so your particular soln would be:
#🍁・general-2
rotund pawnBOT
abstract scaffold
you can quickly verify that indeed y(0) = 1 there
abstract scaffold
@median trail en cualquier tiempo que no sabes si es el caso positivo o negativo... solo tienes que sustituir los valores en la ecuacion original (la del valor absoluto)
|y| = 2cosx - 2c
y(0) = 1
|1| = 2cos(0) - 2c
-2c = -1 {only one constant solution, no other constant solution}
=> |y| = 2cosx - 1
but because it has to pass through (0,1), the absolute value is redundant.
y = 2cosx - 1 (with some domain restrictions)
my tip is don't bother simplifying... once you have "some sort of general soln" and initial conditions... sub in the initial conditions as soon as you are able to. This way you won't have to worry about "2 constants"
exotic kiteBOT
median trail
ohhhh so you mean like substituting in the general solution that has the abs values, right? okay and if I'm asked to find the solution interval, should I do it using the general solution with the c I found?
abstract scaffold
ohhhh so you mean like substituting in the general solution that has the abs values, right? - yes
okay and if I'm asked to find the solution interval, should I do it using the general solution with the c I found? - could you elaborate?
like |y| = 2cos(x) - 1
since y >= 0
we get
y = 2cos(x) - 1... but looking at our original function with |y|... for example x \in (pi/3, 2pi - pi/3) are not included in the final solution
essentially we only include the top part of the function rather than reflected part due to the initial conditions.
pero el valor absoluto ya nos da restricciones en el dominio
if you keep jumping by 2pi. you'll see this graph repeat itself.
median trail
Lets say i have this, with the initial condition of y(1) = - 2 and Im also asked to find the largest interval of solution
as you can see there are some restrictions
abstract scaffold
ok. first step is to just sub in immediately.
abstract scaffold
let's think now. hmm.
im trying to factorise the polynomial inside the square root
=tex |y-1| = \sqrt{(x+2)(x^2+2)}
rotund pawnBOT
abstract scaffold
@median trail the domain seems to be [-2, \infty) is this what you want?
median trail
exactly
abstract scaffold
=wolf graph |y-1| = sqrt((x+2)(x^2+2))
abstract scaffold
i have no idea what it looks like. so i'll cheat
seems to shoot down to negative infty on the y axis.
yeah, that makes sense.
@median trail this is one of those cases where you just keep the absolute value in your solution... no need to go ahead and try to simplify it.
actually. scratch that. you can simplify that.
@median trail ignore what i just said. because of our initial conditions....
the branch we take is:
-(y-1) = sqrt((x+2)(x^2+2))
=> y = 1 - sqrt((x+2)(x^2+2)) where x >= -2
red and blue es the graph regarding the absolute value... pero el grafico que queremos es el que tiene y(1) = -2 (el de azul solito)
median trail
The blue graph is the one I used for finding c and finding the solution interval
abstract scaffold
yep.
dominio: x >= - 2
rango : y <= 1
si tuvieramos y(1) = 4, tomariamos la parte arriba (la de color rojo)
y el rango cambiaria,
dominio: x >= -2
rango: y >= 1
and y = 1 + sqrt(blah)
boreal peak
is this how vectors are drawn?
subtle zinc
Hi I need some help to find a song, I try to use Shazam and others apps but dont find the song, so I need someone that could say me what the girl of the min 1:32 to the end is saying, to search it on YouTube
Link https://youtu.be/pP5tvVqShrY
Plese someone?
gusty ermine
lo intente pero no entendí nada
edgy quarry
Shazam.
subtle zinc
Dije que no detectaba la canción😔
gusty ermine
pregúntales a ellos
subtle zinc
El vídeo es de hace 3 años y no responden comentarios
gusty ermine
pues
oye oye oye
no sos un hablante nativo?
no c que puedo decirte
Dios mio, yo no entendí que fue lo que dijo la chica y soy hablante nativa x'D
subtle zinc
Pues decirme que escuchas tu
Pero nada
?
Yo entiendo somebody solo
Ni una palabra entendeis
?
gusty ermine
hola
https://www.youtube.com/watch?v=zpVr-6qt34M
She has a beautiful voice, but I literally clicked on the link because I thought she would be pretending to scream like a siren in a subway and freak others out.......whats with my mind
outer fox
cool
gusty ermine
siren también es la sirena (🧜♀️ )
fallow dock
(_ for _ in ()).throw(Exception("gg explicitly raising an exception without the raise keyword"))```
twin summit
@gusty ermine ohh good voice withecho
gusty ermine
yeah, she is good. (y una sirena) @twin summit
median trail
@abstract scaffold if the derivartive of a funcion is the function itself, what does that mean asides from the fact that the rate of change is the function itself?
abstract scaffold
I mean the only function that does that is e^x
i dunno what else you want but that's basically it. the rate of change is the function itself.
y' = y
dy/dx = y
dy/y = dx
ln|y| = x + C_1
y = Ce^x
median trail
I have one question, if I have this v = x/t and I plug x = 3m and t = 5s seconds, so I get v = 3/5 (m/s), why do we read that as 3/5 meters per second? why do we change seconds from plural to singular
@abstract scaffold
near berry
Imagine it's a fraction over a 1
near berry
(3/5 of a meter) per 1 second
median trail
why is it a fraction in the first place
why isn't velocity defined as idk x * t or e^t * x or whatever
near berry
Oh. I don't think many people think like that is all
ashen mist
@median trail lo tratamos como una tasa
near berry
In your daily life have you ever needed to express the quantity distance * time?
ashen mist
3/5 meters per second dice que cada segundo, va 0.6 metros
near berry
I've not. But there's been lots of situations where I needed to talk about how fast something is going
ashen mist
podríamos definir la velocidad como x*t, pero en ese caso las unidades serían muy extrañas
median trail
@median trail lo tratamos como una tasa
what is a tasa? (the term is correct I just don't remember what that is)
ashen mist
rate
distance traveled per unit of time
para nosotros, ese concepto es la velocidad (técnicamente, "velocity" también tiene el concepto de dirección, pero no sé si es así cuando hablamos de "velocidad" en espanol)
median trail
Oh so the denominator is expressed as a single unit and the denominator expresses the rate of change :0
ashen mist
el numerador y el denominador ambos tienen una unidad
en el caso de la rapidez, el numerador tiene la unidad de distancia (metros, kilómetros, millas, etc), y el denominador tiene la unidad de tiempo (segundos, minutos, horas)
por ejemplo, cuando hablamos de la rapidez de un auto, usamos kilómetros por hora o millas por hora, no?
median trail
yes
ashen mist
y cuando el numerador y el denominador se unen para formar una fracción, esa fracción es una tasa
median trail
I just don't understand how a fraction lets me compare two different units and how they change
ashen mist
no es una comparación
la fracción en sí te dice sobre el cambio porque la fracción es una tasa
"kilómetros por hora" dice que la distancia cambia X kilómetros cada hora
cuando hablamos de los cambios a través del tiempo, lo natural es darle la unidad de tiempo al denominador
y la unidad de lo que se aumenta o decrece al numerador
un sueldo de X dólares por año
una velocidad de X metros por segundo
median trail
okay so rates are a fraction when the numerator depends on the denominator?
ashen mist
qué querés decir con "depend"?
near berry
If you're buying some apples
And it's 3 dollars for 5 apples
That ratio doesn't change 3/5
median trail
what confuses me is that I can't wrap my head around rates being expressed as fractions because I don't see how dividing two things in two different units is connected to calculating how fast the dependent variable changes with respect to the independent one
median trail
qué querés decir con "depend"?
@ashen mist like the numerator being a function of the variable in the denominator
ashen mist
si viajé 10 metros en 30 segundos, entonces mi tasa de cambio de distancia es 10 metros / 30 segundos, o sea 1/3 metros por segundo
lo cual dice que en un solo segundo, viajo 1/3 metros
o, en 3 segundos, viajo 1 metro
median trail
oh
ashen mist
la tasa necesita unidades diferentesp
porque hablamos de un cambio de una unidad con respecto a otra unidad
median trail
im gonna write something on a paper and show it to you guys. I think I get it now
ashen mist
un cambio de distancia con respecto al tiempo,
un cambio de precio con respcto al tiempo
cosas así
ok
ashen mist
la derivada es así - la tasa de cambio de la variable dependiente con resecto a la variable independiente
es que una fracción es como una derivada muy sencilla
dy/dx es una constante, por ejemplo 3/5
edgy quarry
¿Mates? :O
edgy quarry
Interesante.
ashen mist
if object A is faster than object B, it means that A traveled more distance than B in the same amount of time
gusty ermine
I like the correction you did there Edsel
ashen mist
or, it took less time for A to travel the same distance as B
median trail
So essentially what i wrote is correct?
near berry
Your pictures are off
abstract scaffold
your diagram, each section represents distance rather than time.
it seems a bit inverted
median trail
but wouldnt 1/3 be like a rectangle split into three parts
ashen mist
1 meter per 3 seconds
median trail
so that's not a rectangle split into three parts 
?
ashen mist
well what do you want your rectangle to represent
median trail
I have to think more about this 
median trail
@median trail it might help to think about "rise over run"
it's just that that doesn't make sense for me haha
abstract scaffold
each rectangle represents distance travelled per second. the width of each rectangle is not all constantly 1s.
the more rectangles you have to draw... the more time it takes to cover the same distance.
thus fewer rectangles is faster indeed. but your labelling of the rectangles is just a tad incorrect
median trail
each rectangle represents distance travelled per second. the width of each rectangle is not all constantly 1s.
so how do I represent this
median trail
i have a question, do mathematicians consider dx is a non-zero constant? like how do I know the derivative at certain points represents more distance traveled in the same time than at other points if dx is not the same?
abstract scaffold
its distance being measured over a constant 1s. not constant distance measured of varied time.
it's an infinitesimal width in the x direction.
treating it as an exact 0 just seems off.
median trail
If delta X is different I have no way of knowing which of the two triangles I drew is the fastest and which is the slowest
Oops
abstract scaffold
the point is we make that delta x as small as possible through limits
median trail
I need to compare distances travelled in the y direction using the same distance travelled in the x direction
To know which of the two is the fastest
No?
abstract scaffold
yeah. make delta x constant. then see which delta y is bigger
median trail
exactly
abstract scaffold
and as you make delta x approach 0, it gets more accurate
abstract scaffold
la derivada in a nutshell. haha
median trail
yea haha
I just had to understand what a rate was and what makes something "faster"/"slower"
median trail
did we get rid of the abs(u(x)) because the expression on the right-hand side of the equation is always positive? @abstract scaffold
(Context: Linear Differential Equations)
this is for first order LDE
abstract scaffold
@median trail is this the integrating factor method?
pues no importa si eliges el caso positivo o negativo.... pero "nos podemos simplificar la vida" y elegir el caso positivo.
median trail
@median trail is this the integrating factor method?
pues no importa si eliges el caso positivo o negativo.... pero "nos podemos simplificar la vida" y elegir el caso positivo.
yes
why though
does it not affect at all?
abstract scaffold
@median trail si multiplicas ambos lados por 2... tienes que dividirlo entre dos en el futuro....
asi que es inutil pensar en otras constantes
en este método, estás tratando de buscar "una función" para multiplicar en ambos lados para que puedas resolver la ecuación diferencial en una manera muy fácil
|mu(x)| = c_1e^\int p(x)dx es toda la familia de funciones que puedes elegir como tu factor de integracion(?
median trail
is the dx missing on the right-hand side of the last equation?
abstract scaffold
yes. dx is missing.
factor integrante. that's what i was looking for
just a typo. should stick a dx there.
@median trail ¿puedes ver que si decido elegir:
-e^\int P(x) dx (el caso negativo).... puedo usarlo... pero es inutil porque tengo un signo negativo en el lado izq, y tambien en el lado derecho....
asi que, haz que tu vida sea mas facil por favor.
or any constant c_2 as a matter of fact
that constant just becomes a useless factor on both sides.
it might be easier to see by actually doing examples
median trail
I'm gonna read through your explanation once I'm done with studying for my DE class for today uwu thanks for helping me a lot
fallow dock
does programming count as math
summer tinsel
Never mind
fallow dock
thank god, I live here and I have nowhere to go
now you must solve my riddle:```python
False == False in [False]
True```
gusty ermine
math* fuck the UK
now you must solve my riddle:```python
False == False in [False]
True```
@fallow dock
gusty ermine
déjame pensar
fallow dock
don't actually call me
gusty ermine
ping
okay pues
False en [False] es False
False == False es True
dejame usar mi computadora
OH
no
de verdad no entiendo nada
fallow dock
nice
gusty ermine
decíme como que es True
fallow dock
dependiendo del lenguaje, vas a obtener diferentes resultados
la mayoría de hechos dirán false
en Kotlin es posible escribirlo casi de la misma forma:```kotlin
false == false in arrayOf(false)
res0: kotlin.Boolean = false```
fallow dock
no, es algo más, esto es propio de Python y otros lenguajes
fallow dock
en Python es posible encadenar operadores
por ejemplo
>>> 6 < 5 < 4
False```esto no es (6 < 5) < 4, porque entonces sería False < 4
gusty ermine
interesante
fallow dock
y ya que estamos, para hacerlo más confuso:```python
False < 4
True```en Python, los booleanos heredan deint, así queFalsees 0 y eso es menor que 4
encadenar esos operadores como python A OPER B OPER Cprovoca algo comopython A OPER B && B OPER C
entonces
gusty ermine
OH YA ENTENDÍ
fallow dock
False == False in [False]```es algo como```python
primer_false == segundo_false AND segundo_false IN [False]```eso es lo que pensé pero estaba como
eso no es posible
guau
muy interesante de verdad
también como se dice PEMDAS en español (el orden de operaciones creo)?
fallow dock
también es gracioso ver al type coercion en JavaScript:```js
5 < 2 < 1
true```
falso es menor que 1, por supuesto
gusty ermine
> 5 ?
fallow dock
sólo es el prompt de la REPL
gusty ermine
oh oh, ya veo
fallow dock
> console.log("hola men")
hola men
undefined```es que uso Node para eso
JavaScript sufre de no tener una filosofía clara y haber cambiado el paradigma varias veces lol
y va más allá de == vs ===
> [0, 2, 5, 11].sort()
[ 0, 11, 2, 5 ]```como estoque también tiene explicación, simplemente son tratados como strings
gusty ermine
eso ya lo sabía
que javascript compara (?) números por su
pues no se como puedo decirlo en español pero que
no es el valor total del número (o variable) pero el valor en un posición
fallow dock
también el hecho de que las clases sean 90% syntatic sugar sobre prototypes
fallow dock
uh, no me sé los términos específicos de esas cosas, era orden lexicográfico?
gusty ermine
creo que si
pues me entendés
también te voy a ping después, tengo que bañarme y después ir al mercado
fallow dock
> {}.__proto__.x = 100
100
> {}.x
100
> Array.x
100```epic> liek = {
... length: 5,
... 3: 'hola',
... 10: 'fuerita'
... }
{ '3': 'hola', '10': 'fuerita', length: 5 }
> Array.prototype.forEach.call(liek, n => console.log(n))
hola```me gusta hacer deformidadessi tenés google, no tenés que memorizarte nada
viral shard
bueno en eso tenes razon xd
fallow dock
tu cerebro va a recordar los que uses más frecuentemente
en todo caso, suena a que no tenés un autocompletador, eso está mal (?)
viral shard
tengo. El VS Code uso y suele autocompletar todo. Pero empecé hace poco con JS y el curso que estoy haciendo me hace leer la documentacion primero antes de hacer proyectos
fallow dock
la parte importante es aprender a encontrar documentación y saber interpretarla
viral shard
la parte importante es aprender a encontrar documentación y saber interpretarla
@fallow dock https://devdocs.io/ esta pagina encontre hace poco y esta buena
gusty ermine
tu cerebro va a recordar los que uses más frecuentemente
@fallow dock si, y también es mejor que usas el documentation cuando no sabes algo
fallow dock
la fuente sigue siendo MDN
gusty ermine
en vez de memorizar, xq cosas pueden cambiar
fallow dock
eso en frameworks xd
viral shard
Una pregunta. Es real eso de que los developers googlean en el trabajo? O es un meme nada mas?
gusty ermine
sí lo gocen
viral shard
Porque tener google en el trabajo suena buenisimo la verdad jaja
gusty ermine
lo hanen**
fallow dock
la parte de copypastear de SO no es real en mi experiencia :|
boreal peak
We should make a channel for maths specific. Call it NerdLand. This chat is active on it 👀
gusty ermine
es para mi jaja
viral shard
A ver pero tu jefe sabe que googleas o es algo que se hace a escondidas? xD
gusty ermine
depende de tu jefe
pero en mi opinión, tenés que esconder que usas google
tu jefe es una mierda y vas a odiar trabajando para el
boreal peak
Who doesnt Google at work
viral shard
Bue la meta última sería ser freelance entonces
viral shard
We should make a channel for maths specific. Call it NerdLand. This chat is active on it 👀
@boreal peak Or we should rename this channel
gusty ermine
the math talk is amazing
boreal peak
But it has no real purpose, general is already not tied to topics
gusty ermine
everyone here is really intelligent and i love it
boreal peak
Or language switch. Its just a general but a bit more rigged on words
viral shard
Yeah, we should talk to the mods about this
It could be nice, for better organization
boreal peak
Ye, its been active on math for a while
There's lots of coders/programmers/CS students on discord
And engineers etc
gusty ermine
and weebs
boreal peak
Nono but weebs is another branch
viral shard
coders weebs
gusty ermine
casi la mitad de las personas aquí tienen una foto de anime
viral shard
JAJA exactamente
exotic kiteBOT
fallow dock
yo no soy programador ni weeb
boreal peak
What do you study then, Mauricio
fallow dock
magia de conjuración
viral shard
otaku e ingeniero de software
gusty ermine
soy ex presidente
boreal peak
Wdym, you were talking about math and the other day you were talking in a very knowledged manner
You are a programmer of some kind
Stop lying
fallow dock
nunca he hablado de mates lol
boreal peak
JavaScript
gusty ermine
no soy obama
gusty ermine
entonces mi nombre es obama obama?
viral shard
obama barack
viral shard
now this is the off topic I wanted
boreal peak
Same
Now I can actually add something instead of being disruptive to the math geniuses
snow compass
median trail
We should make a channel for maths specific. Call it NerdLand. This chat is active on it 👀
@boreal peak ok kath
median trail
@boreal peak uwu
@boreal peak don't you know the uwu code?
if someone uwus you, you have to uwu back
median trail
ahh
boreal peak
@median trail UwU back 🥚
median trail
uwu 🤤
boreal peak
ashen mist
def uwu(uwu):
uwu(uwu)
no
edgy quarry
xDDD
fallow dock
(lambda uwu: uwu(uwu))(lambda uwu: uwu(uwu))```ok pero hay un lenguaje UwU: https://github.com/Deltaphish/UwUpp
UwU is this fibonacci?
a iws 1
b iws 1
c iws 0
OwO *notices 100 gweatew than a *
c iws b
b iws b pwus a
a iws c
n iws n pwus 1
stawp
nuzzels a```jajajajajajaja
@fallow dock dios mio
nyaa *fiwb(a)*
*notices a gweatew twan 1*
c iws fiwb(a minwus 1) pwus fiwb(a minwus 2)
stawp
*notices a eqwall twoo 1*
c iws 1
stawp
*notices a eqwall twoo 0*
c iws 0
stawp
wetuwn c
nuzzels(fiwb(20))
no puedo mas
fallow dock
ashen mist
"stawp"
grim lava
lol
agile robin
boreal peak
twin bridge
gusty ermine
Private message me so I can save it pls
boreal peak
I can see that
still radish
it seems like being a mod sucks
boreal peak
It does.... You cant hangout with people as normal anymol
Its cool to care and manage a server tho... Very challenging. But you learn so much
fallow dock
it's alright when the community is relatively small or predictable
when it's like 100k+ people distributed in many types of communication channels and activities and the faces you see every day are always new, it becomes really tiring
I don't feel like dealing with that
many have a stronger mental capacity than me tho
boreal peak
I'm the opposite 
I wouldn't moderate a small server... There's nothing to moderate... I guess I also talk about admin. When you were are admin the whole sever is part your responsibility
You gotta think of projects ideas and analyze also. Make good responses to situations
fallow dock
I never dared to administrate a community, you'd better pay me
boreal peak
Nah it's fun
But you gotta care
And you gotta trust and respect your team
Other wise, no point
still radish
I hate being a mod in real life too
boreal peak
Ig it's rare to like having responsibility over others and organize stuff
fallow dock
>>> this
res0: Line_0 = Line_0@748904e8
>>> this
res1: Line_1 = Line_1@42107318
>>>
>>>
>>>
>>> this
res5: Line_5 = Line_5@3957d88b
>>> this.javaClass
res6: java.lang.Class<Line_6> = class Line_6```what a weird implementation for a REPLthat guy might or might not be able to help -> @median trail
maybe you should just say what you're trying to do tho
gusty ermine
i need major help
@gusty ermine we can try lmao
ight can i post a picture of the problem here?
totes (totally, sure yes)
ight bet
also send me your profile photo it's funny
only if the problem is solved
lmao i got you
And away we go
can you use L'Hôpital's?
my proffesor has not gotten there
Oof then shit
and using it would be obvious that i used the internet
i already tried multiplying and dividing by the conjugate of the denominator but i got something that would work
let me do it so i can show
I'm stuck here
is the answer 0?
i believe its 3/2
cause with the conjugate the bottom stops becoming 0, and the top has a 0 in it
wait
cause with the conjugate the bottom stops becoming 0, and the top has a 0 in it
@gusty ermine my thoughts exactly
dejarme voy a hacerlo con lhopitals
ok
appreciate it
near berry
l'hopital should give 3/2 yeah
gusty ermine
yeah thats what the calculator tells me to do but since we havent gotten there in the actual class i cant use it
near berry
Try multiplying by (sqrt(4x+5)-3) in the numerator / denominator instead?
(Instead of (sqrt(4x+5)+3))
gusty ermine
i have to use the conjugate
near berry
I haven't checked yet but that should be a lot more useful
gusty ermine
saque 0
perame
the problem is that once the sqrt on 4x+5 gets eliminated, 5+ 3^2 gives me 14
3/2
if only it was 5-3^2 then it would be -4 and i could simplify
ashen mist
I thought (a+b)(a-b) is a^2 - b^2
gusty ermine
@near berry imma try what you said
I thought (a+b)(a-b) is a^2 - b^2
@ashen mist yeah thats a difference of squares
ashen mist
He had a^2 + b^2on the paper
gusty ermine
What can i help you with
@median trail a calc problem
median trail
Oh ok
gusty ermine
we know the answer but i cant use that method yet
gusty ermine
the question directly says to use conjugates
@near berry didnt work
it had promise tho
gusty ermine
near berry
(x+a) * (x+a) is rarely helpful cause you just get a messier equation
but (x+a) * (x-a) is frequently useful cause you end up with x^2 - a^2
which you can do a lot more with
Can you share a picture of your work like you did before?
gusty ermine
sorry i went to the bathroom, yes give me a moment
median trail
near berry
Sure, sorry 👍
gusty ermine
@median trail so it was conjugate
ashen mist
Yo
median trail
you can tell how much my markers were wearing out on each step 
gusty ermine
you can tell how much my markers were wearing out on each step
@median trail you're fucking amazing
debes ser un admin
do you guys wanna do another one👁️ 👄 👁️
near berry
Sure, have you given this one a solid attempt?
gusty ermine
its ok i can do this one
fallow dock
Aunque a veces he solucionado cosas mientras me duchaba
THE MITOCHONDRIA IS THE POWERHOUSE OF THE CELL
grim lava
👀
fallow dock
Guys, look at JavaScript's math```js
1000 / 0
Infinity```
you probably thought I was going to complain about https://0.30000000000000004.com/ (?)
I know it's not JavaScript's math per se, but what a faulty design
grim lava
same thing happens in c# with floats and doubles 
and java, but i think thats a standard for floating point numbers
idk
fallow dock
you're talking about the long number, yes, I was talking about the allowed division by zero
which iirc is also specified in some way in IEEE 754 but I don't know the details and I can't look it up rn
I find it "faulty" because I really can't tell why anyone would want that in a browser lol
grim lava
no, i mean dividing by zero being infinity
fallow dock
ah, but you can use doubles or whatever
grim lava
but the .30 blah blah blah as well i suppose
grim lava
are all numbers automatically represented as floats in js?
grim lava
fallow dock
https://en.m.wikipedia.org/wiki/IEEE_754 the behavior is as you would expect, at least
JS is full of these little weird details
Ah, doubles are also defined there, right
I suppose you could use BigDecimal but what a pain in Java lol
seems JavaScript Number is technically a double, since it's 64 bits
gusty ermine
es buena ciudad Monterrey?
glossy shuttle
sip
gusty ermine
hay Tim hortons allá?
glossy shuttle
sí
past harbor
has visto lo que pasó con git? @ashen mist
glossy shuttle
¿de dónde eres? @gusty ermine
past harbor
Bueno, creo que empezó todo hace mucho tiempo pero me acabo de dar cuenta de algo
gusty ermine
De los EEUU
glossy shuttle
ustedes tienen el In-N-Out 😠
gusty ermine
Jaja eso
gusty ermine
Sí
glossy shuttle
nice
gusty ermine
Mis padres son de Puebla
glossy shuttle
ahh genial
gusty ermine
Ya me tengo que ir
glossy shuttle
okk
ashen mist
qué
past harbor
La rama dejará de llamarse
master y será main
Parece ser que la gente que va con el "lenguaje inclusivo" dando por culo, denunció a Git
por incitar el odio/racismo
Dicen que la palabra master viene de los grupos de África en el que sólo hay un hombre al poder
Cuando lo leí, me morí de risa
@ashen mist
Desde hace dos meses o así la gente empezó a cambiarle el nombre a la rama, ya no va a ser "master" sino "main"
ashen mist
@past harbor oh wow
past harbor
😄
glossy shuttle
boreal peak
Chupi chupi
gusty ermine
Eso se toma en Brasil
median trail
Thats what we call it in venezuela
glossy shuttle
xD
en méxico hay 3249908492384 maneras de decirle
una parte le dice bolis, otra gelatina, otra sabalito,
boreal peak
Pero no chupi chupi?
glossy shuttle
no jajaja
fallow dock
hola Viossa
gusty ermine
como estan hoy?
fallow dock
bien y tú
gusty ermine
bien Yo quiero hablo espñol porque yo solo hablo inglés
gusty ermine
Gracias
fallow dock
allí la gente debería hablar en un nivel básico y corregirte, creo
ashen mist
hola
fallow dock
también habían cambiado todas las referencias de whitelist/blacklist del kernel de Linux
no recuerdo a qué
algo tipo allowlist (?)
ashen mist
blocklist y allowlist?
fallow dock
creo idk
ashen mist
y qué va a pasar con "whitehat" y "blackhat" lol
fallow dock
igual creí que lo de main lo habían hecho en GitHub nomás pero me salió del loop hace meses 
ashen mist
no sabía que lo habían hecho
hasta hace una hora o algo así
cuando Evil me avisó lol
fallow dock
taba en las news de GitHub
de lo de git ni idea
pero igual que el kernel está relacionado con el señor Linus
cuando primero pasó lo de GitHub hubo todo un revuelo porque eso salió en medio de BLM
y muchos no le veían sentido a cambiar el nombre de master cuando no veían relación master-slave en las branches
como sí lo hay en otras cosas
y fue tipo "weno GitHub quiere tener buenas apariencias"
pero también salieron unos a decir "nono, en realidad ese master si se refiere al amo" y citaban links a mailing links de Gnome (¿?¿?) que a su vez citaban fuentes de algún otro lado
y ni idea la verdad
no sé si hay relación o no xd (originalmente)
fallow dock
sí, ese es el argumento que se daba en general
ashen mist
con bluetooth, hay "master" y "slave", y por eso tendría sentido
fallow dock
pero también decían
"ok pero master bedroom viene de X origen, donde hay un amo de esclavos"
en dev.to había una de las tantas discusiones sobre el asunto
ashen mist
"master" también trata con los servidores, o sea personas que no son esclavos
no sé, para mí significa algo como "main" a menos que se use como "my master"
fallow dock
idk idc xdd
yo tampoco le veo connotaciones implícitamente racistas
sino qué es un master's degree, creo que en ese caso tiene que tener una relación indirecta con por ejemplo maestro del español
igual que kung fu master
https://www.zdnet.com/article/github-to-replace-master-with-alternative-term-to-avoid-slavery-references/ esta fue la noticia original
luego de eso pasó lo del kernel y demás
I think
ashen mist
weno a mí me da igual
si quieren cambiar los términos para evitar problemas, que lo hagan
fallow dock
no, viejo, ofendete, decile a tu compañía que se cambie a GitLab
ah re
no sé si GitLab y otros siguieron el mismo camino
fallow dock
tengan un Gitea local y que sean 3
tengo un amigo que tiene un montón de SBCs (como la Raspberry Pi) y tiene montones de servicios en su casa xdd
esto es parte de un esquema de su casa (?)
y encima los usa
yo sólo le reviso el Gitea y le corrijo código (?)
el tipo es "weno quiero descargar X cosa de bittorrent" y tiene el servicio ahí en su nube local
y así con todo
es un huge media center
en mi casa hay una RPi y no tengo nada lol
fallow dock
estás diciendo que tu tiempo en casa es invertido en el jardín y no como sysadmin de una locura?
fallow dock
@grim lava me corrijo, agregaron un unbound integer a JS hace unos 11 meses definitivamente. Aunque no es para usar en todos lados, es de uso específico, así que no soluciona mucho xd
There is no separate integer type in common everyday use. (JavaScript now has a
BigInttype, but it was not designed to replaceNumberfor everyday uses.37is still aNumber, not aBigInt.)
es similar a BigInteger de Java o los enteros de Python, so, de precisión arbitraria
> for (let i = 0n; i < 5n; i++) console.log(i)
0n
1n
2n
3n
4n```la notación es medio extraña tho> 1n / 0n
Uncaught RangeError: Division by zero```epicardo> 99999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999n
99999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999n```big boi
intenté hacer 99999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999n << 999999999999999n y se murió Node, no lo intenten en casa (?)
slender merlin
Hello what Is this
fallow dock
it's #☕・general but stronger
gusty ermine
por que encuentro operaciones arimeticas en off topic jaja
median trail
@abstract scaffold if I have 4m times 2s is that equal to 8m/s or 8 m*s
if the answer is 8m/s, why 8m/s * 1s = 8m
abstract scaffold
it's exactly as you say.
4m * 2s = 8 metre seconds (whatever the fuck this means)
and 8m/s * 1s = 8m
speed = distance/time
distance = speed * time
abstract scaffold
yeah. it doesn't make sense practically. or at least not any i can think of.
@median trail another example with units multiplying together.
Area (metres by metres m^2)
Volume (length x width x height m^3 metros cubicos... o lo que sea (cm, km etc....))
median trail
doing 4m/2s is just a fast way to get how many meters I traveled in one second?
abstract scaffold
4m/(2s) = 2m/s
as long as you have your units right, then yeah.
if you travelled 4 metres for 2 seconds... then it must be your average speed is 2m/s
1 kWh (one kilowatt hour)
1 * 1000W * h
1000 * J/s * h
1000 * J/s * 60 min
1000 * J/s * 3600 s
1 KWh = 3 600 000 J (joules)
median trail
so kWh is not kW each hour?
median trail
I have another question if f'(x) = dy/dx represents the slope at x = k, why this linear approximation gets better and better for small values of dx because f'(x) is a value that's like how much y changes for one unit in the x direction
abstract scaffold
you mean f'(k)?
median trail
Ye
Like doing dy = f'(k)dx is a line that helps me understand how much dy changes depending on dx
But why does it get better and better when dx is smaller
abstract scaffold
because when dx is approaching 0, you get the tangent.
which is ultimately what you want.
median trail
Ah and since it's a line the slope dy/dx is the same when dx is small than when its large
abstract scaffold
more or less. yeah. la pendiente es aproximadamente igual cuando dx es chiquito
and not really accurate when dx is large (for obvious reasons)
median trail
Exactly because the error between the tangent line and the graph gets smaller
abstract scaffold
mhmmm
sweet plume
Is it allowed to look for a tutor in here?
median trail
A tutor for what?
sweet plume
Learning Spanish. :p
past harbor
sweet plume
Thanks homie 😛
sweet plume
My bad!
past harbor
Si necesitas a alguien que te ayude, puedes mandarme un DM
Puedo corregirte y explicar gramática, @sweet plume
sweet plume
Thanks you so much! I definitely will man!
past harbor
hablame x dm
median trail
=tex
=tex \frac{dy}{dx} + ctg(x)y = tan(x), p(x) = ctg(x);f(x) = tan(x);\varkappa(x) = \left | sinx \right |
@abstract scaffold if I have this do I have to like get two general solutions, right? Like when sinx >= 0 and sinx < 0
I'm not sure about this exercise because i get this
=tex \frac{dy}{dx} + ctg(x)y = sec^2x, p(x) = ctg(x);f(x) = sec^2x;\varkappa(x) = \left | sinx \right |
rotund pawnBOT
abstract scaffold
@median trail creo q no necesitas preocuparte del valor absoluto
\, para un espacio
\\ para un linea nueva
solo estas tratando de buscar "un factor integrante"
whether you choose +/- sin(x), no importa
median trail
=tex when, sinx,>=,0\ sin(x)y = \int sec^2(x)dx,+,C1\ sin(x)y = tan(x) + C\ y = cos(x) + \frac{C}{cos(x)}
rotund pawnBOT
median trail
sinx disappeared
so, do I still have to account for that when typing the solution interval?
like, it'd be
abstract scaffold
=tex \frac{dy}{dx} + ctg(x)y = sec^2x
median trail
=tex when, sinx,>=,0\ sin(x)y = \int sec^2(x)dx,+,C1\ sin(x)y = tan(x) + C\ y = cos(x) + \frac{C}{cos(x)}, I = (0, \frac{\pi}{2})
median trail
oh
OH I SEE
wait a second
=tex \frac{dy}{dx} + ctg(x)y = \frac{sec^2x}{sin(x)}, p(x) = ctg(x);f(x) = sec^2x;\varkappa(x) = \left | sinx \right |
this is
rotund pawnBOT
abstract scaffold
ok. makes more sense now.
median trail
and I get this
=tex when, sinx,>=,0\ sin(x)y = \int sec^2(x)dx,+,C1\sin(x)y = tan(x) + C\y = cos(x) + \frac{C}{cos(x)}, I = (0, \frac{\pi}{2})
rotund pawnBOT
median trail
I chose (0, pi/2) because I accounted for the sinx >= 0 and cos(x) cannot be zero
when 0 <= x <= 2pi
oops I made another mistake
=tex when, sinx,>=,0\ sin(x)y = \int sec^2(x)dx,+,C1\sin(x)y = tan(x) + C\y = \frac{1}{cos(x)} + \frac{C}{cos(x)}, I = (0, \frac{\pi}{2})
rotund pawnBOT
median trail
this should be correct now
abstract scaffold
=tex
\varkappa(x) = \begin{cases}
e^ln(sinx) if sin(x) > 0 \
e^ln(-sinx) if sin(x) < 0
\end{cases}
rotund pawnBOT
abstract scaffold
oops. forgot to close stuff
median trail
ye
abstract scaffold
@median trail no te procupes de los dos casos. va a ser lo mismo. +/- sin(x)
median trail
yea
abstract scaffold
so u don't need domain restrictions
median trail
my question is do I have to account for the sinx >= 0 when choosing the solution interval?
abstract scaffold
nope
abstract scaffold
you don't need to state an interval
abstract scaffold
like, interval could be something like (0,pi) for one branch i guess
rotund pawnBOT
median trail
if I have this, do I have two identical cases because when x is greater or equal to zero is the same as x being less than zero
abstract scaffold
yep. its identical
median trail
I'm confused because e^x is greater or equal to one when x >= 0 and 0 < e^x < 1 when x < 0, so Idk if I should just say they are identical and use that
abstract scaffold
it shouldn't affect the final result.
you can try treating them separately and realise it's the same case
=tex |x|^2e^x = x^2e^x \forall x \in \mathbb{R}
rotund pawnBOT
amber barn
does anybody here understand pre-calc/calculus?
(and is willing to waste a little bit of their time)
gusty ermine
décinos la pregunta
abstract scaffold
do you know your log laws?
amber barn
mm sort of
gusty ermine
do you know your log laws?
@abstract scaffold ^ con eso podés simiplificar
amber barn
im mainly not sure what to do about the coefficients
amber barn
yeah, but am i correct to assume you cant use the addition log law when theres who different numbers in front of the natural log
gusty ermine
Use product and qhotenr rule
yeah, but am i correct to assume you cant use the addition log law when theres who different numbers in front of the natural log
@amber barn yes you can
abstract scaffold
@amber barn indeed. so you need to find a way to get the coefficient inside the log. or maybe another method
gusty ermine
3ln(2) - ln(20) + 2ln(5)
@amber barn take out 3 and 2 so it's
6 [ ln(2) - ln(20) + ln(5)]
wait lemme double check if you can do this
abstract scaffold
^that's a bit off
u can't really do that
because if u expand back, you dont get what u started with originally
gusty ermine
@amber barn take out 3 and 2 so it's
6 [ ln(2) - ln(20) + ln(5)]
@gusty ermine lemme re do it
Y LN(X) = LN(X^Y)
abstract scaffold
that's the law you need.
gusty ermine
3ln(2) - ln(20) + 2ln(5)
@amber barn So it's ln(2^3) - ln(20) + ln(5^2)
2^3 is 8, 5^2 = 25
with quotient and product rule, left to right
ln(8/20) (from ln(8) - ln(20))= .4
.4 * (from ln(.4) + ln(25) (product rule)) = 10
answer is ln(10)
@amber barn
amber barn
thank you so much!!! sorry i was writing it all down
i really appreciate it
we took a precalc diagnostic test today and it would seem my memory from over a year ago is lacking : (
abstract scaffold
=tex Prove: $yln(x) = ln(x^y)$ \
Let $\xi = yln(x) \
\implies \frac{\xi}{y} = ln(x) \
\implies x = e^\frac{\xi}{y} \
\implies x^y = e^{\xi} \
\implies \xi = ln(x^y) \
\therefore yln(x) = ln(x^y)$ as required
=tex Prove: yln(x) = ln(x^y) \
Let \xi = yln(x) \
\implies \frac{\xi}{y} = ln(x) \
\implies x = e^\frac{\xi}{y} \
\implies x^y = e^{\xi} \
\implies \xi = ln(x^y) \
\therefore yln(x) = ln(x^y) as required
gusty ermine
ni siquiera dios puede entender que estás haciendo
abstract scaffold
amber barn
thanks!
gusty ermine
it's obvious but just be careful with the case y=0
amber barn
gotcha : )
abstract scaffold
the law still works for y = 0.
because anything raised to the 0 is 1. (unless the base is 0)
so the things to caution is when x <= 0
abstract scaffold
depends on the function
ln(x) you just gotta know the graph.
it's the inverse of e^x
@amber barn do you know the domain and range of e^x?
amber barn
not exactly
abstract scaffold
ok. do you know what domain means?
amber barn
the problem im working on asks for the domain of the function f(t) = ln(25-t^2)+(1/t-3)
the range of values on the x axis that the function reaches?
abstract scaffold
yep. the "x" values you can plug in such that you get an ouput "y" value
well. in ur case, "t" values to get an f(t)
@amber barn so. let's start simple. what x values of e^x can and cannot be substitued in?
amber barn
there are certain values that can't be substituted in?
abstract scaffold
ok. it was a trick question. because the domain is all real x
amber barn
abstract scaffold
@amber barn now that the domain of all real x has been established. how about the range of y values for y = e^x ?
amber barn
okay so im pretty sure theres some sort of limit right?
abstract scaffold
or maybe it might be easier to find, what range of y values can't be an output?
amber barn
anything at 0 or below?
abstract scaffold
exactly. thus the range is y > 0
amber barn
ah okay
abstract scaffold
now because ln(x) is the inverse of e^x
swap the domain and range around
domain : x >0
range: all real y
we can generalise it to say for y = ln(f(x))
domain: f(x) > 0
range: all real y
@amber barn so for your question f(t) = ln(25-t^2)+(1/t-3)
let's just focus on the ln first and deal with the other function later
don't try to everything at once. just split things into chunks.
do you think you can find the domain of ln(25-t^2) now? @amber barn
abstract scaffold
are you stuck on 25 - t^2 > 0 or do you think you can handle it? remember this is the thing inside the log... and the thing inside the log must be positive
as we established from the inverse of e^x that the domain of ln(x) is x>0
so we have to solve for 25 - t^2 > 0
abstract scaffold
@amber barn the other part we still have do deal with as it still affects the range and domain. but we first deal with ln() then the other part later
amber barn
okay
abstract scaffold
after doing things separately, you then combine the ideas into one to find the final domain for the whole function
abstract scaffold
with 25 - t^2 > 0?
abstract scaffold
the first step was to deal with the log function first:
find the domain of the log function. that is when is the inside function positive.
@amber barn almost.
amber barn
wait t<5
abstract scaffold
not quite
amber barn
i forgot to account for the sign flip
abstract scaffold
try sketching this parabola
what are the t intercepts.
t<5 doesn't quite cut it.
like for example. try substituting t = -100 into 25 - t^2 and see if that satisfies the inequality 25 - t^2 > 0 or not
amber barn
i guess it doesn't
abstract scaffold
edit: t = -100, a really negative number
what's 25 - 100^2 is super negative. so t < 5 is not quite it.
it's part of the solution though
@amber barn do you know how to sketch this parabola?
try just sketching g(t) = 25 - t^2
amber barn
okay
abstract scaffold
and then deduce from your sketch which t values satisfy g(t) > 0
inequalities can be tricky because you can't really treat them like equations. like you have to be careful when taking square roots of both sides.
amber barn
it would be downwards facing with a y-int of 25, so all y values below 25 would work ?
abstract scaffold
thus the graphing approach is probably the best approach
@amber barn almost. not just below 25, there's some other condition
@amber barn remember we're trying to find t values, not y values.
amber barn
ohhhh okay sorry
abstract scaffold
because we're finding domain.
if we're finding range, then we'd be looking at f(t)
amber barn
so from the roots can i find a hole
abstract scaffold
i guess u can phrase it like that
amber barn
what would you actually call it?
abstract scaffold
basically I want to be sketching g(t) 25 - t^2 vs h(t) = 0 and finding when g(t) is above h(t)
the roots will help with this
so, where are your roots @amber barn
amber barn
5, -5 ?
abstract scaffold
hence. can u deduce now which t values satisfy 25 - t^2 > 0?
amber barn
would it be all real numbers?
abstract scaffold
nope. we already established that t >= 5 won't satisfy the inequality
because 25 - 99999^2 is super negative
amber barn
hmm
abstract scaffold
t<5 is partially correct
amber barn
would i use interval notation to account for the roots?
abstract scaffold
you can use whichever notation you prefer to write the domain
hence: when is 25 - t^2 > 0.
when is 25 - t^2 above y = 0
when is 25 - t^2 above the x (or t in this cases) axis?
for which t values?
amber barn
oh sorry!
abstract scaffold
between -5 and 5 exclusive.
amber barn
yeah
abstract scaffold
because -5 and 5 is 0... which we don't want to be equal to 0 either
=tex t \in (-5,5)
rotund pawnBOT
amber barn
so is finding the domain limited to numbers that are above 0?
abstract scaffold
for log functions
since the domain of a simple log function ln(x) is x>0
=wolf graph ln(x)
amber barn
ah, this is something i was not aware of
rotund pawnBOT
amber barn
thank yoou
amber barn
we still have the rest of the equation i guess
abstract scaffold
yep
thus we're not done yet
look at the other one.
1/(t-3)
what's the domain of this?
amber barn
as its own equation?
amber barn
hmm graphing radical functions is something i havent done in a while
abstract scaffold
ok. let's ask a different question. @amber barn what values of t can i not substitute into k(t)
amber barn
3
abstract scaffold
hence or otherwise, what's the domain of k(t)
remember, the domain is the t values you can substitute into the equation
amber barn
(-infinity,3)u(3,infinity)? im not sure exactly how to answer that : (
rotund pawnBOT
abstract scaffold
hence or otherwise. find the domain of your original function
ln(25 - t^2) + 1/(t-3)
amber barn
3>t<5 ? im not sure
abstract scaffold
not quite.
remember for the ln() part it was
-5 < t < 5
and for the hyperbola it was
all real t except at t = 3
amber barn
what does this function look like? im having a hard time visualizing it
abstract scaffold
try combining those two together.
amber barn
(-5,3)u(3,5) ?
abstract scaffold
yep.
amber barn
yay
thank you for your patience
i'm sure that was incredibly painful for you haha
but i really appreciate your help, i really can't afford to fall behind any more in this class
abstract scaffold
=wolf graph ln(25-t^2) + 1/(t-3)
amber barn
thanks!
abstract scaffold
the graph is pretty inaccurate. it should shoot to negative infinity as t approaches +5