#geometry-and-trigonometry

1 messages · Page 315 of 1

silent plank
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still vague

fresh galleon
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the small angles on the line

silent plank
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consider the red line

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what information can you get about
4x+40 and 2y
from that

upper karma
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guten morgen

fresh galleon
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im not sure

upper karma
#

look at the angles

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what's "the angle of a line"

silent plank
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how big is that angle
180

fresh galleon
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180

upper karma
#

and what happens when a line passes through another else?

fresh galleon
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they intersect

upper karma
#

yes, what do you can observe focusing on the angle?

fresh galleon
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2y and 4x+40 are on the other side

upper karma
silent plank
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how big is that full red angle

fresh galleon
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180

silent plank
#

and do you see that angle is formed by combining angles with measures (4x+40) and 2y

fresh galleon
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yeah

silent plank
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and use that to set up your equation

upper karma
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i think the best way to see that is thinking like scissors

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when you open the scissors, it opens down too, right?

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if you close it..

fresh galleon
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it closes the bottom too

upper karma
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yes

fresh galleon
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but how do I apply the equation

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like 4x+40x2y

upper karma
#

do you see that both angles follow each other?

fresh galleon
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yes

upper karma
#

so

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both are equal to each other

silent plank
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that's the sum of the measures

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and what is the numerical value of that sum

upper karma
#

that also happens to right and left

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if it happens to both sides and they are equal to, then you can equal both to each other and it will arise an equation

fresh galleon
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so find 4x+40x2y?

silent plank
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wait

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misread that

#

where are you getting
4x+40x2y

fresh galleon
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the red line that only leaves them

silent plank
#

the measure of one of the angles is
4x + 40

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the measure of the other is
2y

fresh galleon
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CE is 4x+40

silent plank
#

no

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fml

fresh galleon
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only one part of it?

silent plank
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you're way overthinking this probably

fresh galleon
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I have online school and my teacher only sends me the assignments

silent plank
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angle sum on a line = 180°
yes/no

fresh galleon
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yes

silent plank
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is CE is a straight line

fresh galleon
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yes

silent plank
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would the measure of angle CBE be 180°

fresh galleon
#

yes

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its just one line still

silent plank
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the angles on line CE are <BDC and <DBE

fresh galleon
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ok yes

silent plank
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i'll just do it another way

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blue + green = red

fresh galleon
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so 4x+40 and 2y both touch line d

upper karma
#

?

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wdym

fresh galleon
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oh nevermind its just oneline

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so the blue and green make a bigger angle measurement?

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like 190 and 200?

silent plank
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where are you getting 190 and 200

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what's the size of the red angle

fresh galleon
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red angle is 180

silent plank
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hence blue + green = ?

fresh galleon
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180?

silent plank
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yes.

upper karma
#

that reminds me Feynmann when he went to Brazil. the students recorded the meaning of the things but when they tried to apply, they couldn't understand what was happening holothink

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Feynman*

silent plank
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and use that to set up an equation

fresh galleon
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so what do I do know that I know it equals 180

silent plank
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what's the size of the green angle

fresh galleon
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180

silent plank
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what's the size of the blue angle

fresh galleon
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180

silent plank
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wtf

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nonon

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nonono

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NO

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NON

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NO

fresh galleon
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half of that?

silent plank
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No

upper karma
fresh galleon
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yeah the blue angle

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but earlier you said blue and green was 180

silent plank
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whats 4x+40, which is definitely not 180

fresh galleon
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now it's split?

silent plank
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green + blue = 180

upper karma
#

but earlier you said blue and green was 180
the sum of both

silent plank
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because together they form red

upper karma
#

because the sum of angles of a straight line is always 180°

silent plank
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fml, i'll just fkn explicitly write it

upper karma
#

(in euclidean geometry precisely)

fresh galleon
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so 180 isn't split now

silent plank
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$\blue{(4x+40)} + \green{(2y)} = \red{180}$

upper karma
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😮 colors

somber coyoteBOT
fresh galleon
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4times180+40

silent plank
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NO

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hwo

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wtf

#

no

fresh galleon
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4 times what

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OH

silent plank
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x

fresh galleon
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4times15

upper karma
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4times180+40
where did it arise?

fresh galleon
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120+2y=180

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so now I just find 2y

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y=60

upper karma
silent plank
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no

upper karma
#

what

fresh galleon
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120+60=180

upper karma
#

where did this 120 come from

fresh galleon
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4x15+40

silent plank
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is not 120

fresh galleon
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oh

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it's 100

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100+80

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so 80=y

silent plank
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no

upper karma
#

15? 🤔

silent plank
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yes, we reached x=15 earlier

upper karma
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you're getting numbers from nowhere

fresh galleon
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I got x as 15 earlier

silent plank
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y isn't 80 though

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where are you getting that

fresh galleon
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ok so it's 100+2y=180 rn

upper karma
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are you trying one's luck?

fresh galleon
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no

upper karma
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mm

fresh galleon
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ygg

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y=40

silent plank
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yes

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you really need to go back and review basics of geometry

upper karma
#

ah

fresh galleon
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I need chromosomes

upper karma
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no you need a review

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a thorough review

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you really need to go back and review basics of geometry
i think he just misunderstood some basic concepts

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like the sum of angles

silent plank
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angle sum on a line is within the first 5 things they teach you in geo

fresh galleon
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last part of the problem is finding m<ABE

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uhh

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@upper karma now that i know x=15 and y= 40 how do I find m<ABE

silent plank
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y isn't 80

fresh galleon
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oop

silent plank
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vertical angles and/or angle sum on a line

fresh galleon
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ok so I know it's 180

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4x+40 is on line E

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m<ABE=55

upper karma
#

same concept

fresh galleon
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So 7x+40 = 3x

upper karma
#

?

fresh galleon
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how do I find the x

upper karma
#

angle sum on a line is 180

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Ramonov told you this in the previous prob

fresh galleon
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not finding the x though

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just the y

upper karma
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why are you doing x y in your head

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angle sum on a line is 180
Use this

fresh galleon
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so for a problem

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to find x

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how would I write it

upper karma
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Why do you want to be told the same thing multiple times

fresh galleon
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I need an example to follow

upper karma
#

Bruh

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You just solved a prov

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Prob*

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Same

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Thing

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Same concept

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You didn't pay attention

fresh galleon
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4x+40 = 6x+10

silent plank
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variables are arbitrary

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4x+40 = 6x+10 was applying vertical angles in the previous question, (which is derived from angle sum on a line)

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since for the current question

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you have angles on a line

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then perhaps you should apply something related to angle sum on a line

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addition postulates should be pretty intuitive

fresh galleon
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3x is 3=x

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ABC is 61

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Thanks

silent plank
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3x is 3=x
ABC is 61
Thanks

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no

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@fresh galleon

upper karma
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Just put (7x+40) + 3x =180

fresh galleon
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Oh

upper karma
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Study your geo basics again

silent plank
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^

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like where did:

3x is 3=x
even come from

upper karma
#

until now?

strange cosmos
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^ I was so confused as to how you even got 3x is 3=x lol

bitter turret
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anyone?

upper karma
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@bitter turret i think you can mention helpers

bitter turret
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oh

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<@&286206848099549185>

dusty badge
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is j hat dot k hat = 0?
since (0,1,0) dot (0,0,1) = 0 * 0 * 0 = 0

bitter turret
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any1 help?

hallow crystal
#

Is this right? I think I have a quiz on segment addition postulation tomorrow 🤡

west basin
#

looks good

hallow crystal
#

Thankssss

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I miss my old math teacher lmao

hallow crystal
west basin
#

looks good

still jackal
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-2cos(x) = 1
how should I solve for x

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ping me

hallow crystal
west basin
#

yeah

hallow crystal
#

But then by that logic, for number 14, RT should be 12y + 12, when it’s actually 15y-9. Why?

west basin
#

its the sum of both segments

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its just a different way to express it

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its weird

hallow crystal
#

:0

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There’s two ways to express a segment?

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Or are there just two different possibilities?

west basin
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they just give you some arbitrary function

hallow crystal
#

:0

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“An arbitrary function simply means that it is a function that you are free to define in any way you want”

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How is this allowed in math?!

west basin
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it just be like that

hallow crystal
#

it do be like that doe

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Ohh are they just dummy variables

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Like they’re not realistic?

west basin
#

i wouldnt say that

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i mean they give line segments of undefined length

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the length is totally dependent on the functions they give

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they give you a function of the total segment that is equivalent to the sum of both segments functions

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so you can find y

hallow crystal
#

i mean they give line segments of undefined length
@west basin
Is 15y-9 not a (or maybe the) defined length of segment RT?

west basin
#

its defined as the length of the segment RT

hallow crystal
#

Aint that the same thing 😀

west basin
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and RT is the sum of RS and ST

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which means its equal to RT = RS + ST

hallow crystal
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Yes

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So is that not the defined length? :0

west basin
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its just a silly way to teach SAP

hallow crystal
#

:0

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F

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So I won’t be using this in the future, this is just for learning basics?

west basin
#

depends

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if you go into a math career you might

hallow crystal
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the length is totally dependent on the functions they give
@west basin
And what are the functions in this case?
8x+4 and 4y+8?

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Wait what are functions 😀

west basin
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a relation between x and y

hallow crystal
#

they give you a function of the total segment that is equivalent to the sum of both segments functions
@west basin
ohh

west basin
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i could go deep into it but

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thats simple and its true

hallow crystal
#

a relation between x and y
@west basin
What is dat

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Something that connects x and y?

west basin
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yeah

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exactly

hallow crystal
#

Or something that x and y have in common?

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Is it necessary for x and y to be connected by something

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oh yea it is

west basin
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pretty much any function will have a x and y relation

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if it doesnt it wouldnt be a function

hallow crystal
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Oh there are exceptions?

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Oh ight

hallow crystal
#

How are bisectors related to segment addition postulation?

west basin
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you can use the arc length to calculate the angle on each side of the bisection

hallow crystal
west basin
#

its easier if you have an example problem

hallow crystal
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Hm he titled the segment addition postulation and midpoint notes as “bisector notes” so I was wondering

west basin
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you know what a bisection is right

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im sure hell include examples of it

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soon

hallow crystal
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you know what a bisection is right
@west basin
“DescriptionIn mathematics, the bisection method is a root-finding method that applies to any continuous functions for which one knows two values with opposite signs.”

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never heard of it sully

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im sure hell include examples of it
@west basin
We’ll probably learn about it soon

obtuse hornet
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Anyone good with postulates, properties and theorems

west basin
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that says test on it

obtuse hornet
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Oh i didnt realize that

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It's not actually a test though, but I guess is that still not allowed? It's just homework problems

hallow crystal
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It's not actually a test though, but I guess is that still not allowed? It's just homework problems
@obtuse hornet
Yea I dunno why teachers be writing that sometimes, my teacher writes that on notes that are meant to prepare us for a next day test

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Like sully

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So I just cross it out lmao

obtuse hornet
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Lol yeah

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So am i still not allowd to ask for help on this though, cause its not a test lol

west basin
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well the first property is distribution

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you are distributing the 3 across the parenthesis

obtuse hornet
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Yeah I got that one, but I'm not sure about the correct terms for B, D, and E

silent plank
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just literally describe what you'd do to both sides of the equation

obtuse hornet
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Well it's asking for the specific property, postulate, or theorem and I'm not very good with those

west basin
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just write adding or subtracting monomials

silent plank
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something like addition/subtraction property of equality if you're required to formulate it like that

obtuse hornet
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Yeah but for B what do you call that, it's just adding them up

silent plank
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addition i guess

high geode
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anybody know how to write sin(cos-1 2x) as an algebra expression?

obtuse hornet
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Anyone know how to do this? I'm kinda confused how to format it correctly

glacial ice
#

Given triangle ABC with vertices A(−3, 0), B(0, 6), and C(4, 6).
Find the equations of the three altitudes of the same triangle

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my issue is that I'm not too sure which points the alititudes pass through

silent plank
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altitude from A to BC would be perpendicular to BC

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altitudes from B and C would lie outside the actual triangle and for those you'd extend AC and AB if you were to draw them
but doesn't really make a difference for the calculations

glacial ice
#

huh

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oh

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they ask for the equation though

silent plank
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so pretty much determine the appropriate slope and apply point slope formula

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(3 times)

glacial ice
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i know

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but uh

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i don't really know where the altitudes pass

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that's the one issue i'm having

silent plank
#

you don't need to

glacial ice
#

but they ask for the equation, wouldn't i need it

silent plank
#

the altitude would be perpendicular to the respective side

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you can use that to get the slope

glacial ice
#

the midpoint?

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like midpoint AB

silent plank
#

no

glacial ice
#

ahh

silent plank
#

the altitude would be perpendicular to the respective side

glacial ice
#

i know

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but they ask for an equation not a height

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so x = 2 would be different from x = 3

silent plank
#

apply properties of perpendicular lines

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eg, what's the slope of BC

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hence what is the slope of a line perpendicular to that

glacial ice
#

slope of bc is 6/7, perpendicular would be -7/6

silent plank
#

so you want a line with a slope of -7/6 that passes through A

glacial ice
#

but i need to know what point the altitude passes through so i can get the equation

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ohh

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for AB, would the altitude just be x = 2

silent plank
#

not 2

glacial ice
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ahh

silent plank
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the altitude isn't about the midpoint

glacial ice
#

would it be x = 4, then?

silent plank
#

no

glacial ice
#

i know the altitude isn't about the midpoint but the question asks for an equation

silent plank
#

for that the altitude would pass through C

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altitudes from B and C would lie outside the actual triangle and for those you'd extend AC and AB if you were to draw them

glacial ice
#

so if the altitude passes through C, it'd just be a vertical line going through C ( x = -3) ?

silent plank
glacial ice
#

ahh, okay

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and then for AC, would the altitude pass through B?

silent plank
#

similar idea for the altitude from B

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yes

glacial ice
#

so if the triangle were like flipped to AC being the base, the altitude would be from B to the y-coordinate of AC?

silent plank
#

wdym by y coordinate of AC

glacial ice
#

like uh if the triangle was flipped on its side

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so AC was a flat horizontal line

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and it was the base

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. B

 A        .                                                           . C
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so this is sorta what it would look like if the triangle was tilted so that AC was the base, and my question was if this was the case, would the altitude of the triangle be a straight line down from B to the y-coord of A

silent plank
#

dunno how you're bringing the y-cood into this

glacial ice
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yeah ok that's what i meant

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i just suck at explaining stuff sorry

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thanks for the help @silent plank

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@silent plank sorry for the repeat ping, but the answers didn't work

silent plank
#

what were your answers

glacial ice
#

x = -3, y = -7/6x + 6, y = -7/6x + 64/6

silent plank
#

y = -7/6x + 64/6
is wrong

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that isn't perpendicular to (extended) AC

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@glacial ice

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i.e you used -7/6 again

glacial ice
#

oh

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@silent plank y = -1/2x +8 ?

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OMY GOD

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SHOOT ME

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that's right but because i accidentally mistyped y into t i got 1/2 credit 😦

obtuse hornet
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Soo it seems like his problem got cleared up but is anyone able to help me with the one I posted right before>

glacial ice
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@obtuse hornet i would help, but i've literally forgotten all of them

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sorry D:

obtuse hornet
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Lol thats understandable, ive forgotten a lot of em even though its what im learning rn

austere depot
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Anyone that knows how to complete a square?

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And would be so kindly to explain it to my dumbass

silent plank
#

were you given notes?
do you have a specific example?

austere depot
#

x^2-8x+y^2+2y=8 and i have to find r and c(a, b)

silent plank
#

$\cts$

somber coyoteBOT
silent plank
#

alternatively since you have an equation you could add (b/2)^2 to both sides of the equation which would also be fine

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try applying those ideas and tell me if you get stuck

austere depot
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I moved on from it, i don't understand it. Now i'm working with the intersecting of a line on a circle.

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I'm supossed to do this without a calculator, and i think i've done a mistake, can someone confirm?

dark sparrow
#

you're missing a bunch of symbols

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line 4: (x-6)^2 + (x-4)^2 = 10

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2x^2 - 20x + 42 = 0

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you havent made a mistake so far other than the accidental omission of these

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but i strongly recommend dividing out by 2 before continuing

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(tho it is optional)

austere depot
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dividing what out by 2?

dark sparrow
#

dividing both sides of 2x^2 - 20x + 42 = 0 by 2

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so that you have smaller numbers to deal with

austere depot
#

i can do that?

dark sparrow
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i mean, yes?? why couldn't you

austere depot
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how would it look

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I haven't been taught it, and i'm really bad at mental arithmetics

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So dealing with smaller numbers would be the best option

dark sparrow
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if you can divide 20 by 2 and divide 42 by 2 then surely you can simplify (2x^2 - 20x + 42)/2

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it's just obvious here that all of the coefficients are even

austere depot
#

so it'd be 2x^2-10x+21=0

dark sparrow
#

since when is $\frac{2x^2}{2} = 2x^2$?

somber coyoteBOT
austere depot
#

is it x^2 ?

dark sparrow
#

what else would it be

austere depot
#

yeah it makes sense, so x^2-10x+21=0

dark sparrow
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yeah there you go

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now that's still a quadratic equation but the coefficients are smaller

atomic grove
#

<@&286206848099549185> hey anyone know how to do this? it's a prove q

vague forge
upper karma
#

@atomic grove try to complete the square on LHS

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no maybe it's better to expand cos(4x)

fresh galleon
#

anyone in the mood for a geometry test 😎

austere depot
#

a circle has been given the equation^^ how do i find the radius and c(a,b) ?

fresh galleon
#

Can someone proofread my answers?

glad oak
#

so currently I have this 5^2 = x^2 + y^2 and have set it equal to y and ended up with sqrt(25 - x^2) and the answer is over 5 anyone know how is became sqrt(25 - x^2)/5

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wait it's because of the sin isn't it so it'd be o/h and o in this case is y so that's why you set it equal to y and the hyp is 5

supple onyx
#

$\sin^4(x) + \cos^4(x) = (\sin^2(x) + \cos^2(x))^2 - 2\sin^2(x)\cos^2(x) = 1 - \frac{\sin^2(2x)}{2} = 1 - \frac{1-\cos^2(2x)}{2} = 1 - \frac{1 + (1-2\cos^2(2x))}{4} = 1 - \frac{1 - \cos(4x)}{4} = \frac{1}{4}(\cos(4x) + 3)$ @atomic grove

somber coyoteBOT
supple onyx
#

This is all assuming you're accustomed to double angle formulae and the pythagorean identity

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Lemme know if you have a q about a particular step

glad oak
supple onyx
#

Like any function, plot a few points, get a hang of the domain and range, maybe get a few derivatives and see what happens

dusk stratus
#

if r=1, and the halv circle is split into 3 parts where the middle part is removed and replaced with 2 reflections of itself, what would the total area be? i got an area of 2, but i doubt its right. could someone confirm?

upper karma
#

I hope this is enough

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@dusk stratus

dusk stratus
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oh i see

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didnt think of it that way

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got A=2 by visualizing it a much more complicated way

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tyy

upper karma
#

np

hallow crystal
#

Harambe sadcat sadcat

upper karma
#

-4/2 can be simplyfied

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dude it's just calculations

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I believe you can handle them

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@dusk stratus 2 is wrong btw

dusk stratus
#

what

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how

upper karma
#

yellow area = area of triangle

dusk stratus
#

oh shit

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my bad

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so its sqrt(5)?

hallow crystal
#

-4/2 can be simplyfied
@upper karma
Are u talking about number 1? Cuz I simplified that in the final answer

upper karma
#

yes ok

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so its sqrt(5)?
try again

dusk stratus
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i have no clue

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man

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the sides of the triangle are 2

upper karma
#

yes

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what's the area

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sqrt( ? )

dusk stratus
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3

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?

upper karma
#

yes sqrt(3)

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area of an equilateral triangle is $l^2\frac{\sqrt{3}}{4}$

somber coyoteBOT
dusk stratus
#

what i did was solving for the height by using pythagoras theorem the wrong way.. i solved sqrt(2^2+1^2) instead of sqrt(2^2-1^2)...

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bruh

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thats embarrassing

upper karma
#

ohh I see

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dont worry

dusk stratus
#

lol ty anyways man

hallow crystal
#

dude it's just calculations
@upper karma
But is number 7 right? It was different from all the other questions

hallow crystal
west basin
#

what do you need help with @hallow crystal

hallow crystal
#

what do you need help with @hallow crystal
@west basin
R my steps right

west basin
#

yeah

strong dawn
#

How exactly do I do a?

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I know sin = opp/adj so I graphed it and figured out the hypotenuse which was 1.39

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Now i do not know what to do

civic fiber
#

need to solve for x and y

west basin
#

alright

#

to solve for y use interior angels

#

and since both legs are the same you know the other two angles wil be equal

#

180=75+2x

analog sand
#

<D is a supplement of both <E and <F, and <E is a complement of <F, find m<D.

#

could someone please help with this?

paper vale
#

if two angles are supplement of the same other angles than they are equal

#

therefore <E and <f are both 45, so D=135

hearty cloud
gritty sail
#

B is midpoint --> BC = AB = 15

high shell
#

B is the midpoint of $\vec{AC}$ $\iff \vec{AB} = \vec{BC} \iff \vec{B} - \vec{A} = \vec{C} - \vec{B} \iff \vec{B} = \frac{\vec{A} + \vec{C}}{2} $

somber coyoteBOT
undone plaza
upper karma
#

thinking outside the box is also cool

flint crypt
#

can anyone please help me with my homework i am litterly brain dead at this point

hallow crystal
#

@snow hornet
So basically we have to set the two equations equal to each other because we need to eliminate a variable?

snow hornet
#

Which 2 equations @hallow crystal

#

4x+9=10y-1?

#

Ye in order to solve for either x or y

#

As long as u get one variable and u know what the whole is

#

Just plug it into the formula

hallow crystal
#

Which 2 equations @hallow crystal
@snow hornet
8 = x + y and 2/5x + 1 = y
Both of our equations for y

snow hornet
#

Yeah

#

-x+8=y

#

Substitute 2/5x+1 in for y bcuz thats what y is

#

To solve for x, and then from there reflect back on original equation now that u have x

hallow crystal
#

-x+8=y
@snow hornet
Isn’t having a negative variable bad?

#

@snow hornet did u die ff

snow hornet
#

No sorry coffee

hallow crystal
#

Lmaoo

snow hornet
#

Wym

#

Its not bad

#

Its not done yet

#

Think of it as 2 seperate problems

hallow crystal
#

like I thought ppl always avoided tryna work with negative variables so they always flipped shit around 👉👈

snow hornet
#

For 1 answer

#

U found out that y=2/5x+1

#

So u can plug it into 2/5x+1=-x+8

hallow crystal
#

Ight should I write 8-x=y or -x+8=y

snow hornet
#

And do algebra to find the true value of x

#

Doesnt matter bcuz theyre the same thing

hallow crystal
#

8-x=2/5x+1
Now I have to bring the variable to one side again right

snow hornet
#

Its ok for variables to be negative as long as it makes sense

hallow crystal
#

Oh alrighty

snow hornet
#

Correct

#

So from there

#

Solve for x

coral ore
#

Hey wouldnt the answer be 150

snow hornet
#

No

#

How many degree is in a rectangle

coral ore
#

360

snow hornet
#

R u familiar w proofs

coral ore
#

Somewhat

#

Can I tell you how I came to 150

snow hornet
#

Sure

#

Ill tell u a trick

#

Well tell me how u got 150 first

hallow crystal
#

8-x=2/5x+1
-1 -1
——————
7 - x = 2/5x
+x +x
——————
7 = 7/5x
——————
7
——————
1 = 5

#

Wait wtf

#

What the actual fuck did I just do

snow hornet
#

? @hallow crystal

#

U suppose to multiply both sides by recipricol

coral ore
#

So since we know PS and QR are parallel I extended the lines out of the shape and found the supplement of angle P which was 150 and I did this in all sorts of ways including finding the supplement back to the other side snd back again to x and such... when I got these 3 angles I even subtracted them from 360 to be sure and sure enough angle R was 68 which turns out to be a supplement of angle S.

hallow crystal
#

? @hallow crystal
@snow hornet

7 = 7/5x
——————
7
——————
1 = 5
This don’t look right 😭

#

U suppose to multiply both sides by recipricol
@snow hornet
I did that and got 5/1 😭

#

(5/7)7

snow hornet
#

Aha smart but. Did u check ur work? @coral ore

#

Did you add 70+112+68

#

And do 360-that

coral ore
#

Wait a second

snow hornet
#

No @hallow crystal

coral ore
#

Was that angle 70 instead of 30

snow hornet
#

Bingo @coral ore

coral ore
#

Sorry it was a screenshot my friend sent me

snow hornet
#

All gud

#

Another way u can solve is is simple

hallow crystal
#

No @hallow crystal
@snow hornet
I know I got the fractions part right but where did I mess up

snow hornet
#

I cant remember the proof or theorem whatever but

coral ore
#

Yeah I did the long way to be sure cuz my head was spinning

snow hornet
#

Theres one that states a straight line=180⁰

#

U couldve done 180-given angle on that line

#

To get ur answer

#

U multiplied wrong @hallow crystal

coral ore
#

Yeah I know it's just that if I get confused sometimes I go through every single minute step to see if I did anything wrong

snow hornet
#

7/5x=7 and then u multiply 5/7 both sides

#

All gud @coral ore

hallow crystal
#

7/5x=7 and then u multiply 5/7 both sides
@snow hornet
[7/5]/7
(7/5)7/1
(5/7)7/1
(5/1)1/1
5/1
5
You’re supposed to flip the first one around right?? Or does it not matter

snow hornet
#

Thats right, my bad @hallow crystal

#

Its not a 1, its x

hallow crystal
#

yayyy

snow hornet
#

I saw it wrong mb

hallow crystal
#

Wait....

snow hornet
#

Sup

hallow crystal
#

7 = 7/5x
——————
7
——————
1 = 5
@hallow crystal
I was supposed to divide by 7/5 instead of 7 wasnt i ??

#

No wonder my dumbass wrote 1 instead of 5

snow hornet
#

Yeah

hallow crystal
#

and 5 instead of x

#

So is my answer wrong? Cuz then that would’ve made 7 the fraction that gets flipped around

#

Or wait wouldn’t that give the same answer
Does it matter which one’s flipped

#

Lemmie check

snow hornet
#

X=5 and then from there, plug into original equation which was 8=x+y

#

U flip the one ur dividing

#

So like

#

If its

hallow crystal
#

Oh ight

#

5/7 is being divided into 7

snow hornet
#

8/7x=5 u flip 8/7 so it would be x=5(7/8)

hallow crystal
#

@snow hornet now to solve for y do I plug in or do I do the same thing I did with x and make two equations equal each other?

snow hornet
#

@hallow crystal plug x into original equation to solve for y

#

x+y=8

#

x=5

#

5+y=8

hallow crystal
#

Why not do what I did with x

snow hornet
#

bcuz u already have x

hallow crystal
#

Why not make equations for y also

snow hornet
#

all u need is 1 variable

#

to get the 2nd one

#

if u wanted to find y

hallow crystal
#

Oh so I COULD do equations for y but it’s easier to plug in?

snow hornet
#

u find y first and plug y in to the original to get x

#

yeah

#

shorter route

hallow crystal
#

all u need is 1 variable to get the 2nd one
@snow hornet
But it’s different with 3 variables right

snow hornet
#

ye w 3 variables

#

u need to do elimination or substitution

#

dw about that for now

hallow crystal
#

@snow hornet
4x+9+10y-1 = 5x+11y
4(5)+9+10y-1 = 5(5)+11y
20+9+10y-1 = 25 + 11y
28 + 10y = 25 + 11y
-25 -25
——————————-
3 + 10y = 11y
- 10y -10y
——————
3 = -1y
———-
-1
-———-
-3 = y

#

🥺

snow hornet
#

uh

hallow crystal
#

Hm u got positive 3 instead of -3 = y

#

uh
@snow hornet
Is my work confusing 😀

snow hornet
#

ye

hallow crystal
#

F I’ll write it down

snow hornet
#

ye

#

thats right

hallow crystal
#

God fuck finally

#

The fact that this is one of several questions on a 30 minute quiz pepega

snow hornet
#

thats the long way xD

#

lmao

hallow crystal
#

HUH

#

thats the long way xD
@snow hornet
I used the long way to solve for y? 😧

#

@snow hornet

#

Don’t die on me

#

🥺

snow hornet
#

ye

hallow crystal
#

Whaaa

#

I thought substitution was the short way 🥺

#

Substitution is plugging in right

#

And elimination is making two expressions into an equation?

#

Which is what I did for x?

#

@snow hornet vampysmug

snow hornet
#

u can do that but

#

if u know what x or y is already might as well substitute into main equation

#

@hallow crystal

#

sorry im helping this dude explain about pc

hallow crystal
#

if u know what x or y is already might as well substitute into main equation
@snow hornet
Wait what’s the main equation ?! I thought the main equation was
4x+9+10y-1 = 5x+11y
?!

snow hornet
#

x+y=8

hallow crystal
hallow crystal
upper karma
#

can i ask a physics question here ?

umbral sparrow
#

there's a physics server

upper karma
#

ok

upper karma
#

can i ask one here too

#

it's highschool physics

somber coyoteBOT
wet grotto
#

So im having trouble with this question. I really dont know how to setup the equation to solve for width and length in this case. Could I get some help😃

hollow raven
#

Ok

#

So we know that the width is w

#

and the length is tw

#

therefore, the area would be tw * w

#

so we know our area = tw^2

#

Now, the best way to go after this problem is to create an equation for each column isolating the length, the width, and the area

#

For instance, if I wanted to find the width, I can do:

#

2w + 2tw = 2400
2w (1 + t) = 2400

2w = 2400/ (1+t)
w = 2400/ (2(1+t))
w = 2400/ (2t+2)

So now I know an equation to find the width.

#

so if I wanted to plug in 1, for example

#

I can easily just do

w = 2400 / (2*1 + 2)
w = 2400 / 4
w = 600 m

#

You can change the equation above to find out the other values too ^^^^^

#

So you don't need to use multiple equations if you dont want to

upper karma
#

can i ask one here too
Go to #old-network there's a physics server for physics problems

hallow crystal
#

Is there not other way to find GS besides distance formula? I don’t wanna have to deal with a radical while plugging the values into the triangle area formula, and I can’t count the units because it’s a slanted triangle

upper karma
#

got it

hallow crystal
#

My bad I forgot to say I’m referring to the triangle problem

upper karma
#

no there isn't i guess

#

by pythagoras ? if you've found the other 2

hallow crystal
#

that’s smart omg but it doesn’t have a right angle 😭

#

F

#

Doesnt Pythagorean theorem apply only to right triangles? This one’s slanted

#

Lemmie fact check that

upper karma
#

yeah

#

only right

#

mybad

#

finding area is simple

hallow crystal
#

“The converse of the Pythagorean theorem is a rule that is used to classify triangles as either right triangle, acute triangle or obtuse triangle. ... For an acute triangle, c2< a2 + b2, where, c is the side opposite the acute angle. For a right triangle, c2= a2 + b2, where c is the side the 90-degree angle.” Technically ur not wrong, it’s just that we wouldn’t get an exact answer since there won’t be an equal sign since this is an acute angle rip

upper karma
#

you can find the range of GS but not GS

hallow crystal
#

Yea, guess I’ll just simplify the radical and plug it in to see what I get

upper karma
#

for perimeter there is no other way

#

ig

hallow crystal
#

Yea, I guess there’ll just be a radical in both my answers F

upper karma
#

you can only find out PG without distance formula

#

which grade are you in ?

covert rune
#

@hallow crystal To find GS use Pythagorean Theorem

#

To find area use Altitude-base theorem

hallow crystal
#

you can only find out PG without distance formula
@upper karma
and SP lol

#

which grade are you in ?
@upper karma
Taking geometry honors as a freshman kekw

#

@hallow crystal To find GS use Pythagorean Theorem
@covert rune
But I’d only be able to find the range then, since it’s an acute angle I’d have to use the
c squared < a squared + b squared formula
rather than the
c squared = a squared + b squared formula which is only for right triangles

#

To find area use Altitude-base theorem
@covert rune
And that’s the formula I wrote down on the bottom left corner of the image I sent right? A = base(height) divided by 2

#

Wait A means area not altitude 😀

covert rune
#

Height is another name for altitude

#

So that's the same formula

hallow crystal
#

Oh then yea, they’re the same thing

covert rune
#

GS stays the same whether you write the triangle as a right triangle or an obtuse triangle.

hallow crystal
#

GS stays the same whether you write the triangle as a right triangle or an obtuse triangle.
@covert rune
huh? Why would I write it as obtuse or right when it’s acute?! :0

covert rune
#

Triangle SPG is an obtuse triangle because angle SPG > 90 degrees

#

We form right triangles in order to use the Pythagorean Theorem

#

By the way, the coordinates for your point P should be (1,-4) not (2,-4) so you need to check your perimeter again

hallow crystal
#

By the way, the coordinates for your point P should be (1,-4) not (2,-4) so you need to check your perimeter again
@covert rune
Oh I wrote it down right on the distance formula work on the right I dunno why I messed up on the grid 😭

#

Triangle SPG is an obtuse triangle because angle SPG > 90 degrees
@covert rune
Oh my bad,
But I still won’t get an exact value for GS, whether it be in number form or radical form

covert rune
#

You can find GS by forming a right triangle on points G,S,(2,-4)

hallow crystal
#

:0000000000000

#

omg

upper karma
#

I need help with math in vc

thorny aspen
#

i need help with an algebra 2 test anyone pls im desperate

silent plank
#

Alg 2 isn't geo.
we can help with review, not the actual test.

thorny aspen
#

i couldnt find the algebra 2 channel sorry

silent plank
wicked slate
mellow sand
#

wrong channel should use #proofs-and-logic
p => q means p implies q
think of it like an if-then statement
if p is true then q is true which is true

polar sequoia
#

I am stuck on this problem and didn't know whether to classify it as Algebra or Geometry

#

Or proofs and such

#

Mainly the first one is the one I am struggling with

high shell
#

It's what's given.

polar sequoia
#

I need to prove it, at least it says that. How am I supposed to prove it if it is given?

#

That is the aspect I am stuck on

#

If it is given, is it already proven? If so, what am I supposed to out down, just that it is given to me already?

high shell
#

You don't need to. Reason 1 is "it's given".

polar sequoia
#

Oh, ok. That is way simpler than what I was thinking

#

I'm a bit of an over thinker, sorry

upper karma
#

i am told the ones marked purple are wrong, id like some advice to know what ive done wrong

silent plank
#

what's with that numbering on the left

#

in the 4th line, you are replacing <PQR with 90°

mellow sand
#

I think they want it to be substitution

silent plank
#

oh right yeh, sub

#

missed #2

#

#6 is given

mellow sand
#

such a weird way to do two column proofs; normally given is at the top

silent plank
#

many people state given stuff right before using that property

mellow sand
#

hmm I guess I've been doing them wrong then

silent plank
#

which parts were initially given

jagged relic
surreal bolt
#

You should verify the picture with someone.

torpid lark
#

we did it ^

#

in the vc

civic fiber
#

i need to find x and y

west basin
#

it start by solving for x

#

you know that both legs are equal so both the angles that arent 4x+10 will be equal

#

so 2(x-2) + (4x+10) = 180

#

solve for x

#

then 3y+(x-2) = 180

#

you can solve that once you solve for x

civic fiber
#

@west basin i did the first one the triangle didn't add up to 180

#

after finding x

#

<@&286206848099549185>

silent plank
#

show work

civic fiber
#

nvm i figured it out mb

flint crypt
#

Can anyone help me with this piece of the homework I am not familiar to it unfortunately I would appreciate if I can get some help/answers

daring marlin
#

what distance do you travel when swimming through the pool from one angle to the opposite
plz help

west basin
#

use Pythagorean theorem

#

and thats actually a 3-4-5 triangle just each side is multiplied by 4

daring marlin
#

wait wut

brittle turret
#

how would i go about finding the relation between Lines 1 and 2

high shell
#

for example, you can solve the system of these two equations, and see what kind of solution you get

#

no solution means they don't intersect (and so are parallel)
infinite solutions means they are the same line
one solution means they intersect (and the solution is the point in which they do so)

brittle turret
#

solve the system as in factor and finding values for x?

high shell
#

Solve the system as in find such (x,y) pairs that fullfill both equations at the same time.

#

Another way, though it's connected to the first, would be looking at the equations and writing down their normal vectors: (3,1) and (6,2)

#

they are parallel, so the lines also are - so you only need to check if they are the same line.

brittle turret
#

oh okay I think ill do the vectors method haha

upper karma
#

I think 5 planes contain the point E but im not sure can anyone correct me if im wrong and explain why

#

?

dark sparrow
#

this question is vague and as stated imma say there is an infinite number of planes in space which contain E

upper karma
#

but the question just askes it pertaining to the planes present

#

?

dark sparrow
#

a plane exists regardless of whether or not you draw it and/or can define it in terms of the labels you have

#

anyway

upper karma
#

okie but if we were just lookimg at what planes are drawn?

dark sparrow
#

only one plane is drawn explicitly: W

#

and it doesn't contain E

#

so the answer would be zero in that case

#

i'm guessing the question SHOULD'VE been
How many planes contain the point E and can be defined in terms of labels present on the diagram?

upper karma
#

so the sides of the triangle dont count as planes?

dark sparrow
#

in which case the answer is 4

#

cause those planes CAN be defined in terms of the present labels

#

all i've been doing here is criticizing the wording of the question

upper karma
#

oh okie so it should be 4 but which plane doesnt contain point E?

#

bc there are five in total

dark sparrow
#

i already said it, if you reread what i've said

upper karma
#

oh okie ill reread it i apologize

#

oh sorry I didnt read it carefully the first time i know understand thanks

#

so plane W doesnt contain E right?

dark sparrow
#

yes

#

W does not contain E

upper karma
#

okie makes sense thanks for the help

#

if <A and <T are complementary and <T is three times the measure of <A. to figure out <A would I set it up like...

x +3y = 90°?

#

?

#

<@&286206848099549185> Hi the question above me is concerning angle relationships and Id appriciate if anyone has the time to quickly guide me or check the work done, thank you :)

#

I see what you are trying

#

But we need to create a system of 2 eqn not one

#

eqn?

#

Equation

#

oh

#

With the 2 pieces of information given

#

okie so could i have y=30 - 1/3x?

#

and plug in?

#

Plug in what? I still don't see 2 equations

#

You have kind of mixed both into one?

#

Which isn't exactly correct

#

wait im a bit confused on how to set this up sorry

#

As well from noticing that you have 2 variables on 1 eqn

#

Don't be sorry

#

Okay

#

So what are the 2 pieces of information given

#

Individually

#

x and y are both equal to 90°

#

Right

#

Well

#

and y is is 3 times x

#

oh so y = 3x

#

?

#

What have you called A or T

#

But yeah the idea is exactly that

#

A is x and T is y

#

okie so id have x + 3x = 90

#

and just solve from there?

#

Hold up a sec

#

okie its alr

#

Yes exactly

#

okie and now ive come hp with x being 22.5?

#

,calc 90/4

somber coyoteBOT
#

Result:

22.5
upper karma
#

Yeah

#

okie and now we already established <A is x so <A is 22.5?

#

Yeah

#

okie thanks for the help

#

Yw

uncut spade
#

Hello, I would like to find the greatest distance from a point inside a cuboid to any of its sides/corners

untold coyote
#

how do i find the midpoints for my hw

upper karma
#

What?

vapid slate
#

[LS[LSS

eager hatch
#

<@&286206848099549185>

paper vale
#

use y=90-x

#

then u get some linear equation in x

upper karma
#

@eager hatch consider complementary angles properties

eager hatch
#

The 2 angles add to 90

#

use y=90-x
@paper vale so on the other one do I set up to be y=140-2x?

#

I’m so confused

paper vale
#

it is not hard

#

also i already told u what to use y as

eager hatch
#

Oh wait I’m braindead

#

I just substitute

#

I look so stoopid

verbal harbor
#

<@&286206848099549185>

upper karma
#

I slipper over the first one

verbal harbor
#

Hug

#

Huh*

#

Ah got it

pearl comet
#

Anyone wiling to be my math tutor tomorrow I’m in 10th grade geometry learning equalities and find x and y

noble shadow
#

@pearl comet i will

final escarp
#

I tried combining them together to make it equal to 180 but that didn't seem to work

final escarp
#

<@&286206848099549185>

west basin
#

It wants the greatest value x can be where (6x-2) + (3x+11) < 90

#

you might want to find the lowest obtuse value that 11y-2 can be

#

and use 180 minus that value = (6x-2)+(3x+11)

final escarp
#

thx so much

high geode
#

sin(cos-1 2x) Does anybody know how to write that in an algebraic expression?

mossy valve
silent plank
#

measure of angle A

#

how bigs that angle

mossy valve
#

ohh

#

i thought m was one of the points

#

since there was an m point in the image that i didnt put

bronze jewel
#

9x+8y=-64 write the slope intercept form of the equation of each line

#

is the answer 0

thorn linden
#

you're writing the slope intercept form of 9x+8y = - 64 right?

bronze jewel
#

uh the question is

hollow raven
#

slope intercept form is just y = mx + b

#

All you need to do is to get just y on the left side of the equation

bronze jewel
#

write the slope intercept form of the equation of each line 9x+8y=-64

#

so all i do is 8y=9x-64

hollow raven
#

Well, you are putting 9x on the other side of the equation

#

so it will become the opposite "sign"

#

so 8y = -9x-64

#

and the rest I think is self-explanatory

bronze jewel
#

so is the answer y=-9/8x-8

hollow raven
#

seems like it

pearl comet
#

Anyone?

hollow raven
#

x is an alternating angle to 75 degrees, x = 75

#

y is a coresponding angle to x, y = x = 75 degrees

#

y is also an opposite angle to 75 degrees, y = 75 degrees

sleek thistle
#

i picked the second option, which other is true?

hollow raven
#

last one @sleek thistle

sleek thistle
#

oh really?

#

that does not look like a right triangle hm

#

got confused

#

oh but the angle x is 90 degrees

west basin
#

it doesnt matter how it looks

#

you need to do it based on properties/math not by looks

#

for it to be square the diagonals must meet at 90 degrees

sleek thistle
#

got it

#

thank you

upper karma
#

Don’t give ppl free answers

#

Even if it’s for something as simple as geometric properties

paper vale
#

well when that is the entire question then there isnt much else to do

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it is also easy to prove that this claim is indeed valid

flint crypt
#

Can anyone help me with some problems really quick please

upper karma
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Just post it

flint crypt
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ok

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can you help me on that?

upper karma
#

Hmm a test

flint crypt
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this is a review on forms i just need someone to explain how to do it

upper karma
#

You need 2 sides and an angle pair for SAS

flint crypt
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yes that is true but how would i know the answer

nocturne thicket
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What symmetry does the shape contain?

nocturne thicket
#

<@&286206848099549185>

nocturne thicket
#

helpers plz

pearl comet
upper karma
#

So when -x=-12 turns into x=12, what property is that please?

pearl comet
#

<@&286206848099549185>

pearl comet
#

I know! @upper karma

upper karma
#

What is it pls?

pearl comet
#

Is it multiple choice @upper karma

upper karma
#

No.

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Is this right?

inland rock
#

Can anyone help me with this proof?
(the question marks are multiple choice if i click on them btw)

inland rock
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<@&286206848099549185>

stark plume
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I dont understand how wsin(theta) would be found with the given information if theta is equal to 55.

upper karma
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@stark plume wdym by how wsin(theta) be found?

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Is w the weight?

stark plume
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yeah

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I dont understand the trig aspect of it

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@upper karma I dont see how w*sin(55) gives us that length

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if its a hypotenuse

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sin(55)=mg/x

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Lets call WSin(theta)= A

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This assumes A is an Adjecent or Oppossite side

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But the way its drawn appears to make it a hypotenusae

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Which is why im confused

upper karma
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W is the hypothenuse, wsin(theta) is a leg and wcos(theta) is the other

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Why do yoy think it's drawn to make it a hypothenuse??

stark plume
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because how would the angle is still 55

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mind drawing me a simplified model

upper karma
#

Ok gimme some minutes

stark plume
#

This makes mucho sense

upper karma
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@stark plume is it clarified now or what

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I was about to finish the drawing

stark plume
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Yep Thanks

bitter jetty
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how cud i prove this?

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i think it has smth to do with law of cosines

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but I can't figure it out

echo kernel
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no you can use them to construct a bigger parallelogram

bitter jetty
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wdym

echo kernel
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like you can put them one side another to make another parallelogram

bitter jetty
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@echo kernel what?

flint osprey
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How far did you get with the law of cosines?

bitter jetty
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@flint osprey i just did it for c and d

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so c^2 = a^2 +B^2...

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and same for d

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and added the 2

flint osprey
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And the result is?

pearl comet
#

Anyone wiling to hand me math answers only 10 questions

bitter jetty
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so i got c^2 + d^2 = 2(a^2+b^2) -2abcosC - 2abcosD

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@flint osprey

flint osprey
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Yes good

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And what do you know about the angles C and D?

bitter jetty
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no @flint osprey

pearl comet
#

Anyone good with equalities

flint osprey
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What?

pearl comet
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Geometry

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Can anyone feed me 10 math answers very easy

bitter jetty
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idk what to do with angles

flint osprey
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I asked what you know about them

bitter jetty
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@pearl comet i dont thnk thats allowed lol

pearl comet
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I know a little bit

bitter jetty
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I asked what you know about them
@flint osprey idk

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they add up to 180?

flint osprey
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You haven't used the fact that you're working with a parallelogram yet

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Yes exactly