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Mang Ben obtained a fertilizer recommendation of 90-30-60 kg N, P205 and K2O per hectare in his three fourth(3/4) hectare farm. The available fertilizer at the store is complete 14-14-14, Urea (46-0-0) and MOP (0-0-60).How much would be the total cost (Complete @P3,400/bag + Urea@3,000/bag + Muriate of Potash@2,800/bag) in satisfying the above fertilizer recommendation?
To calculate the total cost of the fertilizers required to satisfy the recommendation, we need to figure out the quantities needed for each type of fertilizer.
Given:
Fertilizer recommendation: 90 kg N, 30 kg P205, and 60 kg K2O per hectare.
Available fertilizers:
- Complete 14-14-14 at P3,400/bag
- Urea (46-0-0) at P3,000/bag
- MOP (0-0-60) at P2,800/bag
We'll start by calculating the quantities needed for each nutrient:
For nitrogen (N):
Since Complete 14-14-14 contains 14% nitrogen, we can calculate the quantity needed as follows:
(90 kg N / 0.14) = 642.86 kg
For phosphorus (P205):
Since Complete 14-14-14 contains 14% phosphorus, we can calculate the quantity needed as follows:
(30 kg P205 / 0.14) = 214.29 kg
For potassium (K2O):
Since MOP (0-0-60) contains 60% potassium, we can calculate the quantity needed as follows:
(60 kg K2O / 0.60) = 100 kg
Now, let's calculate the total cost:
Quantity of Complete 14-14-14 needed = 642.86 kg
Cost of Complete 14-14-14 per bag = P3,400
Number of bags of Complete 14-14-14 needed = (642.86 kg / 50 kg per bag) = 12.86 bags
Total cost of Complete 14-14-14 = (12.86 bags * P3,400/bag) = P43,684
Quantity of Urea needed = 642.86 kg
Cost of Urea per bag = P3,000
Number of bags of Urea needed = (642.86 kg / 50 kg per bag) = 12.86 bags
Total cost of Urea = (12.86 bags * P3,000/bag) = P38,580
Quantity of MOP needed = 100 kg
Cost of MOP per bag = P2,800
Number of bags of MOP needed = (100 kg / 50 kg per bag) = 2 bags
Total cost of MOP = (2 bags * P2,800/bag) = P5,600
Adding up the costs of each fertilizer type, we get:
Total cost = (Total cost of Complete 14-14-14) + (Total cost of Urea) + (Total cost of MOP)
Total cost = P43,684 + P38,580 + P5,600
Total cost = P87,864
Therefore, the total cost of the fertilizers required to satisfy the recommendation would be P87,864.
Typhoon odette has fully devastated areas in Southern Leyte that's why The Municipality of Agriculture Office at LGU in Southern Leyte aids their coconut farmers by giving seedlings to their coconut farmers.In the case of Mang Ben, if Mang Ben will only plant half of his total area (0.75ha) with cacao seedling in a triangular planting system with 3m x 3m distance, how many seedlings does he need?
To determine the number of seedlings needed by Mang Ben, we first need to calculate the area he will be planting with cacao seedlings.
If he will only plant half of his total area (0.75ha), the area for cacao planting would be 0.75ha / 2 = <<0.75/2=0.375>>0.375ha.
Next, we need to find the number of cacao trees that can be planted in this area using a triangular planting system with a 3m x 3m distance.
To calculate this, we need to find the area of each triangular planting unit and divide the total area by it.
Area of one triangular planting unit = (base x height) / 2
= (3m x 3m) / 2
= 9 square meters
Area of 0.375ha in square meters = 0.375ha * 10,000 m^2/ha
= 3,750 square meters
Number of seedlings needed = Area of 0.375ha / Area of one triangular planting unit
= 3,750 square meters / 9 square meters
= 416.67
Since the number of seedlings must be a whole number, Mang Ben will need to round up to the nearest whole number.
Therefore, Mang Ben needs 417 seedlings.
Mang Ben obtained a fertilizer recommendation of 90-30-60 kg N, P205 and K2O per hectare in his three fourth(3/4) hectare farm. The available fertilizer at the store is complete 14-14-14, Urea (46-0-0) and MOP (0-0-60).Considering that you computed for Complete (14-14-14) first. To fully satisfy the above Potasium requirement, by using MOP that cost 2,800 pesos per bag, how much (pesos) does he need?
To calculate the amount of MOP fertilizer Mang Ben needs to satisfy the potassium requirement, we first need to determine the amount of potassium (K2O) required per hectare.
The recommended fertilizer ratio is 90-30-60 kg N, P205, and K2O per hectare.
Since Mang Ben has a three-fourths (3/4) hectare farm, we multiply the recommended rates by 0.75:
Potassium requirement = 0.75 * 60 kg
= 45 kg K2O per 0.75 hectares
Now, let's calculate how much MOP is needed to fulfill the potassium requirement:
MOP fertilizer ratio is 0-0-60, which means it contains 60% K2O.
Amount of MOP needed = (Potassium requirement / K2O concentration in MOP) * 100
= (45 kg / 60%) * 100
Since K2O concentration is given in percentage, we need to convert it to a decimal:
K2O concentration = 60% = 0.60
Amount of MOP needed =(45 kg / 0.60) * 100
= 75 bags
Considering that each bag of MOP costs 2,800 pesos, the total cost of the MOP fertilizer Mang Ben needs is:
Total cost = Amount of MOP needed * cost per bag
= 75 bags * 2,800 pesos
= 210,000 pesos
Therefore, Mang Ben needs 210,000 pesos to purchase the required amount of MOP fertilizer.
Joshua is scheduled to do ring weeding his dragon fruit farm so he hire 2 laborer to do it. His men can finish ring weeding 1 pole of dragon fruit plant for 5 minutes. How much will be the cost of ring weeding if his area is only 1/2 half hectare planted with dragon fruit at 2x2 meters given that the current wage of his workers is 500 pesos per man-day?