geometry-and-trigonometry

[livid moss]

That's what it is.

[tidal river]

could I get help with these 2 questions

[earnest echo]

For first one
You've got a point, all you need to make a line is slope, the hint for slope is given as well

Find the slope of required line and write the equation

[upper karma]

Remember $m\cdot m_{\perp}=-1$

[somber coyote]

Al𝟛dium:

[upper karma]

@tidal river

[tidal river]

what

I dont understand

[earnest echo]

What is that you don't understand?

[tidal river]

how would I make the slope with a point

[earnest echo]

You need to get the slope using the information provided in form of it's perpendicular line

[tidal river]

So how would I do that

[earnest echo]

Al𝟛dium:
@somber coyote this is how

[tidal river]

Could you tell me the answer

I don't understand how to do it

plz

[earnest echo]

We don't tell answers here

[tidal river]

isnt there an equation I can plug it into

[earnest echo]

Are you taking a test?

[tidal river]

Its the summer

I dont have tests

[earnest echo]

Then learn how to do it

What's the slope of the given line?

Can you find that?

[fossil kestrel]

@upper karma https://en.m.wikipedia.org/wiki/Analytic_geometry

it was a simple question, books on this subject definitely exist so i was just looking for a good one

[earnest echo]

Try SL Loney

[fossil kestrel]

https://link.springer.com/book/10.1007/978-3-319-78361-1

Try SL Loney
@earnest echo will check that out

[upper karma]

isnt there an equation I can plug it into
@tidal river do you read what we say?

@fossil kestrel yes this is literally linear algebra lol

@fossil kestrel

Vectors and Coordinate Systems
Giovanni Landi, Alessandro Zampini
Pages 1-16

first chapter of that book

rofl

argue with me some more pls

and then link a book that agrees with me

[fossil kestrel]

im not arguing

[upper karma]

i said vectors

4 times?

then you get linked a book

and the first fucking chapter is called vectors

[fossil kestrel]

i just wanted a book with coordinate or analytic geometry on the title

[upper karma]

i honestly don't know what to say.

THE FIRST CHAPTER IS CALLED VECTORS

which is WHAT I TOLD YOU 4 TIMES?

[fossil kestrel]

it does say linear algebra and analytic geometry

[upper karma]

SO???

i told you vectors

the first time you asked

multiple times

[fossil kestrel]

calm down poly lol

[upper karma]

no i am so fucking annoyed people telling me that "no this is not the case"

and then they link a book

which agrees with everything i said

and you still can't admit i am right

[fossil kestrel]

https://www.amazon.com/Analytic-Geometry-Charles-H-Lehmann/dp/0471524379

that is one of the main books

im not saying it has nothing to do with linear alg or vectors

[paper vale]

obviously if it is analytic geometry it will be somewhat related to linear algebra

[fossil kestrel]

its certainly related

[upper karma]

@fossil kestrel you picked a fucking book from 1942 with no table of contents.

find the table of contents for that book.

[fossil kestrel]

dude i dont need to do anything

i just told you thats one of the classic reference books

[upper karma]

yeah you do, you picked some book THAT NOBODY HAS EVER USED in the history of the world

no it's not

[paper vale]

why would u read an outdated book

[upper karma]

i've literally never heard of it

what do you mean "classic"

rudin is classic

spivak is classic

[paper vale]

when there are loads available

[upper karma]

axler is (maybe) classic

not fucking "charles h lehmann"

[fossil kestrel]

that is the reference book that people in a lot of south American countries use

i know there are newer books

[paper vale]

like if ur gonna read a whole textbook at least make sure it is a good one

[fossil kestrel]

but the concepts are the same

[upper karma]

you know a book is shit because nobody buys it and therefore there is no preview for it

hence you can't look at the table of contents

[fossil kestrel]

its not the only version

[upper karma]

just admit you're wrong and that my first suggestion was the one you were looking for please.

[fossil kestrel]

What i am wrong about? are you saying analytic geometry doesnt exist?

[paper vale]

bruh

[upper karma]

no i'm saying that my suggestions of vectors in R^2 was the one you were looking for.

[paper vale]

just let him be wrong man

[fossil kestrel]

i understand i could find equations relating to curves on the Cartesian plane on linear algebra books

[upper karma]

lol

i'm done

[paper vale]

if he wants spend a lot of time reading a worse book when loads of better one are accessible then he can

[fossil kestrel]

i didnt say i wanted to read that one

i was looking for recs remember

[upper karma]

yes, and i gave you one

then you found a book with "analytic geometry" in the name

which has the first chapter on exactly what i recommended

then instead of saying thanks for recommending that from the start

you argued

[fossil kestrel]

thanks for the recommendation

but why do people call it analytic geometry then

or coordinate geometry

[upper karma]

nobody calls it that, maybe in middle school where they introduce you to the cartesian plane

[paper vale]

analytic geometry isnt only cartesian geometry

[upper karma]

"here's how you plot y = x"

[fossil kestrel]

people do call it that, i have other books on "coordinate geometry"

is it just a sub part of linear algebra

[upper karma]

what you are referring to is R^2 in linear algebra.

that is

2 dimensions in the real number plane

@fossil kestrel you do realize linear algebra is a very big field

R^2/R^3 is what you learn about in middle school and high school

you even learn about it in university

then later on you learn about abstract vector spaces.

[fossil kestrel]

yeah i mean im a beginner honestly didnt mean to piss you haha

here at uni we have a subject called analytic geometry

and we deal with equations of lines and curves such as parabolas

someone mentioned midpoint between 2 points and also distance between 2 points

[upper karma]

parabolas are not linear algebra

distance between and midpoint of 2 points definitely is

what do you do with parabolas

[fossil kestrel]

equations that express parabolas

and hiperbolas

the conics

[upper karma]

but what do you do with them

[fossil kestrel]

let me check

I have to go to my computer 1 sec

for example

19. the center of a hiperbola is the point (2;-2) and one of its vertices is the point (0,-2). If the length of its right side (translating from spanish dont know the word for this) is 8, find the equation of the hiperbola, the length of its conjugate axis (also not sure about this) and its excentricty

[upper karma]

you learn this in algebra.

like, school algebra.

[fossil kestrel]

maybe we just call it different

[upper karma]

why are you telling people what they learn?

@upper karma what do you mean

[fossil kestrel]

in highschool we dont call it analytic geometry i think

[upper karma]

you learn this in a intermediate algebra book

[paper vale]

umm he is just stating things which are taught at a certain level

[upper karma]

that has conic sections

the section on this is called exactly that: "conic sections"

,w conic section

isn't it kind of obvious that the education system this person is in isn't the same as yours?

in highschool we dont call it analytic geometry i think
@fossil kestrel trust me, im Spanish and i have seen Analytic geometry problems

[paper vale]

conic sections are probably done in high scool

also wtf is that spam

[upper karma]

@upper karma he asked for suggestions

[fossil kestrel]

im from Paraguay

so

[upper karma]

any american/english/european book will cover this as "conic sections"

[fossil kestrel]

i dont know

[upper karma]

in an intermediate algebra book

maybe precalculus

[fossil kestrel]

well ill get some linear algebra books too and read up on that

im doing the entrance exams for engineering here and we have algebra, analytic geometry, arithmetic and trigonometry

[upper karma]

sounds like what you are really looking for is a precalculus book

that also has linear algebra in R^2 in it

sure but like, your being pretty vehement over... things that arose from a different education system and naming conventions?

they usually cover trig, lin alg in R^2, and conic sections

[gray mason]

Nah, get a proper linalg book.

I honestly don't understand why the course precalculus exists.

It's broken on so many levels.

[upper karma]

i do

students don't know trigonometry

it's basically there to teach trigonometry

[gray mason]

Then, yk, remove cyclic geometry and teach trigonometry.

[upper karma]

wtf is cyclic geometry

[gray mason]

Circle theorems and stuff.

[upper karma]

lol

nobody really learns that tbh

they may learn it at one point

but it's usually way before trig

[gray mason]

Replace that with trigonometry.

[upper karma]

and it's never in depth

[fossil kestrel]

so a precalc book would cover trig, this r^2 stuff, basic algebra and arithmetic?

[upper karma]

no

[gray mason]

A 3-week unit being spread into an entire course's worth of content.

[upper karma]

you need to know "arithmetic"

[gray mason]

"arithmetic" is literally grades 1-8.

[upper karma]

a good precalc book will cover linear algebra in R^2, conic sections, trigonometry and complex numbers

i would say

[gray mason]

all the stuff without variables, basically.

[fossil kestrel]

if any of you can read spanish

i can show you the program

[gray mason]

I mean, how many people actually remember the content from precalc?

[upper karma]

i do

(replying to andrew)

[gray mason]

Well, I'm about to say, not including yourself.

[upper karma]

i learnt a lot of nice identities in precalc

that a lot of people in calc 2 don't know about

because they just don't know trig

[gray mason]

Could it be introduced elsewhere?

[stone adder]

I think @upper karma can read Spanish @fossil kestrel

[upper karma]

i think precalc is good if done properly

Yes i do

[fossil kestrel]

its kind of overwhelming to deal with all these math subjects

[gray mason]

I'm a fan of integrated maths, aka algebra and geometry in each course.

[upper karma]

What can i help on

[fossil kestrel]

i havent done math since high school (8 years ago)

[upper karma]

@fossil kestrel you should try khanacademy.org

[fossil kestrel]

yeah i do go there sometimes

i prefer books

[upper karma]

https://www.khanacademy.org/

[fossil kestrel]

https://discordapp.com/channels/268882317391429632/326138757474680852/740692949041414174 heres what i have to learn at uni, the program, so im kinda looking for a book that covers everything

[upper karma]

if you go from "arithmetic" to "linear algebra", there probably isn't a (good) book that does that

[gray mason]

^

[upper karma]

you would need multiple books, probably 2-3

[fossil kestrel]

maybe exclude arithmetic

thats the easiest subject we have

its mainly just conversion and water tank problems and stuff like that

https://www.cimat.mx/ciencia_para_jovenes/bachillerato/libros/Zill-Dewar/[Zill,Dewar]Algebra_trigonometria_y_geometria_analitica.pdf im using this book now

im a book hoarder

i was just asking out of curiosity

[upper karma]

so i wasted my time

good to know

[fossil kestrel]

how much time did you really waste lol

[upper karma]

none, he enjoyed every second of this

botn, can you stop writing nonsense

prank

memes

relax

chill

[fossil kestrel]

honestly chill

[upper karma]

did I get it right

[stone adder]

No @upper karma lol

[upper karma]

Wait

@abhi

[stone adder]

#bots message

Anyway Qetsyqetsy have you tried using Paul's notes?

[upper karma]

close enough

[stone adder]

It's not a book but I think you can use that

[fossil kestrel]

im sorry whos paul?

so many messages

[stone adder]

https://tutorial.math.lamar.edu/

[upper karma]

Paul's notes are good

[fossil kestrel]

oh ok

this looks nice thanks

https://www.fiuni.edu.py/290-2/ on the first semester were supposed to have something called mathematical analysis?

i think that has something to do with calculus

[upper karma]

don't let polynomial see this

[stone adder]

Can you translate the sylabus?

[fossil kestrel]

i can try

1st semester: mathematical analysis i, physics i, technical communication i, system architecture, intro to programming

[upper karma]

Análisis Matemático is probably not what we call "analysis" in english

[stone adder]

and afaik, Mathematical Analysis is something you would call as Advanced Calculus, which the topics that are discussed there is basically Calculus but more rigorous

[fossil kestrel]

2nd: math analysis ii, physics ii, tech communication ii, discrete mathematics, intro to programming ii

[stone adder]

Not quite sure tho, since as Botn stated, it might be different as what it's usually called in English

and I'm afraid this might be kinda off-topic to be discussed here

[fossil kestrel]

oh yeah sorry

[stone adder]

Maybe we can continue in #math-discussion instead

[upper karma]

it's a first semester engineering syllabus so I doubt it's analysis

@fossil kestrel analysis 1: https://notendur.hi.is/vae11/Þekking/principles_of_mathematical_analysis_walter_rudin.pdf

@fossil kestrel analysis 2: https://59clc.files.wordpress.com/2011/01/real-and-complex-analysis.pdf

but it depends on what it means by analysis

[fossil kestrel]

yeah im not sure either

[azure reef]

@fossil kestrel for analysis i highly reccomend zorich

it can be used as analysis book

and as calculus book as well

(but for the second one you will need additional material)

[austere dragon]

is diagonal reflections more advanced than horizontal/vertical reflections?

things start to get suddenly complicated here

[brisk palm]

It's just as easy. If you're reflecting over y = x, exchange the x and y coordinates

(1, 2) would become (2, 1)

[austere dragon]

what

[dark sparrow]

depends on what you mean by diagonal

do you mean specifically the lines that make 45° angles with the axes? yeah that's not hard to do from a computational pov

[brisk palm]

If you mean perfectly diagonally then you just have to flip the x and ys as i said, but other than that is more difficult

[austere dragon]

theres no explanation whyyy

[brisk palm]

oh i see

[austere dragon]

why flip that isnt logical!!!!!

[brisk palm]

There are a couple of ways to do it

[austere dragon]

no i mean how does that work?? why flip the coordinates

[brisk palm]

give me one sec

Can you get on vc or no?

[dark sparrow]

@austere dragon would it help if i made you an interactive desmos thing for why flipping the coords reflects over the line y=x?

[austere dragon]

what is desmos

also sry im on pc no mic

and am not english not english very well

[brisk palm]

It's a tool that helps you visualize mathematics

[austere dragon]

ow

[brisk palm]

It's a graphing calculator with extra things to help you learn

[dark sparrow]

https://www.desmos.com/calculator/ahb5qfr5bd

here, you can drag the red point $(x_0, y_0)$ and desmos will automatically drag the green point $(y_0, x_0)$ along with it

[somber coyote]

Ann:

[austere dragon]

alrighty

[brisk palm]

For the line y = -x, it's slightly different. The point $(x_0, y_0)$ becomes $(-y_0, -x_0)$

[somber coyote]

Jack Papel:

[austere dragon]

how do you even read this equation?

why is "y = x" equals 0 intercept and 1 slope? what?

[earnest echo]

Can you graph y=x

[dark sparrow]

why is "y = x" equals 0 intercept and 1 slope? what?

y = 1x + 0

does that make it clearer

[earnest echo]

Analytically that +c part is the intercept
In y=x you don't have, therefore for no intercept

[dark sparrow]

@earnest echo no intercept ≠ intercept at 0

please don't conflate "zero" with "none"

[earnest echo]

Okay, I should have worded better

[austere dragon]

what about "y = -2" how do we know theres no slope??

[dark sparrow]

y = 0x + (-2)

it's not "no slope" it's zero slope

[austere dragon]

🤯 awsome

[dark sparrow]

i LITERALLY just told off godfather for conflating "none" with "zero"

like

[austere dragon]

waaaaa dont hurt me

so if theres x then slope but if no x 0 slope

yes??

[dark sparrow]

if it's "y = constant" then that's a slope of zero yes

[austere dragon]

what would 2 slope look like

wait lemme check out that website

[dark sparrow]

what would it look like

[austere dragon]

wait how many slope for a perfect vertical??

[dark sparrow]

"how many slope"

[austere dragon]

perfect horizontal is 0

[dark sparrow]

anyway

vertical lines do not have a slope

[austere dragon]

oh yeah

wait but why is 1 slope equal perfect diagonal??

that just doesnt make any sense at all

shouldnt the input be some kind of angle

[earnest echo]

What do you think slope is?

[austere dragon]

uhh rotating line idk

[dark sparrow]

no.

slope = Δy/Δx

or to put it another way, for a line connecting two points $(x_1, y_1)$ and $(x_2, y_2)$ the slope is given by $$m = \frac{y_2 - y_1}{x_2 - x_1}$$

[somber coyote]

Ann:

[austere dragon]

yeah i think ill wait for high school geometry

[upper karma]

how?

i don't understand this identity?

[azure reef]

should be sin(6t) if i am not missing something

,w cos2tsin4t+sin2tcos4t == sin2t

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Commander Vimes#7532

[brisk palm]

I think so too

[azure reef]

@upper karma

[brisk palm]

Perhaps somewhere else on the paper it says that the two are equal?

Or it could be a typo

[azure reef]

[upper karma]

6t

yes

thanks

the book's answer seems wrong

[upper karma]

@austere dragon I understand you’re having trouble with some maths, if you want, I can give you some one-on-one to give you a jump in school.

[next fable]

i'm somewhat confused

vertical angles are congruent, so a = a but how does 180 degrees come into play?

[dark sparrow]

180° is the angle made by two rays that are part of the same line

[next fable]

ray 1 is angle x and ray 2 is angle a

?

[dark sparrow]

no

rays aren't angles, they're rays

[next fable]

hmm

what are the rays?

[dark sparrow]

the halves this line is split into by the point

[next fable]

the center point?

so that line "f" is split into 2 rays "j" and "k"

and together k and j make 180 degrees

so how does it correlate to angles x and a

[dark sparrow]

the angle between the rays you call k and j is 180 degrees

this 180-degree angle is made of three parts

x, a, and 90°, in that order starting from the bottom ray

[next fable]

i see

so

what you're saying is

the only thing that's stopping line "f" from being 180 degrees are those 3 angles

x, a and 90

[dark sparrow]

??

wym stopping

nobody's stopping anyone from anything

[next fable]

oh lol

[next fable]

it's 180 degrees because they're all on the same line?

sorta like a protractor?

the shape of it atleast

[dark sparrow]

it's 180 degrees because it's half of a full turn

it's 180 degrees because this is literally what a 180 degree angle is almost by defn

[next fable]

right

but the line itself is 180 degrees, each angle has it's own measurement

that all add up to 180 degrees

right?

[sour jacinth]

What's the issue here?

[dark sparrow]

you're overthinking this, leak

[paper vale]

try and think about what an angle actually is

and how a degree is defined

[next fable]

what i'm getting here is that

all angles on the line

add up to 180 degrees?

[livid moss]

Yes

All angles on one side of the line

[little osprey]

A straight

line

Wait does it matter if I mention straight

[next fable]

aren't all lines straight in geometry

[paper vale]

yes

[little osprey]

What if I say curved line

[earnest echo]

Higher geometry?

[paper vale]

that isnt mathematically consistent

in euclidean geometry

it is like mixing everyday usage with mathematical definitions

[earnest echo]

Well, in pre University section
You don't really need this much confusion

Just keep it simple

[little osprey]

Oh ye true

[upper karma]

Youchers

[summer spire]

a "curved line" is just a curve

[simple quest]

Looks right unless you got number 4 wrong I didn't compute

[tidal river]

what

what do you mean by unless you got number 4 wrong

@summer spire could you see if I got this problem right

[gusty swan]

Mentally exhausted so forgive me. But, why is one divided and one multiplied?

[sour jacinth]

Mentally exhausted so forgive me. But, why is one divided and one multiplied?
@gusty swan Cosine is defined as $$\frac{adj. leg}{hyp}$$

[somber coyote]

Max Hetfield:

[sour jacinth]

In the first triangle, you have the angle, the adjacent leg but the hypotenuse is unknown

So you got $$cos(25) = \frac{12}{u}$$

So you multiply by u both sides, and then divide by cos(25) both sides; that way you solve for u

In the second triangle, you have the angle, the hypotenuse, but the adjacent leg is unknown

So you got $$cos(35) = \frac{a}{22.5}$$

[gusty swan]

ah okay that makes more sense now

dont know why I struggle with these functions so much

thank you

[sour jacinth]

So you got $$cos(35\degree) = \frac{a}{22.5}$$
@sour jacinth Then multiply both sides by 22.5 to solve for a

[somber coyote]

Max Hetfield:

Max Hetfield:

[sour jacinth]

thank you
@gusty swan You're welcome

Just remember the corresponding sides that define a trigonometric function and you will be okay

And rest, mental fatigue is a thing...

[gusty swan]

@sour jacinth 3 more units and 27 days to finish it

[sour jacinth]

Well, but that's different

I meant work in time blocks

If you're tired today, call it a day and continue tomorrow with a fresh mind

[shell halo]

i need help with my homework..

[clear depot]

if its similar the sides have the same length proportion

[shell halo]

do i need to find the scale factor?

and then determine x, y and z

[sour jacinth]

Yes

[shell halo]

how would i find the scale factor?

i remember there is a formula for it i think

[sour jacinth]

You don't need a formula for that

Just using your logic will do

Do you want me to guide you?

[dark sparrow]

you need to know what "the perimeter of XYZ is 27 cm"

[shell halo]

yes please

[dark sparrow]

ie what the perimeter of a triangle is

[clear depot]

first get the total perimeter of the small triangle

[dark sparrow]

and be able to write out that the sum of XYZ's side lengths is equal to 27 cm, as an equation

[sour jacinth]

@shell halo What's a perimeter?

[shell halo]

a perimeter is when you add all the sides together

[sour jacinth]

So triangle XYZ's perimeter is X + Y +Z

Agree?

[shell halo]

yep

[sour jacinth]

The problem states that X + Y + Z = 27, right?

[shell halo]

yes

[sour jacinth]

OK,

Then what's the perimeter of ABC

[shell halo]

18

[sour jacinth]

Now, hold there. What characteristic do similar triangles have?

Hint: Something about their sides...

[shell halo]

similar triangles have identical shape but different size

[sour jacinth]

similar triangles have identical shape but different size
@shell halo Yeah

So basically, when you divide the length of the corresponding side they all have the same ratio

For example is ABC is a triangle, XYZ is a triangle twice the size of ABC

If you divide X/A, you will get 2

Y/B = 2

Z/C = 2

[shell halo]

ok, im trying to understand//

[sour jacinth]

It's like you took all the sides of ABC and enlarged them by the same factor

ok, im trying to understand//
@shell halo If you don't at any step, just tell me

If you divide X/A, you will get 2
@sour jacinth Does this make sense for you?

[shell halo]

no, how did u get 2??

[sour jacinth]

no, how did u get 2??
@shell halo It's just an example

[shell halo]

ohHH

alright..

[sour jacinth]

What I want you to get is that simmilar triangles are scaled versions

[shell halo]

yes i undertand that

[sour jacinth]

OK, now let's go to the final part

If the perimeter A+B+C = 18

And let's suppose that triangle XYZ is twice the size of triangle ABC

Is it true that X + Y + Z can be rewritten as 2A + 2B + 2C?

[shell halo]

i think it can be because its twice the size of triangle ABC

[sour jacinth]

Exactly

[shell halo]

2 times A

yep

[sour jacinth]

Let's factorize 2A + 2B +2C

We get 2 (A+B+C)

[shell halo]

yep

[sour jacinth]

Now, do you remember what's the definition of perimeter?

[shell halo]

yep i do

perimeter is kind of like the distance around the shape and to calculate it, you add up all the sides of the shape

[sour jacinth]

2 (A+B+C) = 2 (ABC Perimeter) = 2 (18) = 36

Then XYZ perimeter in our example would be 36

You with me?

[shell halo]

yes sorry, i needed to do something quickly

im back

[upper karma]

yes i am, do you want me to solve it

[sour jacinth]

yes sorry, i needed to do something quickly
@shell halo OK, so notice something

In our example (XYZ Perimeter)/(ABC Perimeter) = 36/18 = 2

[shell halo]

yep

[sour jacinth]

It has the same scale as the sides

So the ratio between the perimeters (XYZ/ABC = 2) will be the same as the ratio of the corresponding sides (X/A = Y/B = Z/C = 2)

Agree?

[shell halo]

yep

[sour jacinth]

So, back to the problem to finally solve it

The thing in your problem is that we don't know the ratio

But we do know the perimeters

[shell halo]

yep

[sour jacinth]

So using the perimeters, can you get me the ratio between the 2 triangles?

[shell halo]

36:18

am i right?

[sour jacinth]

am i right?
@shell halo No, but only because you're using the data from my example

Get the perimeters from your problem

What's the perimeter of XYZ in your problem?

[shell halo]

27

[sour jacinth]

What's the perimeter of ABC in your problem?

[shell halo]

27:18

[sour jacinth]

Yes!

Let's simplify 27/18 a bit

Divide numerator and denominator by 9

By 9 even better

[shell halo]

3

sorry

wait

3/2

[sour jacinth]

Relax, I'll wait

3/2
@shell halo So we know that (Perimeter XYZ)/(Perimeter ABC) = 3/2

Right?

[shell halo]

so its 3/2

when we simplify it

yep

[sour jacinth]

So the ratio between the perimeters (XYZ/ABC) will be the same as the ratio of the corresponding sides (X/A = Y/B = Z/C)
Now, remember this?

[shell halo]

yep

i remember

[sour jacinth]

So this means that each side of XYZ is equal to scale each side of ABC by a factor of 3/2

[shell halo]

okay

[sour jacinth]

So if AB = 6

What's the corresponding side in the triangle XYZ?

[shell halo]

XY=z

[sour jacinth]

Then z = 6 * (3/2)

[shell halo]

ill brb

ok im back

6 x 3/2 = 9

so XY=9

??

[sour jacinth]

A sec

[shell halo]

alrighty

[sour jacinth]

Back

so XY=9
@shell halo Yes

And you can do the same for the other sides

Get me x for example

[shell halo]

XY=9

XZ=12

YZ=6

[sour jacinth]

Final check:

Add those sides

[shell halo]

and we can check if we are correct by adding them and see if they add up 27

[sour jacinth]

and we can check if we are correct by adding them and see if they add up 27
@shell halo I really like this person

Told you that you didn't need a formula

[shell halo]

12+9+6 = 27

YAY!

@shell halo I really like this person
@sour jacinth aww :))

[sour jacinth]

All you have to remember is that similar triangles have a fixed ratio between their corresponding sides

[shell halo]

yep!

thank you so so so much!

[sour jacinth]

You're welcome! Take care!

[shell halo]

i have no idea what i would do without your help

you too!

[finite vigil]

Hey

I need help with something

Can I send the problem?

[earnest echo]

[finite vigil]

Oh shit

wrong pics

[earnest echo]

<@&268886789983436800>

[finite vigil]

snitch

SNITCCCHHH

Fuck u fucking nerd

shove ur glasses up oyo ass

i bet u moan

when u

[earnest echo]

There are kids on this server

[finite vigil]

wipe

yo

ass

Fuck them kids man

ey

[twin heron]

what

[finite vigil]

u moan when u wipe ur ass?

[earnest echo]

The guy is sending nudes

[finite vigil]

godfather tf

I'M A GUY

LMFAO

BRUHHH

Assuming my gender

[twin heron]

...

[finite vigil]

<@&268886789983436800>

This man

is assuming my gender

I take quite offense to this

[earnest echo]

I don't care who you are
This a server where there a lot of kids and such stuff is inappropriate

[finite vigil]

I'm very offended

[earnest echo]

Idgaf

[clear depot]

What did he sent lmao

[next jackal]

Bruh....

Keep this room for questions

Want to shitpost, go to #chill

[earnest echo]

That was beyond shit post

[next jackal]

@finite vigil remove your messages please

The inappropriate ones

[azure reef]

that was not math video man

[brisk palm]

Ok

[azure reef]

so delete it since it is not about math

[dark sparrow]

done

[silent plank]

which one?

there are multiple images of problems

[brisk palm]

Aight

[silent plank]

that literally linked me to an image search of "hard math problems"

[brisk palm]

that literally linked me to an image search of "hard math problems"
@silent plank he got your ip through the link

[shell halo]

you cant do much with an ip

[brisk palm]

But like idk what he'd do with it anyway yeah

[shell halo]

what can u?

[brisk palm]

Oh are you gonna call John Xbox and get his acc banned

[shell halo]

hahaha

[brisk palm]

I guess you can ddos if you wanna but like I don't see why you would

No real reason

[silent plank]

so are you actually serious about needing help with a problem?

[azure reef]

he left

[brisk palm]

Lmao obviously not

[azure reef]

i highly suspect that it was some kind of fishing

[brisk palm]

No it wasn't phishing

He just got his ip

He never had to put a password in

[azure reef]

what for then

also, interesting that grabify itself was not able to expand that url

[brisk palm]

Wdym

<@&268886789983436800> Glizzy Gobblers tries to get people's IPs. that seems against the rules

[azure reef]

he is already out of server

[cosmic pebble]

From

#❓how-to-get-help

Rule 1

The help channels are solely for help with math, so feel free to post your question. Asking whether you can ask a question or if anyone knows about some specific topic is unnecessary, so please try to avoid questions of that nature.

[twin heron]

banned him too, not alright to do that

[clear depot]

Sure ask

[dark sparrow]

what circle thing

can we see the entire problem?

[clear depot]

[dark sparrow]

so that it's easier to help you knowing the whole context yknow

[azure reef]

i just looked above in the logs

hmmmm

<@&268886789983436800>

[livid moss]

Woah

[silent plank]

I'm not inclided to click that

[stone adder]

[weary drift]

[earnest echo]

I'm pretty hannah is alt of that guy who got banned

[clear depot]

Whos raiding lmao

[twin heron]

where did they go?

[weary drift]

[twin heron]

spooky

[livid moss]

So we don't get to do a circle problem? :(

[azure reef]

but what he gets by just knowing some ips lol

[clear depot]

I really wanted to know about the circle thing

[dark sparrow]

uh

[azure reef]

[weary drift]

the txt was their dm logs

[dark sparrow]

oh ok

[azure reef]

the txt was their dm logs
?

ll

can you send screens in cybertopia

[earnest echo]

Luna do you still want a circle problem?

I've got one

[livid moss]

Yes

@earnest echo

[earnest echo]

@livid moss

[livid moss]

Yo, no this is hard. I just wanted to like work out a radius from a circumference, man

[earnest echo]

C'mon you are all knowing problem solver

[livid moss]

Do you know the answer?

[earnest echo]

Yeah, I've solved it

Though I have one unsolved problem as well

I'll post it later after giving some thought

[livid moss]

@earnest echo Am I bad at math if I got none of those?

[earnest echo]

None of what?

[livid moss]

The given answers lol

[earnest echo]

These are actually challenging problems, it's from entrance of one the premier institutes in India

So, no that doesn't make you bad

[sinful stag]

Alittle guidance

[azure reef]

what exactly confuses you

[upper karma]

is this an exam

[sinful stag]

Nah

[upper karma]

screenshot the full page

[sinful stag]

Is an assignment

[azure reef]

@sinful stag what confuses you?

[sinful stag]

I can’t understand what the equation represent , like an elipptic or circle or hyperbola

[azure reef]

well. what will be if a and b are both 1?

[sinful stag]

I found this

[azure reef]

yes

so and a and b actually do not matter

[sinful stag]

So the curve can never pass through origin

[supple onyx]

They simply scale in x and y directions (sort of)

[sinful stag]

And normal is constantly changing like that

[azure reef]

if curwe would pass through origin

it means that 0-0 =1

[sinful stag]

True

But we can’t determine x and y like that

[azure reef]

well we can by that show that in does not pass through origin

ok so it is hyperbola

[earnest echo]

But why are we discussing origin?

[azure reef]

i just pointed out it, it is not really crucial here

[sinful stag]

Agree

Normal to curve is constantly changing at all other points , we can’t determine the x and y intercept with the given info imo

[earnest echo]

You can..........first start by figuring out what's the equation of the normal at the given point

[supple onyx]

Youll have it in terms of x,a and b

[arctic vortex]

can anyone help me with some questons

[upper karma]

Sure

[cosmic pebble]

From

#❓how-to-get-help

Rule 1

The help channels are solely for help with math, so feel free to post your question. Asking whether you can ask a question or if anyone knows about some specific topic is unnecessary, so please try to avoid questions of that nature.

[little osprey]

@arctic vortex

[arctic vortex]

oh

sorry

is tihs correct

[little osprey]

They look parallel

so yes

[arctic vortex]

what about his one?

[upper karma]

Somebody already posted these

Was it you?

[arctic vortex]

what was their name

because i change my name like every week it might be me

[upper karma]

what about his one?
Correct

[arctic vortex]

yesss

is this one correct?

[little osprey]

Are these for a test

[arctic vortex]

nope it is homework

[upper karma]

This is literally 2 ratios

[arctic vortex]

my final test is tomorrow

[little osprey]

Yes its correct

[arctic vortex]

yay

[upper karma]

I think you can do it alone

[arctic vortex]

ok

if i do not know the answer can i ping u?

[little osprey]

Sure

Hobo and me B)

[arctic vortex]

okay yay thanks

wait

there is 1 proof question

can u check it

[little osprey]

achew

Ok

Itw wrong

[arctic vortex]

o

which is worng?

[little osprey]

The reasoning of why its congruent

You have 2 sides congruent

so how could it be ASA

@arctic vortex

[arctic vortex]

o

sas

@little osprey

?

is it sas

[little osprey]

Hello

@upper karma Is it Hobo, Sas?

[arctic vortex]

is it sas then

side angle side

[little osprey]

Goddamit hobo, I wanted to do a funny

[arctic vortex]

what

so it is sas?

[little osprey]

Is there any other thing in your options saying side, angle and side

[arctic vortex]

angle angle side

and hypotensue leg

?

@little osprey

@upper karma

[little osprey]

Yes its SAS

wait

wiat

ait

[upper karma]

What are you talking about

[little osprey]

YES HOBO IS HERE

You should check out my stupid pun

[arctic vortex]

wha

t

[upper karma]

@little osprey where

[little osprey]

Oh you did a kek

Anyways

Its hypotenuse side

its not SAS

[arctic vortex]

whats this

[little osprey]

We dont give answers

[arctic vortex]

o

how to oslve tihs

[little osprey]

Hint though

Any line that is not on line t

is on a line that is parallel to t

[pastel anvil]

its parallel to that line right

also u have that point

so u can find the equaton for the parallel line passing through P

[arctic vortex]

i found 0, -4

[upper karma]

show work

[little osprey]

Did you find anymore

[upper karma]

[little osprey]

wait no

I uh

hahhahaha ignore me

I didnt read the question fully

[upper karma]

‘Select 1 or more’ usually indicates a multiple-answer question

[little osprey]

Yes

[arctic vortex]

let me check it

[upper karma]

Essentially all they need to do is find a line u that satisfies the following conditions
-parallel to t
-passes through point P

[arctic vortex]

the closest i can find is -4,-3

[little osprey]

use point gradient form

I think thats what its called

[upper karma]

@arctic vortex walk me through how you solved it.

That way I can better understand what you’re doing and if it’s wrong / how I can help.

[arctic vortex]

i found more

so i found the slope

of the line

2/1

then i just went 2 up

and 1 left

and i foud more

see

\

[upper karma]

The slope is not +2

[pastel anvil]

true

[arctic vortex]

1.2

1/2

i meant

1 up

2 left

[upper karma]

left is positive or negative?

[pastel anvil]

i think its negative since its moving down

[arctic vortex]

left is negative

[upper karma]

man let him figure it out

[pastel anvil]

figure what out

[upper karma]

Why the line is negative

Don’t just shout the why let them figure it out please

[arctic vortex]

because its going like \

[upper karma]

Yes

[arctic vortex]

like this \

[upper karma]

That’s an indicator that the line is negative

[arctic vortex]

OH I FOUND 1 MORE

8,-8

[upper karma]

If it descends from left to right then it is in fact a negative slope.

[arctic vortex]

yes

[upper karma]

What is the equation of your new line?

The one that is parallel

[arctic vortex]

what does that mean

[upper karma]

What is the equation of the parallel line that intersects point P

[pastel anvil]

like y=mx+b

[upper karma]

yes

Like that

[pastel anvil]

which is linear equation

[upper karma]

yes it is

My strategy would be to find the line and then input some points... process of elimination on the answer choices.

[arctic vortex]

1 up 2 left

the slope is 1/-2

[upper karma]

That is the slope not the equation

[arctic vortex]

y=1/-2x

[upper karma]

nope

[arctic vortex]

i dont know it

sorry

[pastel anvil]

u have to put the constant bit at the end

[upper karma]

Well think about it, what is the equation with the same slope as the first line but intersecting a lower point?

[arctic vortex]

y=1/-2x-6

[upper karma]

now check your work.

[arctic vortex]

ok

it looks correct ome

[upper karma]

The point p is a point (4, -6)

[pastel anvil]

r u sure

[upper karma]

When you plug in 4, do you get -6? @arctic vortex

[arctic vortex]

plug 4 in what

[upper karma]

With this new equation

[arctic vortex]

oh

no

[upper karma]

so then

is it still correct?

[arctic vortex]

no

[upper karma]

Good

[arctic vortex]

o

[upper karma]

So now try again.m

[arctic vortex]

ok

[upper karma]

You have the right slope, so now just find the right constant term.

[arctic vortex]

okh

[upper karma]

The new equation needs to be able to put out -6 when you put in 4.

And it has to have the same slope as the first line.

So, where do you start?

[pastel anvil]

what

[upper karma]

[pastel anvil]

😩

[upper karma]

was that somehow confusing

[pastel anvil]

yea

[upper karma]

In other words:

The new line has to satisfy the following:

-must have same slope to t
-must pass through point P

P:(4,-6)

The slope of the first line is -1/2

[pastel anvil]

yeah

[upper karma]

Better?

[pastel anvil]

so use point slope formula ez

[upper karma]

Sure

That works.

[arctic vortex]

hi guys im back

[upper karma]

Another way is to start with the slope and plug in 4, then solve for the constant term c given the output and input of the line.

(-6 = (-1/2)(4) + c.)

hello

Make any progress?

[arctic vortex]

i had to pee

[upper karma]

ok

Well

[pastel anvil]

fascinating

[upper karma]

😆

[arctic vortex]

i found the equation

y=1/-2x+1

[upper karma]

Did you now? That’s good.

Uhh

[pastel anvil]

its good except for the constant term

[arctic vortex]

is the constant term the B

[upper karma]

(For future reference it is -x/2 not -1/2x)

Yes

[pastel anvil]

yeah its b

[arctic vortex]

ohhhhh

[upper karma]

just plug in the point for x and y and solve for b.

Or use point slope like seagull suggested

[arctic vortex]

-4

[pastel anvil]

ya

[arctic vortex]

y=-x/2-4

[pastel anvil]

ya thats right

[arctic vortex]

yay

[dry glen]

Can anyone help me with this question?

[arctic vortex]

is that sector area

[dry glen]

I think so

[arctic vortex]

i think i can help u

[pastel anvil]

split it into 2 parts right

[arctic vortex]

oh nvm i do not know this

[dry glen]

wait what

[arctic vortex]

sorry

[upper karma]

Interesting question

[dry glen]

@upper karma ikr

[pastel anvil]

so the entire shaded part is made up of 1 segment of big circle and 1 segment of small circle

then its ez pz since u know area of segment

[dry glen]

correct

wait what?

how

I know the angle but I don't know how to take that into account

[pastel anvil]

damn

[dry glen]

the pixels

[upper karma]

Resolution died there

[dry glen]

xD

[pastel anvil]

its the area of the sector minus the area of the triangle inside

[dry glen]

mhm

what about the bigger circle

[upper karma]

Well it is two overlapping segments

[dry glen]

they overlap so

[pastel anvil]

what

ok 1 minute brb

[dry glen]

help meeeeeee

[pastel anvil]

dont worry bro

ok so

[upper karma]

This little line helps me a bunch

[pastel anvil]

yea

[dry glen]

I think it helps me too

[pastel anvil]

exactly

u have the 2 sectors rite

[dry glen]

mhm

[pastel anvil]

ah jesus

is this legible

[dry glen]

I totally get that

yes

alpha and theta

[pastel anvil]

lets start with the circle with 2r radius

[dry glen]

mhm

[pastel anvil]

area of a segment is equals to A = 1/2 ( theta - sin(theta)) r^2

[upper karma]

The segment on that circle is actually the smaller segment.

[pastel anvil]

θ

yea ik

[dry glen]

(2r)^2 * (a/360) - 2rsin(a)

[upper karma]

ok. Just clearing the confusion. You guys got this, I gotta go lol.

Cya later.

[pastel anvil]

ok cya bro

[dry glen]

cya broski

[pastel anvil]

ohhhh

[upper karma]

👌👋

[pastel anvil]

right

α

[dry glen]

(2r)^2 * (a/360) - 2rsin(a)

[pastel anvil]

i understand

[dry glen]

This is the area of the sector, right?

[little osprey]

lol