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#convex filters (helpers) escape hatch pagination. why?
stiff boughBOT
The issue you're experiencing might be due to how the filter helper from convex-helpers works with pagination. According to the documentation (https://stack.convex.dev/complex-filters-in-convex#escape-hatch-pagination), when using TypeScript filters with pagination, it can return small or empty pages to the client. This can slow down load times and cost database bandwidth as it traverses the entire table across many pages. Each query only looks at a small page of data, so they can run within Convex’s query limits.
The filter helper looks at documents one at a time. So doing filter(db.query("posts"), predicate).first() stops when it finds a single post for which predicate(post) is true. This is equivalent to db.query("posts").filter(predicate).first() and better than db.query("posts").collect().filter(predicate)[0] which would look at every post. This might be why you're seeing fewer results when using the filter helper with pagination.
If your query is filtering out results after the paginate call, it could be returning empty pages. You might want to check how big the pages are. If the pages are 0, your query might be scanning a ton of rows to find the next page and giving up. If this is the problem, try pushing some of the filtering into an index. Alternatively, you might be clicking the button multiple times while waiting on a single page, if your connection is slow. When you click it once, the state of the paginated query should no longer be canLoadMore until the new results come in, at which point loadMore can be called again (source (https://discord.com/channels/1019350475847499849/1199788864525570179)).
If you're still having trouble, you might want to reach out to the Convex support team for more specific guidance.
Note: you can ask me a follow up question by @ mentioning me again :speech_balloon:
naive lava
ok so lets not use filter from convex helpers and if i keep using my code as it is but what i'm trying todo is to add another field check with here
recordsQuery = recordsQuery.filter((q) => q.eq(q.field("assignedPerson"), currentUser.id));
what i also want to compare is that if a record has a field with array of user ids and i want to loop through that array to see if user id exists in any of array how can i do it with convex filters because convex doesn't have q.in or q.includes @stiff bough
stiff boughBOT
Let me check the knowledge base for you. One moment! :books:
In Convex, there isn't a direct equivalent to SQL's IN keyword or JavaScript's includes method for array fields. However, you can achieve similar functionality by using JavaScript or TypeScript to process the results of your query.
Here's an example of how you might do this:
const records = await recordsQuery.collect();
const filteredRecords = records.filter(record => record.userIdArray.includes(currentUser.id));
In this example, userIdArray is the field in each record that contains an array of user IDs. The filter method is a JavaScript array method that creates a new array with all elements that pass the test implemented by the provided function. In this case, it's checking if currentUser.id is included in the userIdArray of each record.
This approach involves fetching all the records and then filtering them on the client side, which might not be efficient if you have a large number of records. If performance is a concern, you might want to consider restructuring your data or using indexes to make your queries more efficient.
For more complex queries, you can write the complex logic in JavaScript! Convex guarantees that the results will be consistent. You can find more information about this in the Convex documentation (https://docs.convex.dev/database/reading-data#more-complex-queries).