geometry-and-trigonometry

[wind heart]

Or smth like that

Right?

[silent plank]

that description isn't very clear.
you reflected it over the y-axis just fine
just reflect what you have again except this time over x=6

[wind heart]

I kind of get it now, thanks! I’m not sure if I’m doing it the “best way” possible but the way I do it still gets me the answer now

I’m just counting each block until it gets to the line, and counting the same amount after the line

And then I plot it

[viscid ginkgo]

What is reason 6 on problem #10?

I got triangle JDH congruent to triangle DJK for #5 for reason HL

and #6 angle H is congruent to angle K because of CPCTC

[tight relic]

I have a slight problem, we have an excercise with pyramids and we this is all the information we have for it, not even height, is there any way to find out the height or is it just impossible ?

[tight relic]

nvm the teacher gave us height now

[inland kiln]

can someone give me answers for b and c

[idle bloom]

@inland kiln for part b use a trig ratio. One of the side lengths you know and you know the angle and the other side length is the radius

Part c use Pythagorean theorem

One side is r, the other is 14

And then the trick is the hypotenuse is r+10

[inland kiln]

oooooh

thanks @idle bloom

I got this now

[idle bloom]

👍

[inland kiln]

I need help on this one can someone walk me through it please?

[flint osprey]

can you find angle ADB?

[idle bloom]

ABC is a right angle

And then there's an isoceles triangle in there that you can take advantage of

[jaunty crane]

hey guys

i need help w 4 and 5

is the answer to 4 75 and 435?

[silent plank]

not quite
75 and 435 are coterminal with -285
however it seems you missed a solution

did you check whether 255 or -645 were coterminal?

[flat jackal]

As long as you can add any integer multiple of 360° to -285° and get to one of the angles in the list, then the angle is coterminal to -285°. Same for both 4 and 5, you can simply take the difference between the angles in the list and -285° (for 4) or 120° (for 5), and if the resulting angle is some multiple of 360°, it is coterminal to -285°/120°

[upper karma]

it's just anything that's -285 mod 360

which is basically 75 mod 360

for 5, it's anything 120 mod 360 or -240 mod 360

@jaunty crane

[jaunty crane]

@silent plank o is it also -645?

ty @flat jackal and @upper karma :-)

[upper karma]

yeah it is

[jaunty crane]

yay

[upper karma]

because -645 is a mod -285

-285-360

[jaunty crane]

ah i c

but 255 isnt right

[storm dock]

hello, so i received this maths assignment from my school and there is two question that is confusing me
first question is "indicate where the graphs of cot(x) and 1/tan(x) are different. if necessary, make the alterations by hand to your existing graph of y=1/tan(x)"
and the second question is "use the unit circle to explain why there is a difference between the 2 graphs"

i cant find any difference between them when i put it on desmos

[onyx cloud]

the definition of cot(x) is 1/tan(x) if im not mistaken

so it should be the same graph

[storm dock]

yes, thats im thinking

i dont know why teh question is asking me to explain the difference

[onyx cloud]

can you take a picture of it

[storm dock]

sure, give me a second

my upload speed is a bit trash

[onyx cloud]

dw

[storm dock]

http://imgur.com/a/nSqBRyf

there are 2 pages

@onyx cloud

[onyx cloud]

it says they are the same on the paper

so for this front part you can just draw the same graph twice i'd assume

[storm dock]

yeah thats fine

the 2nd page is what i dont get

[onyx cloud]

does it say "there is a difference" or "isn't"

[onyx cloud]

c) nowhere

[storm dock]

i wouldve put that

but then question d comes and asks use the unit circle to explain the difference????

why there is a difference*

[onyx cloud]

can you send a picture of d)

[storm dock]

click the link

[onyx cloud]

it only shows c

[storm dock]

wait what

[upper karma]

Wtf do these answer choices do

And what is this?

[onyx cloud]

for the first one

you draw the line

and if the square is crossing it at any point

then that means that reflecting over it will cause it to land on itself

its asking which of those won't have that happen

second one no clue

[upper karma]

So what line does y=x draw

How can it get reflected over that

[onyx cloud]

y=x means that for every x, the y coordinate is that same number

so what line will it be

[upper karma]

A diagonal one with a slope of 1

[onyx cloud]

perfect

so reflecting over that line means that x -> -x and y -> -y

[upper karma]

So how are you supposed to reflect something if it’s overlapping

[onyx cloud]

you just switch up the coordinates like i said, in the case of y=x

[upper karma]

Why is it -x, -y

[onyx cloud]

not exactly sure how to explain it

its like drawing a perpendicular to the line from every point

nvm that explanation is bad

if you draw the line you'll see why

but i think they want visual analysis for this hw rather than actual mathematical analysis

[upper karma]

So for a, I draw a vertical line on x=5

[onyx cloud]

correct

and if you do that

does the square cross it?

[upper karma]

Wym

[onyx cloud]

is the line passing through the shape?

[upper karma]

No

[onyx cloud]

then that means that if you reflect it

there will be no overlapping

[upper karma]

Do that’s the answer?

[onyx cloud]

i'm assuming it is

[compact spire]

$\left(r,:\theta \right)=\left(4,:-60^{\circ }\right):to:\left(x,:y\right)$

[somber coyote]

Pony Boy:

[compact spire]

Can anyone help me with this question?

[onyx cloud]

do you know how to switch from polar to x and y

[compact spire]

not really no

[onyx cloud]

ok so

super quick

x=rcos(theta)

y=rsin(theta)

see if you can go from there

[compact spire]

Okay

so x = 4cos(-60)

y = 4sin(-60)

[onyx cloud]

yep

now you gotta solve

[compact spire]

$(2,-2\sqrt{3})$

[somber coyote]

Pony Boy:

[compact spire]

sweet

Thanks for the help 🙂

I only remembered how to go from x,y to r,theta

[onyx cloud]

ok

glad i could help 😄

[compact spire]

yeah thanks to you, I knocked out 4 problems lightning fast!

[onyx cloud]

nice@

!

[compact spire]

Convert to rectangular equations. $ r=4cos\theta$

[somber coyote]

Pony Boy:

[compact spire]

Okay is this similar to what I was just doing?

[onyx cloud]

yeah i believe so

so you find the parametrics which will be done through x=rcostheta

and y=rcostheta

then you can try and substitute to find an y(x) = ...

[compact spire]

so its not like the $x^2+y^2=r^2$?

[somber coyote]

Pony Boy:

[compact spire]

$x^2+y^2=4cos\theta$

[somber coyote]

Pony Boy:

[onyx cloud]

oh shoot

no yeah i think you're right

mb

[compact spire]

Okay, I didn't know if you had an alternate way of figuring it out

so how would I go about solving it like this?

[onyx cloud]

wait redo the r^2

[compact spire]

Is it wrong?

[onyx cloud]

r = 4costheta

so what does r^2 equal

[compact spire]

Oh

$x^2+y^2=(4cos\theta)^2$

[somber coyote]

Pony Boy:

[onyx cloud]

yeah

[compact spire]

I honestly don't remember what its supposed to equal to

[onyx cloud]

as in, you don't know the answer?

[somber coyote]

Pony Boy:

[compact spire]

$(4cos\theta)(4cos\theta)$

[somber coyote]

Pony Boy:

[compact spire]

$16cos^2(\theta)$

[somber coyote]

Pony Boy:

[compact spire]

that would be it correct?

[onyx cloud]

that is (4costheta)^2

if that's what you're asking

[compact spire]

Okay yeah thats what im asking, but Im just going to be square rooting all this I think anyway

[chrome sedge]

Need help finding x

Dont mind instructions it just asks x

[upper karma]

$1+1

lol

[dark sparrow]

if you wanna fuck around with the bot, go to #bots.

[rich wolf]

@chrome sedge what does it say

Actually cant help you without the instructions because there is no information on figure 2

[worldly whale]

can someone help me find cofunctions

i just want to know how to enter them into my calculator

if i wanted to find the cosecant of 83 would i do 1/sin(83) or sin^-1(83)

[dark sparrow]

1/sin(83)

[worldly whale]

thanks

[tiny halo]

dont understand at all

[paper mauve]

@tiny halo tell me, what are we given here? in terms of the lines. are they tangents, etc.?

[tiny halo]

im given that X = 8

[paper mauve]

ok perhaps my question wasnt worded correctly

what types of lines are these

@tiny halo

[tiny halo]

secants?

[paper mauve]

yes

and how do you find the length of a secant line?

[tiny halo]

ummm.... idk

i struggle in mat

math

[paper mauve]

so the length of a secant line can be found by HJ*HK (in this example)

its the length of shorter segment times the length of the longer segment

[tiny halo]

so hj times kj ?

[paper mauve]

no

[tiny halo]

im so cinfused this is my last question for my lesson and i dont know how to do this

[paper mauve]

its hj times hk

[tiny halo]

oh

[paper mauve]

yeah you were close

so we know x=8

[tiny halo]

yes

[paper mauve]

so what is the length of hj?

[tiny halo]

11 or 3x

[paper mauve]

not quite

i asked for HJ

[tiny halo]

oh

8

[paper mauve]

good

and what is the length of HK?

[tiny halo]

11

[paper mauve]

beautiful

so the length of a secant line is the smaller line times the bigger line

[tiny halo]

oh

[paper mauve]

so that makes this 8*11

[tiny halo]

88

[paper mauve]

and since the two secant lines have the same origin (H) we can make this whole thing secant line1=secant line2

so secant line 1 length is HJ times HK and we found thats 88

so 88= secant line 2

now we have to find secant line 2

[tiny halo]

yeah

[paper mauve]

so what is the smaller line's length on the second part

[tiny halo]

hg

[paper mauve]

good

what is hg's length

[tiny halo]

3

[paper mauve]

good

what would the larger line be?

[tiny halo]

fg

fg = y

[paper mauve]

not fg

[broken mantle]

Anyone knows some kind of way?

[tiny halo]

fh?

[paper mauve]

youre close but its not fg. you are right that fg=y

bingo!

[broken mantle]

sorry to interrupt 😐

[paper mauve]

@broken mantle not to worry

[tiny halo]

yes]

[paper mauve]

i will take a look at your q in a sec we will be done in a min

so what is length of HF?

[tiny halo]

3y?

[paper mauve]

not quite

the values are right

but the operation is off

we want the total length of this

[tiny halo]

just so i dont have to keep on scrolling

[paper mauve]

all good

[tiny halo]

3?

[paper mauve]

nope

thats hg

you were right that 3 and y are in it

just the operation is off

[tiny halo]

is it 8

[paper mauve]

no

its 3+y

[tiny halo]

bruh

[paper mauve]

the length of HF is 3+y

[tiny halo]

i had that in my head but i thought it was wrong

[paper mauve]

never be afraid to say whats in your mind we are all friendly here. we are fellow students

we dont bite. we are friendly

[tiny halo]

ok thanks

[paper mauve]

so now we have our long length, 3+y, and we have our short length, 3

just like the first part, multiply these two together

3*(3+y)

=________??

[tiny halo]

3

[paper mauve]

what?

3(3+y)=__

[tiny halo]

9 + 3y

[paper mauve]

good

[tiny halo]

then you divide by 3 on both sides

[paper mauve]

yep!

cause now its just 88=9+3y

[tiny halo]

subtract 9 from 88

?

[paper mauve]

just make sure you write out your steps when solving this and explain them to yourself so then that way when this sort of problem comes back up you can kick its butt

yes

[tiny halo]

i got 26.33

[paper mauve]

that should be it

[tiny halo]

so hk is 11

y is 3

hf is 26.33

cuz i need to find those three

[paper mauve]

i havent run the numbers but the process is right so im sure youre right

[tiny halo]

so those are the answers to those three

[paper mauve]

good job!

@broken mantle still need help?

[broken mantle]

yes @paper mauve

[tiny halo]

is this 270

[broken mantle]

no

[tiny halo]

what is it

[tiny halo]

😦

[paper mauve]

ok so lets look at what we are given here we need 20 dots

so in order to make 20 dots total we can make the dots into an assembly of 4 rows of 5

[broken mantle]

@tiny halo its 45 degrees

how do i figure out an assembly

for any given number of dots

[paper mauve]

so think of it like an area

we want an area of 20 dots

[broken mantle]

i think i got an idea

[paper mauve]

do tell

[broken mantle]

rectangle area = 30*12

so for this example ill use numbers

thats 360 i think

we have 20 dots

divide 360 by 20 to get 18

18 is the area that each dot should get

i place it in the centre of that area

[paper mauve]

what is "it"

[broken mantle]

dot

[paper mauve]

kk

continue

[broken mantle]

iterate for each next dot by incrementing distance over its area length

[paper mauve]

well how do you know the area length?

[broken mantle]

i dont 😐

[paper mauve]

even then im not entirely sure if that would pan out correctly

because area is units^2

[broken mantle]

it doesnt have to be perfectly distanced from eachother

[paper mauve]

so unless you assumed the spacing between dots are square i cant think of a way that this could work

[broken mantle]

i can imagine smaller areas like shrinked big rectangles and calculate their sides by
dividing a side by dot amount or so

[paper mauve]

you just gave me an idea

[broken mantle]

cause im shrinking big rectangle by number of dots as well

[paper mauve]

ok so have you seen area described as a grid before?

[broken mantle]

that sounds strange to me but im sure ill understand

[paper mauve]

like this

[broken mantle]

okay

i would imagine coordinates there but this works too

[paper mauve]

so if we do the same thing to our case and place a dot at every intersection between the x and y coordinate lines

[broken mantle]

my area =/= number of dots

[paper mauve]

hm yeah youre right

[broken mantle]

it would mean i would need to iterate

by area/dots

instead of 1

[paper mauve]

so what if we were to just scale everything

[broken mantle]

wait area/dots wont work, how do we scale?

[paper mauve]

well what if we were to instead place dots at the center of each grid

this giving 20 dots

thus*

and then find the coordinate distances between each dot?

[broken mantle]

in my case grid would have 360 cells

i need to place 20 dots

[paper mauve]

well we can split the entirety into 20 cells

[broken mantle]

tell me how and ill take care of the rest from that point

it can be easy to say 4x5, but what if grid rectangle is 8916x98524 and we need 56543 dots?

[paper mauve]

maybe my wording was off here. im not trying to replace dots with area. im trying to split the entire area into smaller areas

and use those as the foundations for each independent dot

[broken mantle]

that would work for me as well

[tiny halo]

@paper mauve are u guys still working?

[paper mauve]

so as you can see from my beautiful drawing

if we were to continue adding dots we will end with 20

yes we are

[broken mantle]

but how do u figure out that grid should be 4 by 5?

[paper mauve]

well its a rectangle

and we need 20 dots to be evenly spaced

[broken mantle]

but how do you generalize it?

[paper mauve]

just by splitting it up so that we can incrementally add in a new rectangle each time without throwing off the space

so we can split the lengths into increments

we dont even have to do this as 4x5

i can do this as 2x10

imagine youre putting decor on a wall

[broken mantle]

yeah, but as i mentioned these solutions are very computation intense

[paper mauve]

not at all

its just simple scaling

so in this example if we split up 30 into 2, we get 15 feet of width. if we split 12 into 10, we get 1.2 feet of length each time

[broken mantle]

first i would need to factor out all solutions that factor number of points with an error of maybe +/- 2 and then find the permutation that has the best scale of small width/big width and same with height if you follow my thoughts here

[paper mauve]

except you dont need to

have an error

**

its a symmetrical shape

[broken mantle]

if i get a rectangle with dimensions 789982x687422 and need to fit 320074 dots

that is why i either need to generalize of find solutions in some kind of other way

another idea was to create a physics simulation where each dot and border have a same charge(like electron or proton) and they repel eachother to perfectly spaced distances, but this would be too extreme

there must be a generalized mathematical way for it

[paper mauve]

then you can do it as 2 rows of 160,037 dots starting from a space 4.93 for each legnth and 343711 in width

ok so heres what i did if you want general:

1. decide your spacing pattern (2 by 160,037)
2. divide the number of rows you want by the length (687422 by 2)
3. divide the number of columns you want (789... by 160...)
4. take both the dimensions in step 2 and 3 and divide by 2 to find the center of each rectangle

5. place dot

[torpid torrent]

can i use slant height with a hexagonal pyramid's volume

i forgot

i thought only way was base1/3height

[broken mantle]

Will try to @paper mauve

[paper mauve]

@broken mantle https://www.madeofsundays.com/blogs/news/how-to-install-a-wall-decal-pattern take a look at this and hopefully this will help you conceptualize it a little more

@torpid torrent wym slant height?

like the total height?

[torpid torrent]

im confused on radical form

where do radicals come into this

[paper mauve]

itll come from the area of the base

so i think youre overthinking dis

volume of a basic shape is lxhxw

lxh=base

basexh=volume

find the area of the base first

then you can multiply by height

but be aware that its a pyramid so its 1/3xbasexheight

[torpid torrent]

but theres no radicals

[paper mauve]

its a 30 60 90 triangle

youre gonna have a root 3 in there

[torpid torrent]

oh shit

i was doing trig

[upper karma]

Okay so, supposing that ABC is an obtusangle triangle; calculate the area of EBC, knowing that the area of ABC is 24

What i got

We know that

A(ABC) = A(EBC)+A(ECX)+A(AEX)

And
A(AEX) = (aH)/2
A(ECX) = (ah)/2

And by the theorem of tales:

h/H = B / (B+a)
Some simplification:
a = H/2h

We substitute in the initial equation, the areas with their values/equations:

24 = 6h/H + H²/4h + H/4

Remove denominator:

24Hh + H²h + H²h - 94Hh = 0

-70Hh + 2H²h = 0

Hh(-70+2h) = 0

And im stuck here

And please note that my drawing is far from being on scale, the first one is on scale

[lilac isle]

I’m working on finding the volume shell of an rectangular and wonder if anyone can help check my work if they correct?

[upper karma]

I dont understand your letter @lilac isle

And you gave little context, is that all you got? Not even a drawing?

[viscid ginkgo]

How can I prove line segments EG and KJ are parallel?

Since there's no transversal lines, I can't say that there are alternate interior angles that are congruent.

nvm I see now that intersection can mean just lying on the other line

[wintry mural]

Hello. Can you please give me a good reference/textbook for studying solid mensuration/geometry? A book with lots of problem sets and exercises is preferable. I only have elementary knowledge on the volume of solids such as sphere, cone, cylinder, cube, and so on. Please @ me. Thanks! Have a good day.

[silk musk]

How do I find the distance between two circles given only the circumference? Work my way back yo the radius, then find the difference in the radii?

#2

[plain pollen]

well, you know the circumfrence, of the first circle, so you can find the circumfrence of the second one too

using the original circumfrence, you can find the diameter of the first omne

then using the second circumfrence, find the second diameter

Then get the difference between the two

Or did I misinterpret the problem?

[silk musk]

There is one rope allegedly "wrapped tightly around the equator." So I assume it is just the circumference of 132,000,000. Given the 6 feet of additional rope, second circumference would be 132,000,006, I suppose.

[plain pollen]

correct

[silk musk]

But why would I need the diameter instead of the radius?

If I am trying to find the distance from one point on Earth to the rope.

[plain pollen]

well, yeah radius would be better

my bad

[silk musk]

Aight, thanks for the help. Was stumped on it for like, 20 mins.

[plain pollen]

knowing they radiate from the same point, subtracting the firsst from the second gives the difference

anytime

I also have a question: how do I go about this?

[eternal crag]

do you still need hlpe @plain pollen

[plain pollen]

yes please @eternal crag

[eternal crag]

alright, let's do a) first

you're given that y = -2, yeah?

[urban oxide]

cos2x-3sinx=4 I got that it doesn't have real solutions.

but the exercise says that it's supposed to have one

I wrote cos2x as 1-2sin^2x

[eternal crag]

you don't actually need any uhh substitution

and yes it doesn't have real solutions

cos(2x) is at most 1
-3sin(x) is at most 3

so the only chance that they'll sum up to 4 is that their peak happens at the same time

show that that is not possible and you're done

[urban oxide]

yeah i was confused cause it said that it should have

tysm

[flint osprey]

did you copy the question correctly?

[eternal crag]

yeah good point^

[urban oxide]

i checked again

it's correct

[flint osprey]

maybe in the solution they found a point with cos(2x) - 3*sin(x) = -4

[urban oxide]

It says

if the solution of the equation is a*pi/2 who is a

[plain pollen]

@eternal crag sorry I was doing smth else, are you still here?

[eternal crag]

yes i am

shall we continue?

so i was saying,

you're given that y = -2, yeah?

i'm not going to reply you incase you come back again, this is the second time you ghosted me

[urban oxide]

I got another problem

sin4x=2/(n-1)

It says how many n natural numbers are there so that the equation doesnt have real solutions

i thought first one would be 1

2 and 0

[rich wolf]

@urban oxide sin^4(x) or sin(4x)??

[urban oxide]

sin(4x)

[olive plover]

is creating a picture through equations in desmos fun

[paper mauve]

@olive plover fun is subjective. Some people are capable of doing it and have fun doing it, others not so much. Personally I have no clue how to work desmos

[upper karma]

how do i find the fundamental frequency of the superposition of two sinusoids
and btw they arent harmonics

[slate phoenix]

Challenge: give me an elegant solution to this problem

[mellow vector]

@slate phoenix Though it's just physically, you can use Thales Theorem :)

[severe flare]

"R" the radius of the circle ?

[mellow vector]

I think so

[slate phoenix]

@mellow vector how would you use thales's theorem? It doesn't seem quite obvious

[mellow vector]

With the right angles

I am not that knowledgeable, just happened to watch a video about that and thought it's perfect timing.

You can find the center of a circle with it,

But only physically.

[vagrant owl]

hey red

[mellow vector]

Hello

[vagrant owl]

is there someone on here that can help me with trig

[rich wolf]

@vagrant owl just ask

[slate phoenix]

Oh, I want to

[rich wolf]

Same

[eager pendant]

@slate phoenix nice problem, where’d you find it?

I got a solution just involving angle chasing

[olive plover]

is -1/(x+2)+5 a rational function

[rich wolf]

yeah

[visual mist]

can someone help me? im stuck

[hollow finch]

Sure

Just find the sum of the two angles that make up angle ABC

[visual mist]

wdym?

[hollow finch]

It's made of an equilateral triangle and an isosceles triangle right

[visual mist]

ye

[hollow finch]

Oh uh, one of the angles of the isosceles triangle and one of the angles of the equilateral triangle makes up angle ABC right?

[visual mist]

ohh

i get it now

[hollow finch]

Ya, just find those two angles and add them up

[visual mist]

so the angles in the equilateral is 60

[hollow finch]

Yes

[visual mist]

so angle abc would be 30

because 90-60 is 30

no

wrong angle

[hollow finch]

You need to prove that angle ABC is 90 degrees

Uh... ok, what is the sum of the angles that make up a straight line

[visual mist]

180

[hollow finch]

So what the large angle of the isosceles triangle

[visual mist]

uh 120?

[hollow finch]

Yes

So what is one of the smaller angles

[visual mist]

60

[hollow finch]

No

[visual mist]

oh

wait 30

i thought u meant something else

[hollow finch]

Yes

It's ok

Ok ok, so 30+60=?

[visual mist]

90

[hollow finch]

That's it

[visual mist]

oh okay

thankq

[hollow finch]

Np

[visual mist]

but like when you meant one of the smaller angles do u mean of the eqailateral one or isoceles

[hollow finch]

The isosceles

[visual mist]

why would 60+30 prove that

[hollow finch]

Wait, i'll show you

[visual mist]

okay

oh do u mean like one the angles of the equilateral and one angle from the isosceles add up to 90?

[visual mist]

yes

[hollow finch]

So what are the two angles that make up ABC

30° and 60°, you add the two together, you make 90°. Therefore, angle ABC=90°

[visual mist]

oh ye

[hollow finch]

That's it

[visual mist]

okay thanks

[hollow finch]

You understand?

Np

[visual mist]

i get it

[hollow finch]

Ok ok good

[visual mist]

i have another problem that im not sure how to do it would you mind helping me again? sorry lol

[hollow finch]

Sure

Send ah

[hollow finch]

let angle COD=x and let angle AOB=y

What is the sum of angles on a straight line

[visual mist]

180

[hollow finch]

What are the angles that are on the line

[visual mist]

EOD, DOC,C0B and BOA

[hollow finch]

Ya

Write those angles in terms of x and y

[visual mist]

wdym?

[hollow finch]

let angle COD=x and let angle AOB=y use this substitution

[visual mist]

y,y,x,x?

[hollow finch]

Yes

y,y,x,x

So 2y+2x=180

[visual mist]

ohhh

[hollow finch]

y+x=90

[visual mist]

wow

so smart

thanks

[hollow finch]

Thank you

angle DOB= angle BOC+ angle COD

=x+y

So angle DOB=90

[visual mist]

okay

[hollow finch]

You understand?

[visual mist]

yes very much

u make everything so clear B)

[hollow finch]

Ya, geometry is to use your eyes and the laws of geometry

So can see everything from one image

Just need to help you look in the right direction

[visual mist]

yep

anyways thank you so muchh

[hollow finch]

Np

[quick hull]

can anyone tell me how to find the intercepted arc without knowing the intercepted angle

[rich wolf]

@quick hull what do you know

[ashen karma]

So u know rhe angle

@quick hull

(0.27)2pie r

[quick hull]

wait huh? i haven’t learned this yet, we were supposed to learn it this quarter but can’t go to school

[golden panther]

Guys i want to know how to do cos5theta=3/4; 0<theta<2pi

thank u🙏

[surreal bolt]

um ... arccos(3/4)/5 + n(2pi/5)?

[golden panther]

wow

[surreal bolt]

sorry kinda busy with something eles 🙂

I must go.

[golden panther]

Wth

[upper karma]

Wait

Nvm

Yeah

Is this is a true thing?

Then it would be $beta=90-frac{alfa}{2}$

[quick hull]

can some help me out

[upper karma]

@quick hull ill try but can you try mine

[quick hull]

@upper karma i’m not very good at geometry

[upper karma]

Shit

Okay ill try with yours

That 50 is from inside right?

[quick hull]

the 50 is the inscribed arc

my school has me doing Q4 shit and we haven’t learned it

[upper karma]

I mean

That 50 is the angle of the inside

Arc

Yeah right

?

[quick hull]

inscribed*

[upper karma]

Okau

Wait

Omg i did it

I was expecting it to be harder xD

@quick hull

Lemme take a pic

Do you know why or i explain?

@quick hull

Emmm

Hello?

[upper karma]

Is this true?

It is, isnt it?

[rich wolf]

that is true. the proposition doesn't make sense however because it implies that alpha is negative

because theta is clearly greater than 90

[upper karma]

Yeah it was ramdom example

Thanks

[quick hull]

@upper karma yeah sorry i figures it out but you were right

can someone help me out?

shit that’s blurry

[rich wolf]

dude you know on a macbook

you can take a screenshot right?

[humble pebble]

@quick hull late but it's 95

oh wait i might be wrong lmao

[quick hull]

@rich wolf dude i’m not on discord on my macbook

[humble pebble]

what does subtends mean

[quick hull]

@humble pebble i got it thanks though

[humble pebble]

just download discord on ur mac

@quick hull

[quick hull]

i have it

[humble pebble]

lmao

ok

[quick hull]

just easier to use on my phone

[humble pebble]

coo

[frail vigil]

sorry for the fucked up drawing

i need to find the dot's geometrical space

geometric*

i did many things and i am getting stuck

e and c and have the same y value

so i tried e(Ex,Ey)

and then c(0,Ey)

then the dot in the middle is p

so p(x,y)

and tried to get to

Ex= and Ey=

so i could put in ab line

[upper karma]

were you given any information about point E?

@frail vigil

[frail vigil]

no

only that ec is parallel to x

[rich wolf]

@frail vigil find the length of ab

[frail vigil]

10

how would it help me

ec/bo= ae/ab?

[rich wolf]

Yes

[frail vigil]

Ex/8=ae/10

i still have to use pitagoras on ae

but it's not the way

i need to do

Ex= Ey=

through the middle dot

and then put it in ab lline

doing ae= is 10-sqrt(6-Ey)^@+Ex^2)

not @ , 2

[rich wolf]

Prove oce = ace

[frail vigil]

i cannot prove it

that's the point of geomatric place

you are talking about something else

[runic pasture]

Hey ! I have this problem and I can't resolve it, their is some highest common factor in it :

B is a box in the shape of a straight paving stone of height L, with a square base on side l, where l and L are
non-zero natural numbers such as l < L.
We want to fill box B with identical cubes where the edge a is a non-zero integer.
(the cubes must completely fill box B without leaving any empty space).

In this question, the volume of box B is v = 77,760.
We know that, to fill box B, the largest possible value for a is 12.
Show that there are exactly two possible boxes B, the dimensions of which will be given.

So I started doing things but i don't know if it will be useful : the volume of the cube is 12^3 = 1 728 so we in B we have 77 760 / 1 728 = 45 cubes and.... i'm blocked, help !

[native parrot]

anybody reccomend any websites?

for trig help/review?

I failed my 'intro to trig' test so i wanted to take this covid break as some time to learn everything properly

@ me if you can help :)

[weak ember]

khanacademy does all of this

and he goes to pretty advanced topics. just go through his entire course, you should learn a lot

[fickle light]

Hey can someone please help me with finding the volume of a complex shape

[upper karma]

Sure

Gimme a question and I’ll help you through it.

(Assuming you understand the properties of imaginary and complex numbers, this should be pretty simple.)

[dapper comet]

what is it called when you find the greatest line segment in a group of lines

you do this by taking the point at the end of the line segment

and its slope

m(y) + x

not sure what this is called tho?

[prime ledge]

@everyone can someone help me solve this

[onyx cloud]

@prime ledge the diagonals of a parallelogram intersect at their midpoints

[prime ledge]

ohh

[onyx cloud]

if thats not enough lmk but give it a shot

[prime ledge]

ok

thank you

[boreal narwhal]

Can anyone help me with my geometry transformations homework?

[onyx cloud]

shoot

[onyx cloud]

where are you stuck

[boreal narwhal]

For starters, Did I do number 1 right?

[onyx cloud]

right off the bat it says to show coordinates for all transformations

so im guessing no

[boreal narwhal]

oh i didnt see that

[onyx cloud]

the answer looks right to me though

[boreal narwhal]

ok

[brisk orbit]

hi i got a task for my homework can someone help me

its to construct a triangl with b+c the angel in a and the height from c

im bad ik

[ashen karma]

Yeaj ..there are tons of people to help u here

[high zephyr]

feel free to just post the question, no need to ask if u can be helped

[rich wolf]

B+C=(BB+BC)/B

[upper karma]

hey how can i solve this

[dark sparrow]

by knowing that any tangent line to a circle is perpendicular to the radius drawn to the point of tangency

[upper karma]

Thanks

[devout harbor]

You can use sin(51) = DE / 18

[bronze geyser]

with this new e-learning i'm going to be super active..

[tiny halo]

Is my answer correct

[supple wedge]

,w calculate sin 22

[somber coyote]

Display results online and refine query

Requested by Hmm#2554

[supple wedge]

guess so @tiny halo

[tiny halo]

Do you know how to do this

[dark sparrow]

do you know what "geometric mean" means

[tiny halo]

No

[dark sparrow]

http://lmgtfy.com/?q=geometric+mean

[tiny halo]

Ok I get it

Is this trig

[eager kraken]

Can anyone help me solve through this?
I think the Sin's are
9/25
3/5
I am not sure however how to solve the tan functions for these kinda of problems.

[surreal bolt]

what's sin(x + y)?

[eager kraken]

sin(x)cos(y)+sin(x)cos(y)

[dark sparrow]

[eager kraken]

wait do I just add 9/25 and 3/5?

[dark sparrow]

no

[eager kraken]

it was confusing when they gave me a sin now it's got 2 cos's

[dark sparrow]

... wait where do you even get 9/25 from

but no sin(s+t) ≠ sin(s) + sin(t)

and you also didn't answer pestamist's question correctly

[eager kraken]

9/25 is from sin^2=1-(-64/289)^2

[dark sparrow]

you're being incredibly sloppy

[eager kraken]

sin(x)cos(y)-sin(x)cos(y)
is the corrected six(x+y) then?

[dark sparrow]

no, it is not

read what you're writing

you've just written 0

[idle bloom]

What happened to the y's?

[dark sparrow]

when asked what sin(x+y) is, you answered

sin(x)cos(x)+sin(x)cos(x)

do you not see the issue in your answer

[eager kraken]

yes

i see

i obv meant the second x to be y's

[dark sparrow]

no

[idle bloom]

It's not obvious

[dark sparrow]

that's no excuse

it's not obvious to anyone here whether you really meant y - and where you meant y and not x - or you actually didn't know until it was pointed out to you

and in any case, the numbers you blurted out (9/25 and 3/5) are not even the correct values for sin(s) or sin(t).

[eager kraken]

im glad we got that out of the way

[dark sparrow]

so it would REALLY HELP if you showed your work

so that i could tell you exactly where you messed up

(of course, that's only possible if your work is clear and comprehensible)

[eager kraken]

I will ask someone else for the time being

[tiny halo]

How do you this I’m confused

[ashen karma]

Neartest 10 means 9 becomes 10

8 goes to 10 ..is it??

[dark sparrow]

@ashen karma nearest tenth != nearest ten

[tiny halo]

Can you explain to me what I have to do

[eager kraken]

https://www.wikihow.com/Find-the-Magnitude-of-a-Vector
@tiny halo
Then just round to the nearest 10 for your answer

[wind heart]

Ummmm I’m kind of confused with this project I was assigned

It’s so weird

So, we’re supposed to use our prior knowledge of ratios, proportions and similar triangles to solve these problems. We’re supposed to use real world objects and not measure them and some how put them into a proportion to figure out the length. I’m really confused. How and the world could I get the height of a tree that I didn’t measure using my shadow and the trees shadow?

[tiny halo]

Can someone help me with a question

[upper karma]

Someone

Help

Help

Help

Plz

Plz

Plz

Plz

Help

[fierce pebble]

@upper karma

what question?

[smoky lark]

@upper karma u gonna answer back

smh

[upper karma]

Sorry

[fierce pebble]

lol

[upper karma]

I was watching hype house drama hahaha

[fierce pebble]

bruh

[fierce pebble]

use cosine

3sqrt3cos60 = x

wait no im stupid

cos 60 = 3sqrt3 / x

cause cos(angle) = adjacent / hypotenuse

[smoky lark]

OR U CAN USE THE 30-60-90 thing

[upper karma]

Ok ill try that

[smoky lark]

3 √3 times 2

👀

[fierce pebble]

I completely forgot about that stuff lol

I always just use a calculator 😛

[ocean light]

Omg I’m not on the timer no more

Was sup guys I know I’m late

[wind heart]

<@&286206848099549185>

[rich wolf]

What do you want

[rich wolf]

The geometric mean of $n$ numbers is calculated by the $n$th root of their product

[somber coyote]

AMD:

[upper karma]

I need some assistance

[rich wolf]

@upper karma draw a horizontal line that goes through B

And call the point where the line intersects line DA point P

[upper karma]

Yeah figured it out

Thanks computer processor company

[rich wolf]

Nice

[novel yacht]

Hi, I have a few questions can someone help me

[onyx cloud]

just ask

[novel yacht]

How do i solve 64^5x+2=8 with no calculator

using logorithms i believe

[onyx cloud]

first things first simplify it one step further

its a very simple thing

[novel yacht]

how do I do that?

[onyx cloud]

can you subtract something from both sides?

[rich wolf]

Wait what do you mean by that

[novel yacht]

oh subtract 8

right?

[rich wolf]

$64^{5x+2}=8$

[somber coyote]

AMD:

[onyx cloud]

oh

i see

[rich wolf]

Or $64^{5x}+2=8$

[somber coyote]

AMD:

[novel yacht]

wait huh

[rich wolf]

Very different problems

Which one do you mean

[novel yacht]

the top one is correct

so 64^(5x+2)=8

[rich wolf]

Take log base 64 of both sides

[novel yacht]

what does that look like

idk how to do that

[unborn jacinth]

wait why is that given 3 sides of a triangle, the law of cosines gives you an answer in terms of degrees

is it possible to manipulate the law a little bit so it gives it in radians

(I know you can covert but I'm trying to understand it better)

[novel yacht]

You would need to change your calculator

[onyx cloud]

the answer can be in radians or degrees

it doesn't matter, like you said you can convert

[unborn jacinth]

so I would just change my calculator mode to radians?

[novel yacht]

@onyx cloud can you help with my problem the other dude dipped

[onyx cloud]

yep

oh sure

[novel yacht]

it was the top one he posted by the way

[onyx cloud]

so

start with this

2^x = 4

can you do log base 2 of both sides?

would you know what that looks like?

[novel yacht]

Idk what that would look like

[unborn jacinth]

(x = logbase2(4))

[onyx cloud]

yup

[novel yacht]

so what is my while first equation then?

[onyx cloud]

?

[novel yacht]

oh whoops

so what am I left with after doing logbase2 of both sides

is it what @unborn jacinth said?

[unborn jacinth]

yeah wait which question are you working on?

I see the one with 5x+2

as the exponent

[novel yacht]

$64^{5x+2}=8$

[somber coyote]

nolan:

[unborn jacinth]

ok

[novel yacht]

yes

[rich wolf]

Ok

Take log base 64 of both sides

[unborn jacinth]

then 5x + 2 = logbase64(8)

[acoustic jungle]

log 8 would work too right

[unborn jacinth]

yes

[acoustic jungle]

k

[unborn jacinth]

but

[rich wolf]

Its easier to do this way

Less steps

[unborn jacinth]

yeah bc otherwise you'll have log on both sides still

[novel yacht]

Ok so after taking log64 from both sides what do i do

well whats my equation

[unborn jacinth]

actually

logbase 64 (8) means something to the power of 64 = 8

[rich wolf]

$5x+2=\log_{64}(8)$

[somber coyote]

AMD:

[unborn jacinth]

so thats 1/2 correct?

[acoustic jungle]

yes

[unborn jacinth]

now you have a regular equation

5x+2 = 1/2

[rich wolf]

Dude dont do the problem for him

[unborn jacinth]

oops

[novel yacht]

lol its fine

[rich wolf]

How's he supposed to learn how to do it himself if you just solve it for him

[novel yacht]

can u just expain how u simplified the logbase64(8)

[rich wolf]

Of course

[unborn jacinth]

yes

[acoustic jungle]

64^what=8

64^1/x = xth root64

[novel yacht]

ohhh i see

[weary drift]

you can alternatively do a change of base

[unborn jacinth]

(srry for bad image quality)

but I think that should help you understand the different ways of writing a log function

[weary drift]

$\log_{64}(8)=\frac{\log_8(8)}{\log_8(64)}=\frac12$

[somber coyote]

RokettoJanpu:

[acoustic jungle]

That is smart

[unborn jacinth]

that is another way to do it that uses change of base

[novel yacht]

Oh wth

[unborn jacinth]

@novel yacht does that help?

[weary drift]

you can alternatively do a change of base

[novel yacht]

Yee i got it now

[weary drift]

i did just say it so

you never know when change of base can be useful

[unborn jacinth]

ok sorry for accidently solving it

😬

[novel yacht]

4^-6=x^3

[acoustic jungle]

also if you logged 8 instead of 64 on both sides it's good to know log k^x = x log k

[novel yacht]

how do i do this one without a calc

4^-6=x^3

[weary drift]

for future reference
$$\log_b(a)\equiv\tfrac{\log_c(a)}{\log_c(b)}$$
for any values of $a,b,c$ that make sense to plug in

[somber coyote]

RokettoJanpu:

[unborn jacinth]

@novel yacht what does a negative exponent mean

1/x

what is x in your case

[acoustic jungle]

yes I know how

Try logging both sides by a number

[novel yacht]

1/6

[unborn jacinth]

is it?

[acoustic jungle]

no -6 is 1/x^6

that is 6th root

[novel yacht]

wait huh

[acoustic jungle]

x^-n = 1/x^n

[unborn jacinth]

a^-b

[acoustic jungle]

x^1/n = nth root x

[unborn jacinth]

is 1/(a^b)

[acoustic jungle]

I think you learn this in grade 10

I learned it in grade 10

[novel yacht]

I am in grade 10

[acoustic jungle]

yes did you learn it?

[novel yacht]

Not whatever u guys just said

[acoustic jungle]

I had it last semester I'm sure it's in the Canadian curriculum

[novel yacht]

Im not canadian idk

[acoustic jungle]

o

[novel yacht]

ok restart

[acoustic jungle]

it's exponent rules

[novel yacht]

isnt a -6 exponent 1/6?

[acoustic jungle]

nono

[novel yacht]

what is it

[acoustic jungle]

search up exponent rules that will help you and I also told you above

FishraiderToday at 8:08 PM
x^-n = 1/x^n
MeHereToday at 8:08 PM
a^-b
FishraiderToday at 8:08 PM
x^1/n = nth root x

[novel yacht]

would it be 1/x^6?

[acoustic jungle]

that's right

[novel yacht]

oh okay

so then what

[acoustic jungle]

oh you're trying to solve the problem?

Try logging both sides by a number

[novel yacht]

trying to solve for x yeah

[acoustic jungle]

and use the rule log k^n = nlogk

[novel yacht]

ur gonna have to show me that idk what that is

i missed over a week of school before coronacation so thats probably why I didnt learn this

[acoustic jungle]

You should try some easier problems first or look over the log rules

http://web.gccaz.edu/~andso40741/MAT151/Proof-of-Log-Properties.pdf

and you don't learn logarithmetics in grade 10

we were learnig parabolas and completing the square

[novel yacht]

Oh we did that a while ago

[acoustic jungle]

Unless you are from china or india or something

[novel yacht]

lol nah america

[rich wolf]

@upper karma angle addition formula?

[upper karma]

@rich wolf that's the first step yeah..

Cos(2alpha)=sin(theta)+cos(2theta)

This is what that leads to