#help-0

1 messages · Page 209 of 1

limpid aurora
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combine 0.8 and x/5 into one fraction and multiply by the reciprocal again

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but honestly i like this more

round meteor
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So, it's x = 5/0.8 ?

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not divide by 0.8?

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0.8 = 5/x; x * 0.8 = 5/x * x/1; 0.8x = 5; x = 5/0.8;

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That's how I got there.

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Can I please get a thumbs up or down, and I can close the help. Don't need a walk-through, just whether it's right or wrong.

limpid aurora
slate jolt
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yeah its divide by 0.8

limpid aurora
#

sorry for not responding sooner

slate jolt
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its just i was thinking on terms of the "multiply by the reciprocate of the fraction"

round meteor
#

Thank you, both.

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.close

lone heartBOT
#
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clear magnet
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i am having trouble understanding this question

clear magnet
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the parts under say this:
deepest section of the lake has an area of 57.93km^2 and a depth of 350m

second region of the lake has an area of 47.51km^2 but a total area of 105.44km^2 and the new section has a depth of 300m

third region of the lake has a total area of 190.24 km^2 and the new section has a depth of 250m

fourth region of the lake has a total area of 372.66km^2 and the new section has a depth of 125m

fifth region of the lake has a total area of 579.07 km^2 and the new section has an average depth of 50m

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and what i dont understand is why it gives me the total area for the 2nd, 3rd,4th and 5th region

lone heartBOT
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@clear magnet Has your question been resolved?

clear magnet
#

i still don't understand after 20 minutes if searching

limpid turret
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What's the question the book is giving you?

clear magnet
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it's asking me to figure out the volume of a lake

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and its giving me the area of each section

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in a very confusing way that i don't understand

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and i am not sure how i am supposed to find the volume for each section if it's giving me the total area of every region

lone heartBOT
#

@clear magnet Has your question been resolved?

lone heartBOT
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uncut galleon
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again

lone heartBOT
uncut galleon
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so

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this

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i have this

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but what do we do with the 1/rad2pi

chrome salmon
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hi thee

uncut galleon
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hi!

chrome salmon
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how did you get that T3

uncut galleon
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taylor series

chrome salmon
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of what tho?

uncut galleon
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wdym?

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of e^x

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sorry

chrome salmon
last spire
chrome salmon
uncut galleon
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do i multiply it by everything?

uncut galleon
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to counter that

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then i can just use e^x

chrome salmon
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oh then okay but I hope you made no sign mistake

uncut galleon
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my TA checked that part so i think it’s fine

chrome salmon
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you haven't used parenthesis

uncut galleon
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i jusg need to know what to do w the 1/rad2pi . do i multiply it by the whole series or like

chrome salmon
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like (-0.09)^2

uncut galleon
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ah okie

chrome salmon
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you just multiply to the value you get after finding T3(-0.09)

uncut galleon
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got it

chrome salmon
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okahy

uncut galleon
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thank u b much 🙏 bye bye

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.close

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sturdy sky
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Yo, im not really sure what this question is asking from me. Do i just use first principles?, do i have to take the limit from both sides?

tacit arch
naive valley
sturdy sky
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yeah but first i prove its differentiable right

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so how do i do that

tacit arch
tacit arch
naive valley
sturdy sky
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whats that

tacit arch
sturdy sky
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oh right first principle

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sorry i just havent heard that phrase before

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ok so now how do i do that from both sides

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hellooo?

tacit arch
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Use one-sided limit definition

sturdy sky
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.closre

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.close

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willow wraith
lone heartBOT
willow wraith
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it should be 8/3 where did I fuck up

lone heartBOT
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@willow wraith Has your question been resolved?

chrome salmon
willow wraith
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Find the length of the curve

chrome salmon
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well I can't figure out what you have written for x and y

willow wraith
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I have the original written at the top

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x= 2/3 (T^2+2)^3/2

shrewd ermine
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2s look like Zs

willow wraith
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y= 2t

chrome salmon
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then what is t

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is it 2T

chrome salmon
willow wraith
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there is no z anywhere in the question

chrome salmon
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there's no s

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and there's no z it's 2 loking like z

willow wraith
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you can click the picture it makes it larger

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its not that bad guys come on

chrome salmon
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yeah that was already done

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is y=2t or 2T

willow wraith
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I write t and T interchangeably sometimes

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its the same thing

chrome salmon
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no it's not same thing

willow wraith
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brother can we get to what I did wrong and not my handwritting

tacit arch
willow wraith
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you want I can type it out

chrome salmon
tacit arch
willow wraith
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well thats what I did wrong

chrome salmon
willow wraith
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no he found the mistake

chrome salmon
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maybe if you see that you'll understand

tacit arch
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It was hard to find because of your handwriting

chrome salmon
willow wraith
#

.close

lone heartBOT
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mighty berry
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This is from my elementary number theory class:

mighty berry
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We recently learned about the Chinese Remainder Theorem, but I'm not entirely sure how that's related to this problem. I know that one million consecutive non-perfect numbers exist somewhere, but how do I show that?

radiant jasper
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a^2-(a-1)^2=1000000?

mighty berry
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I actually considered just writing that, but it seems too easy... is that really the only logic I can apply here?

radiant jasper
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If It Works i dont see the problem

mighty berry
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That's fair...

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Hm, then, what about the next one? Also related to CRT:

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Wait, nevermind. I think I see the solution. Thanks!

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kindred anchor
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Find the remainder when $17^{101}$ is divided by $20$

ocean sealBOT
keen plinth
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oh my

kindred anchor
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Bad Tex

keen plinth
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is there a reason you're binomial expanding this

vale wigeon
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^

kindred anchor
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I wanna do the problem using binomial expansion

vale wigeon
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there are much better ways of doing this problem

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what you are doing is painful

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also all the -17's should be -3's...

kindred anchor
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Oh shit yes

vale wigeon
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best case scenario: you realize that all but the last term are multiples of 20 and end up saying in a very longwinded way that 17^101 = (-3)^101 mod 20
worst case scenatio: you agonize over the hundred and two terms, trying pointlessly to calculate each one

kindred anchor
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Ok so all the terms in the binomial expansion is divisible except nCr(101,101) (-3)^101

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What do I do next?

vale wigeon
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are you going to insist on not using any modular-arithmetic considerations

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yes/no

kindred anchor
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best case scenario: you realize that all but the last term are multiples of 20 and end up saying in a very longwinded way that 17^101 = (-3)^101 mod 20
I had this idea in my mind, that's why I used binomial expansion

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In this problem yes

vale wigeon
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why?

kindred anchor
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I tried the problem this way first and couldn't get to the answer, so I wanna know the ways

vale wigeon
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there is a way to do it with modular arithmetic.

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and the other way i have in mind is a detour that uses essentially the same idea except in bulkier, harder-to-understand and more painful notation.

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so like, are you a masochist?

kindred anchor
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I'm facing difficulty in these kinds of problems, so I'm learning bunch of different methods to get familiarized

vale wigeon
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when two methods are essentially the same except one is full of pain, do you still want to learn the painful one?

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(-3)^4 = 81 = 1 mod 20, therefore (-3)^101 = (-3)^(101 % 4) = (-3)^1 mod 20

chrome salmon
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I love this

vale wigeon
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like what could you do here? break off one (-3) and then go with (-3)^100 = 81^25 and then binomial-expand AGAIN and have to face twenty-five vanishing terms AGAIN?

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it's a waste of effort.

kindred anchor
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Understood

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I will try more problems and get back here if I have any doubts

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.close

lone heartBOT
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upbeat kayak
lone heartBOT
upbeat kayak
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"For what values of p the integral converges?"

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My idea was to do evaluations at the 0 and inf

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But I think I didnt exactly do them right

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At 0 i said it behaves as 1/sqrt(x)^p

upbeat kayak
lone heartBOT
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@upbeat kayak Has your question been resolved?

lone heartBOT
#

@upbeat kayak Has your question been resolved?

rugged nymph
#

can u apply the series tests

lone heartBOT
#

@upbeat kayak Has your question been resolved?

lone heartBOT
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twin hawk
lone heartBOT
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Please don't occupy multiple help channels.

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@twin hawk Has your question been resolved?

lone heartBOT
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kind yarrow
#

can someone please help me with this i dont understand

kind yarrow
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I dont understand what to do

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<@&286206848099549185>

atomic flax
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i think this is simple

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set the variable with the number or word

kind yarrow
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yes

atomic flax
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like part a is 16

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b is mcdonald

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after setting the value for the variable

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classify it

kind yarrow
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ok

atomic flax
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put same type of variable in a group

kind yarrow
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ok but for the example it says this

atomic flax
atomic flax
kind yarrow
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so like i just have to count up

atomic flax
kind yarrow
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ok thank you

atomic flax
kind yarrow
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ok

atomic flax
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each element is a "pin"

kind yarrow
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ok for example it would be like i send 0 1 text messages a day

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.close

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dry tartan
#

can someone help me with this question

lone heartBOT
atomic flax
dry tartan
atomic flax
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i mean

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what is

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the title of the question

harsh socket
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hlep

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help*

dry tartan
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show that an equation is the derivative of another

dry tartan
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this is occupied...

atomic flax
harsh socket
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how

atomic flax
atomic flax
harsh socket
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im confused

atomic flax
atomic flax
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question*

dry tartan
atomic flax
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okay, wait for ninutes

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minute*

ornate leaf
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@dry tartan do you know how to do diffrentation?

dry tartan
ornate leaf
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do you know the power rule?

atomic flax
dry tartan
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no

ornate leaf
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dont send the sol

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!nosols

lone heartBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

dry tartan
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g (x) = x^2 - 5x

ornate leaf
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yes

dry tartan
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and g '(x) = 2x - 5

ornate leaf
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yeah

dry tartan
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im not sure how to "show" that the second equation is a derivative of the first

atomic flax
#

To calculate the derivative of the function
g(x) we use the formula to calculate the derivative of the quadratic function as follows:
d/dx x^2 = 2x
so, d/dx g(x) = d/dx (x^2 - 5x)
= d/dx x^2 - d/dx 5x
= 2x-5

dry tartan
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oh hold on i found a video about it

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if g (x) = x^2 does g ' (x) = 2 x x^2-1 ?

ornate leaf
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yes

atomic flax
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so the derivative of g(x) = x^2 - 5 is 2 x - 5

dry tartan
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what about the -5 part?

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what do i do with that

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do i just leave it?

ornate leaf
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yes

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wait

dry tartan
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ok

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is that it?

ornate leaf
dry tartan
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can we move on to the next part of the question pls

ornate leaf
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i thikn they meant x^2 - 5x

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ok sure

dry tartan
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wait lemme move it down here again

ornate leaf
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sure

atomic flax
dry tartan
ornate leaf
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so, what does “derivative” mean

atomic flax
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so the derivative of g(x) = x^2 - 5x is 2 x - 5

ornate leaf
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what does it outpit

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output*

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like what does 2x-5 represent? @dry tartan

dry tartan
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no its a curve right

ornate leaf
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2x-5 is of degree 1, it can only be a straight line

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but like

dry tartan
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and the tangent is a line going in the direction of the line

ornate leaf
#

yes

dry tartan
ornate leaf
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so g’(x) is the tangent of g(x)

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g’ (x) gives the gradient of g(x)

atomic flax
ornate leaf
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for example g’(7) gives the slope of tangent to g(7)

dry tartan
#

i see

ornate leaf
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so now your question wants the slope

dry tartan
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so for the second question

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yea

ornate leaf
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your “slope-outputting-function” is 2x-5

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so lets start with the first one aka 1

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so 2x-5 outputs the slope, which is 1, aka 2x-5=1

dry tartan
#

oh

ornate leaf
#

is that clear or is it weird

dry tartan
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so 2x-5 is the gradient

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and the question gives me a set of gradients

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and i assume i solve for x?

ornate leaf
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yes

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but, you dont stop there

dry tartan
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but what about the y coordinate?

ornate leaf
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the question wants both x and y

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so you have to subsitutte the x back into the original function

dry tartan
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so i put the x back

ornate leaf
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to find y

dry tartan
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yea

ornate leaf
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yep

dry tartan
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alright then

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ill do that later

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so the last one is just sketching right?

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so i find the x and y coordinate of all 5 gradients and then plot them on a graph?

ornate leaf
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yeah

dry tartan
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alright then

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looks like that question is done

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ill go do it now, thanks

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wait a minute

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@ornate leaf i have one question

dry tartan
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in the first equation its -5x

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and in the second one its just -5

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what happened to the x?

atomic flax
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solution of part b(i think so):
To find the coordinates of points whose tangent slope is m, we need to use the formula for tangent to a curve at a point.
The formula for tangent to a curve =f(x) at point P=(x0,y0) is:
y - y0 = f'(x0)(x-x0)
So, to find the coordinates of the points whose tangent slope is m, we need to solve the following equation to find the values of x respectively:
f'(x) = m
For the function f(x) = x^2 - 5x, we calculate the derivative of f(x) as follows:
f'(x) = d/dx(x^2 - 5x) = 2x - 5. as mentioned above
So, to find the coordinates of the points on the graph of the function
f(x) has a tangent with slope equal to m, we need to solve the following equation:
2x - 5 = m
--> x = (m+5) / 2
After finding the value of
x, we can calculate the corresponding y value by feeding the value of x into the function
f(x), ie:
y = f((m+5)/2) = (m+5 / 2)^2 - 5(m+5)^2)
So, the coordinates of the points on the graph of the function f(x)=x^2−5x whose tangent has a slope equal to
m is:
((m+5 / 2) , ((m+5)/2)^2 - 5(m+5 / 2))
bruh so tired

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@dry tartan

dry tartan
#

i see

ornate leaf
dry tartan
#

alright

ornate leaf
#

yes, in diffrentiaiotn, whenever you see constant*x, just change it to c in the thing

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and whenever you see just a constant by itself, you can ignore it

dry tartan
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alright

atomic flax
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okay, i helped u part a and b. can u do part c?

dry tartan
#

yes

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it is just graphing and drawing the tangents

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ok i have another question

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slightly different

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@atomic flax how to deal with this

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@ornate leaf ?

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nvm i did it

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.close

lone heartBOT
#
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spring nest
#

hey, i have a equation of matrix, X * (3 2; 5 5) = (-3 4; -5 1; 2 5)
I have to find X and the matrix sum of X, can anyone help me fast

spring nest
vague coral
#

find the dimension of the matrix first

spring nest
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3,2 right ?

vague coral
#

yea

spring nest
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for my first line i have this

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is it correct ?

vague coral
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how could I know, i didnt calculate anything

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and im too lazy to do it :x

spring nest
#

argh, if i send you my whole paper can you get a quick look on it to see if everything seems fine ?

vague coral
#

maybe

spring nest
vague coral
#

la méthode est correcte

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fais la meme pour y et z

spring nest
#

ah t'es francais mdrrr

#

vsy merci

#

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torn tapir
lone heartBOT
torn tapir
#

the answer in the book is throwing me off

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this is a quad formula question, rn x^2+5x-10=0

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is it not (-5+-root25+40)/2

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wait nvm im stupid as

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can only be positive so they auto added

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.close

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torn tapir
#

.reopen

lone heartBOT
#

torn tapir
#

hold on

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thats still not root 105 like the answer

midnight grail
#

s = 1/2hx

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=> 10 = 1/2 * x * (x+5)

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=> x^2 + 5x - 20 = 0

torn tapir
#

ooh i forgot the half i think

midnight grail
#

yup

torn tapir
#

thanks my guy

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.close

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ornate leaf
midnight grail
lone heartBOT
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paper sage
#

What is my bounds please help

lone heartBOT
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@paper sage Has your question been resolved?

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.close

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unkempt token
#

l

lone heartBOT
unkempt token
#

su[

#

Need help!

#

i no understand this

#

pls someone 😭

warm cipher
#

cross product

#

25*9/4

unkempt token
#

what u mean

warm cipher
#

oh sry

unkempt token
#

pls help

warm cipher
#

4/9=25/x

#

x=9*25/4

unkempt token
#

so how do i t

#

is that the answer

warm cipher
#

search up cross product

#

and ull see

pseudo junco
unkempt token
#

THANK YOU OMG

#

how about this one

#

@pseudo junco

#

!

pseudo junco
# unkempt token

do the same thing, you have to know what they multiplied 12 to get 78

#

(just divide 78 by 12)

unkempt token
#

this one?

#

@pseudo junco :DDD

#

!

strange fractal
#

i think ur just getting epople to help with ur homework and not understanding it

#

OK

strange fractal
#

what did u do??/

unkempt token
strange fractal
#

AYYYYYYYYYYYYYYYYYYYYYYYYYYYY

unkempt token
#

easy 🥱

#

need help with this one

#

fr

strange fractal
#

the shorter one will be the smaller number

unkempt token
#

uh

#

how do i do it

strange fractal
#

ok

#

so basically

#

u divide 4 by 1.6 and that gives u 2.5

#

to understand more 1.6 multipled by 2.5 gives u 4

unkempt token
#

and then times to 5

#

?

strange fractal
#

yeah

unkempt token
#

okay good

#

woof

strange fractal
#

WAIT

ocean hawk
#

no...

strange fractal
#

NO

#

U FIVIDE

split oriole
#

Divide 1.6 with 4

strange fractal
#

DIVIDE

#

NOOOOOOOOOOOO DONT DO ITT

ocean hawk
#

4 / 5 = 1.6 / x

unkempt token
#

i cant

#

put

#

decimal

#

i wish im full asian

ocean hawk
#

it won't be a decimal answer

strange fractal
#

im full asian 😎 but im still dumb

#

r u aussie

unkempt token
#

no

strange fractal
#

NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO

#

YOU'VE BETRAYED ME

unkempt token
#

100% asian

#

i live in australia

#

nsw

strange fractal
#

oh

#

im wa

unkempt token
#

good papi

strange fractal
#

are u viet

unkempt token
#

uh

#

quarter chinese and others are filipino

#

okay

#

!

hard aspen
unkempt token
#

ban this guy

strange fractal
#

NO

unkempt token
#

duh

strange fractal
#

LOL

hard aspen
#

no i meant grade

#

you have algebra ryt

unkempt token
#

no one shame me!

#

im year 8

#

!

#

i dont listen to class tbh

#

but still on the top 10

strange fractal
#

AY SAM,E

#

IMTOP 3

hard aspen
#

can you convert them to fractions

#

the ratios

strange fractal
unkempt token
unkempt token
strange fractal
#

10

unkempt token
#

what're you picking for year 11

#

senior high

#

like

#

steam

strange fractal
#

oh

unkempt token
#

humss

strange fractal
#

im picking

#

the asian 5

#

chem physics english math specialist math methods

unkempt token
#

wtf is that

strange fractal
#

the maths is like extension 1 and extension 2

#

for nsw i think

unkempt token
#

NOW

#

straight to my point

strange fractal
#

WHAT

unkempt token
#

this one

#

!

strange fractal
#

oh yeah

ocean hawk
strange fractal
#

idk im not good at explaining i just do it

ocean hawk
#

solve for "x"

unkempt token
#

whats an x

#

jk

#

GOT IT

#

2

strange fractal
#

do u mean

unkempt token
#

nationality

#

u know what i mean

#

j/y

strange fractal
#

my nationality is australian

unkempt token
strange fractal
#

my ethnicity is viet

unkempt token
strange fractal
#

yes

unkempt token
#

LMAO

strange fractal
#

my kangaroo is so big it can fit a family of 4

unkempt token
ocean hawk
#

you have your ratios "backwards"

unkempt token
#

hm?

ocean hawk
#

you did it as 4 / 5 = 55 / x

#

but that's wrong

unkempt token
#

okay what i do

ocean hawk
#

Aisha:Harry = 4 / 5. you are given Harry's weight, you want to find Aisha's (which will be "x")

#

you have to match the numerator/denominator for each person

#

so the "x" won't be on the bottom

unkempt token
#

so its on the top

ocean hawk
#

yes

unkempt token
#

44

#

55

ocean hawk
#

yes

unkempt token
#

NO ITS 44 SHIT

#

FUCK ME

ocean hawk
#

yea you wrote 44...

unkempt token
#

NAUR

#

this one

strange fractal
#

..........................

ocean hawk
#

same type of problem, you should be able to solve this one

strange fractal
#

YES U GOT THISSS

#

APPLY WHAT U KNOW 💰

unkempt token
#

hell nah

#

i no what i do

strange fractal
#

IT SAYS DOGS TO CATS

unkempt token
#

i eat dogs?

strange fractal
#

omg.

unkempt token
#

lol

strange fractal
#

its literally 20 divide 1....

#

for the cats

unkempt token
#

um

strange fractal
#

U SHOULD KNOW THIS

unkempt token
#

60

strange fractal
#

OMGGGGGGGGGG

#

U DID IT

unkempt token
#

YES

#

CHEERS MATE

#

i feel so smart

strange fractal
#

ik ur sooo smart 😍

unkempt token
#

so rude

strange fractal
#

AM NOT

unkempt token
#

what i do with this one

ocean hawk
#

same type of problem

unkempt token
#

what

ocean hawk
#

set up an equation, solve for "x"

unkempt token
#

1/7 = 5.5/x

#

?

ocean hawk
#

yes

unkempt token
#

38.5

#

!

ocean hawk
#

yea

unkempt token
#

this one?

#

lakaka

ocean hawk
#

same steps

unkempt token
ocean hawk
#

not exactly like that one

#

pay attention to the order

unkempt token
#

uh

#

um

#

.8

#

um

#

5

#

?

ocean hawk
#

you've done several of these now, take your time and follow the same steps

#

be careful of the order of the two things you're given

#

.8 was right

unkempt token
#

what steps

#

!

ocean hawk
#

set up an equation and solve for the unknown. exactly the same as the other problems

unkempt token
#

WHAT IS AN EQUATION

#

LIKE FR

#

x

#

nvm

#

pls help

#

i go sleep i no do this no more

strange fractal
#

hi..

#

NOOO DONT GIVE UP

#

@unkempt token

lone heartBOT
#

@unkempt token Has your question been resolved?

lone heartBOT
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vale hollow
#

im dont quite understand someting, when subtracting u need to have a cd and i got which is 20 and thenm your supposed to times the numertor by how much it took you to get the that number (the denominator) so i dont understand here which number i should times by numerator by? if that makes sense

wary stream
#

u need to have a cd and i got which is 20
Yes the denominator needs to be 20, so start with 3/4 fraction, 4 times what equals 20?

vale hollow
#

5

wary stream
#

supposed to times the numertor by how much it took you to get the that number (the denominator)

#

So if you multiplied by 5 in the denominator then you need to multiply the numerator by that same number

vale hollow
#

both the numerators or just one?

wary stream
#

For 3/4 to have a denominator of 20. you need to multiply by 5

#

For 1/5, would you multiply the denominator by 5?

vale hollow
#

no that would make 25

wary stream
#

So then what should you multiply by to get 20?

vale hollow
#

4

wary stream
#

From there, do you know what to do?

vale hollow
#

yep, but i was wondering can you use different numbers to muliply the numerators?

#

like obv the number you got to get to 20 but like it two different numbers 4 & 5 i though you had to use only one of them

wary stream
#

Do you mean if the common denominator was 20 and take the 3/4 fraction, you multiplied the denominator by 5 and the numerator by a different number that’s not 5?

vale hollow
#

i meant like for both fractions dont you use the same number like either 4 or 5 or do you use 1 number for that fraction like 3/4 you times the numerator by 5 and the other fraction numerator by 4?

wary stream
#

No you don’t use the same number for both fractions. You use whatever number that gets you that common denominator

vale hollow
#

oh okay that makes a lot more sense because i watched a youtube vidoe on it and it didnt tell me that

#

thank you

wary stream
#

As before for 3/4, the common denominator is 20 so you multiply by 5. The other fraction 1/5, you don’t multiply by 5 to get a common denominator of 20, do you?

#

You need to apply a different number

vale hollow
#

4?

wary stream
#

Yes

vale hollow
#

ah okay i understand now

wary stream
#

Notice how you had to apply two different numbers for each fraction

vale hollow
#

thank you very much i have a test exam in just a while

wary stream
vale hollow
#

okay

#

.close

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lone atlas
#

To find the degree of the polynomial is it the highest degree in the function?

lone atlas
#

LOL

#

Is that a yes???

#

I think so

#

Ok thank you

#

.close

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alpine sable
#

How to find range of f(x)=cos(2sinx)

lone heartBOT
ruby current
#

find the range of 2sinx and then find its image under cosx

alpine sable
#

What shud u do after this

#

I*

ruby current
#

you can see from the graph what the range is

#

it's the y-values of the shaded region

alpine sable
#

I don't understand one thing like cos(anything) should be [-1,1]

#

Right?

ruby current
#

that's the codomain/target

alpine sable
#

Oooo

#

Thanks 😊

ruby current
#

that's the maximal set of any possible range

alpine sable
#

Yeah bro I understand now

ruby current
#

but your function can never achieve values less than cos(2)

alpine sable
#

Yeah got it

#

Thanks for helping

ruby current
#

not sure why your diagram is labeled with pi/2 though

#

ah those are the points before 2

lone heartBOT
#

@alpine sable Has your question been resolved?

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alpine sable
lone heartBOT
alpine sable
#

Stuck on this question

#

Don’t know where to start

gray isle
#

note that you have a quadratic function
and to find the maximum here you can consider the vertex of a parabola

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

hi

#

i need help

lone heartBOT
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tardy pond
#

how do i find the limit of this ?

lone heartBOT
quasi vector
#

use small angle approximation

tardy pond
#

can you pls explain

slow hound
#

cant use lhopitals?

ruby current
#

or multiply by 36/36

chrome salmon
#

Yes

#

The best

tardy pond
#

so like this?

lone heartBOT
#

@tardy pond Has your question been resolved?

ruby current
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austere compass
#

For which $\beta > 0$ do you guys think this function is continuous?
$$
g: \mathbb{R}^2 \rightarrow \mathbb{R}, \quad g(x,y) = \begin{cases} \frac{x^4-y^4}{x^4+y^4}, & \text{ if } (x,y) \neq (0,0) \
\beta & \text{ if } (x,y) = (0,0) \end{cases}\text{?}
$$

lone heartBOT
#

Please don't occupy multiple help channels.

ocean sealBOT
#

Levens

lone heartBOT
#

@austere compass Has your question been resolved?

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violet idol
#

$\frac{2x}{|x^2 + 1|} \leq 3$

lone heartBOT
ocean sealBOT
#

idiotic|spaceman

violet idol
#

hello! Been stuck for a while on this. I am getting my answer as x belongs to a null set but apparently the answer is x belongs to all real numbers

#

ohh nvm, solved it

#

.close

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hard charm
#

.claim

#

how would i find x and y?

lone heartBOT
limpid spade
#

what

hard charm
#

like the areas of the shapes cut off

#

if i have a triangle with it's corners both touching the surface of a circle part of the triangle is cut off, i need to find that area so i can subtract it from the actual area

lone heartBOT
#

@hard charm Has your question been resolved?

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past steeple
#

I am trying to get the polynomial differentiation rule by pullbacks or differentials of
that tensor field. But I am not sure what to do. So we can write x^n as e tensor e n times
e being the standard basis for R* I am trying to then get the polynomial rule
I know this is kind of stupid, but I am trying to
understand tensors a bit better What doesn't make sense to me is then, if we
take the exterior derivative of this form, we get
an n+1 form. Which doesn't really make sense.
Unless I am wrong

past steeple
#

I forgot to add a part

#

I am trying to get nx^n-1 as some sort of thing from treating x^n as an nth rank tensor

#

so I know that x^n can be represented as
e tensor e n times I think. Where e is the standard basis for R*

#

So like. We have a tensor field being dx tensor dx n times in local coordinates right?

#

is what I am saying impossible/ doesn't make any sense

lone heartBOT
#

@past steeple Has your question been resolved?

past steeple
#

<@&286206848099549185>

alpine sable
#

btw @past steeple your question is probably way outside the knowledge base of the people who frequent the help channels

#

way better luck in the advanced channels probably

past steeple
#

Right I forgor

#

.cloae

#

.close

lone heartBOT
#
Channel closed

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alpine sable
lone heartBOT
#
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vapid cipher
#

My answer is the red lines. My answer gave me 3/4 marks, which means I missed something out or I got something wrong, what is it?

remote heron
#

whatd the prof say?

#

looks fine to me thonk

vapid cipher
#

its a maths website for homework, if its correct a bug maybe?

#

<@&286206848099549185> Is there a reason I got 3/4 marks or is the website tripping

last ether
#

Slap the website

lone heartBOT
#

@vapid cipher Has your question been resolved?

rigid gorge
#

Does anyone know how to solve this problem: Given x+1/x =-1. What is x^2019+1/2019= ?. Show full working out.

vapid cipher
#

!close

#

.close

lone heartBOT
#
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chilly hawk
#

soo liek

lone heartBOT
heady finch
#

23rd question please

chilly hawk
#

i already claimed

#

sorry

heady finch
#

Oh my bad

wary stream
chilly hawk
chilly hawk
#

i think

#

yea it is

wary stream
#

You didn't need to close your channel and open a new one

#

You did not need to close it

chilly hawk
#

ye

#

i agree

wary stream
chilly hawk
#

so like

#

when i was doing the adding part

#

would it be 1.331 + 64.2

#

also why are the (1.1) and (1.2) in brackets

wary stream
chilly hawk
#

there

wary stream
#

I know that, I mean how did you get that value?

chilly hawk
#

this

#

but then

#

d exponent 3

#

1.1 x 1.1 x 1.1 = 1.333

#

and the

#

5 + f e

#

57 + 1,2 = 58.2

wary stream
#

You know that says 5fe, which is 5 * f * e

#

None of those are getting added

chilly hawk
#

ohhh

#

so it would be 5 x f then e

#

5 x f and the total

#
  • by e
#

5 x 1.2 = 6 x 57 = 342

#

342 + 1.3 = 343.3

#

is that right?

#

@wary stream

wary stream
#

Don't ping me

chilly hawk
#

mb

wary stream
chilly hawk
#

wait how

#

1.1 x 1.1 x 1.1

#

is 1.333

wary stream
#

Where is .2 coming from?

chilly hawk
#

1.331

#

i mean

wary stream
#

342 + 1.3 = 343.2
How did you get .2? When the decimal was .3

chilly hawk
#

oh

#

jsut a small mistake

#

so is this correct

#

343.3

wary stream
#

Yes

chilly hawk
#

so now which part do i do next

#

5d3e - d3?

wary stream
#

Why would you do the d^3 again?

chilly hawk
#

oh ye

#

so use 343.3

wary stream
#

You already did it

chilly hawk
#

yeah

#

okay

#

5 x d3

#

d3 = 1.1

#

d = 1.1

#

1.331

#

5 x 1.3 = 6.5

#

6.5 x 57

#

370.5 - 343.3

#

27.2

#

is that right

#

27.2 - 1.2

#

=

#

26

lone heartBOT
#

@chilly hawk Has your question been resolved?

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dim kettle
#

Where is that sqrt coming from

lone heartBOT
long axle
#

Pythagorean theorem

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But 25 + 9 isn’t equal to 31

dim kettle
#

Also why 3/sqrt31

long axle
#

3/sqrt(34) is sin of that angle, theta

dim kettle
#

Rught thx

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. Close

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.close

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hallow dock
lone heartBOT
hallow dock
#

How do we get there numerator and denominator?

#

I think I am confused about it.

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@hallow dock Has your question been resolved?

hallow dock
#

<@&286206848099549185>

placid zinc
#

They are using a lot of "law of total probability", where one term reflects if the defendant is innocent, and the other term reflects if the defendant is guilty

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For example, let's say:

  • The defendant is guilty (0.8)
  • Judge 3 votes guilty (0.8)
  • Judge 1 votes inno (0.2)
  • Judge 2 votes inno (0.2)
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Multiply those together, you get the first term of the numerator

#

@hallow dock

#

The other term of the numerator is the same logical process, but if the defendant is inno

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normal holly
lone heartBOT
normal holly
#

can i please have help figuring out the equations

tulip shell
#

chocolate disco

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wheat isle
lone heartBOT
wheat isle
#

How do I start

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I know perimeter is 2x+2y

safe spindle
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let height be x

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and then calculate the length

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and then maximize

wheat isle
safe spindle
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prolly a better letter, like a

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so u are given the y vvalue is a, then find the x value using the parabola equation

wheat isle
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Hm

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Don’t I need width

safe spindle
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u can calculate the value of Q and P

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using the height

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the y value of P is a, so u can calculate the value of x

wheat isle
#

But height is only a variable no?

safe spindle
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in terms of a

safe spindle
wheat isle
#

So like P=6-x^2?

safe spindle
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$a=6-x^2$ where x is the x value of Q and P

wheat isle
#

Oh

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So I can isolate x?

safe spindle
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yes

wheat isle
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Okay

ocean sealBOT
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tan g ent

wheat isle
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x^2= 6-a

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is sqrt necessary

safe spindle
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u can let the x value of P be a instead of height, so instead of sqrt it is a square

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so u have $y=6-a^2$ where y is the y value of Q and P

ocean sealBOT
#

tan g ent

wheat isle
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Hm

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So how would I solve this?

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I thought I had to isolate a variable

safe spindle
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so u have that the length is 2a, and the height is 6-a^2

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now u find pereimeter in terms of a, and then maximize

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@wheat isle Has your question been resolved?

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digital relic
#

What are the zeros?

lone heartBOT
safe spindle
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let f(x)=0

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so then 2(x+4)^2=8

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then (x+4)=-+2 so x is -2 adn -6

digital relic
#

ok

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@digital relic Has your question been resolved?

proven leaf
# digital relic What are the zeros?

The ``zeroes" of a function are the points at which the function crosses the x-axis. So this is when $y$ or $f(x)$ is equal to zero, hence: $f(x)=2(x+4)^2-8=0$. Once we know this we can solve for the $x$-values of our zeroes. From there the coordinates can be found, do you think you can do that?

ocean sealBOT
#

XxMrFancyu2xX

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safe spindle
lone heartBOT
safe spindle
#

Ive figured that the Circumradii must be equal for all possible ABC by Law of Sines

#

can someone give me a hint

pure pier
#

I got a question regarding center of dialation. How do you find it?

safe spindle
#

pic ?

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and also this is my channel, can u ask in a different one?

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one that is available, not occupied

pure pier
#

Okay. Sorry. I’m new to this server

safe spindle
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its fine

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<@&286206848099549185>

#

aaaaaaaa

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normally im not this impatient but

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aaaaaaaaa

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<@&286206848099549185>

real cipher
#

@vale wigeon

wary stream
vale wigeon
real cipher
#

okay

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@safe spindle Has your question been resolved?

safe spindle
#

hellpp

#

<@&286206848099549185>

gleaming ridge
#

No idea

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@safe spindle Has your question been resolved?

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@safe spindle Has your question been resolved?

alpine sable
#

You can draw the tangent

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Oh heyy your name is also

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Tangent

#

,av @safe spindle

ocean sealBOT
#
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alpine sable
#

Nice

alpine sable
#

A hint

#

Try and let me know if its useful

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wheat isle
#

This still confuses me. So I have 2x+2y but I don’t understand the maximising part

wheat isle
#

The sides of the rectangle

naive valley
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they have to satisfy y = 6 - x^2

wheat isle
#

that’s the equation of the parabola correct

wheat isle
naive valley
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right

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so use that in your 2x + 2y formula for the perimeter

wheat isle
#

Ah okay

whole shell
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4x + 2y

wheat isle
#

So now we have a quadratic

wheat isle
whole shell
#

Yh it definitely should be 4x + 2y

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Go back

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And look at it

wheat isle
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But I asked this question before as well and 3 people said it would be 2x+2y or whatever variable 2a+2y etc

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I can see it being 2x+2y but I don’t get how it would be 4x+2y

whole shell
#

One sec

naive valley
wheat isle