#geometry-and-trigonometry | Mathematics | Page 197

vapid condor Feb 7, 2019, 3:10 PM

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yesssss

winged saddle Feb 7, 2019, 3:10 PM

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ok

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so

vapid condor Feb 7, 2019, 3:10 PM

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1 and 3 is equal to?

winged saddle Feb 7, 2019, 3:10 PM

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1 and 3 is botht he same

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like if 1 is 50 degree

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3 is also 50 degree

vapid condor Feb 7, 2019, 3:11 PM

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Oh okay.

winged saddle Feb 7, 2019, 3:11 PM

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u know y?

vapid condor Feb 7, 2019, 3:11 PM

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y?

winged saddle Feb 7, 2019, 3:11 PM

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ok

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so

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lets say u have a line

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like that i showed u

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ok

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📎 unknown.png

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like this

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is 360 degree right

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and lets say

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there is a line

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that travels through

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📎 unknown.png

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so the lines

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make a point in the middle

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📎 unknown.png

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and that creat 4 angles

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📎 unknown.png

vapid condor Feb 7, 2019, 3:12 PM

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yessa

winged saddle Feb 7, 2019, 3:12 PM

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ok

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remember how

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1+2=180

vapid condor Feb 7, 2019, 3:12 PM

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okayy

winged saddle Feb 7, 2019, 3:12 PM

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and 3+4 also = 180

vapid condor Feb 7, 2019, 3:12 PM

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yess

winged saddle Feb 7, 2019, 3:12 PM

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if u add them togehter

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its still 360

vapid condor Feb 7, 2019, 3:13 PM

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yess

winged saddle Feb 7, 2019, 3:13 PM

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so angle 1 = angle 3

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becuz

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1+3+2+4 = 360

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ok wait

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i need a better to explian

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im bad at explain

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wait wait wait

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ok

vapid condor Feb 7, 2019, 3:14 PM

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okay

winged saddle Feb 7, 2019, 3:14 PM

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im stupid

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vertical angle

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theorem

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bruh

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its just that

vapid condor Feb 7, 2019, 3:14 PM

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no its okay

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yeaa

winged saddle Feb 7, 2019, 3:14 PM

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ok sorry

vapid condor Feb 7, 2019, 3:14 PM

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wait imma pic the actual lecture

winged saddle Feb 7, 2019, 3:14 PM

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i think its just one of those thing in math like 1+1=2 its just defined like that u cant change it

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like natural

vapid condor Feb 7, 2019, 3:15 PM

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📎 20190207_231551.jpg

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There are statements and reasons and i need to prove something

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based on the given and illustration

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📎 unknown.png

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Btw thank you it really helpedd me alott

winged saddle Feb 7, 2019, 3:29 PM

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oh ok

rustic cairn Feb 7, 2019, 3:45 PM

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How do i solve this

📎 image0.jpg

buoyant oasis Feb 7, 2019, 3:48 PM

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You wanna find all the inside angles of the triangle, then you can find "?"

rustic cairn Feb 7, 2019, 3:50 PM

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Yes how do i find the angles inside

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The triangle

buoyant oasis Feb 7, 2019, 3:52 PM

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📎 Screen_Shot_2019-02-07_at_22.51.47.png

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Find e and d
Find c
Find b
Find a
Find (?)

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Things to remember : supplementary angles, vertically opposite angles, and angles in a triangle.

winged saddle Feb 7, 2019, 4:02 PM

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d is 30

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e is 25

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c is 125

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b is also 125

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a is 30

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so ? is 150

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@rustic cairn

rustic cairn Feb 7, 2019, 4:04 PM

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Thank you

upper karma Feb 7, 2019, 4:07 PM

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No clue how to do today's math problem from my calendar. It goes:

The smallest n such that a regular n-gon cannot be constructed with a straightedge and compass.

umbral snow Feb 7, 2019, 4:08 PM

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I don't know how you'd find that with a pencil and paper, lol

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Galois theory covers this idea, and shows which n-gons aren't constructible with algebra

slim needle Feb 7, 2019, 4:17 PM

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How would I find D. My latest step was to find slope MB

📎 IMG_20190207_124038.jpg

slim needle Feb 7, 2019, 4:36 PM

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Ok the book was wrong. It says D (2;6) but it is D (2;8)

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Can you verify?

tranquil wigeon Feb 7, 2019, 6:01 PM

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It's (2,8)

slim needle Feb 7, 2019, 6:37 PM

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Yes I supposed that

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I was on this all the day

little thistle Feb 7, 2019, 9:00 PM

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👀

bleak sedge Feb 7, 2019, 9:01 PM

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there we go

little thistle Feb 7, 2019, 9:01 PM

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Seems fine

bleak sedge Feb 7, 2019, 9:01 PM

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well atleast it works now Thanks 😄

little thistle Feb 7, 2019, 9:02 PM

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Cool, tag me if any issue comes up

bleak sedge Feb 7, 2019, 9:02 PM

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Okidoki 😄

little thistle Feb 7, 2019, 9:02 PM

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Also, you might get your question answered sooner in #❓how-to-get-help

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rather than here

bleak sedge Feb 7, 2019, 9:02 PM

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oO ook ill delete the question here and go over there

little thistle Feb 7, 2019, 9:02 PM

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Good luck 🍻

bleak sedge Feb 7, 2019, 9:02 PM

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😄

zinc grail Feb 8, 2019, 1:44 AM

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https://cdn.discordapp.com/attachments/326138737606262786/543244848644227072/unknown.png

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hello

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how would I go about solving this

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the hypot is 2

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so idk

gloomy python Feb 8, 2019, 1:59 AM

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Can someone help with a proof

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📎 Snapchat-1190472708.jpg

gloomy python Feb 8, 2019, 2:15 AM

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<@&286206848099549185>

jovial sierra Feb 8, 2019, 2:17 AM

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oh nice, this is fun

raven relic Feb 8, 2019, 2:17 AM

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Try

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Law of Sines

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would be my guess

gloomy python Feb 8, 2019, 2:17 AM

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What's that lol

raven relic Feb 8, 2019, 2:17 AM

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Sin[a]/A=sin[b]/B

gloomy python Feb 8, 2019, 2:18 AM

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Uhh

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Can somone explain this problem step by step lmal

jovial sierra Feb 8, 2019, 2:20 AM

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yeah, was helping someone else

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okay, so you see how AEB is a triangle, and angle E is bigger than angle A

gloomy python Feb 8, 2019, 2:20 AM

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Yea

jovial sierra Feb 8, 2019, 2:20 AM

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that tells you that the segment AB is longer than the segment EB

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you should have that as a theorem in your book

gloomy python Feb 8, 2019, 2:21 AM

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Whats a theorem again

jovial sierra Feb 8, 2019, 2:25 AM

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a theorem is a thing you have proved

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a fact you can use in this proof

gloomy python Feb 8, 2019, 2:27 AM

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I see

jovial sierra Feb 8, 2019, 2:29 AM

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you only need that fact to prove this proposition -- you might want to look at the recent things you studied in the book to find that fact

gloomy python Feb 8, 2019, 2:29 AM

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The thing is i don't have a book

raven relic Feb 8, 2019, 2:35 AM

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...

gloomy python Feb 8, 2019, 2:35 AM

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It's in my locker

raven relic Feb 8, 2019, 2:35 AM

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I feel like you're messing with him

gloomy python Feb 8, 2019, 2:35 AM

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???

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I need help with this problem

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I'll leave after if you'd like

raven relic Feb 8, 2019, 2:37 AM

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what no

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He gave a pretty good answer

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I mean the bigger the angle the bigger the line

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This is something that makes intuitive sense if you have to prove it, you can look it up online

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I'd just use law of sines if you've learned that

gloomy python Feb 8, 2019, 2:38 AM

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I haven't

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What is it?

raven relic Feb 8, 2019, 2:39 AM

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https://www.ck12.org/geometry/Comparing-Angles-and-Sides-in-Triangles/lesson/Comparing-Angles-and-Sides-in-Triangles-GEOM/

Comparing Angles and Sides in Triangles

This concept teaches students the relationship between opposite angles and sides in triangles and how to use this relationship to compare triangles.

zinc grail Feb 8, 2019, 2:50 AM

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📎 unknown.png

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so I somehow got this right

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but im not sure how to prove that (x+x)/2

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would be the midpoint of h

jovial sierra Feb 8, 2019, 2:55 AM

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i'm not sure what you mean by x or h, since h is the x-coordinate of the center of the circle

zinc grail Feb 8, 2019, 2:56 AM

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I meant the

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4 and 20

jovial sierra Feb 8, 2019, 2:56 AM

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for this problem, you should draw the triangle

zinc grail Feb 8, 2019, 2:56 AM

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I figured out how to solve it

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but how do I know exactly

jovial sierra Feb 8, 2019, 2:57 AM

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so the triangle is isosceles, right, since both the legs are the radius of the circle

zinc grail Feb 8, 2019, 2:57 AM

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that h is the middle of (4,0) and (20,0)

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hm?

jovial sierra Feb 8, 2019, 2:57 AM

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an isosceles triangle is really just two right triangles put together which are congruent

valid pike Feb 8, 2019, 2:58 AM

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Can anyone help me with a geometry challenge problem?

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📎 IMG_20190207_215442.jpg

jovial sierra Feb 8, 2019, 3:00 AM

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there are two triangles

valid pike Feb 8, 2019, 3:00 AM

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Yes

jovial sierra Feb 8, 2019, 3:00 AM

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their bottom legs are the same length

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they are both right triangles

valid pike Feb 8, 2019, 3:04 AM

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Well ok then

jovial sierra Feb 8, 2019, 3:07 AM

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you may not be looking at the right triangles

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i don't want to give you too many hints since this is a challenge problem

valid pike Feb 8, 2019, 3:09 AM

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Ohh ok I get what your doing

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I'll look at it again

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Still no clue

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Do I need a proportion

jovial sierra Feb 8, 2019, 3:32 AM

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i'd just try to find as many lengths and angles as i could

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and eventually find out the altitude of the triangle you outlined

golden nymph Feb 8, 2019, 5:35 AM

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Is this correct? Isn't the ratio tan(30)? How is he getting 1/sqrt(3)?

📎 unknown.png

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Oh I see... same ratio

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My brain is permanently poisoned by the unit circle

hexed birch Feb 8, 2019, 4:44 PM

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Remember, to show that two polygons are similar, the angles need to be the same and the sides have to be proportional

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Since you're working with rectangles, all the angles are guaranteed to be the same

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So you'd just have to check the ratios to show that the triangles are similar

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So say for the first one, you'd check which of the ratios 5:7, 8.5:11, and 10:14 equal each other

royal coral Feb 8, 2019, 5:21 PM

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So uh im new to this type of high schools im from venezuela and uh i dont understand alot this

📎 JPEG_20190208_093309.jpg

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Its also my first day so yeah i would like some help I'll still grab a book from the library and take it home with me to study

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An explanation works too

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Im in gym rn so I'll be out around 2:30pm

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Also i never learned this in my high school in venezuela, what im showing here its just something new ive seen in life.

hallow smelt Feb 8, 2019, 6:56 PM

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https://imgur.com/a/BkqTL1I

Imgur

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https://imgur.com/ARLr76P

Imgur

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I can see that sin is just getting shift up, but i don't know how explain it numerically

compact yew Feb 8, 2019, 8:57 PM

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I have a more general question. I hope I am not violating any server rules due to its generality but I was wondering what you guys find the best way to create geometry intuition. I am having a hard time visualizing and remembering graphs in my head of simple equations which I think are key to having intuition on more complex equations. While I found algebra to be some sort of a logic puzzle, geometry has always been one of my problematic fields of maths.

twin ingot Feb 8, 2019, 10:11 PM

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I think trig is the least enjoyable class I have ever taken

twin ingot Feb 8, 2019, 10:38 PM

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Is there anything to make learning trig identities easier, mnemonics etc?

glad ocean Feb 8, 2019, 10:49 PM

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hmm not sure about identities although you can use unit circles to solve for a few of them if that helps

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If ur talking about the 3 main trig functions do:

SOHCAHTOA

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Sine
Opposite (divided by)
Hypotenuse

Cosine
Adjacent (divided by)
Hypotenuse

Tangent
Opposite (divided by)
Adjacent

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in which:

opposite is the side opposite to, let's say, angle x

adjacent is the non-hypotenuse side that touches angle x

Hypotenuse is the side opposite the right angle

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@twin ingot ^

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by divided by I mean the length of the numerator (side) over the length of the denominator (side)

twin ingot Feb 8, 2019, 10:54 PM

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@glad ocean those ones Ive got these other ones there are 25 of them

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like (A+B) = cos(A)cos(B)-sin(A)sin(B)

glad ocean Feb 8, 2019, 10:58 PM

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oh

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Yeah I guess it's just a matter of memorization often

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honestly lots of students just get homework to memorize that ruins the point of learning

twin ingot Feb 8, 2019, 10:58 PM

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and it certainly doesn't make me enjoy math more

glad ocean Feb 8, 2019, 10:59 PM

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mood

twin ingot Feb 8, 2019, 10:59 PM

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this is also a half semester course so we just saw them today and I have to memorize them over the weekend

glad ocean Feb 8, 2019, 11:00 PM

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rip

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just no life

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start with memorizing one of them

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And do two at a tine

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time

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Then three at a time

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don't proceed until you've done it perfectly

twin ingot Feb 8, 2019, 11:01 PM

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well to make it worst we havent actually learned what we are even doing with them so I can't even apply them to anything

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we get to use them monday and wednesday and test friday, I guess I will get to see what its like to try and eat an elephant

umbral snow Feb 8, 2019, 11:02 PM

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sin conserves the sign

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cos conserves the grouping

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sin(a + b) = sin(a)cos(b) + cos(a)sin(b)

twin ingot Feb 8, 2019, 11:03 PM

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for the difference identities I see what you are saying

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thanks

umbral snow Feb 8, 2019, 11:04 PM

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cos(a + b) = cos(a)cos(b) - sin(a)sin(b)

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Any other ones you having trouble with?

twin ingot Feb 8, 2019, 11:05 PM

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its just a lot Im overrun

umbral snow Feb 8, 2019, 11:06 PM

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Needless to say sin doesn't conserve the grouping
cos doesn't conserve the sign

twin ingot Feb 8, 2019, 11:06 PM

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thanks that did help

umbral snow Feb 8, 2019, 11:07 PM

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Do you have to know tan²(x) + 1 = sec²(x)

twin ingot Feb 8, 2019, 11:08 PM

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I have to learn pythagorean , negative angle, difference of sin,cos, tan, double angle, half angle, and tangent half angle identities

umbral snow Feb 8, 2019, 11:09 PM

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You can get the double angle equations easily with the sum/difference equations

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cos(2x)
= cos(x + x)
conserve grouping, not sign
= cos(x)cos(x) - sin(x)sin(x)
= cos²(x) - sin²(x)

twin ingot Feb 8, 2019, 11:10 PM

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interesting I see

umbral snow Feb 8, 2019, 11:12 PM

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sin²(x) + cos²(x) = 1²
Is just Pythagorean theorem on a unit circle

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Dats ez

twin ingot Feb 8, 2019, 11:13 PM

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haha I wish the rest of trig was that easy

hallow smelt Feb 8, 2019, 11:57 PM

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what is the proper notation for the domain of Tangent, CoSecant and Secant?

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I know tangent of theta can take on any value except for multiples of pie/2

timber hinge Feb 9, 2019, 12:25 AM

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1^2 👁

glad ocean Feb 9, 2019, 12:46 AM

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@twin ingot

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https://en.m.wikipedia.org/wiki/List_of_trigonometric_identities

List of trigonometric identities

In mathematics, trigonometric identities are equalities that involve trigonometric functions and are true for every value of the occurring variables where both sides of the equality are defined. Geometrically, these are identities involving certain functions of one or more an...

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do you legit have to memorize all that (not the image, go to the link)

atomic gull Feb 9, 2019, 1:07 AM

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hey guys i need help on my homework

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how am i going to solve this without a graphing calculator

📎 Screen_Shot_2019-02-08_at_7.07.37_PM.png

hallow smelt Feb 9, 2019, 1:19 AM

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its cot

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the domain of tangent is all real numbers except for odd increments of pie/2

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but i think co tangent is all real numbers except for increments of pie

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anyone confirm?

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@glad ocean You only have to memorze 2 pie/4 (root 2 over 2, root 2 over 2) and pie/6 (root 3 over 2, 1 over 2)

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@glad ocean The rest of the radians are all reflections of those or in the inverse (pie / 3 is the inverse of pie /6) so (1/2, root3/2)

atomic gull Feb 9, 2019, 1:23 AM

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you mean the 45 degrees (cos,sin)?

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root 2 over 2

hallow smelt Feb 9, 2019, 1:24 AM

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45 degrress = pie/4

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pie/4 is radians 45 is degrees

atomic gull Feb 9, 2019, 1:24 AM

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i really hate to solve this one without a calculator.
i can't remember the steps, period, amp

hallow smelt Feb 9, 2019, 1:24 AM

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you only need to remember 2 of them

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pie/4 and pie/6

atomic gull Feb 9, 2019, 1:25 AM

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i don't get one thing at all. same to cos and sin.
this is tan and cot

📎 Screen_Shot_2019-02-08_at_7.24.43_PM.png

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i fail precalc class, gg

hallow smelt Feb 9, 2019, 1:25 AM

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do you know the formula and what the parts of the formula correspond to?

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like do you know what B means and C and K etc.

atomic gull Feb 9, 2019, 1:26 AM

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yeah but i don't have the memory to remember all this

hallow smelt Feb 9, 2019, 1:27 AM

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y=aSink(x-b) you know each part does to the graph?

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you're using tan so swap out sin for tan

atomic gull Feb 9, 2019, 1:28 AM

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well yeah. i don't even get all this useless trig

hallow smelt Feb 9, 2019, 1:28 AM

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trig is the most important math

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you use it for everything

atomic gull Feb 9, 2019, 1:29 AM

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and even i barely have a hard time doing the trash unit circle

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tru that. i only want to be bridge designer

hallow smelt Feb 9, 2019, 1:29 AM

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LOL

atomic gull Feb 9, 2019, 1:29 AM

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and the graph here is useless craps for me

hallow smelt Feb 9, 2019, 1:29 AM

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i only want to be a bridge designer

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you need to learn trig

atomic gull Feb 9, 2019, 1:29 AM

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POE is the only class i enjoy

hallow smelt Feb 9, 2019, 1:29 AM

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before you kill us

atomic gull Feb 9, 2019, 1:30 AM

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maybe i won't tbh. i don't have any interests

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maybe not bridge designing

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but now im currently designing the game with my friend.
fuck school

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i want to drop out

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smh

hallow smelt Feb 9, 2019, 1:31 AM

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im not an expert in trig im just barely taking it. 2 Weeks in

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but chegg has helped a shit ton

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chegg is god

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you should use it

atomic gull Feb 9, 2019, 1:32 AM

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i don't have a debit/credit card

hallow smelt Feb 9, 2019, 1:32 AM

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oh dam

atomic gull Feb 9, 2019, 1:32 AM

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not everything is free

hallow smelt Feb 9, 2019, 1:32 AM

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well that sucks

atomic gull Feb 9, 2019, 1:35 AM

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but yeah bridge designing is not an interest for me anymore

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idk man. im not that interest into school or choosing a career

glad falcon Feb 9, 2019, 1:51 AM

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📎 unknown.png

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I have solved the first bit.

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I need help with the equation of the horizontal bisector

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What does that mean

tranquil wigeon Feb 9, 2019, 2:58 AM

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Since the bisector is horizontal it should not have any slope, so it should only intersect the point of intersection between the two lines.The bisector will then divide the two lines in two parts to give them the same length when dropping a pependicular to the bisector line. @glad falcon

twin ingot Feb 9, 2019, 3:19 AM

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@glad ocean there are 23 I have to memorize

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that wiki may as well be latin or hangul

glad ocean Feb 9, 2019, 3:35 AM

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^

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i love how people are like "omg wikipedia isnt trustworthy assasfdaafsd!1!!1" when the actual concern is

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how unnecessarily flawed their syntax is

mighty kayak Feb 9, 2019, 4:10 AM

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Hey guys, first time here.

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I have a serious question

plucky marlin Feb 9, 2019, 4:10 AM

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is it about pi = e = 3

mighty kayak Feb 9, 2019, 4:11 AM

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It will be very basic, but I need help to "prove" why this parallelogram is indeed right angles across the board

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📎 unknown.png

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I've been out of geo-trig for a long time, but my friend, who is trying to pass an exam for work, struggled with this question for 2-3 hours.

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I asked him to link it to me and I was able to arrive at the answer for the last question, area CDE

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with his help with formulas... of course...

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Anyway, he said I "assumed" that corner D was a right angle... we had a giant debate and eventually it ended with "if you can prove why you KNOW all corners are right angles, I'll believe you"

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I don't care about being right or wrong, I truly want to help him realize why and prove they are right angles, given the information on the screenshot. He is upset, I think, because he didn't arrive at this answer and I glanced at it. Lets ignore feelings and arguments and focus on "how can I truly help him pass this test" -- How do I, mathematically, prove these are right angles, without "assuming?"

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I would really appreciate any help. I apologize for the wall of text, but I had to google math discords, wait 10 minutes to post and here I am... I just want to help my friend pass his test. Thank you 😃

nimble lynx Feb 9, 2019, 4:24 AM

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its just a regular n-gon with n = 4

plucky marlin Feb 9, 2019, 4:24 AM

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https://prnt.sc/minv77

Lightshot

Screenshot

Captured with Lightshot

nimble lynx Feb 9, 2019, 4:24 AM

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o

plucky marlin Feb 9, 2019, 4:24 AM

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it's rectangular shape

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so opposite angles are equal ?

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kongouDerp

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@mighty kayak

mighty kayak Feb 9, 2019, 4:25 AM

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Right

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I arrived at that answer too

plucky marlin Feb 9, 2019, 4:25 AM

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so what's the problem then ?

mighty kayak Feb 9, 2019, 4:25 AM

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Is there anyway to prove this without looking at the world "rectangle" in the problem?

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He is saying that I can't prove it without the word problem.

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I disagree

plucky marlin Feb 9, 2019, 4:26 AM

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u can try to show pythagorean theorem hold for the triangle

mighty kayak Feb 9, 2019, 4:26 AM

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I did that

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without his help on the formulas

plucky marlin Feb 9, 2019, 4:26 AM

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does it hold ?

mighty kayak Feb 9, 2019, 4:26 AM

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Well sort of, right?

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I was able to do p.theorm on the A to C triangle

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BUT that doesn't subtract the E to A length

plucky marlin Feb 9, 2019, 4:31 AM

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A to C triangle ?

mighty kayak Feb 9, 2019, 4:31 AM

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Right angle --> A ---> C

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the box is split in half down the middle, diagonally

glad falcon Feb 9, 2019, 7:57 AM

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Question:

📎 IMG_20190209_205141.jpg

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I tried solving it

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📎 IMG_20190209_205126.jpg

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But leads me to p sqaured -2p

plucky marlin Feb 9, 2019, 8:08 AM

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factor out a p

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p(p - 2) = 0

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now use null factor law

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@glad falcon

glad falcon Feb 9, 2019, 8:09 AM

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Ohh yes. I am Soo brainded

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Thank you ma man

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😀😀😀😁

plucky marlin Feb 9, 2019, 8:09 AM

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GWnanaPepoHype

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anytime fren

glad falcon Feb 9, 2019, 8:11 AM

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Ok. I need some help understanding this @plucky marlin

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📎 unknown.png

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I get everything and all.

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but the thing that i dont understand is that why is it always TAN ?

fleet wolf Feb 9, 2019, 8:19 AM

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remember sohcahtoa?

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tan is opposite over adjacent

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what the rise? thats the opposite side and what’s the run? well thats the adjacent side

glad falcon Feb 9, 2019, 8:39 AM

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Oh. ya true. Never thought of that. Thanks !

tranquil wigeon Feb 9, 2019, 8:43 AM

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@glad falcon my man Cymath 👍

wind trail Feb 9, 2019, 8:45 AM

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hi.

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ghosthug

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I want to learn Trig, which book should I buy

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think_down

glad falcon Feb 9, 2019, 9:11 AM

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@tranquil wigeon Ye bud ! I gotchya. 👋 😎

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@wind trail There are pretty good ones here https://www.amazon.com/Trigonometry-Mathematics-Science-Books/b?ie=UTF8&node=13991

Amazon.com: Trigonometry - Mathematics: Books

Online shopping for Trigonometry - Mathematics from a great selection at Books Store.

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Books are not the only resources to learn trig. There are many great VIDS online that are very helpful.

tranquil wigeon Feb 9, 2019, 9:27 AM

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Khan academy is all you need

winged saddle Feb 9, 2019, 1:17 PM

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lol ikr khan academy=god

lyric gorge Feb 9, 2019, 1:30 PM

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god?

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naaah

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its not even good

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not even once

winged saddle Feb 9, 2019, 1:44 PM

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wdym

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@lyric gorge

lyric gorge Feb 9, 2019, 1:44 PM

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I never learned anything out of khan academy

winged saddle Feb 9, 2019, 1:44 PM

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oK wEll i sTarT3d LeanrNIng ALgnegra 1 this summer and now i finished algebra 2 USING KHAN ACADMEY AFJ;ADSLFJDSKLFJ

lyric gorge Feb 9, 2019, 1:45 PM

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gordon would be proud of u

steady sleet Feb 9, 2019, 1:45 PM

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could we not

winged saddle Feb 9, 2019, 1:45 PM

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if u cant learn from khan academy doesnt mean hes bad at traeching boi

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ok

vital frost Feb 9, 2019, 1:57 PM

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how to you find an apothem?

glad ocean Feb 9, 2019, 2:55 PM

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Um Khan academy is useful excuse me?

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It's just for review questions for, let's say, an exam

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That you would want something else

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Cause Khan academy doesn't give that many questions

past siren Feb 9, 2019, 4:14 PM

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📎 image.jpg

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Could anyone tell me the difference between cos and sin graph? Got this question wrong because of this 😭

glad ocean Feb 9, 2019, 4:20 PM

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!graph

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,graph sin(x), cos(x)

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,help

somber coyoteBOT Feb 9, 2019, 4:21 PM

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A brief description and guide on how to use me was sent to your DMs! Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

glad ocean Feb 9, 2019, 4:21 PM

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@past siren

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https://www.desmos.com/calculator/excenis4e4

Desmos Graphing Calculator

sinx, cosx

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sin(x) or the red line is increasing at x = 0, and cos(x) of the blue line is decreasing at x = 0

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Also @past siren did you have a graphing calculator?

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that may have helped

past siren Feb 9, 2019, 5:03 PM

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@glad ocean I do

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Not very familiar on plugging them in though. Trying to self learn trig

glad ocean Feb 9, 2019, 5:19 PM

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ah

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ok I'll figure out how to do it later but remember

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If you don't know how to do it, just use a calculator

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a graphing calculator

wind trail Feb 9, 2019, 5:25 PM

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@glad falcon tinktonk thank you.

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wait. those are normal books

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normal books 🤢

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🤢 💩 😩 🤢 💩 normal books

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for normies 😫

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Im a visual learner. I need all the flashy stuff tinktonk

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Im gonna look at Khan ty

opaque folio Feb 9, 2019, 5:45 PM

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Hey folks...

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so I'm a graphic designer...got me some equations I barely understand that deal with hypertrachoids...

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I understand them..barely..but yeah...plug them in, I get the pretty circle pattern I want....

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but then someone says, if you apply those same equations but in polar coordinates, you get them on a straight line...

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https://tex.stackexchange.com/questions/46507/recreating-a-guilloche-with-tikz

TeX - LaTeX Stack Exchange

Recreating a guilloche with TikZ

One of my last questions talked about certificates and I got great answers. Now my questions is, can one recreate a guilloche in TikZ like the one shown below:

or may be a border like

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now, I remember vaguely that polar coordinates is just plotting the cartesian coordinates that would give me teh circle, but instead of x,y, we're giving it in terms of radians & angles...

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I think...

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where am I best starting out trying to brush up on my maths here...

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(probably not articuting this very well)

glad ocean Feb 9, 2019, 6:21 PM

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thats trig?

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im scared now

opaque folio Feb 9, 2019, 6:51 PM

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how you think I feel? I'm 35. Hacen't done any real maths since i was 16

timber hinge Feb 9, 2019, 7:40 PM

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thonkzoom

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Polar coordinates are (r,theta)

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where r is the length of the line, and theta is the angle to the positive x-axis

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polar coords are typically not taught alongside trig

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Khan Academy probably has the basics you want @opaque folio but hypertrachoids are probably something you'll need to dig around for explicitly, I found a formula but its pretty darn ugly even in polar form

opaque folio Feb 9, 2019, 7:43 PM

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thanks...I've just about gotten to grips with the formula in cartesian form...

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(I have a script open in adobe illustrator that draws it for me)

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but transposing it to a polar form eludes me presently...

timber hinge Feb 9, 2019, 7:45 PM

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x = r cos(theta), and y = r sin(theta)

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then a lot of

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fiddling

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to see if it simplifies nicely

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Some stuff gets really nice in polar form

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Other stuff 🤢

opaque folio Feb 9, 2019, 7:46 PM

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well this is for guilloches;

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they look very pretty, hence my interest...I know that they turn from a rosette to, well, basically a sin wave when expressed in polar

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I've literally just worked out how the script (written by someone else) us using the actual equation...

timber hinge Feb 9, 2019, 7:49 PM

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Don't most programmers just hijack other peoples code lmfao

opaque folio Feb 9, 2019, 7:54 PM

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i certainly do lol

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I'm not really a programmer...I'm a designer, but there is literally nothing on the market that does what I'm wanting that costs less than $1000

glad falcon Feb 9, 2019, 8:33 PM

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@opaque folio I can code for ya. For free

timber hinge Feb 9, 2019, 8:44 PM

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yea software is pricey, esp specialist stuff

hallow smelt Feb 9, 2019, 8:48 PM

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-2+cos(4pix) https://www.desmos.com/calculator/3mqdzddv6o

Desmos Graphing Calculator

Desmos graph

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can someone explain how I interpret what is happening to the amplitude? I know cos should normally be at 1 and the way i want to read this is its 1 shifted up 2 and reflected down, but thats not whats happening

timber hinge Feb 9, 2019, 8:50 PM

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Amplitude is unchanged for this graph

hallow smelt Feb 9, 2019, 8:52 PM

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oh man

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you are right so its just 1 -1-1

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hahaa

timber hinge Feb 9, 2019, 8:52 PM

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fishthonk

hallow smelt Feb 9, 2019, 9:35 PM

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in the Function F(x)= -4 Sin 2 ( X + Pi/2)

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do i distribute the 2 into the X and Pi/2 ?

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so it becomes 0 < 2X < 2(Pi/2)

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wait nvm 0 < (2X+ Pi) < 2Pi

dire rampart Feb 9, 2019, 9:48 PM

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first one

hallow smelt Feb 9, 2019, 9:55 PM

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its the last one i posted

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cause look here https://www.desmos.com/calculator/dwu2i16kme

Desmos Graphing Calculator

Desmos graph

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0 < (2x + Pi) < 2Pi you subtract pi from all 3 sides -Pi < 2X < Pi then divide everything by 2 and -Pi/2 < X < Pi/2

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given -Pi/2 < X < Pi/2 the Period should be Pi and the spacing should be every Pie/4

upper karma Feb 9, 2019, 10:41 PM

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https://cdn.discordapp.com/attachments/507991872942374922/543256941741342730/unknown.png

finite river Feb 9, 2019, 10:41 PM

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@upper karma use the cosine rule after working out the angle A

hard gale Feb 9, 2019, 10:41 PM

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~~or pythagoras twice~~

upper karma Feb 9, 2019, 10:41 PM

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How would I work out |AC| though?

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This problem is melting my brain lol, I suck at math

zealous kiln Feb 9, 2019, 10:54 PM

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I guess these guys don’t answer very simple problems

upper karma Feb 9, 2019, 10:58 PM

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📎 Screenshot_20190209-225812.png

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Is this the correct answer?

hard gale Feb 9, 2019, 11:07 PM

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,calc sqrt(63)/2

somber coyoteBOT Feb 9, 2019, 11:07 PM

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Result:

3.9686269665969

hard gale Feb 9, 2019, 11:07 PM

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so you get 27-ish ?

upper karma Feb 9, 2019, 11:10 PM

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Was that the correct answer?

hard gale Feb 9, 2019, 11:10 PM

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i get sqrt(63)/2

upper karma Feb 9, 2019, 11:10 PM

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I did not write that. My older cousin attempted it. Could you help me formulate solid proof of a correct answer?

hard gale Feb 9, 2019, 11:12 PM

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so if you apply pythagoras in BCD you get BC²+CD² = 7²

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in ACD you get AC²+CD² = 8², or (BC+3)²+CD²=8²

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two equations

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two unknowns

upper karma Feb 9, 2019, 11:13 PM

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Hmm

hard gale Feb 9, 2019, 11:14 PM

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(and the area of BCD is just BC*CD/2)

lament bay Feb 10, 2019, 12:28 AM

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📎 image0.jpg

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I know a and b but not really sure about the rest

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<@&286206848099549185>

opaque folio Feb 10, 2019, 2:18 AM

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@glad falcon very kind, and i'd take you up on that, but then I wouldn't have learned...

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tho I may ping you for tips/advice

glad falcon Feb 10, 2019, 2:51 AM

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@opaque folio no worries

timber hinge Feb 10, 2019, 2:52 AM

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👁

glad falcon Feb 10, 2019, 2:52 AM

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Aight socthis question is pretty easy but I don't know how to approach this

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📎 Screenshot_2019-02-10-15-46-05.png

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Like it could be ab the CD at the bottom

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Or ac and the bd at the bottom

astral hornet Feb 10, 2019, 2:56 AM

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well, for a parallelogram, do diagonals bisect?

opaque folio Feb 10, 2019, 3:02 AM

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@glad falcon I've almost got the code doing what I want now...I have a hypertrachoid and a epitrochoid...

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now it's just putting in repetition steps and working out whether I want to write a plugin for Adobe Illustrator in C++ which I don't know very well, or an extension in JavaScript...which I also don't know very well lol

glad falcon Feb 10, 2019, 3:06 AM

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@opaque folio sorry ma dude I can't help rn. I am on Android and my laptops gone to the manufacturer department

opaque folio Feb 10, 2019, 3:06 AM

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📎 Screen_Shot_2019-02-10_at_03.05.52.png

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hah, no, it's cool man. thanks..

glad falcon Feb 10, 2019, 3:07 AM

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Beautiful

opaque folio Feb 10, 2019, 3:07 AM

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only help I need now is advice from seasoned Adobe plugin folks as to which route I should take

tranquil wigeon Feb 10, 2019, 3:07 AM

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@opaque folio what are you trying to achieve?

opaque folio Feb 10, 2019, 3:07 AM

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I'm trying to build a guilloche generator inside Adobe Illustrator (I'm a graphic designer)

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there's only one plugin suite to do them, and it's only sold ot governments/large design studios, for tens of thousands....there are 3 external programs that do it, but the cheapest is $500, and all 3 are shite and only run on windows, and 2 are now completely unsuported

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guilloches are essentially repeated curve forms

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eg the one on the left above there I just did...it's manually repeated cos I haven't coded repetition in yet...

tranquil wigeon Feb 10, 2019, 3:10 AM

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what language are you using?

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or software?

opaque folio Feb 10, 2019, 3:11 AM

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Javascript running in Adobe Illustrator's script function

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I have a JS script someone else wrote that did a simple guilloche, but only one, with limited paramters etc, and I'm slowly editing/building on it

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but I am unsure if I should abandon JS and go for a full-on C++ plugin, for better IO

zealous kiln Feb 10, 2019, 3:18 AM

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Idk my English not too good can someone vaguely explain what is going on in this question cause i find it wierd and something missing

📎 image0.jpg

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It’s the last slab on the page

upper karma Feb 10, 2019, 3:26 AM

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the one about desert tank?

zealous kiln Feb 10, 2019, 3:26 AM

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Yeah

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I’m finding it hard to follow what they are saying...due north due east? Idk

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Don’t need it solved just need vague guide on what they are directing me to draw

upper karma Feb 10, 2019, 3:29 AM

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hold on im trying to draw it!

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im not that good at math but ill try and see if i can help

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here you go! @zealous kiln

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https://i.imgur.com/QLlQKja.png

Imgur

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so basically, it says "13.5km from A to B"

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so i first started with a point A

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then a point B

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I drew a line, 13.5km

zealous kiln Feb 10, 2019, 3:33 AM

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Ooo....tht means I just did east as west wtf!??!!!

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Bruh I mistook west as east

upper karma Feb 10, 2019, 3:33 AM

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Then it says, 42 degrees, "True Bearing"

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lolll

zealous kiln Feb 10, 2019, 3:33 AM

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Oh my god I need sleep

upper karma Feb 10, 2019, 3:33 AM

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you know what true bearing is right?

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i pretty much jsut googled all this and drew it

zealous kiln Feb 10, 2019, 3:33 AM

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Ok thnx for making me remember directions of a compass lol

upper karma Feb 10, 2019, 3:33 AM

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okay no problem

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and because it asks for "due east"

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im assuming directly east of where it was originall on A

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is what you have to calculate for from Point B!

zealous kiln Feb 10, 2019, 3:34 AM

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I made a huge mistake omg yeah thnx u actually cleared a lot of space in my head now

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Ok so due east ok I get it

upper karma Feb 10, 2019, 3:34 AM

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no problem!

zealous kiln Feb 10, 2019, 3:34 AM

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There was but now I guess there is “no problem “

tranquil wigeon Feb 10, 2019, 3:35 AM

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@opaque folio what parameters do you have on your epitrochoid?

opaque folio Feb 10, 2019, 3:36 AM

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erm...

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hypertrachoid at the moment

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tho I think I drew an epitrochoid by accident by making the radius of the secondary circle negative

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it's in the javascript...

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but essentially i'm drawing by using a for loop to iterate theta by a small amount

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changing all the parameters manually, but I want to integrate a control to allow for discrete changing...

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the equation is the hypertrachoid one

tranquil wigeon Feb 10, 2019, 3:41 AM

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i'm trying to achieve the same design as the one you have, but it would be impossible to guess

opaque folio Feb 10, 2019, 3:42 AM

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prety sure it can be resolved

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you can measure it etc

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eg I just created this

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📎 Screen_Shot_2019-02-10_at_03.45.56.png

tranquil wigeon Feb 10, 2019, 3:46 AM

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damn looking good

opaque folio Feb 10, 2019, 3:47 AM

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I have the r set to be R/3

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so it will always be one third the radius of the major

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d (distance from centre of the smaller circle to the point being drawn...I'm sure there's a term for this) is set to 60

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and then to make that pattern I just replicated the script 9 times, varying the major radius (R) from 60-140

zealous kiln Feb 10, 2019, 7:43 AM

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Umm...please tell me I can still solve this regardless of the fact tht distance of B from the rock is missing?...

📎 image0.jpg

real sparrow Feb 10, 2019, 7:44 AM

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Yes.

zealous kiln Feb 10, 2019, 7:45 AM

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Hmmm

real sparrow Feb 10, 2019, 7:45 AM

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Use tan function to get the height and use tan again to get the distance

zealous kiln Feb 10, 2019, 7:45 AM

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But what distance do I have to work with here

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I need one of B distance right?

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But I only given A

real sparrow Feb 10, 2019, 7:46 AM

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Coz the perpendicular distance will be the same for both the tan functions and that gonna fetch you the distance of B

zealous kiln Feb 10, 2019, 7:47 AM

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I’m sorry I don’t know what you meant by perpendicular tan function

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I visualised the two triangles but I don’t find any equal depistances betweeen them on any side of triangle

real sparrow Feb 10, 2019, 7:51 AM

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Well both the triangles gonna share a common side ? And you can use the tangent/tan of the different angles to get that value of the base of the largest triangle and then for the smaller triangle ?

zealous kiln Feb 10, 2019, 7:51 AM

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But they dont have a common side

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Isn’t tht a rule when I increase angle the H increase, O increase and A decrease

real sparrow Feb 10, 2019, 7:53 AM

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What's O , A or H tho ?

zealous kiln Feb 10, 2019, 7:53 AM

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Hyp adjecent, opposite

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We r using standard right angles that meet at the origin or in this case Group a and b

real sparrow Feb 10, 2019, 7:53 AM

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Oh umm there's a variation in the angle coz of the distance tho

zealous kiln Feb 10, 2019, 7:54 AM

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Yes yes which is why the question has something missing which is distance of group b from rock

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So still leaves my question if It’s still possible to solve the uestion

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Idk imma skip it

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Ping me if someone knows a way to get around not having a single side of b triangle given

stark bluff Feb 10, 2019, 8:02 AM

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@zealous kiln I'm not english, what is a bearing

real sparrow Feb 10, 2019, 8:02 AM

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📎 IMG_20190210_133205283.jpg

stark bluff Feb 10, 2019, 8:02 AM

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I only know what a Bearing 9 is

real sparrow Feb 10, 2019, 8:03 AM

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shrugs

buoyant oasis Feb 10, 2019, 8:40 AM

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📎 Screen_Shot_2019-02-10_at_15.39.46.png

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Asked : BF?

real sparrow Feb 10, 2019, 8:45 AM

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Well just apply the similar triangle concept in triangle AFB and triangle EDM where M is the point where line AE intersects line CD.

buoyant oasis Feb 10, 2019, 8:46 AM

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will try, thanks!

real sparrow Feb 10, 2019, 8:46 AM

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👌

zealous kiln Feb 10, 2019, 9:40 AM

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Sigh...dead nvm man the questions isn’t solveable

real sparrow Feb 10, 2019, 9:44 AM

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The rock one ?

simple mica Feb 10, 2019, 9:48 AM

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I'm with dead. It's supposed to, nothing missing. Line OP in dead's diagram is the common side you're looking for, @zealous kiln

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*It's solvable, nothing missing

real sparrow Feb 10, 2019, 9:51 AM

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🐷

zealous kiln Feb 10, 2019, 10:08 AM

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:/

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If it were that then my English is wrong haha

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Which it’s most likely

opaque folio Feb 10, 2019, 6:24 PM

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@glad falcon hey man you around?

upper karma Feb 10, 2019, 8:05 PM

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It's not
This identity works fine when the tangens is defined and nonzero

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,wolf sin(900)/tan(900)

somber coyoteBOT Feb 10, 2019, 8:06 PM

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📎 wolf.png

Display results online and refine query

upper karma Feb 10, 2019, 8:07 PM

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yeah

steady sleet Feb 10, 2019, 8:07 PM

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you get 0/0

upper karma Feb 10, 2019, 8:07 PM

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that's because $\tan(900^\circ) = 0$

somber coyoteBOT Feb 10, 2019, 8:07 PM

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Xaositect:

📎 198106775495507973.png

steady sleet Feb 10, 2019, 8:08 PM

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:S not good enough

upper karma Feb 10, 2019, 8:08 PM

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I'm surprised worfram does not count in radians by default

steady sleet Feb 10, 2019, 8:09 PM

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== sind(180)/tand(180)

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oof right

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no MathBot

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but sin(180) and tan(180) are equal to 0

stuck jewel Feb 10, 2019, 8:43 PM

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sorry i have a quck question

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cos^2(2x)

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if you expand, you get (1+cos(4x))/2

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but my question:

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cos(4x) = cos(2x +2x)

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and so that becomes cos^2(2x) -sin^2(2x)

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what am i doing wrong here?

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,wolf cos^2(2x)

somber coyoteBOT Feb 10, 2019, 8:48 PM

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📎 wolf.png

Display results online and refine query

stuck jewel Feb 10, 2019, 8:49 PM

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,wolf (1-cos(2x +2x))/2

somber coyoteBOT Feb 10, 2019, 8:49 PM

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📎 wolf.png

Display results online and refine query

exotic meteor Feb 10, 2019, 10:19 PM

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how do you calculate the length of $\vec{AB} = 3\vec{p} - 4 \vec{q}$ where $|\vec{p}| = |\vec{q}| = 2$ ?

somber coyoteBOT Feb 10, 2019, 10:20 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 10, 2019, 10:20 PM

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Usually if it were $\vec{i}$ and $\vec{j}$ you would just do

somber coyoteBOT Feb 10, 2019, 10:20 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 10, 2019, 10:21 PM

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$|\vec{AB}| = \sqrt{3^2 + 4^2}$

somber coyoteBOT Feb 10, 2019, 10:21 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 10, 2019, 10:21 PM

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But I believe this doesn't apply here...

gritty siren Feb 10, 2019, 10:24 PM

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$|\vec v| = \sqrt{\vec v\cdot\vec v}$

somber coyoteBOT Feb 10, 2019, 10:24 PM

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Tuong:

📎 94730921676115968.png

exotic meteor Feb 10, 2019, 10:31 PM

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hmm

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Also how would I do somethinglike

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$3\vec{p} \times 5\vec{q}$

somber coyoteBOT Feb 10, 2019, 10:32 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 10, 2019, 10:33 PM

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Is it the same as

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$15(\vec{p} \times \vec{q})$

somber coyoteBOT Feb 10, 2019, 10:33 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 10, 2019, 10:33 PM

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Which is the same as

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$15(|\vec{p}| |\vec{q}| sin(\phi))$

somber coyoteBOT Feb 10, 2019, 10:33 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 10, 2019, 10:33 PM

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No?

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$\displaystyle \vert\mathbf{a}\vert=\sqrt{x^2+y^2+z^2}.$

somber coyoteBOT Feb 10, 2019, 10:42 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 10, 2019, 10:43 PM

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I've been taught this for the length of a (x,y,z) vector...

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@gritty siren Does $|\vec v| = \sqrt{\vec v\cdot\vec v}$ always apply?

somber coyoteBOT Feb 10, 2019, 10:43 PM

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Autistic Hoodie:

📎 162305820107735040.png

gritty siren Feb 10, 2019, 10:44 PM

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it's kind of a definition

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the definition of the euclidean norm

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(with the usual dot product)

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you could work with a fancier dot product, and it would still be a norm

exotic meteor Feb 10, 2019, 10:52 PM

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Wait is like

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$\vec{v} \cdot \vec{v} = |\vec{v}|^2$

somber coyoteBOT Feb 10, 2019, 10:52 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 10, 2019, 10:52 PM

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I assume it's not but I've seen it being done like this...

dire rampart Feb 10, 2019, 10:57 PM

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yes it is

exotic meteor Feb 10, 2019, 11:04 PM

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Awesome then 😄

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Thank you

zinc grail Feb 11, 2019, 1:59 AM

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hi

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would B be right since they are opposite angles?

📎 unknown.png

astral hornet Feb 11, 2019, 2:19 AM

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yes, and opp angs are just part of it

zinc grail Feb 11, 2019, 2:22 AM

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@astral hornet

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so just for clarification

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since we know the lines are all parallel

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we know the angle on the other side is gonna be the same?>

astral hornet Feb 11, 2019, 2:24 AM

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bcd is composed of bce and ecd

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abc and bce are linear pairs, so bce can be found

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and b is opposite aec, so aec is found

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using aec, ced is linear pair so that is also found

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ced is isosceles so cde is found

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through angle sum ecd can be found

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and angle addition of bce and dec gives bcd

paper minnow Feb 11, 2019, 4:16 AM

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ineed help

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hi

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okz

tropic shard Feb 11, 2019, 4:16 AM

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Que pasa

paper minnow Feb 11, 2019, 4:16 AM

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plz

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how do i do a cordinate proof

tropic shard Feb 11, 2019, 4:17 AM

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Um.

paper minnow Feb 11, 2019, 4:17 AM

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https://cdn.discordapp.com/attachments/373217754666500097/544222074403553280/IMG_3496.JPG

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@tropic shard

tropic shard Feb 11, 2019, 4:17 AM

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Hm.

paper minnow Feb 11, 2019, 4:18 AM

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:/

tropic shard Feb 11, 2019, 4:18 AM

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Man, that's a tough one to word out.

paper minnow Feb 11, 2019, 4:19 AM

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:/

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IDK How to do it

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i have my test tomorrow

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im so screweeed

tropic shard Feb 11, 2019, 4:19 AM

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oof

paper minnow Feb 11, 2019, 4:19 AM

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if this is the proof its 10 point

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ikr

tropic shard Feb 11, 2019, 4:19 AM

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Okay so imma guess on this explaination..

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Ok so we know that For the left vertice it starts at (0,0)

paper minnow Feb 11, 2019, 4:20 AM

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yes

tropic shard Feb 11, 2019, 4:20 AM

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The top left vertice is at (a,b)

paper minnow Feb 11, 2019, 4:20 AM

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how do u know that

tropic shard Feb 11, 2019, 4:20 AM

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A and B are dummy variables

paper minnow Feb 11, 2019, 4:20 AM

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ok

tropic shard Feb 11, 2019, 4:20 AM

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Meaning we just define them as so.

paper minnow Feb 11, 2019, 4:20 AM

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kk

tropic shard Feb 11, 2019, 4:21 AM

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So we know that midline means in between (0,0) and (a,b),

paper minnow Feb 11, 2019, 4:21 AM

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yes

tropic shard Feb 11, 2019, 4:22 AM

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So it'd be ([a+0]/2,[b+0]/2)

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(let me check to see if that's right, I'm a little tired)

paper minnow Feb 11, 2019, 4:22 AM

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oh

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k

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its ok

tropic shard Feb 11, 2019, 4:22 AM

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Oh okay, so we go by the same thinking for the right side

paper minnow Feb 11, 2019, 4:22 AM

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oh

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wait

tropic shard Feb 11, 2019, 4:23 AM

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Just instead of starting at (0,0) for the bottom, it'd be (c,d)

paper minnow Feb 11, 2019, 4:23 AM

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i know what this person did

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like they did 2a, 2b on the top

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📎 IMG_1360.JPG

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that was not me @tropic shard

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i dont get it but i know they put it as 2b

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2a

tropic shard Feb 11, 2019, 4:25 AM

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I know how I'd explain it, but I'm not sure if they'd let you put it my way lol

paper minnow Feb 11, 2019, 4:25 AM

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rip

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do u know how the perosn did it

tropic shard Feb 11, 2019, 4:26 AM

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Let's say... His handwriting is as good as mine.

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We'd make good doctors.

paper minnow Feb 11, 2019, 4:26 AM

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LOL

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how old r u

tropic shard Feb 11, 2019, 4:26 AM

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19 xD

paper minnow Feb 11, 2019, 4:26 AM

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LOl thanks for trying to help

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im 14

tropic shard Feb 11, 2019, 4:26 AM

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Handwriting really doesn't get better with practice xD

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They're asking you for some deep stuff

paper minnow Feb 11, 2019, 4:27 AM

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lol

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yes

tropic shard Feb 11, 2019, 4:27 AM

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Good job making it this far

paper minnow Feb 11, 2019, 4:27 AM

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hahah

glad falcon Feb 11, 2019, 5:32 AM

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📎 unknown.png

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My final distance for the radius is : 10.6

exotic meteor Feb 11, 2019, 12:23 PM

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What is the trick when finding the line where two planes intersect?

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I know how to find the vector of the line but how do I find a point where they intersect?

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$2x-y+5z-5=0 \ 7x+14y-24=0$

somber coyoteBOT Feb 11, 2019, 12:24 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 11, 2019, 12:30 PM

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Okay I realized it

upper karma Feb 11, 2019, 1:22 PM

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📎 unknown.png

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how would i do this problem?

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i'm really confused

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i know how to get the center, just not the radius

tropic shard Feb 11, 2019, 1:49 PM

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x²-2x+y²+4y=20
(x²-2x+1)+(y²+4y+4)=20+1+4
(x-1)²+(y+2)²=25
5 would be the radius.

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@upper karma

winged saddle Feb 11, 2019, 2:03 PM

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no

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mathlyfe

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u keep doing that lmao

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its

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(x-1)^2+(y+2)^2=25

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so 5 is radius

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@tropic shard

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@upper karma

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cuz u complete the square there but u forgot to square the term

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the constant

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u did +2 its +4

tropic shard Feb 11, 2019, 2:04 PM

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?

winged saddle Feb 11, 2019, 2:04 PM

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u completed the square wrong

tropic shard Feb 11, 2019, 2:04 PM

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You sure?

winged saddle Feb 11, 2019, 2:04 PM

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yes

tropic shard Feb 11, 2019, 2:04 PM

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oh

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Hmm

winged saddle Feb 11, 2019, 2:05 PM

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kongouDerp

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gtg switch classes

tropic shard Feb 11, 2019, 2:05 PM

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Seeya.

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OH I C

winged saddle Feb 11, 2019, 2:09 PM

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lmaooo

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make sure not to do that on a test

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xDDDDDD

tropic shard Feb 11, 2019, 2:12 PM

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xD

exotic meteor Feb 11, 2019, 4:02 PM

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Some complex number

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$w = \frac{z+1}{z-1}, z \ne 1$

somber coyoteBOT Feb 11, 2019, 4:02 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 11, 2019, 4:02 PM

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Where Re(w) = 0

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|z| = 1

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How do I prove that?

dire rampart Feb 11, 2019, 4:08 PM

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prove what exactly

exotic meteor Feb 11, 2019, 4:09 PM

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That if Re(w) is 0 |z| will always be 1

gritty siren Feb 11, 2019, 4:25 PM

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express z in term of w

dire rampart Feb 11, 2019, 5:14 PM

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do you have to?

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should be able to reach that by setting the real part of the fraction to 0

upper matrix Feb 11, 2019, 6:54 PM

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what would be my first step in solving for x here:

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tan^4(x)-2=tan^2(x)+sec^2(x)

upper karma Feb 11, 2019, 6:57 PM

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sec^2 = 1+tan^2

upper matrix Feb 11, 2019, 6:57 PM

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is that each side simplified?

upper karma Feb 11, 2019, 6:57 PM

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no no

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that's just a formula

upper matrix Feb 11, 2019, 6:57 PM

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ohh its an identity nvm

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yeah

upper karma Feb 11, 2019, 6:57 PM

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Plug it into sec

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and you have tan everywhere

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then u get = tan^4 - 2 - tan^2 - 1 -tan ^2

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tan^4 - 2*tan^2 -3 = x

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tan^2(x) = t

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t^2 - 2t - 3 = 0

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4 - 4 * -3 * 1 = 16
2+-4 / 2*1

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t = 3 or t = -1

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tan^2(x) = 3 or tan^2(x) = -1

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tan^(x) = +-sqrt(3)

upper matrix Feb 11, 2019, 6:59 PM

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alright thank you so much

upper karma Feb 11, 2019, 7:00 PM

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np

outer aspen Feb 12, 2019, 12:52 AM

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📎 image0.jpg

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i am incredibly lost.

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so all im given is acb = 40 deg, and the theorem that "two triangles drawn on the same side of a chord will have the same angles where they touch the circle"

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and i'm trying to find the measure of BDC. i got 50 degrees on my first attempt, but it feels wrong. if someone could break this down, i would greatly appreciate it

astral hornet Feb 12, 2019, 3:46 AM

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50 is right PandaHugg

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since bca and bda intercept the same arc, the angle measures are equal

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and sicne adb is inscribed in a semicircle, adc is 90

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and do some angle addition and you'll find bdc to be 50 🐱

glad falcon Feb 12, 2019, 4:02 AM

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if there was a triangle inside of a circle

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and the points were given for the triangle in coordinates

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I would have to look for the centroid right ? to get the coordinates of the midpoint ? of the circle

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@astral hornet 😃 ^ ??

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I am pretty sure I am correct

astral hornet Feb 12, 2019, 4:05 AM

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the circumcenter is equidistant to the vertices of a triangle

glad falcon Feb 12, 2019, 4:05 AM

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But this is what confuses me

📎 unknown.png

astral hornet Feb 12, 2019, 4:05 AM

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being equidistant, circumcenter is the center of the circle that includes the vertices of the triangle

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the special property of a centroid is the 1:2 ratio

glad falcon Feb 12, 2019, 4:06 AM

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Hmm. So the I can say that the center of the circle = centroid of the Triangle ?

astral hornet Feb 12, 2019, 4:07 AM

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no. did you even read what i wrote?

glad falcon Feb 12, 2019, 4:07 AM

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Yes.

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but i dont understand it

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If u could make it a bit simpler it would be great thanks

astral hornet Feb 12, 2019, 4:08 AM

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📎 unknown.png

glad falcon Feb 12, 2019, 4:09 AM

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Woah.

astral hornet Feb 12, 2019, 4:09 AM

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equidistant

glad falcon Feb 12, 2019, 4:10 AM

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Is the drawing of scale due to mouse drawing Or is that other line meant to be out side of the triangle

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That means If I calculate the centroid of the triangle. That is not equal to the center of the circle

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Ok. I think I understand

astral hornet Feb 12, 2019, 4:11 AM

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in the drawing assume the circle is a true circle, triangle vertices on circle and tick marks mean congruent

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the only time centroid would be useful is for 1:2 ratios, not circumscribing

glad falcon Feb 12, 2019, 4:12 AM

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Oh.

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Ok. So one more thing

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https://www.youtube.com/watch?v=ImFJJfrUOuk

YouTube

eHowEducation

How to Find the Circumcenter of a Triangle With Coordinates : Esse...

Subscribe Now: http://www.youtube.com/subscription_center?add_user=ehoweducation Watch More: http://www.youtube.com/ehoweducation Finding the circumcenter of...

▶ Play video

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Why does she call the Medians, " perpendicular bisector "

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A perpendicular bisector is whole differnet level isnt it ?

astral hornet Feb 12, 2019, 4:13 AM

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they're diff

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she's prob dumbing down content

glad falcon Feb 12, 2019, 4:15 AM

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Hm.

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Ok

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Good thing that she is cuz Im dumb

tropic shard Feb 12, 2019, 4:20 AM

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Nice basketball.

glad falcon Feb 12, 2019, 4:25 AM

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What.

patent echo Feb 12, 2019, 4:31 AM

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📎 image0.jpg

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How do u do this

astral hornet Feb 12, 2019, 4:40 AM

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for the circle parts just find circumference of circle, then circumference if radius is decreased by 8

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the rectangle its subtracting diameter from length of field

patent echo Feb 12, 2019, 4:40 AM

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wait waht

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wait so the track is a circle

astral hornet Feb 12, 2019, 4:44 AM

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2 semi circles (or just one circle) + rectangle

patent echo Feb 12, 2019, 4:52 AM

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@astral hornet sorry for pinging but the circle circumference would be 76pi
but how would u find the other side lengths for the rectangle

tropic shard Feb 12, 2019, 4:54 AM

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The length of the field is 60ft, the track is 8 ft, so the total height is 76 ft.

patent echo Feb 12, 2019, 4:54 AM

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yeah

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@tropic shard

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https://gyazo.com/2646084a44bb3d4375ccf77b90a7ced7

Gyazo

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how would u find this length tho

tropic shard Feb 12, 2019, 4:56 AM

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Ohh

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Circumference=2πr=76π

patent echo Feb 12, 2019, 4:56 AM

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ye

tropic shard Feb 12, 2019, 4:56 AM

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r=38

patent echo Feb 12, 2019, 4:57 AM

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ye

tropic shard Feb 12, 2019, 4:57 AM

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Diameter = 76, 136-76

patent echo Feb 12, 2019, 4:57 AM

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yea

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wait

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nvm

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76 is both of the semi circles

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combined

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right

tropic shard Feb 12, 2019, 4:58 AM

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Yup.

patent echo Feb 12, 2019, 4:58 AM

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o

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the answer

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would be the perimeter of the rectangle

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which is 60

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wait nvm

tropic shard Feb 12, 2019, 4:58 AM

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It'd be the distance between the two dots

patent echo Feb 12, 2019, 4:58 AM

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wait

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so all the sides

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are the same

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then?

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for the smaller

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the circle inside

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i mean

tropic shard Feb 12, 2019, 4:59 AM

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Yeah, seems so

patent echo Feb 12, 2019, 4:59 AM

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oh

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thanks

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@tropic shard

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would it be 82?

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@tropic shard

tropic shard Feb 12, 2019, 5:09 AM

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Hmm.

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What are you trying to find again?

patent echo Feb 12, 2019, 5:10 AM

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how much farther would someone running a lap on the outside lane travel than someone running a lap on the inside lane

tropic shard Feb 12, 2019, 5:11 AM

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Hmm.

patent echo Feb 12, 2019, 5:11 AM

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this question is weird af

tropic shard Feb 12, 2019, 5:12 AM

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I gotta work it out, so it may take me a minute lol.

patent echo Feb 12, 2019, 5:12 AM

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alright thanks for the hep

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help

tropic shard Feb 12, 2019, 5:12 AM

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lol okay

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@patent echo I'd think they'd have to run 16π more ft.

patent echo Feb 12, 2019, 5:16 AM

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how do u get that? wait wut

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wait

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did u do

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76pi - 60pi

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don't u need the perimeter of the rectangles

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@tropic shard

tropic shard Feb 12, 2019, 5:18 AM

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Nah, the horizontal distance of the rectangles are the same regardless if you're close or far from the center

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It's when you're doing those curves that distance piles up.

patent echo Feb 12, 2019, 5:18 AM

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so all u need to do is subtract the diameters

tropic shard Feb 12, 2019, 5:27 AM

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No, you'd only subtract the circumferences.

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So the large circumference is 76π, the small one is 60π, 76π-60π=16π

patent echo Feb 12, 2019, 5:29 AM

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oh

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i meant

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diameters

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i mean

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i mean

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circumferences

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xd

glad falcon Feb 12, 2019, 5:58 AM

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📎 unknown.png

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Sorry The Image is kinda unclear

plucky marlin Feb 12, 2019, 6:02 AM

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drop an altitude from E on BC

glad falcon Feb 12, 2019, 6:06 AM

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@plucky marlin yes ma dude

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But thats not helping

plucky marlin Feb 12, 2019, 6:07 AM

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y not ?

glad falcon Feb 12, 2019, 6:07 AM

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U only have one length 8

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The ten is the whoole base

plucky marlin Feb 12, 2019, 6:07 AM

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use pythagorean theorem on both triangles

glad falcon Feb 12, 2019, 6:07 AM

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wdym

plucky marlin Feb 12, 2019, 6:07 AM

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let one length be x

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so the other one would be 10 - x

glad falcon Feb 12, 2019, 6:07 AM

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Aight

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Then do pytogoras ?

plucky marlin Feb 12, 2019, 6:16 AM

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yup

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@glad falcon did u solve it yet ?

glad falcon Feb 12, 2019, 6:20 AM

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Oh yea Thanks Man 😃

plucky marlin Feb 12, 2019, 6:20 AM

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https://prnt.sc/mjw440

Lightshot

Screenshot

Captured with Lightshot

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oh great

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GWnanaPepoHype

glad falcon Feb 12, 2019, 6:21 AM

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Love ya ( no homo ) 😃 Thanks for the help @plucky marlin

plucky marlin Feb 12, 2019, 6:23 AM

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np

glad falcon Feb 12, 2019, 6:24 AM

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@plucky marlin Ok what did u get for the final value

plucky marlin Feb 12, 2019, 6:24 AM

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i didnt do it

glad falcon Feb 12, 2019, 6:25 AM

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oh. 😦 Ok 👋

plucky marlin Feb 12, 2019, 6:25 AM

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,w solve (10 - x)^2 + h^2 = 64 and x^2 + h^2 = 36 and h > 0

somber coyoteBOT Feb 12, 2019, 6:26 AM

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📎 wolf.png

Display results online and refine query

plucky marlin Feb 12, 2019, 6:26 AM

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so the area is 24/5 * 10 = 48

glad falcon Feb 12, 2019, 6:27 AM

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Wow ! I got 47.098 before

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Well thanks for the clarification

exotic meteor Feb 12, 2019, 11:09 AM

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How would one prove that $\overline{(\frac{z_1}{z_2})} = \frac{\overline{z_1}}{\overline{z_2}}$

somber coyoteBOT Feb 12, 2019, 11:10 AM

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Autistic Hoodie:

📎 162305820107735040.png

glad ocean Feb 12, 2019, 11:19 AM

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wtf is this

exotic meteor Feb 12, 2019, 11:19 AM

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@glad ocean What?

dire rampart Feb 12, 2019, 11:19 AM

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algebra PandaHugg

glad ocean Feb 12, 2019, 11:20 AM

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Ok so the proof

exotic meteor Feb 12, 2019, 11:20 AM

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conjugated complex number

glad ocean Feb 12, 2019, 11:20 AM

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It's like

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Since the whole thing is

exotic meteor Feb 12, 2019, 11:21 AM

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Like what am I supposed to do to prove it's true?

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Test it for a complex number?

glad ocean Feb 12, 2019, 11:22 AM

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No

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Just since both at positive

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Wait

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I'm an idiot so forgot what the overbar means

exotic meteor Feb 12, 2019, 11:23 AM

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its conjugate

gritty siren Feb 12, 2019, 11:24 AM

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maybe work with the re^(iθ) form to make things easier

exotic meteor Feb 12, 2019, 11:24 AM

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._.

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We don't learn that

dire rampart Feb 12, 2019, 11:25 AM

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yikes

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you could set variables up

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gon be messy tho

exotic meteor Feb 12, 2019, 11:28 AM

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You mean like

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Prove that

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$\line{(\frac{x+iy}{a+ib})} = \frac{\line{x+iy}}{\line{a+ib}}$

somber coyoteBOT Feb 12, 2019, 11:28 AM

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Autistic Hoodie:
Compile Error! Click the errors reaction for details. (You may edit your message)

📎 162305820107735040.png

exotic meteor Feb 12, 2019, 11:29 AM

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Extend it'

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Sot aht it looks the same

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I think that would work yeah

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Cool

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$(z-\frac{1}{2})^4 = (1+i\sqrt{3})^6$

somber coyoteBOT Feb 12, 2019, 11:35 AM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 12, 2019, 11:35 AM

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What is the simplest way to solve this?

dire rampart Feb 12, 2019, 11:37 AM

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cis form

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or re^itheta

exotic meteor Feb 12, 2019, 11:39 AM

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Hmm

real sparrow Feb 12, 2019, 11:53 AM

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Yes.

exotic meteor Feb 12, 2019, 12:03 PM

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Okay

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When calculating the right side i get that it is 64

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$(x-1/2+iy)^4 = 64$

somber coyoteBOT Feb 12, 2019, 12:04 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 12, 2019, 12:04 PM

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Since the right side does not have an imaginary unit

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The equation is actually

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$(x-1/2)^4 = 64$

somber coyoteBOT Feb 12, 2019, 12:05 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 12, 2019, 12:05 PM

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If we get the 4th root of every side

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Hmm

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We get

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$(x-1/2) = 2\sqrt{2} \ (x-1/2) = -2\sqrt{2} \ -(x-1/2) = 2\sqrt{2} \ -(x-1/2) = -2\sqrt{2}$

somber coyoteBOT Feb 12, 2019, 12:06 PM

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Autistic Hoodie:

📎 162305820107735040.png

exotic meteor Feb 12, 2019, 12:06 PM

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RIght?

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$(64)^{1/4} = 2\sqrt{2}, -2\sqrt{2}$

somber coyoteBOT Feb 12, 2019, 12:07 PM

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Autistic Hoodie:

📎 162305820107735040.png

gritty siren Feb 12, 2019, 12:10 PM

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$64^{1/4}=2\sqrt 2$

somber coyoteBOT Feb 12, 2019, 12:10 PM

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Tuong:

📎 94730921676115968.png

exotic meteor Feb 12, 2019, 12:11 PM

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Hmm

#

How do I solve it then

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I believe I am correct till the part

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$(x-\frac{1}{2})^4 = 64$

somber coyoteBOT Feb 12, 2019, 12:11 PM

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Autistic Hoodie:

📎 162305820107735040.png

gritty siren Feb 12, 2019, 12:11 PM

#

but the set of fourth roots of 64 is\
${2\sqrt2, i2\sqrt 2,-2\sqrt 2,-i2\sqrt2} $

somber coyoteBOT Feb 12, 2019, 12:12 PM

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Tuong:

📎 94730921676115968.png

exotic meteor Feb 12, 2019, 12:12 PM

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I don't understand that

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If we are talking about complex numbers than that applies?

real sparrow Feb 12, 2019, 12:16 PM

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$_(x-1/2+iy)^{4} = 2^6 \ (x-1/2+iy) = 2^{3/2} / <=> x-1/2 = 2^{3/2}$

somber coyoteBOT Feb 12, 2019, 12:17 PM

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DEAD.:

📎 505422185285025822.png

gritty siren Feb 12, 2019, 12:17 PM

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You get a unique solution if you do that

#

though there are 4