#help-0

1 messages · Page 610 of 1

alpine sable
#

What do I do with the 6/3

#

Oh sorry

oak chasm
#

@plucky crow So, we'll go clockwise 90 degrees to get due east. Then we'll add another 90 to get due south. Then we'll add another 90 to get due west. Then we'll add 90 - 15.5 to get the angle.

plucky crow
#

oh

oak chasm
#

Do you see how I got that?

plucky crow
#

its just abit confusing

#

cus north

#

intersects

#

that blue area

oak chasm
#

Yes, but do you see how I start out north and start going clockwise?

plucky crow
#

yeah

oak chasm
#

I get to due east, then due south, then due west.

#

Do you see why I went an additional 90 - 15.5?

plucky crow
#

yeah

oak chasm
#

Where does the 15.5 come from?

plucky crow
#

its 15.5 west from north

oak chasm
#

Right.

plucky crow
#

so you just go past

#

the east line

#

and stop at the other one]

oak chasm
#

Not sure what you mean.

#

I went past three cardinal directions.

plucky crow
#

okay so the section shaded blue has two radiuses

oak chasm
#

What?

#

It's a circle, the radius is the same throughout.

#

Oh, you mean the lines from the middle to the edge?

plucky crow
#

i mean lines coming out to the edge

#

yeah

#

my bad

oak chasm
#

That diagram is just to show you where the northwestish angle was.

#

Forget the blue part and the line due east.

#

Focus on the line that goes northwestish.

plucky crow
#

oh

#

okay

oak chasm
#

Then start at north.

plucky crow
#

im a bit confused about the method you used

oak chasm
#

Then go 90 clockwise to get due east, then 90 clockwise to get due south, then 90 clockwise to get due west, then 90 - 15 clockwise to get to that angle.

plucky crow
#

yeah i get that

#

but the other method

oak chasm
#

What other method?

plucky crow
#

you made the horizontal components = 0?

oak chasm
#

Yes, because you want to be swimming due north.

#

So, the horizontal components of the sum of the vectors has no horizontal movement.

plucky crow
#

ohh

#

thanks

oak chasm
#

No problem.

plucky crow
#

1 last thing'

#

@oak chasm

#

"coming from the west"

#

does it mean its acting east?

oak chasm
#

What is coming from the west?

plucky crow
oak chasm
#

Yes, the wind comes from the west and heads east, so it pushes your aircraft eastward.

plucky crow
#

alright

celest wagon
#

Is it true that a function cant be considered to be an operation if the output can result in something outside of the functions domain? Take for instance the function f(x) = x-1 with the natural numbers as the domain. This function can result in an output that is outside of the domain of the function, and can therefore not be considered as an operation. Am I onto something or is this wrong?

#

I haven't really found a formal definition to figure this out, so its mostly intuition im thinking with here

#

formal definition of what an operation is

oak chasm
celest wagon
#

Thanks, this is a unary function tho am i right?

oak chasm
#

Yes, it will still require that you produce an element in the domain as your output.

celest wagon
#

"More specifically, a binary operation on a set is an operation whose two domains and the codomain are the same set." this is what i needed. Cheers @oak chasm

oak chasm
#

No problem.

final crag
#

Can someone explain how this is antisymmetric?

oak chasm
#

@final crag What definition do you have for antisymmetric?

final crag
#

not sure

#

the instructor said it was antisymmetric

oak chasm
#

Let me know when you've finished.

final crag
oak chasm
#

No, I mean, that's one possible conclusion of your proof.

#

I think it's not antisymmetric.

#

Is R((1, 2), (2, 1)) true?

final crag
oak chasm
#

Is R((2, 1), (1, 2)) true?

final crag
#

nope

#

waait

#

yeah it s not right

#

cuz 1 doesnt equaal 2

oak chasm
#

Doesn't have to.

#

What's the relation?

final crag
#

Z×Z. (a, b) is related to (c, d) if a ≤ c or b ≤ d

ocean sealBOT
#

Chai T. Rex

final crag
#

what would b be here?

oak chasm
#

You saw that they had R((a, b), (c, d)), right?

#

So, b would be the second part of the first tuple.

#

I also filled it in in the parentheses.

final crag
#

so 1,2?

oak chasm
#

No

ocean sealBOT
#

Chai T. Rex

final crag
#

so b = 1

oak chasm
#

Right, b is 1.

final crag
#

so that statement is false

oak chasm
#

What statement is false?

final crag
oak chasm
#

There's been a lot of statements so far.

ocean sealBOT
#

Chai T. Rex

final crag
#

oh if you put it that way its true

#

lol

oak chasm
#

So, R((2, 1), (1, 2)) is true.

#

R((1, 2), (2, 1)) is also true.

final crag
#

so that would be 1 <= d(1<=2)?

oak chasm
#

What?

final crag
oak chasm
#

Which part of it?

final crag
#

all of it haha

#

like how did you come up with that

ocean sealBOT
#

Chai T. Rex

oak chasm
#

The second part came from filling in b and d.

final crag
#

so if u do (1,3)(3,1) isnt it false?

#

b =3, d = 1?

oak chasm
#

Are you just guessing on these things or do you plan to use the relation's definition?

#

What's the relation's definition?

final crag
#

R(a, b) and R(b, a), then a = b.

oak chasm
#

No, that's antisymmetric's definition.

#

What's the relation's definition?

#

Right. What part comes after the if?

final crag
#

inclusive or

oak chasm
#

Of what?

final crag
#

of a ≤ c or b ≤ d?

oak chasm
#

Right, so figure out both parts of the or statement.

ocean sealBOT
#

Chai T. Rex

oak chasm
#

Then use or on them.

final crag
#

So our example was (2,1) ,(1,2)

oak chasm
#

No, on your latest example.

oak chasm
final crag
#

(1,3)(3,1)

#

yep true

oak chasm
#

Why?

final crag
#

1 <= 3 or 3 <= 1

#

the or statement makes it true

oak chasm
#

less or equal.

final crag
#

the first part is true

#

if it was and, it would be false

oak chasm
#

Right, but you need a small correction. It's less than or equal, not less than.

final crag
#

yeah idk how to do that here on keyboard other than <=

oak chasm
#

<= is fine.

#

So, what if you reverse those and have (3, 1), (1, 3)?

#

Is the relation true or false?

final crag
#

3 <= 1 or 1<= 3 would be true

oak chasm
#

So, we have a = (1, 3), b = (3, 1). R(a, b) and R(b, a) are both true.

#

Is a = b?

final crag
#

yes

oak chasm
#

(1, 3) = (3, 1)?

final crag
#

wait but it states "R(a, b) and R(b, a), then a = b."

oak chasm
#

Right.

#

Is the consequence a = b true?

final crag
#

Yes because it states then a = b?

oak chasm
#

I don't care what it states.

final crag
#

1,3 = 3,1 is not equal to each other though

oak chasm
#

Relations aren't always antisymmetric, so what it states isn't always true.

#

Right!

final crag
#

so why is it saying then a =b?

oak chasm
#

Do you know how a logical implication works?

ocean sealBOT
#

Chai T. Rex

final crag
#

if and only if?

oak chasm
#

No.

final crag
#

oh then, im not sure

oak chasm
#

Do you see a doubleheaded arrow?

ocean sealBOT
#

Chai T. Rex

oak chasm
#

If you have the P, you should also have the Q.

final crag
#

oh okay

#

what if it was double arrowhead?

ocean sealBOT
#

Chai T. Rex

final crag
#

then it would be true if its false and false?

ocean sealBOT
#

Chai T. Rex

oak chasm
#

What about the other three?

final crag
#

true true is false

oak chasm
#

No.

final crag
#

true false is false

#

oh

oak chasm
#

If you have the left side true, you should also have the right side true.

#

If you have the left side false, it's fine.

final crag
#

ah so false -> true would be true?

oak chasm
#

No, read what I wrote.

#

Oh, wait.

#

Yes, that's right.

#

What's T -> T?

final crag
#

True

oak chasm
#

What's T -> F?

final crag
#

True as well

oak chasm
#

What's the rule?

final crag
#

left side has to be true

oak chasm
#

No.

#

Please quote what I wrote.

final crag
oak chasm
#

Right.

#

And if the left side is false?

final crag
oak chasm
#

What does "it's fine" mean to you?

final crag
#

oops

#

but then wouldnt that mean if you have true on the left side but false on the right side

#

it would result false?

oak chasm
#

Yes.

#

So what's T -> T?

final crag
#

oh i see now

#

True

oak chasm
#

What's T -> F?

final crag
#

False false would be true

oak chasm
#

No.

#

What does "it's fine" mean to you?

final crag
#

oops i keep messing up my true and false

#

T -> F would be false

oak chasm
#

What's F -> T?

final crag
#

F -> T would be True

oak chasm
#

What's F -> F?

final crag
#

because false is on the left

#

F -> F is true

oak chasm
#

Right.

final crag
#

F is on the left which means its fine

oak chasm
#

Now, let's go back to the definition of antisymmetric.

#

$$(R(a, b) \lor R(b, a)) \to a = b$$

ocean sealBOT
#

Chai T. Rex

final crag
#

oh i think i see whats happening now

ocean sealBOT
#

Chai T. Rex

sly mantle
#

@oak chasm \land not \lor

final crag
#

so first sstaement is True, 2nd is False?

oak chasm
#

@sly mantle In the relation definition, it's inclusive or.

final crag
#

That means its False

oak chasm
#

@final crag Right!

final crag
#

jeez

oak chasm
#

So, if you see "if ... then ...", it's like "... -> ..."

final crag
#

ur better than my professor teach my class

sly mantle
#

@oak chasm wdym

final crag
#

so u just gotta remember left has to be false

#

in order for the result to be True

oak chasm
#

@sly mantle This relation.

#

@final crag And when else can it be true?

sly mantle
#

i'm not talking about the relation above

oak chasm
#

@sly mantle Oh! I see what you mean.

sly mantle
#

what you wrote isn't the definition of R being antisymmetric

ocean sealBOT
#

Chai T. Rex

sly mantle
#

yes

oak chasm
#

@final crag You need to study this truth table

#

,w truth table a implies b

ocean sealBOT
final crag
#

will do!

#

this question atleast made sense

#

thanks for the help

oak chasm
#

No problem.

limber ledge
#

how would I approach solving this?

#

please can I get some help?

civic crypt
#

@limber ledge What have you tried?

limber ledge
#

I dont know how to solve this if I am being honest

#

this is my first time trying to do these types of problems

civic crypt
#

You know what is a measure m of something?

limber ledge
#

yes

#

mEFG is unknown

#

radius is 7

civic crypt
#

One of the questions asks you to find the measure of EFG arc.

limber ledge
#

mEFG/pi7^2 = 80/360

#

is that how I would solve for EFG arc

#

I am using the formula in my textbook

civic crypt
#

Wait a second.

#

The question says that angles EDF and FDG are equal

limber ledge
#

yes

civic crypt
#

Now it asks you to find the measure of arc EFG

#

What is the measure of arc EFG?

limber ledge
#

Im not sure

civic crypt
#

What is the measure of some arc?

limber ledge
#

FDG = 80

civic crypt
#

I mean the measure of any arc?

#

What is an arc at all?

indigo cedar
#

Anyone know engeneering?

limber ledge
#

The measure of an arc is the arc length divided by the radius of the circle.

civic crypt
#

OK, that's a formula that relates arc measure to arc length and radius.
But what means the measure of an arc, what is its definition?

civic crypt
indigo cedar
limber ledge
#

@civic crypt is my statement correct

civic crypt
#

yes, but it is not the definition, it is a formula that relates those 3 values

limber ledge
#

ok

#

how do I solve this

civic crypt
#

What is an arc?

limber ledge
#

a part of the circumference of a circle or other curve

civic crypt
#

OK, what is the central angle of the arc?

limber ledge
#

the radius

civic crypt
#

The radius is the radius. It is not an angle

limber ledge
#

ok

#

the arc length of EFG = 34

civic crypt
#

First find the measures, cause they are easier

hallow herald
#

Can someone help me with this?

#

Pleaseee

upper spruce
#

Someone please help me with this sum of progression

For the sequence
1² + 2×2² + 3² + 2×4² + 5² + 2×6² + ..........
If sum of first 20 terms is equal to A and sum of first 40 terms is equal to B
Given:- B-2A=100₩ then find the value of ₩

#

@velvet pelican pls help

#

@civic crypt pls help

muted raft
#

Can you not like mention people for help?

limpid spade
#

don't ping -

#

why am I always late

muted raft
#

F

gray gorge
#

sniped

upper spruce
#

<@&286206848099549185>

#

If any <@&286206848099549185> wishes to help me then pls ping me so that I may come online

muted raft
#

nice

alpine sable
#

Does anyone know the answer to this Biotechnology question?

limpid spade
#

The sum of n terms of AB is the sum(addition) of first n terms of the arithmetic sequence. It is equal to n divided by 2 times the sum of twice the first term – 'a' and the product of the difference between second and first term-'b' also known as common difference, and (n-1), where n is numbers of terms to be added.

limpid spade
alpine sable
#

Which one is that

#

@limpid spade

#

Ping me there

limpid spade
alpine sable
#

I am trying to find out if the series is convergent or divergent and come to the conclusion that is is divergent

#

Not sure where I went wrong

#

The entire question for context

#

I now know it converges (as I can tell by my choice being wrong), but how do I calculate the sum

severe forge
#

right side diverges clearly right ?

alpine sable
#

Are you taking about the (-1)^n/3^n?

severe forge
#

yeah

#

wait lmao

muted raft
#

does it diverge?

#

I don't think so.

severe forge
#

yeah XDµ

muted raft
#

It is a geometric series.

severe forge
#

even then it wouldnt help

stray pawn
#

no zs i just tested that

alpine sable
#

1/3^n is bigger than (-1)^n/3^n, and it converges, therefore the other also converges

muted raft
#

tested what

stray pawn
#

its not geometric series

severe forge
#

the right one should converge tho

#

left*

muted raft
stray pawn
#

am i wrong? i dont see a common ratio

alpine sable
#

is this true?
$\\sum_{n=a}^{b} f(n) + g(n) = \sum_{n=a}^{b} f(n) + \sum_{n=a}^{b} g(n)$

ocean sealBOT
#

Mofumofu

muted raft
#

Yes this is valid

alpine sable
#

You can separate them PogChamp

stray pawn
#

yes so break it up into two then you have geometric series

severe forge
#

isn't the left one a o(1/n^2) ?

alpine sable
#

oh then that makes it easier

muted raft
#

and $\frac{\qty(-1)^n}{3^n} = \qty(\frac{-1}{3})^n$

ocean sealBOT
alpine sable
#

\qty ?

muted raft
#

$\qty()$

ocean sealBOT
stray pawn
#

oh okay. so it seems you have to break up the summation into two terms. then find the sum of each summation using geometric series formula and sum them up

muted raft
#

vs $\left( \right)$

ocean sealBOT
alpine sable
#

god, i used to do it like this $\left( \right )$

ocean sealBOT
#

Mofumofu

muted raft
#

\qty is from physics package

#

which texit supports

alpine sable
#

oh

severe forge
#

left one is o(1/n^2) so it converges

#

i think bro XD

alpine sable
sage lynx
#

How do I find this?

severe forge
#

depends

stray pawn
#

you find derivative of f'(x) and plug the point (1, -1) to find the slope

sage lynx
#

oh alr

stray pawn
#

then you use point (-1, 1) in formula y = mx + b to find b

sage lynx
#

cool, i'll do that then get back to see if i got it right

alpine sable
#

Or I might be confusing the rule that a convergent series stays convergent if something is summed or if it is multiplied by a term

#

I probably has a misconception here

severe forge
#

but since the right one is also convergent it converges yes

alpine sable
#

Got that

#

So I would separate the summations, find their individual sums, and add them together

#

Then that would be the value of the original summation

severe forge
#

wait what are you looking for already ? Lmao

alpine sable
#

wdym

severe forge
#

whats the problem

#

the question

#

XD

alpine sable
#

The summation problem above

severe forge
#

yeah

alpine sable
severe forge
#

oh

#

ok

alpine sable
#

Bottom part

severe forge
#

so it converges

#

then you have to find the thing

muted raft
#

thing?

severe forge
#

XD

#

the sum

alpine sable
#

the thing 🤣

severe forge
#

you go badaboom

#

you separate

#

and do geometric shit

#

and gg

alpine sable
#

Thank you all

severe forge
#

lmao

alpine sable
#

@severe forge this is beautiful lmao

severe forge
#

since im here

#

for f an endomorphism show existence and uniqueness of f* an endomorphism so that for all (x, y) in E^2,(f(x)|y)=(x|f*(y)) (E is euclidian)

#

anyone has an idea for existence pls ?

muted raft
#

haven't studied this so can't help.

severe forge
#

alright np

sage lynx
#

bc then there's no variable

#

or do i add an m or b somewhere

#

nvm i got it

tacit pebble
#

What’s the final equation of:
f(x) = x^2 + x - 3
When you horizontally dilate it with a scale factor of 1/2?

#

<@&286206848099549185>

alpine sable
#

If by dilate you mean stretch, then you would do f((1/2)(x))

tacit pebble
rigid pivot
#

Is there a way to transform the Fibonacci sequence's formula so that F0 and F1 are not equal to 0 and 1 respectively, but something else I arbitrarily choose?

#

This formula:

#

It assumes that F0 = 0 and F1 = 1, but what if I wanted that F0 = 3 and F1 = 7?

severe forge
#

If you start the sequence from somewhere else you can

#

But then you had 1 to n in the formula soo

muted raft
#

Does binet's formula work for arbritary a, b?

rigid pivot
#

That's what I mean. How can I transform that equation?

#

I think not

#

At least not to my knowledge

muted raft
#

it would pretty much just be a recursion then.

severe forge
#

It does

#

I think

neon aurora
#

Hi guys, drew a little problem for you as I'm trying to do a linear regression 🙂
What do you guys think? Graph #1 or #2?

rigid pivot
#

Where do you plug the arbitrary a and b?

severe forge
#

Wait what

muted raft
#

really?

#

Can you send me a link?

#

I am curious about this.

sly plank
#

found this

severe forge
#

I lied @muted raft

#

I didnt understand what you meant

muted raft
#

need to go eat, will check out that link later

rigid pivot
#

Ok thanks. I'll try to figure my issue out from there if it works.

quasi sable
#

scatter plot in question>

#

this would be no correlation right? x increases as y increases but there is also random dips in the plot

#

so by that logic it would be no correlation right

neon aurora
#

correlation exist, but just weak

quasi sable
#

right so what category would it fall into

#

positive, negative, none??

#

because i wouldnt be able to tell if its + or none

neon aurora
#

I'd say positive

quasi sable
#

kk ill try that

uncut osprey
#

It's definitely a positive correlation. You can make out a positive slope

#

The random dips are just slight anomalies in the data likely caused by some form of margins of error

#

But there's a trend visible throughout the entire sample

alpine sable
#

yo whats gay x sex again?

stray pawn
#

cavities im pretty sure you accidentally typed that in the wrong server

alpine sable
#

no this is the right one

#

stfu

final crag
#

Could someone explain how to do part a?

#

<@&268886789983436800>

final crag
alpine sable
#

no

#

on

#

on

#

on

#

on

final crag
#

go get help man

#

u cant keep living a miserable life, ur not going to make it

fading citrus
#

cheers

sage lynx
#

anyone know how to obtain (f+g)'(2)

quasi sable
uncut osprey
#

You can definitely think of it like that.

#

I doubt your teacher will be evil and intentionally give scatter data that's really hard to pick out if there's any correlation. But here's a general diagram to help you see the 3 types

#

Even this has some pretty extreme disparity between the positive/negative points, so if you can see the scatter plot correlations on this you're set.

blazing oak
#

Shit

blazing oak
glass lichen
#

what's (f+g)'(x)?

sage lynx
#

thats what i dont know lol

#

i dont know what (f+g) means

blazing oak
sage lynx
#

no

blazing oak
#

Mee too

glass lichen
#

$(f+g)(x)=f(x)+g(x)$

ocean sealBOT
sage lynx
#

Oh

#

so then how do i get f(x) and g(x)

blazing oak
glass lichen
#

what do you mean?

#

you have a table of values for f and g and their derivatives

strong furnace
sage lynx
#

so can i just take (6+2) for fx + gx?

glass lichen
#

no

blazing oak
#

I don’t understand

glass lichen
#

you take the derivative of (f+g)(x) first

sage lynx
#

oh

#

so 4+5?

blazing oak
#

Bruh this lesson is so hard

glass lichen
#

I didnt know 2 = 1

#

thanks for letting me know

sage lynx
#

wat

glass lichen
#

is it asking for (f+g)'(1)?

sage lynx
#

no

blazing oak
#

Someone explain it to me

glass lichen
#

so why did you plug in x=1?

blazing oak
#

?

sage lynx
#

youre right

#

dammit

glass lichen
sage lynx
#

what do i plug in then?

glass lichen
#

x=2. . .

sage lynx
#

ok

#

oh my days i just realized how dumb i am

#

wow

#

thanks lol

alpine sable
#

(f+g)'(x) = f'(x) + g'(x)

#

If x is 1

glass lichen
#

yes due to the linearity of the derivative

alpine sable
#

f'(1) + g'(1)

#

Then get the values from the table and sub them in

sage lynx
#

2 you mean?

alpine sable
#

and you get an addition problem

sage lynx
#

isnt the x value 2

alpine sable
#

If x is 2, then you have f'(2) + g'(2)

sage lynx
#

ah

glass lichen
#

then b is just quotient rule and plug in

#

$h(x)=\left(\frac{f}{g}\right)(x)$

sage lynx
#

so from the table, i get 2+1=3

ocean sealBOT
glass lichen
#

yes

sage lynx
#

so is that the answer to the first part?

misty pebble
#

Two taxi companies: Company 1 charges $6 and then $1.50 every km and Company 2 charges $8 and $1.20 every km. What's the best way to find when the cost is the same?

sage lynx
#

or do i have to do another step

alpine sable
#

2+1

#

=

#

3

sage lynx
#

alr

alpine sable
#

and like mosh said, the second one is the quotient rule

sage lynx
#

alr i'll use that

alpine sable
#

then plug in the x, get values from table, substitute, solve

sage lynx
#

sweet, thanks guys

blazing oak
#

I don’t understand

alpine sable
#

I posted the work one sorry

sage lynx
sage lynx
blazing oak
sage lynx
#

stop trolling dude

misty pebble
#

Can anyone help me with linear modelling? With questions where there are two services, both respectively having an initial fee and an ongoing cost(per hour/per year etc). What is the best way to find where the cost is the same between the two?

blazing oak
sage lynx
#

do i take the x = 3 values for f and g first and then the x=3 values for f' and g'?

#

Oh ok

alpine sable
#

$\frac{g(x)f'(x)-f(x)g'(x)}{g(x)^2}$

ocean sealBOT
oak chasm
#

@misty pebble Sorry, this channel is busy. You can try #help-9 if you hurry.

blazing oak
#

Guys I need help with something

alpine sable
#

@sage lynx That's the chain rule

sage lynx
#

Alr I'll plug in the numbers

alpine sable
#

Then plug in the x value

#

and then plug in the numbers

#

$\frac{g(3)f'(3)-f(3)g'(3)}{g(3)^2}$

ocean sealBOT
alpine sable
#

Then substitute that in with the values from your chart

#

Also, I am new to Latex, so I will be a slow typer

blazing oak
#

I need help with something

sage lynx
#

I appreciate it Fung

#

I'm plugging in the numbers rn

alpine sable
#

Sure, send your problem @blazing oak

alpine sable
blazing oak
#

So can anyone solve this pls put steps 3x-5>4+5x-3>20=

random crypt
#

Can someone help me w a couple of Calc questions ?

alpine sable
blazing oak
#

So can anyone solve this pls put steps 3x-5>4+5x-3>20=

random crypt
#

I dont know how to do this

alpine sable
alpine sable
#

@random crypt You can graph the function and evaluate how it approaches -1 from the right side

random crypt
#

Can you show me how

#

Like idk what that means

alpine sable
#

Yes

#

Give me one second to write it all out

blazing oak
#

Ok

alpine sable
#

@random crypt You see how the graph approaching -1 from the right side? It is going up forever

#

No matter how far out we go it keeps going up and getting closer to -1

muted raft
#

$$\lim_{n\to -1^{+}} \frac{x}{\qty(x-1)\qty(x+1)} = \lim_{n\to -1^{+}} \frac{x}{x^2-1} = \lim_{n\to -1^{+}} \frac{1}{x-\frac{1}{x}}$$

alpine sable
#

@muted raft New to latex and not really sure how to use it for graphs

ocean sealBOT
alpine sable
blazing oak
muted raft
#

graphing on latex is kinda pain

#

but you can use tikz package or the other tool called inkspace or something.

alpine sable
#

@blazing oak
x - 4 > 3
You need x by itself. That means you need to get the 4 on the other side

#

To do this you would add 4 to both side

#

(Note: Whatever you do in one side, you have to do in the other)

sage lynx
#

I got 265 as my answer, is that correct or did I do something wrong?

alpine sable
#

$x - 4 + \textbf{4} > 3 + \textbf{4}$

ocean sealBOT
alpine sable
#

@blazing oak Do you know how to go from here?

blazing oak
random crypt
#

Can you help me and show me how you do (g)and (h)

alpine sable
sage lynx
alpine sable
#

Use it to check your answer if your professor hasn't shown you that yet

sage lynx
#

Ok I'll do that, thanks

blazing oak
alpine sable
#

This is for one of your problems

#
x - 4 > 3
You need x by itself. That means you need to get the 4 on the other side
To do this you would add 4 to both side
(Note: Whatever you do in one side, you have to do in the other)
#

Then from here you would simplify both sides

#

and that will be your answer

sage lynx
#

I'm like 99% sure this is 1/2 because when you get the derivative its 1/2sqrt2x = 1/sqrt2sqrtx = 1/sqrt2*sqrt2 = 1/2

muted raft
#

it is 1/2

sage lynx
#

great

blazing oak
#

Can anyone help me with the last one

alpine sable
#

So move one of the xs to another side

sage lynx
#

this is just 0 right because the derivative is 2x/e^x = 2(0)/e^0 = 0/1 = 0

i dont think there are any other values of x that work

alpine sable
#

and 2

sage lynx
#

wait 2?

alpine sable
#

at 0,2 and infinity

sage lynx
#

how come?

alpine sable
#

Calculate the derivative and equate it with 0

#

You get 0 and 2

alpine sable
#

Then just factorise and write e^x in the denominator

sage lynx
#

ah

alpine sable
#

As exponential grows faster than quadratic, at inifnity it goes to 0

sage lynx
#

so its 0 and 2 and then dips back down to infinity

alpine sable
#

Yea

sage lynx
#

ight

muted raft
#

I don't think infinity counts here?

#

Infinity is not a number.

alpine sable
muted raft
#

It isn't a number we can assign to x

sage lynx
#

O

muted raft
#

We take the limit yes.

alpine sable
#

No but f approaches 0 as x approaches infinity

muted raft
#

Yes key word is approaches

#

Not the value of x is itself infinity.

alpine sable
#

That’s a perfectly valid argument cos x approaches infinity

sage lynx
#

im a little confused by the part where you plug it in because when i do 2(2)/e^2 i get a number different than 0

alpine sable
#

That’s not the derivative my guy

#

The derivative is -(x-2)xe^-x

sage lynx
#

i took the derivative of the original x^2/e^x

#

and got 2x/e^x

alpine sable
#

The derivative is $2x^(-x) - x^2e^-x$

ocean sealBOT
blazing oak
alpine sable
#

Not sure how you got that

#

I need to work on latex

#

Apply quotient rule

sage lynx
#

oh

#

alright

#

i think i did my work wrong

blazing oak
muted raft
#

You need {} to raise to exponent @alpine sable

#

not ()

sage lynx
#

so do you guys think infinity would count or not

alpine sable
#

$2xe^{-x}- x^2e^{-x}$

sage lynx
#

because it asks for a number

ocean sealBOT
alpine sable
#

There we go

#

I think it would

#

But idk

muted raft
#

I don't think it would.

sage lynx
#

hmm

alpine sable
#

I don't think it would as it approaches 0

sage lynx
#

i'll ask my teacher on monday ig

alpine sable
#

Problem says equal to zero

muted raft
#

Approaching is not the same as assigning value.

blazing oak
sage lynx
#

oh yeah it wouldn't be inifnity then

alpine sable
alpine sable
blazing oak
alpine sable
#

Second

blazing oak
#

How old are you?

alpine sable
#

17

#

Damn already in college

#

Wait...

#

Yea. Birthday is next year

#

🤣

#

That is, when you go to college isnt it?

severe panther
#

Yall so old.. im in 8th.

alpine sable
#

I’m in 10th

#

@alpine sable College is usually from 17-19

severe panther
#

Why the pepe scared

alpine sable
#

I started at 16 and turned 17 not too long ago

severe panther
alpine sable
alpine sable
alpine sable
#

Only one thing can ever save us DANCE time dilation

alpine sable
severe panther
#

I flunked on all my surface area and volume tests in 5th so they are making me take more this year

alpine sable
#

I wanna go to MITstareFlushed

severe panther
#

i cant flunk again or i have to do 8th.. again.. for the 3rd time.

alpine sable
#

Bruh

alpine sable
#

Transfer decisions come out at the end of this month

#

Kind of specific

#

Why Columbia

severe panther
#

I wanna go to brown, the future lies ahead but only surface area determines my future.

alpine sable
#

Pablo Escobar intensifies

#

Narcos theme plays

#

I love the environment built inside of Columbia, how friendly the students are and outgoing for their community, the professors are also amazing

#

Well where are you studying rn

#

I have a friend that attends there and he sneaked me into his dorm multiple times

severe panther
#

Also i am considering Swarthmore College.

alpine sable
#

what TO DO WHAT

alpine sable
#

After Columbia, my top choices are Harvard & MIT

#

The bubble built in Cambridge is amazing

severe panther
#

My dad always says : Learn surface area, attend calculus, pass it- i can’t even pass 5th grade geometry catAngery

alpine sable
#

Geometry was the hardest math class for me tbh

severe panther
#

Yeah exactly

alpine sable
#

Let’s be honest I’m never going to get into MIT😔it’s fine tho imma try anyway

#

For me Calc 1 is easier than geometry

alpine sable
#

Thancc PepoG

#

You are still in 10th. You have a lot of time to get out of this world stats

#

In terms of ECs etc

severe panther
#

My dad got accepted in MIT but didn’t go.

alpine sable
#

Yea imma try olympiads this year

severe panther
#

He went to rutgers.

alpine sable
#

I sadly only realized my passion to study and research towards the end of my junior year when it was too late x_crycat

severe panther
#

His mom, dad, uncle, my uncle, all of them went to rutgers

alpine sable
#

I have a friend attending Rutgers this year

#

I just wanna live a simple life and teach myself maths and physics

severe panther
#

Swarthmore.

alpine sable
#

Yo that’s nice af

alpine sable
#

Chat died rip

#

Oh bruh this was questions channelmonkaS

severe panther
#

I am only 4 minutes away from Swarthmore

#

The surrounding campus area is hot

Best pizza ever

alpine sable
#

Sounds nice

severe panther
#

Well there is a dark side.

#

Want me to dm you what happened there?

alpine sable
#

Yes.

crystal needle
teal frigate
#

Can someone explain why this is a shift by 4?

#

To me it looked like it was a shift of 2

jagged imp
#

it is a shift of 2 to the left

#

but thats not an option

#

there are multiple ways you could translate it to get the same result

fossil grail
#

it could be left or right, right?

tepid crypt
#

Can anybody help me how to find the slope line in a graph

rugged lynx
tepid crypt
#

1.5

rugged lynx
#

how is it 1.5?

tepid crypt
#

U divide 2 by 3 easy

#

As that

#

Taht should be easy

rugged lynx
#

ok 2 divided by 3 is .6

tepid crypt
#

Nooe

rugged lynx
#

3 divided by 2 is 1.5

tepid crypt
#

Yes

#

Correct

#

@rugged lynx what grade u in

rugged lynx
#

so the bigger number first or what

rugged lynx
tepid crypt
#

Ohh

#

Im in 8th

rugged lynx
#

so is it the bigger number divided by the smaller number?

tepid crypt
#

Correct sur

rugged lynx
#

or the unit divided by the rate

#

ok

tepid crypt
#

Just divide the amount of gallons per minute

alpine sable
#

could anyone help me out?

tepid crypt
#

Wtf

#

What grade ur in

#

@alpine sable

alpine sable
#

12

woeful pulsar
#

what have you tried here

#

urgh bad parentheses

#

because obviously p(1) is a constant and if you differentiate that with respect to x you get 0

#

lol

#

but urgh it's bad notation

fossil grail
#

when you are given a question to find the area between a parabola and the x axis, is there any other way to find the area other than using integration?

alpine sable
#

all of them have a 33x on each side
when i click check tho it says im choosing too many answers
am i missing something

alpine sable
#

OHH

#

YEA

fossil grail
#

yeah

alpine sable
#

ty

fossil grail
#

I will admit, that tripped me up in the beginning

fossil grail
muted raft
#

I mean you have a parabola, so integral would probably be the fastest way to calculate the area here?

#

Its gonna need more context than just this.

unborn sail
#

i need help somebody to here to help me?

#

I need to take the volume of a cilinder but the problem is that i only have tree numbers the height is 10 the width is 25 and the large is 2000

alpine sable
unborn sail
#

i dont have d or r

alpine sable
#

Wdym width?

shrewd sable
#

Isn't the width the diameter?

#

What is "the large"

alpine sable
#

Maybe he means thickness

unborn sail
#

long

alpine sable
#

“The large”👁👁

shrewd sable
#

what's the height then

unborn sail
#

like i need to find the volume of a cave

unborn sail
#

meters

shrewd sable
#

I don't think what you're describing is a cylinder

alpine sable
#

What’s the large

unborn sail
#

i dont know my miss only ask for that

#

sorry to you guys

alpine sable
#

Np that’s why we’re here isnt it

unborn sail
#

ill try to explain again

alpine sable
#

Do u have a figure maybe?

unborn sail
#

i am doing the volume of a cave and the only numbers i have that are important are 25width 10 height my miss wants me to split the big cylinder into pieces and then i finish

unborn sail
#

all the numbers are a media

crystal needle
alpine sable
#

I’m sorry I have no idea

unborn sail
#

can you help me to get to the radius

oak chasm
#

@crystal needle Sorry, channel is busy. #help-9 looks empty if you hurry.

alpine sable
#

Everyone

#

This is my friends channel

#

He just started

#

Pls like his video 🙏

#

It will mean a lot 🙏

#

U have the powe to subscribe too

woeful pulsar
#

please don't advertise here

alpine sable
#

Umm sorry

#

Sorry🙏

woeful pulsar
#

you can probably delete your own messages so that you reduce the chance of getting into trouble

tribal geyser
#

Hey guys for question 9)a) I don’t know where the right angle is I’m triangle ATB

#

like how do I even know that it is right angled

woeful pulsar
#

triangle ATB is probably not right angled

tribal geyser
#

Th answer says it is

woeful pulsar
#

oh

#

I see lol

tribal geyser
#

That’s how a) is 400cos52

woeful pulsar
#

calculate all 3 angles

#

you are given two angles

#

can you calculate the 3rd angle?

oak chasm
tribal geyser
#

Yes but that’s not for triangle ATB

#

Like I don’t get how they got 400cos52

oak chasm
#

For that, sum of angles is 180 degrees.

tribal geyser
#

yes yes thanks

oblique stirrup
#

can some1 help me with why solution is wrong

#

complete cycle is 14 units

#

amplitude is 1

#

vertical shift none

#

horizontal shift is 4 to the left

#

not sure what that nessesarily mean

oak chasm
#

A constant function isn't a sinusoidal function.

carmine lion
#

you basically forgot the x

#

idk if ur other parts are right tho

#

,w calc cos(pi/7 + 4)

oblique stirrup
#

o

carmine lion
#

yea

oblique stirrup
#

ty :)

carmine lion
#

how do i combine these

#

$(\frac{1}{x^3})^r \cdot x^{20-r}$

ocean sealBOT
lusty plaza
#

When you multiply numbers of the same base you add their exponents. x^n * x^(n+1) becomes x^(n+(n+1))

carmine lion
#

yeah i realised

#

i feel kinda stupid now

alpine sable
#

can someone help me with this (integration)

#

Can anyone help me with these 2 questions

Research factorial notation and show how factorials can be used in your solution.

How many 5 digit numbers can be formed from the digits 2, 3, 4, 5, 6 (without repetition)?

oak chasm
#

@alpine sable Get the equations of the lines of all three sides.

alpine sable
#

ok

quasi sable
#

someone please tell me im right on this

#

the line of best fit goes right through every unit so its y = x right?

crystal needle
harsh swallow
#

i'd say you're not exactly right @quasi sable

#

there's more points to the down right of the line than up left

alpine sable
#

can someone help me understand the second to last blank line for this prob

quaint trout
#

Evaluate the sum of the expression you got in e

#

It will depend on n but not on k since the k will disappear when you take the sum.

lime lintel
alpine sable
#

like im confused in regards to the evaluation

lime lintel
#

btw its sine and cosine graphs

blazing ridge
untold lynx
#

pls work

nimble matrix
#

Can we replace 0 with C in the context of Exact differential equations because 0 is also a constant ?

#

such as C-C=0 so can we write C instead of 0

glossy nymph
nimble matrix
#

because i am practicing exact diff equations and if we equate general solution to C and there is also a C present on left side and if we subtract them then we get 0 so 0 is a constant so according to my intuition, i think we can replace it with C but i need justification @glossy nymph

glossy nymph
#

You cannot cancel the constants since you don't know what they are

nimble matrix
#

Cant we do C-C
BTW i am getting a true answer

glossy nymph
#

And the point of having no constant in an exact integral is cause when you calculate upper and lower bound you subtract the same constant from itself. That's why you get no constant

#

In a general integral, you simply do NOT know what the constant is, so you have to call it c

nimble matrix
#

thats why i am writing C instead of 0
because then we can put limits in definite integrals

#

C-C=C and now we still have our constant C in equation

glossy nymph
#

In your general integral c is anything. In definite, c is 0

#

They are not the same

glossy nymph
#

How is 5-0=0?

nimble matrix
#

I am writing C as 0 in general integral

#

but not in definite integral

glossy nymph
#

You better provide the context you wanna use it for.

nimble matrix
#

ok wait

#

I meant to say "equate it to C"

#

Y(1)=1 is initial value for equation

red spoke
#

anyone know arithmetic and geometric sequence

nimble matrix
#

@glossy nymph

oak chasm
#

@red spoke Sorry, channel is still busy.

nimble matrix
#

Channel is busy bro @proud agate

glossy nymph
#

I mean we write C to show any arbitrary constant but it doesn't mean it's the same value, you get it?

nimble matrix
#

So if we put C in equ 3 and also equate it to C
Then there will be 2 C's left and right side so how else would we solve it ?

#

@glossy nymph

glossy nymph
#

But you can't equate to 0 unless you have information that the constants are equal

nimble matrix
#

Why not name It C

glossy nymph
nimble matrix
#

That's what I was saying that after subtracting C-C, can we write just C rather than 0

glossy nymph
#

Yeah that's right!

nimble matrix
#

0 and C are both constants

#

Thanks brother

glossy nymph
#

Np

grizzled sundial
#

@night geyser its looking better but why is my graph still in the 2nd quadrant?

night geyser
#

oh you didnt translate it enough

#

idk what the x axis of your original graph actually was

#

i assumed it was years

#

but apparently that was incorrect

grizzled sundial
#

i don't know

#

it's so confusing

#

are you busy rn?

night geyser
#

just increase 2000 until you get the correct placement i guess

#

without further information i cant be more specific

grizzled sundial
elder quarry
#

Can someone help me? What is the Derivative of y = cx²

#

please

nimble matrix
#

dy/dx=2cx

#

@elder quarry

elder quarry
#

thanks so much man

lost crane
#

Why is e^-infinity = 0?

upper sparrow
#

@lost crane e^(-inf) = 1/e^inf = 1/inf = 0

lost crane
#

Oh, that makes sense

#

never saw it that way

#

thanks for clearing it up!

upper sparrow
#

👍

novel haven
#

Please tell me im not going insane.

#

The question I have is
A) This triangle has angles in the ratio 1:2:3 please prove it is a right-angled triangle. Pretty easy right?

#

So I type: that there are 180 degrees

#

split into 6

#

so its 30:60:90

#

90 is a right angle

#

but i onlt get 1/2 marks?

gloomy lintel
#

Makes sense to me

#

Hmmm

gray isle
#

were there any comments?

novel haven
#

No. This is on Mathswatch.

#

Ill probably e-mail the support team.

keen fable
#

Hello

#

i need help

#

with my hw

#

what should the two equations be

#

i can do the rest

upper sparrow
#

So, just denote the time spoken as t.

#

Now, what would be the cost of talking if you were using kaseem mobile?

#

@keen fable

keen fable
#

27+0.12t

upper sparrow
#

Good.

#

And for hafeez?

keen fable
#

14+0.15t

#

but our teacher wants it to be 2 equation 2 unknown

upper sparrow
#

Now, the questions tells you that the 2 costs are equal

keen fable
#

yeah

upper sparrow
#

So, you put them equal. And solve for t

keen fable
#

oh ok

upper sparrow
#

So, just define one more variable

keen fable
#

which would be

upper sparrow
#

The cost of talking. Let it be c1 and c2.

#

So, u have c1 = cost for kareem
C2 = cost for hafeez
And c1 = c2 is your 3rd equation

#

It's basically, just beating around the bush though

keen fable
#

yeah ok i'll just do it how you told me before

#

because our test coming up is gonna be solutions of system of equations and that

#

but thank you a lot anyways

civic crypt
#

You can mutiply with y cause it is positive.

#

y/x > 1

#

No

#

Wait

#

What if you move 1 to the left

#

(y - x)/x > 0