Hey, I and a friend of mine gonna play Cards agaisnt humanity (app store game), someone wanna join?
#🍁・general-2
signal crypt
median trail
still radish
well
median trail
That was made using this
a = <3,8>
<3,8> = (7/3)<1,3> + (1/3)<2,3>
still radish
it + jt = at
median trail
it = <1,3>
wait
I made a mistake
and jt = <2,3>
and I could transform the cartesian plane and get another that uses it and jt as those vectors that make up any other vector in that new plane
and k = 7/3
m = 1/3 this is how much I have to squeeze or stretch out it and jt to get a
And this is pretty interesting because I could also write that vector as
a = 3i + 8j
so I have two different solutions for the same vector
by the way, it and jt stand for "i transformed" and j transformed"
I hope what I said made sense 
shrewd pendant
Everything you’re saying makes sense although I don’t really understand the part about transforming the Cartesian coordinates
median trail
I should have said cartesian plane in that part
shrewd pendant
Hm I’m not sure what the difference is. It’s been a while since I took math though
median trail
oh wait I thought you were quoting me
Yeah I just mean the XY plane
linear algebra is so interesting
shrewd pendant
so I'm gonna take a guess
are you saying that as long as the two vectors aren't coincident, then any point in cartesian space can be made up of a summation of those two vectors, and therefore you could consider that a new coordinate system?
median trail
yes
shrewd pendant
oh cool
median trail
it and jt could be considered as a new coordinate system where it and jt can generate any vector in that plane, so basically R^2
shrewd pendant
sure I don't see why not
I was never good at the semantic sort of stuff though
but I'm sure doing something like that would have some applications
abstract scaffold
@median trail yes, that's exactly it.
it's easier to visualise it with 2D as you kinda visualised it there
but 3D it's a bit harder to visualise
then for R^n, lol, wtf is that visually. so we rely on algebra for that.
https://www.youtube.com/watch?v=1zgv24QsdzI the first few minutes kinda show the shifting of coordinate systems
in 2D at least.
median trail
abstract scaffold
if it didn't form a triangle, it wouldn't have gone back to the origin. but the axioms state it goes back to the origin.
thus, c vector must be the "head to tail"
thus similarly, the converse (starting with a resultant vector) can be made with the sum of 2 other vectors where those 3 vectors make a triangle.
so starting with a resultant vector c, means that "a" and "b" can be whatever as long as it makes a triangle.
median trail
One day I want to develop the necessary skills for proving stuff by induction 
west thicket
west thicket
Gonna listen to it in the shower
unreal pagoda
singing in the shower xD
rain ermine
unreal pagoda
Lel
west thicket
Que hay de malo 
alpine cradle
Hola Pixi 
modest lantern
Ugh
I stop posting on my cats insta for a few weeks
And suddenly no one sees the photos anympre
I go from 50+ likes always to 2 likes!
still radish
Instagram para tu mascota 
modest lantern
Please be sure to follow
junior thicket
And right behind them are torties
modest lantern
She does funny things
Like screaming at the dog (she was secretly yawning but shhh)
Or waving. (She was tryna get the camera)
Or leaping (after a toy)
junior thicket
She's so cute 
modest lantern
Ikr!
junior thicket
How old is she? Can't be more than 6 months I think
junior thicket
Oh damn
I was close tho
modest lantern
Arguable that photo is 1 and a half months old
Because she was asleep and i didnt want to disturb her so i used an old photo
What is your instagram?
junior thicket
The latest follower probably xd
modest lantern
Pixie? Or moon? Both recently followed
junior thicket
Ah, moon
median trail
electronics day
silver bear
sweet cape
Edsel, que pc es ese?
median trail
@sweet cape https://www.youtube.com/watch?v=lNcuLphasDM
median trail
I bought it in the USA for around 940USD
still radish
must be a good one
sweet cape
Wow, it’s pretty normal about the price
still radish
@sweet cape what do you mean?
sweet cape
Like when you’re finding other pc with same specs, it means that it has average price
still radish
oh right yeah
mortal dagger
Multiplica
| 1 0 | | 0 0 |
| 0 0 | | 0 1 |
date cuenta que es 0, pero ninguna de las 2 matrices es nula
sweet cape
Ohh i forgot this
median trail
hahaha my university uses the same platform
sweet cape
^
median trail
hmm
real imp
a>0 and b>0
Not sure if that's correct, but that's my interpretation of "for two positive values a and b"
@median trail dw
https://www.youtube.com/watch?v=xT8agzwsR7Q this kid explained it
idk what a 10 year old is doing algebra for but its good that he did lol
rain ermine
this sort of looks like stuff ive learned
ashen mist
No tenés que mostrar que (ab)^c = (a^c)(b^c)?
real imp
no
√a ⋅ √b =√a ⋅√b ∀ a>0 and b>0
that's what it says
huh i had written it wrong whoops
mortal dagger
se refiere a que si no tienes que demostrar que el exponente es distributivo antes de usarlo
median trail
I don't know how to use axioms at this "simple" level
mortal dagger
porque por ejemplo, en el caso de las matrices el exponente se distribuye de una manera especial
real imp
oh
uh
no tengo idea
no creo que sea necesario
porque ya tenemos la propiedad conmutativa de la multiplicación
y lo que se quiere demostrar no es eso, en este caso
es la propiedad distributiva de la raíz
supongo que se llamará así
bueno no, no es distributiva porque no tiene un +
pero se entiende
fathom flame
past harbor
@gusty ermine 😛
still radish
median trail
@safe igloo @thin copper hahahahaha
safe igloo
😂 😂
thin copper
vesavaina*
safe igloo
Si yo oigo ese coño hablar tampoco salgo
fathom flame
JAJA
brittle vector
alguien está armando un ordenador y necesita un código de windows 10 pro? quiero regalarlo porqué lo compré por error
still radish
how come my discord is so compressed
what can I do
can I close the side bars or something?
oh ctrl + u
still radish
nice one
gusty ermine
median trail
4(cosx(1/2) - sen(x)(sqrt(3)/2))
@gusty ermine
median trail
cos(x+y) = cosxcosy - senxseny
cos(x-y) = cosxcosy + senxseny*
cos(pi/3) = 1/2
sen(pi/3) = sqrt(3)/2
that's all you need
gusty ermine
Sorry I don't think I understand
I get the cos(x+y) and cos(x-y) and what you explained but I don't understand why you got 4(cosx(1/2) - sen(x)(sqrt(3)/2)) as the answer
median trail
x = x
y = pi/3
cos(x+y) = cosxcosy + senxseny
cos(x+pi/3) = cosxcos(pi/3) + senxsen(pi/3)
cos(pi/3) = 1/2
sen(pi/3) = sqrt(3)/2
cos(x+pi/3) = cosx(1/2)+ senx(sqrt(3)/2)
so now that we have what cos(x+pi/3) is equal to, let's multiply it by 4
4cos(x+pi/3) = 4(cosx(1/2)+ senx(sqrt(3)/2))
gusty ermine
The question looks weird, I am not sure if it is pi or not (??/3 thing)
nevermind
@median trail Thanks a lot! I probably have more questions haha
median trail
I'm pretty sure it's pi since that's the only way to get sqrt(3) haha
median trail
so, the part that's on the first quadrant is basically the one that's between two roots of your equation
gusty ermine
so the vertex? Since it's a parabola?
median trail
I think the vertex is one, and the other would be...
y = 3x - x^2
y = x(3-x)
so you have x = 0 and x = 3
gusty ermine
Is it possible for me to do dy/dx and find zero?
median trail
so I guess you have to do the integral from 0 to 3
and then divide it by 3
well... You can but you are just gonna find one of the roots
since remember that the vertex (I think this is what it is called) of the parabola is always the max or min point depending on if it's upwards or downwards
but okay
gusty ermine
mm yes
median trail
the integral from 0 to 3 of the function 3x - x^2 is = (3x^2)/2 - (x^3)/3 from x = 0 to x = 3
gusty ermine
I got -3
median trail
sorry my markers are running our of tint
x2 and x1 are the values used to define our integral
gusty ermine
Your handwriting is beautiful
Absolutely love it
Thank you so much. I understand it.
When do I use derivative or not??
median trail
you don't need it, remember you use the derivative if you are studying how the graph "changes" over the time
I'm gonna check how to figure that one out after I get done what I'm currently doing
gusty ermine
Ah okay. Thank you!
median trail
well... so
if you thing about it, let's split the function in half, and we end up with e^x and sin x
e^x is never zero unless you use limits, but we are not gonna do that
but sin x can be equal to zero at x = 0, x=pi and x= 2pi
abstract scaffold
=wolf cosx+sinx = 0
rotund pawnBOT
median trail
so I'd say two zeroes
abstract scaffold
just draw the graph cosx+sinx = 0 or cosx = -sinx or -cosx = sinx and find relative points.
gusty ermine
I think three zeroes
Sin(0) = 0
Sin(pi) = 0
Sin(2pi) = 0
abstract scaffold
ah. wait. i didnt read the question. haha no derivatives here.
median trail
yeah hahaha
abstract scaffold
it's just solving e^x = 0 or sin(x) = 0
which can be done via unit circle
or graphing sine
median trail
ye
abstract scaffold
and show that e^x cannot be zero just by drawing the graph. so the sin(x) = 0 is the only part needed.
still radish
only 14 places to climb today
still radish
trabajo honesto
fathom flame
What app is that?
fathom flame
thanks huevito
light folio
what does it do
still radish
gives you a sentence with a word missing over and over and over and over and over....
trail basin
its better than the duolingo method imo
past harbor
¿Alguien que esté aburrido y me pueda echar una mano con algo de diseño?
eager wagon
puedo intentar aunque mis habilidades de diseño.. no sé 😄
past harbor
Necesito poner el botón de Nuevo para crear más tableros, pero no sé dónde
trail basin
a little + buttom behind that 2 ?
fallow dock
es un side menu?
shrewd pendant
tan pronto como sea posible
bold gull
¿Quién es el Isaac Newton de el server?
fallow dock
probablemente F14 en la mente colectiva
mortal dagger
Newton es el CEO de la Gravedad™️
real imp
@bold gull
median trail
AAAAAAAAA I love this assignment
For some reason the Phys 1 host could not ping the ones in the bio network
but now it can
I just turned in the assignment 
crystal kraken
Omgggg edsel tascla
median trail
real imp
Hey math gods
I invoke you
How would you interprete this?
Let p > 0 fixed. Represent in the real line the set A = {p, 2p, -p, 0}.
gusty ermine
@real imp can u translate that
wait nvm
wouldn't that be like zigzag
first line with postive slope then negative slope than positive slope
real imp
uhhhh
but
no it doesnt ask to graph
it asks to represent it in the real line
@gusty ermine
real imp
copper fox
fathom flame
gusty ermine
oh number line
gusty ermine
i dont really understand but wouldn't you put a dot on 0, and set p equal to a postive number and stuff
so if p=1, you would put the dot at -1, 0, 1, and 2
real imp
ok so this is what i thought
but idk if its correct
because uh
you dont know the value of p
you know that 0 is 0
but you have inf values in p
and you also have -p
fathom flame
p>0
median trail
@real imp I think the answer could be R
since for each p you have -p
so...
you can stay as close to zero as you want
median trail
yeah
real imp
its just the whole line then right?
median trail
I guess so
real imp
like <==========>
real imp
aight
tanks
@median trail Será así? Porque luego viene uno que tendria el mismo resultado creo...
igual no entiendo del todo a qué se refiere con "fijos"
shrewd pendant
que significa la notacion A = {w, x, y, z} ?
shrewd pendant
thanks
real imp
set A contains w, x, y and z
fathom flame
@shrewd pendant lmfao I thought u were going to explain it xd
shrewd pendant
no haha
yeah I don't get it haha
if you figure it out post it here, I'd be curious to know what they are expecting
real imp
oki
fathom flame
no
shrewd pendant
lol
shrewd pendant
@real imp
rain ermine
idk
shrewd pendant
what's oml?
rain ermine
Oh my lord
real imp
I signed up for the most elementary math class in my uni
Bc i struggle at maths
Ok so for the first one
Itd be
<---[-p]--[0]--[p]--[2p]--->
shrewd pendant
yeah
I guess the idea is just to have the distance between points equal, in both the solutions
real imp
Yeah i mean idk
rain ermine
This is why I’m gonna hate college math
fathom flame
y
rain ermine
It becomes more about letters and less about numbers
fathom flame
xd
fathom flame
du think the formulas just magically appear?
rain ermine
No
real imp
something is the letter
2+x=4.9
the letter literally plays the dot of a blank space
2+__=4.9
but you add a name to that blank space
so if you reference it more than once, you know which one ur talking about
x^2+x+2=y
real imp
??
a good example of the name calling is bhaskara's formula
(-b +- sqrt((b) ^ 2 - 4 * a * c))/ 2 * a
real imp
rain ermine
Oh that
mortal dagger
=tex x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
rotund pawnBOT
grizzled hedge
It’s the universal language of logic ❤️
misty talon
Love is the universal language of logic @grizzled hedge 💓
Hi my name is miranda cosgrove, and you're watching the disney channel.
west thicket
@marsh linden
a ver
this, basically
so basically they gather all that info from people who gave their permission to do so
west thicket
banned
untold elk
So that's the smartest shit I've ever seen
I've always wondered how did they know how bad the traffic is
muted latch
median trail
in matrices?
real imp
yes
still radish
oh good Jazn has left
real imp
matrices is the plural for matrix in case you don't know, edsel
i found out fairly reciently
severe vortex
past harbor
alguien sabe php?
copper fox
.se 
junior crystalBOT
copper fox
.se :peepowhy:
junior crystalBOT
copper fox
.se 
junior crystalBOT
bold gull
¿Alguien sabe que función tienen {} en un ejercicio matemático?
median trail
well it depends
you can use curly brackets when studying about laplace transforms, or when defining a set, or when you already have parentheses and brackets then you can use curly brackets
like
{[(2x)+5y]3z+1}5
But I don't think that's common these days
severe vortex
Yeah you don't see brackets too much until advanced calculus/set theory
exotic kiteBOT
🆙 | themaddman leveled up!
real imp
perhaps they just like curly braces
still radish
{}
real imp
mmm nice
bold gull
I'm trying to do an exercise. For now I have this:
5 + {-31/10}
mortal dagger
el A\B significa los elementos incluidos en A que no pertenezcan a B ni a la intersección entre A y B
=tex 5 + \frac{-31}{10}
rotund pawnBOT
mortal dagger
¿ese es tu ejercicio?
subtle finch
da 19/10 creo sí
bold gull
old charm
anyone know any good Japanese learning resources?
median trail
3blue1brown did an awesome job in this series of videos on linear algebra https://www.youtube.com/watch?v=kYB8IZa5AuE&list=PLZHQObOWTQDPD3MizzM2xVFitgF8hE_ab&index=3
grizzled hedge
❤️ 3blue1brown
median trail
glass dragon
@old charm there's probably some Japanese servers like this one
real imp
fathom flame
3blue1brown did an awesome job in this series of videos on linear algebra https://www.youtube.com/watch?v=kYB8IZa5AuE&list=PLZHQObOWTQDPD3MizzM2xVFitgF8hE_ab&index=3
rain ermine
@gusty ermine where can I watch totally spies
rain ermine
gusty ermine
You gave me an idea for tonight JEHHDD
rain ermine
The whole series?
gusty ermine
Probably
gusty ermine
There are tons of full episodes
rain ermine
nice
gusty ermine
Naiz
cursive wave
@real imp did you get the answer to the set thing? the A={a,b}
abstract scaffold
What does A\ B mean in matrices?
@real imp The reference you gave, that's not a matrix. That's just another set.
\ is a "set minus". excluding the elements in set B from set A
for example. Let A = {1,2,3,4,5,14} and B = {0,14}
Then A \ B = {1,2,3,4,5}
We don't want to include "0" and "14" from set A, if that makes any sense.
A \ B, I want all elements from A, excluding the elements from B.
basically find which elements are the same in both and get rid of it.
{1,2,3,4,5,14} \ {0,14} = {1,2,3,4,5} (since 14 exists in both sets, but we want to exclude both 0 and 14 [no need to exclude 0, since it already doesn't exist in set A].)
real imp
@real imp The reference you gave, that's not a matrix. That's just another set.
@abstract scaffold By "In matrices" I mean just the topic
@real imp did you get the answer to the set thing? the A={a,b}
@cursive wave yeppers
thank you catorce :D
abstract scaffold
any time
median trail
I LOVE LINEAR ALGEBRA
rain ermine
nice
bold gull
fathom flame
unreal pagoda
What is c++11
cunning scaffold
Whats the best yt channel for computer science course?
thin copper
Jajja I need the car
fallow dock
@unreal pagoda it seems the Mobile Edition was written in C++ so they could port it to iOS, which doesn't support Java
unreal pagoda
gusty ermine
I would like help on a calculus test if anyone is good at it and wants to help me- unlikely but I might as well ask
still radish
there are some maths fans here
median trail
I didn't know about this method for converting from decimal to binary
fallow dock
that applies to positional notation in general
mortal dagger
12786 = 1 * 10^4 + 2 * 10^3 + 7 * 10^2 + 8 * 10^1 + 6 * 10^0
base 12 >>> binary >>>>>>>>>>> base 10
fallow dock
dek el
mortal dagger
dek el do
cursive wave
@cunning scaffold what kind of computer science are you interested in learning?
median trail
LAUREN
cursive wave
I have various resources but it really depends on what you mean with comp-sci
suuuuup duude
cursive wave
oh which one?
median trail
cursive wave
umm can you tell me a bit more about that method
i dont really see what is going on tbh
median trail
you check if the number is greater than 128, if it is you substract the number from 128
then
cursive wave
ohhh hold on i see now
median trail
you take the result and check if it's greater than the lower power of 2
cursive wave
ok mmmm
median trail
and then you do the same thing over and over again
cursive wave
let me just refresh my memory real quick and ill get back to you asap
cursive wave
oh right i kinda see why
but idk how to explain this intuitively
can you come to a vc so i can maybe use word words to explain
median trail
I'm in class rn
swift yew
Hello 👋
cursive wave
the first thing we do is we find the biggest power of 2 that is not bigger than this number
2^3 = 8 < 9
so we know that we will need a 2^3 + something else to make 9
we subtract 8 from 9 to get 1
now we find the next power of 2 that is less than or equal to 1
which is 2^0
so now we have 2^3 + 2^0 = 9
so if we remember that from binary to decimal we use this formula:
x(2^3) + x(2^2) + x(2^1) + x(2^0)
where the xs are 1 or 0 from the binary number
so all we do is we put a 1 in the position that gives us the correct multiples of two to add to 9
so we get 1(2^3) + 0(2^2) + 0(2^1) + 1(2^0)
so in binary 1001
9 = 1001
idk if that helped at all lol
im bad at explaining over text
bold gull
@gusty ermine ¿podrías decirme el nombre de ese libro que estás leyendo?
perdón por el ping
glass dragon
@bold gull prince doesn't usually see his pings, but I think he mentioned in that channel once if you wanted to try to search up what it was
actually all he said is that it was a book related to The Witcher
if you really want an answer, you have to ping him in #📘・questions-lounge while he's actively in there typing lol
bold gull
I better go search "The Witcher book" on google, I trust I'll find it.
shrewd pendant
They are quite famous. The Witcher games and tv series are loosely based on it
real imp
Can someone explain to me why this is incorrect?
Like,
A={-1,0,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}
B={0,1,2,3,4}
HOW TF IS THE INTERSECTION NOT {0,1,2,3,4}???
shut gull
B = {-4,-3,-2,-1,0,1,2,3,4}
real imp
fuck
shut gull
Note -4^2 = 16!
real imp
nice, congratulations
shut gull
thx!
real imp
what about this one
why is it wrong
how am i supposed to know
that it can have 2 elements
real imp
tyt
shut gull
mmmm no se
exotic kiteBOT
🆙 | sangstar leveled up!
shut gull
me odie pure maths
lol
a mi, parece que los elementos de los conjuntos son arbitrarios
por eso no se como es posible decir que puede tener dos
there are no specifications on the elements of A and B
so I don't know how you can make a claimlike that
real imp
yeah like
i have literall no info
but it is just wrong like
lets say A={1,2,3} and B={1,2,3,4}
fathom flame
where du get that from?
real imp
since it says A has 3 elements and B has 4
right?
its a test
so there is NO way that A\B is different from null
since A is a proper subset of B
fathom flame
set theory?
real imp
yes
shut gull
This is a poor question
real imp
there is absolutely no way to make that not be null
shut gull
since this needs to be specified in the question itself
real imp
i got scammed man
no but there is actually no way
like even if A is completely different from B
shut gull
was my spanish making any sense btw lol
real imp
lets say A={1,2,3} and B={4,5,6,7}
shut gull
I haven't touched it since high school
real imp
|A\B| = 3
like
ok sure the answer "it can have 2 elements" is correct
since it CAN
but man what a shitty question and answer
shut gull
why?
real imp
i hate this so much
fathom flame
real imp
why?
@shut gull because it CAN have 2
fathom flame
if it can have 2 elements in common
real imp
if A={0,1,2} and B={1,2,3,4}
for example
|A\B| = 2
aaaaaaaaaaaaaaa
i hate this
and i hate even more that it makes sense now
fathom flame
xd
shut gull
i dont even know man
fathom flame
why
shut gull
this is why I stick with applied
real imp
what is applied
real imp
yes what is that
real imp
pure maths is maths for the sake of it
real imp
applied maths is maths to resolve real world problems
shut gull
basically pure maths is the root and applied is the stem
pure topics are all topics which are then used and made shorthand in applied
real analysis -> calculus
fathom flame
is it from your university? @real imp
real imp
yes
shut gull
donde estudias?
real imp
UdelaR
shut gull
no se cual es
real imp
its a public university from uruguay
shut gull
ah i see
fathom flame
what du want to study?
shut gull
estudia matematicas
shut gull
o lol
real imp
its the closest thing i have to CS
god no i dont study maths
i dont hate myself THAT much
shut gull
oh fair
shut gull
same I can't speak spanish nearly as well as I write it
real imp
i mean its understandable but it still has way too much room for improvement
(my speaking)
shut gull
well I cant understand anything anyone says when they speak it lol
real imp
oh getting to that point is just woaaa
shut gull
yea lol
too fast
and accents
rip
it needs to be clear and dumbed down for little old me
real imp
baby steps
shut gull
well im trying to find an outlet to speak it
ideally I join some world of warcraft guild or something lol
something involving gaming
so I dont have to make conversation for the sake of it
fathom flame
duolingo 
gusty ermine
Duolingo
abstract scaffold
@median trail
209 in base 10 is just
2 * 10^2 + 0 * 10^1 + 9 * 10^0
so, just use the same logic in base 2.
You can also use the same logic in hexadecimal.
209(base10) = x(base16)
16^0 = 1
16^1 = 16
16^2 = 256 (too big)
so in base 16, it should be something like
p * 16^1 + q * 16^0, where p and q are elements of {0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F}
therefore 16 * y = 209 - extra bit
209/16 = 13 remainer 1
A = 10, B=11, C= 12, D=13, E=14, F=15
therefore we have
209(base10) = D1(base16)
since D * 16^1 + 1 * 16^0 = 13 * 16^1 + 1 * 16^0 = 209
I think the problem here is you just need to understand what "base 10" means exactly. then from there you can convert to the other ones.
I see a few people have tried to explain this already.
Like,
A={-1,0,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}
B={0,1,2,3,4}
@real imp Just wanna be nitpicky here notation wise.
A = [-1,16] in this case means all REAL numbers between -1 and 16 (including -1 and -16, since it's square brackets on both ends) {integers, rational, irrational etc...}, just means not complex.
so there's technically "no way to list all the elements here" e.g. the number e and the number pi can be included in set A.
but in this question, you realise that just using the integers is enough here due to the intersection with set B.
a more rigorous way to find which x values satisfy the inequality x^2 <= 16
or you can rearrange it to find where it is below the x axis (y = 0) graph{more algebraic friendly}
abstract scaffold
similarly you can see if x^2 >= 16, then it's true for
x<= -4 or x>= 4
past harbor
Me Voy a contestar en español (si puedo lol) Estoy aprendiéndolo
(Yo) odio las mates puras
A mí me parece que los elementos de los conjuntos son arbitrarios. *
@shut gull
glass dragon
If anybody has a scanner app, this engagement in Elko City Nevada is really exciting
past harbor
alguien sabe de php, me estoy desesperando con algo
fallow dock
ni idea, pero si lo compartes tal vez alguien pueda deducirlo
past harbor
es una gilipollez
sólo intento hacer un if ternario con etiquetas de html
pero es que no va
twin bridge
avr
past harbor
tipo esta mierda
{{ condicion ? '<p> 1 </p>' : '<p> 2 </p>' }}
pero es que no va
se lo pasa por el forro del trasero
twin bridge
bueno, creo que no podría retornar una etiqueta como valor
y si intentas algo como esto?
@past harbor
sacred harbor
se ve más limpio con el if normal 
y para que blade te imprima en raw es {!! !!} si mal no recuerdo
fathom flame
sacred harbor
si no siempre te escapará los símbolos
fallow dock
oic
no se enoje con el framework pueh ||aún||
{!! rand(0, 1) ? '<i>Vives</i>' : '<i>Mueres</i>' !!}```epicmi hello world (?)
Unparenthesized `a ? b : c ? d : e` is deprecated. Use either `(a ? b : c) ? d : e` or `a ? b : (c ? d : e)` (View: /home/manuel/lara/blog/resources/views/welcome.blade.php)```este estúpido framework se opone a mi esoterismodigo, lenguaje
{!! rand(0, 1) ? rand(0, 6) > 5 ? '<b>Quedas malherido, pero sobrevives</b>' :'<i>Mueres</i>' : '<i>Vives</i>' !!}```nice{!!rand(0,1)?!array("yegh",null,"wuff")[eval(strrev(';)3,0(dnar=e$'))||$e]?'<b>Quedas malherido, pero sobrevives</b>':'<i>Mueres</i>':'<i>Vives</i>'!!}```lo ofuscamos un poco
still radish
why simulate it when we can just live it
fallow dock
2:25
glass dragon
damn edsel this video is interesting
still radish
he is a smart guy
he wrote his own python library to create the animations if I recall correctly
median trail
yeah I think that's true
grizzled hedge
3blue1brown makes the best math vids
lusty widget
eager wagon
median trail
x = 15
median trail
15 is dividing 2x, so in that case you can multiply it by the two that's on the other side of the equations
so you end up with
2x = 2(15)
and since 2 is multiplying the x, then it can divide the expression that's on the other side of the equation
x = 2(15)/(2)
and you can cancel out the 2 that's both in the numerator and the denominator
therefore x = 15
bold gull
¿Siempre es el denominador el que se mueve hacia el otro lado?
timber crown
To sum it up:
Since you are in an equation, if you do something to one side, you must do it to the other. So, if you multiply by 15 to get rid of the fraction, you have to multiply the other by 15.
You then have 2x=30. To get rid of the 2, you divide the 2x by 2, and then you must divide the other side (30) by 2.
Then, it brings you back to x=15. You could also multiply by the reciprocal (flipped fractions) to get rid of it. Multiply each side by 15/2.
bold gull
Thanks!
hybrid hull
¿Alguien aquí ha implementado el algoritmo de distancia levenshtein?
still radish
no 😭
shrewd pendant
No creo que ese algoritmo sirve para nada
Cuando lo necesitaba, inventé mi propio algoritmo en su lugar
unreal pagoda
Hola?
still radish
buenas pixie
fathom flame
gusty ermine
What's the equation for getting limits haha
i totally forget
I need help with #2 and #3 haha
@abstract scaffold If you have time, can you help me? It would be greatly appreciated.
abstract scaffold
k
@gusty ermine 2 is too blurry
and i assume the last one is limit approaching infinity
is that 3n^3 on the numerator?
and n^3 on the denominator?
gusty ermine
My bad. I will take the picture again. and yes. number 3 is n approaching infinity and the eqation is (3n^3-5n)/(n^3-2n^2+1)
Sorry my phone's broken so I have to use computer camera and the resolution is not good
abstract scaffold
what u can do for the third one is try to plug in a super big number into ur calculator
for a "guess"
since it's multiple choice
=wolf (3(999999)^3-5n)/((999999)^3-2(999999)^2+1)
=wolf (3(999999)^3-5*999999)/((999999)^3-2(999999)^2+1)
gusty ermine
I am not allowed to use a calculator. I am not sure how to do this algebraically
abstract scaffold
the way to do it algebraically. when dealing with limits with infinity, you want to see what is the highest power in the numerator and denominator
the rest of the powers don't matter. because for example. "x^4" approaching a really big number vs "x" approaching a big number. "x^4" is super big that "x" is insignificant
gusty ermine
I see. In this case, there is n^3 both in numerator and denominator, would it be nonexistent?
abstract scaffold
in my made up example, u see the ones in red are "insignificant when approaching infinity"
@gusty ermine I'm assuming your course doesn't go through l'hospital's rule. because that's another trick that could be used.
gusty ermine
Didn't learn that. Interesting name tho.
abstract scaffold
here's another way to think about it.
factor out the highest power on each. then do some cancellations.
then the limits should be easier to calculate
abstract scaffold
no no no. factor out the highest power on both numerator and denominator first.
gusty ermine
ohhh i see!
abstract scaffold
the highest power is significant
the other powers are puny
when approaching infinity
gusty ermine
abstract scaffold
for question 2: I'd ask. What is the area of the whole rectangle first?
and, yes. u r on the right track now.
gusty ermine
the answer is 3 because as n approaches infinity, the fractions will be smaller and smaller therefore almost 0
abstract scaffold
yes. exactly
abstract scaffold
technically i should've placed brackets around the limits on the second line (before i separated the limits out) as to show the whole thing is being taken as a limit rather than just say "3". not including the brackets makes it look like for example "5/n^2" is not part of the limit.
gusty ermine
I see. It was pretty clear that lim was both for 3 and -5/n^2
can you help me with number two haha
abstract scaffold
first. what is the area of the rectangle?
abstract scaffold
which in this case is?
gusty ermine
so (b-a)(d)
gusty ermine
Integral of f(x) from a to b?
gusty ermine
so my equation is (b-a)d-integral (from a to b) y dx
abstract scaffold
ok. lemme step back a little. tell me how you'd solve this
gusty ermine
get the anti derivative of 2dx which is x^2. then evaluate it from a to b, so it would be (b^2)-(a^2)
abstract scaffold
derivate of x^2 = 2?
abstract scaffold
lemme show u another method
sometimes you gotta step back to think "what does integration actually mean"
gusty ermine
Area under the curve
gusty ermine
Wait
I think the answer's integral (from c to d) f(y)dy
because if the graph rotates 90 degrees its under the curve...?
but then it would have excess area of (d-c)(a)
abstract scaffold
ur right that it leaves excess for the first one. so it can't be the first one alone. it needs extra terms.
gusty ermine
I think the answer is the second one but i don't really get what would be accomplished through (d-f(x))
abstract scaffold
try to solve the integral partly and you'll see.
you're probably not used to questions where an arbitrary graph is given to you with a shaded area and you have to make your own integral, then hence solve.
one thing someone may do like in the above semicircle example is recognise it's a semicircle and find out the area immediately...
but another thing that could be done is to convert it into an integral and hence solve.
especially if the graph is some weird curve that doesn't resemble any 2D shape area. then a question may just give you a graph with no integral, but you as the person attempting the question need to recognise that it's related to integrals and need to make your own integral and hence solve.
try working from the answer to see what i mean
gusty ermine
I tried to integrate that as parts and got d(x)^2/2 (from b to a)- (F(b)-F(a))
abstract scaffold
split it like i've done.
you don't know what f(x) is.
thus you can't really do it by parts. plus none of your answers in multiple choice seem to have the primative function F(x) in your final answer, only the integrand f(x)
gusty ermine
yea...
abstract scaffold
see if my next line helps
it's very confusing, because the "d" from your graph and "dx" are different. so yes, this letter "d" is a very shit letter
the final line. I don't mean "dx", rather just d*x
abstract scaffold
haha, u made the same mistake.
gusty ermine
I don't know why I am keep doing that!
abstract scaffold
"d" is just a constant here.
it's like integration is just the reverse of differentiation.... but it's like saying "i know how to write my own name forwards.... but writing it backwards can take a little practise and mistakes may happen"
or writing it upside down vs writing it normally
so mistakes with integration like that can happen
you get confused easily
gusty ermine
Haha yeah. I don't think calculus is my thing but I am trying.
WAIT
I get it!!!
integration (from a to b) of d = the area of the rectangle!!! and when the area under the curve is subtracted, the shaded region is what is left!!!
abstract scaffold
you see what im trying to get at now? you were over complicating it by "going to the final answer", but first you needed to think "what are other ways i could find the area of this rectangle"
gusty ermine
I can't believe how simple that was!
Yeah I see why you explained the concepts to me
Thank you so much
abstract scaffold
any time
gusty ermine
Is it possible to ask more questions?
abstract scaffold
go ahead
gusty ermine
abstract scaffold
first I suggest trying to draw what the question is trying to tell you, to give you a rough idea. "hint, it's kinda like the idea I was trying to get you to do earlier"
gusty ermine
=wolf graph 1/(x-1)
gusty ermine
i didn't understand the question and what they meant by 'and the lines x=3 and x=4' but im kinda thiking that i have to integrate y from 3 to 4?
because x=3 and x=4 are horizontal lines and that would make almost a rectangle
abstract scaffold
=wolf graph x = 3
abstract scaffold
=wolf integrate 1/(x-1) from x = 3 to x = 4
gusty ermine
wouldn't it be ln(3/2)? Why does it say log(3/2)?
abstract scaffold
log = ln
when you see log without a number, assume base "e" most of the time, i.e. log_e
if you do computer science, it's maybe log_2
since binary is common there.
but in the mathematics world, assume base e or ln (which is log base e)
don't worry about it too much. using "ln" everyone should understand.
glass dragon
it is
gusty ermine
abstract scaffold
calculator wise, the log button is base 10
in all my high school and uni life, they've been base e.
abstract scaffold
so there's always a "trick question" trying to trick ya with base 10 or base e in an exam
glass dragon
i feel like that's some weird australia thing
abstract scaffold
especially when it's the natural complex log. that's Log, and not Ln
glass dragon
oh apparently it's common in certain fields of mathematics but not others
none of which I took any of in college lol
gusty ermine
probably not in american high school level
glass dragon
it's used a lot in statistics and egineering, which I avoided at all costs
gusty ermine
Yup math is really cool but it's only for smart people
This calculus stuff is already making my brain explode
abstract scaffold
ur on the right track for question 7.
think about what tangent at a point means in terms of derivatives.
abstract scaffold
=wolf derivative of (2x+3)/(3x-2) at x = 1
abstract scaffold
it seems you flipped the quotient rule a bit maybe
wait no, ur fine.
ur number punching just must have been wrong somewhere
ah. u expanded it wrong.
ur "calculus" was correct, the the "algebra" afterwards was a bit off.
gusty ermine
aha i see haha
i am so ashamed to be a korean and be so bad at math lol
i got -13
abstract scaffold
ok. good. -13 is on the right track. need to know what to do afterwards is the key.
gusty ermine
Mmm no idea
abstract scaffold
what type of "graph/curve/line" is a "tangent"?
median trail
I missed the math talk :(
gusty ermine
a line
abstract scaffold
yep, a straight line.
do you remember the formula for finding a straight line given a point?
there are 2 versions.
gusty ermine
y2-y1/x2-x2?
abstract scaffold
that's the reciprocal of the gradient
that's now just the gradient of the line
abstract scaffold
one version is y1 = mx1 + K
where m is your gradient
and (x1, y1) are your given point
and K is a constant needed to be found.
median trail
is this multivariable calculus? 
marsh linden
ooh
gusty ermine
point slope form and stuff
abstract scaffold
this is not multivariable calc
marsh linden
my maths friends are here
median trail
ah
marsh linden
i require your assistance
gusty ermine
y2-y1=m(x2-x1)
gusty ermine
yup
abstract scaffold
yep