#help-0

1 messages · Page 53 of 1

lone heartBOT
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@zenith compass Has your question been resolved?

lone heartBOT
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neon berry
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ay

lone heartBOT
neon berry
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Ima wait until someone asks me what I want

trim wagon
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okay

neon berry
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What I currently need is double checking my answers to algebraic questions

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I'm gonna just download lightshot to show them here

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The first three need to be simplified, 4th must have the root evaluated.

wanton tusk
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okie where’s ur work

neon berry
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1 sec

ornate condor
wanton tusk
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QUEEN

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<33

neon berry
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answers and solutions to questions 1 to 3

wanton tusk
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it’s blue HAHAHA

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blur

trim wagon
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how do you take so crisp quality img

wanton tusk
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omg

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android

neon berry
wanton tusk
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quality is super crisp

trim wagon
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lmfaooooo

wanton tusk
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WHA

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HAHAHHA

trim wagon
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i’m literally die hahahahha

wanton tusk
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ans to 1 is ok from what I can see

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omg

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pc camera

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HAHAHHA

neon berry
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yep

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its a laptop camera

wanton tusk
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is ur ans to 2 $(256)^{\frac{1}{8}}$

ocean sealBOT
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swaggofishballs

neon berry
wanton tusk
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simplify

neon berry
wanton tusk
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oh

fluid basin
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256 is a power of 2

wanton tusk
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ya u can still simplify

neon berry
wanton tusk
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I don’t

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um

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understand that

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is that French

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German

neon berry
fluid basin
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swedish?

neon berry
wanton tusk
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oooo

wanton tusk
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answer to 3 seems okay

neon berry
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yes I can answer it with 2

fluid basin
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256 = 2^k for some k

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you need to find that k

neon berry
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done

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Now let me show my 4th answer and solution, caught in 4k

wanton tusk
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ya

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seems okay

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but why so long

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what is the qn asking btw

neon berry
wanton tusk
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okie

neon berry
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I like being precise when it comes to solving

wanton tusk
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oh okay that’s fine

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as long as ur able to do it fast+precisely

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in the exams

neon berry
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I need to get an undergrad-level problem solving skills in order to attend undergrad courses next year

neon berry
wanton tusk
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okie that’s gd then

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btw why do u have equal signs at the end

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of each line

neon berry
wanton tusk
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presentation error

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why is my name green

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but ya ure dealing with equations

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don’t need to have that = sign

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when ure simplifying expressions

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then ya

neon berry
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If you look at the point where I eliminate the 3's, I don't put the equal signs because it would be incorrect to do that

wanton tusk
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an example

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im just saying this to be safe HAHAH bec I’ve been penalised for it before 😭

neon berry
# wanton tusk

In these cases, I'd definitely not write with equals signs

wanton tusk
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yepp! that’s gd

neon berry
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though, if I'm simplifying only one side of the equation, it should be correct when it comes to the first steps that I did

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Tomorrow I have my first math exam, I don't know what I can do further to improve

wanton tusk
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ya the steps u did are fine (:

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just the = sign

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u seem to have the knowledge so ya

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all the best ya

neon berry
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thanks

ornate condor
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@wanton tusk GREEN

wanton tusk
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GREEN

lone heartBOT
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@neon berry Has your question been resolved?

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lone heartBOT
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quartz cave
lone heartBOT
quartz cave
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I know that with the power rule, the derivative of this function should be df/dx = -1x^-2

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But how do we get there algebraically?

karmic rapids
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limit definition

lucid bridge
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first principals? f'(x) = lim h -> 0, [f(x + h) - f(x)]/h

quartz cave
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Alright but then you are left with 1/x - 1/x

mortal trellis
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No

quartz cave
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If you let the h run to 0 immediately

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There should be more steps before that right?

karmic rapids
quartz cave
karmic rapids
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if you directly substitute h as 0 you get something divided by 0

mortal trellis
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Well you can't let it run to 0 immediately. You would divide by 0

lucid bridge
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you have to "remove" the denominator before applying your limit

karmic rapids
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so you have to do other work first

lucid bridge
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simplify

quartz cave
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Alright well if I try to then I end up with (x/x(x+dx) - x+dx/x(x+dx))/dx

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Is this the moment to let dx -> 0?

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Then it would be x/x^2 - x/x^2

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Still not possible I suppose

mortal trellis
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You would still divide by 0

quartz cave
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Right so multiply the numerator by dx first?

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But then still I would run into the same problem

mortal trellis
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Oh wait you can just combine the fractions

quartz cave
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so -dx / x(x + dx)?

mortal trellis
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All over dx

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And now you can cancel the dx's

tawny condor
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Wait no

quartz cave
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How do I cancel the dxs?

tawny condor
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You forgot a dx at the bottom

quartz cave
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right right

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/dx

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This should be added my bad

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So how do I then cancel?

mortal trellis
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Well you have a dx in the numerator and in the denominator. Those cancel

quartz cave
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also I thought you could only leave out dx^2 because those are negligible not dx

quartz cave
tawny condor
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I have the full process written in latex

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do you want me to send it or you want to continue yourself?

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@quartz cave

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$$\frac{\frac{1}{x + h} - \frac{1}{x}}{h} = \frac{x}{xh(x + h)} - \frac{x + h}{xh(x + h)} = \frac{-h}{xh(x + h)} = \frac{-1}{x(x + h)}$$
$$\lim_{h \to 0} \frac{\frac{1}{x + h} - \frac{1}{x}}{h} = \lim_{h \to 0} \frac{-1}{x(x + h)} = \frac{-1}{x(x + 0)} = \frac{-1}{x^2}$$

quartz cave
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Hmm let me see

ocean sealBOT
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RedstonePlayz09

quartz cave
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So how does -h turn into -1?

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Oh I see

tawny condor
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it cancels out

quartz cave
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So this was not correct

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It should be

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(x/xdx(x+dx) - x+dx/xdx(x+dx))/dx instead of (x/x(x+dx) - x+dx/x(x+dx))/dx correct?

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Oh no I see

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In my step I leave the over dx

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But you add it to the denominator in one go do you not?

tawny condor
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In the first step, I take the h in the denominator and distribute it to the denominators of both fractions, while also making a common denominator.

quartz cave
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Multiplying by the LCD and distributing the h

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Because then I follow allong what is happening

tawny condor
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$$\frac{\frac{1}{x + h} - \frac{1}{x}}{h} = \frac{1}{h(x + h)} - \frac{1}{xh} = \frac{x}{xh(x + h)} - \frac{x + h}{xh(x + h)}$$

ocean sealBOT
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RedstonePlayz09

lone heartBOT
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@quartz cave Has your question been resolved?

quartz cave
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Now I am onto the derivative of sqrt(x)

tawny condor
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Good luck!

quartz cave
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🙏

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.close

lone heartBOT
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alpine sable
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hi, so i wanted to ask that what works interms of solving quadratic equations, for middle term do you use the lcm or another method that is other than taking lcm

alpine sable
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im currently learning the lcm one and ive entirely forgotten about another one that was without taking the lcm one

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and i find taking lcm a little harder

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for solving quadratic equations specificalli

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thanks

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lcm u mean prime factorization?

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if u find factoring tedious

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just use quadratic formula

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or just complete the square

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thats if u dont like the guessing part

alpine sable
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i wanna know which one is more preferred

manic wind
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methods of factorizing a quadratic?

alpine sable
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it just depends person to person

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sometimes its kinda hard to find two numbers which add up to something

alpine sable
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and there product is something

alpine sable
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so if u cannot do it in case

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u can always use quadratic formula

manic wind
alpine sable
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thats the last thing u wanna use

alpine sable
alpine sable
alpine sable
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well thanks

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.close

lone heartBOT
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alpine sable
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help :')) ive been trying to solve this but i keep erasing my answers because they might be wrong

lone heartBOT
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@alpine sable Has your question been resolved?

alpine sable
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i deleted them- but im rlly only struggling with finding the ratio

lone heartBOT
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@alpine sable Has your question been resolved?

alpine sable
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.close

lone heartBOT
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wispy urchin
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How do you solve these kind of problems?

lone heartBOT
tawny condor
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Divide by numerator and denominator by 4^x (for the first limit)

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Then you should be able to apply limit arithmetic.

lone heartBOT
#

@wispy urchin Has your question been resolved?

wispy urchin
#

.close

lone heartBOT
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tawny condor
#

No problem!

lone heartBOT
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lilac silo
#

Hey, I need to prove that 1-1/2+1/3-1/4+.... = ln(2) but I'm not sure where I am wrong in this

uncut torrent
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is this true?

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uh yeah it probably is nvm

vague coral
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yea its true

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but if you want to switch sum and integral, you need to prove why its possible

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Unless you are an engineer or physicist

alpine sable
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lol

lone heartBOT
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@lilac silo Has your question been resolved?

keen plinth
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it's not switched tho kekw

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just factored

lilac silo
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<@&286206848099549185>

keen plinth
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i mean

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your integral looks like its wrong

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g(0) = 1

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and now you're missing both the constant term and the x term

lilac silo
#

thanks!!

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.close

lone heartBOT
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broken beacon
#

how can I tell how many roots this equastion has?

trim wagon
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uhh sad_think

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well 8x^2 is dominating term so for very large values it will just shoot off to infinity, at least thats what i believe

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have you checked on desmos?

tawny condor
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Well, f(0) = -1

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and this function is continuous

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so you have a positive root

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and since this is an even function

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you also have a negative root

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I'm not sure how to prove these are all of the roots though

trim wagon
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hmm 🤔

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,w derivative of 8x^2 -ln(1+x^2) -cos(2x)

tawny condor
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Any inequality or equation with this will be very hard

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Well, if there are anymore roots, there must be at least 4.

trim wagon
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if we can show its derivative is positive for x> 0 and even function is then ig we should be good no?

tawny condor
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Yeah

trim wagon
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so it is monotonic?

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okay

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not ez job

carmine reef
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you mean odd function?

tawny condor
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Proving that f''(x) is positive will also work

trim wagon
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is it odd?

tawny condor
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yes f'(x) is odd

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since f(x) is even

trim wagon
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,w plot 8x^2 -ln(1+x^2) -cos(2x)

trim wagon
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i mean f(x)

carmine reef
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ah

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f(x) is even right

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for some reason i saw the ln and was like nah that's not even

trim wagon
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well even is easy to show

trim wagon
carmine reef
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i think second derivative would be useful here

trim wagon
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yes

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,w second derivative of 8x^2 -ln(1+x^2) -cos(2x)

tawny condor
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If we can show that f''(x) > 0 it would go like this:
Assume that there are more than 2 real roots, meaning there are at least 4 (since f is even).
Between the 2 positive roots and the 2 negative roots, we have a point where f'(x) = 0.
So in between those 2 points, there is a point where f''(x) = 0.
But f''(x) > 0, contradiction.

trim wagon
#

hmm

carmine reef
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$\frac{2(8x^4+17x^2+7)}{(1+x^2)^2}+4cos(2x)$

ocean sealBOT
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monikanicity

tawny condor
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We need to show that this left fraction is bigger than 4.

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Then this whole thing will be positive.

carmine reef
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Subtract a 4(1+x^2)^2 from the numerator igg

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ig

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I'll be a bit busy here

lone heartBOT
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@broken beacon Has your question been resolved?

trim wagon
#

the guy better not go afk

tawny condor
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I think he already did

broken beacon
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yeh I'm here guys

keen plinth
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use rouche's theorem kekw

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8x^2 dominates -ln(1+x^2) - cos(2x) on the boundary of the unit disc

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so they have the same number of zeroes counting multiplicity

broken beacon
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Maybe you are right about solving this problem with the theorem but it was not thought in the course this question from

carmine reef
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Don't we almost have it

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$\frac{2(6x^4+13x^2+5)}{(1+x^2)^2}+4+4cos(2x)$

ocean sealBOT
#

monikanicity

carmine reef
#

Isn't this obviously >4

trim wagon
tawny condor
#

my next stop after linear algebra is complex analysis

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or maybe I'll finish calculus first

lone heartBOT
#

@broken beacon Has your question been resolved?

lone heartBOT
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meager lotus
lone heartBOT
meager lotus
#

bruh like how tf i do this

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Special right triangle

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Solve for sides x and y

shell widget
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use sin and cos formulas

meager lotus
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ok thanks ✅

floral river
meager lotus
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idk but my teachers explaining it now

floral river
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x=y

meager lotus
#

idk what to do after i find out my cos and sin

lone heartBOT
#

@meager lotus Has your question been resolved?

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upper grail
#

Need help with line integrals. tried different yt vids. not one gives proper explanation about parameterisation or etc etc

lone heartBOT
#

@upper grail Has your question been resolved?

hollow lantern
lone heartBOT
#

@upper grail Has your question been resolved?

lone heartBOT
#

@upper grail Has your question been resolved?

lone heartBOT
#

@upper grail Has your question been resolved?

real gazelle
limpid nymph
#

I need help with my tenth grade homework on Linear equations

lone heartBOT
#

@upper grail Has your question been resolved?

upper grail
lone heartBOT
#

@upper grail Has your question been resolved?

mortal trellis
#

What exactly do you mean with "how to do parametrization" ?

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It's not always obvious how to parametrize a given curve if that's what you are asking

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(Depends on how you are given that curve of course)

upper grail
ornate condor
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what type of curve

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if its just a straight line u can just use

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given it starts at x1 and ends at x2

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x1(1-t)+x2t

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for t in 0,1

upper grail
mortal trellis
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Well it depends on the curve

ornate condor
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...

mortal trellis
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You can parametrize a line by x1+t(x2-x1), where x1 is your startpoint, x2 is the endpoint and as t runs from 0 to 1 you run between them. What they wrote is just this but rearranged

upper grail
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Thanks alot both of u @ornate condor @mortal trellis

ornate condor
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hm

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i still find my way of writing more intuitive

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np harri

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imma just close dis too

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.close

lone heartBOT
#
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mortal trellis
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Yeah it's interesting what people see as more intuitive. I personally like my way a lot more

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Don't just close a channel lol

ornate condor
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yea ik other see it differently

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.reopen

lone heartBOT
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ornate condor
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wot oki

mortal trellis
#

Let people close their own channel

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If all their questions are answered

trim wagon
#

hello, this is preoccupied channel, you can read on how to make ur own channel in #❓how-to-get-help

pulsar breach
trim wagon
#

the ones you’ve circled

pulsar breach
#

ok, Thanks👍

trim wagon
lone heartBOT
#
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#

lilac nest
#

.close

lone heartBOT
#
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coarse socket
#

why

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i mean why close open close

lilac nest
#

Initially I thought the question hadn't been answered since the last message wasn't sent by op, then I read above and closed it

coarse socket
#

ohh

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anyways back to study

lone heartBOT
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trail delta
#

.open

compact coral
#

This is what im trying to solve, i knew how to solve it a year ago but now i have forgotten everything. I know that there's a short way. I don't want to just calculate the values of everything.

echo socket
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Factor out powers of 3

minor needle
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factor 3^2

compact coral
#

like cross them out?

echo socket
#

No, put them out of brackets

compact coral
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what do i do now

echo socket
compact coral
#

whats in the brackets?

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can you type it out please?

echo socket
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3^2 (3^3 + 1) on top and 3^2 (3^2 + 1) on bottom

compact coral
#

and then i cross out 3² right?

echo socket
#

Yes

compact coral
#

and then i just calculate the rest?

echo socket
#

Yeah

compact coral
#

alright thank you very much

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have a good one

#

.close

lone heartBOT
#
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hard remnant
lone heartBOT
hard remnant
#

in a chessboard of nXn, we define that p(i,j) is the placement of a square in that chessboard where i = 1,2,3,4 ... n and j=1,2,3,4 ... n

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why in the second picture it says that two squares given that the first square is in p(i,j) and second square is in p(i',j') are diagonal, i+i' = j+j'

tropic sail
#

ive seen this one before

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where did u get it from>

hard remnant
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any value of p(i,j) all it diagonals can be found by adding the same number to i and j

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it should be like this p(i+n, j+n) where n is an integer

hard remnant
#

specifically the application of satisfiability

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when we add them we find that

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2i+n = 2j+n

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meaning for this to be equal i and j must have the same value

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and that's not the case for different values of i and j

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Could someone explain please

lone heartBOT
#

@hard remnant Has your question been resolved?

lone heartBOT
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tepid drum
#

Hi everyone

lone heartBOT
ornate condor
#

hi

tepid drum
#

I'll send the question just gimme a sec

#

First of all let A be a subset of N

#

If A is finite then a part of the theorem is already proved

#

Now if A is infinite then I have to prove |A|=|N|

#

Now first of all if I consider the function g:A→N where g(x)=x+1

#

Assume that g(a)=g(b) for some a,b included in A

#

Then a+1=b+1 which means a=b

#

So this function is injective

vale wigeon
#

why +1? you can just consider the inclusion map from A into N w/o that complication

tepid drum
#

Yea but I just chose x+1

#

It's not so different

vale wigeon
#

well it's not fatal

#

just a bit odd

#

||i assume now you will want an injection the other way around to apply csb, which is where the least-element principle comes in||

tepid drum
#

Now let x=y-1 where x belongs to A and y belongs to N then g(y-1)=y-1+1=y then this function is also surjective

#

Then it is bijective and thus |A|=|N|

vale wigeon
#

wait can you state more clearly your function N -> A

#

your g is not surjective unless A happens to be all of N !

tepid drum
#

That's what someone told me but the theorem states that for every infinite set A in N |A|=|N|

#

How should I do this

earnest topaz
#

Hey guys am I doing this right?

vale wigeon
#

try to think about the least element principle

tepid drum
vale wigeon
#

@earnest topaz channel busy please move

keen plinth
#

g is not surjective even if A = N because of the +1 thonk

vale wigeon
#

don't worry about it for now.

earnest topaz
#

Lol sorry

#

Whenever yall are done

tepid drum
#

It says that for every non empty set there is a least element that set right

#

But what does that have to do with this

earnest topaz
#

Thanks mate imma catch on

keen plinth
#

least element principle will help you create the function from N -> A

tepid drum
#

Let me think about it for a moment

#

Is the function f:N→A where f(x)=x+c such that x for x in N and a constant c such that c starts from 0 and for c=0, f(x) is the least element in A a surjection ?

vale wigeon
#

no you're kind of overdoing it...

#

let A be your subset of N.
it has a least element, call it a_1.
A \ {a_1} is also a subset of N, and also has a least element. call it a_2.
there is a way to describe in words the relationship of a_2 to the original set A.

#

if you want to think on your own from here that's fine, but do still answer my question here.

vale wigeon
tepid drum
vale wigeon
#

don't overthink it

#

i am confident that you know the English word that describes it

tepid drum
#

Do you mean a_2 belongs to A

#

?

vale wigeon
#

of course it belongs to A, but that isn't what i'm looking for

tepid drum
#

I don't think it's the description you want bc it's obvious that it belongs to A

vale wigeon
#

in the set {4, 20, 69, 533, 895475, ...}

4 is the smallest element
20 is the ______

tepid drum
#

2nd smallest one

vale wigeon
#

that's right

#

a_2 is the second smallest element of A

tepid drum
#

I thought of that but I didn't think that this Is what you want

vale wigeon
#

you can similarly construct the third smallest, and the fourth smallest, and so on.

tepid drum
#

Yea I can do this continuously since A is infinite

vale wigeon
#

in fact this alone already gives you a bijection between A and N, since every element of A will be numbered in this way eventually!

#

and injectivity is obvious as each n'th smallest element is obviously different from any below it, by construction.

tepid drum
#

And each element in N won't have more than 1 a that gives it as an output since each a is greater than the one before it

#

So it is also surjective

#

Then it's bijective and thus |A|=|N|

vale wigeon
#

yes

tepid drum
#

But I just still have to write the expression of the function

vale wigeon
#

nyeh

tepid drum
#

Which is f(a)=a_n

vale wigeon
#

i think writing f: N -> A, f(n) = n'th smallest element of A

#

will be just fine

#

and for the inverse you could send a in A to the number of elements in A that are less than or equal to a, if you so desired

tepid drum
tepid drum
vale wigeon
#

are you penalized for non symbolic expressions or just allergic to them personally?

tepid drum
#

No I don't have problems with them but its good to know how to use the symbols

vale wigeon
#

i don't think it's worthwhile to worry about a symbolic expression for f, honestly.

tepid drum
#

Oh ok

#

Tysm for your help and have a nice day

#

.close

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icy wedge
#

Hello i dont know how to start on answering this question

Show that a^4 + a^2 + 1 = (a^2 - a + 1) (a^2 + a + 1)

echo socket
#

Expand the RHS

icy wedge
#

Yeah but then theres

#

Another question

#

Show that 10101 can be divided by 111

swift sky
#

II think you can turn (a^2 - a + 1) = (a+1)^2

echo socket
#

First figure out the prime factors of 111

swift sky
#

and use substitution

#

I meant a-1

#

no sorry

echo socket
#

Still wrong

vale wigeon
#

still no

swift sky
#

that is wrong never mind

icy wedge
#

.close

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versed island
#

Hi can anyone give a hint for my problem?
we have a sequence of $n>=6$ numbers, first 3 numbers arbitrary, others follow $a_{i+3}=2a_{i+2}-a_{i+1}+a_{i}$, we know $a_2=-2, a_3=6, a_{n-2}=2022,a_n=6226$, find the sum of the sequence

ocean sealBOT
#

AlterNet

lone heartBOT
#

@versed island Has your question been resolved?

alpine sable
#

$a_{i+3}+a_{i+4}=2a_{i+3}+a_{i+2}+a_i$, so {$\sum_{i=1}^m a_i=-a_{m-2}-2a_2-a_1+2\sum_{i=1}^{m-1}a_i$}

ocean sealBOT
alpine sable
#

(that should be correct now)

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proud igloo
#

Okay here's a problem I've been trying to solve:

A cucumber weighs 500g. It's 96% water. It dries. Now it's 92% water. How much weighs the cucumber?

mellow tusk
#

tries?

proud igloo
#

Tries? My attempt you mean?

#

480g

long axle
#

Maybe “dries”

proud igloo
#

because of the lack of information of what it's 92% off I assume it just lacks water after drying

#

yes.

mellow tusk
#

let the dried amount be x
initial water=480, final water=480-x, final weight=500-x, final water is also=0.92(500-x)=480-x
on solving- 0.92(500-x)=480-x
u will get ur ans

mellow tusk
proud igloo
#

How much weighs it after drying I meant

mellow tusk
#

ok

proud igloo
#

Okay where was my reasoning wrong then

#

Cause I assumed 0.04 * 500 of non-water was kept

#

And that the WATER decreased so we get 0.92 * 500

mellow tusk
#

Now it's 92% water
the word now

proud igloo
#

Okay the 500 should not be there

#

right

mellow tusk
#

yea cuz some of its weight dried

lone heartBOT
#

@proud igloo Has your question been resolved?

proud igloo
lone heartBOT
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bronze pilot
#

this is continius when x=pi/3 ((tan(x)-tan(((π)/(3))))/(x-((π)/(3)))

bronze pilot
#

right?

mellow tusk
#

dude the number of brackets

bronze pilot
#

XD

#

i put it in geogebra and copied it

vague coral
mellow tusk
#

can u send the ss ?

#

,w ((tan(x)-tan(((π)/(3))))/(x-((π)/(3)))

mellow tusk
#

this right

bronze pilot
#

there you go

#

so i just calculate lim in the right and left

mellow tusk
#

hm

bronze pilot
#

and show they are equal ?

#

to 4

mellow tusk
#

yea

bronze pilot
#

ok i just was scared of it not beeing

#

thx

mellow tusk
#

np

bronze pilot
#

.close

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mellow tusk
#

shank's is a villan?

bronze pilot
#

sully maybe

mellow tusk
#

potential

bronze pilot
#

like 80%

mellow tusk
#

yh

bronze pilot
#

to 99%

#

XD

lone heartBOT
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gilded vale
#

Are you allowed to use the word “greater” when describing distribution?

royal meadow
#

no

#

it's not a distribution

#

it's just a greater number

lone heartBOT
#

@gilded vale Has your question been resolved?

gilded vale
#

Like there is an equal/unequal distribution?

lone heartBOT
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untold panther
#

How do you solve this?

lone heartBOT
#

@untold panther Has your question been resolved?

untold panther
#

.close

lone heartBOT
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compact swallow
lone heartBOT
compact swallow
#

i dont get which one would be uncalculatable

#

since each of them are rewrites of each other

#

btw this is a practice test

#

.close

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lone heartBOT
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frail geyser
#

help

lone heartBOT
frail geyser
#

I am confused because I am trying to solve this problem: 3x-4=12

#

How do I solve it?

#

.close

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vernal lance
#

I'm not sure where to progress on this

lone heartBOT
vernal lance
#

my apologies it should be this

#

<@&286206848099549185> chain rule with trig trollge

snow furnace
#

well you can start by moving the -2 to the outside

#

and remembering that the derivative of cot(x) is -csc^2(x)

#

and derivative of cscx is -cot(x)*csc(x)

#

then you should just be able to use the chain rule like normal

lone heartBOT
#

@vernal lance Has your question been resolved?

vernal lance
#

thank you

lone heartBOT
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quick laurel
#

Hello

lone heartBOT
quick laurel
#

Currently struggling to solve the separable equation for y

#

My work is posted above

#

Thank you in advance.

sudden herald
#

Im stuck on which one to choose can someone help the answer is 61

quick laurel
#

@sudden herald Hey, I am currently occupying this channel. Do you mind reposting in a free help channel?

sudden herald
#

sorry i dont know how to use this

quick laurel
#

Refer to that

#

and if you don't mind deleting your original question. Thanks.

slender marten
#

Fix this:

quick laurel
#

Do you mind elaborating for me?

slender marten
#

You wrote y^(e^(-y)).

#

I think you meant y e^(-y).

quick laurel
#

That is actually just a typo.

slender marten
#

That's what I mean. To fix the typo.

quick laurel
#

Let me correct.

#

Will do, but my question still stands on the final isolation of y.

slender marten
#

A integral calculator returns this for the integral of e^y - y e^(-y).

quick laurel
#

Right, but that is the Maxima calculation

#

the "hand" method provides what I have

#

through integration by parts

slender marten
#

To be fair, you did never say what you performed integration by parts on.

#

A lot has been left to the reader to try and understand what you've done on each line.

#

$\int (e^y - y e^{-y})\dd{y} = 2\int \sin x \dd{x}$

ocean sealBOT
#

stabulo

slender marten
#

From using a integration calculator, it would seem you should end up with:

#

$e^y + (y + 1)e^{-y} = -2\cos x + c$.

ocean sealBOT
#

stabulo

slender marten
#

Alternatively, $e^{-y}(e^{2y} + y + 1) = -2\cos x + c$.

ocean sealBOT
#

stabulo

quick laurel
#

Hmm, a question similar to this is going to be on my test tomorrow and I don't see how I can derive -2cosx + c from the integral

slender marten
#

Sine integrates to a negative. That's why it's -2cos(x).

quick laurel
#

Correct, rather, I don't understand how $2\int \sin x \dd{x} = \int (e^y - y e^{-y})\dd{y}$

ocean sealBOT
#

Thasis

slender marten
#

You literally have it wrote:

quick laurel
#

Okay I'm sorry I understand now

slender marten
#

I just disagree with your results for the integrations.

quick laurel
#

so if $e^{-y}(e^{2y}+y+1) = -2cosx + c$

#

How does one isolate y

ocean sealBOT
#

Thasis

slender marten
#

Implicit functions can be harder to solve for y than solving the original equation.

quick laurel
#

Right, but given the initial condition y(0) = 2; does one not have to find y to then find the value of c in order to get the exact solution to the DE?

slender marten
#

No. You can just replace y with 2 and x with 0 in the implicit solution to determine c.

quick laurel
#

Yeah I suppose that makes sense. I don't particularly know why I thought otherwise

slender marten
#

🙂

quick laurel
#

Therefore, $y(0)=2 \longrightarrow e^{-2}(e^{4}+3)=2cos(0)+c \Rightarrow e^{2}+3e^{-2}=c$

#

?

ocean sealBOT
#

Thasis

quick laurel
#

.close

lone heartBOT
#
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keen pewter
#

Need help with this

lone heartBOT
keen pewter
#

Its dimensional analysis

#

I can turn Klygenes into Widgets no problem but idk how to turn Klygenes/Seilas into Widgets/Dueseldorfs

#

These are just made up units i need to convert

#

so it'd be like

#

the answer for klygenes -> widgets divided by seilas -> dueseldorfs?

#

so for example if kly -> widgets is 10 and seilas -> duese is 5

#

i can just do 10/5?

#

im confused on that

#

okay ill try it out and show you

#

yea im stumped

#

what is the name of what you just did?

#

when i look for dimensional analysis videos i just get the regular one

#

not the one where its something/something

#

okay, i'll watch that then try it out and if im still confused ill show you what i got

#

oh shit

#

this shit is actually easy

#

thanks for the resource ill try out the problem now

#

I got this

#

so just assuming that the conversions I put there are correct did I do it right?

#

Ah shit

#

Thanks a lot

#

Physics

#

My teacher didn’t teach us DA

#

He taught us sigfigs for like 1 day and then 1 day they did an assignment without a lesson on DA but I wasn’t here and then boom had to take a quiz

#

So I’m tryna learn it rn before I retake it

#

he could’ve just put normal conversion units but he wants to make his class fail lmao

#

I already have 3 F’s worth 70% of my grade because I was in a group and they didn’t do work

#

So imma good it gets better

#

I hope so

#

Thanks a lot for the help

lone heartBOT
#

@keen pewter Has your question been resolved?

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crimson isle
lone heartBOT
crimson isle
#

can someone help with #1?

#

i got the identity matrix and the row operations,

#

not sure what to do nex

#

t

alpine sable
#

You need to do the same operations to A to find the inverse of A if you're looking for it

crimson isle
#

after i find the invers

#

e

#

do i do those same operations

#

on the 3x3 identiy matrix

#

@alpine sable

#

to get the elementary matrices

#

or are they obtained another way

alpine sable
#

Idk, ask helpers after 15m

crimson isle
#

alright thank you

lone heartBOT
#

@crimson isle Has your question been resolved?

#
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crimson isle
#

sorry hellolol

#

my bad

#

forgot to close

flint tree
#

It’s ok!

#

😄

crimson isle
#

is it possible for me to get your help on 2.1?

flint tree
#

Yeah sure thing!

crimson isle
#

.reopen

lone heartBOT
#

crimson isle
#

if we assume A to be noninvertible

#

that would mean that the column vectors are independent

#

then the solutions are not all identically 0?

#

which could contradict

#

@flint tree whenever you get time please let me know, thank you sm

#

okay, dont need help

#

FTIM proves for me

#

thank you guys

#

.close

lone heartBOT
#
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arctic mortar
lone heartBOT
arctic mortar
#

for 10a I would think that it would just be $$ \frac{1}{7!} = \frac{1}{5040} $$

ocean sealBOT
snow furnace
#

you have to remember that there are 52 cards in a deck

arctic mortar
#

why would that matter tho is my question?

#

the order of the 7 cards dealt shouldn't be affected by the number of total cards

#

there's 7! permutations of the cards and only 1 is in ascending order no?

snow furnace
#

one sec

arctic mortar
#

alr

snow furnace
#

it should be 52P7 though

arctic mortar
#

i tried 1/52P7

#

,wolf 1/(52 permutation 7)

snow furnace
#

because you are picking 7 cards from 52

arctic mortar
#

textbook answer

snow furnace
#

oh I guess that is equal to 1/7! lol

arctic mortar
#

,wolf 1/7!

arctic mortar
#

i have no idea what the actual answer is

#

the textbook doesn't match up with either of what i thought

snow furnace
#

it wouldnt be 1/52P7

arctic mortar
#

hm

#

i was pretty sure it'd be 7! but idk tbh

snow furnace
#

it is 1/7!

arctic mortar
#

oh i just realized

#

answer key thru me off because it started with a 4

#

i see

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thanks

#

.close

lone heartBOT
#
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arctic mortar
#

.reopen

lone heartBOT
#

arctic mortar
flint tree
#

Hiii can I say what I need help with now?

arctic mortar
#

i was thinking it'd be

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$$ \frac{something}{52^7} $$

ocean sealBOT
arctic mortar
#

52^7 being the total number of possiblities

snow furnace
arctic mortar
#

right

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something over 52P7?

snow furnace
#

one sec

#

its probably 52C7 right, because the order dosnt mater

arctic mortar
#

im thinking it might be 13P7 because there's 13 denominations and they can only be used once

snow furnace
#

I figured out one way

arctic mortar
#

how?

snow furnace
#

dont always have to use ncrs and pcrs, could always just find the probability of each single draw

arctic mortar
#

I see

#

that makes sense

#

thank you

#

.close

lone heartBOT
#
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lunar girder
#

Hello!

lone heartBOT
lunar girder
#

Did I expand the first three terms correctly?

lone heartBOT
#

@lunar girder Has your question been resolved?

lunar girder
#

.close

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long axle
#

Is that homework

#

@covert tapir

lone heartBOT
#

@covert tapir Has your question been resolved?

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lime halo
lone heartBOT
solemn juniper
#

Cool question, thanks for sharing

lime halo
#

I need help

tidal rivet
#

theres 2 of each side for the box

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calculate the given 3 sides

#

it should be twice of that

lime halo
#
  • or +
#

Do I multiply 3, 2 and 5 or add it

tidal rivet
#

you can do either, really

#

multiplication is just repeated addition

lone heartBOT
#

@lime halo Has your question been resolved?

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celest hearth
#

How do you solve this ? I know how to do it if there's only one || on the left but not if there's 2

tacit arch
#

do a sign chart analysis for separate cases to remove the absolute values.

celest hearth
tacit arch
#

on the real line, find where each of the individual absolute values change signs

#

they're different for each so you'll have 3 combinations

#

for example for x > 2, you know both terms are positive

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so you just solve for (x-2) + (2x+3) = 6

#

do the same for x<-1/2 and -1/2 < x < 2

#

by combinations i mean (x-2) - (2x+3) or -(x-2) + (2x+3) or -(x-2) - (2x+3)

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should only be 3 unless i made a mistake

celest hearth
#

I still don't understand, can you please draw it for me?

tacit arch
#

no

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draw it yourself and share it here

#

something like that

#

but instead of - + -, you replace it with (x-2) or -(x-2)

#

similarly for the 2x+3 term

celest hearth
#

Ah so that's what you meant by real line

lone heartBOT
#

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grizzled cliff
#

Hey guys

lone heartBOT
grizzled cliff
#

I need help

#

with um

#

proving Trigonometric Identities

trim wagon
#

rewrite everything in sin and cos

#

and at some point use $\cos^2 x = 1- \sin^2 x$

grizzled cliff
#

OH

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So that's what I've been missing

ocean sealBOT
grizzled cliff
#

I think?

trim wagon
#

yea ig, idk if i don’t see what you’ve done

grizzled cliff
#

is this right

trim wagon
#

yes

grizzled cliff
#

okay okay

#

is this the next step?

trim wagon
#

and now write numerator in form of (1-sin^2)

grizzled cliff
#

cos^2(C)?

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like this?

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or like without the parenthesis

autumn pasture
#

helloo

grizzled cliff
#

oh hi

autumn pasture
#

are you trying to show the left hand side?

grizzled cliff
#

yes

autumn pasture
#

I think

grizzled cliff
#

oh

#

well uhh this is what I've got so far

autumn pasture
#

$\frac{sinC - sin(C) cos^{2}(C)}{cos^{2}C}$

trim wagon
#

you ate some terms

ocean sealBOT
#

duckiescute!

trim wagon
#

also PARENS

autumn pasture
#

I think it should be that

grizzled cliff
#

oh

autumn pasture
#

then you factor out sinC

grizzled cliff
#

oh yeah I saw my mistake

autumn pasture
grizzled cliff
#

I turned 1-sin(C) into cos^2(C)

autumn pasture
#

oh how did you get 1-sin(C)

grizzled cliff
#

I think I ended up adding it instead 💀

autumn pasture
#

ohh hahaha

grizzled cliff
autumn pasture
#

making the denominator the same

grizzled cliff
#

I'm confused

#

😟

#

I'll start over

autumn pasture
#

okayy

grizzled cliff
#

okay so left hand side

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changed into sin and cos

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should I make that -sin(C)/1 actually

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or

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hm

#

nah

#

okay

autumn pasture
#

okay so far so good

#

do you see the sin(C) on the right most part

grizzled cliff
#

yes

autumn pasture
#

what denominator does it have

grizzled cliff
#

oh do you mean the left?

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or

autumn pasture
#

right

grizzled cliff
#

uhh

autumn pasture
#

the one with -

grizzled cliff
#

none?

#

1

#

?

autumn pasture
#

yes

#

1

grizzled cliff
#

oh 1

autumn pasture
#

we want it to have the same denominator as the one on the left

#

what’s the denominator

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for the left

grizzled cliff
#

cos(C)

autumn pasture
#

cos^2(C)

grizzled cliff
#

oh huh

autumn pasture
#

cosC x cosC = cos^2 C

grizzled cliff
#

do I multiply it already

autumn pasture
#

yes

grizzled cliff
#

oh okay

#

so this is what we have so far?

autumn pasture
#

why multiplied?

grizzled cliff
#

oh am I not supposed to

#

🥲

autumn pasture
#

it’s - hahaha

#

right now you have $\frac{sinC}{cos^{2}C} - \frac{sinC}{1}$

ocean sealBOT
#

duckiescute!

grizzled cliff
#

oh

#

OHH

#

Alright

autumn pasture
#

to make denominator the same

#

what do we do

#

to the right

grizzled cliff
#

um

#

pythagorean identity? 💀

autumn pasture
#

umm that’ll come in later

#

if I have $\frac{9}{4} - 2$

ocean sealBOT
#

duckiescute!

autumn pasture
#

the right is 2/1 right

#

it has denominator 1

grizzled cliff
#

yeah

autumn pasture
#

so to make common denominator

grizzled cliff
#

oh

autumn pasture
#

we multiply it’s numerator and denominator by 4

grizzled cliff
#

multiply by 2

#

OH

#

By 4*

#

so it'll be

#

8/4

#

yes yes

autumn pasture
#

yes

#

same thing here

grizzled cliff
#

so we multiply both the numerator and denominator

autumn pasture
#

what do we multiply the numerator and denominator by

grizzled cliff
#

by cos^2(C)

autumn pasture
#

yes

#

yay

grizzled cliff
#

YES

autumn pasture
grizzled cliff
#

so this?