help-0

[raw nexus]

can u just walk me through

it

[solemn juniper]

bruh

u = 2t^2 -> u/2 = t^2

just plug it in

[raw nexus]

$\int0^{0.48} \sin(\pi u/2) \underbrace{4t \dd t}{\dd u}$

[ocean seal]

Rysee

[raw nexus]

to where^

is that right

[solemn juniper]

$\int_{t=0}^{t=0.48} \sin(\pi u/2)\dd u$

[ocean seal]

Steakanator

[solemn juniper]

you also need to change the bounds

[raw nexus]

why?

[solemn juniper]

because when they were initially defined they depended on t

now they depend on u

[raw nexus]

how do i do that?

so 2*0.48^2

[solemn juniper]

yes

[raw nexus]

=0.4608

[solemn juniper]

,calc 2*0.48^2

[ocean seal]

Result:

0.4608

[raw nexus]

and 0

$\int_{u=0}^{u=0.4608} \sin(\pi u/2)\dd u$

[solemn juniper]

no

the bounds are now related to u

[ocean seal]

Rysee

[raw nexus]

like that

[solemn juniper]

sure

[raw nexus]

then what do i do from there?

[solemn juniper]

solve the integral

[raw nexus]

could you explain a bit further?

[solemn juniper]

you have a basic integral, solve it

[candid sleet]

Is this correct

[raw nexus]

what sin(π⋅u/2)

[candid sleet]

OG equation

[raw nexus]

how do i get 144pi and 625?

@solemn juniperhow do i get the 2 quations after that = 0.160

[solemn juniper]

do you actually not know how to solve that integral?

[remote pollen]

"An animal population increases by 4% every year. Karl claims: "Then the population will increase by 40% in 10 years." -Decide if Karl is right? Give reasons for your answer."

please help me

is Karl right?

or wrong?

[glass lichen]

Well what do you think?

[remote pollen]

that's why i'm asking but I think it's correct

[raw nexus]

@solemn juniperno

[glass lichen]

Ok, how come?

Why is he correct?

[raw nexus]

so do i need to sin(pi* 0.4608) - sin(pi* 0)

[solemn juniper]

then go look at your notes, this is a very basic integral and you should be able to solve it without much thought

[remote pollen]

I guess because 4 * 10 = 40

[raw nexus]

not sure

im dumb

[remote pollen]

@glass lichen am I right?

[glass lichen]

No

[remote pollen]

then??

[glass lichen]

That's true only if the increase doesn't depend on the population

Assume a population of 100, after 1 year you'll have (1.04)100=104 people

The 2nd year you'll have (1.04)(104) which isn't 108

[jade birch]

Hahaha

<@&268886789983436800>

Nvm

[alpine sable]

For sets A and B,

s(A) = 2.s(A n B)
s(B) = 3.s(A n B)
s(A u B) = 16

then, what is s(A)?

[alpine sable]

hellpppp

[restive perch]

hello there
any help?

[alpine sable]

to find original amount after 5 years at 10% depreciation rate. Would I do 1000x0.9^5

[restive perch]

another one

how can i minimise pa.pb? i could do it if it was pa +pb

[vagrant basin]

Im confused why does this graph just stop at ~140

[alpine sable]

what is the formula for the graph

[vagrant basin]

the x'th root of x^x

[alpine sable]

basically just a dumb way to say x = y lol

[vagrant basin]

but y=x shouldnt just stop right? im very confusus srry

maybe i broke

program

[alpine sable]

yeah thats probably just a bug with the site

[vagrant basin]

okay thank u

[alpine sable]

if you think of it the power of x and square root of x cancel each other out so its just x

[fringe comet]

ignore the selected answer

what is this question asking / how do i appraoch it?

[surreal oak]

help

pls

what

[alpine sable]

75x5 = 375. 375-15 = 360

[fickle pewter]

i need help please i'm a senior studying derivable function

[mighty laurel]

somebody help please

[glossy briar]

sure ill try

errr.....

[mighty laurel]

?

[glossy briar]

sorry i dont know either

[mighty laurel]

oh man-

thanks for trying tho

[glossy briar]

someone will know

its also ten at night for me

[mighty laurel]

Oh

[fickle pewter]

 f (x) = 3 / 2x```

[alpine sable]

Depends on the lvl of problem

[fickle pewter]

senior level

[fickle pewter]

<@&286206848099549185>

[north stump]

HI I HAVE GCSE IN LIKE 12 HOURS I REALLY NEED SOME HELP HERE

please dm me if possible

it’s for math

[supple tundra]

whats your problem

[north stump]

@supple tundra ^^

[compact lynx]

have you tried forming two equations @north stump

like have u started there

or do u not know where to start

[north stump]

no clue where to start really

[compact lynx]

well okay

well the formula of the mean is sum of all the elements / number of elements yeah

and you're given that x is the number of elements (boys)

so you know, sum of elements / x = 171

your second equation has to use that second bit of info they give you

and would thus be something like (sum of elements) - 179 / (x - 1) = 170

can you solve it from here?

[red ledge]

2x2 = 4 Because 2+2 = 4
1x1 = 1 Because 1+1 = 2

Why is this wrong?

[north stump]

yup i think i got it,thanks

[compact lynx]

wait like

what do u mean why is that wrong... that's not wrong? can u give the context of the entire question

[restive perch]

please anyone any ideas?

[red ledge]

Bro it's so obv, Multiplication means Repeated addition! Then why when we say 1x3 {1 + 1 +1 = 3 } Shouldn't equal 3

[compact lynx]

what

okay idk

I don't know what "because" means in this statement

2x2 = 4 Because 2+2 = 4
1x1 = 1 Because 1+1 = 2

like the arithmetic is correct

are u saying 1x1 = 1 because 1+1 = 2 isn't 1...?

3x3 = 9 because 3+3 = 6 is wrong for the same reason... you're just not adding the right amount of times

[placid zinc]

It might as well say
Elephant because alligator

[simple parrot]

i dont get how the last line happened

can someone explain

[compact lynx]

do u see why that's a

perfect square trinomial

this term

[simple parrot]

no idea what that means

[compact lynx]

u ever done something like

[simple parrot]

like x^2 + xy + y^2?

[compact lynx]

x^2 + 6x + 9 = (x+3)^2?

yes

so do u see how this is a

perfect square trinomial

[simple parrot]

ahh yes that makes sense

[compact lynx]

ah do u get it then

[simple parrot]

x and b/a okay

[compact lynx]

uhh wait

[simple parrot]

what about the right part

[elder glacier]

they times the a on the numerator cancel out, then make the c term as 4ca/4a

and take out the minus

[compact lynx]

yup yup that^

[simple parrot]

alright cool i think i get it

thank you guys

[elder glacier]

@compact lynx sorry, for the ping but may i ask you a question?

[compact lynx]

yea go for it

no promises i will know how to solve it lol

[elder glacier]

Am i wrong in saying vector AD = vector BC, thus D-A=B-C

thus D = B - C + A

D = < 7, -6, -1 > - < 4, 0 ,1 > + <8,-1,8>

[compact lynx]

im a bit curious how u got

oh wait

hm

no sounds right

its been a while since ive gone lin alg but

it looks correct to me?

i also remember there were easier ways to get parallelograms... but idk you'd have to look through ur notes for htat

[white meteor]

anyone? pls

[elder glacier]

solving for congruency, but I can't see why my answer is coming up as incorrect using my above stated working out

[formal fossil]

Hi guys. I'm trying to get x

[compact lynx]

what is the initial question

[formal fossil]

Sorry I mean t

[compact lynx]

@elder glacier yea idk it's been way too long since i've done linalg..

[white meteor]

callum can u help me out

[elder glacier]

allg allg

[compact lynx]

also have not done physics in a long time LOL

[white meteor]

damn

[alpine sable]

can anyone give me tips on how to get the range of a complex function

[compact lynx]

@formal fossil the initial question is 6t^1/3 / t = 0.375?

[alpine sable]

and getting a graphical idea of how it looks like

[formal fossil]

no, it's an equation and i stucked here

[compact lynx]

can u give me

the initial question

lol

[clever mural]

i need to find a real function such that

any ideas that are less crude than cos(3acos(x))?

[magic root]

does this mean something like the w for whole numbers and etc.

[gentle ingot]

That's the complex number set

[magic root]

oh

okay thx

[gentle ingot]

https://owlcation.com/stem/How-to-use-complex-numbers

Ye

[magic root]

Ohh I see. Thanks.

[pseudo pebble]

Is there an easier way to get to the Goal here?

[jade blaze]

factoring equations was always my weakness

[untold warren]

looking for some guidance

from what I know λ denotes the empty string right?

[magic geyser]

its not an exam or test rite?

That ur doing rn

[untold warren]

yeah its neither

[magic geyser]

whats wff

[untold warren]

well formed formula

[compact lynx]

can u

send the definition of ur recursive definition of an element of wff

it may differ slightly from source to source

and lambda there is what

[untold warren]

well at least according to my readings it denotes the set of empty strings or something

and wff looks sorta like this for the definition

actually wdym by the recursive definition?

[final coyote]

how the hell was this 31.5

[celest flower]

Hey guys, I have more of a general problem

Can someone explain to me

what exactly a derivative is, and how to solve differential equations

If anyone is asking why, It is because This material is 3.5 years ahead of my current syllabus, and I want to learn ahead

[red ledge]

Guys

2x2 = 4 Because 2+2 = 4
1x1 = 1 >>> 1+1 = 2

Why shouldn't it equal 2 then?

[magic geyser]

first of all

2x2=4 not because of 2+2

end of all

[red ledge]

Isn't Multiplication repeated addition?

[warped bramble]

can i ask a question?

[red ledge]

Yes ofc

[warped bramble]

how do u write this with a prime number base

[red ledge]

Ask as many as u can and want.

[red ledge]

What is this c on the left?

[warped bramble]

question x

question c

i did all but number c

[red ledge]

I dunno about this honestly..

[warped bramble]

np

[red ledge]

Maybe try to google until someone explains it

[rustic frigate]

You can multiply √5 with √5 then you’ll have 5 in the bottom

[bleak meadow]

Hey, sorry if this channel is currently in use, but this is a quick question

[glass lichen]

rationalize the denominator, then simplify

[bleak meadow]

2cos2x-5cosx+3=0

Is this a question?

[severe zodiac]

does prime number base, mean a primenumber on the denominator, if so i would do what steppaz says

[rustic frigate]

But if you multiply √5 at the denominator you have to multiply √5 at the numerator as well :)

[warped bramble]

this should be the answer

[rustic frigate]

Channel is occupied

[bleak meadow]

It’s a really quick question

Is that an equation

[glass lichen]

Ok so can you write 625 as a power of 5?

[bleak meadow]

Just need a yes/no answer

[glass lichen]

no, a random equation is clearly not a question.

[warped bramble]

5^4

[glass lichen]

and sqrt(5) as 5^(number)?

[bleak meadow]

So it’s not even a question that can be attempted?

[glass lichen]

clearly not.... you have no instructions

[bleak meadow]

Thanks, love you </3

[glass lichen]

k.

[warped bramble]

5^1/2

[glass lichen]

yes so you have $\frac{5^4}{5^{0.5}}$ can you simplify that?

[warped bramble]

but then what happens

[ocean seal]

Mosh

[red ledge]

@glass lichen 2x2 = 4 Because 2+2 = 4
If 1x1 = 1 because 1+1 = 2

Isn't Multiplication repeated addition

[glass lichen]

that's irrelevant to anything being discussed.

[warped bramble]

wwait can you minus a power if its a decimal?

[glass lichen]

yes, you have the same base so the exponents subtract

leaving $5^{4-0.5}=5^{\frac{7}{2}}$

[ocean seal]

Mosh

[warped bramble]

oooh shieeee

wait but would it be correct if it was 5^3.5?

[glass lichen]

yes, 3.5=7/2

[warped bramble]

thanks mosh

[glass lichen]

even if you had something like $\frac{a^{\pi}}{a^{17.3}}$ you can still apply exponent laws

[ocean seal]

Mosh

[warped bramble]

appreciate it

[glass lichen]

how did you get from line 1 to line 2...?

[red ledge]

@glass lichen Can u answer my question now?

[glass lichen]

yeah where the hell did that come from?

$\abs{5x-7}+4\leq 6 \ \iff \abs{5x-7}\leq 2$

[ocean seal]

Mosh

[warped bramble]

mosh do you type and memorise the commands?

[bleak meadow]

2nd of all idk if they're stupid or not but the 3 rules of the trigonometric formulae of cos2a are: cos^2A-sin^2A. 2cos^2A-1 or 1-2sin^2A

Is this true?

[glass lichen]

google, or refer to the pinned identity sheet #geometry-and-trigonometry

[warped bramble]

nice

[fringe comet]

so confused by this

bc

graphs

how do i figure an equation from them

[glass lichen]

you swap ineq's direction if you multiply/divide by -1 or take reciprocal

adding -4 to both sides preserves direction

so you have $\abs{5x-7}\leq 2\iff -2\leq 5x-7\leq 2$

[ocean seal]

Mosh

[glass lichen]

which is just a linear compound inequality

yeah so am I

I have no idea where -3/5 came from, cause it's unfortunately wrong

since -2+7 isnt -3

[fringe marlin]

hello there people, I have a question. What is 15kg corrected to the nearest kg

[echo island]

-2+7= 5

https://tenor.com/view/think-smart-gif-22411928

[glass lichen]

k, didnt ask the peanut gallery

[wintry sail]

Got a question if anybody here

[echo island]

huh?

[echo island]

ya

[glass lichen]

I never directed anything I said to you, so please don't comment pointless things.

[wintry sail]

just want to ask I feel like I am doing terrible in math since had not done it since 2017 as finish at calculus 2 and trying to back u to doing calculus 2 but still feel like I am doing terrible in it as want to do a masters in engineering

[warped bramble]

can someone go over this with me

[glass lichen]

@wintry sail @warped bramble channel in use.

[echo island]

i was letting him know

[warped bramble]

sorry mb

[echo island]

because he might not have known

[warped bramble]

ill wait

[glass lichen]

Yeah I genuinely have no clue where you're pulling that 1st line from

like you're assuming it's positive then fucking with signs, but only on 1 side

OH

ok

yeah no

the property you're trying to apply only works if |f(x)|<a

not |f(x)|+c<a

you have to "isolate" for the abs value, then apply it

$\abs{5x-7}\leq 6-4$

[ocean seal]

Mosh

[glass lichen]

then you can apply that rule since 2>0

[warped bramble]

sheesh

ok so i know its 1/x^3

wait

for the denominator

do i have to flip it up

if its a negative power

uh guys

bruh im dumb

nvm i got it

because its a negative power i just find the reciprocal of the fraction and then apply the power of three to each term correct?

[buoyant kayak]

yes

[warped bramble]

thank u sir

[wise stump]

Anyone know how to find (f^-1)'(a) for this

[glass lichen]

yes, though you can solve it all in 1 hit instead of splitting it

[next viper]

@glass lichen can you go dms and help me with an equation

[glass lichen]

no

[next viper]

D:

bully wth

[glass lichen]

$\abs{5x-7}\leq 2 \ -2\leq 5x-7\leq 2 \ 5\leq 5x\leq 9 \ 1\leq x\leq \frac{9}{5}$

[ocean seal]

Mosh

[glass lichen]

@solar mural

just an alternative

[next viper]

dont need u anyways mosh ik im right

[glass lichen]

ok

[next viper]

no @glass lichen i take it back :(

can u solve 2cos2x-5cosx+3=0

u said it wasnt an equation

[glass lichen]

Never said that.

[next viper]

sm1 did .,.

[glass lichen]

I said a random equation isnt a question.

[next viper]

lemme see

but

can u solve it in radians

im debating with someone

whether its right or not

[glass lichen]

you can solve it in any angle measurements..

even gradians

[next viper]

yesyes but like its required in radians

[glass lichen]

ok so solve it in radians..

[next viper]

cant get the question wrong 😔

i did

but someone said its wrong >:(

now i want sm1 smart to solve it which is why i gave u the honour to solve it for me c:

[glass lichen]

$2(2\cos^2(x)-1)-5\cos(x)+3=0$

[ocean seal]

Mosh

[next viper]

i-

wha

radians where sir

[glass lichen]

just apply double angle and solve the quadratic

radians dont come into the picture till you get x=

[next viper]

i got x=75.7

thats 0.42pi

[glass lichen]

,w solve 4x^2-5x+1=0

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Omegabet_#9771

[glass lichen]

right so you have solutions when $\cos(x)=0.25$ and $\cos(x)=1$

[ocean seal]

Mosh

[next viper]

i also got that

inverse of cos 1/4 is 75.5

[glass lichen]

approximately, yes.

[next viper]

subtract that from 360 specified in the cos quadrant to get 284.5

[glass lichen]

approximately, yes

so you have those solutions +2pi*n for integer n

[next viper]

and that divided by 180 gives me 1.58pi

[glass lichen]

idk why you divided by 180

but you have $x\approx 75.5+360 n$ and $x\approx 284.5+360 n$

[next viper]

since pi is 180 degrees and its required in radians its simpler to just divide it by 180

[glass lichen]

oh you're working in degrees

thought you said radians...

[next viper]

well

[ocean seal]

Mosh

[next viper]

since the x=75.5

i had to take 75.5 from 360

in the cos quadrant

that forces me to work in degrees for simplicity

[glass lichen]

it doesnt

but ok

[next viper]

and turn it into radians after that

just simpler imo

[glass lichen]

nothing forces you to work in degrees

[next viper]

WELL

ITS SIMPLER

[glass lichen]

well yeah, cause you're more use to it

[next viper]

yeeee

u get me

anyways thank you for your hard work sir my answer is right

[glass lichen]

so yeah, you have those solutions then 2pi*n solutions for cos(x)=1

[next viper]

yus

[merry umbra]

@alpine sable is angle G 180 degrees

[next viper]

nah no way it is

i think

its 66

ye

straight line always 180

[merry umbra]

Or is g the center point of all the angles

DGB looks like a 45 degree

From all the angles top and bottom they create half a circle

[rain onyx]

How can i know the value of k?

[merry umbra]

Put that in English then we'll see

[rain onyx]

They are probabilities. They ask me to calculate the value of k when the summary of the 3 equation is 1

With the different values of X

Never mind, i figuered it out

[wintry perch]

how do I infer the relative strength/probabilty of two sides facing each other when I know:
A to beat B 80%, B to beat C 40%. Whats the expected probabilty of A to beat C?

[dull lance]

[plain heath]

I need the procedure. The answer is (Sen18°)km

[vagrant rover]

Can the degree of a term be a negative integer?

[plain heath]

maybe

[vagrant rover]

?

[plain heath]

If you get the answer all right

[short night]

can someone help and explain

[dapper frost]

@short night what are they looking to find*

[short night]

what do you mean?

[dapper frost]

i worded that incorrectly

what are they checking over time

[vernal flicker]

any idea of how to do this?

[short night]

bodyweight ?

[dapper frost]

sec

sorry gimme 2 secs

[short night]

ok

[dapper frost]

https://socratic.org/questions/what-is-a-paired-and-unpaired-t-test-what-are-the-differences @short night here's the best and easiest to understand explanation, i have to brb.

[short night]

ok, so in this case it would be paired?

[dapper frost]

i would assume

but i would research farther to come to a definite conclusion

[astral bramble]

did you really need to ask your question in the channel i just asked mine in?

[woeful pulsar]

what is Sen18?

[astral bramble]

please have better social awareness thank you

[woeful pulsar]

do you understand what average change is?

[astral bramble]

yes i do

[woeful pulsar]

okay, what happens if you apply it?

[astral bramble]

i dont know exactly what it means with the "2+h" being an interval

[woeful pulsar]

ah, it's just the endpoint of the interval

so instead of it being a number like 2.01

it's an expression that includes the unknown h

it also means h>0 (probably)

[astral bramble]

im still a bit unsure on how to solve

[woeful pulsar]

so how would you do if the interval is [2, 2.01]?

[astral bramble]

you put in 2 x values and subtract solutions / x values right?

[woeful pulsar]

can you show your work perhaps?

[sleek schooner]

help?

i dont know where to start. i just want to know the process of solving these equations

[sturdy nova]

perpinduclar graphs are negative reciprocals

they have negative reciprocals slopes

[sleek schooner]

so woudl the answer be -4?

[sturdy nova]

put 4x + 12y = 8 in y = mx+b form

[sleek schooner]

12y=4x-8? how would i isolate y?

divide -4x and 8?

8?

-4?

so

12/-4?

-4/12?

man i knew that

its been a stressful week so far

and its only monday...

[sturdy nova]

same

[sleek schooner]

-4/12=-.3333333

so just -4/12?

[sturdy nova]

-1/3

[sleek schooner]

thanks.;

nights like these make me forget basic math

-1 x -1/3? can i solve it using that?

[sturdy nova]

wait what, the answer would be 3?

[sleek schooner]

huh

im really sorry im making you do it in dumb people language im so overwhelmed im actually dizzy rn

[woeful pulsar]

visualise it perhaps

like take some paper, try drawing it

[ocean seal]

Joey

[sleek schooner]

-1/3 x m= -1

i see

[sturdy nova]

no thats wrong, the perpendicular of any 2 lines is the negative recipircal

the answer is 3

as -1/3 negative reciprical is 3

[sleek schooner]

H U H

[sturdy nova]

perpendicular line ?

it would actully be 3 in that formula bruh

[sleek schooner]

wait

yes it would be

so the answer is 3?

[sturdy nova]

yes

[sleek schooner]

cheers lads. 22 questions to go!

[dapper frost]

i'm here for 25 more minutes then im out but if u need help during that time i'm free.

[alpine sable]

can you help?

[sleek schooner]

my school sucks. i got put into an accelerated math class meant to help me with this stuff but its literally just a 7th grade math class. not to mention my actual math teacher is...not the best. so i should be recieving this help, but im not.

[alpine sable]

Send question

[dapper frost]

sure, what do u need help with?

[alpine sable]

I know high school maths

[alpine sable]

i have a triangle

angle c is 106 and the two legs are 27 and 13

using cosine rule i get 27^2+13^2 - 2(27)(13) * cos106

which gives me hypotenuse^2 = -54.024

which clearly cant be right

can you help?

[dapper frost]

um

I haven't learned this yet, i would say try waiting for someone else to help you. Sorry.

[alpine sable]

scroll up

[alpine sable]

Which 2 legs?

the two which arent the hypotenuse

both are adjacent to angle c

Okay

hmm

lmk when you get whats wrong

[alpine sable]

Isn't cos negative in second quadrant?

[alpine sable]

we arent there yet this is simple trig

106?

sine and cosine rules

nothing more

How did you find cos 106

because thats the formula

[glass lichen]

calculator

[alpine sable]

That's where he probably went wrong

look up cosine rule formula

Calculator takes in radians

the last part is * cos (angle)

[glass lichen]

...

[alpine sable]

Did you convert?

im pretty sure its in degrees

[glass lichen]

calculators can swap b/w degrees radians and gradians

most can at least

[alpine sable]

yep its in degrees

Yes but he didn't switch. Else he would have gotten a negative value

i did get a negative value

-54.024

Cos 106 is negative though.

yes

but i need it positive to sqrt it

Brooo

R u not getting me 😂

i get what ur saying

but how am i supposed to solve it then

Negative value not for that. But for cos(106)

yes

Wait I will give you value of cos 106

the solution was positive until i got to cos(106)

Brb

[glass lichen]

ok so 1) cosine rule isnt sqrt(cos(C)). 2) How the fuck did you get an output of -54?

[alpine sable]

i never said it was

scroll up, i gave you my whole train of thought

[glass lichen]

ok, answer the 2nd thing I said

cause that's more pressing

[alpine sable]

-0.275

by plugging the values into the formula

[glass lichen]

then you fucked that up

[alpine sable]

Use this in cos value

clearly i did

i just need to know what i did wrong

[glass lichen]

have you tried posting your working then?

[alpine sable]

You will get answer

[alpine sable]

i already do

Mchdi use the cos value I sent

[alpine sable]

ok give me a sec

[glass lichen]

cause yeah, Im not getting any problems w/ negatives and whatnot

[small cypress]

how do u do this

<@&286206848099549185>

[alpine sable]

from 9 thats literally it lmao

and the cut off part is -54

[alpine sable]

-b/2a

[glass lichen]

yeah, messed up putting it in the calculator

cause you did $(27^2+13^2-2(13)(27))\cos(106)$

[ocean seal]

Mosh

[glass lichen]

which is not cosine law

[alpine sable]

what is it then

[glass lichen]

??

$c^2=a^2+b^2-2ab\cos(C)$

[ocean seal]

Mosh

[small cypress]

what doe b n a repsrent again

[alpine sable]

@small cypress open it up and get it in ax^2+bx+c form. And use x=-b/2a

[small cypress]

oh ok

i see

[glass lichen]

the turning point occurs at the average of the roots...

[alpine sable]

im solving for a not c

therefore its 2bc

[glass lichen]

no you're not

they're variables

it doesnt matter

[alpine sable]

true

[glass lichen]

you're solving for the lone variable

[alpine sable]

That's also true. 😁

so then how would i put it

if the way i put it was wrong

[glass lichen]

the cos(106) only gets multiplied to the -2ab part

[alpine sable]

ah ok

[glass lichen]

I really cant teach you how to use a calculator either

[alpine sable]

that was confusing bruh

shouldve been specified

i just put the entire thing in

Sure

lmao

thanks

[glass lichen]

Are you saying the formula is confusing or trying to figure out what the issue was?

[alpine sable]

the formula

[glass lichen]

it isnt

it's typical notation

[alpine sable]

True

if i had known that from the beginning there wouldve been no issue

[glass lichen]

so... you didnt know the formula

[alpine sable]

how am i supposed to know though

what goes with what

From experience

[alpine sable]

no i had it in front of me

but it doesnt have any parantheses like what you described

[glass lichen]

yeah so you saw -2abcos(C) not -2ab)cos(C)

[alpine sable]

yes

precisely

[glass lichen]

yeah, but you didnt bat an eyelid at the a and b like that...?

[alpine sable]

what about them?

[glass lichen]

you didnt multiply the entire expression by b

despite it looking identical to how cos(C) looked

[alpine sable]

because it seemed obvious it was being multiplied to -2 and a

[glass lichen]

yeah, this is "obvious" for the exact same reason the b thing was obvious

same notation

[alpine sable]

ah ok

did i do something wrong again lol

i have 10 mins left and im just stuck on the angle part of the problem

rip

[alpine sable]

you still there?

[glass lichen]

You literally did the same thing

[alpine sable]

i put it by itself

isnt that what you wanted

[glass lichen]

No

Compute -2(13)(27)cos(106), then add 13^2 then add 27^2.

[alpine sable]

okay

[glass lichen]

Should get something around 33

[alpine sable]

got it thank you a ton

[alpine sable]

after the sqrt?

i got 22.5

[glass lichen]

Yeah... can't teach you how to use a calculator

[glass lichen]

Where did 12 come from????

[alpine sable]

im stupid

LOL

i meant 27

ok thanks

Would I be doing this right?

[sturdy nova]

No

You wouldn't use tan

[alpine sable]

what would I use?

[sturdy nova]

SOHCAHTOA

H and A

So cos

Also you would put Cos 21

[alpine sable]

Ok thanks

I got 5.355

but I feel like it’s wrong

[pliant lava]

I got 4.66, 5cos21 right?

[alpine sable]

Yea that should be it

how did you get there

[pliant lava]

tan * adj angle

5*cos21

[alpine sable]

Oh I divided

I’m still getting a different answer

[pliant lava]

do the cos21 first then multiply

[alpine sable]

I put tan on accident

Ok thanks I’m good now

[oak granite]

I’ve just had my class today on reciprocal function(Multiplicative inverse of the function) and this example troubles me. I believe my range should be y is smaller and equal to -1/4, bigger than zero. However in class I was taught to only put y≠0. Am I wrong or did the teacher made an mistake?

In one of many YouTube video I watched on reciprocal function, they did it exactly so where the vertex of the flat parabola would be used to state the maximum value and the y>0 can represent all y value in the two semi-hyperbola from quadrant 1 to 2

[cold vessel]

anyone know how to do this cuz i dont

[forest sage]

What is the function

[cold vessel]

idk

thats all they give me

[pliant lava]

This looks like cotan of Pi but I can't prove it.

[forest sage]

Minimums become maximums and vice versa

Y values become reciprocated:
Minimum at e.g. (1,2)
Becomes maximum at (1, 1/2)

[astral bramble]

you guys completely lack any social awareness

people just stack questions all asked within a few minutes of each other

is it so hard to just each get your own channel

[raw shard]

@astral bramble yes because no one reads rules lol

[rigid wind]

average #help-0 chat

[raw shard]

like at least of a third of the questions happen like that

pretty annoying and i don’t even ask questions

sometimes i wish that the question channels would be role restricted

[oak granite]

Right. When I reciprocate my original function which is y=(x-1)(x-5), my vertex which before carries a minimum value, are now flipped to be maximum value, which in this case, (3,-4) becomes (3,-1/4). That means my range will be {y|y≤-1/4,y>0, y∈R} ? Instead of {y|y≠0, y y∈R}?

[raw shard]

@astral bramble honestly just go to another channel and hopefully this doesn’t happen again

[forest sage]

@oak granite you can check using desmos,

@oak granite y is NOT defined between -0.25 and 0

so its all real other than between this range

[oak granite]

Exactly, so it shouldn't be y≠0. Thanks for the help, I believe its just a small error my teacher made.

[forest sage]

well it is y not equal to 0

but it is also not equal for the range stated

[oak granite]

what should the correct range be?

[oak granite]

All I want is making sure my range {y|y≤-1/4,y>0, y∈R} shows that it won't equal to zero, but also state the fact that the vertex part of the flat parabola would not touch zero. Is this wrong or did I do it right? Sorry for the confusion.

[vale elbow]

anyone know what this is

[oak granite]

@vale elbow yeah you got it right, by setting domain as x is bigger or smaller and equal to 1, your inverse will only show one side of the parabola, therefore making it a function not relation. (P.S, you can also set it as x is smaller and equal to 1, which would make the inverse a function as-well, but just now your y value of your inverse will only go infinitely negative. )

[red ledge]

Anyone have questions?

[obsidian inlet]

I do lol, how do I find this? It's about derivatives of linear functions

[buoyant kayak]

so first find the inverse of f(x)

[obsidian inlet]

I already got that g(b) is 4 since the inverse of the function is 1/b - 8, which plugging in 1/12 for b gives you 12 - 8 = 4

Not sure where to go from there though, this is a completely new topic to me and I missed the lecture today because of a migraine

[placid zinc]

You already have g(x). You now need g'(x)

The ' means "derivative"

[alpine sable]

guys

why is the average

[obsidian inlet]

so that would just be g'(4) right?

[placid zinc]

What's "that"?

g'(x) is not g'(4), no.

The final answer will be g'(1/12), but you'll need g'(x) first.

[eternal cave]

I need help with one question

[alpine sable]

guys that question is coming one xam i need to undrstand anyone good at calc?

[red ledge]

I would've answered u if I knew.

[alpine sable]

😦

it is what it is

[waxen lichen]

Hi,can someone help me with this?

[alpine sable]

thanks though abstract

is that your cat

[buoyant kayak]

boxster, no need to ask if people can do questions. simply post your question

[tough obsidian]

Hi very confused currently

Was trying to see where this function doesn’t change

But my mind is blank in the final steps

[buoyant kayak]

you want to find where the slope is zero?

[tough obsidian]

Yes I believe so

[buoyant kayak]

once you set your derivative equal to zero, you don't want to get your constant on another side

[buoyant kayak]

keep it equal to zero

so go back to the step where you added 48 to both sides

and keep 48 on the side it's on

then factor completely

[tough obsidian]

Ooof

Thanks

My blanked so hard

Why can’t we solve with a constant on the left though?

[buoyant kayak]

because you're trying to find where the derivative is equal to zero

so you have to set the derivative equal to zero

[raw shard]

sorry for barging in but after you take the derivative and you set it equal to zero, you have to use the quadratic formula

if you didn’t already realize

[buoyant kayak]

no you don't

it's easily factorable

[raw shard]

oof i’m dumb

[alpine sable]

The derivative of f(x) is $3x^2+18x-48$

[ocean seal]

Euclid

[alpine sable]

Then find the roots

Then it’s easy after that

[buoyant kayak]

yeah they already have the derivative written

[stuck pewter]

Can Anyone help me on this?

[tough obsidian]

Wait so I was trying to find tangent line

I’m up to the point where I have the slope at that point

Though I am now stuck

[buoyant kayak]

use point slope form

you found the slope, and it gives you an x coordinate

what can you do with that x coordinate to get a y coordinate?

[tough obsidian]

I am confusion

Plug that slope into the original equation?

[buoyant kayak]

that won't do anything for you

[tough obsidian]

Oh dammit

[buoyant kayak]

but you are plugging something into the original equation

[tough obsidian]

4 maybe?

[buoyant kayak]

yes

that is the x value

and to get a y value, you plug x into your equation

just like if f(x)=5x and you were given x=3, you know that y=15 at x=3, so your pair is (3,15)

[tough obsidian]

I got -4

Oh so 4,-4

And the slope of line is -2

[buoyant kayak]

now use point slope form and simplify

[tough obsidian]

Yay I got it

So I just need slope of line and x and y

Slope of line = derivative at that point

nice thanks

[buoyant kayak]

👍

[tough obsidian]

Wait also I seen some other formula for that last step that confused me

[buoyant kayak]

what formula?

[tough obsidian]

Towards the end

That

[buoyant kayak]

they just rearranged point slope form

normally it's $y-y_1=m(x-x_1)$

[ocean seal]

a disappointing son

[buoyant kayak]

they rearranged to $y=y_1+m(x-x_1)$

[ocean seal]

a disappointing son

[buoyant kayak]

then replaced $y_1$ with g(x) and m with g'(x)

[ocean seal]

a disappointing son

[buoyant kayak]

it makes sense, what did you do to get your y coordinate? you plugged 4 into g(x), which is g(4)

so g(4)=y_1

and to find the slope? well, you took the derivative, then plugged in 4

so g'(4)

[fiery sluice]

how does texit work

[stark trail]

okay

[buoyant kayak]

depends on what you want to display lol

[fiery sluice]

x^3 -1

how do you factor that

[buoyant kayak]

$x^3-1$

[ocean seal]

a disappointing son

[stark trail]

$x^3-1^3$

[ocean seal]

Muzan Jackson

[buoyant kayak]

difference of cubes

[fiery sluice]

which means?

[stark trail]

there's a formula for it

[buoyant kayak]

$x^3-y^3=(x-y)(x^2+xy+y^2)$

[ocean seal]

a disappointing son

[fiery sluice]

ooooooo

ty

[buoyant kayak]

👍

[lucid wadi]

Hi

so for this, if I plot a point at 0, I would get 1

cause anything raised to the 0 is 1

but for some reason on mathway it's -1

[buoyant kayak]

-(3^0)=-(1)=-1

[lucid wadi]

OH SHOOT

exponents first

sorry

thanks

[buoyant kayak]

👍

[tulip nexus]

Can I use channel

[buoyant kayak]

sure

[tulip nexus]

Need help w this question

Pls

[eager fern]

i dont understand how my teacher finds out what f(1) and f(3) is

[buoyant kayak]

by plugging in 1 and -3 into the original function

[tulip nexus]

Can u help me out @buoyant kayak

Not sure what to do

[buoyant kayak]

turn tan(2x) into sin and cos

then use a double angle identity

and i think you should be able to evaluate from there?

[tough obsidian]

Hi

Was practicing more derivatives

Is there something i did wrong

Multiplying the x feels weird

Or maybe I’m misunderstanding exponent rules

[toxic meadow]

can someone help me find g(f(x))

[buoyant kayak]

you used the quotient rule incorrectly

$\frac{d}{dx}\frac{f(x)}{g(x)}=\frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}$

[ocean seal]

a disappointing son

[buoyant kayak]

plug $\frac{1}{x-9}$ into g(x) whenever you see an x

[ocean seal]

a disappointing son

[buoyant kayak]

then simplify

[toxic meadow]

what did i do wrong

[tough obsidian]

Thank you wise math wizard

[tough obsidian]

🙏

[buoyant kayak]

$x-9-9\neq -18x$

[ocean seal]

a disappointing son

[toxic meadow]

oops

x - 18

right?

[buoyant kayak]

👍

[toxic meadow]

i’m slow sorry lol

[buoyant kayak]

happens to all of us

[toxic meadow]

thanks

[buoyant kayak]

👍

[alpine sable]

lmao

[thick shard]

hey yall! can anyone help me through this problem? solution is at the bottom, but I can't seem to solve it

[tough obsidian]

Hi quick question my mind is breaking

You know how if you have (w+x+y) - (a+b+c)

The negative distributes

Does that happen if You know how if you have (w+x+y) + (a-b-c)

[buoyant kayak]

instantaneous rate of change formula is $\frac{f(b)-f(a)}{b-a}$

[ocean seal]

a disappointing son

[thick shard]

I think this is for average rate of change not instantaneous

[buoyant kayak]

you can use the values around week 21, that being week 18 and 24, which are both conveniently 3 weeks apart, so your average will be at 21 weeks

[thick shard]

ahhh

got it

I'll try that

[buoyant kayak]

the positive distributes, i guess lol

if you want to think about it that way

but negative * positive = negative

[tough obsidian]

So would it stay negative

[buoyant kayak]

yes

[tough obsidian]

Oh ok

Gotcha

Brain is breaking rn

Need sleep

Thank you for helping my noob questions 🙏

[ruby dagger]

Can someone help me for this question

[eager fern]

How do i do this

[buoyant kayak]

use synthetic division, work backwards

[raw shard]

guys go to different channels

question after question right here

[ruby dagger]

got it thanks

[buoyant kayak]

👍

[chilly tide]

This is an infinite series question. I thought part C would require the use of the infinite geometric series formula (a/1-r) however the answer i get is incorrect. Anyone know how to approach this question?

[stable dune]

is this right

[peak raft]

<@&286206848099549185> hey any helper can help with this question?

[chilly tide]

bruh

i asked a question before yall

[peak raft]

oh my apologies

[chilly tide]

nah all g

This is an infinite series question. I thought part C would require the use of the infinite geometric series formula (a/1-r) however the answer i get is incorrect. Anyone know how to approach this question?

posted the wrong ss before 😐

a/1-r

2/1-0.6

2/0.4

5

?

[lapis valley]

yea

[chilly tide]

but its wrong

[lapis valley]

how

[chilly tide]

do u want me to tell what answer the book gives you?

[lapis valley]

yes

[chilly tide]

8 m

instead of 5

[lapis valley]

it should be 5

[chilly tide]

idk i dont thing the book has a wrong answer. but i also think that...i dont have a wrong answer....

so who has a wrong answer

[lapis valley]

textbooks can sometime have wrong answers

[chilly tide]

hmmm

idk

that sounds like winning the lottery

[lapis valley]

the textbook i use has lots of wrong answers

[chilly tide]

rlly

the textbook i use is like a standard for alot of schools in my state

[lapis valley]

ok let someone else come to confirm

[chilly tide]

ok

should i ping helpers?

[lapis valley]

idk

oh

i see

the ball travels up and down

[chilly tide]

soooooo.....

[lapis valley]

yes it should be 8

so if u take the first three bounce

then its 2 + 1.2 + 1.2 + 1.2* 0.6 + 1.2* 0.6

the ball goes down then up

so its twice the height

except for the first one

[lapis valley]

yes

so its $2+ 2\cdot \frac{1.2}{1-0.6}$

[ocean seal]

hduxueiwkwnxudi

[chilly tide]

oh

[lapis valley]

Once the ball hits the ground

the ball goes up to x and down to the ground

before makign the next bounce

so its 2x where x is the max height

do u get it?

[chilly tide]

i get that you multiply by two becuase the ball travels up then down

[lapis valley]

yea

[chilly tide]

but the algebra u just did didnt make sense

[lapis valley]

why?

[chilly tide]

why are we adding 2 to the infinite geometric series?

[lapis valley]

because thats the inital distance between the ball's height and ground

at first the ball travels 2m

and then it will bounce 2x

the ball doesnt go back to 2m once it reaches the ground

i have class rn so im typing fast sorry

[chilly tide]

OHHHHH

[lapis valley]

if its unclear

[chilly tide]

I GET IT

THANK YOU

[lapis valley]

ayy

nice

: )

[chilly tide]

TYSM

[lapis valley]

yea