geometry-and-trigonometry

[past mantle]

Given perimeter

Hold on

[umbral snow]

You can construct 6 triangles in that shape. Each of them have an angle π/6 from the side. So, we can split this triangle in half and use trig for the apothem

tan(π/6) = a / 1.5
a = 3/2 tan(π/6)
a = sqrt(3)/2

[past mantle]

We only used degrees for trig

Im not in algebra 2

[umbral snow]

Oh. Then 30 degrees. 180/6

[junior scaffold]

=tex tanx/-tan^2(x)

[junior scaffold]

how do u simplify this

[umbral snow]

What's u/u²?

[junior scaffold]

so its -cotx

?

[mossy vine]

ye

[past mantle]

is that right?

had to find area

[sudden stream]

How do you do this?

The length of one base of a trapezoid is 19 meters and the length of the median is 23 meters. Find the length of the other base in meters.

[reef cave]

https://gyazo.com/c618d45e1f43b4d29d295f431613e4fe

basically

u need to draw

a diagonal

whcihh makes 2 triangles

[sudden stream]

@ToasterTomster#9783 do you know how to do this one

[reef cave]

ye

[sudden stream]

ok teach plz

sp00nfeed xD

[reef cave]

o hold n

lemme see

[sudden stream]

k

[reef cave]

i think its 120

[sudden stream]

ok

[upper karma]

I hope that’s right and I hope that helps!

[reef cave]

well ye

one part of it is

82

but thats like

part of angle mno

u found mnp

[upper karma]

OH

[reef cave]

so u just do the same

ya

[upper karma]

my b

[reef cave]

plus it has to be obtuse

[upper karma]

xD

[reef cave]

xD

[upper karma]

so then let me ask you, what do you have to do to find that angle?

[reef cave]

erm

lemme draw

xD

[upper karma]

cause i figured out my mistake

[reef cave]

well

no urs is right

its like the step

u jsut need to keep going

ehre lemem draw it

wait

nvm

im so dumb

they wantd mnp all along

@upper karma u were right

Lol

i thoguht we were looking for mno

LOL

apologies

:3

[upper karma]

all good haha

i went back and thought i was solving for something else hence why i thought i made a mistake

[covert osprey]

http://prntscr.com/ih4f2j I have no idea how to go about answering these

[chrome fiber]

convert everything to sine/cosine first.

then use the pythagorean identity.

[covert osprey]

cos^2 + sin^2 = 1?

@chrome fiber

[chrome fiber]

yes.

try the first one.

[covert osprey]

would I isolate cos or sine?

[chrome fiber]

what are you given?

[covert osprey]

cos(theta)

[chrome fiber]

so you would isolate that.

and you should notice that your expression will only be in terms of sine.

[covert osprey]

cos^2 = 1 - sin^2?

[chrome fiber]

one more step.

[covert osprey]

ooo

rad 1 -sin?

sin^2*

[chrome fiber]

yup.

and remember, since you're taking the square root, you'd have two solutions, ome positive and one negative.

but that's already covered.

[covert osprey]

I see

[chrome fiber]

can you do the rest?

[covert osprey]

im a little stuck on cot(theta)

bc I wrote cos(theta) / sin(theta)

[chrome fiber]

you know already what cosine of theta is in terms of sine.

and the denominator is in terms of sine already.

[atomic knot]

Hey

379

I have that so far

[waxen gorge]

@atomic knot haven't seen u in a long time lok

Lol*

Let's see

Which number

[atomic knot]

Lol

379

@waxen gorge

It has been a while 😂

It goes from one of the vertices to the midpoint of the opposite side

[waxen gorge]

A line

Ya

That mean its a right triangle

Not necessarily 45,45,90

[atomic knot]

Oh

[waxen gorge]

That statement is true for every right triabgle

[atomic knot]

It has to be a right triangle?

I just know that those two sides are the same

[waxen gorge]

O I never saw the half side thing

Then ya it's 45, 45, 90

uwu

[atomic knot]

What

Yeah

But it never said it was bisecting

I just came to the wrong conclusion

Ph

Oh right

But it’s not 90 degrees

Not necessarily

No

Altitudes has to be perpendicular

Really? Why

oh true

Lol

[waxen gorge]

woa sotto has godlike drawing skills 👀

[atomic knot]

Yeah

How could I find their angles

😂

So it’s 45 45 90

I was right

Because the two sides are the same?

[waxen gorge]

Lol

[atomic knot]

I’m not completely sure why it makes the right triangle. I get it and the drawing but not totally sure how I could explain this

😂

[waxen gorge]

Angle bisector theorem!

yay

[atomic knot]

Yes

[waxen gorge]

O nvm

:(

[atomic knot]

Because we know the side lengths

😂

Yeah

Got it

Thx

😃

[waxen gorge]

uωu

[atomic knot]

❤️❤️

[waxen gorge]

Lol

[eager pendant]

@mint ore tag me when you're ready

[mint ore]

ready

[eager pendant]

okay

do you know trig

trigonometry

if not, i'll just move on

[mint ore]

some of it

[eager pendant]

well, if you know that a/ sin(a)=2r

then you can figure it out

but if we dont know that:

let's mark a centre

let's call it O

[mint ore]

i didnt know that 😮

[eager pendant]

we know cd=7

and ab=8

so let's take O and extend it to meet AB

and call this intersection M

do this similarly for O and CD; let's call that N

can you work out em?

[mint ore]

ok i did it

[eager pendant]

okay cool

[mint ore]

what now

[eager pendant]

what's EM?

[mint ore]

2

[eager pendant]

nice, what's EN?

[mint ore]

1.5

[eager pendant]

recheck

[mint ore]

1?

oh wait its 1/2

[eager pendant]

good

so you can work out OE?

[mint ore]

why do i need oe

cant i solve it already

[eager pendant]

you're looking for the diameter, correct?

or radius

[mint ore]

yeah

[eager pendant]

what do you mean by 'solve already'

[mint ore]

i have ON and CN

so can i find the radius

[eager pendant]

oh true

yeah

nice

[mint ore]

so r is sqrt 16,25 and d is sqrt 32,5?

[eager pendant]

radius is sqrt(16.25)

but 2*sqrt(16.25) doesn't equal 32.5 -

it equals sqrt(4*16.25), see if you can understand

[mint ore]

oh yeah

😄

thanks

[waxen gorge]

Hi

sinx = -.4

-.4/cosx = 9.6

cosx = -.4/9.6

cosx = -1/24

now use inverse cosx function to find x

[golden parrot]

https://cdn.discordapp.com/attachments/326138757474680852/415433183513804801/RjZhZNQmRkGhRngXPXqh9g.png

about this

so is none of the solutions shown correct?

[mossy vine]

A

[golden parrot]

but A should be sqrt(65/4)

then

[night lotus]

How do I find the measures of sides of similar shapes?

[mossy vine]

@golden parrot the radius is sqrt(65/4), the diameter is sqrt(65)

@night lotus in similar shapes, corresponding sides are in the same ratio

[night lotus]

What's the ratio in the problem?

15:20?

[mossy vine]

yes

so you have 15:20 = w:10

[night lotus]

How do I know which number goes first in the ratio?

[mossy vine]

it doesn't matter which

as long as it's the same way round when looking at equality

you don't actually have to use ratios at all, you can use fractions instead if you want

you'd get 15/20 = w/10

you could just as easily do 20/15 = 10/w or 20:15 = 10:w

it really doesn't matter

[golden parrot]

oh it said diameter

k den

[night lotus]

@mossy vine so w = 13 1/3?

[mossy vine]

no

you've done the ratios different ways round

[night lotus]

it's 7.5?

[mossy vine]

yeah

as a rough check

it must be smaller than 10

because the 15 on that triangle is smaller than the corresponding 20 on the other triangle

[night lotus]

oh yea

So for question 15, x is 5?

[mossy vine]

ye

[night lotus]

and y is 6?

[mossy vine]

ye, nice

[night lotus]

okay, thank you very much

[mossy vine]

no problem 😃

[night lotus]

I'm not 100% sure about these vocab words

is number 1 A?

[reef cave]

can someody help me with 13 pls

<@&286206848099549185>

[crude kraken]

AC=x+5

You just add the parts

Same works for AB

and then the proportionality is just AB propto AC

Valid hint?

[reef cave]

oh

lemme try that

@crude kraken#219 how wouild i write out AB propto AC?

x+5 = x + 13?

[crude kraken]

We have an equatoin for AB

And we have an equation for AC

=tex x+5\propto x+13

[crude kraken]

However that doesn't work too well

So it's probably saying to proportionalize the two things you're given

namely

=tex \frac{x+7}{6}=\frac{5}{x}

[reef cave]

yes ive tried that

[crude kraken]

It didn't work?

[reef cave]

i got x^2 + 7x - 30

thats not factorable?

[crude kraken]

x^2+7x-30=0

=pup factor x^2+7x-30

[reef cave]

idk if i use quadratic

[charred spear]

Query made by @crude kraken
Data sourced from Wolfram|Alpha: http://www.wolframalpha.com/input/?i=factor+x^2%2B7x-30
Do more with Wolfram|Alpha Pro: http://www.wolframalpha.com/pro/

[reef cave]

oh wait

OH

im dumb

thanks

ugh cant belive i didnt see that

thank u

[crude kraken]

👍

[night lotus]

dilation if the scale factor is greater than 1 is called an enlargement right?

[crude kraken]

Mhm

Smaller is a reduction

[night lotus]

For number 20, I'm not sure how to do it

[abstract arch]

What is your x coordinate

[night lotus]

4?

Woa, your thing is messed up to the max

[spiral lintel]

Can someone help me with questions 28 and 29

[spiral lintel]

I used coordinates to find #29 and got 122, can someone provide an easier solution?

[keen aspen]

My brain is sorta slow right now is that supposed to be a rectangle?

[spiral lintel]

yes

I need #28 now

I got #29

[waxen gorge]

what r the side lengths

for 28

[spiral lintel]

they don't give u lengths

[waxen gorge]

o

nvm proof

[spiral lintel]

I only need an explanation

[waxen gorge]

the side of the square is a diagonal from the midpoint of the rectangle to and edge

[chrome fiber]

how do you know C is the mid point?

[waxen gorge]

i dont 😮

👀

i see similarity tho :/

ead

cdg

feh

meh whatev june can do it .-.

june knows everything

[chrome fiber]

what?

i mean i know how to do this one but lol no.

also feb?

[waxen gorge]

idk that last letter

h

[chrome fiber]

h.

i think.

ya.

but anyway.

hfe and cdg are congruent.

so their areas must be equal.

cbh and dea are also congruent.

so their areas are equal too.

now look at the figure and this:

arCDAB + arCGD + arCBH = arFGDE + arEAD + arFHE = total area of the figure.

arCGD = arFHE.

so.

arCDAB + arCBH = arFGDE + arEAD.

so you basically need to prove that arCBH = arEAD.

[spiral lintel]

okay thxs

[chrome fiber]

but you know that's already true bc they are congruent.

therefore, arCDAB = arFGDE.

which is what you needed to prove.

[spiral lintel]

how would u solve for 29? I did it with coordinates and it got messy even though I am correct

is there an easier way?

[restive void]

im just lost

like

he doesnt tell us how to do this

and i want to die

im assuming its a lot of slope and distance formula?

[waxen gorge]

Not really

First check if x and y spacing are the same

Then check if their differences are the same

Then I guess u can sketch if it fails both

[restive void]

im supposed to sketch and show work

like this looks like a rectangle

[keen aspen]

you're back

[restive void]

so to prove its a rectangle, you need opposite uh

whats that word called

recip something

[keen aspen]

To prove its a rectangle make the slopes opposite reciprocals

[waxen gorge]

parallels?

[restive void]

idk if im even right

[waxen gorge]

ya

[restive void]

oh that yeah

[waxen gorge]

what PJS said

[restive void]

so unless i did my math awfully wrong, CB and BA arent opposite reciprocals

[keen aspen]

Let's see 2-5/-7-6

[restive void]

well

[keen aspen]

-3/-13

[restive void]

well i did it wrong already lol

[keen aspen]

-4-2/-5-(-7)

-6/2

[restive void]

aaa i suck at math

oh, im still right hell yeah

so that eliminates a rectangle

[keen aspen]

Yep

[restive void]

wouldnt that also get rid of a square

wait

[keen aspen]

Yep

[restive void]

wait it would

why?

i like

[keen aspen]

Yeah a square and rectangle all have 90 degree angles

[restive void]

i just know a square is a rectangle but a rectangle isnt a square

oh yeah

im a bit mental sometimes

[keen aspen]

and since they arent opposite reciprocals it eliminates both of those

[restive void]

so it has to be just a regular quadrilateral, or a parallelogram

[keen aspen]

now we can try to see if its a trapezoid maybe, or a parallelogram

[restive void]

or that

yeah

so a trapezoid is one set of parallel sides, and one set of congruent sides right

[keen aspen]

yep

and a parallelogram has two sets of parallel sides

[restive void]

now uh

how the hell do i prove that

[keen aspen]

Well, you see if, the opposite sides have the same slope

[restive void]

ah

so this shape isnt a paralleogram

[keen aspen]

Okay so how did you prove that?

[restive void]

well

i found the slopes of CD and AB

not the same

so its either a trapezoid, iscoc trap, quadrilateral, or none

[keen aspen]

Hmm lets, see

AB: 5-(-1)/6-8 = 6/-2 = -3

CB= 2-5/-7-6 = -3/-13

[restive void]

CB or CD

cuz those are the opposite sides

[keen aspen]

DC = -4-2/-5-(-7) = -6/2 = -3

[restive void]

oh they are equal? am i doing slope wrong or something

y2-y1/x2-x1

[keen aspen]

DA = -4-(-1)/-5-8 = -3/-13

You got the equation right

But we can see that AB and DC have equal slopes

and CB and DC have equal slopes

[restive void]

so parallelogram

how do i find which one it is

[keen aspen]

since we have two sets of parallel lines we can say its a parallelogram

?

[restive void]

well i have to say what type of parallelogram it is

i would think its a rhombus right?

because sides are equal, angles arent?

[keen aspen]

In order for it to be a rhombus all sides must be equal

so you would use the distance formula

[restive void]

so distance formula thats some stupid annoying stuff right there aaaa

[keen aspen]

Lol its just the pythagorean theorem lel

[restive void]

wait

i mean

kinda

but i dont like :(

[keen aspen]

Yeah it is annoying

[restive void]

so since they're parallel

i only need to find the distance of one of the opposite sides right

[keen aspen]

For AB its sqrt(5-(-1)^2) + (6-8)^2)

So 6^2+-2^2

36+4

sqrt(40)

So in order for it to be a rhombus all sides must be sqrt(40) in length

[restive void]

wouldnt CD be 40 because parallel?

or sqrt 40 my bad

[keen aspen]

Not necessarily

Even though they are parallel doesnt mean they have equal side lengths

like a trapezoid

[restive void]

so this is just a parallelogram

[keen aspen]

For CB its sqrt((2-5^2)+(-7-6^2))

so -3^2+-13^2

9+169

sqrt(178)

[restive void]

so yeah just a parallelogram right

[keen aspen]

From this we can say that its not a rhombus so yeah a parallelogram

[restive void]

okay, i know that took a long time, i have seven more of those to do

will you kindly help me out

im still barely understanding this

[keen aspen]

Sure

Actually btw there is a name for it

[restive void]

next one

hm?

[keen aspen]

A rhomboid

[restive void]

oh

[keen aspen]

A rhomboid is the same as a rhombus but the side lengths are not equal

[restive void]

we havent learned those yet i dont think

lets do number three?

[keen aspen]

Eh ok I mean a parallelogram and rhomboid are the same term

Ok

[restive void]

hey earlier

how did you get the opposite sides, did you graph it?

[keen aspen]

I did

Just for clarification

You dont need to graph

[restive void]

then how could you tell which sides are opposite?

just mental image?

anyway, number three

so it looks like a trapezoid

so we should find the bases' slopes right?

[keen aspen]

hold on

Ill show you

Thats what I did

[restive void]

thats too complicated for me aaa

[keen aspen]

LOL just showing you what I do

[restive void]

oh

[keen aspen]

Anyways next question i wont use the graphing tool

[restive void]

i graph it

[keen aspen]

You can but you dont need to

[restive void]

so when i graphed this, where should we start

[keen aspen]

All you need to do is find the slopes and distances

[restive void]

see if the angles are 90 degrees right?

[keen aspen]

You can

[restive void]

so lets see AD and DC first

[keen aspen]

Ok

AD: -10-6/4-(-2) = -16/6

Which reduces to -8/3

[restive void]

mkay

[keen aspen]

So CD ; -10-(-7)/4-13 = -3/-9

or 1/3

[restive void]

is the other 1/3

yea

so no, its not a square or rectangle

[keen aspen]

Yep

[restive void]

how do we prove if its a trapezoid?

[keen aspen]

If its a trapezoid itll have a pair of parallel sides

[restive void]

the bases right?

[keen aspen]

yep

[restive void]

so ad and bc slopes?

[keen aspen]

They have to be the same in order for it to atleast be a trapezoid

[restive void]

hm?

[keen aspen]

BC; -7-(-4)/13-4 = -3/9

-1/3

BA; -4-6/4-(-2) = -10/6

=-5/3

So.....

We have slopes -8/3; 1/3; -1/3; -5/3

[restive void]

wait so they are 90 degree angles?

wait im so lost

i didnt write something down

[keen aspen]

All slopes are different

meaning no parallel sides

[restive void]

oh okay wait nevermind

so it has to be a kite?

or wait

no

false

where do i go next

[keen aspen]

Whats the definition of a kit

kite

[restive void]

one pair of opposite angles

uh

something else

diagonals are perp

[keen aspen]

Also a kite has two pair of equal side lengths

[restive void]

yeah

so distance formula

[keen aspen]

Yep

You can do that ?

[restive void]

well which sides should i check

i dont even know we never did this on a kite

aaa

i really want a new teacher

[keen aspen]

LOL

Ok

Hold on imma test my latex skills

$$\sqrt((-4-6)^2 + (4-(-2))^2)$$

[restive void]

wait pjs

if there are no parallel sides

[keen aspen]

Ye

[restive void]

we only have a quadrilateral and a kite left right?

[keen aspen]

yep

[restive void]

so its 100 + 36

sqrt136

[keen aspen]

Yep

[restive void]

what side is that

[keen aspen]

For BC : $$\sqrt (-7-(-4))^2 + (13-4)^2)$$

[restive void]

so 9 + 81

sqrt90

or did i do mental math wrong

i did that really fast lol

[keen aspen]

youre good

[restive void]

so its just a quad

[keen aspen]

Not yet

[restive void]

hm?

[keen aspen]

The other sides could have the same length

[restive void]

AAAAAAAA I HATE THIS CLASS JESUS

sorry

[keen aspen]

For CD: $$\sqrt ((-10-(-7)^2 + (4-13)^2)$$

[restive void]

sqrt 9 + 81

same thing?

sqrt 90?

so would that be a kite?

please say yes i dont want to do any more math

even though we have 6 more after this

and i dont just wanna not do it lol

bad ethics

[keen aspen]

Hold up

Im stupid

[restive void]

you're telling me

[keen aspen]

For a kite, the diagonals must be perp.

[restive void]

so we dont even need to do this

[keen aspen]

NOPE lol

[restive void]

we could just

i really

really

want to die

[keen aspen]

Haha yeah shouldve realized that

[restive void]

so how do we find that

slope of DB slope of AC

[keen aspen]

So, AC and BD must be opposite reciprocals

[restive void]

?

[keen aspen]

yep

and we already proved that

[restive void]

we did

oh

okay

so kite

i did my math wrong already

late

i got a 0 lol

aaaaaaaaaaa

[keen aspen]

It's not a kite

[restive void]

oh my god im just done with math lol

[keen aspen]

Its an irregular quadrilateral

[restive void]

i really

really

want to dispose of my teacher

NEXT QUESTION

[keen aspen]

Alright

[restive void]

so this looks like an easy shape

[keen aspen]

$$\frac {4-3}{3-(-2)}$$

[restive void]

how many points do i get taken off if i just right quadrilateral because four sides

:)

[keen aspen]

Alot prob lol

[restive void]

okay so how do we solve this

uh

looks like a parallelogram we're starting with opposite sides slopes

what you did was ba right

BA

[keen aspen]

1/5?

[restive void]

i got same slopes for AB and DC

yeah

i got 1/5 for both of them

[keen aspen]

Hold on lemme see

[restive void]

thats not opposite reciprocal

hold on gonna get a gun

[keen aspen]

For BC $$\frac {-1-4}{2-3}$$

[keen aspen]

-5/1

[restive void]

AAAAAAAAA i keep doing things wrong

[keen aspen]

-5

[restive void]

so opposite

[keen aspen]

Opposite reciprocals so far

[restive void]

so now ad and bc

[keen aspen]

DC: $$\frac {-2-(-1)}{-3-2}$$

[keen aspen]

-1/-5 = 1/5

[restive void]

yeah

i got that

[keen aspen]

DA: $$\frac {-2-3}{-3-(-2)}$$

[keen aspen]

-5/-1 = 5

[restive void]

so not opposites

damnit

wait

no opposites

im so dumb rn lol

yes

parallelogram

now i need to find if its a square or rect right

[keen aspen]

No

We showed that the slopes are not opposite reciprocals

so it cant be a square or rect

[restive void]

oh yeah, so thank lord

NEXT

[keen aspen]

Not next lol

[restive void]

what

the

hell

okay

im going to die inside

what else is there

[keen aspen]

It can be another type of parallelogram

[restive void]

what else is there

oh

that meme

rhombus

?

[keen aspen]

Are there two sets of parallel sides

?

[restive void]

uhhhhh

i know all of them are congruent

so yes

???

i really dont know anymore

im dying

yes it is final answer

[keen aspen]

LOL

Um well we know we have one set of parallel sides

[restive void]

wait didnt we say both are congruent

i dont

even know anymore

aaaaaaaaaaaaaaaaaaaa

[keen aspen]

Hmmm hold up now im a bit confused

[restive void]

i meant parallel

not congruent

SO AM I

you know what my answer is

i skip this one and make my teacher do it for me tomorrow

<3

so lets do this one thanks bb

[keen aspen]

Hold on I cant quit now

[restive void]

damn

[keen aspen]

So yes; two sets

so it can be a parallelogram or a rhombus

use the distance formula to see if the side lengths are equal

[restive void]

i really really really dont want to

[keen aspen]

Test with just two side lengths and when they arent the same you can say its just a parallelogram

[restive void]

but i will

really regretably

[keen aspen]

Hahaha

[restive void]

while contemplating my life choices of honors geometry

y2-y1^2 + x2-x1^2 all in square root right

[keen aspen]

yep

[restive void]

so BA i got sqrt26

check my mental math?

[keen aspen]

es

yes

[restive void]

DC i got 26 am i right

if i am its a rhombus right

please say yes im dying

[keen aspen]

LOL hold up

Yes DC is sqrt(26)

[restive void]

ALRIGHT DONE WITH THAT HELL OF A PROBLEM

next one thanks

[keen aspen]

No no no

[restive void]

dont u dare say no

fuck you

i was too late

[keen aspen]

You gotta do all sides

LMAO

[restive void]

i really really dont want to

[keen aspen]

ill do it for you

[restive void]

11:00 pm

doing math homework

OH I HAVE SPANISH HOMEWORK TOO

LOOKS LIKE IM STAYING UP PRETTY LATE

BECAUSE ON QUETION TAKES LIKE THIRTY MINUTES

[keen aspen]

Yes

It is a rhombus

[restive void]

THANK GOD

[keen aspen]

All side lengths are the same

[keen aspen]

ok

-2-4/8-10 -6/-2 = 3

2-(-2)/2-8 = 4/-6

= -2/3

8-2/4-2 = 6/2 = 3

[restive void]

what side

for the first slope

[keen aspen]

8-4/4-10 = 2/-6

-2/3

Slopes; 3, -2/3, 3, -2/3

BA, CB, DC, DA

[restive void]

is that like

a rectangle

say yes

so its over

[keen aspen]

Nope

[restive void]

damn

i tried

[narrow sleet]

How do you know it has right angles?

[restive void]

oh youre right

it doesnt

[keen aspen]

For it to be a rectangle if the angles are opposite reciprocals

[restive void]

because no opposite reci

[keen aspen]

yep

[restive void]

you beat me to it again

[narrow sleet]

Yes

[restive void]

stop typing fast

wait no type fast

[keen aspen]

however you have two pair of parallel sides

[restive void]

i want to get this done with

so distance i would assume is best to do nextt

[keen aspen]

Yep

[restive void]

to see if its a rhombus

[keen aspen]

Yep

[restive void]

oh boy here we go this shit again

[narrow sleet]

Yes

Lol

[keen aspen]

Im assuming you can do it

[restive void]

so DA is sqrt 8-4^2 + 4-10^2

right

so sqrt 52

[keen aspen]

yes

[restive void]

three more !!!!!!!!

progress guys!!!

[waxen gorge]

Guys it's been like 2 hrs

[restive void]

slow, painful progress

shut up

dont remind me

[waxen gorge]

This is not good homework

[restive void]

<3

[waxen gorge]

ur teacher sucks

[restive void]

YES

HE DOES

THANK YOU

[narrow sleet]

Actually u need to do CD will be enough

[restive void]

wait really

[narrow sleet]

To proof

[restive void]

why

teach me

[narrow sleet]

Because if AD is not equally to CD,it will be a parallelogram

If AD = CD, it is a rhombus

[keen aspen]

true

[restive void]

oh, is it because the same slope?

or something

i dont know man

im gonna d

[keen aspen]

Nah; slopes dont matter

[narrow sleet]

Because two lines with the same slope are parallel lines

[restive void]

for cd i got sqrt 5

what the hell

did i do wrong

oh i see

i looked at the wrong problem

shh

[narrow sleet]

And you proof that it has 2 parallel lines and it doesn't have right angles, so it can be a rhombus or a parallelogram

[restive void]

is CD sqrt 40?

[narrow sleet]

Wait

[keen aspen]

yes

[restive void]

THANK GOSH I DID SOMETHING RIGHT

AWAY WITH THAT PROBLEM

8 MINUTES NEW RECORD LETS GO

im going insane sorry

[narrow sleet]

Lol

@restive void Good luck

[restive void]

wait so

its just a parallelogram

right

[keen aspen]

yep

[restive void]

four more

[keen aspen]

rhomboid but you havent learned that

[restive void]

shut up with confusing words

<3

next

[narrow sleet]

Rhomboid...

[restive void]

havent learned it

[keen aspen]

Ok BA = 1/2 CB = -2 DC = 1/2 DA = -2

Opposite reciprocals you see?

[restive void]

yeah

[keen aspen]

This means that its either a square or rect

use distance formula to see if they are the same

[restive void]

well

so i should only do say ike DA and DC

[narrow sleet]

Yes

[restive void]

if those are the same its a square

if different its rect

[narrow sleet]

Yes

[restive void]

is DA = sqrt 20?

or did i math wrong

[narrow sleet]

Correct

[keen aspen]

yep

[restive void]

aha

im better than all of u fools at math

[keen aspen]

lol

[narrow sleet]

Lol

We are just waiting for u

[restive void]

:(

so should i do ab now

[keen aspen]

Sure

[restive void]

i really dont want to do more work than i need anymore

[narrow sleet]

JUST DO IT!!

[restive void]

N E V E R

i got sqrt 20 for AB

please say yes

[keen aspen]

yes

[restive void]

hell yes

see better than all of you

[keen aspen]

hehe

[narrow sleet]

I got that like 5 mins ago

Like what I say we are waiting for u

[restive void]

we dont talk about that

[narrow sleet]

Kkk

[restive void]

we just talk about me here

because im the best

next question btw

okay, hey

will you walk me through what you do to get the slopes

[keen aspen]

oK

[restive void]

because i obviously dont do this right

[narrow sleet]

Lol

[keen aspen]

For AB: $$\frac {-4-(-1)}{9-5}$$

[narrow sleet]

@restive void Mhmm I thought u are better than us...🤔 🤔 🤔

[restive void]

i am in my moments smile

let me have my moments

thanks bb <3

[narrow sleet]

Ok

[restive void]

alright pjs

do you do BC next

[narrow sleet]

Lol try

Urself

[restive void]

I DONT WANT TO

😡

rage emote best emote

[keen aspen]

For BC: $$\frac {-10-(-4)}{6-9}$$

[restive void]

cant you simplify 6/-3

so like

6/-1

i meant

3/-1

its late okay

i dont even know

[keen aspen]

[restive void]

so for cd you do -5 -(-10)/ 3-6?

CD*

[keen aspen]

yes

[narrow sleet]

Yeap

[restive void]

DA = -5-(-1)/ 3-5

[narrow sleet]

Yes

[restive void]

DA =2 right

[keen aspen]

yes

[restive void]

okay im starting to get it

[keen aspen]

Yayayayaya

[restive void]

so we dont have opposite recipricoles

so no square or rect

unless im absolutely fucked in the mind and messed up?

its the latter isnt it

[keen aspen]

Hm; -3/4, 2, -5/3, 2

There are a pair of parallel lines

[restive void]

i got -3/4, 2, -3, 5/-3

well that coulda been bad

[keen aspen]

How did you get -3

[restive void]

BC idk wht i did

okay

[keen aspen]

and 5/-3 is the same as -5/3

[restive void]

dont ask me

[keen aspen]

-10-(-4) = -6 6-9 = -3 -6/-3 = 2

[restive void]

reasons why i despise math - you do one thing wrong everything else is wrong

[keen aspen]

yep lol

[restive void]

okay so from here

no opposite recips

no square/rect

[narrow sleet]

Yes

But it has a pair of parallel lines so...????

[restive void]

oh

trapezoid

i didnt even notice that

jesus i suck at this

[narrow sleet]

Yes

[restive void]

okay fuck you too <3

kidding

[narrow sleet]

U just need to practise more

[restive void]

2nd to last one

[keen aspen]

Okay you know how do to it correct?

[restive void]

i want to say no

but yes

sort of

i really dont want to anymore

im d y i n g

[narrow sleet]

Just write ur answer here and we will check

[restive void]

wait question

ab the slope will have a zero right?

how do you work with that

0/3

no?

[narrow sleet]

So the slope is 0

[restive void]

oh

what about CD with its -3/0

is that still zero

or is it -3

[keen aspen]

Undefined

[restive void]

so how the hell do i do this

[keen aspen]

It's a straight line vertically

[restive void]

oh okay

but should i still write -3/0?

[keen aspen]

Sure

[restive void]

wait this is just a trapezoid right? one set of parallel lines?

[narrow sleet]

Yeah

[restive void]

holy shit see better than all of u

im sorry i dont mean it <3

[keen aspen]

lol one morwe

more

[restive void]

yeah, last one

[keen aspen]

BA: $$\frac {2-4}{-1-(-4)}$$

[narrow sleet]

U can do it right

Let him try

[keen aspen]

ye

[restive void]

are my slopes right - AB = -2/3 BC = 2/3 CD =2/3 AD =2/3

wait

i think i missed a negative

[narrow sleet]

CD = -2/3

[keen aspen]

CD is -2/3

[restive void]

Yeah figured

[keen aspen]

So two pairs of parallel sides

Now test if the side lengths are equal

[restive void]

So is this going to be a square or rectangle or rhombus?

[narrow sleet]

Do it has right angles?

[restive void]

Uh

I see opposite reciprocals

Wait

No I don’t

So at this point a rhombus or a parallelogram right

[narrow sleet]

Yes

[waxen gorge]

@restive void it's been 3 hrs just sleeeeppppp