geometry-and-trigonometry

[fossil ledge]

dont worry Birdie

[queen python]

im 13 freshmen year

[olive solar]

overall curriculum can vary between schools birdie

[tired laurel]

Is your bday like

Really late

[queen python]

Dec 31st

[fossil ledge]

I would not feel worried about anything Bongo says

[tired laurel]

Ah well ok

I can see that

[olive solar]

anyways lets go back to the topic of what is included in the subject of geometry, as a course

[queen python]

ok

[tired laurel]

I mean

[upper karma]

it's alright

[fossil ledge]

oh yea, send that syllabus

[tired laurel]

Areas and perimeters right

[upper karma]

age never matters

[queen python]

Well want a basic run down

[trail minnow]

nothing happens in geo kek

[tired laurel]

That’s all I know

[upper karma]

I'm looking for it

sorry for the wait

[queen python]

Hey Hegel

[fossil ledge]

no worries

what country btw?

[queen python]

missed you 😉

[tired laurel]

Us

[olive solar]

@trail minnow it's like. an intro do baby's first mathematical reasoning

[queen python]

me?

[tired laurel]

NY

[queen python]

Im in nyc

[trail minnow]

ye kinda

[olive solar]

oh boy is that 8bit

[trail minnow]

n y c

[queen python]

nyc gang

[tired laurel]

I don’t live in nyc

[trail minnow]

[tired laurel]

I live sorta close to it tho

[trail minnow]

anyway geometry basically is just simple logical reasoning

[tired laurel]

Long Island

[fossil ledge]

I was asking @upper karma

[queen python]

that's nyc

[upper karma]

Yeah still looking for it

sorry

[tired laurel]

No

[queen python]

Nyc included Long Island

[tired laurel]

Only parts of it

[queen python]

[tired laurel]

Not my town

[trail minnow]

[queen python]

o

didn't know that

[trail minnow]

anyway im not sure but your class may open with a short unit on shit formal logic kek

[olive solar]

the best proofs

[trail minnow]

if then statements, and/or, syllogisms, etc

[tired laurel]

I have some textbooks but they make everything seem so hard

[queen python]

Well

[upper karma]

Ok, doxx

but I don't give a fuck

[queen python]

That's cause reading is not more math

Doing is

[tired laurel]

Like I still can’t do the algebra one and I’m supposedly good at it

[trail minnow]

the algebra textbook?

[queen python]

Send one

[trail minnow]

you can't do the problems?

[queen python]

Let's figure it out together

[upper karma]

,rotate 90

[trail minnow]

,rotate

oof

[upper karma]

haha

[trail minnow]

lmao

[tired laurel]

Is that a cat

[trail minnow]

oh boy

please delete this img after

[upper karma]

yes doxx

[queen python]

^

[trail minnow]

pearson is standard

[tired laurel]

Ok

[upper karma]

Got it?

[tired laurel]

I know trigonometry

Thanks

[trail minnow]

"""logic and reasoning""" kek

[upper karma]

anytime

[fossil ledge]

okay pretty standard

seems similar enough to Canadian curriculum

[upper karma]

actually, I'm taking a summer course

option 2

[queen python]

Good

[tired laurel]

Does this server include physics

[upper karma]

to skip it over the summer

[trail minnow]

nice

[queen python]

Yes

[trail minnow]

geometry is shit

[olive solar]

you should delete that image, the non rotated one

[queen python]

Anything math

[trail minnow]

well actually

[fossil ledge]

not really bongo

[upper karma]

@olive solar both have been deleted

[trail minnow]

high school geo is shit

[tired laurel]

Where?

[queen python]

just ask it

[tired laurel]

Can’t find the chat

[olive solar]

i still see it on my discord client

[upper karma]

Right on, I bid you farewell

[olive solar]

"just ask it" you make no sense

[queen python]

bye

[tired laurel]

Ye

[queen python]

i know

[fossil ledge]

there is a physics server in the network

go there

[queen python]

^

goat is smart

never thought of that

[upper karma]

how do you get the helpers role

[fossil ledge]

ask mod

[trail minnow]

physics 🤢

[olive solar]

you bribe the mods

[queen python]

Help people

[upper karma]

is there a set amount of times you need to help

ah I see

[fossil ledge]

sometimes several times

I had to ask Jun 3 times :(

[olive solar]

i paid woog 30$

[queen python]

@copper valve can I get helper

[upper karma]

I'm willing to help other geometry students, as it's fresh in my mind

[fossil ledge]

pinging woog

[upper karma]

also anything before algebra 2

[queen python]

I've pinged woog on her other servers

[fossil ledge]

you dont need helper role to do that

[upper karma]

I know

[queen python]

She's mod on a school server im in

[upper karma]

but having a color is nice

[olive solar]

hm. honestly i'm not sure how they should handle asking for helper role

maybe a channel for it so that mods don't all have to get pinged?

[upper karma]

yeah, it should be standardized

but I can't change that right now can i?

[trail minnow]

all of high school is meme

[olive solar]

all of school is a meme

[upper karma]

^ that's facts

[trail minnow]

high school math anyway

[olive solar]

just drop out now while you still can

[trail minnow]

colo if u fail analysis plis send my ur tears

i wanna bottle them

[olive solar]

lol

[queen python]

Hegel what do I need too know for Rome part of history

[olive solar]

thanks hegel

[trail minnow]

nothing kek

[upper karma]

I don't think i should drop out

[queen python]

oke

[upper karma]

when I've been doing so well so far

[trail minnow]

its garbo

[queen python]

Ima try to finish world by Sunday

[upper karma]

that's very motivated

[trail minnow]

more seriously you should know the founding of rome + the gracchi brothers

[queen python]

then comes micro and macro for a week

[upper karma]

Also this has gone off topic

[trail minnow]

wait

you know none of the pre-1400 material is on the AP exam right

[olive solar]

this is an appropriate time to go to chill

you know this, right?

[upper karma]

don't want the geometry chat clogged up

[queen python]

huh

[olive solar]

[trail minnow]

chill mi g r a t i o n

[queen python]

Wait

[trail minnow]

no u

[queen python]

When does ap go back too?

[upper karma]

Right, cheers

[trail minnow]

ask in chill smh

[upper karma]

I've invited others in my summer course as well to join

[trail minnow]

kek

invasion

[upper karma]

oh god do I really have to ping the mod role?

this feels so wrong

[queen python]

No

Ping a mod

Not the whole role

[trail minnow]

ping flimflam

or mniip

[fossil ledge]

lets go to chill

[upper karma]

ah, alright

I'm sorry

[queen python]

What did you do?

[trail minnow]

fookin stop talking here

[tired laurel]

Can someone explain to me how u do dis

[upper karma]

Which problem?

[tired laurel]

Triangle

[upper karma]

dang I didn't get to dilations yet

it's a transformation

[tired laurel]

Idk how u draw them

[upper karma]

wait let me think about this one

[tired laurel]

I understand the concept

[queen python]

@tired laurel

What's the question

[tired laurel]

Just plotting

[queen python]

Ok

[tired laurel]

K is scale factor

[queen python]

So lemme explain

If the graph was centered at (0,0)

And a point was at 2,2

[tired laurel]

No pls is there an algebraic way to this

[queen python]

A scale factor of 1/2 is 1,1

Yes

Multiply the points by scale factor

[tired laurel]

Ohh I see what u mean

Thanks

[queen python]

2x 1/2

Is 1

If it was 2 it would be 2x2

[tired laurel]

Very nice online course knowledge you’ve got there

[queen python]

Thanks

[tired laurel]

Thank you owo

[queen python]

:0

Im a helper

[tired laurel]

Who’s also younger than me

By 364 days

[queen python]

Lol

It's oke

[tired laurel]

uwu

[queen python]

Anyone need help?

[stuck torrent]

I need help

[queen python]

Ok

With what

[stuck torrent]

How do I differentiate f(g(h(x))) n times

[upper karma]

oh

[queen python]

it doesn't matter

Just look at the equation

Or the problem

And this is pre alg

[stuck torrent]

right

[queen python]

Anyone need help on geometry

[upper karma]

Teach me all about circles

everything

[stuck torrent]

Oh yeah look at this @queen python

,w 9th derivative of f(g(h(x)))

[queen python]

What

[somber coyote]

Display results online and refine query

Requested by Whoever#5822

[queen python]

@upper karma

[upper karma]

everything about circles

[queen python]

Ok

Circle is 360 degrees

[stuck torrent]

There is this formula for the volume of nth ball

[queen python]

All you need too know

[upper karma]

Mainly proving the theorems on the back

[queen python]

I don't have proofs memorized

I can do math though

send a problem

I'll be able to probably do it

Unless it's advanced geo

i can't do that stuff yet

[upper karma]

Lol I'm good

just need to study

[mighty gull]

oh volume of nth unit ball is fun

$x_1^2+x_2^2+\dots +x_{n-1}^2+x_n^2=1 \to x_1^2+x_2^2+\dots +x_{n-1}^2 = \sqrt{1-x_n^2}^2$

[somber coyote]

JohnDoeSmith:

[mighty gull]

a nth unit ball can be thought of the integral of many different (n-1) balls of radius sqrt(1-x_n^2)

[upper karma]

Org-mode can do latex too

[stuck torrent]

xD

[upper karma]

which was pretty cool when I first looked at it

but in practice, markdown is much faster to write

whoops wrong channel

[stuck torrent]

Also another interesting fact, the volume of an n balls with radius 1 actually vanishes when n approaches infinity

I think

Which is really weird to me

[mighty gull]

yeah that is wierd, the volume maxes out somewhere near n=7 i think, and it starts going down aftr that

[stuck torrent]

yeah

What is the sum of all the even nth ball volume with radius 1

Think about it

It's interesting

[mighty gull]

its gonna be something like e^(pi) right

[stuck torrent]

ya

I think it's $e^\pi$

[somber coyote]

Whoever:

[stuck torrent]

can we use this to prove the irrationality of e^pi?

@sullen bramble

[mighty gull]

hmm

[sullen bramble]

hm?

[stuck torrent]

Well I guess it is already proven to be transcendental

Nvm

[eternal crag]

this is probably one of those "14yr old asking graduate level question," but how does one go proving a number is normal or not?

[stuck torrent]

normal

uh

wdym by normal

This is discrimination against real numbers

[mighty gull]

http://mathworld.wolfram.com/NormalNumber.html
apperantly this is a thing, seems interesting tho

[stuck torrent]

Do you mean rational, irrational, and transcendental?

[eternal crag]

irrational number that contains all combination of sequence of numbers sort of

[mighty gull]

hmm actually they havent proven Pi is that yet

[eternal crag]

for example, 0.010010001000100001... is not normal but irrational

[stuck torrent]

ah

I see

[eternal crag]

yeah

[stuck torrent]

nvm

interesting

so pi is one I think

has not been proven

[mighty gull]

have they proven it for sqrt(2) or smth?

[tawdry pivot]

I'm pretty sure the only known normal numbers are one's constructed to be normal

[stuck torrent]

let's move to #advanced-number-theory

xD

MOVE TO #advanced-number-theory

[supple abyss]

I don't think there's much you can do to prove a number is normal

[mighty gull]

yeah, it seems hard, like where to even begin(atleast for now that is). irrationality for example can be done with continued fractions etc

[stuck torrent]

infinite series of a number with a term of 1/10^k

then you can do something about it

[tawdry pivot]

I heard some like almost all numbers are normal

[stuck torrent]

I guess

[supple abyss]

yes

normal numbers are normal

[tawdry pivot]

almost all real numbers are normal

[mighty gull]

hmm can that be proven

[stuck torrent]

is it dense in R

prob

[supple abyss]

it's been proven

[mighty gull]

oh nice. although a bit over my head as i havent studied enough analysis yet

[tawdry pivot]

so basically we know almost none of the reals

[supple abyss]

well we know almost none of the naturals

[tawdry pivot]

oh right lol, i think "know" is kinda vague

[stuck torrent]

Godel's incomplete theorem be like

[quiet mason]

lol incompleteness not incomplete

[fossil ledge]

Oh so when I don’t do homework I get in trouble but when Godel does he gets famous

[quiet mason]

😂

lul

[upper karma]

Lol

[quiet mason]

pin

that

it deserves

[worthy root]

Inequality

[upper karma]

Hello there i have a doubt regarding locus of a poitn

Point

[olive solar]

[upper karma]

So i am confused whether a locus is A point or it defines OTHER GEOMETRICAL Figures that are a collection of points and they satisfy some condition ?

Like in wikipedia it says

In geometry, a locus (plural: loci) (Latin word for "place", "location") is a set of all points (commonly, a line, a line segment, a curve or a surface), whose location satisfies or is determined by one or more specified conditions.

While in a book which i am reading i am required to prove the locus of a point equidistant from two fixed points is the perpendicular bisector of the line segment joining the 2 points

Any hints guys ?

Colorodos stains ?

[olive solar]

your question is, if im reading correctly

you want to prove that if a 3rd point is equidistant from 2 others, then drawing a pine from that third point perpendicular to the line formed by the first 2 will give a perpendicular bisector,correct?

[upper karma]

@olive solar i actually want to know what a locus actually , the proof is quite basic its the use of locus , which is confusing me.

[obsidian atlas]

@upper karma So the perpendicular bisector is the locus

The locus is the set of points that are equidistants from the two points (that are connected by a line) i.e. the perpendicular bisector...

#SmokeWeedErryday

[upper karma]

Hey guys

,rotate

,rotate 90

[trail minnow]

hint

[upper karma]

So, I don’t really know a way for sure to prove these triangles congruent

[trail minnow]

label CD y

[upper karma]

so I’m a bit lost

[trail minnow]

they aren't congruent

[upper karma]

yeah alright

[trail minnow]

not similar either

[upper karma]

rip

[trail minnow]

but they do share one side, so we can label that side CD y

[upper karma]

was just about to check for that

[trail minnow]

now try relating the three sides of each triangle

[upper karma]

and yes, I did

[trail minnow]

hint: triangle inequality

[upper karma]

Hmm

let me think about it for a bit

[trail minnow]

👍

[upper karma]

Thanks

lol I think I got it

[lusty quest]

how do i know what period these trigs are? sometimes its 180 and 360, then its just 180

[cinder portal]

draw your circle

on the 4 quadrant thing

figure out where your solution(s) are

[lusty quest]

can i graph it?

on a calc

[cinder portal]

have you learned unit circle trigonometry?

[lusty quest]

yes

probably

[cinder portal]

figure out where your solutions are

and then send me a picture

[lusty quest]

i think im gonna go sleep tho

[cinder portal]

k

[stuck torrent]

@upper karma you only got x>1 tho

[quiet mason]

yea

[worthy root]

l and k are parallel find angle B

[cinder portal]

uhhhhhhh what are you trying to do?

[worthy root]

Done with that

[cinder portal]

why did you post it if you were done with it, what

im so confused

[worthy root]

Line L and k aree parallel

find angle B

[cinder portal]

here'e one solution for you

[worthy root]

I am donw with it

[cinder portal]

connect points l and k, and then you can probably figure it out from there

well wtf do you want

you're telling me to find angle B, but you say you're done with it

[worthy root]

I am done with it got the answer

its 160

[cinder portal]

Did you want to check the answer?

[worthy root]

yes i checked on alcumus they had different solution but same conclusion

[cinder portal]

he posted a problem, i thought he wanted help

cuz if he didn't want help, what else did he want?

[worthy root]

I mean i was confused first i am done with it now

[cinder portal]

damn what was the point of posting it if you could solve it in a couple mins

[worthy root]

I mean i first got scared

Leave it sorry

[cinder portal]

so what you're saying is, you never attempted it and then posted it, only to then attempt it then realize you can solve it

[worthy root]

yEa i did some constructions then it was easy

I mean i didnt use the book pen first

tried to solve it in my small mind

butthe question asks for some construction

[rigid wharf]

I think its B but im not sure

[echo trench]

https://cdn.discordapp.com/attachments/595919530530963456/607394266528088066/Capture.PNG

Any assistance?

[umbral snow]

It would be nice if you had l - h without needing to use h

Let l - h = x, then naturally h = l - x

[echo trench]

@umbral snow
Ok starting with 17, explain

[echo trench]

Anyone explain pls?

And then assist with 18

[fringe dirge]

Can you find any other length in this picture?

[echo trench]

No this is all information given

Its in the trig section @fringe dirge

[fringe dirge]

Can you find any other length in this picture?

[echo trench]

I dont understand

Sorry

You just repeated that question

I mean I look at it

And I see only 2 lengths but nothign else

1 height

the weird 0 with line dividing it

[fringe dirge]

Can you figure out how long any other line is in this picture?

[echo trench]

No I cannot

Like it just says find h in terms of l and 0

*0 with line

[fringe dirge]

Why can't you

[echo trench]

@fringe dirge Bc i dont know

Dude this is everything that is given

Just variables

[fringe dirge]

That doesn't mean you can't find how long other lines are in this picture

Think about what you know about trig

[echo trench]

I dont know much about trig

Just functions

sohcahtoa i mean but that wouldnt help here

[fringe dirge]

why not?

[echo trench]

I dont see no use to it as this is a cone and like theres no triangles

[balmy linden]

Think about it - there's a right angled triangle

[echo trench]

Unless theres that weird one at top with the dotted line but how the heck would that help

Like its just the 0 with the line as an angle and one l as a side

and i cant put that in a calculator to get an amount

[fringe dirge]

What does soacohtoa let you do

[balmy linden]

That's theta not zero btw

[echo trench]

zero with a line= theta

o yeah

cool

sohcahtoa lets me

find missing sides and angles

[balmy linden]

You got yourself the way to do it (:

[echo trench]

what the hecky does that mean

but how does that help me find an expression for h in terms of l and theta

😦

[balmy linden]

I think it's best to learn a bit of trig before doing these sorts of questions

[echo trench]

Yes

And this is the place to go

[fringe dirge]

It's not. We're not here to teach you a whole subject

[balmy linden]

Yea...

[echo trench]

Not the whole subject

ok its not like

im not knowledgeable about it

[balmy linden]

There are good websites like Khan academy

And youtube

Or school

[echo trench]

great help guys

[fringe dirge]

It might help you to do 18 first, before you do 17 honestly

[spark stag]

can you solve for the side i labelled x here

?

[echo trench]

oh look #s

Uh yeah

So

maybe

[spark stag]

what side of the right triangle do we know

?

[echo trench]

Hypotsafnause

The big side

[spark stag]

yes, hypotenuse

[echo trench]

Ah thakn

[spark stag]

and what side (relative to theta) are we looking for?

[echo trench]

The

adjacent

[spark stag]

right

what trig ratio includes the adjacent and the hypotenuse?

[echo trench]

C

cosine

[spark stag]

yep

[queen python]

Hello there

[spark stag]

so $\cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}$, right

?

[somber coyote]

Namington:

[echo trench]

yos

[queen python]

Am I needed?

[echo trench]

not yet

[spark stag]

and in this case, the adjacent is x, the hypotenuse is l

[queen python]

Ping me if I am

[spark stag]

so

$\cos \theta = \frac{x}{l}$

[somber coyote]

Namington:

[echo trench]

mmmmm

Yesh

[spark stag]

can you solve for x now?

[echo trench]

ahh

[spark stag]

ie, get it by itself

[echo trench]

so to do that

would i have to get rid of denominator

[spark stag]

yes

[echo trench]

so multiply l on both sides

[spark stag]

right

so we get

$x = l \cos \theta$

[somber coyote]

Namington:

[spark stag]

but of course, this side "x" isnt actually what we're looking for

[echo trench]

nope

[spark stag]

we're looking for h

[echo trench]

yesh

[spark stag]

there's a reason i chose x, though

x and h are related

[echo trench]

really?

[echo trench]

ITS HALF

OPSPSP"

[spark stag]

not half

[echo trench]

Oh

[spark stag]

but x + h = l

[echo trench]

ahhhh

OHHHH

[spark stag]

so if we solve that for x

what do we get?

[echo trench]

$x = 1-

cos

theta

[spark stag]

1?

[echo trench]

no

sprru

l

😃

L

aha

[spark stag]

not quite

[echo trench]

doarn

[spark stag]

we have $x + h = l$

[somber coyote]

Namington:

[spark stag]

solve that for x

by itself

ie, get x by itself

[echo trench]

alright

so

$x= l-h

[spark stag]

yes

so we have

[echo trench]

$x = l - h

[spark stag]

$x = l \cos \theta \ x = l - h$

[somber coyote]

Namington:

[spark stag]

since those both equal x, we can just set them equal to each other, right?

$l \cos \theta = l - h$

[somber coyote]

Namington:

[heady juniper]

Help please struggling so hard

[spark stag]

you're interrupting.

so if we have

$l \cos \theta = l - h$

[somber coyote]

Namington:

[spark stag]

can you solve for h?

[echo trench]

da

subtract l from both sdies

[spark stag]

$l \cos \theta - l = -h$

[somber coyote]

Namington:

[echo trench]

but

no negative h

[spark stag]

how do we get rid of the negative

?

[echo trench]

divide?

[spark stag]

by what?

[echo trench]

-1

[spark stag]

sure

[echo trench]

oh

[spark stag]

so doing that flips the sign of each side

$-l \cos \theta + l = h$

[somber coyote]

Namington:

[spark stag]

and there's our equation

though i think it looks cleaner written as $h = l - l \cos \theta$

[somber coyote]

Namington:

[echo trench]

um

it says expression

so do i just sa -lcostheta +l

[spark stag]

then just write the $l - l \cos \theta$ part

[somber coyote]

Namington:

[spark stag]

or yeah, that way

same thing

let's give a brief idea of what this "means"

l is the length of this side

[echo trench]

yesh

[spark stag]

l cos theta, we said, is the length of the adjacent side

the side x

so if we take the entire side

l

and subtract the x

we're left with just the h

which makes sense, looking at the diagram, right?

[echo trench]

oui oui

[spark stag]

and there's your expression for part 17

you can use it to do #18

(or you can go through the full process again, but thats not really necessary)

(we already did it once!)

[echo trench]

(nooooopesies, you always make me understand concepts and you've been there most of the time actually maybe even all teh times i asked for help, your great dudee, thanks Helper Namington)

[heady juniper]

Hey I'm assuming you guys are done

Would you mind helping me a bit?

I'm not sure how to approach this question

I'm setting BC as chord and touches PQ at Z

And trying to prove BZC pi/2

But I'm not sure that's the correct line of reasoning

Please help

@queen python I think you're needed atm

[queen python]

Huh

@heady juniper

[heady juniper]

Would you mind helping with this question?

I'm not sure what condition I need for the circle to touch at PQ

[queen python]

Which one

The first or second

[heady juniper]

They're the same Q

Part a it's telling you to draw a diagram

But I fucked that up

[queen python]

Ok

So

[heady juniper]

Part b is a proof for the situation listed out in the top of a

[queen python]

We know that the center of both circles is B

That means the circles go around it

Wait

No

Nvm

Give me a minute to find the answer

[heady juniper]

Ok

[queen python]

Are you sure you are wrong?

It seems right too me

If you are ping the helpers

This might be above me

[olive solar]

dont ping before 15 minutes please

[queen python]

welp

If that’s what you say

[olive solar]

ill look over it but it's been so many years since ive done any geometry

[queen python]

I still haven’t even taken geo

This looks a bit more advanced than the geo I’ve been doing

I leave it too you

[olive solar]

your diagram is just about fine

for @

*a

your diagaram for b is incorrect though

it's asking for a circle with bc as diameter

meaning that the midpoint of bc is the center

also, since R and r are different lengths, the center of said circle wouldn't be point A

since A cannot be assumed to be the midpoint

[heady juniper]

In that second diagram I tried a different approach

I tried to make it touch

Have the centre to be O

A as point of common tangencency

And prove BZC is 90

Or O as midpoint BC

Yeah I think that ones a lost cause and too confusing over two pages

I have one with a similar concept would you mind helping with that?

[chrome crypt]

can someone help me with this

2sinxcosx = cos2x 0<x<2pi

but the underscore thing under the <

which means 0 can equal x and x can equal 2pi

[upper karma]

do you know any identities for sin 2x

[chrome crypt]

ye uh the 2sinxcosx

[upper karma]

ok

so you're essentially solving sin 2x = cos 2x

[chrome crypt]

on wait i can

simplify that so sin 2x

[upper karma]

yep

[chrome crypt]

oh shit yeah guess s

so

ah fuck lemme see where i can go with this ahaha

[upper karma]

nice

[chrome crypt]

wait no im still stuck go on if u can help me

[upper karma]

do you know any expressions for tan 2x

like what's the simplest one you can think of

[chrome crypt]

2tanx/1-tan^2x

[upper karma]

even simpler

in terms of sin and cos

[chrome crypt]

uhh

oh sin 2x/cos2x

[upper karma]

yeah

[chrome crypt]

oh

ohhhhh

LOL im so fucking stupid thanks

[upper karma]

np

[eager pendant]

@heady juniper hi

[eager pendant]

well i was gonna give a solution but i have to go soon

@heady juniper as a hint, you should be able to prove something is cyclic, concurrent, and then use power of a point

[upper karma]

i need to know how to find the perimeter of an oblique triangle that has only 2 sides given and no angles

[fringe dirge]

That's impossible

[upper karma]

i know right but theres a problem of it then they just guess what the other side is and solved the perimeter lmao

[fringe dirge]

Take a picture of it

Or show us the whole problem

@upper karma

You might just be missing something

[upper karma]

@fringe dirge

[fringe dirge]

Yep you are missing something

The first thing you should notice is that they're not exactly finding the perimeter

They're just choosing which one it could be from the options

The first you should ask yourself is if you understand why c<35

@upper karma

[upper karma]

@fringe dirge ohhh it make sense!!! But why is c<35 is it theory?

Rule ormsomething

I must have missed some rules

[fringe dirge]

It's called the triangle inequality

You understand that the bigger the angle C is, the larger side c will get right?

@upper karma

[upper karma]

Yes but how can u know that c must be lesser than 35

[fringe dirge]

Well think about what happens when the angle C gets really really big

Like closer and closer to 180 degrees

[upper karma]

Both b and d gets smaller

[fringe dirge]

No they don't have to

Oh you mean angles B and D

Yeah that's true

[upper karma]

Yes angles

[fringe dirge]

But think about what the triangle looks like when the angle C is close to 180 degrees

[upper karma]

Almost flat

[fringe dirge]

Right

So how long would the side length c be in that case

[upper karma]

Very long almost b+d?

Ohhhh

[fringe dirge]

Yup

That's the triangle inequality

[upper karma]

Alright ahhaah thanks now i understand its the only problem that bothers me

Are u a math major?

[fringe dirge]

Yup

Also a lot older than you probably

[upper karma]

Ahhh im on my 20s

Anyways thanks !

[fringe dirge]

Yeah no problem

[upper karma]

can someone check if my answer is correct?

[fringe dirge]

Just ask

[upper karma]

ask you?

[fringe dirge]

Ask here

[upper karma]

ah okay

how do i screenshot lol

[mental wharf]

snipping tool

[upper karma]

here we go 😄

im pretty sure im right i just want to clarify

[mental wharf]

yeah

looks right

[upper karma]

alright thx

[upper karma]

I can’t arrive at this answer

[pulsar mica]

I'm so confused can someone explain? The answer is, X = 1/3

[mighty gull]

what have you tried?

@pulsar mica

[pulsar mica]

Well on the problem before I was able to set tan(-1) = 2x-5, and solve for x, but on this one having the x nested in two different places is just throwing me off and idk where to start

[mighty gull]

well generally in these kind of problems, it helps to draw out a diagram

draw a right triangle with an angle such that its sine is sqrt(2x) and its cosine is sqrt(x)

[mental wharf]

you could use sin(arccos(...))

[pulsar mica]

When drawing the triangle, how would I write 2x? I'm used to the fractions where you know where to put the opp/hyp values but am a little thrown off by the single term

[mighty gull]

well let hyp be 1, then the rest of the triangle will follow

(notice this doesnt end up mattering as what matters is the angle not the side lenghts, i.e we could scale the triangle up or down and get the same result)

[pulsar mica]

Thank you so much! Bells are going off in my head now

[mighty gull]

no problem

[coarse mortar]

I need help with algebra 1/2 assignment, PM me if you can help.

[trail minnow]

fam just ask the question @coarse mortar

[stuck torrent]

[mental wharf]

[rigid wharf]

@mental wharf Is it Sigma from overwatch or no?

[mental wharf]

no

[rigid wharf]

Ah

Sorry lol

[upper karma]

lol

This isn't you?

[rigid wharf]

Hes honestly a cool hero lol

Minus the eyebrows

[upper karma]

i can totally see the resemblance b/w sigma overwatch hero and sigma's pfp

[trail minnow]

u rite oxide

they're exactly the same

[trail minnow]

lel

emote material

[gritty siren]

[rigid wharf]

Bruh its so similar how could u miss it

[upper karma]

can someone help me

[digital stirrup]

Hi everyone, I had a question: So, say we have a triangle and we draw out its angle bisectors. Then we connect the points where the angle bisectors meet the opposite sides (the endpoints of the angle bisectors). Connect those endpoints and you get the "incentral" triangle. My question is, are the sides of this incentral triangle perpendicular to the angle bisectors of the original triangle? In this link: http://www.ddekov.eu/e2/htm/01_definitions/02_triangles/02_01_Incentral_Triangle.htm

Is LcC perpendicular to LaLb?

Thanks so much 😃

[coarse bronze]

no pair is perpendicular in a scalene triangle

[digital stirrup]

So the incentral triangle is not always equilateral, right?

Just because I was playing around with the idea, and it seems like the incentral triangle must be equilateral if the angle bisectors are perpendicular to its sides

Ah thanks, I think I understand now actually

[undone mist]

YOOO

is every function that uses sin/cos/tan a rational function

[fringe dirge]

what no

no functions that use sin/cos/tan are rationals functions

[undone mist]

@fringe dirge I'd assume since sine is O/H, cosine is A/H, and tangent is O/A

[rigid wharf]

https://cdn.discordapp.com/attachments/536995777981972491/608116039430963200/chart.png

If m∠ABC = 70°, what is m∠ABD? Justify your reasoning.

A) Using the addition property of equality, 40 + 70 = 110, so m∠ABD = 110°.
B) Using the subtraction property of equality, 70 − 30 = 40, so m∠ABD = 30°.
C) Using the Angle Addition Postulate, 40 + m∠ABD = 70. So, m∠ABD = 30° using the subtraction property of equality.
D) Using the Angle Addition Postulate, 40 + 70 = m∠ABD. So, m∠ABD = 110° using the addition property of equality.
Its either B or C but im a little confused on the wording

Its C, nvm

[obsidian sierra]

jesus christ what is it with this formality on such a simple problem

[rigid wharf]

Ye

Its confusing

[worthy root]

Why not just say angle ABD and angle BDC are adjacent angles because they share a common arm and their uncommon arm lies on the opposite side of common arm and say both angles add to 70 then use those shitty postulate . @rigid wharf

Boi you overthinking on such a basic problem

[queen python]

Hmm

[rigid wharf]

@worthy root it’s cause the wording is there to throw you off, I know math but I always do bad on a test if it is worded like that shit above

[worthy root]

It's not that badly worded tho

[upper karma]

I don’t understand why it is 6cube/9cube

[upper karma]

it's asking you to find the ratio in height from the smaller cube to the bigger cube

why is it h^3

because you are finding the ratio of a 3D object

but honestly i might be wrong because it is a 1D measurement

[silent plank]

ratio of V of similar object = ratio of dimension cubed

[rigid wharf]

@worthy root Whats easy for you is hard for others, I struggle in math but im great in history, science and decent in english

I joined the server to improve my math skills, it is my weakest point and I want to change that

[upper karma]

what's your math level? @rigid wharf

[rigid wharf]

What do you mean level?

@upper karma

[upper karma]

what math are you taking

[mental wharf]

algebra, calc, precalc, trig

etc

[rigid wharf]

geometry

[upper karma]

are you taking that in the fall?

[rigid wharf]

Right now

[upper karma]

oh

through the summer?

[rigid wharf]

Yea

[upper karma]

damn thats tough

[rigid wharf]

Its much harder online cause the tools are stoopid

[upper karma]

geometry almost gave me ptsd

[rigid wharf]

But hey ill be ahead for high school

[upper karma]

algebra 2 was pretty easy for me

[rigid wharf]

I hope I get it for freshman year

[upper karma]

the 1st half of the year was algebra 1

and the 2nd half was new material

[rigid wharf]

Review stuff?

[upper karma]

yea

[rigid wharf]

Ah

[upper karma]

the new material isnt hard at all

and the precalculus for me was a joke

i took it at a college though

[rigid wharf]

Algebra is really eh

Its can be hard if you dont get it right away

But I tend to get it right away

[upper karma]

it was literally the 2nd half of algebra 2 and the professor crammed in trigonometry at the last minute but he was a nice guy and barely gave us any trig

and he gave us free pizza during the quizzes

[rigid wharf]

See, I am really good at history and english

But math

[upper karma]

i love history

[rigid wharf]

I love it too

I love the war and death side anyways

[upper karma]

do you watch oversimplified

[rigid wharf]

Sometimes

[upper karma]

i'm one of his server nitro boosters

[rigid wharf]

Ah

[upper karma]

back on topic

[rigid wharf]

Lol

[upper karma]

when you take calculus, you better be on this server every single day

[rigid wharf]

Lol

I will probably need it

[upper karma]

calculus 1 was challenging for me

[rigid wharf]

Looks hard

[upper karma]

i hear rumors that calculus 2 is even worse

[rigid wharf]

https://cdn.discordapp.com/attachments/326138772477575180/608432681809608721/unknown.png

[upper karma]

thats calculus 2

[rigid wharf]

Idk what im looking at right there

Oh

Actually I think I get it a little

Wait nope

[upper karma]

you're looking at finding the area of the funky shapes formed by 2 lines

[rigid wharf]

Ah

[upper karma]

the funky S is an integral sign

[rigid wharf]

That makes a bit of sense

[upper karma]

think of the S as a representation on a graph as vertical lines that are so close to each other that it fills up all of the space

[rigid wharf]

okkkk

[upper karma]

now what are you working on in geometry?

[rigid wharf]

Just started proofs

[upper karma]

did you prove the crap out of triangles yet?

[rigid wharf]

Kinda

Well

I just started proofs, theres suppose to be a class discussion but its not for awhile and I finished everything up to it

[upper karma]

what textbook

[rigid wharf]

Its not a textbook its like online notes

Hang on lemme get it

It might be a textbook and im just stupid but oh well

oop hang on I got mail

[upper karma]

Hello home

So I’m asking about number 8

I have no idea what kind of transformation “H” would ask me to do

[dark sparrow]

the book has to have introduced the notation somewhere @upper karma

[upper karma]

Turns out we just happened to know it was a half turn

so that’s cool

thanks for the help

[tidal rune]

I need an example of a quadrilateral that has one pair of opposite sides congruent, one pair of opposite angles congruent, and is NOT a parallelogram.

and is a simple quadrilateral

[trail minnow]

thats

by definition a parallelogram

[tidal rune]

[trail minnow]

[tidal rune]

Well apparently it's not.

[trail minnow]

ngl

tell your book to fuck off

[tidal rune]

It's my prof and a homework question that I can't wrap my head around

[trail minnow]

thats because the question is wrong

in euclidean geometry that is by definition a parallelogram

like

having those properties is sufficient to prove a quadrilateral a parallelogram

wait

hmm

ohhh

i see

[tidal rune]

???

[trail minnow]

nvm i was being dumb

hmmmst

[tidal rune]

👀

[trail minnow]

@tidal rune do you have to prove that the shape is not a parallelogram, or demonstrate that a shape exists which is not necessarily a parallelogram

[tidal rune]

I need to show an example of a quad with those properties to prove that those properties are not sufficient to show that the quad is a parallelogram

I think just proving its existence isn't enough. Need an example

[trail minnow]

i mean this shape theoretically isn't one

but this isnt a proof

like

[tidal rune]

Isn't a counterexample a good enough proof? I'm essentially disproving a universal statement alike "For all X, if X is a quadrilateral that has a pair of opposite sides congruent and a pair of opposite angles congruent, then X is a parallelogram."

[trail minnow]

hmmmst

[spark stag]

a counterexample is a good enough disproof, yes

[trail minnow]

i think for this it'd be best to construct a counterexample with a compass

[spark stag]

you just need to show that it's a counterexample

[trail minnow]

ye

which is the hard part : p

[upper karma]

Can I be of help?

[spark stag]

i mean, it's sometimes easy!

consider the statement "all prime numbers are greater than 4", then 3 is fairly easy to verify as a counterexample!

[upper karma]

I'm so hecking done I just need a break

[tidal rune]

Yea I'm pretty sure I need to draw the example to scale with the right lengths and angles for this.

[upper karma]

...by trying to help others with geometry

[trail minnow]

@tidal rune construct it with a compass and straightedge

[tidal rune]

Compass?

[supple abyss]

I could just as well say I have constructed a quadrilateral in which the interior angles don't add up to 2pi

[tidal rune]

Or protractor

[trail minnow]

like this

channel ur inner ancient greek

[tidal rune]

Why that tho? I'm not drawing circles

[trail minnow]

um

you can use a compass to construct any shape

well any shape that can feasibly be drawn anyway

its very easy to create congruent lines and angles with a compass

[tidal rune]

I'm not smart enough for that

[trail minnow]

um

fren

its very simple

like 2 steps

[tidal rune]

🙄

[trail minnow]

https://www.youtube.com/watch?v=KUtwbmx0LV0

[tidal rune]

[trail minnow]

[tidal rune]

I try to draw the counterexample and I keep drawing a parallelogram instead

[dark sparrow]

what are you trying to get a counterexample for again

[tidal rune]

A simple quadrilateral with a pair of opposite sides congruent, a pair of opposite angles congruent, and is not a parallelogram.

[vale bobcat]

how do I solve a special right triangle when there is only 1 side and its on the hypotenuse part of the triangle with all three angles already showing

|
|
| 60° \14
|
|■____\30°

[dark sparrow]

use microsoft paint seriously

[vale bobcat]

im on phone

[dark sparrow]

is this what you mean

[vale bobcat]

yeah

[dark sparrow]

so what's giving you trouble here

[vale bobcat]

the other length of the other sides

[dark sparrow]

i'm not asking you what you're trying to find

i'm asking you what's giving you trouble when it comes to doing that

[vale bobcat]

I forgot what formula it is sin cos or tan

[dark sparrow]

sin, cos and tan aren't "formulas"

they're trig functions. or trig ratios.

anyway

which function to use depends on three things:

• what angle you're using
• what side you know
• what side you're trying to find

as long as you always choose the trig function correctly, different choices for angle and known side will always yield the same value for the unknown side

but like

ok

let's say you want to find the vertical leg of that triangle, as depicted in my photo

you'll need both anyway but we gotta start somewhere

ok?

@vale bobcat

[vale bobcat]

im new to this triangle with only 1 side showing

[dark sparrow]

i'm asking you if you're following and want me to walk you through this y/n