🔒 someone explain this

[frigid bloom]

@trail musk

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[coral crater]

you probably need to add the folder name in the file path to it while renaming

[trail musk]

how would it know what the file is called

he said i cant find the file called this

how would he know its name if he cant find it

if the only way to get the name is through iterating

he obviously can find it if he can name it

[coral crater]

the os.listdir is one process. os.rename is a separate process

!d os.rename

[frigid bloom]

os.rename

os.rename(src, dst, *, src_dir_fd=None, dst_dir_fd=None)```
Rename the file or directory *src* to *dst*. If *dst* exists, the operation will fail with an [`OSError`](https://docs.python.org/3/library/exceptions.html#OSError) subclass in a number of cases:

On Windows, if *dst* exists a [`FileExistsError`](https://docs.python.org/3/library/exceptions.html#FileExistsError) is always raised. The operation may fail if *src* and *dst* are on different filesystems. Use [`shutil.move()`](https://docs.python.org/3/library/shutil.html#shutil.move) to support moves to a different filesystem.

[trail musk]

oooooooooo

[coral crater]

So what os.listdir is able to find is not shared with os.rename

provide the full file path in os.rename

[trail musk]

you genius

[fallow aspen]

or better yet, start using pathlib instead (here is a good comparison and conversion table): https://docs.python.org/3/library/pathlib.html#corresponding-tools

from pathlib import Path

for file_path in Path("spriteicons").iterdir():
    new_file_path = file_path.with_name("civ_" + file_path.name[4:].lower())
    file_path.rename(new_file_path)

[frigid bloom]

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