#precalculus
1 messages · Page 159 of 1
you're solving for a and b for now
a+b = 0
3b - 2a = 5
the x terms are equal to the x terms
the non x terms are equal to the non x terms
so you have two equations now
yup
there is no c
in the first equation
can't find something that doesn't exist at all lol
As a limit?
7^infinity climbs faster than 3^infinity
yes as a limit
kinda
A better way is to keep the fraction
but a more honest-to-goodness way of thinking of this is that $\frac37 < 1$
Ann:
thank you ^3^
that wasn't funny, @wraith idol
ok



I wanna do pre-calculus after i'm done with my current studies (I mastered pre-algebra, algebra basics, and most of algebra 1 so far), I'm gonna take algebra 2/high school geometry/trignometry and master them as well, however will I need more than this for pre-calculus, like math analysis as well? https://i.imgur.com/9f8LklB.png
I just need to know if covering these topics is sufficient information to be considered as calculus ready.
that just sounds like a "precalc" class
like, i'm pretty sure "math analysis" is just what your school calls precalc.
the curriculum lines up pretty exactly
and yes, that's definitely enough for calculus
How do you transform polygons using matrices?
Not the transformation part. But, the matrix multiplication part.
Like, I always get the answer wrong because I would have put the wrong coordinates into the matrix.
It would be much appreciated if anyone can help me explained the matrix multiplication part for transformation.
So even if I don't take math analysis which is considered "Algebra 3" i'll be ready for calculus? @short sorrel
no, i'd imagine your calculus class will expect you to have it
"calculus" and "precalculus" are different things
precalc comes before calc, generally
Hmm
That's a lot for me to study, so I need math analysis as well..
Challenge accepted.
again, i'm pretty sure "math analysis" is just what your school calls precalculus
the term isnt really standardized
but it covers the exact same material
I'm going to University I don't think they'll make me learn pre calculus.
behaviour of common functions and limits
I mean they'll help me with pre calculus*
So I gotta educate myself on this ffirst.
Facepalm, I mean I don't think my university will help me with precalculus so yeah.
Anyone?
?
@viscid thistle don't ask to ask

and as it's about matrices #linear-algebra is probably a better place to ask your question
Oh...okay.
@wraith idol dw they already helped them in #linear-algebra
'less you're talkin about something else
Yeah I'm talking about the previous image
@charred hull
"Whereas Math Analysis, which some instructors sometimes call Algebra 3"
It just sounds a bit funny to me
- How is the quotient rule for logarithms derived from the product rule and the power rule?
- How does the interest rate affect the present and future values of an annuity?
help
pl0x
please
help
if you're dividing to get a/b
you can rewrite that to become a * (b^-1)
@deft fox
i found the answer from someone else, but this also helps too since the answer i found is alot of reading
thx
np
$|R|^2=2F^2+2F^2(cos^2(\theta/2)) \implies F/3=2Fcos(\theta/2) \implies \theta/2=\cos^{-1}(\frac{1}{6})$
?
Ann:
yeah you fucked up there
you don't need to square-root anything here
the equation is linear in cos(θ)
Krishna (An average mathy):
NO
even if it's not quite in the same form as any of the options
but the angle IS equal to $2 \arccos(1/6)$
Ann:
hint: what is $\cos(2 \arccos(1/6))$?
Ann:
answering this question will help you select the right answer option
i dont have calculator
also dont now how to manipulate inverse trig
anyways
answer is the first
i didnt makee the sub that 1+cosx=2cos^2x/2

Help please
<@&286206848099549185>
if they move 30(sqrt(2)) southwest
just think of it as a triangle
a right triangle with a diagonal of 30 sqrt(2)
DRAW IT FIRST
i refuse to help anyone that doesn't put in the same effort
$30\sqrt{2}-10\sqrt{13}$
Krishna (An average mathy):
it's a lot easier to understand visually than me explaining through words
So the answer is $30\sqrt{2}-10\sqrt{13}$
Krishna (An average mathy):
then show them, please
do you know what a 45-45-90 triangle is
🤔
break the southwest portion up into its x and y components

Let me figure out what's the x
stop right there
again
take the information
that it is south-west
meaning it has a bearing of 45 degrees from south
meaning it forms a right triangle
.yup
with 2 45 degree angles
meaning that the legs of said right triangle are equal
in fact, just reverse pythagoreas

The sw displacement is more then the hypo of the tri u talk abouy
Yes correct
i'm giving you the method with which you can find the x and y components of the southwest displacement
>The sw displacement is more then the hypo of the tri u talk abouy
how is the southwest displacement more than the hypotenuse if it is the hypotenuse
did you split the 30sqrt(2) SW into its x,y components?
i've spent 20 minutes trying to get them to, for some reason they completely refuse
just draw it on a plane, then try to divide it in triangles maybe and use pythagorean theorem
Reee is so cringe 
No U
Q 49
What have you tried
See I know how to do it but the problem is. I can't factorise 6x²+5x+4
well its discriminant is negative
Yeah then is q wrong
Okay
how can i solve this recurrence f(n)=n*sqrt(1+f(n+1))
Looks like cancer but I guess doable
f(0) = 0 obv
I would presume maybe rearrange to have what f(n+1) is on outside just to make it look better
So we’d have (f(n)/n)^2 - 1 = f(n+1)
right...
it's f(1)=sqrt(1+f(2))
Yes ok I guess I can rearrange just not for n = 0
Hmm
Maybe difference of squares hmmmm
Is this for ur precalc class? Lol
no im still in high school it's for smth esle
Oh ok
1 sec I’ll try it with paper
@viscid thistle couple of questions
A. am i finding the explicit formula and B. is it for integer values n>0 or is it anything
if an explicit formula is possible to derive then yes and if it's for any n even better.If it's easier to assume that n>0 then that's also cool
what is this problem for lol
i'm trying to solve this: sqrt(1+2sqrt(1+3sqrt(1+4*sqrt(...)))) to infinity
yeah i've tried different things but nothing worked just approximations
converging approximations i think at least
but with no discernible pattern so they're useless
k one sec
@viscid thistle
its uhm very difficult rather congested in finding a number = to that expression
throught the expression
think of how each and every number can be represented in surd form
The sum of a positive arithmetic infinite series is infinity, right?
wat
It might be
Might not be
Oh arithmetic
skipped a very key word there
I guess so
its divergent, yes.
According to my teacher, it isn't
are you sure you heard them correctly?
Ask for an example
The following statement is false. Rewrite the statement to make it true.
The sum of the infinite series 3 + 4 + 5 + 6 + … is LaTeX: \infty ∞ . (This symbol is infinity.)
I mean, saying "the sum is infinity" is being... imprecise with wording
I'd say "the series is divergent"
you cant really define summation of an infinite divergent series, so assigning a value like "infinity" is being informal
Maybe that's what they want?
Saying something like that equals infty is questionable
Maybe they want it written in sigma notation
that seems unlikely.
I'm pretty sure they just want you to say it's divergent
What are explicit and recursive formulas?
Explicit
Is the nth term
So the formula is defined in terms of n, the term number
Recursive means it's defined in terms of itself
i.e.
Can you give an example of recursive?
,$ f_{n+1}=f_n+1
Pseudo:
that's a very simple example
I still don’t quite understand
So we say f_0 = 1 or smth
So you set the equation up to be equal to itself?
No
The n+1th term
is the nth term +1
Like f_0 = 1
We want f_2
Now
,$ f_2=f_1+1
Pseudo:
Pseudo:
Pseudo:
I just picked f for consistency here
EItherway it's irrelevant tbh
The point is nth term can be an expression of previous term(s)
That isn’t what I asked
,$ f(n)=\sum_{i=0}^{n-1}f(i)
Pseudo:
I’m doing an example with common difference
Then yes
Thank you
But it doesn't have to be
So this sequence doesn't have a common ratio or a common difference, it's going up in increments of odd numbers 3, 5, 7....
How would I find the equation for that if there was one?
The sequence starts on four
Got it
draw a diagram
make a equation and take one from the question and solve simultaneously
Done thanks
hi
hi lmao

help
.
ur pretty close to getting banned
k
LOl
trig doesnt really come into play for a while tho imo
the ability to graph, visualize graphs
that's p good as a skill
^
I think you just need calculus
i actually. am not sure what goes into calc from precalc. and not sure what goes into calc from alg 2
@subtle masonnah you dont do any calculus in calc
Sorry I meant precalculus
precalculus is just a lot of preparation before calculus
lots of algebra, trig, conics, main part is graphing
the main point is just a bit of mathematical maturity being developed, but there's not exactly a direct application for some of the skills
oh wait. exponents and logarithms
understanding limits is the start of calculus i think
zeros of graph sounds like precalc
true
thinking about it, there's a decent amount that's necessary from precalc
it's just hard remembering it now 
People say the concept of limits is difficult but I think it’s really simple
r/iamverysmart
look whos talking lol
@subtle mason do you know the actually definition of limits
Kek
I don't think you know what a definition is
He's like 15 so its probably fine
I know what it means but I can’t word for word recite a definition
You don't know what it means
Trust me
Actual definition is very different from what you learn in a precalc class
it means whatever you want it to mean 
So the precalc definition is different from the real definition?
Yes
yes
Do you know what delta and epsilon are?
What you learn in precalc is not a definition
It's just an intuitive idea of what a limit is
precalc doesnt really define a limit, it gives an intuitive explanation
Yeah
Stupid precalc
precalc doesnt really define anything
It gives you enough to apply to certain well behaved cases
you wouldn't be able to understand the definition so
Bruh I can’t wait for real ap calculus
wait until analysis tbh
Or read spivak or smth
But it’s better than precalculous
or some good college calculus
Both are meme tier
college calc doesnt rly get that rigorous depending on your path tho @valid flint
In terms of rigor
i took engi calc so basically: no rigor
now i have to make up for it 
Maybe in another life you could have escaped your fate
no regerts
well yeah, which is why i specified good. physics calc usually not too rigorous either

see i am making up for my lack of rigorous calc with analysis lol
Yes
in another life idve paid more attention to my capstone timeline and be done by my 3rd year of uni
smh
Hmmm
You'll probably learn the rigorous definition in like
2nd year
Depending on how early you take calculus
1st year uni lol
Lel
Or I can go to Wikipedia and learn it now
Kek
math majors prolly do analysis around then
That's not learning
@subtle mason it wont translate well
buying books
yeah
Baby rudin before knowing any calc 
that you finish precalc first
baby rudins pcool, i just constructed the reals from it and i am happy due to it lol

actually, it's probably closer to squeezing from a beet, you will get a result that seems to be correct but most likely is not
Kek
I will eat the spivak book to absorb the knowledge and learn it
All the math you have done so far is just skirting around actual mathematics
I know
Learn precalc first
You should always stop saying shit like "People say the concept of limits is difficult but I think it’s really simple"
will probably be just as effective as reading it rn without precalculus maturity
I can’t wait until later math
i mean if we are being honest how much of precalc do you really need in calc
Well now I know the precalculus definition is different
i have always thought that calc and precalc hybrid class would be better than wasting a year on precalc
@valid flint as mentioned before, understanding what limits are 
imo it's just to develop mathematical maturity tho
Comparing yourself to others like that is just an asshole thing to do
being able to visualize graphs somewhat familiarly
I thought the precalculus definition was the actual definition and the precalculus definition is simple and that’s why it’s simpler than I thought
Is there any mathematical maturity in precalc
This is a bruh moment
Precalc level induction kek
No there isn’t
hmm i thought visualizing graph was an algebra ii thing, but tb fair i am not really all that familiar with algebra ii/precalc
precal does like
polynomial shit a gud amount
finding zeroes of graphs
curvature of graphs
I thought that was alg II
they're p much the same
yeah i thought those were alg ii too
It is algebra II but I’m pretty sure there’s a fair amount of it in precalculus
from what i hear precalc is trig identity spam
o wait
Precalculus is supposed to be preparing you for calculus
hmm still would imagine alg ii for that
if those are not in alg ii, then what is taught in alg ii lol
me too, but they kinda bleed together in my head
Can we rename precalculus so that it’s now named algebra iii
they feel like the same course to me, but like. whatever it is, finish it before trying to do analysis
didnt someone have that as a class
i think, alg ii and precalc should either be combined, or calc and precalc should be combined, or combinations thereof
yeah some people call math analysis algebra 3 for some reason
which i think means they should be shot
lol analysis algebra iii, why
@valid flint there's a bit of complex numbers that pops up and idk how long that takes to explain to kids
as well as polar coords
thats fair. although highschool complex number is like 5 minutes of content tbh
and in my opinion, they should wait until taylor series is taught before teaching eulers identity
yeah that is true i guess
nah just teach em stuff before they can properly comprehend it
teach em riemmann sums before even teaching em addition
lol highscools pmuch like that
lol the precalc "mathematical induction"
the "proofs" you get in geometry
altho it's like. an okay ish way to teach mathematical logic ig
those geometry proofs were stupid. didnt all of them like use similarity
i dont know why they dont have a mathmetical logic class
like it doesnt really have prereqs
not enough school funding
I thought all of that was in alg II
and it is super useful
plain and simple, schools dont have the money most likely
esp bc it goes for math degrees, which isnt engineering so it gets tossed to the wayside
schools already struggle to get students to precalculus before uni in the US
logix
Logix
well i would argue mathmetical logic is important in many fields, even if it isnt explicitly helping.
The rad version of formal logic
not sure about that
engineering doesnt rly use it tbh
just aboos the work of actual mathematicians
like just thinking of statements by logical connectives is very useful for critical thinking imo
true
Engineers that admit their inferiority are allowed to live as clowns in the coming revolution
i mean, that's the whole reason that cs has discrete maths
and also the reason that discrete maths is considered a weeder class lol
lol
if you talk about ee, it relies heavily on calculus , algebra and probability
i need help ;w;
A bicyclist races on a bicycle with 13-inch-radius wheels. When she is traveling at a speed of 43 ft/sec, how many revolutions per minute are her wheels making?
i found it out so its ok lol
o 
Pearson SOCKS!
A sample of 4 million bacteria increases by 25% each hour. How long does it take for the sample to reach 24 million?
having difficulty with this question, how would I set this up in the formula
Well okay, how much would you have after one hour
what do you mean by 24(t)?
That one is correct
how would I go on about solving for t
P(t) is a function. you can't swap in the 24 like that.
divide the 4 right?
your need to find t when P(t) = 24
Can u solve the bacteria problem using geometric sequence?
sure
well first $A(x) = (x-4)(x+1)$
187:
$\therefore M(4) = M(-1) = 0$
187:
actually nevermind u dont need it, i didnt see the question above
i didn't know they were connected
ok so using ur result from part (i)
uh
$x^4-5x^3-6x^2+4x-8=(x^2-2x-8)(x^2-3x-4)-28x-40$
187:
what we can do is move the -28x-40 to the other side
$x^4-5x^3-6x^2+32x+32=(x^2-2x-8)(x^2-3x-4)$
187:
OHHH
so thats what it meant
alright
yeah the wording was really weird i didnt understand it
but i get how u did it thanks
👍
can someone help me with the intermediate steps
of this function?
it kinda seems like they used the quotient rule
but it looks a little weird to me
product rule was also being applied in the same step
yea
last step was just factorisation
okay, i see, thanks!
Show that vector $\vec{a}=2i+5j-6k$ and $\vec{b}=i+5/2j-3k$ are parallel.
Krishna (An average mathy):
i know that both are parallel as $\vec{a}=2\vec{b}$
Krishna (An average mathy):
assume i is a unit vector along +X and j along +Y
Is here a better way to show this/
?
from what i learnt just $\vec{a}=k\vec{b}$ where k is a scalar
Not Chezstick:
Ok .
Hi guys. Are there anyone who can give me arithmetic and geometric sequence problems in which i will solve? :")
if you want i can try to generate some problems of that sort for you
Yes please thanksss
how many do you want
Atleast 5-10?
ok
Thankss!!
On a scale of 1-10, 8
alright i got one, more coming soon i guess
[01] An arithmetic progression consists of 20 terms. Its sum is equal to thrice the value of the 5th term, and its last term is equal to -2 times the first term. Find the 11th term in the progression.
Thanks
[02] A sequence of four numbers is such that the first three are in AP and the last three are in GP. The sum of the first and last numbers is 2 more than the sum of the second and third numbers. If the first number is increased by 5/2, the entire sequence becomes a GP. Find the four numbers.
02 may be a bit over the top in its difficulty but it should be solvable unless i messed this up
Ok ill try
[03] A nonconstant geometric progression consisting only of positive numbers is such that its 4th, 10th and 13th terms are in AP. The 10th term of the progression is 1. Find the floor of the 49th term.
coming up with these as we speak, btw, so these aren't arranged by difficulty
Thanks
[04] Three distinct numbers are in AP. Switch the last two numbers and the AP becomes a GP. Find the step of the AP.
this one's a bit easier than the other three
i'd say the difficulty ranking is approximately 01 < 04 < 03 < 02
Thank u
have you solved any yet?
Number 1is 53?
that doesn't match the answer i had for it, can you show your work?
Im so bad lol
The 5th term and i cube it
why are you cubing the fifth term?
i did not say that the 5th term was equal to 5, nor did i say that the last term was equal to the cube of the fifth.
you seem to be making some stuff up that has no relevance to the problem i wrote
so how do i know their values
you don't, nor do you need to
Can i see yours?
Okay ill try again
need help finding angle
i know the triangle adds up to 180 but forgot the other rules
x is 180° minus the 3rd angle of the triangle
so 180 - 31
yes
ok thank you i havent practiced in awhile so this helps a lot
after all, a full circle is 360 degrees, right? and this is half a full circle
half of 360 is 180
so x + the missing angle of the triangle should add up to 180
wow at first i thought the horizontal line was 360 but that statement really helped to clear the confusion
its okay
for this problem i have the equations, 1st worker=x , 2nd worker= y, x + y = 235, x times 20 + y times 15= 4100
am i on the right track?
<@&286206848099549185>
@proud raven how would i go about this
in which way could i define it better? would i be able to start to solve or do i need to define more?
no you can start
use substitution
its better to define precisely so when you get a number as an answer you know what it means
i.e. x= hourly rate for this worker $/hr
go ok?
ok got it thank you
Can someone help explain what exactly this set is describing I’m having a hard time getting my head around it!
x is an element of the rational numbers such that 3 times that number is an element of the integers
1/3 for example
1/3 is an element of the rational numbers
and 3(1/3) is an element of the integers
got it? @tame wedge
Oh okay so B only contains x that satisfies both of these
y
that | means such that
so x is an element of q such that 3(x) is an element of z
Q* Z*
Would it mean the same thing if it were written the other way around?
lets try
x is an element of Z such that 3x is an element of Q
so you want an integer
which 3 times that integer gives a fraction
is that possible
?
Definitely not
got it?
Yeah, I actually do yeah thanks !
@limber bone ummmmmm no
no
${ x \in \bbZ \mid 3x \in \bbQ}$ isn't empty as mo2men seemed to suggest, @tame wedge
Ann:
because Q isn't the set of "fractions"
it's the set of RATIONAL NUMBERS
which contains the integers
every integer is also a rational number
scroll up
no seriously
this is a pretty fucking serious fuckup on mo2men's part and i want to make sure it's set straight 
uh ohh
wat
sorry

fuck bad mistake
{x in Z | 3x in Q} is actually the same thing as Z
bc 3 times an integer is again an integer, and hence a rational number too
ye
there's no reason to include the condition 3x in Q there
sorry guys
scroll up sloth
This is an example of people self-studying and don’t know what they are talking about @limber bone . But hey, it’s a mistake and he will@learn from it
Thanks for the help guys, I understand the mistake all is well!
Consider example A is it wrong ?
example what
there are examples 9, 10 and 11
which one are you talking about
(also, φ for empty set? yuck)
Example 11 @willow bear
ok then what do you mean by "is it wrong"
Yes that phi is for null set or empty set
yeah ok phi is not meant for that. the empty set has its own symbol. but whatever
Read the example 11
How?
how what
Is A={1} is an element of Of B and B is an subset of C then why not A Subset of C
Yes
the only element of A is 1
therefore, if A were a subset of C, then 1 ∈ C
do you agree
Yes It is
1 ∉ C
C={1,2,3}
🤔
what
And A={1}
yes
C={{1},2,3}
yes
A Subset C means all elements of A are contained in C .
Yes
"contained" is usually reserved for subsets, not elements
A is an singleton set all elements A are in C then why not A Subset C . I am confused
What's the difference between {1} and 1?
Donno
@faint mason do you know?
What you asked
Oh
I don't know anything about sets really, but I'd assume 1 is the element of 1. Whereas {1} is the set containing the single element 1.
C contains a set containing 1, but it doesn't contain 1 itself.
Someone more knowledgeable in this topic please correct me if I'm wrong.
Finally gotcha
It seems intuitive that way.
Q.3: Let A = { 1, 2, { 3, 4 }, 5 }. Which of the following statements are incorrect and why?
(i) {3, 4} ⊂ A , (ii) {3, 4} ∈ A, (iii) {{3, 4}} ⊂ A
(iv) 1 ∈ A, (v) 1 ⊂ A, (vi) {1, 2, 5} ⊂ A
(vii) {1, 2, 5} ∈ A, (viii) {1, 2, 3} ⊂ A, (ix) φ ∈ A
(x) φ ⊂ A, (xi) {φ} ⊂ A
phi used for empty set 🤢 
i think it'd be helpful if each of those 11 statements were on its own line js
1 is not correct as 3,4 is not an element of A
do you mean to say that neither 3 nor 4 are elements of A
(you're right, but your wording needs work)
ok
\begin{enumerate}
\item $ { 3, 4 } \subset A$
\item $ {3, 4 } \in A$
\item $ {{3,4}} \subset A$
\item $1 \in A$
\item $1 \subset A$
\item ${1,2,5} \subset A$
\item ${1,2,5} \in A$
\item ${1, 2, 3} \subset A$
\item $\varnothing \in A$
\item $\varnothing \subset A$
\item ${\varnothing} \subset A$
\end{enumerate}
crap
??
Ann:
3 is true as {3,4] is an elmen tof A
TYPING on laptop is frustrating
4 is true
Confused about 5
5 is nonsensical because 1 isn't a set.
yes so 5 is wrong too lol
6 is true
7 is not true
8 is not true
Confused abou 9 and 10
my textbooks state that {} is subset of all set
no its not
right
correct
why do wesay that {} is subset of all sets
if a set X is a subset of a set Y
then every element of X is also in Y
the empty set has no elements
so by default, every element it does have is in every set
since it... has none
ok
there is no element in {} that is not in A
since {} has no elements
so it must be a subset
THATS WHAT I AM SAYING
yes
(its comparable to #1 and #3)
its false
yep, since the empty set is not an element of A
so if the empty set is an element of this set, it cant be a subset of A
@short sorrel the 3 is wrong says the answer key
that's... weird. 3 should be correct.
3 is true
If A = { 3, 5, 7, 9, 11 }, B = {7, 9, 11, 13}, C = {11, 13, 15}and D = {15, 17}; find
(i) A ∩ B (ii) B ∩ C (iii) A ∩ C ∩ D
(iv) A ∩ C (v) B ∩ D (vi) A ∩ (B ∪ C)
(vii) A ∩ D (viii) A ∩ (B ∪ D) (ix) ( A ∩ B ) ∩ ( B ∪ C )
(x) ( A ∪ D) ∩ ( B ∪ C)
I misread the answer key again
How is this difficult?
🙀
I mean, $A \cap B = {7, 9, 11}$ is kinda child's play.
Rajarshi:
sorry bossman
I must be dumb, but I have a question thats
"Which points are the same as (5,64 degrees)?"

So I thought of just going with coterminal angles so like (5,424) and (5,-296)
but the answer also includes (-5, 244) and (-5,-116)
to which I dont understand the latter answers
Yeah, this is the one. This ought to make it easier.
@shrewd urchin use this one to solve it.
@tidal sequoia
(2.1918557339453875, 4.493970231495835)
This point, I think.
I mean, (5, 64 degrees) is in Polar coordinates, right?
oh ok
I was just confused because polar coordinates tend to do radian measurements so I forgot derp
thx
Glad to be useful.
useful in exams
it helps to model things like, well, coordinates for navigation
that aren't served well by an Cartesian coord system
so it's just an alternative model to something that can already be modeled, but it's just more user-friendly for the application(s)?
kinda
In the equation above, a, b, c, and d are constants. Which of the following is a factor of ax^5+bx^2+cx+d if the equation has roots 2, 5, and −7 ?
How would I do this?
I dont know how to facotr
yes
when we factor a polynomial, we break it into a form that shows its roots
for example, a root of 2 means the polynomial is 0 when x = 2
so if we have the factor (x - 2)
this corresponds to a root of 2
since when x = 2, (2 - 2) = 0, so our polynomial is multiplied by 0
and anything multiplied by 0... is 0
so let's try and reverse-engineer our polynomial with this knowledge
it has roots of 2, 5, and -7
these correspond to the factors (x - 2)(x - 5)(x + 7)
can you see why?
yes
(2-2) = 0 and (5-5) = 0
@short sorrel Would that be all I have to do? just find the opposite of the root given?
that lets you find the factors we know
are any of those choices?
and yeah, you "find the opposite"
2,-2,5, and -7 are all the choices i have for my answers
more precisely, you rearrange the equation:
x = 2
x = 5
x = -7
for 0
Would -2 be the answer since its the only one that +/- my root or 2, would be 0?
not quite, in that case
(x - 2) is a factor, but we dont know whether is a factor yet
can you expand (x-2)(x-5)(x+7) into a polynomial?
ax5+bx2+cx+d=0
In the equation above, a, b, c, and d are constants. Which of the following is a factor of ax5+bx2+cx+d if the equation has roots 2, 5, and −7 ?
thats the exact wording
A
x+2
B
x−2
C
x+5
D
x−7
ok thank you
a root of 2 corresponds to the factor (x - 2)
because a root makes a polynomial equal to 0
and if we input 2 into (x-2), we get (2-2) = 0
anything multiplied by 0 is 0 (remember, a factor is something you multiply by)
so when we have a root of 2, we have a factor of x - 2
again, we can think of this as rearranging x = 2 to be equal to 0
x = 2
subtract 2 from both sides
x - 2 = 0
ok thank you
Which of the following expressions is equivalent to x2−5x+1 / x−2
can anyone help me?
A
x−7+15/x-2
B
x−7−13/x-2
C
x−3+ 7/x-2
D
x−3− 5/ x-2
<@&286206848099549185>
Eh close enough
im not sure
its polynomial division my man
yes
wait long division?
Parentheses are your friends —Ann
yea but with variable expressions instead of numbers
oh
its essentially the exact same process except with variables
so if you have a good grasp
the part that remains a fraction is just the remainder
If u(x)=7x^2+19x−27 and v(x)=7x^2−8x−9, then the function w(x)=u(x)−v(x) must be divisible by which of the following?
A. 2
B. 6
C. 9
D. 12
<@&286206848099549185>
is this pre calc?

doesnt look pre calc
Why bot not working
think im3
not sure though
I dont understand what to do since 7 is an integer which can not be divisable
where does w(x) come from
you have to wait 15 minutes
oh ok
that is how the question is worded
read #❓how-to-get-help
i copy and pasted the exact wording
i feel like if you examine how to get to w(x) youll see the question is easier than you think
@charred hull 1) the bot isn’t even online, 2) the sentence there means you can only tag helpers if you’re in #❓how-to-get-help 
o shit speyr down
speyr doesnt work anywhere else



