#geometry-and-trigonometry | Mathematics | Page 116

spring lion Dec 14, 2025, 10:04 PM

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Or is it 8/x how do I determine that? They're both

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Ohhhh mb forgot the parenthesis

spring lion Dec 14, 2025, 10:05 PM

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spring lion Or is it 8/x how do I determine that? They're both

The smallest side

grave pond Dec 14, 2025, 10:05 PM

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Just use the same order when you convert each side of the blah:blah = blah:blah to a fraction.

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So either 8/(12.2+x)=x/8 or (12.2+x)/8=8/x. These both work (and they'll give you the same equation after you clear denominators).

spring lion Dec 14, 2025, 10:06 PM

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Ohhhh

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Okay

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So when I start with a 8 in the first ratio it's gotta be 8 in the denominator

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In the second ratio

shut sand Dec 14, 2025, 10:07 PM

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well it doesnt have to be

spring lion Dec 14, 2025, 10:07 PM

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But why

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I need to understand the logic

shut sand Dec 14, 2025, 10:07 PM

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but if you do 8/x, you also have to do 12.2+x/8

spring lion Dec 14, 2025, 10:07 PM

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shut sand but if you do 8/x, you also have to do 12.2+x/8

Yeah

shut sand Dec 14, 2025, 10:07 PM

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because you HAVE to do small/big:small/big, you can't do big/small: small/big

spring lion Dec 14, 2025, 10:08 PM

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Ohh

grave pond Dec 14, 2025, 10:08 PM

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(12.2+x)/8, not 12.2+x/8.

spring lion Dec 14, 2025, 10:08 PM

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But

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Hmmm

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OHHHH

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OKAY I GET IT

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Let me do the calculation now then

shut sand Dec 14, 2025, 10:09 PM

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yeah

spring lion Dec 14, 2025, 10:09 PM

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8/(12.2+x)=x/8

shut sand Dec 14, 2025, 10:10 PM

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yes

spring lion Dec 14, 2025, 10:10 PM

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This gives some weird equation 😭

shut sand Dec 14, 2025, 10:10 PM

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so cross multiply

spring lion Dec 14, 2025, 10:10 PM

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Yeah one second

shut sand Dec 14, 2025, 10:10 PM

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wait its a quadratic

spring lion Dec 14, 2025, 10:11 PM

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Yes

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64=12.2x+x²?

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Or is that wrong

grave pond Dec 14, 2025, 10:13 PM

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That looks right.

spring lion Dec 14, 2025, 10:13 PM

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Okay

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So I put everything on one side of the equation?

shut sand Dec 14, 2025, 10:13 PM

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yep now subtract 64 from both sides

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yeah

spring lion Dec 14, 2025, 10:13 PM

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Okay one sec

shut sand Dec 14, 2025, 10:13 PM

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and then use quadratic formula I think

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should be the easiest

spring lion Dec 14, 2025, 10:14 PM

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x²+12.2x-64=0

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Do I use the -b±√(b²-4ac)
2
Here?

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Wouldn't that give 2 results like normal?

shut sand Dec 14, 2025, 10:15 PM

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use the positive solutions

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*solution

spring lion Dec 14, 2025, 10:15 PM

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Oh

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Ohh

shut sand Dec 14, 2025, 10:15 PM

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because a side doesnt have a negative value

spring lion Dec 14, 2025, 10:15 PM

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Yeahhh truee

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Alright give me 3 min

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Damn I think I did a calculation mistake?

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Screenshot_2025-12-15-01-18-51-687_com.miui.calculator.jpg

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148.84+256 no?

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(12,2)²+4*64

shut sand Dec 14, 2025, 10:19 PM

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that's the numerator?

spring lion Dec 14, 2025, 10:20 PM

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Yes

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Plus or minus -12.2 as well.

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-12,2±√148.84(+)256

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/2

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Should I ask a quadratic calculator?

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Okay the calculator did the same thing as me.

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Positive value is 3.96.

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Is that the answer?

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-12,2+20.12=7.92

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7.92/2=3.96

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Hey I didn't even need a calculator lmao

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Okayyyy it's correct!!

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😭

grave pond Dec 14, 2025, 10:31 PM

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(Did you miss "round to the nearest tenth"?)

spring lion Dec 14, 2025, 10:32 PM

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No it was like 3.960...

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3.96 is correct

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Okay let me see I did the other one so I can do this one too

Screenshot_2025-12-15-01-33-37-251_com.android.chrome.jpg

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Small/big=Small/big?

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Except I'm not sure which one is which here 😭

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x is the small one

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grave pond Dec 14, 2025, 10:38 PM

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First you need to decide which triangles you use similarity on.

spring lion Dec 14, 2025, 10:38 PM

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Okay

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I'm not good at deciding which ones hmmm

grave pond Dec 14, 2025, 10:39 PM

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Look for triangles in the diagram where you can write expressions for at least two of the sides.

spring lion Dec 14, 2025, 10:40 PM

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BD/DA?

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Does that work?

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Or CB/CA

grave pond Dec 14, 2025, 10:46 PM

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Which triangles are you using?

spring lion Dec 14, 2025, 10:49 PM

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Hmm

spring lion Dec 14, 2025, 10:49 PM

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grave pond Which _triangles_ are you using?

I'm so bad at this 😭 CBD CBA?

grave pond Dec 14, 2025, 10:50 PM

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Can you write expressions for at least two edges in each of those?

spring lion Dec 14, 2025, 10:51 PM

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Let me see

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Wait I think this is false 💀

spring lion Dec 14, 2025, 10:51 PM

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spring lion I'm so bad at this 😭 CBD CBA?

^

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CB/CA

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Is this valid?

spring lion Dec 14, 2025, 10:52 PM

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grave pond Can you write expressions for at least two edges in each of those?

.

grave pond Dec 14, 2025, 10:53 PM

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Can you write expressions for CB and CA?

spring lion Dec 14, 2025, 10:54 PM

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I don't get what you mean exactly sorry can you give an example?

grave pond Dec 14, 2025, 10:54 PM

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For example we can write an expression for the lenght of BA, namely x+7.4.

spring lion Dec 14, 2025, 10:54 PM

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Ohhh

spring lion Dec 14, 2025, 10:55 PM

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grave pond Can you write expressions for CB and CA?

Let me see for this then

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Well CA is 9.3

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Not sure if we can derive CB from anything...

grave pond Dec 14, 2025, 10:58 PM

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So perhaps it's best not to have CB in your plan.

grave pond Dec 14, 2025, 10:58 PM

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grave pond Look for triangles in the diagram where you can write expressions for _at least ...

(See this).

spring lion Dec 14, 2025, 10:59 PM

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grave pond So perhaps it's best not to have CB in your plan.

Yeah true.

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Let me try again.

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Would CAD work maybe?

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It has 7.4 and 9.3.

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CA=9.3
DA=7.4

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What's the other triangle?

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🤔

grave pond Dec 14, 2025, 11:05 PM

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CAD looks like a good candidate, yes. Now you'll need a second one too.

spring lion Dec 14, 2025, 11:05 PM

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grave pond CAD looks like a good candidate, yes. Now you'll need a second one too.

Okay

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Can you give a hint

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I'm thinking of uhh

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CBA?

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7.4+x and 9.3 BA and CA respectively.

grave pond Dec 14, 2025, 11:07 PM

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Okay. So in CAD we know the hypotenuse (CA) and the long leg (DA). Which "roles" do we know in CBA?

spring lion Dec 14, 2025, 11:08 PM

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Let me see!

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BA=Hypotenuse (7.4+x)

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CA=9.3

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The long leg.

grave pond Dec 14, 2025, 11:10 PM

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Excellent, those are the same roles. So now you can start writing an equation from the similary of CAD and CBA.

spring lion Dec 14, 2025, 11:10 PM

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Let's see

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Soooo

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CAD and CBA

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CA=9.3

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CB=

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Bruh wait

grave pond Dec 14, 2025, 11:12 PM

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CB is neither the hypotenuse nor the long leg.

spring lion Dec 14, 2025, 11:12 PM

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Right right

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Let's not go with that

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I ratio hypotenuse to hypotenuse?

grave pond Dec 14, 2025, 11:13 PM

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Based on what we have to work with, the relevant similarity is [one hypotenuse]:[one long leg] = [other hypotenuse]:[other long leg].

spring lion Dec 14, 2025, 11:13 PM

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Ohhh

grave pond Dec 14, 2025, 11:13 PM

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(Though you might also write it as [one hypotenuse]:[other hypotenuse] = [one long leg]:[other long leg] -- that will end up being the same equation after you cross-multiply).

spring lion Dec 14, 2025, 11:14 PM

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Ahh

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Let me see.

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9.3/(7.4+x)

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=

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9.3/7.4?

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I might be getting something wrong.

grave pond Dec 14, 2025, 11:16 PM

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Yes, you used different orders in the two fractions.

fierce stump Dec 14, 2025, 11:17 PM

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Can someone help me with my Pythagore homework

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It’s in French tho

spring lion Dec 14, 2025, 11:17 PM

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grave pond Yes, you used different orders in the two fractions.

I knew it

spring lion Dec 14, 2025, 11:19 PM

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grave pond Yes, you used different orders in the two fractions.

9.3/7.4+x=7.4/9.3?

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I went with small/big

fierce stump Dec 14, 2025, 11:20 PM

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spring lion 9.3/7.4+x=7.4/9.3?

Can y pls help w

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Me

spring lion Dec 14, 2025, 11:21 PM

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fierce stump Can y pls help w

Idk french

fierce stump Dec 14, 2025, 11:21 PM

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spring lion Idk french

I’ll translate it

spring lion Dec 14, 2025, 11:21 PM

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Send an SS maybe I can help

fierce stump Dec 14, 2025, 11:21 PM

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DMs

spring lion Dec 14, 2025, 11:21 PM

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Ok

spring lion Dec 14, 2025, 11:24 PM

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spring lion 9.3/7.4+x=7.4/9.3?

Is this correct?

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I will nuke myself if this gives another quadratic

grave pond Dec 14, 2025, 11:26 PM

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spring lion 9.3/7.4+x=7.4/9.3?

Almost. It should be 9.3/(7.4+x) rather than 9.3/7.4+x.

spring lion Dec 14, 2025, 11:26 PM

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grave pond Almost. It should be 9.3/(7.4+x) rather than 9.3/7.4+x.

I keep forgetting the damn parenthesis 😭

grave pond Dec 14, 2025, 11:26 PM

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But otherwise, yes, it should just be algebra from here on.

spring lion Dec 14, 2025, 11:26 PM

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grave pond But otherwise, yes, it should just be algebra from here on.

Alright alright

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I got this!!

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4.28->4.3

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HELL YEAAAA I DID IT BROOO

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Damn it I tried doing the next question and I failed ahhh

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I made a calculation error.

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And now this next question has only 2 sides with a value 😭😭😭

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I actually thought I could do this damn itttt

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Screenshot_2025-12-15-02-36-55-240_com.android.chrome.jpg

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14/32 or whatever how in the hell?

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I genuinely have no clue

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If I can get this right I can do the bonus question

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🙏

spring lion Dec 14, 2025, 11:39 PM

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grave pond But otherwise, yes, it should just be algebra from here on.

Can you help?

grave pond Dec 14, 2025, 11:41 PM

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spring lion Can you help?

The same general procedure as before ought to work: First look for triangles where you can write expressions for two of the sides.

spring lion Dec 14, 2025, 11:41 PM

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But there are only 2 values

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Oh wait.

grave pond Dec 14, 2025, 11:42 PM

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Each of the previous problems also just had 2 explicit lengths.

spring lion Dec 14, 2025, 11:42 PM

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I think I see the vision??

spring lion Dec 14, 2025, 11:42 PM

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grave pond Each of the previous problems _also_ just had 2 explicit lengths.

I'm schizo I suppose

spring lion Dec 14, 2025, 11:42 PM

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spring lion I think I see the vision??

Let me see

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DBH DGH

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?

grave pond Dec 14, 2025, 11:43 PM

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Which roles can you write in each of those?

spring lion Dec 14, 2025, 11:43 PM

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One sec

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DB=18 long leg

grave pond Dec 14, 2025, 11:44 PM

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(Beware that the word "role" here is my own invention; it's not standard).

spring lion Dec 14, 2025, 11:44 PM

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DH=x=hypotenuse

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Is this correct so far?

spring lion Dec 14, 2025, 11:44 PM

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grave pond (Beware that the word "role" here is my own invention; it's not standard).

Alright

grave pond Dec 14, 2025, 11:44 PM

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Yeah.

spring lion Dec 14, 2025, 11:44 PM

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Okay gotcha

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DG=32=hypotenuse DH=x=long leg

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Right?

grave pond Dec 14, 2025, 11:45 PM

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Right.

spring lion Dec 14, 2025, 11:45 PM

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Alright

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Now hypotenuse/hypotenuse

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x/32?

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And long legs are:

grave pond Dec 14, 2025, 11:46 PM

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Okay so far.

spring lion Dec 14, 2025, 11:46 PM

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Hmmm

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Give me a min

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x/18?

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No no

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18/x

grave pond Dec 14, 2025, 11:47 PM

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Indeed.

spring lion Dec 14, 2025, 11:47 PM

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Alrightttt

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so the equation is:

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x/32=18/x?

grave pond Dec 14, 2025, 11:47 PM

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Yeah.

spring lion Dec 14, 2025, 11:48 PM

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24!!!

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It's correcttt

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Alright man last one. Let me thinkkk!

Screenshot_2025-12-15-02-50-38-186_com.android.chrome.jpg

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Uh...where's the second triangle?

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😭

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What do I do with this

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grave pond Dec 14, 2025, 11:52 PM

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There are actually two triangles here.

spring lion Dec 14, 2025, 11:52 PM

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Let me think

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ACB and AED?

grave pond Dec 14, 2025, 11:53 PM

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Yes.

spring lion Dec 14, 2025, 11:53 PM

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I'd need to find the "roles" though to confirm.

slim plinth Dec 14, 2025, 11:54 PM

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spring lion

Set a proportion

spring lion Dec 14, 2025, 11:55 PM

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Short legs are 6 and 8 could I do a ratio with those?

grave pond Dec 14, 2025, 11:56 PM

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Yeah.

spring lion Dec 14, 2025, 11:56 PM

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Okayy

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I'm confused about one part though.

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spring lion Dec 14, 2025, 11:57 PM

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spring lion

What's this?

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It doesn't look like hypotenuse or anything

grave pond Dec 14, 2025, 11:57 PM

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I read it as being BD.

spring lion Dec 14, 2025, 11:58 PM

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Yeah it's BD

grave pond Dec 14, 2025, 11:58 PM

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It doesn't need to be a side itself, as long as you can express all the sides you need somehow.

spring lion Dec 14, 2025, 11:58 PM

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Okay

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So first of all

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We got one ratio set!

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6/8

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And then next is

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The second ratio.

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6/8=8/(x+8)?

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I feel like this is definitely false...I'm not sure how I'm gonna find the short hypotenuse.

spring lion Dec 15, 2025, 12:03 AM

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grave pond It doesn't need to be a side itself, as long as you can express all the sides yo...

I'll wait till u respond I'm curious what this will be.

grave pond Dec 15, 2025, 12:04 AM

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spring lion 6/8=8/(x+8)?

Yeah, that doesn't look right. How did you get that second ratio?

spring lion Dec 15, 2025, 12:04 AM

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grave pond Yeah, that doesn't look right. How did you get that second ratio?

Yeah I knew it would be false ahh

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I just divided 8

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The one I circled.

grave pond Dec 15, 2025, 12:04 AM

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Which roles of which triangles are involved here?

spring lion Dec 15, 2025, 12:05 AM

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Well this one is wrong so none

grave pond Dec 15, 2025, 12:05 AM

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Yeah, but which roles of the triangles did you intend to use?

spring lion Dec 15, 2025, 12:05 AM

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Um

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Hypotenuse?

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grave pond Dec 15, 2025, 12:07 AM

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That's not the hypotenuse of anything in the diagram.

spring lion Dec 15, 2025, 12:07 AM

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Rip

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Long leg then?

grave pond Dec 15, 2025, 12:08 AM

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So what is the long leg of each of the two triangles?

spring lion Dec 15, 2025, 12:08 AM

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I mean the big long leg is x+8 right?

grave pond Dec 15, 2025, 12:09 AM

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Yes.

spring lion Dec 15, 2025, 12:09 AM

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I'm really not sure what's the small long leg.

spring lion Dec 15, 2025, 12:14 AM

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grave pond Yes.

What do you think?

spring lion Dec 15, 2025, 12:15 AM

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spring lion Short legs are 6 and 8 could I do a ratio with those?

OHHHH WAIT

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I HAVE ALZHEIMER'S

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I already found it here LMFAOOO

grave pond Dec 15, 2025, 12:16 AM

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Okay, so what do you get now?

spring lion Dec 15, 2025, 12:16 AM

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6/8=?(/x+8) I'm still not sure about ?

grave pond Dec 15, 2025, 12:16 AM

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Okay, so stepping back a bit, what is the small triangle?

spring lion Dec 15, 2025, 12:17 AM

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ACB

spring lion Dec 15, 2025, 12:17 AM

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spring lion ACB and AED?

.

grave pond Dec 15, 2025, 12:18 AM

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So the edges of that triangle are AC, CB, and AB -- what are the roles of each?

spring lion Dec 15, 2025, 12:18 AM

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AC hypotenuse

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CB=short leg=6

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Ohhh.

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OHHHHH I GET IT

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6/8=x/(x+8)

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??

grave pond Dec 15, 2025, 12:19 AM

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Yes.

spring lion Dec 15, 2025, 12:19 AM

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Let me do the equation

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6x+48=8x?

grave pond Dec 15, 2025, 12:20 AM

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Yeah.

spring lion Dec 15, 2025, 12:21 AM

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24 then

grave pond Dec 15, 2025, 12:21 AM

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Yes.

spring lion Dec 15, 2025, 12:21 AM

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HELL YEAHHHHHHHH

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BEST WAY TO SPEND 3 HOURS AFTER MIDNIGHT

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THANK YOU A LOT MANNNNN

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Sorry for being so slow

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🙏🙏🙏 GOD BLESS YOU

vale iron Dec 15, 2025, 1:12 AM

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euler to compute it into like trig identitie like e^I(A+B)

sly urchin Dec 15, 2025, 3:10 PM

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How can I prove this using complex numbers?

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I is the incenter and G is the centroid

wanton spear Dec 15, 2025, 4:38 PM

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👋

obsidian hornet Dec 15, 2025, 4:39 PM

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sly urchin How can I prove this using complex numbers?

If i remember correctly, then if a,b,c are complex coordinates of verticies (A) (B) (C) and A,B,C are side lenghts then we can write down that G =1/3(a+b+c), I = ((aA+bB+cC)/(A+B+C)) and N = ((p - A)a +(p-B)b + (p - C)c)/p and try to solve the equation g - a = 2( i - g). It seems like not the right way, coz i just tried to rewrite some barycentric coordinates in complex form, but i think it should lead to smth like that and you can try to rewrite it in correct form and solve. Maybe in some moment you need to rewrite lengths in |a-b| complex form.

magic sierra Dec 15, 2025, 5:45 PM

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spring lion

WhatsApp_Image_2025-12-15_at_11.15.11_PM.jpeg

magic sierra Dec 15, 2025, 5:46 PM

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magic sierra

here we use the concept of parallel lines and also similarity in which ratio of corresponding sides are equal

mellow moth Dec 15, 2025, 8:52 PM

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uh right so i dont have the question cause its in dutch and on my laptop which i do not have right now but i think i remember the question relatively well

its asking for the coordinates of the intersection with the outline of the cone and line OF
those points are S and U

oh right yea coordinates for the points are O(0,0,0), A(40,0,0), C(0,30,0), D(0,0,40) and T(20,15,40)
thats all thats given i mighta missed some stuff but its relatively minor im pretty sure

so yea i dont understand how to calculate the coordinates of S and U. the chapters on vectors and they want to solve it like A + ABt = C stuff like that

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ignore the ‘and’ im pretty sure thats supposed to be an e i dont know why it did that

jade sierra Dec 16, 2025, 1:25 AM

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magic sierra

i had the same question today

queen shadow Dec 16, 2025, 8:30 AM

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magic sierra

I think bro you made a mistake because x= 24

spring lion Dec 16, 2025, 12:01 PM

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Screenshot_2025-12-16-15-00-54-973_com.android.chrome.jpg

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How do I solve this?

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I can see the 10

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But that's it

obsidian harness Dec 16, 2025, 12:11 PM

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spring lion

PAM is another similar right triangle

spring lion Dec 16, 2025, 12:12 PM

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obsidian harness PAM is another similar right triangle

Okay

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I need to find the other side of the rectangle

next mantle Dec 16, 2025, 12:16 PM

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obsidian harness PAM is another similar right triangle

Similar to PAL?

obsidian harness Dec 16, 2025, 12:16 PM

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next mantle Similar to PAL?

they said they can see the 10 already

spring lion Dec 16, 2025, 12:20 PM

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Yeah

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Hmmm

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Wait actually.

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8/10=6/x maybe?

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7.5?

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Or wait

next mantle Dec 16, 2025, 12:23 PM

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obsidian harness they said they can see the 10 already

Yeah but what is PAM similar to?

spring lion Dec 16, 2025, 12:24 PM

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It's 75 then

next mantle Dec 16, 2025, 12:24 PM

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You said "PAM is another similar right triangle"

next mantle Dec 16, 2025, 12:24 PM

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spring lion It's 75 then

catthink

spring lion Dec 16, 2025, 12:24 PM

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next mantle <:catthink:526983414226747393>

breadthink

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7.5*10

next mantle Dec 16, 2025, 12:24 PM

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How is PM side 7.5?

spring lion Dec 16, 2025, 12:25 PM

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spring lion 8/10=6/x maybe?

.

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x in question here is PM.

next mantle Dec 16, 2025, 12:25 PM

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spring lion 8/10=6/x maybe?

What does that mean sotrue

spring lion Dec 16, 2025, 12:25 PM

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next mantle What does that mean <:sotrue:826971355542192148>

I just

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Let me write it.

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AL/PL=PA/PM

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No?

next mantle Dec 16, 2025, 12:27 PM

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But why?

spring lion Dec 16, 2025, 12:27 PM

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thinkfold

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Similar triangles

next mantle Dec 16, 2025, 12:27 PM

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Which triangle and which triangle are similar?

spring lion Dec 16, 2025, 12:27 PM

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PAM PAL

spring lion Dec 16, 2025, 12:28 PM

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spring lion AL/PL=PA/PM

This is probably a little off then.

next mantle Dec 16, 2025, 12:28 PM

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By which similarity criterion?

next mantle Dec 16, 2025, 12:28 PM

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spring lion This is probably a little off then.

Idk I'm genuinely asking, idk if you're wrong or right

spring lion Dec 16, 2025, 12:28 PM

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Angle angle?

next mantle Dec 16, 2025, 12:29 PM

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I see the 90⁰ angle (they're both right angle triangle(

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but that other angle is equal?

spring lion Dec 16, 2025, 12:29 PM

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Now idk about that part

next mantle Dec 16, 2025, 12:29 PM

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bro just said "similar triangles!" without verifying if the triangles are actually similar 🗿

spring lion Dec 16, 2025, 12:29 PM

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💀

tall lantern Dec 16, 2025, 12:30 PM

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👋

spring lion Dec 16, 2025, 12:30 PM

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next mantle bro just said "similar triangles!" without verifying if the triangles are actual...

How do I verify?

next mantle Dec 16, 2025, 12:31 PM

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I mean

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Are they actually similar?

spring lion Dec 16, 2025, 12:31 PM

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☠️

next mantle Dec 16, 2025, 12:31 PM

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What if they're not similar

spring lion Dec 16, 2025, 12:31 PM

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Then I can't solve this

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Lol

next mantle Dec 16, 2025, 12:31 PM

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Don't say that

spring lion Dec 16, 2025, 12:32 PM

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No they need to be similar for me to actually do something

next mantle Dec 16, 2025, 12:32 PM

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Giving up is easy, but it doesn't suit you

spring lion Dec 16, 2025, 12:32 PM

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Okay let's continue

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Where do I find a similarity in these triangles?

next mantle Dec 16, 2025, 12:33 PM

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I was thinking you could do something like this

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Apply pythagorean theorem twice and reduce it to solving a quadratic

#

idk maybe

spring lion Dec 16, 2025, 12:33 PM

#

next mantle Apply pythagorean theorem twice and reduce it to solving a quadratic

☠️

next mantle Dec 16, 2025, 12:33 PM

#

I'm just conjecturing

next mantle Dec 16, 2025, 12:34 PM

#

next mantle I was thinking you could do something like this

Here PM = y and LM - 8 = x

spring lion Dec 16, 2025, 12:34 PM

#

Huh

#

LM=8+x no?

next mantle Dec 16, 2025, 12:34 PM

#

Same thing?

spring lion Dec 16, 2025, 12:34 PM

#

Ohh

#

Algebra

next mantle Dec 16, 2025, 12:34 PM

#

Me when brainrot

spring lion Dec 16, 2025, 12:35 PM

#

Right lol

spring lion Dec 16, 2025, 12:35 PM

#

next mantle Me when brainrot

💀

#

My bad

next mantle Dec 16, 2025, 12:35 PM

#

splendid

#

np

next mantle Dec 16, 2025, 12:36 PM

#

next mantle Apply pythagorean theorem twice and reduce it to solving a quadratic

@spring lion see if that works, I haven't tried it yet

#

I'm reading Arc 4 sotrue

spring lion Dec 16, 2025, 12:36 PM

#

I didn't understand what that means

spring lion Dec 16, 2025, 12:36 PM

#

next mantle I'm reading Arc 4 <:sotrue:826971355542192148>

🗿

next mantle Dec 16, 2025, 12:36 PM

#

skill issue catglasses

spring lion Dec 16, 2025, 12:37 PM

#

y²=36+x²?

next mantle Dec 16, 2025, 12:37 PM

#

Yeah that's one equation

spring lion Dec 16, 2025, 12:37 PM

#

What's the other

next mantle Dec 16, 2025, 12:37 PM

#

now you can do the same with the other triangle

#

LUM

spring lion Dec 16, 2025, 12:37 PM

#

That's just 10 bruh

next mantle Dec 16, 2025, 12:37 PM

#

The other one

spring lion Dec 16, 2025, 12:37 PM

#

Oh

#

One sec

next mantle Dec 16, 2025, 12:38 PM

#

Holy triangle blindness

spring lion Dec 16, 2025, 12:38 PM

#

100+y²=64+x²

#

Or something

next mantle Dec 16, 2025, 12:38 PM

#

what the helly 🥀

spring lion Dec 16, 2025, 12:38 PM

#

Let me re check

next mantle Dec 16, 2025, 12:38 PM

#

ain't no way

spring lion Dec 16, 2025, 12:38 PM

#

next mantle what the helly 🥀

LMAO SHUT UP

#

Let me

#

Which one's the hypotenuse

next mantle Dec 16, 2025, 12:38 PM

#

"they hypotenuse"

spring lion Dec 16, 2025, 12:38 PM

#

8+x no?

next mantle Dec 16, 2025, 12:38 PM

#

sotrue

next mantle Dec 16, 2025, 12:38 PM

#

spring lion 8+x no?

Yeah

spring lion Dec 16, 2025, 12:38 PM

#

next mantle "they hypotenuse"

Typo

spring lion Dec 16, 2025, 12:39 PM

#

spring lion 100+y²=64+x²

Then why is this wrong

next mantle Dec 16, 2025, 12:39 PM

#

Apply Pythagorean theorem again

#

but slowly

#

step by step

spring lion Dec 16, 2025, 12:39 PM

#

Oh

#

Wait.

#

Right

#

next mantle Dec 16, 2025, 12:40 PM

#

ya

spring lion Dec 16, 2025, 12:40 PM

#

Okay

#

OHHHH

#

LMAOOO

#

I DID THE LEGENDARY BLUNDER

next mantle Dec 16, 2025, 12:40 PM

#

opencry

spring lion Dec 16, 2025, 12:40 PM

#

Quadratics about to slap my ass

#

Give me one second

#

(x+8)²

#

x²+16x+64?

next mantle Dec 16, 2025, 12:41 PM

#

Yeah

#

Where did X come from though?

#

You have both x and X 🗿

spring lion Dec 16, 2025, 12:42 PM

#

The x from PAM

spring lion Dec 16, 2025, 12:42 PM

#

next mantle Where did X come from though?

Bro the first letter of the sentence on mobile is always caps lock

#

🌹

next mantle Dec 16, 2025, 12:43 PM

#

Anyway you have two equations and two variables, you should be able to solve for x and y

spring lion Dec 16, 2025, 12:43 PM

#

Wait I don't understand one part, what do I do with these two equations?

#

thinkfold

next mantle Dec 16, 2025, 12:44 PM

#

Solve for x and y

#

y is what we need, x is just coming along for the ride

spring lion Dec 16, 2025, 12:45 PM

#

Ohh

#

Okay

#

Let me see.

#

Quadratics knowledge come onnnnn

spring lion Dec 16, 2025, 12:46 PM

#

spring lion 100+y²=64+x²

Do I start from here?

#

Man my brain's fried

next mantle Dec 16, 2025, 12:46 PM

#

spring lion Do I start from here?

isn't that wrong

spring lion Dec 16, 2025, 12:46 PM

#

Ohh

next mantle Dec 16, 2025, 12:46 PM

#

spring lion Man my brain's fried

take a 20 minute break and then come back

spring lion Dec 16, 2025, 12:46 PM

#

Right

spring lion Dec 16, 2025, 12:46 PM

#

spring lion x²+16x+64?

.

#

OHHH WAIT I GET IT

#

y²+100=x²+16x+64???

#

Is this finally right.

spring lion Dec 16, 2025, 12:49 PM

#

next mantle take a 20 minute break and then come back

👁️

next mantle Dec 16, 2025, 12:50 PM

#

spring lion y²+100=x²+16x+64???

Yes

spring lion Dec 16, 2025, 12:50 PM

#

I think??

#

Okayyy!

#

Now I put everything on one side of the equation?

next mantle Dec 16, 2025, 12:50 PM

#

spring lion y²=36+x²?

Now you have y^2 in terms of x^2

spring lion Dec 16, 2025, 12:50 PM

#

Ohh

#

RIGHTTTT

spring lion Dec 16, 2025, 12:50 PM

#

spring lion

^^^

next mantle Dec 16, 2025, 12:51 PM

#

Ya

spring lion Dec 16, 2025, 12:51 PM

#

spring lion y²=36+x²?

.

next mantle Dec 16, 2025, 12:51 PM

#

You can also do it the other way around

#

or maybe you can't

spring lion Dec 16, 2025, 12:51 PM

#

136+x²=x²+16x+64?

next mantle Dec 16, 2025, 12:52 PM

#

Ye

#

Now it's a quadratic in x

spring lion Dec 16, 2025, 12:52 PM

#

x² cancels out

#

136-64

next mantle Dec 16, 2025, 12:52 PM

#

Oh yeah

spring lion Dec 16, 2025, 12:52 PM

#

Hmmm

next mantle Dec 16, 2025, 12:52 PM

#

lol I didn't see that

spring lion Dec 16, 2025, 12:52 PM

#

72?

#

Okay yeah

next mantle Dec 16, 2025, 12:52 PM

#

,calc 136 - 64

somber coyoteBOT Dec 16, 2025, 12:52 PM

#

Result:

spring lion Dec 16, 2025, 12:52 PM

#

72-16x=0???

next mantle Dec 16, 2025, 12:53 PM

#

,calc 72/16

somber coyoteBOT Dec 16, 2025, 12:53 PM

#

Result:

4.5

next mantle Dec 16, 2025, 12:53 PM

#

x = 4.5

spring lion Dec 16, 2025, 12:53 PM

#

Ohhh

#

Okay

#

4.5

next mantle Dec 16, 2025, 12:53 PM

#

Now you can use x to find y

spring lion Dec 16, 2025, 12:53 PM

#

So

#

Yeah yeah.

spring lion Dec 16, 2025, 12:54 PM

#

spring lion y²=36+x²?

Let's go with this then?

#

What's 4.5^2

next mantle Dec 16, 2025, 12:54 PM

#

you can use the bot

spring lion Dec 16, 2025, 12:54 PM

#

I'm an old man idk technology

#

I'll just use calculator

next mantle Dec 16, 2025, 12:54 PM

#

,calc is the command

next mantle Dec 16, 2025, 12:55 PM

#

next mantle ,calc 72/16

Bro I just used it infront of you

spring lion Dec 16, 2025, 12:55 PM

#

Oh

next mantle Dec 16, 2025, 12:55 PM

#

sully

spring lion Dec 16, 2025, 12:55 PM

#

,calc 4.5^2

somber coyoteBOT Dec 16, 2025, 12:55 PM

#

Result:

20.25

spring lion Dec 16, 2025, 12:55 PM

#

Wow

#

Okay

#

36+20.25=y² then?

#

56.25?

next mantle Dec 16, 2025, 12:55 PM

#

Yeah

#

that's y^2 yeah

spring lion Dec 16, 2025, 12:56 PM

#

,calc 56.25=y^2

somber coyoteBOT Dec 16, 2025, 12:56 PM

#

The following error occured while calculating:
Error: Invalid left hand side of assignment operator = (char 6)

spring lion Dec 16, 2025, 12:56 PM

#

Rip

next mantle Dec 16, 2025, 12:56 PM

#

Now take the principal square root

spring lion Dec 16, 2025, 12:56 PM

#

spring lion ,calc 56.25=y^2

How do I do it with bot

next mantle Dec 16, 2025, 12:56 PM

#

spring lion ,calc 56.25=y^2

For taking square roots you need to do sqrt(45)

#

or something

spring lion Dec 16, 2025, 12:56 PM

#

Ohh

#

,sqrt(56.25)

#

Bruh

next mantle Dec 16, 2025, 12:57 PM

#

spring lion I'm an old man idk technology

400 years old?

spring lion Dec 16, 2025, 12:57 PM

#

next mantle 400 years old?

Yeah

next mantle Dec 16, 2025, 12:57 PM

#

spring lion ,sqrt(56.25)

no wrong command

#

the bot command is always ,calc

spring lion Dec 16, 2025, 12:58 PM

#

Oh

next mantle Dec 16, 2025, 12:58 PM

#

you then follow that by whatever you want to calculate

spring lion Dec 16, 2025, 12:58 PM

#

,calc sqrt(56.25)

somber coyoteBOT Dec 16, 2025, 12:58 PM

#

Result:

7.5

spring lion Dec 16, 2025, 12:58 PM

#

7.5!!!!!!!

next mantle Dec 16, 2025, 12:58 PM

#

opencry

spring lion Dec 16, 2025, 12:58 PM

#

ALRIGHT

next mantle Dec 16, 2025, 12:58 PM

#

sorry man, I guess the triangles were similar after all

spring lion Dec 16, 2025, 12:58 PM

#

next mantle sorry man, I guess the triangles were similar after all

Wow

#

But why?

next mantle Dec 16, 2025, 12:59 PM

#

spring lion

#

let's see

spring lion Dec 16, 2025, 12:59 PM

#

So y is 7.5... 🗿

#

75 then.

next mantle Dec 16, 2025, 1:00 PM

#

next mantle

maybe it's angle angle similarity but that's for the triangles PAM and LUM?

proper peak Dec 16, 2025, 1:00 PM

#

I was about to say you messed up an equation, didn't mean to be rude

#

I got 75 too

obsidian harness Dec 16, 2025, 1:00 PM

#

y = 7.5 is correct though

next mantle Dec 16, 2025, 1:01 PM

#

proper peak I was about to say you messed up an equation, didn't mean to be rude

No need to think it's rude, making mistakes is how people learn catthumbsup

obsidian harness Dec 16, 2025, 1:01 PM

#

if you understand similar triangles though it's literally y/6 = 10/8

spring lion Dec 16, 2025, 1:02 PM

#

obsidian harness if you understand similar triangles though it's literally y/6 = 10/8

Yeah but I didn't understand where we got the triangle similarity

#

I did get a 7.5 really early on

#

But that was just memorizing not understanding

next mantle Dec 16, 2025, 1:03 PM

#

obsidian harness if you understand similar triangles though it's literally y/6 = 10/8

Which two triangles though?

obsidian harness Dec 16, 2025, 1:04 PM

#

PMA similar to LPA

next mantle Dec 16, 2025, 1:04 PM

#

Oh yeah PAL and LUM by angle-angle similarity

spring lion Dec 16, 2025, 1:04 PM

#

thinkfold

obsidian harness Dec 16, 2025, 1:04 PM

#

or that also works

next mantle Dec 16, 2025, 1:04 PM

#

obsidian harness PMA similar to LPA

By which similarity criterion? catthink

obsidian harness Dec 16, 2025, 1:05 PM

#

AA again

next mantle Dec 16, 2025, 1:05 PM

#

Right angle is one thing, but what's the other angle

obsidian harness Dec 16, 2025, 1:05 PM

#

spring lion

angle LPA = 90 - angle MPA right?

so what's PLA = 90 - LPA equal to?

next mantle Dec 16, 2025, 1:05 PM

#

Oh I see it

#

Yeah I just missed it devastation

spring lion Dec 16, 2025, 1:06 PM

#

I don't see it ☠️

next mantle Dec 16, 2025, 1:06 PM

#

obsidian harness angle LPA = 90 - angle MPA right? so what's PLA = 90 - LPA equal to?

@spring lion read this

spring lion Dec 16, 2025, 1:07 PM

#

I understand the first one

#

OHHHHHHH

#

WE'RE BLIND 😭🙏

next mantle Dec 16, 2025, 1:08 PM

#

Who's we? 🥀

#

(but no fr we are)

next mantle Dec 16, 2025, 1:08 PM

#

spring lion OHHHHHHH

Did you get it?

spring lion Dec 16, 2025, 1:08 PM

#

next mantle Did you get it?

Yepp

#

I did the 2 other questions so I'm at 3/4 rn.

next mantle Dec 16, 2025, 1:09 PM

#

me when I waste your time for no reason getting to the same answer you got by a round about method

#

joia

spring lion Dec 16, 2025, 1:09 PM

#

next mantle me when I waste your time for no reason getting to the same answer you got by a ...

Lol nahhhh

#

Different ways of solving helps

next mantle Dec 16, 2025, 1:09 PM

#

But hey at least you learned a different way to solve it sotrue

spring lion Dec 16, 2025, 1:10 PM

#

Yep

next mantle Dec 16, 2025, 1:10 PM

#

something that's 2000 times more time consuming

spring lion Dec 16, 2025, 1:10 PM

#

Now there's this

Screenshot_2025-12-16-16-10-17-778_com.android.chrome.jpg

#

Umm

#

kongouderp

#

If I can't even do this on my own I'm cooked man...

#

So NW is x

#

OW is y

#

Would I be able to go with that?

#

...I don't think so.

obsidian harness Dec 16, 2025, 1:13 PM

#

spring lion If I can't even do this on my own I'm cooked man...

same idea again, triangle NWO is similar to NOS

spring lion Dec 16, 2025, 1:14 PM

#

Let me see.

#

NW is x and NW/NO=x/6?

#

Or wait

#

Should I go with 6/x?

obsidian harness Dec 16, 2025, 1:15 PM

#

it doesn't matter as long as the sides of the other triangle are in the right order

spring lion Dec 16, 2025, 1:15 PM

#

Right

obsidian harness Dec 16, 2025, 1:15 PM

#

NW / NO is slightly easier to cross-multiply though

spring lion Dec 16, 2025, 1:15 PM

#

Okay

obsidian harness Dec 16, 2025, 1:16 PM

#

since you want to find NW

spring lion Dec 16, 2025, 1:16 PM

#

I'll go with x/6 then.

#

NO=6 NS=8

#

x/6=6/8?

obsidian harness Dec 16, 2025, 1:17 PM

#

spring lion x/6=6/8?

yep!

spring lion Dec 16, 2025, 1:17 PM

#

Alright

#

Let me write that

#

8x=36?

#

4.5?

#

Okay

#

x is 4.5.

#

NW=4.5

#

Now Pythagorean theorem on the triangle...NWO?

obsidian harness Dec 16, 2025, 1:18 PM

#

spring lion Now Pythagorean theorem on the triangle...NWO?

yeah!

spring lion Dec 16, 2025, 1:18 PM

#

Give me 2 min

#

6²+4.5^2=OW?

spring lion Dec 16, 2025, 1:19 PM

#

spring lion 6²+4.5^2=OW?

I feel like this is false.

spring lion Dec 16, 2025, 1:20 PM

#

spring lion 6²+4.5^2=OW?

Is this right?

analog agate Dec 16, 2025, 1:20 PM

#

sorry I thought 6 was 9

obsidian harness Dec 16, 2025, 1:20 PM

#

spring lion I feel like this is false.

you're so close

#

$6^2 + 4.5^2 = OW^2$

somber coyoteBOT Dec 16, 2025, 1:20 PM

#

south

analog agate Dec 16, 2025, 1:20 PM

#

spring lion 6²+4.5^2=OW?

6² + 4.5² = OW²

spring lion Dec 16, 2025, 1:21 PM

#

spring lion 6²+4.5^2=OW?

Ohhh

#

OW²

#

Mb

#

Let's see

#

√56.25 again?

#

,calc sqrt(56.25)

somber coyoteBOT Dec 16, 2025, 1:21 PM

#

Result:

7.5

spring lion Dec 16, 2025, 1:21 PM

#

7.5.

#

8+10+6+7.5+4.5

#

No no

#

Lol

#

Um

#

24+12?

#

Is it 36?

obsidian harness Dec 16, 2025, 1:22 PM

#

spring lion 8+10+6+7.5+4.5

which sides are in the perimeter though

spring lion Dec 16, 2025, 1:22 PM

#

OHHH

#

RIGHT

obsidian harness Dec 16, 2025, 1:22 PM

#

7.5 is correct but

spring lion Dec 16, 2025, 1:23 PM

#

I made that mistake once before

#

Let me see wait.

#

SOW

#

Do I not include 6?

obsidian harness Dec 16, 2025, 1:24 PM

#

spring lion Do I not include 6?

mhm

spring lion Dec 16, 2025, 1:24 PM

#

30 then!!!

obsidian harness Dec 16, 2025, 1:24 PM

#

yep, it's 30

spring lion Dec 16, 2025, 1:25 PM

#

HELL YEAHHHHH

#

💪🤝🧠

#

@next mantle we did it :D

#

Thank you all

analog agate Dec 16, 2025, 1:26 PM

#

Can someone solve this one? I got 17.5 on this one. I am not sure, is it right, guys

next mantle Dec 16, 2025, 1:26 PM

#

Who's we lil' bro 🥀

#

jk

analog agate Dec 16, 2025, 1:27 PM

#

#

that is my solution

spring lion Dec 16, 2025, 1:28 PM

#

next mantle Who's we lil' bro 🥀

🗿

spring lion Dec 16, 2025, 1:31 PM

#

analog agate

Damn I solved the other ones but it looks like I can't move a finger on this question breadpensive

#

I really suck at geometry...

#

Sorry for not being able to help man.

analog agate Dec 16, 2025, 1:31 PM

#

spring lion Damn I solved the other ones but it looks like I can't move a finger on this que...

It's ok, I just want to know I am right or not

spring lion Dec 16, 2025, 1:32 PM

#

👍

analog agate Dec 16, 2025, 1:33 PM

#

I am just afraid that I might be wrong about BE because BE is an imaginary line that I drew to support the sum.

obsidian harness Dec 16, 2025, 1:35 PM

#

analog agate

if BE bisects angle B, then AE is not EC

#

think about what the angle bisector says

#

AE = EC would imply BA = BC

analog agate Dec 16, 2025, 1:36 PM

#

oh yeah, so I have find other way around to reprove that SAS cor

obsidian harness Dec 16, 2025, 1:38 PM

#

analog agate oh yeah, so I have find other way around to reprove that SAS cor

wait, are you allowed to use trig for this?

analog agate Dec 16, 2025, 1:40 PM

#

obsidian harness wait, are you allowed to use trig for this?

I don't know, I want to help someone who is stuck at that problem

#

I have to ask him

spring lion Dec 16, 2025, 1:46 PM

#

Is it bad that I can't solve it? 💀

cosmic kiln Dec 16, 2025, 1:46 PM

#

Yooo I am in class 10

#

Give me a question related toclass 10th

obsidian harness Dec 16, 2025, 1:49 PM

#

spring lion Is it bad that I can't solve it? 💀

not at all

#

this is several levels of difficulty ahead of what you're doing right now

#

even though it looks simple

spring lion Dec 16, 2025, 1:51 PM

#

obsidian harness this is several levels of difficulty ahead of what you're doing right now

Wait really??

obsidian harness Dec 16, 2025, 1:51 PM

#

spring lion Wait really??

yeah

spring lion Dec 16, 2025, 1:51 PM

#

Omg okay

#

Thank you

analog agate Dec 16, 2025, 1:53 PM

#

spring lion Is it bad that I can't solve it? 💀

If you can't solve this, it doesn't mean you are bad. I myself just solved this wrong

obsidian harness Dec 16, 2025, 1:53 PM

#

analog agate Can someone solve this one? I got 17.5 on this one. I am not sure, is it right, ...

if you're allowed trig:
(area of ADC)/(area of BDC) = AD/BD

hence (k * 5k/7 sin 2x)/(5 * 7 sin x) = 7/k

you also have sin(2x)/7 = sin(x)/k, solve simultaneously and that should be it

spring lion Dec 16, 2025, 1:54 PM

#

analog agate If you can't solve this, it doesn't mean you are bad. I myself just solved this ...

Okay

analog agate Dec 16, 2025, 1:54 PM

#

obsidian harness if you're allowed trig: (area of ADC)/(area of BDC) = AD/BD hence (k * 5k/7 sin...

yeah it is allowed

#

To be honest, tomorrow is physics and Bio exam for me, and I am spending my time solving this

obsidian harness Dec 16, 2025, 2:00 PM

#

obsidian harness if you're allowed trig: (area of ADC)/(area of BDC) = AD/BD hence (k * 5k/7 sin...

I think there's a problem with this question though

strong token Dec 16, 2025, 2:55 PM

#

analog agate

SAS doesnt work here ??

#

Right

obsidian harness Dec 16, 2025, 2:56 PM

#

strong token SAS doesnt work here ??

yeah, those are definitely not similar

strong token Dec 16, 2025, 2:57 PM

#

#

And for SAS

#

Like i am confused

#

Please help

upper echo Dec 16, 2025, 4:33 PM

#

analog agate Can someone solve this one? I got 17.5 on this one. I am not sure, is it right, ...

No, 17.5 is not correct

slim plinth Dec 16, 2025, 11:29 PM

#

Proof this

violet oasis Dec 17, 2025, 12:29 AM

#

@slim plinth

#

Was your question...

slim plinth Dec 17, 2025, 12:29 AM

#

What is this formula for

#

sin(a+k x 2pi)= sin(x)

violet oasis Dec 17, 2025, 12:30 AM

#

Oh okay.

slim plinth Dec 17, 2025, 12:30 AM

#

I only know sin(90-x)=cos(x)

violet oasis Dec 17, 2025, 12:32 AM

#

,tex $\text{Just use}\
\sin(A+B) = \sin(A)\cos(B) + \cos(A)\sin(B)$

somber coyoteBOT Dec 17, 2025, 12:32 AM

#

Restarter

violet oasis Dec 17, 2025, 12:35 AM

#

,tex $\sin(\alpha + k(2\pi))\
= \sin(\alpha)\cos(k(2\pi)) + \cos(\alpha)\sin(k(2\pi))\
= \sin(\alpha)(1) + \cos(\alpha)(0)\
= \sin(\alpha) [Q.E.D]$

somber coyoteBOT Dec 17, 2025, 12:36 AM

#

Restarter

violet oasis Dec 17, 2025, 12:50 AM

#

@slim plinth

slim plinth Dec 17, 2025, 12:50 AM

#

Thanks

violet oasis Dec 17, 2025, 1:47 AM

#

Welcome.

slim plinth Dec 17, 2025, 2:04 AM

#

Where do you use this formula

stuck creek Dec 17, 2025, 2:23 AM

#

Are inverse trig functions different to secant, cosecant and cotangent?

cunning lion Dec 17, 2025, 2:23 AM

#

yes, they are

#

"inverse" here means inverse when composing as functions, whereas secant, etc are inverses for multiplication

stuck creek Dec 17, 2025, 2:25 AM

#

Ahhh that makes a lot of sense, thank you cloud

short swift Dec 17, 2025, 3:21 AM

#

Hi I am in 8th grade taking Algebra 1 and I want to jump ahead into higher level classes so I need to learn Geometry. Is there any suggestions for textbooks or quality sources that I can study and learn Geometry in 6 months with? (I don't plan to use Khan Academy as a main source as it feels more like a practice source)

stuck creek Dec 17, 2025, 4:23 AM

#

Find the lengths of the missing
sides if side a is opposite angle A, side b is opposite
angle B, and side c is the hypotenuse.

$sin B = \frac{1}{2}, a=20$

somber coyoteBOT Dec 17, 2025, 4:23 AM

#

4E656F

stuck creek Dec 17, 2025, 4:24 AM

#

Does anyone have any tips for this? Just for understanding this problem intuitively

hybrid kestrel Dec 17, 2025, 4:25 AM

#

I would say the intuitive understanding comes from understanding how to draw the triangle, and knowing the definition of the trig function (in this case, sin is the ratio between the opposite side and the hypotenuse)

#

So I can kind of imagine how this triangle looks just based on the information they gave, and I can draw it out to visualize it clearly

#

Like sin(B) = 1/2 means the hypotenuse is 2 times as long as side b

shut thorn Dec 17, 2025, 5:05 AM

#

if xsin^3(A) + ycos^3(A) = sinAcosA and xsinA = ycosA. prove that x^2 + y^2 = 1
posting it here becasue i have to go in a while. I dont even know where to begin with this one. my mind like. Went blank

exotic yarrow Dec 17, 2025, 5:12 AM

#

shut thorn if xsin^3(A) + ycos^3(A) = sinAcosA and xsinA = ycosA. prove that x^2 + y^2 = 1 ...

Note that:
\begin{align*}
x\sin^3 A +y \cos^3 A &= x \sin A \cdot \sin^2 A+y \cos A \cdot \cos^2 A
\end{align*}

somber coyoteBOT Dec 17, 2025, 5:12 AM

#

Civil Service Pigeon

shut thorn Dec 17, 2025, 5:13 AM

#

oh oh

#

then you like

#

xsinA = ycosA

#

so take that common. and then youre left with uh

#

ycosA(sin^2(A)+cos^2(A))
which is ycosA

#

??

exotic yarrow Dec 17, 2025, 5:14 AM

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shut thorn ycosA(sin^2(A)+cos^2(A)) which is ycosA

keep going

shut thorn Dec 17, 2025, 5:15 AM

#

oh ycosA = sinAcosA
->y = sinA.

#

similarly x = cosA

#

OH I GOT IT

#

thanks

exotic yarrow Dec 17, 2025, 5:15 AM

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shut thorn thanks

catthumbsup

shut thorn Dec 17, 2025, 5:16 AM

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exotic yarrow <:catthumbsup:614540188747563008>

have this in return i guess

exotic yarrow Dec 17, 2025, 5:18 AM

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shut thorn have this in return i guess

lol ok

meager trellis Dec 17, 2025, 5:37 AM

#

Can someone help me with everything in first semester geo i have my final on thursday and im absolutely fried

violet oasis Dec 17, 2025, 5:38 AM

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meager trellis Can someone help me with everything in first semester geo i have my final on thu...

Snap your questions.

fringe moss Dec 17, 2025, 5:39 AM

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meager trellis Can someone help me with everything in first semester geo i have my final on thu...

I’ll help

meager trellis Dec 17, 2025, 5:39 AM

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fringe moss I’ll help

no u wont

fringe moss Dec 17, 2025, 5:39 AM

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meager trellis no u wont

sorry

meager trellis Dec 17, 2025, 5:39 AM

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fringe moss sorry

Open. up my eagercakez

#

im getting my study guide

fringe moss Dec 17, 2025, 5:40 AM

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meager trellis Open. up my eagercakez

TStoP

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Im mr brightjakes

meager trellis Dec 17, 2025, 5:40 AM

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No one make fun of me for the questions im about to ask

#

I swear im in in high school

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@fringe moss

violet oasis Dec 17, 2025, 5:42 AM

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???

#

Hello?

#

Any questions?

meager trellis Dec 17, 2025, 5:43 AM

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im ngl how do u do this bro

violet oasis Dec 17, 2025, 5:43 AM

#

From the diagram.

#

AC = CD.

#

So $4x-3 = 2x+9$.

somber coyoteBOT Dec 17, 2025, 5:44 AM

#

Restarter

violet oasis Dec 17, 2025, 5:44 AM

#

Solve for x.

#

Hello?

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No response?

meager trellis Dec 17, 2025, 5:48 AM

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okay thanks bro

violet oasis Dec 17, 2025, 5:49 AM

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Also.

#

An altitude is basically "height" of a triangle.

To form it, you draw a line from a vertex to it's opposite side perpendicularly.

meager trellis Dec 17, 2025, 5:52 AM

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wait so whats the difference between the altitude and the perpendicular bisector thing

#

oh nvm does the altitude have to be from the vertex

tribal edge Dec 17, 2025, 6:04 AM

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yes

violet oasis Dec 17, 2025, 6:10 AM

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meager trellis oh nvm does the altitude have to be from the vertex

Yes.

violet oasis Dec 17, 2025, 6:11 AM

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meager trellis wait so whats the difference between the altitude and the perpendicular bisector...

Perpendicular Bisector = perpendicular line passing through the midpoint of a straight line.

shut thorn Dec 17, 2025, 7:00 AM

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exotic yarrow lol ok

i have two more like these tbh 💔

minor smelt Dec 17, 2025, 8:19 AM

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idk if this is a bad question but I just started learning about trig functions like graphing, I was wondering how those relate to like the right angle triangle rules and what not

violet oasis Dec 17, 2025, 8:29 AM

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?

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Why is right angle triangle rule?

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I have never heard that in my life.

#

,tex
\begin{tikzpicture}
\coordinate (A) at (0,0);
\coordinate (B) at (3,0);
\coordinate (C) at (0,2);

\draw (A) -- (B) -- (C) -- cycle;

\draw (A) -- ++(0.3,0) -- ++(0,0.3) -- ++(-0.3,0) -- cycle;

\node[below left] at (A) {A};
\node[below right] at (B) {B};
\node[above left] at (C) {C};

\end{tikzpicture}

somber coyoteBOT Dec 17, 2025, 8:31 AM

#

Restarter

violet oasis Dec 17, 2025, 8:32 AM

#

Let angle B be our angle theta.

wise thorn Dec 17, 2025, 8:33 AM

#

Anyone know circles

violet oasis Dec 17, 2025, 8:36 AM

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Then \
$\sin(\angle{B}) = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{\text{AC}}{\text{BC}}$\
$\cos(\angle{B}) = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{\text{AB}}{\text{BC}}$\
$\tan(\angle{B}) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{\text{AC}}{\text{AB}}$\

somber coyoteBOT Dec 17, 2025, 8:36 AM

#

Restarter

violet oasis Dec 17, 2025, 8:36 AM

#

somber coyote **Restarter**

@minor smelt I hope this is what you meant.

If not, please elaborate further by providing an example.

violet oasis Dec 17, 2025, 8:37 AM

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wise thorn Anyone know circles

Of course.

A shape.

wise thorn Dec 17, 2025, 8:38 AM

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violet oasis Of course. A shape.

Bro circles proving

#

Circles is a type of geometry

#

We have

violet oasis Dec 17, 2025, 8:38 AM

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wise thorn Bro circles proving

Oh.

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You mean Circle Theorem?

#

Just send your question.

#

You don't have to ask if anyone knows it or not.

#

If not then what's the purpose of this group?

stuck creek Dec 17, 2025, 8:45 AM

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minor smelt idk if this is a bad question but I just started learning about trig functions l...

literally dying over here, slowly understanding it though

stuck creek Dec 17, 2025, 8:46 AM

#

violet oasis <@945233855571451914> I hope this is what you meant. If not, please elaborate ...

The special right angles, 45-45-90 and 30-60-90. Just wrapping my head around em rn, hard to imagine them scale

violet oasis Dec 17, 2025, 8:51 AM

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stuck creek The special right angles, 45-45-90 and 30-60-90. Just wrapping my head around em...

Oh....

#

They're not special right angles.

#

They're the special angles.

#

If that so...

#

I'll deal with that later.

stuck creek Dec 17, 2025, 8:52 AM

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violet oasis They're the special angles.

Oh, thanks for letting me know

grave pond Dec 17, 2025, 8:52 AM

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They're special right triangles, though.

stuck creek Dec 17, 2025, 8:53 AM

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Special right triangles, crazy

stuck creek Dec 17, 2025, 9:10 AM

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How to do this?

lone panther Dec 17, 2025, 9:15 AM

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stuck creek How to do this?

do you have a trig table or a calculator

#

If you don’t you’ll have to use the unit circle and memorize a few details

stuck creek Dec 17, 2025, 9:16 AM

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lone panther do you have a trig table or a calculator

I have calc. Ik that cosine sqrt(2)/2 is pi/4 or 45 degrees and then I'm stuck there

lone panther Dec 17, 2025, 9:19 AM

#

have you tried putting in arccosine of the same thing but with a negative sign just like in the problem

stuck creek Dec 17, 2025, 9:31 AM

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lone panther have you tried putting in arccosine of the same thing but with a negative sign j...

Isn't arccosine the same thing. Ik the answer, I just don't get how to get there. It says that you compute pi - pi/4 which equals 3pi/4 but yeah I dont understand these shapes

vapid jay Dec 17, 2025, 9:31 AM

#

its the same thing

#

-pi/4 is 45 degrees clockwise

#

grave pond Dec 17, 2025, 10:00 AM

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stuck creek Isn't arccosine the same thing. Ik the answer, I just don't get how to get there...

Try to plot the relevant points on the unit circle.

stuck creek Dec 17, 2025, 10:31 AM

#

grave pond Try to plot the relevant points on the unit circle.

Hmmm

random apex Dec 17, 2025, 11:00 AM

#

why do you need to convert the sin into whatever thats called in english instead of solving normally/how do you know when to do this? No graphing tool or CAS available

spiral lodge Dec 17, 2025, 11:07 AM

#

It's just one way of solving that equation

#

And it's probably the most straightforward, since you can then factorize a cosine

random apex Dec 17, 2025, 11:08 AM

#

Idk i tried just moving the sin over and i didnt even get enough answers, i guess i probably went wrong somewhere there?

spiral lodge Dec 17, 2025, 11:09 AM

#

spiral lodge It's just one way of solving that equation

Another way could be transforming the sin into cos or viceversa, using the fact that cos(a) = sin(π/2 - a) or sin(a) = cos(π/2 - a)

spiral lodge Dec 17, 2025, 11:09 AM

#

random apex Idk i tried just moving the sin over and i didnt even get enough answers, i gues...

Do you mind showing the steps you did?

random apex Dec 17, 2025, 11:11 AM

#

spiral lodge Do you mind showing the steps you did?

spiral lodge Dec 17, 2025, 11:12 AM

#

random apex

It seems all well done to me 🤔
What was the solution of the book?

violet oasis Dec 17, 2025, 11:13 AM

#

?

sudden folio Dec 17, 2025, 11:13 AM

#

(a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k

violet oasis Dec 17, 2025, 11:13 AM

#

sudden folio (a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k

Hi bro.

sudden folio Dec 17, 2025, 11:13 AM

#

how to use this bot

random apex Dec 17, 2025, 11:13 AM

#

spiral lodge It seems all well done to me 🤔 What was the solution of the book?

violet oasis Dec 17, 2025, 11:13 AM

#

sudden folio how to use this bot

Include the symbol $.

sudden folio Dec 17, 2025, 11:13 AM

#

$ (a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k

violet oasis Dec 17, 2025, 11:13 AM

#

violet oasis Include the symbol $.

At both the starting and the end of the sentence.

sudden folio Dec 17, 2025, 11:14 AM

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$ (a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k $

#

hmm

violet oasis Dec 17, 2025, 11:14 AM

#

$(a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k$

somber coyoteBOT Dec 17, 2025, 11:14 AM

#

Restarter

sudden folio Dec 17, 2025, 11:14 AM

#

oh

violet oasis Dec 17, 2025, 11:14 AM

#

violet oasis $(a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k$

You have to make them join.

#

No spaces in between.

#

Between the $ and the symbols before or after it.

sudden folio Dec 17, 2025, 11:15 AM

#

$Given that \sin \theta = \frac{3}{5} and \theta is in the first quadrant, find \cos \theta and \tan \theta.$

violet oasis Dec 17, 2025, 11:15 AM

#

sudden folio $Given that \sin \theta = \frac{3}{5} and \theta is in the first quadrant, find ...

For text.

#

Use \text.

#

$\text{Given that \sin{\theta} = \frac{3}{5} and \theta is in the first quadrant, find \cos{\theta} and \tan {\theta}.}$

sudden folio Dec 17, 2025, 11:16 AM

#

anyway how do i do trig

somber coyoteBOT Dec 17, 2025, 11:16 AM

#

Restarter

$\text{Given that \sin{\theta} = \frac{3}{5} and \theta is in the first quadrant, find \cos{\theta} and \tan {\theta}.}$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.49 ...ant, find \cos{\theta} and \tan {\theta}.}
                                                  $
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.```

sudden folio Dec 17, 2025, 11:17 AM

#

$\text{Evaluate } \int (3x^2 + 2x + 1) , dx$

somber coyoteBOT Dec 17, 2025, 11:17 AM

#

.

sudden folio Dec 17, 2025, 11:17 AM

#

oh ik how to now

violet oasis Dec 17, 2025, 11:17 AM

#

somber coyote **.**

Sorry, you're at the wrong place for this question.

sudden folio Dec 17, 2025, 11:17 AM

#

but now i know soh cah toa what should i learn next

#

trig

violet oasis Dec 17, 2025, 11:18 AM

#

Line 3.

sudden folio Dec 17, 2025, 11:19 AM

#

what’s line 3

spiral lodge Dec 17, 2025, 11:19 AM

#

random apex

Honestly, I can't figure out why your solution (which is also how I'd have done it) doesn't match

violet oasis Dec 17, 2025, 11:19 AM

#

random apex

$3\sin(-x) \neq 3\cos(\frac{\pi}{2} + x)$

somber coyoteBOT Dec 17, 2025, 11:19 AM

#

Restarter

spiral lodge Dec 17, 2025, 11:20 AM

#

Why not?

violet oasis Dec 17, 2025, 11:20 AM

#

This is the place where you did the mistake.

sudden folio Dec 17, 2025, 11:20 AM

#

can someone explain this

violet oasis Dec 17, 2025, 11:20 AM

#

spiral lodge Why not?

Where did you learn that?

sudden folio Dec 17, 2025, 11:20 AM

#

$\sin^2 \theta + \cos^2 \theta = 1
1 + \tan^2 \theta = \sec^2 \theta
1 + \cot^2 \theta = \csc^2 \theta$

somber coyoteBOT Dec 17, 2025, 11:20 AM

#

.

violet oasis Dec 17, 2025, 11:22 AM

#

somber coyote **Restarter**

Oh wait. I think they are equal.

random apex Dec 17, 2025, 11:22 AM

#

violet oasis This is the place where you did the mistake.

what is the mistake? This is what my equation book or whatever says

#

i see that its -x but the x is already negative

violet oasis Dec 17, 2025, 11:22 AM

#

Oh okay.

spiral lodge Dec 17, 2025, 11:23 AM

#

random apex what is the mistake? This is what my equation book or whatever says

Yeah that's correct, indeed

random apex Dec 17, 2025, 11:25 AM

#

spiral lodge Honestly, I can't figure out why your solution (which is also how I'd have done ...

yeah idk but the book seems to be correct

violet oasis Dec 17, 2025, 11:25 AM

#

random apex

Did you compare their quadrants?

random apex Dec 17, 2025, 11:27 AM

#

violet oasis Did you compare their quadrants?

i dont know what that means

violet oasis Dec 17, 2025, 11:27 AM

#

random apex

Okay...

#

I actually found a lot of mistake.

#

But fixing those won't come to your solution.

random apex Dec 17, 2025, 11:29 AM

#

i skipped noting down a bunch of steps incase thats the issue? if not could i get at least a hint or something

violet oasis Dec 17, 2025, 11:30 AM

#

somber coyote **Restarter**

Yeah this part is indeed the issue.

random apex Dec 17, 2025, 11:31 AM

#

i dont see it

#

like take x = pi and you get sin -\pi = 0 and

#

$\cos\left(\frac{\pi}{2}+\pi\right)=\cos\left(\frac{3\pi}{2}\right)=0$

somber coyoteBOT Dec 17, 2025, 11:36 AM

#

dinoaurus

violet oasis Dec 17, 2025, 11:40 AM

#

random apex

Well...

Last line

-π + 4πn = π + 2πn

random apex Dec 17, 2025, 11:43 AM

#

are they? i see that they meet occasionally but does that make them the same?

violet oasis Dec 17, 2025, 11:44 AM

#

Yes.

spiral lodge Dec 17, 2025, 11:44 AM

#

violet oasis Well... Last line -π + 4πn = π + 2πn

Mmh no. With -π+4πn you can't have -3π, for example

violet oasis Dec 17, 2025, 11:44 AM

#

spiral lodge Mmh no. With -π+4πn you can't have -3π, for example

?

violet oasis Dec 17, 2025, 11:45 AM

#

somber coyote **Restarter**

This thing itself is poorly justified you know?

violet oasis Dec 17, 2025, 11:45 AM

#

random apex

Just follow the normal way.

random apex Dec 17, 2025, 11:46 AM

#

violet oasis Just follow the normal way.

this loops back into me not knowing why it does this and why nothing else works nor do i know when to do that method

random apex Dec 17, 2025, 11:48 AM

#

violet oasis This thing itself is poorly justified you know?

its not exactly supposed to be, its a non graded practice problem im not being super rigorous, the idea is that since sin t = cos pi/2 - t and t here is -x it comes out as cos pi/2 -(-x)=cos pi/2 +x

spiral lodge Dec 17, 2025, 11:48 AM

#

Honestly, I feel like you're saying nonsensical things @violet oasis

violet oasis Dec 17, 2025, 11:49 AM

#

spiral lodge Honestly, I feel like you're saying nonsensical things <@1431204983126360098>

Okay I guess.

#

Then I will shut up.

spiral lodge Dec 17, 2025, 11:49 AM

#

somber coyote **Restarter**

Don't worry, this relation is perfectly valid

violet oasis Dec 17, 2025, 11:49 AM

#

And you continue.

#

To find the mistake

spiral lodge Dec 17, 2025, 11:52 AM

#

I found it, and it was pretty trivial

#

You just forgot to divide by 3 the 4πn on the bottom right equation

random apex Dec 17, 2025, 11:54 AM

#

why am i dividing it by 3

#

nvm looking at wrong iamge

#

oml well

#

thanks!

spiral lodge Dec 17, 2025, 11:55 AM

#

You're welcome 🤗

sudden folio Dec 17, 2025, 12:19 PM

#

#

wait i’m finally starting to understand trig

#

but this is easy trig

#

don’t mind the dividing fractions i sold

obsidian harness Dec 17, 2025, 12:24 PM

#

yeah was about to point out it should be 15/8

obsidian harness Dec 17, 2025, 12:25 PM

#

sudden folio but this is easy trig

nice work

sudden folio Dec 17, 2025, 12:26 PM

#

obsidian harness nice work

thanks idk why i find trig hard

#

,w If \cos \theta = \frac{8}{17} and \theta is in the first quadrant, find
\sin \theta \quad \text{and} \quad \tan \theta

obsidian harness Dec 17, 2025, 12:26 PM

#

sudden folio thanks idk why i find trig hard

these are pretty fun also

#

trigonometric proofs

sudden folio Dec 17, 2025, 12:27 PM

#

obsidian harness these are pretty fun also

i’ll try

obsidian harness Dec 17, 2025, 12:27 PM

#

sudden folio ,w If \cos \theta = \frac{8}{17} and \theta is in the first quadrant, find \sin ...

it's not GPT

sudden folio Dec 17, 2025, 12:27 PM

#

obsidian harness it's not GPT

oh

#

i understand it now

#

should i go to that next?

obsidian harness Dec 17, 2025, 12:27 PM

#

sudden folio should i go to that next?

sure

sudden folio Dec 17, 2025, 12:27 PM

#

is it ideal

obsidian harness Dec 17, 2025, 12:27 PM

#

wdym ideal

sudden folio Dec 17, 2025, 12:28 PM

#

like you wouldn’t go from addition to fractions u gotta build up

#

like subtraction

#

all the arithmetic

obsidian harness Dec 17, 2025, 12:29 PM

#

sudden folio

right, so if you can do this in all 4 quadrants

sudden folio Dec 17, 2025, 12:29 PM

#

oh shoot there’s 4

obsidian harness Dec 17, 2025, 12:29 PM

#

for example

sudden folio Dec 17, 2025, 12:30 PM

#

i thought there was only negative and positive

#

like 2

obsidian harness Dec 17, 2025, 12:30 PM

#

sudden folio oh shoot there’s 4

yes if you didn't realise sin(theta) could also be -15/17

so tan(theta) could also be -15/8

#

okay that's a serious gap in your knowledge

sudden folio Dec 17, 2025, 12:30 PM

#

i put +and minus

#

but first is plus

#

so i just put plus

#

alr imma do those questions ill answer them ill send it

obsidian harness Dec 17, 2025, 12:34 PM

#

just do question 1 first so that it's easier to correct mistakes

umbral raven Dec 17, 2025, 12:36 PM

#

KEK KEK

#

Is this B or A?

obsidian harness Dec 17, 2025, 12:38 PM

#

umbral raven Is this B or A?

select two that apply

sudden folio Dec 17, 2025, 12:38 PM

#

ok

umbral raven Dec 17, 2025, 12:41 PM

#

obsidian harness *select two that apply*

Would it be both?

obsidian harness Dec 17, 2025, 12:41 PM

#

umbral raven Would it be both?

which options?

umbral raven Dec 17, 2025, 12:41 PM

#

obsidian harness which options?

B and A

obsidian harness Dec 17, 2025, 12:41 PM

#

umbral raven B and A

yep!

#

clearly AA is not a congruence (all sides and angles equal) condition

#

you need 3 pieces of information for a triangle

#

more importantly, see if you can spot why ASA can be used

umbral raven Dec 17, 2025, 12:43 PM

#

I see it

obsidian harness Dec 17, 2025, 12:43 PM

#

umbral raven I see it

indeed

sudden folio Dec 17, 2025, 12:46 PM

#

this is hard i don’t think i got it right

#

ohh but isn’t it

#

sqrt 3 over 2

spiral lodge Dec 17, 2025, 12:48 PM

#

sudden folio sqrt 3 over 2

√(3/4) is √3 / 2, yes

#

So tanx = sinx/cosx

Meaning tanx = (-√3/2)/(-1/2)
Which equals √3

sudden folio Dec 17, 2025, 12:49 PM

#

spiral lodge √(3/4) is √3 / 2, yes

i can’t memorise the quardrant

#

see

#

i knew it was positive

spiral lodge Dec 17, 2025, 12:49 PM

#

First quadrant: x and y both positive
Then you increase the numeration by going counterclockwise

obsidian harness Dec 17, 2025, 12:49 PM

#

sudden folio i knew it was positive

really? the y-coordinate is positive in the 3rd quadrant?

sudden folio Dec 17, 2025, 12:49 PM

#

obsidian harness really? the y-coordinate is positive in the 3rd quadrant?

what is why

#

y

#

guys i need a new notes thing this one charges now

#

wait i remember

#

ward

#

a s t c

#

so first all

obsidian harness Dec 17, 2025, 12:51 PM

#

sudden folio wait i remember

like, these are the x- and y-axes

sudden folio Dec 17, 2025, 12:51 PM

#

second sine

sudden folio Dec 17, 2025, 12:51 PM

#

obsidian harness like, these are the x- and y-axes

is trig year 9 level

#

wait are u guys american

obsidian harness Dec 17, 2025, 12:51 PM

#

sudden folio is trig year 9 level

year 10 usually

obsidian harness Dec 17, 2025, 12:51 PM

#

sudden folio wait are u guys american

you following the British system right

sudden folio Dec 17, 2025, 12:51 PM

#

yeah

obsidian harness Dec 17, 2025, 12:51 PM

#

no I'm not American

#

I did IGCSE then IB

sudden folio Dec 17, 2025, 12:52 PM

#

i do gcse

#

uk

#

so i’m just trying to be ahead

#

cuz i’m in year 9

#

and maths is fun

obsidian harness Dec 17, 2025, 12:53 PM

#

sudden folio and maths is fun

~~you know what you're doing isn't even in GCSE~~

#

it'd be in year 12

sudden folio Dec 17, 2025, 12:53 PM

#

obsidian harness ~~you know what you're doing isn't even in GCSE~~

what

obsidian harness Dec 17, 2025, 12:53 PM

#

yeah

sudden folio Dec 17, 2025, 12:53 PM

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bro my math teacher

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said trig is in gcse

obsidian harness Dec 17, 2025, 12:53 PM

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sudden folio said trig is in gcse

true

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but not this trig

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basically you're limited to the sine rule and cosine rule

sudden folio Dec 17, 2025, 12:53 PM

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oh like pythagoras

obsidian harness Dec 17, 2025, 12:53 PM

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and don't forget your bearings

obsidian harness Dec 17, 2025, 12:54 PM

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sudden folio oh like pythagoras

yes, so you only need to care about the first quadrant

sudden folio Dec 17, 2025, 12:54 PM

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obsidian harness and don't forget your bearings

bearings easy just directions

obsidian harness Dec 17, 2025, 12:54 PM

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sudden folio bearings easy just directions

good, if you know your parallel line angle properties and think a bit, you're sorted

sudden folio Dec 17, 2025, 12:54 PM

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obsidian harness yes, so you only need to care about the first quadrant

i don’t want to just win i want to ascend

obsidian harness Dec 17, 2025, 12:54 PM

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you only need to do this at GCSE

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A levels doesn't bother with this

sudden folio Dec 17, 2025, 12:55 PM

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obsidian harness yes, so you only need to care about the first quadrant

that’s too easy bruh imma keep doing ts

obsidian harness Dec 17, 2025, 12:55 PM

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sudden folio that’s too easy bruh imma keep doing ts

honestly get an A level pure textbook

sudden folio Dec 17, 2025, 12:56 PM

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obsidian harness honestly get an A level pure textbook

wish i could

obsidian harness Dec 17, 2025, 12:56 PM

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cause there's basic definitions you're missing, such as the unit circle definition:

x-coordinate = cos theta
y-coordinate = sin theta

young mist Dec 17, 2025, 12:56 PM

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May anyone help with this

sudden folio Dec 17, 2025, 12:56 PM

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yeah

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actually

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no

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ur on ur own 😭😭

young mist Dec 17, 2025, 12:57 PM

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sudden folio ur on ur own 😭😭

is it that hard opencry

sudden folio Dec 17, 2025, 12:57 PM

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for me atleast

young mist Dec 17, 2025, 12:57 PM

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I would use chatgpt but nope

sudden folio Dec 17, 2025, 12:58 PM

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thanks

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help this guy

obsidian harness Dec 17, 2025, 12:59 PM

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young mist May anyone help with this

okay, where are you stuck?

young mist Dec 17, 2025, 12:59 PM

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obsidian harness okay, where are you stuck?

on finding the maximum and minimum turning points

obsidian harness Dec 17, 2025, 1:00 PM

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young mist on finding the maximum and minimum turning points

right, you just have to know the shape of the graph

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the maximum is at theta = 0

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the minima are at theta = -180 and 180

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for cos(theta)

slim plinth Dec 17, 2025, 1:01 PM

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I only know the identity sin(90-x)=cos and cos(90-x)=sin

young mist Dec 17, 2025, 1:01 PM

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obsidian harness the maximum is at theta = 0

is this for Y1=cos theta

obsidian harness Dec 17, 2025, 1:02 PM

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young mist is this for Y1=cos theta

yes

young mist Dec 17, 2025, 1:02 PM

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obsidian harness yes

oaky cool noted

obsidian harness Dec 17, 2025, 1:02 PM

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young mist oaky cool noted

do you know your function transformations?

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what does f(x/2) do to the function f(x)?

slim plinth Dec 17, 2025, 1:02 PM

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slim plinth I only know the identity sin(90-x)=cos and cos(90-x)=sin

Is this true

obsidian harness Dec 17, 2025, 1:02 PM

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slim plinth Is this true

yes

slim plinth Dec 17, 2025, 1:03 PM

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Can we have a - degree

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Like sin(90-180)

obsidian harness Dec 17, 2025, 1:03 PM

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slim plinth Like sin(90-180)

yes, true for all x

young mist Dec 17, 2025, 1:03 PM

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obsidian harness do you know your function transformations?

im still learning this topic its still kinda new to me

obsidian harness Dec 17, 2025, 1:03 PM

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obsidian harness what does f(x/2) do to the function f(x)?

okay, the answer is that it stretches everything in the x-direction by a factor of 2

young mist Dec 17, 2025, 1:03 PM

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slim plinth Can we have a - degree

nope you have to add 180 to the - degree

slim plinth Dec 17, 2025, 1:04 PM

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Aka sin(90+180)

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Or sin(90-(-180))