#Can I build the query below in convex?

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stray gazelle
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Query: SELECT * FROM workspaces WHERE id IN (SELECT workspaceId FROM members WHERE userId = $userId)
Can I build the query above in convex, where it needs to search workspaces by index and not filter? I couldn't find an alternative to the IN Operator. Also, does the ID field get indexed by default?

dusky hornetBOT
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Hi @stray gazelle. I'm kapa.ai, your friendly support bot. I will try to answer your question by searching through the knowledge base. :wave:

#

In Convex, you can achieve similar functionality to the SQL IN operator by using separate point lookups in parallel. However, Convex does not support the IN operator directly in its withIndex method for efficiency reasons. Instead, you can use the eq operator to match specific values.

Here's an example of how you might structure your query in Convex:

const memberWorkspaceIds = await ctx.db
  .query("members")
  .withIndex("by_userId", q => q.eq("userId", $userId))
  .collect();

const workspaces = await Promise.all(
  memberWorkspaceIds.map(workspaceId => ctx.db.get(workspaceId))
);

In this example, we first query the members table with an index on userId to get all the workspaceIds for a specific user. Then, we use Promise.all to fetch all the workspaces with those IDs in parallel.

As for your question about indexing the id field, Convex does not automatically index any fields. You need to explicitly define indexes on the fields you want to index using the index method when defining your table schema. Here's an example:

import { defineSchema, defineTable } from "convex/server";
import { v } from "convex/values";

export default defineSchema({
  workspaces: defineTable({
    id: v.string(),
    // other fields...
  }).index("by_id", ["id"]),
});

In this example, we define an index by_id on the id field of the workspaces table.

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For more information, you can refer to the following resources:


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