#geometry-and-trigonometry | Mathematics | Page 282

upper karma May 18, 2020, 9:52 PM

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How do you remember back like, 5 hrs-

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Iconic 🤩

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scroll up?

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right click message - copy link

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@upper karma Your status fake information tbh.

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Wait lemme get the video

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https://youtu.be/uD4izuDMUQA

YouTube

melodysheep

TIMELAPSE OF THE FUTURE: A Journey to the End of Time (4K)

Support my work on Patreon: https://www.patreon.com/melodysheep | Get the soundtrack: https://bit.ly/2HKl9fi | How's it all gonna end? This experience takes us on a journey to the end of time, trillions of years into the future, to discover what the fate of our planet an...

▶ Play video

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Wow you noticed my status

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:D

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That was at 1:32 and you’ve been helping a lot of people since then and there’s been a lot of problems and it-

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Yea, I would forget :(

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Your status assumes that we are the only life form tho.

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I specified humans

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Oh wait

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Life isn't humans tho.

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No like life on earth

brisk ginkgo May 18, 2020, 9:57 PM

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Lmfao I realized there’s a lot of math servers

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Gonna keep joining

upper karma May 18, 2020, 9:57 PM

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Bruhh.

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It said that in the video too

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Like the chances for you to be alive?

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Like it was a ctrl c+ctrl v

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No

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The chances for you to be alive is like $\frac{1}{10^{2.5m}}$

somber coyoteBOT May 18, 2020, 9:57 PM

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leviosa:

📎 604465962053533709.png

upper karma May 18, 2020, 9:57 PM

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How long life is compared to the whole universe time length

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Until like all black holes die left and there’s nothing left in the universe

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So time becomes irrelevant

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"Life is possible for .0000000000000000000000000000000000000000000000001% of the universe's lifetime."

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This suggests that the chance of life in general is that number in the universe's lifetime.

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Yesyes, it was a line in the video

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It’s not saying the “chance of life”

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We haven't discovered even a fraction of the universe.

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We only know that we're the only one.

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Astrophysicists are using what they can to predict how long it will be until the “end”

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What if, hypothetically, we are the only living things in the entire universe and there were no more planets of life to arise?

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I also wouldn’t suggest we talk this out here

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Wouldn't the chance of life in a universe's lifetime be 0.

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And we'd be an outlier?

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But there’s no hypotheses to this

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This is near-accurate information from a factual video

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From what astrophysicists know

brisk ginkgo May 18, 2020, 10:00 PM

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I need help solving this

📎 image0.jpg

upper karma May 18, 2020, 10:01 PM

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Alright, you can think what you want in the end ig, but I’m definitely not arguing here and I would agree with the scientific video. Keep talking if you want, I’ll just ignore you ig

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That video is far from scientific.

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Unless assumptions = science, then sure.

pearl lava May 18, 2020, 10:02 PM

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Umm what does that have to do with geometry?

remote heart May 18, 2020, 10:02 PM

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this

upper karma May 18, 2020, 10:02 PM

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Mb.

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I'm out.

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📎 image0.png

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Good, finally

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sigh

pearl lava May 18, 2020, 10:02 PM

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why is that in here lmao?

upper karma May 18, 2020, 10:03 PM

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Someone just attacked my status

pearl lava May 18, 2020, 10:03 PM

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ooooooh

upper karma May 18, 2020, 10:03 PM

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And wanted an argument abt it in here

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Loll

pearl lava May 18, 2020, 10:03 PM

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wow

upper karma May 18, 2020, 10:03 PM

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@upper karma Wow attack.

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I only bothered to challenge it.

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Well you were pretty aggressive..

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And I thought you said you’d leave?

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Unless you’re actually helping..

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Alright, you can think what you want in the end ig, but I’m definitely not arguing here and I would agree with the scientific video. Keep talking if you want, I’ll just ignore you ig
@upper karma As if this was not aggressive?

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Lmao talking shit about me is helping.

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Nice.

remote heart May 18, 2020, 10:05 PM

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I think he just meant for a debate

upper karma May 18, 2020, 10:05 PM

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I’m not? I literally just pointed out all the verified sources for you. You’re saying all of those sites are wrong when it’s the closest info we can get.

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Not in this channel, oh no

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In DMs, I would be fine

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I only pointed out that your status was assuming that we're the only life form.

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But I don’t wanna waste my time arguing

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“Your status is wrong”

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And then you went on a rampage on how your sources are superior to whatever anyone says.

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All life on earth

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Your status suggests life in general in the universe..?

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Not my sources.. accurate, scientific sources confirmed by astrophysicists and other scientists

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I literally just copied what the video said

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Watch it before you start an argument

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You realize one of their sources was "Google."

remote heart May 18, 2020, 10:06 PM

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you might be misinterpreting @upper karma

upper karma May 18, 2020, 10:06 PM

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Some google sites like .gov are accurate

pearl lava May 18, 2020, 10:06 PM

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Wow this is some pretty good geometry

upper karma May 18, 2020, 10:06 PM

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Lol fr.

pearl lava May 18, 2020, 10:06 PM

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this is more than I learn in school

upper karma May 18, 2020, 10:07 PM

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Then leviosa can leave and we can continue with actual Geo

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Like they said they would

remote heart May 18, 2020, 10:07 PM

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#discussion , or no?

brisk ginkgo May 18, 2020, 10:07 PM

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I still need helpppp

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Sorry if I seem impatient

upper karma May 18, 2020, 10:07 PM

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I know, I’m trying

brisk ginkgo May 18, 2020, 10:07 PM

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No it’s fine lol

upper karma May 18, 2020, 10:07 PM

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No worries haha

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Sorry abt this argument

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@brisk ginkgo inscribed angle

brisk ginkgo May 18, 2020, 10:08 PM

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Ok

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@upper karma

upper karma May 18, 2020, 10:09 PM

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RS would be double the measure of angle SUR

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Because of the inscribed angles theorem

pastel anchor May 18, 2020, 10:09 PM

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is number 2 even possible

📎 Screenshot_76.png

upper karma May 18, 2020, 10:09 PM

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@brisk ginkgo https://youtu.be/GppOSNTi5OA?t=717

YouTube

The Organic Chemistry Tutor

Circle Theorems

This geometry video tutorial provides a basic introduction into circle theorems. It contains plenty of examples and practice problems.

Here is a list of topics:

If a radius is perpendicular to a chord, it bisects the chord into two congruent segments. The point of conta...

▶ Play video

brisk ginkgo May 18, 2020, 10:10 PM

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I’m unsure on how to set up though @upper karma

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@upper karma oh lol I see the video

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Similar problem

upper karma May 18, 2020, 10:10 PM

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Then measure angle STR is congruent to measure angle SUR because they share the same intercepted arc.

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AO is 1/2 the diameter. The diameter is 8. So take 1/2 of 8 for AO.

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Zezexx ^

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@pastel anchor if the diameter (AC) = 8 ... the radius = ?

pearl lava May 18, 2020, 10:11 PM

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What is an inscribed angles theorem?

upper karma May 18, 2020, 10:12 PM

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📎 image0.png

brisk ginkgo May 18, 2020, 10:12 PM

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Wait wrong

upper karma May 18, 2020, 10:12 PM

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Goosy ^

pearl lava May 18, 2020, 10:12 PM

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...

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My head broke

pastel anchor May 18, 2020, 10:12 PM

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@upper karma 4

brisk ginkgo May 18, 2020, 10:12 PM

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The video

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They way make problem is shaped differently

pearl lava May 18, 2020, 10:12 PM

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how to calculate the length of the arc?

upper karma May 18, 2020, 10:13 PM

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📎 image0.png

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@brisk ginkgo

📎 unknown.png

brisk ginkgo May 18, 2020, 10:14 PM

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Ok

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I just don’t know what to plug for the inscribe angle

pearl lava May 18, 2020, 10:15 PM

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how do you even find the arc?

upper karma May 18, 2020, 10:15 PM

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You would multiply 32 by 2 PWE

pearl lava May 18, 2020, 10:15 PM

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why?

brisk ginkgo May 18, 2020, 10:15 PM

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Ok

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So it’s 64

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Why would I multiply by 2 tho? @upper karma

upper karma May 18, 2020, 10:16 PM

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Because of the intercepted angles theorem

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📎 image0.png

brisk ginkgo May 18, 2020, 10:16 PM

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Would RS be 64?

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@upper karma

upper karma May 18, 2020, 10:16 PM

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SUR is the inscribed angle

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Arc SR is the intercepted arc

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Yes, arc SR is 64 degrees

pearl lava May 18, 2020, 10:17 PM

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So how do you find the arc?

upper karma May 18, 2020, 10:17 PM

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SR is the intercepted Arc of the inscribed angle STR

brisk ginkgo May 18, 2020, 10:17 PM

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Ok thank u

upper karma May 18, 2020, 10:17 PM

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@pastel anchor

📎 unknown.png

brisk ginkgo May 18, 2020, 10:17 PM

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Omg I gotta go out now

upper karma May 18, 2020, 10:17 PM

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Np

brisk ginkgo May 18, 2020, 10:17 PM

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I’ll be back lol

upper karma May 18, 2020, 10:17 PM

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Alright

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Sure cx

brisk ginkgo May 18, 2020, 10:17 PM

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My mom be calling me

pearl lava May 18, 2020, 10:17 PM

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My brain broke

pastel anchor May 18, 2020, 10:17 PM

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yea i said that already @upper karma

pearl lava May 18, 2020, 10:17 PM

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How do you find the length of a circle's arc

upper karma May 18, 2020, 10:18 PM

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📎 unknown.png

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the entire thing is 360 degrees

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and that quarter is 90 degrees

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what do you think the measure of angle BCA is?

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Goosy, you’d use proportions:

📎 image0.jpg

pastel anchor May 18, 2020, 10:20 PM

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i thoguht angle BCA was a typo

pearl lava May 18, 2020, 10:21 PM

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Wait the arc length can be in degrees?

upper karma May 18, 2020, 10:21 PM

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Yes, there’s degrees for arc length and distance of an arc length

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A whole circle is 360 degrees

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📎 unknown.png

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^this is angle BCA

pastel anchor May 18, 2020, 10:22 PM

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wow i didnt think of that

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so its 270

upper karma May 18, 2020, 10:22 PM

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obtuse angles are a thing, you know

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360 - 90, yes

pastel anchor May 18, 2020, 10:23 PM

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yea it just looks weird ig, most of the time at school they use the standard generic shapes

pearl lava May 18, 2020, 10:23 PM

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My eyes never saw this much math before

pastel anchor May 18, 2020, 10:31 PM

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how would the formula look like?

📎 Screenshot_77.png

upper karma May 18, 2020, 10:31 PM

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@pearl lava

📎 unknown.png

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just an example

pastel anchor May 18, 2020, 10:38 PM

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send help pls guys last quesstion of my hw 😭

upper karma May 18, 2020, 10:39 PM

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📎 unknown.png

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A rectangle = ?

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or, another way to look at it (not the actual values):

📎 unknown.png

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12 = ?

pastel anchor May 18, 2020, 10:41 PM

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why did u divide by 56? i thought it subtraction

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and isnt 7x suppose to be 7+x because it says "more"

upper karma May 18, 2020, 10:42 PM

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oops

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I read it as 56 times less

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my bad

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📎 unknown.png

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x * x = x^2

pastel anchor May 18, 2020, 10:45 PM

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why did u do 7x?

upper karma May 18, 2020, 10:46 PM

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it probably should've been a vertical rectangle, right?

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area of the rectangle is x * 7x

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either way, it still the same thing

pastel anchor May 18, 2020, 10:47 PM

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but wouldn't the "more" means its adding

upper karma May 18, 2020, 10:47 PM

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oh, man...

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I'm tired, and it shows

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yes, you're right

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it's really late here

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I should be sleeping

pastel anchor May 18, 2020, 10:48 PM

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np i think i understand now

upper karma May 18, 2020, 10:56 PM

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📎 SPOILER_unknown.png

buoyant mirage May 18, 2020, 10:57 PM

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anyone have a good trig book for independent study?

upper karma May 18, 2020, 10:57 PM

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and since the width of the rectangle = side of square (which is x) ...

weak shoal May 18, 2020, 10:57 PM

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Try Israel Gelfand's Trigonometry @buoyant mirage

buoyant mirage May 18, 2020, 10:57 PM

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thanks

upper karma May 18, 2020, 10:58 PM

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@buoyant mirage https://www.khanacademy.org/math/trigonometry

Khan Academy

Trigonometry | Khan Academy

Learn trigonometry for free—right triangles, the unit circle, graphs, identities, and more. Full curriculum of exercises and videos.

buoyant mirage May 18, 2020, 10:59 PM

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thanks :)

weak shoal May 18, 2020, 10:59 PM

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Wowww i didn't get a smiley face sadcat

buoyant mirage May 18, 2020, 11:00 PM

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thinks OwO

upper karma May 18, 2020, 11:07 PM

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all right, I'm off to bed

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I posted the solution above

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hopefully it's correct (I'm really tired)

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g'night

gentle sparrow May 18, 2020, 11:47 PM

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can i use sin to find the angles opposite of 7

📎 Screenshot_2020-05-18_at_19.47.07.png

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the angle to the left of the 90 degree angle

upper karma May 18, 2020, 11:48 PM

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Yes you can

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You can do

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Arcsin7/sqrt74=Angle left of the right angle

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$arcsin:\frac{7}{\sqrt{24}}=$ Angle left of the right angle

somber coyoteBOT May 18, 2020, 11:59 PM

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B):

📎 397918068199653386.png

upper karma May 18, 2020, 11:59 PM

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And then just punch that into your calculator xP

rich wolf May 19, 2020, 12:44 AM

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@upper karma

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\arcsin

upper karma May 19, 2020, 12:46 AM

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Ah thank you!

stark snow May 19, 2020, 1:56 PM

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$$\sin{(b - 1)\theta} - \sin{(a-1)\theta} = 0$$

$$\sin{(b - 1)\theta} = \sin{(a-1)\theta}$$

$$(b - 1)\theta = (a - 1)\theta$$

$$\theta ( b - a ) = 0 \Rightarrow \theta = 0$$

somber coyoteBOT May 19, 2020, 1:56 PM

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Daniel Cann:

📎 341594962779176961.png

stark snow May 19, 2020, 1:56 PM

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Why is this wrong to solve for theta? Why can't you simply take inverse sine of both sides like this?

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I did it correctly afterwards using a formula I looked up online for sin(A) - sin(B)

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But I would like to know why this doesn't work

umbral snow May 19, 2020, 2:12 PM

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What function are you applying to both sides to go from line 2 to line 3?

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Basically, "take sin off one factor" isn't a function that exists. @stark snow

silent plank May 19, 2020, 2:14 PM

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^ generally arcsin(sin(x)) \neq x
also improper placement of parentheses

umbral snow May 19, 2020, 2:14 PM

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Ohh oops I fell for the parentheses

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Listen to Ramonov he's smarter

stark snow May 19, 2020, 2:16 PM

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I was trying to do arcsin of both sides

silent plank May 19, 2020, 2:16 PM

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$\sin(b-1)\theta$ implies $\sin(b-1)\times \theta$ which I'm almost certain isn't what you intended.

somber coyoteBOT May 19, 2020, 2:16 PM

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ramonov:

📎 220517274845577216.png

stark snow May 19, 2020, 2:16 PM

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No

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Well

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It's what the book uses ahaha

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But I agree, it's not really what I intend

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But I mean sin((b-1)theta)

umbral snow May 19, 2020, 2:17 PM

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Ultimately yes, because arcsin isn't really a proper inverse to sin. It works only for "a part" of sin, and you have to reason your way out of the cases where it doesn't work

stark snow May 19, 2020, 2:17 PM

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Ahh yes

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that makes sense

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okay thanks

upper karma May 19, 2020, 3:21 PM

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How does a right triangle with one of the angles being more than 90 degrees even work

dark sparrow May 19, 2020, 3:21 PM

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in euclidean geometry it doesn't

upper karma May 19, 2020, 3:22 PM

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Well someone showed it in a graph

dark sparrow May 19, 2020, 3:22 PM

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can you show the graph

upper karma May 19, 2020, 3:22 PM

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Said sin120 was 0.5 or something I'll need to check later

dark sparrow May 19, 2020, 3:22 PM

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oh that

upper karma May 19, 2020, 3:23 PM

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https://youtu.be/yAHl_kpqr-k

YouTube

Coding Math

Coding Math: Episode 2 - Intro to Trigonometry

In this episode, I cover some of the more useful basics of trigonometry - sine, cosine, tangent, with more in depth coverage of sine. Ending with a coding experiment that renders a sine wave.

Support Coding Math: http://patreon.com/codingmath
Source Code: http://github.com/bi...

▶ Play video

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Around 5 min mari

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Mark*

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Like the opposite side literally flipped from the right side to the left side

ripe dove May 19, 2020, 3:24 PM

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Better have been sin(150degrees) is .5

dark sparrow May 19, 2020, 3:24 PM

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sin(120°) is sqrt(3)/2, not 1/2.
anyway

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📎 unknown.png

upper karma May 19, 2020, 3:25 PM

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Wait he said it was .866

dark sparrow May 19, 2020, 3:25 PM

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the 120 degree angle is no longer inside the triangle

upper karma May 19, 2020, 3:25 PM

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For sin120

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Wouldn't it just be not a right triangle then why would the entire opposite side just appear on the left

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Or is this one of those abstract things that I shouldn't think too hard on

ripe dove May 19, 2020, 3:27 PM

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@brisk ginkgo you need to find an open channel

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@upper karma the 120 degree angle is not inside the triangle

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There is A right triangle still, but it has a 60 degree angle inside instead of the 120 degree angle

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The initial triangle has “broken”

dark sparrow May 19, 2020, 3:28 PM

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Wouldn't it just be not a right triangle then why would the entire opposite side just appear on the left
it's still a right triangle

ripe dove May 19, 2020, 3:28 PM

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If you notice, it’s not just the opposite side that had to move

upper karma May 19, 2020, 3:29 PM

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So beyond 90 degrees the hypotenuse stops working?

ripe dove May 19, 2020, 3:29 PM

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In plane geometry, the sum of the INTERNAL angles of a triangle is 180degrees

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And there MUST BE 3 angles

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In a right triangle, one of the angles is 90 degrees

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No angle in a triangle can have a negative measure

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So both of the other angles INSIDE the triangle MUST BE smaller than 90 and sum to 90

upper karma May 19, 2020, 3:32 PM

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It's still hard for me to grasp but I think I'm getting a bit of it

ripe dove May 19, 2020, 3:33 PM

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The right triangle that appears when someone uses an angle of 120 degrees is the same triangle as if they had used 60 degrees

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It has just been turned around/reflected across the y-axis

upper karma May 19, 2020, 3:34 PM

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I guess it's the whole turning around thing that confuses me. I keep trying to find a real example of that in my head but there's nothing

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Perhaps it's just an abstract concept or something that doesn't necessarily have a direct connection to a real life phenomenon?

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It is in a plane after all

ripe dove May 19, 2020, 3:36 PM

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📎 video0.mov

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Does that Help?

upper karma May 19, 2020, 3:39 PM

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Idk I just feel like I have a triangle and I extended it beyond 90 degrees, it'll just end up looking like those 2d pyramid shape triangles

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But not necessarily equilateral, a badly shaped pyramid

ripe dove May 19, 2020, 3:46 PM

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In order to do that, you must abandon the right angle

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What I’m saying is that you are correct, if an internal angle of the triangle is greater than 90 degrees there is an obtuse triangle that can be made.

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📎 image0.jpg

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@upper karma

upper karma May 19, 2020, 3:53 PM

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@brisk ginkgo

📎 unknown.png

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angle STR = T in the middle, T is the "tip" of the angle

brisk ginkgo May 19, 2020, 3:57 PM

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@upper karma would it equal to 32?

upper karma May 19, 2020, 3:57 PM

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I mean, look at where it's "opening" up to

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it's opening up to a 64 degree arc

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what do you think?

brisk ginkgo May 19, 2020, 3:58 PM

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I thought it be 32 since it’s congruent? @upper karma

upper karma May 19, 2020, 3:58 PM

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it's an inscribed angle

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same as angle SUR

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did you not learn about inscribed angles?

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didn't I link you a video yesterday?

brisk ginkgo May 19, 2020, 3:59 PM

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Yeah u did

upper karma May 19, 2020, 3:59 PM

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https://youtu.be/GppOSNTi5OA?t=728

YouTube

The Organic Chemistry Tutor

Circle Theorems

This geometry video tutorial provides a basic introduction into circle theorems. It contains plenty of examples and practice problems.

Here is a list of topics:

If a radius is perpendicular to a chord, it bisects the chord into two congruent segments. The point of conta...

▶ Play video

brisk ginkgo May 19, 2020, 4:00 PM

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Thank u!

upper karma May 19, 2020, 4:01 PM

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sure thing

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📎 unknown.png

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all of them are congruent

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(meaning they're the same)

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because they open up to 64 degrees

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and they're inscribed angles

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so that means they're all 32 degrees

brisk ginkgo May 19, 2020, 4:03 PM

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@upper karma it is 32

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@upper karma thank u!

upper karma May 19, 2020, 4:03 PM

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same as angle SUR, yes

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they're all congruent to angle SUR

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if they were to start from the center of the circle, it would've been a different story

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(see the above video)

brisk ginkgo May 19, 2020, 5:06 PM

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📎 image0.jpg

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I just don’t understand this question lmfao

upper karma May 19, 2020, 5:11 PM

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https://youtu.be/GppOSNTi5OA?t=1663

YouTube

The Organic Chemistry Tutor

Circle Theorems

This geometry video tutorial provides a basic introduction into circle theorems. It contains plenty of examples and practice problems.

Here is a list of topics:

If a radius is perpendicular to a chord, it bisects the chord into two congruent segments. The point of conta...

▶ Play video

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@brisk ginkgo

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it's called "the chord-chord power theorem"

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you really should watch that entire video

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you might just learn something

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if not, search youtube for "circle theorems"

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pick a video

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and always read the comments because sometimes they mess up

brisk ginkgo May 19, 2020, 5:27 PM

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@upper karma thank u!

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@upper karma can u give me a time lapse of which part to watch?

upper karma May 19, 2020, 5:28 PM

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click the video

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it has a timestamp

brisk ginkgo May 19, 2020, 5:28 PM

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Oh ok

upper karma May 19, 2020, 5:29 PM

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27:43

brisk ginkgo May 19, 2020, 5:31 PM

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@upper karma thanks and neither of them is possible right?

upper karma May 19, 2020, 5:32 PM

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do you really need to ask? ...

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I mean...

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if you multiplied them correctly, are you really not sure of the result?

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5 * 12 = 6 * 10 ?

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well?

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are they equal?

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4 * 9 = 6 * 8

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again, equal?

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also, why are you quitting Discord immediately

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?

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I don't... understand

brisk ginkgo May 19, 2020, 5:35 PM

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Oh no I’m not quitting discord lol

upper karma May 19, 2020, 5:35 PM

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is it because of the notification sounds?

brisk ginkgo May 19, 2020, 5:35 PM

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I’m multitasking

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Behind behind......

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@upper karma

upper karma May 19, 2020, 5:35 PM

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it says you're offline

brisk ginkgo May 19, 2020, 5:35 PM

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It does?

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Ok I put online

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Yeah I’m just double checking

upper karma May 19, 2020, 5:37 PM

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you need to have a little more confidence in your work

brisk ginkgo May 19, 2020, 5:39 PM

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@upper karma literally exactly what my teachers say lmfao they say I overthink a lot

upper karma May 19, 2020, 5:40 PM

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you have a calculator on your phone, right? use that to check your work

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even though in general, you should avoid using one

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because you won't have access to one during tests

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or when you're in front of a whiteboard

brisk ginkgo May 19, 2020, 5:42 PM

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We are allowed to use calculator in test

upper karma May 19, 2020, 5:58 PM

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Ahah

brisk ginkgo May 19, 2020, 7:24 PM

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Ok this one I don’t understand

📎 image0.jpg

upper karma May 19, 2020, 7:26 PM

#

UwU

#

@brisk ginkgo Very easy

#

For 2nd one, see if the intersecting secants theorem applies

#

And this for the 1st one @brisk ginkgo

📎 image0.jpg

#

Use google sometimes son

#

Google has many valid answers

#

Just interpret what is happening in the diagram

#

See how in the diagram it shows a tangent and secant intersecting

brisk ginkgo May 19, 2020, 7:29 PM

#

Like I didn’t use google lol

upper karma May 19, 2020, 7:29 PM

#

?

brisk ginkgo May 19, 2020, 7:29 PM

#

Thank u

upper karma May 19, 2020, 7:29 PM

#

Learn theorems son

brisk ginkgo May 19, 2020, 7:29 PM

#

I did use google but i couldn’t find it

upper karma May 19, 2020, 7:30 PM

#

Geometry is all about theorems

#

@brisk ginkgo Just interpret what’s happening inside the circle

#

You do know what a tangent and secant is right?

brisk ginkgo May 19, 2020, 7:30 PM

#

@upper karma wait PC? What would I do with 20 and 28?

upper karma May 19, 2020, 7:31 PM

#

Is 20 the length of the outer segment?

#

Look at the picture I sent u

#

https://media.discordapp.net/attachments/326138757474680852/712386187431510066/image0.jpg

#

Check this too, see how I just specified how a tangent and secant is intersecting.

📎 image0.png

brisk ginkgo May 19, 2020, 7:32 PM

#

Yeah PC^2

#

Look at my problems

#

It doesn’t even have letters

#

@upper karma

upper karma May 19, 2020, 7:32 PM

#

What is PC?

#

https://media.discordapp.net/attachments/326138757474680852/712385240634621972/image0.jpg

#

It doesn’t specify what is pc

#

What u talking about?

brisk ginkgo May 19, 2020, 7:33 PM

#

Intersect at point u

#

So the equation for diagram A I did 20*22

upper karma May 19, 2020, 7:34 PM

#

https://media.discordapp.net/attachments/326138757474680852/712386187431510066/image0.jpg Try again

#

20 * 28 = 22^2

#

If it’s correct

#

Then the diagram is true

#

@brisk ginkgo

brisk ginkgo May 19, 2020, 7:36 PM

#

Ok thanks!

upper karma May 19, 2020, 7:36 PM

#

But do you understand how I got the equation 20 * 28 = 22^2?

#

Do you?

brisk ginkgo May 19, 2020, 7:36 PM

#

Yeah

upper karma May 19, 2020, 7:36 PM

#

Alright 👍

brisk ginkgo May 19, 2020, 7:36 PM

#

The PC part I wasn’t sure

#

@upper karma so it’s not possible diagram a?

upper karma May 19, 2020, 7:37 PM

#

Check your arithmetic

#

Does it equal?

brisk ginkgo May 19, 2020, 7:38 PM

#

Nope

upper karma May 19, 2020, 7:38 PM

#

Correct

#

Yes

brisk ginkgo May 19, 2020, 7:38 PM

#

I got 560=44

upper karma May 19, 2020, 7:38 PM

#

Good job

#

Ya but it’s 22 squared

#

Not 22 x 2

#

@brisk ginkgo You understand?

brisk ginkgo May 19, 2020, 7:39 PM

#

Oh

#

Still not possible

upper karma May 19, 2020, 7:39 PM

#

Ya

#

Good job

#

@paper oar Awesome

brisk ginkgo May 19, 2020, 7:40 PM

#

@upper karma for diagram B I have to do 4524 and 4923?

upper karma May 19, 2020, 7:40 PM

#

Hold on

#

Do you know what the intersecting secant theorem is?

brisk ginkgo May 19, 2020, 7:41 PM

#

Why did my numbers change?

upper karma May 19, 2020, 7:41 PM

#

What

brisk ginkgo May 19, 2020, 7:41 PM

#

So both of them not possible

upper karma May 19, 2020, 7:41 PM

#

What theorem did you apply on the second one

brisk ginkgo May 19, 2020, 7:41 PM

#

Nm

upper karma May 19, 2020, 7:42 PM

#

?

#

📎 image0.jpg

#

Did you apply this theorem?

#

@brisk ginkgo

brisk ginkgo May 19, 2020, 7:44 PM

#

Yeah

#

Same thing!

upper karma May 19, 2020, 7:44 PM

#

Ya it’s false

#

It isn’t possible

#

Good job

brisk ginkgo May 19, 2020, 7:45 PM

#

Thank u!

upper karma May 19, 2020, 7:45 PM

#

👍

foggy path May 19, 2020, 10:35 PM

#

Hello I need some trig help for class work

upper karma May 19, 2020, 10:35 PM

#

Yes

#

I got u

foggy path May 19, 2020, 10:36 PM

#

The equation is 4cscx + cot^2x=-5

upper karma May 19, 2020, 10:36 PM

#

Yeah nvm

#

Sorry

foggy path May 19, 2020, 10:36 PM

#

🥺

upper karma May 19, 2020, 10:36 PM

#

Ping helpers if u need to

foggy path May 19, 2020, 10:36 PM

#

It’s ok

#

@river forge

#

@old holly

#

@graceful totem

#

<@&286206848099549185>

weak shoal May 19, 2020, 10:42 PM

#

Stop tagging 1000 different people for your problem

upper karma May 19, 2020, 10:43 PM

#

Keep going @foggy path

#

Oh my god thats so annoying @foggy path

#

Stop

weak shoal May 19, 2020, 10:44 PM

#

We know that:

$\sin^2(x)+\cos^2(x) = 1$

$1 + \frac{\cos^2(x)}{\sin^2(x)} = \frac{1}{\sin^2(x)}$

$1 + \cot^2(x) = \csc^2(x)$

Now, let $\cos^2(x) = \csc^2(x)-1$. Then:

$4\csc(x)+\csc^2(x)-1 = -5$

upper karma May 19, 2020, 10:44 PM

#

Didn't even waited the 15mins rule smh

somber coyoteBOT May 19, 2020, 10:44 PM

#

Abhijeet Vats:

📎 340191992636243968.png

weak shoal May 19, 2020, 10:44 PM

#

This is a quadratic in $\csc(x)$

somber coyoteBOT May 19, 2020, 10:44 PM

#

Abhijeet Vats:

📎 340191992636243968.png

weak shoal May 19, 2020, 10:44 PM

#

I hope you can do something with that

foggy path May 19, 2020, 10:54 PM

#

Lol it didn’t @weak shoal

#

But thx for trying to help

rich wolf May 20, 2020, 12:15 AM

#

@foggy path let csc(x) = c

#

then

#

$c^2+4c+4=0$

somber coyoteBOT May 20, 2020, 12:15 AM

#

AMD:

📎 251927217800478720.png

rich wolf May 20, 2020, 12:15 AM

#

solve for c

upper karma May 20, 2020, 12:42 AM

#

ok

sullen pollen May 20, 2020, 1:23 AM

#

hey guys can y’all solve this problem for me i’m stuck on it on my homework

#

📎 image0.png

upper karma May 20, 2020, 2:19 AM

#

@sullen pollen Still need?

sullen pollen May 20, 2020, 2:20 AM

#

yes

upper karma May 20, 2020, 2:23 AM

#

@sullen pollen The angle AKD is given.

#

Use that to get x. (180-that angle)

#

Then use laws of sines to get y.

#

Then use pythagorean theorem to get w (since you have 2 sides of that triangle.)

#

Angle AKD is 130.

sullen pollen May 20, 2020, 2:25 AM

#

ok heres what i got could u check?

#

📎 image0.jpg

upper karma May 20, 2020, 2:26 AM

#

How'd you solve for x?

#

📎 circle-theorems-no-brainers-n.png

#

Look at 1.

sullen pollen May 20, 2020, 2:28 AM

#

okay

#

i’m still very confused on x

upper karma May 20, 2020, 2:29 AM

#

x=130.

sullen pollen May 20, 2020, 2:29 AM

#

ohhh okay

rich wolf May 20, 2020, 2:29 AM

#

i wouldn't say that 1 and 2 are no brainers necessarily

sullen pollen May 20, 2020, 2:29 AM

#

but my y and w were correct right?

upper karma May 20, 2020, 2:30 AM

#

No.

#

Because your x was initially wrong.

#

But your method seems to be right.

sullen pollen May 20, 2020, 2:34 AM

#

my head is bursting 😂

#

so i would change the sin and tan from 65 degrees to 130 and then solve it again

upper karma May 20, 2020, 2:36 AM

#

Yes.

#

Jkjk.

sullen pollen May 20, 2020, 2:38 AM

#

?

ripe dove May 20, 2020, 2:49 AM

#

x is not 130

#

130 is the supplement of x

#

because x is inside that little right triangle

sullen pollen May 20, 2020, 2:53 AM

#

@ripe dove so was my previous answer for x correct?

ripe dove May 20, 2020, 2:53 AM

#

no, that was wrong too

#

because x corresponds to angle BKD

sullen pollen May 20, 2020, 2:54 AM

#

do you know how to solve for x?

ripe dove May 20, 2020, 2:54 AM

#

yes, i know what x is

sullen pollen May 20, 2020, 2:54 AM

#

so x is 50

ripe dove May 20, 2020, 2:54 AM

#

oddly enough, so did @upper karma earlier

#

Use that to get x. (180-that angle)

#

yes, x is 50

#

degrees

sullen pollen May 20, 2020, 2:55 AM

#

thankyou

#

is there a theorem for that? o

ripe dove May 20, 2020, 2:58 AM

#

well, angle AKD and angle BKD are supplementary since AB is a straight line

#

and the sum of the measure of supplementary angles is 180 degrees

upper karma May 20, 2020, 3:00 AM

#

Awesome

#

Oh oof.

#

Accidentally said x=130.

#

Smh mb.

#

Yes

sullen pollen May 20, 2020, 3:49 AM

#

this should be correct? @ripe dove

📎 image0.jpg

upper karma May 20, 2020, 4:04 AM

#

@sullen pollen Ye.

#

Is anyone here good at identifying and proving trig identities? I am having trouble with them

versed river May 20, 2020, 4:14 AM

#

Plenty of people, but you gotta post the actual question you want help with

upper karma May 20, 2020, 4:14 AM

#

Ah ah I’m sorry

versed river May 20, 2020, 4:14 AM

#

Dw mate

upper karma May 20, 2020, 4:16 AM

#

Here is my first one

📎 image0.png

#

Okay what can you do on the spot.

#

You can do 2 things using trig identities.

#

Sneaky you help.

#

I gtg.

versed river May 20, 2020, 4:22 AM

#

Bruh im in class now. Start by multiplying both sides by (1+tan^2(x)) since those fractions are ugly. Then notice that you have sin^2x+cos^2x which is equal to 1

#

See what you can do from there

upper karma May 20, 2020, 4:23 AM

#

Ok uh

#

?

#

No.

#

Don't listen to him.

#

@upper karma sin^2+cos^2=...?

#

I’m sorry I really don’t know

#

Oh.

#

I have the functions and stuff

#

Bruh you kinda need to know trig identities.

versed river May 20, 2020, 4:24 AM

#

Huh what did i do wrong

upper karma May 20, 2020, 4:24 AM

#

@versed river Easier way to solve this.

#

All I know is this

📎 image0.png

#

A lot easier way.

#

Okay sin^2+cos^2=?

#

Oh wait Lima

#

*lmao

#

1

#

Alright.

#

Now the numerator is 1+cot^2

#

What is that?

versed river May 20, 2020, 4:25 AM

#

Oh ok i see yeah thats mb

upper karma May 20, 2020, 4:25 AM

#

2nd collumn first row KEKW

#

csc^2x

#

And then the denominator is 1+tan^2.

#

Which is?

#

3rd collumn first row KEKW

#

sec^2x

#

Oh oh and then

#

Yeah the rest should be easy.

#

cot^2x/sec^2x is cot^2x

#

Yeah.

#

Wait no

#

It is.

#

Wait.

#

Wtf is that cot doing there.

#

csc^2/sec^2=cot^2

#

Yea that’s what I meant

#

csc^2=1/sin^2
sec^2=1/cos^2.

#

(1/sin^2)/(1/cos^2)=(cos^2)/(sin^2)=cot^2.

#

Basically multiply by reciprocal.

#

📎 image0.png

upper karma May 20, 2020, 4:45 AM

#

https://gyazo.com/d9c188a4f87c2f5254ad68da5f894be6

Gyazo

umbral snow May 20, 2020, 4:54 AM

#

,w graph 4^x

somber coyoteBOT May 20, 2020, 4:54 AM

#

📎 wolf.png

Display results online and refine query

rich wolf May 20, 2020, 4:59 AM

#

,w graph exp(xln4)

somber coyoteBOT May 20, 2020, 4:59 AM

#

📎 wolf.png

Display results online and refine query

raw jay May 20, 2020, 10:49 AM

#

is anyone good at geometry and able to help me?

gleaming yoke May 20, 2020, 10:55 AM

#

could someone explain to me how it went from h/10 to 1/10 ?? (if u need more context i can provide - its an exercise on double angle formulae)

📎 Screen_Shot_2020-05-20_at_8.54.26_pm.png

versed river May 20, 2020, 10:57 AM

#

this step? both sides divided by h

📎 unknown.png

gleaming yoke May 20, 2020, 11:04 AM

#

aa right, ty

upper karma May 20, 2020, 11:18 AM

#

<@&268886789983436800>

#

@raw jay no offering money; against the rules

#

remove it from your msg

#

read #rules

nocturne thorn May 20, 2020, 11:31 AM

#

How can I find the sides of the triangle?

#

📎 unknown.png

upper karma May 20, 2020, 11:44 AM

#

is triangle ABC an isosceles triangle?

nocturne thorn May 20, 2020, 11:44 AM

#

yes

little osprey May 20, 2020, 11:45 AM

#

Is it equilateral

nocturne thorn May 20, 2020, 11:45 AM

#

sadly not

little osprey May 20, 2020, 11:46 AM

#

What have you covered so far in class

upper karma May 20, 2020, 11:48 AM

#

you need 3 things to solve a triangle, either one of these scenarios: AAS, ASS, AAA, SSS

nocturne thorn May 20, 2020, 11:48 AM

#

Recipical Identities, Tangent Identities, Contangent Identity, Pythagorean Identities, Law of sines, Ambiguius case, Angle Difference Identities, Angle sum idnntities, etc..

little osprey May 20, 2020, 11:48 AM

#

Ok so trig

#

epic

#

cosine?

upper karma May 20, 2020, 11:49 AM

#

cosine of what?

little osprey May 20, 2020, 11:49 AM

#

law of cosines

nocturne thorn May 20, 2020, 11:49 AM

#

yes

upper karma May 20, 2020, 11:49 AM

#

ok, law of cosines

#

with what?

little osprey May 20, 2020, 11:50 AM

#

I was just asking

#

with triangles ig

upper karma May 20, 2020, 11:50 AM

#

it's missing the distance to the triangle

nocturne thorn May 20, 2020, 11:50 AM

#

I need a side, but i can't figure out how to find a side

#

what if I do this:

#

📎 unknown.png

little osprey May 20, 2020, 11:52 AM

#

ok, how will you utilise that

upper karma May 20, 2020, 11:53 AM

#

then you would have two angles and a side

#

which is enough to solve it

little osprey May 20, 2020, 11:53 AM

#

Is AcC and BcC right angles

upper karma May 20, 2020, 11:54 AM

#

he said it's an isosceles triangle, so... if that's the height, then yes

little osprey May 20, 2020, 11:54 AM

#

True DSpider

upper karma May 20, 2020, 11:54 AM

#

they're right angles

little osprey May 20, 2020, 11:55 AM

#

I only caught on to what you ment about the congruent triangles now DSpider 😅

nocturne thorn May 20, 2020, 11:56 AM

#

I forgot to tell u guys that this is a real life scenario question. The math teacher told us to create a clinometer to measure the angles. I just measured beta and it's 110

upper karma May 20, 2020, 11:57 AM

#

📎 unknown.png

#

~~you have two angles now~~

nocturne thorn May 20, 2020, 11:58 AM

#

u are smart

#

holy cows xD

azure reef May 20, 2020, 11:58 AM

#

beta= 110?

#

oh no

little osprey May 20, 2020, 11:58 AM

#

Hello Commander

upper karma May 20, 2020, 11:58 AM

#

angle beta is less than 90 degrees

azure reef May 20, 2020, 11:58 AM

#

beta is 25 hence

#

hello jc

#

with known alpha however now you actually know all the triangle's angles

upper karma May 20, 2020, 11:59 AM

#

UPDATE: this is wrong:

📎 unknown.png

azure reef May 20, 2020, 12:00 PM

#

since 180-alpha should be equal to the two remaining angles of triangle which you obtain by extending height

#

and since one of them would be 90 deg you have half of an angle ACB

#

hence you have ACB as well

#

and is triangle isosceles? it is, so the remaining two angles of ABC are also known now

#

with three angles and at least one side you are done

#

and, actually, i suppose you implicilty have at least one side

upper karma May 20, 2020, 12:04 PM

#

UPDATE: this is wrong:

📎 unknown.png

azure reef May 20, 2020, 12:04 PM

#

180 minus sum

#

of the remaning two

upper karma May 20, 2020, 12:04 PM

#

hint: all angles from a triangle need to add up to 180

#

yep

azure reef May 20, 2020, 12:04 PM

#

and you have one side also

#

so from this you can find the remaining two sides

#

and so on

upper karma May 20, 2020, 12:05 PM

#

wait...

nocturne thorn May 20, 2020, 12:05 PM

#

huh

#

how does that help me with finding sides a b c?

upper karma May 20, 2020, 12:06 PM

#

155 + 25 = 180, it's wrong

azure reef May 20, 2020, 12:06 PM

#

you have two right triangles also
one with catet h and also catet 13+h

#

90-65 = 25 -> beta = 25

#

huh really

#

~~you have two angles now~~
because here is a mistake

upper karma May 20, 2020, 12:08 PM

#

it's not 25

azure reef May 20, 2020, 12:08 PM

#

alpha can not be just moved down if it still "points" to the C

#

i mean it changes the angle

#

oh yes, look i cannot draw it but if you move a down by 177 cm you ll be able to find beta = 90-65=25

#

so beta is 25 it is correct

nocturne thorn May 20, 2020, 12:12 PM

#

📎 unknown.png

azure reef May 20, 2020, 12:12 PM

#

ano

nocturne thorn May 20, 2020, 12:12 PM

#

isn't betta 55

#

beta*

#

wait

#

nvm

upper karma May 20, 2020, 12:15 PM

#

📎 unknown.png

azure reef May 20, 2020, 12:15 PM

#

rough sketch

📎 unknown.png

upper karma May 20, 2020, 12:16 PM

#

📎 unknown.png

#

@azure reef are you sure those alphas are right?

azure reef May 20, 2020, 12:17 PM

#

yes

upper karma May 20, 2020, 12:18 PM

#

📎 unknown.png

#

those lines would have to be parallel

#

what makes you think they are?

azure reef May 20, 2020, 12:19 PM

#

it the only configuration that preserves alpha

upper karma May 20, 2020, 12:19 PM

#

that would also make the height of the triangle 177

#

and it might not be

dire mural May 20, 2020, 12:19 PM

#

um sorry to bother you guys, but I need help with math :/

azure reef May 20, 2020, 12:20 PM

#

that would also make the height of the triangle 177
@upper karma btw it is

upper karma May 20, 2020, 12:20 PM

#

@dire mural use another channel, this is occupied.

dire mural May 20, 2020, 12:20 PM

#

Sorry!

upper karma May 20, 2020, 12:21 PM

#

Use anyone that isnt being used like #help-3

dire mural May 20, 2020, 12:23 PM

#

okay

azure reef May 20, 2020, 12:23 PM

#

since 25+25=50

90+a+90+a=360-50

📎 unknown.png

#

nvm

#

we know a lol

#

oh shit

#

i am idiot

upper karma May 20, 2020, 12:25 PM

#

bruh

azure reef May 20, 2020, 12:25 PM

#

now we know one of the cathetus of rectangular triangle

#

and angle

upper karma May 20, 2020, 12:25 PM

#

is it a right angle

azure reef May 20, 2020, 12:26 PM

#

so we are actually able to find all the sides of rectangular triangle

#

and hence of original

nocturne thorn May 20, 2020, 12:26 PM

#

my brain is exploding

upper karma May 20, 2020, 12:26 PM

#

📎 unknown.png

#

so you have all 3 angles from this triangle

#

now you just need a side

minor flower May 20, 2020, 12:27 PM

#

i have a math test can anyone help?

upper karma May 20, 2020, 12:27 PM

#

@minor flower we don't help with tests

minor flower May 20, 2020, 12:27 PM

#

😦

upper karma May 20, 2020, 12:27 PM

#

it's against the rules

#

see number 6 from #❓how-to-get-help

nocturne thorn May 20, 2020, 12:29 PM

#

📎 image0.jpg

upper karma May 20, 2020, 12:30 PM

#

,rotate -90

somber coyoteBOT May 20, 2020, 12:30 PM

#

📎 525410943279169548.png

azure reef May 20, 2020, 12:32 PM

#

here, all you need is to find AC and AB from sines/cosines theorem

📎 unknown.png

upper karma May 20, 2020, 12:32 PM

#

what makes you think it's 25?

azure reef May 20, 2020, 12:32 PM

#

BC should be equal to 177

nocturne thorn May 20, 2020, 12:32 PM

#

📎 image0.jpg

#

Does that makes any sense?

upper karma May 20, 2020, 12:32 PM

#

,rotate -90

somber coyoteBOT May 20, 2020, 12:32 PM

#

📎 525410943279169548.png

azure reef May 20, 2020, 12:33 PM

#

here, all you need is to find AC and AB from sines/cosines theorem
@azure reef then you'll find AD from ADB triangle and by that you get DC and all sides

#

Does that makes any sense?
it does not give you anything since you are not able to find the sides

#

you have not enought data

upper karma May 20, 2020, 12:34 PM

#

@nocturne thorn what makes you think these are 65 degrees?

#

📎 unknown.png

azure reef May 20, 2020, 12:35 PM

#

follow my setting, it gives height and hence sides and two angles which is better

nocturne thorn May 20, 2020, 12:36 PM

#

here, all you need is to find AC and AB from sines/cosines theorem
@azure reef where did u get 25 ° from?

azure reef May 20, 2020, 12:36 PM

#

alpha is 65

upper karma May 20, 2020, 12:36 PM

#

📎 unknown.png

nocturne thorn May 20, 2020, 12:36 PM

#

oops

upper karma May 20, 2020, 12:37 PM

#

🙂

nocturne thorn May 20, 2020, 12:37 PM

#

📎 unknown.png

#

how can i go further to dind the answer

azure reef May 20, 2020, 12:37 PM

#

a = 65
BC = 177

#

ACB angle is also right angle

#

to you have triangle ACB with three angles and side

#

from these you are able to find AB

#

and AC also then is derived

nocturne thorn May 20, 2020, 12:39 PM

#

How is the angle 25? (the bottom left)

azure reef May 20, 2020, 12:39 PM

#

the issue then is to find BD or AD (-> CD)

#

How is the angle 25? (the bottom left)
@nocturne thorn because i just moved AB down by 177 units

#

so it is parallel

#

and preserves alpha angle

#

and hence presevers 90-a=90-65=25

nocturne thorn May 20, 2020, 12:40 PM

#

📎 unknown.png

#

Oh ok

upper karma May 20, 2020, 12:41 PM

#

^no

azure reef May 20, 2020, 12:41 PM

#

prove that no

#

oh

#

here

#

25 is inner angle of parallelogram

#

not outer

nocturne thorn May 20, 2020, 12:42 PM

#

what?

azure reef May 20, 2020, 12:42 PM

#

📎 unknown.png

nocturne thorn May 20, 2020, 12:43 PM

#

oh ok

azure reef May 20, 2020, 12:43 PM

#

then you just use cosine and sine theorem and that's it you got all sides

nocturne thorn May 20, 2020, 12:44 PM

#

oh that makes sense now

#

@azure reef thanks for your time

#

wait

#

how would i find the angles?

#

📎 unknown.png

azure reef May 20, 2020, 12:48 PM

#

25 = ABC

#

a = AC[lower end of height from A down]

nocturne thorn May 20, 2020, 12:49 PM

#

How would I find BDC and CDB?

#

and why do u think BC is 177?

upper karma May 20, 2020, 12:54 PM

#

📎 unknown.png

nocturne thorn May 20, 2020, 12:55 PM

#

that makes a lot more sense now

#

thanks @upper karma

#

but, do u know how i can find angle CAB?

#

📎 unknown.png

upper karma May 20, 2020, 1:12 PM

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I got nothing

#

do they give you the area of the isosceles triangle?

#

because then we could get the base of the triangle from that (side AB)

autumn wind May 20, 2020, 1:36 PM

#

Can i post graphs here?

little osprey May 20, 2020, 1:36 PM

#

yes

dark sparrow May 20, 2020, 1:36 PM

#

wdym

#

image sending is allowed and in fact encouraged for posting problems

little osprey May 20, 2020, 1:36 PM

#

^

autumn wind May 20, 2020, 1:36 PM

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I mean i'm new here caz i need help

#

and idk

dark sparrow May 20, 2020, 1:37 PM

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post your problem

#

it's PREFERRED that you send a picture

autumn wind May 20, 2020, 1:37 PM

#

oh..

#

it's in dutch so welp

#

:/

dark sparrow May 20, 2020, 1:37 PM

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post the pic and a translation

autumn wind May 20, 2020, 1:38 PM

#

Find S so that P is on the straight line a

📎 unknown.png

dark sparrow May 20, 2020, 1:38 PM

#

okay

#

so what's giving you trouble here?

autumn wind May 20, 2020, 1:39 PM

#

the problem

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i'm not good at geometry and first time we do it

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and it's online school teacher just gives us homework with no explanation

upper karma May 20, 2020, 1:43 PM

#

translate the description?

ripe dove May 20, 2020, 1:43 PM

#

P is the point (5,something)

autumn wind May 20, 2020, 1:43 PM

#

i did translate

ripe dove May 20, 2020, 1:43 PM

#

a is the line $ y = 2 x +1 $

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What is the x-coordinate of P?

#

If you put that into the equation for a, what must the y coordinate be?

somber coyoteBOT May 20, 2020, 1:45 PM

#

Malix:

📎 454774842491928596.png

upper karma May 20, 2020, 1:45 PM

#

P(x,y)

#

P(5,y)

#

what is the x coordinate of point P?

ripe dove May 20, 2020, 1:47 PM

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I wonder if they will answer if every helper asks the same question...

autumn wind May 20, 2020, 1:47 PM

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uhhh idk
that's all the problem gives

upper karma May 20, 2020, 1:48 PM

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the x coordinate of point P is 5

autumn wind May 20, 2020, 1:48 PM

#

yes

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and s is y

upper karma May 20, 2020, 1:48 PM

#

📎 unknown.png

#

yes

#

now, can you graph that line?

#

what does y = 2x + 1 look like?

#

https://www.desmos.com/calculator/4ucmumgzr2

Desmos

Desmos | Graphing Calculator

#

this is what it looks like

autumn wind May 20, 2020, 1:50 PM

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so s is 1?

upper karma May 20, 2020, 1:50 PM

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no

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open that website

autumn wind May 20, 2020, 1:51 PM

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yes i did

upper karma May 20, 2020, 1:51 PM

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draw your cursor/finger on the red line

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until you get to 5

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on the x axis

autumn wind May 20, 2020, 1:52 PM

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5;11

nocturne thorn May 20, 2020, 1:52 PM

#

📎 unknown.png

upper karma May 20, 2020, 1:52 PM

#

do you understand why it's 11?

#

hint: it rhymes with Mythagora

autumn wind May 20, 2020, 1:52 PM

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y axis

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uh no

#

u mean pythagora?

upper karma May 20, 2020, 1:53 PM

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well, I mean they don't ask you for the size of the segment

#

just the y coordinate

#

📎 unknown.png

#

how about now?

#

the horizontal line is the x axis

#

the vertical line is the y axis

autumn wind May 20, 2020, 1:55 PM

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yes

#

so y is 11 and x is 5

upper karma May 20, 2020, 1:56 PM

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so if you reach the x coordinate (which is 5) when you drag your finger on the red line...

#

you would also reach 11 on the y axis

autumn wind May 20, 2020, 1:56 PM

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yes

upper karma May 20, 2020, 1:56 PM

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ok

#

by the way, this is called linear algebra

autumn wind May 20, 2020, 1:56 PM

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so P(5;11)?

upper karma May 20, 2020, 1:57 PM

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yes

#

obviously

autumn wind May 20, 2020, 1:57 PM

#

and what if we changed the numbers

#

p(s;21)

upper karma May 20, 2020, 1:57 PM

#

and there's #linear-algebra for linear algebra related questions 🙂

#

same thing

#

first draw the line

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(make sure it's graphed correctly)

autumn wind May 20, 2020, 1:58 PM

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i just have to write it down

upper karma May 20, 2020, 1:58 PM

#

then drag your cursor/finger until you reach 21 on the y axis

autumn wind May 20, 2020, 1:58 PM

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ok ty

#

now i can do this

upper karma May 20, 2020, 1:58 PM

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good luck

autumn wind May 20, 2020, 1:58 PM

#

but i have one more that i have never heard of

upper karma May 20, 2020, 1:58 PM

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post it in #linear-algebra if it's similar to the one above

autumn wind May 20, 2020, 1:59 PM

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uh

#

i don't think it is

upper karma May 20, 2020, 1:59 PM

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is it related to trigonometry?

autumn wind May 20, 2020, 1:59 PM

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it's something with Cartesian equation

upper karma May 20, 2020, 1:59 PM

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if not, post in one of the free #help-5 [greek letter] channels

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cartesian equations = linear algebra

dark sparrow May 20, 2020, 2:00 PM

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uh

#

no

upper karma May 20, 2020, 2:00 PM

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no?

dark sparrow May 20, 2020, 2:00 PM

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no

upper karma May 20, 2020, 2:00 PM

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no 😦

dark sparrow May 20, 2020, 2:01 PM

#

linear algebra is about vectors and matrices and things like that

#

if you're just doing basic things with equations in 2 variables that's #prealg-and-algebra

nocturne thorn May 20, 2020, 2:12 PM

#

📎 unknown.png

#

is that correct? (the top right)

#

So angle C is 60

upper karma May 20, 2020, 2:16 PM

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no

nocturne thorn May 20, 2020, 2:17 PM

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huh

upper karma May 20, 2020, 2:18 PM

#

there's nothing to indicate the fact that the angle there is 30 degrees

nocturne thorn May 20, 2020, 2:19 PM

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i just realized aswell

#

I thought that it was a 90 degree angle

upper karma May 20, 2020, 2:21 PM

#

there's nothing to indicate that this angle is 90 degrees

📎 unknown.png

nocturne thorn May 20, 2020, 2:21 PM

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i know, it's wrong

#

i just had a though

#

Can we assume it is?

upper karma May 20, 2020, 2:22 PM

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based on what?

nocturne thorn May 20, 2020, 2:22 PM

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On nothing :/

#

I found sides: x, y, h and angles delta and beta

#

how can i move forward

upper karma May 20, 2020, 2:24 PM

#

the problem is that triangle ABC is completely independent of the other ones

#

at most, they share the height as one of the sides

#

but

#

you can't use that information if you don't have the area of triangle ABC

nocturne thorn May 20, 2020, 2:25 PM

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So, it's a dead end?

upper karma May 20, 2020, 2:26 PM

#

to solve triangle ABC (or any triangle, really) you need 3 things

#

AAS, ASS, SSS, AAA

#

A - angle

#

S - side

#

you have neither

#

you only have the height of triangle ABC

#

which I suppose you could use half of the triangle (since it's an isosceles triangle)

#

but then you'd only have one side

#

yay?

#

oh, and I suppose you also have an angle

#

(90 degrees)

#

so you have a side, and an angle

#

you need another side or an angle to solve it

#

AAS, ASS, SSS, AAA

nocturne thorn May 20, 2020, 2:29 PM

#

hmmmm, thanks a lot @upper karma

upper karma May 20, 2020, 2:29 PM

#

sure thing

azure reef May 20, 2020, 2:30 PM

#

📎 unknown.png

upper karma May 20, 2020, 2:31 PM

#

like I said, if they had given you the area of triangle ABC, you could've extracted the base of the isosceles triangle, and had another side to work with

nocturne thorn May 20, 2020, 2:32 PM

#

@azure reef

#

how do i find

📎 unknown.png

#

wait, that wont help me

#

right?

azure reef May 20, 2020, 2:33 PM

#

it was just notation

upper karma May 20, 2020, 2:33 PM

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that's the Greek letter "gamma"

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and it's completely unknown

dark sparrow May 20, 2020, 2:34 PM

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it's upside down

azure reef May 20, 2020, 2:34 PM

#

i mean it should be connected to the cosine and sine theorems

dark sparrow May 20, 2020, 2:34 PM

#

doesn't look like a gamma

#

$\gamma$

somber coyoteBOT May 20, 2020, 2:34 PM

#

Ann:

📎 183668144404037632.png

dark sparrow May 20, 2020, 2:34 PM

#

this is a gamma

azure reef May 20, 2020, 2:34 PM

#

it is lambda btw

#

supposed to be huh

#

$\lambda$

somber coyoteBOT May 20, 2020, 2:34 PM

#

Commander Vimes:

📎 694042020100046990.png

nocturne thorn May 20, 2020, 2:35 PM

#

📎 unknown.png

ripe dove May 20, 2020, 2:35 PM

#

The little purple ones in the pic look like gammas

#

That is false

azure reef May 20, 2020, 2:36 PM

#

where did yo get 30 and 60?

ripe dove May 20, 2020, 2:36 PM

#

Unless there is supposed to be a variable somewhere

azure reef May 20, 2020, 2:36 PM

#

alpha was 65, no?

#

and beta 25

upper karma May 20, 2020, 2:37 PM

#

he changed it

#

or his teacher did

nocturne thorn May 20, 2020, 2:37 PM

#

📎 unknown.png

#

📎 unknown.png

#

to find that line

#

yeah, i changed it

azure reef May 20, 2020, 2:38 PM

#

wait but if you changed it makes the whole thing easier

upper karma May 20, 2020, 2:38 PM

#

yes, it's called the law of sines

#

it does, yes

nocturne thorn May 20, 2020, 2:38 PM

#

does it?

upper karma May 20, 2020, 2:38 PM

#

because 30-60-90 triangles have the shortest leg half of the hypothenuse

azure reef May 20, 2020, 2:38 PM

#

i mean sin30 and sin60 are table ones

upper karma May 20, 2020, 2:38 PM

#

but that still don't help you get sides a and/or b

azure reef May 20, 2020, 2:38 PM

#

and yes ^

nocturne thorn May 20, 2020, 2:39 PM

#

i hate math now

upper karma May 20, 2020, 2:39 PM

#

this problem is flawed

#

or it is missing information

azure reef May 20, 2020, 2:39 PM

#

btw, angle ACB should be quite small since it is anyway smaller than 30

little osprey May 20, 2020, 2:39 PM

#

I like how the building is irrelevant to the question but they decided to add it there

azure reef May 20, 2020, 2:40 PM

#

i firslty tried to understand what building is about

nocturne thorn May 20, 2020, 2:40 PM

#

xD

azure reef May 20, 2020, 2:40 PM

#

we are given its height but there is no connection

#

can you btw send original task?

upper karma May 20, 2020, 2:40 PM

#

yeah, post a pic of the problem

little osprey May 20, 2020, 2:40 PM

#

^

nocturne thorn May 20, 2020, 2:41 PM

#

i'll find it, give me a sec

#

📎 unknown.png

#

📎 unknown.png

little osprey May 20, 2020, 2:43 PM

#

IB 😂

#

What math are you in

nocturne thorn May 20, 2020, 2:44 PM

#

I'm in Algebra 2 w/ Trig, starting the IB next year

little osprey May 20, 2020, 2:44 PM

#

Oh youre just like me then, taking AA HL?

nocturne thorn May 20, 2020, 2:44 PM

#

i'm taking AA HL next year

little osprey May 20, 2020, 2:44 PM

#

Good luck

nocturne thorn May 20, 2020, 2:44 PM

#

xD

little osprey May 20, 2020, 2:45 PM

#

We'll be on the same playing field

azure reef May 20, 2020, 2:45 PM

#

wait but it does not look like there is an angle between your head and roof

nocturne thorn May 20, 2020, 2:45 PM

#

i guess, but it's a bit above my head

#

This exercise is so annoying

azure reef May 20, 2020, 2:49 PM

#

wait wait looks like your picture was a bit wrong

little osprey May 20, 2020, 2:49 PM

#

oof

#

I dont know what though

ripe dove May 20, 2020, 2:51 PM

#

Side AB appears to be the bottom edge of a quadrilateral not a triangle for one thing

upper karma May 20, 2020, 2:51 PM

#

^there's that

nocturne thorn May 20, 2020, 2:52 PM

#

I just created a point C

upper karma May 20, 2020, 2:52 PM

#

and you're trying to establish the distances between you and those points? from a 2D image?

ocean axle May 20, 2020, 2:52 PM

#

Consider all isosceles trapezoid in which we can inscribe a circle.
Restrictions are: sum of longer base and height of this trapezoid is equal to 2 (i.e. a+h = 2)

What are all values of a with those restrictions? That is, figure out all values of a.

little osprey May 20, 2020, 2:53 PM

#

Taken @ocean axle

ripe dove May 20, 2020, 2:53 PM

#

@upper karma no, the assignment says how would they do it without leaving their house

#

They have access to 3D

nocturne thorn May 20, 2020, 2:54 PM

#

I will probabaly just make up angles

#

from the picture to the points A / B

ripe dove May 20, 2020, 2:54 PM

#

You have no guarantee that the quadrilateral lends itself to an isosceles triangle

nocturne thorn May 20, 2020, 2:55 PM

#

"Actual measurements are not necessary" - i think i'm allowed to assume that it's the case here

#

cuz it looks like an isosceles triangle

upper karma May 20, 2020, 2:56 PM

#

you can get the distances to those points, for sure

#

how much lateral movement do you have from your window?

#

1m wide?

nocturne thorn May 20, 2020, 2:57 PM

#

1 meter

ripe dove May 20, 2020, 2:57 PM

#

That looks nothing like an isosceles triangle to me

#

The other face of that roof, yes. But not that one

#

That one looks an awful lot like you could make it a right triangle with your imaginary point c though

azure reef May 20, 2020, 3:04 PM

#

lol now imagine how it was for ancient greeks who didnt have disc

ripe dove May 20, 2020, 3:05 PM

#

Also, spitballing here, since you can assume line AB is horizontal is there a way to use the apparent difference of the angle from you to each of them to determine that length?

nocturne thorn May 20, 2020, 3:07 PM

#

I can use a homemade clinometer, but I just randomly picked the angles that looked like they were correct

ripe dove May 20, 2020, 3:08 PM

#

Well, you are supposed to “describe the process” not just get some answer

upper karma May 20, 2020, 3:10 PM

#

@nocturne thorn

📎 unknown.png

#

this is how you get the distance to point A

#

same with point B

#

then you form a triangle

#

and you get the distance between them

#

no clinometer needed

#

just lateral movement

#

(at a 90 degree angle)

nocturne thorn May 20, 2020, 3:11 PM

#

You are the absolute best @upper karma

upper karma May 20, 2020, 3:12 PM

#

this is similar to the ones from Khan Academy, btw

nocturne thorn May 20, 2020, 3:12 PM

#

check your DM's please @upper karma

upper karma May 20, 2020, 3:19 PM

#

you could also simplify it a bit

#

📎 unknown.png

#

by moving d1 to the other side

#

using the 90 degree angle

#

remember, both points (A and B) need to have a common vertex

#

this is a top-down view, btw

#

not sure if you got that