geometry-and-trigonometry

[ebon sundial]

what is math

it just 1 answer

it easy

a mathmatician could answer this in 3 sec flat

[cedar tendon]

what

MATHmatician

could do this?

[ebon sundial]

yes

[cedar tendon]

so if i answer this problem would i be smart as a mathmatician

[sinful anvil]

lol

[ebon sundial]

yes

that if u can get this correctly

we will admit to you that you are smarter than ramonov and can beat him in chess

only if u can get it right

[cedar tendon]

WHAT

omgosh

[sinful anvil]

we will admit to you that you are smart than ramonov
@ebon sundial * We'll admit that you're smarter than ramonov

[cedar tendon]

i have to solve this

[sinful anvil]

lol

Do they mean addition by this? or

[ebon sundial]

you have 3 seconds to give us an answer because a mathician could solve this in 3 secs flat

[sinful anvil]

If so, it's 19

[cedar tendon]

oh

it 19

[ebon sundial]

wumbo

why

it was his question

[sinful anvil]

That is easy

Anyone should know that

[ebon sundial]

but we was testing to see if he actually know that

[cedar tendon]

@ebon sundial remember our deal

[sinful anvil]

Do you think anyone who is in trigonometry class won't know addition lol?

[cedar tendon]

no take backs

[rich wolf]

Bro he got it wrong

[sinful anvil]

me?

[rich wolf]

It's 21

[upper karma]

^

9 + 10 = 21

[ebon sundial]

@cedar tendon fine we admit to you are smarter than ramonov. and you can beat him in chess.

[sinful anvil]

I said if you meant it as a joke

lmao

[cedar tendon]

YES

[upper karma]

no

[cedar tendon]

IM SMARTER. THAN ramonov

and i can beat him in chess

yes

[sinful anvil]

Anyways

[rich wolf]

No ur not

[upper karma]

no

[sinful anvil]

You know the deal

[cedar tendon]

that was the deal

[sinful anvil]

help him

[cedar tendon]

im smarter than ramonov and i can beat him in chess

[rich wolf]

No one is smarter than Stroganoff

[sinful anvil]

I searched that up

and it said it was a dish

[upper karma]

beef stroganoff

more like

beef ramonov

[sinful anvil]

Anyways

[cedar tendon]

and mr.tai remember our deal you will help me with the question

[desert vortex]

is r=12+12sin(theta) a limacon without a loop or a cardioid graph? idk where to put this its kinda trig lmao

[sinful anvil]

repost it @cedar tendon

[ebon sundial]

find

[upper karma]

if youre so smart answer it yourself

[desert vortex]

is r=12+12sin(theta) a limacon without a loop or a cardioid graph?

[ebon sundial]

we already had a deal

so imma just give the answer

[cedar tendon]

so what is the answer

i need it

[sinful anvil]

Did you watch the video? @cedar tendon

[cedar tendon]

yea

[sinful anvil]

@cedar tendon https://youtu.be/Qz_7T0GpCFU

[upper karma]

@desert vortex cardiod bc a=b

[desert vortex]

bruh how

oh

shit

[cedar tendon]

and i got 461

[desert vortex]

im so dumb hahahha

[sinful anvil]

Did you write your solutions down on paper?

[desert vortex]

thank you

[upper karma]

np 🙂

[cedar tendon]

yea

wumbo i got 461

[upper karma]

@sinful anvil no, this is patrick

[sinful anvil]

Shall I summon the mods?

[ebon sundial]

noo

not yet wumbo

[upper karma]

^

[ebon sundial]

lets just help him out

he did answer 9 + 10

[desert vortex]

is r=6-6sin(theta) a limacon without an innerloop?

[ebon sundial]

so we gotta give him this one

[upper karma]

yes

its a cardoid, so whatever your first question was, this also is that

[desert vortex]

wait what

lol

[cedar tendon]

so guys

i need help

[cedar tendon]

with the quesiton

[desert vortex]

Is it not C?

oh

wait

b

B?

[upper karma]

https://www.desmos.com/calculator/0cgd42syg8

[desert vortex]

yeah i graphed it kek

[upper karma]

heres the graph, decide yourself

lel

[desert vortex]

bro B

?

am i trippng

the no response makes me feel like it is B but lmao

[cedar tendon]

help me

[upper karma]

@cedar tendon Sure 1 min

@desert vortex i think its D

[sinful anvil]

@cedar tendon was in line 1st

[upper karma]

what did u think the answer was>

@cedar tendon

[desert vortex]

huh why polar axis

[cedar tendon]

461

[upper karma]

bc its not symmetric to pi/2

[sinful anvil]

@cedar tendon post your solutions on here

[upper karma]

whats makes you doubt that its wrong?

and its a cardoid

so

@cedar tendon

[cedar tendon]

i need help

[desert vortex]

what how is it not symmetric to pi/2

[upper karma]

@cedar tendon what makes you doubt that its wrong

[desert vortex]

am i tripping this hard

[upper karma]

did u follow everything in the video

if u did then sure ur correct

[cedar tendon]

because no one told me it right

[sinful anvil]

lol

[upper karma]

ya k 1 min

[desert vortex]

smh my head

it was B

[sinful anvil]

I told you to post your solutions on here @cedar tendon

[desert vortex]

i was correct kek

[sinful anvil]

So if you made mistakes, we'd point it out

[cedar tendon]

ok

[upper karma]

@sinful anvil Ya the video was wrong

im stupid

the problem had nothing to do with arc length

u already know the central angle

[sinful anvil]

Well theta is 120?

[upper karma]

ya

[sinful anvil]

Radius is 21

[upper karma]

ik

the video i posted is wrong

im very sorry

i misunderstood the problem

[cedar tendon]

120/360 * pie * 441 and i got 461pie

[sinful anvil]

*pi

It's math

[upper karma]

@desert vortex im sorry

@cedar tendon Nah wrong

^

[ebon sundial]

math it is wrong

[sinful anvil]

Imma ping helpers lol

[desert vortex]

its good lol

[upper karma]

@cedar tendon Simplify 120/360 to 1/3

that will possibly help

[sinful anvil]

<@&286206848099549185>

[upper karma]

or just use calculator

or just not ask the question

[cedar tendon]

i did 1/3 * pi and i got 1.047

imma x 21^2

by that

[upper karma]

ya ur good

[cedar tendon]

but it keep giving the same answer

for some reason

[ebon sundial]

@cedar tendon you are doing it all wrong

this is why i need to give you the answer

[upper karma]

ya idk anymore

u help him

im out

[ebon sundial]

noo

xi

you do it

[upper karma]

lol bye

[cedar tendon]

xi

he left

[sinful anvil]

I had 461

as well

It's 461

[cedar tendon]

they told me it wrong

[sinful anvil]

I did 1/3 * pi * 21^2

and I had 461

[cedar tendon]

ok

[sinful anvil]

Any other questions?

[sinful anvil]

oof

I didn't study radians, but I know a bit about them

[cedar tendon]

ok

<@&286206848099549185> i need help

[sinful anvil]

https://revisionmaths.com/advanced-level-maths-revision/pure-maths/trigonometry/radians

I found this lol

[cedar tendon]

ok

[fallow edge]

@cedar tendon 15 mins before pinging helpers

[cedar tendon]

oh

my bad

[sinful anvil]

I did like 10 minutes before lol

[fallow edge]

It's fine, just don't do it again

[sinful anvil]

Too many trolls were in here

[cedar tendon]

ok

[sinful anvil]

so that's why I did it

We both need help with radians @fallow edge

[fallow edge]

@cedar tendon do you know the formula for area of a sector

[cedar tendon]

nope

[sinful anvil]

I had it written down

Wasn't it A= 1/2(theta)(r^2)?

I'm probably off

[fallow edge]

Yeah

You're correct

So what's theta?

[sinful anvil]

It represents the angle

[upper karma]

@sinful anvil it was literally one of his questions that we answered

but ofc he doesn't know it

smfh

[sinful anvil]

Maybe because someone mislead him?

[cedar tendon]

ok

[fallow edge]

I'm talking to math I give up or whatever

What's theta in your problem

So you can apply the formula

[sinful anvil]

It's Pi/3

[fallow edge]

Again, I'm asking @cedar tendon

[cedar tendon]

this is my problem

[fallow edge]

Ik

What's theta

[cedar tendon]

is n/3

i think

[fallow edge]

N?

[cedar tendon]

idk

[fallow edge]

The "n" is a pi

$\pi$

[cedar tendon]

oh yea

[somber coyote]

IAmJon:

[cedar tendon]

my bad

pi

[fallow edge]

It's a number

[cedar tendon]

ok

[fallow edge]

But you're correct that pi/3 is theta, as it is the angle of the arc you're considering

Now we just need the radius

[cedar tendon]

ok

is it 4

[fallow edge]

Yes

So you know that A=(1/2)(theta)(r^2), right?

[cedar tendon]

yea

[sinful anvil]

Ok, I know the answer, I did it

🏃‍♂️

[fallow edge]

So you know what theta and r are, so you can just plug 'em into the formula

With me?

[cedar tendon]

ok

[fallow edge]

Can you do that?

[cedar tendon]

but what the formula?

[fallow edge]

So you know that A=(1/2)(theta)(r^2), right?

[cedar tendon]

yea

i know that

wait that the formula?

[fallow edge]

That's the formula

[cedar tendon]

ok

[fallow edge]

Remember you want to find the area

And this gives the area of the sector if you know the radius and angle, which you do

[cedar tendon]

ok

[fallow edge]

Can you plug values into a formula, or do you want me to show you how this time?

[cedar tendon]

ok

[fallow edge]

It's either/or

[upper karma]

he doesn't know the difference

[sinful anvil]

I know the answer @upper karma

I did it like 5 minutes ago

[upper karma]

what is it

[sinful anvil]

I don't wanna ruin it for @cedar tendon

[upper karma]

tru

big brain thinking right here

[sinful anvil]

I'll tell you in dm's

[upper karma]

yee

[cedar tendon]

so it 1/2

right

in the formula

[sinful anvil]

yeah

1/2 *π/3 * 4^2

Is what you're looking at

$\1/2*pi/3**4^2$

[cedar tendon]

yes

[somber coyote]

Wumbo:
Compile Error! Click the reaction for details. (You may edit your message)

[sinful anvil]

come on

How do I do it

oh

[fallow edge]

My lord

[cedar tendon]

i got 8/3

for the answer

[sinful anvil]

yep

[fallow edge]

$\frac{1}{2}\cdot\frac{\pi}{3}\cdot 4^2$

[sinful anvil]

It's 8pi/3

[somber coyote]

IAmJon:

[sinful anvil]

oh

[cedar tendon]

ok

[sinful anvil]

I'm not used to bots like this

So I don't know anything

[fallow edge]

Don't forget the pi, but otherwise you're good @cedar tendon

[cedar tendon]

ok

[sinful anvil]

oof

[fallow edge]

This is basically the same, except you have to work a little harder to find theta

Can you find theta?

[cedar tendon]

how do i do this

[upper karma]

this is not 461 pi

@sinful anvil

the answer is 147 pi which is = to 461

@cedar tendon which one did u choose

@cedar tendon Hello

[cedar tendon]

oh

xi

[upper karma]

what

[cedar tendon]

i did choose yet

i didn't

choose yet

[upper karma]

wth

[cedar tendon]

their still more question before i submit

so i can go back to it and change it

[upper karma]

why cant u learn

@cedar tendon Yes ill help

[cedar tendon]

ok

[upper karma]

i have nothing else to do anyway

[upper karma]

do u have any ideas on how u can solve this

tell me ur ideas

[cedar tendon]

i have none

[sinful anvil]

It's the same as last time

But a little tricker

[cedar tendon]

and the thng

so it hard

[upper karma]

u do know the radius

[sinful anvil]

Isn't the radius 12?

It says

[cedar tendon]

oh

[upper karma]

bruh wtf is wrong with u

[sinful anvil]

now cut the circle into 8 pieces

[upper karma]

we literallly did so many fking questions

[sinful anvil]

equally

ik

But the reality is

it's a math server

$\frac{8pi}{3}$

[somber coyote]

Wumbo:

[sinful anvil]

$\frac{8\pi}{3}$

[somber coyote]

Wumbo:

[sinful anvil]

there

That was the answer to the last question

[upper karma]

how did u get that

[sinful anvil]

this is my problem

[upper karma]

what

[sinful anvil]

Wumbo:
@somber coyote

[upper karma]

oh nice

[cedar tendon]

so guys so what are the steps i need to do to solve this

[sinful anvil]

Did you draw the circle with a radius of 12 that's equally cut into 8 slices

[upper karma]

@sinful anvil wait how did u get 8pi/3

[cedar tendon]

i got 0.83

[cedar tendon]

oh

i need. to do that

[sinful anvil]

@upper karma

[upper karma]

u need to do that but wont

[cedar tendon]

i got 12.5

[sinful anvil]

for this problem?

the one where you had to draw a circle

[cedar tendon]

i got it for this problem

[sinful anvil]

oh

So that's your theta?

[cedar tendon]

i got 12.56

[upper karma]

@cedar tendon Nah wrong

what were ur steps

@cedar tendon tell me

[cedar tendon]

1/2 * pi x 12^2

[upper karma]

@cedar tendon What exactly did u do

bruh how do u not know this

wait

@cedar tendon Why did u multiply it by 1/2

explain to me

[cedar tendon]

you guys said do what we did last problem

and im doing it

[upper karma]

not exactly what we did last problem

we use the idea

ya idk anymore

So we doing this one right

@cedar tendon

[cedar tendon]

yea

[upper karma]

see how the circle is cutted into 8 equal slices

we know the area of the circle is pi * 12^2 right

if you wanna find 1 slice

@cedar tendon

what would u do

[cedar tendon]

we gotta do pi * 12^2

[upper karma]

thats the area of the circle yea

@cedar tendon then what do u do after

[cedar tendon]

idk

[upper karma]

ofc u dont

lmaooooo

[ebon sundial]

man i wonder if the next question is harder than this one

[cedar tendon]

i got 452.38

xi

[upper karma]

1 min

@cedar tendon Ok tell me, how did u get that

what did u do

its wrong btw

[cedar tendon]

i did what you said

pi * 12^2 and i got 452.38

[upper karma]

ok thats the first part

thats the area of the circle

now see how it says the circle is cutted into 8 pieces

[cedar tendon]

ok

[upper karma]

how would u find 1 piece

[cedar tendon]

idk

[upper karma]

uh 1 min

If 8 pieces = 144 pi, how would u find 1 piece

[sinful anvil]

144/8?

[upper karma]

yea

ur not the kid tho

144pi / 8

@cedar tendon Hello

and if u know 1 piece

just multiply it by 3

to know the area of 3 pieces

[cedar tendon]

ok

[upper karma]

@sinful anvil Im bad at this, u wanna take over

im also currently taking geometry right now

@cedar tendon hello

[cedar tendon]

so 144/8

x 3

[upper karma]

144 pi / 8

yes

and do u understand why

[cedar tendon]

i got 53

[upper karma]

53 for what

final answer?

[cedar tendon]

144/8 x 3 and i got 53

[upper karma]

no its 144 pi / 8 x 3

[cedar tendon]

oh

i got 169.69

[sinful anvil]

lol

[upper karma]

@cedar tendon Ya correct

Congratulations

👏

[sinful anvil]

What's the next one lol

[ebon sundial]

the next question probably will be harder than this

[sinful anvil]

true

[sinful anvil]

oof

[cedar tendon]

need help

[sinful anvil]

${81\pi}$

[somber coyote]

Wumbo:
Compile Error! Click the reaction for details. (You may edit your message)

[sinful anvil]

Is the area

of the circle

${18\pi}$

[somber coyote]

Wumbo:

[sinful anvil]

Is the area of the sector

[cedar tendon]

but their still one problem

i don't see 169.69 in this question

[upper karma]

one of them is = to 169.69

retrace your steps

[cedar tendon]

oh 144

[upper karma]

1 min

no

@cedar tendon No

[cedar tendon]

54pi

[upper karma]

ya cool

congrats

[cedar tendon]

ok

now lets continue with this question

[sinful anvil]

Imma head out for now

I need sleep

it's 12:17AM

It was nice being here

[cedar tendon]

ok

[upper karma]

use the formula for the area of a circle

(google it if you don't know)

then write it as = 360

then formula for area of a sector of a circle = x

[cedar tendon]

@upper karma idk the radius

[upper karma]

but you know the formula for the area of a circle

right?

[cedar tendon]

is it pir^2

[upper karma]

yep

[cedar tendon]

but i don't got the radius

so i can't do it

[upper karma]

so, pi * (r^2) = 81 * pi

find r

[cedar tendon]

i can't do the formula

idk what r

spider can you help me find r

[upper karma]

pi * (x^2) = 81 * pi

[cedar tendon]

i need you help

to find r

[upper karma]

solve for x

[cedar tendon]

where the x

[upper karma]

https://discordapp.com/channels/268882317391429632/326138757474680852/719856991316607098

[cedar tendon]

i don't see x

how do i solve for x

[upper karma]

multiply both sides by pi

what do you get?

[cedar tendon]

i don't know how to solve for x

[upper karma]

sorry, divide

divide both sides by pi

(so you get rid of pi on both sides)

[cedar tendon]

so what is the equation?

[upper karma]

https://discordapp.com/channels/268882317391429632/326138757474680852/719856991316607098

[cedar tendon]

Dspider im confused

@upper karma im confused

[upper karma]

ok, what are you confused about?

[cedar tendon]

the whole thing

all of it is making me confused

[upper karma]

Area = pi * r^2

right?

[cedar tendon]

yea

[upper karma]

Area = 81 pi

right?

[cedar tendon]

yes

[upper karma]

81 pi means 81 * pi

[cedar tendon]

yea

[upper karma]

all right, so:
Area = pi * r^2
Area = 81 * pi
pi * r^2 = 81 * pi

now divide both sides of the equation by pi

[cedar tendon]

which number should i divide

idk what to divide

im confused

[upper karma]

both sides (of the equal sign)

[cedar tendon]

we don't know what is r so how am i supposed to divide it

[cedar tendon]

but we don't know what is r

how am i supposed to divide it

[upper karma]

the pi 's cancel out

do you understand why?

[cedar tendon]

yes'

[upper karma]

why?

[cedar tendon]

because it cancel out

[upper karma]

because you can also write it like this

[cedar tendon]

yea

so now what we do

[upper karma]

ok, so r^2 = 81

what does that mean?

[cedar tendon]

we don't know what is r

so what we do?

dspider

[upper karma]

what's square root of 81?

[cedar tendon]

ok

[upper karma]

meaning "what" x "what" = 81

[cedar tendon]

dude so what is the square root of 81?

[upper karma]

do you have a calculator?

[cedar tendon]

yea

so what the square root of 81?

[cedar tendon]

dspider so what is the square root of 81

[upper karma]

maybe you don't use Windows

are you on a phone right now?

[cedar tendon]

im on mac

[upper karma]

ok, let me google what OSX calculator looks like...

[cedar tendon]

ok

[upper karma]

https://cdn.osxdaily.com/wp-content/uploads/2015/05/scientific-calculator-mac-610x353.jpg

https://osxdaily.com/2015/06/14/access-scientific-programmer-calculator-mac-os-x/

[cedar tendon]

so what is the square root of 81

[upper karma]

or "Scientific"

[cedar tendon]

dude

[upper karma]

then you have access to those features

[cedar tendon]

imma just guess

is it 9

[cedar tendon]

dude idk im guessing

is it 9

[upper karma]

use the calculator, Luke

[cedar tendon]

ok

imma used it

yea i got 9

in the calcaltor

[upper karma]

good job

[cedar tendon]

ok

now what

[upper karma]

now you have the radius

[cedar tendon]

ok

i got 254.46 is that the answer

idk

what is the answer

dspider

[upper karma]

let me see

[cedar tendon]

ok

[upper karma]

yeah, that's wrong

you just multiplied 81 with pi

"81 pi" is the area for the entire circle

from here: https://www.onlinemathlearning.com/area-sector.html

(which I got by googling "formula for area of sector of a circle")

[cedar tendon]

ok

[upper karma]

solve for theta

[cedar tendon]

what is 0

idk what is 0

[upper karma]

it's a Greek letter

[cedar tendon]

what it means

[upper karma]

called theta

[cedar tendon]

what a theta

[upper karma]

it's a way to represent angles, kind of like how x is in an equation

[cedar tendon]

ok

[upper karma]

do you see the blue area of the segment?

[cedar tendon]

so the theta is 81

[upper karma]

that's where theta is on the circle

it's the central angle

[cedar tendon]

i got 57.25

[upper karma]

you need to isolate theta to one side of the equation

[cedar tendon]

ok

how do i. do that

[upper karma]

well, first thing you can do is reverse it

it's the same equation

a = b
b = a

[cedar tendon]

im confused

[upper karma]

that's ok, about what?

[cedar tendon]

their no a and b in the image

[upper karma]

"a" means the left side of the equation

"b" means the right side of the equation

[cedar tendon]

ok

so what is the theta

[upper karma]

so you have:

you need to move everything else except theta, to the other side

[cedar tendon]

i did now what

[upper karma]

you can split them up into something like this:

[cedar tendon]

ok

i did

now whar

what

[upper karma]

this makes it easier to move to the other side

called reciprocal

[cedar tendon]

ok

dspider

now what i do

[cedar tendon]

dspider what is the next step

i do

[upper karma]

hopefully you can see that the pi's cancel each other out

[cedar tendon]

ok

i got 4.44

[upper karma]

hmmm

what equation are you left with after you cross out those pi's?

[cedar tendon]

81 and 360

[cedar tendon]

i got 80

for the answer

[upper karma]

well done

was there some part you didn't understand?

[cedar tendon]

nope

i understall all of it

[upper karma]

here's another way to solve it:

do me a favor, change your nickname

because it doesn't help you

it doesn't help your outlook on math

and influences how you treat it

[cedar tendon]

im on my last question now

help me

someone

[upper karma]

I'm not helping you until you change your nickname

😛

[cedar tendon]

dude

math is so hard

[upper karma]

don't keep telling yourself that

say math is easy

and please don't start with the asian kid

ooooh, there's an asian kid in your class

so what?

[cedar tendon]

but dude im not like you for me math is hard

for you it easy

[upper karma]

no, it wasn't easy for me

[calm prairie]

@cedar tendon did you checked DM

[upper karma]

in fact, the above solution is kind of dumb 🙂

the "proper" solution is to divide both sides and stuff, not use number/1

like I did

but it works

so...

[cedar tendon]

dude their this asian kid in my class math is so easy for him compare to me it hard everything in math is hard but everyone in my class follow the asian kid except me

the asian are born with math intelligent except me

that why im bad at math

[upper karma]

I 100% guarantee you that kid practiced, and read, and studied his ass off

that's why you think he's good

it's not "genetics" or some shit like that, lmao

[cedar tendon]

that asian kid in my class alway have an A

in any mathwork

im not like him

i usually gets D

[upper karma]

yes, because his parents probably pay for his tutoring, or they put pressure on him to study instead of playing vidya

[cedar tendon]

because is math is so hard

[upper karma]

it's asian culture

it brings shame to his parents if he doesn't do well in school

don't compare to that kid

fuck that kid

lol

[calm prairie]

@cedar tendon i am asia

[cedar tendon]

and dude last time my teacher made this contest to see who would answer the most equation and we gotta be up against our classmates to see who wins for me i was the worst one the teacher told us our score in the classroom and i. was failed and. i gotten 1 point for doing 1 equation that was hard but my other classmates got more points than me and highest was that asian kid

and math is so hard

for me

people called me. a loser of the class cause of it

sense im the worst

one

[upper karma]

yeah, that sucks... boo-hoo... stop

[cedar tendon]

that why math is so hard

for me

it is so hard

[upper karma]

stop right now and listen to what I'm saying

you need to stop comparing yourself to the other kids

work on your own knowledge

[cedar tendon]

and. i need help

doing this assignment

my last assignment

[upper karma]

study the material, look up everything you don't know

[cedar tendon]

and i need help

with that

assignment

[upper karma]

you still haven't changed your nickname

[cedar tendon]

DUDE

math is so hard

[upper karma]

stop saying that

it doesn't help you

quite the opposite

[cedar tendon]

just help

Dspider

please

I NEED HELP

[upper karma]

just change your nickname

please

[cedar tendon]

noo

[upper karma]

do it nao

[dark sparrow]

dspider was abundantly clear in asking you to change your nickname

no new nick, no help

[cedar tendon]

what

a

[dark sparrow]

no new nick, no help

[cedar tendon]

Ann you support this

[dark sparrow]

no new nick, no help

[upper karma]

^fact

^truth

[cedar tendon]

i can't believe you Ann why would you support this?

someone please help me

[dark sparrow]

because you've been told multiple times to do it and have completely ignored it every single time

i'm not gonna repeat the reasons why i and everyone else here think you should change your nickname

so

no new nick, no help

[cedar tendon]

but in rules it never said i. should change name

[dark sparrow]

we aren't talking about rules

you're not violating a rule

[cedar tendon]

so i can get help

sense im not violating any rules

[dark sparrow]

you're ignoring people

no new nick, no help

no new nick, no help

no new nick, no help

no new nick, no help

no new nick, no help

no new nick, no help

[cedar tendon]

but in the rules it never i. said i should change my name

[dark sparrow]

no new nick, no help

[cedar tendon]

Cmon ann the rules

i thought everyone follow the rules

[dark sparrow]

following the rules is necessary but not sufficient to get help

we are not machines mindlessly checking everyone for compliance with rules and always helping those who don't break any

[cedar tendon]

and i. didn't break any so im asking for help

[dark sparrow]

and everyone's been ABUNDANTLY CLEAR on saying

no new nick, no help

well ok

DSpider and i so far

i'm pretty sure a lot of ppl would follow suit

[weary drift]

no one wants to help you since your name pollutes the air with a smell of desperation and helplessness

[cedar tendon]

What

dude it just name

im jsut telling everyone math is hard for me

what wrong with that

[silent plank]

there is no obligation for anyone to help anyone.
but if don't demonstrate that you have an appropriate attitude to learning such as:
-insisting that you only want the answer
-not looking up recommended materials when you have knowledge gaps
-using a nick that shows a disdain towards learning math
then people are less likely to help you

[cedar tendon]

oh ramonov you are back

[silent plank]

and this applies to all forms of learning, not just math

[cedar tendon]

i thought u were gone forever

Ramonov i need help

with my math problem

help me ramonov

[silent plank]

since it is impossible for a human to make exact cuts it is impossible
Q.E.D

[cedar tendon]

so guys what do i do

someone help me

[calm prairie]

@cedar tendon DM\

[cedar tendon]

i need help someone please help me

[ebon sundial]

Fine

imma help ya

[cedar tendon]

Yes mr.tai thank you so much

[ebon sundial]

So, what is the problem?

[cedar tendon]

it this

so what i do mr.tai

[ebon sundial]

well think of that protractor as half of a cake.

[cedar tendon]

ok

so it halve

[ebon sundial]

now you'd have to split it in 5 slices
since it's just a half.

[cedar tendon]

Ok

5 slices like pizza

right

[ebon sundial]

Yea you can maybe think that.

so basically once every x degrees you'd have to cut that half.

considering that a protractor measures 180 degrees.

and there must be 5 slices for one half.

basically divide the protractor in 5 equal parts.

which is easy since you have the degrees written on it.

[cedar tendon]

the degreess

you mean that 180

degress

?

[ebon sundial]

Yea the protractor measures 180 degrees.

the question comes down to: how many degrees must an arc measure so that we have 10 equal slices?

[cedar tendon]

yes

10 equal slices

that the question

[ebon sundial]

so?
there are 360 degrees in one full circle

[cedar tendon]

yes

in the one circle there are 360 degrees.

[ebon sundial]

basically 2 protractors

[cedar tendon]

Yes

[ebon sundial]

what's the equation we're left with?

@silent plank im just doing this

to help him out

i feel like he need some help

[cedar tendon]

ok

idk what the equation

I NEED HELP

[ebon sundial]

Calm down and think about what the equation we have left with?

think about it?

[cedar tendon]

i am thinking

[ebon sundial]

umm dude im helping someone

[cedar tendon]

yea

he helping me

first

Mr.tai

[surreal vector]

sorry my disc lagged out showed no new messages

[ebon sundial]

Ok!

[cedar tendon]

now what we do

[ebon sundial]

Lets continue with the problem we were on so what equation did we have left with?

[cedar tendon]

dude

im thinking

I NEED SOME. TIME

[wooden current]

😐

[ebon sundial]

Well calm down and think about it.

[cedar tendon]

5

I THINK

[ebon sundial]

No I mean

we have to divide the degrees of a full circle to get 10 equal arcs

[cedar tendon]

ok

[ebon sundial]

so 360/x = 10

[cedar tendon]

360/180 right

[ebon sundial]

Noo

[upper karma]

180 is half of 360
5 is half of 10

[surreal vector]

Think of it this way, a circle is 360 degrees, and you to distribute it evenly among 10 people, the tool you get is a protractor, which is half the degrees of a circle, meaning you can use it on half the people, and half the cake at a time

[ebon sundial]

solve for x

[silent plank]

to divide 360 into 10 equal parts you would divide 360 by 10

[azure reef]

360/180=10
hm
36/18 = 10 therefore
2=10????

[cedar tendon]

by 10

oh ramonov. you finnally helping me

Yes

[upper karma]

And then how do you change that to a 180° protractor?

Which is half of 360?

[ebon sundial]

@cedar tendon just solve for x

[silent plank]

the actually complicated part of the problem is applying bisection theorems to get the centre and diamater

[cedar tendon]

oh

so what do i do

first

[upper karma]

It's better if you can get the answers on your own with guidance without just being told them

[ebon sundial]

i think he doesn't understand math that well

which could be hard

for him

[surreal vector]

@cedar tendon If a circle is 360 degrees and a protractor is half that, how much degrees is a protractor?

[upper karma]

Well what is one half as a fraction?

[ebon sundial]

@cedar tendon 360/x = 10
just solve for x

[cedar tendon]

how do i solve for x?

[surreal vector]

Did you study algebra?

[ebon sundial]

he doesn't understand math that well that probably reason why he not getting it so imma just give him some hints

@cedar tendon you can switch 10 with x than divide

[cedar tendon]

how do i like switch them?

[ebon sundial]

switch means changing it places

like lets say you want to buy a candy corn by giant

right

[cedar tendon]

Yes

[ebon sundial]

than you want to switch it up with an even better candy like jolly rancher

that what switch means do you understand?

[cedar tendon]

i get it

i know what switch means now

[ebon sundial]

ok now applied it with math

switch the 10 with x than divide it

[cedar tendon]

ok

MR.tai

but math is so hard

do you think i can do this?

[upper karma]

Yes

[ebon sundial]

We all believe in you we will help you in your problems in math

no mather what

Alright

I know how math is hard for some people

[cedar tendon]

YOU REALLY DO

o0k

imma do this

[ebon sundial]

so just switch the 10 with x than divide it than tell me what you got?

[cedar tendon]

ok

I GOT 36

[ebon sundial]

Good.

Correct

[upper karma]

Aye nice !

:)

[wooden current]

https://media.discordapp.net/attachments/715789961491644428/719241860211671120/JotaroParty.gif

This is so wholesome

[upper karma]

Haha

[ebon sundial]

now write what you did to get 36 for 1@cedar tendon

[cedar tendon]

I DID

i wrote everything down

now what for 2

[ebon sundial]

ok for 2 you really need to think about it

[cedar tendon]

so does it change?

mr.tai

for 2

[ebon sundial]

lemme ask you this @cedar tendon does the circle changes?

[cedar tendon]

NOPE

it stays at 360

[ebon sundial]

than their your answer

for 2

[sinful anvil]

I just woke up

Sup my dudes

[ebon sundial]

you can applied this what we did for 1 into 2 and it stays the same because the circle doesn't change

[upper karma]

I'm gonna go to sleep now, good luck !!

[cedar tendon]

IM FINISH

[silent plank]

technically the same approach can be used, but think about practicality

[cedar tendon]

now

[ebon sundial]

yea ramonov

any more question math i give up or that the last one

[cedar tendon]

that is the last one

im done

[ebon sundial]

@sinful anvil i saved the day

[surreal vector]

Hello, I'm stuck on a homework assignment

I am given, theres a point A on the line y = 7 on it's first quarter.
point A is the same distance from the Y axis as its distance from the point (2,3).
I need to find the point A coordinates and the distance between A and the Y axis.

This is what I wrote so far, not sure even if this is correct:

[small mauve]

You could always just take the line perpendicular CD at the midpoint of CD and find its intersection with y=7

To get A

[surreal vector]

you mean find the midpoint of CD?

I can only find the x value of that midpoint as well, cant I?

I'm having troubles with that line definition, y = 7, the teacher explained that if we wish to check if a point is on a line, we need to use our x and y values and place them in the equation, but this equation only has y, and any y!=7 would be false

[silent plank]

consider drawing a better diagram

[gritty hollow]

if I have a rectangle with the sides 10cm and 15cm, how can I make a function out of this? I need to derivative this function to find a maximum point, but how do I make a function if I only have 10cm and 15cm? Do I make it so x = 10cm and y = 15cm?

I should make a function for the volume of the rectangle*

[silent plank]

in use
also if you're supposed to use calculus, use an appropriate channel

[gritty hollow]

sorry new to this discord, I'll ask it there

[surreal vector]

like this?

[silent plank]

no

start with the cartesian plane

[surreal vector]

I only know one point tho

[silent plank]

then draw the line y=7,

and plot the point (2,3)

[surreal vector]

oh, is y = 7 = (0,7)?

[silent plank]

no, y=7 is a horizontal line

y=7 for all values of x

[surreal vector]

oh ok

[silent plank]

and A is a point on that line

[surreal vector]

where do I put A? or it doesnt matter?

I don't know if its in the positive or negative side of X

[silent plank]

it mentions its somewhere in the first quarter/quadrant

i.e. where both x and y are positive

[surreal vector]

but isn't that line infinite? across the X axis

ohh I see, first quadrant means of the plane and not the line

[silent plank]

that indicates that the x-coordinate of A is positive,
and you are supposed to use appropriate methods to determine its value

[silent plank]

label the axes and the y-value of the line

[silent plank]

let the coordinates of A be something like
(x_A, y_A) and apply distance formulae

[surreal vector]

sorry isp crashed

isn't this what I did earlier?

oh wait I think I understood

[silent plank]

i'm having some difficulty telling your 7s and ys apart

[surreal vector]

theres no 7's in the last picture

only y's

there's no 7's at all when I come to think of it

[silent plank]

using y-y like that is a bit dodgy

[surreal vector]

well that's the y of the y axis and y of the point A

[silent plank]

as well as the use of x and y themselves

[surreal vector]

this is what I got so far with the new plane

[silent plank]

to specify they're the x and y coordinates A, you should use appropriate subscripts

also from that information, the y-coordinate of C is 7

[surreal vector]

like that? y of A

C is a given point (2,3) from the question