geometry-and-trigonometry

[lavish glacier]

How do ik what type of triangle this is?

[regal shell]

U can treat that like a regular cone too

[lavish glacier]

How would i find r?

[regal shell]

It’s a 3 4 5 triangle

[lavish glacier]

Oh i am muy stupido

What does 3 4 5 triangle mean again

But ik i can use pythag thm so i know how to get it

[upper karma]

Ya just use Pythagorean theorem

[regal shell]

Yeah basically since 16 and 20 are sides, the last side fits the 3 4 5 proportion

[regal void]

3^2 + 4^2 = 5^2

[lavish glacier]

Ok thx

Which is the base?

[upper karma]

You can consider any side as the base

Base times height

[lavish glacier]

Oki

(13x9)(3)

[upper karma]

@lavish glacier is this a test?

[lavish glacier]

No, es a hw assignment

[upper karma]

Okay

👍

[lavish glacier]

Okay

👍

[upper karma]

https://www.google.com/search?q=volume+of+triangular+prism

https://www.google.com/search?q=volume+of+triangular+prism&tbm=vid

[lavish glacier]

Is A corrct?( 10 x 8x 13) /2?

@upper karma

[upper karma]

what? no

maybe this will help: https://www.youtube.com/results?search_query=volume+of+triangular+prism

[lavish glacier]

Does it matter which base is which?

I used a formula

This is what I got

[upper karma]

but do you understand why?

this guy explains it pretty well: https://www.youtube.com/watch?v=G5Izs4wdor8

[lavish glacier]

Wouldn't it be 8 times 10 /2

Times 13?

[upper karma]

that's not how you get the height of the prism

[lavish glacier]

The height is 13 right?

[upper karma]

nope

it rhymes with Mythagora

once you have the area of that triangle (base * h), you multiply it by 13 Edit: and all / 2

like I said, watch the video

@lavish glacier Edit: Area of triangle: base * height * 1/2. And the area of the triangular prism: area of triangle * length. But it gets you the same result, so that's good

[lavish glacier]

Thx

I understand a little bit better now

[silent plank]

Area of a triangle is NOT bh

[upper karma]

Oh

[sage blaze]

I don't understand the second line

When they squared both numerator and denominator, how did they end up with 1-cos^2A in denominator?

[dark sparrow]

When they squared both numerator and denominator
no they didn't, and that's not something you can do to fractions in general without altering their value

$\frac{1-x}{1+x} = \frac{(1-x){\color{red}(1-x)}}{(1+x){\color{red}(1-x)}} = \frac{(1-x)^2}{1-x^2}$

[somber coyote]

Ann:

[harsh lintel]

to find the angle from cosine, is it arccos or secant

i forgot

[dark sparrow]

arccos

[harsh lintel]

aight thx

[dark sparrow]

sec(x) is 1/cos(x)

[harsh lintel]

o ok

[old orbit]

Question 1G

Note: Its theta not ‘0’

[dark sparrow]

what's giving you trouble here

[stone spoke]

This is a confusing question. Is it B?

Like this is a dumb question.

Either that or I'm not getting the point of it.

[eternal crag]

this channel is not free

[stone spoke]

This isn't a question channel Pube

[upper karma]

it's still not free

[eternal crag]

can you stop calling me pube

[stone spoke]

I didn't think it had to be free but alright. No worries, I'll wait.

[eternal crag]

this is the second time i'm asking you this, do you have any manner??

[upper karma]

go to #❓how-to-get-help

[stone spoke]

Alright.

[stone spoke]

Can someone check my answer?

[somber coyote]

Result:

29.935450997894

[versed aspen]

Oops

[upper karma]

@stone spoke may you show your work

[stone spoke]

Solved it. Thanks anyways!

[silent plank]

what have you tried?

[round valley]

my teacher didnt teach us trig

whatsoever

but started assigning us trig work

[silent plank]

do you at least know the basic trignometric ratios?

[round valley]

not at all

[silent plank]

that's a huge issue

so you haven't worked with single right triangles?
special angles?

don't know what sin, cos , tan are?

[round valley]

no

they didnt teach us any of it

[silent plank]

i.e. there's no point in trying to do with question without those foundations

[round valley]

they just showed the work to a question

and now im failing math

cuz i need to finish the workd he didnt teach

[silent plank]

since this is a midlevel problem

consider using some online resources like khan for the basics first

[round valley]

im sure we will re-learn all this shit at the start of next year

cuz we started this at the end of the year during quarantine

[silent plank]

yeh the state of things had a huge effect on education

[round valley]

i jus need this one done

so i can complete my homework for today

the other 8 i got help with frum sumone

[silent plank]

were they also trig?

[round valley]

yes

[silent plank]

oh... then you should at least have some idea of what sin,cos,tan do in the context of right triangles

[round valley]

i dont

[silent plank]

over 8 questions, those have to have been mentioned multiple times....
unless they did everything for you

but seriously, I highly suggest you attempt to learn the basics on your own as I'm not inclined to teach trig from scratch

(knowing some information about tan and a little algebra would be sufficient for this question)

(there's also a direct formula that you could apply which may or may not have been given, that I had initially intended to help derive)

[drowsy escarp]

could someone help me with this

my teacher never taught how to do a slanted cylinder ive never even heard of these before

[silent plank]

fun fact; it has the same formula for volume as a normal right cylinder

[upper karma]

just like a parallelogram is to a rectangle

[drowsy escarp]

oh wait fr

nvm thats so easy then lmao

[arctic zinc]

Hello , my brain is completly stuck so if i know the sin, how do i find the degrees ?

which in this case is 0,88

[silent plank]

$\sin(x) = 0.88$

[somber coyote]

ramonov:

[silent plank]

are you told anything about the angle (x)?

[arctic zinc]

no not rly , its about a problem in regarding electrical engineering and idk my brain is stuck , i got the sinφ which is 0,88 and i need to find the cosφ :/

i was thinking of getting the degrees first and then convert it to cos

[silent plank]

apply a pythagorean trig identity

and then use context to determine the appropriate sign

[fast charm]

can someone help, solve for x 2cos(x) + x = 0

[silent plank]

consider factorisation

wait

solve: x2cos(x) + x = 0
OR
solve: 2cos(x) + x = 0 for x

@fast charm

[fast charm]

The 2nd one

The 1st one is easy 🙂

[silent plank]

no nice way to do it

[fast charm]

Was afraid so

[silent plank]

graphically and get an approximation, use approximation methods

(should really belong in the calculus or general questions and not here)

[fast charm]

My sister, 12 grade, asked this so

Thats why i didnt put in calculus

But yeah, thanks anyway

[silent plank]

if its yr12 sounds like calculus

[fast charm]

Well, here we get calculus in college like i did

[brisk ginkgo]

I need help!

<@&286206848099549185>

[silk crown]

dont we all

not sure how to help you if you dont post your question though

[brisk ginkgo]

@silk crown

[upper karma]

@brisk ginkgo Very easy

[brisk ginkgo]

And this pls!!!

[upper karma]

find the circumference of the circles

@upper karma U explain

I cannot explain

welp

ill try

ok

so

Yea go for it

[brisk ginkgo]

Thank u

[upper karma]

find the circunference of the circle,

then u multiply the length of the curve given

with 360

so take the length of the curve, multiply it with 360, then divide it by the circumference of the circle

and boom theres ur answer

[silent plank]

wait

[upper karma]

yah ik

[silent plank]

that was extremely confusing

[upper karma]

we're finding the arc measure

lol wut

its not

[brisk ginkgo]

Ok so I need to find the circumference

[upper karma]

yes find the circunference

[silent plank]

wait there's 2 questions

didn't see the first one

[brisk ginkgo]

So that’s 23.1410? @upper karma

[upper karma]

yes

[brisk ginkgo]

Oh wait shit

[upper karma]

20 pi

[brisk ginkgo]

What happens

So that equals to 20?

@upper karma

[upper karma]

20 pi

[brisk ginkgo]

20 * 3.14?

[upper karma]

which is about 62.8

ok now you take the length of the curve

and multipley it with 360

[brisk ginkgo]

That’s like 22,608 @upper karma

Divide by 145?

I get like 155 I can’t round that number to somewhere tho

[upper karma]

um how did u get 22,068

[brisk ginkgo]

@upper karma I multiplied 62.8 * 360

[upper karma]

u don't multiply 62.8 with 360

[brisk ginkgo]

Oh

[upper karma]

u multiply the length of the curve (8.7) with 360

Go rent :)

big brain

Big brain gang

[brisk ginkgo]

Ohhh

[upper karma]

yeet

[brisk ginkgo]

So I got 3,132 @upper karma

Do I then dived by 145?

[upper karma]

no

divide by 20 pi

[silent plank]

145° was part of a completely different question

[upper karma]

oh wtf are you talking about the 2nd question? im talking about the first oone

LMAO

[brisk ginkgo]

OH

Sorry I was looking at the wrong thing oh my god

@upper karma

Ur good

[upper karma]

no u

[brisk ginkgo]

No I need help in the first one

[upper karma]

ik lol

[brisk ginkgo]

I dived by 20 * 3.14

[upper karma]

yah thats rigjht

so whats ur answer

[brisk ginkgo]

What the heck

I got 196 @upper karma

[upper karma]

your answer should be : (360 * 8.7 / 20pi)

which yields 49.8

[brisk ginkgo]

Oh wait

I think dived it wrong then lol

Thank u!

@upper karma

The second problem

I need help in aswell

[silent plank]

did you label that correctly?

radius is in feet while answers are in km

[brisk ginkgo]

Yeah @silent plank

Yeah ik I labeled

[calm lintel]

does anyone know how to find the volume of this shape 😭

[silent plank]

in use

[upper karma]

my wifi is sus rn

for the 2nd question you have to find the circumference of the circle, then multiply it by 145

then divide by 260

and boom theres ur length

[brisk ginkgo]

So I do 23.1412? @upper karma

[upper karma]

yes

[brisk ginkgo]

Oh it answered for me

[upper karma]

then multiply that by 145

then divide by 360

@calm lintel google the volume formula and plug in the correspnding values

remember the top is a hemisphere so its only half the volume of a sphere

[brisk ginkgo]

@upper karma 30.4 thank u!

[tiny rune]

Guys I have one question if you have time

[upper karma]

np 🙂

@tiny rune Yea

[tiny rune]

So text is on my language but I can translate that to english hold on

[brisk ginkgo]

I found the circumference to this but now I need to find the area @upper karma

I do the same thing right

[silent plank]

just apply formula for area

[upper karma]

u don't need to find the circumference for this one

@brisk ginkgo

just multiply the radius with 2 pi

[brisk ginkgo]

Ik

[upper karma]

then bobs your uncle

[brisk ginkgo]

3.14 * 2 * 5.8

[upper karma]

36.4

[tiny rune]

So it says that there is a triangle ABC. AK is Bisector. AB=8cm AC=10cm and BC=14cm. Calculate length of BK and KC. I can draw that triangle as well

[brisk ginkgo]

Thank u!

[upper karma]

np

[brisk ginkgo]

Last one!!! Lol @upper karma

[upper karma]

ight so u need to find the area of the whole circle

[brisk ginkgo]

@upper karma do I use area of a circle formula?

[upper karma]

ye

[brisk ginkgo]

So 3.14 * 20 * 2? @upper karma

[upper karma]

pi * r ^ 2

so pi * 20^2

[brisk ginkgo]

1,256

@upper karma

[upper karma]

yes

now multiply that by 20

[silent plank]

just multiply the radius with 2 pi
gets the circumference and is not the method for finding area

[brisk ginkgo]

25,120 @upper karma

[upper karma]

ok

[brisk ginkgo]

I have to find the area of the shaded region @silent plank

[upper karma]

now divide by 360

@tiny rune AK is bisector of what

and boom theres ur area

[tiny rune]

@tiny rune AK is bisector of what
@upper karma Of that triangle

[brisk ginkgo]

I GoT IT

THANK U

[silent plank]

the comment was addressed at the previous question

[brisk ginkgo]

@upper karma

[upper karma]

np

@tiny rune draw it

[tiny rune]

@tiny rune draw it
@upper karma Sure

[silent plank]

ie. you were told to (re)calculate the thing you said that you calculated that you weren't supposed to

[upper karma]

ill draw u @upper karma

Lol

@tiny rune post it when you are done drawing

[upper karma]

well if its a bisector there are 2 90 degree angles right

[tiny rune]

BK and KC was question

[upper karma]

,rccw

[upper karma]

Uhhh

ayy big brain knows

[silent plank]

what type of bisector?

[upper karma]

what i wanted

Lol

[tiny rune]

what type of bisector?
@silent plank I think angle here doesn't matter.

[upper karma]

$\angle{AKC}=\angle{AKB}=90$

Which you should have indicated

u need to find the height of the bisecting line

[silent plank]

wait what?

[upper karma]

so AK

[silent plank]

it's they're not 90° angles

[tiny rune]

not Height tho Length

And angles aren't right path I'm sure

[upper karma]

@silent plank wdym tho

i think u have to use the sine laws

[tiny rune]

Yeah probably

[upper karma]

damn

thats rough bro

[silent plank]

bisecting the top angle doest mean it's perpendicular to the base

[upper karma]

wanna bet

Oh true mb

[silent plank]

and it won't, if the triangle isn't isosceles

apply angle bisector theorem

(and/or variations of the sine law) and solve the equation

[tiny rune]

and it won't, if the triangle isn't isosceles
@silent plank Thanks

I'm not that fluent in english so I don't know math terminology that well. Thanks

[silent plank]

eg . let CK = x
KB = 14 - x
Search "angle bisector theorem"
should get you images explaining it.
apply it and solve the (linear) equation

[tiny rune]

I think I solved part of it

X/14-x=10/8

8x=(14-x)*10

28x=140

x=5

And if X=5

then 14-X=14-5=9

So KC=5 BK=9

If I'm not wrong

eg . let CK = x
KB = 14 - x
Search "angle bisector theorem"
should get you images explaining it.
apply it and solve the (linear) equation
@silent plank Thanks

[silent plank]

parentheses in first line

and try to fix capilisation issues

1sec

algebra also looks off

3rd line. not 28x

[tiny rune]

Oh it's 18

And it doesn't work, I mean it's 7.77

I'm gonna skip that one

[silent plank]

leave it as a fraction. 70/9

and there's nothing wrong with it not being an integer

[tiny rune]

I know

but

In this case teacher would't wrote that

I'm gonna ask teacher about that

It

It's 1 in the morning so, It would be kinda rude to wake him up

Thanks Ramonov for help

[ebon oar]

A point on a piece of paper is the vertex of four rays which create
four angles. Afterwards, the paper is cut into four pieces along the bisectors of each
of the original angles. Prove that among these four new angles are actually two pairs
of angles that add up to 180 degrees.

How do I visualize this?

[upper karma]

well... visualise?

you can test on a piece of paper to see

but to prove

first call all angles alpha beta etc.

if you take the bisectors of each angle

what are the values of the new angles?

[upper karma]

@cedar tendon i honestly dont think it needs further explanation than "use total angle of a circle"

To substract it to the arc

[cedar tendon]

so what should i do

[silent plank]

apply the inscribed angle theorem

[upper karma]

I wont repeat myself

@cedar tendon do you want the first one or the second one

[cedar tendon]

i want both

a

And guys what the inscribed angle theorem?

[upper karma]

For a, use what i said

And for b, do what Ramonov told you

@cedar tendon google it

[cedar tendon]

guys for a what am i supposed to do

[upper karma]

@cedar tendon last time.

Substract the arc given with the total angle of a circle
Substract the arc given with the total angle of a circle
Substract the arc given with the total angle of a circle

[cedar tendon]

ok i got 80

[upper karma]

For which one

[cedar tendon]

the first one

[upper karma]

Do you know what the total angle is?

[cedar tendon]

for which side

[upper karma]

?

Total angle of a circle

[cedar tendon]

for bcd i got 80

[upper karma]

Both are bcd

[silent plank]

make it clear whether you are referring to the arc or the inscribed angle

[cedar tendon]

the arc

i got 80

[upper karma]

Do you know what the total arc measure of a circle is?
@upper karma

[silent plank]

total arc measure would be a better term

[cedar tendon]

Guys i got 80 for the first one

[upper karma]

Yeah

[cedar tendon]

so now what i do

[unique junco]

80 is wrong

if they didnt tell you that yet

[silent plank]

answer the question being asked

[upper karma]

@cedar tendon do you have something against reading

[silent plank]

by Al

[cedar tendon]

nooo

just help me find the answer

[upper karma]

I'm out.

[silent plank]

this is basic geometry knowledge

[unique junco]

dw, not ur fault Al

[silent plank]

the total arc measure of all circles (or angle around a point) is: how many degrees?

[cedar tendon]

guys isn't the total angle of the circle 240

[silent plank]

NO

not this circle, not any circle.

Google it

[cedar tendon]

google what?

[silent plank]

the total arc measure of all circles (or angle around a point) is: how many degrees?

since you kinda need to know that

it is also something you should already know

[cedar tendon]

it said the circle is 360

[silent plank]

degrees yes.

[cedar tendon]

now what i do

[silent plank]

hence
arcBED + arcBCD = what?

[cedar tendon]

i got 320

[silent plank]

where are you getting 320?

[cedar tendon]

i thought bcd is 160

[silent plank]

why would you think that?

[cedar tendon]

ok

what ineed to do

OH

that it

[silent plank]

if the total arc measure of a circle is 360°,
and the arcs BED and BCD form the circumference, then the sum of their arc measures is?

[cedar tendon]

200

i got 200

[silent plank]

skipping ahead?

not answering my question?

[cedar tendon]

noo

i thought it was 200

[silent plank]

what's "it"

[cedar tendon]

Ramonov

im doing what usaid

u told me to add the sum

of bed and bcd and i got 360

[silent plank]

and that was all I was looking for at that point

hence

skipping ahead?

[cedar tendon]

oh

So ramonov so what i do?

now

[silent plank]

I assume you did your algebra properly to get
arcBCD = 200° which would be correct

for part a)

[cedar tendon]

yes

Ramonov what for b now

I need the answer for b

[silent plank]

now for part b), apply the inscribed angle theorem

[cedar tendon]

what the answer for b

Waht that?

the inscribed angle theorem?

[silent plank]

ask Jeeves

[cedar tendon]

who jeeves

[silent plank]

a dead search engine intended as a joke
if you don't know a certain term, Google it

[upper karma]

haha

jeeves

classic

[cedar tendon]

Guys i need to find jeeves

@grand kindle

come on

i need you

[upper karma]

lol

[silent plank]

the correct answer is the value you get if you apply the inscribed angle theorem properly

[cedar tendon]

ramonov what a joke?

and where can i. find jeeves

[silent plank]

the joke is despite explicitly being told the theorem needed, you've made zero effort to look it up and despite me and several others saying no, you are still somewhat expecting us to do the work for you.

I'm out

[cedar tendon]

ramonov noo

i need help

i need to find the length of the arc

[upper karma]

stop trolling then

ffs

[cedar tendon]

im not trolling

[upper karma]

i doubt it

[cedar tendon]

i just need the length

[upper karma]

use the volume formula

@lunar flower

[cedar tendon]

i need help

[upper karma]

V = pi * r^2 * h

what u need help on

[cedar tendon]

the question above

[upper karma]

its been explained to you multiple times

[cedar tendon]

idk what the inscribed angle theorem

[upper karma]

google it

[cedar tendon]

i only got this

[upper karma]

what dont u understand about it

@cedar tendon

[cedar tendon]

what the 0 symbol mean

[upper karma]

any angle

hold on

theta

search it up

it just refers to any specific angle

[cedar tendon]

so how am i supposed to used the inscribed angle theorem to help me find the answer

[upper karma]

https://youtu.be/8g5grYXSE_E

Watch this

[cedar tendon]

ok

[upper karma]

good luck!

[cedar tendon]

ok

i read it

[grand kindle]

Guys i need to find jeeves
@cedar tendon I am here

[cedar tendon]

@silent plank jeeves is on now

[sullen pollen]

anyone know what theorems i would use for these? can’t find it in my textbook

[silent plank]

search for a general list online.
you'll need to apply the following for these questions.
total arc measure,
inscribed angle theorem (you will need this a LOT)
-external angle theorem (in the context of circle geo)
-also worth it to look up internal angle theorem in the context of circle geo (which isn't needed here)
intersecting chords
secant-secant (also worth it to look up tangent-secant)

[sullen pollen]

thanks

[cedar tendon]

ramonov

help me

i got 80

[cedar tendon]

guys

i got 80

[upper karma]

@cedar tendon wut

[cedar tendon]

xi. i got 80

for halve of 160

i got 80

[upper karma]

Which problem

[cedar tendon]

in the therem

[upper karma]

Yea

Correct

[cedar tendon]

so that b

xi is b 80

[upper karma]

Can u post problem again

[cedar tendon]

ye it is 80

now i need help with this

@upper karma

[upper karma]

@cedar tendon What r u trying to find

What does it mean “what type of angle is”

[cedar tendon]

ok

i need to find the angle

[wooden current]

what angle

x or y? or both?

[silent plank]

was the drop down hiding any part of the question

[cedar tendon]

i need to find the measure of the arc and angles of circle above

[wooden current]

Ok

What have you tried so far

[cedar tendon]

I need help

[regal crag]

^^^^

ANC=DNC as the triangles

[upper karma]

assuming you mean AD is perpendicular to BC

then yes

they are mirrors to each other

[regal crag]

yeah perpendicular that one

thanksss

[cedar tendon]

i need help

[eternal crag]

[cedar tendon]

i did

look above

[eternal crag]

looks like you never answered Dan's question

[cedar tendon]

Help me

i need help

[eternal crag]

what have you tried?

[cedar tendon]

i need help

[eternal crag]

what have you tried?

[wooden current]

bruh

[cedar tendon]

dude the problem is hard and i need help

[eternal crag]

seriously, we're not going to help without you spending any effort first

so again,
what have you tried?

[wooden current]

^^

[cedar tendon]

dude the first question hard

and i need help

[wooden current]

😐

[cedar tendon]

i need find what type angle it is

and i need help

[wooden current]

So you haven't tried anything?

[cedar tendon]

dude it is so hard

and i need help

[upper karma]

This channel is free...

[dark sparrow]

do you know what the word "try" means

[versed aspen]

i need help

[supple onyx]

with what

[versed aspen]

i need help

this question is so hard

plz help me

@supple onyx I need help

[supple onyx]

what question or am i blindly being trolled

[versed aspen]

||yes you're being trolled, I was imitating them||

[supple onyx]

wooosh

oh yeah now that I read further up wow

[upper karma]

Lol

[gray mason]

Please go back to basic algebra. You find everything hard because the foundation isn't in place.

For circle theorem, go ALL THE WAY to the fundamentals.

Parts of the circle. Angles in a circle. Relationships of each type of angles.

Do tons of practice.

THEN come back and attempt this question.

[dark sparrow]

dude the first question hard
and i need help

[upper karma]

Yeah lol

Yesterday he acted the same effing way and i gave up on him

[dark sparrow]

doesnt help that he insists on not changing his name

and keeping it as "BLUH BLUH I GIVE UP MATH HARD" (paraphrased)

[upper karma]

Agreed

[gray mason]

A bit on attitude. If their teachers accept them having that mindset, they're doing a shit job.

And as you can see, I did not answer his question.

[upper karma]

When putting sin(x) in a calculator, with x being any real number, are you just finding the sin of a triangle with x as its angle?

and 1 as the hypot

[upper karma]

no

[cedar tendon]

someone help me

[upper karma]

what do u need help on

[wooden current]

omg

[upper karma]

@cedar tendon I’m here for you

Remember me

[cedar tendon]

ok

Help

me

[upper karma]

@cedar tendon What r u looking for

[cedar tendon]

i need to find which angle it is

and the measure of the arcs and angle

[upper karma]

Ok what r u struggling on

What don’t u understand

[cedar tendon]

the first one

idk if it inscribed

[upper karma]

Ya but what angle is it referring to

I don’t understand

[cedar tendon]

ok

so what should i do

[upper karma]

Wait for someone else I don’t get it

Sorry

[cedar tendon]

ok

[upper karma]

for the first one i think its inscribed

[cedar tendon]

ok

now i need to find the arcs and angles of the first one

[upper karma]

ok so theres a theory where the measurement of an angle inside the circle is half of the measurement of the arc that its opposite to

so if angle E inside the circle is 41 degrees, and the opposite arc is DC, ehat is the measurement of angle DC?

[cedar tendon]

true

it the measurement

of dc

[upper karma]

smh

if angle E is 41 degrees, what is angle DC

[cedar tendon]

20.5

[upper karma]

no

go the other way

don't divide by 2

but...

[cedar tendon]

ok

[upper karma]

so...

[eternal crag]

looks like they've gave up already, cue the

dude the first question hard
and i need help

[upper karma]

^

this guy shouldn't be in the server

Tbh

yo big brain

Yo

whats g

[cedar tendon]

Guys

the opposite

what the opposite

[upper karma]

bruh

how you not know what the opposite is

[cedar tendon]

oh

i gotta mutiply

by 2

my bad

[upper karma]

no worries

all g

[cedar tendon]

i got 82

[upper karma]

correct

so arc DC is 82 degrees

now apply this to the other angles and arcs

[cedar tendon]

how do i. apply it with the other angles and arcs?

[upper karma]

literally just do the same thing as you did for the first one

[cedar tendon]

but idk what ishould do to find ec

[upper karma]

bruh EC is double angle D smfh

[cedar tendon]

so is ec 156

[upper karma]

yes

[cedar tendon]

ok so what i do next

how do i find ed?

[upper karma]

angle C is indirectly given to you

take 180 and subtract it with 41 and then subtract it with 78

[cedar tendon]

i got 61

[upper karma]

now double that number to get the angle of ED

[cedar tendon]

122

[upper karma]

correct

[cedar tendon]

ok

how do i find for eB

[cedar tendon]

rent

do u know

[cedar tendon]

i need help

[upper karma]

what are the options for EB

[cedar tendon]

@upper karma these are the option s

I NEED help

@upper karma help me

[upper karma]

@upper karma

When putting sin(x) in a calculator, with x being any real number, are you just finding the sin of a triangle with x as its angle?
so what are you doing?

[cedar tendon]

Dude

Rent

free i really need help

[upper karma]

looks like you are just making people do your homework

maybe go somewhere else for that

[cedar tendon]

What you mean

I'm just here asking for help

you should go somewhere else

and let me ask for help

[regal shell]

Have you tried doing it yet?

[cedar tendon]

yes

i h ave tried

doing it

AND I relly need help

please

help me

[regal shell]

What’s the question

[cedar tendon]

i need to find the measure of the arc of angle of this

[regal shell]

Well angle c is 180-78-41

[cedar tendon]

i already solve for that

[regal shell]

Which arcs are they asking for none of the boxes are labeled

[cedar tendon]

we have to find hte measure of hte. arc of the picture

ok

[upper karma]

DC is 82

[cedar tendon]

yea i got 82 and 41

i need the others

[upper karma]

no, you have 82 and 156

[cedar tendon]

rent u told ec is 156

[regal shell]

Nvm

[cedar tendon]

u told me ec is 156

this is whati. got so far

[upper karma]

what angle is this referring to

why don't the boxes have labels

[cedar tendon]

i really don;t know

but it has only answer

so we need find the answer

[upper karma]

the answer could be any 3 of them

[upper karma]

show us the entire page

[cedar tendon]

i did

remember

only 3 boxes left

82

[upper karma]

how do we know which box corresponds to which angle

?

[cedar tendon]

i don't know

[upper karma]

like are we supposed to find the measurement of arc CB?

[cedar tendon]

yea

we just to find the measurement of the picture

[upper karma]

well arc CB is 180

[cedar tendon]

that matches with one of the answer in the boxes

their no 180

in the boxes

[upper karma]

yes there is

[cedar tendon]

so we just need to find the measurement of the angles i think

[upper karma]

for the 3rd box

[cedar tendon]

my bad

didn't see it

[upper karma]

the 3rd box has 180 as an option

[cedar tendon]

@upper karma that what left

[cedar tendon]

ok

so how do find out

for them

Rent Free

what should i do

I need help

finding the measurement

[violet sun]

How do I restrict an elipse?

How can I say that Y can't equal between a certain range of numbers in math notation?

[cedar tendon]

guys

i need help to

@regal shell

Help me

some one

[plucky marlin]

$y \not \in [a, b]$

[somber coyote]

soαρ:

[plucky marlin]

@violet sun

[upper karma]

http://sketchtoy.com/69213743 why are these two lines parallel

lol

[boreal socket]

How do you find the depth and radius of a circular segment at some point into a cone?

that is, not at the base but at some other point

when you're only given the overall height of the cone and the radius of the base edit: congruency given height relative to radius, makes sense

[eternal crag]

@upper karma

[upper karma]

@eternal crag thanks this makes it very clear and obvious

[dark sparrow]

i can't tell if that's sarcastic or genuine

[upper karma]

@dark sparrow why would it be sarcastic

i didn't think to draw some triangles

skipped my mind

even tho in hindsight it was obviously the thing to do

[dark sparrow]

idk, i'm shit at detecting sarcasm in text and i've seen people get sarcastic with a similar tone

[upper karma]

i mean unless you thought publius severely overcomplicated it

i don't see a reason to think it would be sarcasm

[dark sparrow]

i'm shit at detecting sarcasm in text

(and as a consequence, i tend to err on the safe side)

[upper karma]

thinking people are being mean is not the safe side..

unless you think i'm mean

[azure reef]

idk, i'm shit at detecting sarcasm in text and i've seen people get sarcastic with a similar tone
(how you can determine tone of the text?

[upper karma]

Why does polynomial always ask the most self explanatory questions and looks for a near impossible explanation?

[boreal socket]

@azure reef text has tone, it's just that the meaning of it is relative to the context of the text, so misjudging tone of text is more misjudging the application of that tone

[dark sparrow]

how you can determine tone of the text?
written text has its own means of conveying intonation, such as italics, bold, or CAPS, or some mix of these
as well as just phrasing

[upper karma]

aS WeLl aS jUsT pHraSiNg

[wooden current]

tts

[cedar tendon]

guys i found it the answer now to that question

now i need help with this one

HELP ME

[dark sparrow]

The measure of [BLANK] is twice the sum of blah blah blah

why's there a huge blank space in there

[cedar tendon]

where

[dark sparrow]

in your second screenshot

[cedar tendon]

the teacher just write it like that

for some reason

[dark sparrow]

i mean

one can be hardly expected to say anything about an angle or arc or whatever when one does not even know what arc is being talked about

can you like... reload the page or something

[cedar tendon]

i did

it still pop up same way

[dark sparrow]

well until you get that sorted out there is no way anyone could help you do this problem.

[cedar tendon]

i mean my teacher makes mistake

so sometimes i guess

[dark sparrow]

my point still stands.

[cedar tendon]

on them

[dark sparrow]

teacher mistake or not, THE PROBLEM IS IMPOSSIBLE TO SOLVE (LET ALONE HELP YOU WITH) THE WAY IT IS PRESENTED RIGHT NOW.

[cedar tendon]

well imma just go to the next question

that one

[dark sparrow]

okay...

have you learned (and understood and remembered) any circle theorems at all in the last few days, or are you just gonna beg me to give you the answer for this one too

[cedar tendon]

the only circle theorem i have learned is when saint taught me how it works

[dark sparrow]

i don't really know what to say that wouldn't just give away the answer.

[cedar tendon]

I need help

[dark sparrow]

https://www.onlinemathlearning.com/arc-angles.html

here

give this a read

[cedar tendon]

@dark sparrow i told me to divide

it told me to divide

by 2

[dark sparrow]

it told you, perhaps, to ADD those arcs you've got there. and only then divide the result by 2.

[cedar tendon]

yea and i got 50

[dark sparrow]

congratulations

[cedar tendon]

i need help with this

[dark sparrow]

oh no

not only would this problem have you do algebra, there are DECIMALS in here. oh no. how scary.

[cedar tendon]

WHAT DECIMALS

that my weakness

i failed

math is so hard

[dark sparrow]

$\frac{39.3+x}{2} = 32.9$, are you able to solve this equation for $x$

[somber coyote]

Ann:

[cedar tendon]

if it has decimals it hard

[dark sparrow]

if this problem had no decimals would you be able to do this

for example, if we set this aside for a moment

i'll give you a simpler equation: $\frac{z+11}{2} = 25$

[somber coyote]

Ann:

[dark sparrow]

can you solve this for z?

[cedar tendon]

it doesn't have like terms so i can't

[dark sparrow]

you can't even multiply both sides by 2?

[cedar tendon]

i can if they have like terms but unfortunately i can't without like terms

[dark sparrow]

what

[graceful narwhal]

[dark sparrow]

you are physically incapable of going from $$\frac{z+11}{2} = 25$$ to $$2 \times \frac{z+11}{2} = 2 \times 25?$$

[somber coyote]

Ann:

[cedar tendon]

ok

[dark sparrow]

no seriously

was that such a big leap of faith for you that you can't grasp it?

boy you need to go through khanacademy's pre-algebra course at LEAST.

[cedar tendon]

oh

[dark sparrow]

no seriously like

i've basically DONE an entire problem for you and didn't even get so much as a "thank you"
and then i ran up against your... inability to do basic algebra

and not only that, but you seem blind to the point i've seen others on here make many times

[cedar tendon]

my bad forgot to say thank you

[dark sparrow]

if you don't have a grasp of basic algebra, then everything else in math will be either very hard or impossible since it relies on algebra.

[cedar tendon]

ann i told them all that im in algebra class

but told me to be in this chat

channel

[dark sparrow]

you struggle with the simplest of things

[cedar tendon]

yea

[dark sparrow]

channel choice notwithstanding, you just demonstrated to me that you cannot solve even a simple linear equation

this is an issue that needs addressing before we can come back to the problem you posted.

and this is not an issue i can address in a few minutes of chatting over discord.

[cedar tendon]

ok

[half jasper]

https://cdn.discordapp.com/attachments/387447700234174464/717756402181079180/unknown.png

send help

[silent plank]

interior angle theorem (in the context of circles)
and/or multiple applications of inscribed angle theorem

[half jasper]

ty i appreciate thi

[upper karma]

Damn Ann just ended math I give up

[dark sparrow]

????

[split geyser]

I think there should be quotation marks, and the lack of a comma is unintentional

[steep temple]

ann being a savage,,,

[upper karma]

Tbh it had to be told before it grew more

[steep temple]

not that i condemn it or anything

[upper karma]

^

that dude is straight up troll

[upper karma]

https://www.youtube.com/results?search_query=circle+theorems

@upper karma

https://www.youtube.com/watch?v=GppOSNTi5OA

1st one is "secant-secant power theorem" (@28:50 from the video)

2nd one is "secant-secant angle theorem" (@19:42)

[violet sun]

How can I wrap a sine wave into a circle?

for example

[dark sparrow]

uh

[violet sun]

Is this possible lmao?

[dark sparrow]

in polar i guess it'd be $r = R + \sin(k\theta)$ where $R > 1$ is the radius of your circle and $k$ is the number of outward bulges

[somber coyote]

Ann:

[dark sparrow]

is this what you're looking for?

[violet sun]

Yeah lmao

Are those the only three functions you used in desmos?

nvm got it!

Thank you @dark sparrow

[dark sparrow]

uh yeah that's my entire setup

[upper karma]

https://www.desmos.com/calculator/ijdetkumw1

added a phase shift slider 🙂

https://www.desmos.com/calculator/4xr6ol8p6g

and one for the amplitude

[silver radish]

If g(x)=(x+2)^2, what is the value of g(x+2)

[graceful narwhal]

what is g(1)?

[upper karma]

its the value of your function g when x =1

[cedar tendon]

could u guys help me now

[graceful narwhal]

did you learn pre algebra?

[cedar tendon]

yea

[graceful narwhal]

awesome so you solved the problem

[cedar tendon]

yea

[wooden current]

ok help you with what

[cedar tendon]

that

[wooden current]

Have you learned Circle Theorems?

[cedar tendon]

i only learn the linear equation

[wooden current]

😦

https://www.youtube.com/watch?v=GppOSNTi5OA

You can't just solve these problems without even knowing elementary theorems

[cedar tendon]

what that

[wooden current]

What

[graceful narwhal]

Dan I would just leave math is a job for ann

[wooden current]

I mean Ann did a lot. Doesnt Ann deserve a break?

[graceful narwhal]

he's being purposely dense

[wooden current]

[graceful narwhal]

if he was actually seriously trying to learn he would have started to fix his holes

but he just keeps coming back doing the whole "lol I don't know anything"

[wooden current]

True 😕

[cedar tendon]

ok

i finish

watching the vieeo

video

[cedar tendon]

so now

what i need to do

[upper karma]

this is like the 5th time we'd have to tell you about circle theorems

[cedar tendon]

yea

i know about that

ok

so what i need to do in the problem above

[upper karma]

what have u done so far

[cedar tendon]

so far i added 39.3 and 32.9 and i got 72.2 and. i mutiply it by 2 and i got 144.4 and i don't know what i do now

[meager nova]

Anybody know how to find x on triangles?

[silent plank]

what theorem are you trying to apply?

[meager nova]

Solving for X on triangles

Can I show you a picture of one of the problems

[silent plank]

that wasn't directed at you, use an open chanel this is probably still in use

[meager nova]

Sorry

[cedar tendon]

guys help me

as well

i need help

[upper karma]

Google your probĺem

This should help

@cedar tendon use this to solve your problem

[cedar tendon]

i mean it an. external angle

@upper karma i got 3.2

[upper karma]

well obviously thats wrong so try again

show me your work

[cedar tendon]

i just did what u said follow the external angle but i don't know what 0

o

mean

[upper karma]

show

me

your

work

[cedar tendon]

ok

39.3 - 32.9 = 6.4 /2 = 3.2 their

[upper karma]

thats now how you use the theorem

and it's there, not their

[silent plank]

also, don't chain equations like that

[upper karma]

look at the equation again

[cedar tendon]

ok

can you guys at least tell me the steps

[upper karma]

put the question and the image of the theorem beside each other, so you can tell which number goes where

[cedar tendon]

but that an external angle

[upper karma]

youre supposed to use the external angle

[cedar tendon]

oh

@upper karma what does the x and y mean in the image u gave me

[silent plank]

its all in the diagram