help-0

[modern sedge]

Even if you are adding up infinitely many things, it may not be infinity

[gray patio]

wat how

[modern sedge]

such as 1/2+1/4+1/8+1/16...=1

[gray patio]

well

[modern sedge]

but yeah, maybe just stick to your grade lvl

[gray patio]

ye

[modern sedge]

you will learn this later

[gray patio]

simple grade lvl stuff

[modern sedge]

gtg, sorry. Bye. Have a good day. If you had any other question, someone else will help you

[gray patio]

oh

alr

have a gud day

.close

[lone heart]

Channel closed

Closed by @gray patio

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[left frigate]

what is the laTeX command to wrap strings?

[ocean seal]

SippieSpoonWoon

[left frigate]

so i can fix this to look better

[undone lantern]

$\text{I think}$

[ocean seal]

roxyit

[undone lantern]

yeah

[left frigate]

ahhhhhh

[ocean seal]

SippieSpoonWoon
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[undone lantern]

$\text{Need_Halp. Question_is:} \newline
\text{determine the inverse for;} \newline
f(x)= \frac{1}{x-1} \newline
\newline
%I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.% \newline
\newline
Method1: \newline
f(x)= \frac{1}{x-1} \newline
\Rightarrow \frac{1}{y}= \frac{x-1}{1} \newline
\Rightarrow \frac{1}{y}+1 = \frac{x}{1} \newline
\therefore f^{-1}(x)=\frac{1}{y}+1 \newline
\newline
Method 2: \newline
f(x)= \frac{1}{x-1} \newline
1.\Rightarrow y(x+1)= \frac{1}{1} \newline
2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \newline
3.\Rightarrow x+1 = \frac{1}{y} \newline
4.\Rightarrow x=\frac{1}{y}-1 \newline
\therefore f^{-1}(x)=\frac{1}{y}-1 \newline
\newline
\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$

[ocean seal]

roxyit
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

SippieSpoonWoon
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[undone lantern]

weird

$\text{Need_Halp. Question_is:} \newline
determine the inverse for; \newline
f(x)= \frac{1}{x-1} \newline
\newline
%I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.% \newline
\newline
Method1: \newline
f(x)= \frac{1}{x-1} \newline
\Rightarrow \frac{1}{y}= \frac{x-1}{1} \newline
\Rightarrow \frac{1}{y}+1 = \frac{x}{1} \newline
\therefore f^{-1}(x)=\frac{1}{y}+1 \newline
\newline
Method 2: \newline
f(x)= \frac{1}{x-1} \newline
1.\Rightarrow y(x+1)= \frac{1}{1} \newline
2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \newline
3.\Rightarrow x+1 = \frac{1}{y} \newline
4.\Rightarrow x=\frac{1}{y}-1 \newline
\therefore f^{-1}(x)=\frac{1}{y}-1 \newline
\newline
\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$

[ocean seal]

roxyit

$\text{Need_Halp. Question_is:} \newline
determine the inverse for; \newline
f(x)= \frac{1}{x-1} \newline 
\newline
%I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.% \newline
\newline
Method1: \newline
f(x)= \frac{1}{x-1} \newline 
\Rightarrow \frac{1}{y}= \frac{x-1}{1} \newline
\Rightarrow \frac{1}{y}+1 = \frac{x}{1} \newline
\therefore f^{-1}(x)=\frac{1}{y}+1 \newline
\newline
Method 2: \newline
f(x)= \frac{1}{x-1} \newline 
1.\Rightarrow y(x+1)= \frac{1}{1} \newline
2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow  \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \newline
3.\Rightarrow x+1 = \frac{1}{y} \newline
4.\Rightarrow x=\frac{1}{y}-1 \newline
\therefore f^{-1}(x)=\frac{1}{y}-1 \newline
\newline
 \big(f^{-1}(x)=\frac{1}{y}-1  \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.57 $\text{Need_Halp. Question_is:}
                                     \newline
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.```

[left frigate]

idk whats wrong lol

[undone lantern]

hmm

! Missing $ inserted.
<inserted text>
$
l.57 $\text{Need_Halp. Question_is:}
\newline
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.

$\text{Need_Halp. Question_is:}$

[ocean seal]

roxyit
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[undone lantern]

$ \text{Need_Halp. Question_is:} $

$$ \text{Need_Halp. Question_is:} $$

its something to do with the formatting

[left frigate]

yeahh

[undone lantern]

$$ \text{Need Halp. Questionis} $$

[ocean seal]

roxyit

[undone lantern]

look

[left frigate]

do you need $ before \text?

[undone lantern]

I think its the _

[undone lantern]

yeah i think

$ \text{Need Halp. Question is:} \newline
\text{ determine the inverse for;} \newline
f(x)= \frac{1}{x-1} \newline
\newline
%I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.% \newline
\newline
Method1: \newline
f(x)= \frac{1}{x-1} \newline
\Rightarrow \frac{1}{y}= \frac{x-1}{1} \newline
\Rightarrow \frac{1}{y}+1 = \frac{x}{1} \newline
\therefore f^{-1}(x)=\frac{1}{y}+1 \newline
\newline
Method 2: \newline
f(x)= \frac{1}{x-1} \newline
1.\Rightarrow y(x+1)= \frac{1}{1} \newline
2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \newline
3.\Rightarrow x+1 = \frac{1}{y} \newline
4.\Rightarrow x=\frac{1}{y}-1 \newline
\therefore f^{-1}(x)=\frac{1}{y}-1 \newline
\newline
\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$

[left frigate]

bot gave up xd

[undone lantern]

$\text{Need Halp. Question is:} \newline
\text{ determine the inverse for;} \newline
f(x)= \frac{1}{x-1} \newline
\newline
%I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.% \newline
\newline
Method1: \newline
f(x)= \frac{1}{x-1} \newline
\Rightarrow \frac{1}{y}= \frac{x-1}{1} \newline
\Rightarrow \frac{1}{y}+1 = \frac{x}{1} \newline
\therefore f^{-1}(x)=\frac{1}{y}+1 \newline
\newline
Method 2: \newline
f(x)= \frac{1}{x-1} \newline
1.\Rightarrow y(x+1)= \frac{1}{1} \newline
2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \newline
3.\Rightarrow x+1 = \frac{1}{y} \newline
4.\Rightarrow x=\frac{1}{y}-1 \newline
\therefore f^{-1}(x)=\frac{1}{y}-1 \newline
\newline
\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$

[ocean seal]

roxyit

[undone lantern]

yeah lmao

ok it worked

finally

aparently you cant use spaces just after $

[left frigate]

ahh

[undone lantern]

and you cant use _ in \text

latex is weird

[ocean seal]

SippieSpoonWoon
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[left frigate]

ughhh

[undone lantern]

what happened

you forgot the $$ here

$test

hi

bye$

[ocean seal]

roxyit
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[undone lantern]

much better than \newline

omg

[left frigate]

$$\text{Need Halp. Question is:}$$\newline
$$\text{determine the inverse for;}$$\newline
$f(x)= \frac{1}{x-1} \newline
\newline$
$$\text{I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.}$$
$\newline
\newline$
$$\text{Method1:}$$
$\newline$
$f(x)= \frac{1}{x-1} \newline
\Rightarrow \frac{1}{y}= \frac{x-1}{1} \newline
\Rightarrow \frac{1}{y}+1 = \frac{x}{1} \newline
\therefore f^{-1}(x)=\frac{1}{y}+1 \newline
\newline$
$$\text{Method 2:}$$
$\newline
f(x)= \frac{1}{x-1} \newline
1.\Rightarrow y(x+1)= \frac{1}{1} \newline
2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \newline
3.\Rightarrow x+1 = \frac{1}{y} \newline
4.\Rightarrow x=\frac{1}{y}-1 \newline
\therefore f^{-1}(x)=\frac{1}{y}-1 \newline
\newline$
$$\text{Problem:}$$
$\newline
\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$

[ocean seal]

SippieSpoonWoon

[left frigate]

ahhhhh okok so text has to be wraped with $$ then you have to wrap math notation with single $
so $$text$$ $math$
not $ $text$ math $

[ocean seal]

SippieSpoonWoon
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[undone lantern]

$\text{Need Halp. Question is:}

\text{determine the inverse for;}

f(x)= \frac{1}{x-1}

\text{I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.}

\text{Method1:}

f(x)= \frac{1}{x-1}

\Rightarrow \frac{1}{y}= \frac{x-1}{1}

\Rightarrow \frac{1}{y}+1 = \frac{x}{1}

\therefore f^{-1}(x)=\frac{1}{y}+1

\text{Method 2:}

f(x)= \frac{1}{x-1}

1.\Rightarrow y(x+1)= \frac{1}{1}

2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big)

3.\Rightarrow x+1 = \frac{1}{y}

4.\Rightarrow x=\frac{1}{y}-1

\therefore f^{-1}(x)=\frac{1}{y}-1

\text{Problem:}

\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$

[ocean seal]

roxyit

$\text{Need Halp. Question is:}

\text{determine the inverse for;}

f(x)= \frac{1}{x-1} 


\text{I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.}


\text{Method1:}


f(x)= \frac{1}{x-1} 

\Rightarrow \frac{1}{y}= \frac{x-1}{1}

\Rightarrow \frac{1}{y}+1 = \frac{x}{1}

\therefore f^{-1}(x)=\frac{1}{y}+1 


\text{Method 2:}

f(x)= \frac{1}{x-1}

1.\Rightarrow y(x+1)= \frac{1}{1}

2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow  \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) 

3.\Rightarrow x+1 = \frac{1}{y}

4.\Rightarrow x=\frac{1}{y}-1

\therefore f^{-1}(x)=\frac{1}{y}-1


\text{Problem:}

 \big(f^{-1}(x)=\frac{1}{y}-1  \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.58 
     
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.```

[undone lantern]

I dont think you need $$ for every text

it should work fine without it

[left frigate]

hmmmm

why did it compile 'f(x)=\frac{1}{x-1}' wrong

[undone lantern]

no idea

$\text{Need Halp. Question is:}

\text{determine the inverse for;}$

$f(x) = \frac{1}{x-1}

\text{I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.}

\text{Method 1:}

f(x)= \frac{1}{x-1}

\Rightarrow \frac{1}{y}= \frac{x-1}{1}

\Rightarrow \frac{1}{y}+1 = \frac{x}{1}

\therefore f^{-1}(x)=\frac{1}{y}+1

\text{Method 2:}

f(x)= \frac{1}{x-1}

1.\Rightarrow y(x+1)= \frac{1}{1}

2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big)

3.\Rightarrow x+1 = \frac{1}{y}

4.\Rightarrow x=\frac{1}{y}-1

\therefore f^{-1}(x)=\frac{1}{y}-1

\text{Problem:}

\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$

[ocean seal]

roxyit

$\text{Need Halp. Question is:}

\text{determine the inverse for;}$

$f(x) = \frac{1}{x-1} 


\text{I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.}


\text{Method 1:}


f(x)= \frac{1}{x-1} 

\Rightarrow \frac{1}{y}= \frac{x-1}{1}

\Rightarrow \frac{1}{y}+1 = \frac{x}{1}

\therefore f^{-1}(x)=\frac{1}{y}+1 


\text{Method 2:}

f(x)= \frac{1}{x-1}

1.\Rightarrow y(x+1)= \frac{1}{1}

2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow  \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) 

3.\Rightarrow x+1 = \frac{1}{y}

4.\Rightarrow x=\frac{1}{y}-1

\therefore f^{-1}(x)=\frac{1}{y}-1


\text{Problem:}

 \big(f^{-1}(x)=\frac{1}{y}-1  \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.58 
     
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.```

[left frigate]

whoa

[undone lantern]

$\text{Need Halp. Question is}

\text{determine the inverse for}$

$f(x) = \frac{1}{x-1}

\text{I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.}

\text{Method 1}

f(x)= \frac{1}{x-1}

\Rightarrow \frac{1}{y}= \frac{x-1}{1}

\Rightarrow \frac{1}{y}+1 = \frac{x}{1}

\therefore f^{-1}(x)=\frac{1}{y}+1

\text{Method 2}

f(x)= \frac{1}{x-1}

1.\Rightarrow y(x+1)= \frac{1}{1}

2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big)

3.\Rightarrow x+1 = \frac{1}{y}

4.\Rightarrow x=\frac{1}{y}-1

\therefore f^{-1}(x)=\frac{1}{y}-1

\text{Problem}

\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$

[ocean seal]

roxyit
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[undone lantern]

aaaaa latex eats my brain

php is better than latex at this point

[left frigate]

this is like my 2nd day using latex

never used php

[undone lantern]

$\text{Need Halp. Question is}

\text{determine the inverse for}$

$f(x) = \frac{1}{x-1}

\text{I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.}

\text{Method 1}$

$f(x)= \frac{1}{x-1}

\Rightarrow \frac{1}{y}= \frac{x-1}{1}

\Rightarrow \frac{1}{y}+1 = \frac{x}{1}

\therefore f^{-1}(x)=\frac{1}{y}+1

\text{Method 2}$

$f(x)= \frac{1}{x-1}

1.\Rightarrow y(x+1)= \frac{1}{1}

2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big)

3.\Rightarrow x+1 = \frac{1}{y}

4.\Rightarrow x=\frac{1}{y}-1

\therefore f^{-1}(x)=\frac{1}{y}-1

\text{Problem}

\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$

[ocean seal]

roxyit

$\text{Need Halp. Question is}

\text{determine the inverse for}$

$f(x) = \frac{1}{x-1} 


\text{I did it 2 ways, I'm pretty sure method 1 is the correct answer but I don't know where I went wrong on method 2.}


\text{Method 1}$


$f(x)= \frac{1}{x-1} 

\Rightarrow \frac{1}{y}= \frac{x-1}{1}

\Rightarrow \frac{1}{y}+1 = \frac{x}{1}

\therefore f^{-1}(x)=\frac{1}{y}+1 


\text{Method 2}$

$f(x)= \frac{1}{x-1}

1.\Rightarrow y(x+1)= \frac{1}{1}

2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow  \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) 

3.\Rightarrow x+1 = \frac{1}{y}

4.\Rightarrow x=\frac{1}{y}-1

\therefore f^{-1}(x)=\frac{1}{y}-1


\text{Problem}

 \big(f^{-1}(x)=\frac{1}{y}-1  \big) \neq \big(f^{-1}(x)=\frac{1}{y}-1 \big)$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.58 
     
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.```

[undone lantern]

ive been using it for a year but still fucking it up 😩

[undone lantern]

same

lmao

but php is infamous for sucking

[left frigate]

1 sec lemme try an rewrite this

[undone lantern]

where is the missing $ 😭 at least tell me that

[left frigate]

$\text{Need Halp. Question is:}$
$\newline$
$\text{determine the inverse for;}$

$\newline
f(x)= \frac{1}{x-1} \newline
\newline$

$\text{I did it 2 ways, I'm pretty sure method 1 is the correct answer}$
$\newline$
$\text{but I don't know where I went wrong on method 2.}$

$\newline
\newline$

$\text{Method 1:}$

$\newline
f(x)= \frac{1}{x-1}
\newline
\Rightarrow \frac{1}{y}= \frac{x-1}{1}
\newline
\Rightarrow \frac{1}{y}+1 = \frac{x}{1}
\newline
\therefore f^{-1}(x)=\frac{1}{y}+1
\newline
\newline$

$\text{Method 2:}$
$\newline
\newline
f(x)= \frac{1}{x-1}
\newline
1.\Rightarrow y(x+1)= \frac{1}{1}
\newline
2.\Rightarrow \big( \frac{y}{1} \cdot \frac{x+1}{1} = \frac{1}{1} \big)\rightarrow \big(\frac{y}{y} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \rightarrow \big(\frac{1}{1} \cdot \frac{x+1}{1} = \frac{1}{y}\big) \newline
3.\Rightarrow x+1 = \frac{1}{y}
\newline
4.\Rightarrow x=\frac{1}{y}-1
\newline
\therefore f^{-1}(x)=\frac{1}{y}-1
\newline
\newline$
$\text{The Problem:}$

$\newline
\big(f^{-1}(x)=\frac{1}{y}-1 \big) \neq \big(f^{-1}(x)=\frac{1}{y}+1 \big)$

[undone lantern]

nice

no errors

[left frigate]

FINALLY

[undone lantern]

GG

[left frigate]

I AM GODDDDD

[undone lantern]

took forever~~~~

[left frigate]

wait

yeah just saw that

wtf

[undone lantern]

forgot a \

easy fix though

welp I'm gonna crash for today, if you need help with math/latex feel free to dm me :)

[left frigate]

ahhhh

[ocean seal]

SippieSpoonWoon

[left frigate]

i still need the problem solved tho

[undone lantern]

which problem?

[left frigate]

thats the reason im here xd

read the prompt xd

[undone lantern]

ah

one sec

this step

when you cross multiplied

[left frigate]

ohhh... when movin 'x-1' to the other side, it stays x-1 doesnt it

[undone lantern]

yeah it stays x-1

[left frigate]

i seeee

[undone lantern]

yup

[left frigate]

what does cross multiplied mean

[undone lantern]

when you have
$\frac{a}{b} = \frac{c}{d}$
you can directly write
$ad = bc$

[ocean seal]

roxyit

[undone lantern]

that's cross multiplication

the denominators go to numerators of the other side

its just merging 2 elementary steps into 1

[left frigate]

$\text{So it should be:}$
$\newline
f(x)= \frac{1}{x-1}
\newline
1.\Rightarrow y(x-1)= \frac{1}{1}
\newline$
$\text{Not:}$
$\newline
f(x)= \frac{1}{x-1}
\newline
1.\Rightarrow y(x+1)= \frac{1}{1}$

[ocean seal]

SippieSpoonWoon

[undone lantern]

Yes that's correct

[left frigate]

wait so what did i do wrong with cross multiplication

OHHH

i read it wrong

[undone lantern]

you changed - to +

[left frigate]

im dumb

i thought you said 'you cross multiplied' but you said 'when you cross multiplied'

thnx for your help ❤️

[undone lantern]

ah np all good

good luck

you taking calculus?

[left frigate]

wait ur pre uni?

[undone lantern]

techically yeah

im going into uni this year tho

[left frigate]

no, im taking grade 11 functions. I'm going to be taking calc and advanced functions soon

i want to get into chem engineering

[undone lantern]

results for 12th grade aren't out yet

[left frigate]

GOOD LUCK

I'm going to finish gr12 next year

[undone lantern]

woah nice, I want to get into CS engineering

[left frigate]

computer science?

[undone lantern]

thanks :)

[undone lantern]

yep

[left frigate]

isnt that just computer engineering?

[undone lantern]

yeah some people call it CSE here

[left frigate]

I'm bent on whether I want to take a chem+bio engineering dual degree or a chem engineering + computer tech dual

[left frigate]

ah ok

[undone lantern]

hmm both are cool, although i'd take computer any day over bio

[left frigate]

computer tech can be learned easy outside of uni so bio probably better

[undone lantern]

thats true too

uni computer stuff just gets outdated every year

lmao

they cant keep up

[left frigate]

not really worth paying for uni when you can just learn it outside of uni, and your portfolio is more credible than your degree in computer tech

[undone lantern]

yeah agreed

[left frigate]

bio it is i guess

[undone lantern]

mhm

[left frigate]

but i kinda hate bio

i cant remember nomenclature

[undone lantern]

I like bio but I hate learning stuff (like mugging up names)

IKR

💀

[left frigate]

i literally cant remember people names .-.

how do i do science names

[undone lantern]

mhm

yeah thats why I didnt take bio after 10th grade

[left frigate]

welp gn, you said u need sleep, ill let you go

tyvm

.close

[lone heart]

Channel closed

Closed by @left frigate

Use .reopen if this was a mistake.

[undone lantern]

yeah

👋

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe ruin]

dad's and mom's ages are directly proportional with 9 and 8 and it was inversely proportional with 6 and 7 8 years ago ,what is dad's age

[subtle birch]

Let current age of dad be x and currenr age of mom be y

So x/y=9/8

And x-8/y-8=7/6

Simply solve them

[severe ruin]

oh thanks

.close

[lone heart]

Channel closed

Closed by @severe ruin

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[alpine sable]

.close

.close

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strange rampart]

Hello, if anyone could help with this Exercise about trigonometric Functions, the exercise is to simplify

[strange rampart]

https://media.discordapp.net/attachments/1008978533634297856/1093238728685785159/20230405_211820.jpg?width=339&height=452

[alpine sable]

Which # do you need help with?

[strange rampart]

1 and 3 if possible

[alpine sable]

have you seen these?

Oh wait. It looks like you just use the periodicity of the functions

[strange rampart]

i dont think so

[alpine sable]

for 1. You just use properties like this:
$sin(2\pi + x) = sin(x)$

[ocean seal]

hannibal

[alpine sable]

and for odd multiplicatives of pi watch out for whether the function becomes negative or not

for example:
$sin(3\pi + x) = sin(\pi + x) = -sin(x)$

capiche?

[ocean seal]

hannibal

[strange rampart]

oh ok thanks

.close

[lone heart]

Channel closed

Closed by @strange rampart

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[idle raven]

got a question is this hard to solve? can I do it just with the info on my screen?

[idle raven]

I was sick and i missed this lesson

I only have 4 questions thankfully

if anyone can help? can I just type this into a calculator or something?

[carmine reef]

you need either a table that gives z-score values or a calculator with normalcdf

[idle raven]

i have a scientific cal cassio fx one

just not sure what button/imput to press

i assume the 2nd function then something else?

@carmine reef

I found it

can I ask another question

[carmine reef]

sure

[idle raven]

omg nvm

u helped me lol

actually yeah i followed this video sorry

https://www.youtube.com/watch?v=y_HwrzT4Et4

ty again

okay wait dont go..

when its left... I use P and when its right.. I use R?

correct?

R here..

P here...?

sorry if that dosent make sense but it does ty again

closing but u helped me ty

.close

[lone heart]

Channel closed

Closed by @idle raven

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quaint compass]

hi there

[quaint compass]

Your patient was admitted to the hospital with a hacking cough, and has been diagnosed with a severe fungal lung infection. The antifungal medication, Diflucon (fluconazole), has been ordered. The initial medication order is:

IV Loading dose 12 mg per kg. The recommended rate of infusion is 200 mg/hr.
The patient weighs 183.4 Lbs
The pharmacist delivers 1,000 mg of the medication in a bag of 500 mL of NS.
At what rate will you set the pump to deliver the dose of medication?

I need some help with med cal homework

i am a nursing student

[ocean hawk]

well you first half to convert the pt's weight into Kg, to get the loading dose

is "loading dose" the total amount you put into the IV?

[quaint compass]

thank you

heres my work if you dont mind

(500ml/100mg) x 200mg/hr = 100ml/hr

1000mg/200mg/hr = 5

500ml / 5 = 100ml

[ocean hawk]

in the first equation, should it be (500 ml / 1000 mg)?

[quaint compass]

yes, thank you .

i miss typed

the equation should equal as if it were 1000

[ocean hawk]

so it looks like the answer should be 100 ml / h

[quaint compass]

should be?

i am a nursing student learning dosage calculations

Your patient experienced a narcotic overdose and is experiencing respiratory depression.

· A naloxone infusion is ordered to be delivered over 6 hours at 0.03 mg per hr.

· The medication comes in vials with a concentration of 0.4 mg of naloxone in one mL of sterile water.

· Directions state that 2 mg of the medication must be diluted in 500 mL NS or D5W.

After you prepare the medication, at what rate in mL/hr will you set the intravenous infusion pump for delivery of the medication delivery?

Round your answer to the nearest 10th (one decimal point). Be sure to include the correct units of measurement in your answer.

heres another

[ocean hawk]

yes, i mean the math checks out

[quaint compass]

Your patient experienced a narcotic overdose and is experiencing respiratory depression.

· A naloxone infusion is ordered to be delivered over 6 hours at 0.03 mg per hr.

· The medication comes in vials with a concentration of 0.4 mg of naloxone in one mL of sterile water.

· Directions state that 2 mg of the medication must be diluted in 500 mL NS or D5W.

After you prepare the medication, at what rate in mL/hr will you set the intravenous infusion pump for delivery of the medication delivery?

Round your answer to the nearest 10th (one decimal point). Be sure to include the correct units of measurement in your answer.

ANSWER = 7.5ml/hr

?

where are my atist?

i need your help my math frends

or at least make sure my answers are correct

Your patient arrives in the Emergency Department in hypovolemic shock. His blood pressure is dangerously low.

· The physician orders dopamine HCl infusion 3 mcg per kg per minute.

· The patient’s weight: 82 kg.

· The medication comes in a concentration of 200 mcg in 250 mL of NS.

At what rate in mL/hr will you set the infusion pump to deliver the medication?

Round your answer to the nearest 10th (one decimal point). Be sure to include the correct units of measurement in your answer.

for real need help on this one

246 x 3mcg = 738mcg/min

72ml/hr

?

done

.d

.f

.close

[lone heart]

Channel closed

Closed by @quaint compass

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spark berry]

(i hope this is the right place for this question. Please let me know otherwise)

You have this graph. https://cdn.discordapp.com/attachments/481923623024853003/1093266890308202628/IMG_20230405_2210032.jpg
Given a sequence A consisting of 1s and 0s, you can traverse this graph from any start node and reach an end node. For example, if A = 101, then from node 00 you will reach node 21 (going from 00 to 10, then to 20, and finally to 21).

Prove the following:

a) For any given sequence A: if you start in two different start nodes and traverse the graph using the same sequence A, you can never reach the same end node.

b) For any given sequence A of odd length, define B as !A, i.e. B is a sequence of the same length as A, but B is 1 wherever A is 0 and vice versa. Then the sequence ABA, starting from node 00, always end up in one of the nodes 20, 21 or 22.

c) For any given sequence A of odd length, define ABA like in b), and assume that all graph traversals will start in node 00. Then if A ends in nodes 00, 01 or 02, then ABA will end in node 20. Similarly, if A ends in nodes 10, 11 or 12, then ABA will end in node 21. Finally, if A ends in nodes 20, 21 or 22, then ABA will end in node 22.

Note: I have proven a) and b), but I'm struggling with c). I'm happy to share my solution if requested by the helper.

[lone heart]

@spark berry Has your question been resolved?

[slate monolith]

#competition-math #combinatorial-structures

[lone heart]

@spark berry Has your question been resolved?

[lone heart]

@spark berry Has your question been resolved?

Channel closed

Closed by @spark berry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oak walrus]

Reaching out to discuss a chain of calculations that i am getting a NaN value for somewhere

[oak walrus]

The calculations are as follow

[outer lark]

no idea to the context of this! But try taking the absolute value of the stuff you're throwing into the log functions,

[oak walrus]

Thank you… I am on mobile but will refine and reopen this ticket with more context I suppose!

When I get back home

Appreciate the advise

Can close this one for now

[outer lark]

did it work?

it might change the intended functionality

[outer lark]

.close

[lone heart]

Channel closed

Closed by @outer lark

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oak walrus]

I’ll try at home but thanks mate, do you have python knowledge? I might show you the full thing if so

[outer lark]

yes, if you're finding regression and don't NEED or want to do it yourself, quite a few libraries exist

[lone heart]

@oak walrus Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[red hollow]

Can someone see if I did this right

[placid zinc]

You have
3(3) + 3(5)

You actually want
3(5) - 3(3)

[red hollow]

I was very confused on the ending haha

[placid zinc]

Question is not actually asking you to carry out any integrals though

[red hollow]

I see so it would be -6

[placid zinc]

Sorry, I made a mistake. See my edit.

[red hollow]

Wait so is this whole process wrong

[red hollow]

Ahh I see

So 6

[placid zinc]

Yep. Draw the graphs, interpret the integral as areas, but compute those areas geometrically

[red hollow]

Would it not be possible this way?

Is it possible if you show me what you mean?

[placid zinc]

What's "it"?

[red hollow]

I don’t understand

<@&286206848099549185>

[placid zinc]

Not certain what your question is, at this point

[red hollow]

Can you link me to a video so I can follow steps

I don’t understand how to do it the way you tried explaining it

[placid zinc]

Here's one off Google that finds the area under a curve geometrically:
https://youtu.be/1Mp8Cxk-G7Y

[red hollow]

Wait so my first calculation I use none of that?

[placid zinc]

The work you showed at first does not solve the integral by interpreting it as areas

It does solve the integral, though!

[red hollow]

I’m sorry haha my prof has no examples of this so it’s kind of confusing lol

I tried watching the video I’m confused even more

Tbh 😂

[red hollow]

Would it be possible if you show me it like the actually way that she wants it

[lone heart]

@red hollow Has your question been resolved?

[red hollow]

@placid zinc wait so would the answer be

6

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[red hollow]

.reopen

[lone heart]

✅

[alpine sable]

,,\int_{a}^{b} f(x) \text{dx} = F(b) - F(a)

[ocean seal]

!Kiz__

[alpine sable]

You added instead of subtracting

[red hollow]

But the dude just said do this?

[red hollow]

Wait what am I supposed to subtract?

[alpine sable]

?

[red hollow]

Didn’t I subtract?

[alpine sable]

you did for the right one

not the left one

oh actually you did yeah

[red hollow]

Lmao

[alpine sable]

You didn't above though

[red hollow]

So is wrong

It

[alpine sable]

.

[red hollow]

Ik not the way but the answer

[alpine sable]

This is okay i mean you did "solve" the problem via integration

[red hollow]

I see

Tysm

[alpine sable]

You're also supposed to geometrically show it though

[red hollow]

True I’ll look into it more

[alpine sable]

Dismissing the ugly shading

You're supposed to interpret this as an integral and show that the orange and green triangle is equivalent thus leaving you only with the red area to work with

area of that triangle is 3 *2 = 6

which is what you had but you should probably break it down to three parts to geometrically show it instead of numerically solving it

[lone heart]

@red hollow Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jolly isle]

The chef has 50 pounds of strip loin. The trim loss on the strip loin is 60% and the cooking loss is 20%
of the trimmed weight. How many pounds of trimmed, cooked strip loin will the chef have left to serve
to his customers?

[slender quiver]

!status

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[jolly isle]

2

[slender quiver]

can you show your work

[jolly isle]

I use this thing called the PAW method

P for percent

A for part

W for whole

50 pounds is the whole

but 60% and 20%

would it be like solving it in 2 parts?

[slender quiver]

well you can add both of the percents

[jolly isle]

oh

wait

Can I try it and get back to you?

[slender quiver]

ig

[jolly isle]

is the answer 40?

[gray isle]

no

[jolly isle]

I did this

x/50 = 80/100

cross multiply them

4000/100 = 100x/100

40 = x

[gray isle]

you didn't make any calculations related to trim

[jolly isle]

oh

how do I do this because I am very confused now

I did 80/100 because the other guy said to add the percents

[gray isle]

as you first thought, split this into two parts

first consider how much you have left after trim

[slender quiver]

mb

[gray isle]

and from that, how much you have left after cooking

[jolly isle]

so I was doing it right ;-;

[gray isle]

or if you're being efficient, that can be done in a single step

[jolly isle]

no I'm just doing it the way my teacher showed us

part/whole = percent/100

[jolly isle]

how can it be done in a single step though?

[gray isle]

try do it the way you've been taught first and I'll show you after

[jolly isle]

ok

ok so I did it in 2 parts

for 60 I got 30 = x

and for 20

10 = x

now what?

[gray isle]

how are you getting that last part

[jolly isle]

wdym

[gray isle]

wdym

for 20
10=x
where's that coming from

[jolly isle]

cuz it's

x/50 = 20/100

cross multiply

and divide 100 on both sides

[gray isle]

but you're forgetting about the trim again

[jolly isle]

20 is the trim

[gray isle]

no?

[jolly isle]

...

what's the trim

[gray isle]

the trim loss is 60% of what you originally had

[jolly isle]

so what do I do with 20

[gray isle]

misinterpreted what you meant

20 is what you have left over after trimming.

[jolly isle]

OH

[gray isle]

and you determine how much you have left after cooking based on that

[jolly isle]

Ok ok ok

so

still confused

[gray isle]

you've done the first part of the problem so you can put that aside

you now have 20 pounds of meat

you lose 20% of that from cooking

how much would you have left after cooking

[jolly isle]

20 - 50?

[gray isle]

no forget about the 50 that's irrelevant now

focus only on what i've just said

the exact same principle/formulae apply

[jolly isle]

so I minus

20%

?

from

x?

[gray isle]

you minus 20% of 20pounds from 20pounds

[jolly isle]

sorry My 3 braincells aren't linking up rn

I haven't eaten all day

[jolly isle]

4 - 20?

[gray isle]

no

[jolly isle]

16

[gray isle]

from, not by

20 - 4

= 16

[jolly isle]

oh

ok

thank you so much ^^

[gray isle]

part/whole = percent/100
a more efficient form would be
part = whole * percentage/100

[jolly isle]

oh

[gray isle]

note that losing 60%, you'll have (100-60)/100 = 40/100
of what you had
similarly losing 20%, you'll have 80/100 of what you had

so you can do
50 * 40/100 * 80/100
(where the bolded part gives the amount after trimming)

[jolly isle]

tysm ^^

[lone heart]

@jolly isle Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lunar lintel]

is this correct

[whole shell]

firstly no

secondly

just divide by ke^rx

after this line

[lone heart]

@lunar lintel Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tribal cosmos]

what does 3 vertical lines mean in maths?

[tribal cosmos]

like this

[real gazelle]

Okay you should be able to post the image here I think

[tribal cosmos]

idk if thats a thing

or not

im confused

[real gazelle]

Oh weird, I've never seen that before, but maybe it means congruent to? like
[\triangle ATC \cong \triangle AMD]

[ocean seal]

mollifiERIC

[real gazelle]

Does that make sense from context

[tribal cosmos]

yea kinda

thanks

[real gazelle]

np! the other guess I would make is that the two triangles are similar?

[\triangle ATC \sim \triangle AMD]

[ocean seal]

mollifiERIC

[tribal cosmos]

yea i was thinking that

[real gazelle]

Can you post more

Maybe the logical reasoning surrounding it will help

[tribal cosmos]

basically from that

[real gazelle]

ohh okay

it's definitely that they're similar then

[tribal cosmos]

oh ok

thanks

[real gazelle]

no problem!

.close

[lone heart]

Channel closed

Closed by @real gazelle

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

i need help with this

[azure harbor]

Hi

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

hi @azure harbor

[azure harbor]

Can u help me

It’s simple

[alpine sable]

4 a b or 5?

@azure harbor

[azure harbor]

B a 500

^2

[alpine sable]

it should be 100cm^2

.close

[lone heart]

Channel closed

Closed by @pastel dust

Use .reopen if this was a mistake.

[alpine sable]

.reopen

[lone heart]

✅

[alpine sable]

.close

[lone heart]

Channel closed

Closed by @pastel dust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ionic sail]

Help please

[ionic sail]

<@&286206848099549185>

[lone heart]

@ionic sail Has your question been resolved?

[ionic sail]

<@&286206848099549185>

I think this is right but it does mention matrices so I wonder if I need to use matrices to get the answer knstead? <@&286206848099549185>

[lone heart]

@ionic sail Has your question been resolved?

[open fern]

,rotate

[ionic sail]

<@&286206848099549185>

[lone heart]

@ionic sail Has your question been resolved?

[gaunt leaf]

Triangle ABC, E on AB, D on BC side, F on AC side, known as 3AE=AB, 2AF=AC, 4BD=BC, EC intersects AD at point G, BF intersects AD at point L, BF intersects EC at point H, S triangle ABC=1, find the area of triangle GHL

[ionic sail]

What?

I’m not finding a triangle

I’m doing matracies

<@&286206848099549185>

[lone heart]

@ionic sail Has your question been resolved?

[tawny sorrel]

your method is basically what the matrix multiplication does

if u write a 3x3 matrix with the shoes table

then multiply it with the 3x1 table of the price

you end up with a 3x1 table of the total prices for each type of shoe

then u just add those numbers up

which is basically what u have done, just not using matrices

[lone heart]

@ionic sail Has your question been resolved?

[gloomy pine]

Translate:
In which case the interval [–3; 1) correctly represented on the coordinate line?

[warped tinsel]

C

[ means 3 is included and ) means -1 is excluded

[gloomy pine]

@warped tinsel
Given the inequality –3 < –1. Write the inequality that we get:
a) both its sides multiplied by 4;

b) both sides are divided by -1

So like a) would be -12 < -4? right?

[warped tinsel]

yup

[gloomy pine]

Find the largest integer value of y for which the value of the expression −y3+200 is positive?
I wrote: 600

[warped tinsel]

is it y.3 or y^3?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm tundra]

,f^{-1}(x-8)^{3}

[storm tundra]

,lex f^{-1}(x-8)^{3}

,lax f^{-1}(x-8)^{3}

,list

[ocean seal]

My commands!

Use ,ls to obtain a briefer listing, and use ,help <cmd>to view detailed help for a particular command, or ,help to view general help.

If you still have questions, talk to our friendly support team here.

LaTeX Rendering

Render LaTeX code and configure rendering options.
​ ​ ​ ​ ​ ​ ​ ​ ​ ​ tex: Render LaTeX code.
​ ​ ​ ​ ​ ​ ​ ​ ​ ctan: Searches the ctan
​ ​ ​ ​ ​ ​ ​ texdoc: Searches the texdoc
​ ​ ​ ​ ​ ​ autotex: Toggle whether your LaTeX is automatically rendered.
​ ​ ​ ​ ​ preamble: View or modify your LaTeX preamble.
​ ​ ​ ​ texconfig: View or modify your personal LaTeX rendering options.
guildpreamble: View or modify the guild's default LaTeX preamble

Guild Admin

Guild administration
​ ​ ​ ​ ​ ​ ​ ​ config: View and set the guild configuration.
​ ​ ​ ​ ​ ​ ​ ​ rmrole: Deletes the provided role
​ ​ ​ ​ ​ ​ ​ disable: Disable commands in this guild.
​ ​ ​ ​ ​ ​ editrole: Create or edit a server role.
​ ​ ​ ​ ​ autoclean: Automatic deletion of messages in the current channel.
forgetrolesfor: Forget stored persistent roles for one or all members.

Page 1/4

[storm tundra]

,tex f(x)=\sqrt[3]{x}+8

[ocean seal]

J64n
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[storm tundra]

if the domain for that function is 1 between 1 and 1000

how would i find the domain of the inverse?

,tex f^{-1}(x)=(x-8)^{3}

[ocean seal]

J64n
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[lone heart]

@storm tundra Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[barren scroll]

i dont understand how to solve this

can someone explain how to get the answer of just "x"

[coral thorn]

what are you trying to find

[barren scroll]

ive written out the bottom as (2 sqrt x)^1

and the top as (2 sqrt x)^3

im simplifying

im not sure how to get to just an x though

[coral thorn]

you can just take the bottom x to the top then add the exponents

[slender quiver]

hint convert the exponents into one

[slender quiver]

subtract*

[coral thorn]

i mean

[barren scroll]

how does this work

[coral thorn]

same thing

[barren scroll]

ill take a pic pf my work

[coral thorn]

it goes to the top, -ve

[barren scroll]

here

is it actually just x/x

which is my guess

what does that ^3 and the ^1 indicate

[slender quiver]

something is 100% wrong with the 3rd step

[barren scroll]

im guessing thats what happened

yup

is it a misunderstanding of exponent rules?

[slender quiver]

ok mutliply everything by x^1/2

[vale wigeon]

yes

or rather, a misconception that those square roots are somehow cancellable.

[barren scroll]

how should i be proceeding

in situations like these

[slender quiver]

just subtract the bottom from the top

[barren scroll]

but that's still

x^2

[slender quiver]

?

[coral thorn]

3/2 - 1/2

[slender quiver]

x^3/2 - x^1/2 = x^2/2

[barren scroll]

2/2=1

so it's just x

when

x/x = x

[slender quiver]

x^1 = x

[barren scroll]

and the exponent is x^1=x

[slender quiver]

?

[barren scroll]

ohhh

like

the 2 x's

when u do x divided by x u get x

or 1x^1

im j overcomplicating it

but

i get it

how could i have solved it the way i did though

initially

if it's ok to do it that way

without a calculator

[slender quiver]

eyah

[barren scroll]

how should i have done it

[slender quiver]

you subtract tboth exponents

in the 2nd step

[barren scroll]

isn't it just

x^2 still

even if u did that

bc

(2 sqrt x)^2

that's just square rooting x to get just x and then adding on the 2

to get x^2

[slender quiver]

where did you get the first 2

[barren scroll]

just rwrote it

rewrote it

according to epxonent rules

[slender quiver]

(√x)^(3-1) = √x^2

they cancel so

ye

[lone heart]

@barren scroll Has your question been resolved?

[barren scroll]

what does that mean @slender quiver

explain with the notation maker thingy if u can

keyboard is hard to translate

[slender quiver]

√ = sqaure root

idk

[slender quiver]

sorry don't know latex

[barren scroll]

can anyone here help us out

[slender quiver]

what

do you want

[barren scroll]

just writing it out

[ocean hawk]

what is your question?

[barren scroll]

i don’t understand

can u help us write out the solution to this

that first rey’s to on

[slender quiver]

answer is x

[barren scroll]

the same why i did it here

i know i could’ve just subtracted the exponents

but i’m curious to see how it could be solved if i did it this way too

[ocean hawk]

$x^{3/2} = \sqrt{x^3}$, no?

[ocean seal]

cwatson

[slender quiver]

thats the point

[ocean hawk]

where's the confusion coming from? just subtract exponents, right?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prisma frost]

<@&286206848099549185>

[frozen dove]

6^9

[frozen dove]

5^-6

[fierce prairie]

!nosols

[lone heart]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[frozen dove]

Ohhh ok got it

[prisma frost]

bruh

[frozen dove]

Thanks for reminding

[prisma frost]

i jst want the anwser smh

[fierce prairie]

it's better to learn it so you don't fail your test

lol

just saying

[prisma frost]

true but

im tryna get this over with

anyways can i get sum help

[fierce prairie]

you would want to divide the number of debit card customers by the total customers

that's the probability

[prisma frost]

i alr got that one wrong

im on this now

[fierce prairie]

are you just guessing?

[prisma frost]

no i tried but i got it wrong

[fierce prairie]

well let's start with the parentheses

4^0 is obviously 1

so the whole numerator is 1

can you solve $\frac{1}{4^{-3}}$?

[ocean seal]

Kihei

[prisma frost]

how the hell do u solve that💀

[coral thorn]

its basically 4^3

[prisma frost]

uh huh

[coral thorn]

bruh

try harder

[fierce prairie]

for negative exponents

[prisma frost]

…

[coral thorn]

else youll fail your finals

[fierce prairie]

simply move it to the numerator

if it's in the denominator

and vice versa

[prisma frost]

im literally asking for help on DISCORD. obviously im seeking help.

[coral thorn]

but are you learning anything

[prisma frost]

im trying to read what this persons saying but you wont stfu they were teaching me

so can u go

[fierce prairie]

just ignore them lol

[prisma frost]

ok

[ocean seal]

Kihei

[fierce prairie]

does this sound familiar?

(a and n are just random numbers)

[prisma frost]

no

[rocky grove]

Hmm

[fierce prairie]

well this is an exponent rule

[prisma frost]

yea i forgot abt those

[rocky grove]

Are you familiar with multiplying by fractions?

[prisma frost]

yes

i think so

[rocky grove]

$\frac 15 \times \frac 25$

[ocean seal]

VulcanOne

[prisma frost]

dont i just times on top and bottom??

[rocky grove]

Yep

[prisma frost]

but why am i doing this

[rocky grove]

I'm just checking your skills so that we can bridge it to the exponent rules

[prisma frost]

ok

so now what

[rocky grove]

Now suppose we wanna divide by 5^5

[prisma frost]

by what

[rocky grove]

Just in general

[prisma frost]

what..

[rocky grove]

Let's say we will divide 16 by 5^5

[prisma frost]

ok

[rocky grove]

What will the answer to that look like?

16/(5^5) right?

[prisma frost]

wait what

Ok

i did it

but this is what i did

i did the 5^5 and then the anwser divides by 16?

[rocky grove]

Well

[prisma frost]

idk

[rocky grove]

16 is the number that we will divide

It's called the dividend or numerator

We will divide it by 5^5

It's called divisor or denominator

[prisma frost]

Ok

[rocky grove]

So our fraction will be like

$\frac{16}{5^5}$

[ocean seal]

VulcanOne

[prisma frost]

ok

[rocky grove]

Okay?

Nice

[prisma frost]

ye

[rocky grove]

Now another example to make sure we're good

Let's say we divide 8 by 20,000

[prisma frost]

okay

[rocky grove]

How would we write it down?

[prisma frost]

8/20,000?

[rocky grove]

Yep

[prisma frost]

mhm

[rocky grove]

Great :)

[prisma frost]

:)

[rocky grove]

If you notice though, 20,000 is quite a big number

[prisma frost]

Yes

[rocky grove]

We need to short hand it and also we don't wanna write fractions every time

But we wanna express the fact that we are dividing by 20,000

[prisma frost]

Yea

[rocky grove]

So first let's remember that

[prisma frost]

my thing is written down tho?

[rocky grove]

We can express numbers as factors

It's a bit unclear

But I think it is

$\frac{(4^0)^{-3}}{4^{-3}}$

[ocean seal]

VulcanOne

[rocky grove]

Right?

[prisma frost]

yes

[rocky grove]

Okay

Could we go back to our example before we tackle this though?

[prisma frost]

ok

[rocky grove]

I wanna lay down some ideas first

Okay so

[prisma frost]

yea

[rocky grove]

8/20,000

We wanna express 20,000 in a way that is easy to write

Could you break 20,000 down into factors?

[prisma frost]

whats factors

[rocky grove]

Factors that if we multiplied together, we get 20,000

Like

How we can write 8 as 2 * 2 * 2

[prisma frost]

oh

yea idk

this is stuff i learned like a while back im pretty sure

[rocky grove]

Okay

It just needs you to point out the obvious

Like

Doesn't 20,000 have a lot of zeros?

[prisma frost]

yess

😭

[rocky grove]

So that means we can divide it by 10 right?

[prisma frost]

yea

[rocky grove]

Okay

[fierce prairie]

Wait what is the point of this

There's just an exponent rule for their problem lol

[rocky grove]

Trying to reach from fractions to exponents

It's more of building on past knowledge

[fierce prairie]

I think they understand fractions but okay 😭

[rocky grove]

Well

[prisma frost]

😭

[fierce prairie]

Continue as you wish ig

[prisma frost]

🆘

[rocky grove]

Okay how many times can we divide 20,000 by 10?

[prisma frost]

ISK

IDK

[rocky grove]

Hmm

So like

4 zeros

[prisma frost]

4 times

[rocky grove]

Yep

[prisma frost]

ohhhh ok😭

can we do my thing now

[rocky grove]

[prisma frost]

🙁

[rocky grove]

We didn't get there yet

[prisma frost]

dude i have a bunch of homework to do

[rocky grove]

Negative exponents are basically a way to show that we are dividing by that number

[prisma frost]

Ok

[rocky grove]

So like

Instead of writing it as a fraction, we can write the denominator and raise it to -1 power

So in your problem

(4^0)^-3 means that you're dividing by (4^0)^3

Do you get this?

[prisma frost]

I have to go my phones gonna turn off

[rocky grove]

Oof

[prisma frost]

umm

[prisma frost]

Yea

[prisma frost]

Yea

[rocky grove]

Okay do you know how to do 4^0?

[prisma frost]

So if i stop responding u know why

dosent it turn into 1

[rocky grove]

You can't charge?

[rocky grove]

Yep

[prisma frost]

its not that

Screen time

[rocky grove]

So you're essentially dividing by 1^3

[rocky grove]

Wow. Screentime sucks

[prisma frost]

yep

[rocky grove]

Anyways

Let's do this

So

We know that the top is 1

Let's look at bottom

[prisma frost]

Uh huh

[rocky grove]

(4)^-3

Since it's in the bottom, it means we're dividing

[prisma frost]

Ok

[rocky grove]

But it has a negative power

So that means we will do the opposite of dividing

Aka multiply

So we will multiply top by (4^3)

[prisma frost]

ok

[rocky grove]

Can you do 4^3?

[prisma frost]

can i multiply 4x3…?

[rocky grove]

Nope

The 3 is a power

[prisma frost]

what

oh ok

[rocky grove]

Powers

[prisma frost]

4x4x4

[rocky grove]

4^3 = 4 * 4 * 4 yep

So that should be your answer

[prisma frost]

okay thank uuu

[rocky grove]

Small advice

[prisma frost]

i have 1 min

Ok

[rocky grove]

Practice your exponents

Please

:)

[prisma frost]

Okay 👍

thanks so much

byebyee

[rocky grove]

Good luck :)

[lone heart]

@prisma frost Has your question been resolved?

[tawdry oriole]

$$Can someone give me a 1 dollar please?$$

[ocean seal]

Noam

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mighty nimbus]

Could someone please explain ii

[pseudo ice]

if $p = 3\ln\pqty{\frac{20}{p + 3}}$, then $p - 3\ln\pqty{\frac{20}{p + 3}} = 0$ and in between 3.3 and 3.5 the function $p \mapsto p - 3\ln\pqty{\frac{20}{p + 3}}$ is continuous

[ocean seal]

@pseudo ice

[pseudo ice]

so assumedly they want you to say that because the sign changes in that interval, the solution must be there [if you've heard of it, intermediate value theorem - may not be called that yet though]

[lone heart]

@mighty nimbus Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neat sierra]

I'm trying to understand why $\sum_{I=0}^n c(n,i) = n!$ with symmetric groups

[ocean seal]

KN

[neat sierra]

where c(n,k) is the number of permutations on [n] with exactly k cycles

I know a symmetric group Sn has n! elements.

Is there some connection between these two things?

If so, what would it be?

.close

[lone heart]

Channel closed

Closed by @neat sierra

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wicked geode]

So far this is what I have

[lone heart]

@wicked geode Has your question been resolved?

[wicked geode]

anyone can help?

[lone heart]

@wicked geode Has your question been resolved?

[lone heart]

@wicked geode Has your question been resolved?

[wicked geode]

i just need an explanation on what to sub in?

[alpine sable]

@wicked geode
Is your question answered??
If not you can ping helpers

[wicked geode]

no it hasn't been asnwered yet

[alpine sable]

Okay

Ping helpers then it's been some time since you asked

<@&286206848099549185>

[wicked geode]

Thanks

[lone heart]

@wicked geode Has your question been resolved?

[wicked geode]

still struggling with the question

[wicked geode]

<@&286206848099549185>

[magic bison]

What is your question?

Tag me when you reply

[lone heart]

Channel closed

Closed due to the original message being deleted

[wicked geode]

oops

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert junco]

Let’s say we’ve gathered multiple geographical coordinates which all revolve around point A. We currently don’t know where point A is, but we do have access to coordinates and an approximate distance to point A from the given coordinate.

How could we calculate the coordinate of point A?

[mellow grail]

can u give some more data?

like names to what these coords and distances are

[desert junco]

I thought converting geographical coordinates to cartesian coordinates would be a good first step but I have no idea what to do after

The coordinates are just coordinates on a map

and each coordinate has an approximate distance to a certain point (they all point to the same point)

[mellow grail]

well, u could use the distances of two of them, and equate it

[prime badge]

assuming you can get precise cartesian 3d corrdinates, it just becomes gps

[desert junco]

one solution i thought of would be drawing circles on a map with the distance as radius and see where they are intersecting

[prime badge]

that's 2d case yes

[mellow grail]

since d = sqrt( (y2-y1)^2 + (x2-x1)^2 )

[desert junco]

the problem is, the distance to point A that comes with the coordinates is an estimate

I don't even know where to start

[desert junco]

how would that help with my problem

[prime badge]

no you already described it

i just meant that, intersection of circles, or spheres in 3d

[desert junco]

right

[prime badge]

well if they are estimates, you can plot like, washers

[desert junco]

yeah but ive been trying to solve this programatically

and i'll be honest..i suck at maths

and another thing I can't quite wrap my head around is the fact that we already have the distance but not the exact distance

this could be the data

[prime badge]

here you have 3 points, you could just average them into one

well you have 6

but it's clear which three are real

[desert junco]

right but it gets more complicated when we have like 8 inputs

and we don't always know which point to pick

i don't want to draw circles on the map you know.. im trying to find some sort of algorithm

that calculates those points

also, we'd be working with spheres instead of circles in the case of working with cartesian coordinates

.close

[lone heart]

Channel closed

Closed by @desert junco

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[latent magnet]

Guys, need a help

[latent magnet]

If AD = 120°, then AOD = 120° too?