I want to define following schema:
export default defineSchema({
dashboards: defineTable({
nodes: v.array(v.type<MyType>()),
user: v.id('users'),
}),
})
Is it possible to put a type in an array?
#How can I generate a schema which contains an element from a given object?
thick sundial
crude oakBOT
Hi @thick sundial. I'm kapa.ai, your friendly support bot. I will try to answer your question by searching through the knowledge base. :wave:
Yes, it is possible to define a type in an array in Convex. You can use the v.array() validator to define an array of a specific type. However, the type you want to use inside the array should be inferred from the Convex's Infer as shown in the Discord support thread:
type MyType = Doc<'table_name'>['fieldName']
Then, you can use this type in your schema definition:
export default defineSchema({
dashboards: defineTable({
nodes: v.array(v.type<MyType>()),
user: v.id('users'),
}),
})
Please note that the v.type() function is not mentioned in the provided knowledge sources, so you might need to check the Convex documentation or support for the exact syntax and usage.
Also, remember that the schema's own types come from the validators used to define it, for example, v.boolean(), v.string(), v.number(), v.any(), v.literal(), and v.union() as shown in the knowledge sources here (https://docs.convex.dev/database/schemas#any), here (https://docs.convex.dev/database/schemas#literals), and here (https://docs.convex.dev/database/schemas#unions).
For more complex schemas, you can use defineTable and defineSchema to define the types of your tables and schemas as shown here (https://stack.convex.dev/end-to-end-ts#definetable-and-defineschema) and here (https://docs.convex.dev/api/modules/server#definetable).
Note: you can ask me a follow up question by @ mentioning me again :speech_balloon:
thick sundial
But the function type does not exist
@crude oak But the function type does not exist
crude oakBOT
Let me check the knowledge base for you. One moment! :books:
I apologize for the confusion. Based on the provided knowledge sources, Convex does not seem to provide a v.type() function for defining custom types in a schema.
Convex supports the following types of values: Id, Null, Int64, Float64, Boolean, and String. Each type has a corresponding validator that can be accessed on the v object imported from "convex/values". For example, v.string(), v.boolean(), v.int64(), etc. as shown here (https://docs.convex.dev/functions/validation#convex-values) and here (https://docs.convex.dev/database/types#convex-values).
For arrays, you can use v.array() validator, but it seems that it should be used with the provided validators, not with custom types.
If you need to use a custom type in your schema, I would recommend checking the official Convex documentation or reaching out to their support for more specific guidance.
Note: you can ask me a follow up question by @ mentioning me again :speech_balloon:
thick sundial
@crude oak I following function
export const list = query({
args: {
user: v.id('users'),
},
handler: async (ctx, args) => {
return await ctx.db
.query('dashboards')
.filter((q) => q.eq(q.field('user'), args.user))
.collect();
},
});
How can I use this function and pass an argument?
crude oakBOT
Let me check the knowledge base for you. One moment! :books:
You can use the list function in your React component by using the useQuery hook provided by Convex. You need to pass the argument as an object to the useQuery hook. Here is an example:
import { useQuery } from "convex/react";
import { api } from "../convex/_generated/api";
export function App() {
const { results, status } = useQuery(api.dashboards.list, { user: "userId" });
return (
<div>
{results?.map(({ _id, text }) => <div key={_id}>{text}</div>)}
</div>
);
}
In this example, replace "userId" with the actual user ID you want to pass as an argument. The useQuery hook will call the list function with the provided user ID and return the results.
Please note that the api import path might be different in your project. You should adjust it according to your project structure.
You can find more information about using query functions in React components in the Convex documentation here (https://docs.convex.dev/database/pagination#paginating-within-react-components).
Note: you can ask me a follow up question by @ mentioning me again :speech_balloon:
thick sundial
@crude oak How would it look like without using React?
crude oakBOT
Let me check the knowledge base for you. One moment! :books:
If you're not using React and want to call the list function, you can do it directly in your JavaScript or TypeScript code. Here's an example:
import { list } from './path-to-your-list-function';
async function fetchData() {
const result = await list.handler({ db: yourDatabaseInstance }, { user: 'userId' });
console.log(result);
}
fetchData();
In this example, replace 'userId' with the actual user ID you want to pass as an argument. Also, replace yourDatabaseInstance with the actual database instance you're using in your application. The list.handler function will be called with the provided user ID and database instance, and it will return the results.
Please note that the list import path and how you get your database instance might be different in your project. You should adjust it according to your project structure.