friction

[chrome ridge]

Acc to my understanding
W1 is work done by friction in moving from a to c' to b

W2 is work done by friction in moving from a to c to b

Clearly the path length acb is larger

Since friction is a non conservative force it depends upon the path length . Therefore w2>w1
Toppr site says otherwise and coaching module says w1=w2

[shut pulsar]

<@&1227987967939838003>

Note for OP

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[chrome ridge]

@rancid sedge any ideas?

[rancid sedge]

Im out ill definitely look into this once i get bck to home

[chrome ridge]

ohkk , np

[rancid sedge]

W1=w2 use Work energy theorem

[chrome ridge]

but friction is non conservative so it should depend on path taken, w2>w1

[rancid sedge]

Vertical plane h

Har jagh normal same thodi hai

Directly friction nhi nikal sakte

Wd by frction + wd by mg = k2-k1=0

Dono hi case m A to B jara hai to work done by mg constant hai

Islie firction ka work dono case me same hoga

[chrome ridge]

k2 and k1 is kinetic energy final and initial respectively ?

if yes then how do we know particle has same velocity upon reaching b through 2 diff paths

[rancid sedge]

It is the difference in kinetic energy

Initial bhi velocity zero h Finally bhi zero

[chrome ridge]

ohh , got it. big brain question. thanxx

can you please the "elastic rubber " one too @rancid sedge . thanks again

[rancid sedge]

Let me see

[chrome ridge]

+solved @rancid sedge000

+solved @rancid sedge