#precalculus

1 messages ยท Page 117 of 1

hexed ermine
#

because there are two points where sin is -sqrt3/2

void patio
#

@upper smelt it sounds like to me you don't know the unit circle very well

hexed ermine
#

Yes

void patio
#

yeah

#

oh ouch

#

i understand

charred jasper
#

<@&286206848099549185> Can i get some help on parametric equations?

charred jasper
#

please

gritty blaze
#

Show it !!!

true vigil
#

yeah just ask!

thick raptor
#

rip

prisma tapir
#

not sure of this would be in calc or precalc but does anyone know how to help me with this
i know that the sum from k=0 to n of k^2 = (n(n+1)(2n+1))/6
but how would you do it for any power like 5 or 1/2

gleaming wing
#

Math steps unclear. Now stuck in the 5th dimension. What do?

zenith juniper
#

Hi. Where can I find hard questions that are tricky and so regarding a certain subject?

granite stirrupBOT
viscid thistle
#

what ^

viscid thistle
#

I got -1 for Horizontal asymptote, and -2 & 2 for vertical asymptote but it

#

'is incorrect

clever inlet
#

how'd you get -1 for horizontal asymptote?

#

@viscid thistle

viscid thistle
#

where the top part intercepts athe the infinite curve

clever inlet
#

?

#

just use the red dotted horizontal line

viscid thistle
#

I thought that was the y-intercept asymptote

clever inlet
#

?

hexed ermine
#

Lol

#

The y-intercept asymptote

clever inlet
#

Don't all horizontal asymptotes have some form of y intercept?

hexed ermine
#

Indeed so

true vigil
odd lichen
#

@clever inlet you still need help?

queen ibex
#

Dont mind the math test mark lol

viscid thistle
#

7?

queen ibex
#

yep

hexed ermine
#

Okay

#

So you started off a bit correct

#

You want to determine the amplitude and and the vertical shift

#

which so far would be 4cos(x)-1

#

now what we need is the b and c value

#

@queen ibex

queen ibex
#

ok how do i find that? thats where im lost on

hexed ermine
#

Alright

#

so first find the period

#

What you want to do is subtract the x coordinates

#

$$\frac{\pi}{6}-\frac{-\pi}{3}$$

granite stirrupBOT
hexed ermine
#

Using simple algebra

#

pi/6-(-2pi/6)=pi/2

#

Got it so far?

queen ibex
#

yea

hexed ermine
#

Okay so that's the distance from the minimum to the maximum

#

that means its a half a period

#

so multiply that by 2 to get the full period

#

Which is just pi

#

so pi is the period

#

Now you know that 2pi/b is the period right?

queen ibex
#

yep

hexed ermine
#

Okay so we do 2pi/b=pi

#

since pi is the period

#

and we can say that b is 2

#

2pi/2 = pu

#

pi*

queen ibex
#

Wait dont u do 2pi/b=7pi/6?

hexed ermine
#

No

#

pi is the period

queen ibex
#

ok

hexed ermine
#

Okay so we have so far

#

4cos(2x)-1

#

now lastly we need to find the phase shift

#

Which is defined as c/b

#

Now I prefer to use cosine first bc it's easier for this problem imo

#

I notice that the maximum is pi/6 to the right

#

So what I can do is c/b=pi/6

#

and we said that b is 2 already

#

$$\frac{c}{2}=\frac{\pi}{6}$$

granite stirrupBOT
hexed ermine
#

Cross multiply 2pi=6c

#

c=pi/3

#

There you have it

#

and since it's pi/6 to the right you do -pi/6

#

So we have as a final answer..

#

$$4\cos(2x-\frac{\pi}{3})-1$$

granite stirrupBOT
hexed ermine
#

got it?

queen ibex
#

yep

hexed ermine
#

Alright and finding the sin is answer

queen ibex
#

i didnt know u can find the shift like that

hexed ermine
#

You can!

#

So do you know how to find sin version?

queen ibex
#

is it the same thing but different shift value??

hexed ermine
#

yep!

#

pi/2 degrees out of shift

#

so just add pi/2

queen ibex
#

ok thank you so much

hexed ermine
#

No problem

queen ibex
#

@hexed ermine can C/B to find phase shift can be used for sine equations as well???

hexed ermine
#

Indeed

#

the only thing you need to do is add pi/2

#

since cosine and sine waves are 90 degrees out of sync

queen ibex
#

ok thank you

fringe stream
#

I highlighted the important parts for you

viscid thistle
#

Draw a force body diagram first @upper smelt

#

So just draw a diagram first showing the respective forces

#

Yes

#

Weird that forces are in kg not N

#

Oh I see

#

Anyways, you could decompose each vector into their x and y components then add them up for resultant force

#

Assume one of the forces is parallel to the x axis for convenience

#

How does your pic look like, I'm on android so can't draw sorry

#

If you draw a diagram, the x component is just cos theta multiplied by the magnitude of the vector

#

Y is sin theta nultiplied by mag

#

Add together the components, use pythag to find magnitude: sqrt (x^2 + y^2)

#

Angle is just arctan y/x

#

Nice, there's an answer on homework help server too for your q @upper smelt

#

Same method

#

Llama's method is probably best way

#

That's what I would've done

severe snow
#

can anyone help me with parametric equations

viscid thistle
#

Ok

severe snow
#

@viscid thistle How do I graph this stuff

viscid thistle
#

What are the eqns

severe snow
#

x=4cos^3(t)

#

y=2sin^3(t)

viscid thistle
#

Add them

#

x+y=4cos3 (t)+2sin3 (t)

#

Try get rid of the t

#

Then you are left with only x and y then you can graph

fringe stream
#

@cosmic nacelle

#

=tex \sin ^2 (x) \leq \dfrac{1}{2} ~in~ 0\leq x <2\pi

granite stirrupBOT
cosmic nacelle
#

yeah

fringe stream
#

What have you tried?

cosmic nacelle
#

ive already tried 0<=x<=pi/4, 3pi/4<2pi

#

@fringe stream hello?

fringe stream
#

Oh sorry

#

$$-\frac1{\sqrt2} \leq \sin{x} \leq \frac1{\sqrt2}$$

granite stirrupBOT
fringe stream
#

Try solving this

cosmic nacelle
#

umm

fringe stream
#

=pup sinx from 0 to 2pi

granite stirrupBOT
cosmic nacelle
#

0<=x<=pi/4

#

3pi<=x<=5pi/4

#

7pi<=x<2pi

fringe stream
#

All values of x greater than that for which sin(x) is -1/sqrt2, and all values of x less than that for which sin(x) is 1/sqrt2

#

Between 0 to 2pi

cosmic nacelle
#

???

fringe stream
#

=pup solve -1/sqrt(2) <= sin(x) <= 1/sqrt(2)

granite stirrupBOT
fringe stream
#

=pup solve -1/sqrt(2) <= sin(x) <= 1/sqrt(2), x between 0 and 2pi

granite stirrupBOT
fringe stream
#

=pup solve -1/sqrt(2) <= sin(x) <= 1/sqrt(2), 0 <= x < 2pi

granite stirrupBOT
cosmic nacelle
#

hey @fringe stream i put in your answer, and it was wrong

#

idk why

dense zealot
#

Lol

simple vault
#

#8

#

I dont understand how to do those kind of questions

hexed ermine
#

Make time stamps and plot it on a graph

#

If it makes 1.5revolutions per minute/ that means it makes 1 revolution every 1/1.5minutes

#

so 1 revolution = 40sec

hexed ermine
#

You know i've been working through this problem and im not sure if you can do it

#

This is the closest thing I have to it

#

you need a function where it goes up and down in a linear fashion and im not sure if there is a way

#

<@&286206848099549185>

#

Maybe they might know

grizzled hull
#

Gut says $$150\sin\left(1.5x\right)+156$$

granite stirrupBOT
grizzled hull
#

No, no....

#

$$-75\cos(\frac{3}{4\pi}x)+75+6$$

granite stirrupBOT
simple vault
#

I dont understand how you got that @grizzled hull

grizzled hull
#

I'm still editing it.

simple vault
#

ok

hexed ermine
#

I mean I think mine would be correct maybe thonker

#

$$|150\sin(\frac{\pi}{40}x)|+6$$

granite stirrupBOT
hexed ermine
#

Final answer lol

simple vault
#

it doesnt say its right on the website

hexed ermine
#

huh okay I guess ill wait for Shenzao

simple vault
#

I hate webassign lol

#

wouldnt the amplitude be 156?

#

since its 150 feet + the wheel(6)

grizzled hull
#

Want amplitude to be radius.

#

Radius is 75

hexed ermine
#

but mine is in seconds

grizzled hull
#

We translate it up by radius + height above ground

#

So we have at least $$-75\cos(_)+81$$

granite stirrupBOT
grizzled hull
#

I just need to figure out how to make periodicity of -cos(x) 1.

hexed ermine
#

2pi/b=period

#

1.5minute is one period

grizzled hull
#

Mm. Didn't see"minute" there.

hexed ermine
#

oops

grizzled hull
#

still, 1.5 per minute is 3 per two minutes.

hexed ermine
#

1.5revoltions per minute :v

#

so 2/3 is period

simple vault
#

I get the period from the revs/min?

hexed ermine
#

It makes one revolution in 40seconds

#

or 2/3 minutes

#

so put 3pi as b????

#

2pi/b=2/3

grizzled hull
#

$$-75\cos\left(3\pi x\right)+81$$

granite stirrupBOT
grizzled hull
#

I like this one.

#

Feels right.

#

3 full revolutions in 2 minutes.

hexed ermine
#

Yes

grizzled hull
#

Minimum height is 6.

#

Maximum height is 156.

#

Feels right.

hexed ermine
#

Looks correct to me

grizzled hull
#

@simple vault $$-75\cos\left(3\pi x\right)+81$$

granite stirrupBOT
grizzled hull
#

I dunno, I like $$-r\cos(2\pi\omega x)+r+h$$

granite stirrupBOT
grizzled hull
#

Let omega be the number of revolutions in a minute.

#

r is the radius of the ferris wheel.

#

h is the distance off the ground from the lowest point.

#

the negative starts it at the bottom.

#

Let it be positive if it starts at the top.

#

Use sin if it starts in the middle.

#

This make sense @simple vault ?

hexed ermine
#

I was on the right track :v

simple vault
#

That answer was incorrect

#

from what it shows on webassign

hexed ermine
#

Lol savage

grizzled hull
#

Did we miss a small detail?

fringe stream
#

It doesn't say if t is in minutes or seconds

grizzled hull
#

wrote it in terms of h and t, yes?

fringe stream
#

Try seconds maybe

grizzled hull
#

Something friendlier to the website may be $$h=-75\cos(3\pi t)+81$$

granite stirrupBOT
grizzled hull
#

Since it specified that it needed to be an equation in terms of h and t.

#

If you already did that, we'd just need to turn 3 into 180 to get it into seconds, I think.

fringe stream
#

Nope

#

pi/20

hexed ermine
#

yep

#

$$h = -75\cos(\frac{\pi}{20}t)+81$$

granite stirrupBOT
hexed ermine
#

Try that @simple vault

grizzled hull
#

Graphed that.

#

It looks way off.

#

No

#

It looks perfect.

#

Kill me.

#

I did that right, then edited it 6 times.

#

It seems I'm no longer confident.

hexed ermine
#

Nah your equation was good in terms on minutes

#

They really need to specify

simple vault
#

@hexed ermine also incorrect :/

fringe stream
#

It says equation

#

Try h = <...>?

grizzled hull
#

Where is your h=?

#

It wants an equation.

#

Needs an =

simple vault
#

um...?

fringe stream
#

Where's the h?

#

Do you need it written out for you?

#

Which, btw, has already been done, multiple times

hexed ermine
#

Write it just like that

fringe stream
#

If that doesn't work, replace pi/20 with 3pi

simple vault
#

3pi worked

hexed ermine
#

:+1:

simple vault
#

so I have these set of problems here but I don't know how to go about approaching them. The textbook doesn't have good examples of it either

clever inlet
#

Think about what inverses do

#

They basically undo each other right?

#

@simple vault

simple vault
#

yes

#

wait

#

so they cancel out?

clever inlet
#

Yes

simple vault
#

and the answer is whats left

#

in the parenthesis

clever inlet
#

It's the number

#

Yes

#

The arcsin function does something to the number

#

And then the sine function undoes that

#

Giving back your original number

simple vault
#

okay now what is the inverse is outside of the parenthesis?

#

if*

#

if the inverse is outside and the sine/cosine/tan is inside

clever inlet
#

I mean

#

They're still inverses to each other

simple vault
#

so theyd still cancel eachother out?

clever inlet
#

Yeah

stark trench
true vigil
#

mostly try to find the equation of the parabola

#

put the coordinate system with (0,0) at the vertex

pure hazel
hexed ermine
#

Where is the law of tangents ๐Ÿค”

mortal basin
#

what is the symmetry of sin and cos

ornate notch
#

Could you elaborate a bit more on that?

mortal basin
#

Sorry

#

Im reviewing my test

#

And the question is what type of symmetry does f(x)=sin(x) have?

#

I said neither

#

But that because i compeltely forgot

ornate notch
#

Oh, well, cos has reflective symmetry over the y axis then

hexed ermine
#

^

#

And sin(x) has symmetry at pi/2+pik

mortal basin
#

But its asking for odd or even

hexed ermine
#

For sin(x) at 0; it's odd

viscid thistle
#

Could anyone help me with this?

dense zealot
#

Yes x(x-2)(x-4)

viscid thistle
#

For f(x)>0
I presumed that the area in between is (2,0)โˆฉ(4,0)

#

but I got that wrong

viscid thistle
#

I think it's actually negative

#

but you can't go below two 0's in one place

#

so I am not sure how to write this

clever inlet
#

That does not look right

#

Go from left to right

#

It's positive from negative infinity to 0

#

And again from 2 to 4

wraith shell
#

Hello, is anyone available to help me understand how future and present values work? I was trying to answer the following question : "How does the interest rate affect the present and future values of an annuity?" This is my answer but after thinking about it more I don't think it is correct : "Assuming the time it takes to pay off a loan stays the same, the present value of an annuity with higher interests rates will have to pay larger annuities while the present value of an annuity with lower interest rates will have to play smaller annuities. Assuming the time given to future value annuity and the outcome is the same, higher interest rates correlate to lower annuities and lower interest rates correlate to higher annuities." It seems the more I think about this I start to get it and then I confuse myself.

wraith shell
#

Could you answer the question "how does the interest rate affect the present and future values of an annuity?" by saying...

#

Higher interest rates increase the future value, and lower interest rates increase the present value?

rotund musk
#

can someone help me simplify a trig expression?

haughty thicket
#

If you send the trig identity sheet

rotund musk
#

well I can't find a good trig identity for sin(sq)x-1

#

there are a bunch for 1-sin(sq)x

wintry moat
#

here is the right one then

#

naturally it should work

#

got something

#

@rotund musk

#

just found : -1+sin(s*q)*x

rotund musk
#

that doesn't work. I just checked.

wintry moat
#

yeah checked too

rotund musk
#

wait

#

yes it does

wintry moat
#

website is shitty

rotund musk
#

SHIT

wintry moat
#

oh

#

lol

#

had also this one in mind

#

hope i couldve help you a bit

#

๐Ÿ˜ƒ

#

first it was like ( dosent support multiple functions ) and then you just had to adjust it a bit

#

I believe that the internet/ computing all these huge ressources made possible a lot of complex / boring tasks such as these calculations and made our lives just simpler and eaiser. If you were to go on math , go on computational / symbolic algebra

#

machines do the hard work for you

#

Like imagine a huge repertoire where hunders and thousands of devolopers contribute their efforts in calculating stuff like a huge dictionnary and compile all of that

#

main intrest left is just to learn new concepts on and on

#

back then it was just as boring as it might seem

viscid thistle
#

Calculatorsbare best

candid vine
#

Wow.

viscid thistle
#

๐Ÿ‘Œ

dense zealot
#

@candid vine did u simplify it

#

It's the imaginary part of (cosx + isinx)^17 divided by i

candid vine
#

I can complexify it

dense zealot
#

U can use binomial theorem

static zinc
#

Regarding my question yesterday, this is what I needed:

static zinc
#

And from then I look up the value in radians and solve for x. Sorry for the mess

naive surge
#

do you guys have any tips on remembering reduction, half-angle, etc. formulas other than just writing it a ton.

true vigil
#

half angle formulas are dumb

#

you can get all of them from sin though

#

by noting cos(x) = sin(x+pi/2)

naive surge
#

lright thank you

eternal solstice
#

I know that the Amp = 2 , Midline = 0 and the Period is 6 which is 2pi/6 so pi/3

#

It is a cosine function shifted to the right one unit so that would be -1

#

Therefore the answer should be -2cos(pi/3x - 1 )

#

It looks almost identical on desmos but I cant get it to line up perfectly.

rocky bison
#

ok

#

So starting with

#

You want to use cos

#

Now

#

=pup plot cos(x)

granite stirrupBOT
rocky bison
#

Now problem 1

#

cos only goes between 1 and -1

eternal solstice
#

Ok

rocky bison
#

You want 2 and -2

#

So you're going to just multiply by 2

#

So currently we have 2cos(x)

eternal solstice
#

Amplitude should = 2

rocky bison
#

Which lines up in y

eternal solstice
#

yeah

rocky bison
#

=pup graph 2cos(x)

granite stirrupBOT
rocky bison
#

Looks good

eternal solstice
#

Yep.

rocky bison
#

Now

#

Period is 6

#

So we need to somehow convert our current period of 2pi

#

into 6

eternal solstice
#

divide 2pi by 6 and simplify

rocky bison
#

I'm going to do this algebraically

#

Just for clarity

eternal solstice
#

Sure thanks

rocky bison
#

Some multiple of 2pi will equal 6

#

let's call it k

#

So =tex 2k\pi=6

#

=tex 2k\pi=6

granite stirrupBOT
rocky bison
#

Now we're just going to solve got k

#

=tex k=\frac{6}{2\pi}=\frac{3}{\pi}

granite stirrupBOT
rocky bison
#

nice

eternal solstice
#

Oooh

rocky bison
#

btw this is using radians hopefully that's no issue

eternal solstice
#

I think that might be where I messed up?

rocky bison
#

Hold up

#

We want the inverse of that function

#

Because we'll be making a transformation

#

Of type

#

f(ax)

#

Which is a "squeeze" of a

#

Wait no that's good, 6 is less than pi

#

nvm

#

Let's graph it and see if period is correct though

#

=pup plot 2\cos(\frac{3x}{\pi})

granite stirrupBOT
rocky bison
#

ok

#

that's a little bit off

#

So there's an issue somewhere here

eternal solstice
#

I think pi/3 might be the correct period

rocky bison
#

Yep

#

It is

#

It is the reciprocal

#

1/a

#

stupid mistake

#

whatever though

#

=pup graph 2cos(\frac{\pi x}{3})

granite stirrupBOT
rocky bison
#

ok

#

perfect

#

now last

#

we want the first peak

#

at -2

#

you can choose any point on the graph

eternal solstice
#

so -A

rocky bison
#

just make it consistent

#

not -a

#

+a

#

It's of type

#

f(x+a)

#

which shifts everything left

#

by a

#

So from 0 to 2

#

2

#

=pup graph 2\cos(\frac{x\pi}{3}+2)

granite stirrupBOT
rocky bison
#

Looks pretty good

#

So your function

#

=tex 2\cos\left(\frac{x\pi}{3}+2\right)

granite stirrupBOT
rocky bison
#

Hopefully that was useful to you

eternal solstice
#

It was

#

But the software doesn't like that answer either.

#

But it does look very similar to it on desmos

rocky bison
#

what software?

#

desmos?

eternal solstice
rocky bison
#

probably because it wants sin

#

not cos

eternal solstice
#

Ok. So the amplitude and the period and the midline will be the same

rocky bison
#

Not sure what midline is

eternal solstice
#

So i just need to find the horizontal shift

rocky bison
#

Ye

eternal solstice
#

midline is y=0

#

the line that shifts the graph directly in the middle

rocky bison
#

Urm

#

well

#

just use

eternal solstice
#

splits*

rocky bison
#

=tex \sin(x)=\cos\left(x-\frac{\pi}{2}\right)

granite stirrupBOT
rocky bison
#

Although might not like that

#

Might be easier starting agian

#

Also tests your understanding

eternal solstice
#

like a new problem completely?

rocky bison
#

yeah

eternal solstice
#

I can reset it. Ok

rocky bison
#

I'm heading to sleep though, so goodluck ๐Ÿ˜ƒ

eternal solstice
#

Appreciate it.

#

thanks

jolly turret
dense zealot
#

Hi

jolly turret
#

hi

dense zealot
#

have you tried row reductions

jolly turret
#

not sure what that is

dense zealot
#

inverses?

jolly turret
#

do you mean like get zeros in the other rows?

dense zealot
#

No

unborn mist
dense zealot
#

If u wanna solve a 3x3

#

U find the inverse

#

Then transpose

#

Well I guess there r faster ways

unborn mist
#

gaussian elim to get 4/5 for z

#

your last step is wrong

#

if you do r1+r3 you get 1 in the first column third row

#

but you set it to 0

jolly turret
#

oh ok yeah that last step really messed me up

candid vine
#

I don't understand what you are doing, what is that 4th columnsupposed to represent?

jolly turret
#

its a system of equations and the 4th column is the = to part like 4x +5y + 6z = 7 ... the 7 would be on the 4th column

candid vine
#

Oh you write your systems like that, that's weird :o

jolly turret
#

its just something in math i guess

candid vine
jolly turret
#

theyre called matrices

unborn mist
#

its a linear algebra concept

#

of gaussian elimination in matrices

#

look up augmented matrices

jolly turret
#

i shall be back when i fail this next practice example lol

candid vine
jolly turret
#

got the next one right panda_happy

jolly turret
candid vine
#

Line 1 minus Line 3

#

You have 2y = 7

#

So y = 3.5

jolly turret
#

im trying to use the matrices though

candid vine
#

Well you write your matrice, you do line 1 minus line 3

#

The method doesn't change

jolly turret
#

it does

wind igloo
#

Why don't you show us what you've done?

jolly turret
#

give me a sec i did the problem multiple times so ill try to separate the work

candid vine
#

It's just that you wrote 2 instead of -2 in the first matrice (last line, last column)

wind igloo
#

You made a mistake copying down the right hand column.

#

One of those values should be -2

candid vine
#

Those sorts of mistakes are the worst, you never see them when you make them

wind igloo
#

Sign errors are some of the hardest errors to catch.

jolly turret
#

on which set?

wind igloo
#

If you look at problem 37, you have ... = 5, ... = 2 and ... = -2

#

But your right hand columns in the top line do not contain -2.

jolly turret
#

oh my god

#

i made the same mistake on my first attempt when i wrote the second set smh

true vigil
#

double check when you copy stuff

jolly turret
#

its funny because i usually get more errors on that kind of stuff than anything else

#

by the way gator would you if you add line 1 to line 3 get 2x + 2y = 7?

wind igloo
#

2x+2y = 3

jolly turret
#

oh wait nvm i see now

wind igloo
#

Err. 2x + 2z = 3

jolly turret
#

its the negative of the 3rd line

wind igloo
#

Yes

jolly turret
#

do you guys know if there are solutions when a row in a matrix is 0 = SomeNumber? Normally if its all zeros id say z=z but with this is it just no solution?

unborn mist
#

inconsistent system

wind igloo
#

Agreed. There are no solutions.

haughty portal
dense zealot
jolly turret
#

sounds good. i was making sure there wasnt something like for dependent systems

sacred eagle
clever inlet
#

do you know the identity?

sacred eagle
#

no

#

what identity

#

do u mean like

#

cos sine sine cos

clever inlet
#

hmm, does this actually require the identity?

sacred eagle
#

not sure

clever inlet
#

i'm pretty sure it does

sacred eagle
#

how can i solve it though

#

after this its gonna ask me for tangent and sine too

dire crypt
#

hello

#

so do you know the identity

sacred eagle
#

i dont

dire crypt
#

cos(a+b) = cos(a)cos(b) - sin(a)sin(b)

sacred eagle
#

do i need to make the triangle and find the missing side for each one

dire crypt
#

yea, given hypotenuse = 1, sin(a) = 15/17, you can find cos(a)

#

etc

#

but you have to be careful about the signs of the cosine values

#

for example

#

if sin(a) = 15/17, and a is in quadrant I

#

will cos(a) be positive or negative?

sacred eagle
#

mnissing isde is 8

#

it will be positive

dire crypt
#

so if the missing side is 8, what is cos(a)?

sacred eagle
#

all are positive in 1st quadrant

dire crypt
#

yea

sacred eagle
#

8/17

dire crypt
#

yep

#

seems like you have a fine hold of the problem. any other questions?

sacred eagle
#

whats the next step ?

#

is it just

#

8/17 + 7/25

dire crypt
#

well, to find cos(a+b)

#

you use the formula

#

that

#

cos(a+b) = cos(a)cos(b) - sin(a)sin(b)

#

so you can substitute the values you have for cos(a), sin(a), cos(b), and sin(b)

#

remember

#

cos(a+b) does not equal cos(a) + cos(b)

sacred eagle
#

8/17 x 7/25 - 15/17 x 24/25

dire crypt
#

yep

sacred eagle
#

200/425 119/425 -

#

is that

#

right so far ?

#

i havent solved something like this before so

dire crypt
#

I think you multiplied the numerators incorrectly

#

&& \frac{8}{17} \cdot \frac{7}{25} = \frac{56}{425} and -\frac{15}{17} \cdot \frac{24}{25} = -\frac{360}{425} $$

sacred eagle
#

is it just 8 x 7 ?

dire crypt
#

[(8 x 7) - (15*24)]/425

sacred eagle
#

$$ \frac{8}{17} \cdot \frac{7}{25} = \frac{56}{425} and -\frac{15}{17} \cdot \frac{24}{25} = -\frac{360}{425} $$

granite stirrupBOT
dire crypt
#

(56-360)/425

#

-304/425

sacred eagle
#

wait

#

wahts 56 - 360

dire crypt
#

-304

#

so some important identities to know are sin(a+b)=sin(a)cos(b) + sin(b)cos(a)

#

and the one for cosine

sacred eagle
#

oh i understand how u got the answer now

#

but it says its wrong when i entered it

dire crypt
#

for cos(a+b)?

sacred eagle
#

yeah

dire crypt
#

you typed only 304, right? not -304 (since it puts the negative there for you)

sacred eagle
#

i tested both

dire crypt
#

ohh

#

it says that b lies in quadrant II

#

sorry

sacred eagle
#

what does that do

dire crypt
#

so the cos(b) should be negative

sacred eagle
#

so its 416/425 ?

dire crypt
#

well -416/425

#

but yea, you would type 416

sacred eagle
#

it doesnt put negative for me

#

i have to do the -

#

ok it worked

dire crypt
#

alright sweet

sacred eagle
#

what is the identity for sin now ?

#

sin ( a + b)

#

sin(a+b)=sin(a)cos(b) + sin(b)cos(a)

#

ok

#

thx

#

i saw it up there

dire crypt
#

if you ever wanted to find them online, you can search angle addition formulas

#

also

#

since you already know cos(a+b), you could also try to complete the triangle

#

but if you did it by completing the triangle, you would have to figure out which quadrant a+b is in

sacred eagle
#

that seems complicated lol

#

im opening paint to draw triangles

dire crypt
#

you could always just use the sin(a+b) formula

#

so that you don't have to figure out the quadrant

#

the only reason finding the quadrant is necessary

sacred eagle
#

yeah im gonna use that

dire crypt
#

oh alright

sacred eagle
#

but i draw the triangles so i can figure out the sin and cosine

dire crypt
#

didn't you already figure them out?

sacred eagle
#

yeah but i did it all in my head

dire crypt
#

oh, do you need to show work?

sacred eagle
#

no

#

its just

dire crypt
#

yea that's fine

sacred eagle
#

better if i can just look at it than try to remember it

#

lol

#

is that the quickest way to solve these

#

with the indentity ?

#

and what is the identity for tan(a + b )

dire crypt
#

The identity is going to be the fastest

#

for tan(a+b)

#

well

#

I never remember the identity for this one XD

#

because usually

sacred eagle
#

oh it gave it to me

dire crypt
#

you can just use the fact

#

that

#

tan(a+b) = sin(a+b)/cos(a+b)

sacred eagle
#

yeah

#

how do i do that lol

#

-416/ 425 // 87/425

dire crypt
#

oh

#

just multiply by one

#

:D

#

for gnarly fractions like that

#

you can use the property that anything times one equals itself

#

like

#

2 x 1 = 2

#

fancy

#

but

#

you also know that, for example

#

2/2 = 1

#

$$ \frac{\frac{-416}{425}}{\frac{87}{425}} $$

granite stirrupBOT
dire crypt
#

so this is the fraction

#

and since anything times 1 equals itself

sacred eagle
#

so -416 / 87 ?

dire crypt
#

yea

#

just multiplying numerator and denominator by 425 (aka multiplying the entire thing by 1)

sacred eagle
#

it says its wrong

dire crypt
#

uh

#

and 87/425 is indeed correct for sin(a+b)?

sacred eagle
#

yes

#

do i need to take off the negative sing for tan

dire crypt
#

oh shoot

#

you did cos(a+b)/sin(a+b)

#

instead of sin(a+b)/cos(a+b)

sacred eagle
#

what do u mean

dire crypt
#

keep the negative sign

#

I mean

sacred eagle
#

i did the identity for each one

dire crypt
#

sin(a+b) = 87/425

#

cos(a+b) = -416/425

sacred eagle
#

yes i got those correct

dire crypt
#

tan(a+b) = sin(a+b) / cos(a+b)

#

so it should be

#

$$ \frac{\frac{87}{425}}{\frac{-416}{425}} $$

granite stirrupBOT
sacred eagle
#

is that 87/-416

dire crypt
#

yea

#

remember

#

you can take the negative sign up to the numerator

#

by multiplying numerator and denominator by -1

#

just a by the way sorta thing

sacred eagle
#

so it should really be -87/416 ?

dire crypt
#

yea, they're the same thing, but it's more common to put the negative sign in the numerator

sacred eagle
#

oh ok

#

that worked

dire crypt
#

did everything make sense?

sacred eagle
#

yes

#

i can do these now

dire crypt
#

if you want, I can show you how the cos(a+b) formula was derived

#

kinda fun ๐Ÿ˜„

sacred eagle
#

yes i want to

#

but

#

first i need to finish this homework

dire crypt
#

alright

sacred eagle
#

its taking me like 3 hrs now

#

im on question 11 out of 30

dire crypt
#

aw

#

well

#

I mean one problem at a time

#

you got dis

#

I'm going to go now though, sorry :/

#

good luck though

sacred eagle
#

alright

finite crescent
#

I'm not sure what I'm doing wrong for this problem. My understanding of the definition of the secant line is that it is just the line between two points of a function.(edited)
My understanding to find the solution to this problem is y = 42 * ((heartbeats at t - 2936)/t - 42)
but the website doesn't like my answers

haughty thicket
#

Your first one should be

#

=tex \frac{2936-2804}{42-40}

granite stirrupBOT
haughty thicket
#

That is the slope of the tangent line

#

Which is the same as the slope of the secant line

finite crescent
#

Huh, that's what I have and it doesn't accept it. 1

wind igloo
#

The numbers shown in the image are not what @haughty thicket has calculated.

#

The calculation above gives, approximately, 66 beats/min

opaque parrot
#

can anyone suggest me good website for learning function sketching?

meager nymph
#

Iโ€™m on 4. The answer is going to be in fractions like is for the example problem at the top of the pic. I can also show an example problem if that helps. I am confused when sliding everything to one side and then the factoring.

hexed ermine
#

Make everything in terms of sin first

#

And factor out a 2 on RHS

eternal solstice
storm stirrup
#

ayyyy general solutions

eternal solstice
#

I know that I can use the double- angle formula to turn it into 16sin(x)cos(x)+15sin(x)=0

#

Do i combine like terms?

storm stirrup
#

Let me quickly do it

#

Then I'll come back to u

eternal solstice
#

Thanks

storm stirrup
#

Oh cool it's asking for non exact answers

#

Phew

#

So yeah getting to 16sin(x)cos(x) + 15sin(x) = 0 is correct

#

You just have to factor out sin(x)

#

So you get sinx(16cosx + 15) = 0

#

This is true when either sin(x) = 0

eternal solstice
#

Ok

storm stirrup
#

or 16cos(x) + 15 = 0

#

Go from there, if you get stuck just shoot. List your solutions here before you input them

eternal solstice
#

So i need to solve for x for the last solution?

storm stirrup
#

In both

eternal solstice
#

Ok. Thanks for pointing me in the right direction. Let me try and figure the rest out.

storm stirrup
#

Make sure you find ALL solutions between 0 and 2pi, you should have 4

eternal solstice
#

@storm stirrup Ok so I know that sin is 0 at 0, and pi

storm stirrup
#

tep

#

yep

eternal solstice
#

but I'm blanking on how to find the other two values. cos(x)=-15/16

storm stirrup
#

So for the other two values

#

The first one you can find by simply putting in your calculator arccos(-15/16)

#

Make sure you're in radians

eternal solstice
#

ok I got 2.786

#

arccos is the samething as cos^-1 right?

storm stirrup
#

yeah

#

Just a different way of writing it

#

Do you have or know a formula for general solutions?

eternal solstice
#

+2pi n ?

storm stirrup
#

Because you're dealing with cos(x)

#

You have cos(x) = cos(2.786)

#

And because trigonometric functions are cyclic, you can use the general solutions formula for cosine

#

so x = 2n(pi) +- 2.786

#

You just have to find the integer(s) "n" that make x between 0 and 2pi

eternal solstice
#

So i could subtract?

storm stirrup
#

yeah

eternal solstice
#

2n(pi)-2.786?

#

because if I add, it would put me over 2pi

#

ok

storm stirrup
#

yeah

eternal solstice
#

Still cant figure out that number.

#

357.21?

#

Nvm nvm nvm

storm stirrup
#

Well the only two values of n that allow for an x between 0 and 2pi are n=1 and n=0

eternal solstice
#

I thought i could do 360- the value

storm stirrup
#

Yeah stay in radians

eternal solstice
#

but i had to do 2pi-2.786

storm stirrup
#

yep

eternal solstice
#

Great. Thanks for the help.

storm stirrup
#

So what are your 4 solutions?

eternal solstice
#

I was stuck on that for quite a while.

#

0, pi, 2.786, 3.5

storm stirrup
#

Yep

#

To 2d.p. they would be 0.00, 2.79, 3.14, 3.50

eternal solstice
#

Very helpful. Thank you.

dense trellis
#

how do you find the inital speed of a function

#

for example

earnest sable
#

initial speed of a function?

bold isle
#

Mmmmmm are you talking about integrals and that such?

hexed ermine
#

Probably if you are talking about time being as x values; at when x=0

#

So at 7

bold isle
#

@dense trellis show us the complete problem

dense trellis
#

its literally that function and it was in a test involving rate of change and instataneous and stuff

#

and it asked for the initial speed

bold isle
#

i agree with PJS in any case ๐Ÿ˜…

lucid spindle
#

-9,8x+13,4

#

Fill in x 0

#

You get 13,4

#

Thats the initial speed

rocky bison
#

but what is that function is speed and not displacement thonker

#

It's too ambiguous

earnest sable
#

@lucid spindle thats only the vertical speed

lucid spindle
#

Isnt that what they asked for?

earnest sable
#

they asked for the initial speed
they equation they gave is y=f(x)

#

you would initially have to find the 2 equations x = f(t) and y = f(t) and then sub one into the other to get y = f(x)

rocky bison
#

How is that just vertical speed?

#

He took a differential of the graph which I assumed was based on the idea it's a displacement function

#

@earnest sable

wind igloo
#

Meh. It's a poorly-framed question.

#

The form of the equation, f(x) = -4.9x^2 + 13.4x + 7 -suggests- that it ought to be displacement as a function of time.

#

Because -4.9 is -9.8/2, which happens to be the acceleration due to gravity in m/s^2

#

That said, Dusty isn't wrong in that it only accounts for vertical displacement.

#

There is, however, no information given on what, if any, horizontal displacement/velocity/acceleration there is.

jolly olive
#

A particle is moving along the curve y^2 โˆ’ 6x^4 = y. At the moment when x = โˆ’1 the x-coordinate is increasing at the rate of 5 cm/sec. If the y-coordiante is negative at this moment, is y increasing or decreasing?How ast?

#

anyone know how to solve this

#

all i know is i need to take the derivative implicitly

#

nvm found a khan academy vid on how to do it

calm thicket
#

What is a "Trace" of a matrix? When and why would we need it?

#

I can google pretty easily to find it's the sum of the diagonals, but that doesn't tell me what it represents geometrically or answer the second question.

eternal solstice
#

Hi guys. Anyone available for some quick trig help?

#

I know how to replace the sin^2 with cos^2, and I know how to factor the equation. I get cos=-3/4 and cos = 1/2

#

I also know the values of cos = 1/2 between 0 and 2pi. But i struggle understanding how to figure out the values of cos=-3/4 over two pi.

earnest sable
#

can't you just do arccos(-3/4) forthat?

eternal solstice
#

Yeah I can gives me the correct value in the QII

#

Now I need to find the value in QIII

earnest sable
#

QIII?

eternal solstice
#

quadrant 3

#

Nvm. I think I figured it out. I was over thinking it.

#

take the value and subtract it from 2pi

hexed ermine
#

Yep

eternal solstice
#

or add pi/2

viscid thistle
#

For anyone interested, I spent some time on Desmos making an interactive Unit Circle

#

You can play around with it if you want

eternal solstice
#

Damn. That is pretty cool.

viscid thistle
#

Ty

hexed ermine
#

๐Ÿ‘๐Ÿผ

eternal solstice
#

Okay basic question. I need to distribute 3(2sinxcosx)

#

would it be 6sinxcosx or 6sinx3cosx

viscid thistle
#

Treat sin x and cos x as if they were just variables

#

It would be 6 sin (x) cos (x)

eternal solstice
#

okay thanks

viscid thistle
#

np

eternal solstice
#

arcsin(-.45) = -.4668

wind igloo
#

=tex sin\bigg(\frac{\pi}{2} + x\bigg) \neq sin(x)

granite stirrupBOT
viscid thistle
#

I hate how they use x there

#

Should be theta

wind igloo
#

Eh.

eternal solstice
#

so replace the x in that equation with -.4668?

#

I'm confused.

viscid thistle
#

Oh I see

#

It has to do with the Unit Circle

#

The graph I sent up in chat has some explanation

#

Do you have it open?

eternal solstice
#

yeah

wind igloo
#

No. That's a Not Equals sign.

#

You want this:

#

=tex sin(x) = sin(\pi-x)

granite stirrupBOT
viscid thistle
#

Ok so do you know how sine and cosine correspond with the Unit Circle?

eternal solstice
#

yes, cos in the x value, sin is the y value

viscid thistle
#

Ok so sine can equal -0.45 more than once, yes?

#

It equals it twice

eternal solstice
#

yes

viscid thistle
#

Try and visualize that

eternal solstice
#

ok sin is negative in the 3rd and 4th quadrant

viscid thistle
#

Yep

#

So since it's a circle, what's significant about these two values?

#

Hint: I'm talking about the x-coords

eternal solstice
#

I'm not sure

viscid thistle
#

They're opposites of each other

eternal solstice
#

oh yeah

viscid thistle
#

For example in another problem one would be x = 1/2 and the other would be at x = -1/2

eternal solstice
#

ok yes

viscid thistle
#

Hold on, no it's asking for the angle in radians not the x coordinate.

#

Damnit

#

Ok so you want to find arcsine (-0.45)

#

And that's one of your answers

#

You still here?

eternal solstice
#

Yeah I am

viscid thistle
#

kk

#

So find arcsine (-0.45)

#

In radians

eternal solstice
#

I found arc sin(-.45)

#

-.4668

viscid thistle
#

Ok good, but since we want our answer as a positive, what can we add to it?

eternal solstice
#

pi

viscid thistle
#

Close, ฯ€ is only halfway around

#

2ฯ€

eternal solstice
#

ohok

#

5.8164

viscid thistle
#

gg

eternal solstice
#

That answer is correct

viscid thistle
#

yes

eternal solstice
#

now i just need to find the other value

viscid thistle
#

Now we have to find the other

#

And I don't think it's the negative of it

eternal solstice
#

so 5.8164 is in the QIV right?

viscid thistle
#

Ok I know how to find it but it might be a bit tricky to explain

#

yes

eternal solstice
#

can't i just subtract pi/2 from our original answer

viscid thistle
#

Anything greater than 3ฯ€/2 is in quadrant IV

eternal solstice
#

because i need QIII

viscid thistle
#

No, you could only subtract ฯ€/2 if theta was halfway through Quadrant IV

#

(315 degrees)

eternal solstice
#

hmm

viscid thistle
#

I'll make a visual

#

The shaded areas are the same area, just mirrored across the y-axis

eternal solstice
#

ok

viscid thistle
#

So what we want to do to find the question mark is subtract 5.8164 from 360 degrees or 2ฯ€ to get the shaded angle

#

And then add that value to ฯ€

#

Can you visualize why that works?

eternal solstice
#

Yeah that helps

viscid thistle
#

Ok so

eternal solstice
#

So i got .4667

#
  • pi
#

3.6083

viscid thistle
#

(2ฯ€ - 5.8164) + ฯ€

#

Yeah let me get my calculator lol

#

Yep I got the same

eternal solstice
#

that is correct

#

Thanks for the help

viscid thistle
#

np

eternal solstice
#

I really need to get into the habit of drawing

#

I'm realizing im much more of a visual learner haha

#

so soon as I saw that picture it clicked.

viscid thistle
#

Visual representations always help, especially when you get into physics

#

Yeah me too

#

I need a video or a whiteboard in front of me lol

eternal solstice
#

Lol exactly.

#

I really appreciate the help. ๐Ÿ‘

viscid thistle
#

No problem man

gilded marten
hexed ermine
#

Some tips would be to determine the amplitude

#

and the period of the function

#

and if there is any vertical shift or phase shift

gilded marten
#

A=3 period= 8?

#

but would i write it as a cosine or sin?

#

and i think it is moved

hexed ermine
#

Well so far you have 3cos(x)

gilded marten
#

maybe cos -1

hexed ermine
#

now the period is 8

#

and period is defined as 2pi/b=period

#

so 2pi/b=8; solve for b