geometry-and-trigonometry

[little osprey]

the human being 5 feet high

[brittle knoll]

like on a stoll

this makes no snse

sense*

[little osprey]

It says

the kite is 5 feet above the ground

right?

[brittle knoll]

hold on

[little osprey]

so that means the additional height to the kite is 5 feet

[little osprey]

the base isnt 5 feet

its 5 feet above the ground

like the human

is 5 feet

high

[brittle knoll]

where does the 5 go

[little osprey]

on the human

which is beneath the right vertex of the triangle

[deep trail]

i made an actually good picture ok now i dont know what to do

[little osprey]

Kind of like this

but not the same values ofc

[steep temple]

https://cdn.discordapp.com/attachments/279435476757250049/700035853229097050/Screenshot_2020-04-15_at_18.32.04.png

[little osprey]

@brittle knoll

[steep temple]

i have deduced that 2 inequalities is enough to cover the area of every trapezium. is there a proof or something mathematically sound for this

[little osprey]

@deep trail Gameson the angles are from the GROUND

[deep trail]

it says 400 feet form the ground

[brittle knoll]

ok

so draw that

[little osprey]

Do you understand

[brittle knoll]

yes

first time ive seen this question

[little osprey]

ok good good good

yeah no worries

youve got this

[deep trail]

https://gyazo.com/9a308c0c25eebfabbd1f970dc68ac186

[little osprey]

angle of elevation

is from the ground

so could you please correct that

@steep temple Whats the question?

[steep temple]

is there a mathematical proof for my assertion

[brittle knoll]

is this right so far'

dont mind my 0

[little osprey]

no mannnn

the guy

is 5 feet high

not the base of the triangle

[steep temple]

what is your question

[brittle knoll]

i have no clue

[steep temple]

you dont know your question?

[brittle knoll]

You are holding a kite string in your hand. The angle of elevation from your hand to the kite is 44degrees and the distance to the kite is 250 feet. Your hand is 5 feet above the ground. How high is the kite? Round your answer to the nearest tenth of a foot.

[little osprey]

@steep temple Youre the one that presented an inequality

[steep temple]

?

[brittle knoll]

imma just guess

[steep temple]

i was talking to soupy

[little osprey]

Oh

@brittle knoll Do you remember this

Instead of 3 feet

make it 5

[steep temple]

the question should ask how high the kite is relative to the ground

or from the ground

or something to do with the ground to make it clear what you're meant to find out

[little osprey]

yeah

but soupy is having difficulty that the hand is 5 feet off the ground

So im trying to help him understand that first

[steep temple]

all you're meant to do is find the length of the opposite side and add it to the offset from the ground, no?

[little osprey]

yeah

but look at his diagram

[steep temple]

yeah im looking at his diagram

[little osprey]

if he cant understand the person is 5 feet high

[steep temple]

i think your diagram is really good at explaining the problem

[little osprey]

Thank you

[steep temple]

@brittle knoll the question is telling you the triangle is levitating 5 feet above the ground but in a confusing manner

[steep temple]

yes

[brittle knoll]

we have never done this type of question

[little osprey]

YESSSS

[steep temple]

what does that mean

[little osprey]

GOOD JOB SOUPY

OOFOGKSGSDOGDKSGSDG

[brittle knoll]

so where does the 44 go

[little osprey]

angle of elevation

do you know what that means?

[brittle knoll]

no sir

[little osprey]

well do you know what elevation means

[brittle knoll]

yes

[little osprey]

could you give an educated guess of where the 44 degrees would be then

hint: you have placed the 44 degrees in previous diagrams correctly

[steep temple]

this is your question, soupy

hold on

[little osprey]

nice DLP!!!

[little osprey]

GOOD JOB SOUPY

[steep temple]

the goal is to work out l_1 + l_2

[brittle knoll]

so what formula would i need to solve this

[steep temple]

now tell me

which length do you already know

[brittle knoll]

hyp

[steep temple]

no i mean

which length

l_1 or l_2?

look at my diagram

[brittle knoll]

2

[steep temple]

2...?

[brittle knoll]

its 5

[little osprey]

Do you know trigonometry soupy

[steep temple]

ok so we know the value of l_2

therefore our answer is l_1 + 5

[brittle knoll]

yes but im a slow leaner and very stupid

[steep temple]

now we have to figure out l_1

[steep temple]

which side of the triangle is l_1

[brittle knoll]

idk sir

[steep temple]

ok name every side of the triangle

[little osprey]

corresponding to the 44 degrees

[steep temple]

ok lets relax on the drawing and just message for now

ok but name the side

O...?

[brittle knoll]

o=opposite

[steep temple]

okay

do you know sohcahtoa

[brittle knoll]

yes

[steep temple]

ok

so what are we meant to do here

https://cdn.discordapp.com/attachments/326138757474680852/700040408750620682/Screenshot_2020-04-15_at_18.50.31.png

we already worked out l_2

what is left to do

remember our answer is l_1 and l_2

[brittle knoll]

are we trying to work out l_2 or tan 250/5

[steep temple]

so if we already have l_2 then all that is left to work out is...

[upper karma]

Can anyone help me I posted in question b

[steep temple]

what

ok from l_1 and l_2 which length do we know

[brittle knoll]

how would we solve for l_1

[steep temple]

first of all lets make sure we know all the pieces of information up to this point

[upper karma]

Evalutate sec^-1x use the values of what

[steep temple]

which length do we already know?

[brittle knoll]

distance =250 length from the hand to the kite is 5

i give up bruh

[steep temple]

ok

lets look back at what i said

your final answer is l_1 + l_2

do you see those 2 lengths annotated on the graph

[brittle knoll]

what does that mean

yes'

[steep temple]

it means length 1 and length 2

[brittle knoll]

so where solving for the height aka length 1

[steep temple]

no

the height of the kite is l_1 + l_2

[brittle knoll]

ok

[steep temple]

so i am asking you

[brittle knoll]

i understand part now

[steep temple]

between the 2 lengths

which one do we already know

[brittle knoll]

2

[steep temple]

refer to it as l_2

ok

[brittle knoll]

ok

l_2

[steep temple]

so the height is l_1 + 5

do you agree

[brittle knoll]

yes

[steep temple]

ok

so what side of the triangle (relative to the angle) is l_1 found on?

[brittle knoll]

the opposite side

[steep temple]

okay

so which part of sohcahtoa do we use

(keep in mind the other side you have is the hypotenuse)

(and the side you are trying to work out is the opposite)

[brittle knoll]

sine

[steep temple]

ok

write out the equation

[brittle knoll]

so sin44 x/250

[steep temple]

write out the equation

sin44 = ...

[brittle knoll]

sin44= x/250

[steep temple]

ok

if we replace x with l_1 we see it is within our grasps

sin44° = l_1/250

[brittle knoll]

so x+5?

sin44=x+5/250

[steep temple]

no no

the height is l_1 + 5

[brittle knoll]

im retarded

[steep temple]

we haven't figured out l_1 yet

[brittle knoll]

so do we use sin to find it out

[steep temple]

well you established it's the correct ratio to use, no?

based on sohcahtoa

[brittle knoll]

yes

[steep temple]

okay so our equation is at

sin44° = l_1/250

now we have to rearrange to solve for l_1

so write out the equation again, but this time rearranged

[brittle knoll]

how would i rearrange it

im basically wasting your time is sorry

[steep temple]

well you're trying to seperate the l_1 on one side of the equation

lets keep it on the RHS

so to do that we'd need to move the /250

how do u counter division

[brittle knoll]

250sin=x/44?

[steep temple]

(what is it's inverse operation)

[brittle knoll]

sum like that

[steep temple]

what is division's inverse operation

you take a number

you divide it by 2

what operation do you have to do on the new number to go back to the original number?

[brittle knoll]

https://tenor.com/view/sorry-stitch-gif-10399341

idk

[steep temple]

okay you have 10 apples

i take away 2 of your apples

how many apples do you have now

[brittle knoll]

i give up takes for your time i wasted it im guess im going to CC

[steep temple]

how many apples do you have now

[upper karma]

No dont give up @brittle knoll he is explaining very well

You are about to finish it

[brittle knoll]

8 apples

[steep temple]

what was your original apple count

[brittle knoll]

10

[steep temple]

what is your new apple count

[brittle knoll]

8

[steep temple]

what operation was performed for you to go from 10 apples to 8

[brittle knoll]

subtraction

[steep temple]

what operation needs to be performed for you to go from 8 apples to 10

[brittle knoll]

addition

[steep temple]

okay

subtraction-addition is 1 pair of inverse operations

[brittle knoll]

ok

[steep temple]

so if you have a number, x

and i subtract y from it

your new number is x-y

if i add y to your new number

it goes back to x, your original number

do you see

[brittle knoll]

yes

[steep temple]

so if i give you 2 apples how many apples do you have now

[brittle knoll]

4?

[steep temple]

you had 8 apples

[brittle knoll]

8

[steep temple]

and i give you 2

[brittle knoll]

10

[steep temple]

how many did you have originally?

[brittle knoll]

holy shit im stupid

10

[upper karma]

https://tenor.com/view/monkey-beauty-funny-animals-gif-8057241

[steep temple]

ok

so

what is division's inverse operation

okay if i divide your 10 apples by 5 how many apples do you have now

[paper mauve]

@upper karma find an open questions channel that doesn’t have a recently asked question or that has a question that’s been resolved and I’ll be happy to help you

[upper karma]

i'll be there, im just in an online classroom right now.

[steep temple]

someone has yet to answer my question

:(

[acoustic jungle]

I haven't bought any apples

0 apples

[rich wolf]

what question

[paper mauve]

Inverse of division is multiplication

[steep temple]

https://cdn.discordapp.com/attachments/279435476757250049/700035853229097050/Screenshot_2020-04-15_at_18.32.04.png

[rich wolf]

it doesn't make physical sense to divide apples by apples though

[steep temple]

is there a proof that states 2 inequalities is the minimum number to cover the area of a whole trapezium

[rich wolf]

you divide apples by making groups of them

[steep temple]

i didn't say if i "divide 10 apples by 5 apples"

i said "divide 10 apples by 5"

[rich wolf]

makes more sense

[steep temple]

@brittle knoll im not letting you go come back here finish your question

[foggy beacon]

hey guys i have a question please

If the cosine of an angle is −0.4328, can the angle be acute?

[steep temple]

no

[foggy beacon]

is this channel being used? sorry if i disturebed

i just feel like it's a trick question

[steep temple]

my calculator is telling me that's equal to roughly 115 degrees

[foggy beacon]

maybe it has to do with like rations and stuff

[steep temple]

which last time i checked is greater than 90 degrees

[foggy beacon]

like how different angles have teh same rations sometimes

[steep temple]

what do you mean

[ionic bluff]

the words acute and obtuse only make sense for positive angles less than 180 degrees

so no the angle itself is not acute

[steep temple]

how can angle be negative

[ionic bluff]

unit circle

going clockwise

lmao

[foggy beacon]

yeah

wiat guys so if i got 115 degrees, if i subtract 180 from it and i get -64 do they have the same cosine

no right?

[ionic bluff]

no

[foggy beacon]

oh

[ionic bluff]

cosine is an even function

[foggy beacon]

so how can i find that negative angle

[steep temple]

] EndTimes: unit circle
[7:22 PM] EndTimes: going clockwise

wtf does that mean

[ionic bluff]

shh

[steep temple]

there is no such thing as a negative angle

[ionic bluff]

you don't know unit circle yet

it's ok

[steep temple]

you cant have an angle which is -115 degrees

[foggy beacon]

i took it bro

[ionic bluff]

you can

[foggy beacon]

like the unit circle

[steep temple]

or -pi radians

[ionic bluff]

you can have -pi radians

[steep temple]

who the hell measures angles clockwise

[foggy beacon]

but i just don't know if i subtract 180-115 will have teh same ratio

[ionic bluff]

wdym?

[wide scroll]

@steep temple he left the discord

[foggy beacon]

like what should i say

[wide scroll]

i think he gave up

[ionic bluff]

?

just say the question again

[foggy beacon]

okay

If the cosine of an angle is −0.4328, can the angle be acute? If the sine of another angle is 0.3781, can the angle be obtuse? Explain [Communication]

[little osprey]

oof you tried dlp

[steep temple]

cos(x) = cos(360°±x)

[ionic bluff]

if the cosine is negative then the angle is not acute

[steep temple]

@little osprey so close as well 😔

[foggy beacon]

can I just tell her that?

[wide scroll]

i’ll dm him

[ionic bluff]

yes

[upper karma]

@steep temple so you were doing pretty good honestly

[ionic bluff]

because acute angles lie in quadrant I

[foggy beacon]

or will she say that the unit circle and negative agnles

alright yes thank u

[steep temple]

@upper karma thanx

[foggy beacon]

thank u so much endtimes i love u thank u

[ionic bluff]

Acute and obtuse only make sense for positive angles

np i gotchu

[wide scroll]

i think he got stressed but u did really good

[ionic bluff]

ronnie are you that guy's alt

[steep temple]

bro u and ur negative angles are anoying

[ionic bluff]

how do you know so much about him

lmao

just wait till you get to calc class

polar coordinates are fun

[steep temple]

unsatirically i like working with them

[ionic bluff]

we don't use (0, 2pi) for polar coordinates, but (-pi, pi)

[steep temple]

ok i will admit my assertion that negative angles do not exist was p. dumb

[ionic bluff]

very dumb indeed

[steep temple]

however they are just used for like trig identities bro

cos(x) = cos(360°±x)

or atleast that's what ive ever used them for

[ionic bluff]

try graphing arccos(x)

what is the domain?

[steep temple]

stupid orthogonal (incomplete) sinusoid

[ionic bluff]

what's the domain?

[wide scroll]

what’s the answers to sin44=85/224

[steep temple]

the answer is right there?

[silent plank]

sin44=85/224
doesn't make sense

[ionic bluff]

yeah lol there's nothing to solve for

[silent plank]

because it is clearly false

[ionic bluff]

yes

[steep temple]

domain = [-1, 1]

sin44 = 85/224 makes sense if sin is a custom function and not the trigonometric one

[rich wolf]

dlp ur being dum

why would someone name a custom function sin

[steep temple]

i dont know im not that person

[foggy beacon]

hey guys so sorry to disturb again but i asked the teacher and she said that i have to use the unit circle and negative angles

and i just remembred this one thing that said cos was a positive function

does that mean the cos of -0.4328 and 0.4328 are the same

[steep temple]

fuckn endtimes

cant believe he fucking predicted the future itself

[silent plank]

even function not positive function

[foggy beacon]

sorry

even

[silent plank]

yes. cos(a) = cos(-a)

[foggy beacon]

does that mean angle 115 and 64 have the same ratio

[steep temple]

have you considered the following:

• looking at the graph of cos(x)

[foggy beacon]

no i haven't looked at the graph

im just answering this one question that asks if the cosine of -0.4328 can be acute

and i got angle 115 but then the teacher said that it can for negative angles

so can i say that 115-180 = -65 degress has the same cosine?

[steep temple]

i dont know if you're being sarcastic or not

[foggy beacon]

im not doing a graph problem rn man

[steep temple]

but you can see here cos(pi) = -1 and cos(-pi) = -1

what

ok think about it this way

using ur dumb unit circle

[foggy beacon]

yes

yes

[steep temple]

that is it

[foggy beacon]

thank u

[steep temple]

nevermind don't listen to that

let me show you a diagram

that isn't correct

[foggy beacon]

yes

this is the question

If the cosine of an angle is −0.4328, can the angle be acute? If the sine of another angle is 0.3781, can the angle be obtuse? Explain [Communication]

[little osprey]

'Communication' yikes sounds like IB keywords

[foggy beacon]

no its a stupid bitch ugly class that doens't even explain shit

[steep temple]

if you go 90 degrees counter clockwise its the same thing as going 360-90 degrees anticlockwise

[foggy beacon]

yes

[steep temple]

that is it

[foggy beacon]

okay man thank u

[steep temple]

okay so now to answer the question

[foggy beacon]

yes

i just said no because if we do 115-360 = -244 which is also an abtuse angle so no

does that make sense

[steep temple]

no

it would be 360-~115

which is ~244

which yes, is not an acute angle

[foggy beacon]

alright love u bro

[steep temple]

as for the second part

[foggy beacon]

yes the angle is 22.2

[steep temple]

yes

but why?

[foggy beacon]

becasuse the question gave me the ratio and i used the calculator i think its correct

[steep temple]

what identity does sin have that you used here

[foggy beacon]

but can i do this 22.2+2(360)=742.2 which means that the angle can be abtuse

it's odd

sin is odd

sorry i found the proper way of answering it

thank u

[steep temple]

sin(x) = sin(pi-x)

the value that ur calculator gave u was lucky

u could just have well gotten 22.2 degrees

wait

you did get 22.2 degrees

so how did u arrive at the conclusion that the angle is obtuse if u got 22.2 degrees

??

[foggy beacon]

yes i got 22.2 degress

because we are using degrees not radians

[steep temple]

sin(22.2) == ~sin(180°-22.2) == ~sin(157.8)

do u realise if an angle has 22.2 degrees then it is not an obtuse angle

do u know what an obtuse angle is

[foggy beacon]

why subtract 180

yes i know what abtuse angle is bro

[steep temple]

obviously you dont since you think an angle of 22.2 degrees is obtuse

[foggy beacon]

i didn't say that

[steep temple]

you definitely implied it

[foggy beacon]

i said 360 + 22.2 = 382 had a the same sine ratio which means that this ratio can give us an abtuse angle

lmao what did i do for u to hate me 😄

[steep temple]

r u telling me there exists an angle with 382 degrees

obviously 360 + 22.2 would give you the same ratio because sine wave's period is 360 degrees

!!

[foggy beacon]

yes

so is my answer wrong

[steep temple]

what is your answer

[foggy beacon]

i said 360 + 22.2 = 382 had a the same sine ratio which means that this ratio can give us an abtuse angle

is this a correct answer

[steep temple]

https://www.youtube.com/watch?v=x36tRrVGtX0

If the cosine of an angle is −0.4328, can the angle be acute? If the sine of another angle is 0.3781, can the angle be obtuse? Explain [Communication]

[foggy beacon]

okay so sin (180 - 22.2) = sin(22.2) thank u so much

[rich wolf]

sin(pi-x) = sin(pi)cos(x) - sin(x)cos(pi) = -sin(x)*-1 = sin(x)

[golden panther]

GUYS r=2cos2θ and θ=30, to find r do i use 2(cos^2(30)-sin^2(30))

[rich wolf]

r = 2 cos^2(30) ?

[golden panther]

no r=2cos2θ

[rich wolf]

$r=2\cos(2\theta)$

[somber coyote]

AMD:

[rich wolf]

??

be clear in your notation

[golden panther]

That isnt what it looks like on the worksheet

no parenthesis

[rich wolf]

yeah but that's what it means

it's good practice to keep the argument inside the parantheses

but anyway

2*30 = 60

[steep temple]

A) No, as

• arccos(-0.4328) = ~115 degrees
• Using the identity cos(x) = cos(360-x), we get the second value of x; 360-115 = ~225 degrees
• An acute angle is one below 90 degrees, neither of the values here are below 90 degrees
  B) Yes, as
• arcsin(0.3781) = ~22.2 degrees
• Using the identity sin(x) = sin(180-x), we get the second value of x; 180-22.2 = ~157.8 degrees
• An obtuse angle is one which has an angle between 90 degrees and 180 degrees and the second value fits the criteria

Proof: [8:19 PM] AMD: sin(pi-x) = sin(pi)cos(x) - sin(x)cos(pi) = -sin(x)*-1 = sin(x)

@foggy beacon

[golden panther]

but the worksheet

[foggy beacon]

@steep temple I LOVE U THANK U LOVE U U ARE THE BEST COOLEST GUY EVER

[rich wolf]

bro its just 2cos(60)

[golden panther]

fine

if your telling the truth then the answer is 1

[steep temple]

why would he lie to you

[golden panther]

you never know on the internet

anways thanks for the help

Beef Out

[steep temple]

if you dont trust people on the internet what you expecting will happen out of asking them for help

[drifting parrot]

I need help with a problem

[upper karma]

Post it

And we'll see who can help or not

[drifting parrot]

I was getting ready to post it

[upper karma]

Oh lol

[upper karma]

Is the second term a step

Or is the whole thing an equation

[drifting parrot]

the second term is a step

[upper karma]

Anyways, i can't figure it out, wait for help

[silent plank]

,rotate

[silent plank]

75/2 isn't 75

[drifting parrot]

i know it's 37.5 but when I asked my professor, she said that I am not supposed to be looking for the cosine of 37.5 .

[silent plank]

which is what I'm implying

75 is the half of what?

[drifting parrot]

I don't understand the question

[silent plank]

$\frac{?}{2}=75$

[somber coyote]

ramonov:

[drifting parrot]

is it 37?

[silent plank]

,calc 37/2

[somber coyote]

Result:

18.5

[silent plank]

solve x/2=75

[drifting parrot]

ok

[silent plank]

so 150/2 = 75

and would it make more sense to do:

$\cos(75\deg)=\cos(\frac{150}{2}\deg)$

[somber coyote]

ramonov:

[drifting parrot]

ok. That makes more sense

[upper karma]

👍

[drifting parrot]

what about the rest of the problem? Do I need to change anything?

[silent plank]

yes. update values

you should choose the appropriate sign based on you angle

[drifting parrot]

where it's located?

[silent plank]

where is 75 deg?

[drifting parrot]

the first quadrant

[upper karma]

hello I am back from my online classes. So, who would like to help me with my homework? I really don't know anything so I'd like help

ping me when any of you are interested in helping me 👍

@upper karma very easy! Use trigonometric functions!

And Pythagorean theorem!

Easy!

@upper karma what u need help on

On the impairs, I really do not have a clear mind on the trigonometric and Pythagorean method

1. Use sin and try to get x by itself

Just use trigonometric functions, get x by itself

7. You would use Pythagorean theorem

A^2 + b^2 = c^2

Just plug it in and get c by itself

So 18^2 + 18^2 = c^2

Square root both sides

And you found x!

Woohoo!

I’ll do example for 1

please do hehe

Sin(45)

=

7/x

Get x by itself by doing simple algebra stuff

So

X = 7/sin(45)

And then use calculator

Sorry if u don’t understand

Watch a video on YouTube

Or something

About trigonometric functions

But that’s the answer to the 1st question

U just have to plug it in to calculator

To get exact number

I think I got it, divide 7 with the sin, right?

which gets me 0.155

Well sin(45) = 7/x you aren’t technically divided 7 both sides

Oh what

Wait

[austere terrace]

Heyyy, I’ve been doing really badly in math recently. (It may be because my math teacher didn’t go to grad school) But I was hoping someone could help me understand what I’m supposed to do here, I have a test coming up soon.

Oh shoot sorry I interrupted

[upper karma]

Easy! Use trigonometric functions!

Cos and sin

Try it out

just get s and t by itself

And then put into calculator

[austere terrace]

That’s the thing, I don’t know how to do it

[upper karma]

Ok why don’t you watch a video explaining trigonometric functions first

Here’s the basics, Sin = Opposite Side/Hypotenuse

Cos = Adjacent Side/Hypotenuse

[austere terrace]

The only thing I really know is SOHCAHTOA

[upper karma]

Ya same thing

That’s what I said

SOH = SIN = OPPOSITE/ HYPOTENSE

[austere terrace]

Yeah, I understand that. I just don’t know how to set it up if there are two unknowns

[upper karma]

Sin(25) = t/18

Now just get t by itself

Using simple algebra

And then plug it into calculator

Try cos

[austere terrace]

Also it’s not the easiest thing for me cuz I have discalculia and ADHD

[upper karma]

Oh damn

I’m very sorry for you

[austere terrace]

Yeah, and for some reason I go to a private school so there’s no real math help there

It’s fine, I try my best

[upper karma]

Well do you understand what I did now?

[austere terrace]

I think so

[upper karma]

Alright

Try cosine

And come back and I’ll check ur answers

[austere terrace]

How do I get t by itself? Do I need to divide by 18 on both sides, because that’s what my teacher said to do

[upper karma]

Yep

You got it 👍

[austere terrace]

Okay that’s much easier than I thought

[upper karma]

Oh wait

It’s multiply

[austere terrace]

My problem is that I overcomplicate things a ton

[upper karma]

Both sides

[austere terrace]

Oh yeah

[upper karma]

You just have to get the unknown variable by itself

That’s it

[austere terrace]

You have to multiply the bottom numbers and you have to divide by 1 if there’s the unknown on the bottom right

Or is that extremely wrong

[upper karma]

What do you mean divide by 1?

[austere terrace]

So my teacher set something up before where you had to divide 5/5 (in fraction form) which is pretty much dividing by 1

Idk tbh, it’s probably wrong

[upper karma]

Divided by 1 is just the number itself

[austere terrace]

Yeah

[upper karma]

So yeah sure

I guess

It’s just the same number

[austere terrace]

Yeah

[upper karma]

Why would it be necessary tho

[austere terrace]

It was a while ago, probably when I was in algebra/geometry

[upper karma]

Alright but I don’t think that’s necessary since dividing by 1 is just itself

But whatever your teacher teached you is fine

[austere terrace]

Gotcha, thanks

Sorry for interrupting

[upper karma]

Your welcome 👍

@upper karma so did you figure it out

Hello i’m back. Haven’t made any progress and search up the themes youve told me but it wasnt what i was looking for

Ya now just get x by itself

Get the unknown variable by itself

Like in regular algebra

Try it

Do you need more help

On how to do that?

Ill try leaving the x by itself

You can help me out in the road

Just try getting the variable by itself

You it would x = .....

X = something

ight so X = 7

The equation is sin(45) = 7/x right?

Where did the sin(45) go?

yes

?

idk

Ok I’ll help u out with this first

You multiply both sides by x

And then divide both sides by sin(45)

I’ll find a video for you hold on

https://youtu.be/a5WQlcFTXyk

Try watching this

Alright

Or this https://youtu.be/Zrp7NyO12ho

[upper karma]

winding function(unit circle)>>>>>>>>>>>>>>>>>>>>> SOH CAH TOA

[golden panther]

GUYS! how do i find the 2nd pair of a polar coordinate

[steep temple]

I swear to god next time someone comes here with some elementary trigonometric function question I’ll get all dot product on their ass

@golden panther what is 2nd pair

polar coordinates only produce one pair of Cartesian coordinates?

[golden panther]

the worksheet says give two pairs

[steep temple]

if you have a line of length 5 and you slap that bad boy on an angle of 52 degrees then there is only one real pair of coordinates (x,y) that can be at the line’s end

show picture

[golden panther]

ok wait i have to learn how to crop

[steep temple]

ok

[steep temple]

...

[golden panther]

What

[steep temple]

it’s 2 pairs of polar coordinates

not Cartesian coordinates

[golden panther]

???

thats what i asked bruv

[steep temple]

ok I must’ve misunderstood

Anyway

[rich wolf]

ok

[golden panther]

how do i find the 2nd pair

Please

[steep temple]

do you know what a polar coordinate is first of all

[rich wolf]

add 360 to the angle

[golden panther]

Of course I Do

Ok Thank you AMD

[steep temple]

okay I also thought of that but I don’t think they would ask for something so silly

but I don’t know any other way to get a second pair 🤔

[rich wolf]

what else could it possibly be lol?

it's just asking for a coterminal angle

[steep temple]

ok I think that is the only answer since it can’t be anything else

yeah

[frigid maple]

-how do ithbis

[steep temple]

what is FJ

does it mean FKJ

and GKH, respectively?

[frigid maple]

can u rephrase sentence

brain no work

[steep temple]

when it refers to "FJ", is it talking about angle FKJ?

similarly, goes GH mean angle GKH?

[frigid maple]

nono the arc

arc\

[upper karma]

That’s cool

[steep temple]

i must be an idiot because i dont know how to measure arcs in degrees

[versed river]

its referring to angle jko, i thinik

jkf

sorry

[steep temple]

it should be noted jkf is not always equal to fkj

are you sure it's jkf

that's weird notation you americans have

[versed river]

im not american

thats why im not sure

[steep temple]

makes sense

[upper karma]

I’m American

[steep temple]

can u confirm

[upper karma]

Confirm what

What’s happening

@steep temple tell me

@versed river ???

[golden panther]

@steep temple where are you from

[steep temple]

can u confirm FJ means FKJ

and GH means GKH

[sacred blade]

can someone help me with a question?

if anyone knows lmk

[upper karma]

@steep temple ya because FJ is the arc that intercepts FKJ, Right?

[steep temple]

i dont think "intercepts" is the right word

but yeah, its the arc

[upper karma]

Ok so then what

[boreal adder]

This is my math warmup

I know 35 is one but don’t know the other

[steep temple]

does that imply angles are measured from the negative x axis? @boreal adder

also is it going clockwise or counterclockwise?

i assume counterclockwise

if so, none of the angles there are coterminal (apart from obviously 35*)

@languid finch that is not geometry/trigonometry related
(but you should note 0.55 * 0.14 = 0.077 as P(A&B) = P(A)*P(B))

[languid finch]

@steep temple thanks, it was on my geometry hw so idk

[steep temple]

probably venn diagram

[languid finch]

@steep temple so would 0.077 be the answer?

[steep temple]

no

well, yes

but not 0.077**%**

[languid finch]

Thanks

[steep temple]

(u have to convert 0.077 to percentage)

[languid finch]

so 7.7%

[steep temple]

yes

[upper karma]

how do i do this

[onyx cloud]

do you know what they mean by common difference

[upper karma]

i found it

nevermind

its 3y-x

[boreal adder]

@steep temple I turned this in and it said 35 was wrong but 955 was right

My brother said the 9 in 955 was supposed to be a 7

[steep temple]

then that would make sense

because then it can be expressed as 35+2(360)

which would make it coterminal

also while i agree that 35* isn't technically a right answer, since it was given to you in the question, the question did ask for 2 angles

so there is nothing else that you could have picked

[languid finch]

im so confused

[onyx cloud]

this doesn't exactly fit geometry and trigonometry

[languid finch]

which channel should it go in?

its from my geometry teacher huh.....

idk it says geometry on the title 🤷‍♂️

[onyx cloud]

oh nevermind i see now

its just asking for the ratios of the regions my bad

[languid finch]

could you help me with the questions a b and c?

im so confused.

[onyx cloud]

sure

can you tell me what region x is

[languid finch]

thanks!

[onyx cloud]

the shape of it

[languid finch]

circle?

[onyx cloud]

yeah

whats the radius

[languid finch]

4 right

[onyx cloud]

yep

so whats the area of it

[languid finch]

about 50.27

[onyx cloud]

good

now the probability of landing in X

is the probability of landing in that area, over landing in the whole circle

so what is the area of the whole circle

[oblique minnow]

^-1 in this case means arc function

[onyx cloud]

tes

yes

[languid finch]

would the area of the whole circle be 804.25

@onyx cloud

[onyx cloud]

i don;t think so

how did you get there

[languid finch]

it says 8 for the radius

[onyx cloud]

whats the area of a circle

[languid finch]

oh my b

201.06

[onyx cloud]

yeah that looks righter haha

but ok

now we have the area of x and the total area

to find the probability we do x over the total

[languid finch]

so 50.27/201.06

[onyx cloud]

yep

[languid finch]

would that be the answer or do i have to divide

[onyx cloud]

i would simplify it

[languid finch]

0.25002486?

[onyx cloud]

yeah looks right

[languid finch]

it says round answers to a tenth of a percent...

?

[onyx cloud]

to get percent you multiply the decimal by 100

abd tenth means you get rid of the decimals after the first one

so 1.1111111 becomes 1.1

but 1.05 and above become 1.1

hope that made sense

[languid finch]

yeah so it would be like 25 percent?

[onyx cloud]

yeah pretty much

[languid finch]

ok thanks

[ancient jacinth]

ping me!

[eager pendant]

@ancient jacinth

[ancient jacinth]

funny on e

[eager pendant]

i was gonna answer your problem but ok

have you heard of the alternate segment theorem

[analog igloo]

how to do?

[dark sparrow]

what have you tried

[digital gulch]

Bruh

Ok so 33k-9 is equal to 90

Solve for k

Plug it in to find the measure of angle CPD

Assuming P is the center of the circle, arc CD has the same measure as angle CPD

So whatever u got for angle CPD would be ur final answer

[upper karma]

@digital gulch Yes Great Job

But he got the answer already

He figured it out on his own

[upper karma]

help, please

I've been stuck in sine graph hell for the last 3 weeks

[rich wolf]

@upper karma what is the average value of a sinusoidal wave?

[upper karma]

@rich wolf its a test

when sin = 0

Dont

[little osprey]

Yeah

On Khanacademy

So

Does it count?

[upper karma]

Mmm

I dont know really

[little osprey]

@upper karma

[rich wolf]

Yeah its just khan lol

[upper karma]

I've been going through Khan Academy math courses since January, I think

[quiet mason]

weird situation lol

[rich wolf]

Its practice so its fine

[upper karma]

Then i think its okay lol

Yeah

[little osprey]

Ping a higher up?

[upper karma]

it's not graded or anything, lol

[little osprey]

oh

yeah then its fine

[upper karma]

I'm 31 years old, still doing trig 😐 smh

[little osprey]

yeah dw

[upper karma]

There is no age in maths

:)

[little osprey]

^

[upper karma]

I just don't wanna mess up my streak

(8/9)

[rich wolf]

Ok

Do you know what the avg value of a wave is?

[little osprey]

AMD you got this?

[rich wolf]

Ye

[upper karma]

average value of a wave... it's the midline

[rich wolf]

Yes

[little osprey]

principle axis

[rich wolf]

So set that function equal to its midline

[upper karma]

50 seconds?

[rich wolf]

No its referring to 50 cm

Basically

You must find the intersection of that function

And y=50

The first intersection to the right of the y axis

Because you cant have a negative time value

[upper karma]

t + 0.23 means that the sine wave has an offset to the left, and I can't say that the answer is "-0.23" since it's a negative value

it wouldn't make sense

[rich wolf]

Write out the eq

[upper karma]

-23 sin (pi(t + 0.23)) + 50

[rich wolf]

Set that equal to 50

Because you are trying to find the first intersection

[upper karma]

so the answer is 50? are you sure?

[rich wolf]

No

Set that equation equal to 50

You are trying to find when the wave is equal to its average

So find when the function is equal to its own midline

[upper karma]

ok, I'll give it a shot

[dark sparrow]

AMD, there's a difference between equations and expressions

-23 sin (pi(t + 0.23)) + 50 is not an equation

there's no equals sign in it

[upper karma]

yeah, but you can append a = 50 at the end of that

sin(pi) is also 0

t = 0.77

is this correct?

[rich wolf]

Yeah checks out

[upper karma]

it does

thank you

[little osprey]

uh

0.77 seconds?

[upper karma]

0.77 was accepted, yes

[little osprey]

ok

goodie

Good job on the 9/9

[upper karma]

thank you 🙂

[vale nimbus]

[austere terrace]

Hey! So I think I did this totally wrong

I got t = 450

I meant 25 sorry

[acoustic jungle]

sin 25 = t/18

18 * sin 25 = t

[austere terrace]

ohh

I got 7.596

[acoustic jungle]

Ok.

[austere terrace]

Is that right?

[acoustic jungle]

Perhaps

[upper karma]

you can also use the law of sines

because you know 2 angles (25 and 90), so you can find out the 3rd angle

since all angles from a triangle must be equal to 180

[austere terrace]

Oh yeah

[acoustic jungle]

you can just use the definition of sin.

[austere terrace]

And to solve for s I need to use cosine right

[upper karma]

s/sin(65) = 10/sin(90)   [for 's']```

law of sines

[austere terrace]

Ah

I don’t understand that at all

[upper karma]

https://www.mathsisfun.com/algebra/trig-sine-law.html

[acoustic jungle]

Why are you using law of sines

use the definition of sin

also sin 90 is just 1

you are basically using the definition of sin

[upper karma]

law of sines

ftw

[austere terrace]

I think I’m just dumb, but I still don’t know how to find s

[upper karma]

s/sin(65) = 10/sin(90)

replace s with t, by keeping in mind the opposite edges of the angles

65 because like I said, all the edges add up to 180

(for any triangle)

I need help with this assinment

260.23 KB? bruh

[austere terrace]

That doesn’t help me at all, because 65 + s + t isn’t 180

[upper karma]

yeah

s is the length of the edge, not the angle

same with t

i couldn't fin the assignment online so i had to download it

[austere terrace]

I think I’m just dumb tbh

[upper karma]

@austere terrace what does this square mean?

[austere terrace]

90* angle

[upper karma]

ok

[austere terrace]

oh

[upper karma]

yeah

[austere terrace]

I read it wrong

So all the angles in total are 90 65 and 25

[upper karma]

yep

[acoustic jungle]

Why are you using law of sines

Dspider

[upper karma]

if it was a rectangle (instead of a triangle), they would need to add up to 360 degrees

[austere terrace]

So it would be sin 65 = s/18?

I got 14.88

[upper karma]

no, that means you have your calculator set to radians

set it to degrees

this button. This is wrong

needs to say DEG

14.88 is wrong

only set it to RAD when you're dealing with a unit circle graph and you have PI in your equation

[austere terrace]

Ohh

Ok

Could I also get a little help with this

[little osprey]

what have you tried

[austere terrace]

I don’t know how to start it, but that’s all I need to know

[upper karma]

are you familiar with Pythagoras' theorem?

[austere terrace]

Yeah

[upper karma]

yeah? what is it?

[austere terrace]

A^2 + B^2 = C^2 right

[upper karma]

yes

[little osprey]

oof is this a lot of subbing

[upper karma]

what's subbing?

is it like clubbing?

[little osprey]

nah I want to see your solution

sadly not :(

yup

subbing

What did you get @upper karma

[upper karma]

well, first you need to calculate the edge of the right

[little osprey]

yeah

[upper karma]

using the Pythagorean theorem

then, once you have all of the edges, you can find the height of the triangle

[little osprey]

nahp

[upper karma]

@austere terrace is that an exam?

[austere terrace]

Nope, just a packet

[little osprey]

'formatives' arent exams

I dont htink

they prepare for exams

[austere terrace]

My school does everything on goformative, including daily homework

[upper karma]

Oh i didnt know that

Nice

[little osprey]

yeah lol good eye though

[upper karma]

:)

[austere terrace]

Yeah I wouldn’t do that for a test

[upper karma]

if you know the formula for the area of the triangle, you can find its height

https://www.youtube.com/watch?v=CkH_LoD0ZoQ

[little osprey]

oof oof ok

have you tried

subbing in 16-d=c

and

[austere terrace]

That’s what I started with

[little osprey]

sqrt14^2 -(16-d)^2 as e

[upper karma]

Yeah the normal method lol

Never heard of Heron's

me neither, tbh

[little osprey]

Heron's is a good formula

but it doesnt get taught in schools

@austere terrace what did you get?

[upper karma]

all I did was google "triangle height" and clicked the first link

[austere terrace]

Working on it

[little osprey]

ok

[upper karma]

https://www.youtube.com/watch?v=LBHI_oppbCs

[little osprey]

Wait wait