Available help channel!
#help-0
lone heartBOT
Available help channel!
scenic kestrel
What's the phase difference between these two wave functions here?
scenic kestrel
Is it π?
whole geode
what do you mean by difference?
scenic kestrel
what do you mean by difference?
I mean phase shift
whole geode
they don't have the same frequency
scenic kestrel
Phase shift to go from the below wave to the above wave
whole geode
you should see that both the amplitude and the frequency are different
and there is a phase shift
can you see what the frequency and amplitude are?
scenic kestrel
can you see what the frequency and amplitude are?
The amplitude is 2
I don't know about the frequency
whole geode
The amplitude is 2
of which function?
scenic kestrel
Wait, this is the full question
scenic kestrel
of which function?
The above one
whole geode
yes
scenic kestrel
Wait, this is the full question
Can you explain how to find the equation of the above function here?
whole geode
we're getting there
scenic kestrel
Oh ok
whole geode
what is the amplitude of cosine
scenic kestrel
1
whole geode
how would you modify cosine to get it to have amplitude 2
whole geode
can you put that into a formula
whole geode
basically
scenic kestrel
Oh so 3
whole geode
what is it of cosine?
scenic kestrel
0
whole geode
and how do you modifiy cosine to get it to have a mean of 3
scenic kestrel
2 cos (x) + 3?
whole geode
ok good
now the frequency is still wrong
can you identify a part of the cosine function, that looks like the entire section you see above (just smaller)?
scenic kestrel
Mm aren't there two?
scenic kestrel
Okay
whole geode
ok, do you have one?
scenic kestrel
4 pi
whole geode
and how do you modify cosine so you go through the same motion in "half the speed"
scenic kestrel
2 cos (0.5x) + 3?
whole geode
yes
and how the phaseshift is still missing
we need to align them
so what is 2 cos (0.5*0)+3?
scenic kestrel
5?
scenic kestrel
Isn't the above function at 5?
whole geode
yes
scenic kestrel
Below one is at 1
scenic kestrel
0?
whole geode
exactly
whole geode
This was methodical
We did the last part because in general you'll need to do that too
if you go through these steps, you'll get it every time
if you know that the function above has the correct form
and that was the premise of the exercise
scenic kestrel
Ok, got it
scenic kestrel
and that was the premise of the exercise
Thanks for the help
whole geode
no problem
scenic kestrel
.close
vocal hawk
I have two objects that are moving in 2d space with constant velocities:
object1: pos = 19, 13 vel = -2, 1
object2: pos = 18, 19 vel = -1, -1
how can I found their intersection point?
vocal hawk
I tried the following
r = v*t + x
so v1*t + x1 = v2 * t = x2
this will give me two equations in the x dimension and y dimension
where t = (x2 - x1) / (v1 - v2)
but when solving this, I get different t's for each dimension
I get t = 1 for x, and t = 3 for y
what am I doing wrong?
golden canyon
That means they will never intersect
vocal hawk
according to the question, they will intersect
the question says: the intersection point is : x = 14.333, y = 15.333
golden canyon
19 + -2 * t = 18 + -1 * t and 13 + 1 * t = 19 + -1 * t, right?
hmm, seems t = 1 and t = 3 are correct
Maybe send a picture of the original question
vocal hawk
golden canyon
ah, the paths will cross, not the objects
vocal hawk
the points also have z componenets, and the question says to ignore them for now
what's the difference?
golden canyon
the path is a line, independent of time
their paths crossing means that there is a point they both visit
vocal hawk
I see
so they both reach (14.333, 15.333), but at different t values
alright, thank you
golden canyon
Yes
vocal hawk
so the vector equation is
v1 * t1 + x1 = v2 * t2 + x2
how do I proceed?
I will get a system of 2 equations to solve for t1 and t2, right?
I think this is correct
.close
scenic umbra
can somebody help me with it
lone heartBOT
can somebody help me with it
exotic canopy
$2x^2+3 = 2x^2 - 4 + 7$
ocean sealBOT
artemetra
exotic canopy
подставляешь в числитель и упрощаешь
ocean sealBOT
artemetra
exotic canopy
так?
scenic umbra
da
exotic canopy
$\lim_{x\to \infty} \left(1+\frac{7}{2x^2 - 4}\right)^{3x}$
ocean sealBOT
artemetra
chrome tiger
Понадобится правило Лопиталя, не?
scenic umbra
метод логарифмирования скорее
chrome tiger
**artemetra**
Просто вот этот приём полезен, если предел сводится ко второму замечательному
Но это не наш случай
exotic canopy
Понадобится правило Лопиталя, не?
тоже вариант
chrome tiger
метод логарифмирования скорее
Это понятно, просто после этого Лопиталь как раз
scenic umbra
а как это правилом Лопиталя решить?
foggy pecan
элементарный предел функции, здесь мы используем определение числа e,
exotic canopy
элементарный предел функции, здесь мы используем определение числа e,
там ведь 2x^2, а не линейный член, не?
foggy pecan
там ведь 2x^2, а не линейный член, не?
с этим нет проблем
$\text{например:}\\\lim_{x \to \infty } \left( \frac{x^{2}+5}{x^{2}+2} \right)^{5x}=\left[ 1^{\infty } \right]=\\=\lim_{x \to \infty }\left[ \left( 1+\frac{1}{\frac{x^{2}+2}{3}} \right)^{\frac{x^{2}+2}{3}} \right]^{\frac{3}{x^{2}+2}5x}=e^{0}=1$
chrome tiger
элементарный предел функции, здесь мы используем определение числа e,
Не соглашусь, ведь в определении числа е берётся предел $\lim_{x \rightarrow \infty} (1 + \frac{1}{x})^x$, а здесь вместо $\frac{1}{x}$, по сути, $\frac{7}{x^2}$, и история другая
ocean sealBOT
Joanna Angel
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
EQUENOS
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)
foggy pecan
Не соглашусь, ведь в определении числа е берётся предел $\lim_{x \rightarrow \in...
прочитай мой пример
chrome tiger
прочитай мой пример
а, ну так вроде прокатывает
foggy pecan
этот факт также верен, например:
$\lim_{x \to \infty } \left( 1+\frac{1}{x^{2}} \right)^{x^{2}}=e$
ocean sealBOT
Joanna Angel
chrome tiger
это я знаю
foggy pecan
ok)
remote escarp
Не соглашусь, ведь в определении числа е берётся предел $\lim_{x \rightarrow \in...
вместо х может быть просто бесконечно большая функция
chrome tiger
Это не меняет сути
remote escarp
и (2x^2-4)/7 бесконечно большая, так что все верно
chrome tiger
Мне кажется вы неправильно меня поняли
Я не спорю, что если f(x) -> inf при x -> inf, то lim (1 + 1/f(x))^f(x) = e
Я лишь хотел сказать, что если lim x/f(x) = 0, то lim (1 + 1/f(x))^x = 1
Точнее, намекнуть на это
remote escarp
аа, поняла)
lone heartBOT
@scenic umbra Has your question been resolved?
past gull
lone heartBOT
ocean sealBOT
alpine sable
are you doing. 35. Or 36.
past gull
35
alpine sable
Oh
Take the cross-section of the sphere/cone
And you have a triangle in a circle
Then u add another triangle to that shape to find the diameter
Ill need to draw a diagram rq
alpine sable
Like that
u can work out the heights of the triangles separately then add them together to get the diameter
its like ((root3/3) + root5)r
i think
wait not root 5 mb, its root 3
lone heartBOT
@past gull Has your question been resolved?
alpine sable
@past gull figured it out yet?
lone heartBOT
@past gull Has your question been resolved?
lone heartBOT
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
past gull
its like ((root3/3) + root5)r
how is this the height
it's a cylinder bro
not a pyramid
@alpine sable
i mean cone
lone heartBOT
@past gull Has your question been resolved?
glass finch
Hi guys, could you please help me solve these two exponential equations?
grizzled gulch
Start by taking common factor
exotic canopy
$(\sqrt[5]{3})^x = (3^{\frac{1}{5}})^x = 3^{\frac{x}{5}}$
ocean sealBOT
artemetra
exotic canopy
frankly, i don't see any other one ahah
exotic canopy
pretty certain this is 5th root
grizzled gulch
Okee
exotic canopy
Hi guys, could you please help me solve these two exponential equations?
is it $\sqrt[5]{x}$ or $5\sqrt{x}$
ocean sealBOT
artemetra
glass finch
pretty certain this is 5th root
Yeah its 5th root
exotic canopy
👍
glass finch
**artemetra**
First one
grizzled gulch
Yeah
glass finch
Like this?
exotic canopy
yep
grizzled gulch
Yesss
exotic canopy
now factor
glass finch
Sorry, I have no idea what to do next
lone heartBOT
@glass finch Has your question been resolved?
glass finch
.close
hushed ether
lone heartBOT
hushed ether
i cant let P(t) =0 right?
dusky grotto
can anyone help me ?
hushed ether
can anyone help me ?
use other available channel
dusky grotto
okay
hushed ether
so it would never land
narrow kelp
yes
hushed ether
alright wat a dum question
narrow kelp
you could do algebra and eventually end up with ln(0)
lethal dock
lone heartBOT
lone heartBOT
@lethal dock Has your question been resolved?
alpine sable
lone heartBOT
alpine sable
How do I calculate that without a calculator
raw stream
Ok
golden canyon
You don't have to calculate 4x * sqrt(3), try expanding the rest as well
alpine sable
Wait what
raw stream
yes
raw stream
i just give you the identity
when you have two numbers a and b in form of
(a+b)(a-b) it is equal to a^2-b^2 which is (a square - b square), you can try proving this after the doubt just multiply (a+b)(a-b) and see what u get...
@alpine sable
frigid mirage
(4x)^2, not 4x^2
alpine sable
Why
frigid mirage
if you look at the formula a^2 - b^2 = ...
your variable a here is 4x
not just x
therefore the whole thing(4x) should be squared
frigid mirage
expand the square and I think you should be done
alpine sable
expand the square and I think you should be done
How do I do that without a calc 😭
raw stream
How do I do that without a calc 😭
what
frigid mirage
How do I do that without a calc 😭
wdym
alpine sable
Calculator
frigid mirage
$(\sqrt{3})^2 = 3$
ocean sealBOT
nebula40
frigid mirage
does this make sense
alpine sable
What how
raw stream
$(\sqrt{n})^2 = n$
ocean sealBOT
Spacephoenix
raw stream
**nebula40**
I won't suggest giving direct answers
frigid mirage
I won't suggest giving direct answers
I couldn't think of a way of hinting towards that lol. anw I'll let you explain the rest
alpine sable
So whenever is number is sqrt by 2 it stays the same? 😭
raw stream
$(n^1/2)^2 = n^((1/2)*2)$
ocean sealBOT
Spacephoenix
raw stream
**Spacephoenix**
this is wrong
frigid mirage
So whenever is number is sqrt by 2 it stays the same? 😭
you should probably go and revise about what "square root" of a number actually means
raw stream
So whenever is number is sqrt by 2 it stays the same? 😭
squaring a square root of a number gives the same number
alpine sable
Oh wait no power of
raw stream
you should probably go and revise about what "square root" of a number actually ...
yes
raw stream
**nebula40**
or this?
alpine sable
Yeah I understand it now
frigid mirage
use {}
ocean sealBOT
Spacephoenix
raw stream
yes!
raw stream
Omgggg thanks
well the answer isn't imp
alpine sable
Oh
raw stream
okay you could try proving it
alpine sable
Uhhhh
frigid mirage
@raw stream for reference you can do fractions like this $\frac{a}{b}$
ocean sealBOT
nebula40
raw stream
<@886846638730129509> for reference you can do fractions like this $\frac{a}{b}$
thank you
one more task..
prove this $(\sqrt{n})^2 = n$
ocean sealBOT
Spacephoenix
raw stream
Can I use an example to prove it lol
you need to multiply (a+b)(a-b)
you should be able to do this
you must understand this before you proceed to solve other q
raw stream
**Spacephoenix**
or do this atleast
raw stream
Nicely done but do the first proof again using laws of exponents
you can't take any example
alpine sable
you can't take any example
Ok idk how if prove it😭😭😭😭
what does sqrt(n) can be written as
raw stream
Ok idk how if prove it😭😭😭😭
ok you know exponents?
alpine sable
using exponents
alpine sable
ok you know exponents?
No
raw stream
how else can you write this $(\sqrt{n})$
ocean sealBOT
Spacephoenix
alpine sable
using exponents
N^0,5?
write 0,5 as a fraction
1/2
Wait
So
yes
but we are trying to prove n² is equal to it
so what do we add
so far we have n^1/2
alpine sable
so what do we add
Times two?
no
n^2 is not equal to n * 2 is it?
Yes
,align
\s[m]{x^n} &= x^{\ff nm}\
x^n \cd x^m &= x^{n+m}
ocean sealBOT
alpine sable
use the above two facts
alpine sable
still wrong
alpine sable
you are trying to say [
\p{x^{\ff1m}}^n = x^{\ff nm}
]
ocean sealBOT
alpine sable
but yes you could use that as well
raw stream
This is what they need to use
alpine sable
@alpine sable pinging you again in case you went away
No I’m here
you know that $\s x = x^{\ff12}$ yes?
ocean sealBOT
alpine sable
Yeah
ocean sealBOT
Spacephoenix
alpine sable
so evaluate $\ds \p{x^{\ff12}}^2$
ocean sealBOT
alpine sable
r u familiar with exponent laws at all Elle
No 😭
then I guess skip this until it comes your way or something. hard to explain something over text
My teacher gacebr gone through it but I’m trying to write this all down run
But it’s in the mock exam
oh
ok then uh
wait
I’ll just remember the formula
skim thru the topics here they talk about exponent laws
and a bunch of other stuff that will be helpful for you
That’s eighth grade? Gosh I’m behind
how old are u lol
Okay thanks I’ll watch them
15
what's the grade for that 
9th.. I should’ve learned that last year
it's alright youll catch up. anyways study from khan academy it's MASSIVELY helpful.
raw stream
9th.. I should’ve learned that last year
and u were busy doing tik tok? insta?
alpine sable
and u were busy doing tik tok? insta?
No I swear I have all As it’s just the dumb education system it brainwashed my Asian genes
And how to am I supposed to do this
divide
like straight up dividing
But I only learnt how to divide with like one number not those big numbers
I just get calculators for that
raw stream
whaaat
alpine sable
you should probably learn how to do that still then
alpine sable
What
alpine sable
How
raw stream
idk abacus?
alpine sable
How teach me
raw stream
II was taught abacus
alpine sable
What’s that
raw stream
How teach me
took me 4 yrs
alpine sable
Oh
raw stream
you could do long division
raw stream
I just get calculators for that
you guys get calculators fr?
alpine sable
you guys get calculators fr?
Yes in every test
alpine sable
read thru this then
also just wanna say you may want to change the undergraduate in your roles to Pre-University, so ppl would know what level you are at to better help you
alpine sable
also just wanna say you may want to change the undergraduate in your roles to Pr...
Ohhhh that’s why sorry I thought it meant something else
Thanks I’ll work on this 😭
.close
stable merlin
Why is:
$\frac{1-\sqrt{3}}{3-\sqrt{3}}=-\frac{1}{\sqrt{3}}$
lone heartBOT
Why is:
$\frac{1-\sqrt{3}}{3-\sqrt{3}}=-\frac{1}{\sqrt{3}}$
zealous ingot
add a dollar sign at the end
alpine sable
$ at the end
ocean sealBOT
garodueng
alpine sable
multiply by conjugate
stable merlin
$\frac{(1-\sqrt{3})(3+\sqrt{3})}{(3-\sqrt{3})(3+\sqrt{3})}=-\frac{3-3}{9-3}$
ocean sealBOT
garodueng
alpine sable
i got -sqrt(3)/3
stable merlin
i got -sqrt(3)/3
how
alpine sable
no
alpine sable
definitely not
alpine sable
you welcome
stable merlin
.close
lone heartBOT
lone heartBOT
Available help channel!
gritty stone
Please assist me with the meaning of this derivative notations. Is it written incorrectly?
tight locust
yeah that looks weird
i don't like it either
also makes no sense because lambda is not even present
lone heartBOT
@gritty stone Has your question been resolved?
vale crag
that notation looks a lot like elasticity in economics
relative change in demand / relative change in price in the wiki article
relative change in R0 / relative change in lambda for your first example
as they say in the wiki article, when you have derivatives, you have to interpret $\frac{\frac{\partial{R_0}}{R_0}}{\frac{\partial{\lambda}}{\lambda}}$ as $\frac{\pdv{R_0}{\lambda}}{\frac{R_0}{\lambda}}$
ocean sealBOT
aPlatypus
vale crag
@gritty stone
misty salmon
Can anyone help in this prob
lone heartBOT
Can anyone help in this prob
limpid turret
,rotate
ocean sealBOT
limpid turret
Can anyone help in this prob
What's the question?
misty salmon
I'm translating it in english
We have ABCD is a trapezoid
Such that ab || cd
Ab > cd
K and L are poits that lie on ab and cd respectively
Such that ak/kb = dl/lc
Suppose that P and Q are points on LK such that <apb=<bcd
And <cqd=<abc
Prove that P , Q , B , and C loe on the same circle
That's it
west girder
How would you construct L given K?
misty salmon
I did it AK/KB =1/3
west girder
Yeah but ruler and compass
lone heartBOT
@misty salmon Has your question been resolved?
lone heartBOT
@misty salmon Has your question been resolved?
misty salmon
Yeah but ruler and compass
Ohh so u mean my drawing is wrong ?
lone heartBOT
@misty salmon Has your question been resolved?
west girder
Ohh so u mean my drawing is wrong ?
no i dont know hwo to construct L given K, and i think if we know how it will give a lot of information
misty salmon
no i dont know hwo to construct L given K, and i think if we know how it will gi...
It is okay thanks for ur help I solved it
craggy briar
How do I solve this problem?
lone heartBOT
How do I solve this problem?
quiet karma
Can anyone help me with this question?
A marine observation station is monitoring the positions of two ships at sea. The angle between the lines of sight from the observation station to the two ships is measured and found to be 60 degrees. The distances from the observation station to the first ship and second ship are 80 km and 100 km, respectively. Using the appropriate trigonometric relationships, determine the distance between the two ships
quiet karma
i really have a bad brain so i cant visualize that
and idk what the wordsmean
this is what i draw
is it just 80 + 100?
idk how a triangle works
dry dawn
lone heartBOT
@quiet karma Has your question been resolved?
valid bluff
lone heartBOT
valid bluff
so
i solved it
on my second try
but my first try was interesting
so what i did was:
so i made the denominator this
oh wait
🤣
ok i get it now
it's to the power of 2
it doesn't match with the numerator's power of 1
🤣
nvm
.close
sand ermine
lone heartBOT
inner musk
sand ermine
Hey
inner musk
hi
sand ermine
to ask a question
you put it in another channel
not in an occupied one
I alreadu asked here
inner musk
oh shoot myb
sand ermine
its ok
inner musk
i just joined and ngl, i just started using discord like yesterday so everything is mad confusing
sand ermine
its alr
sand ermine
og question
alpine sable
what did you find for $\m{f'}x$
ocean sealBOT
sand ermine
one min
sand ermine
what did you find for $\m{f'}x$
-8/x^2
ocean sealBOT
sand ermine
and what did you evaluate $\ds\f{\m fb -\m fa}{b-a}$ as
16/6
alpine sable
ok great
the mean value theorem basically states that there exists a $c$ such that [
\m{f'}c = \f{\m fb -\m fa}{b-a}
]
ocean sealBOT
alpine sable
so
alpine sable
yes
waxen turtle
lone heartBOT
waxen turtle
idk
Idk how I would ever subtration on this
so I guess addition
sin of pi + π/12
Idk
tacit arch
sin of pi + π/12
Yea try this
tacit arch
Isn't sine of pi like 0
Yes
waxen turtle
Then
waxen turtle
Cos is √3 right
waxen turtle
1/3 - 1/4 = ?
wat the
waxen turtle
Fr
tacit arch
Find a common denominator
3 and 4 don't have common divisors so their least common multiple is just their product 3 * 4
waxen turtle
I meant the fomrula
Anyways
Wait
Am I doing cos or sine I forgor
Sine right
Rn
Since the other thing is 0
tacit arch
Am I doing cos or sine I forgor
Read your problem again
tacit arch
And cosine of π is 1
No
waxen turtle
yes
tacit arch
Use it to check your answer
waxen turtle
okk
waxen turtle
Use it to check your answer
It's wrong😔
raw stream
??
raw stream
I just gave you the values
raw stream
it is
waxen turtle
no
raw stream
bruh how
waxen turtle
it's irrational
raw stream
it's irrational
bruh
raw stream
holy f.....
waxen turtle
what
waxen turtle
No it's not
raw stream
root6 = root3 x root2
raw stream
No it's not
it is
waxen turtle
It doesn't matter what it is anyway
raw stream
you don't
raw stream
need rest of the values
waxen turtle
@tacit arch
raw stream
<@261933205387477002>
how old are you
waxen turtle
sus
raw stream
Your calculator is in the wrong mode. Find radians
why radians
tacit arch
You messed up before this first step
waxen turtle
How is it √2-√6 over 4
tacit arch
,tex .sum diff trig
ocean sealBOT
riemann
waxen turtle
That's what I did
tacit arch
You messed up before this first step
Oh no you didn't
waxen turtle
Oh no you didn't
wat did I do wrong
tacit arch
wat did I do wrong
Your second step
real panther
Q53?
real panther
No
lone heartBOT
lone heartBOT
Available help channel!
shrewd mirage
https://www.desmos.com/calculator/eav9ba8o5d can someone uh point out my mistake please
shrewd mirage
<@&286206848099549185>
mellow grail
but whats uh wrong w the uhm thing
Its stupid
shrewd mirage
LMAO
misty salmon
.close
shrewd mirage
Its stupid
yeah i noticed all the mistakes in a second ☠️ ☠️ mb
lone heartBOT
Available help channel!
carmine garnet
Centimeter to Kilometer = x10^-5
1.25 x10^-5
=0.0000125 Km
How do I make the number shorter? I don't know how my sister turned it into 1250 km
shrewd mirage
Centimeter to Kilometer = x10^-5
1.25 x10^-5
=0.0000125 Km
How do I make the...
i think ur sisters on crack
lone heartBOT
@carmine garnet Has your question been resolved?
carmine garnet
<@868734529161007165> Has your question been resolved?
No..Im still waiting for help
carmine garnet
i think ur sisters on crack
You know how to do it? 
Centimeter to Kilometer = x10^-5
1.25 (cm) x10^-5
=0.0000125 Km
How do I make the number shorter? I don't know how my sister turned it into 1250 km
golden canyon
You can write it in scientific notation as $1.25 \cdot 10^{-5}$
ocean sealBOT
Jelle
carmine garnet
You can write it in scientific notation as $1.25 \cdot 10^{-5}$
I have no Idea what you mean, I need a simple answer
Maybe I dont even understand simple things.
golden canyon
$1.25 \times 10^{-5}$
ocean sealBOT
Jelle
golden canyon
this is the same, I used a different symbol for multiplication in the one before
Yes, but writing it like this is called scientific notation
it's usually preferred over numbers with a lot of decimals
carmine garnet
Oh
golden canyon
If you have never heard of this though, you will probably have to write it as 0.0000125
golden canyon
No, because 0.125 doesn't equal 0.0000125
golden canyon
👍 You can type .close if you are done btw
vale moth
hello
vale moth
can u guys help me with this equation?
exotic canopy
what equation?
vale moth
exotic canopy
oh
exotic canopy
where's x?
vale wigeon
this is poorly written
exotic canopy
i just see sigma
vale wigeon
to a fault
vale moth
wait i forgot to add x to -2
vale wigeon
!original
lone heartBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
exotic canopy
what is the thing right before dx? |sigma|?
exotic canopy
well $\sqrt{2\pi}|\sigma|$ is a constant so take it out
ocean sealBOT
artemetra
vale moth
ok now i get it
exotic canopy
what is the $\land$-like symbol?
ocean sealBOT
artemetra
vale moth
raised to
vale moth
oh okay
exotic canopy
do you know how to integrate $e^{ax}$
ocean sealBOT
artemetra
exotic canopy
for any a?
vale wigeon
so you're asking to find $\int_{-\infty}^{+\infty} \sqrt{2\pi} |\sigma| e^{-\frac{2x}{2\sigma^2}} \dd{x}$?
ocean sealBOT
Ann
exotic canopy
or just make a u sub
vale wigeon
are you 110% sure you did not fuck up your integral again?
vale moth
if i sub it take for let I = $\int_{-\infty}^{+\infty} e^{-\frac{2x}{2\sigma^2}} \dd{x}$?
ocean sealBOT
Zakuhashi
ocean sealBOT
artemetra
vale moth
ohh
exotic canopy
and just do that
vale moth
okay okay
exotic canopy
do you know how to integrate $e^{ax}$
this applies
vale wigeon
$\int_{-\infty}^{+\infty} \sqrt{2\pi} |\sigma| e^{-\frac{2x}{2\sigma^2}} \dd{x}$ diverges
ocean sealBOT
Ann
exotic canopy
yeah lol
lone heartBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
vale moth
okay thank you guys, I’m still familiarizing integrals at this rate.
vale wigeon
where did this problem come from?
did you just make up this integral on the spot?
or were you doing some kind of homework assignment or maybe self study
vale moth
where did this problem come from?
remember that one equation on the scene in the move The Gifted?
vale wigeon
i have not seen that movie
so no
you're going to have to bring me into the loop on that
@vale moth
vale wigeon
OK RIGHT HERES THE THING
exotic canopy
YEP
vale wigeon
heres the thing
this sort of shit
is EXACTLY why we ALWAYS ask for the ORIGINAL problem
we can tell if you fuck up a problem statement and we can tell if a problem looks strange
like ok you dont know much about calculus thats fine
exotic canopy
we don't fuck around with the gaussian integral 🙅🙅🙅
vale wigeon
but poor communication will make it impossible for people who DO know calculus to help you
exotic canopy
we don't fuck around with the gaussian integral 🙅🙅🙅
but generally for this kind of thing google gaussian integral derivation, the proof is very much not short
vale wigeon
yeah and if you are unfamiliar with integrals generally it will be super hard to understand
if not outright impossible
vale moth
I really do want to study calculus
vale wigeon
ok sure
but this is NOT the place to start from
would you tell someone who wants to get into alpinism to climb mt fucking everest as their first practice??
vale moth
no
vale wigeon
yeah exactly.
so go on something like khanacademy instead and learn calculus properly
and also all the fundamentals before it
if you dont know algebra you will suffer endlessly in calc
vale moth
good thing my knowledge in algebra is still functioning 😅
vale moth
so go on something like khanacademy instead and learn calculus _properly_
okay, thank you
lone heartBOT
@vale moth Has your question been resolved?
loud linden
open
loud linden
algebra, if A is nxn and r(A) = n -> r(A^2) = n
my attempt: if r(A) = n it means A is invertible thus AA also invertible since multiplication of two invertible matrixes produces invertible matrixes(alredy proven) thus AA is nxn matrix and thus its invertible iff r(A*A) = n.
is my proof fine
limpid turret
algebra, if A is nxn and r(A) = n -> r(A^2) = n
my attempt: if r(A) = n it means...
What is r(A)?
lone heartBOT
@loud linden Has your question been resolved?
mortal trellis
yes its fine
formal ginkgo
aren't we supposed to change the first term to 2 when changing n by n+1 ???
lone heartBOT
@formal ginkgo Has your question been resolved?
formal ginkgo
why should we
replace n with 1 and it'll give you 2
so the first term will be 2 not 1
mortal trellis
thats not how the n appears in the formula
we are adding until n^3
so then in the induction step we are adding one more number
lone heartBOT
@formal ginkgo Has your question been resolved?
rare grotto
how do we solve this? ; this is striaght lines chapter of junior high...
rare grotto
what does it mean when a bisector "contains " a point?
not understanding that part..
I am able to find 2 bisectors , but what should it "contain" exactly?
lethal belfry
what does it mean when a bisector "contains " a point?
the line passes via that point
I think
frigid mirage
none of the options passes through -1,4
maybe it's to specify which angle they want the bisector for?
since there would be two angles between those lines
tight locust
-1/4
rare grotto
maybe it's to specify which angle they want the bisector for?
wdym?
they want one of the two bisectors , but I dont get what it means to "contain" that point..
vale wigeon
do you get how a line can contain a point
frigid mirage
I think they want the bisector for this angle
rare grotto
do you get how a line can contain a point
I know it has something to do with inequality..., maybe the line when x and y =(-1,4) should be greater than 0?
not sure
but that doesnt make sense..
rare grotto
I think they want the bisector for this angle
how does that suggest , the bisector containing the point , in any waytho?
I found both the bisectors...
-21x-27y+121=0
99x-77y=191=0
frigid mirage
how does that suggest , the bisector containing the point , in any waytho?
the wording can also suggest that "the angle .... which contains the point"
which is itself kinda weird but makes more sense than the line itself containing the point (since none of them do that here)
storm ridge
I found both the bisectors...
Now you've to find the bisector which contains that point
rare grotto
Now you've to find the bisector which contains that point
just that I dont understand what 'contain' means exactly
rare grotto
none of the options pass through -1,4...
storm ridge
For example the line x=y+1 contains the point 0,-1
rare grotto
I dont think thats what they mean ...
frigid mirage
I'll try to rephrase what I was saying before
each of the four angles in between those 2 lines can be thought of as dividing the coordinate plane into 4 regions
I think they want you to find the bisector of the angle whose region (-1, 4) lies in
frigid mirage
I think they want the bisector for this angle
which is the red angle here
and so your 1st equation should be the answer
rare grotto
frigid mirage
I can't remember seeing any questions where people mention "angles containing points" so maybe my interpretation could be faulty
lone heartBOT
@rare grotto Has your question been resolved?
winter gate
how do you do MSE for multivariate functions?
lone heartBOT
how do you do MSE for multivariate functions?
@winter gate Has your question been resolved?
lone heartBOT
@winter gate Has your question been resolved?
alpine sable
isn't possible. This server isn't meant for that
we can only help you with solving questions not cheating them off
.close please If you have no actual questions
lone heartBOT
@grizzled bough Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
dire gale
How is 29 is solved?
lone heartBOT
How is 29 is solved?
storm ridge
How is 29 is solved?
!status
lone heartBOT
How is 29 is solved?
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above