geometry-and-trigonometry

[silent plank]

look at where x and y are marked and those pretty colours

[cedar tendon]

yea

i did

and what?

[silent plank]

that's what x and y represent...

[cedar tendon]

i don't know what is represent in the image

[silent plank]

is this the image you're looking at:

[cedar tendon]

yea

[still pendant]

Alright so I have a test due tomorrow, and it was given to me today, I look into it today, and Its on some more advanced PRE-AP Geometry and not Normal Geometry, and i'm already struggling with normal math. Is anyone willing to help me in depth on how to do the questions?

[cedar tendon]

oh

[silent plank]

post in an open channel

[still pendant]

This test was given to me as a saving grace by my ap in order to help me not go to summer school

[cedar tendon]

ramonov but how am i supposed to do this if it a decimals

decimals are hard

to

do

[silent plank]

it doesn't matter if its in decimals

they're still numbers

[cedar tendon]

u don't understand decimals has alway been my one and only weakness in math

[silent plank]

align decimal points when adding or subtracting decimals

add trailing zeroes if needed

[cedar tendon]

ok

so can at least tell me the the steps

[silent plank]

given the diagram above,
substitute in the labels/values being presented in your problem.

https://cdn.discordapp.com/attachments/326138757474680852/717864982410297445/Screen_Shot_2020-06-03_at_9.21.26_AM.png

what's the external angle here?

[cedar tendon]

32.9

[silent plank]

what's the smaller arc?

[cedar tendon]

ac

[silent plank]

no

[cedar tendon]

39.3

[silent plank]

the smaller arc is 39.3

what is that represented as in the theorem

[cedar tendon]

ok

[cedar tendon]

@silent plank but we don't know what is x

in the theorem

[silent plank]

arcAC will be your x in the theorem

i.e. what you are trying to find

[cedar tendon]

ok

im trying to find the answer

[silent plank]

that's incorrect

you calculated a value that is less than the smaller arc so its clearly wrong

show all you work

[cedar tendon]

dude im trying

[silent plank]

show all you work

[cedar tendon]

ramonov isn't the arc less than 90 degreee

[silent plank]

the arc AC? not in this case

[cedar tendon]

ok

[silent plank]

like work through the problem here

instead of going off for 15 minutes and coming back with 0 progress

[cedar tendon]

dude im trying to give a better help

[silent plank]

https://cdn.discordapp.com/attachments/326138757474680852/717902842228113519/unknown.png

what's the expression for the external angle here (in terms of x and y)?

[cedar tendon]

we do not know what is x

[silent plank]

doesn't matter

that's why i'm saying " in terms of x and y"

if x isn't known yet, leave it as x and it will end up something you end up determining by solving the resultant equation

[cedar tendon]

ok

y is 39.3

[silent plank]

also not answering the question i'm asking

[cedar tendon]

what is the question

than

[silent plank]

what's the expression for the external angle here (in terms of x and y)?

[cedar tendon]

1/2 (x -y)

their

[silent plank]

ok good

and what numerical value are you given for it

[cedar tendon]

the y

[silent plank]

no

the external angle isn't y

[cedar tendon]

oh yea

[silent plank]

also not a number

[cedar tendon]

ok

[silent plank]

?

[cedar tendon]

ramon so 32.9

[silent plank]

so you can starting with something like: $\frac{1}{2} (x\deg - y\deg) = 32.9\deg$

[somber coyote]

ramonov:

[silent plank]

and like you said, y° = 39.3°

[cedar tendon]

yea

[silent plank]

arcAC will be your x

[cedar tendon]

ok

so what i do

[silent plank]

sub that in

[cedar tendon]

i did

[silent plank]

what do you have now?

[cedar tendon]

i have 39.3 - x = 32.9

[silent plank]

do did you get from:
$\frac{1}{2} (x\deg - y\deg) = 32.9\deg$ where $y = 39.3\deg$ to that?

[somber coyote]

ramonov:

[silent plank]

literally just replace y with 39.3°

and do nothing else

[cedar tendon]

y is 39.3

i did replace it

[silent plank]

$\frac12 (x \deg - 39.3\deg) \wthonk 39.3\deg - x\deg$

[somber coyote]

ramonov:

[cedar tendon]

i told you. we do not know what is x

[silent plank]

if x isn't known yet, leave it as x and it will end up something you end up determining by solving the resultant equation

and that isn't what i'm even point out atm

[cedar tendon]

ok

[silent plank]

after you SUB y = 39.3°, you should have what's on the left for the left side

HOW the fk did it end up turning into 39.3° - x

[cedar tendon]

because we need x in order to divide

we can't divide without x

[silent plank]

not what I'm saying

[cedar tendon]

ok

[silent plank]

when you sub $y = 39.3$ into $ \frac{1}{2} (x\deg - y\deg)$ you get $\frac12 (x \deg - 39.3\deg)$ right?

[somber coyote]

ramonov:

[cedar tendon]

yea

[silent plank]

and that's all i wanted at that point

but that also begs the question of how the fuk that turned into
39.3° - x°

anyway, right now you should have:

$\frac{1}{2} (x\deg - 39.3\deg) = 32.9\deg$

[somber coyote]

ramonov:

[silent plank]

and then solve by applying the same operations to both sides to work towards isolating your variable x

[cedar tendon]

so i should add them both

and which side should i add

[silent plank]

same operations to both sides

[cedar tendon]

so i should add 39.3 + 39.3

and do the samething with 32.9

[silent plank]

what would you be doing 39.3 +39.3?

[cedar tendon]

u just told me add them both

[silent plank]

when?

[cedar tendon]

u did

[silent plank]

where?

[cedar tendon]

and then solve by applying the same operations to both sides to work towards isolating your variable x(edited)

see

what

it didn't

[silent plank]

that didn't say anything about adding both "39.3"

[cedar tendon]

ok

[silent plank]

e.g. multiply (or divide) both sides by something to get rid of the fraction first

(would be an appropriate step towards helping isolate x)

[cedar tendon]

WAIT

I CAN DO THAT

wait i can mutiply both sides by 2

Ramonov

can i?

[silent plank]

yes that is what i implied

[cedar tendon]

i thought u told me i'm not supposed to mutiple both sides

[silent plank]

no i clearly said do the same shit to both sides

[cedar tendon]

OK

[silent plank]

eg lets start with 1 = 1
why not only multiply the left side by 3.
3= 1 is clearly true right?

[cedar tendon]

78.6 and now 32.9 x 2 is 65.8

i did

it

on both sides

[silent plank]

wtf is happening?

[cedar tendon]

i did the same as u suggestion i mutioly 39.3 x 2 and i got 78.6

[silent plank]

that's not what i suggested

[cedar tendon]

what

it not

[silent plank]

multiply both sides of the equation by 2

[cedar tendon]

and i did

[silent plank]

$2 \times \frac{1}{2} (x\deg - 39.3\deg) = 2\times 32.9\deg$

[somber coyote]

ramonov:

[cedar tendon]

u multilay 39.3 x 2

oh

i see

nvm

4 and 65.8

i got

[silent plank]

$2 \times \frac12 = ?$

[somber coyote]

ramonov:

[split geyser]

you seem to have several huge misconceptions about basic algebra. we saw those earlier, and we're seeing them again now. You should go back and review your fundamentals before you do more of this

[silent plank]

the whole reason we decided to multiply by $2$, and not any other number like $e^\pi$

[somber coyote]

ramonov:

[cedar tendon]

wait if 1/2 x 2 it equal 1

[silent plank]

don't use x for multiplication in plain text

[cedar tendon]

ok

[dark sparrow]

congrats @split geyser you're like the 5th person to say exactly that

[silent plank]

probably my last time trying to "help"

[cedar tendon]

ramonov what i need to do next

[silent plank]

what do you have now?

[cedar tendon]

i have the problem

u said

[silent plank]

after multiplying both sides by 2, what do you have after simplifying that step AND ONLY THAT STEP?

[cedar tendon]

i have 1 and ( x - 39.3) = 78.6

[silent plank]

wdym by you have "1 and"?

[split geyser]

@dark sparrow I'm well aware lol. That was the "we saw those earlier". This person clearly won't listen though, so idk why I wrote it

[cedar tendon]

2 * 1/2 = 1

[dark sparrow]

don't use x for multiplication in plain text

[silent plank]

don't use x for multiplication in plain text

[dark sparrow]

ninja'd

[silent plank]

did you add that to your macros?

[cedar tendon]

what is a macros?

[silent plank]

as in: $1 ( x\deg - 39.3\deg) = 78.6\deg$? \
writing the 1 there is completely unnecessary

[cedar tendon]

oh yes

I HAVE

[somber coyote]

ramonov:

[silent plank]

and then continue to solve

by applying the same operations to both sides to work towards isolating your variable x

[cedar tendon]

Ramonov if this is an linear equation i mean i solve 5 linear equation problems but right now that problem is way much harder than problem i did with linear equation

because i did word problems

that is numerical

linear equation]

so that problem is harder than ones i did before

[silent plank]

just treat variables (that represent numbers) like any other number

[cedar tendon]

i can't i on ly practice with word problems

that different than this

but i. will try

to do it

so 1 - 39.3 = 78.6

[silent plank]

where'd the x go?

[cedar tendon]

i forget the * because * is to hard for me

[silent plank]

no like your variable x that you're trying to determine

[cedar tendon]

oh the x

so imma x - 39.3

[silent plank]

where's the rest of it

[cedar tendon]

1(x - 39.3) = 78.6

[silent plank]

writing the 1 there is completely unnecessary

[gray mason]

(at this stage, let him get away with it)

[gritty tangle]

What about writing

1.0

[cedar tendon]

ok

[gritty tangle]

1.0(x - 39.3) = 78.6

It is much better now

[silent plank]

we need to get rid of it and the parentheses to be able to continue

[cedar tendon]

ok

[gray mason]

Quick question: have you taken algebra 1?

[cedar tendon]

andrew who?

[gray mason]

You.

[cedar tendon]

im currently in algebra 1

the server just put me in this channel for some reason

[silent plank]

rewrite the equation without that unecessary 1

[cedar tendon]

ok

(x - 39.3) = 78.6

[silent plank]

parentheses are also unecessary

[gritty tangle]

what about x - 39.3 = 78.6

[cedar tendon]

oh hi ms. M

[silent plank]

then continue to solve by applying the same operations to both sides to work towards isolating your variable x

[cedar tendon]

-ok

i. got one question ramonov is 39.3 a negetive number now is it positive still

[silent plank]

what?

39.3 is a postive number that is being subtracted from x atm

[cedar tendon]

ok

so imma just keep mutiplying 39.3 x 2 and the same will go for 78.6

[silent plank]

right now you have something like thia right?

x - 39.3 = 78.6

[cedar tendon]

yea

[silent plank]

why would you do any more multiplication

[cedar tendon]

u said the same goes for side

[silent plank]

the left side looks very close to x

[cedar tendon]

both side

[silent plank]

i mean you can multiply both sides but pi^pi if you want,but that doesn't help you isolate x

[cedar tendon]

ok

so i divide

both sides by 2

[silent plank]

why would you divide by 2?

[cedar tendon]

idk

geez

im tryna

[silent plank]

which just undoes what you did a step earlier

[cedar tendon]

help

[silent plank]

the left side looks very close to x

what could you do to:
x - 39.3 to get just x?

[cedar tendon]

imma just subtract x - 39.3

[silent plank]

what does that even mean

[cedar tendon]

fine

[silent plank]

that's the expression you have

what could you do to:
x - 39.3 to get just x?

[cedar tendon]

imma just divide 39.3 by both sides

[silent plank]

$\frac{x - 39.3}{39.3} \neq x$

[somber coyote]

ramonov:

[cedar tendon]

yea

[silent plank]

think of some WAY simpler

[cedar tendon]

i need to do the same thing to 78.6

[silent plank]

think of what to do first:

what could you do to:
x - 39.3 to get just x?

[cedar tendon]

78.6 / 39.3

[silent plank]

what could you do to:
x - 39.3 to get just x?

[cedar tendon]

oH

SUBTRACT

BOTH SIDES

39.3 - 39.3

[silent plank]

huh?

[cedar tendon]

and samething with 78.6

subtract

[silent plank]

$x - 39.3 - 39.3 \neq x$

[somber coyote]

ramonov:

[cedar tendon]

yea

ramonov u are right

[silent plank]

i realised i may have made a few for the rhs because i copy and pasted stuff

[soft gulch]

Have you try adding 39.3 to both sides

[cedar tendon]

we can't

ramonov said it close to x

[silent plank]

by "close to x" i meant you only needed a simple step to get to x

such as "adding 39.3" to both sides

which is a legitimate valid step

and

[cedar tendon]

oh

[silent plank]

$x - 39.3 39.3$ does indeed equal $x$ which is what you want

$x - 39.3 + 39.3$ does indeed equal $x$ which is what you want

[somber coyote]

ramonov:

[cedar tendon]

but that is 78.6

[silent plank]

what is 78.6?

there were a few typos originally, don't know how that happened

anyway,

[cedar tendon]

ok

ramonov

so what ido

now

[silent plank]

can you repost the original values

i don't want to scroll up

[silent plank]

$\frac12 (x - 39.3) = 32.9 \
2 \times \frac12 (x - 39.3) = 2 \times 32.9 \ \
x - 39.3 = 65.8$

[somber coyote]

ramonov:

[silent plank]

$x - 39.3 + 39.3 = 65.8 + 39.3 \ x = ~~ ?$

[somber coyote]

ramonov:

[silent plank]

(fk was copying the incorrect value of 78.6 for the rhs for an hour)

[cedar tendon]

ok

ranmonov

so i just add 39.3 + 39.3

and 65.8 + 39.3

right

i got 458.8

[ebon sundial]

have you taken algebra 1?

[cedar tendon]

oh hi mr. Tai

who

wereu talking to

[ebon sundial]

you

[silent plank]

458.8
how?

[cedar tendon]

65.8 + 39.3 = 458.8

[silent plank]

,w 65.8 + 39.3 = 458.8

[somber coyote]

Display results online and refine query

Requested by ramonov#0921

[cedar tendon]

oh

i got 105.1

[silent plank]

thats better

[cedar tendon]

@ebon sundial im currently in algebra 1 but server put me in this channel for some reason

[ebon sundial]

(x - 65.8) = 105.1
It is much better now

[silent plank]

(x - 65.8) = 105.1
whut

x - 39.3 + 39.3 = 65.8 + 39.3
x = 105.1
is fine

[cedar tendon]

ok

[ebon sundial]

@cedar tendon why your name is called math is so hard?

[cedar tendon]

mr.tai who?

[ebon sundial]

you

[cedar tendon]

because math is so hard for me

[ebon sundial]

@gritty tangle @gray mason come on here

[gritty tangle]

?

[ebon sundial]

it math is hard again doing it

[cedar tendon]

huh?

[ebon sundial]

lets help out ramonov real quick ms. M

[cedar tendon]

Ramonov what do i do next

[silent plank]

that's it

x represents the arc measure of AC (in degrees)
and you found x

[cedar tendon]

yes

i found it

[silent plank]

then you're done

[ebon sundial]

Ramonov

[gritty tangle]

?

65.8 + 39.3 = 458.8

[azure reef]

,calc 458.8-39.3

[somber coyote]

Result:

419.5

[azure reef]

,calc 419.5-65.8

[somber coyote]

Result:

353.7

[gritty tangle]

commander vines

[azure reef]

????

[gritty tangle]

you left me yesterday

[azure reef]

probably had to go

[gritty tangle]

it's ok

Can you help me with some questions now?

If you are free

[azure reef]

sure

[dark sparrow]

wrong channel.

this goes in #advanced-analysis.

[ebon sundial]

I'm so glad that math is hard is gone for good this time the server can be at peace for right now

[snow estuary]

?

[dark sparrow]

!

[snow estuary]

huh

[dark sparrow]

you didn't tell us what you tried or where you're stuck or what's troubling you

[snow estuary]

the whole thing

i think x is 6

[dark sparrow]

ok, why do you think x is 6?

and what's making you uncertain about it?

[snow estuary]

idk

im just dumb

[dark sparrow]

that does not answer my first question

[snow estuary]

my friend told me x is 6

bc x squared eequals 36

is y the square root of 180?

[dark sparrow]

yes

[supple wedge]

lmao

[wooden current]

smh

[cedar tendon]

I NEED HELP AGAIN

[wooden current]

😳

The length of what

[cedar tendon]

we have to find the length

[upper karma]

of what

[wooden current]

smh my head

[upper karma]

this dudes questions are always so cringe worthy

[cedar tendon]

idk the teacher only gave us 8

for the radius

[wooden current]

your teacher must be insane

[upper karma]

i get that

but what length are you supposed to find?

[cedar tendon]

idk

[upper karma]

well there you go

thats the problem

[cedar tendon]

find imma go to the next question

[upper karma]

will the next question be as vague?no

[wooden current]

Bruh

[cedar tendon]

yes this is the next question

[wooden current]

That is literally elementary stuff

How the hell do you not know how to do this

[cedar tendon]

wiat

what is elementary stuff?

[wooden current]

😤

[cedar tendon]

OH

u mean

[wooden current]

Do you recall what a chord is?

[cedar tendon]

i forgot

[wooden current]

[cedar tendon]

can. u tell me again

so i can remember

[wooden current]

Look. What do you think a chord is? ( hint: connects something )

[cedar tendon]

man

[wooden current]

😐

[cedar tendon]

lemme think

[wooden current]

Ok

[cedar tendon]

a chord is passing through the center of the circle

i think

[versed aspen]

bruh

[upper karma]

no

[wooden current]

Do you see the chord in that picture pass through the center?

Use the picture

[versed aspen]

If you don't even try to remember and practice stuff, nobody here can help you.

[upper karma]

@cedar tendon you are correct

@cedar tendon but not always

bruh this dude isn't learning anything smfh

@cedar tendon a chord can pass through the center, but it does not have to

[wooden current]

I mean it's a special case

[upper karma]

all a chord is

is just two points connected on a circle

[wooden current]

^

[upper karma]

it can pass through the center just fine

but doesn't have to

the diameter however has to pass through the center

and the diameter is a special case of a chord

[wooden current]

oof

you gave math the answer too easily

[cedar tendon]

ok

[wooden current]

Now let's go back to the problem

Which segment do you think is a chord?

[versed aspen]

you gave math the answer too easily
So their name is officially math ?

[wooden current]

i mean

[versed aspen]

yeah whatever I get it

[wooden current]

Would you say "MATH I GIVE UP MATH IS SO HARD"

[cedar tendon]

dude their mutiple chord

idk

which one is

i think it JH

[wooden current]

We can't just tell you the answer without you putting effort into solving the problem

Well you are right

But it's not an option in the list

Think of another one

[cedar tendon]

see

their mutiple chord

that why it is hard

to find out which one

it is

so i think gf

[upper karma]

theres only 1 chord

[cedar tendon]

so is it gf

?

[silent plank]

math is case sensitive

[upper karma]

yes its GF

[silent plank]

gf is not the same as GF, but GF is indeed a chord

[cedar tendon]

is dh radius dan

[silent plank]

yes, DH is a radius

[cedar tendon]

i need help finding the right angle

i don't see it in the image

[silent plank]

properties of a tangent

[cedar tendon]

wait i found it

it edj right

?

[upper karma]

yes

[silent plank]

wait

you can't assume that

[cedar tendon]

im just guessing

[upper karma]

math, is that one of the options?

[silent plank]

from what i can see in that diagram, there is insufficient info to conclude that

[silent plank]

there is however one angle there that is definitely 90°

[cedar tendon]

so which those option is the answer ramonov

i need the answer

[silent plank]

!r7

[cosmic pebble]

From

#❓how-to-get-help

Rule 7

When asking for help, do not insist on getting just the answer; we are here to help you learn, not cheat. Likewise, if you are providing help to others, try your best to explain and elaborate instead of simply giving away the answer.

[silent plank]

properties of a tangent

[cedar tendon]

ok

ok

so what i do

ramonov

[silent plank]

do you know the properties of a tangent to a circle?

[cedar tendon]

yea

[silent plank]

list some

[cedar tendon]

the tangent line never crosses a circle

it just touches the circle

[silent plank]

do you know anymore?

[cedar tendon]

at the point of tangency it is perpendicular to the radius

[silent plank]

perpendicular

that sounds like it has something to do with right angles

[cedar tendon]

what

it does

oh djL

DJL

[upper karma]

what does "DJL" even mean?

Davy Jones Locker?

[idle bloom]

read above

it's an answer choice in reference to an angle

[cedar tendon]

ok

[upper karma]

then he should've specified "angle DJL"

I just joined the chat and I was like wut?

[wooden current]

[silent plank]

do you know you circle theorems?

there is one specifically about bisected chords

[upper karma]

@upper karma inscribed angle theorem

yah the perpendicular one seemed kinda obvy

Yeah

big brain whats g

Eyey

Wait

bc they wanna trick you

Am i tripping and arc measurement isnt the same as arc length? @upper karma

arc measurement and arc lenght are different

arcm easurement is degrees

arc length is lenght

Then its not 60

[upper karma]

Im pretty darn sure is using the sector of a circle

Yeah exactly lmao

well find the circumference of the circle

@upper karma you have r and theta

You can guess whats theta lol

30°

lmao

[graceful lily]

d/2 = r

[upper karma]

Yes it is 30°

https://cdn.discordapp.com/attachments/326138757474680852/718203304567504936/arc_length.png

s is what you are looking

0?

[wooden current]

isnt theta for central angles?

wouldn't theta be 60 degrees

[upper karma]

True

No, Dan is right

[wooden current]

😭

[upper karma]

@wooden current you are right

[wooden current]

Hello

[upper karma]

dan is bae

@upper karma dont do 10 times 30

[wooden current]

Omg this is the first time I'm right in my entire life

[graceful lily]

😄

[upper karma]

:)

10 times the double of 30

Are you asking me lol

[graceful lily]

yes

[upper karma]

Yeah

[graceful lily]

how do we know that 60 is the central angle degree?

[upper karma]

bc 30 is the given angle

so 30 * 2 = 60

the arc length you calculated doesn't look right imo

[graceful lily]

ah ya i see it now

[upper karma]

bc the circumference is 20 pi

which is about 628

and CD looks a lot less than the entire circumference

Might not be to scale

[wooden current]

shouldn't theta be in radians ?

[upper karma]

Hm let me see

yah i guess

Yeah thats what i was thinking

@upper karma this is why its 30 * 2

@upper karma do you know how to get angle to radians

[graceful lily]

like that rent free?

[upper karma]

[graceful lily]

did you get it right?

😦

oh well

did it give an answer for it?

oh well

[upper karma]

i just guesssed
If you guess then dont expect it to be right

wait so did u put 600 as the length

,ask 60° to radians

[somber coyote]

Display results online and refine query

Requested by Al𝟛dium#4084

[upper karma]

,calc pi*10/3

[somber coyote]

Result:

10.471975511966

[upper karma]

This was the ans @upper karma

this is what i got as well

[wooden current]

oof

sorry 😭

[graceful lily]

it was kind of a tricky question

[violet sun]

How do I add a vertical and horizontal translation to this equation?

[upper karma]

https://gyazo.com/aa19f20173257cacc63fe5aa44abfe79

can sum1 help

[wooden current]

Area of circle - Area of hexagon

Apply formulas and done

[upper karma]

👍

[marsh plover]

@violet sun for any y=f(x), a vertical translation of C is achieved by f(x)+C, and a horizontal translation is f(x-C)

[cedar tendon]

guys

is it dJL

[wooden current]

@marsh plover yea but that is polar coordinates

not the same as cartesian coordinates

[marsh plover]

ah, true, my bad

[wooden current]

😭

[marsh plover]

waaah

[wooden current]

I don't know how you can translate polar functions doe

[cedar tendon]

is it djl

[wooden current]

what

[ebon sundial]

OMGOSH

he is back

math

i give up

[marsh plover]

wait, we all love math here, right?

that's why I'm here

[ebon sundial]

not you

it that math i give up guy

[marsh plover]

sad but true story, the mathematicians in my grad program actually said "when will I ever use this"

[cedar tendon]

Guys so is it djl

[marsh plover]

I was so depressed when I heard them

[wooden current]

😦

[ebon sundial]

@cedar tendon your in algebra go back to the algebra channel

no one wants you

here

you a despointment to me and dancastan

[marsh plover]

back to the polar problem

[cedar tendon]

what

[marsh plover]

cart -> polar is...

[cedar tendon]

so i supposed to go back to the algebra

[marsh plover]

x=rcos0

[ebon sundial]

Yea

[marsh plover]

y=rsin0

[ebon sundial]

@wooden current tell math to go to <@&689987404085723258> so they can answer his question

[wooden current]

I mean

His problem involves geometry

[cedar tendon]

what?

[wooden current]

Cant do anything about that

@cedar tendon post the problem again

[ebon sundial]

but he in algebra

[idle bloom]

??????

[idle bloom]

you a despointment to me and dancastan
@ebon sundial

No need to be an asshole

[wooden current]

What have you solved so far?

[idle bloom]

Also that's fucking geometry

[cedar tendon]

im on the right angle

still

[marsh plover]

a horizontal translation of C is x = rcos0 + C

how do you start a new paragraph?

[wooden current]

Recall that the angle between a tangent to a circle and a radius of that circle intersecting that tangent is 90 degrees

[ebon sundial]

but he told us he in an algebra class so why is he in this channel

[marsh plover]

and a vertical translation is y = rsin0 - C

can anyone verify?

[idle bloom]

God forbid someone in algebra has to do some geometry as well not everything is so cut and dry

[marsh plover]

those are just definition questions, barely counts

[cedar tendon]

guys is it dlj

i ment

djL

is it djL

[wooden current]

Yep. The radius DJ intersect tangent JL so the angle is 90 degrees

[cedar tendon]

ok

[wooden current]

?

[cedar tendon]

what am i supposed to do

[wooden current]

How should I know

I'm not the one that has been assigned this

[cedar tendon]

ok than imma go the next question

[wooden current]

Ask your teacher about this

There's no way you can solve this

[upper karma]

do u not know what a right angle is?

smfh

[ebon sundial]

man i don't know why we even help that guy

he should go back to algebra

he a disappointment here

[wooden current]

Why Algebra

😳

[upper karma]

what a wonderful concept

4

ok

lol

[marsh plover]

ok, so the conversion formulas should be...

$r=\sqrt{(x-c)^2+(y-c)^2}$

[somber coyote]

GenFrogKing:

[cedar tendon]

need help

with this

[marsh plover]

$\theta = tan^{-1}\left(\frac{y-c}{x-c}\right)$

[ebon sundial]

that problem is in algebra

see

[somber coyote]

GenFrogKing:

[worthy igloo]

@ebon sundial please don't be disrespectful to other people

[cedar tendon]

help me

someone

[upper karma]

im here

@cedar tendon what

remember me

i can help u

send

[cedar tendon]

ok

[upper karma]

well what do u thinl

think

do u know what each of them mean?

Pi, arc length, radians and central angle

have u learned this stuff yet?

@cedar tendon

[cedar tendon]

i think i did

[upper karma]

what are radians then?

@cedar tendon

[cedar tendon]

i haven't learn that

[upper karma]

and that explains why

u should learn about radians

since thats another way of measuring angles

ill find a video for u

[cedar tendon]

ok

[upper karma]

@cedar tendon Do u know what is pi, arc length and central angles tho?

https://www.youtube.com/watch?v=cgPYLJ-s5II

https://www.youtube.com/watch?v=EnwWxMZVBeg

https://www.youtube.com/watch?v=JmLN3QxshlE

these are a couple good videos explaing radians

@lilac thicket Hola

[cedar tendon]

ok

[upper karma]

Sure can u send it again?

[marsh plover]

@lilac thicket I'll take a look

What information does the problem give you? Is this a measuring or geometry problem?

the problem at least says it's a rectangle, right?

[upper karma]

ya idk

[marsh plover]

I'll assume the shape is a rectangle, I guess

ok ty

[upper karma]

@marsh plover does u know answer

i am also curious of answer

[marsh plover]

working on it

[upper karma]

cool

https://gyazo.com/6dff475194d6f38037dbf00775bf2f9a

@upper karma Try to imagine it rotating around that axis

see what shape it produces

im failing this class

[marsh plover]

@lilac thicket Did your class learn Law of Sines?

[upper karma]

bro i have like 20 absences

in this class

[marsh plover]

I think I'm overthinking it

[nova bone]

I think it creates a circle with the point furthest from the origin

when you rotate it

[marsh plover]

it definitely creates a cone

[upper karma]

@upper karma Cone with height of 3 and base radius 5

figure out why

thats all

thank u

it was a quiz

i guessed on it

and got 70%

it was a what now?

you're not supposed to ask for help on exams, friend

you can get banned

see #❓how-to-get-help number 6

@upper karma I didnt know

im sorry

he didnt tell me

[upper karma]

i’m sorry i didn’t know

[marsh plover]

@lilac thicket Can you please post the entire problem with the prompt?

[upper karma]

Rip

[brisk holly]

how does this make sense?

[upper karma]

theres 4 of them

https://www.desmos.com/calculator/jeokx4lif8

14.5 is outside the domain

[upper karma]

What

[lavish glacier]

#7

21 and 6

[upper karma]

Ok

[lavish glacier]

So how do i start?

Any suggestions?

[upper karma]

Google the volume of a cylinder

What does LA and TA mean?

[lavish glacier]

Length area and total area i think

Do u actually know how to do this?

[upper karma]

Google the surface area of a cylinder

[lavish glacier]

Ok

What does that give u?

[upper karma]

The total area , I presume

[lavish glacier]

Ok

La?

[upper karma]

LA is lateral area, notlength area

[lavish glacier]

Oh right

[upper karma]

That's the area of the long part

[marsh plover]

LA TA V

sounds close to cest la vie

[lavish glacier]

Cest la vie?

[marsh plover]

yes

[lavish glacier]

Que esa?

[marsh plover]

c'est la vie

[lavish glacier]

Idk?

[marsh plover]

so it goes

[lavish glacier]

Speak English pls

[marsh plover]

i think it's french, but getting back on track...

oh, it's already been answered

[upper karma]

Have u searched up the formulas

[lavish glacier]

Yeah

Do u actually know how to do this or not?

[upper karma]

Yes

What are the formulas you Have? Plug the appropriate number in each formula

[lavish glacier]

So how do i find la?

[upper karma]

Google the formula of the lateral area of a cylinder

[lavish glacier]

Ok

Thx

[upper karma]

Do you know what the area of a circle is?

Have you figured out the lateral area formula

?

It's 2 × pi × r × h

[cedar tendon]

ok i finish watching the video

now i need help

@upper karma

[upper karma]

Well if u watched the video u must know the answer now

[cedar tendon]

i mean i think it radian

[upper karma]

Yes

[cedar tendon]

is that right

[upper karma]

Ya

[cedar tendon]

now i need help with this

[upper karma]

Just apply your knowledge gained from the videos

Or did you not understand?

[cedar tendon]

i need help

[upper karma]

Did you understood the videos?

[cedar tendon]

yea i kinda understand it a little

[upper karma]

Try the problems

Have you atleast tried it first

[cedar tendon]

i mean don't understand what the question is talking about

[upper karma]

https://youtu.be/tMfeVClKjZg

I’m not gonna answer it for you

Learn and try

[cedar tendon]

oh yea i watched that

already

[upper karma]

You went on YouTube

And searched this?

[cedar tendon]

yea

[upper karma]

Ok what makes you confused

[cedar tendon]

the 2pie/9

idk what that means

[upper karma]

There’s a simple equation described in the video

Just apply that equation

And also try to understand why the equation works

It helps

[cedar tendon]

ok

[upper karma]

And what do you mean you don’t know what 2pie/9 means

@cedar tendon

[cedar tendon]

idk what the question is asking me to do?

[upper karma]

Convert them to degrees

@cedar tendon So do you understand?

Recall that there are 2 Pi radians in a circle

And just multiply them by 180/Pi

To convert them to degrees

[cedar tendon]

ok

[upper karma]

This isn't chill

[upper karma]

@upper karma hmmmmmm

[cedar tendon]

darn

it got deleted

well repost this

I need help with this question

[upper karma]

@cedar tendon Hello

U on

[cedar tendon]

yea\

i need hlep

how to do this

@upper karma

[upper karma]

is there supposed to be something at the top of that circle?

it looks like it's cropped out

[cedar tendon]

do you need the whole image

?'

[upper karma]

only if there's something at the top of the circle

if it's just a circle, no

[upper karma]

do they give you angle A?

[cedar tendon]

they gave what ever in the image

what they gave me

thatwhat

they gave me

[upper karma]

yeah, you're gonna have to eyeball it

[cedar tendon]

what eyeball mean?

[upper karma]

it means you're gonna have to judge this by simply looking at it

"throwing your eyeball on it"

"casting your eyes upon it"

lol

[cedar tendon]

they only gave us 4.2

[upper karma]

this would be a 90 degree angle

[signal sky]

Can someone give me a hand?

[cedar tendon]

OH

IT 180 DEGREE

angle

[upper karma]

do you think 8.4 and 2.1 are even close to 90 degrees?

[cedar tendon]

@upper karma it 180

[upper karma]

?

my dude

[cedar tendon]

it an obtuse angle

it more than 90 degree

[upper karma]

obtuse angle, yes

but where did 180 come from?

[cedar tendon]

so lets assume it 180

sense it is an obtuse

[upper karma]

why would you think it's 180?

180 is a flat line

[cedar tendon]

because that is an obtuse

[upper karma]

does it look like a flat line?

[cedar tendon]

so every obtuse angle is alway consider 180 degree

automaticlly

so it has to be 180

[upper karma]

obtuse angles can be 120 degrees

[cedar tendon]

what

it can?

[upper karma]

the very definition of obtuse means >90

[cedar tendon]

oh

i thought all obtuse angle is only 180 degree

[upper karma]

180 degree angles are called "straight angles"

[cedar tendon]

ok

[upper karma]

complementary angles are 0 - 90
supplementary angles are 90 - 180

[cedar tendon]

0ok

[upper karma]

acute angles are <90

obtuse angles are >90

270 is also an obtuse angle

[cedar tendon]

ok

[upper karma]

I guess you could say 180 is obtuse, as well

[cedar tendon]

that why the answer should be 114.6

@upper karma

[upper karma]

obtuse is >180, apparently

https://www.splashlearn.com/math-vocabulary/geometry/obtuse-angle#:~:text=What is obtuse Angle%3F,90° and 180°.

[cedar tendon]

yea and the answer should be 114.6

[upper karma]

well, it looks larger than 8.4 and 2.1 degrees, that's for sure

it's generally a bad idea to rely on these figures

because they try to trick you

but in this case...

I think that's what they want you to do (just look at it)

[cedar tendon]

need help

with this

one

[upper karma]

well, what would the length of arc YZ be?

in degrees, I mean

[cedar tendon]

ok

so how do i do this d spider

[upper karma]

you get the length of arc YZ (in degrees) and convert it to radians

https://youtu.be/GppOSNTi5OA?t=250

https://www.youtube.com/results?search_query=convert+angles+to+radians

^how to convert from angles to radians

[signal sky]

lel

[cedar tendon]

wow

bot is no go

[upper karma]

Yes I sent a video awhile ago too to this guy

2.25 is not an angle

On how to convert them

He should know it by now

[cedar tendon]

oh 45 is the angle

[upper karma]

yep

so if angle YXZ is 45 degrees...

what is the measure of arc YZ?

[cedar tendon]

i have to convert that into a degree

[upper karma]

what is the measure of that arc?

[cedar tendon]

ok

[upper karma]

in degrees

if angle YXZ is 45 degrees

https://youtu.be/GppOSNTi5OA?t=289

the measure (or length) of arc YZ is... ?

[cedar tendon]

so i gotta halve 180

[upper karma]

what happens if you halve 180?

[cedar tendon]

wait

noo

it 90

@upper karma the arc is 90

[upper karma]

why 90?

it's not an inscribed angle

[cedar tendon]

true

[upper karma]

point X is in the center

so angle YXZ is a central angle

not an inscribed angle

did you even click the video above?

can you figure out what that arc would be if the central angle would be 45?

[cedar tendon]

it an external angle

right

[upper karma]

it's not external, no

it's inside the circle

not outside it

(that's what "external" means)

[signal sky]

how do i find the area of a square?

[upper karma]

@signal sky https://www.google.com/search?q=area+of+a+square

[signal sky]

🙂

i thought it was 7

[upper karma]

for all squares in existence?

[signal sky]

obviously

[upper karma]

https://www.google.com/search?q=formula+for+the+area+of+a+square

Nice

[cedar tendon]

OH

IT 45

the arc is 45

[signal sky]

we cant have some squares bigger than others, that would be unfair