geometry-and-trigonometry

[upper karma]

not sure, Im using another formula

i really dont get this

does y-y1=m(x-x1) work?

[silent plank]

yes

[upper karma]

k

i got this

[silent plank]

looks good

[upper karma]

ty

ill try this one

so its first or the last one

[livid moss]

Yes

[upper karma]

i got the first one

[upper karma]

first options, 1. P | 2. C --- Second option, 1. circumcenter | 2. Intercenter ---- anyone know how to figure this out?

[humble pulsar]

well which point is equidistant from the sides?

[echo gyro]

dm me if you want to help me with this geometry project

[humble pulsar]

simplify the rhs, factor and simplify lhs

[glacial dawn]

25*(5^x ) = 5(5^14)

5(5^x) = 5^14

5^x = 5^13

x = 13

[rain nebula]

https://drive.google.com/file/d/1p3uMhteQD7Zyl1ZcGPVP3O0c3xoN-w4O/view

help with my last proofs

[surreal inlet]

i need help with two questions

i will send a photo

[crystal charm]

How do I know whether a polynomial admits a symmetry or not?
Like all polynomials of degree <=3 have a symmetry (axial or central), and for polynomials with degree >3?
Do all polynomials have symmetry? (even if the symmetry is for example an axial symmetry of axis Δ:x|->3x-1)

[umbral snow]

Like even/oddness?

Compute f(-x) and compare it to f(x)
@crystal charm

Or, you mean general symmetry about any point/axis? Haha that's much harder

I'm fairly certain that answering that is equivalent to solving that polynomial's roots, which is impossible in many cases

[crystal charm]

Yeah that

I mean for every axis

I thought of exactly that

But it does't work

I thought since, generally, you can't factorize a degree >4 polynomial, the coefficients are not symmetric polynomials so there is no symmetry
But it doesn't seem to work since generally, degree 4 polynomials don't admit any kind of symmetry.. While their roots can be found with no problem (quartic formulas)

[silk patio]

Their roots do have symmetries

They’re just hidden symmetries

[crystal charm]

Can you develop?

[viral zenith]

how do i do this

[humble quail]

Remember that a³-b³=(a-b)(a²+ab+b²)

[tulip grail]

Anyone understand how to do this? I’ve been trying for so long I just can’t figure it out

[gritty sail]

similar triangles --> ratios

you know D and E are midpoints

[agile rain]

@tulip grail I would help you out and explain it but I am in a rush. Just know that the slopes for the perpindicular line will always be the opposite recipricol of eachother. So your equations slope is: -20/3, hence, the slope for any perpindicular line will be 3/20.

Hopefully you can figure our the rest yourself 👍

[upper karma]

can anyone explain how you would do this
still need help

[silent plank]

similar triangles --> ratios
you know D and E are midpoints

[agile rain]

@upper karma Using the midsegment theorem you would get 5x + 6 = (12x + 8)/2

Because the midsegment is always half the length of the third side

[sterile dew]

Could someone explain to me how to solve this I’m so confused

[agile rain]

@sterile dew Let's say that width of this rectangle is x

Then we could say that the length of this rectangle is 7x because the length is 7 times more than the width

And the perimeter of a rectangle is 2(length) + 2(width) = perimeter

so plugging our values into here we get 2(x)+2(7x) = 80

and if we solve then we get x = 5

So the width of this rectangle would be 5

and the length of this rectangle would be 35 because; 5 * 7 = 35

does that make sense?

[sterile dew]

Thank you so much 🙏🙏🙏

[agile rain]

np

[analog fossil]

How would you work out 20tan30

[dark sparrow]

by working out tan(30°) and then multiplying the result by 20, presumably.

[analog fossil]

Tan30 is square root 3 over 3

20 times that?

[gilded silo]

Yeah, then multiply that by 20

[analog fossil]

Which is?

[gilded silo]

11.54700538

[analog fossil]

I’m sorry I’m new to trigonometry 😹

Ah thank you

Also

[gilded silo]

I assume you have a calculator

[silent plank]

exact values pls

[analog fossil]

No

[upper karma]

^

[analog fossil]

It’s a non calculator

[gilded silo]

20 root 3 all over 3

[analog fossil]

I think they will give easier numbers to work with

[silent plank]

after knowing tan(30°) = sqrt(3)/3,
it isn't even a matter of trig anymore

[analog fossil]

Or do u always need a calculator to figure it out

[silent plank]

$20 \times \frac{\sqrt{3}}{3} = \frac{20\sqrt{3}}{3}$

[somber coyote]

ramonov:

[analog fossil]

Oh

[silent plank]

that's all there is to it

[analog fossil]

Thanks bro that’s it?

Bruh that’s easy 😹

[rich ocean]

https://prnt.sc/vgpuqt

how do i determine which is cos or sin for the components

[silent plank]

definitions of sin and cos

[rich ocean]

k

ik the y component is sin and x is cos but i dont know why it was that

[cunning olive]

@rich ocean trigonometry and unit circle

[nova belfry]

I'm confused on what exact values are in trigonometry and how to work them out, I have a upcoming test. Can anybody here help me please ?

[hollow raven]

@nova belfry degrees or radians? and what range of values do you need to know?

[nova belfry]

I don't understand sin cos tam exact values sir @hollow raven

Tan*

Like they give shapes and some angles have equations

[hollow raven]

I will assume you are using degrees

Oh

[nova belfry]

o

[hollow raven]

In that case

[nova belfry]

so yeah

[hollow raven]

So like you are given like an angle and maybe one side in a right angled triangle right?

[nova belfry]

sorta

Those kind of questions

They'll say to work out the smallest angles

And some angles have equations

There's just do many topics so I though why not come here

[hollow raven]

Can you post an example question from your review sheet or past homework and show me what you mean?

[nova belfry]

ok

Like what even is this

And how do I solve it, are there any equations I need to know or something

@hollow raven

There is some other topic that's got to do with forc pressure and somethin else

[hollow raven]

Okay, what is the sum of all the angles in a triangle?

In any triangle

[nova belfry]

180 degrees

[hollow raven]

Right

So if we have an angle at 90 + angle with a value of 7x + angle with a value 5x+18

We know that they will all add up to?

[nova belfry]

Ok

So

180 degrees

We need to work out the 2 angles right ?

so I'll just do 180-90

I think

[hollow raven]

That works

[nova belfry]

cause I don't need to work out the ra

ok

So I get.90

Now I need to find the values to substitute

I don't get that biy

Bit*

[hollow raven]

90 = ?

[nova belfry]

90 = 7x + 5x - 18

that's all the values

Soo

I do

+18

On both sides

I need to make X the subject

How do i

[humble pulsar]

90 = 12x-18

[hollow raven]

Just add the coefficients as moshill shows

if I have 2x + 3x, I can confidently say that I have 5x

[nova belfry]

ok

What's a co efficient again

The big base nikbers

Number's*?

[humble pulsar]

ax, a's a co-efficient

[nova belfry]

ok thx

so

7c + 5x

7x

= 12x

[humble pulsar]

yes

[hollow raven]

The coefficient is anything other than the term you want to find the coefficient for more specifically

so the coefficient of x in 256x is 256

[nova belfry]

90 = 12x - 18

ohh

[hollow raven]

I think you got it

[nova belfry]

so then j work out the equation

[hollow raven]

and solve for x

[nova belfry]

ok

So

+18 on both sides

108=12x ?

[humble pulsar]

you dont need to annotate your steps to us btw

[nova belfry]

oop

[hollow raven]

Yeah, just write them down if you want to make sure

like -> 2x =3

[nova belfry]

is it 7

[humble pulsar]

no

[hollow raven]

108 = 12x

[nova belfry]

hm

[hollow raven]

x = 108/12

we divide 12 on both sides to get x alone on one side

[nova belfry]

hmm

9

[humble pulsar]

yes

[nova belfry]

There we go

Thanks!

Can you guys give me another question :)

[hollow raven]

You're not done!

[nova belfry]

I'm not ?

o.o

oops

[hollow raven]

You need to find the smallest angle value remember

[nova belfry]

oh yeah

so

56

And

45

5x+18

Is the smallest

I think

WAITTTTT

NOO

it's 56

Cause I have the 18

[humble pulsar]

7*9 is what?

[hollow raven]

Substitute x with the value you just got

[nova belfry]

63

ok

[humble pulsar]

5*9 + 18 is what?

[nova belfry]

79 = 63
59 + 18 = 58

[humble pulsar]

9*5 isnt 40

[nova belfry]

It's 45

[humble pulsar]

yes

[nova belfry]

+10

= 55

[hollow raven]

+18?

[nova belfry]

+5

o

[humble pulsar]

bruh

[hollow raven]

Oh

[nova belfry]

😭😭😭

[humble pulsar]

45+18

[nova belfry]

63

[humble pulsar]

yeah

[hollow raven]

wait what

[humble pulsar]

so the question is fucked

[nova belfry]

Can we get a F in the chat for my brain 😩

[humble pulsar]

cause it aint a triangle

[nova belfry]

It isn't ?

[hollow raven]

no we did something wrong LOL

thats impossible

[nova belfry]

wh

[humble pulsar]

90+63+63 > 180

[nova belfry]

uh

Wth

Where did you get another 63

[hollow raven]

12x + 18 = 90
12x = 72
x = 6

[nova belfry]

god I'm so baffled

[humble pulsar]

yeah

[hollow raven]

Accidently did 90 + 18

instead of 90 - 18

which is why we got 108

[humble pulsar]

yep

[nova belfry]

o

[hollow raven]

Try doing them with 6 now

[nova belfry]

42

And

48

[hollow raven]

looks better

[nova belfry]

eh?

[hollow raven]

soo

which one is the smallest angle?

[nova belfry]

42

7x

:D

[hollow raven]

good job

[nova belfry]

can you give me another question

That's similar

it would really help me :D

[hollow raven]

We have three angles: 56 degrees, 4x+22 degrees, and x/4 degrees in a triangle, what is the value of the sum of the two biggest angles?

What do you know about this problem?

Hint: SSS theorem

Another hint: what is a midpoint?

[upper karma]

ooo

[nova belfry]

@hollow raven I think you need to label the angles

Idk I'm confused on how to work out x/4 as a angle

[hollow raven]

Its possible

[nova belfry]

let me think it

[upper karma]

ohh

i c it now.

[nova belfry]

180-56=124
124 = 5x/4 + 22

Hmm

4x + 22 + X/4 how do I make X the subject

124 = 4x + 22

[hollow raven]

Try to make the denominators of the coefficients match

[nova belfry]

ok

[hollow raven]

Example: 2 * 2/2 = 4/2

[nova belfry]

ok

5x/4 + 22

5.75+5x = 124

AAAAAAA this is so confusing

[hollow raven]

Nope

[nova belfry]

hmm

[hollow raven]

1 = 4/4

2 = 8/4

[nova belfry]

wha

1 = X/4

[hollow raven]

a*x + b*x = (a+b)*x

[nova belfry]

Oh god

[hollow raven]

Think of it this way

If I have one pair of dice on one hand, and two pair of dice on the other, how many pairs of dice do I have in total?

[upper karma]

@hollow raven ok i thought i had it but im still clueless

😔

[hollow raven]

@upper karma Notice how the smaller triangle has two sides that are half of the bigger triangle, and the top angle for both triangles are equal

Because midpoints intersects at a point where the sides on each side are equal

so seperated equally in half

[nova belfry]

180-56 = 124 right ?

124 = 5x/4 + 22
102 = 5x/4
102/4 + 5x =
25.5+ 5x

please tell me I did it right

I'm confused on the re arrangements

Making X the subject is confusing

[hollow raven]

124 = x/4 + 4x + 22

[nova belfry]

Ok

[hollow raven]

124 - 22 = x/4 + 4x + 22 - 22

[nova belfry]

102 = X/4 + 4x

[hollow raven]

102 = x/4 + 4x

[nova belfry]

ok

[hollow raven]

102 = (1/4)x + 4x

[nova belfry]

What did you just do there

[hollow raven]

2/4 = 2 * (1/4)

[nova belfry]

Huh

[hollow raven]

Im trying to show you that x/4 is just 1 over 4 multiplied by x

Because we would just be multiplying the numerators here

That's a bad way to put it

[nova belfry]

Hm

Okk

[hollow raven]

But x*1 = x right?

[nova belfry]

Yeah

X = 1

[hollow raven]

Not what I mean

[nova belfry]

Nono

1x

=

X

[hollow raven]

Right

Like If I did 2x/4

[nova belfry]

that's 1*2x

/4

[hollow raven]

Would you understand why I say its equal to x*(2/4)?

[nova belfry]

Yeah

[hollow raven]

Okay

[nova belfry]

I get it now

Ok Carry on

[hollow raven]

102 = (1/4)x + 4x

[nova belfry]

Okay

[hollow raven]

Do you know how to add fractions?

[nova belfry]

/x

Uh

Multiply

The

Denominator

Or something

Common values

I know how to do it

what do I add

[hollow raven]

Okay

[nova belfry]

(1/4)/X + 4x/x

Right ?

[hollow raven]

Its very easy to do 3x + 4x because we can add 3+4 easily

[nova belfry]

ol

ok

[hollow raven]

But it gets more challenging when we have to add (1/4)x + 4x

[nova belfry]

e

[hollow raven]

But its generally the same idea right?

[nova belfry]

yeah

It is

[hollow raven]

Just adding 1/4 + 4

[nova belfry]

yeah

1/4 + 4/1

ok

[hollow raven]

Right, and now you have to find the least common denominator right?

[nova belfry]

mhm

It's 4

Or is it

[hollow raven]

Yep

[nova belfry]

okk

[hollow raven]

Okay, we see that 1/4 already has 4 in its denominator

How about 4/1?

[nova belfry]

Soo

16/4

[hollow raven]

Right

[nova belfry]

1/4+16/4

17/4

[hollow raven]

Yep :))

[nova belfry]

1 1/4

[hollow raven]

?

[nova belfry]

I keep it as improper?

[hollow raven]

We end up with 17/4 x

[nova belfry]

ok

[hollow raven]

Depends on what your teacher wants

But improper is usually fine

[nova belfry]

You made the question

[hollow raven]

Im no teacher haha

[nova belfry]

o.o you sure about that

Anywaysb

So

[hollow raven]

improper is fine here i suppose

[nova belfry]

102= 17/4x

[hollow raven]

All we have to do is isolate for x on one side and we can find the sum of the two largest angles

[nova belfry]

Okk

[hollow raven]

x = ?

[nova belfry]

Hm

X = 102/4

Or 17

[hollow raven]

Actually, we just put the whole thing under

x = 102 / (17/4)

[nova belfry]

ok

[hollow raven]

Looks confusing

[nova belfry]

it does

So the answer should be

[hollow raven]

But if you can remember this one thing, you will be fine

[nova belfry]

102/12.25

What the one thing

[hollow raven]

Or that

17/4 is not = 12.25

[nova belfry]

mm

huh

o

[hollow raven]

The one thing is btw

[nova belfry]

3.25

[hollow raven]

102 / (17/4) = 102 * (4/17)

[nova belfry]

Ok

[hollow raven]

You just reverse the numerator and denominator

and multiply

[nova belfry]

Why did you reverse

[hollow raven]

Looks much easier don't you think?

[nova belfry]

sorta

I'm gonna add you so when I get the hang of this topic I'll come back to you for questions

[hollow raven]

Well, you can always test it

[nova belfry]

:D

hm

[hollow raven]

I don't usually add people

[nova belfry]

I got school tommorow

[hollow raven]

Sorry

[nova belfry]

oh

:(

[hollow raven]

But you can ping me here

[nova belfry]

ok

[hollow raven]

For example, anyways

If I have 1, and divide it by 1/2

[nova belfry]

anyways ciao thanks for helping me out :)

[hollow raven]

I get two

[nova belfry]

why 2

huh

[hollow raven]

1/2 is one half right?

[nova belfry]

WHA

yeahhh

0.5

[hollow raven]

1/0.5 = ?

[nova belfry]

2

HUH

[hollow raven]

and if i flip the fraction

1/2 becomes 2/1

[nova belfry]

2/1

[hollow raven]

1*2 = ?

[nova belfry]

4

2

2

[hollow raven]

right

[nova belfry]

It's two

[hollow raven]

yep

[nova belfry]

1 times 2 is 2

0.5 X 4 is 2

[hollow raven]

1 divided by half is 2

[nova belfry]

Ok

[hollow raven]

1 / (1/2) = 1 * 2/1

[nova belfry]

yeah

[hollow raven]

and thats why it works

[nova belfry]

I'm gonna flop my tuition test

[hollow raven]

try your best with what you've learned

[nova belfry]

The work the teacher gives me just isn't right for me

it's not the level I'm working at

but my parents don't listen to me

And they just want me to go with the class

like what on EARTH is P = F/G

[hollow raven]

Maybe you should sit down and talk about what you really need with your parents @nova belfry whether its more specialized classes or tutoring at a pace you can understand

[nova belfry]

Yeah

[young umbra]

You can also try looking on YouTube, there are many YouTube channels that explain math you’ll surly find someone that fits your style and taste better than your teacher.

[upper karma]

^^ honestly my teacher sucks so i just learn everything from youtube

[young umbra]

I’m studying CS at Uni and do that a lot of the time I just take the name of the topic from my Professor and learn the details form YouTube. 😅

[upper karma]

same here 🤣

[hidden pulsar]

posted this in precalc but it might go in trig too idk so

can someone explain this, particularly the boxed part

[humble pulsar]

@hidden pulsar what are you confused about?

[hidden pulsar]

nvm nvm i literally just understood it, i realized the negative in front of pi/6 is just used to say look in quadrants where sin is negative

which is quadrant 3 and 4

[humble pulsar]

i mean yes, but no

[hidden pulsar]

what am i missing

[humble pulsar]

arcsin(-1/2) = -pi/6 if you put it into your calculator

[hidden pulsar]

arcsin?

[humble pulsar]

sin inverse

[hidden pulsar]

ohh yea ik

[humble pulsar]

easier to type arcsin than sin^-1

anyway

-pi/6 = 11pi/6 since -pi/6 is quad 4

[hidden pulsar]

yea cause 2pi -pi/6 right

[humble pulsar]

yeah

but sine is also negative in quad 3

[hidden pulsar]

so pi + pi/6

[humble pulsar]

which is pi + the reference angle

[hidden pulsar]

okok

[humble pulsar]

but the minus on pi/6 doesnt mean when sin is negative

the - on 1/2 means that

[hidden pulsar]

ohhhh yea nvm you're right

thanks

🙏

[languid wraith]

@hidden pulsar

[upper karma]

please help

[pure pumice]

Can you translate that to english? @upper karma

[upper karma]

If the lines PR and SU are parallel m = (angle oqr) = 30 ° find m (PQT)

[pure pumice]

30°

Vertically opposite angle.

[upper karma]

which is the value of x

-120°

• ?

[pure pumice]

Ya -120 if included direction, if only magnitude then 120 only.

[upper karma]

-130°

no

-65°

[pure pumice]

65

Yup

[upper karma]

damn

im going to be a teacher

[pure pumice]

Yup

[upper karma]

thx

this was a test

btw

9.10 like a-

biscuite

hai pv

[upper karma]

@upper karma what language wss it written in

[upper karma]

Romanian

[meager cairn]

Anybody know why I got this wrong?

[wise hornet]

maybe they want them the other way round idk

[naive walrus]

@green tree

[green tree]

https://i.imgur.com/dNWuzRo.png

https://i.imgur.com/4RmXNJT.png

[quick wigeon]

Someone please help me I don't understand how to do this

[wise hornet]

cut off the rectangle on the left and you have a right-angled triangle

[quick wigeon]

Once I solve for the bottom of the right angled triangle I made and get 3.36 what do I do now?

oh wait the bottom is 3

so you just add it

ok nvm thank you so much that helped a lot!

[zenith garnet]

can someone help me prove this congruence?

[wise hornet]

use RHS

[zenith garnet]

I know that proving the middle fat triangle is isoceles will prove a side sied angle congruence

whats rhs

[wise hornet]

triangles are congruent if they both have a right angle, their hypotenuses are equal and one other side is equal

hypotenuses?

hypoteni?

hypotenurem?

[zenith garnet]

oh ok...

[wise hornet]

hippopotami?

[zenith garnet]

so i know they are both right

and have an equal angle

oh and i know that they have an equal hypotenuse right?

i dont rlly have to do much to prove that

[wise hornet]

ok

[zenith garnet]

right?

lmao

[wise hornet]

yes

[zenith garnet]

ogey 😄 ty

[wise hornet]

but that's not enough

@zenith garnet

[zenith garnet]

how come

[wise hornet]

you can't use the right angle twice

[upper karma]

You have 2 sides and a 90 degrees angle

[zenith garnet]

huh

[wise hornet]

the right angles are the same, that and the hypotenuse is only 2 things

[zenith garnet]

one of the legs are equal

[wise hornet]

wait hang on

[zenith garnet]

https://cdn.discordapp.com/attachments/326138757474680852/776186065824383046/Screen_Shot_2020-11-11_at_12.42.09_PM.png

[wise hornet]

oh right that's what you meant

yeah okay

so that'll do it

[zenith garnet]

so UW = VZ and the right angles, adn the hypotenuse

[wise hornet]

yes

[zenith garnet]

time to write a proof 😩

[upper karma]

WY=ZX because WY=WX+XY, ZX=ZY+XY and WX=ZY

[wise hornet]

that'll do it

[upper karma]

time to write a proof 😩
It's literally 2 lines come on

[zenith garnet]

😦 i literally just learned this

[cloud valve]

hi

umm

idk if this is right channel to ask about conditional identities

[wise hornet]

never heard of them

[cloud valve]

can I send a picture of a task my example?

I will try to translate the task for you as much as I can

since my professor is an complete idiot

[wise hornet]

go on

[cloud valve]

prove that the following equations hold for the angles of a triangle

[wise hornet]

oh

fine

what's the problem?

[cloud valve]

I have no idea what to do

but here are examples

[wise hornet]

ok but like they're the angles of a triangle

so gamma will be 180-alpha-beta

you can do things with that

[cloud valve]

let me write that

k.

[hybrid solstice]

anyone know if this shit is ASA AAS SSS SAS or woudl it be HL or not congruent

[wise hornet]

RHS

[hybrid solstice]

HL?

new it

rhs is HL right?

@wise hornet thanks i get it

@wise hornet you know thise one?

[wise hornet]

not necessarily

[hybrid solstice]

nah its good

[wise hornet]

no i mean it's not necessarily congruent

[hybrid solstice]

oh

alright good i said thats what it was

on my paper

ight thx

[main lintel]

What's RHS and HL?

@wise hornet

[zenith garnet]

RHS (Right-angle-Hypotenuse-Side), also known as HL (Hypotenuse-Leg): If two right-angled triangles have their hypotenuses equal in length, and a pair of shorter sides are equal in length, then the triangles are congruent.

can someone help me prove this

tbh idk where to start

[wise hornet]

draw lines

[main lintel]

So in RHS, the shortest leg should be equal, or the longest leg, it is not enough that they have equal one leg?

[zenith garnet]

wdym draw lines

[wise hornet]

what lines can you draw that aren't already there

[zenith garnet]

uh i can make the diameter on the y axis

[wise hornet]

vraf: if they're right-angled triangles and the hypotenusi, the longest sides of the triangles, are equal, and one other side of each is equal, they're congruent

what other lines other than that

[main lintel]

Connect ACBO maybe.

@zenith garnet

[zenith garnet]

ahh i see...

[main lintel]

@wise hornet Are you sure that is enough.

[zenith garnet]

still not sure how to prove its 90 degrees

[main lintel]

What if of one triangle shortest is equal to the other triangle longest.

[wise hornet]

it's gotta be the hypotenusi

the longest ones gotta be equal

otherwise it obviously doesn't work

drizy, that's what you want to end up with

that'll be the same as what you want

draw more lines first

[zenith garnet]

k

[main lintel]

@wise hornet I'm not sure we are on the same page. Do you have to specify that the longest legs are equal, or that they have one leg equal is enough.

[wise hornet]

if they're right-angled triangles and the longest sides of the triangles are equal and one other side of each is equal, they're congruent

[main lintel]

OK, so right angled, hypotenuse, and any leg equal.

Because on google it says: "If the hypotenuse and one leg of one right-angled triangle are equal to the corresponding hypotenuse and leg of another right-angled triangle, the two triangles are congruent."

So they say "the corresponding..."

[wise hornet]

okay how about this

the proof that that works as a congruence thing follows from pythagoras' theorem

so you know length of hypotenuse h and another side a

the other other side is b

[main lintel]

ok, makes sense.

[wise hornet]

and h^2 - a^2= b^2; as b >=0, b is uniquely determined by the other facts, so it just turns into SSS or SAS or something

[main lintel]

yes, if you know 2 sides, the third is necessarily implied

The google is missleading then.

@zenith garnet Yes this should be simple to prove if you connect OA and OB, you don't even need C.

[zenith garnet]

wait so what does that prove

@main lintel

[wise hornet]

RHS works

[main lintel]

@zenith garnet you mean this: "Yes this should be simple to prove if you connect OA and OB, you don't even need C "?

[zenith garnet]

huh

[main lintel]

wait so what does that prove
What are you refering to with this

[wise hornet]

draw more lines

[zenith garnet]

connecting OA and OB

[wise hornet]

okay so fiddle with that

what do you know about things to do with that

[zenith garnet]

draw more lines
@wise hornet yes, i did

[wise hornet]

okay

[main lintel]

Connect OA and OB and then observe the triagnles OBM and OAM.

[wise hornet]

what do you know about OA and OB

[zenith garnet]

well they are congruent i believe

actually yeah

they have SSS congruencty

[wise hornet]

ok

so what does them being congruent mean

[zenith garnet]

their angles are equal as well

[wise hornet]

anything you can do with that?

[zenith garnet]

mmmm

well i do want to prove that theyre right triangles...

but i dont rlly have any like

values

well ik they add up to 180

*the angles

[wise hornet]

yes

each of the triangles' angles adds up to 180

is there anything else which adds up to 180

[zenith garnet]

oh the angle

like

ya

like the 180 degree angle

[wise hornet]

yeah okay there we go

[zenith garnet]

mhm

uhhh

sooo

[wise hornet]

?

[zenith garnet]

idrk what that does

[wise hornet]

hat OMA = hat OMB

[zenith garnet]

hat?

[wise hornet]

and hat OMA + hat OMB = hat AMB = 180

[zenith garnet]

what is hat

[wise hornet]

the angle thingy

[zenith garnet]

oh oop ok

yeah

that makes sense

OMA + OMB = 180

*angles

OH

AND SINCE THE TRIANGLES ARE CONGRUENT

OMB= OMA

[wise hornet]

yee

[zenith garnet]

ADHAHDFHADJFHLASFHDAJSK

TY 😄

[slow void]

If cos theta=-3/5 for pi < theta < 3pi/2 such that theta is in radians, evaluate the following cos theta/2?

Need some help 🙂

[wise hornet]

cos^2(x) = (1+cos2x)/2

[slow void]

What are the steps

[buoyant oracle]

Anyone help?

[wise hornet]

trig

[buoyant oracle]

opp/adj?

[wise hornet]

go on

[buoyant oracle]

tan 38.4 x/17

[wise hornet]

you missed an equals but yes

[prime gull]

how many platonic solids are there?

and how do you figure out?

[main lintel]

Anyone help?
@buoyant oracle omg imperial units 🤭

[wise hornet]

consider the vertices at which the polygons meet

what works

[buoyant oracle]

x=17tan38.4

x= 13.5 ft

[prime gull]

i dunno

[main lintel]

does anyone know how to do this?
@prime gull Arent these platonic solids.

[prime gull]

i think so? but i need to have reasoning

[main lintel]

Proving 1 and 2 is nottrivial

[wise hornet]

okay well how many polygons do you need at minimum at a corner

[main lintel]

Platon proved that, or euclid. But I would never find the solution if I havent read the proof before. You should search wikipedia for platonic solids and read the article

[wise hornet]

for it to be 3d

[prime gull]

3

[buoyant oracle]

@wise hornet am i correct?

[wise hornet]

think os

okay and how many triangles can you shove at maximum around a corner before it stops really working

they're equilateral btw

[wise hornet]

trig

[prime gull]

i guess 6? but then the shape wouldn't close

[main lintel]

not 🦶 🦶 again 🤮

[wise hornet]

okay so 5 then

so gotta have at least 3 and at most 5 triangles

what about squares

[prime gull]

ohh ok

[wise hornet]

etc.

[prime gull]

for squares 3 ig

thanks!!

[wise hornet]

and then pentagons...

yadda yadda

a tale as old as some greek buggers

[buoyant oracle]

help please

@wise hornet

[wise hornet]

yes

the answer is 2

idk do you have an answer

okay no i must sleep

i am sorry

i have not yet ascended beyond biology

[buoyant oracle]

lmfao

its fine no worries

gn

[pearl lava]

can I use law of sines to solve this?

[main lintel]

I think so. Find the remaining sides using law of sines.

And then the area using the formula for the area from the sides.

[pearl lava]

thanks

would the perimeter be this:

[main lintel]

Seems too big.

It actually might be

One side is 9, and the angles are 60 and 45, so other sides are similar to that, so the perimeter is somewhere around 3*9=27

Your answer is around 32, so this is close enough.

[pearl lava]

then I do this to get the area?

[main lintel]

Actually yes, you can get the height using side_length * sin(respective_angle) and multiply it with the base and divide by 2.

[pearl lava]

ok thanks

[main lintel]

Not sure that the figures are correct, but the concept is ok

[silent plank]

you probably would have found the altitude at one point

when finding the perimeter

[main lintel]

No, perimeter he found by the law of sine.

I mean, perhaps the intermediate of the law of sine is the altitude.

[silent plank]

multiple ways to approach it and those values are corect

[upper karma]

If you can help with a 6 question geometry homework please dm me

[main lintel]

What's aPb?

[snow isle]

oh thats just a mistake my teacher made while typing it out sorry!

[foggy talon]

hi can someone help me with my homework

i really need help

[humble pulsar]

cant help w/o the question @foggy talon

[foggy talon]

yes sorry this is the question

[bronze thistle]

"parallel" means that both lines have the same slope

do you know how to find the equation for a line given the slope and a point it goes through?

[foggy talon]

not really my teacher doesnt

really teach

i have a new question

could you please give me the answer

[humble pulsar]

we dont give answers

[foggy talon]

okay im sorry for asking then

please help me on this one

my teacher doesnt explain anything to us

so i really dont know

[agile rain]

@foggy talon If the line is parallel it must have the same slope

so, right now, we have: y = 7x + b

so we need to get b

In order the get b, we need to plug in the point (1, -3) into the equation and solve

so if we do this we get: -3 = 7(1) + b

and solving will give us, b=-10

so our answer is y = 7x - 10

[nocturne thicket]

Can someone check my proof?

[snow isle]

could someone help me with my problem

ignore the APB

[foggy talon]

@agile rain thank you so much

[agile rain]

@foggy talon np

@nocturne thicket In your given you forgot to state AC = CD

wait never mind

im dumb

thats what you are trying to prove

@snow isle The reflection of PQR would be SLU

The translation of DEF would be ACB

[slow void]

Can any help me?

If cos theta=-3/5 for pi < theta < 3pi/2 such that theta is in radians, evaluate the following cos theta/2?

[snow isle]

how much would they reflect by

[agile rain]

The units are not labled so we wouldn't know

[sterile prism]

can someone help

if u could draw out how to do it that would be great i really need help on this

[dusky surge]

Hello there @sterile prism

Which part of the question you do not understand?

[dusky surge]

Hello there @whole carbon
Hmm...Mode median mean

[whole carbon]

Hey

[dusky surge]

Although is not on the right channel, but I can help I guess

[whole carbon]

Okay

[dusky surge]

Mode first

[whole carbon]

I didnt know what to put it in

sorry

[dusky surge]

What does mode mean?

[whole carbon]

the number

that appears the most

often

[dusky surge]

yea

So there will be at least two 7s right

[whole carbon]

yeah

[dusky surge]

Good

Now median of four numbers is ?

[whole carbon]

wym

[dusky surge]

There are four numbers

[whole carbon]

yup

[dusky surge]

Let's say they are in ascending order

What is the median of those numbers

[whole carbon]

so like

5 6 7 8

is that what u mean

by ascending order

[dusky surge]

Yea

[whole carbon]

6 7 8 9

well

no 9

[dusky surge]

What is the median

[whole carbon]

7

7.5 right

[dusky surge]

7.5is correct

[whole carbon]

Ok

[dusky surge]

I'm just making sure you know what does median mean

[whole carbon]

yup

[dusky surge]

So, now we have 2 7s and the median is 7.5 what is the next number?

[whole carbon]

8?

wait

[dusky surge]

Yea

[whole carbon]

ok nvm

[dusky surge]

We have 7 , 7 , 8 , _

[whole carbon]

9

[dusky surge]

Median is the sum between the middle 2 numbers divided by 2

[whole carbon]

7.25?

[dusky surge]

That's why the median of 7,7,8,_ is (7+8)/2=7.5

Finally, mean is 9

What does mean mean?

[whole carbon]

all of them added

and then divided by 2

or

4

[dusky surge]

4 is good

So we add 7,7,8,_ together and divided by 4 needs to be =9

[whole carbon]

Yeah

[dusky surge]

You can guess the number now :D

[whole carbon]

wait

9 isnt it right

[dusky surge]

nope， you can try to add them

7+7+8+9

[whole carbon]

11?

[dusky surge]

7+7+8+11=?

[whole carbon]

nah

hold up

14

[dusky surge]

Good!

[whole carbon]

so

Its 7

7

7

14

I mean 8

[dusky surge]

Yep

[whole carbon]

7 7 8 14

[dusky surge]

Done!

[whole carbon]

Ok

so now 2nd one

@dusky surge

[sterile prism]

btw @dusky surge i figured it out

sorry i didn’t answer earlier

[upper karma]

Help anyone

[silent plank]

uh...timed test...

[errant grove]

How is that middle triangle a right triangle

Lmao

[errant grove]

Wait nvm

[azure vigil]

How to find the value of the ?

[upper karma]

recall similar triangles

[sharp socket]

I made a picture

it's not obvious to me why BE is the angle bisector of ABC

[cloud valve]

hi

[upper karma]

it's not obvious to me why BE is the angle bisector of ABC
you need to prove it

consider triangles BNE and BQE

@sharp socket

[sharp socket]

@upper karma They have two equal corresponding sides

[upper karma]

how about BE

[sharp socket]

that's one of them

[upper karma]

my bad I thought we had 3 sides

maybe consider triangles BNP and BQM

from that you have angles BNP and BQM are congruent

[sharp socket]

How we know the triangles are congruent

[upper karma]

they have 2 sides and an angle between those 2

[upper karma]

not here

[cloud valve]

no no

wait let me ask

[upper karma]

no

[sharp socket]

go somewhere else pls

[cloud valve]

i dont want you to solve it

I have question about it

[sharp socket]

yes but i had a question first

[cloud valve]

...

[upper karma]

@sharp socket do you agree ?

[sharp socket]

Which two sides are those

[upper karma]

BN = BQ and BP = BM

[sharp socket]

Oh okay

And the angle that would be congruent is angle B?

[upper karma]

?

[sharp socket]

Does this look right? @upper karma
S : BN = BQ
A : B = B
S : BP = BM

[upper karma]

yes

[sharp socket]

from that you have angles BNP and BQM are congruent
OK, i agree

[upper karma]

now there are many ways to proceed

[sharp socket]

Ok so I can show that triangle BNE is congruent to triangle BQE

[median sky]

Tf is trigonometry

[upper karma]

for example considering triangle MNE and PQE

[median sky]

Ah yes i understand

No

Anyway imma leave

[sharp socket]

@upper karma Whats the goal of looking at those

my internet is being whack rn

[upper karma]

I cannot tell you everything

your final goal should be proving triangles BNE and BQE are congruent, or triangles BME and BPE

notice that to prove congruency between triangles BNE and BQE, you are just missing NE = EQ

[sharp socket]

oh ard

[upper karma]

for example considering triangle MNE and PQE

[foggy talon]

hi can someone check my answer

i really need to get this done

i got y=1/3x+15

[dark sparrow]

incorrect

this does not pass through (3,7)

[foggy talon]

can you please help me then

what did i do wrong?

which step?

[dark sparrow]

you haven't given me any steps so i can't really tell

[foggy talon]

i did 7+8=1/3(3+5)+b

is that the first step?

[dark sparrow]

theres no such thing as "the" first step

i mean, the equation $y+8 = \frac13 (x+5) + b$ certainly does describe a line parallel to $l$ no matter the value of $b$, so you have not done anything wrong thus far

[somber coyote]

Ann:

[foggy talon]

oh alright

i got the answer

i have a new one

pls help me on this one

[grave thunder]

first reduce it y=mx+c

you have your m find c by putting the coordinates

[foggy talon]

okay so -2+6=-12-3+b

?

[grave thunder]

wait what did you do though

first reduce this equation to y=mx+c

it will be y=6x-24

so u has m =6 too cause its parallel

so u:y=6x+b(b is the intercept / constant like c)

put -2,-3 in this one and get b