#Optimal amount of input formula?

11 messages · Page 1 of 1 (latest)

meager apex
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I have been annoyed about the amount of input required to supply a mam with full throughput 100% of the time, and have been looking for alternatives.

I tried so make a graph that would show average throughput based on input. For example; if i supplied 50% of the "max" input, the mam would still produce full throughput most of the time. To do this i assume a quadrant can be 1 of 7 shapes (including empty) and 1 of 8 colors, all with a equal chance of happening. This approach will probably be flawed since i don't have enough knowledge on the ros1 algorithm.

For anyone wondering why I'm doing this, it's because i suspect that aiming for max throughput all the time might be less building efficient, especially as mams get more efficient and input also use a fair amount of building. And so i can justify not spending hours suppling my mam. So the goal is to create a formula where you can plot in your mams building per full belt of output and input building required to supply that full belt, and the formula will output the optimal amount of shape and color input. (will need 2 formulas. one for shape. one for color.)

As probability is not my strong side in math i will need some help.

So my question is quite open: Does anyone have any tips on how to create this formula or any relevant knowledge on the ros1 algorithm?

bronze wagon
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usually people will input 1 crate of every shape/color type

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which is 4 belts or 4 launchers

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and that mam would then make any 1 layer of a shape

meager apex
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Optimal amount of input formula?

little harness
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All I do is set up a MaM, pipe supplies to it and watch what doesn't keep up. Then put more of those in line. Supply logistics is my least favorite part of MaMs though.

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meager apex
meager apex
little harness
meager apex
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if my math is correct you don't have to think about it:) It basically says you can supply half of worst case and see no difference in throughput

toxic nymph
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If you are supplying solid shapes and then chopping them into quads in the MAM, you will need 4 belts of each of the 5 shapes (including pins) to produce a worst case scenario of a shape like CuCuCuCu:CuCuCuCu:CuCuCuCu:CuCuCuCu.