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does g^-1(x) denote inverse function or just 1/g(x)
btw I got b=13/3 I'm not sure if this is right
Hii
g^-1(x) is different than 1/g(x)
g^-1(2)=3 implies g(3)=2
So b=8
Bc b-2(3) = 2
b=2+6
b = 8
Also where did u reach while trying to get the value of a
@livid flame are you still there
@livid flame Has your question been resolved?
Inverse function
Yes that's true
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how would you calculate the difference between 2 numbers if you don't know one of them, meaning you don't know which one is bigger than the other
if you know only one of the numbers but not the other, and know absolutely nothing else at all, then it's impossible.
however, http://xyproblem.info/
Asking about your attempted solution rather than your actual problem
yeah of course but if i can put in an equation, for example if I have to divide 5 by the difference between 5 and c and i know that the result is equal to 3
would it still be impossible
sorry, i don't understand.
can you post a picture of the problem, or its statement clearly written out?
Kinda sounds like (5-c)/5 = 3 (or 5/(5-c) = 3 I guess with the wording)
kinda sounds like someone misread something
...
@alpine sable do you have a picture of the original problem so that we can see its statement exactly as it is written, with zero modification?
i completely misread it, and i was doing mental gymnastics, so none of it actually makes sense
but thanks for your guys time
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how tf can a rectangle be right-angled, if one of the angles is 30 degrees?!
why not
"ABCD is a rectangle. If angle BAC=30 degrees, and AD =4sqrt(7), find the radius of the circumscribed around ABCD circle"
are you asking how a triangle can have a right angle, and yet has an angle with 30˚?
I think it is a rectangle with a bisecting line from one corner to another
So DAC would be 60 degrees
I'll go with that, ty a lot! The problem is incredibly confusing
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did you draw a graph?
@undone iris Has your question been resolved?
drew this on ms paint......
MS Paint has a line tool, FYI.
oh, i didnt know that
but its multiplied by 2 right?
yes, this is just a half
wouldnt that make it $l \cdot \sin \theta$
Invisible
秋水
this is wrong
$\sin\theta = 2 \sin(\frac{\theta}{2}) \cos(\frac{\theta}{2})$
秋水
hMmMmM
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Why did the 3x replace the 2x+1
How does the last line work
$$6x^2+3x = 3x \times 2x +3x \times 1 = 3x(2x+1)$$
秋水
ah okay
But what about the last part?
(3x+2)<---- how does dis work?'
ok so
Take 2x + 1 common
Then you'll get your answer
do you understand btw
I did
Like
(2x+1) (2x+1) after this
Idk what to do
I gtg eat I will come in 15
$3x(2x+1) + 2(2x+1)$ right ? Now just like you took out a common factor of $3x$ in $6x^2 + 3x$, and 2 in $4x + 2$, do the same thing by taking 2x+1 common. You are basically following the reverse process of the distributive law here
S🅱innoto
k
@earnest river Has your question been resolved?
@earnest river you back?
ok so
lets say b = (2x+1)
3x(b) + 2(b) = (3x + 2)(b)
3x( 2x + 1 ) + 2(2x + 1) = (3x + 2)(2x + 1)
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.reopen
✅
you're welcome
i mean like !close works?
oh
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ok that makes sense
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ok
I am stuck here
As the bot stated, don't open multiple channels
unfortunately
I mean I did
-dldh guy
It means close your other channels before opening a new one
put numbers in x
oh
and see what the root is
I forgot everything about cubics
u just put numbers in x
can I just simplify it and use quadratic formula
that doesn't seem like a great way of approaching it
yes
thats how you get the root of cubics
can you explain it (sorry I literally forgot everything about them)
u cant
how tf r u gonna use quadratic formula on that
ok so what's the root?
what's the cubic formula
no
no idea
I know it is
??
ok
but he used another theorem
This is probably the worst way to approach this problem
which was the Rational Zero Theorem
yeah that's what I thought
Yes , use that
Look it up
This precalculus video tutorial provides a basic introduction into the rational zero theorem. It explains how to find all the zeros of a polynomial function by using the rational zero theorem and by factoring polynomials. The rational zero theorem helps you to identify the first zero by listing all possible rational zeros and then evaluating t...
It's not hard to Google
ikk
Ok, consider the factors of 360, both positive and negative and substitute them into the equation
thats literally the same method
I'm not high level math
this is the same one
xD
Atleast one of the factors will turn out to be a root of the cubic
you put numbers in x first
yeah i know
but you need to put numbers in x first
and get the root for it
how can I pick which to get
No it's not, you're saying plug in numbers for x and just randomly guess, that is not the same method
@robust phoenix
ok
so uh
Apply the rational root theorem, where you find the factors of the last term and the factors of the first term. And you create a fraction, where it's the last term factorsover the first term factors
did you even watch the video?
im talking about the video
last term is 360?
You're saying plug in random numbers, the video uses rational root theorem, a more logical approach than just plugging in values
Yes
You want the coefficient of the terms
x is either 5 or 3 or 2
So not x^3
but neither of those are the result
After finding one root, factorise the expression (follows from factor theorem) to get another quadratic. Find roots for that other quadratic if possible and you have your other 2 roots
What's the coefficient of x^3?
1
1
tbh just putting numbers is easier in this one
Stop giving horrible methods.
checkpoint
not that horrible
4/1
describe methods clearly
My suggestion, start with the smaller factors
pretty similar
if they're not familiar with rat root theorem, they might plug in random numbers like pi
Factor out 360
tbh i am not that dumb
you generally put integers first
3 * 2 * 3 * 2 * 5 * 2
Not prime factorization
you generally put integers first
not the point i'm trying to make
then what
Like for example, 24 is 1 x 24, 2 x 12, 3 x 8, 4 x 6, etc
That's why you would start with the smaller values
what do they look like
Sure, now you put the factors of the last term over the factors of the first term, and simplify the fraction, if possible then plug them into the equation
You don't prime factorize
You leave it as 360/1, simplify and plug that into the equation
360/1 is as simple as it can get
But anyways, you plug that into the equation
And that's why I suggested that you start with the smaller factors
And not 360 first
dude
my brain can't comprehend ;l
isn't 180*2/1 the same as 360/1
isn't 90*4 /1 the same as 360/1 and 180x2 / 1
yes, but that isn't really what we're trying to do here
So the factors of 360 = 1, 2, 3, 4, 5, 6, 60, 90, 120, 180, 360, etc. I know I missed some factors in between but that's not the goal I'm trying to achieve here. You put the factors of 360 over the factors of 1, so 1/1, 2/1,..., 180/1, 360/1. You then want to plug each of those fractions into the equation and you want to start at the high end meaning plugging in 360/1 first when you should start on the low side, doing 1/1 first
You wanted to do that first
and see if its higher then we go down
Because that's not how the rational root theorem works
it technically does
No
you'll try every number until you get the solution
yeah
numbers from high to low
but why don't we do low to high?
e.g.
1 won't ever work
That's what I'm saying to do
You go from low to high
alr
You were trying to start with 360 first
yeah ik what you meant
so I can skip 1 2 3 right
its ok
because I know for sure it won't be that
yes, that's fine
alr
make sure you also consider the negative values as well where appropriate
I just understood a new theorem xD
will do!
so we do both -3 and +3
6 and -6
yeh
depending on what you have, there are other useful approaches
what are they
as someone mentioned earlier
x^2(x+4) = 360
you could consider perfect square factors of 360
which makes it easier to filter out what values to test/consider
I did
xD
but for something like
$$x^3 - 5x^2 - 4x -12 = 0$$
you'd usually approach it with rational root theorem as dldh described
ℝamonov
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<iframe src="https://discord.com/widget?id=992582694863126659&theme=dark" width="350" height="500" allowtransparency="true" frameborder="0" sandbox="allow-popups allow-popups-to-escape-sandbox allow-same-origin allow-scripts"></iframe>
Answer go bum
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Can anyone help me with the following question found in my linear algebra book in the chapter on matrices:
John has 15000 euros and invests this in 3 seperate funds A, B and C. He has 5% gain on A, 7% on B and 8% on C. He made 870 euros of gain and invested double as much in A than B and C combined. How much did she invest in each fund?
I already tried and ive got the following:
a+b+c = 15000
a+-2b+-2c=0
0,05a+0,07b+0,08b=15870
Which results in the following matrix:
\begin{pmatrix}
1 1 1 15000 \
1 -2 -2 0 \
0,05 0,07 0,08 15870\
\end{pmatrix}
Its a really simple matrix but i keep ending up with certain negative values as answers
نعمان
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the answer should be the first box right ?
n^1,5 is slower than 3* n log n
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It's not
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Hello, I need help with this. I suck at Math, pls do not make fun of me
What have you tried?
Oh ok ahah
But I just dk how to do the next step
Let's start by expressing 6 1/3 either in fractions or decimals
Yes
Those are feet
But the problem wants us to cut 5 inch pieces
Convert it to the right unit
Yes
6.33x5 ig?
Oh wait its the other way around, my bad
I suggest to convert 6.33 feet in inches
each feet is 12 inches
no
Ok, 75.96 inches of ribbon. How many times can we take 5 inches without making shorter strips?
How are you solving this?
75.96 divide by 5 ig
Yes
What is that .192 telling us?

15.192?
That is the result of the division, but bear with me, there's something we are forgetting
Let's say we have a 10 inch ribbon and cut it each 5 inches
10 ÷ 5 = 2 pieces
What about a 15 inch ribbon?
15 ÷ 5 = 3 pieces
What about a 14 inch ribbon?
14 ÷ 5 = 2.8 pieces, and that means that we are left with two 5 inch pieces and another smaller one
so getting 15.192 pieces means that we got 15 pieces and some ribbon left
So is 15?
That's what I think, but the exercise says "pieces", and technically that small part we are left with is still a piece
I'm not sure
Nice

It is very helpful!
@autumn turret Has your question been resolved?
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where did the f go
yes
So you just did f(0 + h)
yes
So then what exactly is the confusion?
okkk i get it now
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sup
5632148860000000
thanks
5.63214886 * 10^15
It's the same as $$5.63214886\cdot 10^{15}$$
Umbraleviathan
It's what is called a scientific notation
It's super useful because the power of the 10 describes how much digits you have after your unit digit
Digits
Ah yeah thx
How many digits*
And is concisely written as "E" in order to say "10^"
Why E ? E stands for exponent, which is the role of the number besides !
👌
When you have 5.632*10^3 for example
It would be exactly the same as writing
5632
It's just written in a scientific notation. This notation might seem more complicated, but it can become very helpful depending on what you do with it !
So if you want to put it into zeros
You'll have to go through all the decimals first
The same way the point in here went from after the 5
You can reproduce the same procedure with this number @alpine sable
There is 7 decimal digits in your number
So if you write it as 563214886
You have moved the . through 7 digits
So the power of 10 will have, as a consequence, to reduce by 7
And then the power left is the number of zeros you get from your number
Don't hesitate to read that calmly and carefully
And don't hesitate to respond to a certain message in order to ask for clearance
Hell yeeeeeeeeeee good job
lol thanks
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if a ring R is a subring of ring E does that mean that a given ring R' isomorphic to R is a subring of some ring E' isomorphic to E?
That took me a couple seconds to parse but I believe so
This should be intuitively obvious, since an isomorphism preserves everything. However, this should also be true with homomorphisms
The proof isn't immediately obvious to me
Hm
I mean it would probably be by construction of E'
Basically assume r1 and r2 are elements of R. This implies φ(r1) and φ(r2) are elements of R'. Abuse the fact that R is closed under + and * to show that the image of φ is as well
I guess R' would be the image of φ here, if φ is only a homomorphism
I feel like if I was given E' and trying to construct R' it would be easier but there are infinitely many E' s that would work
yeah
I feel like the hard part is defining the binary operation in a way that's precise enough for it to work
also here you could define the isomorphism between the Rs to be the same function as the isomorphism between the Es
in the other direction you have to extend the function somehow
Why wouldn't you have an E'?
If you have an isomorphism, you have an E'. If you have neither an isomorphism or an E', then you don't really have anything to work with
You don't have R?
I also have R
and isomorphism between R' and R
and how can I make an E' out of those
You don't, in general, have any kind of guarantee that an iso between R and R' extends to an iso between E and E', I think
I'll think on it to be sure, though
oh I figured it out
Actually yeah, you don't even have any guarantee that extending such a function is well defined
to construct E' you take E and replace all the elements that are in R with their corresponding elements from R'
@placid zinc no problems with my construction right?
Let's do this on an example.
Let E be the integers
Let R be the even integers
Let R' be the integers mod 4.
What's E'?
even integers are not isomorphic to integers mod 4
and in your example you didn't even give me the homomorphism
Oh, then yes what you propose should work
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Find two numbers whose difference is 16 and whose product is a minimum
I have possible answers if you want them
numbers from what set?
Possible answers are -8, -4, -20, 4, 8, 20
are you looking for natural numbers, integers, rationals or reals
I have no idea. I gave all the info that I have
-8 and 8 give you -64 when multiplied
which I solved by plotting (x)(x+16) and looking for the minimum
What does the minimum mean? Just the lowest possible answer ??
I was never taught that cause my teacher was shit so I’m trying to relearn all of it before next year
-8 and 8 are both on the list of numbers you gave
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how would i prove for any natural number x, $x^2 - x + 3$ is always odd?
aniket
i’m new to proofs, i haven’t rly found a way to figure this problem out yet
hey! trying splitting it up into two cases, one where x is even (x = 2n) and one where x is odd (x = 2n+1)
that's one way you can do it, there are many others
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Hello is this a fine proof ? I know it’s a very simple one and one of my first problems but I’m not sure if the notation and what not looks optimal
hello
Hello
@carmine harbor Has your question been resolved?
Ohhhh you’re right
@carmine harbor Has your question been resolved?
Well, you've done this by choosing some random values, and you need to prove that the above statement holds for all values. Are you going to sit around and verify each pair of numbers till the end of time ?
Let me give you a hint: if $x - \lfloor x \rfloor < \frac{1}{2}$ and $y - \lfloor y \rfloor < \frac{1}{2}$ then by adding both equations, we get $x+y - \lfloor x \rfloor - \lfloor y \rfloor < 1$ which means that x+y is $\lfloor x \rfloor + \lfloor y \rfloor$ + some number < 1. If you take floor of x+y, then you'll get your answer
S🅱innoto
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I need help with this question
Which part?
I dont even know where to start. I know the error formula but it would need the second derivative of the integral and im not sure how pi would come into play
It's not asking you for the error, just for the approximation of the integral with the trapezoid rule
Unless there's further context you didn't post
where's second derivative of integral coming from
no i guess not just the preceding questions were regarding the error rule
ok so if im using the trapezoidal rule then how does pi still come into play
Show the whole set of preceding questions
Integral = pi/4
Approximation to integral ~~ pi/4
4 * approximation ~~ pi
That's the logical step it wants you to take
Where ~~ is "approximately equal"
I guess I still dont understand. If I evaluated the integral using the rule, the result is 0.780766666667
That is not even close to pi
Try reading this again
so take my answer and multiply it by pi
0.785398163397
pi/4
So this approximates pi/4
yes
So let's use the equals sign rather loosely here.
If:
pi/4 = 0.78...
Then can you solve for pi?
multiply the other side by 4
but using my value of the trapezoidal rule from the first time
Yes
ok that makes so much more sense. Thank you
👍
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what does the ^ mean here
the one between the union and the sum
And
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I found it funny that your only reply was "and", even though it is just "and"
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If 5/15 = tanθ and sinθ < 0, then determine the exact value of cos θ.
How do I do this?
hint: sinθ < 0 leaves you with only quadrants III and IV, tanθ being positive tells you that your answer is in either quadrant III or quadrant I
and quadrant III is the only one that satisfies both
Im not sure if it is a special triangle
Cause I dont know how to find its angle to see if it is a special triangle
Or is it just 15/15.8113883?
Cause Im assuming exact value means to leave it as a root if I have to
tanx = 3
tan^2 x = 9
sec^2 x = 1 + tan^2 x
find cos x, its sign will be -ve since it lies in the 3rd quadrant
tan theta is 3, right?
Yeah
so its square is 9
that is a common route for the derivation of $\sec^{2}{\theta} - tan^{2}{\theta} = 1$, im assuming you're referring to pythagoras
kinglacto
where's R?
no
R as like the hypotenuse
Yeah
and since we know our answer is in the third quadrant, that means both cosine and sine are negative
Yeah
wait hold on
alr, so tan(θ) = sin(θ) / cos(θ) and since we know that sin(θ) < 0, we get that -1 / cos(x)
which is the same as -1 / x
and since we know that tan(θ) = 15/5 you can write:
Oh wait no
15/5 = -1/x
Its 5/15
oh
Sorry I wrote it wrong
well tan is still positive so everything we've done so far still holds
wait can u give me a minute my moms calling me
Ok
Trig dies
Okay so the way my teacher taught us is that you can draw a triangle from the quadrant
What’s the square root of 250?
Wait but cant you reduce the 5/15
3.16227766
Btw lily you can reduce 5/15 it doesn't really matter
Sorry ocd
This is 5 root 10 my mind failed me
Anyways
Okay I got it thanks!!
👍
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.reopen
OMG ITS NEGATIVE
OH YA YOURE RIGHT
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can someone please explain why Pi^2/6 is so popular??
huh?
Do you know what series it's equal to
wdym by "popular"
here
If something is popular just search on Google?
𝟝𝟚
wtf
$\sum_{k=1}^{\infty} \frac{1}{k^2} = \frac{\pi^2}{6}$
Ann
this what you meant?
explain what
how much calculus do you know
um
enough for 2 variables and 3 constants, any more and my head will hurt

So multivariate calculus?
there is a proof that involves going through some taylor series shenanigans
i saw that but ew
any other method?
the taylor series proof is cool, but if you dont want it then there's a 3b1b vid
ok but is there any other methods?
Is that the product of roots of sine function?
the 3b1b method uses circles
A most beautiful proof of the Basel problem, using light.
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Brilliant's principl...
You're depriving yourself a lot of good math by not understanding Taylor series
ok let me see it
ooohh dawm
i remember using it to calculate sine by hand
sad days
now can someone explain it?
explain what, Taylor series in general?
how the taylor series explains the original function
???
How does the taylor series explain this
uh. alright
*listens intensely *
so in fact you need another somewhat more sophisticated result known as the weierstrass factorization theorem, which is kind of like a version of polynomial factorization except you're working with a function that has infinitely many roots and is also "nice" in a calculus-y sense
the function to be considered in particular is sin(pi x)/(pi x)
whose factorization in this sense is: (1-x)(1+x)(1-x/2)(1+x/2)(1-x/3)(1+x/3)...
wait wait how?
its zeroes are precisely the integers except 0 itself
....
sin(pi x) = 0 iff x is an integer...
ohhhh
sin(pi x)/(pi x) = 0 iff x is an integer other than 0
also just ftr our function's value at x=0 is 1
i can see
this factorization can be written as prod[k=1, infty] (1 - x^2/k^2)
otoh sin(pi x) = sum[n=0, infty] (-1)^n (pi x)^(2n+1)/(2n+1)! = pi x - (pi x)^3/6 + (pi x)^5/120 - ...
that's its taylor series
dividing this by pi x termwise gives us 1 - (pi x)^2/6 + (pi x)^4/120 - ...
and then after doing some polynomial expansion fuckery you can get that the coefficient of x^2 in prod[k in N] (1 - x^2/k^2) is exactly the sum of inverse squares of natural numbers, times -1
this is incorrect
but i fail at the first step
you misread my expression
this one?
it's $\paren{1-\frac{x^2}{k^2}}$ not $\frac{1-x^2}{k^2}$!
Ann
but this is.... difficult
you will probably not get more elementary proofs than this, sorry.
no, i mean like the parsing
im a baby who can only understand LaTeX and symbols
i'm on my phone so typing latex takes some effort
and why is it factorial?
the +1 is meant to go in the exponent...
or rather
since we're dividing by pi x, the +1 should just be gone
are you asking why i put an exclamation mark in the message you replied to? that's just an exclamation mark, not a factorial symbol.
oh
I'm sorry for wasting your precious time but I still do not understand, tell me when you have a PC and can use LaTeX 🥲 .
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w is in Nul(A) if and only if Aw = 0
w is in Col(A) if any only if the system Ax=w has a solution
is what yes
no...
would really advise not relying on wa so blindly
if you want, you can have it compute the column space of A
(which, by the way, is not preserved by diagonalization)
,w column space {{2,6},{4,12}}
the result of the query i just posted is the column space of A
determine whether or not your w lies in this set
indeed it is not.
no
you are overthinking it again.
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.reopen
✅
there is a much easier way to check whether or not a vector lies in the null space of a matrix
and that easier way is what i suggested at the start
which i think was ignored by you
.
calculate Aw and see if it's the zero vector or not!
literally just calculate the matrix-vector product! nothing could be simpler!
do you know how to multiply matrices
you are multiplying A by w...
whether or not the result is the zero vector!
what property
we can't and i made no claim that we could!
i'm going to lose my mind
it really feels like
whatever i say
at least three quarters of it just
escapes you entirely
and you fail to read it
and then i have to repeat
repeat
repeat
i have no idea what property you are talking about, still
maybe you have something in mind but you are not making yourself clear at all lol
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They don't say what parabola it is tho
How are we meant to know the shape of cross section
I think just assume it to be x^2
they mentioned that the cross section is parabolic, hence it's shape is that of a parabola
all parabolas are similar
Don't we wanna know the what function defines it tho?
also, there might be no need for integration here
sure, but like i said, all parabolas are similar, so we can just say that the parabola has the axis of symmetry at x=0 and it's vertex to be at (0,0)
for the depth and width that makes up the waterway, that's for clinx to figure out
@sly comet Has your question been resolved?
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Im learning data types and it says "Categorical data are values that cannot be measured up against each other." Can someone explain this to me
I know categorical data is data that can be grouped like age of students in a class, race, sex, etc. Im just confused on what "are values that cannot be measured up against each other" means
i think it doesn't mean anything, they compressed the idea too much
just ignore that sentence
Alright thanks, so categorical data is just data that you can group together right?
it's something that doesn't behave like a number, e.g. a color of a car, there's no point in averaging two colors, or determining which of 2 colors is larger
What do you mean by doesnt behave like a number
Isnt categorical stuff mainly numbers?
no it's not
i was thinking about nominal data, it's true that the ordering may be super meaningful
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,rotate
so I thought this was pretty simple
but I keep getting the wrong answer
and incongruent answers such as a = 2 and a = 4 ??
may I see ur working
I don't think youre supposed to cube (x+a), the problem did not state that the box is a cube
oh, my bad then
I guess it looked like a cube in the diagram, so I didn’t think much about it
how does the volume of the box relate to the area of the top and its height
I believe the volume is lxhxw
we know the height
and we can probably figure out what the top is
if (x+a)(something) = x^2 + cx + 4
i think im mistaken actually
you're right that the volume is lxhxw
so we know h
and how can we express the area of the top in terms of the sides of the box?
(x+a)(something)(something) = this
I don’t know how to find the something
just answer this question first
x^2 + cx + 4 ?
sorry, im confused
in terms of l,h, and w how can we express the area of the top of the box
the top would be w x l ?
ah
we also know lxw, that's the area of the top which is x^2+cx+4
yeahhh
so we just expand and compare?
and so you should equate them and then compare coefficients yeahhh
great, thank you !
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how do i find the solution curve of dy/dx = 1 - y
what have you tried?
@alpine sable Has your question been resolved?
you can separate and integrate or use if
(integrating factor)
which one have you learnt
La place transform for this is overkill but it defo works
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could try somethiung like that?
I don't know how to do
the sum of all angles on a straight line is 180 and the sum of all angles in a triangle is 180
@thick star can u help them cos i dont trust myself😭
same
yay!
ok
how about this one?
I think U should approach the problem like this
angle CDE = 70
angle DCE + angle CDE = 96
angle DCE = 26
26 + x = 180
x = 154
u should ping helpers they can help u better
I count until 64
I agree
why don't you count CED
cause I didnt require
I think this will help
where do you find DCE?
oh nvm I saw it
But my answer is completely different from yours
what is ur answer
180-96=84
180-110=70
180-70-84=26=DCE
360-26-26=128=2x
128 divide 2=64
that's what I got
180-96=26?
sorry, wrote wrong
Is my answer still wrong?
-idk mate I am confused myself lol-
360-28-28=128?
its the center, so I used 360 minus DCE or 26 from both sides, then I get 2x
360-26-26 is not 128
my calculation, is literally off the railing
154
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ElevatedElmo
@lapis merlin Has your question been resolved?
@lapis merlin Has your question been resolved?
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Good day! Anyone able to help with this exponential equation? The key is to solve without logs but I’m kind of at a lost here without it. Thanks!
3^(2x+1) - 3^(x+2) + 6 = 0
have you tried anything?
I tried to break up 6, break down 3, etc to use exponential properties but I can’t really get to anything.
One of the solutions is definitely 0 because dividing the whole solution out by 3 throws (x) out the window but my test question is asking for 2 answers without the use of logs. Seems like I’m missing something obvious but I’ve been stuck for awhile now