#🔒 TypeError: The view function did not return a valid response. The return type must be a string, di

16 messages · Page 1 of 1 (latest)

jagged gardenBOT
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@tranquil marsh

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ornate oxide
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Because you're returning an image, that's why

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Try responding with the image URL inside a dictionary

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You do have it saved with img.save

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Since its saved, you can return with the image url of where its saved.

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Normally stored in a static folder for CDN to process

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Its either that or use the send_file

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what did you change?

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Show your latest code

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is the img the filename?

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If you look at the answer from SO:

from flask import send_file

@app.route('/get_image')
def get_image():
    if request.args.get('type') == '1':
       filename = 'ok.gif'
    else:
       filename = 'error.gif'
    return send_file(filename, mimetype='image/gif')
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filename is the name of the image file.

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Did you also change it so its saved and used the image file name too?

jagged gardenBOT
#
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