It was all about groups of automorphisms so it was really just topological group stuff
Algebraic geometry as a subject does not have good exercises
So there was this disconnect where
The stuff you learn and the stuff I did were not at all connected
and this extends to Riemann surface stuff
Algebraic Geometry as a discipline sort of sucks
I’m inclined to parrot what people say that it’s just very hard and...
But all math is hard
Yet they manage to teach it in a less shitty way lmao
But I’m just stuck in the grindstone, so Hartshorne is always by my side
forming an area into an easily digestible story takes time
and is especially difficult when the area is constantly shifting focus
Fair enough, it’s just I feel that the mindset of the people doing it is a bit off
Any other subject I’ve seen people actively recommend you start with easier stuff with normal exercises
Which build up, and have some computation, builds the story up gradually
yeah, I think in Algebraic Geometry they should really make you do the classical stuff in a better way first.
It seems most people just tell you to go do every Hartshorne exercise from the get go and to go duck off
haha yeah, I think "Don't look at Hartshorne" was good advice that I got
but I have very few algebraic geometry sources I enthusiastically recommend
I’m already stuck with it 😔
I feel like the subject is sort of, this self feeding loop tho which sort of bred this issue
I think modern day some people are trying to change it like Vakil
yeah, I do like his notes, and wish they existed when I was a student
But AG suffers that issue where all the terminology becomes so fucked it’s all but impenetrable even for those in neighboring fields
I feel like there’s sort of a “big boys club” mentality
Which I hope to see be eroded
haha neighboring fields? it is impentrable to me and I'm published in it 😛
but yeah, I think taht mentality bled over from number theory, and especially the style of people like Grothendeik who really loved abstraction
Idk, I didn’t think I’d ever do AG but UW just sucks you into it
You've heard of the Grothendeik prime, right?
My analysis prof said for some reason a ton of his students just go and do AG for their PhD
Yeah lmao
I don’t know it, I wanna say 42?
Or something lol
57
Is that not prime?
Does 7 divide it
Yeah 7*13
Tricky asshole
I thought to myself “okay if anything divides it it’s gotta be 7”
That’s the trickiest one among low numbers haha
91 is the only number less than 100 that will trick you
if you can identify squares, evens, mutliples of 3 5 and 11
Yeah, I’m incluned to say some multiples of 3 look prime until you just add the digits
Like if you had only 100 milliseconds to answer I think I’d say 93 is prime
But at least there’s an easy test lol
What is the centre of an action?
I’m not familiar with the term
can we see the context?
What’s the context
it should be defined somewhere before
I have never seen that term, and to be honest google comes up with nothing. What textbook are you using?
ctrl+f center
It certainly isn’t a standard definition, so if it isn’t defined earlier on the problem set or something send an email to your prof
He hasnt' responded yet
It can’t be like the set of elements x such that for all g, gx = xg since a group action ai priori only has one side
Dummit and Foote
Probably think of an action as a homomorphism G->Sym(X)
Ohhhhhh
Symmetric group on X
That's my guess
Adjoint action = conjugation?
I think so?
The set of g such that ghx = hgx for all h
Like we have
So phi(g) is in the center of phi(G)
Perhaps they mean the stabilizer?
C^infty functions are great
A lot of the uh things here are not very well defined?
Who dissed on them?
I.e, he never explained what a semidirect product is but it's in the homework
you know what else is great? modules over C^infty(M)
zeta and magician did up above
And thus shamrock just discovered sheaf theory
ban them plz
wait while I'm asking questions, what does a "Set of representatives" look like
I didn’t shit talk modules
haha I'm very happy with modules of functions
Because we have this
Ah
So a conjugacy class is formed by an equivalence relation right?
A representative is one element in a given equivalence class
But the onyl thing that we have regarding "set of representatives is
A set of representatives is just a fundamental domain 🙃
So it just means one element from each conjugate class
- Grothendieck probably
oh also magician, sandor said he always tells his students to do several complex variables/complex manifolds
and no one ever does
So like for D_4 you'd have r is a representative?
be the change he wishes to see in the world
Well
Lmao
Let’s go with a quotient group first
ok
There's a guy in the actual UW who does K3 surfaces
UW?
He's fairly young (first year as an assistant prof, previously he was a Vakil postdoc)
who is this?
So like what’s an explicit example
Michael Kemeny
Umm Take Z/4Z
Sure
Your elements are like 0,1,2,3 right up to equivalence
https://www.math.wisc.edu/~kemeny/homepage.html his stuff is basically complex geometry and it seems cool
K3 surfaces, syzygies, moduli stuff
Then you have a copy of Z/2Z in ther with {0,2} right?
It’s iso to Z/2Z
ok yes
Then the quotient is Z/2Z right? Or at least isomorphic to it?
quotient of?
ah ok
For ease call Z/4Z G
So elements of G/H are of the form g + H
Where g + H = g’ + H if g^-1g’ is in H?
What's g'
That’s like, the element wise construction you probably have seen
Just any other element of G
g,g’ in G
Like in our specific case
0 + H = 2 + H
Since the difference of 2 and 0 is in H = {0,2}
sure
I mean, if it doesn’t make sense that’ll be big so it sure means yes then I can move in
But if it means “uh, idk sure” the next part won’t make sense
I understand what G/H is
Yea
A representative of that object is the specific form you write it in
So in this case
0 + H is a representative of that element
As is 2 + H
You can choose to write that element multiple ways, but a specific way you choose to write it is a representative
That’s why when you define a function from a quotient you have to make sure it’s well defined
Oh but 0 + H and 2+H are the same objects
Since you normally write it in terms of “a representstive” but you have to check that if you took a different one the output is the same
Yeah
But for example if I made a function that sends x + H to just x
It isnt well defined
Because then 0 + H goes to 0
And 2 + H goes to 2
But they’re equal!
So they have to go to the same thing
I think I see
So for conjugacy classes
So then say for example 1 + H is a different object from 0 + H or 2 + H
Yea, for Z/4Z and H = {0, 2}
Yup
Oh so like let’s take a set of representatives for G/H
You have 4 choices
{0 + H, 1 + H}
Or {2 + H, 1 + H}
Or {0 + H, 3 + H}
Or finally {2 + H, 3 + H}
so you expressed G/H as a set, you accounted for all (2) elements it has
By providing one representative of each equivalence class
Oooh ok
So conjugacy classes is the same thing
Pick one element from each conjugacy class
So you have to compute what the conjugacy classes are
So it's ilke how for modular arithmetic you have like, say if it's mod 4 then you have just {0, 1, 2, 3} to pick from right?
Yeah
I mean teeechnically
You could pick 5
But that’s the same as 1
So why bother?
There’s a most natural set of representatives
That’s {0,1,2,3}
So in this case I want to find all the things in that can possibly be mapped to in S_8?
And then pick 1 to represent each one?
No so
You know what a conjugacy class is right?
A set where like all the elements are conjugate to one another
You need to pick one of them from each one
Buuuut in the case of symmetric groups conjugacy classes are exactly the same as the like, sizes of the orbits
Oh wait it's not asking for equivalence classes
Ok yea idk what a conjugacy class is
😔
So you can use that to figure out what the conjugacy classes are
I will read through this and then if I still have questions come back
Thank you!
Oh wait ok this bit I think I understand; partitions iand combinatorices are something that I understand 
That’s good then!
o_o nubre of conjugacy classes of S_n equals the number of partitions of n.... that means 22 conjugacy classes of this lmao
Oh so there's a bijection between partitions and conjugacy classes
Yeah
But you can just write trivial examples for each conjugacy class
I mean, not trivial
Yea
Yea
So it’ll just be tedious to write out
The issue is justifying the size
I don’t think D&F does it, but it’s all combinatorics
Justifying the size?
I just don’t think it’ll be fun to compute it 22 fucking times
The problem asks for the size of the conjugacy classes too
Yeah, not very fun
It’s a lot of !
GL, I did this for like... S_6? But that’s way less
You can have something of the form (123)(45)
And that isn’t
You have to calculate how many of any given cycle type there can be which is annoying
I forget the formula off the top of my head
There isn’t a really nice way to put it
It’s like n!
Then you divide by how many cycles of every size you have
Since (123)(456) = (456)(123)
Then divide it by like the product of the sizes of cycles since (123) = (312) = (231)
Then you do something else I totally forget lol
https://groupprops.subwiki.org/wiki/Conjugacy_class_size_formula_in_symmetric_group that does not look fun
It isn’t too bad once you do a few
But justifying it is annoying and it’s hard to write in a closed form
thanks prof
So I'm a bit stuck on this one here. How does a have an order of 9 if the group has an order of 27?
Why do you think a having order 9 is a problem?
Also, a^9 = e does not mean a has order 9
It means it has order dividing 9 (i.e. 1, 3, 9)
@half nebula the group doesn't have an element of order 27. If it did, it would be cyclic, but the problem assumes the group isn't cyclic
Ooooooooh okay.
So the elements for it can't be order 27, so they have to be order 1, 3, or 9.
...
