#geometry-and-trigonometry | Mathematics | Page 311

whole carbon Sep 17, 2020, 6:21 AM

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yeah

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and 15

dark sparrow Sep 17, 2020, 6:21 AM

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oh yeah there's an unfilled blank in 15

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okay so let's start with that then

whole carbon Sep 17, 2020, 6:22 AM

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Okay

dark sparrow Sep 17, 2020, 6:22 AM

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P(M & S)

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what percentage of the students like math and science?

whole carbon Sep 17, 2020, 6:22 AM

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53?

dark sparrow Sep 17, 2020, 6:22 AM

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why 53?

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where did you get 53 from

whole carbon Sep 17, 2020, 6:22 AM

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I added both math and science percentages

dark sparrow Sep 17, 2020, 6:23 AM

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did you add the 32 and the 21?

whole carbon Sep 17, 2020, 6:23 AM

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yeah

dark sparrow Sep 17, 2020, 6:23 AM

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32% is the percentage of people who like ONLY MATH
21% is the percentage of people who like ONLY SCIENCE

whole carbon Sep 17, 2020, 6:23 AM

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Ohg

dark sparrow Sep 17, 2020, 6:23 AM

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neither of these count towards the percentage of people liking BOTH MATH AND SCIENCE

whole carbon Sep 17, 2020, 6:23 AM

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so 18?

dark sparrow Sep 17, 2020, 6:23 AM

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there we go

whole carbon Sep 17, 2020, 6:23 AM

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my fault

dark sparrow Sep 17, 2020, 6:24 AM

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ok now let's move on to 16

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P(M & SS)

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what percentage of people like BOTH MATH AND SOCIAL STUDIES

whole carbon Sep 17, 2020, 6:24 AM

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12

dark sparrow Sep 17, 2020, 6:24 AM

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great

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P(M or SS or S)

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what percentage of people like math or science or social studies

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(i.e. at least one of the three)

whole carbon Sep 17, 2020, 6:25 AM

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so any subject?

dark sparrow Sep 17, 2020, 6:25 AM

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i said what i said

whole carbon Sep 17, 2020, 6:26 AM

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oh

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okay so

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21

dark sparrow Sep 17, 2020, 6:26 AM

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that... is way too low

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why 21?

whole carbon Sep 17, 2020, 6:26 AM

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u said at least one of the three

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oh its 6

dark sparrow Sep 17, 2020, 6:27 AM

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no

whole carbon Sep 17, 2020, 6:27 AM

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what

dark sparrow Sep 17, 2020, 6:27 AM

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i didn't say count the ones that like ALL THREE AT ONCE

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i said count the ones that like AT LEAST ONE THING

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first you counted only the ones who like just science

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then you counted only the ones who like all three at once

whole carbon Sep 17, 2020, 6:28 AM

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im confused

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would it be 100

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lol

dark sparrow Sep 17, 2020, 6:29 AM

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yes

whole carbon Sep 17, 2020, 6:29 AM

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what does the U mean

dark sparrow Sep 17, 2020, 6:29 AM

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union, which in this context is the same as or

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the upside down U is intersection, a.k.a. and

whole carbon Sep 17, 2020, 6:30 AM

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so how do I do that one

dark sparrow Sep 17, 2020, 6:31 AM

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P(M ∩ S ∩ SS) = the percentage of ppl who like math AND science AND socials

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i.e. all three at once

whole carbon Sep 17, 2020, 6:33 AM

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oh

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Okay

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so 6

dark sparrow Sep 17, 2020, 6:33 AM

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yes

whole carbon Sep 17, 2020, 6:34 AM

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whats the U

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like wym by intersection or aka

dark sparrow Sep 17, 2020, 6:35 AM

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a.k.a. means also known as

whole carbon Sep 17, 2020, 6:35 AM

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yeah ik

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but how does that go in the math question

dark sparrow Sep 17, 2020, 6:36 AM

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??

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ok fine

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∩ = AND

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∪ = OR

whole carbon Sep 17, 2020, 6:37 AM

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so are they both 100?

dark sparrow Sep 17, 2020, 6:37 AM

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no

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first one's 6 second one's 100

whole carbon Sep 17, 2020, 6:37 AM

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but their both or

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ik

dark sparrow Sep 17, 2020, 6:37 AM

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no they aren't!

whole carbon Sep 17, 2020, 6:37 AM

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im talking about the other 100

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the one above it

dark sparrow Sep 17, 2020, 6:37 AM

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oh

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yes then those are both the exact same thinhg

whole carbon Sep 17, 2020, 6:37 AM

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ok

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okay so now 18

dark sparrow Sep 17, 2020, 6:39 AM

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oh boy 18

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with the bad notation

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these should both be answered as "nonsensical" tbh

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cause you can't take the intersection of two numbers

whole carbon Sep 17, 2020, 6:40 AM

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yeah its kinda confusing me

dark sparrow Sep 17, 2020, 6:40 AM

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yeah let your teacher know their formatting and notation both suck

whole carbon Sep 17, 2020, 6:41 AM

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lmfao

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so what is 18

dark sparrow Sep 17, 2020, 6:43 AM

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i refuse to interpret bad notation as what's intended as opposed to what's written

whole carbon Sep 17, 2020, 6:43 AM

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oh

stark plume Sep 17, 2020, 7:30 AM

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Look at that document im sure i have aids

hybrid hornet Sep 17, 2020, 7:52 AM

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am i tweaking or does x not have a solution

📎 unknown.png

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sin(x) for all x in that interval is <0

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catThimc

silent plank Sep 17, 2020, 8:00 AM

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the question is borked

dark sparrow Sep 17, 2020, 8:05 AM

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the question is fucked up for exactly that reason @hybrid hornet

kindred walrus Sep 17, 2020, 9:12 AM

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IM DEAD, I’ve never seen formatting like that for an assignment before 💀.

keen goblet Sep 17, 2020, 11:00 AM

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Hey, im confused over one thing in trigonometry

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So in Quadrant 3

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Sin and cos are negative

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while tan is positive

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What im confused about is why is tan positive?

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actually i know why tan is positive, but why isnt the Sin and Cos positive?

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since the x and y axis are both negative in the 3rd quadrant

pure cape Sep 17, 2020, 11:05 AM

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i think you just answered yourself, the sin and cos are negative in the 3rd quadrant

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because the axis consists of negative values in that area

keen goblet Sep 17, 2020, 11:10 AM

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ye but -y/-x is positive

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i just realised the Hypotenuse is always positive, thats why they are negative in the 3rd quadrant

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problem solved

violet surge Sep 17, 2020, 12:05 PM

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Hello everyone! I am an Italian student who will soon take an entrance test for the faculty of "Computer Engineering". Goniometry / trigonometry is my weak point. Do you have any material to help you learn more easily? Thanks so much in advance for the support

Problem solved

simple walrus Sep 17, 2020, 2:13 PM

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anyone have any tools to easily study algebra 2/trig?

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i just need some good resources to rebuild and strengthen the basics of algebra

Problem solved nvm

empty granite Sep 17, 2020, 3:16 PM

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📎 20200917_161548.jpg

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Something to do with pythagoras theorem

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So so so so hard

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The measurements are correct but the diagram is not to scale

left zinc Sep 17, 2020, 3:40 PM

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📎 unknown.png

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pls help

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📎 unknown.png

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these 2 shy

dark sparrow Sep 17, 2020, 3:44 PM

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what's giving you trouble here?

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this is a matter of applying two things:

angles in a triangle add up to 180°
angles at the base of an isosceles triangle are the same

left zinc Sep 17, 2020, 3:46 PM

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how to find x like this

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like whats the solving steps

silent plank Sep 17, 2020, 3:50 PM

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this is a matter of applying two things:

angles in a triangle add up to 180°

angles at the base of an isosceles triangle are the same

dark sparrow Sep 17, 2020, 3:50 PM

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^ that, and also i'm not a sir.

left zinc Sep 17, 2020, 3:51 PM

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sorry.

dark sparrow Sep 17, 2020, 3:52 PM

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just edit your message

left zinc Sep 17, 2020, 3:53 PM

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omg i cant do

silent plank Sep 17, 2020, 3:55 PM

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Q21: forget about the variables for a sec
can you determine the size of the base angles?

left zinc Sep 17, 2020, 3:55 PM

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uh 64?

silent plank Sep 17, 2020, 3:55 PM

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degress, yes

left zinc Sep 17, 2020, 3:56 PM

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👀

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OMG

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X = 11

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y = 11

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TYYYY

upper karma Sep 17, 2020, 4:24 PM

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@empty granite do you know the Pythagorean theorem?

empty granite Sep 17, 2020, 4:37 PM

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Obviously

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@upper karma

upper karma Sep 17, 2020, 4:37 PM

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Do you know how it’s applied?

empty granite Sep 17, 2020, 4:37 PM

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I've solved it now but its much harder than it looks

upper karma Sep 17, 2020, 4:38 PM

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Mhm well

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I would essentially just fill out enough data till there’s enough there to find the final length

pliant osprey Sep 17, 2020, 4:41 PM

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i really liked bjshnog's solution. is that how y'all did it?

mental vessel Sep 17, 2020, 7:11 PM

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📎 unknown.png

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i need help with this

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i know how to do the first part but b is where i get stuck

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its saying that the whole angle is 60 degrees

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but when i put it into a calculator it comes out to 66.4 degrees

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im just super confused

mental vessel Sep 17, 2020, 7:29 PM

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?

upper karma Sep 17, 2020, 7:55 PM

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It’s asking how far away the wire base attachment is from the base of the tower

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Just start fillin in data until you get what ya need

hollow raven Sep 17, 2020, 8:15 PM

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@mental vessel
a)
You know the angle of elevation of the first rope is 60 deg, and the hypotenuse (length of the rope) is 10.0 m

How can we determine the ground distance?

Well we see that the ground is adjacent to the angle of elevation.

Angle, Adjacent Side, hypotenuse, how are these all related. Hold on, remember trig ratios?

SOH CAH TOA -> CAH -> cos(angle) = adj/hyp

cos(60) = adjacent/10.0 m
adjacent = cos(60)x10
adjacent = 0.5x10
adjacent side = 5.0 m

b)
Ok, now we know the adjacent side value, and we know that the second rope length (hypotenuse), is = 8.0 m.

Ok, try to figure this one out. How would you solve this? 🤔

mental vessel Sep 17, 2020, 8:18 PM

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oh i got 4m

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instead of 5

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i used the 8 and cos60

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shouldnt it still be the same tho

hollow raven Sep 17, 2020, 8:18 PM

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Well that can't be right, cause the second rope doesnt look like it has the same angle as the first rope

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so you have to find the angle using trig ratios again

mental vessel Sep 17, 2020, 8:19 PM

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ill just show you my picture and you can pick it apart cause im pretty confused lol

hollow raven Sep 17, 2020, 8:20 PM

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Hold on

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lemme give u another hint

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we know cos(angle) = adj/hyp

mental vessel Sep 17, 2020, 8:20 PM

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yea

hollow raven Sep 17, 2020, 8:20 PM

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We need to find the angle, and we have the adjacent side 5.0 m and hypotenuse 8.0 m

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so plugging those values in..

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you get cos(angle) = 5.0/8.0

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how would you isolate the angle in this case?

mental vessel Sep 17, 2020, 8:22 PM

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ohhh

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yea okay

hollow raven Sep 17, 2020, 8:23 PM

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hopefully you get the point

mental vessel Sep 17, 2020, 8:23 PM

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i get how i got 4 instead of 5 because the inner angle isnt the same as the whole angle in the bigger triangle

hollow raven Sep 17, 2020, 8:23 PM

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right

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the only thing that is similar about them is that their ground distance from the pole is equivalent

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Which is why you can reuse the adjacent side length from question (a) onto question (b)

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the best part is we didn't even need to use the pole height in this scenario!

mental vessel Sep 17, 2020, 8:26 PM

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then you would subtract whatever 5/8 is off 60 to get the other angle right

hollow raven Sep 17, 2020, 8:26 PM

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nope, you just need to isolate the angle from cos(angle) = 5.0/8.0 to get the angle measure

mental vessel Sep 17, 2020, 8:26 PM

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oh

hollow raven Sep 17, 2020, 8:26 PM

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cause the second rope creates a triangle of its own

mental vessel Sep 17, 2020, 8:27 PM

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its asking for the triangle with the hypotenuse 8 right?

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angle

hollow raven Sep 17, 2020, 8:27 PM

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Yep

mental vessel Sep 17, 2020, 8:27 PM

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like its asking for the angle in the triangle with hypotenuse 8

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ohhh okay

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i thought it was asking for this anlge

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angle

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📎 unknown.png

hollow raven Sep 17, 2020, 8:28 PM

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Nope, just the angle of elevation, which is the angle from the ground to the second wire

mental vessel Sep 17, 2020, 8:28 PM

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ah okay

hollow raven Sep 17, 2020, 8:29 PM

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hopefully i helped lol

mental vessel Sep 17, 2020, 8:29 PM

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you did lol

hollow raven Sep 17, 2020, 8:29 PM

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but yeah for any similar problems try looking at what you have and taking advantage of those trig ratios

mental vessel Sep 17, 2020, 8:29 PM

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ill send my final product here in a lil bit to see if i did it correct cause this gets marked so haha

hollow raven Sep 17, 2020, 8:29 PM

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sure

mental vessel Sep 17, 2020, 8:29 PM

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yeah okay

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📎 image0.png

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@hollow raven

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did I do it

hollow raven Sep 17, 2020, 8:40 PM

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make sure to show step by step

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im not sure about c cause idk the question but b you got it

mental vessel Sep 17, 2020, 8:41 PM

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Oh yeah sorry lol

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📎 unknown.png

hollow raven Sep 17, 2020, 8:42 PM

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thats should be right

mental vessel Sep 17, 2020, 8:42 PM

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Okay cool

hollow raven Sep 17, 2020, 8:43 PM

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make sure to check over your work, cause you can't do a^2 + 5^2 = 8^2 then forget about a^2 in the next step

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and additionally
a = 2 + b
= a - b = 2
^ this is not needed

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but yeah u got the work down

mental vessel Sep 17, 2020, 8:44 PM

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ahh okay

bronze jewel Sep 17, 2020, 11:33 PM

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is anyone here good at geometry that can help me

next jackal Sep 17, 2020, 11:49 PM

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bruh there are a lot of people here, just ask your question here and wait, if there's no one answering even after 15 mins, then ping helpers

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like "@ helpers " without space

nova rune Sep 17, 2020, 11:50 PM

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how do i do this

📎 unknown.png

gaunt moon Sep 18, 2020, 12:05 AM

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<@&286206848099549185> Idk if they answered or not yet but here ya go^^^^^

oak citrus Sep 18, 2020, 12:28 AM

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@mental vessel bro get a tutor

upper karma Sep 18, 2020, 1:29 AM

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@hollow raven next time don't just give them the answer right off the bat

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but nice solution

hollow raven Sep 18, 2020, 1:30 AM

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oh yeah gotcha

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sort of new to the server ^_^

upper karma Sep 18, 2020, 1:32 AM

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no problemo broother

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next time just start with step A and see if he can make it logically to step B

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so on and so fourth until he understands the problem

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he/she that is

hollow raven Sep 18, 2020, 1:37 AM

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okay

upper karma Sep 18, 2020, 1:38 AM

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👍

upper karma Sep 18, 2020, 4:52 AM

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i wna do some geomegy problems lol

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geomegy looks cool

terse vine Sep 18, 2020, 10:51 AM

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📎 2020-09-18-125030_335x234_scrot.png

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How is $(4 sec^2(\theta) - 4)^{(3/2)}$ equal to $4tan^2(\theta)^{(3/2)}$

somber coyoteBOT Sep 18, 2020, 10:53 AM

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Xhendos:

📎 210784417482801152.png

terse vine Sep 18, 2020, 10:53 AM

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I know the trig identity $cos^2(\theta) + sin^2(\theta) = 1$

somber coyoteBOT Sep 18, 2020, 10:53 AM

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Xhendos:

📎 210784417482801152.png

terse vine Sep 18, 2020, 10:55 AM

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So $(4 sec^2(\theta) - 4)^{(3/2)} = 4(sec^2(\theta) - 1)^{(3/2)} = 4(\frac{1}{cos^2(\theta)} - 1)^(3/2) = 4(\frac{cos^2\theta + sin^2\theta}{cos^2\theta} - 1)^{3/2} = 4(tan^2\theta - 1)^{3/2}$

somber coyoteBOT Sep 18, 2020, 10:58 AM

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Xhendos:

📎 210784417482801152.png

terse vine Sep 18, 2020, 10:59 AM

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How did they get rid of the -1 after $tan^2\theta$?

somber coyoteBOT Sep 18, 2020, 10:59 AM

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Xhendos:

📎 210784417482801152.png

wind vector Sep 18, 2020, 11:02 AM

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take lcm with -1

upper karma Sep 18, 2020, 11:02 AM

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📎 unknown.png

wind vector Sep 18, 2020, 11:02 AM

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(1-cosx ^2)/cosx ^2

upper karma Sep 18, 2020, 11:02 AM

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I have no idea what process to take to solve this problem

wind vector Sep 18, 2020, 11:03 AM

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why is 1/pi an odd one out in here

upper karma Sep 18, 2020, 11:04 AM

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I don't know

wind vector Sep 18, 2020, 11:05 AM

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lmao what is this problem

upper karma Sep 18, 2020, 11:05 AM

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uni problem

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I mean I just don't know how to solve it 😦

wind vector Sep 18, 2020, 11:07 AM

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me too

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we in the same boat

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OH WAIT

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they cut out a circle from the slice

terse vine Sep 18, 2020, 11:13 AM

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I thought I've seen your problem on MindYourDecision his YouTube channel.
https://www.youtube.com/watch?v=9HH6D5oM9hc

YouTube

MindYourDecisions

A Super Hero's Solution To A Challenging Problem

High school geometry is the only super power you need to solve this puzzle!

Subscribe: https://www.youtube.com/user/MindYourDecisions?sub_confirmation=1

Send me suggestions by email (address in video). I consider all ideas though can't always reply!

Like many YouTubers I us...

▶ Play video

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But it's not exactly what solves your problem.

wind vector Sep 18, 2020, 11:13 AM

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this is almost it

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but the thing is that it is a part of a circle not a triangle

somber coyoteBOT Sep 18, 2020, 11:14 AM

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Xhendos:

📎 210784417482801152.png

wind vector Sep 18, 2020, 11:17 AM

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all i know is that it has pi/3 radians

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angle

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why do i feel like it is 1/pi

terse vine Sep 18, 2020, 11:17 AM

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Oh yeah you're right.

wind vector Sep 18, 2020, 11:18 AM

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for no particular reason at all

terse vine Sep 18, 2020, 11:20 AM

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Because it's about circles and the answer contains π in it? 🙃

wind vector Sep 18, 2020, 11:20 AM

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yes

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the area of the piece of slice is pir^2/6

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what about the circle inscribed

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the answer is either 1/3 or 1/pi

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imo

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can't solve it lol

upper karma Sep 18, 2020, 11:24 AM

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rip

wind vector Sep 18, 2020, 11:24 AM

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also who parent gives his son a cutout from the bigger slice

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like ewhat

upper karma Sep 18, 2020, 11:24 AM

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I mean I don't really want to know the answer

wind vector Sep 18, 2020, 11:24 AM

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you are fooling your son

upper karma Sep 18, 2020, 11:24 AM

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I want to know how to solve it

wind vector Sep 18, 2020, 11:24 AM

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idk how to solve it lmao

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i failed

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the area of that slice is (pi*r^2)/6

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so that's that

fresh jasper Sep 18, 2020, 12:39 PM

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I know the eqn of a hyperbola.

The curve of two variables which are inversely proportional is also a hyperbola.

How can i show that 2 variable inversely proportional have a hyperbola curve using the eqn x^2/a^2 - y^2/b^2 = 1?

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Please tag me while answering

next flower Sep 18, 2020, 1:00 PM

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hi could anyone help with a question im stuck on?

arctic vortex Sep 18, 2020, 1:04 PM

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i will try to help you

upper karma Sep 18, 2020, 1:04 PM

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Yes

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I have extensive knowledge of shapes

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Yep I know all the shapes

arctic vortex Sep 18, 2020, 1:05 PM

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me too

upper karma Sep 18, 2020, 1:05 PM

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Including yellow

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FeelsSpecialMan

arctic vortex Sep 18, 2020, 1:05 PM

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what

upper karma Sep 18, 2020, 1:05 PM

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Ok @next flower ask questions

silent plank Sep 18, 2020, 1:05 PM

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the only way to find out is to actually asked the math question

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asking to ask is pointless

arctic vortex Sep 18, 2020, 1:06 PM

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ramonov hwo do i get the honorable role

upper karma Sep 18, 2020, 1:06 PM

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by being honorable

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that’s how

next flower Sep 18, 2020, 1:06 PM

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Okay so I did this how I usually do set them equal to find x but why does it matter if it is 60 ft long (Ik this might not seem hard)

📎 image0.jpg

arctic vortex Sep 18, 2020, 1:06 PM

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how can i be honorable

upper karma Sep 18, 2020, 1:06 PM

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That’s like asking for people to watch while you take initiative

arctic vortex Sep 18, 2020, 1:06 PM

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being honorable?

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or asking to ask

upper karma Sep 18, 2020, 1:06 PM

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Ok so

silent plank Sep 18, 2020, 1:07 PM

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segment addition postulate

upper karma Sep 18, 2020, 1:07 PM

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yea that’s

arctic vortex Sep 18, 2020, 1:07 PM

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i have to go to my homeroom class now

upper karma Sep 18, 2020, 1:07 PM

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Yep

arctic vortex Sep 18, 2020, 1:07 PM

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its 9:00 am

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bye guys

upper karma Sep 18, 2020, 1:07 PM

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Ok

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Adios

next flower Sep 18, 2020, 1:07 PM

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i did 4x+3=2x+21 did all the math and got 12

upper karma Sep 18, 2020, 1:07 PM

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wrong

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They are not equal

silent plank Sep 18, 2020, 1:07 PM

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why are you setting them equal?

next flower Sep 18, 2020, 1:07 PM

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o

arctic vortex Sep 18, 2020, 1:07 PM

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i thoguht u had to add them

upper karma Sep 18, 2020, 1:07 PM

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bro

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Let him figure it out FeelsSpecialMan

arctic vortex Sep 18, 2020, 1:08 PM

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sorry my A+ in geometry overall is leaking

upper karma Sep 18, 2020, 1:08 PM

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mmmk

silent plank Sep 18, 2020, 1:08 PM

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the segments DO and OG form line DG, and you are told the length of that line

upper karma Sep 18, 2020, 1:08 PM

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Well given you know the length of the line and they ask you to find 2 segments of unequal length that make up the line

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what to do?

next flower Sep 18, 2020, 1:09 PM

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so i added them

upper karma Sep 18, 2020, 1:09 PM

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mhm and

arctic vortex Sep 18, 2020, 1:09 PM

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now i think its like algebra

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u have to do something

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but i cant asy it

upper karma Sep 18, 2020, 1:09 PM

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No dip Sherlock

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He has to breathe

next flower Sep 18, 2020, 1:09 PM

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6x+18

arctic vortex Sep 18, 2020, 1:09 PM

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he is breahing

upper karma Sep 18, 2020, 1:09 PM

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Ok

arctic vortex Sep 18, 2020, 1:09 PM

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===

upper karma Sep 18, 2020, 1:09 PM

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That’s the two added

silent plank Sep 18, 2020, 1:09 PM

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and the numerical value of that is:

arctic vortex Sep 18, 2020, 1:09 PM

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now u have to do something with 60

next flower Sep 18, 2020, 1:10 PM

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set that equal

arctic vortex Sep 18, 2020, 1:10 PM

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yeaaaa

upper karma Sep 18, 2020, 1:10 PM

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To what

arctic vortex Sep 18, 2020, 1:10 PM

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6x+10 ======= what

upper karma Sep 18, 2020, 1:10 PM

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+10

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Boi

arctic vortex Sep 18, 2020, 1:10 PM

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oh it was 8

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oops

next flower Sep 18, 2020, 1:10 PM

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6x+18=60

upper karma Sep 18, 2020, 1:10 PM

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Good

arctic vortex Sep 18, 2020, 1:10 PM

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yesss

upper karma Sep 18, 2020, 1:10 PM

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Now solve

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For x

arctic vortex Sep 18, 2020, 1:10 PM

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now what do u do

upper karma Sep 18, 2020, 1:10 PM

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I mean x

arctic vortex Sep 18, 2020, 1:11 PM

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i know what x is now

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its above 6 under 8

upper karma Sep 18, 2020, 1:11 PM

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Can you don’t

next flower Sep 18, 2020, 1:11 PM

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7

upper karma Sep 18, 2020, 1:11 PM

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Good

arctic vortex Sep 18, 2020, 1:11 PM

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yess good job

next flower Sep 18, 2020, 1:11 PM

#

nice

upper karma Sep 18, 2020, 1:11 PM

#

Now what’s the initial question?

next flower Sep 18, 2020, 1:11 PM

#

u guys are better than my teacher

#

find x

arctic vortex Sep 18, 2020, 1:11 PM

#

and x is

upper karma Sep 18, 2020, 1:11 PM

#

Oh nvm that is the question

#

Bababababam you found x good job

#

100%

next flower Sep 18, 2020, 1:11 PM

#

thanks

upper karma Sep 18, 2020, 1:12 PM

#

yep

#

Np

arctic vortex Sep 18, 2020, 1:12 PM

#

100% but u required assistance so 80%

next flower Sep 18, 2020, 1:12 PM

#

it still says it wrong tho idk maybe its the site

arctic vortex Sep 18, 2020, 1:12 PM

#

what

next flower Sep 18, 2020, 1:12 PM

#

it says its wrong]

upper karma Sep 18, 2020, 1:12 PM

#

6x + 18 = 60,
6x = 42
x = 7

arctic vortex Sep 18, 2020, 1:13 PM

#

what

next flower Sep 18, 2020, 1:13 PM

#

and i went to the next problem which is find og

#

and i got 35

upper karma Sep 18, 2020, 1:13 PM

#

Maybe it wants you to give just the number

#

Instead of the x =

next flower Sep 18, 2020, 1:13 PM

#

oh i did just do 7

upper karma Sep 18, 2020, 1:14 PM

#

Ok maybe do x = 7

next flower Sep 18, 2020, 1:14 PM

#

it must be the way it was inputed by the teachers way

upper karma Sep 18, 2020, 1:14 PM

#

thinkspin

next flower Sep 18, 2020, 1:14 PM

#

tried that to

upper karma Sep 18, 2020, 1:14 PM

#

Weird

next flower Sep 18, 2020, 1:14 PM

#

sadcat

arctic vortex Sep 18, 2020, 1:14 PM

#

what if we all are wrong

upper karma Sep 18, 2020, 1:14 PM

#

Well plug them into each segment

#

And tell me what they are

#

25 + 35 = 60

#

weird

arctic vortex Sep 18, 2020, 1:15 PM

#

yea

upper karma Sep 18, 2020, 1:15 PM

#

Eh just move onto the next one

silent plank Sep 18, 2020, 1:15 PM

#

just claim your marks from the work you show

next flower Sep 18, 2020, 1:15 PM

#

Also what could this be

📎 image0.jpg

arctic vortex Sep 18, 2020, 1:15 PM

#

ramonov how old are u

next flower Sep 18, 2020, 1:15 PM

#

Those are the only ones I’ve been stuck on

silent plank Sep 18, 2020, 1:15 PM

#

don't get hung up on crappy entry methods

arctic vortex Sep 18, 2020, 1:16 PM

#

equal

#

ab is equal to bc i think

#

because b is the mindpoint

#

so ab = bc

upper karma Sep 18, 2020, 1:16 PM

#

Y e p

arctic vortex Sep 18, 2020, 1:16 PM

#

yea

#

u all seem like people who graduated

#

everyone here is too smart

next flower Sep 18, 2020, 1:17 PM

#

oh

#

this website is pretty bad most of the time

#

it says thats wrong to

arctic vortex Sep 18, 2020, 1:17 PM

#

congruent

#

then

next flower Sep 18, 2020, 1:18 PM

#

yup

arctic vortex Sep 18, 2020, 1:18 PM

#

yea

next flower Sep 18, 2020, 1:18 PM

#

that was it

#

also my teacher sucks

arctic vortex Sep 18, 2020, 1:18 PM

#

mine too

next flower Sep 18, 2020, 1:18 PM

#

she dosent really teach me

#

just videos

arctic vortex Sep 18, 2020, 1:19 PM

#

nice

next flower Sep 18, 2020, 1:19 PM

#

no

#

bad

upper karma Sep 18, 2020, 1:50 PM

#

If i need to substract x+4 from 3x+2 would i do 3x+2-x+4 or 3x+2-x-4

#

PARENS

#

so second one

#

alr

round prism Sep 18, 2020, 3:33 PM

#

I need halllpppp pleaseee

#

Oh nvm

#

Actually I still need help

#

📎 20200918_113429.jpg

#

How would I do this?

#

Nvmmmm I just figured it out

next flower Sep 18, 2020, 4:05 PM

#

im confused on this any help?

📎 Capture.PNG

#

i got a little into it

#

got to 6x+11

#

now im stuck

silent plank Sep 18, 2020, 4:06 PM

#

howd you get that?

next flower Sep 18, 2020, 4:07 PM

#

4x+10+2x-1

silent plank Sep 18, 2020, 4:07 PM

#

does not give 6x+11

next flower Sep 18, 2020, 4:07 PM

#

o

#

lol

silent plank Sep 18, 2020, 4:07 PM

#

also what's that supposed to be for

next flower Sep 18, 2020, 4:07 PM

#

9

#

meaning?

silent plank Sep 18, 2020, 4:08 PM

#

6x-9 is :?

next flower Sep 18, 2020, 4:08 PM

#

um

#

well

#

thats what im confused on

silent plank Sep 18, 2020, 4:08 PM

#

why did you decide to add 4x+10 and 2x-1 together and how does that help you

next flower Sep 18, 2020, 4:08 PM

#

idk

#

thats why i need some help lol

obtuse tapir Sep 18, 2020, 4:08 PM

#

4x+10+2x-1=9x-15

silent plank Sep 18, 2020, 4:09 PM

#

adding them together gives you the length of the segment DF

next flower Sep 18, 2020, 4:09 PM

#

yes then do that

silent plank Sep 18, 2020, 4:09 PM

#

and you are also given the expression of in terms of x

#

and using that you have an equation

obtuse tapir Sep 18, 2020, 4:09 PM

#

the additions of all parts of a line gives the lenght of the whole tdboots

next flower Sep 18, 2020, 4:10 PM

#

okay so just do the way you said greg

silent plank Sep 18, 2020, 4:10 PM

#

solve for x, and hence determine the numerical value of DF = 9x-15

obtuse tapir Sep 18, 2020, 4:10 PM

#

x=-4/-3

next flower Sep 18, 2020, 4:10 PM

#

?

#

two numbers

obtuse tapir Sep 18, 2020, 4:11 PM

#

its a fraction

next flower Sep 18, 2020, 4:11 PM

#

o

silent plank Sep 18, 2020, 4:11 PM

#

its incorrect though

next flower Sep 18, 2020, 4:12 PM

#

i got x=8

#

?

silent plank Sep 18, 2020, 4:12 PM

#

yes

#

good

next flower Sep 18, 2020, 4:12 PM

#

then input

obtuse tapir Sep 18, 2020, 4:12 PM

#

oh wait

#

i didnt add the brackets in

next flower Sep 18, 2020, 4:13 PM

#

57?

obtuse tapir Sep 18, 2020, 4:13 PM

#

calc error

#

yep

silent plank Sep 18, 2020, 4:13 PM

#

yes

next flower Sep 18, 2020, 4:13 PM

#

yessss

#

thank you

arctic vortex Sep 18, 2020, 4:21 PM

#

📎 Screenshot_2020-09-18_121842.png

#

oh wrong chanel

pale cargo Sep 18, 2020, 9:30 PM

#

Hey wouldn't $cot^2(\theta) - sec^2(\theta) = 1$?

somber coyoteBOT Sep 18, 2020, 9:30 PM

#

Albot1288:

📎 194879088765173770.png

upper karma Sep 18, 2020, 9:33 PM

#

Why do you think so?

pale cargo Sep 18, 2020, 9:35 PM

#

Nvm It was csc - cot because of pythagorym identies

#

identities

lunar junco Sep 19, 2020, 3:28 AM

#

📎 trig.PNG

#

Can someone help me with this

#

Would the answer be 3/5

runic pasture Sep 19, 2020, 12:29 PM

#

what is sin a + sin b ?????

dark sparrow Sep 19, 2020, 12:38 PM

#

you can simplify that to 2 sin( (a+b)/2 ) cos( (a-b)/2 )

#

was that what you were looking for?

runic pasture Sep 19, 2020, 12:39 PM

#

yes probably i don't really know, is there a way to demonstrate it just so i know

dark sparrow Sep 19, 2020, 12:40 PM

#

...wait then what ARE you looking for

runic pasture Sep 19, 2020, 12:41 PM

#

my question is : complete the formula sin a + sin b = .........
i'm preparing myself for an oral exam, it would be cool if i knew where it came from

dark sparrow Sep 19, 2020, 12:42 PM

#

look up sum to product formulas

runic pasture Sep 19, 2020, 12:43 PM

#

ok thanks

vale nimbus Sep 19, 2020, 3:48 PM

#

📎 20200919_174822.jpg

#

i have to find the intersection point between the line DF and the plane AEGC

#

i thought i'd project F onto EG and D onto AC then connect the projected points in the plane AEGC (and then the interscept of that line with the dotted line between DF would be the intersection point)

#

sounds kinda sketchy + im not even too sure how i'd go about projecting

#

would the projection of F be done perpendicular to EG and the projection of D perpendicular to AC?

#

<@&286206848099549185>

#

either that or just connecting EC and the intersection between EC and the dotted EF line would be the intersection point

#

(these 2 ways end up giving me the same point but im still not sure weither or not this is correct + no correctoin key)

paper vale Sep 19, 2020, 4:05 PM

#

you are not giving us enough information

vale nimbus Sep 19, 2020, 4:05 PM

#

am i not?

#

its a cut off pyramid

#

thats about all im really told

paper vale Sep 19, 2020, 4:05 PM

#

what do u mean find intersection

vale nimbus Sep 19, 2020, 4:05 PM

#

just the point in which the line intersects with the plane

#

like passes through it

paper vale Sep 19, 2020, 4:05 PM

#

yea but what are the coordinates of these other points

vale nimbus Sep 19, 2020, 4:06 PM

#

no coordinates

#

its not analytical

paper vale Sep 19, 2020, 4:06 PM

#

but what do u mean find the point

vale nimbus Sep 19, 2020, 4:06 PM

#

draw it

#

like just mark it on the drawing where the point would be

#

poor choice of words on my end there, true

paper vale Sep 19, 2020, 4:07 PM

#

lol is that it?

vale nimbus Sep 19, 2020, 4:07 PM

#

yes 🙂

paper vale Sep 19, 2020, 4:07 PM

#

bruh

vale nimbus Sep 19, 2020, 4:07 PM

#

soo did i get it or not

#

i know its not a hard problem but as you can see im still confused

paper vale Sep 19, 2020, 4:07 PM

#

i mean this is a 3d image on a 2d picture

#

u cant just mark the point like that lol

vale nimbus Sep 19, 2020, 4:08 PM

#

yes you can

#

other problem but

📎 unknown.png

paper vale Sep 19, 2020, 4:09 PM

#

actually the only way you could do it if it was some special point for example u know the ratios like being the midpoint and then u can just get a ruler

vale nimbus Sep 19, 2020, 4:09 PM

#

Z is the the intersection point of PQ with the plane ADCB

paper vale Sep 19, 2020, 4:09 PM

#

u cant just project it or wtv u were saying

vale nimbus Sep 19, 2020, 4:09 PM

#

bro instead of get mad could you like help me? lmfao

paper vale Sep 19, 2020, 4:09 PM

#

bruh

vale nimbus Sep 19, 2020, 4:09 PM

#

to find the interscept of a line in a cube with the bottom plane of the cube u have to project

#

so yes you can do it with projecting

#

📎 unknown.png

#

point P's projection is point Z

#

to find the intersception point of PQ with the plane ADCB

#

man i just want help 😭

#

@paper vale so are you gonna help or just keep proving me wrong

supple onyx Sep 19, 2020, 4:12 PM

#

what's going on here?

vale nimbus Sep 19, 2020, 4:12 PM

#

https://discordapp.com/channels/268882317391429632/326138757474680852/756904626074288168

#

this message for the problem

#

can you help me?

paper vale Sep 19, 2020, 4:13 PM

#

the locus of points which satisfy this condition is a perpendicular line to centre of square at bottom

supple onyx Sep 19, 2020, 4:13 PM

#

as kane said, it does not seem as though there is enough information to do the problem

vale nimbus Sep 19, 2020, 4:13 PM

#

i was just told what kind of figure it is

#

thats it

paper vale Sep 19, 2020, 4:14 PM

#

so u know that it is gonna be directly above the centre of the bottom square pretty much

supple onyx Sep 19, 2020, 4:14 PM

#

rectangle*

#

it's not specified as a regular pyramid

paper vale Sep 19, 2020, 4:15 PM

#

yea i meant that

vale nimbus Sep 19, 2020, 4:15 PM

#

📎 20200919_181506.jpg

#

this is the point what i get with my projection shit

#

idk if u can see it too well lol

paper vale Sep 19, 2020, 4:15 PM

#

well find the midpoint of AC and draw vertical line

#

and its intersection with green is it

vale nimbus Sep 19, 2020, 4:16 PM

#

yeah its the same point

#

lol

#

projection 🐐

#

📎 20200919_181652.jpg

#

now i have to find the intersception point between the line PQ and the plane EFGH

supple onyx Sep 19, 2020, 4:17 PM

#

is this a cube?

vale nimbus Sep 19, 2020, 4:17 PM

#

so i thought i'd just project P and Q onto the plane and then connect those points, then connect PQ and the intersception of the projected points' connection line and PQ would be the intersception point

#

yeah

supple onyx Sep 19, 2020, 4:17 PM

#

or rectangular prism?

vale nimbus Sep 19, 2020, 4:17 PM

#

its actually not stated

supple onyx Sep 19, 2020, 4:17 PM

#

and how high above is P

vale nimbus Sep 19, 2020, 4:17 PM

#

so a cube i guess?

supple onyx Sep 19, 2020, 4:18 PM

#

these questions are pretty shit XD

vale nimbus Sep 19, 2020, 4:18 PM

#

not specified either

#

PES2_Shrug

#

now i have to find the intersception point between the line PQ and the plane EFGH
all thats said

supple onyx Sep 19, 2020, 4:18 PM

#

is Q a midpoint?

paper vale Sep 19, 2020, 4:18 PM

#

u cant work it out without knowing P's height

vale nimbus Sep 19, 2020, 4:18 PM

#

nope

supple onyx Sep 19, 2020, 4:18 PM

#

yeah exactly these questions are crap haha

vale nimbus Sep 19, 2020, 4:18 PM

#

u just have to draw it

#

not find cords or know anything

#

just draw it

supple onyx Sep 19, 2020, 4:18 PM

#

oh what

paper vale Sep 19, 2020, 4:18 PM

#

well then draw it lol

supple onyx Sep 19, 2020, 4:18 PM

#

then just kind of approximate with perspective

vale nimbus Sep 19, 2020, 4:18 PM

#

4Head

#

well it has to be accurate :/

supple onyx Sep 19, 2020, 4:19 PM

#

ruler from P to Q, and where it seems to be on EFGH by perspective

paper vale Sep 19, 2020, 4:19 PM

#

yea u can literally just draw it and it is there

vale nimbus Sep 19, 2020, 4:19 PM

#

but u have to find it accurately, not just guess

tribal wind Sep 19, 2020, 4:20 PM

#

draw a line 🙂

vale nimbus Sep 19, 2020, 4:21 PM

#

📎 20200919_182104.jpg

#

i think this is how its supposed to be done to find it accurately lol

tribal wind Sep 19, 2020, 4:21 PM

#

looks good

vale nimbus Sep 19, 2020, 4:22 PM

#

projection strat mocked yet again 😡

#

eh i hate these kinds of problems anyway

hollow raven Sep 19, 2020, 4:22 PM

#

do we assume cube side length is n?

tribal wind Sep 19, 2020, 4:22 PM

#

it's more fun when it's a game https://play.google.com/store/apps/details?id=com.hil_hk.xsection&hl=en_US

XSection - Apps on Google Play

Master different methods and solve puzzles.

More than 100 tasks: from basics to challenges
11 chapters to explore
Built-in glossary with geometric terms
Step-by-step instructions
Easy to use

XSection is a trainer of solid geometry problem solving. It teaches you ho...

hollow raven Sep 19, 2020, 4:22 PM

#

cross sections are very cool

paper vale Sep 19, 2020, 4:22 PM

#

do we assume cube side length is n?
@hollow raven lol he isnt finding interesction, he is literally locating it

vale nimbus Sep 19, 2020, 4:22 PM

#

i suck at cross sections

tribal wind Sep 19, 2020, 4:22 PM

#

nah you're supposed to do like straightedge compass manipulations like transporting parallel lines and w/e

vale nimbus Sep 19, 2020, 4:23 PM

#

kane seems mad that it isnt some big IQ question

#

pre-uni section bro calm down

paper vale Sep 19, 2020, 4:23 PM

#

realshit

hollow raven Sep 19, 2020, 4:23 PM

#

ok ok

#

that makes sense

vale nimbus Sep 19, 2020, 4:24 PM

#

welp so i got both of them? lol

wheat swan Sep 19, 2020, 7:16 PM

#

Can anyone help me get started on this?

📎 image0.jpg

paper vale Sep 19, 2020, 7:18 PM

#

you can use inverse tan to work out angles in two grey triangles

#

then subtract those from 90

fresh pike Sep 19, 2020, 7:47 PM

#

where did the added 1's come from in the left and middle masures

📎 unknown.png

#

in this one what is "borrowing" and why do you have to do it in the first place

#

📎 unknown.png

hollow river Sep 19, 2020, 9:38 PM

#

I'm taking geometry for 8th grade and a some others but I'm just wondering what algebra 1 skills I should brush up on

upper karma Sep 20, 2020, 2:01 AM

#

question

#

inverse trig (i.e. tan^-1) is just used to find an angle

#

@ me

wheat swan Sep 20, 2020, 3:59 AM

#

yeah i think so

#

thats what I used it for right now

#

@upper karma

#

@paper vale I did what you told me but I feel that I am wrong

#

<@&286206848099549185>

#

So I did the inverse of tan in the picture i sent earlier and I got approx. 4 for one and approx. 2 for the other one but that doesn't seem right to me

#

Would it just be 84?

#

https://discordapp.com/channels/268882317391429632/326138757474680852/756956796421144616

#

Thats the picture of it

harsh lintel Sep 20, 2020, 4:34 AM

#

The method should be right, not sure about the exact calcs cause I don’t have a calculator with me rn

#

It probably just seems weird cause the diagram isn’t to scale

wheat swan Sep 20, 2020, 4:35 AM

#

Ok thank you I appreciate it

harsh lintel Sep 20, 2020, 4:35 AM

#

Np

rocky rune Sep 20, 2020, 7:06 AM

#

How do you find angles with only one side with SOH CAH TOA

dark sparrow Sep 20, 2020, 7:12 AM

#

context?

#

one side alone is insufficient.

rocky rune Sep 20, 2020, 7:17 AM

#

Never mind wrong calculations

real star Sep 20, 2020, 9:23 AM

#

I need to find the value of x but I'm not sure where to start

📎 unknown.png

paper vale Sep 20, 2020, 9:25 AM

#

do u know parallel line rules

real star Sep 20, 2020, 9:25 AM

#

yes

paper vale Sep 20, 2020, 9:25 AM

#

so u can set up an equation to get x

real star Sep 20, 2020, 9:25 AM

#

dont they sum to 180?

paper vale Sep 20, 2020, 9:25 AM

#

yea

#

so do 180-(one of them)=other one

real star Sep 20, 2020, 9:26 AM

#

180-(x+60)

#

so 60-60 is 0

#

then 180-60 is 120

#

which leaves 120 and x

paper vale Sep 20, 2020, 9:27 AM

#

u have made a mistake

real star Sep 20, 2020, 9:27 AM

#

where

paper vale Sep 20, 2020, 9:28 AM

#

well first u didnt do what i suggested

#

oh wait ur still on step 1, i thought that u claimed u solved nvm

#

ok so continue

real star Sep 20, 2020, 9:30 AM

#

im confused

solid swan Sep 20, 2020, 9:30 AM

#

just set (x+60) + (3x+10) = 180

real star Sep 20, 2020, 9:39 AM

#

X would be 33 here right?

📎 unknown.png

#

Because what I did was used the alternate interior angle theorem to find out the top angle of the isosceles triangle was 114 then I did 180-114 and got left with 66 and the base angles of a isosceles triangle are the same so 66/2 is 33

silent plank Sep 20, 2020, 9:44 AM

#

alternate interior angle theorem
how exactly is that theorem relevant here

paper vale Sep 20, 2020, 9:45 AM

#

yea all u need for this is opposite angles are equal and trianlge sum is 180

real star Sep 20, 2020, 9:46 AM

#

how

silent plank Sep 20, 2020, 9:46 AM

#

can you state the alternate interior angle theorem in its entirety

#

*(also angle sum on a line is 180°)

paper vale Sep 20, 2020, 9:47 AM

#

ok so u know all the angles in the lower triangle

real star Sep 20, 2020, 9:47 AM

#

yes

paper vale Sep 20, 2020, 9:47 AM

#

therefore u know all angles in the triangle above it

real star Sep 20, 2020, 9:47 AM

#

57, 66 and and 57

#

therefore u know all angles in the triangle above it
@paper vale how though

paper vale Sep 20, 2020, 9:49 AM

#

do u know opposite angles thing

real star Sep 20, 2020, 9:49 AM

#

yes

paper vale Sep 20, 2020, 9:49 AM

#

well use that

real star Sep 20, 2020, 9:49 AM

#

but its a whole triangle

#

im confused on how to do it

silent plank Sep 20, 2020, 9:50 AM

#

don't see how it being a whole triangle makes a difference

#

determine what you know, write/mark it, and you have 1 less unknown to deal with

#

and then angle chase until you get what you want

paper vale Sep 20, 2020, 9:51 AM

#

if u dont understand it, u can just use lines sum to 180 twice but there is no point

silent plank Sep 20, 2020, 9:53 AM

#

which of a,b,c,d were you able to determine?

#

📎 unknown.png

real star Sep 20, 2020, 9:55 AM

#

a

#

a=57

#

and b=57 right?

silent plank Sep 20, 2020, 9:55 AM

#

yes

real star Sep 20, 2020, 9:55 AM

#

so 57+90=147

#

then 180-147=33

#

so c=33

#

and c and d are vertical angles so they are both 33

#

and 180-33=147

#

and base angles are the same so

#

147/2=x?

silent plank Sep 20, 2020, 9:57 AM

#

yes

real star Sep 20, 2020, 9:57 AM

#

so the reasoning is just vertical angles

#

and the sum of triangles are 180

silent plank Sep 20, 2020, 9:57 AM

#

pretty much

jade heath Sep 20, 2020, 11:31 AM

#

are there any unsolved/"open" problems in euclidean geometry ?

paper vale Sep 20, 2020, 11:41 AM

#

Lol obviously there is

upper karma Sep 20, 2020, 11:42 AM

#

https://en.wikipedia.org/wiki/List_of_unsolved_problems_in_mathematics#Euclidean_geometry

List of unsolved problems in mathematics

Since the Renaissance, every century has seen the solution of more mathematical problems than the century before, yet many mathematical problems, both major and minor, still remain unsolved. These unsolved problems occur in multiple domains, including physics, computer science...

jade heath Sep 20, 2020, 11:43 AM

#

nice thanks

paper vale Sep 20, 2020, 11:43 AM

#

It’s not that important but if u put < > around the link the big description thing doesn’t come up

upper karma Sep 20, 2020, 11:44 AM

#

how would it look like

paper vale Sep 20, 2020, 11:44 AM

#

It would just show the blue link

upper karma Sep 20, 2020, 11:44 AM

#

https://en.wikipedia.org/wiki/List_of_unsolved_problems_in_mathematics#Euclidean_geometry

#

I see thanks

paper vale Sep 20, 2020, 11:46 AM

#

But yea there are loads of open problems in every field, but not necessarily “important”

upper karma Sep 20, 2020, 6:09 PM

#

ahaah dont worry

quartz prism Sep 20, 2020, 6:10 PM

#

ok
see ya!

upper karma Sep 20, 2020, 6:10 PM

#

good day

dusty sleet Sep 20, 2020, 7:47 PM

#

hey

#

what does bgsin and Bgsin mean ?

paper vale Sep 20, 2020, 7:52 PM

#

lol are u dutch

#

idk dutch, but i searched it up and it sent me to dutch wikipedia, and on that it said inverse sin

dusty sleet Sep 20, 2020, 8:30 PM

#

so

#

yeah im dutch btw 🙂 but youre right

#

but im still wondering

#

is it just they give you for example

#

bgsin 1/2 and you will have to answer

#

pi/6 and 5pi/6

paper vale Sep 20, 2020, 8:34 PM

#

well if they want the interval to be [0,2pi] then yea

#

but obviously as sin is periodic adding any multiple of 2pi to those also gives 1/2

iron rain Sep 20, 2020, 8:35 PM

#

bgsin means boogsinus (arcsine)

paper vale Sep 20, 2020, 8:35 PM

#

does boog mean arc in dutch

iron rain Sep 20, 2020, 8:35 PM

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yeah

dusty sleet Sep 20, 2020, 8:36 PM

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ohh thanks 🙂

paper vale Sep 20, 2020, 8:38 PM

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also u would need to consider negative values differently, but yea easy to work out

unborn bison Sep 21, 2020, 1:08 AM

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📎 Screen_Shot_2020-09-20_at_9.03.52_PM.png

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what do they want me to do here by finding PQ to nearest tenth? distance?

versed river Sep 21, 2020, 3:55 AM

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i assume so

upper karma Sep 21, 2020, 3:56 AM

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@unborn bison yes they want you to find the distance. and the midpoint.

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of the line that connects them

blazing coyote Sep 21, 2020, 11:23 AM

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yo

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📎 Screen_Shot_2020-09-21_at_8.18.44_PM.png

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can anyone help with this ^

silent plank Sep 21, 2020, 11:27 AM

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where are you stuck

blazing coyote Sep 21, 2020, 11:28 AM

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I'm not rly sure what to do first

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im quite new to this concept haha

silent plank Sep 21, 2020, 11:29 AM

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whats the relation between angle 2 and 3

blazing coyote Sep 21, 2020, 11:29 AM

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vertical angles, right?

silent plank Sep 21, 2020, 11:30 AM

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yes

blazing coyote Sep 21, 2020, 11:30 AM

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ok

silent plank Sep 21, 2020, 11:32 AM

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you first two lines should look something like

somber coyoteBOT Sep 21, 2020, 11:32 AM

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ramonov:

📎 220517274845577216.png

blazing coyote Sep 21, 2020, 11:33 AM

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that makes sense thanks

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but, where exactly do I go from there? showing that K and N are parallel

silent plank Sep 21, 2020, 11:34 AM

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what does that tell you about angles 1 and 3

blazing coyote Sep 21, 2020, 11:34 AM

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corresponding angles?

silent plank Sep 21, 2020, 11:36 AM

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uh, they're corresponding angles regardless of whether they're equal in size or the lines are parallel
what specifically do those first two lines tell you about angles 1 and 3

blazing coyote Sep 21, 2020, 11:37 AM

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erm... that they're parallel lines cut by a transversal?? sry im quite bad at this

silent plank Sep 21, 2020, 11:37 AM

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ignore the diagram

blazing coyote Sep 21, 2020, 11:37 AM

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vertical lines are congurent, so they're equal???

silent plank Sep 21, 2020, 11:37 AM

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what do <1 = <2
and <2 = <3
tell you about <1 and <3

fast radish Sep 21, 2020, 11:37 AM

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Hello

blazing coyote Sep 21, 2020, 11:38 AM

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that they're congruent?

fast radish Sep 21, 2020, 11:38 AM

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How do you remember the graphs of all of the trigonometric functions

silent plank Sep 21, 2020, 11:38 AM

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yes

fast radish Sep 21, 2020, 11:38 AM

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Especially the csc sec and cot

silent plank Sep 21, 2020, 11:38 AM

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equal things are equal, and that would be an application of the transitive property

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$\angle1 \cong \angle3$ (transitive)

somber coyoteBOT Sep 21, 2020, 11:39 AM

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ramonov:

📎 220517274845577216.png

fast radish Sep 21, 2020, 11:39 AM

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Wha

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I do simple trig not this stuff

silent plank Sep 21, 2020, 11:39 AM

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would be the next line in your 2col proof

fast radish Sep 21, 2020, 11:39 AM

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What even is transitive

blazing coyote Sep 21, 2020, 11:39 AM

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thanks man

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that's it, that shows that the lines are parallel?

silent plank Sep 21, 2020, 11:40 AM

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you still need the conclusion

blazing coyote Sep 21, 2020, 11:41 AM

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ok

silent plank Sep 21, 2020, 11:41 AM

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k || n (converse of corresponding etc)

blazing coyote Sep 21, 2020, 11:41 AM

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So that concludes that these lines are parallel

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thank you Ramonov

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that concludes it?

silent plank Sep 21, 2020, 11:44 AM

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yes

blazing coyote Sep 21, 2020, 11:44 AM

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thank u

unborn bison Sep 21, 2020, 11:57 AM

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yeah midpoint was obvious, @upper karma, just didnt get distance

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ty 😛

runic leaf Sep 21, 2020, 12:42 PM

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Can I ask who are good in calculus can I add you in the other discord? We need a tutor :))

upper karma Sep 21, 2020, 12:45 PM

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I CAN'T FIGURE OUT THIS PUZZLE PLEASE HELP I AM GOING INSANE

📎 c833bbc84d766fd6.PNG

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Are they coincident circles?

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I am still trying to work out different arrangements of circles and see if I find an arrangement in which circles somehow coincide or something, but I can't fully grasp it

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A small hint will be great

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Np @unborn bison

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Perhaps something like this? Or maybe I am just overthinking and they are simply coincident circles

📎 431fc4582079412b.PNG

dark sparrow Sep 21, 2020, 12:53 PM

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@upper karma the answer is that at least one person in the room is drunk, high, or otherwise lying

upper karma Sep 21, 2020, 12:55 PM

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lol, but seriously how do you work out the solution? I found the problem in Chapter Zero of Mathematical Circles, it can't be something trivial like a kids riddle or brain teaser (~~or maybe it can?~~)

silent plank Sep 21, 2020, 1:07 PM

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it can't be something trivial like a kids riddle or brain teaser
yes it is

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its so bad

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hint: on a sheet of paper as opposed to drawing on a whiteboard

upper karma Sep 21, 2020, 1:13 PM

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thonkzoom

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hint: on a sheet of paper as opposed to drawing on a whiteboard
@silent plank AHA

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one can fold a sheet of paper

junior light Sep 21, 2020, 1:15 PM

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This problem is from Fomin, right?

upper karma Sep 21, 2020, 1:16 PM

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yes

junior light Sep 21, 2020, 1:16 PM

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Hmm, I didn't know the answer when I first read it but I learnt just now lol

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I didn't even exactly understand that elephant passing through a hole in the paper problem(Ig a solution could be to tear the paper apart, but that isn't exactly a hole)

silent plank Sep 21, 2020, 1:18 PM

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what elephant problem

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you don't even need to fold the paper

upper karma Sep 21, 2020, 1:19 PM

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ohk, I will work it out

slow void Sep 21, 2020, 2:50 PM

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can't seem to figure this one out

📎 5.JPG

vale nimbus Sep 21, 2020, 3:09 PM

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@slow void which one are you stuck on?

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tbf i dont really like how there arent exact values given for the points that touch the x-axis lol

surreal bolt Sep 21, 2020, 3:29 PM

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Er so is it cosine or sine?

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Then, what are A and C? (This deals with max, min y-values.)

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Finally what is k? (This deals with period.)

grim cairn Sep 21, 2020, 5:26 PM

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any idea of what to do here

📎 Capture.JPG

dark sparrow Sep 21, 2020, 5:29 PM

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think about what functions have what signs in what quadrants

grim cairn Sep 21, 2020, 5:34 PM

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where would you find sec on a unit circle

mental vessel Sep 21, 2020, 5:39 PM

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📎 unknown.png

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how can i find the angles and the side lengths with only 2 values given, shouldnt it be at least 3? im confused

dark sparrow Sep 21, 2020, 5:43 PM

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@grim cairn think about what sec is defined as

upper karma Sep 21, 2020, 5:43 PM

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@mental vessel this channel is occupied, proceed with a free one.

grim cairn Sep 21, 2020, 5:48 PM

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hypotenuse / adjacent

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@dark sparrow

dark sparrow Sep 21, 2020, 5:49 PM

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sec is 1/cos.

grim cairn Sep 21, 2020, 5:49 PM

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oops

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yeah u rite

dark sparrow Sep 21, 2020, 5:50 PM

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sec has the same sign as cos

mental vessel Sep 21, 2020, 6:34 PM

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https://media.discordapp.net/attachments/326138757474680852/757657232878862377/unknown.png?width=960&height=277

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how can i find the angles and the side lengths with only 2 values given, shouldnt it be at least 3? im confused

earnest echo Sep 21, 2020, 6:35 PM

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Clearly it's an isoceles triangle

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So if you know one angle you can find other two

paper mauve Sep 21, 2020, 6:43 PM

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just failed

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it's fine

upper karma Sep 21, 2020, 7:02 PM

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@paper mauve was it a test

paper mauve Sep 21, 2020, 7:02 PM

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no a quiz

upper karma Sep 21, 2020, 7:05 PM

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Asking help on tests is not allowed here

paper mauve Sep 21, 2020, 7:09 PM

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pikaWow

silent plank Sep 21, 2020, 7:11 PM

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whats the difference between a test and a quiz

upper karma Sep 21, 2020, 7:12 PM

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Not sure but does not look something that respects academic honesty

upper karma Sep 21, 2020, 7:49 PM

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whats the difference between a test and a quiz
Good question

tribal wind Sep 21, 2020, 7:51 PM

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quizzes are when the exam tries to make you fail

keen lantern Sep 21, 2020, 9:10 PM

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📎 unknown.png

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How do i show that ABD is isosceles?

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the only way i could think of is,

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if angle ABC, and ACB are x

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then BAD is 2x,

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and ABD is 90 - x

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making ADB 90 - x as well

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but i feel like there's a much quicker and logical answer

bitter jetty Sep 21, 2020, 10:03 PM

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📎 unknown.png

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can i get helpp with this

upper karma Sep 21, 2020, 11:16 PM

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but i feel like there's a much quicker and logical answer
@keen lantern I found a neat solution

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Just a moment

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Rather than straight away giving the answer, I would like to know what you have tried so far for this question

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Yes <BAD=2<x "<" here referring to "angle", and your other findings are also correct

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making ADB 90 - x as well
but you haven't proved this lol

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first you will need to prove that angle ABD=angle ADB

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The main thing you need to do here, is to somehow relate angle ABD and angle ADB to angle x

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||if you add both ABD and ADB you will get ext angle i.e. BAC, and BAC=180-2<x (angle sum property for triangle)||
||from here on you can substitute and eliminate to reach to the final conclusion that <ADB=<ABD||
||then you can use the property that sides opposite to equal angles in a triangle are equal||

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try working on it yourself by using the hints above

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I will send my sol. now

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📎 SPOILER_IMAG0069.jpg

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LP means linear pair and ASP means angle sum prop

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Ah I made a mistake, instead of LP it should be complementary angles

silk patio Sep 22, 2020, 12:15 AM

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Draw a circle centred at A containing B and C. Because of the property of right angles in a circle, CD is the diameter. Hence AB = CD/2
As well as AD = AB like you wanted
@keen lantern
@upper karma

lapis stratus Sep 22, 2020, 1:08 AM

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http://puu.sh/Gv79a/75ad26be9b.png
hey guys, so I got this answer up until ((sin(x))(1-cos^2(x)))/cos^2(x) . I dont get where the 1-cos^2(x) comes from. I know sin = cos^2 - 1, but I dont understand what happens to the other cos^2(x) instead. If anyone can help that would be greatly appreciated : D
edited
Oh Nvm I just GOT IT!
I can just take out of the sinx's and then change it to distributive form Sin(x) (1 - cos(x))

upper karma Sep 22, 2020, 1:09 AM

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@silk patio Yes this is better

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I haven't studied circles all that much yet so didn't think of that

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Thanks

gritty sail Sep 22, 2020, 2:41 AM

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ew webassign lol

upper karma Sep 22, 2020, 10:40 AM

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📎 mathhelpcf2.PNG

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Could anyone help me please, I don't really understand the question

deft cairn Sep 22, 2020, 10:46 AM

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5 of those equations will result in the graph on the right, one of them won't.

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Remember where cos and sin start as well as your graph transformations, and you should be able to figure it out 👍

upper karma Sep 22, 2020, 11:16 AM

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okay thank youuu

delicate apex Sep 22, 2020, 1:13 PM

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can anyone help

📎 unknown.png

tired terrace Sep 22, 2020, 2:44 PM

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@delicate apex do you still need help?

delicate apex Sep 22, 2020, 2:44 PM

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yes

tired terrace Sep 22, 2020, 2:45 PM

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Okay, so what its asking you to demonstrate a truth table with shading

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Have you heard of a truth table?

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(this also runs hand and hand with boolean algebra which you will probably look at later on)

upper karma Sep 22, 2020, 2:53 PM

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@delicate apex we ain’t gonna do this for you. What’s giving you trouble?

delicate apex Sep 22, 2020, 2:53 PM

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I dont understand any of it

upper karma Sep 22, 2020, 2:53 PM

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Is it homework?

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Or is it a quiz or something?

mighty wharf Sep 22, 2020, 2:55 PM

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sully

upper karma Sep 22, 2020, 3:01 PM

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anton

tired terrace Sep 22, 2020, 3:02 PM

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arrowbruh

upper karma Sep 22, 2020, 3:02 PM

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Cinnamónē

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FeelsSpecialMan

tired terrace Sep 22, 2020, 3:03 PM

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why am i smooth brain

upper karma Sep 22, 2020, 3:03 PM

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ThonkTriangle

mighty wharf Sep 22, 2020, 3:03 PM

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pepethonk

upper karma Sep 22, 2020, 3:03 PM

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fast_parrot

tired terrace Sep 22, 2020, 3:03 PM

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hyperthonk

upper karma Sep 22, 2020, 3:03 PM

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akko_lewd

mighty wharf Sep 22, 2020, 3:03 PM

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Pi_thonk

upper karma Sep 22, 2020, 3:03 PM

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realshit

tired terrace Sep 22, 2020, 3:03 PM

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thonkstein

mighty wharf Sep 22, 2020, 3:03 PM

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HyperUltraThonks

upper karma Sep 22, 2020, 3:04 PM

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P 👀

mighty wharf Sep 22, 2020, 3:04 PM

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We should prolly stop

upper karma Sep 22, 2020, 3:04 PM

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Pfft

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Seriously though

tired terrace Sep 22, 2020, 3:04 PM

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ya

upper karma Sep 22, 2020, 3:04 PM

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It is not nice to leave the chat after answering a question

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Er

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Asking one

tired terrace Sep 22, 2020, 3:04 PM

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right wasnt there a question?

mighty wharf Sep 22, 2020, 3:04 PM

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No reply

upper karma Sep 22, 2020, 3:05 PM

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There was at one point but I think he expects us to do it for him... either that or he just needed to go

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And image is messy cuz of that ‘exit’ thing

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Anyways

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Why is this in geo-trig?

mighty wharf Sep 22, 2020, 3:06 PM

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CH_topkek

junior light Sep 22, 2020, 3:07 PM

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Why is this in geo-trig?
Apparently some people think Venn Diagrams are about circles and rectangles.

ashen rain Sep 22, 2020, 4:27 PM

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Lmao

vale lintel Sep 22, 2020, 5:16 PM

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||tbbt||

nocturne thicket Sep 22, 2020, 5:21 PM

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📎 unknown.png

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am i stupid

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this is just 60 right

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or am i just dumb

earnest echo Sep 22, 2020, 5:25 PM

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No, it's not 60

nocturne thicket Sep 22, 2020, 5:25 PM

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OH its 30

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@earnest echo right?

earnest echo Sep 22, 2020, 5:25 PM

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Yeah

nocturne thicket Sep 22, 2020, 5:25 PM

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ah i see

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i was like wtf theres no way its that simple

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📎 unknown.png

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im guessing i got this one wrong too?

earnest echo Sep 22, 2020, 5:29 PM

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Looks alright to me

nocturne thicket Sep 22, 2020, 5:29 PM

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alright ty

#

i just did 14.9*6

earnest echo Sep 22, 2020, 5:30 PM

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👍

upper karma Sep 22, 2020, 5:36 PM

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📎 unknown.png

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could someone explain this section to me?

📎 unknown.png

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like i legitimately dont understand wtf just happened

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why does the cosine rule have that many numbers on it ;v;

mighty wharf Sep 22, 2020, 5:37 PM

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Do you know the cosine formula

upper karma Sep 22, 2020, 5:37 PM

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yes i know

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but wouldnt it just be

mighty wharf Sep 22, 2020, 5:38 PM

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a²=b²+c²-2bc CosA

upper karma Sep 22, 2020, 5:38 PM

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if theyre doing cosine c it would just be (50/71) would it not ;v; why was there all square routes doe

#

O H

#

I THOUGHT

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IT WAS

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omg

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i am braindead

mighty wharf Sep 22, 2020, 5:39 PM

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no lol

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not that cos rule

upper karma Sep 22, 2020, 5:39 PM

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thank u ;v;

mighty wharf Sep 22, 2020, 5:39 PM

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no problem

upper karma Sep 22, 2020, 5:39 PM

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right um could you elaborate a bit further on why it's a fraction doe ;v;

mighty wharf Sep 22, 2020, 5:40 PM

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just solve everything in the bracket

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then find the cos inverse

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arccos

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,calc 50^2+71^2-50^2

somber coyoteBOT Sep 22, 2020, 5:40 PM

#

Result:

mighty wharf Sep 22, 2020, 5:41 PM

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,calc 25071

somber coyoteBOT Sep 22, 2020, 5:41 PM

#

Result:

upper karma Sep 22, 2020, 5:41 PM

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im really confused on why they used those numbers though ;v;

#

like

#

i thought the formula was

mighty wharf Sep 22, 2020, 5:41 PM

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,calc 5041/7100

somber coyoteBOT Sep 22, 2020, 5:41 PM

#

Result:

0.71

upper karma Sep 22, 2020, 5:41 PM

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📎 unknown.png

mighty wharf Sep 22, 2020, 5:41 PM

#

so arccos of 0.71 gives you your C°

#

nooo

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I mean yeah

upper karma Sep 22, 2020, 5:42 PM

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like why they b didin

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dividin

#

📎 unknown.png

#

sorry im like

#

pea brain

mighty wharf Sep 22, 2020, 5:42 PM

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but that's the same thing as $c²=a²+b²-2abcosC$

somber coyoteBOT Sep 22, 2020, 5:42 PM

#

raelo:

📎 573945657510068234.png

mighty wharf Sep 22, 2020, 5:42 PM

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let me explain

#

you know the rule is $c²=a²+b²-2abcosC$

somber coyoteBOT Sep 22, 2020, 5:43 PM

#

raelo:

📎 573945657510068234.png

mighty wharf Sep 22, 2020, 5:43 PM

#

but in this case

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you have c²

upper karma Sep 22, 2020, 5:43 PM

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right

mighty wharf Sep 22, 2020, 5:43 PM

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and you don't have cosC

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so you want to surrogate them

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so you can find your cosC

paper vale Sep 22, 2020, 5:44 PM

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it is trivial

upper karma Sep 22, 2020, 5:44 PM

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so you wanna replace the c2 w the cosC

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thats why the equation changed?

mighty wharf Sep 22, 2020, 5:44 PM

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yes

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so you divide both sides

upper karma Sep 22, 2020, 5:44 PM

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aH

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tHATS HW

#

i'm legitimately pea brained

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thank you sm

mighty wharf Sep 22, 2020, 5:45 PM

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do you get it though

upper karma Sep 22, 2020, 5:45 PM

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yes

mighty wharf Sep 22, 2020, 5:45 PM

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divide both sides by -2bcCosC

upper karma Sep 22, 2020, 5:45 PM

#

they were using that equation but just modifying it so it could be cosC = right

#

mhm

#

also um do you mind if i send a friend req so i can ask more pea brained questions sometimes pls ;v;

mighty wharf Sep 22, 2020, 5:46 PM

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no problem

#

but I'm going somewhere rn

#

you can always ask anyone though, maybe they even can explain better

upper karma Sep 22, 2020, 5:46 PM

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ah yea thats fine

paper vale Sep 22, 2020, 5:46 PM

#

the best thing to do is to try and work it out yourself

upper karma Sep 22, 2020, 5:46 PM

#

thank you so much for the clear explanation though

#

ah okay

#

will do c: thank you for your help

mighty wharf Sep 22, 2020, 5:47 PM

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np

upper karma Sep 22, 2020, 5:49 PM

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i just found this

#

📎 unknown.png

#

holy shit i AM pea brained

mighty wharf Sep 22, 2020, 5:49 PM

#

You were supposed to be taught that before given that kind of question

upper karma Sep 22, 2020, 5:50 PM

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unfortunately my math teacher is a terrible communicator

#

we're given assignments before class ;v;

#

im doing ibd and hahhah im fucked probs

mighty wharf Sep 22, 2020, 5:51 PM

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Bye for now.

upper karma Sep 22, 2020, 5:53 PM

#

cya o:

#

📎 unknown.png

#

um how do i write this on a tinspire

#

;v;

#

i tried nsolve but it wouldn't work

paper vale Sep 22, 2020, 6:07 PM

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try clicking the correct buttons