#geometry-and-trigonometry | Mathematics | Page 296

upper karma Jul 14, 2020, 9:16 AM

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Thank you so much 🙂

wraith drum Jul 14, 2020, 11:31 AM

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I have a question:
Let S be a triangle on a co-ordinate grid with vertices (x_1,y_1),(x_2,y_2),(x_3,y_3) , and Q=(x_q,y_q) be a point inside the triangle. Let R=(x_r,y_q) be a point on triangle S such that x_r is maximum, let P=(x_p,y_p) be a point anywhere on the triangle, and let "theta" be the angle PQR, and the length of the line segment PQ be "d", if the function f(x) is defined such that d=f(theta), then what is this function?

twin prawn Jul 14, 2020, 12:08 PM

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The way this question is phrased seems to suggest that there's an easy formula for the function, but I'm under the impression that might not be the case after drawing a sketch

wraith drum Jul 14, 2020, 12:17 PM

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it's okay

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i worked on this for 6-7 hours now

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i want to cry

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https://www.desmos.com/calculator/bukr2zhy17

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that is all i could do

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i managed to work out point R

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and the black bit at the top is the "d" value for the bit b/w P2 and the purple point

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which is point R

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that is correct

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AA theorem is a valid answer

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OMN=RPQ, and MON=PRQ

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angles

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so they are similar

silent plank Jul 14, 2020, 12:29 PM

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2 pairs of corresponding angles will be equal

arctic vortex Jul 14, 2020, 12:46 PM

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how much square feet do you need for a chicken

dark sparrow Jul 14, 2020, 12:57 PM

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thonk wat

arctic vortex Jul 14, 2020, 1:04 PM

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nvm i figured it out

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im confsued on what #2 is telling me

📎 Annotation_2020-07-14_090414.png

dark sparrow Jul 14, 2020, 1:07 PM

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so your animal is a chicken?

arctic vortex Jul 14, 2020, 1:07 PM

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no i changed it to a horse

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but i dont understand what #2 is telling me

dark sparrow Jul 14, 2020, 1:08 PM

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how many horses are you building your enclosure for?

arctic vortex Jul 14, 2020, 1:09 PM

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1

dark sparrow Jul 14, 2020, 1:10 PM

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okay, so you need an area of 4500 ft^2

arctic vortex Jul 14, 2020, 1:10 PM

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20250000 ft

upper karma Jul 14, 2020, 1:11 PM

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not really

dark sparrow Jul 14, 2020, 1:12 PM

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no

upper karma Jul 14, 2020, 1:12 PM

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it's not (4500 ft)^2 but 4500 (ft)^2

dark sparrow Jul 14, 2020, 1:12 PM

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i did not say (4500 ft)^2 and even that AREA would not be equal to a DISTANCE of twenty million feet and change.

arctic vortex Jul 14, 2020, 1:12 PM

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oh

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418 meters

dark sparrow Jul 14, 2020, 1:13 PM

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no what the fuck

arctic vortex Jul 14, 2020, 1:13 PM

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418.1

dark sparrow Jul 14, 2020, 1:13 PM

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do you not understand the distance between length and area

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feet vs square feet

arctic vortex Jul 14, 2020, 1:13 PM

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yes

upper karma Jul 14, 2020, 1:13 PM

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it's the radius of the earth

dark sparrow Jul 14, 2020, 1:13 PM

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yes as in "yes i do not understand the difference"?

arctic vortex Jul 14, 2020, 1:14 PM

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no yes i do understand the difference

dark sparrow Jul 14, 2020, 1:14 PM

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anyway, #2 is asking you to sketch three rectangles which don't have the same dimensions but which each have an area of 4500 square feet

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and to calculate the perimeter for each one

arctic vortex Jul 14, 2020, 1:14 PM

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ohh

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ok

dark sparrow Jul 14, 2020, 1:14 PM

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the dimensions can be anything you want so long as the area is right

arctic vortex Jul 14, 2020, 1:15 PM

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so i just find stuff like x * y and y* z = 4500

dark sparrow Jul 14, 2020, 1:15 PM

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no. three rectangles, not three lengths.

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for example, you could have a 1 ft by 4500 ft enclosure.

arctic vortex Jul 14, 2020, 1:15 PM

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oh

dark sparrow Jul 14, 2020, 1:15 PM

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or a 150 ft by 30 ft enclosure

arctic vortex Jul 14, 2020, 1:15 PM

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so i could do 2 * 2250

dark sparrow Jul 14, 2020, 1:15 PM

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sure

arctic vortex Jul 14, 2020, 1:15 PM

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ok

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wow you are a genius

dark sparrow Jul 14, 2020, 1:16 PM

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how nice of you to label me a genius for essentially repeating what the problem states, almost verbatim

arctic vortex Jul 14, 2020, 1:17 PM

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yeah

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📎 Shape_2.pdf

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📎 Shape_1.pdf

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📎 Shape.pdf

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well i did these

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shape_2 wont load :(

dark sparrow Jul 14, 2020, 1:20 PM

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uhhhhhh can you screenshot lmao

arctic vortex Jul 14, 2020, 1:21 PM

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o ok

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nvm this site is bad

dark sparrow Jul 14, 2020, 1:21 PM

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if you really want me to make you check your own work

arctic vortex Jul 14, 2020, 1:21 PM

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yeah

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wait where do i create my rectangles agin

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again

dark sparrow Jul 14, 2020, 1:21 PM

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wym where

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you're overthinking it

arctic vortex Jul 14, 2020, 1:23 PM

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?

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@dark sparrow is this good

📎 Annotation_2020-07-14_092634.png

dark sparrow Jul 14, 2020, 1:27 PM

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i don't know, is it?

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is the area of this rectangle 4500 square feet?

arctic vortex Jul 14, 2020, 1:27 PM

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yes

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📎 Annotation_2020-07-14_092733.png

dark sparrow Jul 14, 2020, 1:27 PM

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then what's the issue

arctic vortex Jul 14, 2020, 1:27 PM

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also this one

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oh

dark sparrow Jul 14, 2020, 1:28 PM

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is the area of this rectangle 4500 square feet?

arctic vortex Jul 14, 2020, 1:28 PM

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yes

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📎 Annotation_2020-07-14_092847.png

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o no nvm

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📎 Annotation_2020-07-14_092919.png

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do i just paste this in

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my #2 question now

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@dark sparrow

dark sparrow Jul 14, 2020, 1:32 PM

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yes

arctic vortex Jul 14, 2020, 1:32 PM

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ok

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for this one do i just find the perimeter and tell them the one with the least

📎 Annotation_2020-07-14_093314.png

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o yeah i do

dark sparrow Jul 14, 2020, 1:37 PM

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see how you managed to answer your own question with just a little bit of thinking about it

arctic vortex Jul 14, 2020, 1:38 PM

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yay

meager rapids Jul 14, 2020, 1:45 PM

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Question asks to find value of x

📎 image0.jpg

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This is what I did how did I do

📎 image0.jpg

arctic vortex Jul 14, 2020, 1:49 PM

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is this good

📎 Annotation_2020-07-14_094929.png

arctic vortex Jul 14, 2020, 2:06 PM

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never mind i think it is right

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@dark sparrow can u check my finished assignment

dark sparrow Jul 14, 2020, 2:07 PM

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4500 feet as its area

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here we go again, with you seemingly still not understanding that FEET are for LENGTH while SQUARE FEET are for AREA

arctic vortex Jul 14, 2020, 2:08 PM

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ohhhhhh

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ok i will change that

meager rapids Jul 14, 2020, 2:08 PM

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Someone check my question above qurax

arctic vortex Jul 14, 2020, 2:09 PM

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i would help you but i dont know the midsegment formula

meager rapids Jul 14, 2020, 2:09 PM

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Ah ok

arctic vortex Jul 14, 2020, 2:09 PM

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isnt the midsegment the average between b and c | a

silent plank Jul 14, 2020, 2:10 PM

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x looks fine
what about your calculations for z

arctic vortex Jul 14, 2020, 2:10 PM

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📎 Mod_08_Authentic_Assessment_1.pdf

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here is my assignment @dark sparrow

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can u check it also sorry for ping

dark sparrow Jul 14, 2020, 2:10 PM

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augh what is this

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is this another thing

arctic vortex Jul 14, 2020, 2:10 PM

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no

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the same thing

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but its in pdf

dark sparrow Jul 14, 2020, 2:13 PM

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okay so since when did we require that the dimensions of our enclosure be whole numbers

arctic vortex Jul 14, 2020, 2:14 PM

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i thought that it wasnt allowed

dark sparrow Jul 14, 2020, 2:14 PM

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you thought that what wasn't allowed?

arctic vortex Jul 14, 2020, 2:14 PM

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not having whole numbers

dark sparrow Jul 14, 2020, 2:14 PM

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why?

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a square with sides 67.1 ft long will enclose the necessary area (even going a couple of square feet over) but have a perimeter of 268.4 feet, which is less than your 270.

arctic vortex Jul 14, 2020, 2:15 PM

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oh

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ok ill change that and find the smallest

dark sparrow Jul 14, 2020, 2:15 PM

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i mean good luck ig

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your method is basically guess and check

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which is garbage

arctic vortex Jul 14, 2020, 2:16 PM

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whats the formula to find it then

dark sparrow Jul 14, 2020, 2:16 PM

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ah here we go again, the "what's the formula" mindset

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honestly ive had enough of this lol

arctic vortex Jul 14, 2020, 2:17 PM

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o

upper karma Jul 14, 2020, 2:17 PM

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Develop some intuition, figure out the formula on your own.

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Doesn’t help you to learn how to eat if the other person is holding the fork.

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Hence, your parents stop feeding you at a certain age.

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So get some muscle

arctic vortex Jul 14, 2020, 2:18 PM

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ok i will find the formula

upper karma Jul 14, 2020, 2:18 PM

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ok

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If you need help, just post the question and I’ll help you derive said formula.

arctic vortex Jul 14, 2020, 2:19 PM

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ok

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i did the formula and i got 67.08 @upper karma is this correct?

upper karma Jul 14, 2020, 2:28 PM

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For which question

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And which formula did you use

arctic vortex Jul 14, 2020, 2:28 PM

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p = 2x+2(4500/x)

upper karma Jul 14, 2020, 2:29 PM

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Is that a question?

arctic vortex Jul 14, 2020, 2:29 PM

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and to find the smallest perimeter using the area

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square feet*

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and the square feet is 4500

upper karma Jul 14, 2020, 2:29 PM

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Ok

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welp

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uhh

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Is the area part of a given shape?

arctic vortex Jul 14, 2020, 2:30 PM

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no

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so like the square feet is 4500

upper karma Jul 14, 2020, 2:30 PM

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Because if not then the smallest perimeter given the area is a circle

arctic vortex Jul 14, 2020, 2:30 PM

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and i need to find the smallest perimeter

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and it is a rectangle

upper karma Jul 14, 2020, 2:30 PM

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Ok then it is part of a given shape

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Where did you get said formula that you used?

arctic vortex Jul 14, 2020, 2:31 PM

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youtube

upper karma Jul 14, 2020, 2:31 PM

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B a d

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I mean that’s ok but next time try to derive it

arctic vortex Jul 14, 2020, 2:31 PM

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ok

upper karma Jul 14, 2020, 2:31 PM

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So the question is like: ‘find the smallest perimeter given x area’?

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And it has to be a rectangle

arctic vortex Jul 14, 2020, 2:32 PM

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yeah

upper karma Jul 14, 2020, 2:32 PM

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Ok well...

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If the perimeter you gave is in fact the smallest for the given area, how do you know it’s correct?

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Like how can you trust the formula? Did they explain it?

arctic vortex Jul 14, 2020, 2:34 PM

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i watched that video

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and i watched another one

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and both of them use the same formula

upper karma Jul 14, 2020, 2:34 PM

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Ok, did they explain how it worked?

arctic vortex Jul 14, 2020, 2:34 PM

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no

upper karma Jul 14, 2020, 2:34 PM

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That’s sad

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What’s the formula?

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I need to know how it works before I am ok using it

arctic vortex Jul 14, 2020, 2:35 PM

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p = 2x+2y then i did y=4500/x then i removed that x then i did p=2x+2(4500x/)

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then i did p=2x+900/x

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then i did p=-900/x^2

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9000*

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then i did x^2=4500

upper karma Jul 14, 2020, 2:36 PM

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thonkzoom so their formula is just formula for a perimeter then

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Which is self explanatory

arctic vortex Jul 14, 2020, 2:37 PM

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yes

upper karma Jul 14, 2020, 2:37 PM

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And given one side it’s a series of algebraic manipulations to find the other... not too hard then

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Do you have a picture of the shape?

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Or the question

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I’m going to do it and then we compare answers

arctic vortex Jul 14, 2020, 2:38 PM

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ok

upper karma Jul 14, 2020, 2:40 PM

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So pictur of question?

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Or just describe it

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thonkzoom

arctic vortex Jul 14, 2020, 2:41 PM

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📎 Mod_08_Authentic_Assessment_1.pdf

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here is the pdf

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#4 and #5

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@upper karma

upper karma Jul 14, 2020, 2:45 PM

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It gave you the answers, you want to know how it got to them?

arctic vortex Jul 14, 2020, 2:47 PM

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no those are the wrong answers

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i think its 67.08

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for the size

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can u tell me ur answer then we will compare

upper karma Jul 14, 2020, 2:47 PM

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they’re the wrong answers thonkzoom ?

arctic vortex Jul 14, 2020, 2:47 PM

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yea

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i put them myself

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but they are wrong because i did not acknowledge decimals

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so im asking if you could solve it

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and then we will compare

upper karma Jul 14, 2020, 2:48 PM

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uhH decimals

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perhaps

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What are your dimensions?

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For the rectangle after you gave decimals

arctic vortex Jul 14, 2020, 2:48 PM

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4500 square feet

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and the smallest was 750 * 6

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of my examples

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but i need to make the smallest

upper karma Jul 14, 2020, 2:51 PM

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uhh

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Well

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60*75 is pretty dang small...

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But they said incorrect

arctic vortex Jul 14, 2020, 2:52 PM

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yeah

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67.08 as the length would be 268.32

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@upper karma

upper karma Jul 14, 2020, 2:57 PM

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hmm

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Yea probably

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Turns out that’s the square root of 4500

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Wow am I a dingus

arctic vortex Jul 14, 2020, 3:00 PM

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yeah

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wait

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is it wrong

upper karma Jul 14, 2020, 3:00 PM

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don’t think so

arctic vortex Jul 14, 2020, 3:00 PM

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bc i just submitted it lol

upper karma Jul 14, 2020, 3:00 PM

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Well idk m8

arctic vortex Jul 14, 2020, 3:00 PM

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but i think its right

upper karma Jul 14, 2020, 3:00 PM

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I do too

arctic vortex Jul 14, 2020, 3:00 PM

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:D

upper karma Jul 14, 2020, 3:01 PM

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flonshed sorry

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Today I am a dingus

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Square root ensures all sides same length... long as they don’t give you a side length it’s good

arctic vortex Jul 14, 2020, 3:03 PM

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yeah

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ok thanks

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:D

upper karma Jul 14, 2020, 3:03 PM

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🙂

hollow tiger Jul 14, 2020, 3:07 PM

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I'm having trouble with this problem:

A right pyramid SABCD (AB = 12) has an inscribed sphere in it with O as its center, and has an altitude of SH. M is the midpoint of AB. The pyramid OHMA has a circumscribed sphere around it, and its radius is equal to the previously mentioned one. Find SA
I feel like I'm so close to figuring it out but I just can't
I can send the geogebra thingy I made for easier presentation: https://www.geogebra.org/3d/evxdqqrj

3D Calculator - GeoGebra

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(I chose an h that would be close enough to what I did with sliders, I didn't actually find it)

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I figured out that the OAH angle should be 30° and found the radius

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I also have an equation: h^2 = x^2 - 72 (h being the altitude, and x is SA)

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I feel like I need to find the ratio of h and x using the angles or something, but I just can't seem to find how

arctic vortex Jul 14, 2020, 3:26 PM

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@upper karma what occupation would knowing quadrilaterals be important

upper karma Jul 14, 2020, 3:27 PM

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In general knowing them will benefit you I guess

arctic vortex Jul 14, 2020, 3:28 PM

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o ok

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thanks

upper karma Jul 14, 2020, 3:28 PM

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I mean I use them a lot... but idk really flonshed

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Np

finite vigil Jul 14, 2020, 4:13 PM

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Hey

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I need help w this

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📎 unknown.png

eternal crag Jul 14, 2020, 4:25 PM

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what have you tried?

upper karma Jul 14, 2020, 4:29 PM

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@finite vigil don't ghost ^ sadcat

finite vigil Jul 14, 2020, 4:29 PM

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I don't know how to solve it at all

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someone was just giving me answers

eternal crag Jul 14, 2020, 4:30 PM

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this is not chegg you lazy cow

finite vigil Jul 14, 2020, 4:35 PM

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?

upper karma Jul 14, 2020, 4:47 PM

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That's not an honest thing at all

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It will affect yourself negatively, mind your actions.

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someone was just giving me answers
Damn

finite vigil Jul 14, 2020, 5:11 PM

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ik

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can someone help me tho

upper karma Jul 14, 2020, 5:14 PM

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I'm partly glad thay you decided to try understand instead of blusting it and pass the homework with a hole of knowledge

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$s=r\cdot \theta$ where $\theta$ is on radians

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@finite vigil

somber coyoteBOT Jul 14, 2020, 5:14 PM

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Al𝟛dium:

📎 349552552385314818.png

upper karma Jul 14, 2020, 5:14 PM

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Pretty much it

finite vigil Jul 14, 2020, 5:15 PM

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I have no idea

upper karma Jul 14, 2020, 5:15 PM

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On what?

finite vigil Jul 14, 2020, 5:16 PM

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Like

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How to do it

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could u walk me through it

upper karma Jul 14, 2020, 5:18 PM

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@finite vigil you have the radius, you have $\theta$ on angles, all you have to do is put it in radians

somber coyoteBOT Jul 14, 2020, 5:18 PM

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Al𝟛dium:

📎 349552552385314818.png

upper karma Jul 14, 2020, 5:18 PM

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And plug it into the formula above

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To put into radians basically, you should blatantly know what 90° is on radians, if not, $90° \cdot \frac{π}{180°}=$your desired $\theta$ on radians

finite vigil Jul 14, 2020, 5:22 PM

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Ahh

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I don't know

somber coyoteBOT Jul 14, 2020, 5:22 PM

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Al𝟛dium:

📎 349552552385314818.png

upper karma Jul 14, 2020, 5:23 PM

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You don't know what? All good now? @finite vigil

vale herald Jul 14, 2020, 5:23 PM

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@finite vigil copy and paste the question

finite vigil Jul 14, 2020, 5:24 PM

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ok

upper karma Jul 14, 2020, 5:24 PM

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Don't do it wtf

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Are you really gonna post your pictures with no context again and i still don't know what you did on the one before?

vale herald Jul 14, 2020, 5:25 PM

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yo Hannah

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do u know what the question is asking for?

finite vigil Jul 14, 2020, 5:26 PM

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no

upper karma Jul 14, 2020, 5:26 PM

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...

vale herald Jul 14, 2020, 5:27 PM

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so its asking for

finite vigil Jul 14, 2020, 5:27 PM

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Idk I'm fucking stupif

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kms

upper karma Jul 14, 2020, 5:27 PM

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Are you really gonna post your pictures with no context again and i still don't know what you did on the one before?
.

finite vigil Jul 14, 2020, 5:27 PM

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......

upper karma Jul 14, 2020, 5:27 PM

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thonkzoom

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I'm out.

finite vigil Jul 14, 2020, 5:27 PM

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I'm sorry..

vale herald Jul 14, 2020, 5:28 PM

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📎 Screen_Shot_2020-07-14_at_1.28.10_PM.png

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uh its asking for the angle for this side

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the answer is already there

finite vigil Jul 14, 2020, 5:29 PM

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....

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I'm gonna fail...

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Fuckk

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My Dad is gonna be so pissed at me

upper karma Jul 14, 2020, 6:07 PM

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i feel bad

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yall finna help her or

eternal crag Jul 14, 2020, 6:11 PM

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i don't think they have the correct attitude to accept any help other than be guided through completely

upper karma Jul 14, 2020, 6:12 PM

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@eternal crag so that means you cant help

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like how yall gon start helping

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and if she doesnt understand

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you just give up

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what part would attitude be put into that

eternal crag Jul 14, 2020, 6:14 PM

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are you stupid or don't know how to read? al3dium gave a formula, she replied "I don't know", al3dium then ask for clarification on what she doesn't understand, to which she then replied: "idk i'm fucking stupif" and "kms"

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what the fuck are we suppose to do?

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you tell me

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should al3dium try to clear any confusion without knowing what the confusion is?
should al3dium just give the answer?

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that doesn't mean i can't help, that means i'm unwilling to, i think the other party is not trying hard enough because she refuse to tell us what she doesn't understand

upper karma Jul 14, 2020, 6:17 PM

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someone should ask

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rather than saying

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"im out"

eternal crag Jul 14, 2020, 6:19 PM

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someone should ask
al3dium did, and he is not going to do it again

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i don't know what to tell you

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are we suppose to chase people to work hard?

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nobody has the time to do so, helpers don't get paid here

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either they're going to do some think on their own and show some efforts, or there is no point to continue

wind imp Jul 14, 2020, 6:59 PM

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i feel like if you do not wish to help, that's perfectly fine! however, i would say that insulting people and vehemently arguing against helping might be more the opposite of helpful and could prove detrimental to the atmosphere, especially if someone else is happy to try and reach out/be understanding

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yeah i got mad respect for yall i think it's a really cool thing that you're doing (and people can def be hard to interact with sometimes)

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oof that sucks

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also i missed a comment and would like to add that if anyone feels bad they could consider helping instead of expecting others to do it for them?

wind imp Jul 14, 2020, 7:44 PM

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uh that was not at you at all, that was in response to the person who kind of started the end of the above conversation which made me realize i wasn't exactly very fair in my first message. now i admit i probably shouldn't have said anything in the first place. so i apologize for making this more messy than it already was

upper karma Jul 14, 2020, 9:13 PM

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Yea

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What do u need

gloomy slate Jul 14, 2020, 9:13 PM

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How would I solve this problem?

📎 unknown.png

upper karma Jul 14, 2020, 9:13 PM

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@gloomy slate

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Ok

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Yes just search up a bunch of theorems

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And watch YouTube videos

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Or use google

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Pretty easy

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@gloomy slate

gloomy slate Jul 14, 2020, 9:16 PM

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oh nice thanks man

upper karma Jul 14, 2020, 9:16 PM

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...

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Nice advice lol

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Use cosine law

gloomy slate Jul 14, 2020, 9:17 PM

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lol

fading zinc Jul 14, 2020, 9:28 PM

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hey

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if nobody is in the middle of a question

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Id like to ask one

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Im not quite sure how I calculate the perimeter of this shape

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📎 Geometry_weird_shape.PNG

mossy plinth Jul 14, 2020, 9:44 PM

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How do you simplify,
tan(2t+pi) ?

upper karma Jul 14, 2020, 9:48 PM

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Use the fact that $\tan(u+kπ)=\tan(u), k\in \bZ$

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@mossy plinth

somber coyoteBOT Jul 14, 2020, 9:48 PM

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Al𝟛dium:

📎 349552552385314818.png

mossy plinth Jul 14, 2020, 9:54 PM

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wait, so 2t = u in this case, whereas k = 1?

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so tan(2t+π) = tan(2t)?

upper karma Jul 14, 2020, 10:05 PM

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@mossy plinth yes.

mossy plinth Jul 14, 2020, 10:11 PM

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Oh, thanks.

upper karma Jul 14, 2020, 10:13 PM

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Np.

wraith drum Jul 15, 2020, 3:38 AM

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@mossy plinth if you want, you could use double angle tangent

fading zinc Jul 15, 2020, 3:47 AM

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what happens if i rotate a shape 180 degrees?

upper karma Jul 15, 2020, 3:50 AM

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@fading zinc just think about it

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pretty much common sense

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or idk

glacial haven Jul 15, 2020, 3:51 AM

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if you rotate a shape 180 degrees then it’s rotated 180 degrees

upper karma Jul 15, 2020, 3:51 AM

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yep

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exactly

glacial haven Jul 15, 2020, 3:51 AM

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not much to say

finite sky Jul 15, 2020, 4:15 AM

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📎 unknown.png

#

In this question, it is asking which lines are parallel

#

but im confused why isnt the 68 equal to 64?

#

I feel it might be a textbook mistake

#

cause answers are

#

DE ll GF ( alternate angles are equal)
DG ll EF ( alternate angles are equal)

#

:/

silent plank Jul 15, 2020, 4:23 AM

#

only DE || GF

finite sky Jul 15, 2020, 4:23 AM

#

Maybe textbook has mistake

silent plank Jul 15, 2020, 4:24 AM

#

<DGE and <FEG are alternate angles but aren't equal thus DG and EF aren't parallel to each other

finite sky Jul 15, 2020, 4:24 AM

#

okay

#

thANKS mr

hollow tiger Jul 15, 2020, 9:38 AM

#

hey um
I'm kinda having trouble with this equation
I feel like I know how to start but I have no idea what to do next 🤔

📎 unknown.png

cinder portal Jul 15, 2020, 9:52 AM

#

let sin(x) = a, cos(x) = b

#

you might see something familiar

#

if you don't, ping me

hollow tiger Jul 15, 2020, 10:13 AM

#

@cinder portal yeah that's the thing, I did something similar to this and got a simpler(?) equation, but I don't really see what to do next 🤔

#

now I have this:

2a/b = b^2 * (1 - (a/b)^2) * (9(a/b)^2 + 4 * (a/b) - 3)

royal edge Jul 15, 2020, 11:55 AM

#

📎 image0.jpg

upper karma Jul 15, 2020, 12:55 PM

#

What is this

arctic vortex Jul 15, 2020, 1:04 PM

#

can anyone help me with some geometry questions??

upper karma Jul 15, 2020, 1:04 PM

#

Sure

#

Just post

arctic vortex Jul 15, 2020, 1:05 PM

#

k

#

@upper karma

📎 Annotation_2020-07-15_090603.png

upper karma Jul 15, 2020, 1:06 PM

#

What have you tried

arctic vortex Jul 15, 2020, 1:07 PM

#

i dont know how to get the measure of triangles

upper karma Jul 15, 2020, 1:07 PM

#

Angle BDC

#

Im giving you a hint

#

AB is parallel to DC

arctic vortex Jul 15, 2020, 1:09 PM

#

i still dont get it

upper karma Jul 15, 2020, 1:09 PM

#

Properties of angles and parallels?

arctic vortex Jul 15, 2020, 1:10 PM

#

no how to get bdc by parallel lines

silent plank Jul 15, 2020, 1:11 PM

#

do you know how to identify stuff like:
alternate angles, (interior/exterior variants)
corresponding angles
vertical angles

upper karma Jul 15, 2020, 1:12 PM

#

no how to get bdc by parallel lines
Opposite sides of a parallelogram are always parallel

arctic vortex Jul 15, 2020, 1:13 PM

#

yes

upper karma Jul 15, 2020, 1:14 PM

#

How are <ABD and <BDC called?

arctic vortex Jul 15, 2020, 1:15 PM

#

triangles

#

180 degrees

upper karma Jul 15, 2020, 1:15 PM

#

<means angle

#

Are they vertical, alternate, corresponding...?

arctic vortex Jul 15, 2020, 1:16 PM

#

wait

#

its 25

#

@upper karma

#

is it

#

alternate angles

upper karma Jul 15, 2020, 1:17 PM

#

Yes

arctic vortex Jul 15, 2020, 1:17 PM

#

ok thank god

upper karma Jul 15, 2020, 1:17 PM

#

Any properties of alternate angles?

arctic vortex Jul 15, 2020, 1:18 PM

#

📎 Annotation_2020-07-15_091758.png

#

this one too

silent plank Jul 15, 2020, 1:19 PM

#

do some angle chasing, see what you can determine

upper karma Jul 15, 2020, 1:19 PM

#

What does isosceles trapezoid mean?

arctic vortex Jul 15, 2020, 1:20 PM

#

70

#

its 70

#

right

upper karma Jul 15, 2020, 1:20 PM

#

Do you even need our help

arctic vortex Jul 15, 2020, 1:20 PM

#

e=55 f=125 i=125 g=55 and 70

#

yes

#

io do

#

wait is it 70

upper karma Jul 15, 2020, 1:21 PM

#

Yes

#

"g=55"

arctic vortex Jul 15, 2020, 1:21 PM

#

yay

#

no g=55 and 780

upper karma Jul 15, 2020, 1:21 PM

#

which g?

arctic vortex Jul 15, 2020, 1:21 PM

#

g=125

#

but its 55 and 7

#

70

#

📎 Annotation_2020-07-15_092059.png

#

what about this one

#

i dont understand it with the diagonals and variables

upper karma Jul 15, 2020, 1:22 PM

#

There are 2 variables

#

You know that diagonals in a rectangle have the same length

arctic vortex Jul 15, 2020, 1:23 PM

#

yeah

#

so 7x-6=3x+43

upper karma Jul 15, 2020, 1:23 PM

#

Yes

arctic vortex Jul 15, 2020, 1:24 PM

#

its 12.25

upper karma Jul 15, 2020, 1:24 PM

#

,w 7x-6=3x+43

somber coyoteBOT Jul 15, 2020, 1:24 PM

#

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

arctic vortex Jul 15, 2020, 1:25 PM

#

yes

#

but how do i find 3x+5

#

because it would be infinite

upper karma Jul 15, 2020, 1:25 PM

#

Wut

#

To find y you will need Pythagoras

arctic vortex Jul 15, 2020, 1:25 PM

#

a2+b2?

upper karma Jul 15, 2020, 1:26 PM

#

it says solve for x

arctic vortex Jul 15, 2020, 1:26 PM

#

yea

#

i dont know how

upper karma Jul 15, 2020, 1:26 PM

#

rounded to one decimal place

arctic vortex Jul 15, 2020, 1:26 PM

#

i know the diagonals are 12.3

upper karma Jul 15, 2020, 1:26 PM

#

Aight then we done

arctic vortex Jul 15, 2020, 1:26 PM

#

but what about 3x+54

#

3x+5*

upper karma Jul 15, 2020, 1:27 PM

#

That's useless

#

The problem asks for x

#

that's the size of AB
it doesn't ask you to solve AB

arctic vortex Jul 15, 2020, 1:27 PM

#

what

#

oh

#

but it says solve for x

upper karma Jul 15, 2020, 1:28 PM

#

its 12.25

arctic vortex Jul 15, 2020, 1:28 PM

#

the answer

upper karma Jul 15, 2020, 1:29 PM

#

Yes

#

Actually 12.3

silent plank Jul 15, 2020, 1:29 PM

#

the "diagonals" aren't ~12.3

arctic vortex Jul 15, 2020, 1:29 PM

#

o

#

📎 Annotation_2020-07-15_092059.png

#

wrong one

📎 Annotation_2020-07-15_093015.png

silent plank Jul 15, 2020, 1:30 PM

#

you equated the two diagonals and solved for x to get a rounded value of 12.3

#

what do you know about the diagonals of a rhombus?

arctic vortex Jul 15, 2020, 1:31 PM

#

oh wait

#

i need to use a2+b2=c2

#

16.76

#

16.8

upper karma Jul 15, 2020, 1:31 PM

#

Are you even thinking about those problems or you are immediately posting them?

arctic vortex Jul 15, 2020, 1:31 PM

#

16.8*4

#

im immediately posting them then im solving them

#

67.2

#

?

upper karma Jul 15, 2020, 1:32 PM

#

...

silent plank Jul 15, 2020, 1:32 PM

#

don't round until the end

upper karma Jul 15, 2020, 1:32 PM

#

im immediately posting them then im solving them
@arctic vortex
don't do that

arctic vortex Jul 15, 2020, 1:32 PM

#

ok

#

i will n-ot

#

not

upper karma Jul 15, 2020, 1:32 PM

#

use your head

arctic vortex Jul 15, 2020, 1:32 PM

#

ok

#

wait for a rhombus are all sides equal

silent plank Jul 15, 2020, 1:32 PM

#

rounding prematurely will lead to inaccurate answers

arctic vortex Jul 15, 2020, 1:32 PM

#

oh ok

#

67

#

67.02

#

not rounding 16.76

silent plank Jul 15, 2020, 1:33 PM

#

using 16.76 is still rounding

arctic vortex Jul 15, 2020, 1:33 PM

#

what how

silent plank Jul 15, 2020, 1:33 PM

#

try not to round at all

#

(until the end)

arctic vortex Jul 15, 2020, 1:34 PM

#

oh

#

i think my teacher wants me to round

silent plank Jul 15, 2020, 1:34 PM

#

round at the end

arctic vortex Jul 15, 2020, 1:34 PM

#

ok

#

if i do that then i get 67

silent plank Jul 15, 2020, 1:34 PM

#

you shouldn't

arctic vortex Jul 15, 2020, 1:35 PM

#

rounding at the end?

silent plank Jul 15, 2020, 1:35 PM

#

yes

arctic vortex Jul 15, 2020, 1:35 PM

#

but i get 67 if i round at the end

#

if i dont tehen i get 67.2

silent plank Jul 15, 2020, 1:35 PM

#

specifically the length of a side is sqrt(281)
and you should enter 4*sqrt(281) into your calculator for the perimeter

arctic vortex Jul 15, 2020, 1:36 PM

#

67.05

#

67.1?

silent plank Jul 15, 2020, 1:36 PM

#

yes

arctic vortex Jul 15, 2020, 1:36 PM

#

thats the answer correct

#

📎 Annotation_2020-07-15_093656.png

#

i dont understand this one bc its like the variable one

silent plank Jul 15, 2020, 1:37 PM

#

how long have you thought on this problem?

arctic vortex Jul 15, 2020, 1:37 PM

#

3 minutes

silent plank Jul 15, 2020, 1:38 PM

#

think for a few more

#

throw all knowledge you have about parallelograms at it

arctic vortex Jul 15, 2020, 1:38 PM

#

ok

#

4.4 repeating is X

#

@silent plank i dont know

#

because its repeating

#

it could equal 35 or 36

#

x

silent plank Jul 15, 2020, 1:42 PM

#

use fractions and/or don't round until the end

arctic vortex Jul 15, 2020, 1:43 PM

#

ok

#

40/9

#

8 * 40/9

#

35.5 repeating

#

320/9

#

y = 64.4

#

repeating

#

@silent plank

silent plank Jul 15, 2020, 1:44 PM

#

and round that to 1dp

arctic vortex Jul 15, 2020, 1:45 PM

#

NO WIAT

#

its 100

#

right

silent plank Jul 15, 2020, 1:45 PM

#

wdym?

arctic vortex Jul 15, 2020, 1:45 PM

#

y

#

no nvm

silent plank Jul 15, 2020, 1:45 PM

#

8x + y = 100
y = 100 - 8x

arctic vortex Jul 15, 2020, 1:45 PM

#

64.4

#

yeah

#

@silent plank wait its 64.4?

silent plank Jul 15, 2020, 1:48 PM

#

yes

arctic vortex Jul 15, 2020, 1:52 PM

#

📎 Annotation_2020-07-15_095245.png

#

nvm i solved that one but what is this @silent plank

📎 Annotation_2020-07-15_100616.png

charred zephyr Jul 15, 2020, 2:10 PM

#

ye

#

s

arctic vortex Jul 15, 2020, 2:10 PM

#

is your name sucette

#

like socket

charred zephyr Jul 15, 2020, 2:10 PM

#

is your name kurax

#

like durex

arctic vortex Jul 15, 2020, 2:10 PM

#

no like kurax

#

but can u help me

charred zephyr Jul 15, 2020, 2:11 PM

#

on what

arctic vortex Jul 15, 2020, 2:11 PM

#

📎 Annotation_2020-07-15_100616.png

#

this one

charred zephyr Jul 15, 2020, 2:11 PM

#

DE = 72 thus EB = 72

#

Then u know what to do

#

DE = 72 thus EB = 72
easy to "prove"

#

ok

arctic vortex Jul 15, 2020, 2:13 PM

#

yes

charred zephyr Jul 15, 2020, 2:13 PM

#

did u get the answer

arctic vortex Jul 15, 2020, 2:14 PM

#

im solving it rn

charred zephyr Jul 15, 2020, 2:14 PM

#

ok

#

durex u got the answer

placid night Jul 15, 2020, 3:25 PM

#

im sorry, but what the hell is this

📎 unknown.png

#

am i just being stupid

#

how am i meant to work out PQ?!!!!

azure reef Jul 15, 2020, 3:29 PM

#

@placid night similar triangles

grave coral Jul 15, 2020, 3:29 PM

#

similar triangles

#

or Thales

#

whatever

azure reef Jul 15, 2020, 3:29 PM

#

haha i was first

grave coral Jul 15, 2020, 3:29 PM

#

xD

placid night Jul 15, 2020, 3:30 PM

#

oh yeah

#

im just being dumb

#

thanks guys 😂

upper karma Jul 15, 2020, 6:27 PM

#

📎 Annotation_2020-07-15_122505.png

upper karma Jul 15, 2020, 7:51 PM

#

Seems awesome

meager rapids Jul 16, 2020, 2:10 AM

#

Question asks to find ratio of TAN Z. Is it better if I leave it like that or should I further simplify to 3/4

📎 image0.jpg

stone adder Jul 16, 2020, 2:11 AM

#

Uhh idk, but I think both are fine

upper karma Jul 16, 2020, 2:12 AM

#

Simplify

#

Always

meager rapids Jul 16, 2020, 2:12 AM

#

Ok

upper karma Jul 16, 2020, 2:12 AM

#

Either way they’re equivalent

#

So you should be fine

meager rapids Jul 16, 2020, 2:28 AM

#

This look good?

📎 image0.jpg

wind vector Jul 16, 2020, 2:29 AM

#

that looks about right

#

yes that's correct

meager rapids Jul 16, 2020, 2:32 AM

#

Ok thanks

wind vector Jul 16, 2020, 2:33 AM

#

triangle definition of trigonometric functions got me slow

#

unit circle was easiest one to remember

#

but I don't think you should learn unit circle just yet though, since you're just starting out on trig

meager rapids Jul 16, 2020, 2:37 AM

#

Yeah that’s why I’m practicing rn ahead of time I struggle with this part

#

How’s this

📎 image0.jpg

wind vector Jul 16, 2020, 2:39 AM

#

cos Z is 24/30

#

4/5

meager rapids Jul 16, 2020, 2:40 AM

#

Ah ok

meager rapids Jul 16, 2020, 2:56 AM

#

Is this correct?

📎 image0.jpg

#

I rounded to nearest tenth

silent plank Jul 16, 2020, 2:58 AM

#

what was your answer?

meager rapids Jul 16, 2020, 2:58 AM

#

27.4

silent plank Jul 16, 2020, 2:58 AM

#

oh 1 sec, text so small

#

that's way too big

meager rapids Jul 16, 2020, 2:59 AM

#

Here’s my work

📎 image0.jpg

#

Not sure where I went wrong

silent plank Jul 16, 2020, 3:00 AM

#

multiple things wrong with that

#

firstly what is h?

meager rapids Jul 16, 2020, 3:01 AM

#

I just used h to represent missing side

silent plank Jul 16, 2020, 3:03 AM

#

usually in the context of right triangles, h would be used to represent the hypotenuse
using it to represent something else can only cause confusion

although the question isn't phrased the best way, it seems they want you to find the side indicated by the variable x

meager rapids Jul 16, 2020, 3:04 AM

#

I think I see where I went wrong I’ll re do and @ when done

#

I tried I’m not sure all I know is you use cos

silent plank Jul 16, 2020, 3:15 AM

#

only just saw you stuffed your diagram too

#

relative to the 19° angle,
would x be adjacent or opposite to it?

meager rapids Jul 16, 2020, 3:16 AM

#

Adjacent

silent plank Jul 16, 2020, 3:16 AM

#

is x touching the 19° angle at all?

meager rapids Jul 16, 2020, 3:17 AM

#

It’s not

silent plank Jul 16, 2020, 3:17 AM

#

then it would be the opposite side right?

meager rapids Jul 16, 2020, 3:19 AM

#

Yeah

silent plank Jul 16, 2020, 3:20 AM

#

and then apply the proper trig function to find x

meager rapids Jul 16, 2020, 3:21 AM

#

Ok

versed river Jul 16, 2020, 3:36 AM

#

no

meager rapids Jul 16, 2020, 4:09 AM

#

To explain this I need help I know it can’t be sin as im given the adjacent side

📎 image0.jpg

versed river Jul 16, 2020, 4:11 AM

#

so you have an angle, the side adjacent to it, and you want to find the hypotenuse

#

which trig function relates those 3 things?

meager rapids Jul 16, 2020, 4:13 AM

#

Cos

versed river Jul 16, 2020, 4:14 AM

#

catthumbsup

meager rapids Jul 16, 2020, 4:17 AM

#

Could you help me understand how to solve this

📎 image0.jpg

#

I’m stuck

silent plank Jul 16, 2020, 4:19 AM

#

standard process:
location of the two sides relative to the angle you want to use.
which function relates those 3 things

urban egret Jul 16, 2020, 4:19 AM

#

@silent plank your a beast with math man you are goals

silent plank Jul 16, 2020, 4:24 AM

#

as mentioned before:

#

although the question isn't phrased the best way, it seems they want you to find the side indicated by the variable x

#

NOT the blank unlabelled side

meager rapids Jul 16, 2020, 4:25 AM

#

Gotchu

rich mist Jul 16, 2020, 5:45 AM

#

hello, is someone ready to help right now?

#

📎 unknown.png

glacial haven Jul 16, 2020, 5:46 AM

#

sure

#

whats giving you trouble

upper karma Jul 16, 2020, 6:00 AM

#

||set sec(x)= sqrt(2)||

#

And solve

tropic tide Jul 16, 2020, 12:22 PM

#

📎 JPEG_20200716_202142.jpg

#

How do you find CDE

upper karma Jul 16, 2020, 12:26 PM

#

@tropic tide okay

#

Are you familiar with inscribed angle theorem?

tropic tide Jul 16, 2020, 12:28 PM

#

OK what is that

#

Oh is it that angle at middle is twice at circumference?

upper karma Jul 16, 2020, 12:30 PM

#

That is vague, but yeah it has to do with that

tropic tide Jul 16, 2020, 12:30 PM

#

Yea can't visualise it :/

#

In that problem

upper karma Jul 16, 2020, 12:30 PM

#

Yeah hold up

#

Btw the angle at the center has the same measure as its corresponding measure of the arc

#

Look

#

https://images.app.goo.gl/2j5BUhkEG98fcSXPA

#

Click on it

#

Now that part is set up.

#

The visualising part, we will look at this theorem, do you agree that $\angle{CDE}=\frac12 m\angle{CAE}$

somber coyoteBOT Jul 16, 2020, 12:36 PM

#

Al𝟛dium:

📎 349552552385314818.png

upper karma Jul 16, 2020, 12:37 PM

#

@tropic tide

tropic tide Jul 16, 2020, 12:37 PM

#

O I see

upper karma Jul 16, 2020, 12:39 PM

#

Now

#

Notice that CAE=CB+BAE

#

@tropic tide will you not answer if i don't tag or what?

#

Can you be more participative at least...

#

👻

meager rapids Jul 16, 2020, 2:41 PM

#

Is this correct?

📎 image0.jpg

#

@ me

upper karma Jul 16, 2020, 2:50 PM

#

@meager rapids yes

meager rapids Jul 16, 2020, 2:52 PM

#

Ok

#

Is this correct?

📎 image0.jpg

silent plank Jul 16, 2020, 3:16 PM

#

show work

meager rapids Jul 16, 2020, 3:17 PM

#

📎 image0.jpg

silent plank Jul 16, 2020, 3:18 PM

#

why are you using cos?

upper karma Jul 16, 2020, 3:18 PM

#

HELP anyone ??

silent plank Jul 16, 2020, 3:19 PM

#

you've even labelled opp and adj appropriately on the diagram
which trig function relates the angle, the opposite side and the adjacent side?

upper karma Jul 16, 2020, 3:19 PM

#

can i ask ??

silent plank Jul 16, 2020, 3:19 PM

#

find an open channel

meager rapids Jul 16, 2020, 3:19 PM

#

Tan

silent plank Jul 16, 2020, 3:19 PM

#

yes

meager rapids Jul 16, 2020, 3:26 PM

#

I got 16.1

silent plank Jul 16, 2020, 3:26 PM

#

x should be less than 14

meager rapids Jul 16, 2020, 3:27 PM

#

Ok let me see where I messed up

#

I got 12.2

silent plank Jul 16, 2020, 3:36 PM

#

rounded to 1dp, yes

meager rapids Jul 16, 2020, 3:37 PM

#

Aight thanks

fading bramble Jul 16, 2020, 5:05 PM

#

hello, is someone ready to help right now?
@rich mist hope this helps

📎 2020-07-16.png

#

i see youre supposed to keep it in terms of pi, when you do cos^-1, keep it in exact form then do 2pi- x to get your principle pair

coral dagger Jul 16, 2020, 7:42 PM

#

can someone check my math

#

I have to simplify the expression: 2(2sin(x)cos(x)) (2cos^2(x)-1)

#

📎 image0.png

#

So first I expanded the 2 into 2Sin(X)Cos(X) and got
8Sin(x)Cos(x)*2Cos^2x-1

From there I used distributive property and got
16Sin(X)Cos^3(X)-8sin(X)Cos(X)

But then apparently the answer is 8sin(x)cos^3(x)-4sin(x)cos(x) (I've used x as the variable for theta). Idk what I did wrong?

upper karma Jul 16, 2020, 7:43 PM

#

how did you get 16?

#

@coral dagger

coral dagger Jul 16, 2020, 7:44 PM

#

8*2=16

#

like I expanded (8Sin(x)Cos(x)) (2Cos^2 x-1)

#

So first I got

#

16Sin(x)Cos^3x

#

and then expanded into the -1

#

And got -8Sin(x)Cos(x)

#

so combining I got

upper karma Jul 16, 2020, 7:47 PM

#

i don't get it

#

how'd you get the first expression

#

8 sin(x)

#

how'd you get the 8 in there

coral dagger Jul 16, 2020, 7:48 PM

#

well the original question was like

#

2(2sin(x)cos(x)

upper karma Jul 16, 2020, 7:48 PM

#

yes

coral dagger Jul 16, 2020, 7:48 PM

#

I expanded the two into sin and cos

upper karma Jul 16, 2020, 7:48 PM

#

what does that even mean

coral dagger Jul 16, 2020, 7:49 PM

#

so I got

upper karma Jul 16, 2020, 7:49 PM

#

no stop

#

what does

coral dagger Jul 16, 2020, 7:49 PM

#

4sin(x)2cos(x)

upper karma Jul 16, 2020, 7:49 PM

#

blackmarket1156: I expanded the two into sin and cos

#

mean

#

you have

coral dagger Jul 16, 2020, 7:49 PM

#

I did foil

upper karma Jul 16, 2020, 7:49 PM

#

$2(2 \sin(x) \cos(x))$

somber coyoteBOT Jul 16, 2020, 7:49 PM

#

polynomial:

📎 680637512783495195.png

coral dagger Jul 16, 2020, 7:49 PM

#

and did distributive property

#

yes

upper karma Jul 16, 2020, 7:49 PM

#

do you agree that this is equal to

#

$4\sin(x) \cos(x)$

somber coyoteBOT Jul 16, 2020, 7:50 PM

#

polynomial:

📎 680637512783495195.png

coral dagger Jul 16, 2020, 7:50 PM

#

why is it not

upper karma Jul 16, 2020, 7:50 PM

#

what

coral dagger Jul 16, 2020, 7:50 PM

#

4sin(x)2cos(x)

upper karma Jul 16, 2020, 7:50 PM

#

$2(5\cdot10) = 2\cdot5\cdot10 = 5\cdot2\cdot10$

somber coyoteBOT Jul 16, 2020, 7:51 PM

#

polynomial:

📎 680637512783495195.png

upper karma Jul 16, 2020, 7:51 PM

#

but

#

But

#

$2(5 \cdot 10) \neq 2\cdot 5 \cdot 2 \cdot 10$

somber coyoteBOT Jul 16, 2020, 7:51 PM

#

polynomial:

📎 680637512783495195.png

upper karma Jul 16, 2020, 7:51 PM

#

there is no distributive property

#

this is not addition

#

$a(b+c) = ab + ac$

somber coyoteBOT Jul 16, 2020, 7:52 PM

#

polynomial:

📎 680637512783495195.png

upper karma Jul 16, 2020, 7:52 PM

#

$a(bc) = abc$

somber coyoteBOT Jul 16, 2020, 7:52 PM

#

polynomial:

📎 680637512783495195.png

coral dagger Jul 16, 2020, 7:52 PM

#

ohhh

#

Distributive property is an alhebra 1 thing right

upper karma Jul 16, 2020, 7:53 PM

#

not really? it's just a "math thing"

coral dagger Jul 16, 2020, 7:55 PM

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ok I think that’s where everything went down hill

digital perch Jul 16, 2020, 9:41 PM

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Does Anyone one know what it means and how to solve it?

📎 JPEG_20200716_154051.jpg

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📎 JPEG_20200716_154143.jpg

upper karma Jul 16, 2020, 9:41 PM

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@digital perch which one?

digital perch Jul 16, 2020, 9:42 PM

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First part

upper karma Jul 16, 2020, 9:42 PM

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cos(27)?

digital perch Jul 16, 2020, 9:42 PM

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Yep

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And sin 60

upper karma Jul 16, 2020, 9:44 PM

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Ig you aren't allowed to do it with a calc, and you have to do it with trigonometry, right?

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Bc the instructions are unclear from what you cut off

digital perch Jul 16, 2020, 9:46 PM

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📎 JPEG_20200716_154641.jpg

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Is it clear now

sleek thistle Jul 16, 2020, 9:47 PM

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📎 image0.jpg

upper karma Jul 16, 2020, 9:47 PM

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Yeah

sleek thistle Jul 16, 2020, 9:47 PM

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am i correct here?

upper karma Jul 16, 2020, 9:47 PM

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@sleek thistle how can you not see its occupied...

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@digital perch is it a test btw

sleek thistle Jul 16, 2020, 9:48 PM

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oh you can’t do that? 😳

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my bad

upper karma Jul 16, 2020, 9:48 PM

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No ...

digital perch Jul 16, 2020, 9:48 PM

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No it a summer school homework

upper karma Jul 16, 2020, 9:48 PM

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Reading rules is what you should do once you enter a server ...

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@digital perch okay

sleek thistle Jul 16, 2020, 9:48 PM

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mhm

upper karma Jul 16, 2020, 9:48 PM

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Are you familiar with the unit circle?

digital perch Jul 16, 2020, 9:49 PM

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Ah maybe idk

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No I don't think I have

upper karma Jul 16, 2020, 9:50 PM

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Uhh how are you expected to do this? Bc i may not want me to drive you to a new method you don't know

digital perch Jul 16, 2020, 9:52 PM

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I just wanna know the basics to solving those questions and I will check in with my teacher for further clarification tomorrow

upper karma Jul 16, 2020, 9:53 PM

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Ok

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Ig i should introduce you the unit circle

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https://youtu.be/1m9p9iubMLU

YouTube

Khan Academy

Introduction to the unit circle | Trigonometry | Khan Academy

Extending SOH CAH TOA so that we can define trig functions for a broader class of angles

Practice this lesson yourself on KhanAcademy.org right now:
https://www.khanacademy.org/math/trigonometry/unit-circle-trig-func/Trig-unit-circle/e/unit_circle?utm_source=YT&utm_medium=De...

▶ Play video

digital perch Jul 16, 2020, 9:53 PM

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K am ready

upper karma Jul 16, 2020, 9:54 PM

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Go watch it first

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Look #❓how-to-get-help ....

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Its clearly occupied.

digital perch Jul 16, 2020, 10:08 PM

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am done

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@upper karma

upper karma Jul 16, 2020, 10:09 PM

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Cool

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📎 SAVE_20200707_240528.jpg

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The coordinates works like this (cos(x)), sin(x))

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So you said you wanted the value of sin(60)

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Look at the unit circle and find where it says "60°"

digital perch Jul 16, 2020, 10:12 PM

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yep

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pi/3

upper karma Jul 16, 2020, 10:13 PM

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Now to find the value of sin(60) after you found the 60°, just look at the coordinate

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No, π/3 is 60° on radians

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We are looking at the coordinates

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The coordinates works like this (cos(x)), sin(x))
@upper karma so you should look at the second one as you are looking for the sine not cosine

digital perch Jul 16, 2020, 10:14 PM

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(1/2,square root 3/2)

upper karma Jul 16, 2020, 10:14 PM

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Yep

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But we want sine

digital perch Jul 16, 2020, 10:14 PM

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yep

upper karma Jul 16, 2020, 10:15 PM

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The coordinates works like this (cos(x)), sin(x))
@upper karma so which one should we take? ^

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1/2 or $\frac{\sqrt{3}}{2}$

digital perch Jul 16, 2020, 10:15 PM

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sin(x)

somber coyoteBOT Jul 16, 2020, 10:15 PM

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Al𝟛dium:

📎 349552552385314818.png

digital perch Jul 16, 2020, 10:16 PM

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square root 3/2

upper karma Jul 16, 2020, 10:16 PM

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Yes.

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So we know that $\sin(60)=\frac{\sqrt{3}}{2}$

somber coyoteBOT Jul 16, 2020, 10:17 PM

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Al𝟛dium:

📎 349552552385314818.png

upper karma Jul 16, 2020, 10:17 PM

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And you should leave it like that

digital perch Jul 16, 2020, 10:18 PM

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but the question said to solve to the nearest hundredth

upper karma Jul 16, 2020, 10:19 PM

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You didn't tell me that ...

digital perch Jul 16, 2020, 10:19 PM

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📎 JPEG_20200716_161905.jpg

upper karma Jul 16, 2020, 10:19 PM

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Okay well

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Whatever

digital perch Jul 16, 2020, 10:19 PM

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Lol

upper karma Jul 16, 2020, 10:20 PM

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,calc (sqrt(3))/2

somber coyoteBOT Jul 16, 2020, 10:20 PM

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Result:

0.86602540378444

upper karma Jul 16, 2020, 10:21 PM

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@digital perch ^

digital perch Jul 16, 2020, 10:21 PM

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yea

upper karma Jul 16, 2020, 10:23 PM

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The case on cos(27) is to get an approximation as it is what is asked, by typing it into the calculator

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,calc cos(27)

somber coyoteBOT Jul 16, 2020, 10:23 PM

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Result:

-0.29213880873384

upper karma Jul 16, 2020, 10:23 PM

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Approximate correctly and you are done

digital perch Jul 16, 2020, 10:25 PM

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ok thanks for you help (man/lady) idk but thanks

upper karma Jul 16, 2020, 10:25 PM

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Man lol

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Np catthumbsup

digital perch Jul 16, 2020, 10:28 PM

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have a great day bye

meager rapids Jul 16, 2020, 10:38 PM

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I did x=cos ^-1 (4/5)

upper karma Jul 16, 2020, 11:01 PM

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Correct but its not x, its theta. @meager rapids

meager rapids Jul 16, 2020, 11:02 PM

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👍🏼

upper karma Jul 17, 2020, 12:50 AM

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yes

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@meager rapids

meager rapids Jul 17, 2020, 12:51 AM

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Ok thanks

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I did x=cos^-1 (6.7/8) and got that

silent plank Jul 17, 2020, 1:15 AM

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degrees to 1dp, yes.

meager rapids Jul 17, 2020, 1:45 AM

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I did 12/sin18

urban egret Jul 17, 2020, 2:02 AM

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@meager rapids your correct

meager rapids Jul 17, 2020, 2:08 AM

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Is that good?

silent plank Jul 17, 2020, 2:10 AM

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hyp is wrong

meager rapids Jul 17, 2020, 2:12 AM

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Hyp is 18

silent plank Jul 17, 2020, 2:14 AM

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thats better

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wdym by "the same"

meager rapids Jul 17, 2020, 2:18 AM

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I meant like triangle would be similar by a shortcut

silent plank Jul 17, 2020, 2:18 AM

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yes. they will be similar

meager rapids Jul 17, 2020, 2:19 AM

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👍🏼

silent plank Jul 17, 2020, 2:19 AM

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the use of "the same" implies congruency, not similarity

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so use the proper terminology

meager rapids Jul 17, 2020, 2:29 AM

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The error would be that he would need to multiply 1.5 to both 8.25 and 18 and then divide them?

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This person only multiplied it to 8.25 and not 18

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Right?

silent plank Jul 17, 2020, 2:34 AM

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no

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the error would be with how they setup the ratio

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the algebraic manipulation being performed was actually fine

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they should be starting with

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$\frac{\text{length}}{\text{height}} = \frac{18}{8.25} = \frac{x}{1.5}$

somber coyoteBOT Jul 17, 2020, 2:39 AM

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ramonov:

📎 220517274845577216.png

meager rapids Jul 17, 2020, 2:39 AM

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Ok I gotchu

silent plank Jul 17, 2020, 2:39 AM

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cross multiplication is excessive

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you only need to multiply both sides by 1.5

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no

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$\frac ab \times c \not\equiv \frac ab \times \frac cc$

somber coyoteBOT Jul 17, 2020, 2:47 AM

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ramonov:

📎 220517274845577216.png

meager rapids Jul 17, 2020, 2:47 AM

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Ahhh

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Ok

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I got 2.2 for the answer

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Rounded to tenth

silent plank Jul 17, 2020, 2:53 AM

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its not 2.2

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did you understand what i wrote?

meager rapids Jul 17, 2020, 2:57 AM

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I did, I multiplied both sides by 1.5

silent plank Jul 17, 2020, 2:57 AM

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no

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you didn't

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you multiplied one side by 1

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which was what i was trying to point out

meager rapids Jul 17, 2020, 2:58 AM

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Oh wait I think I understand now

silent plank Jul 17, 2020, 3:00 AM

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NO

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well i mean technically that is mathematically valid though

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but doesn't help you

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$\frac{18}{8.25} \times 1.5 = \frac{x}{1.5} \times 1.5 $

somber coyoteBOT Jul 17, 2020, 3:01 AM

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ramonov:

📎 220517274845577216.png

meager rapids Jul 17, 2020, 3:02 AM

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Oh that’s much cleaner

silent plank Jul 17, 2020, 3:02 AM

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$\frac{18 \times 1.5 }{8.25} = \frac{x \times 1.5}{1.5}$

somber coyoteBOT Jul 17, 2020, 3:02 AM

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ramonov:

📎 220517274845577216.png

silent plank Jul 17, 2020, 3:03 AM

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$\frac{18}{8.25} \times 1.5 \neq \frac{18}{8.25} \times \frac{1.5}{1.5}$

somber coyoteBOT Jul 17, 2020, 3:03 AM

#

ramonov:

📎 220517274845577216.png

meager rapids Jul 17, 2020, 3:05 AM

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So the answer was right before (2.2) I was just setting it up wrong

silent plank Jul 17, 2020, 3:06 AM

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no

#

did you understand how to get to:

#

$\frac{18 \times 1.5 }{8.25} = \frac{x \times 1.5}{1.5}$

somber coyoteBOT Jul 17, 2020, 3:07 AM

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ramonov:

📎 220517274845577216.png

silent plank Jul 17, 2020, 3:08 AM

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no

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otherwise you're implying x multiplied by anything is still x

meager rapids Jul 17, 2020, 3:08 AM

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Ok new answer is 3.3 now I think I get it now

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Is that correct now?

silent plank Jul 17, 2020, 3:12 AM

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should probably use exact values unless specified

meager rapids Jul 17, 2020, 3:12 AM

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Usually it’s rounded just doing some practice to get used to it

silent plank Jul 17, 2020, 3:13 AM

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then its fine

dark sparrow Jul 17, 2020, 5:08 AM

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what's the question here

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find the area of the grey region?

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is there any more information given?

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such as, do we know the big hexagon to be regular?

upper karma Jul 17, 2020, 5:15 AM

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i think it's probably hexagon is regular and semicircles

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@upper karma do you know how to find the area of a hexagon

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what is it

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as opposed to irregular semicircles?

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..so what's the area

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uh

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i am pretty sure that's not the area of it

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yeah

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yeah..

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wait

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so you already solved it

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what's the problem then

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lol

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what does that even mean

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"trig" is the study of triangles

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you just said you broke it up into triangles

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so you solved it using trig

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lol

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yeah no thanks, have fun tho

#

,w define trigonometry

somber coyoteBOT Jul 17, 2020, 5:22 AM

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Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

upper karma Jul 17, 2020, 5:23 AM

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this actually fits

#

since equilateral triangles imply something about the angles

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🙂

somber coyoteBOT Jul 17, 2020, 5:23 AM

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A brief description and guide on how to use me was sent to your DMs! Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

dark sparrow Jul 17, 2020, 5:29 AM

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aight so do y'all wanna clown around or do y'all wanna actually solve this problem

upper karma Jul 17, 2020, 5:30 AM

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but he said he already solved it

dark sparrow Jul 17, 2020, 5:30 AM

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@upper karma the area of a circular sector with radius $r$ and angle $\theta$ is $\frac12 \theta r^2$ (where $\theta$ of course is measured in radians)

somber coyoteBOT Jul 17, 2020, 5:30 AM

#

Ann:

📎 183668144404037632.png

dark sparrow Jul 17, 2020, 5:31 AM

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you can do some trigonometry to write down the area of an equilateral triangle as $\frac12 a^2 \sin(\pi/3)$ where $a$ is the side length

somber coyoteBOT Jul 17, 2020, 5:31 AM

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Ann:

📎 183668144404037632.png

finite sky Jul 17, 2020, 8:38 AM

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https://cdn.discordapp.com/attachments/550610788608507907/733603231887917076/unknown.png

#

How to find alpha

#

I know alpha is 50.

#

But i checked answers, and it says
alpha = 50 (co-interior angle, FI ll GH)

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but its not co-interior..

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cause 120 + 50 = 170

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not 180?

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help?

versed river Jul 17, 2020, 8:39 AM

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what about

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gamma

#

you're forgetting to add gamma

finite sky Jul 17, 2020, 8:39 AM

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gamma is 10?

versed river Jul 17, 2020, 8:39 AM

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120+50+gamma=180

finite sky Jul 17, 2020, 8:39 AM

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Yeah but isnt co-interior

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just 2 angles?

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cause co-interior angles on paralell are adding to 180.

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or do both

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:/

versed river Jul 17, 2020, 8:40 AM

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if your book used cointerior angles

📎 unknown.png

finite sky Jul 17, 2020, 8:41 AM

#

?

versed river Jul 17, 2020, 8:41 AM

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you know red and blue add to 180

finite sky Jul 17, 2020, 8:41 AM

#

oh

versed river Jul 17, 2020, 8:41 AM

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so alpha+64+66=180

finite sky Jul 17, 2020, 8:41 AM

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Oh!!

versed river Jul 17, 2020, 8:41 AM

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you got it now?

finite sky Jul 17, 2020, 8:42 AM

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yeah

#

thanks

versed river Jul 17, 2020, 8:42 AM

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nw

finite sky Jul 17, 2020, 8:42 AM

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I was focusing on

#

120

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not the top side lol

royal edge Jul 17, 2020, 12:39 PM

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Is it 240?

📎 image0.jpg

upper karma Jul 17, 2020, 12:41 PM

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Yep.

royal edge Jul 17, 2020, 12:41 PM

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Thanks

#

Appreciate it

#

How do I convert x^2+y^2+6x-12y+20=0 into standard form?

dark sparrow Jul 17, 2020, 12:54 PM

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complete

#

the

#

square

upper karma Jul 17, 2020, 12:54 PM

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sully

royal edge Jul 17, 2020, 12:55 PM

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I believe I’ve gotten (x+3)^2+(y-6)^2=5

silent plank Jul 17, 2020, 12:56 PM

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something looks off

dark sparrow Jul 17, 2020, 12:56 PM

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this looks sus

#

can you show your work

silent plank Jul 17, 2020, 12:56 PM

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specifically how did you get 5?

royal edge Jul 17, 2020, 12:56 PM

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I have to rewrite my work for it to be legible lol

dark sparrow Jul 17, 2020, 12:56 PM

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yes do that

royal edge Jul 17, 2020, 12:58 PM

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I believe there was a flaw in my work

#

I got 25

#

📎 image0.jpg

dark sparrow Jul 17, 2020, 12:59 PM

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now that's much better

royal edge Jul 17, 2020, 12:59 PM

#

Thanks guys

royal edge Jul 17, 2020, 1:27 PM

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No clue how to do this

📎 image0.jpg

upper karma Jul 17, 2020, 1:30 PM

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Right triangle?

royal edge Jul 17, 2020, 1:30 PM

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They didn’t specify

upper karma Jul 17, 2020, 1:30 PM

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I see

#

First of all label the tangent points

royal edge Jul 17, 2020, 1:30 PM

#

Got it

upper karma Jul 17, 2020, 1:30 PM

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Show