geometry-and-trigonometry

[daring pollen]

math is def my worse

well

shapes are

im good at memorizing formula's and stuff like that but turning and twisting shapes

not my thing

[wary swift]

is viper still here?

[trail tendon]

yeah

[wary swift]

i need him

yay

[trail tendon]

XD

[wary swift]

is x 53?

[trail tendon]

uhh

lemme see

[wary swift]

180-74

106

106/2

53

but i a pretty sure its wrong

[trail tendon]

how did u get 74

[wary swift]

64+10

and 64 comes from 32*2

[trail tendon]

oh

heres the weird thing

it says m<OEF, not m<DEF

doesn't that mean that its like uhh

? :l

i'm not sure

[wary swift]

well

wouldn't it be the same?

[trail tendon]

wait im stupid

its talking about the angle

[wary swift]

ye

[trail tendon]

not the arc length 💀

[wary swift]

oh lol

[trail tendon]

okok

doesn't htat mean arc length DF is 64?

[wary swift]

yep

[trail tendon]

thats horrible scaling

anyway

so EF wouldn't be 64 would it

[wary swift]

and ark ef is 2x+10

wait

why woudl EF be 64

[trail tendon]

it wouldn't

DF is

but you can find EF

[wary swift]

yeah

180-64-10

right?

that makes 106

106/2 bc it;s 2x

[trail tendon]

oh

[wary swift]

53

[trail tendon]

you did like two steps at once mb 💀

[wary swift]

53 is wrong tho 😦

[trail tendon]

yeah its 53 ur right

[trail tendon]

it is???

[wary swift]

idk why

but it says incorrect

[trail tendon]

nah what

[wary swift]

that's weird

[trail tendon]

ok so arc DF is 64

that scaling makes me think we did sum wrong

[wary swift]

yep

[trail tendon]

theres no way thats 64 degrees lol

[wary swift]

hmmmmm

true

[trail tendon]

i mean scaling isnt always correct but like

cmon that much off? 🤔

[wary swift]

looks like it's 140 degrees

well

[trail tendon]

fr

[wary swift]

more like 120

smth like that

im not a pro

huh

i mean i could move on to the next problem

[trail tendon]

i'm confused now ngl ☠️

[wary swift]

same

i think i need someone really good at math to help

time to ask chatgpt

[trail tendon]

💀

[wary swift]

he got it wrong too

but thats no suprise

[trail tendon]

did he get same answer

he 💀

[wary swift]

no

[trail tendon]

what did he get

[wary swift]

he got 50

[trail tendon]

uh

huh

i wouldn't have inputted a response from a bot but whatever 💀

[wary swift]

wat

[trail tendon]

thats a different problem

oh is that another of ur problmes

[wary swift]

yep

[trail tendon]

dude im ngl i need to review geometry

lol

i cant think of how to do this lol

[wary swift]

same

[trail tendon]

XD

[wary swift]

pls help

[upper karma]

🙏🏽help

[trail tendon]

what's the amplitude of the function?

[jagged wyvern]

Can somebody help please?

[upper karma]

Draw it first

[jagged wyvern]

<@&286206848099549185> Not sure if im allowed to use this in this channel

I would have to send 2 pics in 1

I appreciate the suggestion though

[ionic crypt]

help

[dark sparrow]

don't post your problem in multiple channels. pick one and stick to it.

[amber hollow]

why does this evluate to 1? cos^2 + sin^2 = 1, and the square should cancel out the negative no?

[dark sparrow]

did you miss the "not" in your sentence?

[amber hollow]

yes

[dark sparrow]

ie you meant "Why does this not evaluate to 1?"

[amber hollow]

yeah mb

[dark sparrow]

anyway

a^2 - b^2 isn't the same as a^2 + (-b)^2

10^2 - 9^2 is 19 not 181

[amber hollow]

oh

[bitter tundra]

for the first question, a circle has 360 degrees, and since there are 24 total time zones divide 360 by 24. For the second question count the amount of time zones in between and multiply by previous result. The third question mentions 180 degrees which is important. 180 degrees is basically a line so just draw a line to the opposite side of the circle dividng it into semicircles and whichever time it lands on is the answer

[vocal bison]

Halp plz i got 740 gallons but the answer key says 1280 gallons

[amber hollow]

im not sure how to go about this one since im not given the length of any sides

[mortal steeple]

u have the base the question says 2 consecutive mileposts

[amber hollow]

oh

so is one of thse sides 2 miles?

[mortal steeple]

if you draw the diagram you can use tan to find the height

[amber hollow]

does a milepost denote a mile?

[mortal steeple]

i think so

otherwise the question is insolvable

[amber hollow]

all right

[mortal steeple]

im pretty sure you would get 2 triangles hope this helps!

[amber hollow]

But one of them isn’t a right angle triangle?

[dark sparrow]

show work?

[vocal bison]

My work or the key

[dark sparrow]

your work

[dark sparrow]

if i wanted the answer key i would have asked for the answer key

,calc 1/3 * (64 * 8 - 36 * 6)

[somber coyote]

Result:

98.666666666667

[dark sparrow]

hm, seems like we agree here

does the answer key just say "1280 gal, figure it out we aren't sharing any work"

[vocal bison]

no it has work thats wy i asked if u wanted it cuz im cofnused

[dark sparrow]

ok can you show what the answer key shows

[dark sparrow]

,calc 1/3 * (64 * 8 - 36 * 6) * 7.5

[somber coyote]

Result:

740

[dark sparrow]

hold up

512/3 isn't equal to 98 2/3 now is it

,calc 98*3+2

[somber coyote]

Result:

296

[dark sparrow]

so it's the answer key that is fucked

[vocal bison]

oop not the answer key being wrong

das crazy

[dark sparrow]

is your teacher the kind that touts the answer key as inherently infallible and all who disagree shall be punished by expulsion

hopefully not

[vocal bison]

no he just posts it he dont rlly care sometimes its wrong sometimes its right but he doesnt make them so 🤷‍♀️

[slender kelp]

How do I solve the top question I tried using |ABxAC|/2 but it dosnt work

[dark sparrow]

in what way does it not work?

[slender kelp]

Like after applying the formula I am not getting the answer

[dark sparrow]

show your work?

could be an arithmetic mistake.

[slender kelp]

Wait let me redo the one rn is messed up

[dark sparrow]

|BA × BC| should be 2 sqrt(6) tho.

[slender kelp]

Oh I didn't notice got the answer thanks

[slender kelp]

How do I solve 48th question in this is unit vector u=i+j+k or just i, and do I apply scalar triple product directly after putting unit vector u

[dark sparrow]

i+j+k is not a unit vector

no, u isn't necessary just i

you should think geometrically what the scalar triple product means and how to maximize it

[cold schooner]

In my geometry class we were asked to find the fixed point of a glide reflection in $\mathbb{E}^2$. Is it correct that there are none, unless the translation is the trivial one.

[somber coyote]

zlik

[dark sparrow]

a glide reflection is a reflection followed by a translation parallel to the refl axis, right

[cold schooner]

Yes

[dark sparrow]

ok then yeah no fixed points

[silent dawn]

yo guys am i correct?

[sonic bloom]

Q16 read the congruent and those from the question, not the shape cuz i drew some incorrectly

[dark sparrow]

,rccw

[sonic bloom]

@dark sparrow can u chrck #help-16 i wrote stuff there and can u say if its correct

[midnight basin]

where is logarithims?

[upper karma]

#prealg-and-algebra or #precalculus

[dark sparrow]

^

[lavish halo]

Heyo how can i calculate sin cos tan without a calc?

[sonic bloom]

Is this correct

[sonic bloom]

The slightly showing line oj the second pic is nothing btw ignore it

[kind cairn]

Can anyone recommend where I’ll find good information about affine and projective transforms it the context of Euclidean geometry?

[trail tendon]

visiualizing the unit circle

you can only do it with specific angle values though

unless you mean all the values in which case

idevk thats pretty hard

[lavish halo]

Ah gotcha

[bitter tundra]

@hoary totem turns out the geometry problem I asked you about worked my way, it was just an error in my calculator

[north kindle]

Infinite series?

[hoary totem]

oh

[jagged wyvern]

Why is 318 wrong?

Cuz i assumed vertical angles are the congruent so QR is congruent to ST

So i used 360 - minor arc = major

360 - 42 = 318

[trail tendon]

this is true

[trail tendon]

the minor arc is not 42

[jagged wyvern]

I dont get it

[trail tendon]

ok

[jagged wyvern]

Uh

[trail tendon]

ur finding the black arc length right

why did i choose black

the line is already black 💀

but can u see what i mean

thats the arc length QST

[jagged wyvern]

I think yes but i visualized it differenlty

[trail tendon]

how did you visualize it

[jagged wyvern]

I drew the line from Q across the diameter to S, then the arc to T

[trail tendon]

you mean like

[jagged wyvern]

Looks like the SPT angle but bigger

[trail tendon]

uhh

[jagged wyvern]

Im not really sure

[trail tendon]

i'm not really sure what you mean

but anyway

you understand that they are looking for the arc length right?

[jagged wyvern]

Yes

Wait i can just add the other known lengths right?

Instead of using the 360 - minor to get it

Because I thought arc QST was in that specific order so i visuallized it differently

So it should be 222 deg got it

[trail tendon]

👍

[trail tendon]

it is tho

its the arc from QS, then the arc from QT

not the line QS and then the arc QT or smthn

[jagged wyvern]

Why not just write

"QRST"

🤷‍♂️

[trail tendon]

idk, cuz they didnt need to

thers only one arc that goes through QST

they coulda also said QRT

as long as they didnt say QT

which would be the minor arc

[empty yew]

💀

[green crane]

Hey

Can i have help

[dark sparrow]

,rccw

[dark sparrow]

@green crane still here?

[green crane]

Yes

[dark sparrow]

what do those "1" and "2" refer to? they're kind of stuck in the middle of the two small triangles so i can't tell what they mean

[green crane]

Triangle number triangle number 1 and triangle number 2

[dark sparrow]

hm

[green crane]

U can delete them

Not important

[dark sparrow]

ok, that might be better with either Roman numerals or a # sign before them

just so they aren't confused for measurements

ok anyway

the other notation quotation i have is: are the dot and star marks meant to denote equal angles?

[green crane]

Yes

[dark sparrow]

ok

so with that out of the way, what's your progress thus far?

[green crane]

AD perpendicular on cb

[dark sparrow]

well that much is clear, i see the right angle mark

[green crane]

Thats only my brain has stopped

I wanna know x but i can't

[dark sparrow]

ok so that's a verbose way of saying "no progress"

right.

do you know basic trig?

like SOH CAH TOA kind of trig

[green crane]

No

Im in 2nd prep

In Egypt

[dark sparrow]

"2nd prep" doesn't tell me much but ok.

alright but you do know pythagoras at least right

[green crane]

8th grade

[green crane]

Yes

[dark sparrow]

ok

[green crane]

And eclidian

[dark sparrow]

and i see you also wrote that ABD is similar to CAD

[green crane]

Yes

[dark sparrow]

... what is "euclidean" supposed to mean here

[green crane]

Two right angles

[dark sparrow]

?

[green crane]

Right angle and a perpendicular to the other side

[dark sparrow]

???

it sounds like you're saying sth i might be indirectly familiar with but not under that name

[green crane]

Ok ok thats mean the we can get ca power 2 with cd x cb

[dark sparrow]

CA^2 = CD * CB?

[green crane]

Yes

And there others

[dark sparrow]

hmm

so then AD^2 = CD * DB should also be accessible

[green crane]

AB power 2 = db x bc

[dark sparrow]

use the symbol ^ for exponents and * for multiplication

[green crane]

Ok

AD=(ca+ab)÷2

[dark sparrow]

??

that's not true, is it?

[green crane]

This is the therom

[dark sparrow]

are you absolutely 120% sure that you are stating the theorem correctly?

AD = (AC+AB)/2 sounds super wrong to me

[green crane]

Yes

True

I swear

No no

Not ÷2

÷ cb

[dark sparrow]

...

[green crane]

Sorry

[dark sparrow]

????

that makes even less sense

[green crane]

This is true

U can try it

[dark sparrow]

AD = (AC+AB)/CB is nonsense

the left hand side is a length while the right hand side is dimensionless.

so there's no way that's true

[green crane]

So u can solve this

I swear thats true

Eclidian therom

Search

[dark sparrow]

don't call me bro.

[green crane]

Man

[dark sparrow]

i am not a man either.

[green crane]

Sorry 😐

[dark sparrow]

please edit the "bro" out of your message.

or delete it outright

anyway, if you had not started this bullshit (AC+AB)/2 stuff, i would have suggested the following:

express CD and DB in terms of x with Pythagoras, and then apply AD^2 = CD * DB.

[green crane]

Man thars nor Pythagoras

This also eclidian

[dark sparrow]

this snippet is not displaying correctly

and ALSO

if you read what i am saying

i say to use Pythagoras AND THEN Euclid's theorem

[green crane]

U are true continue

[dark sparrow]

i said what i wanted to say already

[cursive viper]

Would the statement “a line does not cross itself” hold when drawing on a Euclidean Cylinder. Obviously not for a vertical line or an angled line, but does a horizontal line cross itself technically?

[upper karma]

hi, quick question, what kind of uh.. idk kind of math is this? x⁴ - 8x³ -4x² - 2x - 10 ?

like linear or quadratic something, what's the name for the equation above? equations that have a lot of different exponents?

i need to search it to YouTube so i can study how to solve that but I don't know what to search

[trail tendon]

it's a fourth degree polynomial

[upper karma]

Polynomial

That’s also not an equation

There’s no = symbol

[trail tendon]

its an expression

[upper karma]

This belongs in #prealg-and-algebra too ig

[trail tendon]

tbf he literally didnt know what it was

lol

[upper karma]

oh i see, thank you very much!!

To be fair it’s an algebraic expression

[smoky jetty]

one way u could help yourself ubderstand this intuitively is by trying to dissect the right triangle into 3 similar triangles, then find the correspoding sides, set their ratios in proportion, then simplify, and there u have it, the formulae you're told to memorize

[tropic hare]

Hey guts! Did you heard about Ceva's Theory

AC1/C1B * BA1/A1C * CB1/B1A = 1

???

[fallow palm]

Well-known.

[jagged wyvern]

You can just use proportionality btw

[vernal pilot]

That’s a quartic expression. More generalised that’s a 4th degree polynomial. If you are googling it either one would work.

[tall coral]

Could you elaborate? I'm not following

3d shapes don't use lines

[cursive viper]

Like take a horizontal line in $R^2$ then apply a projection mapping on that line so it’s in the fundamental domain defined by the translation $T_{(1,0)}$. Many points on that $R^2$ line will map to the same point, but like does that technically count as a self-intersection.

[somber coyote]

LSGUnon

[gentle haven]

I mean I think it depends on how you interpret it.

If you interpret "cross" as "intersect at an angle" then it still holds.

[sonic bloom]

Is this question that the teacher brought us correct? Because at the top it says 45 and 75 (the angles) and they dont add to 180 and its a line (the three lines are parallel btw)

Nvm she didnt say the two lines are parallel tho

[kindred bluff]

guys help

<@&286206848099549185>

[trail tendon]

did u draw a picture

[kindred bluff]

yup

still didn't get it

[trail tendon]

u understand the problem but dont know how to do it?

cuz honestly neither do I 🤣

nah but ye

[kindred bluff]

you gonna solve it?

[trail tendon]

im gonna try...

[kindred bluff]

do it asap, cuz its 3am here and i am gonna sleep after this

[trail tendon]

ok man xD

[merry parrot]

i mean, i dont think he's a robot

[kindred bluff]

thats why i mentioned "asap"

@merry parrot you gonna try?

[merry parrot]

nope, ik its one of those abominations

[trail tendon]

what is P_1?

i cant read the subscripts very well lol

like the straight line SP_1

does it just mean SP?

[merry parrot]

no

P1 is another point

[trail tendon]

ohh im stupid

[kindred bluff]

lol

[merry parrot]

show us your working in the meantime

[trail tendon]

this seems like it needs calculus lol

but hold up

[trail tendon]

whats M?

wherd that come from

[kindred bluff]

tell me that approach, iam curious

[kindred bluff]

i made it up, thats how maths wroks, lol

[trail tendon]

i mean i could be wrong but to find the slope of the tangent line at point P you would implicitly differentiate the function, unless im wrong 🤷‍♂️

i don't see another way to work with the tangent line but there could be

this may not be necesary though

[kindred bluff]

do it anyway

[trail tendon]

lemme try

i dont know if it helps :l

i don't have a strategy to solve it lol

my brain hurts what the heck is this problem ._.

[merry parrot]

im assuming the point P1 is somewhere on the right side of your page

aha

[trail tendon]

where the two lines intersect yeah, whether he drew it in or not xD

[merry parrot]

the distance S_1M

[trail tendon]

how do you figure

[merry parrot]

is beta*sin(alpha/2)

[kindred bluff]

yup

[trail tendon]

how do you...know....

[merry parrot]

the line segment S_1M is perpendicular to that tangent

its a right triangle

so sin(alpha/2) = S_1M/beta

[trail tendon]

ohhhhh

bruh

[kindred bluff]

u got it?

i think i did

[trail tendon]

the answer?

[merry parrot]

also, ik that this question is from JEE advanced and im pretty sure it uses some "jee trick"

[kindred bluff]

idk

[trail tendon]

dude JEE problems and AOPS problems are toxic

literally

idevk

[kindred bluff]

see

[kindred bluff]

whats AOPS?

[merry parrot]

yup there you go

d1d2 = b^2

'jee trick'

[kindred bluff]

thats property ig

[merry parrot]

which you're meant to learn for it 💀

[merry parrot]

[kindred bluff]

.

[trail tendon]

a math......thing

[kindred bluff]

lol

[trail tendon]

company/school/program?

idk

idk exactly

it just has math problems and courses and stuff

and books

and the stupidest math problems

that make you think "outside the box"

or smthn

💀

[inner vapor]

wdym

[trail tendon]

i mean they're hard for arguably no reason

they may teach you techniquest that you'd use in math competitions but you'd never actually use them irl for pretty much anything 💀

at least thats my perspective

[inner vapor]

wdym toxic?

they are only exercises how they can be toxic to you

even if they are hard why toxic?

[trail tendon]

toxic as in poison, which is painful lol

[trail tendon]

i actually dont konw if JEE is actually useful, i was talking about AOPS

but anyway

yea they hard for me 💀

like nearly impossibly hard

maybe because i dont know those special mathemetician techniques or smth

[inner vapor]

I have been reading
zeits: art and craft of problem solving
and engel: problem solving strategies

maybe you find them useful

anyways, I am not an expert or anything, I just really like this ones, you should check them aswell

[trail tendon]

👍

[surreal escarp]

If the formula for the surface area of the pyramid is base plus 1/2 (perimeter) (slanted height) why isn’t this equation (written by my teacher) multipled by 40?

[trail tendon]

why would you multiply by 40?

you're adding the areas of each surface

[surreal escarp]

cuz of the base

[trail tendon]

the base is 40

but you aren't finding the volume

you're finding the surface area

right?

[surreal escarp]

yea but what do u do with the 40?

or do u just not do anything with it?

[trail tendon]

you add it

[surreal escarp]

oh ic

[trail tendon]

you add the area of the base to the area of all the other sides

yea

i should have said you add the area of the base to the sum of the areas of all the other sides

[surreal escarp]

oh i see

think im just confused because i keep mixing up the adding and multiplication

for all the other equations

[trail tendon]

ahh yah

[jagged wyvern]

#1231343544241885224 Could someone help please

[empty yew]

Don't you love mathematics????😱😱😱😱

[trail tendon]

not when i have no clue whats going on

[empty yew]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[trail tendon]

imagine you're in a room and everyone is speaking in a different language bro

☠️

[empty yew]

🤣🤣🤣

[trail tendon]

i should have said everyone is speaking in a language different from yours

but nah

they all speaking a different language from each other 💀

[empty yew]

Why are you going to that hard questions?

Seek for the questions based on your knowledge!

[trail tendon]

wanna be good at math but some math just seems like only possible if you have a really deep understanding of math and are creative in applying it :l

[empty yew]

🙂

[trail tendon]

im decently good at stuff that ive already been taught

but once it gets to creative approaches

🗿

no idea what im doing fr

[empty yew]

🤣

[trail tendon]

i guess i just gotta learn the actual CONCRETE math that is more methodical

and less like a different method for every single problem 😡

[empty yew]

I have a doubt one min

Anyone help

I don't know where to begin with

@trail tendon do you know about this?

Sorry if it is creative 😁

[trail tendon]

uh

[trail tendon]

drawing a picture 👍

[trail tendon]

i don't know if i know 💀

i dont know how to solve the problem off the top of my head but maybe if i try

[trail tendon]

😤

yea nah idk 💀

[empty yew]

@trail tendon Yea nah?

[trail tendon]

nah i dont know how to solve it

at least i dont think

[empty yew]

Yes but what is yea nah 🤣🤣😁

[trail tendon]

🤣

it was like a yeaaaah no

yno

yesn't

[empty yew]

Anyone help

[jagged wyvern]

Does anyone know what level of math is geometric series taught in the US? Cant find any results on google

[empty yew]

It's tenth grade in India

I don't know about US

[empty yew]

<@&286206848099549185>

Anyone help me

I don't know where to begin

[rugged shuttle]

Geometry is taught usually in 8th or 9th grade and sequences/series are taught in 11th

[tall coral]

It may help to use similarity properties rather than congruency theorems

[golden trout]

any idea how to approach this problem? I'm completely lost

[dark sparrow]

first find the parametric equations of the ray

then find its point of intersection with pi, and its reflected direction vector

and then finally the parametric equations of the reflected ray

[brisk ore]

Guys I'm learning how to translate and transform trigonometric graphs, I'm confused on how we find the new y axis. For example: y = cos(x+45) this would be a shift to the left by 45 right? That would also change the y axis so how do I know what the new y int would be? Would I do y = cos(0+45) ?

[nocturne remnant]

Yes, just sub x=0

[golden trout]

is there a relation between the direction vector and the reflected one?

cause that's what's confusing for me

[dark sparrow]

well yeah

do you know how to reflect a vector in a plane

[golden trout]

nope lmao

[nocturne remnant]

Do you know how to project a vector onto a plane?

[golden trout]

I do know how to find the perpendicular projection of a line in a plane, if that's what you're asking, then yes

[brisk ore]

if we had y = 3cos(x) would we multiply the y intercept by 3 only? do we shift the graph by anything

[dark sparrow]

so first you might want to look up stuff on reflecting a vector in a plane

[inner vapor]

there is a vector projection formula but idk if its useful, also I wanted to point out the normal vector of the plane pi is (2, 1, 1) and the direction vectors of the planes in r is (1, 1, 1), (2,-1,1), dunno if thats useful

[golden trout]

i'll look up abt it

I thought about creating a line with the same angle but the opposite one so the angle r makes with pi is the same as substracting that value to 180 and then using that to create the line

idk if that's too complicated, or even possible

[golden trout]

could be, if we know the vectors from the planes with create r, it's vectorial product is the direction vector of the plane

after that I dunno how to continue lmao

[inner vapor]

we need to know the projection formula aswell

[golden trout]

yeah that's easy, but this might be the key

thanks

[brisk ore]

is there an asymptote at 180 degrees?

[dark sparrow]

does it look like there is one?

[golden trout]

First, you could answer what Ann says, then if they ask you to prove it, you could do the limits from the left and right

Depending on what you get you'd prove whether there's an asymptote or not

[brisk ore]

sorry my sister called me

no there doesnt

[brisk ore]

Is that integration? I don't think proofing this will appear in our exams tho but thanks

[golden trout]

Nope

Rhe lateral limits evaluate to what value does the function approach for a certain value for x

I guess you must have been taught them

[brisk ore]

Alr

You know in curves

When we differentiate the equation of a curve, we get something including x = 0 right

If we solve for x what does that x coordinate signify?

[golden trout]

Wdym?

Do you mean what does solving the differentiation for x=0?

[brisk ore]

Like

When you get the differentiated equation

And solve for x what does that x value mean? Is it a coordinate at a special point

[golden trout]

If i remember it correctly, solving for x means the points where the function changes its monotony

For example, if the differentiated equation solves as x=2, you obtain a candidate for a point where on the right could be increasing, and after x=2 would be decreasing, or viceversa.

In general, you obtain the values that could be candidates for maximums or minimums of the function

Have I explained myself? Lmao

[brisk ore]

Hm ok

Then for this question

I’m thinking that I would differentiate the curve equation then equate it to 0 and sub in the x value of 4? If that makes sense to find the gradient

[upper karma]

This belongs in #calculus by the way

[brisk ore]

I’m not doing the integration part

[upper karma]

Oh

[brisk ore]

It’s above what we’ve learnt for now

[upper karma]

Differentiation is still in calculus

[brisk ore]

Oh yh mb I’ll finish this question then go

[brisk ore]

^ @golden trout only part I’m confused on is that if we slap in the x value of the point p, would we need to find the negative reciprocal of the gradient that we find because it’s a tangent?

[golden trout]

What?

I'm confused with the question || Sorry, I'm not native english and I might not fully understand the question ||

[ruby wigeon]

This is a grade10 level problem extracted from my Chinese friend's test paper

wild

[brisk ore]

Ignore the shaded part r because in school we haven’t learnt how to do that, part a) the information they give us is the equation of the curve which is the first equation, and line l is a tangent to the curve at point P. Point P has x coordinate 4 and we aren’t given y coordinate

[brisk ore]

No worries I get that

I’ll check the mark scheme when I get on my laptop

[golden trout]

Right

Soy could get it by substituting in the main equation of the curve x=4

Then you just apply the tangent formula to get the equation of the tangent and you can prove it

[rugged shuttle]

Help on number 2

I also tried squaring both sides but that didn’t lead anywhere

[rugged shuttle]

Oh hell no that is actually crazy

[gentle haven]

are you trying to solve for x

[rugged shuttle]

Trying to verify identity

[marble cliff]

het I have question, its for a firend of mine im not really sure if someone can help
So he wants to draw a geodesic
in the poincaré ball
he has two points A and B, and he wants to draw the geodesic l
which is a circle arc that goes through A and B, and that is perpendicular to the yellow circle at its intersections
The circle in red, denoted C, is the poincaré disk
and the circle in green (with center H) is my geodesic candidate
he wants to show that the geodesic candidate is correct
it is clear that the circle in green goes through A and B, because H lies on the perpendicular bisector of [A, B]
but he has yet to show that it is perpendicular to the circle in red at the intersections
I am not all that convinced that it is the case to be completely honest

[civic salmon]

I think Heron’s formula is easier for finding the area of a triangle when you have all three sides (a, b, c)

s = (a + b + c)/2 (half of the circumference)

A = sqrt(s(s - a)(s - b)(s - c))

[jagged wyvern]

Could someone help please?
How do i determine what type of angle this is?

Answer choices are central angle, right triangle, acute, obtuse, cannot be determined

I managed to eliminate central, acute, and cannot be determined

Central angle would be right if only 1 point was in the center

Acute isnt an option because point Y could be anywhere, because it could be stretched across the field

So could it be obtuse angle? Someone pls confirm

[trail tendon]

why can't it be "cannot be determined"?

[jagged wyvern]

I dont really know but i used up all my "check answer" opportunites

[jagged wyvern]

It was marked wrong though

[trail tendon]

really?

[jagged wyvern]

Ye

[trail tendon]

ohh anywhere on the CIRCLE mb

[jagged wyvern]

Huh

Yes

[trail tendon]

ok so uh

[jagged wyvern]

Ye

[trail tendon]

i know the answer but i forgot the proof as to exactly why 💀

[jagged wyvern]

Uhh

[trail tendon]

do you know the unit circle

from trig

[jagged wyvern]

I have but i havent learned it yet

[trail tendon]

ok

but

[jagged wyvern]

But what

[trail tendon]

you know how like

wait im stupid

thats not a goodp roofat all

cuz that stems from the radius

hmm

i dont know how to prove it but its right

🤔

[jagged wyvern]

Right triangle?

[trail tendon]

ye

[jagged wyvern]

Alr...

[trail tendon]

idk how to prove it tho sorry 😭 💀

[jagged wyvern]

Ye it's all good

All my teacher cares about is the math part

Well in exams

[trail tendon]

lol

[jagged wyvern]

But ye it's fine

Ty

[trail tendon]

np

[vocal bison]

Help pls

[lime dune]

what is the radius of the sphere?

how can you find it?

[vocal bison]

well i know how tod o that its just this part when u get to the surface area how do u take teh cube root and stuff without using a calc

[trail tendon]

you don't

451 is an estimation

its actually like 450.7 ish

[vocal bison]

wait

then what would i put on my test would i just leave it as the cubed root

[trail tendon]

if your test does not allow a calculator it is unlikely that they would put a problem like that on there

but if you do, then yeah probably

[vocal bison]

oh alr

thanks

[trail tendon]

or you could do ur best to round

but honestly they wouldn't put that on a no calculator test lol

[lapis adder]

does anyone here know what the Geometry CBE test is like?

[vocal bison]

thats good to know

[jagged wyvern]

Can somebody help please? The only useful info I found was diameter KM is 180 degrees.

And I cant tell arc FM = 92 is gotten from angle L or the point of the 2 lines where they intersect

Wait i see something

Since KLM is a diameter. KFM should be also 180,

Alr this is what I got to

Both the L from KL and LM is equal to 90 degrees

I dont know where to proceed from here someone help please

[trail tendon]

um

whats that fourth letter thing

[jagged wyvern]

M

[trail tendon]

ok

do you know the arclength LM?

[jagged wyvern]

Uhh nope

[trail tendon]

oh yeah right 💀

i forgot lol

[jagged wyvern]

Ye

[trail tendon]

dang bruh

[trail tendon]

do you know trig functions

[lethal vector]

kind of

[trail tendon]

do you know soh cah toa?

[lethal vector]

yes

[trail tendon]

do you know what they mean?

[trail tendon]

ooh you can find each of the parts of angle L though

right

using the opposite arc length

LOL

OR EVEN EASIER JUST FIND THE ARC LENGTH OPPOSITE THE ANGLE LOL

[trail tendon]

ey bro

[jagged wyvern]

The opposite from 92?

[trail tendon]

opposite from ?

[jagged wyvern]

Arc FM is 92

From angle L

[trail tendon]

so whats arc FK

[jagged wyvern]

88

Dang i did not realize that wow

[trail tendon]

can u find the angle then

yeah

XD

we were overthinking it

lol

[jagged wyvern]

I can continue from here

Ty lol

[trail tendon]

👍

[jagged wyvern]

Use inverse of cos of angle A

Cosine = Adj/Hyp

[lethal vector]

oops i was using inverse sin

[trail tendon]

XD

try inverse cosine lol

[swift light]

How did i get the last one wrong?

and how did they get that number

[upper karma]

The angle should be positive

add 2pi to your answer and it should be correct

[swift light]

why should it be positive

[swift light]

ohhh i see

thank you👍

[swift light]

bro

how did they get that

[upper karma]

The angle shouldn’t be above 2pi

Subtract your answer by 2pi until you get an angle that fits the inequality

[swift light]

for -7+7i i got tan^-1(7/-7) and got -pi/4

if i keep subtracting its not gonna fit in the inequality

[upper karma]

Subtract or add by 2pi until the angle is in the correct range

Because 30 degree is essentially the same as 390 degrees, 750 degrees, etc.

[swift light]

when i put 7pi/4 they also said its wrong

[upper karma]

Show your work

From arctan(7/-7) to -pi/4

Did you consider the quadrant?

[swift light]

ah i see now i shouldve paid attention to the quadrant

[sterile crown]

don't square

usually you'd focus on one side

[dusky bear]

is there were high school is?

can anyone help me with this,

[dark sparrow]

what does 2b+b simplify into?

[dusky bear]

uhhhhhhhhhhh

2b

i think

[hoary totem]

not quite

[dark sparrow]

so the extra b vaporizes into thin air then?

[dusky bear]

yessssssssss

nvm i got the answer someone help me

how are ya'll so smart

[dark sparrow]

https://tenor.com/view/are-you-sure-john-cena-ru-sure-about-dat-gif-14258954

2 boxes plus another box doesn't make 2 boxes.

[dusky bear]

it does because i ate the other box

think outside of the box

[dark sparrow]

this feels like a joke

@dusky bear are you here to get help or are you here to troll?

[dusky bear]

i actually need help fr

[dusky bear]

no trolling

[dark sparrow]

so then you're serious about thinking 2x + 1x is equal to 2x?

or are you not

[dusky bear]

ye i was b4

[dark sparrow]

2+1 is equal to 3, not 2.

review collecting like terms.

[dusky bear]

ohh

i thought it was different for varibles

[dark sparrow]

@dusky bear do you need help with anything else at the moment

[marble cliff]

@dark sparrow can you help me with a hyperbolic geometry question

[dark sparrow]

!noping

[lime crown]

Please do not ping individual helpers unprompted.

[dark sparrow]

but you are better off sending the question than asking to ask

[marble cliff]

that is true

i did that

but the thing is i do not know if its now

i asked first at algebric geometry. They send me here but i do not think that its here

and its not for me

its for a friend of mine

they told me that its here

but the thing is its hyperbolic geometry and here its geometry and trigeometry

[marble cliff]

sorry!

[rich scroll]

Is naming points in an exam allowed? So basically the blank ink represents the given points, but the blue is the one i added, for my teacher didnt have those points as given. Is this allowed?

[dark sparrow]

what could possibly be wrong with it?

[rich scroll]

Idk if the teacher allows it

[dark sparrow]

is your teacher ultra-strict?

if not, then i think it's perfectly fine. just make it clear what label refers to what on your diagram.

[sand bough]

god help me

[vernal pilot]

What with?

[cobalt mauve]

someone help, my teacher didnt discuss this.

[sand bough]

Lessons 6-2, 6-3 & 6-4: Properties & Classifications of Parallelograms_PPT

[vernal pilot]

Idk what you are talking about. Post a picture of the question.

[vernal pilot]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[vernal pilot]

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[vernal pilot]

Do you the properties of a rhombus?

[sand bough]

yes

[vernal pilot]

Then what can you deduce about AD given AB=9?

Here, I’ll post a list of properties of a rhombus from google

[sand bough]

thank you :)

i have it from here now thank you, i found a yt vid

[upper karma]

How tf do I do this I got no sleep last night

[dark sparrow]

@upper karma do you know how to find the circumference and area of a full circle?

[upper karma]

No 🥲

I’m an idiot academically

All I know is 360 and that’s it

[dark sparrow]

C = 2πr and A = πr^2

do you know these?

these should have been taught somewhere and it would be good (necessary, even) to remember them.

also you should not just know "360" -- maybe something like "360 degrees make a full circle"?

[upper karma]

No.5 is tripping my balls how do I do that one

[dark sparrow]

#5 is exactly half of the whole circle.

[upper karma]

So 180 but what do I do with the 7m

[dark sparrow]

7m is the radius

[upper karma]

Ok ty

[dark sparrow]

it is indicated with the same level of explicitness as all the other questions.

[outer wadi]

Use form pi r^2 x/360(for area). Or 2 pi r x/360(for length) where x is ur angle

[dark sparrow]

pi, not pie.

[outer wadi]

Mb

[trail tendon]

i like pie

what's wrong with pie

[dark sparrow]

the name of the greek letter π is spelled pi.

[trail tendon]

pie > pi 😭

[outer wadi]

ONG

[dark sparrow]

are you being serious right now or just pulling my leg?

[trail tendon]

i know the difference but pie is better you gotta admit

[dark sparrow]

like is this a serious argument for "i think the name of π should be spelled <pie>"?

[trail tendon]

nah

i think the food pie is better than the number pi

[outer wadi]

It sounds correct

[trail tendon]

👍

[dark sparrow]

these categories are incomparable.

[trail tendon]

um

[outer wadi]

I was just hungry so like

[trail tendon]

same

[dark sparrow]

it makes no sense to compare food items with numbers and deem one "better" than the other.

[trail tendon]

it's better because i like it more in my opinion, and its probably liked more by many people

[outer wadi]

Look food releases the happy hormone pi releases stress hormone

[trail tendon]

😂

[dark sparrow]

i feel as if y'all are being difficult on purpose.

[outer wadi]

LOL maybe

[trail tendon]

wdym difficult 😂

pie is literally better than pi

we dont need perfect circles we need food

[dark sparrow]

and the shape of most pies straight out of the oven is...?

[trail tendon]

a non perfect circle

[outer wadi]

Any shape IDC as long as it's not burnt

[trail tendon]

we did not need pi in order to create pie

[dark sparrow]

why do i even bother with you people.

[outer wadi]

Maths is good only in school

To get marks

[trail tendon]

you're very technical just accept pie is better 🤣

[trail tendon]

well nah its good irl

pi is ok yeh

but pie is better

mhm

[dark sparrow]

i like pie as much as the next person, i just think it supremely silly to keep insisting upon a comparison between a food item and a number as if it is an objective truth.

what's better: asparagus or the number 38.77234?

[outer wadi]

If u got some time help in precalculas if u know it

[trail tendon]

asparagus

[trail tendon]

send problem

maybe in precalc chat

or wutever

[outer wadi]

Just check that

Precalc chat

[lusty dirge]

Please help, I try but get confused in the end

[lime dune]

what specifically have you tried?

show us all of your work

[trail tendon]

"prove" is so generic

:l

[plush badge]

Who wants to do this geometry assignment for me and ill give them money on cashapp

[trail tendon]

how about instead you post the problem and get help for free 🤔

[plush badge]

The ai bot help shit doesnt work

[trail tendon]

it is doe

[trail tendon]

we're not talking about ai we're talking about real people

like you can just post ur problem here and if ppl know how to do it they can help lol

[plush badge]

Nobodys gonna do it

They say #❓how-to-get-help

[trail tendon]

occasionally they say that but honestly a lot of the time ppl just post their question here

and yeh

[trail tendon]

ok first problem

do you know the circumference of a circle formula?

[trail tendon]

yo?

🗿

[plush badge]

Yo

No

[trail tendon]

ok

the circumference of a circle is 2 * pi * radius

so like if the radius is 1, the circumference is 2pi

and it wants you to round so you'd use a calculator

but in each problem it gives you a radius

basically just multiply the radius by 2 * pi

to get the circumference

ri

thats for the first few btw not the entire thing but yeh

[crimson thunder]

am i aloud to ask for help now

[plush badge]

@trail tendon Can you do the whole assignment ill give you money on cashapp

Ive legitimately tried every single thing online to do it and nothing works

[trail tendon]

dude i can help you it's not actually that hard lol

like you can do it

do you have a calculator?

you just have to press like four buttons for each problem XD

[trail tendon]

sure?

did you get redirected to a help channel last time 😂

[crimson thunder]

i didn't know where to ask for help

also i have the first part of this problem i just need the r^2 part

x^2+(y+4)^2=
is what i have so far

[trail tendon]

ah

[crimson thunder]

i just forgot how to find the radius with a point and center

[trail tendon]

plug in the other point you got for x and y, and you should get the radius

squared

right

[crimson thunder]

oooh

thanks

[trail tendon]

👍

[trail tendon]

do you have a calculator

[crimson thunder]

im gonna be honest i have no idea what you mean by this

[trail tendon]

they gave you the center and a point on the circle, right

[crimson thunder]

yes

[trail tendon]

like this, thats obviously not where the point is but yeh

i wrote down the wrong center but

XD

anyway so far you have x^2 + (y+4)^2 = r^2 right?

[crimson thunder]

yes

[trail tendon]

so if you plug in a point (x,y) into x^2 + (y+4)^2 with numerical values for x and y, you can get the numerical value of the radius

am i still being confusing lol

[plush badge]

Yeah

But like if its not that hard just do it for me youd be a lifesave

R

[trail tendon]

it isn't hard once you know how to do it

so when you actually encounter this again you can know how to do it

[trail tendon]

do you know what pi is

you can say no lol

;-;

why do ppl disappear so much 😂

[crimson thunder]

it gives me 43 so do i square it and thats my circle?

no no i do not\

[trail tendon]

what do you think you do

[crimson thunder]

i don't know

x^2+(y+4)^2= 43 gives me a circle but the points not on it

[trail tendon]

it doesn't ask for the points on it

it asks for the equation of a circle

[crimson thunder]

im dumb

[trail tendon]

xD

[crimson thunder]

ty so much

[trail tendon]

np

and uh

i dont think its 43

(sqrt(44))^2 + (-5 + 4)^2 = 44 + (-1)^2 = 45 ?

ri

or am i trippin lol

wait

but ye

right?

[crimson thunder]

idk

im tripping

[trail tendon]

🤣

alr so

[crimson thunder]

you are off by .002

im so sorry

[trail tendon]

wut 🤣

[crimson thunder]

thats what my calc says

nvm

i have bad aim

[trail tendon]

how do you get off by 0.002 🤣

[crimson thunder]

you are smart

[crimson thunder]

idk

[trail tendon]

☠️

[trail tendon]

nah like the radicals get taken care of so everything is whole numbers XD

aaanyway

the equation of a circle means

if (x,y) is on the circle then if you plug x and y into x^2 + y^2 = r^2 or whatever your formula is then the equation should be true

if it isn't true, (x,y) isn't on the circle

yk

[crimson thunder]

i learned this today, forgot my notes, didn't pay attention during the entire note taking thingy, and got 3rd place on the kahoot

i don't know

[trail tendon]

🤣

[crimson thunder]

i was playing pokemon showdown the entire time 💀

[trail tendon]

💀

[crimson thunder]

i make very good accedemic descesions trust

[trail tendon]

😂

[trim goblet]

How do I even put this into a graphing calculator, or solve it without one?

[red flax]

Can someone explain this without doing inverse 😇🙏

Since there’s no videos that show the way my teacher wants me to do it

[lime dune]

"without doing inverse" is utterly stupid, why would you ever do that

but if you insist,

let $X=\begin{bmatrix}a&b\c&d\end{bmatrix}$

[somber coyote]

elrichardo1337

[lime dune]

and multiply out the LHS

[red flax]

I’m still confused