🔒 Help with a tic tac toe project

[cerulean vortex]

@sharp root

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[sharp root]

def is_victory(icon):
    return (board[0] == icon and board[1] == icon and board[2] == icon) or \
           (board[3] == icon and board[4] == icon and board[5] == icon) or \
           (board[6] == icon and board[7] == icon and board[8] == icon) or \
           (board[0] == icon and board[3] == icon and board[6] == icon) or \
           (board[1] == icon and board[4] == icon and board[7] == icon) or \
           (board[2] == icon and board[5] == icon and board[8] == icon) or \
           (board[0] == icon and board[4] == icon and board[8] == icon) or \
           (board[2] == icon and board[4] == icon and board[6] == icon)

this is my way of making it

I don't know how to make it like he suggested

because going over every possible instance is slow and just not a good way to check the winner

[coral crypt]

well technically you are not checking every single condition unless they all fail

we have something called short circuiting in modern languages, if you have a condition like x == 5 or x == 6 and it finds that the first one is True it wont evaluate the second one at all

[sharp root]

he asked: what if you wanted to show me who won mathematically, how would you do that?

[coral crypt]

hmm are you storing integers in your board? what is icon

he might mean boolean arithmetic, where you do math using bools

!paste sure

[cerulean vortex]

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[coral crypt]

yeah I'm not sure what he means

[sharp root]

same

ill delete him

and just

ask him for the answer lol

[coral crypt]

lol

[sharp root]

thank you tho!!

btw

uh

[coral crypt]

np, good luck with your code

[sharp root]

oh alright thanks! cya around

[fast trench]

please share the answer

[sharp root]

i will

[cerulean vortex]

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🔒 Help with a tic tac toe project