#help-0

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lone heartBOT
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tawdry flicker
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I got 1/12 for the slope

lone heartBOT
worn fox
#

!show

lone heartBOT
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Show your work, and if possible, explain where you are stuck.

alpine sable
#

You forgot to multiply by the internal derivative probably

tawdry flicker
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I differentiated x and y and got 1/12/1

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OH

alpine sable
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Yup

tawdry flicker
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multiply by 2

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Thabks

alpine sable
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This oh moment

tawdry flicker
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.close

lone heartBOT
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tawdry flicker
#

This one i got 4

lone heartBOT
tawdry flicker
#

Idk what its asking for

shell coral
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i need help

neat mango
# shell coral i need help

Sorry, this channel is currently occupied. If you'd like help on a question, please use an available channel

tawdry flicker
#

you can use it now

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.close

lone heartBOT
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tawdry flicker
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:(

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.close

lone heartBOT
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teal herald
#

okay I feel like im doubting myself now for h'(t) i got -16t + 79

teal herald
#

i split it to a power function and linear function

jagged cobalt
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-16t^2 doesnt go to -16t

teal herald
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using power function rule no?

jagged cobalt
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x^n -> nx^(n-1)

teal herald
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move 2-1 is 1

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1t^1 is t

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oh wait

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2t

jagged cobalt
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you dont multiply by the new power

teal herald
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mb

jagged cobalt
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yeah so you have -16(2t)=-32t

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then just the +79 as before

teal herald
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yeah

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i see now

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good catch

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thankyou.

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.close

lone heartBOT
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teal herald
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coming back to this

lone heartBOT
teal herald
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my question is

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what does solving f acutally do

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h`(t) = -32t + 79

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when u solve for 0

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you get 2.47

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what does this represent

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this is a more curious question than acutal help

median oar
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What f

teal herald
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i guess

median oar
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Ah h

teal herald
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part f

median oar
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Well consider some function f(x)

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What is the significance of f’(x) = 0

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(You should’ve covered this at the beginning of calculus)

teal herald
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well if prime doesnt mean anything than that just means x outputs 0

median oar
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Prime means the derivative of f

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With respect to x

teal herald
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i think i am overcomplicatiing it but its just an output no?

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i know that acutally subbing x for a value gives the irc at a point

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instantanious rate of change

median oar
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Anything about critical values?

teal herald
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mmm no

median oar
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For continuous functions f

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f’(x) = 0 solves for local maxima/minimas

teal herald
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ohh okay so that gives the min value that I can plug in and get output?

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that makes sense

median oar
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In terms of your question it solves for the min/max height

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You don’t know if it’s min or max

teal herald
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u know what now that im looking at my paper

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that makes sense

median oar
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You need the 2nd derivative to check concavity to know if it’s a local min or max or neither

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Consider f(x) = x³

teal herald
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i just realized that it acutally matches perfectly with the max that i found in step e

median oar
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f’(x) = 0 is solved by x=0

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But that’s neither a local min or max

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Because f’’(0) is neither positive nor negative

teal herald
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interesting, yeah this is the first im hearing of this concept

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maybe which he thought we would see the values and make a correlation ourselves

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which i didnt

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lmfao

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super cool thankyou for explaining

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.closer

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.close

lone heartBOT
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smoky moss
lone heartBOT
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Please don't occupy multiple help channels.

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@smoky moss Has your question been resolved?

lone heartBOT
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@smoky moss Has your question been resolved?

lone heartBOT
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severe stone
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How would I go about solving this problem. Its from a test I had earlier today and I know I got it wrong

lone heartBOT
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@severe stone Has your question been resolved?

lone heartBOT
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@severe stone Has your question been resolved?

tacit arch
#

Multiply top and bottom bot cosx +1

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honest sundial
#

can anybody tell me how it work

lone heartBOT
honest sundial
#

how that numbers translate into sin/cos

lone heartBOT
#

@honest sundial Has your question been resolved?

honest sundial
#

its solve as 6sin(a)*cos(a)+4(cos^2(a)-sin^2(a) = 5(cos^2(a)+sin^2(a)

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9tg^2(a)-6tg(a)=-1 by a=x/2

honest sundial
lone heartBOT
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@honest sundial Has your question been resolved?

lone heartBOT
#

@honest sundial Has your question been resolved?

limber oasis
#

i dont understand this

ancient saddle
#

So you can write those terms as a single sine and solve the equation

honest sundial
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fcgvbh m ,v

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hellow

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its is not wat i request

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sin(x+p) - is solve but how to sin and cos p

ancient saddle
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?

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Yeah that's what I was beginning to explain

ancient saddle
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Also you can see it's not possible yet because 3 and 4 are greater than 1, which is out of the range of sin and cos

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A strategy is diving both sides of the equation by some number k

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So
Asinx/k + Bcosx/k = .../k
Now,.you want
(A/k)²+(B/k)² = 1
Solve for k and you get
k=√(A²+B²)

ancient saddle
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cosø = A/√(A²+B²)
ø = arccos(A/√(A²+B²))

honest sundial
#

пиздец

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solved

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.close

lone heartBOT
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lone heartBOT
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alpine sable
#

<@&286206848099549185>

lone heartBOT
alpine sable
#

cant make the other sides

wheat isle
lone heartBOT
# alpine sable <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

alpine sable
ionic jewel
alpine sable
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im tryna make 4 shapes

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quadrilaterals

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so basically

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i need to put each quadrilateral

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in this graph

iron hull
lone heartBOT
# alpine sable <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

iron hull
#

can u not ignore everything he just said

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and respect the rules

lone heartBOT
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@alpine sable Has your question been resolved?

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twin thunder
#

i dont understand the teachers procedure

twin thunder
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help

vale wigeon
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your teacher first chooses 3 people to drive the cars

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there are 5 drivers available and 3 cars to put them in, and it matters who goes where, thus 5P3 ways

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do you understand? Y/N

twin thunder
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what about the 9

vale wigeon
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9 is the number of ways to pick who goes in the small car as a passenger

twin thunder
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hm

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why arent 8c4 and 4c4 permutations? only the drivers' arrangements matter?

vale wigeon
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so it appears, yes.

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it matters who goes in what car but not the arrangement of passengers within each car

lone heartBOT
#

@twin thunder Has your question been resolved?

lone heartBOT
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merry meteor
lone heartBOT
merry meteor
#

just a question
i thought if one isnt a multiple of another
then its L.I
why isnt this L.I?

worn fox
#

That's only true for a list 2 vectors

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Look at the definition of linear independence

merry meteor
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and we see a multiple

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then we no its not L.I

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but if we dont

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we still have to test?

worn fox
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That is true yes

merry meteor
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alr makes sense

merry meteor
#

technically this is 2 vectors?

worn fox
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Well no technically it is not

merry meteor
#

is x2 free variable?

worn fox
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Go to the definition of dependence

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Can you add them up with non-zero coefficients to get 0

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The presence of the zero vector is important

merry meteor
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by soving thru system of equation

worn fox
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Okay fine then solve the system

merry meteor
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i just get

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c1 = 0

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c2 = 0

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c1 + c3 = 0
2c1+4c3=0
c1+3c3=0

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c1 = -c3
c1 = -2c3

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this isnt evne possible

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wtf am i doing wrong here

worn fox
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Is what even possible

merry meteor
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c1 = -c3 from first eqn

worn fox
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C1 and c3 are 0

merry meteor
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that means L.I

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oh wait but the 0 vector can be

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any scalar

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making it not L.I

worn fox
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Yeah thats the point

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And didn't really need a whole system set up

merry meteor
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ah i get it

worn fox
#

Take any multiple of the 0 vector and 0 multiples of the other 2

lone heartBOT
#

@merry meteor Has your question been resolved?

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undone plover
lone heartBOT
undone plover
#

i dont know how to solve this?

coral thorn
#

do you know what a power function is?

undone plover
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no

coral thorn
#

can you write the given function in the form $y = kx^{p}$?

ocean sealBOT
coral thorn
# undone plover no

A power function is a function with a single term that is the product of a real number, a coefficient, and a variable raised to a fixed real number.

undone plover
#

ummm

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okay

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sorry can you break that in baby language

coral thorn
#

how would you expand $(4x^{5})^{2}$ ?

ocean sealBOT
undone plover
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like 4x^10?

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is that what you mean?

coral thorn
undone plover
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i feel like im doing the opposite

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im shrinking it when i wanna expand it

coral thorn
ocean sealBOT
coral thorn
undone plover
#

16

coral thorn
#

whats $(x^{5})^{2}$

ocean sealBOT
undone plover
#

okay okay ima sound dumb cause its either x^10 or x^25

coral thorn
#

the former

undone plover
#

ima go with the latter

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aight cool

coral thorn
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its x^10

undone plover
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bro im stupidddddd

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yea

coral thorn
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now

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put those two together

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what do you get?

undone plover
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4x^10

coral thorn
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4?

coral thorn
undone plover
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ohhhh

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cause it outside

coral thorn
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whats outside?

undone plover
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the ^2

coral thorn
undone plover
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so its 16x^10

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dope

coral thorn
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can you identify k, x, and p?

undone plover
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yea

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so k is 16

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and p is 10

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and uhh is x.... x?

coral thorn
#

so is it a power function?

coral thorn
undone plover
#

yea

coral thorn
#

thats it

undone plover
#

tysm!

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uhhh how i close this?

coral thorn
#

.close

undone plover
#

.close

lone heartBOT
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cosmic spruce
lone heartBOT
cosmic spruce
#

Idk how part b is proven

#

I alr diffed it then subbed x=3 then I got this

vague coral
#

did you differentiate a ?

gloomy grove
cosmic spruce
vague coral
#

$2n (1+x)^{2n-1} = \sum_{k=1}^{2n} k \binom{2n}{k} x^{k-1}$

ocean sealBOT
#

Herels

cosmic spruce
#

That’s what I got

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I subbed in x=3

vague coral
#

take x =1

gloomy grove
#

yes

cosmic spruce
#

Ok

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How do I get rid of the x^k-1

vague coral
#

1^anything = 1 bro

cosmic spruce
#

Oh yeah

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Bruh I forgot to sub 1 into that

lone heartBOT
#

@cosmic spruce Has your question been resolved?

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alpine sable
lone heartBOT
alpine sable
#

Sorry someone else took the previous channel I sent this on

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

zealous lichen
#

use the fact that they are not parallel

alpine sable
zealous lichen
#

ok

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we can do this another way

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assume lambda and mu are not 0

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try to show that the vectors are parallel

alpine sable
zealous lichen
#

oh I forgot the case where only one of them is 0

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you need to prove that too

alpine sable
zealous lichen
#

u equals v times some constant

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that's the definition of parallel vectors

alpine sable
#

Ohhh ok

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So they are parallel?

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But that contradicts the question

zealous lichen
#

if lambda and mu are not both 0 then u and v are parallel

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it's the same as saying if u and v are non-parallel then lambda and mu are both 0

alpine sable
#

Ohhhh

alpine sable
zealous lichen
#

we need to consider all cases where lambda and mu are not both 0

alpine sable
#

How did you know to do this though?

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I didn’t think of this

zealous lichen
#

oh it's a pretty common proof technique

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if you want to prove that P implies Q, it's the same as proving not Q implies not P

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you might want to learn some basic mathematical logic

alpine sable
#

Oh ok

#

Thank you

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
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lone heartBOT
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obtuse spindle
#
       [3 2 1]

and B = [2 3]
        [1 4]
        [2 1]
then find rank of matrix AB```


AB i found is  [ 11  25 ]
                          [ 10  18 ]

i am trying to find the rank of matrix using method of highest order square submatrix with non-zero determinants and the order of this matrix is 2x2 and the determinant is -52 so why isn't the rank 2?
median oar
#

,w rank((11,25);(10,18))

median oar
#

Looks 2 to me

obtuse spindle
#

wait so chatgpt was wrong

round geyser
median oar
#

Chatgpt is not great at maths

obtuse spindle
#

fr

median oar
#

It’s very confidently wrong

limpid spade
#

It can't even do 1+1

obtuse spindle
muted hornet
#

be careful monkaT

median oar
#

So if you don’t know the content well you won’t be able to distinguish if it’s confidently correct or confidently wrong

obtuse spindle
#

right

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wait a min

median oar
#

Which actually makes chatgpt is very very bad tool for learning maths

glacial patrol
#

most often very incorrect and not hard to find devastation

median oar
#

Because you can’t even tell if it’s right or wrong

obtuse spindle
median oar
#

Show it

obtuse spindle
#

alr 1 min

median oar
#

,w rank(((1,5,2);(3,2,1))*((2,3);(1,4);(2,1)))

median oar
#

Nope

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Looks like 2 to me

obtuse spindle
#

oo wait a min so the answer in the book is wrong too

median oar
#

Yep

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Maybe they used chatgpt

obtuse spindle
#

lmaooo

#

anyways ty

#

.close

lone heartBOT
#
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cinder sundial
#

given a random experiment has 2 random variables X and Y, and adding these two variables up can obtain new random variable called X+Y.

Then by the "definition," E(X+Y)=E(X)+E(Y)

cinder sundial
#

Above is a line written on my math book.

lone heartBOT
#

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

cinder sundial
#

could you delete your message and open an new channel

cinder sundial
median oar
#

Lol

#

Keep going

cinder sundial
median oar
#

Are we looking at continuous or discrete RVs?

tardy stag
#

if you roll two dice would you not expect to get twice as much on average as if you rolled one?

cinder sundial
median oar
#

Do you know the definition of expectation of discrete RVs

cinder sundial
cinder sundial
median oar
#

Great

#

$\mathbb E[X] = \sum_{i\geq 1}x_ip_i$

ocean sealBOT
#

Frosst

median oar
#

Yes?

cinder sundial
#

yes

median oar
#

Ok

#

$\mathbb E[X+Y] = \sum_{i\geq 1}(x+y)_ip_i$

ocean sealBOT
#

Frosst

median oar
#

Yes?

cinder sundial
#

what does (x+y) stands for?

median oar
#

Well X and Y are functions

#

So the addition of functions is not the same as adding their values at particular points (we need to define this)

cinder sundial
#

lets say someone flip a coin two times and X,Y is the expected head and tail respectively

median oar
#

No no let’s not do that

cinder sundial
#

then what does (X+Y) stands for?

median oar
#

Well

#

There’s your problem

#

What is X?

#

X is a function from the sample space to the reals

#

$X:\Omega \to \mathbb R$

ocean sealBOT
#

Frosst

median oar
#

Your sample space has {heads, tails}

#

How do you want to define X?

cinder sundial
#

X = 2 head in 2 flips

median oar
#

No

cinder sundial
#

Y = 2 tails in 2 flips

median oar
#

You have {heads, tails}

#

This is your domain set

#

And you have ℝ

#

This is your target set

cinder sundial
#

ok

median oar
#

Tell me a mapping from your domain to your target

#

X(heads) = ?
And
X(tails) = ?

#

They need to equal numbers

#

Real numbers

cinder sundial
#

X(heads) = 2 , X(tails) = -2

median oar
#

Ok

#

Now we need to also assign to each event a probability

#

$P:\Omega \to [0,1]$ such that the total probability is 1

ocean sealBOT
#

Frosst

cinder sundial
median oar
#

What

#

You can’t put 2 heads in X

median oar
#

I need you to now tell me about P

cinder sundial
#

I suppose we flip the coin two times?

median oar
#

What is P(heads) =? And what is P(Tails) = ?

cinder sundial
median oar
#

There is 1 flip of a coin

cinder sundial
#

ok

cinder sundial
median oar
#

Ok sorry

#

Singular for both

cinder sundial
#

P(head)=1/2 and P(tali)=1/2

median oar
#

Ok

#

Now we have $\mathbb E[X] = \sum_{i=1}^2 x_ip_i$

cinder sundial
ocean sealBOT
#

Frosst

cinder sundial
#

yes

median oar
#

$\mathbb E[X] = 2\times\frac{1}{2} + (-2)\times \frac{1}{2}=0$

ocean sealBOT
#

Frosst

cinder sundial
#

what kinda of EV it is?

median oar
#

Those are multiply symbols

#

What do you mean what kind

cinder sundial
#

like EV is the expected value

cinder sundial
median oar
#

Why not

cinder sundial
#

as we dont know what it represents

median oar
#

I can be more explicit

#

$\mathbb E[X] = \sum_{x\in\Omega} X(x)\cdot P(X^{-1}({x}))$

#

Is that clearer or no

cinder sundial
#

my mind cannot comprehend the right hand side, it seems like an ancient text before jesus was born

median oar
#

Lol ok

#

Um

#

That’s not even right whoops

ocean sealBOT
#

Frosst

median oar
#

So right, there’s 2 things in omega

#

$\mathbb E[X] = X(\text{heads})\cdot P(X^{-1}({\text{heads}})) +X(\text{tails})\cdot P(X^{-1}({\text{tails}}))$

ocean sealBOT
#

Frosst

median oar
#

Ok let’s dissect this

cinder sundial
#

i cannot figure out what the X^-1 represents

median oar
#

It’s the inverse of X

cinder sundial
#

I suppose it is 1/X?

median oar
#

Um it’s a little weird looking because it’s not necessarily a function

#

It’s also why there’s a {} around the argument

#

Hmm this is still a little wrong

#

The notation is kinda annoying

#

The idea is we look at all the events

#

And we sum their (value * prob)

#

Value is defined by X

#

Prob is defined by P

cinder sundial
#

the sample space = { the head, the tail} = {2, -2}
P(2)= 1/2 = P(-2)

median oar
#

It’s not equal

#

X(heads) = 2

#

X(tails) = -2

#

P(heads) = 1/2

#

P(tails) = 1/2

cinder sundial
#

BUT P(2) = P(head with one flip), as we using 2 to represent the event of getting a head

median oar
#

$\mathbb E[X] = \sum_{x\in\Omega} X(x)\cdot P(X=X(x))$

#

This is probably easier notation

cinder sundial
#

yes

ocean sealBOT
#

Frosst

median oar
#

Man that equality sign is so fucked

#

Wait surely it’s just x

#

Ah this is so fucked

cinder sundial
median oar
#

Let’s just say $\mathbb E[X] = \sum_{x\in\Omega} X(x)\cdot P(x)$

ocean sealBOT
#

Frosst

median oar
#

This probably makes the most sense

cinder sundial
#

yes, it is the definition

median oar
#

Ok now

cinder sundial
median oar
#

No that’s X(heads) = 2

#

Now let’s say you want to add another RV say Y

#

Y has all the same properties as X

cinder sundial
median oar
#

$\mathbb E[X + Y]=$undefined

ocean sealBOT
#

Frosst

median oar
#

That’s because we don’t know what X + Y is yet

#

So we have to define this

cinder sundial
median oar
#

We can’t

#

That’s not how these are defined

cinder sundial
#

ohhh

#

i got you

#

lets E[X] be expected heads within 2 flips and E[Y]= expected tails

median oar
#

Let $\bold{X}$ be the set of all mappings from $\Omega\to\mathbb R\+_{\text{RV}}:\bold{X}\times\bold{X}\to\bold{X}$

ocean sealBOT
#

Frosst

median oar
#

And then, let $X, Y\in \bold{X}$, define $X+{\text{RV}} Y (a) = X(a) +{\mathbb R} Y(a)$

ocean sealBOT
#

Frosst

cinder sundial
#

X,Y belongs to Bold X

median oar
#

Now we can add random variables together and the result is the separate parts’s values

cinder sundial
median oar
#

Yeah bold X is all the different RV mappings

median oar
median oar
cinder sundial
#

ok, then i think bold X is just a set of diffrent events

median oar
#

Now we have $\mathbb E[X +{\text{RV}} Y] = \sum{x\in\Omega}(X(x)+_{\mathbb R}Y(x))P(x)$

ocean sealBOT
#

Frosst

median oar
#

From now on I will omit the subscript on the plus symbols it should be obvious which is which

median oar
#

To continue, $\mathbb E[X +{\text{RV}} Y] = \sum{x\in\Omega}(X(x)+{\mathbb R}Y(x))P(x)=\sum{x\in\Omega}\left[X(x)P(x) + Y(x)P(x)\right]= \sum_{x\in\Omega}\left[X(x)P(x)\right] + \sum_{y\in\Omega}\left[ Y(y)P(y)\right]$

ocean sealBOT
#

Frosst

cinder sundial
median oar
#

Naturally we then have E[X] + E[Y]

cinder sundial
median oar
#

Nope

#

Well I mean

#

It needn’t exist

#

Expectation of an RV isn’t guaranteed to exist

#

Some kinds of RV have no expectation

cinder sundial
median oar
#

Uh, Cauchy distribution

#

It’s a continuous RV

#

We define expectation with integrals from -inf to inf

#

But the Cauchy distributed RV when you try to evaluate the integral you get inf-inf = undefined

cinder sundial
#

I see

median oar
#

So then it has no expectation

cinder sundial
#

I see

median oar
#

An RV need not even have a pdf in fact

#

It needs only the CDF to exist

#

I did skip an intermediate step somewhere early on

cinder sundial
median oar
#

But explaining that will take forever

median oar
cinder sundial
median oar
#

The + in X+Y is not the same + as 3 + 5

median oar
lone heartBOT
#

@cinder sundial Has your question been resolved?

lone heartBOT
#
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karmic osprey
#

does anyone know a link or youtube video for solving this?
$$
A=\left[\begin{array}{cc}
\cos \theta & 1-2 \sin \theta \
1+2 \sin \theta & 4 \cos \theta
\end{array}\right]
$$
Find $\operatorname{det}(A)$, prove that for any value of $\theta, A$ is invertible, and then find $A^{-1}$.
(b) Find all the values of $\lambda$ such that $C=\left[\begin{array}{cc}\lambda-2 & -3 \ -5 & \lambda\end{array}\right]$ is singular.

ocean sealBOT
#

baguette

karmic osprey
#

or a similar problem

#

i just wanna figure out how to solve problems like this

worn fox
#

Which part specifically? All you really need to know is how to compute a determinant and how to invert a 2x2 matrix

karmic osprey
#

both

#

🥺

pallid scarab
#

What's the formula for the determinant of a 2×2 matrix?

karmic osprey
#

oh

#

so ur saying im just doing row operations?

latent drum
#

Coefficient of x¹¹ in (2x²+x-3)^6

worn fox
#

There is a formula for the determinant of a 2x2 matrix, look it up

karmic osprey
#

thanks

#

.close

lone heartBOT
#
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cobalt blaze
lone heartBOT
cobalt blaze
#

how do i rearrange this make "e0" the subject

#

i tried a bunch but they all feel wrong

feral raptor
#

Bro if this is what I'll have to learn in the future, I give up on my future math grades

cobalt blaze
#

same im like 4 days into class i just don't know how anymore

feral raptor
cobalt blaze
#

Gotta make the academic come back tho 😭

feral raptor
lone heartBOT
#

@cobalt blaze Has your question been resolved?

alpine sable
#

Guys can someone help me with vectors please?

peak hare
# cobalt blaze

can you multiply both sides by 4πER and then divide both sides by 4πRV

lone heartBOT
#
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alpine sable
#

is -ln(x-1) + ln(x+1) = ln(x+1/x-1)

lone heartBOT
alpine sable
#

because you could rewrite it as ln(x+1) - ln(x-1) right? then its just a log rule

#

because -4 + 2 = 2 - 4

gray isle
#

missing a few ()
need to be careful when attempting to combine logs like that

#

$$\ln(x+1) -\ln(x-1) \tbp \ln\br{\frac{x+1}{x-1}}$$
note that the domains are different. \
e.g the right side is defined when $x=-3$, whereas the left side isn't

ocean sealBOT
#

ℝam()n()v

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

hmmm

alpine sable
gray isle
#

do nothing

alpine sable
#

i dont know what i did wrong here but i see the point youre making

gray isle
#

unless you're told specific restrictions on x

alpine sable
#

it seems like its fine when x>0 then. ill keep that in mind. thanks

#

.close

lone heartBOT
#
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lone heartBOT
#
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winter tide
lone heartBOT
winter tide
#

I need Help at Question a

lone heartBOT
#

@winter tide Has your question been resolved?

winter tide
#

ig now im allowed to ping <@&286206848099549185>

#

:c

kind hare
lone heartBOT
#

@winter tide Has your question been resolved?

winter tide
#

Noo uw_ztcry

winter tide
lone heartBOT
#

@winter tide Has your question been resolved?

winter tide
#

nope :/

cobalt kindle
#

this server helps with 7 grade?

lone heartBOT
lone heartBOT
#

@winter tide Has your question been resolved?

winter tide
lone heartBOT
#

@winter tide Has your question been resolved?

limber oasis
#

i dont understand how to do 1+3p=1-3p+6p

#

and i have a test tmr

lone heartBOT
#
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nimble sequoia
#

hello chat

lone heartBOT
nimble sequoia
#

so i just need help finding the derivative of 120xsqrtx cuz google aint helping

jagged cobalt
#

$120x\sqrt{x}$?

ocean sealBOT
#

AℤØ

jagged cobalt
#

or $120\sqrt{x}$

ocean sealBOT
#

AℤØ

jagged cobalt
#

in either case the fact $\sqrt{x}=x^{\frac{1}{2}}$ will help

ocean sealBOT
#

AℤØ

nimble sequoia
#

ik it goes to 120x^(3/2) because of the exponents

#

but like

jagged cobalt
#

but...?

nimble sequoia
#

ok so my answer was sqrtx+180sqrtx but apperently thats wrong and i dont know how

jagged cobalt
#

im not sure how you did that

nimble sequoia
#

yeah me neither i think im messing up my product rule

jagged cobalt
nimble sequoia
#

oh im slow

#

you rifht

jagged cobalt
#

its just plain old power rule

nimble sequoia
#

thabk you allah

#

i forgot

lone heartBOT
#

@nimble sequoia Has your question been resolved?

#
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errant yoke
lone heartBOT
errant yoke
#

Am I correct?

#

If not how would I go forward with solving this

jagged cobalt
#

sure

#

but what are you solving?

errant yoke
#

sorry fogot to specify

upbeat onyx
# errant yoke

You flipped the root 3 and 1 but otherwise it looks good.

errant yoke
#

i am supposed to label teh side lengths

errant yoke
upbeat onyx
#

Yes.

jagged cobalt
upbeat onyx
#

You put it opposite of the 30 deg angle.

upbeat onyx
errant yoke
errant yoke
jagged cobalt
errant yoke
#

it seems to easy to be true

upbeat onyx
#

I didn't even see the pi/3, I was just going off the 30 they wrote in the angle.

jagged cobalt
#

ah

errant yoke
upbeat onyx
#

I have extremely bad vision at midnight

errant yoke
errant yoke
#

So for the top two

#

It would be this?

#

Give me a sec

#

The values cired

#

Circled

#

@jagged cobalt

upbeat onyx
#

Can we see the actual instructions at the top?

errant yoke
jagged cobalt
errant yoke
#

thats what i thought

#

but it seemed to easy to be true

upbeat onyx
#

That's a Ask your Professor type question.

#

Only your professor can tell you what they exactly wanted.

errant yoke
#

its 11:51 got a test tmrw

#

yeah should have asked

upbeat onyx
#

Maybe your teacher hates your handwriting?

#

Messed up, but I've seen multiple teachers straight up say "If you have bad handwriting, you need to see a counselor or something because you shouldn't be writing like a 6 year old in high school."

#

They didn't last long, to be fair.

errant yoke
#

only seen one case that bad before

#

but no i just straight up blanked on the question

#

i neglected that i could convert radians to degrees

#

.close

lone heartBOT
#
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errant yoke
#

.done

lone heartBOT
#
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honest merlin
#

Can anyone help me with this?

lone heartBOT
solemn juniper
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
honest merlin
#

I have solved it with a>0 but when a<0 I’m literally stuck

solemn juniper
#

a and b have to have the same sign so it shouldn't be an issue

honest merlin
#

oh and btw I could only be able to approximate its value but cannot calculate it exactly

solemn juniper
#

Given that the answers are all decimals that should be fine

#

What did you get?

honest merlin
#

i could only approximate it to be bigger than 1.5 so I think the answer is D

solemn juniper
#

You can get a better approximation than that

#

How did you get "bigger than 1.5"

honest merlin
#

I substituted b for [log2(7/3) + 3a] /2

solemn juniper
#

I'll need you to show your work

#

You're right to use logs but that seems unnecessary

honest merlin
solemn juniper
#

,rccw

ocean sealBOT
solemn juniper
#

It's not $7 \cdot 8^a = 3 \cdot 4^b$

ocean sealBOT
#

Steakanator

solemn juniper
#

It's (7.8)^a = (3.4)^b

honest merlin
#

I mean the question

lone heartBOT
#

@honest merlin Has your question been resolved?

solemn juniper
#

no it isn't

honest merlin
#

anw thanks for your help @solemn juniper

#

I really appreciate it

#

I guess I might have to figure out another ways myself

#

.close

lone heartBOT
#
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merry meteor
lone heartBOT
merry meteor
#

can sm1 help

#

im following the steps to prove subspace

#

and i dont get why this isnt a subspace

#

the solution says its not

vapid shuttle
#

what if c*(x) and c<0

merry meteor
#

wb this

#

How do we know that x1+x2 is in the set

#

and also we are proving closed scalar + closed addition vector at one time here correct?

#

original question

#

@vapid shuttle why u leave me on read

#

😦

#

i have midterm

#

tom

#

.close

lone heartBOT
#
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molten pivot
#

How many elements are in the union of all quadratic extensions of GF(5)?

mortal trellis
#

how many quadratic extensions are there

molten pivot
#

2, but it's not that simple

#

like of course 2 and 3 are the non squares in GF(5). but some elements of GF(5)[sqrt(2)] and GF(5)[sqrt(3)] will square to the same number

mortal trellis
#

do you not know that all finite fields with the same number of elements are isomorphic?

molten pivot
#

maybe i'm phrasing my question wrong

#

i just want to count the number of unique square roots. like uh:

#

sqrt(2)^2= 2sqrt(3)^2 mod 5

#

they both square to 2

mortal trellis
#

x and -x square to the same thing

#

and x^2=c can only have 2 solutions

#

so thats them

lone heartBOT
#

@molten pivot Has your question been resolved?

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#
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languid sable
#

I am a self-taught calculus student. Whilst working on the Gamma Function, I am confused as to the different derivatives with respect to each other, such as du/dx, which differentiates u with respect to x, and I am confused on how that works. Additionally, I wish to know about how to integrate with substitution and how to change integral bounds accordingly whilst doing so.

worn fox
#

I think you need to be more specific with your first point

languid sable
#

Should I reword it?

worn fox
#

maybe give an example

#

Like du/dx is just the derivative of u wrt x its unclear what you want explaining

languid sable
#

For example, the product law in derivatives, if the pronumeral u was substituted in place of, for example, (3-x^2), the first part of the formula is in the format of v * du/dx. I am confused on how the du/dx stands for and how it works.

mortal trellis
#

du/dx is the same as u' if you have seen that notation before

worn fox
#

So u and v are just names you are giving to functions of x

#

u(x)*v(x) and you're applying the product rule to this product of functions

languid sable
mortal trellis
#

if u(x)=3-x^2, then u'(x) = ?

#

x is the variable

languid sable
#

So how would I format a derivative of one variable with respect to another?

vocal heron
mortal trellis
#

this isnt as important now in single variable calculus, but later if you for example have f(x,y)=x^2+3y^3 or something, then you need to somehow make it clear whether you are differentiating with respect to x or y. but that's a topic you will see later

languid sable
mortal trellis
#

yes

languid sable
#

Apologies if I am a little slow, I am 14 and I have a lot to learn. Calculus is simply a hobby of mine :)

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But thank you for the explaination, I understand now.

worn fox
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Paul's online maths notes are a good resource if you haven't seen them yet

languid sable
#

Oh? Could you provide a link?

languid sable
#

Thank you.

worn fox
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You can probably jump in at the derivatives section and review the functions section when/if needed

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Limits is something worth looking at if you want to know what a derivative really is and its formal definition

lone heartBOT
#

@languid sable Has your question been resolved?

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misty moat
#

need help

lone heartBOT
misty moat
#

need help making sure question 1 is right

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and not sure how to do question 2

barren portal
#

@misty moat

vast burrow
#

Yes seems right

barren portal
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For 1) you just have to evaluate P(20) as you did

misty moat
#

yes?

barren portal
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For 2) compute P’(20)

vast burrow
#

For second question you must differente

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Oh you got this ig lol

misty moat
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i dont got this

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idk how to do 2

vast burrow
#

Difference it

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Diffrentiate*

misty moat
#

do you know the answer to this?

vast burrow
#

Do you know quotient rule?

misty moat
#

yeah

vast burrow
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Yes use that

misty moat
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i did

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still didnt get the answer

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im in a rush

vast burrow
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Oh so diffrentiate the bottom part what do you get?

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And diffrentiate the top part aswell

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You get 3x^2 and 30x(6x-7)^4

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Now just use quotient rule

misty moat
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i did

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i dont know how to do it

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i didnt get any of the answers

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ive got this

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this is not 1 of the answers

vast burrow
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So you get x^3(30x(6x-7))-3x^2(6x-7)^5

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Divided by x^4^2

misty moat
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which is

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B?

vast burrow
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A

misty moat
#

ok

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thanks

#

.close

lone heartBOT
#
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cinder sundial
lone heartBOT
cinder sundial
#

That means the difference of all a-b where the range of a as well as b goes from 1 to 6

flint shoal
#

p much. fix one a/b, compute the difference for every other b/a (respectively) in the range of this other summation index

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so for example, for each value of a, there are 6 things to calculate (one for each b)

lone heartBOT
#

@cinder sundial Has your question been resolved?

zealous lichen
#

I think the slash means or

cinder sundial
cinder sundial
cinder sundial
lone heartBOT
#

@cinder sundial Has your question been resolved?

lone heartBOT
#

@cinder sundial Has your question been resolved?

lone heartBOT
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vestal pilot
#

I'm not sure why they do what they do between 10-12

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They multiply the equation by the integrating factor mu(t), but they they want the left side to be the derivative of the product mu(t)y?

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@ me if anyone answers 🙏

plucky sluice
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@vestal pilot (11) is just the product rule. Then they look at the rhs of (11) and the lhs (10) with the idea to find some function $\mu(t)$ that will work in both cases

ocean sealBOT
#

Xenophon

plucky sluice
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If you set the rhs (11) equal to the lhs(10) you get (12)

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Now they try to solve that equation, which is a differental equation

vestal pilot
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Yeah I'm just not sure why they decided to take the rhs of 11 and the lhs of 10. Like what made them say "we should put those together"?

plucky sluice
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Well, it could be that no function matches both of those, which would be sad

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But if you can find such a function, then you can solve the original differential equation

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Notice that the lhs of (11) is of the form d/dt(something)

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If d/dt(something) = some function of t, then you can integrate directly

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It's not like it's necessarily easy to think of this idea just by looking at the ode

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But once you have the idea, you check that it works (which it does)

vestal pilot
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I'm missing something

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Like I don't really get the entire point of why we're actually multiplying by the integral factor mu(t)

plucky sluice
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Mhmm, the point is to turn an ode into an integral problem

vestal pilot
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Because the ODE can't be integrated without it?

plucky sluice
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Yes

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Well, any method that does integrate it is a generalization of the integrating factor

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Or a special case

vestal pilot
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and then that unknown mu(t) is what would make it integrable

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hmmm

plucky sluice
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Yes, because we choose mu(t) to satisfy (11)

vestal pilot
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But 11 is always true

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that's just the product rule

plucky sluice
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I should say satisfy (11) AND (10)

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(10) makes mu(t) specific to the ode in question and (11) ensures that we can then solve the ode

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I think the key insight is to look at the lhs of a linear, first order ode, and notice that its structure is similar to the identity from the product rule

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i.e. that's just the derivative of another function with the form y*mu(t)

vestal pilot
#

Yeah, I saw that

plucky sluice
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Buuut, I will say that there are a lot of things in math that are not easy to come up with in a vacuum but have been proven to work

vestal pilot
#

mfw I got like 80+ on this course all while not actually knowing what the hell is going on lol

plucky sluice
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Some really smart guys in 18th century tried everything for decades and found stuff like this

vestal pilot
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but it was a year ago, and I've got PDE coming up, so I'm going over it again

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why couldn't they invent it simpler

plucky sluice
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lol

vestal pilot
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well, thanks for the help

plucky sluice
#

np

vestal pilot
#

Do you maybe know what they did between 15 and 16?

#

@plucky sluice sorry for the ping btw 🙏

plucky sluice
#

It's our old friend, the chain rule

lone heartBOT
#

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obtuse mango
#

Hello!

lone heartBOT
obtuse mango
#

I do not understand why z cannot be between 1 and -2i

#

A bit of help would be great, thanks!

#

nvm I did it myself. This chat's hopeless

#

.close

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little spear
lone heartBOT
little spear
#

anyone help with this question

#

.close

lone heartBOT
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fickle sandal
fallen verge
#

Is this an ad?

dim oasis
#

Definitely not a math question

fallen verge
#

<@&268886789983436800> ad i think

real gazelle
#

wdym this seems like a totally legit question

fallen verge
#

ah of course, ahat a lapse i my judgment

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it must be my mistake because i cannot spell so clearly i cannot discern a question from an ad

real gazelle
#

Smh you helpers just slacking on your job

dim oasis
#

,w will brainy give me all the answers?

real gazelle
#

Want excuses to not help people

ocean sealBOT
real gazelle
#

.close

lone heartBOT
#
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regal surge
#

Hi! I'm stuck on this math question from homework and I don't understand how to do it. I thought maybe I was supposed to complete the square, but that does not give me the right answer.

According to the textbook, the answer is x = 0.15, 1.02, 2.12, or 2.99

Any help is appreciated :')

cinder sundial
#

For example, by substitute the sinX by t

fickle sandal
mellow grail
regal surge
regal surge
#

but it doesn't factor nicely

cinder sundial
coral flower
regal surge
#

OH RIGHT

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okay let me try that :D

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But what do I do with this ????

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😭

fickle sandal
#

a=sinx, not sinx=0

mellow grail
#

also u can simplify your vaue for x

fickle sandal
#

*a, not even x

coral flower
#

a*

regal surge
#

I don't understand 😭

coral flower
#

sinx = a
sinx = (2+- sqrt 2) / 4

regal surge
#

oh

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and then do I like inverse.... ?

coral flower
#

sinx = (2+sqrt2)/4 , sinx = (2-sqrt2)/4

regal surge
#

OH I GOT IT :D

coral flower
#

yeah sinv inverse both sides for value of x

regal surge
#

wait but

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I only got 1.022 and 0.15

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how did the textbook get 4 answers? 😭

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they also got 2.12

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and 2.29

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oh is it pi subtract the first two values I got

coral flower
#

yes

#

its actually +pi not -

regal surge
#

Oops, you're right

#

okay, thank you all so much :D

coral flower
#

this is cuz x lies between 0 and 2pi , sinx is positive which means it is either in 1st quadrant or 2nd aka 4 values

regal surge
#

🫶🫶🫶

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.close.

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oh is that not how I close it

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😭

coral flower
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its just .close

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not .close.

regal surge
#

OH

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thank you again 😭

#

lol

coral flower
#

the command is very sensitive