geometry-and-trigonometry

[upper karma]

I’m still confused I just need the b and c values from that equation

The answers should be -3/2 and 1/3 right?

Yes

No you just got the a and c values switched

Ok

The correct quadratic formula would be $\frac{ 7\pm 11}{-12}

The correct quadratic formula would be $\frac{ 7\pm 11}{-12}$

Ok thanks btw

And that gives you the answers you were looking for

Thx

[somber coyote]

Second Mikey:

[upper karma]

No

Np I meant

[untold peak]

when it asks for this is it asking for just the one missing side or the whole triangle?

including angles and such

[round isle]

very vague question, best you ask your teacher

[silent plank]

I'd interpret it as the whole thing

[upper karma]

yeah

i'd find the angles too

[dark bear]

would someone be able to help me identify where is this r=sqrt(m^2+1) equation is coming from?

its a calculus question but the equations at work here are more geometry based

[round isle]

where is figure 11

[dark bear]

@round isle its not needed but i can draw it for you

[wise hornet]

the width is 2 so if it's like a regular roof it'll be like two triangular prisms stacked face-to-face on the rest of the house

each with half the width, 1

[wise hornet]

slope is m and width is 1 so height is m

and it's a right-angled triangle, h^2 = 1^2 + m^2 = 1 + m^2

which they've called r idk why

[dark bear]

Ahh that makes sense @wise hornet . thank you sm

[inland canyon]

h3ll0

<@&286206848099549185>

rob is trying to open a can. he wants to find the arc length the can opener needs to travel to open the can half way the rtadius of the can is 1.5 inches

round your answer to the nearest hundreth of an inch

what do u need to find todo this

like i have all the info

it wouldnt be 3 would it

cuz thats the diameter

or would it be 7.06

[zenith garnet]

how do i construct an isosceles triangle with base angles of 30 degrees

nvm

[zenith garnet]

can someone help me with (a)?

i dont really know the congruence rule im looking for here

thanks!

[tough pilot]

When it comes to understanding a general topic or rule, I’d recommend googling before anything @zenith garnet

[mossy valve]

how would i go about solving this

[round isle]

let's see the work you have done so far

[mossy valve]

i just dont know how to solve it

and how to start

[round isle]

ok

let's walk through this

we see two right angles triangles inside the bigger right-angled triangle

can you define the hypotenuse for right and left triangle in terms of x?

using Pythagoras theorem

[mossy valve]

isnt it uhh

[round isle]

once you do that, you can use the newly discovered expression for base and height of the large right-angled triangle to setup an equation

since you already know the value of the hypotenuse for that

[mossy valve]

oh so

for the left hypotenuse wouldnt be uhhhh

9 + x squared

[round isle]

don't forget the square root

[mossy valve]

oh yea

[round isle]

I think you meant the right one

do the same for the left one

and now you have the base and height in terms of x

which means you can setup a final equation in x by applying Pythagoras on the large triangle

[mossy valve]

ok

can you also do it with proportions?

[round isle]

what proportions?

[mossy valve]

like a/b = c/d

and a * d and b * c or something

[round isle]

maybe, I'm not sure. You can experiment with this method if you wish. I found Pythagoras pretty obvious because of the right-angled triangles

[mossy valve]

yeah

[nocturne jungle]

<@&286206848099549185>

can anyone help with a two column proof?

[tough pilot]

Pictures, people, pictures

[nocturne jungle]

@tough pilot

[tough pilot]

Aren’t there little squares you can drag and drop into those positions

[nocturne jungle]

no they are not

[tough pilot]

You have to type them out?

[nocturne jungle]

yeah

[tough pilot]

What do you need help with

[nocturne jungle]

im just confused idk what to fill in the blanks with im lost

[tough pilot]

This seems like a general lack of knowledge on the subject then

[nocturne jungle]

its about complementary angles

[tough pilot]

Certainly you took notes and paid attention in class and all of that

[nocturne jungle]

and you have to fill in reasons

[tough pilot]

Certainly this isn’t your first time proving something like this

Right?

[nocturne jungle]

perhaps

[tough pilot]

What the hell does that mean

Have you done this in class

[nocturne jungle]

no i havent done it

i kinda know of it

[tough pilot]

You’ve never done this in class, and you have homework for it

[nocturne jungle]

he taught us about it but this is my first time doing it

im lost on what to do

[tough pilot]

So did you take notes

[nocturne jungle]

no i did not

[tough pilot]

Have you literally tried googling anything before coming here

[nocturne jungle]

yes

[tough pilot]

And what exactly did you google

Because google has a lot on this I know it

Because google has a lot on everything

In fact it has close to everything on everything

[nocturne jungle]

im gonna keep looking then

thanks for your help

[tough pilot]

Yeah, for future reference you cannot come in here and basically have someone do it for you, especially when you say you didn’t take any notes and especially when it’s a problem that involves basic knowledge of terms (not even a specific problem with a quirky twist to it that you’ve never seen)

And when google is always there

[nocturne jungle]

no wonder why you don't have helper role you dont even help you just tell them to go to google

👍

[tough pilot]

Did you look at #❓how-to-get-help

Because it ain’t like this

[nocturne jungle]

no i dont think i will

but thank you mau

[tough pilot]

Ignorance is bliss

Keep rocking on

[nocturne jungle]

How old are you

[tough pilot]

103

Dude what does it matter

Everything I’ve said is true

[nocturne jungle]

listen man i was just confused on a question you didn't have to be a dick about it with this whole "its basic knowledge bro"

[tough pilot]

Not once did I say it was basic knowledge now did I

I said there’s google

And you are doing homework for a class

That showed you how to do it

And you didn’t take notes

And you’re here because you’re last minute doing your homework

I’m saying I’m not doing your fucking homework for you

[nocturne jungle]

wah wah bro

love you

have a great day

do my homework peasant

[upper karma]

[forest dove]

Uh

That doesn't quite belong here michael

[nocturne jungle]

no memes in general?

[elfin palm]

if you look at me would you think im a positive vision?

[nocturne jungle]

ofcourse

[elfin palm]

just checking

[forest dove]

Memes go in #chill

[nocturne jungle]

@tough pilot are u obese

[tough pilot]

Do you have any questions that relate to this chat that cannot be easily googled

[tawdry mango]

Why are you doing This

[tough pilot]

???

[next jackal]

I thought maths contests have stricter invigilation

[upper karma]

they do but online contest exist

[brittle gyro]

invigilation, I like that

[acoustic solar]

my brain perfectly made me can't calculate this crap

need the base area

I can't imagine I got stuck in revision

[dark sparrow]

the... base area?

like, the area of the two (supposedly) rectangular faces at the very bottom?

[acoustic solar]

nvm I am just blind

I just forgot how trapezoid was shaped

[granite violet]

@kindred walrus

How?

[kindred walrus]

Group up the a^2 terms, the a terms, and the constant terms. Like you’re doing regular addition and subtraction

[somber coyote]

TeddyAlex:

[granite violet]

like this?

oh wait

[kindred walrus]

No

You can only add or subtract between the a^2 terms, add or subtract between the a terms, and add or subtract between the constant terms

[granite violet]

I think I made it

$2a-4a^2-2a^2-1-1 = 2a-2a^2-2$

[somber coyote]

TeddyAlex:

[granite violet]

@kindred walrus Is this correct?

[kindred walrus]

What was the original equation again? It started at $4a^2 + \cdots$

[somber coyote]

Majez_tic:

[granite violet]

b)

[kindred walrus]

Here:

$4a^2 + 2a - 1 - (2a^2 + 1) = 4a^2 + 2a - 1 - 2a^2 - 1 = (4a^2 - 2a^2) + (2a) - 1 - 1$

[somber coyote]

Majez_tic:

[kindred walrus]

I tried to write it in a way so that you could see how the terms are grouped

All that’s left is for you to simplify

[granite violet]

$2a^2+2a-2$

[somber coyote]

TeddyAlex:

[kindred walrus]

Looks good to me

[granite violet]

Looked at the answer, was right

thanks btw!

[spice jewel]

TeddyAlex:
@somber coyote aaaaa

[granite violet]

wat

[cold siren]

I'm confused how to work this out

[silent plank]

introduce a variable to represent on you your angles

[cold siren]

I tried doing 180-x=15(180-x)-12 for mine but it didn't work out

[karmic cloak]

Can anyone explain this to me?

[silent plank]

don't try to jump to the finish like that.

don't worry about the supplementary property for now

[upper karma]

@karmic cloak

That’s what I did

[karmic cloak]

different question...?

[silent plank]

let x be the measure of what's referred to as the "other" angle

[upper karma]

Idk if it’s right

[cold siren]

let x be the measure of what's referred to as the "other" angle
@silent plank oh I see but I'm confused how the equation would be

since like I haven't tried these problems

[silent plank]

what's 12 less than 15 times of x

[cold siren]

15x-12?

[silent plank]

yes

[cold siren]

wait would it be 15x-12=180?

wait no

[silent plank]

the measures of your angles are:
x and
15x - 12

[cold siren]

ahh

[silent plank]

and their sum is 180°

[cold siren]

thx!

[karmic cloak]

can anyone help me with mine ;p

[cold siren]

I got 12 and 168 so I'm pretty sure that's right

once again I'm confused how to format this since there's both supplementary and complementary

[silent plank]

apply the definitions of supplement and complement

the complement of a is : 90° - a
the supplement of b is 180° - b
and combine those properties

[upper karma]

I also need help with this exercise

I have doubts with exercise number 11

I barely understand because my teacher doesn’t explain it very well.

[cold siren]

the complement of a is : 90° - a
the supplement of b is 180° - b
and combine those properties
@silent plank I believe it would be 9(180-x)+37=90-y, but I'm not sure how I would solve with both variables

[silent plank]

what do x and y represent

[cold siren]

I think the supplement/complement?

[silent plank]

I'd recommend trying to use the minimal amount of variables
let x be the angle you want to find

(supplement of x) = 37 more than 9 times the (complement of x)

what's the supplement of x

[cold siren]

Hmmm, x=9x+37?

uh

180-x

[silent plank]

what's the complement of x

[cold siren]

90-x?

[silent plank]

yes

hence applying that to the above:
180 - x = 37 + 9(90-x)

[cold siren]

ahh

okay

well I got a really large decimal, so I'm not sure if it's wrong or it's meant to be like that

[silent plank]

you'd get a terminating decimal which isn't that bad
(its also between 0 and 90°) which is fine.

if it wasn't clear this part so far is only focusing on finding the angle: x

[upper karma]

I need help with this

Please, anyone?

I only need help with one exercise so that I can understand the rest.

[brittle gyro]

It looks like you've got some Side-Side-Angle stuff going

Also there's some isosceles triangles all over the place. Also, 5 + 2 = 7

@upper karma

[upper karma]

Ohh

Tysm!

[upper karma]

78?

2x + 24 = 180

nvm

[round isle]

yes

[upper karma]

thanks

[stark bolt]

Prove AZ ~= BX using a flow chart proof

[jolly perch]

🤷

solve it ur self

[stark bolt]

bruh

[upper karma]

solve it ur self

If they came here it's probably because they need help and they can't?

[silent plank]

wtf is a flow chart proof

do you mean the horrid 2 column proof
or is it something worse I haven't heard about

[jolly perch]

If they came here it's probably because they need help and they can't?
@upper karma lol I said that s a joke

@silent plank I took geo last year I remember it was like basically the two colummn chart but in english as an essay

[stark bolt]

@silent plank its like boxes and arrows

pretty much two column one just put into boxes

[silent plank]

so worse layout

[stark bolt]

yeah

can you help

i dont know how to do it

i can explain it in paragraph but not two column

[silent plank]

how'd you explain it in a paragraph

[stark bolt]

We are given that ∠X ≅ ∠Z and ("XY" ) ̅ ≅ ("ZY" ) ̅. Because of the ASA Postulate which states that if two angles and one side of a triangle are congruent to that of another triangle, then the two triangles are congruent with each other. With this, we can see the two angles, X and Z, are congruent with each other and line segments XY and ZY are congruent with each other. This means that the two triangles are congruent because of the ASA postulate. Lastly, this means that line segments BX and AZ are congruent because congruent triangles have corresponding sides.

i aint that good at proofsa

i had to learn to do them from a video with virtual

[silent plank]

well for 2-col you can cut out like most of the words

[stark bolt]

yeah i just dont know what postulates or theorems to use

[jolly perch]

@stark bolt if I am to be honest just get a tutor to all the work for you if u have no passion and still want an A

[silent plank]

col1: | col2
statement | sort description of the justification

[stark bolt]

yeah ive done them before

[silent plank]

don't be so strict witht he specific name

[stark bolt]

i have to

thats what the teacher wants

[silent plank]

<X cong <Z | given

[stark bolt]

yeah thats easy

[silent plank]

first line can be as simple as that

state the other given property as well

[stark bolt]

we just need given

thanks

[silent plank]

also you didn't provide the full justification for why you can apple ASA here

[stark bolt]

i dont know what comes in between

its simple

[silent plank]

<Y cong <Y (reflexive property)

[stark bolt]

theres two congruent angles and a congruent line

so ASA

[silent plank]

or <Y is common

you need to state that

[stark bolt]

oh

oh that makes sense

[silent plank]

otherwise from the first 2 statements all you have is A and S

a description that ASA can be used.
but not enough to justify how it applies here

[stark bolt]

what do i do after that\

then can i do the ASA thing

[silent plank]

well basically state the 2 givens,
3rd line will be your <Y = <Y
and then 4th line: triangles congruent ASA

[stark bolt]

oh alright thanks

[silent plank]

and then 5th line for the conclusion

[stark bolt]

whats that

[silent plank]

the statement you're trying to prove

at the 4th line you've only proved congruence

[stark bolt]

oh

your right

now i need to prove this

Prove (AZ ) ̅ ≅ (BX) ̅

[silent plank]

search up images for an example

[stark bolt]

@silent plank what would i put to explain that AZ~=BX

ok

[silent plank]

corresponding sides of congruent triangles

(are congruent)

[stark bolt]

oh alr

isnt that CTPTC or something

[silent plank]

i've never used acronyms for those

[stark bolt]

it means Corresponding Parts of Congruent Triangles are Congruent

[silent plank]

yeh that works

[stark bolt]

CPCTC

ok

[silent plank]

because one letter off, different people may use slightly different acronyms

[stark bolt]

oh

[silent plank]

and a casual reader will have nfi what's going on

whe you write that

[stark bolt]

this is flow chart

[silent plank]

not quite

[stark bolt]

its the same thing as 2 column

oh

[silent plank]

you want the combination of your A, S, A to lead to congruence

whearas in your setup, you've implied that congruence of those angles leads to congruence of the sides

something like that

[stark bolt]

oh

we havent learned to do that

they just taught us to do what i did

[silent plank]

yeh, that's bad-ish

[stark bolt]

oh

we have to use edgenuity and thats what they taught us

for virtual learning

[silent plank]

it defeats the whole purpose of a flow chart

[stark bolt]

yeah i guess so

imma just do what they taught us

thanks for the help bro

[silent plank]

i'd recommend the better way

[stark bolt]

alright

im gonna email the teacher

two more proofs left in the assignment

i mean 3

@silent plank would you be able to help with this one sorry

[vestal pendant]

SSS

[jagged sapphire]

Help for homework

[stark bolt]

AAS

what

[vestal pendant]

Wait

[stark bolt]

Its AAS

[jagged sapphire]

Who do you know its AAS please explain so i know better.

[stark bolt]

It goes angle angle side

[jagged sapphire]

how"

[stark bolt]

I think

[vestal pendant]

Aas

I believe

[stark bolt]

Yeah two angles and a side

well

[vestal pendant]

Son, can you help me w/ sum rq

[stark bolt]

it goes angle angle side

sure

[vestal pendant]

dm

[upper karma]

What do you think?

[stark bolt]

he thinks idk

[grizzled lantern]

@jagged sapphire, those triangles share the same one side,

[jagged sapphire]

@grizzled lantern sss?

[grizzled lantern]

idk? do you have three sides?

not a trick question btw

[jagged sapphire]

No you only 4 sides

[rancid bane]

Is this SAS?

im getting confused

[jagged sapphire]

@grizzled lantern its Sss isn't it?

[grizzled lantern]

yes

[jagged sapphire]

ok thank u

[rancid bane]

som1 halp plz

this is confusing

[jagged sapphire]

Asa Correct?

[stark bolt]

yes

[rancid bane]

SAs?

[silent plank]

no

you only have one pair of congruent sides

given

you'll need to incorporate parallel line theorems

[grizzled lantern]

@silent plank would internal angles be included?

[silent plank]

for what

[jagged sapphire]

SAS right

or am i wrong?

[grizzled lantern]

what do you think

[jagged sapphire]

Sas im 70% sure

[grizzled lantern]

why 70%

[jagged sapphire]

Side angle side

[grizzled lantern]

what are you given?

[silent plank]

the indicated congruent angle isn't between the corresponding sides

[stark bolt]

Wouldnt it be ass

Angle side side

[grizzled lantern]

theres no as

ass

[stark bolt]

I think its sas

wait

couldnt it be HL

if the hypotenuses are congruent the triangles are congruent

[silent plank]

its not sas for the reason mentioned above

[stark bolt]

yeah i see that now

I think its HO

HL

[silent plank]

you need H as well as a side

yeh

[stark bolt]

oh

[silent plank]

H alone isn't enogh

[stark bolt]

oh

well i mean there is a side too

so its HO

Hl

HL

[jagged sapphire]

So its HL

[stark bolt]

yes

[jagged sapphire]

i don't get it

[stark bolt]

If the hypotenuses are congruent and two sides are congruent it means the triangle is congruent

HL means hypotenuse and leg i think

[silent plank]

HL or RHS is also a valid justification for congruence

[stark bolt]

yeah

ramanov

Is ASS a thing or no

angle side side

[jagged sapphire]

don't give awnsers just explain pls

[silent plank]

given a right triangle, the triangle can be solved given any 2 sides from pythag or otherwise

[stark bolt]

the last one because you need more congruent sides

and bc and dc are already congruent

[jagged sapphire]

so AB=AD

[stark bolt]

yes

[silent plank]

as the name implies ASS is ass (in case it wasn't clear it isn't a valid justification)

[stark bolt]

lmao

[jagged sapphire]

Booty is Booty

[stark bolt]

i wish i could do that stuff

instead of stupid proofs

@jagged sapphire anything else

[jagged sapphire]

Man i hate triangles

[stark bolt]

which angle is the right angle

i know what it is but i want you to understand it too

[jagged sapphire]

wym

[stark bolt]

you need to find the right angle first

Is it angle a or b or c

[jagged sapphire]

c to b?

[stark bolt]

no thats just a side

[jagged sapphire]

G to f

how do i find the right triangle

[stark bolt]

it looks like 90°

[silent plank]

the question is cut off

[stark bolt]

The right angle is in an L shape

[silent plank]

looks like there's info above that

[stark bolt]

@silent plank might be answers from another question

looks like the same font as the answer choices

[silent plank]

without given info the question is ambiguous af

[stark bolt]

oh

[silent plank]

what's needed for HL to be applied?

[stark bolt]

The top answer

we cant assume theyre right angles

@jagged sapphire

[jagged sapphire]

If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent

so @stark bolt

what do you think

[stark bolt]

Top answer

We dont know if the angle is right or not

[jagged sapphire]

CDE?

[stark bolt]

yessir

[round isle]

yesù

si

certo

[jagged sapphire]

ASA

correct?

[stark bolt]

i think its AAS

[silent plank]

how are you getting ASA

[stark bolt]

@silent plank would you be able to help me with another proof

[silent plank]

which angles are congruent and is the congruent side between those angles

[urban knoll]

Confused on how to find the x y and z

Once I figure that out I should be fine

[stark bolt]

on the first one

to find x combine 90 and 50 and subtract that from 180

then add 60 and 75 and subtract that from 180

sorry im not good at explaining

it would be easier to show u on paper

[urban knoll]

Yeah I understand what your saying tho

What are the extra lines coming out of the triangle tho

[stark bolt]

oh

those are transversals

i think they are

[urban knoll]

So for the top middle one the x would just be 70?

[stark bolt]

yes

theyre vertical angles

the other angle to the bottom right in that triangle would be 50

since 180-130=50

can someone help me with these

its due tonight by midnight

[round isle]

why are you mentioning your deadline

nobody is going to give you answers straight away because you have a deadline

[stark bolt]

lmao i think thats how it works. We do our homework if the teacher tells us a deadline

if they dont we never do it

[round isle]

we don't care whether you do your homework on time or not

that's your responsibility

we will only guide you

so, I don't see why you mention your deadline like this

[stark bolt]

ok

[proud gust]

can someone help me with a problem

scroll to O

i dont understand how to do it

[round isle]

please post a picture of your question here

[proud gust]

i dont get it

@round isle do you think you can help me

i acctually want to learn

[round isle]

let's see what you have done so far

[proud gust]

i dont have a single clue on what to do

@round isle I dont think the problem gives me enough information

[round isle]

why don't you start by labeling the diagram according to the information provided to you

an isosceles and equilateral triangle

[proud gust]

ok got it

whats next

[jagged sapphire]

@stark bolt

[proud gust]

@round isle can u plz help

[round isle]

well show me what you got

post it here

[proud gust]

i labeled it, what do i do after

[stark bolt]

@jagged sapphire i think its answer choice C

idk

[round isle]

I told you to post here what you've done

don't just tell me that you've done it

show it to me

[proud gust]

its on the paper, so i dont really need to label it

[maiden saffron]

its already labeled for him in the problem isn't it?

[round isle]

take a picture and post it here. Remember, no one will give you answers here. We will only look at what you've done and try to guide you

[proud gust]

im not asking for answers i just dont wanna label something that is already labeled for me

[round isle]

@loud cradle can we help you?

[loud cradle]

I have no idea how to approach this

could you give me a hint?

[round isle]

what have you done so far?

[loud cradle]

nothing really

I just don't have an idea on how to approach it

[round isle]

do you know how to compute the area of an arc?

[loud cradle]

no

[round isle]

sorry, I mean sector of a circle

[loud cradle]

idk the formula

[round isle]

do you know the formula for area of a circle?

[proud gust]

@round isle did u read what i said

[loud cradle]

pi r^2

[upper karma]

can someone tell me the y-int of x^2-22=24

[round isle]

@proud gust I have already explained to you that you need to show me some progress on your end. This could be in the form of anything really. I need to understand that you at least understand the basic terminologies being used in the question

@loud cradle do you know the area of a quadrant?

so, this is a quarter of a full circle

[loud cradle]

yeah wouldn't it be 1/4 pi r^2

[round isle]

okay good

let's say, I cut out a piece from a full circle

and the angle of this piece is theta

do you know how to calculate the area of that?

[loud cradle]

pi r^2/theta?

im just guessing

[round isle]

why are you guessing, has your teacher taught you this yet?

[loud cradle]

i don't remember let me check

[proud gust]

@round isle im hear to get help it shows me the answer already but i want to learn. i havent written anything down because i dont know what to write and what your telling me to label is already labeled on the sheet. so i don't to take up space since its limited

[round isle]

@upper karma I don't udnerstand your question. What is y-int?

[proud gust]

*here

[loud cradle]

1/2 r^2 theta?

[upper karma]

ummm y intercept

[round isle]

has your teacher taught you this yet @loud cradle ?

[loud cradle]

no

its a math competition practice

[round isle]

@loud cradle then why are you posting it here?

[loud cradle]

because it says geometry

and since its a geometry question...

[round isle]

I honestly can't tell if you're just looking for someone to solve your homework or whether this is a genuine math compeition exercise

[proud gust]

@round isle Im here for you to help me so i haven't written anything since the only thing you told me to write is already labeled

[round isle]

@upper karma can you show me where you saw this question?

[loud cradle]

I'm lookign for someone to tell me where to start

so that i can start the question

[upper karma]

@upper karma can you show me where you saw this question?
@round isle its fine i got it

[round isle]

@proud gust I suggest you draw the shape again in the question and do some additional labeling

there is some stuff that is not indicated there

[jagged sapphire]

is SAS? @round isle

[tough pilot]

Do you know what SAS means??

[jagged sapphire]

Side angle side

[tough pilot]

Yeeeeep

[jagged sapphire]

its sas then

[tough pilot]

What do those lines mean on the triangles

[jagged sapphire]

idk

[tough pilot]

You don’t know

[jagged sapphire]

right triangles

[tough pilot]

Oh god

[jagged sapphire]

help

:((

[tough pilot]

Those are congruency lines

A right triangle has a 90 degree angle

[jagged sapphire]

ok?

so its Asa?

[proud gust]

@round isle

[jagged sapphire]

god ur hand writting

[round isle]

sorry, I can't understand what you did

why don't you make labels accordingly. Label equal sides and angles accordingly because the question mentions isosceles triangle and equilateral triangle

make a bigger and upright triangle

[tough pilot]

@jagged sapphire the order of the letters matters

@jagged sapphire it is not ASA

How many pairs of sides of the triangles are congruent?

How many angles?

The drawing you’re given tells you everything

[proud gust]

@round isle

[jagged sapphire]

@tough pilot 1 side and 1 angle

[proud gust]

This?

[tough pilot]

Which side do you see is congruent @jagged sapphire

[jagged sapphire]

The Right Side

[tough pilot]

Okay good

Can you repost your image

[tough pilot]

And tell me the proper notation

Using letters

[jagged sapphire]

JMK=LKM

AAS

[proud gust]

@round isle '

[tough pilot]

Those are the triangle names

Give me the side names

[proud gust]

@round isle /

[jagged sapphire]

jm congruent

[tough pilot]

To what

[jagged sapphire]

so is lk

LK

[tough pilot]

Congruency is a relationship with another shape or line not a state of being on its own

So JM is congruent to LK

[proud gust]

@round isle

[tough pilot]

Which angles are congruent to each other

[jagged sapphire]

m and k

[tough pilot]

And how do you know that

It’s a really simple answer

What tells you that they are congruent angles

[jagged sapphire]

the little circle thingy

[tough pilot]

Yes the angle line

Good so take note of the details in a picture like that from now on so that you can recognize that

The marks on JM and LK

The angle lines

Okay so now what is one last congruent pair

This will determine the answer

[jagged sapphire]

mk and kn

[round isle]

@proud gust what do you need help with?

[upper karma]

Need help with part a only

[tough pilot]

@jagged sapphire now is that an angle pairing or a side pairing

[jagged sapphire]

side

[tough pilot]

What tells you that

[proud gust]

@round isle this is what I have so far

[jagged sapphire]

uhh

idk

[tough pilot]

Exactly, so there is no proof of congruency there

It’s not there

[jagged sapphire]

thanks you taught me alot

[proud gust]

@round isle

[round isle]

you literally drew the exact same thing as in the question

[jagged sapphire]

but i still don't know the answer 💀

[round isle]

did you not understand what I told you in the very beginning?

[tough pilot]

@jagged sapphire we’re getting there, stick with me

[jagged sapphire]

k

[tough pilot]

Here’s a hint

Look for another side

[round isle]

some information is still not mentioned in the drawing

[tough pilot]

And could you repost the picture

[jagged sapphire]

JM LK?

[proud gust]

What’s was I supposed to draw, I’ve litterally been asking u but u don’t tell me, the reason I came here was for u to help me

[tough pilot]

You already have JM and LK

[jagged sapphire]

JN LN

[proud gust]

@round isle

@round isle

[humble pulsar]

dont spam ping

[round isle]

look at XYZ

and yes don't spam my name like this

it's quite annoying

[tough pilot]

@jagged sapphire there is no proof of congruency there

[round isle]

XYZ is an equilateral triangle

[proud gust]

I labeled 60* angles which means it is equilateral

[jagged sapphire]

@jagged sapphire there is no proof of congruency there
@tough pilot Ok?

[round isle]

okay

[jagged sapphire]

what do i do if theres no congruencey

[tough pilot]

Those two triangles share a side don’t they?

[round isle]

draw a straight line from W to Z

[proud gust]

I did

[jagged sapphire]

Yes

[round isle]

this line will bisect the angle XZW

[tough pilot]

Wouldn’t that shared side be a sign of congruency?

[round isle]

should be pretty straightforward after that

[jagged sapphire]

Yea because its the same side

[proud gust]

It’s not straight forward I’m still confused

[round isle]

draw a straight line from W to Z

all the way to the line XY

[tough pilot]

@jagged sapphire you got it

So the ordering of the letters like SAS matter

[jagged sapphire]

so its SAS?

[tough pilot]

First there is the JM LK congruency, then there is the JMK LKM congruency, and then there is the shared side congruency, where MK=KM

Yes, but I hope you can carry on with similar problems without asking similar questions again

[upper karma]

yung moya?

@proud gust

I need help with problem 45

[round isle]

just plug in the values and solve for t

[proud gust]

@upper karma Ye?

[upper karma]

whats the formula for time?

[round isle]

simply solve for t by plugging all the numeric values into the equation d(t)

wait

let me check one thing first

[round isle]

@upper karma ok

so, here's what I would recommend

[upper karma]

wait

its

fine

i just figured it out

but you can tell me to make sure

[round isle]

the maximum height would be at half the total time the ball is in the air

[humble pulsar]

Total time is distance between roots

[tough pilot]

Ignore beam

Yes, but I hope you can carry on with similar problems without asking similar questions again
@tough pilot

[round isle]

take derivative of d(t)

and equate it to 0

you will find a value for t

[upper karma]

....

[round isle]

the total time is twice that

[polar whale]

^

[humble pulsar]

They might not know what a derivative is

[upper karma]

can you give me the equal like write it down

[humble pulsar]

keep in mind

[upper karma]

now im confused again

[round isle]

really?

[polar whale]

Also cease feet usage for g

Yikes

[tough pilot]

This is a trig chat room not a calculus one

[round isle]

@upper karma have derivatives been introduced to you?

damn

[humble pulsar]

^

[round isle]

hmmmmmmmmmmmm

[tough pilot]

Take a couple steps back

[upper karma]

no

[round isle]

life becomes so easier with derivatives

hahaha

[upper karma]

lol

[humble pulsar]

@upper karma agree the time a ball is in the air is the time it takes to br thrown and for it to hit the ground?

[tough pilot]

Is it not telling you a way to simplify the equation right off the bat

Can you repost image

@upper karma

[upper karma]

sure thing

[polar whale]

Should be clear that the time to hit max height is 1/2 of total time

Tbh

[tough pilot]

It’s saying g is equal to 32 ft/sec^2

Can’t you plug g into the original equation

I mean the number g is representing

[upper karma]

ok

[polar whale]

Yes and v0 aswell...

[upper karma]

thanks guys

[humble pulsar]

Then just find the roots

[tough pilot]

You’re just solving for t

[polar whale]

Or dont plug it in and solve for t

And then plug in ur values

Useless to do that tho

[stark bolt]

can someone help me do a proof

[karmic cloak]

anyone a tutor here

id pay ._.

[stark bolt]

me too

[sinful tide]

@jagged sapphire That looks suspiciously like a test...

@mods?

[jagged sapphire]

@sinful tide its homework

[sinful tide]

ah lol

[stark bolt]

bruh

u can use it during tests

they just said no exams

exams are at end of term

@sinful tide

[sinful tide]

@stark bolt 6. Do not ask for help on tests. Any violation of this will lead to appropriate action being taken at mod discretion.

[karmic cloak]

why not tests?

[stark bolt]

oh

@karmic cloak idk they say because its cheating

its the same as homework though

[sinful tide]

You should already know it by the time of the test.

The test is to measure your knowledge without help.

[stark bolt]

yeah thats true

no one knows how to do proofs though

one person in this discord

[tough pilot]

@karmic cloak #discussion message

[stark bolt]

help

[zenith garnet]

When it comes to understanding a general topic or rule, I’d recommend googling before anything @zenith garnet
@tough pilot I'm just not sure what general topic or rule I'm supposed to use in this:

https://cdn.discordapp.com/attachments/326138757474680852/778459522418606080/Desktop_Screenshot_2020.11.17_-_19.19.01.47.png

in question (a)

[viscid garnet]

for (a) there is technically not enough info to prove congruence but could you say there is because of the line and angle placement or no

[zenith garnet]

oh good point

thoughts anyone?

[tough pilot]

when did i send that message lol

[zenith garnet]

a while ago lool

[tough pilot]

i guess in general, i believe that by googling triangle congruency you could get somewhere

explaining these SAS, SSS, ASA proofs and stuff is kinda just like reteaching the subject itself

[zenith garnet]

yeah

i know all those types of congruence

i just dont know which to apply

[tough pilot]

i mean yeah what @viscid garnet said for a)

i wouldn't really be able to infer much from just 2 congruencies

[viscid garnet]

ok

thanks

[tough pilot]

wait you asked a question

hold on

[zenith garnet]

i wouldn't really be able to infer much from just 2 congruencies
@tough pilot same thats why im confused

[tough pilot]

@viscid garnet no i don't think you can just assume

https://www.khanacademy.org/math/geometry/hs-geo-congruence/xff63fac4:hs-geo-congruent-triangles/a/triangle-congruence-review#:~:text=When two pairs of corresponding sides and one pair of,known sides in the triangle.

that's a horrible link but it's for reviewing such things

i'm rusty on it all

[viscid garnet]

ok thanks

[slender idol]

I need help with proofs

lmk if anyone can help out

[cinder nacelle]

Same

How do I do them good

[kindred walrus]

All a matter of practice 👍🏽

[umbral snow]

@slender idol
Ye

[slender idol]

@umbral snow

what is the difference between AAS and ASA?

[umbral snow]

The information that you have

[spark totem]

https://bit.ly/36Rky69

geometry test question, any help?

[grizzled lantern]

@spark totem test question?

[spark totem]

yea

mid chapter test rn

[grizzled lantern]

cya

[spark totem]

ive done everything legitely but that

no clue to do that

havent learned it

[slim warren]

Hi I am really confused and I've used a few trig identities but Idk how to do this, please can someone explain how to do this?

[humble pulsar]

I'd use triangles on the place tbh

cosx = u means cos(u) = -sqrt(3)/4. -sqrt(3) is adjacent, 4 is hypotenuse

[slim warren]

?

It's a question about identities, and u have to solve for x

[humble pulsar]

No, it's about finding tanx

[slim warren]

oh yh true find tan X but like its not to do with triangles

I don't rly understand it

[umbral snow]

I think the first bit is a typo, should only be one cos

[slim warren]

Ah ok

Still how do u get to tanx?

[umbral snow]

So let's say there's a right triangle with
cosθ = -√3 / 4

[slim warren]

Mhm

[umbral snow]

That means adj can be √3
And hyp can be 4

By pythag, opp can be √[16 - 3] = √13

What's tanθ of this triangle?

[slim warren]

opp/adj so inv tan root13 over root3?

But

Im not sure if the right angled triangle is right angled?

[humble pulsar]

Im not sure if the right angled triangle is right angled?
@slim warren

[slim warren]

Lmao *not sure if the triangle is right angled

[humble pulsar]

it is

[slim warren]

How?

[humble pulsar]

you just make it right angled lol

[plain pollen]

Oh my god what am i missinggggggggggggg? So I have a circle sector which, when folded into a cone, the resulting cone has height 22 and the base circle has radius 8. I need to find r and theta in original circle sector. r is easy, I found it to be 23.41. But how do I get to theta? Can't find sector length without theta and can't find theta without sector length as far as I can see. Anyone?

[slim warren]

Ok hang on mate

So I got the answer to be

64.3

@humble pulsar right?

[humble pulsar]

exact answer

[slim warren]

Calc won't give it in surd form

[humble pulsar]

then draw it out 🙂

[slim warren]

I have

[humble pulsar]

can you send a picture of the triangle?

[slim warren]

Ohh I think I'm getting jt

🤦‍♂️🤦‍♂️

[humble pulsar]

yeah

[slim warren]

Don't have much data so cant

But yh opp/adj = root13/root3

That's it

[humble pulsar]

yeah

[slim warren]

Ty mate

[humble pulsar]

$\sqrt{\frac{13}{3}}$

[somber coyote]

moshill1:

[plain pollen]

oop, if anyone sees my thing from earlier, ignore it, i got it

[zenith garnet]

can someone help me solve this? im not really sure where to start...

i know the equilateral triangle has angles of 60 degrees

thats p much all i can think of

pls help 😄

[upper karma]

AEG = AED + DEG

given EG // AC, CDE and DEG are supplementary

and CDE is known

@zenith garnet

[zenith garnet]

is triangle ADE isosceles?

@upper karma

[upper karma]

yes

[zenith garnet]

how do u we know?

[upper karma]

DE = DC

regular pentagon

but D is midpoint

so AD = DC

so AD = DE

[zenith garnet]

ahhhh thank you

that makes sense

[upper karma]

Yo

The answer is either a or b can someone help me

[lyric light]

can somebody help me

[upper karma]

@upper karma what do you think between those 2

If you know what the same-side interior angles theorem and what the alternate interior angles theorem is, then you should be able to know what the converse it actually is, and then select on of those 2

well i went with same side

im really really bad at math

@upper karma

And that's correct

oh ty

:)

If you are able to know this

If you know what the same-side interior angles theorem and what the alternate interior angles theorem is, then you should be able to know what the converse it actually is, and then select on of those 2
There's no more to it

Yw

i dont know that but i do know that usually alternate means that they wouldnt be close to eachother like that

It's all about knowing the theorems and what they mean, if you can, i suggest you to give a review to them

alright

thanks for your help

[humble pulsar]

is it a test?

[upper karma]

jeez bro I dont even know where to begin lmao

[humble pulsar]

then you cant get help

[upper karma]

rest in peace flavored soup

[prime drum]

haha fr

[upper karma]

if i knew i would tell you

[prime drum]

so yall dont help on test just hw?

[earnest echo]

Yes

Read the rules

[prime drum]

kk

[upper karma]

Ayo can somebody help

Let line BD intersect line AC at point B, between point A and C. Perpendiculars from point A and C to line BD meet at points P and Q, respectively. Prove that point P and Q are not on the same side of line AC.

Two column proof

Pls help

[naive scarab]

@upper karma i think you gotta be using the parallel postulate axiom here

[upper karma]

what does that do

[naive scarab]

it’s a mouthful, let me pull it up

[upper karma]

k

[naive scarab]

https://en.m.wikipedia.org/wiki/Parallel_postulate

historically the story of this axiom is actually really interesting

but if you look at the picture here, the axiom says that if alpha+beta < 180, then the two lines meet on that side of the line

[upper karma]

yeah

[naive scarab]

so show <APB + <ABP < 180

then A is to the left

similarly argue C is to the right

[upper karma]

k

[naive scarab]

oh wait sorry wrong points one sec

i think the angles that matter here are <PAB + <PBA. if that’s less then 180 then by the axiom the lines meet on the upper side of the line

and then similarly for the other point

[upper karma]

So APB is 90

[naive scarab]

true

[upper karma]

which means that the other two angles add up to 90

[naive scarab]

yeah and that’s less than 180 🙂

[upper karma]

mhm

wait what were you thinking when I said that points p and q were not on the same side of line ac

[naive scarab]

so you want to prove that right?

[upper karma]

I mean like what were you thinking I was trying to prove

[naive scarab]

you want to prove p and q are not on the same side of the line ac

right?

[upper karma]

I meant that one is above and the other is below or if you turn it one is to the left and one is to the right

[naive scarab]

yeah

so actually “same side of the line” is a bit of a weasel word here

you need to define what that actually means

here’s a definition: “P and Q are on the same side of the line AC if the line segment PQ does not intersect the line AC”

[upper karma]

Idk not my words

[naive scarab]

and so “not on the same line” means “does intersect”

[upper karma]

my teacher said this

[naive scarab]

ok

[upper karma]

So I didnt know what to do so I drew that

[naive scarab]

it really boils down to what definitions and axioms your teacher gave you

[upper karma]

yeah

[naive scarab]

this is actually a super subtle question lol

[upper karma]

Mhm

I dont think anybody got it lol

[naive scarab]

so yeah what axioms do you have?

is it just the 5 from elements by euclid or something else

[upper karma]

we have some other things

But

Nothing really seems like it would be useful

mostly congruence stuff

[naive scarab]

is there an easy reference I can see?

also in my opinion, if “same side of the line” is not defined for you, this is a bad question

[upper karma]

It isn't defined

[naive scarab]

you can’t do a rigorous 2 column proof without having that definition