geometry-and-trigonometry

[trail tendon]

they probably just assume that they haven't taught domains yet so the student won't even think about it

[mint nexus]

yes

it really isnt anything crucial

[lime dune]

that is ... a highly questionable way to teach it but ok

hmm aight

[trail tendon]

she may not even had the unit circle yet

they teach triangles first sometimes

[lime dune]

she* 🤓

[trail tendon]

no unit circle, so no + 2kpi

[mint nexus]

yea, thats the problem. theres a lack of directions

[lime dune]

yea

😔

[trail tendon]

sorry 💀

[lime dune]

lmao

[trail tendon]

bro just got through finished how he questions it being the teachers fault and then says the way they taught it was questionable...

🤣

is funi

[lime dune]

i'm hesitant to jump to conclusions until i actually see hard evidence

is all

[trail tendon]

yeah that makes sense

i'm more on the side of teachers being confusing because

i have been confused a lot 💀

teachers say all these definitions and stuff and im like what

then i go home and study it and it clicks

[lime dune]

i've been through my share of bad k-12 teachers as well

[mint nexus]

idk, its probably concerning that the other geometry teachers have higher success rates with their students as compared to mine. thats what my first red flag was until i started noticing how vague the assigned questions were

[lime dune]

hmm

[trail tendon]

have you had the unit circle

[lime dune]

tbf a lot of them are underpaid and/or do not have particularly strong math knowledge

[mint nexus]

ive gone to extra help with him too, dude just gives answers instead of properly explaining how he got the answer

[trail tendon]

LOL

[lime dune]

damn 😭

[trail tendon]

sometimes teachers go over the solution really fast and assume you get it too

when you hvae no idea what they just said

then they just move on

[mint nexus]

my high school is considered really good/at the top in my state. i dont think its that...

[lime dune]

you'll learn that those stats are largely meaningless

i went to a "bLUe rIBbOn" high school that was an absolute fucking joke

[mint nexus]

yea, it also might just be the want to finish the lesson in one period too. but its not a good idea. other teachers seem to take 1-3 days to teach it and they get better success rates. its just his preference of teaching is poor or something

[mint nexus]

thats fair tbh

[lime dune]

lmao

[mint nexus]

actually yea 100% schools tend to keep shady shit to themselves for dat cute lil rank

[lime dune]

such is the way

😔

[mint nexus]

🙌

[lime dune]

and it doesn't necessarily get better when you get to undergrad either

which is a shame

the math department at my uni is kinda a dumpster fire lmao

[mint nexus]

man oh man how the school system in the u.s never fails to disappoint but amaze me

someone send me to finland, they got that cool Montessori system and i heard its better

[trail tendon]

the school system is kinda mid

everyone knows that to some extent lol

unless they don't

and disagree

[mint nexus]

finland just seems to have more success all around

[trail tendon]

probably better school system lol

[mint nexus]

europe in general maybe...? maybe not

[quaint copper]

Did he solve the question in the end

[mint nexus]

👍

[quaint copper]

Nice

[trail tendon]

yeah thats a good question 💀

[quaint copper]

Btw another way you could've gone about it is dividing by cos(x) on both sides to get tan(x)=1 just so you know the alternate methods

Sin/cos is tan

[lime dune]

while that does work

[mint nexus]

idk if that is applicable

[lime dune]

i don't think they've gotten to that yet

[mint nexus]

yes

[quaint copper]

Oh ok calm

[mint nexus]

will take it regardless for the future

🙌

[trail tendon]

i know this is a stupid question but how do you get 45 outta that besides taking arctan

and visaulizing it

[lime dune]

45-45-90 triangles

the two legs are equal in length

[trail tendon]

what if it wasn't 1

[quaint copper]

What he said

[trail tendon]

what if it was 4

well

💀

i really just said that LOL

[lime dune]

then there isn't as nice a form for it

[quaint copper]

Arctan 4 needs calculator

[lime dune]

yea

[trail tendon]

yea

i guess thats not really applicable anyway

cuz if it was 4 you couldn't use the og method

[tawny panther]

If A+B+C=180°
Then (cotA+cotB+cotC)/(cotA.cotBcotC) will be

[dark sparrow]

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[tawny panther]

1

I tried to use cot(a+b) formula which doesn't help me

[dark sparrow]

show work?

[tawny panther]

<@&268886789983436800>

What should i do next?

[dark sparrow]

i have a feeling that this question is either underspecified or just wrong

it is not constant

are you sure that you didn't forget anything from the question? maybe there are some answer options and we're not looking for just a number?

as it stands, and as it is written, the question expects a single number as an answer. but it is impossible to give one, because (cot(A)+cot(B)+cot(C))/(cot(A)cot(B)cot(C)) is not constant even with the constraint of A+B+C=pi.

[tawny panther]

Here are the options

[dark sparrow]

the one non-constant option doesn't fit either.

and there is no "none of the above" option.

so the question is just wrong.

[dusky locust]

is common proof exercise with A + B + C = 90
not 180

[tawny panther]

If it is 90°

Then it easy to get answer =1

[dark sparrow]

yeah but the problem says 180°, not 90°.

and we cannot just pretend it said 90.

is this question important at all? or is it skippable?

[tawny panther]

Skippable

Thanks for desmos representation ann

[dusky locust]

if u r interested in legitimate exercise, u can show this is ||1 + secA secB secC||

[tawny panther]

Answer for 2nd 3rd will be D?

[dark sparrow]

show your work that led you to those answers.

[dusty ginkgo]

no 💀

[wintry harbor]

Given a circle and its diameter AB, is it possible to construct a tangent to the circle at say, B? With a straightedge only

[median heath]

can anybody help me with this

If the ratio of the base to the height of an isosceles triangle is 3:4, find the angles

[dark sparrow]

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[median heath]

7

[sly ridge]

how to find the radius can somebody help?

[dark sparrow]

gonna need an uncropped screenshot. rn it's impossible to tell.

[dark sparrow]

ok explain yourself

what is your progress on your problem?

[median heath]

ive never stumbled upon a problem like this before

so im just stuck

[dark sparrow]

ok so what you are saying is you don't know how to begin.

that sounds like status 1.

[median heath]

yes ok

[dark sparrow]

but ok whatever.

do you know what an isosceles triangle is?

[median heath]

a triangle with 2 equal sides

[dark sparrow]

have you made a diagram yet?

(brb)

[median heath]

yes

[dark sparrow]

ok, show your diagram.

[median heath]

this is it

[dark sparrow]

it would be better if you drew the height actually inside the triangle

as in, the altitude from the apex to the base

then you could see it splits the base in half and also makes a right angle with the base

you can and should exploit this

[median heath]

right

[muted sorrel]

what's that 30

the area of the blue part?

[proper matrix]

This might be a dumb question but can someone explain this a bit simpler for me I don’t understand why it’s positive or negative 🥲

[cunning lion]

on the unit circle, cos(θ) gives values for x and sin(θ) gives values for y. so you have to think about what quadrants the angles correspond to

[dark sparrow]

did you mean that you don't understand whether it's positive or negative?

[trail tendon]

i think they meant why, because they got it right

[slow sinew]

Is it okay for someone to help me with these questions😭 im kind of confused

[trail tendon]

#1. you have a rectangle, and three sides, right?

do you know the fourth side?

[slow sinew]

nope

[trail tendon]

draw it

draw a rectangle

you may want to label the corners CART

doesn't matter which order

so label one corner C, one corner A, and so on

[slow sinew]

Oke i did it

[trail tendon]

alr

so

[dark sparrow]

well no, it does

[trail tendon]

oh yeah i guess it does

[slow sinew]

yep

[dark sparrow]

if the rectangle is named CART then traversing it in either cw or ccw order starting from C you need to see A, R and T in that order

[dark sparrow]

show us

[proper matrix]

Yes that’s exactly what I mean

[slow sinew]

cuz cr and at are the diagonals of the rectangle

[trail tendon]

oh?

its positive

☠️

[dark sparrow]

uppercase CR and AT.

[slow sinew]

mb

[dark sparrow]

but anyway show us your diagram.

[slow sinew]

Not sure if u can see it

Wait

[trail tendon]

uh

you may want to reverse sum

specifically because

A has to be next to T

[slow sinew]

But i think thats how u write it properly, atleast that how my teacher taught us

[trail tendon]

wait i gotta think about this 💀

[dark sparrow]

no it doesnt?

[trail tendon]

no i mean like there has to be a side AT

no?

[dark sparrow]

AT is a diagonal

[slow sinew]

Yea

[dark sparrow]

nobody said AT was a side. it was only mentioned by name.

[trail tendon]

oh

wait

[dark sparrow]

this is the problem we're looking at.

[trail tendon]

oh

it doesn't matter if its a side or a bisector then?

[dark sparrow]

@slow sinew so you should see now that CR and AT are the two diagonals of your rectangle -- does that tell you anything?

[trail tendon]

wait is it called a bisector idevk 💀

tangent line maybe

naw

diagonal

[dark sparrow]

...

[trail tendon]

it doesnt matter if its a side or a diagonal?

[dark sparrow]

viper i think you are spouting nonsense here a bit

[slow sinew]

Im just kind of confused on how to get x

[dark sparrow]

well

again

[trail tendon]

☠️

[dark sparrow]

CR and AT are the two diagonals of your rectangle -- does that tell you anything?

[trail tendon]

i'm confused so im probably making it more confusing for him

[dark sparrow]

for her*

[trail tendon]

or her

yea

[dark sparrow]

she literally has the pink diamond

that means she/her

[slow sinew]

Uhm

[trail tendon]

oh

[slow sinew]

😭

[trail tendon]

i didnt know that ☠️

[dark sparrow]

what?

[slow sinew]

Idk😭 im sorry😭

[dark sparrow]

you can tone down on the sobbing emoji.

[slow sinew]

That theyre congruent?

[dark sparrow]

yes, exactly.

the diagonals of a rectangle are equal.

you can use this to find the value of x.

[slow sinew]

Ohhh

Oke

[dark sparrow]

in fact thats exactly what part a asks you to do.

so go ahead and do it.

[slow sinew]

So x is 6

[trail tendon]

oh. CART means C adjacent to A adjacent to R adjacent to T, order matters?

i need to review geometry that took way too long to figure out 💀

[slow sinew]

yea

[dark sparrow]

that is what i said earlier yes

[trail tendon]

yea i didnt catch on mb lol

[dark sparrow]

show work to double-check?

[slow sinew]

mental mathed the others

now im kind of confused on how to get the area and perimeter

[trail tendon]

yk what i dont think i know geometry ngl 💀

i have no idea how to get the area or perimeter

[trail tendon]

come back 🤣

[lime dune]

if you don't know what you're talking about

it may be best to not say anything

[slow sinew]

for the perimeter i thinnk u just add all sides

[trail tendon]

um...

thats how to not learn...

i dont help people because im the all knowing mentor

i help people cuz i get it better and they get it better

[dark sparrow]

i mean heres the thing

[slow sinew]

then the area is lenght times width

[trail tendon]

or we both get stuck, worst case scenario

[slow sinew]

but if its like that i dont get it

[dark sparrow]

if you yourself are confused you have a very high chance of worsening the helpee's confusion

[dark sparrow]

that's what perimeter means yes

[trail tendon]

hmm

true

[lime dune]

we appreciate the enthusiasm for sure

[dark sparrow]

@slow sinew so for both area and perimeter you'll need the width of your rectangle

you know the height is 7 and the diagonal is 25

[lime dune]

but you gotta make sure you have a good handle on what you're trying to help with

[slow sinew]

mhm

[dark sparrow]

do you see how to get the width

(or length, whatever. the horizontal side)

[slow sinew]

do u add the diagonals?

[lime dune]

wha

😭

[slow sinew]

uhh

[trail tendon]

I guess. I thought i had a good handle on geometry but i've most likely forgotten a lot 💀

that might actually be my problem

[slow sinew]

OH

PYTHA THEORUM

[lime dune]

pythagoras

yea lol

[dark sparrow]

yes.

[slow sinew]

okeoke

wait hold on

[lime dune]

||and this just happens to be a very well known pythagorean triple||

[trail tendon]

bro 💀💀

there aint no way

[lime dune]

an important skill in geo problems

is

knowing what's important in a diagram

that one above results from cutting away everything except what you need

[trail tendon]

i hope i'm just tired 😭

[slow sinew]

is this correct @dark sparrow ??

[lime dune]

mhm

[dark sparrow]

yes

[slow sinew]

oml thank you

[lime dune]

7-24-25 is an extremely common pythagorean triple

if nothing else

that might be worth memorizing

[dark sparrow]

extremely common is stretching it

it's much less so than 3-4-5

or even 5-12-13

[lime dune]

lmao ig

it's like

3rd-4th most common then

[slow sinew]

so the area=128 and the perimeter=62

[lime dune]

7*24=168 not 128

[slow sinew]

oh mb

[lime dune]

all cool lmao

[slow sinew]

Now i dont get these ones, dont mind the answers ik theyre wrong

Can someone help me pls🙏🙏

[dark sparrow]

well again.

make a diagram.

[crystal locust]

I guess this is kinda a geometry/trig problem

could someone help me

[dark sparrow]

could be better

could be bigger, for one.

instead of being barely three centimeters across.

cause now you're gonna have to write microscopically to put the other info on it (like the lengths, and also the fact that the diagonals meet at right angles -- you know this, right?)

or you could just draw the same diagram but bigger and better.

maybe even with a ruler.

[slow sinew]

wait im drawing a new one

[crystal locust]

HELP

[dark sparrow]

you might want to
(a) go to a help channel, and
(b) share your progress instead of just throwing the problem out there

[crystal locust]

erm

how do i do that

[dark sparrow]

!help

[lime crown]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[upper karma]

what was the hardest part about trig for you all

for me its identities

[fresh night]

for me its everything

[upper karma]

that defeats the ppoint of the question

[lime dune]

complicated geo trig manipulations

which are way beyond the scope of standard curricula

[burnt spire]

Anyone know how to solve this? Our lesson is secand and tangent

No.5

I don't know how can someone show me the process

[red flare]

Hello, I need some help with understanding trigonometric identities to do proofs.

Do I just memorize them?

[strange spear]

number 5?

thats ez

if u ought to get the side

its just 28 ft.

so the area of the square would be 28^2

[burnt spire]

Why's there a square?

[dark sparrow]

the shape into which the circle is inscribed

is a 4-sided polygon with all sides equal and all angles 90°

does this answer your question?

[burnt spire]

Yes thank you

[dark sparrow]

the problem did not ask for the area, did it

[strange spear]

idk

It wasnt indicated

I just gave him that because when i was in the 10th grade whenever it involved lengths itd just be the area

the perimeter would be 112

[dark sparrow]

don't call me bro.

[strange spear]

Okay

sorry

Also

the 90 degrees was implied

[dark sparrow]

please edit that word out.

[strange spear]

there u go

[dark sparrow]

the 90 degrees was not implied. it was marked.

[strange spear]

Okay

Could i ask what the difference between those two are

[dark sparrow]

between what?

[strange spear]

Implied and marked

[dark sparrow]

marked means there's something on the diagram that directly says the angles are 90°

implied means there isn't such a direct indication but it follows from something else

[strange spear]

Oh

Thank u

Im sorry for calling u bro

I simply just call everybody that , sorry again!!!!!

[dark sparrow]

will be a good idea to break that habit.

[strange spear]

Question

in the distance from the line to a point formula

which is ax1+by1+c all over plus minus square root of a^2+b^2

why does the plus minus have to be based on the B

like its in the text book but idk why

[dark sparrow]

... i have a feeling you are misquoting the formula?

can you show how it's written in your textbook

[strange spear]

sorry i have a bad habit of putting =0

bc its literally equated to d

[dark sparrow]

SHOW the formula as it is in the textbook.

[strange spear]

can i draw it in paint

[dark sparrow]

i mean i guess? but why can't you take a photo?

[strange spear]

im on pc

and my phone is dead

yeah i have it on my lap rn thats how it appears

it says here

"The ambiguous sign should follow the sign of B."

[dark sparrow]

...

wait

do you have access to the absolute value function at this point in time

cause if you do, this is just the dumbest way of avoiding it that i've ever heard

[strange spear]

Well the textbook is old

[dark sparrow]

how old

[strange spear]

1964

LMAO

its a local book

on analytic geometry

[dark sparrow]

a book from the sixties that makes zero mention of the absolute value?

also their rule is sus as shit to me ngl

like

[strange spear]

seems like it , can't see it

[dark sparrow]

the way i would have written the formula is $$d = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2+B^2}}$$ WITHOUT any mention of any dodgy sign resolution rules

[somber coyote]

Ann

[strange spear]

Yes

That's also how it is written if u look it up

[proper matrix]

My teacher doesn’t explain every well how to solve this problem can someone please explain I under stand converting degree, minutes, seconds but how does the hour fit in with this…?

[dark sparrow]

ok so let's try to reason this through step by step

at 5:00, what is the angle between the hands?

all in degrees, of course

actually do you still need help with this?

if not, tell me as such so i can go to sleep.

[proper matrix]

Yeah I still need help but it can wait until tomorrow it’s not an emergency. Thank you

[dark sparrow]

no, i am still here.

[proper matrix]

Thank you 😭

[dark sparrow]

ok so like, do you want me to take you through this step by step the way i would do it

y/n

...?

@proper matrix im gonna need a clear "yes, let's do it" or "no, let's wait until tomorrow and i'll ping you at some point then"

i can't do any explanations when you're not there

[proper matrix]

I’m sorry yes

[dark sparrow]

ok

so the first step is:

what is the angle, in degrees, between the hands at 5:00?

[proper matrix]

Yes

[dark sparrow]

that was not a yes/no question

[proper matrix]

lol sorry okay the angle is 90

[dark sparrow]

you sure?

we're talking about 5:00, not 3:00. do you know where the 5 mark is on a clock face?

[proper matrix]

It’s about almost to the 180 mark but exactly maybe 170 as the distance between the two

[dark sparrow]

...

ok hold on

there's some basics that i think you are missing.

ok so

let's start with the very very basics

how many degrees make a full circle?

[proper matrix]

360

[dark sparrow]

right.

the hour marks on a clock split it into 12 equal parts. what is the distance, in degrees, between adjacent hour marks?

[proper matrix]

There are 5 ticks so 60?

[dark sparrow]

that doesn't make much sense no matter which way you slice it.

the full circle (the clock face) is divided into 12 equal parts

how many degrees are in each part?

[proper matrix]

Then is it 5/12…?

[dark sparrow]

(im trying to make sure that you understand the basics of how a clock works. and that we are on the same page.)

[dark sparrow]

no forget about 5 for now

360 degrees divided into 12 parts, how much is each part

[proper matrix]

Thank you I know I’m probably making it harder than it needs to be

[dark sparrow]

you're overthinking it that's for sure

[proper matrix]

1/2

[dark sparrow]

are you sure?

[proper matrix]

Oh wait

30

[dark sparrow]

ok there we go

yes, hour marks are 30 degrees apart.

<@&268886789983436800> spam

[hoary totem]

ew

<@&268886789983436800>

[proper matrix]

Umm rude

[hoary totem]

why woul u raid a math server of all things lol

[dark sparrow]

ok so you can just block the spammer

anyway

ah there we go they're gone

so as i was saying

yes, hour marks on a clock face are 30 degrees apart

[muted sorrel]

What happened 💀

[dark sparrow]

now look at the clock. it is showing 5:00. the hour and minute hands are 5 hour-marks apart. how many degrees is that?

[proper matrix]

150

[dark sparrow]

right.

now, we need to advance the clock by 15 minutes to get to 5:15.

at 5:15, which hour-mark will the minute hand be pointing to?

[proper matrix]

Between the 6 and 5

[dark sparrow]

the minute hand. the long blue one in my picture.

not the hour hand.

we'll get to the hour hand in a moment.

[proper matrix]

Oops I looked at the wrong one

It’s between the 12 and 1

[dark sparrow]

are you sure?

remember, we are advancing the clock by 15 minutes.

where will the minute hand end up then?

[proper matrix]

On the 3

[dark sparrow]

right.

so then let's pretend the hour hand was stuck where it is, still pointing directly at the 5 mark.

what would the angle between the hands be?

[proper matrix]

If one hand was pointing on the 3 and 5?

Would it be 30 degrees then

[dark sparrow]

would it?

they're two hour-marks apart, not one.

[proper matrix]

I’m sorry I’m not sure

[dark sparrow]

when the hands were 5 hour-marks apart, you were able to say the angle between them is 5 * 30 = 150 degrees

what about now when the number of hour-marks separating them is instead 2?

[proper matrix]

Oh the 100

[dark sparrow]

100?

how did you get 100?

[proper matrix]

Sorry typo I meant 10

[dark sparrow]

how did you get 10?

[proper matrix]

2 *5

[dark sparrow]

why times 5?

hour-marks are still thirty degrees apart, not five...

this is what our picture looks like, as a reminder.

this slightly broken clock was showing 5:00 and then we advanced it by 15 minutes, but the hour hand is stuck.

[proper matrix]

So then it’s 150 / 2 so 75

[dark sparrow]

????

it feels as if you are not listening to what im trying to tell you

no, the angle didn't get cut in half...

[proper matrix]

I really am I just don’t do well with word problems it takes a minute to process

I’m sorry

[dark sparrow]

the hands used to be 5 hour-marks apart, and the angle between them was 5 * 30 = 150°
now the hands are 2 hour-marks apart, so the angle between them is 2 * 30 = ?

[proper matrix]

OH!!!! 60

[dark sparrow]

yes exactly

like...

i said several times that hour-marks are 30 degrees apart

that neither stopped being the case nor stopped being relevant

anyway

[proper matrix]

Got it

[dark sparrow]

so the angle would've been 60° if the hour hand was stuck.

but the hour hand moved, actually.

it moved some fraction of the way from the 5-mark to the 6-mark.

specifically, the fraction it moved is the fraction that 15 minutes is out of an hour.

what fraction of an hour is 15 minutes?

[proper matrix]

3/5

[dark sparrow]

15 minutes is three fifths of an hour?

[proper matrix]

Is it 15 decided by 2?

[dark sparrow]

where is two coming from

please read the questions im asking you

it's as if im asking you one thing and you respond to another thing entirely

i asked you:
what fraction of an hour is 15 minutes?

in other words:
"15 minutes is ____ of an hour." what fraction goes in the blank?

[proper matrix]

30 is half an hour so that’s a fraction of the way

[dark sparrow]

30 minutes is half an hour yes

but what fraction is 15 minutes?

[proper matrix]

If I do 60min divided by 15 I get 4 unless I’m still not doing that right

[dark sparrow]

60/15 is 4, yes. but i'd like a straight answer to my question:

15 minutes is what fraction of an hour?

[proper matrix]

Not sure

[dark sparrow]

you said that 60/15 = 4

that means 15 fits four times into 60

15 is one-fourth of 60

[proper matrix]

Oh! I see

Okay then it’s 1/4 of the way

[dark sparrow]

ok, right, so to drag it back.

[proper matrix]

Okay

[dark sparrow]

in the time between 5:00 and 5:15, the hour hand moves 1/4 of the way from the 5-mark to the 6-mark.

accordingly, the angle grows by 1/4 of the distance between hour-marks, i.e. by 1/4 of 30 degrees.

how much is 1/4 of 30?

(it won't be a whole number. answer as a decimal.)

[proper matrix]

1/4 * 30 is 7.5

[dark sparrow]

ok great.

so compared to our broken-clock scenario, the angle is that many degrees greater than 60.

so it is 67.5°.

do you understand this? (we're not done, there's one more thing i'll get to.)

[proper matrix]

Oh!! So it was added to the 60!?

[dark sparrow]

well it should be obvious visually, no?

[proper matrix]

Thank you and sometimes I over think the answer so to me it wasn’t but that makes sense now.

[dark sparrow]

ok right

so one last thing to take care of

converting 67.5° into degrees and arcminutes

(im deliberately calling them arcminutes so they don't get confused with time-minutes)

[proper matrix]

67 degrees +.5 * 60 is = 67 degrees 30minutes

[dark sparrow]

ok great

[proper matrix]

Thank and good night I have to get ready for work now

[dark sparrow]

good night.

[olive ivy]

how do i get the ratio

[past geyser]

,rotate

[olive ivy]

see what im missing

down

right

[past geyser]

@olive ivy have you heard of similar triangles

which triangles here are similar

[olive ivy]

yeahh

[past geyser]

label some more points

[olive ivy]

i need the ratio betwen CD and DB points

[past geyser]

also the question is kinda cut off

can you send a better photo?

[past geyser]

,rotate

[olive ivy]

i need the ratio

[past geyser]

draw out the triangles separately I'd recommend

[olive ivy]

its not a triangle its a lina

line

i need the ratio bettwen points

[past geyser]

i'm sorry i forgot how to do this shit

mb

[olive ivy]

ohhh

[past geyser]

@lilac otter i saw you were typing here

would you like to help?

I can't think right now i'm in a calc tutorial

i know i can do it tho

[olive ivy]

ohhh

do i just mesure the distance?

cuz its 1:6

cm

@past geyser

can u help me with similar triangles

[lilac otter]

AB = AC + CD + DB

You need to find CD

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[dusty ginkgo]

this is the right place to post this question right?

can anyone help me with this

what i tried, but i got stumped here

i do realise i have took the assumpting that 2A>180-3A but either way the process doesnt get easier tbh

[dark sparrow]

do you still need help with this?

[rugged nova]

yes please

[dark sparrow]

ok,

do you have any thoughts on this

[rugged nova]

i think it should be A

[dark sparrow]

why?

[rugged nova]

it asks about the "pair of linear eqns"

since the lines will eventually meet at a point, they have a solution

so whatever the values of the coefficients of x and y be, the pair of equation will be consistent

it can only be inconsistent when it is parallel

and in this case, it is not parallel either

but my stress is on the fact that this system of l.e. will be consistent since it has 1 solution

[dark sparrow]

you're absolutely right

[rugged nova]

so what should be the answer?

[dark sparrow]

if you claimed the answer as (a), and i affirmed that you are right, what should it be?

[rugged nova]

no because i am not sure of the answer

there is no answer key available and everyone is confused

[dark sparrow]

you are not sure of it even after receiving explicit confirmation from me.

[rugged nova]

some claim it to be D but im skeptical

[dark sparrow]

d is wrong. the graph of a linear equation is a straight line that already extends infinitely far both ways, whether you want it to or not.

[rugged nova]

wait u also think it is a?

[rugged nova]

ohh right

[dark sparrow]

what part of "you're absolutely right" (in response to your explanation of your claimed answer as A) is unclear lmao

[neat raft]

Helo

[rugged nova]

btw, what grade/uni are u in

[dark sparrow]

i'm in the first year of a master's degree

what business is it of yours?

[rugged nova]

i am sincerely sorry for asking it in such a rude manner... as an unknown person to me. i just wanted to know if i could trust your take on that.

thank you very much for your help

[fair vapor]

you can solve it through sin theorem but it will get hard ( honestly every solution that i have seen uses this but it gets way too hard )

just draw a bisector

and solve it using similar triangles

[dusty ginkgo]

how?

[rose raven]

how would i calculate a trig function period shift when x has pi in it

[fair vapor]

draw the bisector of the angle that is twice the other one

[dusty ginkgo]

ok i will try that, thanks

[glass copper]

I’m so sorry but does anyone have a black and white picture of Trihexagonal tilting?

I couldn’t seem to find it anywhere

[clever anvil]

can i here also ask questions?

[lime dune]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

[lime dune]

the whole purpose of this channel is to ask questions on the topic in the channel name and get them answered lol

[sour hearth]

<@&286206848099549185> I need help with trigonometry it’s basic

[upper karma]

Go ahead

[sour hearth]

How do I do these @upper karma

[upper karma]

Did you try using law of cosines?

[dusty ginkgo]

what do u have to find?

[upper karma]

Try dividing it in half, use law of cosines on both

[tall coral]

I mean the angle can also just be found out know parelelogram properties too

[sour hearth]

Tbh I don’t understand can someone explain

[tall coral]

what don't you understand?

[sour hearth]

How to do it?

[lime dune]

what specifically don’t you understand?

[exotic depot]

whats the point of the question

[lime dune]

wow very specific

what are they asking for

[exotic depot]

???? u just showed us an image of a parallelogram

[sour hearth]

I start trigonometry today, I am 13 pages ahead of my class so probably why.

[lime dune]

what is the question asking

[tall coral]

what are you even trying to find

[lime dune]

that has nothing to do with reading ahead or anything

show us the full text of the question

[sour hearth]

It literally doesn’t ask a question

[lime dune]

it may be that they’re asking for area now that im looking at it

go to the previous page

[exotic depot]

bro has no question

[sour hearth]

Here

[lime dune]

if they’re similar ok

[exotic depot]

Uhhh this isn’t trigonometry

[tall coral]

alright got it

[lime dune]

for similarity you need to check

[sour hearth]

It is

[exotic depot]

it’s geometry

[lime dune]

are all the corresponding angles equal

[sour hearth]

Fr?

[exotic depot]

[sour hearth]

Yeah

[lime dune]

are the corresponding sides “scaled” by the same ratio from one polygon to the next

for #3 the answer is immediately no because the angles don’t match

[tall coral]

in a nutshell, trig is anything relating to cos, sin, or

[lime dune]

the first parallelogram has angles 40, 140, 140, 40

[exotic depot]

TRIGONOMETRY ARE JUST TRIANGLES

WHAT GRADE ARE U IN KAZ

[lime dune]

the second is 50, 130, 130, 50

[jagged wyvern]

Set up proportionality

[sour hearth]

Oh nvm I think this is the basics and then I start trigonometry tomorrow bc thsi is homework. And my teacher mentioned trig

Idk my teacher is strict and too fast

[tall coral]

I mean

this is just similarity

[sour hearth]

Bro…

[tall coral]

_ _

[sour hearth]

Idek what y’all saying 😭

[exotic depot]

Yap yap yap fr

[jagged wyvern]

Its easy man

[sour hearth]

I’m just trying to figure out from YouTube

[exotic depot]

why

u have us

we are way better

[sour hearth]

Too much big words for me

I am not a math nerd

[exotic depot]

i’ll explain in roblox terms

[sour hearth]

Works

Thanks y’all, but I’m just watch YouTube about it.

[tall coral]

ight, come back here if you get stuck ig

[lime dune]

doesn’t even know how to get help when it’s being given 😭

[sour hearth]

Your not specific enough I’m just too dumb I would ask but y’all would get mad :/

[exotic depot]

Bet ask i won’t get mad i promise

[lime dune]

I already basically gave you the answer to 3

[tall coral]

do you know what similarity is?

[sour hearth]

🤷🏾‍♂️

[exotic depot]

So basically similarity is when something is similar

[sour hearth]

Depends

[exotic depot]

browhat

DEPENDS IN WHAT

THERE IS JUST INE DEFINITINNR

[sour hearth]

How your using it

[exotic depot]

YOURE COOKED WHEN IS YOUR EXAM

[sour hearth]

Ik the word idk it the mathematical term

[lime dune]

stop spouting nonsense

[sour hearth]

Fr my 76% is dropping

[tall coral]

Schrödingers inelegance

[lime dune]

what is the precise definition to use

[exotic depot]

@lime dune que estudias

[sour hearth]

Bro this not help this is pressure

[exotic depot]

NO SHIT

[lime dune]

im in undergrad, this stuff is from like 7+ years ago for me lmao

[exotic depot]

Yh but ur in uni right?

what degree

[lime dune]

im in app math + piano

[tall coral]

ok, let's take a breather. It's fine

[exotic depot]

no clue

[exotic depot]

it’s not

his grades are dropping

[tall coral]

I wasn't talking about the grade part

[sour hearth]

Maybe explain step by step not do the work for me 👍👍

[tall coral]

ok, two shapes are similar if one scales to the other

[sour hearth]

For real I was at a 80%

[exotic depot]

where are you from kaz

[exotic depot]

fax

[sour hearth]

Canada

[exotic depot]

wait until you start seeing letters in your math🔥

[sour hearth]

Yeah

[exotic depot]

Oh

[sour hearth]

I did

[exotic depot]

no way

was it hard

[sour hearth]

I am in 10th grade 💀

[exotic depot]

what

arent u 13

[sour hearth]

I started math 10 days ago

New semester

[tall coral]

wdym...

[exotic depot]

what?? i’m so confused

[sour hearth]

This is new semester and it’s a review of grade 9

[exotic depot]

ur 13, in 10th grade and started studying maths 10 days ago

[sour hearth]

It’s not even actually grade 10 math

[tall coral]

ah

[sour hearth]

It’s just a review

[exotic depot]

Oh so you got this then

[sour hearth]

I’m 16??

[exotic depot]

bro what

[sour hearth]

Where did u get 13

[exotic depot]

ohh i thought u meant ur 13

then you are cooked

[sour hearth]

Aye bro it’s okay, it’s just the first 10 days of math

[exotic depot]

Fax

[tall coral]

let's try to get back on track

[sour hearth]

I know I have to divide and stuff but what am I trying to find here

[tall coral]

is this what you mean by "here"?

[sour hearth]

No that’s the previous page

[exotic depot]

if they are equivalent or not

it says it there

[sour hearth]

I need help with this

[tall coral]

oh so you're trying to find if those are similar

[sour hearth]

Yeah

[tall coral]

got it

[sour hearth]

It would be helpful if you screenshot the picture and show from there

[tall coral]

ok so starting with 3

[sour hearth]

Yeah

I will write along while you tell me

[tall coral]

(just grabbing this to make like easier)

ok so you're familiar with the properties of parallelograms?

[sour hearth]

Yea

[tall coral]

ok, so then we can find all the angles of the parallelogram then

which is important because when finding if two shapes are similar, we refer to their angles

but side lengths are given, so that's also another way to get there

I'll just walk you through both so you're ready depending on what info is given

[sour hearth]

Alright sounds good

[tall coral]

so if we're looking at side lengths, the ratio between matching sides must be equal

because if they don't equal, the sides don't work off the same scale factor

[sour hearth]

Yeah

[low hill]

Hi @sour hearth

[sour hearth]

Hi

[tall coral]

here, we can see they aren't similar because
$\frac{7}{15}\ne \frac{21}{15}$

[somber coyote]

KirbysGames

[tall coral]

makes sense?

[sour hearth]

Yeah

[tall coral]

alright

if you're given angles

angles must always be the same in dialations

think like a square. No matter how you dilate it, it's still gonna have 90 degree angles

and if we use the properties of parallelograms, we can see 130 corresponds to 140

beacuse $130^{\circ} \ne 140^{\circ}$, they can't be similar

[somber coyote]

KirbysGames

[tall coral]

ok that was harder then it needed to be omg

ok I fumbled the notation a little bit, but you understand right?

@sour hearth

[median ledge]

I dont really know where to post this but I tried writing the geometric sum $\sum _{k=0}^n\cos ^{n-k}x\sin ^kx$ in the form $S_n=\frac{a_1\left(1-q^n\right)}{1-q}$ according to the formula. Here the ratio is $q=\tan x$ and the first tarm of the sum $\cos^nx$, so I write down $\frac{\cos ^nx\left(1-\tan ^nx\right)}{1-\tan x}$. However, this doesnt match up. Instead I have to write $\frac{\cos ^nx\left(1-\tan ^nx\right)}{1-\tan x}+\sin ^nx$, where $\sin^nx$ happens to be the last term of the sum, to get it to match. I wonder why this is?

[somber coyote]

647TheSheep

[median ledge]

i must be missing something super elementary but i cant figure it out

[tall coral]

I don't think that'd be geometry...

or maybe that is

idk I'm not the smartest

[median ledge]

it has trig functions so i put it here

[leaden epoch]

the exponent of q is n+1 not n

[leaden epoch]

I guess it fits better in prealg-and-algebra

[tall coral]

I was thinking pre-calc 💀

[floral shale]

Index shift. You need to make it so the initial index is 1 so the Sn formula@applies

The sin^n(x) is to readjust

[river solstice]

isnt ths just ratios?

i cant see 4

[median ledge]

Right, I see now. Thanks !

[brazen cargo]

to do calculus do you only need to know the trig identities or do you need to know whole trignometry

[fiery dagger]

need assistance asap with reference angles

How do you get the number for the outside of the coordinate plane?

What would my numbers be for something like 31pi/18?

[mortal crow]

What kind of Calculus? Regardless, just learn all of it, as memorizing the trig identities isn’t helpful if you don’t know how to work with them

[dark sparrow]

<@&268886789983436800>

[weary drift]

@verbal inlet dont troll

[merry marsh]

Please help

[mystic charm]

I'm pretty sure the part you got stuck is sin^4(x) + cos^4(x)

Try to use
a^2 + b^2 = (a+b)^2 - 2ab

Then you will achieve the right side

[winter wind]

sin(pi + alpha) = -sin(alpha) ???

[merry marsh]

Can you help me to do it ?

[mystic charm]

Ok I'm here

[merry marsh]

Thank you so much

So it will be (cosx² + sinx²)² -2cos²x sin²x ?

[mystic charm]

First write tan(x) and cot(x) this way

[mystic charm]

YES!

And you are done

What do you think you can do ?

[merry marsh]

1² - 2cos²x sin²x ?

[mystic charm]

Exactly!

Next step?

[merry marsh]

Mhhh idk 😂

[mystic charm]

Ok you did everything correctly and that was the only tricky part

[merry marsh]

What i need to do now ?

[mystic charm]

Use this type of thing

[merry marsh]

OK so 1/cos²x sin²x + 1 ?

[mystic charm]

How do you conclude such a thing from that?

[merry marsh]

I need to go 😭😭

[mystic charm]

Ah damn

[merry marsh]

Oh no

Its + 2

?

[mystic charm]

Almost Yes, it is -2

[merry marsh]

Why ?

[mystic charm]

-2sin^2(x)cos^2(x)

1/sin^2(x)cos^2(x) -2

[merry marsh]

Oooh ok isee

I love you brother

[mystic charm]

❤️

[mystic charm]

Yes, but what's your question here?

Re send your question so others can see it

I gotta go right now

[merry marsh]

can i add you ?

[mystic charm]

Of course, why not

[dusty ginkgo]

yooo i tried that yesterday, it made things so easier fr. how did u think of that??

[desert sail]

Whats the formula for this?

Is it the curved surface area of the cylinder (2*pi*r*h) times 2 since there are 2 halves?

[errant belfry]

Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the distance between AB and CD is 6, find the radius of the circle.

[errant belfry]

cn anybody help?

[dark sparrow]

have you made a diagram?

[errant belfry]

ye, 1 min

this was in the question

i think i got the right answer, but wanted to get it checked

[dark sparrow]

well show us your work then

in the future, if you already have work that you want checked, you should post it along with the problem

[errant belfry]

ok

gimme a min im on my computer ill take a photo and send

is it right?

[dark sparrow]

let's see

yeah checks out

[errant belfry]

THXS

[fair vapor]

i had seen these kind of questions before 🙂

[dusty ginkgo]

ohh

[shrewd kiln]

can someone tell me how to simplify

(sinx-1)/secx

[frozen ocean]

does your equation looks like [\frac{\sin x -1}{\sec x}] without RS?

[somber coyote]

アキラ (>_<)

[frozen ocean]

@shrewd kiln

[regal jewel]

Anyone know how to do question 48

[past geyser]

I can help you with this

I suggest you select an arbitrary point (x, y)

and find the distance from (x,y) to F and F', set it equal to 30

this will give you two variables and two equations

makes sense @regal jewel?

[regal jewel]

This is the type of answer their looking for pretty sure

[regal jewel]

How

[past geyser]

oh the set of points

@regal jewel do you know the instance formula?

[regal jewel]

No

[past geyser]

distance*

[regal jewel]

Is that in statistics

[past geyser]

i meant distance

[regal jewel]

Yes

[past geyser]

write out the formula

[regal jewel]

Do I plug the foci into it?

[past geyser]

what is foci?

[regal jewel]

The F

[past geyser]

yes, plug an arbitrary (x, y) and F into it

tell me what you get

[regal jewel]

What what’s an arbitrary

[past geyser]

abitrary as in you selected a point at random

[regal jewel]

But what if I only have the foci and K

[harsh iris]

Hello @gilded sand

[gilded sand]

😭

[dusty ginkgo]

bro

it says to simplify 1 side

[gilded sand]

dude ik chill 💀

[dusty ginkgo]

just put tan(x)=1/cot(x)

[gilded sand]

u can just divide everything by by sin and you're done

[dusty ginkgo]

its unnecessary

on the page it was written tan(x)=1/cot(x)

oh w8 it wasnt

anyways

[gilded sand]

sorry typo, it should be $$L.S.=\frac{\sin\theta-\cos\theta}{\sin\theta+\cos\theta}=\frac{\sin\theta/\sin\theta-\cos\theta/\sin\theta}{\sin\theta/sin\theta+\cos\theta/\sin\theta}=\frac{1-\cot\theta}{1+\cot\theta}$$ $$\therefore L.S.=R.S.$$

@harsh iris

[somber coyote]

Anonymous

[harsh iris]

I'm confused I'm over here

@gilded sand

[gilded sand]

for both fractions just cross multiply

[harsh iris]

So like this? @gilded sand

[gilded sand]

yes exactly

[gilded sand]

like i said i made a small mistake on my paper but ya, do stuff from here and you're done

[harsh iris]

I'm stuck there

[gilded sand]

stuck where?

[gilded sand]

like on the final step here?

[harsh iris]

how did you get this?

[gilded sand]

i just divided the top and bottom by 1/sin

here's what you should think to yourself, if you had $\frac{\sin\theta-\cos\theta}{\sin\theta+\cos\theta}$ how would u change it so that it matches the right side, which contains $\cot\theta$, well the only way you're going to get that is by dividing everything by $\sin\theta$ which is what i did

[somber coyote]

Anonymous

[harsh iris]

so like this? @gilded sand

[gilded sand]

yes

[harsh iris]

Thank you you're the lord of the math

[hollow barn]

Hello, please tell me why this is wrong. My teacher has no clue…

[silent plank]

first line

the length of fraction lines weren't disctinct enough leading to messing up the order of operations

[hollow barn]

That’s it, that’s the issue?

[silent plank]

that's the source of the mistake

expressing $\frac{\pi}{8}$ as $\frac{\br{\frac{\pi}{4}}}{2}$ doesn't help either

[somber coyote]

ℝαμΩℕωⅤ

[silent plank]

when applying the double identity with fractions here, its much better to multiply by 1/2 directly instead of making skyscraper fractions

[hollow barn]

Skyscraper 😅

[silent plank]

$\sin\br{\frac{\pi}{8}} = 2\sin\br{\frac{\pi}{8} \cdot \frac12}\cos\br{\frac{\pi}{8} \cdot \frac12}$

[somber coyote]

ℝαμΩℕωⅤ

[silent plank]

if you wanted to use that unnecessary $\frac{\br{\frac{\pi}{4}}}{2}$, when dividing by 2, you'd need something like
$$\frac{\br{\frac{\br{\frac{\pi}{4}}}{2}}}{2}$$

[somber coyote]

ℝαμΩℕωⅤ

[hollow barn]

My teacher did use sin(pi/4/2) in the solution, but it was to rearrange an identity

How do I use TeXit?

[silent plank]

dollar sign in front and end for typing math

start functions with \

enclose inputs with {}

are pretty much the basics

show what your teacher did

#latex-help

[hollow barn]

$\cos\br{A} = 1 - 2\sin^2\br{\frac{A}{2}}$

[somber coyote]

Angel_15
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[hollow barn]

$A = \frac{\pi}{4}$

[silent plank]

yeh, expressing pi/8 as (pi/4)/2 actually makes sense there

[somber coyote]

Angel_15

[hollow barn]

rearranging for sine

$\sin\br{\frac{\frac{\pi}{4}}{2}} = \sqrt\frac{-\cos\br{A}+1}{2}$

[somber coyote]

Angel_15

$\sin\br{\frac{\frac{\pi}{4}}{2}} = \sqrt\frac{-\cos\br{A}+1}{2}$
```Compilation error:```! Undefined control sequence.
<recently read> \br 
                    
l.49 $\sin\br
             {\frac{\frac{\pi}{4}}{2}} = \sqrt\frac{-\cos\br{A}+1}{2}$
The control sequence at the end of the top line
of your error message was never \def'ed. If you have
misspelled it (e.g., `\hobx'), type `I' and the correct
spelling (e.g., `I\hbox'). Otherwise just continue,
and I'll forget about whatever was undefined.```

[hollow barn]

$\sin\br{\frac{\br{\frac{\pi}{4}}}{2}} = \sqrt\frac{-1 + \sqrt2}{2\sqrt2}$

[somber coyote]

Angel_15
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[hollow barn]

final answer

[limber kernel]

Hi I know what to do after the red line but to get the answers before that I'm not sure can I have some help please

[hollow barn]

Where did those /6 statements come from?