#geometry-and-trigonometry

1 messages · Page 283 of 1

upper karma
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you need a protractor

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something with degrees on

nocturne thorn
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I have two question: what is the red questionmark and how do i find d1

upper karma
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the red question mark is the angle between point A and the initial point you started to move from

nocturne thorn
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so from my head to point A?

upper karma
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you move laterally

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1 m

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forming a 90 degree angle

nocturne thorn
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ohhhh

upper karma
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then you measure the angle in red

nocturne thorn
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i see now, thanks a lot again @upper karma

upper karma
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sure thing

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then you have angle A, because all angles from a triangle need to add up to 180

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and you can use the law of sines to determine the distance (marked as d1)

nocturne thorn
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@upper karma you are a genius

upper karma
nocturne thorn
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How does finding side d1 help me find the length of A to B? @upper karma

upper karma
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you do this the same with point B, having a shared vertex with point A

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and that forms another triangle

nocturne thorn
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I'm not following along here

upper karma
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how about now?

nocturne thorn
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But how would I find line A-B

upper karma
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how about now?

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let's say BP = 50m (for example)

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and AP = 58m

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and you have the green angle

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you use the law of cosines

nocturne thorn
upper karma
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yep

nocturne thorn
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that makes a lot more sense now, you are the best @upper karma

upper karma
nocturne thorn
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Is DPB 90 degrees?

upper karma
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no

nocturne thorn
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how would I find a length of Triangle DPB?

upper karma
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oh, I see

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yes DPB would be 90 degrees

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because it's a shared vertex with the previous triangle

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and you need to move 1 m in the other direction to get the distance

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or, you could start from the original point

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move right 1 m (same as the previous triangle with point A), but at 90 deg

nocturne thorn
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oh, ok. that makes sense now. Thanks again @upper karma

upper karma
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hang on

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if ADP and BPD are both 90 degree angles...

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that's not good

nocturne thorn
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oh oh

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why

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@upper karma

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How would I then find the lengths of triangle DPB?

ocean axle
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@little osprey How is it going?

silent plank
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its fine for both of them to be 90°
DP won't necessarily be exactly 1m.

nocturne thorn
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When a teacher says: "Actual measurements are not necessary" would you consider the teacher not caring about that it's not 90 degrees?

silent plank
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measurements not necessary means that you aren't expected to find lengths

ripe dove
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That really means you need to set up a general solution that takes into account whatever the measurements would be

silent plank
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just an outline of a method

ripe dove
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So use variables instead of numbers

silent plank
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and if constructing 90° angles makes the theoretical calculations easier, you're free to do so.

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however there may be a limitation depending on whether it aligns with your window

upper karma
silent plank
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since its implied that you can measure the base angles and side, you can calculate what you need from:
angle sum / sin law, and cosine law (regardless of the size of your angles)

upper karma
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the green angles are congruent

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you could also do this with lower values

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if 1m is too much

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you can use 0.3m

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(30 cm)

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on a piece of paper or something

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that you can hold flat

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and draw the angles on that, while keeping an eye on the direction they're pointing

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otherwise you'd have to use pieces of 1m string around the house, maybe ask someone to hold it in place

nocturne thorn
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@upper karma thanks again

merry abyss
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I’m confused

silent plank
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consider applying the angle sum of a triangle to get x + y
(i'm using y instead of o, since o looks bad in plain text)

little osprey
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lol

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Also BIC (bigger)

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Then smaller

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That should be enough of a hint for you @merry abyss

merry abyss
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Ah okay thanks guys

little osprey
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No worries

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A bit surprised you got that

merry abyss
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I think I already solved it

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It’s 120?

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I’m not sure if it’s right lol oh well

silent plank
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show your work
why aren't you sure?

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120° is correct btw

merry abyss
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Idk low confidence? Or maybe it was too easy

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Oh thanks lol

little osprey
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What Ramanov said

merry abyss
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I created a system of equations

little osprey
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sounds good

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wait

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only a system of equations?

merry abyss
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Yeah?

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A system of 3 equations and only used one to solve the other

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Sometimes I have a problem with just diving straight into the algebra I try to avoid it :/ which is why I get stuck on simple questions

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so thanks guys

silent plank
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yeh even on paper it looks bad

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2O looks like 20

merry abyss
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^

silent plank
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note that the second equation wasn't needed

merry abyss
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Yeah lol

sudden bane
upper karma
merry abyss
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@sudden bane if you rotate that, the base has another side to the left of AB

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Draw a diagram to illustrate the situation, you should see a triangle in the illustration

sudden bane
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Oh that makes more sense. that means the diameter would be 10 right.

ripe dove
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Yes

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@upper karma start by drawing a picture

upper karma
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Ya I drew a triangle

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I don’t know where to put the measurements

ripe dove
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What part of the triangle is the string? Did you put Timmy and the kite in your pic? Or just the abstracted triangle?

upper karma
ripe dove
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So Timmy’s kite string is dragging on the ground

upper karma
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Should I flip the numbers?

buoyant yacht
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@upper karma ammy can you draw the kite and timmy in the picture? I think you have some confusionabout what the angle of elevation refers to

ripe dove
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And a bird measures the angle between Timmy and the kite to be 48 degrees

upper karma
ripe dove
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Is Timmy holding the string, or it’s tied to a stake in the ground somewhere else?

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But your angle is...better.

upper karma
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Timmy holding the kite

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I think

ripe dove
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So the string should connect Timmy to the kite

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Not the kite to the ground

upper karma
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Ok

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Now what

ripe dove
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What’s your pic look like now?

upper karma
ocean axle
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@little osprey Did you tackle my task?

night summit
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I know how to do this the long way but is there any way to do it very quickly?

ripe dove
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That is not the right picture @upper karma

upper karma
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How@do I draw it then? 😦

ripe dove
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@night summit double angle cosine ID to quadratic in sine

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Or you could graph each side and hope they cross at nice places

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@upper karma you good now?

upper karma
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@ripe dove ohhh

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So then I just gotta find what to do

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Like sin cos or the other thing

ripe dove
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Which side do you want to know, and what is the trig function relating it to the things you know already?

upper karma
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What I’m so confused

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and are you familiar with the law of sines?

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@upper karma Yes I’m familiar

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With it

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Pretty easy

ocean axle
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@upper karma After findiing missing angle you can apply law of sine.

upper karma
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yep

silent plank
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the notation/work is a little dodgy

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also what's with this obsession of applying the sine law. ( overcomplicating the problem)

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you should be writing the degree symbol on paper AND

upper karma
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@upper karma I’m finding that angle

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I got 20.35 for that angle

silent plank
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you mean side?

upper karma
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I used cos

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Ya side

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why a decimal for the angle?

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ah

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No I’m finding x

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My bad

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I got 20.35 for x

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yeah, it's fine

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Ok thanks

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do they specify how many decimals to use?

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No

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because you could round it off to 20.4

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oh

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It just says “using sin cos and tan find the value for x”

silent plank
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you should NOT be writing: \
$ \cos(32\deg) = \frac{x}{24} {\color{red}{,24}}$ \ to indicate that you are multiplying both sides by 24..

somber coyoteBOT
upper karma
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O

silent plank
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either write *24 on both sides

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or skip directly to the next line

upper karma
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Ok

silent plank
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as it is simple enough for that action to be implied

upper karma
silent plank
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$y = -2x+7$ ?

somber coyoteBOT
upper karma
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Ya

silent plank
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yeh

upper karma
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Aye this shit I got it down

silent plank
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please improve your handwriting

upper karma
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After watching like 40 YouTube videos lmao

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Ok I’ll try all my teachers tell me that

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Yes I used soh cah toa our teacher made us memorize that

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or cosine, sure

silent plank
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,w 24cos(32pi/180)

somber coyoteBOT
upper karma
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,w 24cos(32pi/180)

somber coyoteBOT
upper karma
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Woah wtf

silent plank
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,w 24cos(32 Deg)

somber coyoteBOT
upper karma
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is this 11/20

silent plank
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precision sucks when you enter degrees onto wolfram

upper karma
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Tbh ^

supple gazelle
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som1 help

upper karma
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@upper karma look like an exam m8

supple gazelle
upper karma
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its 9/20 nvm

supple gazelle
upper karma
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@supple gazelle JustAsk

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Oh

high hemlock
upper karma
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not trig related

high hemlock
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i think this is the right category

supple gazelle
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this is a trig test

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u nerd

upper karma
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God damn 3 questions at a time

high hemlock
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isnt that trig

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or am i crazy

upper karma
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Your question is vectors related

supple gazelle
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who mine?

upper karma
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No

supple gazelle
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pls fill in this stuff ;-;

upper karma
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the one with the die toss is statistics

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Hell no we dont do this here @supple gazelle

silent plank
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did someone say test?

supple gazelle
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THAN EXPLAIN

remote heart
supple gazelle
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AND HALP

upper karma
high hemlock
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so

supple gazelle
upper karma
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Lmao

high hemlock
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anyone help me

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thanks

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❤️

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dw its not a test

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its my homework

supple gazelle
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al3dium help then

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explain

upper karma
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We weren't talking about you peepee

supple gazelle
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im on a timed test

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;-;

high hemlock
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but can you help me tho

upper karma
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Nope

remote heart
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asking for help during a test is a bannable offence

supple gazelle
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I WAS KIDDING

upper karma
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^

high hemlock
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i havent been in class

supple gazelle
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ITS HOMEWORK

upper karma
supple gazelle
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pranked

upper karma
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Bruh

supple gazelle
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pranked

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its homework

high hemlock
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ty

remote heart
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lumow, shr1nd

high hemlock
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this is on my upcoiming test

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next week

upper karma
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You are just being annoying

high hemlock
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would be greatly appreciated

upper karma
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Aight

supple gazelle
remote heart
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please stop spamming that, shr1nd

high hemlock
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ok but like

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help LUL

supple gazelle
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they won't, apparently.

high hemlock
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lol

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well maybe its cause you told them its a test

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LOL

supple gazelle
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i was kidding

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april fools

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its homework

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u nerd

high hemlock
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but does anyone want to help me tho

upper karma
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@high hemlock notice that $\overrightarrow{AB}=B-A$

high hemlock
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cuz test next week

somber coyoteBOT
high hemlock
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ah

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yes

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thank you

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i have nopticed

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i think

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bro i was not here for this chapter

upper karma
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Hace you calculated AB, AP and PB?

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@high hemlock plot it

high hemlock
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well i kinda skipped the entire lesson

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ill get on desmos

upper karma
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No need to plot it

high hemlock
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oh

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i just did

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LOL

upper karma
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Uhh i dont know why on earth DSpider told you that

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Anyways

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Please get AB

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Try

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$\overrightarrow{AB}=B-A$

somber coyoteBOT
high hemlock
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oh

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like... 19-4 and 17-19?

upper karma
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No

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x with x and y with y

high hemlock
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oh

upper karma
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(17-7,19-4)

high hemlock
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ah okay

supple gazelle
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Thankyou @upper karma it helped greatly

upper karma
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Aight so $\overrightarrow{AB}=(10,15)$

somber coyoteBOT
upper karma
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Now

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@supple gazelle you can always google "what's the amplitude of a graph"

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you'll eventually get there

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$\overrightarrow{AP}$

somber coyoteBOT
high hemlock
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wot

upper karma
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Oh wait

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Pythagora

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to find the length of segment AB

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Uh i assumed AB was the vector

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My bad

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the divide it by 3

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Im used to analitic geometry lol

silent plank
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i wouldn't recommend finding the length of AB.
it's inefficient

high hemlock
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okay

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whats efficient

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pythagoreas?

silent plank
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consider instead the ratios of the change in x and y

upper karma
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Uhh $\overline{AB}$

somber coyoteBOT
supple gazelle
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Could you check if this is right? Does the pie symbols effect my answers?

📎 unknown.png
high hemlock
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okay

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ty

upper karma
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AP = 2/3

high hemlock
upper karma
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PB = 1/3

high hemlock
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i guessed this btw

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i have no clue whats going on in this review

upper karma
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you're done already?

high hemlock
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no

upper karma
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Did you just switched

high hemlock
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im working on both

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i just went to the next one

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to see if i could do it

supple gazelle
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@upper karma Did you check it?

upper karma
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Im just confused by the notation, $\overline{AB}$

somber coyoteBOT
upper karma
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@supple gazelle the amplitude is wrong

supple gazelle
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Isn't the amplitude how many units it takes to get to the midpoint from the top and bottom line

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or vice-versa

upper karma
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@upper karma that is how you mark a line segment

supple gazelle
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oh its 4

barren tide
supple gazelle
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Right?

upper karma
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Bro

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@supple gazelle yes, and what's the midpoint?

supple gazelle
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2

upper karma
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Why are there 3 questions going on here

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^this

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@upper karma that is how you mark a line segment
@upper karma and i know but its weird

supple gazelle
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Is there not allowed to be multiple? Why don't they make multiple channels if it's a problem

silent plank
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this is obviously the only channel in this server

upper karma
#

there are multiple channels

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Yeah there multiple

barren tide
#

kk thnx

supple gazelle
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@silent plank No, but it is the only one for geometry-trig

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You bamboon

upper karma
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What

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No

silent plank
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Greek letter channels are for general use.

upper karma
supple gazelle
#

So if you're the one complaining move channels

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No one else had an issue

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Common Sense

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Or go by who asked first

high hemlock
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nahi ts fine

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io can work out my questions

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take your time

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dw

upper karma
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No one else had an issue
@supple gazelle ITS NOT AN ISSUE FOR YOU BC YOU ARE NOT TRYING TO DEAL WITH 3 PPL AT THE SAME TIME

supple gazelle
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So

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Move channels

upper karma
#

You are only focused on your question

high hemlock
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or we can just chill

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lol

upper karma
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@supple gazelle we were helping peepee until you came again

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Uh

barren tide
#

This dude really giving out Karen vibes

silent plank
#

in general, follow the rules
joking about stuff being a test is highly not-recommended.
as currently we have no confidence on whether it actually is or not.

supple gazelle
#

Yep, I learned that.

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Thankgod it wasn't one, and it was only a joke 😉

ripe dove
#

We could all just Embargo answers for shr1nd

high hemlock
upper karma
#

if you get caught asking or you help with a test, you get banned

high hemlock
#

gg

upper karma
#

so maybe think twice

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Lol

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"Good job" 40%

ripe dove
#

Being rude to the people helping you for free because they like to is a good way to not get helped

supple gazelle
#

I did, I was joking. Didn't know people were on edge, and learned jokes aren't taken well here.

upper karma
#

Well all the jokes can go to whatever chat channel

high hemlock
#

well

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thanks for trying

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i hate zoom classes

upper karma
#

Lol why'd you give up

high hemlock
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i just gave up

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lmao

upper karma
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I know

high hemlock
#

ill review my textbook

upper karma
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Why

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Ok ig

high hemlock
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cause im bored

upper karma
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the problem was you were "solving" two questions at once

barren tide
#

Dude just really pulled out "It's just a joke" card

remote heart
#

indeed

high hemlock
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i think its zoom

upper karma
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to "see if you could do it"

high hemlock
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sorry sir

supple gazelle
#

How would you figure out if a sine or cosine would better model it? Any sources or general help. My teacher said cosine is x and sine is basically y

📎 unknown.png
sudden bane
remote heart
#

it is not c?

supple gazelle
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no, it is c. he's asking why it's c and not d

remote heart
#

uhm, it is not c

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you mixed up water and land, I believe

dusty coral
#

per square mile of land means 2052/(3.5 * 2.75)

remote heart
#

3.5*2.75 is the water

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not the land

supple gazelle
dusty coral
#

no its the land

remote heart
#

oh crap

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god

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ahhfhghg

supple gazelle
#

xD

remote heart
#

sorry, I can't read

supple gazelle
#

LOL

dusty coral
supple gazelle
#

wats dat

dusty coral
#

look up unit circle

silent plank
#

there's a nice unit circle pinned to this channel

supple gazelle
#

so pi/4 = 45 degrees?

languid swan
dusty coral
#

yeah it is shrind

supple gazelle
#

how do I type 5pi/6

dusty coral
#

@languid swan vertical lines

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what is angle <VRU

supple gazelle
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Well, ig the teacher won't care.

upper karma
#

which do you think it uses?

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sine or cosine?

dusty coral
#

either

supple gazelle
#

sine

languid swan
#

bro i dont know any of this

dusty coral
#

its cosine for the simpler one

languid swan
#

im just tryna get it done

supple gazelle
#

well which would better

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be used for it

dusty coral
#

cosine

supple gazelle
#

Why though

dusty coral
#

what a weird question

supple gazelle
#

My teacher just explained cosine as x and sine as y

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my teahcer is weird

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teacher*

dusty coral
#

cause cosine starts off at (0,A)

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whereas sine starts off at (0, 0)

upper karma
#

which is which?

dusty coral
#

1 is sine

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2 is cos

upper karma
#

@supple gazelle do you agree or disagree?

supple gazelle
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Agree, but still confused on excactly how. Like describe the difference between the 2

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Like I see it

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but in words

upper karma
dusty coral
#

there is no difference - you can use sin or cosine for either

just remember sin(x) = cos(pi/2-x)

so sin graph is cosine shifted by pi/2

supple gazelle
#

But it ask me which would be better to model the displacement of the spring, and why

upper karma
dusty coral
#

its cosine man

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it starts off at (0,A)

upper karma
#

@dusty coral he doesn't know why it's cosine

dusty coral
#

yeah, cause it starts off at something besides y = 0 at x=0

supple gazelle
#

Can someone check if this is right? I've never done it with a decimal, I've only practiced with fractions before

📎 unknown.png
upper karma
#

,calc 0.4318^2

somber coyoteBOT
#

Result:

0.18645124
supple gazelle
#

Well, that's 0.5682 squared I believe

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and I don't think she wants us to square it

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Oh nope

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thats not that

upper karma
#

,calc 1-0.18645124

somber coyoteBOT
#

Result:

0.81354876
upper karma
#

and I just realized it's supposed to be like this:
(*typo: max height)

📎 unknown.png
supple gazelle
#

I did cos^2 + sin^2 = 1^2

upper karma
#

,calc √(0.81354876)

somber coyoteBOT
#

The following error occured while calculating:
Error: Syntax error in part "√(0.81354876)" (char 1)

upper karma
#

,calc sqrt(0.81354876)

somber coyoteBOT
#

Result:

0.90196937863766
upper karma
#

This should be the final ans if i haven't messed it up

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@supple gazelle well post your work

supple gazelle
#

a bit messy lol

upper karma
#

My eyes hurts from not seeing cos (theta)

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And you should have squared 0.43...

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Bc its the value for sin(theta) not for sin²(theta)

supple gazelle
#

okay, question

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Why do they teach us this stuff, I'm never gonna use it

upper karma
#

Uh its one of those questions

supple gazelle
#

lol, but its true 😭

upper karma
#

Well you cant fight against your school, so you have to follow it

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Or the education system

supple gazelle
#

how does one

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do this

upper karma
#

Do you know what csc (x) is

supple gazelle
#

no 😭

upper karma
#

Lol

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Its $\csc(x)=\frac{1}{\sin(x)}$

somber coyoteBOT
slate bay
#

Stands for Caesar salad croutons, btw.

upper karma
#

@supple gazelle so you just gotta find sin(x)

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There is even one unnecessary info but oh well

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Are you here? @supple gazelle

supple gazelle
#

Yeah, I got a call hold on

languid swan
upper karma
#

give you the answer?

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Hell no @languid swan.

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It goes against the rules

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Lmao

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Its now a meme on this server @upper karma

languid swan
#

My man

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Who the hell invented this useless crap

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What should being a professional wrestler have to do with this crap

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I simply dont have time for this. Thats why I just want an answer

upper karma
#

Uhh that question again..

languid swan
#

tHat qUesTIOn aGain

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am I wrong?

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Seriously stupid dumb teacher stresses me out over such useless crap man

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When am I gonna use this? Never. My brothers finishing up college and he told me hes never had to use geometry again after like 9th grade

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Like thats absurd man. Theres no point in dis

upper karma
#

@languid swan well?

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you marked arc SV correctly on your paper

languid swan
#

wait

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So uv would be 138 then?

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or would it be 88?

upper karma
#

why would it be 88?

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Smart dudes

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😘

languid swan
#

uhhh

#

so its 138 then? Because that makes the most sense to me

#

Also im smart just not in geo or trig

upper karma
#

@languid swan Ahah

#

you only know that SU is a diameter

#

Yes

#

I know everything

languid swan
#

Yes I do

upper karma
#

segment TV is not

#

it's even slightly crooked if you look at it

#

it's not a straight line (like SU is)

#

anyway, yes

#

it's 138

#

arc VU is 138 deg

#

good job

languid swan
#

Are you actually lying?

#

I sense sarcasm

upper karma
#

you need to trust more people on the internet

#

especially those who promise you candy

#

but seriously, if arc SVU = 180

#

it's obvious, isn't it?

#

also, you shouldn't trust that diagram

#

trust the numbers instead

languid swan
#

Aight I’m sorry for the suspicision and how I acted

upper karma
#

because that "42 deg" angle... looks wider than 90 deg

#

🙂

languid swan
#

Trig got me stressed af

#

I hate doing trig especially when I’m fasting man

#

But you know what I appreciate your help sir

upper karma
#

sure thing

#

sometimes they make these diagrams all crooked so you won't use a protractor like a noob

#

if you would, that would probably be a 105-120 degree angle

#

not 42

languid swan
#

Well thank you man I understand

#

You wanna look at a couple more if you don't mind?

upper karma
#

if they're trig related, sure

#

but I'm about to turn in for the night, so I can't promise anything

languid swan
#

aigh aigh itll only be a couple

upper karma
#

yes

#

I would make the 34.25 look more like .25

#

because it looks like .24

#

but, yeah

#

the second one looks like you got the formula wrong

#

WX is not the hypothenuse

#

this is wrong

#

the hypothenuse is the largest side in a triangle

#

I agree

covert spindle
#

I

#

I'm not sure if this counts here

#

I'm actually trying to calculate some thrust vectors for a rocket autopilot for a game, but at the end it's funny what it all boils down to

#

How to solve for cos(a) * sin(a) = n?

#

I've tried to google but I find googling math in general hard

dark sparrow
#

cos(a) sin(a) = 1/2 sin(2a)

covert spindle
#

If it was cos/sin I'd just spin it around and make it a tangent but it's *

#

Damn

#

Why is that?

dark sparrow
#

look up "double angle identities"

#

sin(2a) = 2sin(a)cos(a)

covert spindle
#

huh

versed river
#

thats the identity that you can use to solve this question

covert spindle
#

Yeah, ik

#

I'm still wondering

#

Apparently you derive that from the fact that sin (α + β) = sin α cos β + cos α sin β

#

However I can't find why that is

#

Like

#

Why sin (α + β) = sin α cos β + cos α sin β

dark sparrow
#

look up "compound angle identity proof"

#

there are many out there

rich wolf
#

@covert spindle ever heard of eulers formula

raw jay
rich wolf
#

@raw jay ok

raw jay
#

AMD?

#

can you check dms?

upper karma
#

i just need help with the points

#

so like

#

my hw says

#

to plot five??

versed river
#

yeah, so just pick some x values to plot

#

choose ones that are whole numbers and aren't too difficult to calculate

upper karma
#

uhh

#

(0,1), (1,4)(2,16)(3,64)

raw jay
#

anyone good with geo that can with a test?

#

I can pa

#

pay

versed river
#

i mean that's correct but its 4 points

#

i would have chosen -1, 0, 1/2, 1, and 2

upper karma
#

ok

versed river
#

1/2 since its just sqrt(4)

upper karma
#

wait

#

what would that look like

#

on the graph

versed river
#

4^(1/2)=2 so the point is (1/2,2)

upper karma
#

ok

#

next

#

would be

#

uh

#

lol

#

@versed river

#

would i get it wrong

#

if i did mine

versed river
#

no you wouldn't

#

but you would need 5 points remember

#

you only said (0,1), (1,4)(2,16)(3,64) which is 4 points

upper karma
#

64

#

isnt even on the graph

#

i have 4 currently

#

with the graph you helped me with

#

can you help me get 1 more

versed river
#

you could do x=-1

#

so f(-1)=4^(-1)=[?]

upper karma
#

-1, 4

#

that doesnt make sense

versed river
#

thats cause its wrong

#

$4^{-1} \neq 4$

somber coyoteBOT
versed river
#

have you done negative exponents in class?

raw jay
#

someone please

#

im legit gonna fail

#

ill pay u

upper karma
#

well

raw jay
#

lol

upper karma
#

yes

raw jay
#

i dont wanna get grounded

versed river
#

<@&268886789983436800> @raw jay

raw jay
#

bro..

zenith ember
#

Don't do that.

#

We're happy to help, but we're not going to do the work for you.

upper karma
#

@versed river ah

#

i see

#

4, 1

zenith ember
#

And offering money will get you banned.

upper karma
#

nope

raw jay
#

sorry

upper karma
#

im wrong again

#

xd

raw jay
#

it's just in an hour and im gonna die

versed river
#

nice try but yeah thats not right

#

hmm if you havent done negative exponents and 64 isnt on the graph...

zenith ember
#

Yeah. And especially not on a test.

upper karma
#

yeah?

versed river
#

you could do x=3/2 ig

#

ok, so you have done rational exponents like 4^(3/2)?

upper karma
#

yes

versed river
#

ok, good so g(3/2)=4^(3/2)=?

upper karma
#

24 @versed river

versed river
#

hmm not quite

#

what did you do to get 24?

upper karma
#

am i graphing

#

or

#

evaluating

#

what am i doing here

#

simplifying

versed river
#

you have to evaluate to get the points on the graph...

#

can you evaluate 4^(3/2)?

upper karma
#

yes

versed river
#

its not 24... what did you do to get 24? if your answer has changed from 24 just tell me that

upper karma
#

4^ is 4 squared

#

correct

versed river
#

4^2 is 4 squared yes

upper karma
#

ok

versed river
#

im not seeing what this has to do with 4^(3/2) though

upper karma
#

it has to be 24?

#

simplifying it

#

thats what im getting it

#

unless

#

10.66 repeating

versed river
#

$4^{\frac{3}{2}}=(4^{3})^{\frac{1}{2}}$

somber coyoteBOT
versed river
#

its neither of those

upper karma
#

;-;

versed river
#

you agree with what ive written above?

upper karma
#

yes

versed river
#

so, thats $64^{\frac{1}{2}}$

somber coyoteBOT
versed river
#

which is?

upper karma
#

?

#

simplified?

#

it's a whole number

versed river
#

$64^{\frac{1}{2}}=\sqrt{64}=?$

somber coyoteBOT
rich wolf
#

$=\pm8$

somber coyoteBOT
versed river
#

yes. we're just talking about +8 here ofc since its the principal root, but that gives us a point

upper karma
#

8

#

right

versed river
#

ok, so we have (3/2,8) as a point now

#

that's 5 points

#

in total

upper karma
#

looks good right

versed river
#

thats not right

upper karma
#

.

versed river
#

so your points were (0,1)(1/2,2)(1,4)(3/2,8) and (2,16)

upper karma
#

yes

versed river
#

why have you plotted (3,2)

#

and you havent plotted(3/2,8)

upper karma
#

smh

#

im sorry

#

its midnight

#

i have gotten like 3 hours of sleep this week

#

working 40 hours..

versed river
#

that looks much better

upper karma
#

HAHA

#

ok

versed river
#

good job then

languid swan
#

Anyone here late at night able to help with trig

dark sparrow
#

it's not late at night for everyone

#

in my timezone it's 07:51

languid swan
#

Are you good with trig?

dark sparrow
#

i suppose so

#

what's your problem

languid swan
dark sparrow
#

what the fuck is this even saying

versed river
#

how do you define an angle by 4 points thonk

dark sparrow
#

my question exactly

#

wait ok

#

the L is meant to be the angle symbol i think?

#

so it's $\angle MKN$ they're talking about

somber coyoteBOT
dark sparrow
#

that's the only thing i can think of

#

you do not need any trig here

stray hedge
#

someone help with answer please

rich wolf
#

@stray hedge bro they literally are congruent

dark sparrow
#

we do not give out answers here

rich wolf
#

Look at the sides

#

Then you can prove the rest

languid swan
#

Ann

#

So do you know what to do or not?

dark sparrow
#

do you know how to find the length of an arc given its radius and angle?

languid swan
#

Uhh

#

Might’ve forgot 😭

dark sparrow
#

might wanna refresh yourself on that

#

if you're measuring angles in degrees, it'll be $L = \frac{\pi r \theta}{180}$

somber coyoteBOT
languid swan
#

I can’t even see the image

rich wolf
#

Same lol

#

Is something up with discord

#

My internet is fine

#

Maybe mobile discord specifically

dark sparrow
#

nope this is happening to me on mobile too

#

L = πrθ/180

languid swan
#

Uhhh

#

What are you tryna do

dark sparrow
#

i'm reproducing the formula in plaintext because of discord's current hiccup with images

languid swan
#

You think you can explain what your doing to solve the question

raw jay
languid swan
#

Because I think that’ll help me understand the best

#

Discord is buggin is anyone else having trouble seeing msgs

dark sparrow
#

i did not provide a solution

#

nor did i intend to

languid swan
#

Then-

dark sparrow
#

you have three quantities (arc length, angle and radius) and a formula relating them
two of them are known and you need to find the third

languid swan
#

Bruh

#

Aight thanks for wasting my time

#

Next?

dark sparrow
#

did you expect me to provide you with a complete worked solution or what

#

i'm trying to boil this down to something you could do on your own

languid swan
#

That is exactly what I expected

dark sparrow
#

WELL TOO BAD THEN

#

we don't do that here

languid swan
#

The other guy did it

raw jay
languid swan
#

wasted my precious 20 mins girl

dark sparrow
#

boo hoo fucking hoo

upper karma
#

i would appreciate help 🙂

languid swan
#

Shouldn’t have trusted someone with that ugly pfp lmfao

upper karma
#

raider, i can tell you the answer.

languid swan
#

What

#

You looking at the rigjt thing bro

#

?

upper karma
#

yeah man

languid swan
upper karma
#

oh

#

it's 174 degrees.

languid swan
#

Wait how

silent plank
#

look up / apply the formula for arc length

dark sparrow
#

that's what i tried to give them

#

but they refused to cooperate

raw jay
silent plank
#

do you know the definitions of those terms?

raw jay
#

kinda

#

yeah

silent plank
#

where are you stuck?

raw jay
#

I dont know how to do it

#

like I check answers

#

but its wrong

silent plank
#

what does it mean for 2 angles to be complementary?

raw jay
#

uhh idk

silent plank
#

kinda
yeah

raw jay
#

nvm

#

i dont know

silent plank
#

look up the definitions of those terms.

#

and attempt the problem again

#

(since its kinda necessary to know what the question is asking for)

raw jay
#

can you help me answer it so I can reflect back

#

and put it into terms

#

of what each one means

silent plank
#

try to look up the info yourself, the definitions are relatively simple and come back if you still don't understand them.

upper karma
silent plank
#

same person different account?

versed river
#

thonk there's two of them

silent plank
#

or is it a coincidence that two people are stuck on the same question at the same time

#

and are posting in the same server

rich wolf
#

Maybe they are classmates

#

Or something to that effect

surreal flume
#

i like girls

dark sparrow
#

good for you

#

wrong channel tho

upper karma
#

Where can I get co ordinate geometry help?

#

Just post it here

#

Im pretty sure it belongs to geometry

upper karma
#

I need to find the angle in blue. The middle angle is 112 and the upper one is 56 degrees

📎 unknown.png
#

can somebody explain how i can find the angle?

silent plank
#

the "blue angle" is ambiguous

high zephyr
#

draw a slight arc from one arm to the other arm of the angle you're trying to find

silent plank
#

^ drawing a circle like that implies angle around a point which is 360°

upper karma
#

no not the blue angle

#

its the angle

#

uhhh

#

wait

high zephyr
#

I need to find the angle in blue. The middle angle is 112 and the upper one is 56 degrees

upper karma
#

like this

#

lol

silent plank
#

ok thats much better

upper karma
#

yeah kind of messed up

silent plank
#

consider properties of tangents and angle sum of a quadrilateral

upper karma
#

hm i still dont get it really :/

#

wait

#

is the middle one the same as the blue or am i just stupid

silent plank
#

no

#

do you know any properties of tangents to a circle?

upper karma
#

some yes but i dont know how to apply them in this case

silent plank
#

list them

upper karma
#

Ohh wait

silent plank
#

forgot to mention that they also seem to want you to apply the inscribed angle theorem

upper karma
#

there are two 90 degree angles there right?

#

Ohhh

#

that makes it much easier lol

#

i did not realise that

silent plank
#

to justify that that is indeed the center of the circle

upper karma
#

Yeah

#

Well yeah, I got the answer.

#

Thank you!

pastel trench
#

Question 40

upper karma
#

Well you aren't retarded bc you cant answer 1 question

pastel trench
#

No I’m retarded people at my age can solve this easily

upper karma
#

@pastel trench anyways, notice that when circle C touches x-axis at A the coordinate of A should be (0, y) and B (x, 0)

#

Just reasoning

pastel trench
#

Yep

#

And x=y?

upper karma
#

Can you continue from here?

pastel trench
#

Because the radius just touches x and y axis

upper karma
#

What

pastel trench
#

Idk I tried to make a quadratic equation but ends up being maths error

#

Since it passes thru p(8,4)
And it touches y and x axis
So x coord of centre is equal to radius and so do y coord

#

So x coord is equal to y coord

#

And for that I set up an equation where

#

(x-8)^2 + (x-4)^2 is equal to x

#

And it forms quadratic equation
2x^2-25x+80=0

#

And I got math error

#

@upper karma please help don’t go

#

Literally crying stuck for several hours

upper karma
#

I just dont understand your reasoning

#

Have you drawn it

#

You should

pastel trench
#

Idk how to visualise

upper karma
#

Well start with an x and y axis

#

And draw a circle

pastel trench
#

Ok

#

@upper karma

#

That’s how I deduced y=x

#

Because y=r&x=r

#

And from here I’m stuck

#

Ok nvm I give up : (

#

Too overwhelming : (

upper karma
#

(x-8)^2 + (x-4)^2 is equal to x
@pastel trench why this tho

#

Im back

#

Its being used

#

@glacial finch well its a simple pythagoream problem

glacial finch
#

What’s the answer?

#

@upper karma

upper karma
#

We dont do that here

glacial finch
#

What’s the formula?

upper karma
#

Just do pythagoras

#

Whats the formula of pythagoream theorem?

glacial finch
#

Got it

#

A^2 + b^2 = c^2

#

Thanks

upper karma
#

Np

#

@pastel trench can you go back and explain me how did you got (x-8)²+(x-4)²=x?

ripe dove
#

“Passes through” doesn’t mean “has its center at”

upper karma
#

^

#

I guessed he really gave up

upper karma
#

Good morning everyone.

#

Given a point A=(x_A, y_A), what is the angle of A and the origin when compared to the x axis?

quiet mason
#

Draw it out on a graph

#

Will be pretty clear

full sierra
#

ight i need help

#

the problem is that the book is in spanish and idk if yall gonna understand

pastel anchor
umbral snow
#

What's S? Surface area?

pastel anchor
#

YES

#

i have to find the x

umbral snow
#

Well, what's the surface area of the shape?

pastel anchor
#

616

umbral snow
#

Lol fair, that is the surface area of the shape

#

I mean, can we find it in terms of the dimensions?

#

Since you don't have x, we can just use x as if we did have it

pastel anchor
#

i think im supposed use the right prism formula

#

S=2b+Ph

umbral snow
#

I don't think I know that one!

pastel anchor
#

idk its in my textbook so

umbral snow
#

What's b, p, h in this case?

pastel anchor
#

any help?

upper karma
#

Yes

vague berry
#

i need some help

upper karma
#

Post it

upper karma
#

@vague berry Post it

vague berry
#

ok

#

1 and 3

#

only

#

i need help help i couldnt study cuz i had to take care of my gramz shes sick

#

@upper karma @upper karma

weak shoal
#

@vague berry Sure, what have you tried so far?

vague berry
#

i tried this

#

i did 2 successfully

#

just 1 and 3

weak shoal
#

you did 1 successfully as well, from the looks of it

vague berry
#

really?

weak shoal
#

yea it looks fine

vague berry
#

i cant do it in that 3rd step